#help-19
1 messages · Page 37 of 1
Youre looking for non-vertical asymptotes
Horizontal asymptotes fall under this category
So horizontal asymptote is x = 0 ?
Yes
Make sense , but how do I suppose to write an answer ?
Prove that as x tends to infinity f(x) tends to 0
Then you can conclude x=0 is a horizontal asymptote
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Hey all, I'm struggling getting started here
When I set y^2 = 2y+1 I get y = 1, 2
oh what
sorry I thought I had the channel
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
@rocky edge Has your question been resolved?
<@&286206848099549185>
can you think of a "rule" for this equivalence relation?
No
theres clearly a pattern right
Ye
can you express that pattern in plain english
can you deduce something about any of the elements in each set
is it something to do about the last element or first element on each set
for the first elements of each set i.e
1,2,4,7,11 they increase by 1 then 2 then 3 then 4
can you find a closed form for those?
closed form as in mathematical notations?
yeah
ill give you a hint
might be easier to find a closed form for the max of each set
max as in size?
yeah
ok
the last element of each set
how are you getting on with the q? igtg soon
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i need help with 6b. i just need to know if i even need to do long division cuz it seems pointless??
fractions but partial
No you don't need to do long division
aight thanks
You do it when the power of the numerator is equal to or greater than the power in the denominator
oh right 💀 i didn't notice the numerator is less than the denominator
thanks thanks
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Is there a nicer way to do this instead of just listing out?
It'd get messy if the number was something other than 11 so that's why
well I'd probably try by first finding a possible sequence of numbers
yes i'm aware
i'm curious about another way rather than listing out numbers
I think there probably is, but it's going to be a hell of a lot harder
yeah there probably is a "trick"
i'm looking for that
11 is 5+6
so everything else has to cancel out
1,2,3, and 4 cancels out with -1,-2,-3, and -4
okay there
You got a list of 10 consecutive integers but you could have just taken all the integers between -10 and 11 included
wait that pfp omg lol
@pearl patio Has your question been resolved?
yeah but i want the least cardinality of the set right to make a comparison
kuromi pfp too cute 
Oh right, you want to find a sequence of fewer than 10 terms
Well you need and odd number of odd numbers in it
If there is one yeah
None here i guess since the lowest cardinality it can have is 11 iirc
So you can try 2,3,4 but that's too small
1,2,3,4,5 is too big
So you necessarily have to go into the negatives
I don't think there's a nicer way
isn't 5+6 one the nicer way?
I just saw it on some site
I did it like you, but i was confused until i translated
oh maybe it just worked for this problem but you can't extrapolate?
without some work at least ig
I mean if you replace the 11 with a 9, you can find 4+5 and so you can have the sequence -3, -2, ..., 4, 5
But you could have just taken 2,3,4
since 10 + 11 = 21
yeah indeed lol
okay thanks
could i get help on this?
This one is confusing me
I have to compare the quantities in a similar fashion
Like i have an intuitive feel that Quantity A > quantity B
but that's really it
more of the areas are bunched up towards the middle so the value at the 75th percentile is closer to 60th percentile than it is to the 90th percentile
Not sure about that
aww
@summer cradle would you be kind enough to help me like last time or if you're busy its okay~~ (sorry for ping)
Oh the change of curvature occurs one standard deviation away from the mean
Hm actually I'm not sure this solve that
i was gonna try to take a nap sorry T_T but it might be that you can’t determine
I'm relatively sure you are correct but only because the 90th percentile isn't far enough
it's okay thanks for looking
the answer is i think A
as in Quantity A> Quantity B
Damn
@pearl patio Has your question been resolved?
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Consider 20 statements:
"I have exactly 1 sister." "I have exactly 1 brother."
"I have exactly 2 sisters." "I have exactly 2 brothers."
"I have exactly 3 sisters." "I have exactly 3 brothers."
"I have exactly 4 sisters." "I have exactly 4 brothers."
"I have exactly 5 sisters" "I have exactly 5 brothers"
"I have exactly 6 sisters" "I have exactly 6 brothers"
"I have exactly 7 sisters" "I have exactly 7 brothers"
"I have exactly 8 sisters" "I have exactly 8 brothers"
"I have exactly 9 sisters" "I have exactly 9 brothers"
"I have exactly 10 sisters." "I have exactly 10 brothers."
Find the largest natural number n such that each of the n siblings can make a different one of these 20 statements and be right. (all siblings have same parents)
ans: n=4 - say x is number of sisters and y number of brothers, there are only 4 possible statements: man can say I have x sisters and y-1 brothers and woman can say I have y brothers and x-1 sisters. 4 possible statements = max. of 4 siblings
Could someone please tell me if it is correct?
I found it kinda easy and Im worried that it is some kind of tricky question
Yeah that should be right
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Since I can’t find this question online
And also if I got it wrong,may you tell me where I went wrong
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how do i do this?
consider the function $f(t)=e^t-1$
Pure2
there exists some c in (0,x) such that it conforms to the MVT:
$e^c=\frac{e^x-1}{x}$
Pure2
then: Take the natural logarithm of both sides and then multiplying by 1/x
u can make some observation, ie c is between 0 and x, and x>0, it follows some nice inequalities to prove the thing
@cold urchin CALC
@honest hawk Has your question been resolved?
Nice one my disgraced student
np
can i be pure 3?
yes, i permit
thanks
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hi, can I ask here?
@mystic saffron Has your question been resolved?
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.reopen
✅
@mystic saffron Has your question been resolved?
@mystic saffron Has your question been resolved?
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Fisher's exact test can be used as a quick test for correlation between two variables X and Y, each of which has at least an ordinal scale of measurement. Divide the scatterplot of the N values of (X,Y) with a vertical line at the median of X, and a horizontal line at the median of Y, and count the number of observations in each of the four quadrants. note that the row and column totals are N/2, and are not at random. Suppose 16 observations of X = age of marriage of a husband, and Y = age of marriage of his father, result in 7 pairs where both ages were above the median. Are the two variables positively correlated?
I've made this table
+---------------------------+--------------+--------------+-------+
| | Above Median | Below Median | Total |
+---------------------------+--------------+--------------+-------+
| Husband's age of Marriage | X | 8-X | 8 |
| Father's age of marriage | 7-X | 1+X | 8 |
| | 7 | 9 | 16 |
+---------------------------+--------------+--------------+-------+
I don't understand how to proceed from here on, without the value of X
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Someone help me solve this
chat gpt can make images?
?
!status
ye
what's up with the bots today
interesting
when showing you a math problem solution
i see now
k
do the higher ups know about it?
about the bot?
the elites know everything
oh yeah the whole system is sown
yeah its happened before
last time it eventually fixed itself
would need mniip to look at it i imagine
wow
such a coincedence
that it is happening now
lol
when I have a math question
must be the opps
no wannder why their is less help channels
??
ik but your message didn't make sense here ^
yeah ik
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How do I solve AU=B if A has no inverse?
write U = (x, y, z), do the multiplication and solve the system
so like for the top one it would be
3y -3z = 9
2y -2z =6
x - y -z = -5
?
yes
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First step would be to factor the denominator
Then
What do you get
Yeah so since you can cancel x-1 from numerator and denominator what type of discontunuity is that? Since you can't cancel x+2 but its still undefined, what type of discontinuity is that?
When you can cancel a factor in numerator and denominator it means that value is discontinuous at a point
if you cant it means its an asymptote discontinuity
Yes I get a hat but that but how they get 1/3
this should be 1/x+2 but yeah thats the simplified form
Then 1/3 follows from plugging in 1
Use formula for circumference, and multiply it by the appropriate scale factor so you are only talking about the given length (100cm). Then you can solve for the radius of the smaller circle arc. Then you can probably do the rest from there
You have any ideas for how to do it?
No
Try moving sinx to the left and factoring
How to factor after
sin^2x=sinxsinx. How would you factor 2sinxsinx+sinx
Sorry of it's a dumb question
What thing do both of the terms share
using trigono identity
Sinx
?
Did not learn that yet but teacher is said we have to do these questions
No
What value is the left side equal to when sinx=0
Pi and neg pi
Ohh
Do the same thing for 2sinx+1 now (when 2sinx+1 is 0, the entire left side is 0)
or technically u could look at the answers and see only option 4 has -pi
Yeah including negative pi, but not positive pi
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bot broken or smth
😭
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what have you done
@sharp thistle Has your question been resolved?
Just imagined and feel about its domain
you just went on a spiritual adventure with the functions?
whats the definition of uniform continuity
It should be increasing continuously
Yes
have you tried applying the defintion on them to see if they fulfull it
I don't understand how to apply the definition
youll do it as normal
you get your e>0 and f=...
you say for all x,c in interval with |x-c|<f then...
then just do the |f(x)-f(c)|..... stuff
if you can get it so that delta has no dependence on c (or x by extension) then its uniformly continuous
Can we try an easy example so that i can understand the concept?
Suppose if we take sin(1/x)
I know that x=0 is not existing
Rest of all points it will be continuous
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Nvm
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how to calculate g1(y) and g2(y) without sketching?
like without sketching, idk if g1(y) = y/8 or g2(y) = y/8
Why can't you sketch
Yup
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i need help with trigonometry
if cosθ=3/5, and 0°<θ<90°, find tanθ-(1/sinθ)
@weak dew Has your question been resolved?
cos theta is 3/5 so sin theta is?
bet
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- The centers of four circles (in the plane) of radius 1 are the vertices of a square of side 1. Through how many points do at least two of these circles pass? Explain with the help of a neat figure.
tried drawing it?
no I don’t understand how to draw it
we are going to draw 4 circles, one at a time, pick your favorit vertex on the square with side length one. Then draw a circle where that vertex, is the center, and the circle has radius one, the same length as the side of the square
so the vertex is the center?
yes
I drew one
now, do this three more times, for each vertex
done
let me se
perfect!
so the answer is 8?
"Through how many points do at least two of these circles pass?" is a bit weird, we need to mark all intersections, then see if it is between atleast two circles, to count this write numbers next to the intersection to make sure to not miss any or over count
i think thats all of them?
Do you also have to count the circles?
no
so 8?
12 intersections of at least two circles
im confused
1: black and red intersects
2: black and blue intersects
7: black and green intersects
10: black and red intersects again
9: black and blue interects again
5: black and green intersects again
the answer thing says 8
weird
Shoot
What language?
Which inequality is wrong? (Explain graphically without SSM)
(A) sin 300° < sin 350°(B) cos 300° < cos 350°
(C) sin 300° < cos 350°(D) tan 300° < tan 350°
(E) cot 300° < cot 350°
Dutch
Time to draw a big circle
damn
aight lets skip drawing
we can just stare at this instead
familiar with the unit circle?
so first coordinate is cos, second coordinate is sin
so, now we can read of values to check the inequalites
yes
ah, here, more numbers and sign of the functions
we can start by checking those since postive is greater than negative
okay
(A) sin 300° < sin 350°(B) cos 300° < cos 350°
- < -*+ < +
(C) sin 300° < cos 350°(D) tan 300° < tan 350°
- < +*- < -
(E) cot 300° < cot 350°
- < -
Dam didnt reveal anything
the drawing sucks so hard
ye use the first one
when you have cos and sin then its quick to calculate tan and cot
but it needs to be graphically
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what i got was
a. 30
b. 14880
but apparently its wrong?
show ur work women lover
i did the calculator stuff on google so im unsure how to exactly show my work 😭
u can explain what u did
a is right
it seems you ignored pi for part b)
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I want a function from 1 to 128, I do not care what is beyond of those values, where 1 is 32 and 128 is 128. I think the linear function shall be good.
It is, probably, something as: "(128-32)/something", yet I do not see what.
hmmmmmm
I see it, I do not see the logic behind.
Do you mean like f(1) = 32 and f(128) = 128
If x is 1, y is 32, if x is 128, so is y, in 128 they cross.
Wdym they cross
One function, values cross, in that point x is y, beyond that x is probably bigger.
What do you mean by values cross and x is y
..
A fucntion has two values, not just one.
i mean this statement litterally means what pure said a line above doesnt it?
I do not know.
For x = 1
y = 32
OR f(1) = 32
For x = 128
y= 128
OR f(128 ) = 128
and you need this f(x)
?
Yes. That is what I want.
I did try learning such codes, I failed. I can only read the very basic.
If x passes 128, the y passes 96, x is 1,33..., or is y, times greater, I can do it.
No, it is just 96 because it already starts with 32 when other is 1.
Bingo. Now just to convert it into actual formula.
X/(1+1/3)+32 is the y I want, probably.
so you just wanted a straight line that passes through (1,32) and (128,128)
Yes.
oh my god.
wow

I think this is called linear function.
This is your thank. People in Indo-China, I forgot which land exactly, are collecting, what I remember as lilies.
.close
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yeah a straight line
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did you get the equation as
Oh no, no more questions! I barely understood this amount. Please.
.close mb didnt realise i opened a chat
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(from what i thought i think we can use rolle's theorem but im not sure how exactly)
as f prime here would just be linear
Maybe check all the options one by one
wont work
too many unkowns
specially option c 
cant seem to proof that otherwise too
look at the discriminant of 3ax^2+2bx+c
D = b²-3ac= a² -ac +c²
and then the signs of a,b,c
we do not know a / b / c it can be anything really
unless we get like a perfect square or adition of suares perhaps
From this you can check that the given exp is always non negative
we cant say for sure ig
well draw a rough graph and then mark the vertex and make cases (only 2)
For a,c are real
a>0 and a<0
So option C is incorrect
fair
so for option A
Check f(0).f(1)
And to make worst there is none of these in options
IKR!
Substitute value of c
as -a -b?
f(0).f(1)= -(a+b)(2a+b)= -(2a²+3ab+b²)
not sure what im looking for here..
Wait
what will multiplies them do
I was trying to get expression which is always +ve or -ve
You see how i got this
yeah ofc
already played with the discriminant a lot
im overstimulated
the dumb book doesnt have any other similar question
the book threw a curve ball right at my face and i had no prep
no way
no way
it is just rolle's theorem.
because i want to check if roots lie in the interval
i think i should consider THIS as f'(x)
to find f(x) i can just integrate it
ax^3+ bx+2 +cx+ C = 0
C-> arbitary constant
for f(0 )
we get C
for f(1)
we get a + b + c + C = C ( as a+b+c = 0 )
oh everything is fitting so perfectly now
and since f(0) = f(1)
fprime should have a root in interval 0 to 1
due to rolle's theorem
thanks for trying i think i got the solution , should be A
I have not studied rolle's theorem
oops forgot to close the chat
np
thanks for responding !!!!
( also this theorem was mentioned like so behind this question i swear , and no other question used this, had to read everything )
.close
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!status
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4
l composed r = {(a,3), (c,3), (b,1)} ?
i'll do r composed l later, just checking l composed r first
You can't define composition of l with r
Applying r first gets you an element from {1, 2, 3}, but you need that to be in the domain of l
Wht
This would be correct if you wrote r composed l
Ye
And is l(1) defined?
Na
Neither is $l \circ r$
A Lonely Bean
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$s(f,c)=\left(\floor{\frac{f}{c}}+1\right)\left(c+73-(c\mod{16})+\ceil{\frac{\log_2{c}}{8}}\right)$
Kris
for a given f, I want to find the c which produces the minimum s(f,c)
is it possible to create a formula that can do that, and how would i go about doing it?
right now, I just have some code that brute forces all values for c within a range, but it would be computationally cheaper and more scalable to solve the problem with a formula
also - f, c and the output to the function are all natural numbers
no theres no closed form solution for this
this is an integer programming problem google that
how do you know, is it provable?
and I don't know what this is, sorry
I looked up the wikipedia article and it has way too many things I don't understand, I'm not very smart
There seems to be a pretty easy solution to this
If f < c then floor(f/c) = 0 and the answer is a constant (if c can't be 0 then the minimum is at c=1)
Hm I can't find a way to explain the rest
the problem is about breaking a file down into chunks, where f is the size of the file and c is the size of the chunk, so if the size of the chunk is bigger than the filesize then there will just be one chunk and you can ignore the first bracket. I don't see how the output would be a constant but you only need to consider cases where 1 <= c <= f (or f+15? idk), sorry I should've mentioned that
f is the size of the file in bytes, so an integer greater than 0. c is the size of the chunk in bytes, so an integer greater than 0 and less than or equal to the file's size. the function presented in the latex output the size of the file in bytes after you've chunked it, added metadata, etc. so you're trying to use that function to find the optimal chunksize for reducing the size of the output file
i.e. this
while an explanation would be nice, all i really want is a formula that can be used to find the best c (since a formula is pretty much always gonna be faster than brute force)
or, at the very least, some kind of optimisation for brute forcing, like "only test odd numbers" or something like that (i'm not saying that is something that would work it's just an example)
but yeah. a formula. or how to make one because i don't know where to start.
Then it looks to me like c = ceil((f+1)/2) gives the minimum
based on my testing that doesn't seem to work, but I'm curious how you got that
I may have ignored a term 
rip
Ok first thing to notice, c - (c mod 16) is just 16*floor(c/16)
h u h
It starts at 0 and jumps up by 16 every 16 units
yeah i just tested it on desmos and it works but i can't wrap my head around why
In [0,15], (c mod 16) is just c
So that's c - c = 0
In [16, 31]. (c mod 16) is c - 16
So that's c - (c - 16) = 16
And so on
right
floor(x) jumps by 1 every 1 unit
floor(x/n) jumps by 1 every n units
Did that clear things up?
ceil(log_2(c)/8) starts at 1 and jumps up by 1 after 256^n where n starts at 1 and is just incremented every time
yeah, it's "how many bytes does it take to represent the integer chunksize"
So let's ignore this term, solve for c < 256 and then try to put it back in
i know it's not the correct way to do things but it's such a small term that it doesn't have much impact, so even if you can solve it without that term, that's better than nothing
but yeah okay
Ok, now floor(f/c) + 1 = floor((f+c)/c)
ignore this actually it does make more difference than i thought
why is that? is it like... floor((f+c)/c)=floor((f/c)+(c/c))=floor((f/c)+1)=floor(f/c)+1 or something like that? idk i haven't done maths in a while
Yeah
I probably won't be there in 30 min
Close this and open a new channel when you're back if you need
I have a feeling the minimum will be something like c = ceil((f+1)/(1+n)) where n = ceil(log_256(c)) or something
Otherwise ask for guidance with integer programming
I'm not sure I can actually solve this correctly
@spiral frigate Has your question been resolved?
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When I have this signal, how should I read the values for x[n]?
wdym how?
is the first value cos(pi/2 *0) ?
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im not sure if this is right
the 2/3 exponent should be outside the parenthesis for one
ya
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Question: What does it mean to find the rank of the derivative of a vector-valued function? For context, we recently covered implicit function theorem and rank theorem in my real analysis II class.
the derivative will be a matrix, so its just the rank of that matrix
or the rank of the matrix at an evaluation at a point rather
@gilded jewel Has your question been resolved?
Yeah I took the jacobian and found values for which f' is invertible (by setting determinant = 0)
But that doesn't tell me the rank of f' in general
you just have to determine a maximal set of linearly independent columns like normal
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I really really need help

so, I asked my teacher in thursday "wait, how they figured out that if we have a list, and we sum all the values of that list and we divide the output by the number of elements, we get the average?", and she didn't answer... so I am trying to answer that, and I got that the average between two numbers is (x+y)/2, and now trying to do that for 3 numbers, I got (x+y+2z)/4, and I am trying to prove that it is equal to (x+y+z)/3
can someone help me with that? I have been strugling with it the whole day ( I am not very good at math, like, I am 14 years old, but I have learned some math by watching 3b1b and other channels )
define average
in your context
what you are finding is a mean, one of the types of averages
we are studying statistics
yes
like, the average value between a list like [1, 2, 3, 4, 5] ( idk how to write it in math way, I am a programmer :( )
not really, I did avrg2(avrg2(x, y), z) -> ((x+y)/2+z)/2 -> ((x+y+2z)/2)/2 -> (x+y+2z)/4
how would you find the average of a list/array in whatever programming language you use?
float v = 0;
for(int i = 0; i < arr.size; i++)
{
v += arr[i];
}
v /= arr.size;
I know how
I want to know why
well now that's the average between (average between x and y) and z, which isn't average between x y and z
okay
ohhh, ok that explains
first condition: the order must not matter
so it must be symmetric
so no x+y+2z, because that's not symmetric between x y z
mhhh, true
but how would I find the mid point? for x and y is easy cuz i just did, c ( the middle between x and y ) is equal to x+d, and I want to know what d is, so the distance between x and y is y-x, and then I want the half of it, so d=(y-x)/2, then c=x+(y-x)/2, that is just c=x+y/2-x/2, and that is c=x/2+y/2 -> c=(x+y)/2
woah
first we were doing statistics, now this is geometry
but yes, these 2 things are related
the arithmetic mean of 2 points' coordinates is their midpoint
wait wait wait, wouldn't the actual avrg3 be something like avrg2(avrg2(x, y) avrg2(y, z))?
cuz we find the middle between x and y, and then between y and z, and we find the middle between those?
not gonna work
I will trust you
but now I am just doing trial and error to find what works and trying to see what fails
cuz it again gives bias to a variable
arithmetic mean is defined to be sum of series over its length
I started doing this since 9am or smth, now its 9pm, my brain is just hurting
but why that works?
you can't use combinations of avrg2 to get avrgn
wdym why it works
we use it as one of the measures of the average
why if I do number + number ... (n times) / n = average
yeah but why they found out that it works?
mean, median and mode
how?
yeah I know, that is what my teacher was talking about
and I asked "but how did people come out with this?"
for example
no answer
the mean * the length of array will be the sum of the whole thing
here's a person asking the same thing as you
yay
I mean he is asking "Why it works", I want to know "How they come up with it"
but I think yeah, the answer of one will answer the other in some way
that's history of math
but how did people just woke up one day and said "wait, if i sum all this things together and I divide that number by the number of things i summed up, I get the """average value""" between the numbers in this thing"
what is the thinking you had to do to get that
also, is there a prof that it will always work? for any array size?
any array size
but also again
i'm not sure what you want the proof of
an "average" of a list is a human invented thing
how they realized it worked for any array size?
also, what about an array with no elements inside?
that question is dumb but
it's not like it will lead to a contradiction
I wanted an answer
I mean everything is human invented so /:
you'll be dividing by 0 there :)
exactly
and 0/0 is "undefined" in most fields of math
my teacher said "it just works with any list size", and I was going to answer "what about a list with no elements?"
but I said "nah, this will lead to nothing"
i see you are a little smartass 13 year old
(it's a good thing, keep going)
like seriously i wish i was as cool at 13 lol
oh, thanks!
no way this site is just stackoverflow but with people that know math
damm I hate stackoverflow
a site full of smart people that just answer with vague questions or just don't answer at all and just act like they are supperior
i agree
when I started learning programming it was a pain in the ass
anyways, now I think I got an answer
but
mhhh
I really need that math lore
cuz I just can't see how people come up with tis
well, maybe is just like coding, they tried different algorithms at random until they got values they liked and said "this is good to analize this thing" and it stuck around
anyways, thanks a lot man
I really needed that answer, or at least a way of trying to figure it out, I don't have a clear answer, but I can start looking for info
and ask the right questions
I think this could be a really interesting topic to make a yt video about!"
( cuz I didn't find any info while searching there )
like those VSauce videos
it does sound interesting
yeah
in any case, if your question has been answered, type .close
and there is no info in spanish either so I could do it in spanish and english ( so I can show it to my nerd friend that likes math )
I think it is, for now
.close
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Since when in linear algebra are we allowed to add columns to other columns in a matrix like wtf
why not
wouldn't you expect A + (-A) = 0
i dont understand ur example
like ive never seen in my life someone doing column operations
how is that even legal
:
I mean break the determinant up
and you will see that if they have the same two columns
then det(A) = 0
ex the determinant of this is 0
so you can safely subtract a column from one to another and add one to another
and get the same determinant
ok but that only works cuz detA = 0?
well it works for any matrix
k but thats whats confusing
like in linear equations u cant just add an x column to a y column
yk? 😭
Well the determinant of the transpose is the same yes?
And the rows of the transpose are the columns of the original one
just reocgnize that you can break it up linearly
and that if there is a repeat column
you find that the determinant is zero
let me write it out if you really want
but I have to whip out my notebook
ok
you want me to get my backpack
and take out my notebook
and send a pic to you?
yes pls
so like we can just alternate between row and column operations on the same matrix with no problems?
that seems rly weird to me
I'm sending the page
pls don't use my handwriting for forgery or anything
um i wont
nosqldb probably has a good example coming. To me it seems like you're confusing row reducing and determinant computation. Row reducing forces you to only do operations on rows because it represents the simplification of linear equations. You don't have this restriction on determinants as they represent a scaling factor of a unit n-cube.
so its only for determinants we can do row operations?
i mean
colum
column operations
my example will come up, but trivially you can see usually if you can do column operations, you can also do row operations
since
det(A) = det(A^T)
my example will give an intuitive explanation on why you can do column operations
but a precursor, if a matrix A has two identical columns, then det(A) = 0
if you want the proof for that lmk
is the proof for that cuz theres gonna be a column of 0 when reduced
so the det would be 0 because the diagonal has a 0
if you change two rows or columns, you change the sign
but notice that you get the same matrix if you change the columns that are equal
so
let det(A) = b
then $b = -b \implies b = 0$
nosqldb
bc it's a real matrix
okay I'm sending the work
again don't forge
I sent the example
um why r u allowed to add them like that
well expand along the 3rd column
and you will see
what does expand along the column mean
do you know what an laplacian expansion is
no
@latent scaffold do you wish to explain
this is introductory linear algebra 💀
I also take introductory linear algebra
I thought this was a common topic
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How do you prove that e^x > x^n
You can show their ratio goes to infinity for large x
@old whale Has your question been resolved?
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how do I integrate this if I dont know what the function is?
@distant tartan Has your question been resolved?
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I= integrate (cos^2023 x) dx from 0 to 2pi |
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
(change bounds to use even/odd function properties)
@gleaming dew Has your question been resolved?
@gleaming dew did you understand the hint
@gleaming dew Has your question been resolved?
I'm really not very good at English so I hope everyone can explain in detail 🥲
I'm really grateful
Do you know what odd and even functions are
This is it, right?
help me pls
or this
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What’s the formula to the Pythagorean theorem?
You mean a^2 + b^2 = c^2? A very common formula that you can google
THANK YOU
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Yesss
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.close
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i am stuck on c, i dont know how can i use part a to help me
Maybe not useful, but note sin(π/10) = sin(9π/10)
We will get a polynomial from this process, I'm sure a is useful
I would instead consider x = π/10. However, I have not actually tried this yet so take me with a grain of salt.
@ruby nacelle Has your question been resolved?
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SOS
Distribution
Or just test square numbers
You want x to be square and x+5 to be square
Nvm
i would expand this first
then you can probably do a substitution where a = root(x) and solve from there (may not be exactly root(x))
notice that sqrt(x^2+5x) factors as sqrt(x)*sqrt(x+5)
That may not make this problem a piece of cake but definitely should help in some simplification
$\left( \sqrt{x+5}-\sqrt{x} \right)\left( 1+\sqrt{x^{2}+5x}\right)=5\\\text{ Let's note that the domain of the equation is }[0,\infty )\text{ then we get that: }\\\frac{5\left( 1+\sqrt{x^{2}+5x} \right)}{\sqrt{x+5}+\sqrt{x}}=5<=>1+\sqrt{x^{2}+5x}=\sqrt{x+5}+\sqrt{x}\\<=>\sqrt{x+5}\left(\sqrt{x}-1 \right)-\left( \sqrt{x}-1 \right)=0<=>\left( \sqrt{x}-1 \right)\left( \sqrt{x+5}-1 \right)=0\\<=>x = 1 \vee x=-4\text{, but }x\geqslant 0\text{. then solution is: }x=1$
Joanna Angel
well aren't you providing the entire solution to just be copied by the OP
well, i have just decided to show solution, since it is tricky, little bit
but yeah you did a good observation at STEP 1
(derationalizing sqrt(x+5)-sqrt(x))
yes, wanted to avoid gettign polynomials of he vry high degrees
@spiral atlas Has your question been resolved?
yo im back
i do not understand this by one bit nor the fact if this was even a 9th grade solution
how about this, i found an existing solution but there a part in it that i dont understand
i made solution shorter to decrease number of liens ) but ask
lemme find it
solution is x = 1, you can easily verify it
first i have applied Conjugate (square roots)
because i have noticed also that number 5 wil be reduced
nvm i get the whole thing
high school
but technically its middle school as in my place we still consider 9th grade to be middle
i see, i am trying to compare to our schools, but ok
irrational euqations, reuqire knowledge of many tricks
and mslty they are not pleasant )
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i dont know what to do next
and also idk how to use the results of part a
how is part a useful
can u just post the pic of the question agani please? @ruby nacelle

