#help-19

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mellow axle
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odd edgeBOT
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vast aurora
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My discrete math teacher mentioned gaussian elimination as like the way to solve systems of equations using matricies, how do you do that?

vast aurora
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I know the setup

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But idk how the process works

sharp oak
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If you haven't seen it before at all, check out a YouTube video first imo. It's a very visual process

vast aurora
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Kk

sharp oak
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If you have any questions after that, feel free to ask

vast aurora
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Will do

worn stump
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$\begin{aligned} \lim _{n \rightarrow \infty} P\left(B_n\right) & \leq \lim _{n \rightarrow \infty} n\left(1-p_n\right)^{n-1} \ & =\lim _{n \rightarrow \infty} n\left[1-(1+\epsilon) \frac{\ln n}{n}\right]^{n-1} \ & =\lim _{n \rightarrow \infty} n\left[1-\frac{1+\epsilon}{\frac{n}{\ln n}}\right]^{n-1} \ & =\lim _{n \rightarrow \infty} n\left(\left[1-\frac{1+\epsilon}{\frac{n}{\ln n}}\right]^{\frac{n}{\ln n}}\right)^{\frac{(n-1) \ln n}{n}} \ & =\lim _{n \rightarrow \infty} n e^{-(1+\epsilon) \ln n} \ & =\lim _{n \rightarrow \infty} \frac{1}{n^\epsilon} \ & =0 .\end{aligned}$

anybody can help me this out? from the forth line

clever fjordBOT
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Edison Lee

odd edgeBOT
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@vast aurora Has your question been resolved?

vast aurora
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Yes

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graceful willow
odd edgeBOT
graceful willow
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Need help with this question

rose radish
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whats the question ?

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this is just the data

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@graceful willow Has your question been resolved?

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silent talon
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Determine the canonical and expanded form of each of the functions f , g, h and p associated with the parabolas shown below.

Can anyone tell me if the G one is correct ? ( green parabola )

ember oak
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Looks good

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But your final result is not canonical form.

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Canonical form is a(x-h)^2+k

silent talon
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The first one framed isn’t ?

ember oak
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Oh. Yes

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I read the last one only

silent talon
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Ok thank you catthumbsup

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crude orbit
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<@&286206848099549185>

odd edgeBOT
long tinsel
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oh boy

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For a quadratic to have more than 2 distinct real roots, what does it imply?

crude orbit
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value is greater then 0

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the discriminate is greater then 0

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b^2 - 4ac

drifting valley
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no

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a quadratic that is non zero can have at most two distinct real roots

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if it has more than that, the whole quadratic is always zero

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ie each of the coeff will be 0

crude orbit
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so like y = 0 ?

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just a straight line going through the x-axis ?

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infinite roots

drifting valley
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yes

crude orbit
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ok lemme show you

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sorry for angle

drifting valley
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,rotate

clever fjordBOT
drifting valley
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yes

crude orbit
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thats all ?

drifting valley
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yes

crude orbit
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dam 4 marks

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ok ty

odd edgeBOT
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torpid ginkgo
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Basic question here, but my prof is stating that double integrals can give areas or volumes

torpid ginkgo
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This makes no goddamn sense

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I thought a single integral gave us the area

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Outside of a rotation or something

nocturne belfry
wooden python
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integrals generally are an accumulation of tiny changes

nocturne belfry
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consider like $\int_0^1 \int _0^1 \dd y \dd x$

clever fjordBOT
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jan Niku

wooden python
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in the same spirit as a single integral gives an area under the graph of a singlevar function

torpid ginkgo
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Oh okay I see so a function of two variables is basically the 3rd dimension. ?

torpid ginkgo
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But if there is no function of two variables it’s an are

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So I can just say Z = f(x,y) and call Z my “height”

nocturne belfry
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no interesting contribution from the height component

wooden python
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btw we have a she/her pronoun role

torpid ginkgo
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Thanks !

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boreal hamlet
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(\lim_{{x \to \infty}} f'(x) = 0);

(f'(x) = f'(-x));

(f(a) > f(b)) for all (a > b);

(\lim_{{x \to 0}} f'(x) = k)

f(x) is defined and non-imaginary for all real x, k is a finite number

clever fjordBOT
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padfoot9445

boreal hamlet
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what is f(x)?

odd edgeBOT
# boreal hamlet what is f(x)?
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
boreal hamlet
south plume
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think about hints 1 and 3

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what do they mean together?

boreal hamlet
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does 1 mean it goes steep in the middle and shallow on the outside?
and 3 means it's always increasing, right?

south plume
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they essentially mean that the function is increasing but at a decreasing rate

boreal hamlet
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log?

south plume
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not defined for non-positive

boreal hamlet
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oh shit I left something out

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the first one should be f'(|x|)

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instead of f'(x)

south plume
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ooh

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actually i think condition 2 implies that

boreal hamlet
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oh yeah

south plume
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i have to be honest, i have not solved this yet but i just have some ideas

boreal hamlet
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tbh I'm not sure if f(x) exists

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because I made this up myself

south plume
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f(x) is defined

south plume
boreal hamlet
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it should look like a s shape when we're done

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and I'm certain I read about this before

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but I can't find it at all

south plume
# clever fjord **padfoot9445**

you can also make this whole problem purely about the derivatives of functions, condition 3 implies that f'(x)>=0 for all x

south plume
clever fjordBOT
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artemetra

south plume
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,w integral of e^(-x^2)

south plume
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yeah its erf but it satisfies all of your conditions

boreal hamlet
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odd edgeBOT
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south plume
boreal hamlet
odd edgeBOT
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bold scroll
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Hi!

Got a question that I know the answer to but need to know if theres a "correct way to calculate it.

So the question is:

During a few years, a colony of birds were reduced from 10 000 to 6000 which is on average a 4% decrease per year. How many years did it take for the colony to go from 10 000 to 6000?

I know the answer is around 12 years but I suspect that the way I found out the answer is wrong(did 10 000 * 96 = 9600 * 0.96 etc untill I was at 6127).

Is there any other way to do this where I dont have to do *0.96 12 times to get the answer?

cosmic hearth
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Your intuition for solving the problem is right; generally, we're solving
[ 10000 \cdot (0.96)^n = 6000 ]

clever fjordBOT
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@cosmic hearth

cosmic hearth
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The way I would probably solve this is with logarithms; are you familiar with those?

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@bold scroll ^

bold scroll
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Hmm.. not really. But I found a chapter in my math book for it and I can see that it says logarithms among other things at the top of the homework paper

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I just didnt know that it included this stuff haha.

signal yacht
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they're just

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inverse exponentiation

cosmic hearth
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Basically, yeah

bold scroll
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So thank you! No need for further help. Will go throigh the chapter.

cosmic hearth
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The main form of the logarithm is:
[ a^b = c \iff \log_a c = b ]

We'll probably also want to keep in mind the following rule:
[ \log_a b = \frac{\log_c b}{\log_c a} \text{ for all $a$, $b$, $c$ } ]

clever fjordBOT
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@cosmic hearth

bold scroll
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Ahh.

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Awesome. Thank you!

cosmic hearth
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(the rule is mostly helpful for putting it into the calculator, moreso than actually solving the problem)

odd edgeBOT
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@bold scroll Has your question been resolved?

bold scroll
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Yes

odd edgeBOT
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weary tusk
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Anyone knows how to find the area of a triangle by knowing it's points coordinates

wooden python
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there are at least two ways

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no wait, at least three

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one is (relatively) low-tech but very very painful
the second is a little higher tech and moderately painful
and the third is almost painless but is very sophisticated conceptually

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they are, in that order:

  1. compute all side lengths then apply heron's formula
  2. compute all side lengths, then one angle via cosine law, then find its sine and use the S = 1/2 ab sin(C) formula
  3. compute vectors representing two of the sides, package them into a matrix, and take half the absolute value of its determinant (works only in 2D)
weary tusk
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@wooden python The problem is:

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the point A(x,y) moves on the curve $ y=x^3+x $ such that $\frac {dy} {dt}$ = 2 units/s find the rate of change in the area of the triangle ABO such that O is the origin and B(0,6) at the moment that the x coordinate of the moving point is 3

wooden python
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wrap the y=x^3+x in dollars

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wait did you mean dy/dx or did you mean dx/dt though

clever fjordBOT
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Hamdy Hisham

wooden python
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dy/dt = 2 units/s?

weary tusk
wooden python
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this is kind of hairy

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probably

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it can be done but it's a bit unpleasant

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can i see a pic of the original?

weary tusk
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._.

wooden python
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the notation will be the same i am pretty sure

weary tusk
wooden python
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general policy is you should post originals when people ask even if it's not in english.

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yes

weary tusk
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ok wait

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@wooden python

wooden python
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ok so then this is dy/dt is it

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ok yeah alright

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so this triangle of yours has a vertical side

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(0,0) to (0,6)

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whose length is obviously just 6

weary tusk
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yup

wooden python
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and the height, perpendicular to it, is just x

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so your goal will be to find dx/dt here

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it is easy from there

weary tusk
wooden python
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wdym

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you know the half base times height formula for the area of a triangle, right?

weary tusk
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Yes but how the height is x

wooden python
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there's nothing that stops you from considering the vertical side as the base

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then the height will be horizontal

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the triangle is kind of sideways but that does not really matter

weary tusk
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I don't understand

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How is the height x

wooden python
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drop a perpendicular from the variable point onto the y axis.

weary tusk
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Wait

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Do you mean that this is the height?

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@wooden python

wooden python
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yes

weary tusk
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Aha

wooden python
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and it is equal to the x coordinate of that moving point

weary tusk
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You've just blown my head

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Ok thx

odd edgeBOT
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@weary tusk Has your question been resolved?

odd edgeBOT
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robust moat
#

Why are the bounds different from the original function, and why is the integral a constant over regions undefined in the original function?

hasty escarp
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it is a constant because the func is pres to be 0 for $x<1$

clever fjordBOT
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FluffyFlareon

robust moat
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is that conventional?

hasty escarp
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if it isn't explicitly stated that the func has no val on those int / b

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then it can be ass to be 0

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at least I'd think

robust moat
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is this wrong then?

hasty escarp
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OH it's so dumb x>2 is moved to seemingl wrong row. I'm not sure rn

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first row x<1 makes sense to me as C

robust moat
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well yes under the assumption that its constant where undefined, but also why is it $x \leq 1$

clever fjordBOT
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Jason 지환

hasty escarp
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except w is it $x<=1$?

clever fjordBOT
#

FluffyFlareon

robust moat
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bahaha alright 😭

hasty escarp
robust moat
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whats that?

hasty escarp
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website ?

robust moat
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oh, wolfram alpha

hasty escarp
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ok

robust moat
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<@&286206848099549185>

odd edgeBOT
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@robust moat Has your question been resolved?

robust moat
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.close

odd edgeBOT
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pliant crest
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for point normal eqn of plane or eqn of a plane standard version, why do i need the norm and a points (x,y,z) passing through it? can someone explain why these are needed

shy moth
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Write out the standard eqn of a plane

mortal trench
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To understand the plane equation you must understand the dot product

shy moth
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Pretty much

pliant crest
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can u explain the connection

mortal trench
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If we have two vectors, (a,b,c) and (x,y,z), and we dot them, and set that equal to 0, we get the set of all vectors x,y,z perpendicular to a,b,c

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This explains:
ax+by+cz = 0

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Now to shift this, all you need to do is change the value of k

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Where
ax+by+cz = k

zenith jasper
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if you’re asking why a normal vector and a point defines a plane, it’s because a normal vector is normal to an infinite number of planes (along the axis of the normal vector) and a point will narrow them down to one

shy moth
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I think hes more on about how we got the equations

odd edgeBOT
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@pliant crest Has your question been resolved?

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stiff yarrow
#

Did I do this correctly?

odd edgeBOT
stiff yarrow
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.close

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buoyant solstice
odd edgeBOT
buoyant solstice
#

apparently H is not a normal subgroup of G, but how is that determined?

drifting valley
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I think you're wrong, D4 looks like a normal subgroup of S4

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if you want to prove that a subgroup is not normal, either you prove it's not a subgroup or it's not normal, by contradiction with the def of normal

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like you find a counterexample of a ghg^-1 which is not in H

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but in general, it's way easier to try to prove it's a normal subgroup first

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because if it is there are a lot of results you can use to prove it and you can construct the table at the same time

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while finding a counterexample is straight up impossible if you're wrong and the subgroup is normal

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if I remember correctly my algebra exercises, S4 is the only Sn with n >= 3 such that it has not only An as a normal subgroup, but D4 too so you should check that

odd edgeBOT
#

@buoyant solstice Has your question been resolved?

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proud bison
#

Need help understanding how to find a value of an inverse of a trig equation

The graph of f(x) = cos(3x) + 4x − 2 is strictly increasing with no horizontal tangent lines.
Is f(x) invertible? If so, find f^-1(-1)

I know f(x) is one to one, so its invertable, Im having trouble with the second part where I find f^-1(-1), feel like i tried everything lol

odd edgeBOT
#

@proud bison Has your question been resolved?

proud bison
drifting valley
#

either you sketch in your mind, or you guess, and you use that it's strictly increasing

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like you can calc f(0), if it's > -1, put something less than 0 in f

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and vice versa

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since they give you a function with a cos, which is a pain to invert

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you can reasonably guess that's the value they ask you to find is easy to guess

proud bison
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I think they want us to solve it algebraically, but then idk how to, doing it mentally i know its 0

drifting valley
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cos(3x)+4x-2 = -1
so cos(3x)+4x = 1
and you can't solve it algebraically

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you can only notice that x = 0 is a sol

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and since the function is invertible, the sol is unique, that's f^-1(1)

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and if 0 was wrong, then as I said, you take bigger than 0 or smaller

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using that your function is increasing

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while it's not possible to solve it algebraically, it's possible to study that with a bit more details once you'll have calculus

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also you can notice obvious thing like a solution can't be < 0, nor can be > 1

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but it still doesn't solve the equation algebraically because when you have cos(3x)+4x = 1 you're stuck

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that's why they made the sol obv to guess

odd edgeBOT
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marsh sparrow
odd edgeBOT
marsh sparrow
#

why does the derivative not exist, if we used the power rule on the function when x = 0 then shouldnt the 0 stay as a 0?

nimble blaze
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wdym used power rule on the function

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how?

marsh sparrow
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like dont numbers that arent coefficents become a 0

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like x+1 would be 1 + 0

nimble blaze
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but you don't have a power function here

marsh sparrow
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o

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that makes more sense so i need a variable in it for it to be a power function

nimble blaze
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xsin(x/9)
isn't a power function

marsh sparrow
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o

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so it cant have any trig functions but has to have a variable for it to be a power function

nimble blaze
#

you have a product of x and sin(x/9)
product rule would be applicable
and then you'll get expressions of derivatives of power functions from that

marsh sparrow
nimble blaze
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no

marsh sparrow
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aw man im briandead

nimble blaze
#

power function
constant * variable^(some power)

marsh sparrow
#

o alright ty that makes sense

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.close

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buoyant maple
#

hey how you doing

odd edgeBOT
buoyant maple
#

i have a fast question

#

how did he get

#

2pie 0

#

1 r = 0

#

i was abscent i just want to make sure

#

does he give this to us

#

or did he find it himself

drifting valley
#

he switches to polar coordinates

buoyant maple
#

but how did he know its 2pie

drifting valley
#

because you're integrating for the full turn around, he's integrating for theta = 0 to theta = 2pi

#

it's the whole circle

buoyant maple
#

i mean

#

theta = 0 theta = 2pie

#

does he give it to us

#

or we have to find it

drifting valley
#

you have to find it but it's direct once you understand the drawing

#

these bounds tells you y goes from -sqrt(1-x²) to sqrt(1-x²) with x from -1 to 1

#

it exactly draws the circle

#

so when you switch to polar coordinates, your bounds have to cover exactly the whole circle too

buoyant maple
#

ok i get 2pie and 0

#

what about 1 and r = 0

drifting valley
#

r is the radius

#

he's integrating over the inside of the circle too, he's integrating on the whole disc of radius 1

#

so r has to vary from 0 to 1

buoyant maple
#

ok i see

#

do you have a video i can watch

#

so i can have a better understanding

#

because im just having issues setting it up

drifting valley
#

I don't know videos about it but maybe some people here do, or by looking polar coordinates double integrals you may find some

buoyant maple
#

can i ask you another one

#

this question

#

i know i should do e ^ r^2

#

ooooh never mind

#

i figure it out

#

@drifting valley thank you very much now i understand it

#

for this r will be

#

r^2 = 5

#

so square root of 5

#

and second one will be 3

#

and second quardent will be pie and pie/2

#

is that right ?

drifting valley
#

yeah but be careful you are bounded by x²+y² = 9 too

#

so r² >= 5 but r² <= 9

buoyant maple
#

yea that becomes r = 3

drifting valley
#

you'll be integrating from r = sqrt(5) to r = 3

#

yeah

buoyant maple
#

oh i get it now

#

thank you very much

civic hound
#

@buoyant maple remeber put .close

buoyant maple
#

.close

odd edgeBOT
#
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buoyant maple
odd edgeBOT
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pale bramble
odd edgeBOT
mellow gust
#

Holy

#

Ok

#

This is a big equation

odd edgeBOT
#

@pale bramble Has your question been resolved?

odd edgeBOT
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@pale bramble Has your question been resolved?

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stuck rock
#

How do I apply the chain rule to 1000e^(0.3t)

stuck rock
#

For some reason when this textbook teaches me

#

it goes ok next we apply the chain rule to get

#

and then just skips to the answer

tropic copper
#

are you integrating or differenciating

stuck rock
#

differentiation

tropic copper
#

okay so

#

take the 1000 out it doesnt change

#

now

stuck rock
#

e^0.3t

#

so that's

tropic copper
#

$\frac{d}{dx} e^{ax} = ae^{ax}$

#

use this

stuck rock
#

e^0.3t and then the prime of 0.3t which is 0.3

clever fjordBOT
#

Bettim

tropic copper
#

ah this

stuck rock
#

Ah I see what happened

#

I think I got it now

#

When you do e^(x)*g'(x) its like the chain rule basically

#

so then that would be 0.3 x 1000 which is 300

#

300e^0.3t

#

Okay so I am curious about removing the 1000 though

#

When can I do that

fringe bough
#

$\frac{d}{dx} \ cf(x) = cf'(x)$ for any constant $c$

clever fjordBOT
#

tatpoj

stuck rock
#

Oh okay that's nice

#

thank you very much

fringe bough
#

np 👍

stuck rock
#

.close

odd edgeBOT
#
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robust inlet
#

Why do they do x <=3 not just x = 3

#

Your finding the largest value of r so why would u need to find the probability that it is 0 1 2 and 3 not just 3

#

<@&286206848099549185>

odd edgeBOT
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cerulean obsidian
#

How to do b i do t get it

odd edgeBOT
cerulean obsidian
#

Dont'

tardy lagoon
#

,rotate

clever fjordBOT
tardy lagoon
#

combine the fractions and do the same thing in part a

odd edgeBOT
#

@cerulean obsidian Has your question been resolved?

wooden python
#

@cerulean obsidian do you know how to add fractions with real numbers?

odd edgeBOT
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pine osprey
odd edgeBOT
#

@pine osprey Has your question been resolved?

pine osprey
#

<@&286206848099549185>

pine osprey
#

.close

odd edgeBOT
#
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pine osprey
#

Anyone please?

odd edgeBOT
tardy lagoon
#

find the maximum by letting f'(x)=0

pine osprey
#

.close

odd edgeBOT
#
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jaunty summit
#

.close

#

i need help with this one

#

i got the equation that 0=a(x-3)^2+4.2

#

but can't find a or x

odd edgeBOT
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stray blaze
#

Hi there

odd edgeBOT
stray blaze
#

Can anyone give me a general expression when an tan ( pie*x/2) will go undefined

low locust
#

$\pi$ is just called pi

clever fjordBOT
#

Denascite

low locust
#

its undefined if x is an odd integer

#

is that what you want?

odd edgeBOT
#

@stray blaze Has your question been resolved?

odd edgeBOT
#
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charred barn
odd edgeBOT
abstract locust
#

i can help with that

charred barn
#

using synthetic division

abstract locust
#

im literally right past that stage in my own work

#

wait can't you just make it a fraction

charred barn
#

its our lesson

abstract locust
#

ok listne

charred barn
#

mmm how did it become a-4

abstract locust
#

$2a^2 - 5a - 12 has to be OVER 2a + 3$

charred barn
#

man our teacher didn't taught us the other rules

clever fjordBOT
#

GMDennis

abstract locust
charred barn
#

10

abstract locust
#

same

#

anyway

#

listen

#

so

#

idk how to draw it correctly but ill send you a pic holdup

charred barn
#

okii

abstract locust
#

do this

#

molto importante

charred barn
#

but our lesson is about synthetic division

abstract locust
#

nah but like wtf is synthetic division lmao

charred barn
#

lmfao 😭

abstract locust
#

click on the image

#

on the left side

#

it's a GIF which should demonstrate how you ought to do it

charred barn
#

okie

abstract locust
#

ight peace out

worldly robin
#

Oye

charred barn
#

Wait nvm i was just wrong abt putting signs 😭😭

#

thankssss

odd edgeBOT
#

@charred barn Has your question been resolved?

odd edgeBOT
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sand pier
#

M confused on how to find the cartesian limits

odd edgeBOT
#

@sand pier Has your question been resolved?

sand pier
#

<@&286206848099549185>

#

Broo someone help 😭😭

#

<@&286206848099549185>

lucid schooner
#

Yooo

sand pier
#

HELP plssss

#

I have an exam of this tmrw

lucid schooner
#

@sand pier

#

U help me

sand pier
#

Bro..

#

Just divide 2457 by 189..

#

Also is that a quiz....

#

Calculator is allowed bro

sand pier
#

Pleasee

#

.-.

#

What's the problem I can't understand 2nd time my ques has remained unanswered...

odd edgeBOT
#

@sand pier Has your question been resolved?

odd edgeBOT
#

@sand pier Has your question been resolved?

vague torrent
#

.close

scarlet junco
vague torrent
#

chill I thought that the conv was over

#

sorry

odd edgeBOT
#

@sand pier Has your question been resolved?

odd edgeBOT
#
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mystic saffron
odd edgeBOT
zenith tartan
#

which one?

mystic saffron
#

Two and three

zenith tartan
#

do you know the expansion of $(a-b)^2$?

clever fjordBOT
#

!Yajat!

mystic saffron
#

No

zenith tartan
#

$(a-b)^2=a^2+b^2-2ab$

clever fjordBOT
#

!Yajat!

zenith tartan
#

use this to solve for the third one

mystic saffron
#

how to put together

#

.close

odd edgeBOT
#
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noble ether
#

How Can We Factor The Sum Of Two Squares?

zenith tartan
#

provide any question to work with

noble ether
#

Like, How To Factor (a^2+b^2) as a product?

low locust
#

you mean like we can factor a^2-b^2=(a+b)(a-b) ?

#

there is no similar formula for a^2+b^2

noble ether
#

Nah, The Sum Of Two Squares

mint mirage
#

You can factor it using complex numbers

noble ether
noble ether
mint mirage
#

And as mentioned, it's not factorable under reals

noble ether
mint mirage
#

You added an extra -2ab, that expression expands to a^2 + b^2 - 2ab

noble ether
#

What? It would be (a+b)^2-(sqrt(2ab))^2 which is equal to a^2+b^2?

mint mirage
#

You specifcally asked a^2 + b^2

mint mirage
#

,w expand (a+b)^2-(sqrt(2ab))^2

#

Weird, website said this

noble ether
#

(a+b)^2 = a^2+b^2+2ab, (a+b)^2 -2ab = a^2 + b^2

mint mirage
#

If you want to go it that way you can, but requires more effort, if you wanted something easy like a^2 - b^2 = (a + b)(a - b) formula, then factoring a^2 + b^2 won't result into something that simple

mint mirage
#

Yes

noble ether
#

Thanks for the help mate

#

.close

odd edgeBOT
#
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full rock
#

I really need help with this
I just cant

full rock
#

I wrote almost two pages but it got messed up both times

zenith tartan
#

,w 3(\sqrt{a-19}) + 4(\sqrt{b-17}) = \frac{1}{2}(a+b-11)

full rock
zenith tartan
#

just take power 2 both the side, 2 times

#

its really fked up tho

full rock
#

Maybe I could do S= -b/a

#

Hmm

zenith tartan
#

S=-b/a?

full rock
#

I don't think it would work

full rock
zenith tartan
full rock
zenith tartan
#

what have you done, could you show me your solution

zenith tartan
full rock
#

The digits are Arabic

#

Also this

full rock
cunning peak
#

did you square both sides?

full rock
cunning peak
cunning peak
#

idk 17*19=18²-1

full rock
#

Oh

cunning peak
#

I'm going to try here

#

yeah squaring both sides is a bad idea I'm sorry

#

I'm trying by calling sqrt(a-19) = x and sqrt(b-17) = y

cunning peak
#

I think I found something

#

wait a little bit

full rock
#

k

cunning peak
#

yep

#

I got it

cunning peak
#

I'm going to screenshot

#

After that you have to complete the squares of x and y

#

adding terms to both sides of the equation

#

doing that, it cancels 25/2, so all you have left is a sum of squares

#

and that sum is equal to 0

#

that means both terms NEED to be 0, since x²>=0, for all real x

full rock
cunning peak
full rock
#

Firstly I multiplied it by 2 to remove the fraction (nothing special)

Then I did:
x² - 6x = -y² + 8y -25

cunning peak
full rock
#

x² - 6x + 9 = -(y² - 8y + 16)

#

(x-3)² = -(y-4)²

#

x = 3 and y = 4

#

And then just put in the numbers

full rock
cunning peak
#

you're welcome

full rock
#

.close

odd edgeBOT
#
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cunning peak
full rock
cunning peak
#

yeah

#

Only thing is the + or - by taking the square root

#

but yeah cool problem

odd edgeBOT
#
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cunning peak
#

made my brain thing I'm good at algebra (I'm not)

odd edgeBOT
#

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golden orbit
#

im again not sure of my understanding of discrete functions

golden orbit
#

does the codomain of a discrete function have to be countable?

#

is $f:\mathbb{Z} \to \mathbb{C}$ discrete even though C is not countable?

clever fjordBOT
#

metnal

golden orbit
#

or does the codomain not matter here as long as the range of the function is countable?

#

where the range is a subset of the codomain is the actual set of outputs for the domain of the function

low locust
#

only the range matters

#

you can always make the codomain bigger without really changing the function

crisp wadi
#

And the range will be countable given that the domain is countable

golden orbit
#

got it, tysm

#

.close

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gilded lodge
#

how would i do this question?

odd edgeBOT
gilded lodge
glass wedge
#

sorry wrong image lol

#

i tried all the sin cos rules

#

but i cant get it to work

zenith tartan
#

<@&268886789983436800>

glass wedge
#

Im sorry it was in the clipboard

#

ill remove it

zenith tartan
#

lol

#

!occupied

odd edgeBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

viscid flint
#

however you yeah that

viscid flint
#

then can you find an expression for the chance of him to win at least one game, in terms of x?

gilded lodge
#

is it x^2

#

oh wait

#

i got it

#

.close

odd edgeBOT
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sleek falcon
#

im unsure if im doing, this question correct, could i show my approach?

sleek falcon
odd edgeBOT
#

@sleek falcon Has your question been resolved?

odd edgeBOT
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@sleek falcon Has your question been resolved?

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cedar elm
odd edgeBOT
cedar elm
#

based on the drawn graph are these points correct?

odd edgeBOT
#

@cedar elm Has your question been resolved?

odd edgeBOT
#

@cedar elm Has your question been resolved?

clever fjordBOT
orchid torrent
#

All four are wrong - do you know the definitions of the terms in the questions?

cedar elm
#

@orchid torrentthe graph is exactly the way the problem was presented

odd edgeBOT
#

@cedar elm Has your question been resolved?

odd edgeBOT
#

@cedar elm Has your question been resolved?

odd edgeBOT
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worthy peak
#

wouldn't this be setting the first derivative to 0?

I got 500/e^5t for my derivative, but i can't solve for 0

slow light
#

You want the rate at t=0, not the t at which the derivative is 0

worthy peak
#

oh shoot

worthy peak
#

.close

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keen plover
#

Hi is this correct?

odd edgeBOT
keen plover
#

And need guidance on how to answer number 4

fair prism
keen plover
fair prism
#

Find all combinations of (a,b) where a is in A and b is in B

#

For example (0,2) would be one of them

keen plover
#

what is this for then?

fair prism
#

That is the relation

#

If you plug x and y from an ordered pair (x,y) into that and get an integer, then it is part of the relation (the ordered pair is in the set)

keen plover
#

oke oke

#

this is hard

#

not hard but confusing

fair prism
#

Seems like a big step up from the first problem lol

odd edgeBOT
#

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mystic saffron
#

Can I get some help for 48 please

odd edgeBOT
mystic saffron
#

I already did u-sub, and get the following for all values of p

simple epoch
#

Is there a specific thing you’re confused about? It looks like you got it (although the last part looks it should be converges for p>=1)

mystic saffron
#

I’m redoing the whole thing right now

#

Feel like this makes more sense?

#

@simple epoch

simple epoch
#

Oh wait yeah I’m dumb

mystic saffron
#

Tried to make it as clear as possible

simple epoch
#

Working through it now, your work looks correct to me

mystic saffron
#

I feel like separating different cases for p is easier

simple epoch
#

Alright I worked through it and got what you got so you should be good. Your reasoning looks sound and I don’t see any errors

mystic saffron
#

Appreciate it

#

Was wondering if you could help me with one improper integral

#

@simple epoch

simple epoch
#

Sure

mystic saffron
#

My integral of choice doesn’t help me at all

#

Is there something better

#

That I can use

simple epoch
#

Make sure you wrote that problem down correctly lmao that’s an ugly integral

mystic saffron
#

They want me to compare it to another improper integral

#

Which makes sense I guess

simple epoch
#

Oh yeah that makes this easy

#

Is (the integral of) x^3/x^5 convergent or divergent?

mystic saffron
#

Wait

#

Hold on

#

Convergent

simple epoch
#

Your first guess was right it’s convergent

mystic saffron
#

Final answer

#

Yeah

#

Oh

#

Okay

simple epoch
#

Is that always less than or greater than your main integral

mystic saffron
#

Let me do this

simple epoch
#

You got it

earnest raft
#

its convergent

mystic saffron
simple epoch
#

LGTM

mystic saffron
#

👍

#

Thanks

#

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rose harness
#

How do I find out angle C? Circle theorem maths

swift rock
#

sum of angles in a triangle = 180

odd edgeBOT
#

@rose harness Has your question been resolved?

rose harness
#

.close

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mystic saffron
odd edgeBOT
mystic saffron
#

is it 0.55?

static totem
#

you could check with a calculator

#

,calc 3^(1.1*exp(1))

clever fjordBOT
#

Result:

26.708225867668
static totem
#

hm

#

i guess you can't

mystic saffron
#

i already answered that one can you help me with this one?

#

<@&286206848099549185>

odd edgeBOT
#

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distant spoke
#

How to solve this question? (i forgot 😦 )

clever fjordBOT
distant spoke
#

I know, but i cant simplify the sqrt after simplify the Numerator

mystic saffron
#

what do you mean? can you elaborate?

distant spoke
#

,rotate

clever fjordBOT
mystic saffron
#

that's actually all you need tbh

#

like try to plug in the value the limit approaches

#

you will get something that is 1/0

#

that is undefined and not indeterminate

#

which implies...

distant spoke
#

oh i see

#

thx for the help

#

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odd edgeBOT
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odd edgeBOT
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blissful nimbus
#

hi, just a quick q _ what does the A represent here. is there a specific mathematical term

blissful nimbus
#

gotchu

#

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regal moss
odd edgeBOT
regal moss
#

How do I do parts e and f

odd edgeBOT
#

@regal moss Has your question been resolved?

odd edgeBOT
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@regal moss Has your question been resolved?

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eager void
#

How do I do this improper integral?

odd edgeBOT
eager void
#

I know the limit part, but dont know how to actually do the integral

drifting valley
#

your fraction is just sin(4x)(1-cos(4x))^-1/5, they write it as a fraction just to make it complicated

eager void
#

yeh

drifting valley
#

look how (1-cos(4x))' = 4sin(4x)

eager void
#

substituion?

drifting valley
#

yes, it's a way to do it

eager void
#

is the best way?

#

Ok i'll try that

drifting valley
#

take u = 1-cos(4x)

eager void
#

yep

#

but why is this improper integral?

#

because I get the integral is 5/ 16 * (1-cos(4x))^4/5

#

is it becuase you cant take sqrt(0)

#

so we have to do the limit

drifting valley
#

because at x = 0 the function is not defined since the denom cancels, however, the function still has a finite limit at 0, which lets the integral to converge

drifting valley
#

I mean denom = 0

eager void
#

Dont I just get 5/16 * (-1+1)^4/5 ?

#

Is that not defined?

drifting valley
#

at x = 0, 1-cos(4x) = 0

eager void
#

yes

drifting valley
#

but you can't divide by 0

eager void
#

ohh the function I integrated right

#

got it

#

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odd edgeBOT
#
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odd edgeBOT
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gritty orchid
#

i really need help

odd edgeBOT
zenith edge
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
gritty orchid
#

1

#

i dont know where to begin

zenith edge
#

Okay, how familiar are you with quadratic functions?

gritty orchid
#

i have 0 idea how to this

#

to do this*

cold viper
#

An example of a quadratic function is anything that goes up and down

gritty orchid
#

i have to write it my paper

#

i really have no idea how to do this

#

and im sleepy as heck

cold viper
#

Example: a ball if you forget about friction qnd air resistance

gritty orchid
#

mhm but how do write it in the 2nd box and etc etc?

zenith edge
#

We're not gonna be able to just do the task for you so we'll need you to work with us a bit here. Have you worked with quadratic functions at all? Do you know how they look and how to calculate important values like intercepts and top/bottom points?

gritty orchid
#

no 0%

zenith edge
#

Alright

mint mirage
zenith edge
#

A quadratic function is a function on the form $f(x) = cx^2 + bx + a$, or $ax^2 + bx +c$, this often varies from country to country which way you write it

clever fjordBOT
#

Joachim

zenith edge
#

,w plot x^2 + 4x + 4

zenith edge
#

They tend to look like something like this

gritty orchid
#

i see i see

zenith edge
#

,w plot -x^2 + 10

zenith edge
#

or this

#

See how the sign of that first x^2 decides if the graph is "smiling", positive x^2 = smiling graph

gritty orchid
#

yes yes

zenith edge
#

A real world example like animelover mentioned is throwing a ball into the air

gritty orchid
#

how do i write a table that represents quadratic function?

zenith edge
#

Now we can either graph the ball travelling in the x and y direction, or just think about the y direction(height) and say the x direction is time

#

The table for the qudratic equation could include stuff like starting position, top position, when it hits the ground etc

gritty orchid
#

i see i see

zenith edge
#

You should probably watch a video or two on the subject though to be able to do all the required tasks here

#

You should also probably solve these in the order 1 - 4 - 2 - 3

#

Decide what you want the graph to represent, then figure out an equation for it, then calculate important values, then use those values to draw it

cold viper
#

I just did a quick Google search. There are so many real life examples. U just have to chose one

gritty orchid
#

oh okay i see i see

#

thank you so much guys

#

but im really struggling to do all these im really sleepy lol

#

i have to submit it by tom

zenith edge
#

Watch this video series, everything by Khan Academy is very good in general

#

The videos are pretty short and informative

gritty orchid
#

THANK YOUUUUUU

zenith edge
#

Happy to help

#

You might want to .close this channel in the meantime, but feel free to open a new one and ask for help later if you're struggling with particular points in the task

odd edgeBOT
#

@gritty orchid Has your question been resolved?

gritty orchid
#

how to i make table value for y=x^28x+7?

odd edgeBOT
#
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lone zinc
#

Can someone explain 7 a) i dont understand the solution at all

lone zinc
#

what does Z x Z mean? Ik Z represents integers but why is it multiplying integers by integers

latent scaffold
#

ZxZ are pairs of integers

#

So any pair (m,n) where m and n are integers

#

The x is called a Cartesian product

lone zinc
latent scaffold
#

To show surjectivity, you need to show that for any integer y in the codomain Z, you can find some ordered pair (a,b) in the domain Z x Z such that f(a,b) = y

#

But this is fairly simple since f(a,b) = a - b

#

So if we let b = 0 and a = y, we get f(y,0)=y

#

So the pair (y,0) maps to y

lone zinc
#

so since any value you sub into y will give itself then its surjective?

latent scaffold
#

Yes

lone zinc
#

ahhh ok thanks

#

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vagrant saddle
odd edgeBOT
vagrant saddle
#

pn meansprime number

#

it makes any sense ?

low locust
#

the gap from P_n to P_(n+1) is not good enough (like you noticed). however what about the gap from P_n to P_(n+2) ?

vagrant saddle
#

do I need to consider P_(n+2) ?

#

All i want to proof is P_n+1 >3n+3

low locust
#

yes you need to consider P_(n+2)

odd edgeBOT
#

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untold kayak
odd edgeBOT
untold kayak
#

Need help with b and c

#

And 6

reef sandal
#

Okay so because dy/dx is defined implicitly, it's basically a multivariable function, like f(x,y)

#

So I'd make a note that you let dy/dx = f(x,y) = whatever

#

Then the slope of the tangent line at (a,b) is simply f(a,b)

untold kayak
#

Ok

#

Would it be this

reef sandal
#

Looks like it

untold kayak
#

What about for C

#

Was that how you do it

reef sandal
#

x axis is when y = 0

#

Same process for 5

#

Use f(x,y) = dy/dx

untold kayak
#

Are you talking about 6

reef sandal
#

The process is the same for both questions

untold kayak
#

I’m confused isnt the vertical tangent when you make the equation equal zero

#

The bottom of the equation equal zero

reef sandal
#

Typically if you get something like C/0 where C is some random ass number, that's an indicator of a vertical tangent

#

As long as C ≠ 0

untold kayak
#

Ok yea

#

That was the equation so I made the bottom equal zero

odd edgeBOT
#

@untold kayak Has your question been resolved?

odd edgeBOT
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umbral hawk
#

i have a question, lets say i have a sequence.
i want the first number to be x, x is a fraction
the second number is 2x
the third number is 3x
lets say infinite is n, so nx < 1

static totem
#

okay

#

i don't get the last line

odd edgeBOT
#

@umbral hawk Has your question been resolved?

umbral hawk
#

1/2 2/3 3/4 -> works

#

but 1/2 starts too big

#

thats a good sequence, just not good enough

static totem
#

to big for what

umbral hawk
#

it starts as a half

static totem
#

1/10 2/11 3/12

umbral hawk
#

so

#

starts at 1/5

#

and every step it gets 1/5 closer to 1

#

so like

#

1/5 which is 0.2
then 0.2 of 0.8 which is 0.16, so 0.36 is next

#

how would u do it as a sequence?

static totem
#

1 − (4/5)^n for example

umbral hawk
#

how did u get to it

#

if i may ask

#

ok i got it:

1st term: 1 - 4/5
2nd: 1 - 4/5 + (1 - 4/5) * (1 - (1 - 4/5)) = 1 - 4/5 + (1 - 4/5) * (4/5) = 1 - 4/5 + 4/5 - (4/5)^2 = 1 - (4/5)^2
3nd: 1 - (4/5)^2 + (1 - 4/5) * (1 - (1 - (4/5)^2)) = 1 - (4/5)^2 + (1 - 4/5) * ((4/5)^2) = 1 - (4/5)^2 + (4/5)^2 - (4/5)^3 = 1 - (4/5)^3
summary -> 1 - (4/5)^n
#

thanks @static totem

odd edgeBOT
#

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lone zinc
#

For question 11c what do i do next here?