#help-19

1 messages · Page 18 of 1

odd edgeBOT
south plume
#

set LHS to your initial definition of $a_n$: $a_n=2^n+5\cdot3^n$

clever fjordBOT
#

artemetra

lone zinc
#

.close

odd edgeBOT
#
Channel closed

Closed by @lone zinc

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

zealous basin
#

OPTIMIZATION PROBLEM

An offshore oil well is located 2km from the coast. The refinery is 4 kilometers down the coast. Installing the pipeline in the ocean is twice as expensive as on land. What path should the pipeline follow to minimize the cost?

zealous basin
#

Something like that, pls HELP

odd edgeBOT
#

@zealous basin Has your question been resolved?

inner tulip
#

what do you mean by "path"

#

can it be any shape, or a series of lines?

zealous basin
zealous basin
#

like purple line

inner tulip
#

sorry can't be of much help on this one

zealous basin
#

ok

odd edgeBOT
#

@zealous basin Has your question been resolved?

zealous basin
#

<@&286206848099549185>

odd edgeBOT
#

@zealous basin Has your question been resolved?

exotic lance
#

This is calculus, right?

#

Start by setting some variable x

#

What distance in this problem should be x? 🤔

exotic lance
# zealous basin

yeah this diagram is much better to see which variable defines a path

odd edgeBOT
#

@zealous basin Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

river yacht
odd edgeBOT
river yacht
#

Is this the right process to solving this type of question?

fair prism
river yacht
#

Yea im wasnt sure on how to even start this qeustion

#

i just assumed that adding an inverse on both sides

#

would cancel the inverse on the left side

#

how would you begin to remove hte inverse?

fair prism
#

$AA^{-1}=A^{-1}A=I$

clever fjordBOT
#

Haruno Haruka

river yacht
#

something like this?

#

@fair prism sorry for the ping

fair prism
# river yacht <@280588750373912576> sorry for the ping

No you kinda had the right idea before. You want to cancel out the entire left side. To cancel out (A^T+2I)^-1 we want to turn it into the identity matrix by multiplying it by (A^T+2I) (either side is fine in this case)

#

then from there you can solve for A

odd edgeBOT
#

@river yacht Has your question been resolved?

#
Channel closed

Closed by @river yacht

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

odd edgeBOT
#

@celest bay Has your question been resolved?

odd edgeBOT
#

@celest bay Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

modest bronze
#

If u and v are linearly independent vectors and S is a set where x is orthogonal to at least u or v, what would that set look like?

modest bronze
#

Would it just be the zero vector?

odd edgeBOT
#

@modest bronze Has your question been resolved?

odd edgeBOT
#

@modest bronze Has your question been resolved?

odd edgeBOT
#

@modest bronze Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

full blade
#

I am currently trying to understand when a 1-form w = Σ w_i dx_i is exact.
I understand that the equation in the picture is sufficient enough. However does this need to work for any combination of i and j? so even if i = j?

low locust
#

well if i=j then both sides are the same

full blade
#

true. Okay makes sense. How would i integrate a 1 form if it is exact?
Just write an integral infront without differentials?

#

$\int w$

clever fjordBOT
#

derdotte

full blade
#

basically?

odd edgeBOT
#

@full blade Has your question been resolved?

odd edgeBOT
#

@full blade Has your question been resolved?

#
Channel closed

Closed by @full blade

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fair snow
#

I am confused regarding how to answer this.

If f'(x) and g'(x) exist and f'(x)>g'(x) for all real x, then the graph of y=f(x) and the graph of y=g(x)
A. intersect exactly once
B. intersect no more than once
C. do not intersect
D. could intersect more than once
E. Have a common tangent at each point of intersection

odd edgeBOT
#

@fair snow Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fair snow
#

I am confused regarding how to answer this.

If f'(x) and g'(x) exist and f'(x)>g'(x) for all real x, then the graph of y=f(x) and the graph of y=g(x)
A. intersect exactly once
B. intersect no more than once
C. do not intersect
D. could intersect more than once
E. Have a common tangent at each point of intersection

fair snow
zenith edge
#

What does it mean that f'(x) > g'(x) for every valid x, what does that mean for their antiderivatives F and G

zenith edge
#

Now try to visualize this with some random function, could you move those functions around to force them to intersect?

fair snow
#

I haven't learned antiderivatives.

zenith edge
#

Then you don't know that they won't ever intersect

#

for any given pair of functions f and g

#

the antiderivatives are just f and g before derivation btw

#

Shouldn't have used that word in this context tbh, my bad. Better formulation is what it means for f(x) and g(x)

#

The fact that f always grows faster than g means that it could intersect g given that it "starts" below g

#

So F can catch up to G, but G can never catch up to F

#

Is this making sense?

odd edgeBOT
#

@fair snow Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dim thorn
odd edgeBOT
dim thorn
#

I feel like I may not be understanding level surfaces

#

This seems too simple of an explanation to be right

#

Can somebody tell me if this is completely wrong and give me a little help?

#

Both 3 and 4

tardy lagoon
#

f(x,y,z) is not a line though

dim thorn
tardy lagoon
#

In 3D f gives each point in space a scalar value

#

and In 4D It is a 3D object embedded in 4D

dim thorn
dim thorn
tardy lagoon
#

no that's completely wrong

dim thorn
#

Oh lol

tardy lagoon
#

in this graph it shows z(x,y)=-(x+5y)/3

#

not f(x,y,z)=x+5y+3z

dim thorn
#

When I tried to graphed x + 5y + 3z it gave me an error

tardy lagoon
#

well you need 4 dimensions to graph it

dim thorn
tardy lagoon
#

you have 3 variables x,y,z

#

and you need a extra dimension for f

#

so you need 4 dimensions

#

like when you have f(x)=something

#

you need 1 dimension for x and 1 dimension for f(X)

dim thorn
#

So how would I enter that into the calculator? I’d assume f(x, y, z) would be that dimension then

tardy lagoon
#

well It's hard to draw a 4D graph

#

I doubt your calculator can do that

dim thorn
#

Ah

#

True

#

So I guess not looking at the graph, how would I look at this question?

old gull
tardy lagoon
#

what's the equation of the level curve?

#

of some level a

dim thorn
tardy lagoon
#

??

#

a level curve is when the function equal some constant

#

oh I meant level surface mb

#

so f(x,y,z)=a where a is some constant

dim thorn
#

Like just 1

tardy lagoon
#

yes then you get a level surface

#

and this time it is a plane

#

also slight issue with Q3. f(x,y)=x^2+y^2 is not a circle, rather the level curves are.

dim thorn
#

I was initially under the impression f(x, y) is 2d and f(x, y, z) is 3d

#

Idk how I’m 7 weeks into calc3 lol

tardy lagoon
#

you need to work on your geometric understanding lol

dim thorn
#

So f(x, y) = x^2 to y^2 is a sphere

#

And then level curves would be 2d circles

tardy lagoon
#

umm no

dim thorn
#

Duck

tardy lagoon
#

you should graph it yourself

#

it is graphable

dim thorn
#

Looks like a missile

tardy lagoon
#

btw a sphere would be x^2+y^2+z^2=r^2 or z(x,y) = sqrt(r^2-x^2-y^2)

#

yep

dim thorn
#

Oooo ok so any level curve of the inside would have to be a circle

#

Cause like well it’s a missile

#

So any specific 2d part of it would be a circle

tardy lagoon
#

correct

dim thorn
tardy lagoon
#

sqrt(k)?

dim thorn
#

Wait I’m dumb

#

Just radius k

tardy lagoon
#

umm

#

if f(x,y)=k then yes sqrt(k) is radius

dim thorn
tardy lagoon
#

I was confused about what's k

dim thorn
#

I switched a to k cause it’s what we use in class mbmb

#

So for it to not be centered at the origin wouldn’t it be k = (x^2 + 1) + (y^2 + 1)

tardy lagoon
#

yea you are correct about that

dim thorn
dim thorn
tardy lagoon
#

good

#

you still didn't explain what k is though

dim thorn
#

Ok one sec

tardy lagoon
#

I mean you should explain what k is on your work

dim thorn
#

I thought it was just a constant for the equation?

tardy lagoon
#

that's basically it

#

you should add something like "for the level curve f(x,y)=k, ..."

dim thorn
odd edgeBOT
#

@dim thorn Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hasty wigeon
#

Is this right

odd edgeBOT
odd edgeBOT
#

@hasty wigeon Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

late vessel
#

can u guya hwlp mw

odd edgeBOT
late vessel
#

Its about Synthetic Division and I'm trouble to know the divisor

#

How can I turn 2x²+3 to be a divisor for 4x⁵ + 6x⁴ + 5x² - x - 10?

#

(This is synthetic division and I'm aware of the missing terms)

#

This is so disgusting, i hate math

#

<@&286206848099549185> plz help

#

yee yee ass server

#

.close

odd edgeBOT
#
Channel closed

Closed by @late vessel

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dim thorn
odd edgeBOT
dim thorn
#

Where does my mistake lie here?

#

Im pretty sure this is wrong somewhere but I don’t know where

dim thorn
#

<@&286206848099549185>

odd edgeBOT
#

@dim thorn Has your question been resolved?

dim thorn
#

.close

odd edgeBOT
#
Channel closed

Closed by @dim thorn

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

signal oar
#

Regarding Russell's paradox

odd edgeBOT
signal oar
#

We have that R = {X | X not in X} and the paradox is R in R <==> R not in R.

#

What does X not in X really mean though?

#

Wouldn't e.g. the set {1} be a possible candidate for X?

viscid flint
#

yep

#

so would the empty set

#

it means that X is not an element of itself

signal oar
viscid flint
#

sure

crisp wadi
#

Not in ZFC as I remember

#

At least that is no longer regarded as a set

signal oar
#

It needs to be some never-ending one

viscid flint
#

yeah I mean sure as in "I can write something down but that's why it's a paradox"

signal oar
#

Why must R be in R

signal oar
signal oar
#

Or must it be not, it's just an assumption?

crisp wadi
#

Look up axiom of regularity, it has been introduced in order to avoid paradoxes like these

signal oar
#

I'd first like to find the intuition behind Russell's paradox though

crisp wadi
crisp wadi
#

If X is in X, then it must satisfy the property that it has for its elements

#

Meaning X should not be in X

#

For X to be an element of X

#

But that's a contradiction

#

Alright then, let's now look at the case if X is not in X

#

If X is not in X, then X is in X by the definition of X

#

Which is also a contradiction

signal oar
crisp wadi
#

Sorry I meant to say R instead of X

signal oar
#

If R is in R; then it satisfies the property for its elements X that (X not in X).

#

But why does that mean R should not be in R?

crisp wadi
#

For all X in R, we have X not in X, right?

#

That's the definition of R

#

Yeah my bad

signal oar
#

Then yeah

crisp wadi
signal oar
#

Oh

#

Thank you!

#

How does the barber paradox follow out of this?

crisp wadi
#

thonk have never heard of that

#

What's barber paradox?

signal oar
#

You can define the barber as ‘one who shaves all those, and those only, who do not shave themselves.’ The question is, does the barber shave himself?

#

If the barber shaves himself, then he shaves someone who shaves himself. A contradiction

#

If the barber doesn't shave himself, then no one is shaving him, so he must shave himself (since he shaves everyone who don't shave themselves). Contradiction.

crisp wadi
#

Sounds like a similar thing to Russel's paradox

#

Yeah it looks almost the same

#

But without abstract concepts like sets lol

signal oar
#

We can't directly translate the barber as R or something though right?

#

Or X in X as "X shaves X"

crisp wadi
#

Yeah

#

Exactly

signal oar
crisp wadi
#

To provide an analogy, yes

signal oar
#

Thanks

#

.close

odd edgeBOT
#
Channel closed

Closed by @signal oar

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tardy blaze
odd edgeBOT
tardy blaze
#

explain this part please

errant jay
#

$\frac{1}{5+2\sqrt{6}} = 5 - 2 \sqrt{6}$ by rationalising the denominator

clever fjordBOT
#

Frog_Man

tardy blaze
#

Please explain in more detail

errant jay
#

$\frac{1}{5+2\sqrt{6}} = \frac{5-2\sqrt{6}}{(5+2\sqrt{6})(5-2\sqrt{6})} = \frac{5-2\sqrt{6}}{5^2 - (2\sqrt{6})^2} = \frac{5-2\sqrt{6}}{1} = 5 - 2 \sqrt{6}$

clever fjordBOT
#

Frog_Man

errant jay
#

this means that $\frac{1}{t} = \frac{1}{(\sqrt{5+2\sqrt{6}})^x} = \left(\sqrt{\frac{1}{5+2\sqrt{6}}}\right)^x = (\sqrt{5-2\sqrt{6}})^x$

clever fjordBOT
#

Frog_Man

tardy blaze
#

I understand! Thank you

#

.close

odd edgeBOT
#
Channel closed

Closed by @tardy blaze

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
#

3³+3⁴+3⁵ = 3³(1+2+3²)

odd edgeBOT
mystic saffron
#

Where do you like get 3³(1+2+3²)

#

uh that's wrong

#

I don't know good English but what does faktorise mean

#

Is it not right?

static totem
#

it's a typo

mystic saffron
#

OH ITS MEANT TO BE 3

#

not 2

#

3³(1+3+3²)

static totem
#

yes

mystic saffron
#

Yeah how do you get from 3³+3⁴+3⁵ = 3³(133²??

static totem
#

you divide by 3³

#

you get 1+3+3²

mystic saffron
#

Hmm okay ill try

static totem
#

multiply by 3³ and you get 3³(1+2+3²)

mystic saffron
#

r 3³+3⁴+3⁵ / 3³?

#

Like that?

#

I still don't understand

#

I understand that but I don't understand how to get 3³(1+2+3²)

#

From that

#

I haven't learned algebra in school yet. Does this question need algebra?

#

My teacher says if I somehow show how to get 3³(1+2+3²) it's like A

#

Okay so I just follow that formula?

#

Is there any way to do it another way without algebra? Or no

#

Okay whatever

#

.close

odd edgeBOT
#
Channel closed

Closed by @lunar jolt

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
odd edgeBOT
mystic saffron
#

Correct?

#

<@&286206848099549185>

#

looking for conformation

static totem
#

looks right

mystic saffron
#

this right too?

hushed bobcat
#

Do you know what happens when you have a power to the power of something?

#

Laws of indices ^^

#

So for eg: what happens when you do (2^2)^2?

mystic saffron
#

uhh

mystic saffron
hushed bobcat
#

You multiply the powers

mystic saffron
#

yes

hushed bobcat
#

So then in this case

#

If we have this

mystic saffron
hushed bobcat
#

If when you have a power to a power you multiply

#

Then in this case we also multiply

#

Hence the answer would be?

mystic saffron
#

uhm i don't follow

hushed bobcat
mystic saffron
hushed bobcat
#

When you have a power on top of another power you multiply the powers

#

Similarly in this case we have a power on top of another power

mystic saffron
#

we multiple 2/3 with 6

hushed bobcat
#

Yes

#

👌

mystic saffron
#

which is 4 right

hushed bobcat
#

Yh

#

So it would be 12/3

mystic saffron
#

yep which is 4

hushed bobcat
#

Mhm

mystic saffron
#

so it will be 6 with exponet 4

hushed bobcat
#

Yh

mystic saffron
#

THE question is asking something else

hushed bobcat
#

It wants it as a fraction

#

Or am I wrong on that?

#

It wants it as 12/3 no?

mystic saffron
#

i searched online as well i came across this

#

but i think im supposed to write it with radicals

#

so i tried coming here for
addtional help

hushed bobcat
#

6^2 / 9 is also 4

#

36/9 is 4

mystic saffron
#

yes

#

correct

hushed bobcat
#

Hm

mystic saffron
#

but the question was asking for the 6^2 / 9 specifically i think

mystic saffron
hushed bobcat
#

Oh my

#

I’ve understood it now

mystic saffron
hushed bobcat
#

Cassandra is saying 6^(6^2/3)

#

So this

#

They’ve typed it out weirdly

#

And hence

#

But we know the correct exponent is actually 12/3 = 4

#

In other words how can we change the 6^2/3 to make it into 4

#

Or how can we change 36/3 to make it = 4

#

@mystic saffron

hushed bobcat
#

so what can we do to the 36/3 to make it = 4?

#

What multiplied by 4 = 36

mystic saffron
hushed bobcat
#

Indeed

#

And so we square the 3

#

To make it into 9

mystic saffron
#

mmm makes sense

hushed bobcat
#

That’s how we change it or what we replace with what Cassandra did

#

Hence the exponent 6^2/3 needs to be replaced with 6^2/9

#

Apologies if it’s confused you but it was typed out very weirdly

mystic saffron
#

i do understand it now tho so that's all that matters

#

.close

odd edgeBOT
#
Channel closed

Closed by @cloud bay

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

oblique jasper
odd edgeBOT
oblique jasper
#

can i get help plz

#

<@&286206848099549185>

warm lark
#

@oblique jasper How many sides and angles does it tell you are congruent?

oblique jasper
#

idk tbh

neat dirge
odd edgeBOT
#

@oblique jasper Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

keen matrix
#

A car is traveling at a speed of 80 km/h towards a 30-story building. Each story of the building is 5 m high. A fragment of the building breaks off from the top and falls to the ground. How much does the car need to decelerate to reach the building 2 to 5 cm before the fragment hits the ground?

odd edgeBOT
#

@keen matrix Has your question been resolved?

odd edgeBOT
#

@keen matrix Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

oak jewel
#

have gradient, just need help with b, finding the angle
[3:46 PM]

potent sphinx
#

We know that the gradient is the vector that points in the direction of maximum increase

odd edgeBOT
#

@oak jewel Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

spark yarrow
#

Im not sure what to do for the next step here

spark yarrow
#

Im using implicit differentiation to find dy/dx

cold sage
#

you sure youve done that right

#

specifically the left side

spark yarrow
#

I believe so ?

#

Do i have to add the - 0 ?

cold sage
#

you needed to use the product rule

proud ibex
#

Keep in mind that y also has an x-dependence

spark yarrow
#

Ohh

cold sage
#

but after youve corrected that - the next step is to make dy/dx the subject, which you can do by rearranging and factoring

spark yarrow
#

Okay let me do the work and make sure i did it right

#

Should be right now, right?

#

.close

odd edgeBOT
#
Channel closed

Closed by @spark yarrow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
odd edgeBOT
mystic saffron
#

I've never understand the why behind this

#

can anyone explain why p is inside and q is outside

merry finch
#

qth root of A

#

Just notation

mystic saffron
#

i mean like

#

why is it not

#

sqrtp A^q

#

how is it simplified to the RHS

#

@merry finch

sharp oak
#

It doesn't matter if you put the p outside and q inside, for positive reals anyway

clever fjordBOT
#

Tushar

sharp oak
#

If you're including negative reals, then this question is scary and I don't like it.

zenith jasper
#

Are you asking why it's the qth root rather than the pth root, or are you asking why we can write the root and exponent in any order (for positive A)?

odd edgeBOT
#

@mystic saffron Has your question been resolved?

mystic saffron
#

for this

#

actually nvm

#

i have it

#

.close

odd edgeBOT
#
Channel closed

Closed by @quartz sinew

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

last kindle
odd edgeBOT
plain lagoon
last kindle
#

this is for math

#

its apart of my math assignment

night raft
night raft
#

We have pH=-log[H+], right?

last kindle
#

ok

#

yeah

night raft
#

That [H+] is the concentration of hydrogen ions

#

You’re given the pH

#

So you need to solve for [H+]

#

Does that make sense

last kindle
#

It does but idk how to start it

#

would it be 12.5=-log[H+]

night raft
#

You can do this ye

odd edgeBOT
#

@last kindle Has your question been resolved?

last kindle
#

$H+$ = $10^{12.5}$

#

right?

clever fjordBOT
#

xNiden

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

last kindle
#

.reopen

odd edgeBOT
#

odd edgeBOT
#

@last kindle Has your question been resolved?

odd edgeBOT
#

@last kindle Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

verbal schooner
odd edgeBOT
verbal schooner
#

ok so i got

#

-1.36538313756

#

but it was wrong

#

so we derive cos(2x) right

#

= -2sin(2x)

#

plug in pi/6

#

cos(pi/3)

#

that gives the slope

#

-1.73205080756 (this is the slope i found)

#

then put it into the y - f(a) = m(x-a) formula

#

so what did i do wrong

odd edgeBOT
#

@verbal schooner Has your question been resolved?

#
Channel closed

Closed by @verbal schooner

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
#

help mee

odd edgeBOT
worldly robin
#

Lol

mystic saffron
#

im dum

grizzled tide
#

my brother in christ you know how to solve this

mystic saffron
#

i know its 1/4 but it says wrong

grizzled tide
#

its not 1/4

mystic saffron
#

i know

grizzled tide
#

whats the rise, and whats the run?

mystic saffron
#

rise is 1 run is 4

#

RIGHT

grizzled tide
#

really? the rise is 1? I dont see the graph going up at all

#

it goes up 1 unit for every 4 across it goes?

mystic saffron
#

?

#

ya

grizzled tide
vast dragon
#

The slope is going down

grizzled tide
#

this would be run of 4 and rise of 1

#

its falling (rising a negative amount)

mystic saffron
#

HOLY CRAP
I QUIT MATH
WOW

vast dragon
#

Yea

#

It’s simple stuff

mystic saffron
#

sry to all peope i tortured

#

.close

vast dragon
#

-1/4

odd edgeBOT
#
Channel closed

Closed by @prisma orbit

Use .reopen if this was a mistake.

mystic saffron
#

.reopen

odd edgeBOT
#

vast dragon
#

@grizzled tide can u help me rq

mystic saffron
#

so -1/4 right

vast dragon
#

Ya

mystic saffron
#

.close

odd edgeBOT
#
Channel closed

Closed by @prisma orbit

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

shell sorrel
#

a/b+c +b/c+d + c/d+e + d/e+a + e/ a+b > 5/2

odd edgeBOT
#

@shell sorrel Has your question been resolved?

shell sorrel
#

no

#

are u going to help

#

<@&286206848099549185>

toxic snow
#

What exactly is the question here sorry?

#

like what are you being asked to find

shell sorrel
#

a/b+c +b/c+d + c/d+e + d/e+a + e/ a+b > 5/2

#

prove

#

it

barren elm
#

?

#

this is too vague

odd edgeBOT
#

@shell sorrel Has your question been resolved?

#
Channel closed

Closed by @shell sorrel

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dapper glacier
#

i have a problem when the solution is provided, but i don't understand the solution

dapper glacier
#

the screenshot is the solution
can someone explain how the test makers made the equation?

#

to be more specific, i'm talking about the equations for the series
(-4k-1)^2 + (4k+1)^2 and (-4k)^2 + (4k+2)^2

#

<@&286206848099549185>

odd edgeBOT
#

@dapper glacier Has your question been resolved?

dapper glacier
#

<@&286206848099549185>

odd edgeBOT
#

@dapper glacier Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wheat drum
#

Say I have the equation 2x = 10 mod 23, I've checked the multiplicative inverse of 2 mod 23 is 12, so x = (2^-1)*10 = 12*10 = 5 mod 23
My question is, does the 'natural' way of simplifying directly 2x = 10 into x = 5 work in all cases ? Or does it fail sometimes ?

shy smelt
#

It works if 2 has an inverse, 2^-1 * 10 = 2^-1 * 2 * 5 = 5

#

(mod 23)

wheat drum
#

thank you!

#

.close

odd edgeBOT
#
Channel closed

Closed by @wheat drum

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

radiant shell
odd edgeBOT
radiant shell
#

How do i even start w this question

#

like 2x+y = 6 and x^2 = 9 when x = 3, y = 0, so is it just the question?

#

i don't even know if im supposed to do chain rule

odd edgeBOT
#

@radiant shell Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

radiant shell
#

.reopen

odd edgeBOT
#

odd edgeBOT
#

@radiant shell Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
#

When do I have to put a parenthesis when inserting a value and when do I not?

mystic saffron
#

I often mess this up and it leads to the entire question being wrong so what's the rule for this?

#

E.g. say I have a tangent equation with f'(u)*(x-u)+f(u)

#

And I want to put in -4u+3 for f'(U) ans -2u^2+3u+10 for f(U)

#

Where do I put a parenthesis and why?

low locust
#

you always put parenthesis around the entire thing you plug in

#

if its just a single number then this doesnt really matter so many people dont actually write the parenthesis down in that case

mystic saffron
#

So here I'd do (-4u+3)*(x-u)+(-2u^2+3u+10)?

low locust
#

yes

mystic saffron
#

How about when it's a chain function?

#

Or actually rather

#

if it's u(x)*v(x)

#

Do I then do [(u'(x) * v(x))+(u(x) * v'(x))]

#

<@&286206848099549185>

low locust
#

do you mean if you want to plug (u(x)v(x))' into some other thing? yes

odd edgeBOT
#

@mystic saffron Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

austere rover
#

What happened here?

odd edgeBOT
austere rover
#

where did it come from?

#

is it like derivative of a power series?

#

also why did they differentiate it?

mystic saffron
#

d/dp (1-p)^x is -x (1-p)^(x-1)

#

So xp(1-p)^(x-1) is just -p times by that

austere rover
#

ok

#

.close

odd edgeBOT
#
Channel closed

Closed by @austere rover

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

austere rover
#

can someone explain how they got h(X) to me

austere rover
#

I only know that 1000X is the revenue function

#

but getting the rest, I have no idea how

echo ginkgo
#

1000X + 200(3-X) is the revenue

#

there's X computers you sell normally for $1k

austere rover
echo ginkgo
#

the remaining computers (3-X) are regiven to the manufacturer for $200

#

that's where the 200(3-X) comes from

#

your store makes back some money with the unsold computers

#

@austere rover

austere rover
#

ohhhhh

#

thanks

odd edgeBOT
#

@austere rover Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sudden charm
#

Hello, Im having trouble with a problem: A number has 30 digits all of which are 0 or 6. can it be a square? I got that it has to end in an even number of zeroes and start with a 6.

sudden charm
#

if n ends with 10^2k, then 10^2k|n => n/10^2k is a square

#

and it clearly wont be cuz it ends with 6 and other digits are 0

#

.close

odd edgeBOT
#
Channel closed

Closed by @sudden charm

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz stone
#

I need help with 9b (i) and (ii)

odd edgeBOT
#

@topaz stone Has your question been resolved?

odd edgeBOT
#

@topaz stone Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon ravine
#

if i put a 2x2 matrix in row echelon form, is that basically just the 2nd row becomes 00 and the first row remains the same?

green elm
#

the second row should be of the form [0, c] where c is some number (maybe zero, maybe not)

#

and the first row should be of the form [a, b] where a is nonzero

#

that's assuming that the first column contains a nonzero number

#

otherwise the first row will be of the form [0,a] where a is some number (maybe zero, maybe not) and the second row is [0,0]

neon ravine
#

so it's just the bottom left value that needs to become 0?

green elm
#

yes

#

more precisely, the rules are:

#

the first nonzero entry in any given row has to be to the right of the first nonzero entry in all the rows above it

neon ravine
#

ok, thanks :]

#

.close

odd edgeBOT
#
Channel closed

Closed by @neon ravine

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gilded bluff
odd edgeBOT
gilded bluff
#

why does theta = 30?

drifting valley
#

theta is the angle ABD, and there's a theorem about angles inside circles (don't know the english name, look in your lesson) which says it's half the angle AOD
but since AOD is equilateral, each angle, including angle AOD, is 60°
so ABD, which is half of that, is 30°

gilded bluff
#

ohh thats so true

#

thank u

#

.close

odd edgeBOT
#
Channel closed

Closed by @gilded bluff

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wicked ledge
#

Maybe I'm misunderstanding these

odd edgeBOT
wicked ledge
#

That's the answer but I don't really get it

waxen jay
#

i need help with math

wicked ledge
waxen jay
#

kay sorry

wicked ledge
#

But with sinx it'd have positive and negative?

#

sinu

tardy lagoon
#

?

#

from 0 to pi sin u is positive and from pi to 2pi sin u is negative

#

what's the issue here

wicked ledge
#

Oh my lord. I'm so sorry.

tardy lagoon
wicked ledge
#

Don;t even worry. I'm a complete nobhead

#

Thank you

tardy lagoon
#

np

wicked ledge
#

.close

odd edgeBOT
#
Channel closed

Closed by @wicked ledge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

uneven turret
#

hi

odd edgeBOT
uneven turret
#

if
3|2n+1 and 7|n-2
how many 2-digit n exist

#

I tried multiplying both sides or at some points right side by something but I could not find the answer

#

but I know it's easier to solve it with mod

#

but idk how to

#

.close

odd edgeBOT
#
Channel closed

Closed by @uneven turret

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

coral cloak
#

Resolve x in the interval [0;2pi]
Knowing that:
2cos(x)+sin(x)>1

Help needed once again ;-;

(Ping me)

coral cloak
#

.close

odd edgeBOT
#
Channel closed

Closed by @coral cloak

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

trail raft
#

I am supposed to simplify: (1/cosx) + tanx)(1/cosx) - tanx). and i am wondering if (1/cosx) - (sinx/cosx) will become 1-sinx/cosx or cosx/cosx. i say this because i don't know if 1-sinx becomes cosx in the same way 1-sin²x = cos²x

trail raft
#

nvm i solved it.

#

.close

odd edgeBOT
#
Channel closed

Closed by @trail raft

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jovial cape
#

Hey

odd edgeBOT
jovial cape
#

Wanted some help on this

#

I know how to know if y is a function of X with coordinates but not sure how to otherwise

#

Could yall help me?

mint abyss
#

Wdym "with coordinates"?

stark heart
odd edgeBOT
#

@jovial cape Has your question been resolved?

jovial cape
jovial cape
stark heart
jovial cape
#

because there is 2 variables

#

or am i wrong?

stark heart
#

Yes correct

#

So what do you think are functions out of these options

jovial cape
#

ty guys

#

.close

odd edgeBOT
#
Channel closed

Closed by @jovial cape

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

errant heart
#

After doing all this how do i find the point c?

odd edgeBOT
#

@errant heart Has your question been resolved?

viscid flint
#

is o the origin?

#

if so then oc is the same as the point c

odd edgeBOT
#

@errant heart Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

teal carbon
#

hello can someone help me with this

odd edgeBOT
teal carbon
#

xd

#

i got to this
-cot^2x times secx - secx + 2

#

i was thinking about factoring out secx like this
secx(-cot^x -1 but idk what to do with the +2

haughty scaffold
#

u did well by factoring out sec(x) on the left hand side, u can do the same with 2 on the right hand side as well before u bring anything over

#

well no lets do it differently

#

u can start off by bringing everything on the left hand side, then from (cotx)^2*secx-secx u can factor out a secx, from the 2-2(cotx)^2 u can factor out a -2, and then youll see that u have another common factor (cotx)^2-1

#

so now you can factor that one out as well and then youll have a multiplication equal to 0, so youll just set each of the parts equal to 0

teal carbon
#

hmm one sec let me work it out that way

teal carbon
haughty scaffold
#

no yeah u factor out a secx from the expression before that part of the message, and from the next expression youll factor out a -2

#

like this

#

slightly different order on my notebook, but the idea remains the same

teal carbon
#

i dont get why this is on the right side

#

ohh wait

haughty scaffold
#

i just factored out a 2

teal carbon
#

oh my god

#

the insides r the same

haughty scaffold
#

yup

teal carbon
#

okay yep i get it now

#

thank you so much

haughty scaffold
#

nw!

teal carbon
#

.close

odd edgeBOT
#
Channel closed

Closed by @teal carbon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

nocturne belfry
#

I have I think a simple multivar question

nocturne belfry
#

If im looking at two curves $$x^2 - y^2 = a^2$$ and $$xy=a$$, whats the process to showing that these two curves will always be orthogonal at a point of intersection?

clever fjordBOT
#

jan Niku

steel quarry
#

obtain the differential equation to one curve, replace dy/dx with -dx/dy, and integrate once more

nocturne belfry
#

i have to apologize my multivar is horrible

steel quarry
#

I don't know any multivar, but what you're looking for is an orthogonal trajectory

steel quarry
nocturne belfry
#

why does this show what we want to show

hard field
#

you could skip the integration process

#

take the derivative of both and show the product of the gradients is -1

steel quarry
hard field
nocturne belfry
#

assume ive never taken calc iii

#

do i just work with the LHS of each of these in constructing the gradient?

hard field
#

yes

#

the rhs would become 0 in both cases

#

for example the first one would become 2x dx - 2y dy = 0

nocturne belfry
#

isnt the gradient a vector

steel quarry
#

I think you're overcomplicating the task at hand 😅

#

What clarkie said works nicely

nocturne belfry
#

i want to understand it because i need to write about it

#

its the motivation for a method of approximation of integrals

#

so i need to understand it

#

but i never took multivar 😳

hard field
#

dont need anything gradient vector based I think

nocturne belfry
#

but isnt the gradient defined as a vector?

hard field
#

I suppose so

nocturne belfry
#

oh wait

#

i think i see

#

so in the one youd have $$2x-2yy'=0$$

clever fjordBOT
#

jan Niku

nocturne belfry
#

and the other $y+xy'=0$

clever fjordBOT
#

jan Niku

nocturne belfry
#

so the slopes are y' = y/x and y'=-y/x

#

oh but thats not what we wanted

hard field
#

it is

#

the product is -1

nocturne belfry
#

product in what sense?

hard field
#

oh double check

#

one of them

#

product of their gradients is -1

nocturne belfry
#

how do you know

hard field
#

oh lawd , you're testing my fundamentals ;-;

nocturne belfry
#

oh, wait

#

i think i got you

#

@hard field okay so the products are negative 1

#

this would be like

hard field
#

this makes more sense to me geometrically than any math proof

nocturne belfry
#

if level curve one has y' = m at a point

#

then the other is z'=-1/m

hard field
#

their isnt much of a surface here

nocturne belfry
#

and we just rely on like negative reciprocal

#

negative reciprocal means perpendicular

#

i think i getchu

hard field
#

just a ~~ circle~~ BOWL THING extended through z I guess

nocturne belfry
#

a circle thonk

hard field
#

MY BAD

hard field
#

I think this makes sense to me

#

at least

nocturne belfry
#

okay

#

i can learn more later

#

i do think you need to use vectors

#

taking the gradient of an equation doesnt make sense to me though

#

how do you get a gradient involved with a level set

hard field
#

Im not much use to you for fundamental questions I think, I only learnt general n dimensional gradient vectors weeks ago :D

nocturne belfry
#

would it really just be like x^2-y^2 = a^2 -> <2x, -2y>?

#

and then the other is

#

<y, x>

#

so 2xy-2yx hype

#

okay

#

resolved

#

.close

odd edgeBOT
#
Channel closed

Closed by @nocturne belfry

Use .reopen if this was a mistake.

hard field
#

yes

nocturne belfry
#

thanks @hard field

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

viscid sage
odd edgeBOT
viscid sage
#

how do I find PQS

#

<@&286206848099549185>

haughty scaffold
#

well whats a bisector?

#

by definition

viscid sage
#

line that divides a line or an angle into two equivalent parts

#

so 124 divided by 2

#

=62

haughty scaffold
#

yup

viscid sage
#

What about this one

haughty scaffold
#

again, BD is a bisector

#

what does that tell us about the two angles marked on the photo

viscid sage
#

that it is half

haughty scaffold
#

ABD is 4x+4 and DBC is 6x-14 right?

viscid sage
#

yes

#

they have to equal the same thing

#

I did this but I dont think it is right

#

I looked it up and google said 9

#

Which is correct ?

#

each = 40

#

How do I do this ?

#

<@&286206848099549185>

odd edgeBOT
#

@viscid sage Has your question been resolved?

signal halo
#

If QS was the angle bisector than m<PQS=m<RQS

viscid sage
#

so they are both 75 ?

signal halo
#

Well we know PQS is 35

viscid sage
#

Correct

signal halo
#

So is it possible for RQS to be 35

viscid sage
#

no

signal halo
#

So if PQS and RQS aren’t equal

#

Is QS an angle bisector

viscid sage
#

is the bisector 70

signal halo
#

Yeah if the large angle was 70 then QS would be an angle bisector

viscid sage
#

okay

#

so how do I know if it is true or false

signal halo
#

So let me phrase it like this

#

QS is an angle bisector if and only if the large angle is 70

viscid sage
#

I said it is true because it is in the middle idk if that is correct

signal halo
#

And is the large angle 70

viscid sage
#

no it not

#

so it is false

signal halo
#

Yeah

viscid sage
#

got it

#

I have one more question

#

How do I find the unknown endpoint

signal halo
#

Do you know the midpoint formula

viscid sage
#

x1 x2 y1 y2?

signal halo
#

Yeah

#

So if we plug this into the midpoint formula we get

viscid sage
#

which one do I label first ?

signal halo
#

(B/2, (a-4)/2) = (-5,-4)

signal halo
viscid sage
#

idk

#

is it like this

signal halo
#

The formula formula says

#

The coordinates of the midpoint are

#

((X1+x2)/2,(y1+y2)/2)

viscid sage
#

is this correct

signal halo
#

No

#

First of all the y coordinate is always the one on the right

#

So (0,-4) would be x1,y1

#

And -5,-4 are the coordinates of the midpoint

signal halo
viscid sage
#

this is correct now

signal halo
#

No

#

X2 and y2 are unknown

#

They are what we are trying to solve for

#

But we know the midpoint

signal halo
#

So if we plug in x1 and y1 we can solve for x2 and y2

viscid sage
#

so what do i need to do ?

#

0 + -4

#

?

#

how do I find the other coordinates ?

signal halo
#

(0+x2)/2,(-4+y2)/2 = -5,-4

#

Then split it into two equations

viscid sage
#

I dont understand the equation

signal halo
#

the midpoint is always ((x1+x2)/2, (y1+y2)/2) right

viscid sage
#

yes

signal halo
#

and they also tell us that the midpont is (-5,-4)

viscid sage
#

yes

signal halo
#

so (-5,-4) = ((x1+x2)/2, (y1+y2)/2)

#

this is saying that two points are equal

#

but for two points to be equal they need to have the same x and y values

#

so we can split this into two equations

#

-5 = (x1+x2)/2

#

-4 = (y1+y2)/2

#

we know x1 is 0 and y1 is -4

#

can you solve from there?

viscid sage
#

0,-4

#

=

#

-4

signal halo
#

no

#

theres no commas anymore

#

so we would have -5 = (0+x2)/2 right

#

and -4 = (-4+y2)/2

#

so how do we solve for x2 in the equation

viscid sage
#

-4 dividedd by 2 ?

signal halo
#

use this equation: -5 = (0+x2)/2

viscid sage
#

im just going to close this I cant comprehend

#

thank you for the help tho

#

.close

odd edgeBOT
#
Channel closed

Closed by @viscid sage

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quartz pier
odd edgeBOT
quartz pier
#

this would be false right

#

because

1 2 | 3
1 1 | 1
1 2 | 1

1 2 | 3
0 -1 | -2
0 0 | -2

last row is 0 0 | -2 so it has no solutions

#

right

wooden python
#

yeah sure

quartz pier
#

alr ty and one more question identity matrix dimensions are always Z x Z where Z can be any natural number right

so 2 x 2, 3x3 , 4x4 but 4x5 wont be possible

#

it has to be the same

wooden python
#

that certainly is a choice of letter for denoting an arbitrary natural number

#

but yes identity matrices are always square.

quartz pier
#

bet thanks alot

#

.close

odd edgeBOT
#
Channel closed

Closed by @quartz pier

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bold egret
#

Hi, so I have this trig equation: sinx + cosx = 1, when I square both sides I get some wrong result but when I multiply both sides by sqrt(2)/2 I get the correct result and I don't understand why

zenith tartan
#

post your original quesetion @bold egret

bold egret
#

Find roots of sinx + cosx = 1 that belong to the interval [0, 2pi]

#

When I square both sides I get a wrong answer

teal carbon
#

i think if you square both sides and get sin^2x + cos^2x = 1 then you can replace cos^2x with (1 - sin^2x) and try to solve it that way

#

can you show me how you got the right answer by multiplying both sides by sqrt(2)/2

bold egret
#

Hopefully that's clear enough

#

Now look what happens when I square both sides

#

The results are different

#

@teal carbon