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#help-19
odd edgeBOT
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acoustic atlas
what happened in this step ?
odd edgeBOT
what happened in this step ?
torpid owl
they just moved the 2 from the numerator to denominator by inverting it
acoustic atlas
how exactly ?
my brain is not braining today
oh
i see not talking about
the term above the marked one
how did all of THAT became cos x0
hazy kiln
what happened in this step ?
Ahh they just took 2 common
2((sin(h/2){cos(x+h/2)/2})h/2
,help
clever fjordBOT
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odd edgeBOT
@acoustic atlas Has your question been resolved?
hazy kiln
Uhh
See
For taking 2 common from numerator u would have to divide the cos part with 2 so tht taking 2 common doesn't affect the eq
fluid ivy
but how does that become cos(x)
hazy kiln
I dunno abt thr
fluid ivy
💀
odd edgeBOT
odd edgeBOT
Available help channel!
sly wedge
hello
restive delta
What power of 3 is 2187
copper frigate
3^7
full cape
2x+3y=7
3x-2y=4
copper frigate
Also is that 4^(3x-2y) = 25!
I think it's 256
restive delta
Oh
copper frigate
2x+3y=7
3x-2y=4
So yeah
restive delta
And 4⁴ = 256
So now in both equations, we made the base same
So we can equate the exponents
restive delta
2x+3y=7
3x-2y=4
And get this
sly wedge
ok i though 2187 was not a power of 3
odd edgeBOT
@sly wedge Has your question been resolved?
odd edgeBOT
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Available help channel!
devout plinth
Is there a formula to find this?
odd edgeBOT
Is there a formula to find this?
devout plinth
But how do I find that
torpid owl
how do you find what
devout plinth
the formula
torpid owl
it's given to you in words
the brain (b) is (equals) 2% (0.02) of a person's body weight (x).
stark coyote
rational root theorem. can someone explain this part to me? I'm factoring the second picture.
stark coyote
i have a list of possible roots as +- 1,2,4,5,10,20
toxic monolith
Substitute subsequent roots of a given polynomial one by one, if you get it right, then you can divide by the appropriate binomial, obtaining a trinomial, that allows you for using formula for roots of quadratic equation
stark coyote
so i found +2 works, i would divide by (λ-2)?
toxic monolith
yes
toxic monolith
let me look at it
stark coyote
,w expand (x-2)(x-2)(x-5)
clever fjordBOT
toxic monolith
very well
stark coyote
i definitely see how just dividing and conquering with one known root works, but do you know what the wiki was trying to explain with that highlighted portion?
toxic monolith
no) i rarely read wiki ab maths lol, but what did ?
stark coyote
they used a root that didnt work on the example, then substituted x = 1 + t (the non-root + t) to get a polynomial that has a second list of possible roots, and you cross reference to get the true roots
toxic monolith
some magic way 🙂
hoary cloud
ember oak
round loom
odd edgeBOT
nimble blaze
show your work
round loom
$$\frac{\frac{\sin \left(x\right)}{\cos \left(x\right)}\cdot \sin \left(x\right)-\frac{\sin \left(x\right)}{\cos \left(x\right)}}{\sin ^2\left(x\right)-1}$$
clever fjordBOT
Lex1729
round loom
$$\frac{\frac{\sin ^2\left(x\right)}{\cos \left(x\right)}-\frac{\sin \left(x\right)}{\cos \left(x\right)}}{\sin ^2\left(x\right)-1}$$
clever fjordBOT
Lex1729
round loom
$$\frac{\frac{\sin \left(x\right)}{\cos \left(x\right)}}{\sin ^2\left(x\right)-1}$$
clever fjordBOT
Lex1729
nimble blaze
where'd the reset of the numerator go
round loom
$$\frac{\frac{\sin ^2\left(x\right)}{\cos \left(x\right)}-\frac{\sin \left(x\right)}{\cos \left(x\right)}}{\sin ^2\left(x\right)-1}$$
clever fjordBOT
Lex1729
round loom
where'd the reset of the numerator go
Oh true, my bad.
nimble blaze
continue from here
round loom
So how would I further simplify?
nimble blaze
factorise
round loom
the denominator or numerator?
nimble blaze
both, do it one at a time
odd edgeBOT
@round loom Has your question been resolved?
vocal valve
I don't know where to do this and this isn't education related or anything and just something I need to figure out cause my braincells pulled a my dad
if you have 3 out of 7 objects, what fraction do you have?
dim sandal
You tell your guess
vocal valve
You tell your guess
That the thing. Braincells have shut down. Ik that if it was 6 just be 1/2 but it's not as easy with odd numbers. But since it is 7 maybe a decimal is involved? I'm not sure
cold sage
well, how did you get 1/2 if it were 3 out of 6
presumably you simplified 3/6
3 out of 7 is simply 3/7
odd edgeBOT
@vocal valve Has your question been resolved?
vocal valve
3 out of 7 is simply 3/7
Oh, thank you, you my braincells don't work usually
odd edgeBOT
vocal valve
Wait, so how would one simplify 3/7?
odd edgeBOT
Available help channel!
odd edgeBOT
Wait, so how would one simplify 3/7?
odd edgeBOT
@vocal valve Has your question been resolved?
plain sun
Can someone help me with this induction question?
odd edgeBOT
Can someone help me with this induction question?
@plain sun Has your question been resolved?
Available help channel!
neat juniper
odd edgeBOT
formal surge
<@&286206848099549185>
neat juniper
<@&286206848099549185>
Usually supposed to do that after 15mins
formal surge
Pretty sure its been over 15 mins
patent shard
yeah it is correct
neat juniper
Pretty sure its been over 15 mins
No there’s 2 mins left
patent shard
idk why they marked it as incorrect
formal surge
Nah hold up
formal surge
yeah it is correct
Hey uh can you try redoing on paper
neat juniper
It’s correct ur teacher must’ve made a mistake when putting the answers in
formal surge
Yes im desperate for the .33 points
formal surge
It’s correct ur teacher must’ve made a mistake when putting the answers in
Ok ye maybe
But alright im moving on
patent shard
odd edgeBOT
@neat juniper Has your question been resolved?
old hollow
I had an exam last night and I don't even understand what this supposed to mean
The answer was Y=X-1
old hollow
Yes
old hollow
Yes
mystic saffron
where m is the slope and c is the y-intercept
old hollow
Yes
mystic saffron
now, just assume, that's the equation for the required line
thus, it must satisfy, (2,1)?
old hollow
Yes it does
old hollow
Ok what
mystic saffron
you see
1/2*root2x means
at every x value
slope is different
does that make sense
old hollow
Yes
mystic saffron
does it too have the same slope at every point?
old hollow
Ah no
mystic saffron
do you know that slope of tangent line is dy/dx?
old hollow
Ngl it got me more confused I am entirely sorry to get you into this trouble 💀
mystic saffron
Ngl it got me more confused I am entirely sorry to get you into this trouble 💀
💀
it was entirely my fault
I misread the question
old hollow
do you know that slope of tangent line is dy/dx?
Yes derivatives give slope
old hollow
I misread the question
I don't even know the question
mystic saffron
wait, reading it again
old hollow
It told me to get an equation but I'm not sure what am I given with
2,1 and idk what is the other thing
old hollow
My guy idk either I came here confused
old hollow
maybe just find the equation?
Unfortunately all of the choices gives you 2,1 and is a line
mystic saffron
hmm,
old hollow
The answer was Y = x - 1
mystic saffron
do they want the slope of tangent line at 2,1?
not slope
equation
do they want the equation of tangent line at x = 2?
old hollow
Idk either
As confused as you are
Can you tell me what is 1/2*√2x
Why is it there
Or any question with similar pattern
mystic saffron
I assumed that it's the slope at every point?
old hollow
The slope has an x in it?
old hollow
Oooh
Wait if that's the case doesn't that mean the equation is just the integral of that thhing
old hollow
But it's surely not y = x - 1
mystic saffron
exactly
old hollow
And yeah not a line
It stops somewhere since √ of x
old hollow
It's okay man I mean it's just 10 points and A is still A
mystic saffron
ooh, it's asking the solution for the "initial value problem"
bruh
xD I finally got it
mystic saffron
I wasn't familiar with that term
but googling it seems, to find the value of constant of integration with given constraints and then get the complete equation
old hollow
Well English calculus is certainly something
old hollow
No
That's the entire question
If you're confused then it's fine
I'm also confused because it might be I don't get it or the question has an error
Thanks for helping tho
How do I close the ticket
mystic saffron
.close
old hollow
Thanks
mystic saffron
the solution to the IVP comes out to be y^2 = x/2
if you calculate c it comes out to be 0, so you get y^2 = x/2, not sure if this is helpful though :/
old hollow
It is helpful, I just gotta get an explanation from my lecturer now
Well that's if he is even gonna explain it
.close
tribal jewel
how do i find the bounds of integration for theta in this question (or in these questions generally)
odd edgeBOT
how do i find the bounds of integration for theta in this question (or in these ...
@tribal jewel Has your question been resolved?
quasi sparrow
x^2 + y^2 = r^2 describe circles
tribal jewel
i dont really understand the other constraint
what does y less than or equal to x look like
quasi sparrow
tribal jewel
thank you
one more question
why is the radius from 1 to 2
and not from sqrt(1) to 2
wait nvm
dumb question
disregard it
lol
odd edgeBOT
@tribal jewel Has your question been resolved?
mystic saffron
odd edgeBOT
tardy lagoon
first calculate g^n(x)
mystic saffron
how
mystic saffron
*Suppose $f_n : A \longto \R$ is uniformly continuous on $A$ for every $n \in \N$ and $f_n \longto f$ uniformly on $A$. Prove that $f$ is uniformly continuous on $A$.
clever fjordBOT
mystic saffron
Anyways is this the right way to begin:
\vs{3 mm}
Let $\epsilon > 0$. Since $f_n \longto f$ converges uniformly on $A$, there exists an $\alpha \in \N$ such that[
\abs{\m {f_n}x - \m f x} < \f{\epsilon}3 \tqs{with} x \in A, ; n > \alpha
]
clever fjordBOT
pearl patio
i found this thing somewhere: a+b%c = (a%c + b%c)%c
odd edgeBOT
i found this thing somewhere: a+b%c = (a%c + b%c)%c
mystic saffron
yes
wooden python
so you found something strange and want us to explain what it means while we are missing the context 
but yes if % is taken as the remainder operation then it makes sense
(a+b) % c tho
pearl patio
so you found something strange and want us to explain what it means while we are...
i'm missing the context too 😭
sorryy
pearl patio
(a+b) % c tho
but shouldn't it be (a + b) mod c = a (mod c) + b (mod c)
wooden python
are we looking at mod as an operation
pearl patio
where did the addition (a (mod c) + b (mod c)) mod c come from
wooden python
i.e. a mod b is the remainder of a upon division by b, lying between 0 and b-1 inclusive
pearl patio
are we looking at `mod` as an operation
i have no idea, i guess you may assume whatever you think would work cuz i don't have any context either :C
pearl patio
no
wooden python
cause like i could tell you some shit sure
but if it doesnt align with what you are doing
then it will just confuse you unnecessarily
so i am hesitant
pearl patio
😭 u can tell me anything, but i just don't know much number theory
it's not related to a question either so yeah
wooden python
(a+b) % c may not be equal to a%c + b%c
for example (17+15)%10 is 2 but 17%10 + 15%10 is 7+5 = 12
pearl patio
ahhh i see
wooden python
but if you also reduce mod c again then equality holds always
pearl patio
so the extra mod 10 Was to take care of that
pearl patio
but if you also reduce mod c again then equality holds always
would it be the same for multiplication?
i don't know it generalized but if i had numbers then usually yeah i just do 12 (mod 10) but remainder has to be in 0<R< 10 and then land at 2 (mod 10)
wooden python
(the remainder is allowed to be 0)
wooden python
would it be the same for multiplication?
yes
pearl patio
(the remainder is allowed to be 0)
oh yeah whoops my bad
okay thanks
it makes sense now
odd edgeBOT
Available help channel!
upper onyx
Any hint how to start with $\int_1^{\infty}\frac{|cos(x)|}{x^2}dx$?
clever fjordBOT
ThM
toxic rose
Hmm abs value..well that just means u need to split no?
But I think it might not work cus of the infinity
whole vine
It will work. You'll prolly get some sequence with summation to infinity
odd edgeBOT
Available help channel!
wanton merlin
They asked to find the kth term which doesn't have a relation with x, I found n to be 12 and when I use newton binomial and do some algebra I found k to be -30?? How can there be a -30th term??
lavish kite
,rccw
clever fjordBOT
lavish kite
...ok i think we're missing some context?
the kth term of what, what's k, what's x, what's n
wanton merlin
nth is the power which the expression is raised to, k is the term in the binomial theorem and ur supposed to find the kth term that doesn't have x
i or k
odd edgeBOT
@wanton merlin Has your question been resolved?
silver thicket
how to solve this?
odd edgeBOT
how to solve this?
wooden python
if such a function exists then (f_x)_y should be equal to (f_y)_x
odd edgeBOT
@silver thicket Has your question been resolved?
silver thicket
if such a function exists then (f_x)_y should be equal to (f_y)_x
what does (f_x)_y mean?
$(f_x)_y$
clever fjordBOT
risa★
sterile blaze
the partial derivatives of y of (the partial derivative of x of f)
silver thicket
oh ok!
sterile blaze
find the partial derivative of the f_x given
silver thicket
so i find the partial derivative of fx in terms of y and the partial derivative of fy in terms of x and then compare the two
sterile blaze
(g_x)_y= derivative of (2x+y) wrt y
= 1
wooden python
the partial derivatives of y of (the partial derivative of x of f)
the partial derivative with respect to y of f_x
sterile blaze
oh yes. oops
silver thicket
whats wrt
wooden python
so i find the partial derivative of fx in terms of y and the partial derivative ...
with respect to. not in terms of.
sterile blaze
with respect to
wooden python
indeed
old barn
odd edgeBOT
old barn
how to get from a to b?
thin kelp
explain?
odd edgeBOT
@old barn Has your question been resolved?
old barn
<@&286206848099549185>
odd edgeBOT
@old barn Has your question been resolved?
odd edgeBOT
@old barn Has your question been resolved?
cosmic sandal
Hint: Look for a way to apply part a to get an inequality symmetric in a, b and c.
wind silo
Okay, I have a way for you to solve part a.
The first thing you need to keep in mind is that a, b, and c are all greater than zero. This is important.
Try using the distributive property on the right-hand side of the inequality. After this, you'll want to move all the variables to one side of the inequality and do some factoring. After playing around with it some, let me know what you come up with and we'll proceed to the next part of the process.
cosmic sandal
Okay, I have a way for you to solve part a.
He asked how to use part a to solve part b, not how to solve part a. 😅
wind silo
Ohhhh, sorry
odd edgeBOT
@old barn Has your question been resolved?
cyan pivot
odd edgeBOT
cyan pivot
how does this simplify to that
mellow depot
the 4's get simplified and you divide both sides by 3cosx
pastel dew
tawny frost
why is |v x w| but no || around v dot w
odd edgeBOT
why is |v x w| but no || around v dot w
thin sorrel
v x w is a vector so you need the magnitude
but dot product returns a number already
still axle
odd edgeBOT
still axle
is everything correct so far?
restive delta
is everything correct so far?
Ye
late prism
odd edgeBOT
late prism
Hi so on #30
I found the antiderivative and checked my answer its correct i think
But we're supposed to take the derivative to check our answer
And its not matching the original function
and i cant find the error
restive delta
Could you resend just the question part?
sour grove
when you take anti-derivative -1/3+1=2/3
odd edgeBOT
@late prism Has your question been resolved?
thick mesa
odd edgeBOT
thick mesa
please help me iwth this problem, ive gotten
"-4 less than or equal to k AND k < 4" AND "k greater than or equal to 3 OR -3 greater than or equal to k"
ebon harness
Draw two real lines, and illustrate each inequality, find intersection of both @thick mesa
thick mesa
ebon harness
Drawing two seperate real lines will give you a better view instead of shoving all to one
thick mesa
i saw the answer on photomath and see they found the intersections but
i dont get how thats possible if it was [-4, 4)
or does it not matter
ebon harness
Its not relevant to that
We are taking intersection because of the word 'and'
You would take union of two intervals when you see the word 'or' (misworded earlier, fixed now)
ebon harness
You would take union of two intervals when you see the word 'or' (misworded earl...
Oops i meant union, but typed conjuction
odd edgeBOT
@thick mesa Has your question been resolved?
late prism
odd edgeBOT
formal surge
odd edgeBOT
odd edgeBOT
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
clever fjordBOT
ThM
clever fjordBOT
ThM
formal surge
Alright thats pretty straight forward
What about the next examples
Does it work the same in the numerator
The second one im stuck
I got 3x/√15
Theres no perfect square for 15 wdym
So i would have √15/15
√15^2 = 15
1/√15 = √15/15
Where am i going here
i need you to illustrate it on paper please
clever fjordBOT
ThM
clever fjordBOT
ThM
formal surge
You're not elaborating
I wasnt asking for the answers
How do you replace √15/15 into √9x√15??
Yes
Now what am I suppose to do
√15/15 = 1?
Because the 15's cancel out
clever fjordBOT
ThM
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
formal surge
man
I dont know
Alright
If you multiply the denominator, with both the numerator,
.
clever fjordBOT
ThM
formal surge
@turbid laurel
You cant use it because its a fraction
Plus the radicand doesnt have a factor
turbid laurel
hello
formal surge
Youre not elaborating bro
formal surge
,
turbid laurel
ok so in math we dont really want radicals in denominators
formal surge
Yep
turbid laurel
the reason why i dont know but its just something we gotta do to call it fully simplified
so using this rule
if we have a fraction
and we multiply the top and bottom of the fraction by the same number
it will be the same fraction
so using that info how do we get rid of the radical in the denominator
formal surge
So in this case √9x/√15x
formal surge
2nd question
2nd question
√9x/√15
And yes, we can't have the radical in the denominator
Now how do I rationlize this
turbid laurel
And yes, we can't have the radical in the denominator
ok
i will tell u abt
1 more neat rule
if we have sqrt(x) * sqrt(x), the answer will be x
@upper onyx can you put this in the math formatter pls idk how to use it
formal surge
Numerator*, and I cant have √15 in the denominator
Now get off me
√x * √x = x
√x * √x = (√) = xx^2
turbid laurel
Now for √9x/√15
what do we multiply to the top and bottom to get rid of ur radical
turbid laurel
√15?
yess
now do that
to the top and bottom
sqrt(9x) * sqrt(15)
over
sqrt(15) * sqrt(15)
formal surge
Uh
turbid laurel
dont simplify the fraction yet just tell me what do you end up with
when you multiply the top and bottom by sqrt15
turbid laurel
So √145x/15
yes
also its 135
not 145
but thats okay
just dont do that on a test lmao
formal surge
Ye my bad
turbid laurel
alr
formal surge
I got test tuesday so
turbid laurel
If i tried finding perfect squares?
any perfect squares in there that we can pull out
wait do you know the trick to finding prime factors
formal surge
But 9 is
formal surge
Highest one ye
turbid laurel
I had √9x * √15
ok so you are saying that the square root of 9x is 3x
formal surge
3√15x
formal surge
Wait what
formal surge
3√15x
15
turbid laurel
3√15x
------
15
RIP the x you will NOT be missed
formal surge
Nah u thought
formal surge
Yeah this is where I get stuck
3√15x/15
I feel like the 15's cancel but idk what to do
turbid laurel
I feel like the 15's cancel but idk what to do
remember when i said that multiplying the numerator and denominator by some number gives the same fraction?
formal surge
I dont remember
turbid laurel
I dont remember
now would be a great time to
well the same thing applies to division
we can divide the numerator by some number
and do the same to the denominator
and we would get the same number
what can we divide the numerator and denominator by?
turbid laurel
Wait i think i see something
bro has wanda vision
turbid laurel
Wait i recgonize this
yes
formal surge
what can we divide the numerator and denominator by?
Ok now I got √5x/5
Is that right
turbid laurel
You told me to divide the numerator and deno by something
yeah
but whyd you get rid of the 5
formal surge
there was no 5 what
turbid laurel
Because i divided it by 3
ahh i see
formal surge
Does that work
formal surge
Ye
turbid laurel
can we substitute a variable for sqrt(15x)
we will call it u
3 * u is = 3 * sqrt(15x)
formal surge
Uh
formal surge
All gud
turbid laurel
3 * u is = 3 * sqrt(15x)
you get what i did here right
formal surge
Nah
turbid laurel
ok
lets step away from 3 * sqrt(15x) for a sec
so lets say we have 3 * x
divided by 3
we will do 3 * x first
give me some number
formal surge
6
formal surge
18
turbid laurel
whats 18 divided by 3
turbid laurel
i did
formal surge
Lol
turbid laurel
Wipe your butt that was like 4 mins
a shit does not take 10 mins
formal surge
nvm
turbid laurel
Was it that bad
nah my shits have been feeling extra devious lately
ok
so by whatever you did
like when you said 3*sqrt(15x) divided by 3 is sqrt(5x)
you are kinda saying that
3*x divided by 3 = x/3
and you said that x is 6
so whats 6 / 3
turbid laurel
like when you said 3*sqrt(15x) divided by 3 is sqrt(5x)
when you multiply numbers together
formal surge
Wait what
formal surge
Nah youre doing good
turbid laurel
Ok now I got √5x/5
bc this is like really important to get down
formal surge
Ye
turbid laurel
ok so
what are you thinking abt
when you divide 3 * sqrt(15x) by 3 and get sqrt(5x)
not tryna be mean but i wanna see what you are doing
formal surge
It becomes 1
3/3 = 1
1√5x is the same as just √5x
We're not adding
So 1 is just there
turbid laurel
1√5x is the same as just √5x
no but why does it go from sqrt(15x) to sqrt(5x)
formal surge
Because youre dividing by 3
15x / 3 = 5x
3 has no variable right
But if I had 3x it would be 15x / 3x = 5
√'s remain the same
turbid laurel
15x / 3 = 5x
ok so youre doing 2 things wrong with that
the first thing is that you are messing with stuff inside a radical by doing stuff outside the radical
but the second thing
which i wanna go over
formal surge
yes
turbid laurel
is that you are dividing all thes tuff thats multiplied together
formal surge
yes
formal surge
is that you are dividing all thes tuff thats multiplied together
I used it before
turbid laurel
yes
however
this isnt exactly true
when you have (a * b) / a
think of the a * b as one term
so the a's would cancel out
because you are multiplying b by a
but then right after you are dividing it by a again
so you just end up with b
turbid laurel
when you have (a * b) / a
so this would be = to b, not b / a
turbid laurel
(a * b) / a = b / a
explain why you believe in this
formal surge
Ok now i dont know 😭
turbid laurel
yeah i wish i could find a good way to explain it to you
but for now
just know that (b * a) / a = b
formal surge
Divide by 3
turbid laurel
Divide by 3
do that
formal surge
Why 15x
turbid laurel
Why 15x
because remember (a * b) / a = b
because when things are multiplied together
they are a single term
and when you are dividing you only divide into the term once
turbid laurel
Give an example
(3 * 15) / 3
we are gonna do it 3 wayst
the first way is the normal way with PEMDAS and all that
so whats 3*15
formal surge
45
turbid laurel
45 / 3
formal surge
15
turbid laurel
yes
turbid laurel
15
this will be the correct answer
now we will do it your way
divide each part by 3
so 3 divided by 3
formal surge
1
formal surge
5
formal surge
5
turbid laurel
5
does that make sense?
considering how
doing it the normal way by just plugging in the numbers
we got 15
formal surge
Ye i guess
turbid laurel
Ye i guess
for now idk how to explain it better
but just think of it like
(a * b) / a = b
formal surge
So
To sum that part up
I cannot divide square roots
Right?
because now I got √15x/5
turbid laurel
I cannot divide square roots
yes
turbid laurel
You got me up here confused
ik u aint saying that after u took a minute to do 18 / 3
but u get it now
thats what matters
do the other 2 problems
ping me if u confused
formal surge
18 / 3 = 6 that ez
turbid laurel
18 / 3 = 6 that ez
i took a fat shit while waiting for u to do that
turbid laurel
You took 4 minutes for a dump
it doesnt take that long
formal surge
it doesnt take that long
Do u wipe or wash
formal surge
Oh
formal surge
Alr thats fair
tepid acorn
💀
odd edgeBOT
@formal surge Has your question been resolved?
fickle jungle
odd edgeBOT
fickle jungle
hi
I need help about what do you mean by
SEgment AB had been the same segment as Segment DE
but C and F were different points
btw this is my assignment in google forms
not a quiz
<@&286206848099549185>
odd edgeBOT
@fickle jungle Has your question been resolved?
devout thunder
odd edgeBOT
modest nacelle
!status
odd edgeBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@devout thunder Has your question been resolved?
heady stump
is this just maths
odd edgeBOT
is this just maths
heady stump
i have science question
If object A is on top of object B and we are asked to draw a free body diagram for object B, is the weight of A pushing down or is it the net force of A
heady stump
What are those Nbf
tidal oxide
In the case I drew the floor would have an increased normal force
Normal on b by floor
heady stump
So its normal on b by a pushing down and not gravity of a?
tidal oxide
If the floor isn't there and you push down on a the net force on b also changes
tidal oxide
So its normal on b by a pushing down and not gravity of a?
Yes
heady stump
ok
tidal oxide
It's the force you put on a plus the weight of A
heady stump
It's the force you put on a plus the weight of A
?
tidal oxide
Draw a free body for a. The downward for a in that free body is what b feels
So that's the normal on b by a
heady stump
Draw a free body for a. The downward for a in that free body is what b feels
The downward is gravity
tidal oxide
If that's all it is then that's the answer
heady stump
you said net force of A though
tidal oxide
A better way to think of it actually is to look at a fbd for a
Normal on b by a equals normal on a by b by 3rd law pairs
So if you look for what that is on a is your answer. Which if that is only the weight of a then the normal Al's are both the weight of a
odd edgeBOT
@heady stump Has your question been resolved?
zenith talon
is this sine law? we havent learnt this yet and im not sure if im dumb or this isnt actually part of what we learnt
modern aspen
what you need to have learned for this problem is the sine law and the minimum conditions for similar triangles, I'm pretty sure
silver thicket
what is this problem asking for?
odd edgeBOT
what is this problem asking for?
odd edgeBOT
@silver thicket Has your question been resolved?
tidal oxide
Same level I assume means same z coordinate, so both partials of the function must be 0 in your direction.
silver thicket
Same level I assume means same z coordinate, so both partials of the function mu...
thank you, can u elaborate more on the partials part u said?
both as in x and y?
silver thicket
yes they both need to be zero
do i find the gradient of f first?
tidal oxide
let me write something down and ill send the image
silver thicket
so apparently i had to find the vector thats orthogonal to the gradient
tidal oxide
isnt that just the one i posted at the end?
when u = <> at the end right?
i worded what i meant wrong i see
above my image
mystic saffron
Find the sum of 3 digit numbers whose HCF with 36 is 2
mystic saffron
Find the sum of 3 digit numbers whose HCF with 36 is 2
I just need the answer show ur work or not
odd edgeBOT
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
quasi sparrow
well I've already solved it😅
!done
odd edgeBOT
well I've already solved it😅
If you are done with this channel, please mark your problem as solved by typing .close
mystic saffron
I just need to see if it's correct Mr riemann
nimble blaze
if you're not sure whether you've done it correctly
show your work
quasi sparrow
Then follow the message and show your work
mystic saffron
alright you guys tell me how you would do it, I compare it to mine and inform if it does not match deal?
nimble blaze
no deal
if you've done stuff, show it
the more you try dodging, the more likely people will lose interest/leave and go elsewhere
mystic saffron
my answer is 82800 alright
quasi sparrow
alright you guys tell me how you would do it, I compare it to mine and inform if...
Follow the instructions
nimble blaze
show the work that lead to that
mystic saffron
no thanks
quasi sparrow
This is a waste of a channel
mystic saffron
Find the sum of 3 digit numbers whose HCF with 36 is 2
This is my question if anyone is wondering
quasi sparrow
Follow the bot message or stop wasting a help channel
mystic saffron
I made an AP with all those 3 digit numbers. That AP has 2 common differences and I make 2 APs from that and add those together.
mystic saffron
1 sec
106,110,118,122,130.........982,986,994,998
these are the numbers that we have to sum to get the answer I think
See the CD has 2 variations
4 and 8
so I made 2 APs with common difference 12 each
And the answer came out as 82800
1st AP
2nd one
adding these two I get 82800
mystic saffron
106,110,118,122,130.........982,986,994,998
again these two sums are just to solve this Sum
and I made this AP because all these numbers with 36, give hcf as 2
mystic saffron
Find the sum of 3 digit numbers whose HCF with 36 is 2
This is my question if an...
. Questions here
I'll close this channel if no one's here
anyone here?
.close
odd edgeBOT
odd edgeBOT
@tepid nimbus Has your question been resolved?
grizzled tide
nothing jumps out to me, it's looking like a "hard way" approach
if there's some trick it's not a general one, or it's one that I don't know
fair enough, and also yes Wolfram does this trivially
mystic saffron
I'm not sure it's legal
But you can use wolfree alpha to get a step by step guide on how to solve it
odd edgeBOT
@tepid nimbus Has your question been resolved?
frozen sierra
find the missing term of 20, 40, 100, _, 820?
odd edgeBOT
find the missing term of 20, 40, 100, _, 820?
tardy lagoon
let the missing term be x