#help-19

1 messages · Page 6 of 1

neon pebble
#

@blissful depot what help do u want

upper onyx
#

why?

blissful depot
#

i need help solving point B

blissful depot
upper onyx
#

well, if this is your opinion, i did it.

blissful depot
#

well, show me, please

upper onyx
#

name the side of the square a (or whatever you want). what is EC then?

upper onyx
#

i would take a/cos(15)

blissful depot
#

right, but I cannot use sin/cos, although I learned them.

#

that makes it 5 times harder not gonna lie.

upper onyx
#

you should have said that at the beginning.youre wasting my time.

blissful depot
#

sorry

blissful depot
blissful depot
#

exactly

dry scarab
odd edgeBOT
#

@blissful depot Has your question been resolved?

dry scarab
#

how is it not resolved? @blissful depot

#

more hints: A in ACF is 90°

#

FC = EC + EF

#

EF = ET

odd edgeBOT
#

@blissful depot Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed by @blissful depot

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dense vapor
#
  1. R(5,9) 2. (3,7) U (22,29)
odd edgeBOT
dense vapor
#
  1. R\ (5,9)
    That is = all numbers, but 5 and 9
    but I thought only number 5 or 9
    since (5,9) = all between
    and when R\ it reverse?
#
  1. Numbers between 3 and 7 and between 22 and 29
low locust
#

R\(5,9) is all numbers excluding the numbers between 5 and 9

#

note that 5 and 9 are included in R\(5,9)

dense vapor
#

(5,9) All numbers between 5 and 9, excluding 5 and 9

#

R(5,9) either Number 5 or 9, excluding numbers in middle

#

This is my understanding of the problem

#

Answer says, all numbers excluding middle of 5 and 9

#

@low locust Wait nvm I got it

#

Ty bro

#

.close

odd edgeBOT
#
Channel closed

Closed by @dense vapor

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rapid path
#

I would like to know how to convert a decimal number to its representation on a base of the square of 10.I have to code a program that does so and i don't get to understand the math behind it. Apparently, 9 is represented as 9, 98 as 908 and 987 as 90807. I don't understand how i have to get those numbers

wooden python
#

did you mean the square root of 10, instead of "the square of 10"?

dry scarab
#

98 = 9 * 100 + 8 987 = 9 * 10000 + 8 * 100 + 7

wooden python
#

anyway those representations look sus to me -- base sqrt(10) wouldn't have any digits above 3.

#

please show the original problem exactly as stated

#

yes even if it is in another language

rapid path
wooden python
#

the base sqrt(10) representation of 9 isn't just 9, i'm p sure.

rapid path
#

:/ My program can convert to any other base (simple base at least, such as 8, 2, 15, etc) but this one....

#

I don't see the math

dry scarab
#

looks like base 100 to base 10

wooden python
#

this is a bullshit assignment

#

give me a moment

#

the actual representation of 9 in base sqrt(10) begins with 22.20110110... and goes on forever

rapid path
#

Pretty weird of a problem

dry scarab
wooden python
#

how hard will the teacher punish you for not completing this problem?

#

if at all

rapid path
#

No punishment, it doesnt even count for my grade

wooden python
#

i've computed a few more digits for 9:
22.2011011011220130010012...

wooden python
#

it's poorly stated

#

and there's no consequence

rapid path
#

i sure will although i wont sleep this night

#

Until he explains it

young moss
#

Dude if I don’t need to know smth and don’t know it

#

I would garbage that instantly

wooden python
#

i mean like look

rapid path
#

xD maybe itll wear off my mind

wooden python
#

they WANT you to just insert zeros between each digit of the input number.

#

except the way they try to make it sound "mathy"

#

it just falls flat

dry scarab
wooden python
#

we are talking about converting base 10 to base sqrt(10).

young moss
#

I think I programmed it correctly 👀

rapid path
#

Mathematically?

young moss
#

def decimal_to_base100(decimal):
result = ""
while decimal > 0:
two_digits = decimal % 100
result = str(two_digits).zfill(2) + result
decimal //= 100
return result

#

No lmao

wooden python
#

do you people not understand

young moss
#

Seriously I thought that was the problem 💀

wooden python
#

you JUST saw me tell somebody else

#

that base 100 is NOT involved

#

at all

#

in the slightest

young moss
#

I wasn’t reading the texts :p

rapid path
#

Well if it works... Looks like the problem is either incorrectly written and it should be asking to implement something different or the answers are straight wrong

wooden python
wooden python
#

the problem is incorrectly written

#

AND IT ISN'T YOUR JOB TO FIX INCORRECTLY WORDED PROBLEMS

young moss
#

Throw that in the trash

rapid path
#

On my way!

#

Will send him an email

#

Well thank you all guys!

#

I have been having a nightmare these past 2 hours

#

.close

odd edgeBOT
#
Channel closed

Closed by @rapid path

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

turbid harness
odd edgeBOT
turbid harness
#

do we have to use the del operator here? (gradient)

#

if yes then why , like whats the proof that the del gives us normal vector because i cant find

odd edgeBOT
#

@turbid harness Has your question been resolved?

odd edgeBOT
#

@turbid harness Has your question been resolved?

turbid harness
#

.close

odd edgeBOT
#
Channel closed

Closed by @turbid harness

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

proud schooner
#

why is this the range of the graph? isn't it [2,2]? Or is it the same as that?

proud schooner
#

and why is it not a function? it does pass the vertical line test.

odd edgeBOT
#

@proud schooner Has your question been resolved?

odd edgeBOT
#

@proud schooner Has your question been resolved?

#
Channel closed

Closed by @proud schooner

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

midnight frost
#

can someone double check if my answer is correct pleasee :<<

quasi sparrow
quasi sparrow
#

,calc 223/140

clever fjordBOT
#

Result:

1.5928571428571
midnight frost
#

do i need to round it off?

quasi sparrow
midnight frost
#

i just needed to check if my answer was wrongg

#

or correct

#

T-T

#

is it 1.58 or 1.59

quasi sparrow
quasi sparrow
odd edgeBOT
#

@midnight frost Has your question been resolved?

#
Channel closed

Closed by @midnight frost

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tawdry cave
#

**

**

odd edgeBOT
manic sleet
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
zinc glacier
#

0

#

I dont know what the problem is

lavish osprey
#

-1

H̵͙͐E̸̬̤L̶̞͔P̸̢̧!̵̡̨

fallow tapir
#

Here is the solution, dont !nosol me
**

**

zinc glacier
#

!nosols

odd edgeBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

zinc glacier
#

I didnt !nosol you

#

I fpllowed your instructions

manic sleet
fallow tapir
#

but your solution is wrong according to the 'Golden Rule of Integral Kalkulus', your whole manipulation is wrong, here is a better one that is right according to the 'Bronze Rule of Differential Kalkulus":
**

**

manic sleet
fallow tapir
#

oh

#

i forgot it even existed

#

lemme thonk

manic sleet
#

ik it's pretty obscure

#

this is a good q. enegmagneto

zinc glacier
#

the Bronze Rule is not applicable here, its actually the Copper Rule if you are using the Silver Lemma

manic sleet
fallow tapir
#

but the Copper Rule isn't applicable if the integrand is under coose function.

manic sleet
#

I forgot about those

fallow tapir
#

they are horrible

manic sleet
#

that's like enemagneto theory 101 smh

fallow tapir
#

what we need to do is break the integral using grass theorem and apply pythagoras on the second part.

manic sleet
zinc glacier
#

ah right, the pythagrass method!

fallow tapir
#

ooh yes, you are right

#

this is a really good question

#

I wonder what OP is thinking

manic sleet
#

.close

odd edgeBOT
#
Channel closed

Closed by @manic sleet

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

deep turret
#

How to find the limit of $$\frac{sin x}{x} $$ assuming limit of this is when x = 0?

clever fjordBOT
#

Nerdy_Coder

deep turret
#

I can’t find a way to plugin x = 0

topaz moth
#

if x is tending to 0, sinx/x = 1

deep turret
#

How do you know that?

grizzled tide
#

lhopital probably

deep turret
#

Wdym?

topaz moth
#

yeah you can prove it using l hospital or sandwich

deep turret
#

What’s l hospital?

#

Even if x goes endlessly near 1 how do you know it’s one and not 1.00000…1

#

Or 0.999999….9

manic sleet
#

begin with $\tan\theta\geq\theta\geq\sin\theta$ for $\theta\in[0,\frac{\pi}{2})$

clever fjordBOT
#

MrFancy

grizzled tide
#

"endlessly near 1" is the same as 1

#

0.999... forever = 1

manic sleet
topaz moth
topaz moth
# deep turret How do you know that?

but yeah this is a very important identity so you should just remember it knowing that for very very small values x ~ sinx so if x is tending to 0, sinx/x = 1

deep turret
#

Identity?

#

This is a trig identity?

quasi sparrow
#

No you don't need l'hopital's

#

You use squeeze theorem

deep turret
#

How?

#

There’s only 1 function

#

and finding the limit of h is da proboem

#

Not f(x) and g(x)

deep turret
#

What is this?

manic sleet
clever fjordBOT
#

MrFancy

deep turret
#

Okay

#

That’ll find sin values how does that prove the limit is 1?

manic sleet
#

divide everything by sin

#

then flip everything over$\frac{\sin\theta}{\tan\theta}\leq\frac{\sin\theta}{\theta}\leq\frac{\sin\theta}{\sin\theta}$

clever fjordBOT
#

MrFancy

manic sleet
#

do you see how we can get the sinx/x limit? :)

deep turret
#

How did x become tan x?

manic sleet
deep turret
#

The equation was sin x/x

#

You somehow converted it to sin x/tan x

manic sleet
#

$\tan\theta\geq\theta\geq\sin\theta$\~\
$\frac{\tan\theta}{\sin\theta}\geq\frac{\theta}{\sin\theta}\geq\frac{\sin\theta}{\sin\theta}$\~\
$\frac{\sin\theta}{\tan\theta}\leq\frac{\sin\theta}{\theta}\leq\frac{\sin\theta}{\sin\theta}$

clever fjordBOT
#

MrFancy

deep turret
#

Hmm okay

manic sleet
# deep turret Hmm okay

now take the limit at you'll find the inequality squeezes to one value thats the value of the sinx/x limit! hype

deep turret
#

So you need the find the limit of the other 2 functions?

deep turret
manic sleet
#

you get cos<=sinx/x<=1

#

simple apply the limit

deep turret
#

It has to one because the other limits are one

odd edgeBOT
#

@deep turret Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

primal flume
#

The base of a straight parallelepiped is a rhombus with an area of 12 cm^2. Areas of diagonal sections are 24 cm^2 and 20 cm^2. Find the diagonals of a rhombus. help pls.

odd edgeBOT
#

@primal flume Has your question been resolved?

primal flume
#

<@&286206848099549185>

primal flume
#

<@&286206848099549185>

real arrow
#

Stfu

primal flume
odd edgeBOT
#

@primal flume Has your question been resolved?

primal flume
#

.close

odd edgeBOT
#
Channel closed

Closed by @primal flume

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
odd edgeBOT
mystic saffron
#

How do I do this

dry scarab
#

six - weight 3 then 1, eight - same

odd edgeBOT
#

@mystic saffron Has your question been resolved?

desert marlin
#

@merry finch

scarlet junco
odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dawn ivy
#

Hey I'm trying to rearrange this to use Lhospital

dawn ivy
#

Can anyone point me in the right direction?

#

<@&286206848099549185>

night raft
#

Note 0/0 isn’t the only indeterminate form where we can use LH

#

inf/inf is also valid

dawn ivy
#

Oh yeah that's right

#

Just looking for a little tip in a method to use or something

night raft
#

from the second line, you could also distribute powers to numerator and denominator, apply division limit laws, and note that the denominator’s limit exists and is nonzero
that would leave just (sin(2x))^x to worry about
But you would have to implicit diff anyway in a similar manner

clever fjordBOT
dawn ivy
#

.close

odd edgeBOT
#
Channel closed

Closed by @dawn ivy

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

verbal schooner
odd edgeBOT
verbal schooner
#

thats my work for the problem. can anyone check to make sure i did everything right? just making sure

#

why wasn't the channel renamed lol

#

oh just slow ig

odd edgeBOT
#
Channel closed

The owner is missing!

verbal schooner
#

huh

#

im right here

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cosmic sandal
#

How do you get from the top line to the bottom? This doesn't make sense to me.

cosmic sandal
#

Uhh that was supposed to be a reply.

#

.close

odd edgeBOT
#
Channel closed

Closed by @cosmic sandal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wheat apex
odd edgeBOT
wheat apex
#

could someone tell me if theres anything wrong with my proof?

#

i was thinking that maybe this part was a bit weird

#

should this be implies?

#

or even be there at all?

#

i usually see most proofs only include $0<|x-c|<d$ here

clever fjordBOT
#

Joshii

wheat apex
#

and thats it

#

but it also just made more sense to include it to me

#

does the proof still make sense with that addition? if not, why, if it does and is unecessary, why for that as well

odd edgeBOT
#

@wheat apex Has your question been resolved?

odd edgeBOT
#

@wheat apex Has your question been resolved?

odd edgeBOT
#

@wheat apex Has your question been resolved?

dry scarab
#

if a<b and a<c it doesn't follow that b<=c

#

wait, you took d=e\2

#

so 2d=e

#

and by definition d<e

wheat apex
#

so it should be 2d>e ?

#

its kindd of something i came up with after studying, nothing i rlly saw specificially before but i feel rlly comfortabl ewith it

odd edgeBOT
#

@wheat apex Has your question been resolved?

odd edgeBOT
#

@wheat apex Has your question been resolved?

wheat apex
#

Sad

tropic hazel
wheat apex
#

There's nothing wrong with it?

tropic hazel
#

Aside from your teacher giving you brutal variables

#

Instead of the usuals

#

It should be good

meager juniper
#

I agree that there isn't anything wrong with the proof. You found an appropriate delta for the epsilon.

With these proofs you normally solve them one way, and then present the proof backwards. (i.e. you find the delta from the epsilon, but when presenting the proof you use the delta you found and show that it satisfies the epsilon.) And it looks like this first step is off camera to the left.

As far as the specific thing you asked about (suppose...) it's worded a little weirdly, yeah. I would say "if [we let] foo < e, then [it follows that] 0 < bar < d", but it's not wrong, because if we suppose foo < e, then 0 < bar < d.

#

I think the weirdness is because it's not completely clear that the part after the comma is intended to be a consequence or a second supposition, so maybe just including a "then" or "=>" would help.

odd edgeBOT
#

@wheat apex Has your question been resolved?

late vessel
#

how would i get the radial acceleration of a circle if i am given the velocity and radius?

noble estuary
#

v2/r

#

where v is speed

#

and r is radius

odd edgeBOT
#
Channel closed

The owner is missing!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lone glacier
#

ive gotten the U V dv and du

odd edgeBOT
lone glacier
#

but how do i solve the int(vdu) part without doing long division

red canyon
#

$\int{udv}=uv-\int{vdu}$

clever fjordBOT
odd edgeBOT
#

@lone glacier Has your question been resolved?

lone glacier
clever fjordBOT
#

Flamester7 Tv

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

upper nimbus
#

I don’t understand why the area of a single strip is ydx?

odd edgeBOT
upper nimbus
#

Would it not be the area of a trapezium?

#

Hence (2x+dx)y/2

mint abyss
#

If you take x small enough, you can approximate the area of the trapezium with the area of a rectangle

upper nimbus
#

Yes I figured, thanks

#

.close

odd edgeBOT
#
Channel closed

Closed by @upper nimbus

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

warm rose
#

Solve the following differential equation

warm rose
barren gull
# warm rose

Isn't this a separable equation, where are you stuck?

warm rose
#

I cant continue

barren gull
clever fjordBOT
#

adzetto

barren gull
#

can also be solved using Bernoulli

warm rose
barren gull
#

oh not meant that, I mean rewrite the eq. as

$$\frac{2y\frac{dy}{dx}}{-y^2+2} \text{= }\frac{1}{x^2}$$

clever fjordBOT
#

adzetto

odd edgeBOT
#

@warm rose Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

past sandal
#

How do we do this problem

odd edgeBOT
wooden python
#

well setting up a pythagorean identity might be a good idea

past sandal
#

Lol. Our teacher didn't teach any identities

wooden python
#

???????

#

not even sin^2(x) + cos^2(x) = 1???

past sandal
#

Yea

wooden python
#

wtf

#

then this problem is impossible

past sandal
#

But he did tell us to research

#

And find identities

past sandal
#

Cuz idk

elder vault
#

Is it the Cartesian plane

past sandal
#

Cartesian eq

elder vault
past sandal
#

Yes

elder vault
#

Terrific, i never done a question like this

#

Let me try

shell oracle
past sandal
#

Ok

#

I think I got it but not sure

#

I did it

#

.close

odd edgeBOT
#
Channel closed

Closed by @past sandal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crisp echo
#

Hey ,y’all!I asked the same question yesterday,but got caught up with things,so where can I see explanations ,like how we obtained certain formulas in Math?Where can I find deep explanations pertaining to origins and relations to other formulas?

odd edgeBOT
#

@crisp echo Has your question been resolved?

brittle beacon
odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mystic saffron
odd edgeBOT
mystic saffron
#

this is a physics question but i cant do the math

#

final velocity of the ball is 15 m/s

#

i use v=root(2gx)

#

how do i know if gravity is acos(x) or asin(x)

dry scarab
#

label the diagram

mystic saffron
#

that is the picture from the assignment

#

it itsnt drawn by me

odd edgeBOT
#

@mystic saffron Has your question been resolved?

radiant merlin
#

Can you clarify what you meant in your question? I don't understand why the force due to gravity would be different

#

Also you don't even need to worry about directions here. The formula implies the use of conservation of energy

odd edgeBOT
#

@mystic saffron Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

elder sinew
#

I don't have a problem but I'm wandering if someone could explain to me what exactly a derivative is and it's applications

vague bone
#

i need help

elder sinew
#

Go to an open channel

#

Also both of those equations added together equal 180

#

4x-2+3x+14=180

#

Solve from there

stark elbow
#

@vague bone Next time open your own help channel

mystic saffron
# elder sinew I don't have a problem but I'm wandering if someone could explain to me what exa...

What is an "instantaneous rate of change" when change happens across time?
Help fund future projects: https://www.patreon.com/3blue1brown
This video was supported in part by Art of Problem Solving: https://aops.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Special thanks to these supporters: http://3b...

▶ Play video
elder sinew
#

Thank you

#

.close

odd edgeBOT
#
Channel closed

Closed by @elder sinew

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rain tundra
odd edgeBOT
rain tundra
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
rain tundra
#

$\int_{a}^{b} f(x)dx = \int_{a}^{c} f(x)dx + \int_{c}^{b} f(x)dx$

clever fjordBOT
#

Normed

rain tundra
toxic rose
#

Just find the antiderivative of cos^2 x

light violet
#

Nah you can’t here cuz it’s f(cos^2x) and you’re not given f

light violet
toxic rose
#

I missed the f 🤦‍♂️

toxic rose
odd edgeBOT
#

@rain tundra Has your question been resolved?

hollow maple
#

because if break the limits from 0 to 3pi to 0 to pi and pi to 3pi, we get I1 = I3 + pi --> 3pi (f(cosx))

rain tundra
#

king's property?

hollow maple
#

basically

#

if an integral goes from a --> b f(x)dx

#

we can say it is equal to a --> b f(a+b-x)dx

rain tundra
#

hmm okay

hollow maple
#

bludgy hell, if only it was cos^2(x)

#

but then this question wouldnt be here

#

if cos^2(x) is periodic, does that mean f(cos^2(x)) will also be periodic?

#

then that would mean I1 = 3I3 but thats clearly not an option

#

damn it

#

oh wait

#

it must be right?

#

because cos^2x keeps having the same argument after pi

#

therefore I1 = 3I3

#

and I2 = 2I3

#

So, I1 = I2 + I3

#

therefore I1 - I2 - I3 = 0 @rain tundra

hollow maple
rain tundra
#

hmm alright

#

This makes sense

#

Thanks!

#

.close

odd edgeBOT
#
Channel closed

Closed by @rain tundra

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

scenic prawn
#

what is happening between these 2 steps? (ping please)

grizzled tide
#

double angle foruma

#

or maybe its called half angle formula

scenic prawn
#

hoh

#

how does that work

grizzled tide
#

ur just applying this top line

scenic prawn
#

OHHH

#

omg

#

tysm

#

im so blind AHAHA

#

tsymm!!

grizzled tide
#

yea of course

mystic saffron
#

@scenic prawn .close whenever you r done

scenic prawn
#

how

grizzled tide
#

.close

odd edgeBOT
#
Channel closed

Closed by @grizzled tide

Use .reopen if this was a mistake.

scenic prawn
#

alr

#

.close

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tender carbon
odd edgeBOT
tender carbon
#

not allowed trigonomerty

dry scarab
#

!show

odd edgeBOT
#

Show your work, and if possible, explain where you are stuck.

tender carbon
#

ok iwill

#

i found these lengths

#

thats it

#

@dry scarab

dry scarab
#

did you use coordinates and Pythagoras to find those?

tender carbon
#

not coordinates

#

Pythagoras

#

what to do next ?

dry scarab
#

there are similar triangles

tender carbon
#

which

#

?

#

there is only one pair of triangles on picture and they are not similar

#

not only one pair lol

#

@dry scarab

dry scarab
#

look at equaliteral one

#

ABC

tender carbon
#

then ?

#

I do not seee it

dry scarab
#

Look at the left half of it

tender carbon
#

Can you wright wich triangle you mean by left ?

dry scarab
#

with vertices A and B

tender carbon
#

and the third ?

dry scarab
#

midpoint of AC

tender carbon
#

aha

#

i will draw that line

dry scarab
#

Which is also the altitude

#

Cos equaliteral is isosceles

tender carbon
dry scarab
#

yup

tender carbon
#

so you mean ABH

#

so where is similar triangle shere ?

#

can you name ?

#

tirangles ?

dry scarab
#

well, you need to find E

tender carbon
#

E?

#

what i need to find again ?

#

what is E?

#

@dry scarab

#

why are you torturing me ?

#

Can you name similar triangles here ? Or I should draw some other line ?

dry scarab
#

EF

dry scarab
odd edgeBOT
# tender carbon why are you torturing me ?

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

tender carbon
#

Yes ok but I can not see similar trinagles

#

What can i do now ? \

#

look at this picture all day ?

#

i am looking at it very long time already

tender carbon
#

@dry scarab

#

ARe you helping or not ?

dry scarab
#

!patience

odd edgeBOT
#

Please wait patiently, and do not interrupt other channels with your question. Helpers in this server are volunteers, and the server cannot guarantee that someone will be able to help you. By being impatient or begging, you will only turn potential helpers away.

In the meantime, please make sure your channel contains the original question, clearly describes what you have already tried, and states exactly what you are having trouble with. This increases your chances of getting a good response.

tender carbon
#

Ok patience is good but you have not helped me at all at this point and i am losing it

dry scarab
#

ABH is similar to EB and intersection of line through E parallel to AC

#

the same at triangle CDH

#

use Pythagoras and you are done

tender carbon
#

so ABH is similar to what ?

#

EBI ?

dry scarab
#

yup

tender carbon
#

Ok But

#

what this has to do with EF line ?

dry scarab
#

if you know EI, IH, H to line parallel to HD through F and F to CH, you know EF

tender carbon
#

what ?? :DDD

#

what line should i draw ?

#

first ?

#

just take is slow because i can not get this

dry scarab
#

find EI

tender carbon
#

EI =2

dry scarab
#

how is that

tender carbon
#

it is midsegment in ABH

#

we do not need similarities to find EI

dry scarab
#

so AH is 4?

tender carbon
#

yes

#

oh no

#

oh it is AD not AH

#

OK

#

that AD = 2sqrt3

#

and EI =sqrt 3

#

Thats correct

dry scarab
#

now what is IH

tender carbon
#

6

#

IH =

#

6

#

not 6 oh

#

3

#

IH=3

#

this si better

dry scarab
#

ok, now do exactly the same thing with triangle CDH

tender carbon
#

this line FJ should be drawn

#

?

dry scarab
#

yup

#

show that it's perp though

tender carbon
#

HJ=sqrt3

dry scarab
#

show where lines are perpendicular

tender carbon
#

what ?

#

what lines ?

dry scarab
#

Which lines on your diagram are perpendicular?

tender carbon
#

Well a lot

dry scarab
#

Label it so

tender carbon
#

i do not get it what you are saying

dry scarab
#

Draw a line parallel to BH through E and a line parallel to AC through F

#

And label all angles that are 90*

#

90°

tender carbon
#

ok

dry scarab
#

usually you draw a small square to mark 90°

tender carbon
#

I named K and L that 90 angles

dry scarab
#

I said draw a line

tender carbon
#

ok

dry scarab
#

you drew a segment

tender carbon
#

this

dry scarab
#

And there is more labeling to do

#

yup

tender carbon
#

so now pythagora ?

#

now

dry scarab
#

yup

tender carbon
#

EK = 3+1?

#

and KF = 2sqr3 ?

dry scarab
#

yup

tender carbon
#

wow

#

how you solved it ?

dry scarab
#

what?

tender carbon
#

how to soleved this problem ?

dry scarab
#

what?

tender carbon
#

how you saw that this EKF triangle has to be drawn ?

dry scarab
#

well, I looked at the diagram real hard

#

(really it's Manhattan distance)

tender carbon
#

have not you thought about other ways of solving ?

#

or this triangle was first thing in you mind ?

#

i mean EKF

#

this was the first thing you saw after hard think ?

dry scarab
#

no, I was mistakenly thinking that you need to find coordinates of E and F

#

then adjusted the solution by using Manhattan distance

tender carbon
#

Ok ofther i said it was not about coordinate s ?

#

Manhattan distance what is this ?

#

oh and this K point is on AD ? ?

#

Did you saw that too ?

dry scarab
#

Ofc, it's symmetrical along BD

tender carbon
dry scarab
#

Also G

tender carbon
#

what is symetrical ??

#

F ?

#

and G ?

dry scarab
#

the whole figure is symmetrical along BD

tender carbon
#

not EF line

#

but how you saw that G was on AD i do not get it

#

and how old are you i am just interested

dry scarab
#

this is a public channel

tender carbon
#

ok if you do not want to saty

#

Just halp me on more thing and i am gone

#

how you saw that G was on AD

dry scarab
dry scarab
#

ACD and GFD

tender carbon
dry scarab
tender carbon
#

they are not similar

#

aa

#

a see

dry scarab
#

AC|| GF

#

and ABC is equaliteral bcs ABA1=CBA1=30

tender carbon
#

OK I think you are extrimly good

#

Do you think so ?

#

Or you consider yourself as averige ?

#

average

dry scarab
#

no, i'm in uni. this is high school level stuff. don't forget to .close if there are no more q

tender carbon
#

Ok i will close it I know that but i want to make something clear to me if it is possible ?

#

maby i will close this and send you personal msg ?

dry scarab
#

dont

tender carbon
#

i need to know how good you are in math ?

#

and is this lvl high or average in you country ?

#

the lvl you are in math

#

should i shut up ? @dry scarab

#

Ok sry @dry scarab

#

thx

#

.close

odd edgeBOT
#
Channel closed

Closed by @tender carbon

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cursive cipher
#

Hi theree

odd edgeBOT
cursive cipher
#

Hope someone can help me

#

could somebody explain this to me, step by step? i don't get the whole quadratic approximation at all

mystic saffron
#

Thats what rachel asked in #help-16 , (im just amazed)

cursive cipher
#

So are you going to help us or do i have to wait for someone else?

hollow hearth
#

I can’t

cursive cipher
#

@dry scarab i saw what you sent but

#

I wanted to know where do the solutions f’(0) = 0 and f”(0) = -1 come from

dry scarab
#

((x^2+1)^-1/2)'

#

=f'(x)

#

use the chain rule

cursive cipher
#

two times right?

dry scarab
#

for f''(x) yes

cursive cipher
#

.close

odd edgeBOT
#
Channel closed

Closed by @cursive cipher

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

bitter thunder
#

Struggling with 2a) not sure how to start it / visualize it

odd edgeBOT
#

@bitter thunder Has your question been resolved?

odd edgeBOT
#

@bitter thunder Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hoary marsh
#

I'm not sure how to represent the angle in the answer box

#

I think I am supposed to do arctan(938/408) [S of E]

quasi sparrow
#

arctan(938/408) is in radians

#

so you could convert to degrees if there's no radians option

#

but it could also be "this answer has no units" since radians are unitless

hoary marsh
#

But where is the initial point of the degree?

#

Does it start East or North?

quasi sparrow
hoary marsh
odd edgeBOT
#

@hoary marsh Has your question been resolved?

quasi sparrow
hoary marsh
#

Which equals -67.5

#

Since it below +x (East)

quasi sparrow
#

,calc atan(969/402) * 180 / pi

clever fjordBOT
#

Result:

67.468359895692
hoary marsh
#

Is it right?

quasi sparrow
#

maybe rounding error

#

try putting 2 or 4 decimal places of accuracy

hoary marsh
#

It worked!

#

Thanks

#

.close

odd edgeBOT
#
Channel closed

Closed by @hoary marsh

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gilded rain
#

guys hello

#

please can anyone help me

wheat bramble
#

This channel is occupied, you can find open ones in the category above this

night raft
#

!status

odd edgeBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
gilded rain
#

i have to find AC

night raft
#

Have you solved any linear equations before?

#

Ok, then what’s the first step?

gilded rain
night raft
#

Yep

#

So go do that

#

Put all x’s on one side and put all constants on the other

gilded rain
#

5x=40 => x=8

night raft
#

Yep

#

You can combine the 32+8

#

Yep

#

What do you think we should do next?

#

Yep

#

What do you get?

#

Good

#

You’re done 🙂

odd edgeBOT
#
Channel closed

Closed by @patent cloak

Use .reopen if this was a mistake.

night raft
#

No prob

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

brittle galleon
#

Anyclue how to proceed with this probability problem?

mystic saffron
#

this feels like a binomial problem where N = 7 and p = 0.25, and you want P(X = 1)

#

Assuming they mean you have a 25% chance of getting off at each stop

#

wait wrong way round

#

N = 4 and p = 1/7

#

i think?

brittle galleon
#

wut would the equation be?

mystic saffron
#

have you done binomial distribution? I feel like I'm overcomplicating it

brittle galleon
#

this is supposed to be basic probability lol

#

Should it not be (7(4)(6))/(7^4) ?

#

.close

odd edgeBOT
#
Channel closed

Closed by @brittle galleon

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

viscid oracle
#

hello this is my question "A geometric sequence g starts 12,-3,... with 12 being term #1. Use function notation to write the recursive rule for sequence g.

odd edgeBOT
#

Show your work, and if possible, explain where you are stuck.

viscid oracle
#

this is my answer g(1)=12, g(n)=1/4 * g(n-1)

#

i dont know what could be wrong with my answer unless there is a typo

odd edgeBOT
#

@viscid oracle Has your question been resolved?

dry scarab
#

1/4*12 =/= -3

odd edgeBOT
#

@viscid oracle Has your question been resolved?

#
Channel closed

Closed by @viscid oracle

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

junior ether
#

Suppose a stock decreases by 50 percent in year one and increases 50 percent in year two. Is the stock less than, equal to, or more than its initial value.

steep thicket
#

You can sub in a simple number such as 100 and work with that.

junior ether
#

so like 100 at year 0

#

50 at year 1

steep thicket
#

Correct

junior ether
#

75 at year 2??

steep thicket
#

Correct!

#

So then, what is the stock now?

junior ether
#

its less than the orignal

steep thicket
#

Yup

#

Thats basically it

#

For a simple question like that, sub in an easy number to represent the stock and work with that to find the end solution

junior ether
#

ty

#

.close

odd edgeBOT
#
Channel closed

Closed by @junior ether

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

young moss
#

How to find the domain of the function from the just being given the function

young moss
#

supposedly

#

$y = \frac{x-2}{x+2}$

clever fjordBOT
young moss
#

how would we find the domain

#

The question says to find the domain, holes, x intercepts, y intercepts, vertical asympotes, horizontal asymtote, oblique asymptote and end behavior

heady glen
#

any value of x that doesn't lead to y being undefined will be in the domain

young moss
#

I know how to find the holes, x intercepts, y intercepts, vertical asympotes and oblique asymtotes

young moss
heady glen
#

exactly

young moss
#

so the Domain is all Real numbers except -2

heady glen
#

yup

young moss
#

There are no holes

#

Th x intercept is 2

#

The y intercept is -1

#

,w graph \frac{x-2}{x+2}

heady glen
#

more complete version of that plot

#

just to see the domain more clearly

young moss
#

Also how to find the end behaviour

#

All this has to be done without a graph

#

and without a calculator

heady glen
heady glen
#

ok so no limits

#

this is what you need to know for finding horizontal aymptotes

#

since the degree (largest power) of the numerator and denominator polynomials are the same it falls into the bottom case

#

where the asymptote = the ratio of the coefficients of the term with the highest power

young moss
#

is it just 1 for the question

#

cause 2:2

#

and x:x

#

= 1

#

How to find the end behavior?

#

do I just plug in values for x

#

and see whats happening to y?

#

<@&286206848099549185>

knotty monolith
#

lowkey its been a long time

#

so i forgot

#

sorry

toxic merlin
#

what is x

young moss
knotty monolith
young moss
#

@cold sage sorry ping but need help urgently friend

cold sage
#

whats up

young moss
#

the question ^

#

how to find end behaviour

#

from just the function

#

I literrally helped ppl on this topic, and now the day before the quiz, im comepletely blanking

cold sage
#

do you know about limits?

young moss
#

yep

#

lim f(x) = ?
x approches +-infinity

cold sage
#

yeah

cold sage
young moss
#

so for this do i do hit and trial

#

yep

#

do i like sub x as 100

#

then as 500

#

and see whats going on with the y value

cold sage
#

a trick you can use is to divide the numerator and denominator by the highest degree of x (if they have the same degree)

young moss
#

its 1/1 then ?

#

huh

cold sage
#

its indeed 1

young moss
#

so how does that give me end behaviour :p

cold sage
#

in the positive direction anyway

young moss
#

ohhh

#

I see

cold sage
#

the end behavior is it tends to 1

young moss
#

so when x is approching infinity

#

f(x) is approching 1?

#

bro what

#

that sounds wrong

#

🤮

cold sage
#

approaches 1 on both sides actually

#

you can verify it if you graph it on desmos or something

#

but the limits hold

young moss
cold sage
#

,w graph \frac{x-2}{x+2} (x from -100 to 100)

young moss
#

press more

young moss
#

wait thr is no y and x intercepts???

cold sage
#

you can loosely tell they have an asymptote at y=1

young moss
#

oh nvm its just zoome dout

young moss
#

its the ratio of the highest degree x coefficients

#

how do we find the end behaviour of the graph is x is approaching infity

#

without actually seeing the graph

cold sage
young moss
#

so hit and trial?

#

,calc (200-2)/(200+2)

clever fjordBOT
#

Result:

0.98019801980198
cold sage
#

its not really trial and error since youre just evaluating a limit

young moss
#

,calc 500-2)/(500+2)

clever fjordBOT
#

The following error occured while calculating:
Error: Unexpected operator ) (char 6)

young moss
#

,calc (500-2)/(500+2)

clever fjordBOT
#

Result:

0.99203187250996
young moss
#

this is confusing

cold sage
#

i doubt it'd be accepted to just throw increasingly large numbers into it since its not rigorous

#

all you need to do is evaluate the limit of the function as x tends to infinity and -infinity

#

which you did

young moss
cold sage
young moss
#

yeah but

#

end behaviour is smth else

#

I feel like thats wrong

#

I have this gut feeling

#

wait

cold sage
#

i mean you could go into more detail,
like as x->+inf so right end behavior, f(x) approaches 1 from below
as x->-inf so left end behavior, f(x) approaches 1 from above

#

but i dont see what more there is to say really

young moss
#

OHHH

#

I SEE

#

Thanks man

#

I have 20 practice sums

#

then ill send em here to check

#

thx

#

.close

odd edgeBOT
#
Channel closed

Closed by @young moss

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

orchid inlet
#

Hey! im having trouble using the predictor corrector method on this

orchid inlet
#

alpha =4.8

#

any ideas on where to start?

#

.close

odd edgeBOT
#
Channel closed

Closed by @orchid inlet

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

light wave
#

i know this is not necessary math but chemistry but i have no idea where 0.693 came from

light wave
cold sage
#

its ln(2) if i remember correctly

light wave
#

oh god it is

#

thank you so much

clever fjordBOT
#

The following error occured while calculating:
Error: Undefined function ln

light wave
#

.close

odd edgeBOT
#
Channel closed

Closed by @light wave

Use .reopen if this was a mistake.

weary jolt
#

,calc x = 10 x 10000

clever fjordBOT
#

The following error occured while calculating:
Error: Undefined symbol x

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rose dock
odd edgeBOT
lone mural
rose dock
lone mural
#

okay how many outcomes are there

rose dock
#

Read the top of the photo

tepid yacht
rose dock
#

What?

tepid yacht
#

How many outcomes do you have that have at least two tails?

rose dock
#

4? I don’t know

tepid yacht
#

Literally that column

#

Those are all the possible outcomes

rose dock
#

Where do I go from that

tepid yacht
#

How many of those outcomes have at least 2 tails?

odd edgeBOT
#

@rose dock Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lone mural
#

prove limit x approaches infinity $\frac{3^x}{x^3}$ is infinity

clever fjordBOT
#

dabbingpotato

lone mural
#

i know its because the numerator grows at a faster rate but we have to prove it

#

would be prove it by applying l'hopitals rule 3 times

#

to get

#

$\frac{3^x ln(3)ln(3)ln(3)}{6}$

clever fjordBOT
#

dabbingpotato

distant burrow
#

yeah that works

lone mural
#

okay thx

#

.close

odd edgeBOT
#
Channel closed

Closed by @lone mural

Use .reopen if this was a mistake.

odd edgeBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

austere rover
#
$
\begin{bmatrix}
0 & 1 & 6 & 0 & 9\\
0 & 0 & 1 & 2 &7\\
0 & 0 & 0 & 1 & 2
\end{bmatrix}
$
Can I do R2' = -(R2+R3)
is this legal?
clever fjordBOT
sharp oak
#

Yes

lost dirge
#

Yup!

sharp oak
#

I don't know why you'd want to. But you can.

austere rover
#

thanks

austere rover
#

R2' = (R2 +R3)/2

#

like this for example?

lost dirge
#

Yeah.

austere rover
#

thank you

#
$
\begin{bmatrix}
0 & 1 & 0 & 0 & -9\\
0 & 0 & 1 & 0 & 3\\
0 & 0 & 0 & 1 & 2
\end{bmatrix}
$
clever fjordBOT
austere rover
#

is this correct?

#

I tried to make it in RREF

odd edgeBOT
#

@austere rover Has your question been resolved?

austere rover
#

.close

odd edgeBOT
#
Channel closed

Closed by @austere rover

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

thin kelp
#

trying to find the coefficient of x^6 in this, this is the solution provided, i dont understand a thing

odd edgeBOT
#

@thin kelp Has your question been resolved?

odd edgeBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steep thicket
odd edgeBOT
steep thicket
#

Does this also apply to theta = 180?

dreamy thistle
#

theta = pi is the same as theta = 180, it's just degrees vs radians

#

different ways of measuring the same thing

odd edgeBOT
#

@steep thicket Has your question been resolved?

steep thicket
#

Yup nthanks

#

just wanted ot confirm