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help
i still dont understand derivatives..
Express each root in indice form
our prof was too lazy to teach us bruh
$\sqrt[3]{x^2}=x^{\frac{2}{3}}$
where did the 3 came from
what abt this TOT
im rlly bad at math

denzio321
From here you can use power rule
i dont get the 3/2 square root of x
Well can you express the square root of x in indice form
Alright do you like
Remember your indice laws
he didnt tell us about indice laws..
No I mean like
we're doing self learning
idk what that is
Well fuck
im cooked fr
So $\sqrt[n]{x}=x^{\frac{1}{n}}$
denzio321
So for sqrt(x) its the square root
So n=2
So sqrt(x)= x^(1/2)🙏
Now you can use power rule
Basically you'll just turn the radical into its "reverse form"
Bro why am I getting skull emojied
Cuz why not 🤷🏿
do yall know the answer? cs im kinda slow learning step by step😭
@oblique tree do you know how to use power rule
Just ask your teacher to stop fucking slacking
i prefer studying it after getting the answer
We can't just give the answer instantly, we're here to teach you step by step
fr we've been backstabbing him
can u tell me
its confusing
How about do a vm
If you wanna cheat be smart
Solve derivatives using this free online calculator. Step-by-step solution and graphs included!
What

ty ty, ill do it now
Go cheat faster🔥
Bro tolerated
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Is there a way to check that you're comparing to the right thing? For Direct and Limit Comparison test?
series and sequences
yes when the main condition of limit comparison is satisfied
what is that main condition?
$\lim\frac{a_n}{b_n}=c\in(0,\infty)$
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np
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for an induction proof, i want my algebra in the induction step to reach 1 - 1/(m + 1), but i'm unsure what to do from what i have so far
the end of the induction step should end up as 1 - 1/(m + 1)
Well, it could end up as less than that as well
true. i was thinking of saying that m/(m+1) < 1
I don't see how that helps
What do you get if you simplify 1-1/(m+1)?
Yeah looks good
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Hi! Taking calc and I’m stumped with part j) here. Pls ignore the state of my page lol
How would you go about solving that?
My answers to the other parts are these (fact checked):
g) y= (80/1849)x^2
h) (-√(1849/2)) or abt -30.4056 for the x value, y value is 40
i) y= -2.631095x - 40
Thank you sm!
@strong gyro Has your question been resolved?
Okay. Had to do a double take. We can assume that when the water skier lets go of the boat, they fly in a perfectly straight line (like that line you drew then erased)
The slope of this line is simply the derivative at the point in which you let go. That’s the definition of the derivative
So you need to find a point on the parabola such that a line with slope equal to the derivative at that point (and obviously originating from/intersecting that point) will hit the dock
ohh okay. that makes sense, thank you sm!
is there a specific way to go abt this or is it just guessing from here
You can set up an equation. You can get a function (of x) for the derivative. Plug in that as your slope. Plug in the variable x and f(x) as your point (into the slope intercept formula of a line, or wtv u call it). And set the resulting x,y pair equal to the coordinates of the dock. Then you should be able to solve for x
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How do I show that If A and B are independent and A and C intersect B are independent then A and C is independent
Independent what?
Oh, events
By the definition of independence, we have P(A and B) = P(A) P(B)
Similarly we have P(A and B and C) = P(A) P(B) P(C)
We want to prove that P(A and C) = P(A) P(C)
Consider P(A and not B and C)
If we can prove this value is equal to what, then we can prove our goal
If B intersection C is dependent on A, then either B or C or both B and C should be dependent on it. But since it's not, both B and C are independent of A
That's what I think, I'm not sure whether it's the correct approach though
@mossy belfry Has your question been resolved?
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Looking for some help with this question. When calculating the upper flux (Circle with z=6), I get -144pi. However, answer says 144pi. Wondering where I went wrong.
I get the integral of -36r dr dtheta where 0<=r<=2 and 0<=theta<=2pi
can you show your full work
,rotate
I changed the surface from the cylinder to two circles at z=6 and z=1
From there I get the normal vector of <0,0,r>
One thing I'm confused about is how I should orient this vector
I realise that if I flip the orietation of this vector to be <0,0,-r> for the top and <0,0,r> for the bottom, I would get the correct answer, but not really sure why
use right hand rule?
I used right hand rule initially to determine the orietation of the boundary
But once I switch surfaces, I'm not sure how to use right hand rule/if I can use it
I'm not sure if you can since my working is slightly messy, but the orientation of the top circle is counterclockwise given that outward normal is used for the cylinder
turn your hand upside down and use right hand rule again
Does that mean after I swap the surface, that is my orientation?
Ok, so I use right hand rule again to determine that after surface swap, I now have downward normal for top circle and upward normal for bottom circle?
you're supposed to have an outward pointing normal
Yea
Im a little confused, if I use <0,0,-r> for the top circle after applying right hand rule again, isn't that not outward anymore?
🥴 kinda confused sorry
@grim crow Has your question been resolved?
<@&286206848099549185> sorry for the ping
I now also have a question about this. Is there a reason why I'm not given the direction of the normal vector?
@grim crow normal vectors generally, by convention, point outward, but if you're intended to prove that the flux is zero, then the orientation of the normal vector does not matter
(because -0 = 0)
I see, but how about for part c?
I can show part b is true, but then not sure how to approach part c
Well, you can use linearity
I can see that I = flux of F + flux of G
F = G + <0, 0, z^2>
Yes exactly
However, can I use stoke's theorem here?
Probably not right?
Since <0,0,z^2> isn't a curl of some function?
You can just integrate over the surface
Ahhh so what I need here is a standard surface integral using G(theta, phi)
Rather than trying to use line integral = curl(F)
Exactly
sorry coming back to this question
Would it be possible to help clarify some of my confusions?
And z is simply cos θ assuming you're using θ as the polar angle
Yep, gotcha.
Well r cos theta
Here's my working for this question
but r=1 so it's just cos theta
I'll be honest, it's been a hot minute for me and the particulars of orientations with vector surfaces. I was able to help with the sphere because I had a strong enough memory of that scenario. But edge orientation of a non-closed manifold with a hole is something I'm not super confident on.
Gotcha. Ty! If you wanna through you're opinion in, that'd be great too
I can try to Google it
Oh
Both are rotating clockwise when viewed looking at the circle
So if you're looking at it from the side, the top is rotating to the left, and the bottom to the right
Essentially, imagine your normal vector as having a very small counterclockwise oriented circle around it, and move this vector around.
When it's near the bottom, the bottom is going right at the bottom, near the top it's going left at the top
@grim crow
Ok this is gonna take me some time to take in 😓
Just curious, so the orientation should only affect the direction of the normal right?
The parametrization of the surface itself is independent of the direction of the normal?
If the surface normal is different so is the orientation of the edge
But other than that, yeah
but the edge doesn't affect the parametrization of the surface though no?
The edge shouldn't?
I guess if you're talking about the parametrization of the surface for the purpose of performing a surface integral it absolutely doesn't
@grim crow
I'm not entirely sure that a parameterization for other purposes would be independent of the edge, but for the integral, yeah absolutely, the edge doesn't matter.
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could someone guide me through the explanation of why the curve has exactly one x-int?
do you know what the definition of an increasing function is?
(hint: it does not involve derivatives)
bad on both counts sorry
we say that a function is increasing if, for any a and b in its domain with a < b, we have f(a) < f(b).
which can be phrased informally as "higher inputs give higher outputs".
an x-intercept is a value of x such that f(x) = 0.
but if f(x) were 0 for two different x's, the definition of increasing-ness would be violated.
...
f(1) should be higher than f(0)
at no point did i imply that f(0) = f(1).,
what i said is,
if it were the case that f had at least two x-intercepts,
i.e. if f(SOMETHING) were equal to f(SOMETHING ELSE),
then the definition of f being an increasing function would be violated
mmmmm
oh
so since the function f(x) = x^3 + x - 1 is increasing
therefore there cannot be more than 1 x-int
hence there is only one x-int?
therefore there cannot be more than 1 x-int
hence there is only one x-int?
this needs extra justification
why does an x-int need to exist at all?
would it be because it’s a polynomial so it must intercept the x-axis at least once?
ok, so why does this polynomial of yours have to have at least one x-intercept?
clearly the reason cannot be merely that it is a polynomial, for x^2 + 1 is also a polynomial yet lacks any x-intercept.
could i have a hint
@paper depot would it be that since this polynomial is of odd-degree, then it must go from -inf to +inf and so it must cross the x-axis once
which gives it its one x-int
f(0)=?
f(0) is -1
f(1)=?
1
so is it possible to have a root between 0 and 1?
if u believe it rigorously prove it
erm idk
does f have any nice relevant properties?
what does that mean
does f have any property relevant to proving existence of roots
did u learn any theorems about this
nope
do u know any theorems about continuous functions
no
only proving continuous functions with limits i have
other than that idk abything else
that sucks bc u need one here
intermediate value thm
^
yea i haven’t learnt that
heres the down n dirty
if $f$ is continuous on $[a,b]$ and $y$ is between $f(a)$ and $f(b)$ then there exists $x\in(a,b)$ such that $y=f(x)$
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in plain speak f will hit every value between f(a) and f(b)
thats why its called intermediate value
but surely there’s another way we can explain the answer to this question without using this
in general theres no other way 🙂
that’s strange
this is one of the most famous theorems in calc and is the strat for proving roots exist
the tutors wouldn’t ask me smth on smth i havent learnt
i’ll probably be learning it this week then, or over the next few weeks
idk smth went wrong in the curriculum
so this is invalid?
the proof of the odd degree fact depends on my theorem
is there any other name for the theorem u stated
alrlr
then yell at them to teach u the theorem 🙂
gotcha
nah it’s fine
i’ll ask on thursday
cus if i learn it this week then ill learn the proof for it too
sounds good
alrlr thanks
np 🙂
yes
lesh go
for question 1, what am i missing
im not sure if i should be drawing the curve up or down when y<0
why
this looks ok
Because if you see the question, the value of tangent for negative x is negative
u should do it for x<0 tho
yea that’s what im asking for rn
u said y<0
oh whoops
slope<0 if x<0
but if i draw the curve down then the gradient becomes positive
You dont care about that rn
You just trace the gradient of the original eqn
I mean function
so it’s basically - 0 + 0 - 0 +
those are the gradients of the original function
if the gradient is negative, then the function is decreasing at that point right?
f’(x) = y’
so y’ < 0
which is why the curve goes down?
is what i said true
Yes
ohhhh
Just see what is the direction of the original function at that point
yes
@lilac sluice Has your question been resolved?
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for part b. iv i dont get what its asking me for
ive done everything up to that question
@hearty chasm If I am to assume that part a was to find the terms that agree with the individual logics, then part B should be the probability of each logic happening
Use this for part biv ^
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Im working with statics and find myself making mistakes when projecting forces in some situations like this. What is an easy way to project this mg-force in the x and y components or like what is an easy way of thinking about it?
as you did, you need to change your axis
view the normal force as the y axis and friction as x axis
But im asking with the axis as shown
they are doing exactly what i said
Yes, but what about getting it right in terms of sin or cos
That is what im trying to ask sorry
Yes
now this angle will be equal to 30 degrees
the top one
then you can simply find the components
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Can someone explain how you would approach a problem like this?
well you've got xy on one part and abc on the other, so I'd start by unifying those somehow
and I'd also use the fact that sqrt(ab) = sqrt(a)sqrt(b) plus everything involved is nonnegative so you can happily multiply and divide across the inequality without issue
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how did it go from 2 to 4 terms
bum chicken
nice
and i got a pH of 19
gg
am i cooked
yws
help me with this
which step confuse u
where did ur cos term go
it just evaporated
its not u just have to becareful with ur algebra
what did it say the answer was
try the second derivative again
is not
i knew i shouldnt have done selective school past test
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differentiation is just algebra with extra steps!
omg real;ly
i love algebvra
.reopen
✅
if it makes it easeier
no
oh
ok how do i draw it then ugly
Well 

u should label x=1 and x=3
You need a vertical asymptote at x = 1 as well
chartbit technicall what if u jst draw a massive hole at x=1 and x=3 

At least for the x < 1 parts, that isn't too bad, you want it to be positive, increasing, and having an asymptote at x = 1
also is this not implied in the first dot point where f'>0 for all x except xneq 1 and 3
because if f' >0 then f>0
ITS TOO HARD RIGHT
Not necessarily, e.g. f(x) = ln(x)
You're a weird function 
draw the first 2 dot points
Differentiate it and rearrange 
Agreed!


Careful, what's the derivative of -x^2 + 1?
Yep, that (-1) should rather be -2x instead
But once you've done that, you can factor out a common factor between everything 
chartbit is great a vectors too u should ask chartbit vector questions 
anything with geometry



OMG I DID IT
YESS
i am, so smart..
i jussst wanna thank.
my parents..
and ...
Jesus..
thank me
for giving me this opportunjity
to solve this problem
by myself
thank u so much 😭
blud thanked everyone but the person helping you
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hey guys im student in grade 7 i have a exam tomorrow can you help me with these math converting
Tell what you need the help with
so i have convert like 2.7 mm to m
with full solution
mm cm dm m dam hm km
mass length and capacity
I'm not sure what steps they taught you as the full solution, but this should be it
You can add any extra details according to your notebook's solutions
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,rcw
,rccw
Okay, which one do you want to start with?
i am new discord i don't even now how to use it
this one
^
ahhh how
Do you know, fundamentally, what cosine represents?
cosine = hyp/Perpendicular
.
So, if we use a right isosceles triangle, what angles does it have?
@fallow isle Has your question been resolved?
@fallow isle Has your question been resolved?
thank you so much man
@fallow isle Has your question been resolved?
@fallow isle
yes
ok?
,rcacw
what does these mean?
Nothing just rotating ur image
thanks
so you do not understand question no 5?
i have get answer of the other question from another group
yes
ok
so basically if we change it by 2pi (360) it basically doesn't change
since it just moves back to it's starting point
You understood that
nop
first when they convert rad into degreedegree
i solve this question by another way
i got correct answer
Ok tel
I just see them removing pairs of 2pi
That is what they did?
They did the exact same thing @fallow isle
how
You added it
how they know to solve these into 60degree -3(360)
so basically
-17pi/3 we can take 2pi=360 and remove it hence 2pi=-6/3
we take 2pi out 3 times so we get -17/3 -(-18/3)
That is pi/3=60
i think get better understanding by written
can u please solve this by writing for me
Ok so what they did is you get -1020 degrees and since you can add/subtract 360 and it doesn't change so you find multiples of 360 so 360 x 3=1080 and then -(360*3)=-1080 so we do -1020 - (-1080) and we get 60
ah nice
i convert it into degreen from rad
thanks @tranquil charm
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!done
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thanks
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does {0} under multiplication forms a group?
chatgpt says it does not cuz in multiplication, the identity is 1, which is not present in the set....
But I think it should form a group because though 1 is the identity in multiplication in general, but in this specific case, the set only has one element which when multiplied by itself gives itself, 0.
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
but also this is a set with 1 element
so......... it forms a group?
but it does not satisfies inverse property anyways.....
a way to see it is to notice that since 0 is the only element, 0*0 = 0 and 0 is an identity
but then... 0*0 = e also says that 0 is the inverse of 0, everything holds
what gpt didn't like is that it's not called 1, so it can't think correctly about the inverse
but you can : )
ok thnx
.close
no but 0 cant be inverse of itself cuz 0/0 is not 0
so I think its not a group
there is no division in a group
an inverse is defined by the property of element * inverse = indentity
yes, for the 3rd time
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Here's the translation of the problem into English:
"A diagnostic test for a rare disease has a 1% false positive rate and a 0.5% false negative rate. The incidence of this disease is 50 people per million. Calculate the probability that:
a) A person who is sick will test positive. b) A person who tests negative will be healthy. c) A person who tests positive will be sick."
I'm not sure how to answer point B i'll explain my logic
If you test 10^6 people you expect 10^6 -50 to be sane
of those one hundredth are diagnozed positive
so 99%(10^6 -50) : 10^6 = x :100
this is a mathematical "paradox" I'm pretty sure I've seen something really similar on YouTube, would you like me to see if I can find the video
yeah if you could
About Likelihood Ratios, also sometimes called Bayes Factors*.
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The book by my friend Matt Cook ab...
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can someone help me with this
im a bit stuck
for the inductive step, start by multiplying both sides by (2(n+1)+1)/(2(n+1))
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HI everyone I am trying to derive the Sackur-Treode equation for the translational entropy of an ideal gas. Unfortunately however, I am having a lot of trouble getting the final constant of -1.15, can anyone help explain what Im missing/doing wrong
well essentially, my main problem is the constant, and I think it has something to do with the "dimensionless" aspect of it
like im not sure if my use of units in SI is correct
your error could be anywhere so it's hard to determine where unless you explain the non-obvious steps
what steps are unclear? I feel like for the most part its a straight forward derivation. there isnt any strange operations or anything
each step is essentially a substitution or cancelling
or rearrangment of ln
I appreciate any help
¯_(ツ)_/¯
@untold meteor Has your question been resolved?
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Would like to double check my working here
So once I apply Stokes theorem, I get the double integral of 4 dS where S is surface vector
so then I should have 4 dot unit normal dS
Which should give me 4sqrt3 dS?
Then I simply multiply 4sqrt3 by 16?
@grim crow Has your question been resolved?
,w curl[-z^2,2zx,4y-x^2]
Yea and the unit normal of the surface is 1/sqrt3<1,1,1>
Which results in 4/sqrt3
However I'm unsure if I'm doing it correctly
,w [4-2x,2(x-z),2z] dot [1,1,1]
its right so far
My question is what do I do from here
Like I feel like the answer should be sqrt3/3 * 64
or sorry 64*sqrt3/3
curlF.n=4/sqrt3 yes?
yes
np 🙂
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Could someone please help me out, on how they got from the first form to the second?
heya let me take a look
Thanks I appreciate it!
probably lhopital
i think it is lhopital
It is
okay that is how
uhh quick question to you guys
OH it's the derivative!
no no i get it , sorry I see now!
👍
You don't have to but you should figure out how to use it, its fairly easy and very useful
you'll pick it up quick if you try
dumb brain moment, cheers folks
perhaps i will then thanks 
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hi anybody here to help
😭
whats ur question
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@vagrant gorge
sorry i left cos nobody responded
um i think im at 1
Have you been taught vector?
Okay, let's get more elementary, then.
aight
Can you sketch the movement of the boat?
yeah
Ping me if you have finished.
@vagrant gorge Has your question been resolved?
no i need help
how do i calcualte the bearing
No, just the sketch first.
i have the sketch
Post it here.
Now, from the 3km line, draw a line perpendicular to Y axis. It will form a triangle. Calculate the height and base of the triangle.
Then the bearing can be calculated by using atan.
ok ive done this
now what do i do
@white whale
Send me the sketch, but with the vertices labelled
I'd go with this, tbh
You know OA, AB. Angle BAC can be calculated from the bearing given. Now you have to find the angle BOA, which then you can use to calculate the bearing.
sorry had to go afk
back now
if angle bac is 110 degrees, how do i calculate BOA
@white whale
Uh, what?
BAC is not 110 degress.
Then you find out two of the BC, BO, and AC.
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The slope of the tangent on path P is y'(pi/4)/x'(pi/4)
x'(t) = cos(t) - 4sin(t)cos(t)
y'(t) = -sin(t)
-sin(pi/4)/(cos(pi/4) - 4sin(pi/4)cos(pi/4))
-(sqrt(2)/2)/(sqrt(2/2) - 4(sqrt(2/2)sqrt(2/2))
-(1)/(1 - 4sqrt(2/2)
-1/(1 - 2sqrt(2))
The slope of y = x + 1 is just 1
arctan(-1/(1 - 2sqrt(2))) - arctan(1)
Is that my answer?
<@&286206848099549185>
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Hi, I can't find the answers to this question. I need to match the diagrams with the functions, can anyone help?
I've done it but not sure if I got them correct or not :/
Send your answers here, I'll verify it
B D A F H E
B D A F C E
why is H incorrect?
On simplification, the equation would be 3(x+1)(x+2)
From this, we can say that it's C
But H, the derivative before x = -1.5 is negative, and after is positive
Also the arrows, so is H not correct?
$f'(x) = 6x+9$
Suika
Right, so it is negative
Suika
It should be - for x < -1 and + for x > -1
K, nevermind
That's f directly
Isn't it possible for a question to have 2 answers?
No, it's B
Is it?
I think your answers are correct
Just a misunderstanding on my part
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find x
Try openning brackets and abbreviation.
I cant bracket:(
@lapis jacinth
yes
U cant open brackets?
yes
i cant:(
<@&286206848099549185>
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
can u do it for me
@lean iris bro can u send the picture of this solution:(
Dude, how do u want to solve it without general rules, and without simplification
@lapis jacinth
Try to solve delta and find x1 and x2
;v
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I'm trying to check the differentiablity of $f(z) = \bar z^2/z$ at $z = 0$
dyxn
So I just used the limit definition of a derivative and ended up with
$$\lim_{z \to 0} \left ( \frac{\bar z}{z} \right)^2$$
dyxn
@river arch Has your question been resolved?
well seeing conj(z)/z I'm not super hopeful the limit exists
have you tried finding two paths for which the limit of f(z)/z is different ?
@river arch
Yeah I know that limit doesn't exist
I checked along x = ky and all the limits are -1
Am I allowed to do other paths like was done in multivariable calculus?
y = x^2 and stuff
hmmmmm
so like z = x + ikx stuff like that ?
I don't get -1 at all
how do you end up with that ?
@river arch
Oh
Wait
😭
I made a stupid mistake
((1 - ik)/(1 + ik))^2 = ((1 - k^2 - 2ik)/(1 + k^2))^2
yeah okay so different values of k give different values of the limit
therefore it's not differentiable
yeah it works nice here
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What am I suppose to do after this step? I don’t know how to simplify this further
6
Answer key shows me this
I have no idea how that left expression
Turns into that right
How do they simplify that factorial?
Can someone explain it to me please
wait i legit did this worksheet in my calc class lmao
the left part is from ((-3)^n+1)/((-3)^n)=-3
This is what I did so far
sorry didnt see that lol
All good
ya then u just see that 2(n+1)+1=2n+3
and (2n+1)!/(2n+3)! = 1/(2n+2)(2n+3)
thats where it comes from (:
do u know the definition of factorial?
I understand the line above this but how do they simplify into that? Removing the factorial
bc x!=x*(x-1)!
like (2n+3)!=(2n+3)(2n+2)(2n+1)!
so (2n+1)!/(2n+3)!=1/(2n+2)(2n+3)
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i really dont get this
i got 1570
do you know in general how to read a cumulative freq graph
show work?
ok right so... do you know what "cumulative frequency" means in general
top line approx 10
second line approx 60
thrid line 10
the frequency with the previous added
wdym by "top line"?
in the chart
the entry prices chart
with the 0 < x< 15
ik it isnt just < i cant find the corrent char on the keyboard
ok so you found that there are:
you said you don't know how to read cumulative frequency graphs, yet you just did exactly that...
the price for each age category is literally given to you
an under-5y/o ticket costs £12 and there were 10 such tickets sold, how much does that give?
120
can you do the same for the other two age categories
60*20 is 1200 i think
so 1320 so far
plus 25*10 is 250
so 1570
i put that in but it said it was wrong
@silk cipher Has your question been resolved?
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What's the set theory?
Set theory is the branch of mathematical logic that studies sets, which can be informally described as collections of objects. Although objects of any kind can be collected into a set, set theory – as a branch of mathematics – is mostly concerned with those that are relevant to mathematics as a whole.
The modern study of set theory was initiated...
Set theory is the branch of mathematical logic that studies sets, which can be informally described as collections of objects. Although objects of any kind can be collected into a set, set theory – as a branch of mathematics – is mostly concerned with those that are relevant to mathematics as a whole.
The modern study of set theory was initiated...
ah
beat me to it
Naive set theory is any of several theories of sets used in the discussion of the foundations of mathematics.
Unlike axiomatic set theories, which are defined using formal logic, naive set theory is defined informally, in natural language. It describes the aspects of mathematical sets familiar in discrete mathematics (for example Venn diagrams a...
do you have an actual specific question to ask @gray slate
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Hi, id like someone to critize my proof
or if im doing something wrong
i feel like second line doesnt do anything so i just got rid of it
yes isr
@strange charm Has your question been resolved?
mfw they draw the discrete random variable like a continuous one
OH WAIT SHIT this is not the active question uhhhh
sorry for the ping
@strange charm Has your question been resolved?
You've got the right idea but there are a few typos in it. For instance, you did the chain rule wrong and wrote f(x_0) instead of f'(x_0)
You also said that g'(x_0) is differentiable instead of g(x_0)
Some of the typesetting isn't my favorite either, if you care about that
The second line is needed because it justifies that f is injective
You can cut out a whole line at the end by just writing "= 0. This is a contradiction." if you wanted to make it more concise
@strange charm Has your question been resolved?
Thank you!
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If $M \subseteq \R^n$ is an orientable $(n - 1)$-dimensional manifold, show that there is an open set $A \subseteq \R^n$ and a differentiable $g: A \to \R$ so that $M = g^{-1}(0)$ and $g'(x)$ has rank 1 for $x \in M$.
higher!
I need a hint to start this
I literally have no idea what to do to construct this A and g
anything will help 
@tawny nacelle Has your question been resolved?
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@pulsar star Has your question been resolved?
@pulsar star Has your question been resolved?
$1 - \tan(x) = \frac{\cos(x) - \sin(x)}{\cos(x)}. \text{then use} \frac{a}{\frac{b}{c}} = \frac{ac}{b}$
8n2
i already did that i think
oh
oh
nvm
ok
yup i did it like that thanks for confirming
@pulsar star Has your question been resolved?
first express cot(x) as cos(x)/sin(x)
,tex $\cot(x) = \frac{\cos(x)}{\sin(x)}$
salagata
yes