#help-17

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vocal sleetBOT
#
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vocal sleetBOT
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oblique tree
#

help

vocal sleetBOT
oblique tree
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i still dont understand derivatives..

solar cape
oblique tree
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our prof was too lazy to teach us bruh

solar cape
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$\sqrt[3]{x^2}=x^{\frac{2}{3}}$

oblique tree
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where did the 3 came from

solar cape
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Sorry the latex is not latexing

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Give me a second

oblique tree
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im rlly bad at math

twin meteorBOT
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denzio321

solar cape
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There we go

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@oblique tree

solar cape
oblique tree
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i dont get the 3/2 square root of x

solar cape
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Well can you express the square root of x in indice form

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Alright do you like

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Remember your indice laws

oblique tree
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he didnt tell us about indice laws..

solar cape
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No I mean like

oblique tree
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we're doing self learning

solar cape
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Did y'all ever learn about indice laws

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Before this class

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Not in this class

oblique tree
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idk what that iscat_happycry

solar cape
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Well fuck

oblique tree
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im cooked fr

solar cape
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So $\sqrt[n]{x}=x^{\frac{1}{n}}$

twin meteorBOT
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denzio321

solar cape
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So for sqrt(x) its the square root

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So n=2

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So sqrt(x)= x^(1/2)🙏

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Now you can use power rule

agile imp
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Basically you'll just turn the radical into its "reverse form"

solar cape
agile imp
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Cuz why not 🤷🏿

oblique tree
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do yall know the answer? cs im kinda slow learning step by step😭

solar cape
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@oblique tree do you know how to use power rule

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Just ask your teacher to stop fucking slacking

oblique tree
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i prefer studying it after getting the answerhype

agile imp
oblique tree
oblique tree
solar cape
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Anyway this is the stupidest way to get the answer

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Asking ppl online

oblique tree
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its confusing

agile imp
solar cape
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If you wanna cheat be smart

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What

agile imp
solar cape
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It's not ai

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It's just pure algorithmic computation fr

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Even gives you step by step

oblique tree
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shit

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i get it now

solar cape
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So yea if you just wanted the answer

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This is a inefficient way to do it

oblique tree
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ty ty, ill do it now

solar cape
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Go cheat faster🔥

agile imp
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Bro tolerated

oblique tree
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.close

vocal sleetBOT
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vocal sleetBOT
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heavy palm
#

Is there a way to check that you're comparing to the right thing? For Direct and Limit Comparison test?

heavy palm
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series and sequences

winter hawk
heavy palm
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what is that main condition?

winter hawk
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$\lim\frac{a_n}{b_n}=c\in(0,\infty)$

twin meteorBOT
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ロケットジャンプ

heavy palm
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ah ok

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thank u

winter hawk
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np

heavy palm
#

.close

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pseudo forge
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for an induction proof, i want my algebra in the induction step to reach 1 - 1/(m + 1), but i'm unsure what to do from what i have so far

half imp
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What's the end goal

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In order to prove the induction step what do you need to show

pseudo forge
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the end of the induction step should end up as 1 - 1/(m + 1)

half imp
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Well, it could end up as less than that as well

pseudo forge
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true. i was thinking of saying that m/(m+1) < 1

half imp
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I don't see how that helps

half imp
pseudo forge
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m/(m+1)

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wait a damn minute

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i'll type up smthn brb

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@half imp

half imp
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Yeah looks good

pseudo forge
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tyty :D catking

#

.close

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strong gyro
#

Hi! Taking calc and I’m stumped with part j) here. Pls ignore the state of my page lol
How would you go about solving that?

My answers to the other parts are these (fact checked):
g) y= (80/1849)x^2
h) (-√(1849/2)) or abt -30.4056 for the x value, y value is 40
i) y= -2.631095x - 40

Thank you sm!

vocal sleetBOT
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@strong gyro Has your question been resolved?

cunning plaza
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Okay. Had to do a double take. We can assume that when the water skier lets go of the boat, they fly in a perfectly straight line (like that line you drew then erased)

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The slope of this line is simply the derivative at the point in which you let go. That’s the definition of the derivative

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So you need to find a point on the parabola such that a line with slope equal to the derivative at that point (and obviously originating from/intersecting that point) will hit the dock

strong gyro
cunning plaza
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You can set up an equation. You can get a function (of x) for the derivative. Plug in that as your slope. Plug in the variable x and f(x) as your point (into the slope intercept formula of a line, or wtv u call it). And set the resulting x,y pair equal to the coordinates of the dock. Then you should be able to solve for x

strong gyro
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oooh ok gotcha. thank you sm!

#

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vocal sleetBOT
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mossy belfry
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How do I show that If A and B are independent and A and C intersect B are independent then A and C is independent

green crow
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Independent what?

mossy belfry
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Wdym

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Showing two events are independent in probability

green crow
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Oh, events

spiral turtle
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By the definition of independence, we have P(A and B) = P(A) P(B)

Similarly we have P(A and B and C) = P(A) P(B) P(C)

We want to prove that P(A and C) = P(A) P(C)

Consider P(A and not B and C)

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If we can prove this value is equal to what, then we can prove our goal

green crow
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If B intersection C is dependent on A, then either B or C or both B and C should be dependent on it. But since it's not, both B and C are independent of A

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That's what I think, I'm not sure whether it's the correct approach though

vocal sleetBOT
#

@mossy belfry Has your question been resolved?

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grim crow
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Looking for some help with this question. When calculating the upper flux (Circle with z=6), I get -144pi. However, answer says 144pi. Wondering where I went wrong.

grim crow
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I get the integral of -36r dr dtheta where 0<=r<=2 and 0<=theta<=2pi

flat whale
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can you show your full work

grim crow
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Sure

flat whale
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,rotate

twin meteorBOT
grim crow
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I changed the surface from the cylinder to two circles at z=6 and z=1

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From there I get the normal vector of <0,0,r>

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One thing I'm confused about is how I should orient this vector

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I realise that if I flip the orietation of this vector to be <0,0,-r> for the top and <0,0,r> for the bottom, I would get the correct answer, but not really sure why

flat whale
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use right hand rule?

grim crow
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I used right hand rule initially to determine the orietation of the boundary

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But once I switch surfaces, I'm not sure how to use right hand rule/if I can use it

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I'm not sure if you can since my working is slightly messy, but the orientation of the top circle is counterclockwise given that outward normal is used for the cylinder

flat whale
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turn your hand upside down and use right hand rule again

grim crow
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Does that mean after I swap the surface, that is my orientation?

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Ok, so I use right hand rule again to determine that after surface swap, I now have downward normal for top circle and upward normal for bottom circle?

flat whale
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you're supposed to have an outward pointing normal

grim crow
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Yea

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Im a little confused, if I use <0,0,-r> for the top circle after applying right hand rule again, isn't that not outward anymore?

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🥴 kinda confused sorry

vocal sleetBOT
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@grim crow Has your question been resolved?

grim crow
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<@&286206848099549185> sorry for the ping

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I now also have a question about this. Is there a reason why I'm not given the direction of the normal vector?

spiral turtle
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@grim crow normal vectors generally, by convention, point outward, but if you're intended to prove that the flux is zero, then the orientation of the normal vector does not matter

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(because -0 = 0)

grim crow
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I can show part b is true, but then not sure how to approach part c

spiral turtle
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Well, you can use linearity

grim crow
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I can see that I = flux of F + flux of G

spiral turtle
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F = G + <0, 0, z^2>

grim crow
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or rather yes that

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so flux of G is 0 then it's just flux of <0,0,z^2>

spiral turtle
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Yes exactly

grim crow
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However, can I use stoke's theorem here?

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Probably not right?

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Since <0,0,z^2> isn't a curl of some function?

spiral turtle
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You can just integrate over the surface

grim crow
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Ahhh so what I need here is a standard surface integral using G(theta, phi)

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Rather than trying to use line integral = curl(F)

spiral turtle
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Exactly

grim crow
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Would it be possible to help clarify some of my confusions?

spiral turtle
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And z is simply cos θ assuming you're using θ as the polar angle

spiral turtle
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Well r cos theta

grim crow
grim crow
spiral turtle
# grim crow Here's my working for this question

I'll be honest, it's been a hot minute for me and the particulars of orientations with vector surfaces. I was able to help with the sphere because I had a strong enough memory of that scenario. But edge orientation of a non-closed manifold with a hole is something I'm not super confident on.

grim crow
spiral turtle
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I can try to Google it

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Oh

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Both are rotating clockwise when viewed looking at the circle

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So if you're looking at it from the side, the top is rotating to the left, and the bottom to the right

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Essentially, imagine your normal vector as having a very small counterclockwise oriented circle around it, and move this vector around.

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When it's near the bottom, the bottom is going right at the bottom, near the top it's going left at the top

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@grim crow

grim crow
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Ok this is gonna take me some time to take in 😓

spiral turtle
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This visual might help a lot

grim crow
# spiral turtle

Just curious, so the orientation should only affect the direction of the normal right?

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The parametrization of the surface itself is independent of the direction of the normal?

spiral turtle
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If the surface normal is different so is the orientation of the edge

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But other than that, yeah

grim crow
spiral turtle
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The edge shouldn't?

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I guess if you're talking about the parametrization of the surface for the purpose of performing a surface integral it absolutely doesn't

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@grim crow

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I'm not entirely sure that a parameterization for other purposes would be independent of the edge, but for the integral, yeah absolutely, the edge doesn't matter.

grim crow
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Tysm!

vocal sleetBOT
#

@grim crow Has your question been resolved?

vocal sleetBOT
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After 15 minutes, feel free to ping <@&286206848099549185>.
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lilac sluice
#

could someone guide me through the explanation of why the curve has exactly one x-int?

paper depot
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do you know what the definition of an increasing function is?

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(hint: it does not involve derivatives)

lilac sluice
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the gradient of a line is increasing

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like the gradient at x=a

paper depot
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bad on both counts sorry

lilac sluice
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hmmm

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im not sure then

paper depot
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we say that a function is increasing if, for any a and b in its domain with a < b, we have f(a) < f(b).
which can be phrased informally as "higher inputs give higher outputs".

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an x-intercept is a value of x such that f(x) = 0.

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but if f(x) were 0 for two different x's, the definition of increasing-ness would be violated.

lilac sluice
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but f(1) doesnt equal f(0)

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oh crap

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f’(a) is equal

paper depot
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...

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f(1) should be higher than f(0)

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at no point did i imply that f(0) = f(1).,

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what i said is,

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if it were the case that f had at least two x-intercepts,
i.e. if f(SOMETHING) were equal to f(SOMETHING ELSE),
then the definition of f being an increasing function would be violated

lilac sluice
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mmmmm

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oh

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so since the function f(x) = x^3 + x - 1 is increasing

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therefore there cannot be more than 1 x-int

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hence there is only one x-int?

paper depot
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therefore there cannot be more than 1 x-int
hence there is only one x-int?

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this needs extra justification

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why does an x-int need to exist at all?

lilac sluice
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would it be because it’s a polynomial so it must intercept the x-axis at least once?

paper depot
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do you think that ALL polynomials have to have at least one x-intercept?

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yes or no

lilac sluice
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no

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cus a parabola could have no x-ints

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if its discriminant is less than 0

paper depot
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ok, so why does this polynomial of yours have to have at least one x-intercept?

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clearly the reason cannot be merely that it is a polynomial, for x^2 + 1 is also a polynomial yet lacks any x-intercept.

lilac sluice
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could i have a hint

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@paper depot would it be that since this polynomial is of odd-degree, then it must go from -inf to +inf and so it must cross the x-axis once

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which gives it its one x-int

winter hawk
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f(0)=?

lilac sluice
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f(0) is -1

winter hawk
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f(1)=?

lilac sluice
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1

winter hawk
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so is it possible to have a root between 0 and 1?

lilac sluice
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yea?

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i think

winter hawk
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if u believe it rigorously prove it

lilac sluice
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erm idk

winter hawk
#

does f have any nice relevant properties?

lilac sluice
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what does that mean

winter hawk
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does f have any property relevant to proving existence of roots

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did u learn any theorems about this

lilac sluice
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nope

winter hawk
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do u know any theorems about continuous functions

lilac sluice
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no

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only proving continuous functions with limits i have

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other than that idk abything else

winter hawk
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that sucks bc u need one here

lilac sluice
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oh

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what is it

winter hawk
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intermediate value thm

paper depot
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^

lilac sluice
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yea i haven’t learnt that

winter hawk
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heres the down n dirty

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if $f$ is continuous on $[a,b]$ and $y$ is between $f(a)$ and $f(b)$ then there exists $x\in(a,b)$ such that $y=f(x)$

twin meteorBOT
#

ロケットジャンプ

winter hawk
#

in plain speak f will hit every value between f(a) and f(b)

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thats why its called intermediate value

lilac sluice
#

but surely there’s another way we can explain the answer to this question without using this

winter hawk
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in general theres no other way 🙂

lilac sluice
#

that’s strange

winter hawk
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this is one of the most famous theorems in calc and is the strat for proving roots exist

lilac sluice
#

the tutors wouldn’t ask me smth on smth i havent learnt

lilac sluice
winter hawk
#

idk smth went wrong in the curriculum

winter hawk
#

the proof of the odd degree fact depends on my theorem

lilac sluice
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is there any other name for the theorem u stated

winter hawk
#

no

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just ask if ur prof accepts ur reason

lilac sluice
#

alrlr

winter hawk
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then yell at them to teach u the theorem 🙂

lilac sluice
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gotcha

winter hawk
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wanna see how i prove the root using my theorem?

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@lilac sluice

lilac sluice
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nah it’s fine

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i’ll ask on thursday

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cus if i learn it this week then ill learn the proof for it too

winter hawk
#

sounds good

lilac sluice
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alrlr thanks

winter hawk
#

np 🙂

lilac sluice
#

oh and for question 1

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is that the correct graph?

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@winter hawk

winter hawk
lilac sluice
#

lesh go

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for question 1, what am i missing

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im not sure if i should be drawing the curve up or down when y<0

lilac sluice
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why

winter hawk
#

this looks ok

atomic jetty
#

Because if you see the question, the value of tangent for negative x is negative

winter hawk
#

u should do it for x<0 tho

lilac sluice
winter hawk
#

u said y<0

lilac sluice
winter hawk
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slope<0 if x<0

lilac sluice
atomic jetty
#

You dont care about that rn

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You just trace the gradient of the original eqn

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I mean function

lilac sluice
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so it’s basically - 0 + 0 - 0 +

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those are the gradients of the original function

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if the gradient is negative, then the function is decreasing at that point right?

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f’(x) = y’

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so y’ < 0

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which is why the curve goes down?

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is what i said true

atomic jetty
#

Yes

lilac sluice
#

ohhhh

atomic jetty
#

Just see what is the direction of the original function at that point

lilac sluice
#

yes

vocal sleetBOT
#

@lilac sluice Has your question been resolved?

#
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hearty chasm
#

for part b. iv i dont get what its asking me for

hearty chasm
#

ive done everything up to that question

edgy kayak
dusty marlin
#

@hearty chasm If I am to assume that part a was to find the terms that agree with the individual logics, then part B should be the probability of each logic happening

dusty marlin
hearty chasm
#

ohg okay thanks

#

.close

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cyan forge
#

Im working with statics and find myself making mistakes when projecting forces in some situations like this. What is an easy way to project this mg-force in the x and y components or like what is an easy way of thinking about it?

cyan forge
edgy kayak
#

as you did, you need to change your axis

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view the normal force as the y axis and friction as x axis

cyan forge
#

But im asking with the axis as shown

edgy kayak
#

they are doing exactly what i said

cyan forge
#

Yes, but what about getting it right in terms of sin or cos

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That is what im trying to ask sorry

edgy kayak
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think about the mg vector being a hypotenuse to the triangle

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can you visualise that?

cyan forge
#

Yes

edgy kayak
#

now this angle will be equal to 30 degrees

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the top one

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then you can simply find the components

cyan forge
#

Yea okay that makes it easier

#

Okay thank you

#

.close

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stark flicker
#

Can someone explain how you would approach a problem like this?

sweet birch
#

and I'd also use the fact that sqrt(ab) = sqrt(a)sqrt(b) plus everything involved is nonnegative so you can happily multiply and divide across the inequality without issue

vocal sleetBOT
#

@stark flicker Has your question been resolved?

vocal sleetBOT
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finite hatch
#

how did it go from 2 to 4 terms

vocal sleetBOT
finite hatch
#

in the brackets

river kettle
#

bum chicken

finite hatch
#

i had a chem test today

river kettle
#

nice

finite hatch
#

and i got a pH of 19

river kettle
#

gg

finite hatch
#

am i cooked

river kettle
#

yws

finite hatch
river kettle
#

which step confuse u

finite hatch
#

um..

#

gulp

river kettle
#

where did ur cos term go

finite hatch
#

oh..

#

the firstg one is cos

#

pretend its cos

river kettle
#

it just evaporated

finite hatch
#

this question is too hard

#

im gonna do another one

river kettle
#

its not u just have to becareful with ur algebra

river kettle
finite hatch
river kettle
finite hatch
#

nop i give up

#

im doing another trest

#

thats too hard for me

river kettle
#

is not

finite hatch
#

i knew i shouldnt have done selective school past test

river kettle
#

dont give up

#

never bak down never what

finite hatch
#

bye

#

.close

vocal sleetBOT
#
Channel closed

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river kettle
finite hatch
#

i love algebvra

river kettle
#

yes so u will love this

#

is just algebra

finite hatch
#

.reopen

vocal sleetBOT
#

river kettle
#

if it makes it easeier

finite hatch
#

um.. how do I draw this..

river kettle
#

@dull bear cdCatgun

#

how do they draw this catbit

finite hatch
#

ITS HARD RIGHT

river kettle
#

no

finite hatch
#

oh

river kettle
#

u can draww anything

#

it just has to satisfy the requirements

finite hatch
#

ok how do i draw it then ugly

river kettle
#

the function is increasing for all x except 1 and 3

#

what does that look like

dull bear
#

Well catThink

river kettle
finite hatch
#

is it like this

river kettle
#

u should label x=1 and x=3

dull bear
river kettle
#

chartbit technicall what if u jst draw a massive hole at x=1 and x=3 opencry

dull bear
#

At least for the x < 1 parts, that isn't too bad, you want it to be positive, increasing, and having an asymptote at x = 1

river kettle
#

also is this not implied in the first dot point where f'>0 for all x except xneq 1 and 3

#

because if f' >0 then f>0

finite hatch
#

ITS TOO HARD RIGHT

river kettle
#

whatttt

#

u just sad kitty me

dull bear
river kettle
#

ohh

#

but like thasts a weird function

#

it doesnt count!

dull bear
river kettle
finite hatch
#

ok next question!

#

how do i do thius.//.

dull bear
#

Differentiate it and rearrange Hehe

river kettle
dull bear
finite hatch
dull bear
dull bear
finite hatch
#

-2x

dull bear
#

Yep, that (-1) should rather be -2x instead

#

But once you've done that, you can factor out a common factor between everything catokay

river kettle
#

chartbit is great a vectors too u should ask chartbit vector questions catgiggle

#

anything with geometry

dull bear
river kettle
finite hatch
#

OMG I DID IT

#

YESS

#

i am, so smart..

#

i jussst wanna thank.

#

my parents..

#

and ...

#

Jesus..

river kettle
#

thank me

finite hatch
#

for giving me this opportunjity

#

to solve this problem

#

by myself

#

thank u so much 😭

river kettle
#

blud thanked everyone but the person helping you

finite hatch
#

donmt be rude water hbeam

#

.close

vocal sleetBOT
#
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shell flax
#

hey guys im student in grade 7 i have a exam tomorrow can you help me with these math converting

green crow
shell flax
#

so i have convert like 2.7 mm to m

#

with full solution

#

mm cm dm m dam hm km

#

mass length and capacity

green crow
#

Just use this

#

2.7mm = 2.7 × 0.001m = 0.00027m

green crow
#

You can add any extra details according to your notebook's solutions

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fallow isle
vocal sleetBOT
sweet birch
#

,rcw

twin meteorBOT
fallow isle
quiet echo
#

,rccw

twin meteorBOT
fallow isle
quiet echo
#

,rccw

twin meteorBOT
quiet echo
#

Okay, which one do you want to start with?

fallow isle
#

i am new discord i don't even now how to use it

fallow isle
quiet echo
fallow isle
#

ahhh how

quiet echo
fallow isle
#

cosine = hyp/Perpendicular

fallow isle
quiet echo
fallow isle
#

idk

#

45?

vocal sleetBOT
#

@fallow isle Has your question been resolved?

vocal sleetBOT
#

@fallow isle Has your question been resolved?

shell flax
vocal sleetBOT
#

@fallow isle Has your question been resolved?

tranquil charm
#

@fallow isle

fallow isle
tranquil charm
#

So ur question

#

Is it solved or no

fallow isle
#

till no

tranquil charm
#

ok?

fallow isle
#

how they applied these formula their

tranquil charm
#

,rcacw

twin meteorBOT
fallow isle
tranquil charm
#

Nothing just rotating ur image

fallow isle
#

thanks

tranquil charm
#

so you do not understand question no 5?

fallow isle
tranquil charm
#

huh

#

so you need help with question no 5??

fallow isle
#

yes

tranquil charm
#

ok

#

so basically if we change it by 2pi (360) it basically doesn't change

#

since it just moves back to it's starting point

#

You understood that

fallow isle
#

nop

#

first when they convert rad into degreedegree

#

i solve this question by another way

#

i got correct answer

tranquil charm
#

Ok tel

fallow isle
#

but i have to use these formula to get marks

tranquil charm
#

I just see them removing pairs of 2pi

#

That is what they did?

#

They did the exact same thing @fallow isle

fallow isle
#

how

tranquil charm
#

You added it

fallow isle
#

how they know to solve these into 60degree -3(360)

tranquil charm
#

so basically

#
  • 17 pie/3
#

-17pi/3 we can take 2pi=360 and remove it hence 2pi=-6/3

#

we take 2pi out 3 times so we get -17/3 -(-18/3)

#

That is pi/3=60

fallow isle
#

i think get better understanding by written

#

can u please solve this by writing for me

tranquil charm
#

You can solve

#

Just do what I said

#

from -17pi/3 remove 2 pi

#

So did you do it?

tranquil charm
fallow isle
#

ah nice

fallow isle
#

thanks @tranquil charm

tranquil charm
#

:)

#

close then ig

fallow isle
#

how to close

#

i am new on discord

flat whale
vocal sleetBOT
fallow isle
#

.close

vocal sleetBOT
#
Channel closed

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fallow isle
#

!done

vocal sleetBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

fallow isle
vocal sleetBOT
#
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dense trout
#

does {0} under multiplication forms a group?

paper depot
#

do you think it does or do you think it doesnt

#

in either case, why

dense trout
#

chatgpt says it does not cuz in multiplication, the identity is 1, which is not present in the set....
But I think it should form a group because though 1 is the identity in multiplication in general, but in this specific case, the set only has one element which when multiplied by itself gives itself, 0.

paper depot
#

!nogpt

vocal sleetBOT
#

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

paper depot
#

but also this is a set with 1 element

dense trout
#

so......... it forms a group?

paper depot
#

0*0=0

#

it forms the trivial group, yes

#

there is literally nothing else it could be

dense trout
#

but it does not satisfies inverse property anyways.....

fleet ember
#

a way to see it is to notice that since 0 is the only element, 0*0 = 0 and 0 is an identity
but then... 0*0 = e also says that 0 is the inverse of 0, everything holds
what gpt didn't like is that it's not called 1, so it can't think correctly about the inverse

#

but you can : )

dense trout
#

ok thnx

#

.close

#

no but 0 cant be inverse of itself cuz 0/0 is not 0

#

so I think its not a group

fleet ember
#

there is no division in a group

#

an inverse is defined by the property of element * inverse = indentity

dense trout
#

oh yes

#

so it is a group....?

fleet ember
#

yes, for the 3rd time

dense trout
#

ok thanks

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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white mesa
#

Here's the translation of the problem into English:

"A diagnostic test for a rare disease has a 1% false positive rate and a 0.5% false negative rate. The incidence of this disease is 50 people per million. Calculate the probability that:

a) A person who is sick will test positive. b) A person who tests negative will be healthy. c) A person who tests positive will be sick."

white mesa
#

I'm not sure how to answer point B i'll explain my logic

#

If you test 10^6 people you expect 10^6 -50 to be sane

#

of those one hundredth are diagnozed positive

#

so 99%(10^6 -50) : 10^6 = x :100

pallid flax
white mesa
#

yeah if you could

pallid flax
vocal sleetBOT
#

@white mesa Has your question been resolved?

white mesa
#

.close

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#
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atomic hill
#

can someone help me with this

vocal sleetBOT
atomic hill
#

im a bit stuck

manic dawn
vocal sleetBOT
#

@atomic hill Has your question been resolved?

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untold meteor
#

HI everyone I am trying to derive the Sackur-Treode equation for the translational entropy of an ideal gas. Unfortunately however, I am having a lot of trouble getting the final constant of -1.15, can anyone help explain what Im missing/doing wrong

flat whale
#

your work is hard to follow without explanations

#

try adding some words for each step

untold meteor
#

well essentially, my main problem is the constant, and I think it has something to do with the "dimensionless" aspect of it

#

like im not sure if my use of units in SI is correct

flat whale
#

your error could be anywhere so it's hard to determine where unless you explain the non-obvious steps

untold meteor
#

what steps are unclear? I feel like for the most part its a straight forward derivation. there isnt any strange operations or anything

#

each step is essentially a substitution or cancelling

#

or rearrangment of ln

#

I appreciate any help

flat whale
#

¯_(ツ)_/¯

vocal sleetBOT
#

@untold meteor Has your question been resolved?

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#

@untold meteor Has your question been resolved?

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grim crow
#

Would like to double check my working here

vocal sleetBOT
grim crow
#

So once I apply Stokes theorem, I get the double integral of 4 dS where S is surface vector

#

so then I should have 4 dot unit normal dS

#

Which should give me 4sqrt3 dS?

#

Then I simply multiply 4sqrt3 by 16?

vocal sleetBOT
#

@grim crow Has your question been resolved?

winter hawk
#

,w curl[-z^2,2zx,4y-x^2]

grim crow
#

Yea and the unit normal of the surface is 1/sqrt3<1,1,1>

#

Which results in 4/sqrt3

#

However I'm unsure if I'm doing it correctly

winter hawk
#

,w [4-2x,2(x-z),2z] dot [1,1,1]

winter hawk
#

its right so far

grim crow
#

My question is what do I do from here

#

Like I feel like the answer should be sqrt3/3 * 64

#

or sorry 64*sqrt3/3

winter hawk
#

curlF.n=4/sqrt3 yes?

grim crow
#

yes

winter hawk
#

oh u rationalized the answer

#

64/sqrt3 is fine

grim crow
#

gotcha

#

ty!

winter hawk
#

np 🙂

vocal sleetBOT
#

@grim crow Has your question been resolved?

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delicate cairn
#

Could someone please help me out, on how they got from the first form to the second?

delicate cairn
#

Thanks I appreciate it!

thin vale
#

the two terms are not equivalent

#

can you show the entire context

cobalt crypt
#

probably lhopital

last harbor
#

i think it is lhopital

delicate cairn
#

It is

thin vale
#

okay that is how

last harbor
#

uhh quick question to you guys

delicate cairn
#

OH it's the derivative!

last harbor
#

do we have to use the formatting thing

#

i don't know how to do that lol

delicate cairn
#

no no i get it , sorry I see now!

last harbor
#

👍

thin vale
#

you'll pick it up quick if you try

delicate cairn
#

dumb brain moment, cheers folks

delicate cairn
#

.close

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#
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vagrant gorge
#

hi anybody here to help

vocal sleetBOT
vagrant gorge
#

😭

alpine kestrel
#

whats ur question

vagrant gorge
white whale
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
white whale
#

@vagrant gorge

vagrant gorge
#

um i think im at 1

white whale
#

Have you been taught vector?

vagrant gorge
#

no

#

and im not supposed to use vector for this

white whale
#

Okay, let's get more elementary, then.

vagrant gorge
#

aight

white whale
#

Can you sketch the movement of the boat?

vagrant gorge
#

yeah

white whale
#

Ping me if you have finished.

vocal sleetBOT
#

@vagrant gorge Has your question been resolved?

vagrant gorge
#

how do i calcualte the bearing

white whale
#

No, just the sketch first.

vagrant gorge
#

i have the sketch

white whale
#

Post it here.

vagrant gorge
#

@white whale

white whale
#

Now, from the 3km line, draw a line perpendicular to Y axis. It will form a triangle. Calculate the height and base of the triangle.

#

Then the bearing can be calculated by using atan.

vagrant gorge
#

now what do i do

#

@white whale

white whale
#

Send me the sketch, but with the vertices labelled

vagrant gorge
#

@white whale

white whale
#

I'd go with this, tbh

#

You know OA, AB. Angle BAC can be calculated from the bearing given. Now you have to find the angle BOA, which then you can use to calculate the bearing.

vagrant gorge
#

sorry had to go afk

#

back now

#

if angle bac is 110 degrees, how do i calculate BOA

#

@white whale

white whale
#

BAC is not 110 degress.

vagrant gorge
#

@white whale

white whale
#

Then you find out two of the BC, BO, and AC.

vocal sleetBOT
#

@vagrant gorge Has your question been resolved?

#
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bleak prawn
vocal sleetBOT
bleak prawn
#

The slope of the tangent on path P is y'(pi/4)/x'(pi/4)

#

x'(t) = cos(t) - 4sin(t)cos(t)

#

y'(t) = -sin(t)

#

-sin(pi/4)/(cos(pi/4) - 4sin(pi/4)cos(pi/4))

#

-(sqrt(2)/2)/(sqrt(2/2) - 4(sqrt(2/2)sqrt(2/2))

#

-(1)/(1 - 4sqrt(2/2)

#

-1/(1 - 2sqrt(2))

#

The slope of y = x + 1 is just 1

#

arctan(-1/(1 - 2sqrt(2))) - arctan(1)

#

Is that my answer?

#

<@&286206848099549185>

#

.close

vocal sleetBOT
#
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hybrid sinew
#

Hi, I can't find the answers to this question. I need to match the diagrams with the functions, can anyone help?

green crow
#

Factorise the quadratics and just do it

#

Do you need help in some specific step?

hybrid sinew
#

I've done it but not sure if I got them correct or not :/

green crow
#

Send your answers here, I'll verify it

hybrid sinew
#

B D A F H E

green crow
#

B D A F C E

hybrid sinew
green crow
#

On simplification, the equation would be 3(x+1)(x+2)

#

From this, we can say that it's C

hybrid sinew
#

But H, the derivative before x = -1.5 is negative, and after is positive

#

Also the arrows, so is H not correct?

green crow
#

$f'(x) = 6x+9$

twin meteorBOT
green crow
#

Before -1.5,

#

f'(-2) = -4

hybrid sinew
#

Right, so it is negative

green crow
#

Ok, wait

#

That one's correct

#

But

#

What about the first one?

#

$f'(x) = 2(x+1)$

twin meteorBOT
green crow
#

It should be - for x < -1 and + for x > -1

#

K, nevermind

#

That's f directly

#

Isn't it possible for a question to have 2 answers?

hybrid sinew
#

7.1 is F?

#

Isn't it B

green crow
#

No, it's B

hybrid sinew
#

Oh gotcha

#

Misunderstood

green crow
#

Nvm it

green crow
#

I think your answers are correct

#

Just a misunderstanding on my part

vocal sleetBOT
#

@hybrid sinew Has your question been resolved?

vocal sleetBOT
#
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lapis jacinth
#

find x

vocal sleetBOT
lean iris
lapis jacinth
lean iris
#

@lapis jacinth

lapis jacinth
#

yes

lean iris
#

U cant open brackets?

lapis jacinth
lean iris
#

Try to make it as (x + a)(x-b)

#

Or some general rules a² + b² = (a+b)² -2ab

lapis jacinth
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<@&286206848099549185>

lean iris
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!original

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

lapis jacinth
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@lean iris bro can u send the picture of this solution:(

lean iris
#

Dude, how do u want to solve it without general rules, and without simplification

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@lapis jacinth

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Try to solve delta and find x1 and x2

lapis jacinth
lean iris
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Dont tell me not allowed as well

vocal sleetBOT
#

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river arch
#

I'm trying to check the differentiablity of $f(z) = \bar z^2/z$ at $z = 0$

twin meteorBOT
river arch
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So I just used the limit definition of a derivative and ended up with
$$\lim_{z \to 0} \left ( \frac{\bar z}{z} \right)^2$$

twin meteorBOT
river arch
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It's given that the function is 0 at 0

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I'm having trouble going on from here now

vocal sleetBOT
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@river arch Has your question been resolved?

cyan talon
#

well seeing conj(z)/z I'm not super hopeful the limit exists

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have you tried finding two paths for which the limit of f(z)/z is different ?

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@river arch

river arch
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I checked along x = ky and all the limits are -1

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Am I allowed to do other paths like was done in multivariable calculus?

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y = x^2 and stuff

cyan talon
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so like z = x + ikx stuff like that ?

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I don't get -1 at all

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how do you end up with that ?

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@river arch

river arch
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Oh

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Wait

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😭

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I made a stupid mistake

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((1 - ik)/(1 + ik))^2 = ((1 - k^2 - 2ik)/(1 + k^2))^2

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yeah okay so different values of k give different values of the limit

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therefore it's not differentiable

cyan talon
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z=1+ik ?

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that doesn't even go through 0 mate

river arch
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if you factor the x out and cancel it?

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oh actually can't I just go into polar form

cyan talon
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yeah it works nice here

river arch
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yeah then the limit does not exist

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@cyan talon thanks a lot 🙂

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.close

vocal sleetBOT
#
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vocal sleetBOT
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heavy palm
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What am I suppose to do after this step? I don’t know how to simplify this further

heavy palm
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6

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Answer key shows me this

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I have no idea how that left expression

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Turns into that right

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How do they simplify that factorial?

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Can someone explain it to me please

alpine kestrel
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wait i legit did this worksheet in my calc class lmao

heavy palm
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I have to go afk for a bit

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So i won’t answer for awhile

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But please do help 🙏

alpine kestrel
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the left part is from ((-3)^n+1)/((-3)^n)=-3

alpine kestrel
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sorry didnt see that lol

heavy palm
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All good

alpine kestrel
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ya then u just see that 2(n+1)+1=2n+3

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and (2n+1)!/(2n+3)! = 1/(2n+2)(2n+3)

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thats where it comes from (:

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do u know the definition of factorial?

heavy palm
alpine kestrel
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bc x!=x*(x-1)!

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like (2n+3)!=(2n+3)(2n+2)(2n+1)!

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so (2n+1)!/(2n+3)!=1/(2n+2)(2n+3)

vocal sleetBOT
#

@heavy palm Has your question been resolved?

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silk cipher
#

i really dont get this

vocal sleetBOT
silk cipher
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i got 1570

paper depot
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do you know in general how to read a cumulative freq graph

paper depot
paper depot
#

ok right so... do you know what "cumulative frequency" means in general

silk cipher
silk cipher
paper depot
silk cipher
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in the chart

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the entry prices chart

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with the 0 < x< 15

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ik it isnt just < i cant find the corrent char on the keyboard

paper depot
#

ok so you found that there are:

  • 10 kids under 5
  • 60 kids aged between 5 and 15
  • 10 people aged 15 and up
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you said you don't know how to read cumulative frequency graphs, yet you just did exactly that...

silk cipher
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oh shit yeah lol

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idk how to figure out the price tho

paper depot
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an under-5y/o ticket costs £12 and there were 10 such tickets sold, how much does that give?

silk cipher
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120

paper depot
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can you do the same for the other two age categories

silk cipher
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60*20 is 1200 i think

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so 1320 so far

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plus 25*10 is 250

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so 1570

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i put that in but it said it was wrong

vocal sleetBOT
#

@silk cipher Has your question been resolved?

rigid needle
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there are 20 ppl aged from 15 up

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not 10

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the result should be 120+1200+500

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#

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gray slate
#

What's the set theory?

vocal sleetBOT
paper depot
#

Set theory is the branch of mathematical logic that studies sets, which can be informally described as collections of objects. Although objects of any kind can be collected into a set, set theory – as a branch of mathematics – is mostly concerned with those that are relevant to mathematics as a whole.
The modern study of set theory was initiated...

hushed tree
#

Set theory is the branch of mathematical logic that studies sets, which can be informally described as collections of objects. Although objects of any kind can be collected into a set, set theory – as a branch of mathematics – is mostly concerned with those that are relevant to mathematics as a whole.
The modern study of set theory was initiated...

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ah

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beat me to it

paper depot
#

Naive set theory is any of several theories of sets used in the discussion of the foundations of mathematics.
Unlike axiomatic set theories, which are defined using formal logic, naive set theory is defined informally, in natural language. It describes the aspects of mathematical sets familiar in discrete mathematics (for example Venn diagrams a...

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do you have an actual specific question to ask @gray slate

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#

@gray slate Has your question been resolved?

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strange charm
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Hi, id like someone to critize my proof

vocal sleetBOT
strange charm
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or if im doing something wrong

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i feel like second line doesnt do anything so i just got rid of it

vocal sleetBOT
#

@strange charm Has your question been resolved?

craggy crypt
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OH WAIT SHIT this is not the active question uhhhh

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sorry for the ping

vocal sleetBOT
#

@strange charm Has your question been resolved?

restive tundra
#

You've got the right idea but there are a few typos in it. For instance, you did the chain rule wrong and wrote f(x_0) instead of f'(x_0)

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You also said that g'(x_0) is differentiable instead of g(x_0)

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Some of the typesetting isn't my favorite either, if you care about that

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The second line is needed because it justifies that f is injective

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You can cut out a whole line at the end by just writing "= 0. This is a contradiction." if you wanted to make it more concise

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tawny nacelle
#

If $M \subseteq \R^n$ is an orientable $(n - 1)$-dimensional manifold, show that there is an open set $A \subseteq \R^n$ and a differentiable $g: A \to \R$ so that $M = g^{-1}(0)$ and $g'(x)$ has rank 1 for $x \in M$.

twin meteorBOT
#

higher!

tawny nacelle
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I need a hint to start this

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I literally have no idea what to do to construct this A and g

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anything will help MiniheraSorry1

vocal sleetBOT
#

@tawny nacelle Has your question been resolved?

tawny nacelle
#

okay, I got a tip somewhere else holothink

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time to see what I can do

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.close

vocal sleetBOT
#
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pulsar star
vocal sleetBOT
pulsar star
#

It seems like I’m stuck

vocal sleetBOT
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@pulsar star Has your question been resolved?

vocal sleetBOT
#

@pulsar star Has your question been resolved?

uncut anvil
#

$1 - \tan(x) = \frac{\cos(x) - \sin(x)}{\cos(x)}. \text{then use} \frac{a}{\frac{b}{c}} = \frac{ac}{b}$

twin meteorBOT
pulsar star
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oh

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oh

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nvm

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ok

proper lava
pulsar star
vocal sleetBOT
#

@pulsar star Has your question been resolved?

past sail
#

,tex $\cot(x) = \frac{\cos(x)}{\sin(x)}$

twin meteorBOT
#

salagata

past sail
past sail
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and hold on