#help-19
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set LHS to your initial definition of $a_n$: $a_n=2^n+5\cdot3^n$
artemetra
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OPTIMIZATION PROBLEM
An offshore oil well is located 2km from the coast. The refinery is 4 kilometers down the coast. Installing the pipeline in the ocean is twice as expensive as on land. What path should the pipeline follow to minimize the cost?
Something like that, pls HELP
@zealous basin Has your question been resolved?
trajectory
sorry can't be of much help on this one
ok
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<@&286206848099549185>
@zealous basin Has your question been resolved?
Hello
This is calculus, right?
Start by setting some variable x
What distance in this problem should be x? 🤔
yeah this diagram is much better to see which variable defines a path
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I believe your first step is wrong. It seems like you just moved the inverse to the right but idk any rule that would let you do that
Yea im wasnt sure on how to even start this qeustion
i just assumed that adding an inverse on both sides
would cancel the inverse on the left side
how would you begin to remove hte inverse?
$AA^{-1}=A^{-1}A=I$
Haruno Haruka
No you kinda had the right idea before. You want to cancel out the entire left side. To cancel out (A^T+2I)^-1 we want to turn it into the identity matrix by multiplying it by (A^T+2I) (either side is fine in this case)
then from there you can solve for A
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If u and v are linearly independent vectors and S is a set where x is orthogonal to at least u or v, what would that set look like?
Would it just be the zero vector?
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I am currently trying to understand when a 1-form w = Σ w_i dx_i is exact.
I understand that the equation in the picture is sufficient enough. However does this need to work for any combination of i and j? so even if i = j?
well if i=j then both sides are the same
true. Okay makes sense. How would i integrate a 1 form if it is exact?
Just write an integral infront without differentials?
$\int w$
derdotte
basically?
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I am confused regarding how to answer this.
If f'(x) and g'(x) exist and f'(x)>g'(x) for all real x, then the graph of y=f(x) and the graph of y=g(x)
A. intersect exactly once
B. intersect no more than once
C. do not intersect
D. could intersect more than once
E. Have a common tangent at each point of intersection
What do you think?
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I am confused regarding how to answer this.
If f'(x) and g'(x) exist and f'(x)>g'(x) for all real x, then the graph of y=f(x) and the graph of y=g(x)
A. intersect exactly once
B. intersect no more than once
C. do not intersect
D. could intersect more than once
E. Have a common tangent at each point of intersection
I'm thinking C because one is always growing bigger than the other.
What does it mean that f'(x) > g'(x) for every valid x, what does that mean for their antiderivatives F and G
well yes this
Now try to visualize this with some random function, could you move those functions around to force them to intersect?
I haven't learned antiderivatives.
Sure, by adding x/y offsets.
Then you don't know that they won't ever intersect
for any given pair of functions f and g
the antiderivatives are just f and g before derivation btw
Shouldn't have used that word in this context tbh, my bad. Better formulation is what it means for f(x) and g(x)
The fact that f always grows faster than g means that it could intersect g given that it "starts" below g
So F can catch up to G, but G can never catch up to F
Is this making sense?
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I feel like I may not be understanding level surfaces
This seems too simple of an explanation to be right
Can somebody tell me if this is completely wrong and give me a little help?
Both 3 and 4
f(x,y,z) is not a line though
What would it be?
In 3D f gives each point in space a scalar value
and In 4D It is a 3D object embedded in 4D
This graph above makes sense for this
no that's completely wrong
Oh lol
When I tried to graphed x + 5y + 3z it gave me an error
well you need 4 dimensions to graph it
I don’t understand
you have 3 variables x,y,z
and you need a extra dimension for f
so you need 4 dimensions
like when you have f(x)=something
you need 1 dimension for x and 1 dimension for f(X)
Right
So how would I enter that into the calculator? I’d assume f(x, y, z) would be that dimension then
f(x, y) = z
??
a level curve is when the function equal some constant
oh I meant level surface mb
so f(x,y,z)=a where a is some constant
So you’d set x + 5y + 3z equal to any constant?
Like just 1
yes then you get a level surface
and this time it is a plane
also slight issue with Q3. f(x,y)=x^2+y^2 is not a circle, rather the level curves are.
Ah, yeah this makes sense now working through 4
I was initially under the impression f(x, y) is 2d and f(x, y, z) is 3d
Idk how I’m 7 weeks into calc3 lol
you need to work on your geometric understanding lol
umm no
Duck
Looks like a missile
Oooo ok so any level curve of the inside would have to be a circle
Cause like well it’s a missile
So any specific 2d part of it would be a circle
correct
So any level curves would be circles with radius of sqrt(k) ?
sqrt(k)?
Bruh isn’t this what I said earlier?
I was confused about what's k
I switched a to k cause it’s what we use in class mbmb
So for it to not be centered at the origin wouldn’t it be k = (x^2 + 1) + (y^2 + 1)
yea you are correct about that
How does this look?
I mean you should explain what k is on your work
Maybe I’m a little confused on what k is?
I thought it was just a constant for the equation?
that's basically it
you should add something like "for the level curve f(x,y)=k, ..."
Okay, done. Gonna work a bit on 4 now.
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can u guya hwlp mw
Its about Synthetic Division and I'm trouble to know the divisor
How can I turn 2x²+3 to be a divisor for 4x⁵ + 6x⁴ + 5x² - x - 10?
(This is synthetic division and I'm aware of the missing terms)
This is so disgusting, i hate math
<@&286206848099549185> plz help
yee yee ass server
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Where does my mistake lie here?
Im pretty sure this is wrong somewhere but I don’t know where
<@&286206848099549185>
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Regarding Russell's paradox
We have that R = {X | X not in X} and the paradox is R in R <==> R not in R.
What does X not in X really mean though?
Wouldn't e.g. the set {1} be a possible candidate for X?
Does a set that has the property X in X even exist?
sure
It needs to be some never-ending one
yeah I mean sure as in "I can write something down but that's why it's a paradox"
But isn't R in R just a false statement then?
Why must R be in R
oh, alright
Though, still, why must R be in R?
Or must it be not, it's just an assumption?
Look up axiom of regularity, it has been introduced in order to avoid paradoxes like these
I'd first like to find the intuition behind Russell's paradox though
We begin with the principle of no middle, one of these must be true: X is in X or X is not in X
Yeah
If X is in X, then it must satisfy the property that it has for its elements
Meaning X should not be in X
For X to be an element of X
But that's a contradiction
Alright then, let's now look at the case if X is not in X
If X is not in X, then X is in X by the definition of X
Which is also a contradiction
Wait
Sorry I meant to say R instead of X
If R is in R; then it satisfies the property for its elements X that (X not in X).
But why does that mean R should not be in R?
Then yeah
So, if R is in R, then we must have R is not in R
If R is in R, then it's some set X not in X
Oh
Thank you!
How does the barber paradox follow out of this?
You can define the barber as ‘one who shaves all those, and those only, who do not shave themselves.’ The question is, does the barber shave himself?
If the barber shaves himself, then he shaves someone who shaves himself. A contradiction
If the barber doesn't shave himself, then no one is shaving him, so he must shave himself (since he shaves everyone who don't shave themselves). Contradiction.
Sounds like a similar thing to Russel's paradox
Yeah it looks almost the same
But without abstract concepts like sets lol
We can't directly translate the barber as R or something though right?
Or X in X as "X shaves X"
Do you mean we can translate X in X as "X shaves X" or not?
To provide an analogy, yes
Ah, yeah, seems like that would work approximately, lol
Thanks
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explain this part please
$\frac{1}{5+2\sqrt{6}} = 5 - 2 \sqrt{6}$ by rationalising the denominator
Frog_Man
Please explain in more detail
$\frac{1}{5+2\sqrt{6}} = \frac{5-2\sqrt{6}}{(5+2\sqrt{6})(5-2\sqrt{6})} = \frac{5-2\sqrt{6}}{5^2 - (2\sqrt{6})^2} = \frac{5-2\sqrt{6}}{1} = 5 - 2 \sqrt{6}$
Frog_Man
this means that $\frac{1}{t} = \frac{1}{(\sqrt{5+2\sqrt{6}})^x} = \left(\sqrt{\frac{1}{5+2\sqrt{6}}}\right)^x = (\sqrt{5-2\sqrt{6}})^x$
Frog_Man
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3³+3⁴+3⁵ = 3³(1+2+3²)
Where do you like get 3³(1+2+3²)
uh that's wrong
I don't know good English but what does faktorise mean
Is it not right?
it's a typo
yes
Yeah how do you get from 3³+3⁴+3⁵ = 3³(133²??
Hmm okay ill try
multiply by 3³ and you get 3³(1+2+3²)
r 3³+3⁴+3⁵ / 3³?
Like that?
I still don't understand
I understand that but I don't understand how to get 3³(1+2+3²)
From that
I haven't learned algebra in school yet. Does this question need algebra?
My teacher says if I somehow show how to get 3³(1+2+3²) it's like A
Okay so I just follow that formula?
Is there any way to do it another way without algebra? Or no
Okay whatever
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looks right
Do you know what happens when you have a power to the power of something?
Laws of indices ^^
So for eg: what happens when you do (2^2)^2?
uhh
remind me ig
You multiply the powers
yes
then?
If when you have a power to a power you multiply
Then in this case we also multiply
Hence the answer would be?
uhm i don't follow
Are we alright with this?
yes we are
When you have a power on top of another power you multiply the powers
Similarly in this case we have a power on top of another power
we multiple 2/3 with 6
which is 4 right
yep which is 4
Mhm
so it will be 6 with exponet 4
Yh
i think you might be
i searched online as well i came across this
but i think im supposed to write it with radicals
so i tried coming here for
addtional help
Hm
but the question was asking for the 6^2 / 9 specifically i think
it's a weird one
share
Cassandra is saying 6^(6^2/3)
So this
They’ve typed it out weirdly
And hence
But we know the correct exponent is actually 12/3 = 4
In other words how can we change the 6^2/3 to make it into 4
Or how can we change 36/3 to make it = 4
@mystic saffron
ah yes
9?
mmm makes sense
That’s how we change it or what we replace with what Cassandra did
Hence the exponent 6^2/3 needs to be replaced with 6^2/9
Apologies if it’s confused you but it was typed out very weirdly
yeah i think it was a trick question
i do understand it now tho so that's all that matters
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@oblique jasper How many sides and angles does it tell you are congruent?
idk tbh
how many sides and angles are rhe same amoung both triangles
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A car is traveling at a speed of 80 km/h towards a 30-story building. Each story of the building is 5 m high. A fragment of the building breaks off from the top and falls to the ground. How much does the car need to decelerate to reach the building 2 to 5 cm before the fragment hits the ground?
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have gradient, just need help with b, finding the angle
[3:46 PM]
We know that the gradient is the vector that points in the direction of maximum increase
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Im not sure what to do for the next step here
Im using implicit differentiation to find dy/dx
you needed to use the product rule
Keep in mind that y also has an x-dependence
Ohh
but after youve corrected that - the next step is to make dy/dx the subject, which you can do by rearranging and factoring
Okay let me do the work and make sure i did it right
Should be right now, right?
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I've never understand the why behind this
can anyone explain why p is inside and q is outside
i mean like
why is it not
sqrtp A^q
how is it simplified to the RHS
@merry finch
It doesn't matter if you put the p outside and q inside, for positive reals anyway
Tushar
If you're including negative reals, then this question is scary and I don't like it.
Are you asking why it's the qth root rather than the pth root, or are you asking why we can write the root and exponent in any order (for positive A)?
@mystic saffron Has your question been resolved?
can u give me the latex code u use
for this
actually nvm
i have it
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We have a chemistry server in #old-network
Can you reverse engineer the formula to isolate [H+]?
wdym
We have pH=-log[H+], right?
That [H+] is the concentration of hydrogen ions
You’re given the pH
So you need to solve for [H+]
Does that make sense
You can do this ye
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xNiden
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.reopen
✅
@last kindle Has your question been resolved?
@last kindle Has your question been resolved?
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ok so i got
-1.36538313756
but it was wrong
so we derive cos(2x) right
= -2sin(2x)
plug in pi/6
cos(pi/3)
that gives the slope
-1.73205080756 (this is the slope i found)
then put it into the y - f(a) = m(x-a) formula
so what did i do wrong
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help mee
Lol
im dum
my brother in christ you know how to solve this
i know its 1/4 but it says wrong
its not 1/4
i know
whats the rise, and whats the run?
really? the rise is 1? I dont see the graph going up at all
it goes up 1 unit for every 4 across it goes?
The slope is going down
HOLY CRAP
I QUIT MATH
WOW
-1/4
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@grizzled tide can u help me rq
so -1/4 right
Ya
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a/b+c +b/c+d + c/d+e + d/e+a + e/ a+b > 5/2
@shell sorrel Has your question been resolved?
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i have a problem when the solution is provided, but i don't understand the solution
#14
the screenshot is the solution
can someone explain how the test makers made the equation?
to be more specific, i'm talking about the equations for the series
(-4k-1)^2 + (4k+1)^2 and (-4k)^2 + (4k+2)^2
<@&286206848099549185>
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Say I have the equation 2x = 10 mod 23, I've checked the multiplicative inverse of 2 mod 23 is 12, so x = (2^-1)*10 = 12*10 = 5 mod 23
My question is, does the 'natural' way of simplifying directly 2x = 10 into x = 5 work in all cases ? Or does it fail sometimes ?
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How do i even start w this question
like 2x+y = 6 and x^2 = 9 when x = 3, y = 0, so is it just the question?
i don't even know if im supposed to do chain rule
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When do I have to put a parenthesis when inserting a value and when do I not?
I often mess this up and it leads to the entire question being wrong so what's the rule for this?
E.g. say I have a tangent equation with f'(u)*(x-u)+f(u)
And I want to put in -4u+3 for f'(U) ans -2u^2+3u+10 for f(U)
Where do I put a parenthesis and why?
you always put parenthesis around the entire thing you plug in
if its just a single number then this doesnt really matter so many people dont actually write the parenthesis down in that case
Hm
So here I'd do (-4u+3)*(x-u)+(-2u^2+3u+10)?
yes
Thank you
How about when it's a chain function?
Or actually rather
if it's u(x)*v(x)
Do I then do [(u'(x) * v(x))+(u(x) * v'(x))]
<@&286206848099549185>
do you mean if you want to plug (u(x)v(x))' into some other thing? yes
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Yep
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What happened here?
where did it come from?
is it like derivative of a power series?
also why did they differentiate it?
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can someone explain how they got h(X) to me
I only know that 1000X is the revenue function
but getting the rest, I have no idea how
no
1000X + 200(3-X) is the revenue
there's X computers you sell normally for $1k
why is 200(3-x) part of the revenue?
the remaining computers (3-X) are regiven to the manufacturer for $200
that's where the 200(3-X) comes from
your store makes back some money with the unsold computers
@austere rover
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Hello, Im having trouble with a problem: A number has 30 digits all of which are 0 or 6. can it be a square? I got that it has to end in an even number of zeroes and start with a 6.
if n ends with 10^2k, then 10^2k|n => n/10^2k is a square
and it clearly wont be cuz it ends with 6 and other digits are 0
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I need help with 9b (i) and (ii)
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if i put a 2x2 matrix in row echelon form, is that basically just the 2nd row becomes 00 and the first row remains the same?
the second row should be of the form [0, c] where c is some number (maybe zero, maybe not)
and the first row should be of the form [a, b] where a is nonzero
that's assuming that the first column contains a nonzero number
otherwise the first row will be of the form [0,a] where a is some number (maybe zero, maybe not) and the second row is [0,0]
so it's just the bottom left value that needs to become 0?
yes
more precisely, the rules are:
the first nonzero entry in any given row has to be to the right of the first nonzero entry in all the rows above it
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why does theta = 30?
theta is the angle ABD, and there's a theorem about angles inside circles (don't know the english name, look in your lesson) which says it's half the angle AOD
but since AOD is equilateral, each angle, including angle AOD, is 60°
so ABD, which is half of that, is 30°
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Maybe I'm misunderstanding these
i need help with math
Sorry this channel's in use
kay sorry
I thought that the arrows were put in phase diagrams and their direction was based on whether du/dx was positive or negative before/after that point
But with sinx it'd have positive and negative?
sinu
?
from 0 to pi sin u is positive and from pi to 2pi sin u is negative
what's the issue here
Oh my lord. I'm so sorry.
thus right arrow between 0 and pi and left arrow between pi and 2pi
np
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hi
if
3|2n+1 and 7|n-2
how many 2-digit n exist
I tried multiplying both sides or at some points right side by something but I could not find the answer
but I know it's easier to solve it with mod
but idk how to
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Resolve x in the interval [0;2pi]
Knowing that:
2cos(x)+sin(x)>1
Help needed once again ;-;
(Ping me)
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I am supposed to simplify: (1/cosx) + tanx)(1/cosx) - tanx). and i am wondering if (1/cosx) - (sinx/cosx) will become 1-sinx/cosx or cosx/cosx. i say this because i don't know if 1-sinx becomes cosx in the same way 1-sin²x = cos²x
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Hey
Wanted some help on this
I know how to know if y is a function of X with coordinates but not sure how to otherwise
Could yall help me?
Wdym "with coordinates"?
Do you know what are the conditions that allow y to be a function of x?
@jovial cape Has your question been resolved?
If each input has 1 output
There was a similar question on the homework that used coordinates
Yeah that's correct
Like when it comes to the very first option do you think that it is a function or not?
no
because there is 2 variables
or am i wrong?
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After doing all this how do i find the point c?
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hello can someone help me with this
xd
i got to this
-cot^2x times secx - secx + 2
i was thinking about factoring out secx like this
secx(-cot^x -1 but idk what to do with the +2
u did well by factoring out sec(x) on the left hand side, u can do the same with 2 on the right hand side as well before u bring anything over
well no lets do it differently
u can start off by bringing everything on the left hand side, then from (cotx)^2*secx-secx u can factor out a secx, from the 2-2(cotx)^2 u can factor out a -2, and then youll see that u have another common factor (cotx)^2-1
so now you can factor that one out as well and then youll have a multiplication equal to 0, so youll just set each of the parts equal to 0
hmm one sec let me work it out that way
i dont get this part
//u can factor out a secx, from the 2-2(cotx)^2
no yeah u factor out a secx from the expression before that part of the message, and from the next expression youll factor out a -2
like this
slightly different order on my notebook, but the idea remains the same
i just factored out a 2
yup
nw!
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I have I think a simple multivar question
If im looking at two curves $$x^2 - y^2 = a^2$$ and $$xy=a$$, whats the process to showing that these two curves will always be orthogonal at a point of intersection?
jan Niku
You can show that one of them is the orthogonal trajectory of the other
obtain the differential equation to one curve, replace dy/dx with -dx/dy, and integrate once more
how do you mean? implicitly differentiate?
i have to apologize my multivar is horrible
I don't know any multivar, but what you're looking for is an orthogonal trajectory
yeah
im not sure i understand the process youre describing
why does this show what we want to show
you could skip the integration process
take the derivative of both and show the product of the gradients is -1
I'm unaware of a proof of this fact myself if that's what you wish for
taking the using implicit differentiation ?
assume ive never taken calc iii
do i just work with the LHS of each of these in constructing the gradient?
yes
the rhs would become 0 in both cases
for example the first one would become 2x dx - 2y dy = 0
i want to understand it because i need to write about it
its the motivation for a method of approximation of integrals
so i need to understand it
but i never took multivar 😳
dont need anything gradient vector based I think
i dont think this process gives the result we want here, if i did it right
but isnt the gradient defined as a vector?
I suppose so
how does whatever the process youre describing work out?
oh wait
i think i see
so in the one youd have $$2x-2yy'=0$$
jan Niku
and the other $y+xy'=0$
jan Niku
product in what sense?
how do you know
oh lawd , you're testing my fundamentals ;-;
oh, wait
i think i got you
@hard field okay so the products are negative 1
this would be like
this makes more sense to me geometrically than any math proof
their isnt much of a surface here
and we just rely on like negative reciprocal
negative reciprocal means perpendicular
i think i getchu
just a ~~ circle~~ BOWL THING extended through z I guess
a circle 
MY BAD
yes
I think this makes sense to me
at least
okay
i can learn more later
i do think you need to use vectors
taking the gradient of an equation doesnt make sense to me though
how do you get a gradient involved with a level set
Im not much use to you for fundamental questions I think, I only learnt general n dimensional gradient vectors weeks ago :D
would it really just be like x^2-y^2 = a^2 -> <2x, -2y>?
and then the other is
<y, x>
so 2xy-2yx 
okay
resolved
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yes
thanks @hard field
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line that divides a line or an angle into two equivalent parts
so 124 divided by 2
=62
yup
again, BD is a bisector
what does that tell us about the two angles marked on the photo
that it is half
ABD is 4x+4 and DBC is 6x-14 right?
yes
they have to equal the same thing
I did this but I dont think it is right
I looked it up and google said 9
Which is correct ?
each = 40
How do I do this ?
<@&286206848099549185>
@viscid sage Has your question been resolved?
Angle bisector means it splits it into two equal angles
If QS was the angle bisector than m<PQS=m<RQS
so they are both 75 ?
Well we know PQS is 35
Correct
So is it possible for RQS to be 35
no
is the bisector 70
Yeah if the large angle was 70 then QS would be an angle bisector
So let me phrase it like this
QS is an angle bisector if and only if the large angle is 70
I said it is true because it is in the middle idk if that is correct
And is the large angle 70
Yeah
Do you know the midpoint formula
x1 x2 y1 y2?
which one do I label first ?
(B/2, (a-4)/2) = (-5,-4)
Wdym
The formula formula says
The coordinates of the midpoint are
((X1+x2)/2,(y1+y2)/2)
No
First of all the y coordinate is always the one on the right
So (0,-4) would be x1,y1
And -5,-4 are the coordinates of the midpoint
Which are calculated using this^
No
X2 and y2 are unknown
They are what we are trying to solve for
But we know the midpoint
So we know this is equal to (-5,-4)
So if we plug in x1 and y1 we can solve for x2 and y2
I dont understand the equation
Ok so
the midpoint is always ((x1+x2)/2, (y1+y2)/2) right
yes
and they also tell us that the midpont is (-5,-4)
yes
so (-5,-4) = ((x1+x2)/2, (y1+y2)/2)
this is saying that two points are equal
but for two points to be equal they need to have the same x and y values
so we can split this into two equations
-5 = (x1+x2)/2
-4 = (y1+y2)/2
we know x1 is 0 and y1 is -4
can you solve from there?
no
theres no commas anymore
so we would have -5 = (0+x2)/2 right
and -4 = (-4+y2)/2
so how do we solve for x2 in the equation
-4 dividedd by 2 ?
use this equation: -5 = (0+x2)/2
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this would be false right
because
1 2 | 3
1 1 | 1
1 2 | 1
1 2 | 3
0 -1 | -2
0 0 | -2
last row is 0 0 | -2 so it has no solutions
right
yeah sure
alr ty and one more question identity matrix dimensions are always Z x Z where Z can be any natural number right
so 2 x 2, 3x3 , 4x4 but 4x5 wont be possible
it has to be the same
that certainly is a choice of letter for denoting an arbitrary natural number
but yes identity matrices are always square.
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Hi, so I have this trig equation: sinx + cosx = 1, when I square both sides I get some wrong result but when I multiply both sides by sqrt(2)/2 I get the correct result and I don't understand why
post your original quesetion @bold egret
Find roots of sinx + cosx = 1 that belong to the interval [0, 2pi]
When I square both sides I get a wrong answer