#help-19

1 messages · Page 37 of 1

leaden light
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So that means that we don’t have any asymptotes ?

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Because it don’t have any breaking points

tall veldt
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Youre looking for non-vertical asymptotes

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Horizontal asymptotes fall under this category

leaden light
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So horizontal asymptote is x = 0 ?

tall veldt
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Yes

leaden light
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Make sense , but how do I suppose to write an answer ?

tall veldt
#

Prove that as x tends to infinity f(x) tends to 0

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Then you can conclude x=0 is a horizontal asymptote

leaden light
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Thanks mate

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wide nova
odd edgeBOT
wide nova
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Hey all, I'm struggling getting started here

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When I set y^2 = 2y+1 I get y = 1, 2

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oh what

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sorry I thought I had the channel

shut mantle
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rocky edge
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
rocky edge
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1

odd edgeBOT
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@rocky edge Has your question been resolved?

rocky edge
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<@&286206848099549185>

visual sigil
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can you think of a "rule" for this equivalence relation?

rocky edge
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No

visual sigil
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theres clearly a pattern right

rocky edge
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Ye

visual sigil
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can you express that pattern in plain english

rocky edge
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size of each set increases by 1

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and each set counts the natural numbers

visual sigil
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can you deduce something about any of the elements in each set

rocky edge
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is it something to do about the last element or first element on each set

visual sigil
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youre getting there

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what about those elements?

rocky edge
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for the first elements of each set i.e
1,2,4,7,11 they increase by 1 then 2 then 3 then 4

visual sigil
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can you find a closed form for those?

rocky edge
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closed form as in mathematical notations?

visual sigil
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yeah

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ill give you a hint

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might be easier to find a closed form for the max of each set

rocky edge
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max as in size?

visual sigil
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yeah

rocky edge
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ok

visual sigil
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the last element of each set

rocky edge
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oh

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i thought u meant cardinality Xd

visual sigil
rocky edge
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I finished it thanks

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forgot to say

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misty terrace
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i need help with 6b. i just need to know if i even need to do long division cuz it seems pointless??

mystic saffron
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man

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what is partial fractions anyway

misty terrace
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fractions but partial

mystic saffron
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basically

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u want

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factor of denominator and nume

mint mirage
misty terrace
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aight thanks

mint mirage
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You do it when the power of the numerator is equal to or greater than the power in the denominator

misty terrace
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oh right 💀 i didn't notice the numerator is less than the denominator

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thanks thanks

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pearl patio
odd edgeBOT
pearl patio
#

Is there a nicer way to do this instead of just listing out?

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It'd get messy if the number was something other than 11 so that's why

odd magnet
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well I'd probably try by first finding a possible sequence of numbers

pearl patio
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i'm curious about another way rather than listing out numbers

odd magnet
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I think there probably is, but it's going to be a hell of a lot harder

pearl patio
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i'm looking for that

pearl patio
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so everything else has to cancel out

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1,2,3, and 4 cancels out with -1,-2,-3, and -4

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okay there

late dust
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You got a list of 10 consecutive integers but you could have just taken all the integers between -10 and 11 included

summer cradle
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wait that pfp omg lol

odd edgeBOT
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@pearl patio Has your question been resolved?

pearl patio
pearl patio
late dust
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Well you need and odd number of odd numbers in it

pearl patio
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If there is one yeah

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None here i guess since the lowest cardinality it can have is 11 iirc

late dust
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So you can try 2,3,4 but that's too small

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1,2,3,4,5 is too big

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So you necessarily have to go into the negatives

pearl patio
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that's how i did it yeah

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that's the way to go about it i guess?

late dust
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I don't think there's a nicer way

pearl patio
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isn't 5+6 one the nicer way?

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I just saw it on some site

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I did it like you, but i was confused until i translated

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oh maybe it just worked for this problem but you can't extrapolate?

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without some work at least ig

late dust
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I mean if you replace the 11 with a 9, you can find 4+5 and so you can have the sequence -3, -2, ..., 4, 5

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But you could have just taken 2,3,4

pearl patio
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since 10 + 11 = 21

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yeah indeed lol

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okay thanks

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could i get help on this?

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This one is confusing me

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I have to compare the quantities in a similar fashion

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Like i have an intuitive feel that Quantity A > quantity B

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but that's really it

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more of the areas are bunched up towards the middle so the value at the 75th percentile is closer to 60th percentile than it is to the 90th percentile

late dust
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Not sure about that

pearl patio
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aww

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@summer cradle would you be kind enough to help me like last time or if you're busy its okay~~ (sorry for ping)

late dust
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Oh the change of curvature occurs one standard deviation away from the mean

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Hm actually I'm not sure this solve that

pearl patio
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yeah it's hard to actually show

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😭

summer cradle
late dust
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I'm relatively sure you are correct but only because the 90th percentile isn't far enough

pearl patio
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the answer is i think A

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as in Quantity A> Quantity B

odd edgeBOT
#

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inland cape
#

Consider 20 statements:
"I have exactly 1 sister." "I have exactly 1 brother."
"I have exactly 2 sisters." "I have exactly 2 brothers."
"I have exactly 3 sisters." "I have exactly 3 brothers."
"I have exactly 4 sisters." "I have exactly 4 brothers."
"I have exactly 5 sisters" "I have exactly 5 brothers"
"I have exactly 6 sisters" "I have exactly 6 brothers"
"I have exactly 7 sisters" "I have exactly 7 brothers"
"I have exactly 8 sisters" "I have exactly 8 brothers"
"I have exactly 9 sisters" "I have exactly 9 brothers"
"I have exactly 10 sisters." "I have exactly 10 brothers."
Find the largest natural number n such that each of the n siblings can make a different one of these 20 statements and be right. (all siblings have same parents)
ans: n=4 - say x is number of sisters and y number of brothers, there are only 4 possible statements: man can say I have x sisters and y-1 brothers and woman can say I have y brothers and x-1 sisters. 4 possible statements = max. of 4 siblings

inland cape
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Could someone please tell me if it is correct?

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I found it kinda easy and Im worried that it is some kind of tricky question

boreal crag
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Yeah that should be right

inland cape
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Ok thanks

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karmic hearth
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Since I can’t find this question online

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And also if I got it wrong,may you tell me where I went wrong

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honest hawk
#

how do i do this?

odd edgeBOT
zealous fossil
#

consider the function $f(t)=e^t-1$

clever fjordBOT
zealous fossil
#

there exists some c in (0,x) such that it conforms to the MVT:

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$e^c=\frac{e^x-1}{x}$

clever fjordBOT
zealous fossil
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then: Take the natural logarithm of both sides and then multiplying by 1/x

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u can make some observation, ie c is between 0 and x, and x>0, it follows some nice inequalities to prove the thing

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@cold urchin CALC

odd edgeBOT
#

@honest hawk Has your question been resolved?

cold urchin
#

Nice one my disgraced student

zealous fossil
zenith tartan
#

can i be pure 3?

zealous fossil
zenith tartan
#

thanks

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mystic saffron
#

hi, can I ask here?

odd edgeBOT
odd edgeBOT
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@mystic saffron Has your question been resolved?

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mystic saffron
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.reopen

odd edgeBOT
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@mystic saffron Has your question been resolved?

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@mystic saffron Has your question been resolved?

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forest solstice
#

Fisher's exact test can be used as a quick test for correlation between two variables X and Y, each of which has at least an ordinal scale of measurement. Divide the scatterplot of the N values of (X,Y) with a vertical line at the median of X, and a horizontal line at the median of Y, and count the number of observations in each of the four quadrants. note that the row and column totals are N/2, and are not at random. Suppose 16 observations of X = age of marriage of a husband, and Y = age of marriage of his father, result in 7 pairs where both ages were above the median. Are the two variables positively correlated?

I've made this table

+---------------------------+--------------+--------------+-------+
| | Above Median | Below Median | Total |
+---------------------------+--------------+--------------+-------+
| Husband's age of Marriage | X | 8-X | 8 |
| Father's age of marriage | 7-X | 1+X | 8 |
| | 7 | 9 | 16 |
+---------------------------+--------------+--------------+-------+

I don't understand how to proceed from here on, without the value of X

forest solstice
#

<@&286206848099549185>

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winged jacinth
#

Someone help me solve this

odd edgeBOT
lavish jackal
#

!status

mystic saffron
gray dome
mystic saffron
#

!status

lavish jackal
mystic saffron
#

what's up with the bots today

mystic saffron
lavish jackal
#

when showing you a math problem solution

lavish jackal
#

don't you see the bot is down

gray dome
#

i see now

lavish jackal
#

k

nimble delta
#

do the higher ups know about it?

tall veldt
#

ye

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pinks are working on it afaik

mystic saffron
#

about the bot?

mystic saffron
#

oh yeah the whole system is sown

tall veldt
#

yeah its happened before

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last time it eventually fixed itself

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would need mniip to look at it i imagine

mystic saffron
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guess the bot isn't as constant then

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probs a server outage

nimble delta
mystic saffron
#

such a coincedence

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that it is happening now

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lol

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when I have a math question

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must be the opps

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no wannder why their is less help channels

lavish jackal
#

??

mystic saffron
#

to occupied

lavish jackal
mystic saffron
#

yeah ik

odd edgeBOT
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near ore
#

How did they get those numbers

#

For ad

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distant tartan
odd edgeBOT
distant tartan
#

How do I solve AU=B if A has no inverse?

drifting valley
#

write U = (x, y, z), do the multiplication and solve the system

distant tartan
drifting valley
#

yes

distant tartan
#

gotcha, thanks.

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spare hornet
odd edgeBOT
spare hornet
#

How-to do

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When graphed the points where it says na are 1 and -2

fair prism
spare hornet
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Then

fair prism
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What do you get

spare hornet
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(x-2)(x+1)

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Otherway

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X+2

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And x-1

fair prism
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Yeah so since you can cancel x-1 from numerator and denominator what type of discontunuity is that? Since you can't cancel x+2 but its still undefined, what type of discontinuity is that?

spare hornet
#

Idk

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0/x+2

fair prism
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When you can cancel a factor in numerator and denominator it means that value is discontinuous at a point

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if you cant it means its an asymptote discontinuity

spare hornet
#

Yes I get a hat but that but how they get 1/3

fair prism
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Then 1/3 follows from plugging in 1

spare hornet
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In option 1

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Ohhh

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That makes sense

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What about thos

fair prism
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Use formula for circumference, and multiply it by the appropriate scale factor so you are only talking about the given length (100cm). Then you can solve for the radius of the smaller circle arc. Then you can probably do the rest from there

spare hornet
#

Ok last question

fair prism
#

You have any ideas for how to do it?

opal lantern
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interval it?

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by using -pi and pi for the limit?

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oke seems that i'm wrong

spare hornet
fair prism
spare hornet
#

How to factor after

fair prism
#

sin^2x=sinxsinx. How would you factor 2sinxsinx+sinx

spare hornet
#

Sorry of it's a dumb question

fair prism
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What thing do both of the terms share

opal lantern
#

using trigono identity

spare hornet
#

Sinx

opal lantern
#

?

fair prism
#

yeah

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so sinx(2sinx+1)=0 is what you have now

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Can you see what to do now?

spare hornet
#

No

fair prism
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What value is the left side equal to when sinx=0

spare hornet
#

1??

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No 0

fair prism
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Yeah 0

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What values of x does sinx = 0 for

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in the given interval

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[-pi, pi)

spare hornet
#

Pi and neg pi

fair prism
#

Close but remember ) means exclusive

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so pi is not included

spare hornet
#

Ohh

fair prism
#

Do the same thing for 2sinx+1 now (when 2sinx+1 is 0, the entire left side is 0)

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or technically u could look at the answers and see only option 4 has -pi

spare hornet
#

Yes

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Ohh but can't it be between ngetaove pi and pi

fair prism
#

Yeah including negative pi, but not positive pi

fair prism
#

sin0=0

odd edgeBOT
#
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spare hornet
#

Ok

#

What

fair prism
#

bot broken or smth

spare hornet
odd edgeBOT
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sharp thistle
odd edgeBOT
cold sage
#

what have you done

odd edgeBOT
#

@sharp thistle Has your question been resolved?

sharp thistle
cold sage
#

you just went on a spiritual adventure with the functions?

#

whats the definition of uniform continuity

sharp thistle
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It should be increasing continuously

cold sage
#

what do you mean

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what are you doing this as part of btw

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real analysis?

sharp thistle
cold sage
#

have you tried applying the defintion on them to see if they fulfull it

sharp thistle
cold sage
#

youll do it as normal
you get your e>0 and f=...
you say for all x,c in interval with |x-c|<f then...
then just do the |f(x)-f(c)|..... stuff
if you can get it so that delta has no dependence on c (or x by extension) then its uniformly continuous

sharp thistle
#

Can we try an easy example so that i can understand the concept?

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Suppose if we take sin(1/x)

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I know that x=0 is not existing

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Rest of all points it will be continuous

sharp thistle
#

.close

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odd edgeBOT
tawny notch
#

Nvm

odd edgeBOT
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tawny notch
#

.close

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tawny frost
#

how to calculate g1(y) and g2(y) without sketching?

tawny frost
#

like without sketching, idk if g1(y) = y/8 or g2(y) = y/8

quasi sparrow
#

Why can't you sketch

tawny frost
#

wait

#

is this sketch correct?

quasi sparrow
#

Yup

tawny frost
#

oh it makes now that i sketched it

#

thx

#

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weak dew
#

i need help with trigonometry
if cosθ=3/5, and 0°<θ<90°, find tanθ-(1/sinθ)

odd edgeBOT
#

@weak dew Has your question been resolved?

jolly halo
weak dew
#

4/5

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alright got it

jolly halo
#

bet

weak dew
#

.close

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odd edgeBOT
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eager iris
#
  1. The centers of four circles (in the plane) of radius 1 are the vertices of a square of side 1. Through how many points do at least two of these circles pass? Explain with the help of a neat figure.
sturdy perch
#

tried drawing it?

eager iris
#

no I don’t understand how to draw it

sturdy perch
#

start with square of side 1

#

got that part?

eager iris
#

1 second imma grab a paper

#

yes I got it

sturdy perch
#

now, do you know what a vertex is?

#

verticies in plural

eager iris
#

yeah

#

4 verticies

sturdy perch
#

we are going to draw 4 circles, one at a time, pick your favorit vertex on the square with side length one. Then draw a circle where that vertex, is the center, and the circle has radius one, the same length as the side of the square

eager iris
#

so the vertex is the center?

sturdy perch
#

yes

eager iris
#

I drew one

sturdy perch
#

now, do this three more times, for each vertex

eager iris
#

done

sturdy perch
#

let me se

eager iris
sturdy perch
#

perfect!

eager iris
#

so the answer is 8?

sturdy perch
#

"Through how many points do at least two of these circles pass?" is a bit weird, we need to mark all intersections, then see if it is between atleast two circles, to count this write numbers next to the intersection to make sure to not miss any or over count

#

i think thats all of them?

eager iris
#

Do you also have to count the circles?

sturdy perch
#

no

eager iris
#

so 8?

sturdy perch
#

12 intersections of at least two circles

eager iris
#

im confused

sturdy perch
#

1: black and red intersects
2: black and blue intersects
7: black and green intersects
10: black and red intersects again
9: black and blue interects again
5: black and green intersects again

eager iris
#

the answer thing says 8

sturdy perch
#

weird

eager iris
#

yep

#

is it done?

#

i have some other questions like this one if you wanna help?

sturdy perch
#

Shoot

eager iris
#

Lemme translate them

#

The next one is

sturdy perch
#

What language?

eager iris
#

Which inequality is wrong? (Explain graphically without SSM)

(A) sin 300° < sin 350°​(B) cos 300° < cos 350°
(C) sin 300° < cos 350°​(D) tan 300° < tan 350°
(E) cot 300° < cot 350°

#

Dutch

sturdy perch
#

Time to draw a big circle

eager iris
#

I hate drawing sm

#

How big does it need to be

sturdy perch
#

depends on how small you can write

#

quarter a4

#

half a4

#

something like that

eager iris
#

damn

sturdy perch
#

aight lets skip drawing

#

we can just stare at this instead

#

familiar with the unit circle?

eager iris
#

long time ago tbh

#

a bit

sturdy perch
#

so first coordinate is cos, second coordinate is sin

#

so, now we can read of values to check the inequalites

eager iris
#

yes

sturdy perch
#

ah, here, more numbers and sign of the functions

#

we can start by checking those since postive is greater than negative

eager iris
#

okay

sturdy perch
#

(A) sin 300° < sin 350°​(B) cos 300° < cos 350°

  • < -*+ < +

(C) sin 300° < cos 350°​(D) tan 300° < tan 350°

  • < +*- < -

(E) cot 300° < cot 350°

  • < -

Dam didnt reveal anything

eager iris
#

the drawing sucks so hard

sturdy perch
#

ye use the first one

eager iris
#

i have to draw it on paper

#

il show you in a bit

#

i don’t understand the 350 degrees

sturdy perch
#

its 10 degrees lower than 0 degrees

#

almost a full turn

eager iris
#

okay I got it

#

what about tan and cot?

#

I got this rn

sturdy perch
#

when you have cos and sin then its quick to calculate tan and cot

eager iris
#

but it needs to be graphically

sturdy perch
#

here is all the geometrical meanings of the trigonometric functions

eager iris
#

im so confused

#

.close

odd edgeBOT
#
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thorn pecan
#

what i got was

a. 30
b. 14880

but apparently its wrong?

zenith tartan
#

show ur work women lover

thorn pecan
#

i did the calculator stuff on google so im unsure how to exactly show my work 😭

zenith tartan
#

u can explain what u did

cold urchin
#

a is right

nimble blaze
#

it seems you ignored pi for part b)

thorn pecan
#

OH

#

phew

#

.close

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unborn flicker
#

I want a function from 1 to 128, I do not care what is beyond of those values, where 1 is 32 and 128 is 128. I think the linear function shall be good.

unborn flicker
#

It is, probably, something as: "(128-32)/something", yet I do not see what.

void yew
#

hmmmmmm

unborn flicker
#

I see it, I do not see the logic behind.

cold urchin
#

Do you mean like f(1) = 32 and f(128) = 128

unborn flicker
#

If x is 1, y is 32, if x is 128, so is y, in 128 they cross.

cold urchin
#

Wdym they cross

jolly halo
#

so like two seperate functions?

#

f(x) and g(x)
where f(1 ) = 32
g(128 ) = 128

unborn flicker
#

One function, values cross, in that point x is y, beyond that x is probably bigger.

cold urchin
#

What do you mean by values cross and x is y

unborn flicker
#

I just explained.

#

The x probably surpasses y.

jolly halo
#

..

unborn flicker
#

A fucntion has two values, not just one.

jolly halo
unborn flicker
#

I do not know.

jolly halo
#

For x = 1
y = 32
OR f(1) = 32

For x = 128
y= 128
OR f(128 ) = 128

#

and you need this f(x)

#

?

unborn flicker
#

Yes. That is what I want.

#

I did try learning such codes, I failed. I can only read the very basic.

#

If x passes 128, the y passes 96, x is 1,33..., or is y, times greater, I can do it.

jolly halo
#

wait so you need f(128 ) = 96?

#

huh

#

?

unborn flicker
#

No, it is just 96 because it already starts with 32 when other is 1.

#

Bingo. Now just to convert it into actual formula.

#

X/(1+1/3)+32 is the y I want, probably.

cold urchin
#

so you just wanted a straight line that passes through (1,32) and (128,128)

unborn flicker
#

Yes.

jolly halo
#

oh my god.

unborn flicker
#

We solved it.

#

I like El Risittas.

#

Thank you.

cold urchin
#

np

#

lol

jolly halo
#

wow

cold urchin
unborn flicker
#

I think this is called linear function.

#

This is your thank. People in Indo-China, I forgot which land exactly, are collecting, what I remember as lilies.

#

.close

odd edgeBOT
#
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jolly halo
odd edgeBOT
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jolly halo
#

did you get the equation as

odd edgeBOT
unborn flicker
jolly halo
#

.close mb didnt realise i opened a chat

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jolly halo
odd edgeBOT
jolly halo
#

i thought i got this question , i did not.

#

i dont know where to start

#

,rccw

clever fjordBOT
jolly halo
#

(from what i thought i think we can use rolle's theorem but im not sure how exactly)

#

as f prime here would just be linear

chilly epoch
#

Maybe check all the options one by one

jolly halo
#

wont work

#

too many unkowns

#

specially option c bleak

#

cant seem to proof that otherwise too

noble forge
#

look at the discriminant of 3ax^2+2bx+c

chilly epoch
#

D = b²-3ac= a² -ac +c²

noble forge
#

and then the signs of a,b,c

jolly halo
#

we do not know a / b / c it can be anything really

#

unless we get like a perfect square or adition of suares perhaps

chilly epoch
jolly halo
#

we cant say for sure ig

noble forge
chilly epoch
#

For a,c are real

noble forge
#

a>0 and a<0

chilly epoch
#

So option C is incorrect

jolly halo
#

fair

chilly epoch
#

so for option A
Check f(0).f(1)

jolly halo
#

f(0) is c
f( 1) is 3a+2b+c

#

oof

chilly epoch
#

And to make worst there is none of these in options

jolly halo
#

IKR!

chilly epoch
#

Substitute value of c

jolly halo
#

as -a -b?

chilly epoch
#

f(0).f(1)

#

Yeah

jolly halo
#

doesnt do much

#

f(0) = -b-c
f(1) = 2a + b

chilly epoch
#

f(0).f(1)= -(a+b)(2a+b)= -(2a²+3ab+b²)

jolly halo
#

not sure what im looking for here..

chilly epoch
#

Wait

jolly halo
#

what will multiplies them do

chilly epoch
#

I was trying to get expression which is always +ve or -ve

jolly halo
#

ehh

#

not sure what that will do for you tbh

chilly epoch
jolly halo
#

yeah ofc

#

already played with the discriminant a lot

#

im overstimulated

#

the dumb book doesnt have any other similar question

#

the book threw a curve ball right at my face and i had no prep

#

no way

#

no way

jolly halo
#

because i want to check if roots lie in the interval

#

i think i should consider THIS as f'(x)

#

to find f(x) i can just integrate it

#

ax^3+ bx+2 +cx+ C = 0
C-> arbitary constant

#

for f(0 )
we get C
for f(1)
we get a + b + c + C = C ( as a+b+c = 0 )

#

oh everything is fitting so perfectly now

#

and since f(0) = f(1)
fprime should have a root in interval 0 to 1
due to rolle's theorem

#

thanks for trying i think i got the solution , should be A

chilly epoch
#

I have not studied rolle's theorem

jolly halo
#

oops forgot to close the chat

#

np

#

thanks for responding !!!!

#

( also this theorem was mentioned like so behind this question i swear , and no other question used this, had to read everything )

#

.close

odd edgeBOT
#
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rocky edge
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
rocky edge
#

4

#

l composed r = {(a,3), (c,3), (b,1)} ?

#

i'll do r composed l later, just checking l composed r first

crisp wadi
#

You can't define composition of l with r

#

Applying r first gets you an element from {1, 2, 3}, but you need that to be in the domain of l

rocky edge
#

Wht

crisp wadi
crisp wadi
#

r(a) = 1, right?

rocky edge
#

Ye

crisp wadi
#

And is l(1) defined?

rocky edge
#

Na

crisp wadi
#

Neither is $l \circ r$

clever fjordBOT
#

A Lonely Bean

rocky edge
#

Ok thanks

#

.close

odd edgeBOT
#
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spiral frigate
#

$s(f,c)=\left(\floor{\frac{f}{c}}+1\right)\left(c+73-(c\mod{16})+\ceil{\frac{\log_2{c}}{8}}\right)$

clever fjordBOT
spiral frigate
#

for a given f, I want to find the c which produces the minimum s(f,c)

#

is it possible to create a formula that can do that, and how would i go about doing it?

#

right now, I just have some code that brute forces all values for c within a range, but it would be computationally cheaper and more scalable to solve the problem with a formula

#

also - f, c and the output to the function are all natural numbers

sudden ledge
#

no theres no closed form solution for this

#

this is an integer programming problem google that

spiral frigate
spiral frigate
#

I looked up the wikipedia article and it has way too many things I don't understand, I'm not very smart

late dust
#

There seems to be a pretty easy solution to this

#

If f < c then floor(f/c) = 0 and the answer is a constant (if c can't be 0 then the minimum is at c=1)

#

Hm I can't find a way to explain the rest

spiral frigate
# late dust If f < c then floor(f/c) = 0 and the answer is a constant (if c can't be 0 then ...

the problem is about breaking a file down into chunks, where f is the size of the file and c is the size of the chunk, so if the size of the chunk is bigger than the filesize then there will just be one chunk and you can ignore the first bracket. I don't see how the output would be a constant but you only need to consider cases where 1 <= c <= f (or f+15? idk), sorry I should've mentioned that

#

f is the size of the file in bytes, so an integer greater than 0. c is the size of the chunk in bytes, so an integer greater than 0 and less than or equal to the file's size. the function presented in the latex output the size of the file in bytes after you've chunked it, added metadata, etc. so you're trying to use that function to find the optimal chunksize for reducing the size of the output file

spiral frigate
#

or, at the very least, some kind of optimisation for brute forcing, like "only test odd numbers" or something like that (i'm not saying that is something that would work it's just an example)

#

but yeah. a formula. or how to make one because i don't know where to start.

late dust
#

Then it looks to me like c = ceil((f+1)/2) gives the minimum

spiral frigate
#

based on my testing that doesn't seem to work, but I'm curious how you got that

late dust
#

I may have ignored a term KEK

spiral frigate
#

rip

late dust
#

Ok first thing to notice, c - (c mod 16) is just 16*floor(c/16)

spiral frigate
#

h u h

late dust
#

It starts at 0 and jumps up by 16 every 16 units

spiral frigate
#

yeah i just tested it on desmos and it works but i can't wrap my head around why

late dust
#

In [0,15], (c mod 16) is just c

#

So that's c - c = 0

#

In [16, 31]. (c mod 16) is c - 16

#

So that's c - (c - 16) = 16

#

And so on

spiral frigate
#

right

late dust
#

floor(x) jumps by 1 every 1 unit

#

floor(x/n) jumps by 1 every n units

#

Did that clear things up?

spiral frigate
#

i think so?

#

still strange but yeah

late dust
#

ceil(log_2(c)/8) starts at 1 and jumps up by 1 after 256^n where n starts at 1 and is just incremented every time

spiral frigate
#

yeah, it's "how many bytes does it take to represent the integer chunksize"

late dust
#

So let's ignore this term, solve for c < 256 and then try to put it back in

spiral frigate
#

i know it's not the correct way to do things but it's such a small term that it doesn't have much impact, so even if you can solve it without that term, that's better than nothing

late dust
#

Ok, now floor(f/c) + 1 = floor((f+c)/c)

spiral frigate
spiral frigate
late dust
#

Yeah

spiral frigate
#

oh neat

#

i'm really sorry i've gotta go i'll be back in like 30 minutes tops

late dust
#

I probably won't be there in 30 min

#

Close this and open a new channel when you're back if you need

#

I have a feeling the minimum will be something like c = ceil((f+1)/(1+n)) where n = ceil(log_256(c)) or something

#

Otherwise ask for guidance with integer programming

#

I'm not sure I can actually solve this correctly

odd edgeBOT
#

@spiral frigate Has your question been resolved?

odd edgeBOT
#
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hollow wasp
#

When I have this signal, how should I read the values for x[n]?

hollow wasp
south plume
#

wdym how?

hollow wasp
#

is the first value cos(pi/2 *0) ?

south plume
#

yes

#

not sure what u[n] is tho

hollow wasp
#

no idea either

#

but ty for the clarification

#

.close

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#
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coral heath
#

im not sure if this is right

odd edgeBOT
coral heath
leaden widget
#

the 2/3 exponent should be outside the parenthesis for one

coral heath
#

oops

#

but besides that is it right

leaden widget
#

ya

coral heath
#

thanks

#

.close

odd edgeBOT
#
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gilded jewel
#

Question: What does it mean to find the rank of the derivative of a vector-valued function? For context, we recently covered implicit function theorem and rank theorem in my real analysis II class.

tall veldt
#

the derivative will be a matrix, so its just the rank of that matrix

#

or the rank of the matrix at an evaluation at a point rather

odd edgeBOT
#

@gilded jewel Has your question been resolved?

gilded jewel
#

But that doesn't tell me the rank of f' in general

tall veldt
#

you just have to determine a maximal set of linearly independent columns like normal

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mystic saffron
#

I really really need help

odd edgeBOT
lavish jackal
mystic saffron
#

so, I asked my teacher in thursday "wait, how they figured out that if we have a list, and we sum all the values of that list and we divide the output by the number of elements, we get the average?", and she didn't answer... so I am trying to answer that, and I got that the average between two numbers is (x+y)/2, and now trying to do that for 3 numbers, I got (x+y+2z)/4, and I am trying to prove that it is equal to (x+y+z)/3

#

can someone help me with that? I have been strugling with it the whole day ( I am not very good at math, like, I am 14 years old, but I have learned some math by watching 3b1b and other channels )

south plume
#

define average

#

in your context

#

what you are finding is a mean, one of the types of averages

mystic saffron
#

we are studying statistics

south plume
#

yes

mystic saffron
#

like, the average value between a list like [1, 2, 3, 4, 5] ( idk how to write it in math way, I am a programmer :( )

south plume
#

can you see what's wrong with (x+y+2z)/4

#

you are giving bias towards z

mystic saffron
south plume
mystic saffron
#

I know how

#

I want to know why

south plume
#

okay

south plume
#

first condition: the order must not matter

#

so it must be symmetric

#

so no x+y+2z, because that's not symmetric between x y z

mystic saffron
#

mhhh, true

#

but how would I find the mid point? for x and y is easy cuz i just did, c ( the middle between x and y ) is equal to x+d, and I want to know what d is, so the distance between x and y is y-x, and then I want the half of it, so d=(y-x)/2, then c=x+(y-x)/2, that is just c=x+y/2-x/2, and that is c=x/2+y/2 -> c=(x+y)/2

south plume
#

woah

#

first we were doing statistics, now this is geometry

#

but yes, these 2 things are related

#

the arithmetic mean of 2 points' coordinates is their midpoint

mystic saffron
#

wait wait wait, wouldn't the actual avrg3 be something like avrg2(avrg2(x, y) avrg2(y, z))?

south plume
#

nope

#

not associative

mystic saffron
#

cuz we find the middle between x and y, and then between y and z, and we find the middle between those?

south plume
#

not gonna work

mystic saffron
#

I will trust you

#

but now I am just doing trial and error to find what works and trying to see what fails

south plume
#

cuz it again gives bias to a variable

#

arithmetic mean is defined to be sum of series over its length

mystic saffron
#

I started doing this since 9am or smth, now its 9pm, my brain is just hurting

mystic saffron
south plume
#

you can't use combinations of avrg2 to get avrgn

south plume
#

we use it as one of the measures of the average

mystic saffron
#

why if I do number + number ... (n times) / n = average

south plume
#

there's no 1 average

#

there are 3 types

mystic saffron
south plume
#

mean, median and mode

mystic saffron
#

how?

mystic saffron
#

and I asked "but how did people come out with this?"

south plume
#

for example

mystic saffron
south plume
#

the mean * the length of array will be the sum of the whole thing

#

here's a person asking the same thing as you

mystic saffron
#

yay

#

I mean he is asking "Why it works", I want to know "How they come up with it"

#

but I think yeah, the answer of one will answer the other in some way

south plume
#

that's history of math

mystic saffron
#

but how did people just woke up one day and said "wait, if i sum all this things together and I divide that number by the number of things i summed up, I get the """average value""" between the numbers in this thing"

#

what is the thinking you had to do to get that

south plume
#

it's this, finding something that is 'equidistant from others'

mystic saffron
south plume
#

any array size

#

but also again

#

i'm not sure what you want the proof of

#

an "average" of a list is a human invented thing

mystic saffron
#

how they realized it worked for any array size?

#

also, what about an array with no elements inside?

#

that question is dumb but

south plume
mystic saffron
#

I wanted an answer

mystic saffron
south plume
mystic saffron
#

and 0/0 is "undefined" in most fields of math

#

my teacher said "it just works with any list size", and I was going to answer "what about a list with no elements?"

#

but I said "nah, this will lead to nothing"

south plume
#

i see you are a little smartass 13 year old

#

(it's a good thing, keep going)

#

like seriously i wish i was as cool at 13 lol

mystic saffron
#

no way this site is just stackoverflow but with people that know math

south plume
#

yep

#

there's many 'stackoverflow's

mystic saffron
#

damm I hate stackoverflow

south plume
#

all of those are different communities

mystic saffron
#

a site full of smart people that just answer with vague questions or just don't answer at all and just act like they are supperior

south plume
#

i agree

mystic saffron
#

when I started learning programming it was a pain in the ass

#

anyways, now I think I got an answer

#

but

#

mhhh

#

I really need that math lore

#

cuz I just can't see how people come up with tis

#

well, maybe is just like coding, they tried different algorithms at random until they got values they liked and said "this is good to analize this thing" and it stuck around

mystic saffron
#

I really needed that answer, or at least a way of trying to figure it out, I don't have a clear answer, but I can start looking for info

#

and ask the right questions

#

I think this could be a really interesting topic to make a yt video about!"

#

( cuz I didn't find any info while searching there )

#

like those VSauce videos

south plume
#

it does sound interesting

mystic saffron
#

yeah

south plume
#

in any case, if your question has been answered, type .close

mystic saffron
#

and there is no info in spanish either so I could do it in spanish and english ( so I can show it to my nerd friend that likes math )

mystic saffron
#

.close

odd edgeBOT
#
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visual tide
#

Since when in linear algebra are we allowed to add columns to other columns in a matrix like wtf

summer river
#

wouldn't you expect A + (-A) = 0

visual tide
#

i dont understand ur example

#

like ive never seen in my life someone doing column operations

#

how is that even legal

visual tide
summer river
#

and you will see that if they have the same two columns

#

then det(A) = 0

#

ex the determinant of this is 0

#

so you can safely subtract a column from one to another and add one to another

#

and get the same determinant

visual tide
#

ok but that only works cuz detA = 0?

summer river
visual tide
#

k but thats whats confusing

#

like in linear equations u cant just add an x column to a y column

#

yk? 😭

latent scaffold
#

Well the determinant of the transpose is the same yes?

#

And the rows of the transpose are the columns of the original one

summer river
#

and that if there is a repeat column

#

you find that the determinant is zero

#

let me write it out if you really want

#

but I have to whip out my notebook

visual tide
#

ok

summer river
#

and take out my notebook

#

and send a pic to you?

visual tide
#

yes pls

#

so like we can just alternate between row and column operations on the same matrix with no problems?

#

that seems rly weird to me

summer river
#

pls don't use my handwriting for forgery or anything

visual tide
#

um i wont

latent scaffold
#

nosqldb probably has a good example coming. To me it seems like you're confusing row reducing and determinant computation. Row reducing forces you to only do operations on rows because it represents the simplification of linear equations. You don't have this restriction on determinants as they represent a scaling factor of a unit n-cube.

visual tide
#

so its only for determinants we can do row operations?

#

i mean

#

colum

#

column operations

summer river
#

since

#

det(A) = det(A^T)

#

my example will give an intuitive explanation on why you can do column operations

#

but a precursor, if a matrix A has two identical columns, then det(A) = 0

#

if you want the proof for that lmk

visual tide
#

is the proof for that cuz theres gonna be a column of 0 when reduced

#

so the det would be 0 because the diagonal has a 0

summer river
visual tide
#

oh

#

wait

summer river
#

but notice that you get the same matrix if you change the columns that are equal

#

so

#

let det(A) = b

#

then $b = -b \implies b = 0$

clever fjordBOT
#

nosqldb

summer river
#

bc it's a real matrix

visual tide
#

ohh

#

thats smart

summer river
#

again don't forge

#

I sent the example

visual tide
#

um why r u allowed to add them like that

summer river
#

and you will see

visual tide
#

what does expand along the column mean

summer river
visual tide
#

no

summer river
#

@latent scaffold do you wish to explain

visual tide
#

this is introductory linear algebra 💀

summer river
#

I thought this was a common topic

visual tide
#

oh 😭

#

nah like the low low linear algebra

#

.close

odd edgeBOT
#
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old whale
#

How do you prove that e^x > x^n

odd edgeBOT
old whale
#

For x -> infinity

#

n is any number

latent scaffold
#

You can show their ratio goes to infinity for large x

odd edgeBOT
#

@old whale Has your question been resolved?

odd edgeBOT
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distant tartan
odd edgeBOT
distant tartan
#

how do I integrate this if I dont know what the function is?

upbeat drum
#

u sub

#

f'(x) in the integral serves a clue

odd edgeBOT
#

@distant tartan Has your question been resolved?

odd edgeBOT
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gleaming dew
#

I= integrate (cos^2023 x) dx from 0 to 2pi |

upbeat drum
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
upbeat drum
#

(change bounds to use even/odd function properties)

odd edgeBOT
#

@gleaming dew Has your question been resolved?

quasi sparrow
#

@gleaming dew did you understand the hint

odd edgeBOT
#

@gleaming dew Has your question been resolved?

gleaming dew
#

I'm really grateful

quasi sparrow
gleaming dew
#

This is it, right?

#

help me pls

#

or this

odd edgeBOT
#
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lethal gale
#

What’s the formula to the Pythagorean theorem?

blissful musk
#

a^2+b^2=c^2

mint mirage
lethal gale
#

Oh

#

I’m on the Percy’s

#

*percs

odd edgeBOT
#

@lethal gale Has your question been resolved?

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lethal gale
#

Yesss

odd edgeBOT
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drifting edge
odd edgeBOT
#

@drifting edge Has your question been resolved?

drifting edge
#

.close

odd edgeBOT
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ruby nacelle
#

i am stuck on c, i dont know how can i use part a to help me

ruby nacelle
sharp oak
#

Maybe not useful, but note sin(π/10) = sin(9π/10)

ruby nacelle
#

oh, that might be useful

#

i can sub 3pi/10 = x

#

but what about part a?

sharp oak
#

We will get a polynomial from this process, I'm sure a is useful

#

I would instead consider x = π/10. However, I have not actually tried this yet so take me with a grain of salt.

odd edgeBOT
#

@ruby nacelle Has your question been resolved?

odd edgeBOT
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spiral atlas
odd edgeBOT
spiral atlas
#

im going crazy over this one

#

solve for x

round bone
#

Distribution

#

Or just test square numbers

#

You want x to be square and x+5 to be square

#

Nvm

formal ermine
#

i would expand this first

#

then you can probably do a substitution where a = root(x) and solve from there (may not be exactly root(x))

noble forge
#

That may not make this problem a piece of cake but definitely should help in some simplification

toxic monolith
#

$\left( \sqrt{x+5}-\sqrt{x} \right)\left( 1+\sqrt{x^{2}+5x}\right)=5\\\text{ Let's note that the domain of the equation is }[0,\infty )\text{ then we get that: }\\\frac{5\left( 1+\sqrt{x^{2}+5x} \right)}{\sqrt{x+5}+\sqrt{x}}=5<=>1+\sqrt{x^{2}+5x}=\sqrt{x+5}+\sqrt{x}\\<=>\sqrt{x+5}\left(\sqrt{x}-1 \right)-\left( \sqrt{x}-1 \right)=0<=>\left( \sqrt{x}-1 \right)\left( \sqrt{x+5}-1 \right)=0\\<=>x = 1 \vee x=-4\text{, but }x\geqslant 0\text{. then solution is: }x=1$

clever fjordBOT
#

Joanna Angel

noble forge
#

well aren't you providing the entire solution to just be copied by the OP

toxic monolith
#

well, i have just decided to show solution, since it is tricky, little bit

noble forge
#

but yeah you did a good observation at STEP 1
(derationalizing sqrt(x+5)-sqrt(x))

toxic monolith
#

yes, wanted to avoid gettign polynomials of he vry high degrees

odd edgeBOT
#

@spiral atlas Has your question been resolved?

spiral atlas
#

yo im back

spiral atlas
#

how about this, i found an existing solution but there a part in it that i dont understand

toxic monolith
#

i made solution shorter to decrease number of liens ) but ask

spiral atlas
#

lemme find it

toxic monolith
#

solution is x = 1, you can easily verify it

#

first i have applied Conjugate (square roots)

#

because i have noticed also that number 5 wil be reduced

spiral atlas
#

nvm i get the whole thing

toxic monolith
#

cool

#

is it high scol or colege ?

spiral atlas
#

high school

#

but technically its middle school as in my place we still consider 9th grade to be middle

toxic monolith
#

i see, i am trying to compare to our schools, but ok

#

irrational euqations, reuqire knowledge of many tricks

#

and mslty they are not pleasant )

spiral atlas
#

ye

#

.close

odd edgeBOT
#
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odd edgeBOT
#
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ruby nacelle
odd edgeBOT
ruby nacelle
#

i dont know what to do next

#

and also idk how to use the results of part a

#

how is part a useful

zenith tartan
#

can u just post the pic of the question agani please? @ruby nacelle