#help-19
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My discrete math teacher mentioned gaussian elimination as like the way to solve systems of equations using matricies, how do you do that?
If you haven't seen it before at all, check out a YouTube video first imo. It's a very visual process
Kk
If you have any questions after that, feel free to ask
Will do
$\begin{aligned} \lim _{n \rightarrow \infty} P\left(B_n\right) & \leq \lim _{n \rightarrow \infty} n\left(1-p_n\right)^{n-1} \ & =\lim _{n \rightarrow \infty} n\left[1-(1+\epsilon) \frac{\ln n}{n}\right]^{n-1} \ & =\lim _{n \rightarrow \infty} n\left[1-\frac{1+\epsilon}{\frac{n}{\ln n}}\right]^{n-1} \ & =\lim _{n \rightarrow \infty} n\left(\left[1-\frac{1+\epsilon}{\frac{n}{\ln n}}\right]^{\frac{n}{\ln n}}\right)^{\frac{(n-1) \ln n}{n}} \ & =\lim _{n \rightarrow \infty} n e^{-(1+\epsilon) \ln n} \ & =\lim _{n \rightarrow \infty} \frac{1}{n^\epsilon} \ & =0 .\end{aligned}$
anybody can help me this out? from the forth line
Edison Lee
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Need help with this question
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Determine the canonical and expanded form of each of the functions f , g, h and p associated with the parabolas shown below.
Can anyone tell me if the G one is correct ? ( green parabola )
Looks good
But your final result is not canonical form.
Canonical form is a(x-h)^2+k
The first one framed isn’t ?
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<@&286206848099549185>
no
a quadratic that is non zero can have at most two distinct real roots
if it has more than that, the whole quadratic is always zero
ie each of the coeff will be 0
yes
,rotate
yes
thats all ?
yes
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Basic question here, but my prof is stating that double integrals can give areas or volumes
This makes no goddamn sense
I thought a single integral gave us the area
Outside of a rotation or something
you can use double integrals to get area
integrals generally are an accumulation of tiny changes
consider like $\int_0^1 \int _0^1 \dd y \dd x$
jan Niku
a double integral of a function of two variables can be interpreted as the volume under its graph
in the same spirit as a single integral gives an area under the graph of a singlevar function
Oh okay I see so a function of two variables is basically the 3rd dimension. ?
essentially, yeah
But if there is no function of two variables it’s an are
So I can just say Z = f(x,y) and call Z my “height”
hope this isnt confusing but i think you can interpret this case as z(x,y)=1
no interesting contribution from the height component
kind of meh but yes
btw we have a she/her pronoun role
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(\lim_{{x \to \infty}} f'(x) = 0);
(f'(x) = f'(-x));
(f(a) > f(b)) for all (a > b);
(\lim_{{x \to 0}} f'(x) = k)
f(x) is defined and non-imaginary for all real x, k is a finite number
padfoot9445
what is f(x)?
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
does 1 mean it goes steep in the middle and shallow on the outside?
and 3 means it's always increasing, right?
they essentially mean that the function is increasing but at a decreasing rate
log?
not defined for non-positive
oh yeah
i have to be honest, i have not solved this yet but i just have some ideas
f(x) is defined
Oh.
it should look like a s shape when we're done
and I'm certain I read about this before
but I can't find it at all
you can also make this whole problem purely about the derivatives of functions, condition 3 implies that f'(x)>=0 for all x
integral of $e^{-x^2}$
artemetra
,w integral of e^(-x^2)
yeah its erf but it satisfies all of your conditions
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also, sigmoid function
wha does erf mean?
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Hi!
Got a question that I know the answer to but need to know if theres a "correct way to calculate it.
So the question is:
During a few years, a colony of birds were reduced from 10 000 to 6000 which is on average a 4% decrease per year. How many years did it take for the colony to go from 10 000 to 6000?
I know the answer is around 12 years but I suspect that the way I found out the answer is wrong(did 10 000 * 96 = 9600 * 0.96 etc untill I was at 6127).
Is there any other way to do this where I dont have to do *0.96 12 times to get the answer?
Your intuition for solving the problem is right; generally, we're solving
[ 10000 \cdot (0.96)^n = 6000 ]
@cosmic hearth
The way I would probably solve this is with logarithms; are you familiar with those?
@bold scroll ^
Hmm.. not really. But I found a chapter in my math book for it and I can see that it says logarithms among other things at the top of the homework paper
I just didnt know that it included this stuff haha.
Basically, yeah
So thank you! No need for further help. Will go throigh the chapter.
The main form of the logarithm is:
[ a^b = c \iff \log_a c = b ]
We'll probably also want to keep in mind the following rule:
[ \log_a b = \frac{\log_c b}{\log_c a} \text{ for all $a$, $b$, $c$ } ]
@cosmic hearth
(the rule is mostly helpful for putting it into the calculator, moreso than actually solving the problem)
@bold scroll Has your question been resolved?
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Anyone knows how to find the area of a triangle by knowing it's points coordinates
there are at least two ways
no wait, at least three
one is (relatively) low-tech but very very painful
the second is a little higher tech and moderately painful
and the third is almost painless but is very sophisticated conceptually
they are, in that order:
- compute all side lengths then apply heron's formula
- compute all side lengths, then one angle via cosine law, then find its sine and use the S = 1/2 ab sin(C) formula
- compute vectors representing two of the sides, package them into a matrix, and take half the absolute value of its determinant (works only in 2D)
@wooden python The problem is:
the point A(x,y) moves on the curve $ y=x^3+x $ such that $\frac {dy} {dt}$ = 2 units/s find the rate of change in the area of the triangle ABO such that O is the origin and B(0,6) at the moment that the x coordinate of the moving point is 3
Hamdy Hisham
dy/dt = 2 units/s?
Thats the final thing sorry
this is kind of hairy
probably
it can be done but it's a bit unpleasant
can i see a pic of the original?
the notation will be the same i am pretty sure
Are you sure you want to see this?
general policy is you should post originals when people ask even if it's not in english.
yes
ok so then this is dy/dt is it
ok yeah alright
so this triangle of yours has a vertical side
(0,0) to (0,6)
whose length is obviously just 6
yup
and the height, perpendicular to it, is just x
so your goal will be to find dx/dt here
it is easy from there
wdym
you know the half base times height formula for the area of a triangle, right?
Yes but how the height is x
there's nothing that stops you from considering the vertical side as the base
then the height will be horizontal
the triangle is kind of sideways but that does not really matter
drop a perpendicular from the variable point onto the y axis.
yes
Aha
and it is equal to the x coordinate of that moving point
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Why are the bounds different from the original function, and why is the integral a constant over regions undefined in the original function?
it is a constant because the func is pres to be 0 for $x<1$
FluffyFlareon
is that conventional?
if it isn't explicitly stated that the func has no val on those int / b
then it can be ass to be 0
at least I'd think
OH it's so dumb x>2 is moved to seemingl wrong row. I'm not sure rn
first row x<1 makes sense to me as C
well yes under the assumption that its constant where undefined, but also why is it $x \leq 1$
Jason 지환
except w is it $x<=1$?
FluffyFlareon
bahaha alright 😭
whats that?
website ?
oh, wolfram alpha
ok
<@&286206848099549185>
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for point normal eqn of plane or eqn of a plane standard version, why do i need the norm and a points (x,y,z) passing through it? can someone explain why these are needed
Write out the standard eqn of a plane
To understand the plane equation you must understand the dot product
Pretty much
can u explain the connection
If we have two vectors, (a,b,c) and (x,y,z), and we dot them, and set that equal to 0, we get the set of all vectors x,y,z perpendicular to a,b,c
This explains:
ax+by+cz = 0
Now to shift this, all you need to do is change the value of k
Where
ax+by+cz = k
if you’re asking why a normal vector and a point defines a plane, it’s because a normal vector is normal to an infinite number of planes (along the axis of the normal vector) and a point will narrow them down to one
I think hes more on about how we got the equations
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Did I do this correctly?
.close
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apparently H is not a normal subgroup of G, but how is that determined?
I think you're wrong, D4 looks like a normal subgroup of S4
if you want to prove that a subgroup is not normal, either you prove it's not a subgroup or it's not normal, by contradiction with the def of normal
like you find a counterexample of a ghg^-1 which is not in H
but in general, it's way easier to try to prove it's a normal subgroup first
because if it is there are a lot of results you can use to prove it and you can construct the table at the same time
while finding a counterexample is straight up impossible if you're wrong and the subgroup is normal
if I remember correctly my algebra exercises, S4 is the only Sn with n >= 3 such that it has not only An as a normal subgroup, but D4 too so you should check that
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Need help understanding how to find a value of an inverse of a trig equation
The graph of f(x) = cos(3x) + 4x − 2 is strictly increasing with no horizontal tangent lines.
Is f(x) invertible? If so, find f^-1(-1)
I know f(x) is one to one, so its invertable, Im having trouble with the second part where I find f^-1(-1), feel like i tried everything lol
@proud bison Has your question been resolved?
<@&286206848099549185>
heres the question in an image
either you sketch in your mind, or you guess, and you use that it's strictly increasing
like you can calc f(0), if it's > -1, put something less than 0 in f
and vice versa
since they give you a function with a cos, which is a pain to invert
you can reasonably guess that's the value they ask you to find is easy to guess
I think they want us to solve it algebraically, but then idk how to, doing it mentally i know its 0
cos(3x)+4x-2 = -1
so cos(3x)+4x = 1
and you can't solve it algebraically
you can only notice that x = 0 is a sol
and since the function is invertible, the sol is unique, that's f^-1(1)
and if 0 was wrong, then as I said, you take bigger than 0 or smaller
using that your function is increasing
while it's not possible to solve it algebraically, it's possible to study that with a bit more details once you'll have calculus
also you can notice obvious thing like a solution can't be < 0, nor can be > 1
but it still doesn't solve the equation algebraically because when you have cos(3x)+4x = 1 you're stuck
that's why they made the sol obv to guess
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why does the derivative not exist, if we used the power rule on the function when x = 0 then shouldnt the 0 stay as a 0?
but you don't have a power function here
xsin(x/9)
isn't a power function
o
so it cant have any trig functions but has to have a variable for it to be a power function
you have a product of x and sin(x/9)
product rule would be applicable
and then you'll get expressions of derivatives of power functions from that
so the product of xsin(x/9) is a powerfunction but not xsin(x/9) itself?
no
aw man im briandead
power function
constant * variable^(some power)
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hey how you doing
i have a fast question
how did he get
2pie 0
1 r = 0
i was abscent i just want to make sure
does he give this to us
or did he find it himself
he switches to polar coordinates
but how did he know its 2pie
because you're integrating for the full turn around, he's integrating for theta = 0 to theta = 2pi
it's the whole circle
you have to find it but it's direct once you understand the drawing
these bounds tells you y goes from -sqrt(1-x²) to sqrt(1-x²) with x from -1 to 1
it exactly draws the circle
so when you switch to polar coordinates, your bounds have to cover exactly the whole circle too
r is the radius
he's integrating over the inside of the circle too, he's integrating on the whole disc of radius 1
so r has to vary from 0 to 1
ok i see
do you have a video i can watch
so i can have a better understanding
because im just having issues setting it up
I don't know videos about it but maybe some people here do, or by looking polar coordinates double integrals you may find some
can i ask you another one
this question
i know i should do e ^ r^2
ooooh never mind
i figure it out
@drifting valley thank you very much now i understand it
for this r will be
r^2 = 5
so square root of 5
and second one will be 3
and second quardent will be pie and pie/2
is that right ?
yea that becomes r = 3
@buoyant maple remeber put .close
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My fault first time hearing about it
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help
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How do I apply the chain rule to 1000e^(0.3t)
For some reason when this textbook teaches me
it goes ok next we apply the chain rule to get
and then just skips to the answer
are you integrating or differenciating
differentiation
e^0.3t and then the prime of 0.3t which is 0.3
Bettim
ah this
Ah I see what happened
I think I got it now
When you do e^(x)*g'(x) its like the chain rule basically
so then that would be 0.3 x 1000 which is 300
300e^0.3t
Okay so I am curious about removing the 1000 though
When can I do that
You can do that whenever you have a constant multiplied by your function
$\frac{d}{dx} \ cf(x) = cf'(x)$ for any constant $c$
tatpoj
np 👍
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Why do they do x <=3 not just x = 3
Your finding the largest value of r so why would u need to find the probability that it is 0 1 2 and 3 not just 3
<@&286206848099549185>
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How to do b i do t get it
Dont'
,rotate
combine the fractions and do the same thing in part a
@cerulean obsidian Has your question been resolved?
@cerulean obsidian do you know how to add fractions with real numbers?
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help
<@&286206848099549185>
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Anyone please?
find the maximum by letting f'(x)=0
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i need help with this one
i got the equation that 0=a(x-3)^2+4.2
but can't find a or x
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Hi there
Can anyone give me a general expression when an tan ( pie*x/2) will go undefined
$\pi$ is just called pi
Denascite
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i can help with that
using synthetic division
im literally right past that stage in my own work
wait can't you just make it a fraction
its our lesson
ok listne
mmm how did it become a-4
$2a^2 - 5a - 12 has to be OVER 2a + 3$
man our teacher didn't taught us the other rules
GMDennis
what grade are you in
10
same
anyway
listen
so
idk how to draw it correctly but ill send you a pic holdup
okii
but our lesson is about synthetic division
nah but like wtf is synthetic division lmao
lmfao 😭
In algebra, synthetic division is a method for manually performing Euclidean division of polynomials, with less writing and fewer calculations than long division.
It is mostly taught for division by linear monic polynomials, but the method can be generalized to division by any polynomial.
click on the image
on the left side
it's a GIF which should demonstrate how you ought to do it
okie
ight peace out
Oye
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M confused on how to find the cartesian limits
@sand pier Has your question been resolved?
Yooo
<@&286206848099549185> just tell the limits are 0 to a for both or m i wrong somewhere
Pleasee
.-.
What's the problem I can't understand 2nd time my ques has remained unanswered...
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.close
why ?
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which one?
Two and three
do you know the expansion of $(a-b)^2$?
!Yajat!
No
$(a-b)^2=a^2+b^2-2ab$
!Yajat!
use this to solve for the third one
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How Can We Factor The Sum Of Two Squares?
provide any question to work with
Like, How To Factor (a^2+b^2) as a product?
you mean like we can factor a^2-b^2=(a+b)(a-b) ?
there is no similar formula for a^2+b^2
Nah, The Sum Of Two Squares
a^2 + b^2 is not factorable under real numbers
You can factor it using complex numbers
product of a complex number and its conjugate, right?
But I’m talking about real numbers
And as mentioned, it's not factorable under reals
What about (a+b-sqrt(2ab))(a+b+sqrt(2ab))?
You added an extra -2ab, that expression expands to a^2 + b^2 - 2ab
What? It would be (a+b)^2-(sqrt(2ab))^2 which is equal to a^2+b^2?
You specifcally asked a^2 + b^2
No
,w expand (a+b)^2-(sqrt(2ab))^2
Weird, website said this
(a+b)^2 = a^2+b^2+2ab, (a+b)^2 -2ab = a^2 + b^2
If you want to go it that way you can, but requires more effort, if you wanted something easy like a^2 - b^2 = (a + b)(a - b) formula, then factoring a^2 + b^2 won't result into something that simple
It would be (a-bi)(a+bi)?
Yes
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I really need help with this
I just cant
I wrote almost two pages but it got messed up both times
,w 3(\sqrt{a-19}) + 4(\sqrt{b-17}) = \frac{1}{2}(a+b-11)
I would like the solution, I know the answer
S=-b/a?
Nothing
The sum of the roots of a quadratic equation
I don't think it would work
In this particular question
why dont just do this?
It's not as simple as it looks
what have you done, could you show me your solution
ik
<@&286206848099549185>
did you square both sides?
I tried it here
I'm really dumb at this kinda exercise but what I would recommend is using 19 and 17. anytime you have x and x+2, their product plus 1 is a square number
?
idk 17*19=18²-1
Oh
I'm going to try here
yeah squaring both sides is a bad idea I'm sorry
I'm trying by calling sqrt(a-19) = x and sqrt(b-17) = y
Yeah
k
this is the idea
I'm going to screenshot
After that you have to complete the squares of x and y
adding terms to both sides of the equation
doing that, it cancels 25/2, so all you have left is a sum of squares
and that sum is equal to 0
that means both terms NEED to be 0, since x²>=0, for all real x
Ok I did something different after this
Firstly I multiplied it by 2 to remove the fraction (nothing special)
Then I did:
x² - 6x = -y² + 8y -25
I completed the squares
x² - 6x + 9 = -(y² - 8y + 16)
(x-3)² = -(y-4)²
x = 3 and y = 4
And then just put in the numbers
Bro thank you
you're welcome
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this is not a bad idea
It's really simple
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made my brain thing I'm good at algebra (I'm not)
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im again not sure of my understanding of discrete functions
does the codomain of a discrete function have to be countable?
is $f:\mathbb{Z} \to \mathbb{C}$ discrete even though C is not countable?
metnal
or does the codomain not matter here as long as the range of the function is countable?
where the range is a subset of the codomain is the actual set of outputs for the domain of the function
only the range matters
you can always make the codomain bigger without really changing the function
And the range will be countable given that the domain is countable
right cuz its a function
got it, tysm
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how would i do this question?
<@&268886789983436800>
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however you yeah that
let's say Liam has a chance of x to win a given game
then can you find an expression for the chance of him to win at least one game, in terms of x?
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im unsure if im doing, this question correct, could i show my approach?
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based on the drawn graph are these points correct?
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All four are wrong - do you know the definitions of the terms in the questions?
@orchid torrentthe graph is exactly the way the problem was presented
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wouldn't this be setting the first derivative to 0?
I got 500/e^5t for my derivative, but i can't solve for 0
Plugging t=0 i to the first derivative
You want the rate at t=0, not the t at which the derivative is 0
oh shoot
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Hi is this correct?
And need guidance on how to answer number 4
AxB={(x,y) | x in A and y in B}
this doesn't make sense to me yet. can you please translate it into english
Find all combinations of (a,b) where a is in A and b is in B
For example (0,2) would be one of them
That is the relation
If you plug x and y from an ordered pair (x,y) into that and get an integer, then it is part of the relation (the ordered pair is in the set)
Seems like a big step up from the first problem lol
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Can I get some help for 48 please
Is there a specific thing you’re confused about? It looks like you got it (although the last part looks it should be converges for p>=1)
If p=1, it diverges?
I’m redoing the whole thing right now
Feel like this makes more sense?
@simple epoch
Oh wait yeah I’m dumb
Tried to make it as clear as possible
Working through it now, your work looks correct to me
All good right
I feel like separating different cases for p is easier
Alright I worked through it and got what you got so you should be good. Your reasoning looks sound and I don’t see any errors
Appreciate it
Was wondering if you could help me with one improper integral
@simple epoch
Sure
My integral of choice doesn’t help me at all
Is there something better
That I can use
Make sure you wrote that problem down correctly lmao that’s an ugly integral
They want me to compare it to another improper integral
Which makes sense I guess
Divergent
Wait
Hold on
Convergent
Your first guess was right it’s convergent
Is that always less than or greater than your main integral
Let me do this
You got it
its convergent
LGTM
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How do I find out angle C? Circle theorem maths
to find angle c cant u just do this ?
sum of angles in a triangle = 180
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is it 0.55?
Result:
26.708225867668
i already answered that one can you help me with this one?
<@&286206848099549185>
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How to solve this question? (i forgot 😦 )
I know, but i cant simplify the sqrt after simplify the Numerator
what do you mean? can you elaborate?
that's actually all you need tbh
like try to plug in the value the limit approaches
you will get something that is 1/0
that is undefined and not indeterminate
which implies...
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hi, just a quick q _ what does the A represent here. is there a specific mathematical term
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How do I do parts e and f
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How do I do this improper integral?
I know the limit part, but dont know how to actually do the integral
your fraction is just sin(4x)(1-cos(4x))^-1/5, they write it as a fraction just to make it complicated
yeh
look how (1-cos(4x))' = 4sin(4x)
substituion?
yes, it's a way to do it
take u = 1-cos(4x)
yep
but why is this improper integral?
because I get the integral is 5/ 16 * (1-cos(4x))^4/5
is it becuase you cant take sqrt(0)
so we have to do the limit
because at x = 0 the function is not defined since the denom cancels, however, the function still has a finite limit at 0, which lets the integral to converge
what u mean it cancels out?
I mean denom = 0
at x = 0, 1-cos(4x) = 0
yes
but you can't divide by 0
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i really need help
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Okay, how familiar are you with quadratic functions?
An example of a quadratic function is anything that goes up and down
i have to write it my paper
i really have no idea how to do this
and im sleepy as heck
Example: a ball if you forget about friction qnd air resistance
mhm but how do write it in the 2nd box and etc etc?
We're not gonna be able to just do the task for you so we'll need you to work with us a bit here. Have you worked with quadratic functions at all? Do you know how they look and how to calculate important values like intercepts and top/bottom points?
no 0%
Alright
Sounds like you should look into quadratics first
A quadratic function is a function on the form $f(x) = cx^2 + bx + a$, or $ax^2 + bx +c$, this often varies from country to country which way you write it
Joachim
,w plot x^2 + 4x + 4
Introduction to using the quadratic equation to solve 2nd degree polynomial equations
Watch the next lesson: https://www.khanacademy.org/math/algebra/quadratics/quadratic_odds_ends/v/quadratic-equation-part-2?utm_source=YT&utm_medium=Desc&utm_campaign=AlgebraI
Missed the previous lesson?
https://www.khanacademy.org/math/algebra/quadratics/qua...
They tend to look like something like this
i see i see
,w plot -x^2 + 10
or this
See how the sign of that first x^2 decides if the graph is "smiling", positive x^2 = smiling graph
yes yes
A real world example like animelover mentioned is throwing a ball into the air
how do i write a table that represents quadratic function?
Now we can either graph the ball travelling in the x and y direction, or just think about the y direction(height) and say the x direction is time
The table for the qudratic equation could include stuff like starting position, top position, when it hits the ground etc
i see i see
You should probably watch a video or two on the subject though to be able to do all the required tasks here
You should also probably solve these in the order 1 - 4 - 2 - 3
Decide what you want the graph to represent, then figure out an equation for it, then calculate important values, then use those values to draw it
I just did a quick Google search. There are so many real life examples. U just have to chose one
oh okay i see i see
thank you so much guys
but im really struggling to do all these im really sleepy lol
i have to submit it by tom
Watch this video series, everything by Khan Academy is very good in general
The videos are pretty short and informative
THANK YOUUUUUU
Happy to help
You might want to .close this channel in the meantime, but feel free to open a new one and ask for help later if you're struggling with particular points in the task
@gritty orchid Has your question been resolved?
how to i make table value for y=x^28x+7?
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Can someone explain 7 a) i dont understand the solution at all
what does Z x Z mean? Ik Z represents integers but why is it multiplying integers by integers
ZxZ are pairs of integers
So any pair (m,n) where m and n are integers
The x is called a Cartesian product
ah ok so then why do they sub in y, 0 for m and n then?
To show surjectivity, you need to show that for any integer y in the codomain Z, you can find some ordered pair (a,b) in the domain Z x Z such that f(a,b) = y
But this is fairly simple since f(a,b) = a - b
So if we let b = 0 and a = y, we get f(y,0)=y
So the pair (y,0) maps to y
so since any value you sub into y will give itself then its surjective?
Yes
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the gap from P_n to P_(n+1) is not good enough (like you noticed). however what about the gap from P_n to P_(n+2) ?
yes you need to consider P_(n+2)
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Okay so because dy/dx is defined implicitly, it's basically a multivariable function, like f(x,y)
So I'd make a note that you let dy/dx = f(x,y) = whatever
Then the slope of the tangent line at (a,b) is simply f(a,b)
Looks like it
Are you talking about 6
The process is the same for both questions
I’m confused isnt the vertical tangent when you make the equation equal zero
The bottom of the equation equal zero
Typically if you get something like C/0 where C is some random ass number, that's an indicator of a vertical tangent
As long as C ≠ 0
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i have a question, lets say i have a sequence.
i want the first number to be x, x is a fraction
the second number is 2x
the third number is 3x
lets say infinite is n, so nx < 1
@umbral hawk Has your question been resolved?
for example
1/2 2/3 3/4 -> works
but 1/2 starts too big
thats a good sequence, just not good enough
to big for what
1/10 2/11 3/12
i think i've got it
so
starts at 1/5
and every step it gets 1/5 closer to 1
so like
1/5 which is 0.2
then 0.2 of 0.8 which is 0.16, so 0.36 is next
how would u do it as a sequence?
1 − (4/5)^n for example
ooo thats neat
how did u get to it
if i may ask
ok i got it:
1st term: 1 - 4/5
2nd: 1 - 4/5 + (1 - 4/5) * (1 - (1 - 4/5)) = 1 - 4/5 + (1 - 4/5) * (4/5) = 1 - 4/5 + 4/5 - (4/5)^2 = 1 - (4/5)^2
3nd: 1 - (4/5)^2 + (1 - 4/5) * (1 - (1 - (4/5)^2)) = 1 - (4/5)^2 + (1 - 4/5) * ((4/5)^2) = 1 - (4/5)^2 + (4/5)^2 - (4/5)^3 = 1 - (4/5)^3
summary -> 1 - (4/5)^n
thanks @static totem
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For question 11c what do i do next here?
