Close but no
#help-17
fresh tendon
i tend to overthink yeah
fresh tendon
so 3
blazing wigeon
Yes
vocal sleetBOT
@fresh tendon Has your question been resolved?
vocal sleetBOT
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Available help channel!
acoustic patrol
Its not correct but which line is it?
vocal sleetBOT
Its not correct but which line is it?
acoustic patrol
I picked line 3 first and got it wrong, so it must be line 2 then right?
torn oracle
it does look like the error is the 4th line
acoustic patrol
It was 2nd line
I gambled and got it right
The question sucks because what's a line???
vocal sleetBOT
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Available help channel!
radiant cradle
im having a really hard time visualizing this
vocal sleetBOT
im having a really hard time visualizing this
radiant cradle
im not sure how to apporach it
vocal sleetBOT
@radiant cradle Has your question been resolved?
mint jay
im not sure how to apporach it
What have you tried?
radiant cradle
What have you tried?
i drawed it out
mint jay
Show your work.
mint jay
but like how to apporach it
What have u tried?
radiant cradle
What have u tried?
i know the center to all the edges is the same
but i dont know how to use that
as i said, i dont really have an idea
grand basin
what is the formula for surgface area
mint jay
Do you know what circumsphere means?
radiant cradle
surface area of sphere is 4 pi r^2
radiant cradle
the radius of the sphere ??
mint jay
surface area of sphere is 4 pi r^2
What do you not have here?
mint jay
the radius of the sphere ??
Correct.
grand basin
correct.
radiant cradle
so like how do i approach this
mint jay
Did you not read your notes?
radiant cradle
u can do surface area/4 pi
but like thats useless
because u dont even have the radius
so u cant solve for the surface area
grand basin
well you can find the radius
radiant cradle
Did you not read your notes?
wht do you mean 😭
mint jay
im not sure 😭
This is a very basic problem, it seems like you haven't read your teacher's notes.
grand basin
how would you find the radius
radiant cradle
This is a very basic problem, it seems like you haven't read your teacher's note...
well
😭
uhh
mint jay
Just be honest...
radiant cradle
if i could solve it i wouldnt be asking it rn
mint jay
Did you skip reading the notes or textbook?
radiant cradle
if you think its basic can u just walk me through it then
grand basin
oh
radiant cradle
Did you skip reading the notes or textbook?
why are you accusing me of not reading the notes or textbook? 😭
grand basin
so now you want the answer on a gold platter
radiant cradle
i dont have a textbook, this is a class
radiant cradle
so now you want the answer on a gold platter
i never said to give me the answer HAHAHA
mint jay
why are you accusing me of not reading the notes or textbook? 😭
Because it's obvious, you didn't bother to read the notes?
grand basin
radiant cradle
u guys aren't really helping 💔
radiant cradle
Because it's obvious, you didn't bother to read the notes?
well i did 😭 ???
you might think its an easy problem but i might think its difficult
by saying that you're kind of calling me stupid
so please don't do that, that's really offensive
especially i see that you're an undergrad student, i'm a highschool student
so why not be a little bit more kindhearted
if you call the problem easy, then walk me throug hit
mint jay
Sure
grand basin
sure
mint jay
Well, we need R.
radiant cradle
yeah
mint jay
The circumsphere radius is given by:
R = (sqrt(6) (V) ) / A
Can you tell me what V and A are?
radiant cradle
so i was not aware of this formula at all :Sob
mint jay
That's okay
radiant cradle
okay let me solve for the volume
grand basin
happens to the best
mint jay
okay let me solve for the volume
Do you know how?
radiant cradle
yeah
radiant cradle
surface area
grand basin
why would it represent surface area
radiant cradle
bro you arent even helping so can you stop
mint jay
surface area
No.
grand basin
first of all
mint jay
Yes, sorry.
grand basin
dont assume my gender
its offensive
if you can be more kind hearted
i would muhc appreciate that
mint jay
surface area
It represents the total area of all 4 faces, good job.
radiant cradle
dont assume my gender
u are trolling 💀
grand basin
IM TRYING TO GUIDE YOU
mint jay
So once you find V and A, plug it into the equation above and then that gives you R. You then plug R into the 4piR^2 equation for the final answer.
mint jay
No problem, good luck!
radiant cradle
can you explain why he is right
first of all
do not assume their gender
that is very disrespectful
please be more kindhearted
and secondly, i was not aware of the formula so now i know how to do the problem
modest dirge
For what it’s worth this isn’t a very “easy” problem these people are not being very nice
Geometry can be quite cumbersome for some people
I finished my math bachelors and things like this still fuck me up
radiant cradle
wait you have to use vectors for the volume
radiant cradle
For what it’s worth this isn’t a very “easy” problem these people are not being ...
thank you 😭 🙏
is there a way not to use vectors and just use geometry
modest dirge
If you just ignore the sphere for now
Could you find the distance from the centroid of the tetrahedron to one of the vertices
Because if you can
It might be easier to think about
And that would be precisely the radius of the sphere
So you can use your surface area formula
Think about the 2D case first
Draw a triangle
And try to find the distance from the centroid of the triangle to one of the vertices
How could you approach that simpler problem?
radiant cradle
Could you find the distance from the centroid of the tetrahedron to one of the v...
yeah thats what im trying to find
modest dirge
Ok so try with the 2D case for enlightenment sake
Haha
It’s almost always easier to start with a simpler problem and build up
radiant cradle
oh
u mean like
this type?
tahnk u for helping me again 😭 my mood is kinda ruined from those two but thank u again for helping me 💖
modest dirge
So do you that if you draw a circumcircle then the distance from the centre of the triangle to one of the vertices is exactly the radius?
Can you find that length?
If you need a bigger hint I got you
Also the top two side lengths should be 3 right?
Since its not equilateral in your case
radiant cradle
Also the top two side lengths should be 3 right?
yes
but the thing is i have no idea where the center is and like what point it lands on th triangle
modest dirge
That why you should start with the 2D case
Because you can drop the barycentre to the centroid of the triangular face with a line
And then form a right triangle that includes the radius
Then using Pythagorean theorem you can try to solve for r
modest dirge
Yeah
radiant cradle
but how do you know that
modest dirge
Let me show you what I have
modest dirge
You define draw the line that satisfies that
So the barycenter is the point where the distance between each vertex and the barycenter is equal
The first thing to notice is that b that I’ve drawn is what you need to solve in the 2D case
Another reason why you should start there
But once you’ve done that you need to find a
And then once you got both of those you finally need to get r
That’s the end goal
You can do this by setting up a system of equations like this
,ccw
,rccw
twin meteorBOT
modest dirge
This is the 2D case
I’ve reused a and b but I realized that I don’t even need a in this one so disregard that
Do These two equations make sense to your
You*
And how I arrived at them
radiant cradle
yes
modest dirge
They are basically just applying Pythagorean theorem
modest dirge
So do you know how to solve for r then?
Just using substitution or something
If you’ve done algebra then you’ve probably done this sort of thing before
radiant cradle
so in the end i get
2b^2+2rb-7 = 0
and i have to substitue squareroot b^2+1 as r?
modest dirge
My use of variables was confusing I’ve realized
Because in the 2D case solving for r is what you want
But that’s actually b in the picture I drew for the 3D case
Do you see why?
radiant cradle
yes
modest dirge
And I substituted b=sqrt(r^2-1)
radiant cradle
this is the bottom view right?
modest dirge
Because I wanted to solve for r
modest dirge
this is the bottom view right?
Yeah
But I didn’t use b where I did in the other picture silly me
This was how I solved it
If you want to see
It’s kind of annoying algebra
Also a colored pencil is not it haha
But it’s what I had on hand
modest dirge
That’s b
radiant cradle
okok
modest dirge
That’s the 2D case only
radiant cradle
modest dirge
Yes exactly so now since we solved the 2D case we know b
We just have to find a and r
But we have a system of equations in two variables
Built very similarly
Does this system also make sense
It’s basically the big right triangle and the little one
Applying Pythagoras theorem
radiant cradle
okok thank u sm for ur help!
modest dirge
,w x^2+63/24x-81/3=0
twin meteorBOT
modest dirge
Then I guess it’s the sqrt of that
radiant cradle
oh
radiant cradle
r = 6(root 2)/root 23
i prob did the algebra wrong but idt any of the answer choices had 4pir^2 with the r i got
modest dirge
,w sqrt(3sqrt(817)/16-21/16)
twin meteorBOT
modest dirge
,w 4pi (3sqrt(817)/16-21/16)
twin meteorBOT
modest dirge
,w 11pi
twin meteorBOT
modest dirge
I guess I made a mistake somewhere too if the correct answer is 11 pi
radiant cradle
the radius is like root 11/2
hmm okok wait i need to go to sleep unfortunately but im going to redo the algebra tmr and see what i get
modest dirge
Ok good luck
radiant cradle
thank u sm for your help!! have a wonderful night/day
modest dirge
Goodnight
radiant cradle
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bitter sequoia
vocal sleetBOT
bitter sequoia
can someone explain how they did x - rat -> -x - rat
and why did they do (x+y) + (-x)
this is q.C i
gentle sleet
I think they're using - as meaning "is"
so x is rational -> -x is rational
gentle sleet
and why did they do (x+y) + (-x)
they did that to get rid of the x
and also to use the fact that rational + rational = rational to reach a contradiction
vocal sleetBOT
@bitter sequoia Has your question been resolved?
zenith helm
vocal sleetBOT
zenith helm
can someone explain where i went wrong
its reducing
so I can get the value of x,y,z
website lets everything be Z, where i let everything be accordance to X
shouldnt be a problem that i did that but I made a mistake somewhere because my lines arent = to 0
i think i found it, 2nd equation, 3 + (4/6)(13/2)
nevermind thats not it
it all looks right to me
<@&286206848099549185> basic algebra/matrix reduction
is it even supposed to be equal to 0
if X is an element of real numbers, idk wtf it is, therefore i cant sub it in, just assuming its 1
vocal sleetBOT
@zenith helm Has your question been resolved?
prisma panther
It will be really helpful I am really stuck on it, even tried chatGPT😅😂
cyan shadow
It will be really helpful I am really stuck on it, even tried chatGPT😅😂
what is the number after the x < - ??? in the first statement
regardless it seems untrue that the first two have no overlap
the second one also does
cyan shadow
they "overlap" at x = -5 then (and all x < -4 for that matter)
prisma panther
regardless it seems untrue that the first two have no overlap
Are you sure in the exercise I saw that the first statement has no overlap. the statement is x<-4 and x≤3
cyan shadow
they are both true for x=-5
so unless you use some odd defintion of "overlap" it appears they do have it
prisma panther
Ok thanks 👍
vocal sleetBOT
@prisma panther Has your question been resolved?
vast shale
I am trying to understand why the following systems (transformations)
\[
\7yn = \sum_{k=-\infty}^{\infty} \7xk\7h{n-k},\q \6yt = \int_{-\infty}^\infty \6x\tau\6h{t-\tau} \dd\tau
\]
are considered causal, which means $\6yt, \,\7yn$ never depend on $\6x{t+t_0}\,,\7x{n+n_0}$ where $t_0\,, n_0$ are positive numbers, if and only if $\6ht = 0\,,\7hn = 0$ for $t<0\,,n<0$.
vocal sleetBOT
@vast shale Has your question been resolved?
pseudo violet
vocal sleetBOT
vocal sleetBOT
@pseudo violet Has your question been resolved?
pseudo violet
<@&286206848099549185>
vocal sleetBOT
@pseudo violet Has your question been resolved?
pseudo violet
<@&286206848099549185>
pseudo violet
25
pseudo violet
i havent really, im trying to find theorems that would help me on this one
fervent sphinx
i havent really, im trying to find theorems that would help me on this one
you know how to find the arc measures using angles right
acutally I don't think that is the right way
pseudo violet
nah, cause this lesson is in a few months and im tryna study cause tmmr is quiz bee
so idrk what to do
fervent sphinx
nah, cause this lesson is in a few months and im tryna study cause tmmr is quiz ...
oh
what's the general idea of this lesson
pseudo violet
Theorems on Secants, Tangents,
and Segments of a Circle
i thinks
thats the name of the module
uncut burrow
To find the measure of angle PAQ, we can use the property that the angle subtended by an arc at the center is twice the angle subtended by it at any point on the circumference.
Step 1: Since quadrilateral ABCD is inscribed in a circle, we know that the opposite angles of the quadrilateral are supplementary. Therefore, angle BADC = 180° - angle ABCD.
Step 2: Since lines AB and CD intersect at P, angle APD is an inscribed angle subtended by arc BC. Therefore, angle BPC = 2 * angle APD = 2 * 50° = 100°.
Step 3: Similarly, since lines AD and BC intersect at Q, angle AQB is an inscribed angle subtended by arc BD. Therefore, angle BQC = 2 * angle AQB = 2 * 34° = 68°.
Step 4: Since angle BPC and angle BQC are angles in the same segment, they are equal. Therefore, angle BQC = angle BPC = 100°.
Step 5: Since angle BQC and angle PAQ are adjacent angles forming a straight line, they are supplementary. Therefore, angle PAQ = 180° - angle BQC = 180° - 100° = 80°.
Therefore, the measure of angle PAQ is 80°.
pseudo violet
what do you mean by angle badc?
pseudo violet
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vocal sleetBOT
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Available help channel!
mighty jasper
vocal sleetBOT
mighty jasper
i got every number right except the one highlighted in purple
uneven flicker
,rccw
mighty jasper
Not sure where i went wrong
twin meteorBOT
uneven flicker
when you do
brisk cloak
row 1 - row 2 would turn the 6 to a 1
mighty jasper
Which grade is this
1st year undergrad lin alg, never took this class in high school. I was placed in it by accident instead of integral calc, not my fault
brisk cloak
yeah pretty typical for 1st year undergrad, youll get the hang of it
low willow
1st year undergrad lin alg, never took this class in high school. I was placed i...
Damn
I'm going to give an entrance exam
vocal sleetBOT
@mighty jasper Has your question been resolved?
mighty jasper
yeah pretty typical for 1st year undergrad, youll get the hang of it
hopefully , just need to survive this one semester lol
mighty jasper
I'm going to give an entrance exam
thank you !
graceful oriole
i'm stuck in question c . i have found the inverse but cannot understand why the domain is x is bigger equal than -1
vocal sleetBOT
i'm stuck in question c . i have found the inverse but cannot understand why the...
brisk cloak
to find the inverse you do y=f(x) and solve for x yes? lets walk through it
y=-1-sqrt(x+3)
y+1=-sqrt(x+3)
-y-1=sqrt(x+3)
at this point, keep in mind that -y-1 is equal to a square root. meaning it has to be non negative! -y-1>=0 => y+1<=0 => y<=-1
im sure you know how the rest of it goes
graceful oriole
you get y=(x+1)^(2) -3 right?
brisk cloak
yep sounds good
graceful oriole
uh huh
brisk cloak
but you get where the limitation comes from right?
graceful oriole
as in?
brisk cloak
the domain being x<=-1
thats the mathematical explanation, anyway
algebraic, i mean
graceful oriole
i dont udnerstand why can't x be all numbers except -1
brisk cloak
the correct thing to say would be that the domain of the inverse is the range of the original function, and since f(x) has a max for x=-3 => f(-3)=-1-sqrt(0) = -1, thats the domain
brisk cloak
i dont udnerstand why can't x be all numbers except -1
its all numbers smaller than or equal to -1
long estuary
can anyone help me visualise/prove the numbers with odd number of divisors are perfect squares and vise veresa
vocal sleetBOT
can anyone help me visualise/prove the numbers with odd number of divisors are p...
fallen junco
can some help me with radical in maths im in the 8 grde but pls in call
river minnow
Consider the prime factorization of a positive integer and count the number of its divisors using it
river minnow
can some help me with radical in maths im in the 8 grde but pls in call
This channel is taken
fallen junco
ah sorry
vocal sleetBOT
@long estuary Has your question been resolved?
long estuary
Consider the prime factorization of a positive integer and count the number of i...
btw by divisors it means that
6's divisors are
1 , 2 , 3 , 6 right
wait hold on
12's divisors are 1,2,3,6 yeah
river minnow
Yes, those are the divisors of 6
long estuary
it's prime factorisation is 1x2x3x2
river minnow
12's divisors are 1,2,3,6 yeah
You missed one
river minnow
One more
river minnow
Yeah
river minnow
Yes
long estuary
i think factors and divisors are the same thing?
long estuary
Consider the prime factorization of a positive integer and count the number of i...
6 prime factorisation is 3x2
river minnow
They are synonyms
long estuary
i see
so suppose a perfect square
16
prime factors are 2⁴
wait let me find an example which i was getting confused
suppose p1, p2 and p3 are prime factors
prime numbers sorry
(p1xp2xp3)² is a perfect square
but then the divisors are p1 p2 p3 1 and the number itself??
idk i don't get it
river minnow
but then the divisors are p1 p2 p3 1 and the number itself??
There's more
Consider the products of those
river minnow
Let's start with simple examples, how many divisors does 2^472 have? (You don't need to list them all and count them, think about whether you can describe them with some form)
river minnow
Yes, so every power of 2 with exponent between 0 and 472 will be a divisor
That means it has 472+1 = 473
river minnow
This can be generalised to the fact that p^n has n+1 divisors if p is prime, so far so good
long estuary
yep
river minnow
Now, how many divisors p1^a p2^b should have if p1, p2 are prime?
vocal sleetBOT
long estuary
a+1 and b+1
river minnow
.reopen
vocal sleetBOT
✅
long estuary
.reopen
river minnow
a+1 and b+1
Looks like you are thinking of the powers of p1 and powers of p2, but there are other divisors
long estuary
Now, how many divisors p1^a p2^b should have if p1, p2 are prime?
wait it's the product right
ohh
right yeah
river minnow
Yes, their products will be divisors as well
river minnow
You are close
river minnow
Yes
Any p1^k p2^m will be a divisor with k between 0 and a, m between 0 and b, that gives (a+1)(b+1) possibilities
long estuary
hmm let me think
river minnow
Now, this can easily be generalised to the fact that if $n$ has the following prime decomposition:
[ n = p_1^{a_1}p_2^{a_2}\cdots p_k^{a_k} ]
Then it will have $(a_1 + 1)(a_2 + 1)\cdots(a_k + 1)$ divisors
twin meteorBOT
A Loner Bean
long estuary
Any p1^k p2^m will be a divisor with k between 0 and a, m between 0 and b, that ...
yep
river minnow
Now, assume the number of divisors of n is odd, what does that tell you about the parity of each a_i?
long estuary
let me see
long estuary
Now, assume the number of divisors of n is odd, what does that tell you about th...
what parity?
i mean a_i will be off
odd*
long estuary
let me see
long estuary
That would mean each a_i + 1 is even though
btw I don't mean each a_i
the number of a_i's will be odd
river minnow
That's not true, 36 has an odd number of divisors, but has 2 prime divisors (36 = 2^2 3^2)
long estuary
oh right right oops
long estuary
Now, assume the number of divisors of n is odd, what does that tell you about th...
idk can't seem to find any relation
river minnow
Now, assume the number of divisors of n is odd, what does that tell you about th...
Think of it this way: If a_i + 1 was even for some i, what would happen?
river minnow
If you have an even number in the product, the whole product would become even, right?
river minnow
Think of it this way: If a_i + 1 was even for some i, what would happen?
So, in this case, a_i + 1 being even for some i would make the number of divisors even too
We don't want that to happen due to our assumption that n has odd number of divisors, so each a_i must be even
long estuary
We don't want that to happen due to our assumption that n has odd number of divi...
wait
ohhh
yeah a_i +1 can't be even because we're trying to make the number divisors odd
got itt
river minnow
Right, now, given that each exponent in the prime decomposition is even, can you rewrite n as a perfect square?
long estuary
Right, now, given that each exponent in the prime decomposition is even, can you...
yeah the total number of divisors come out to be odd
by this i can prove the vice versa
if there's any off exponent it'll make a_i+1 even
so the number of divisors become even yes?
river minnow
Yeah
long estuary
got it dude thank you very much
btw
how did you come up with (a+1)(b+1)
does it just indicate all the combinations of multiplying multiple numbers?
river minnow
Yeah, simple combinatorics
If for the prime divisors you have an option of a1+1, a2+1, ..., ak+1 exponents respectively, you will end up with (a1 + 1)(a2 + 1)...(ak + 1) divisors in total
long estuary
i see, i see nice i learnt so much, thank you very much mate you're amazing at explaining
thanks once again
.close
vocal sleetBOT
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true mist
Can someone please help me with this?
vocal sleetBOT
Can someone please help me with this?
true mist
I got e/2 + 7/6 for the first part, but Im not sure how to get to the second part
vocal sleetBOT
@true mist Has your question been resolved?
true mist
<@&286206848099549185>
vocal sleetBOT
@true mist Has your question been resolved?
true mist
<@&286206848099549185>
inner schooner
true mist
<@&286206848099549185>
lament palm
Can someone please help me with this?
Is this prob theory?
lament palm
What is mgf?
vocal sleetBOT
@true mist Has your question been resolved?
lament palm
Yep
ya I vaguely remember those but my prob theory class was 5 weeks long and I don't remember much of how we solve those. Sorry
vocal sleetBOT
@true mist Has your question been resolved?
vocal sleetBOT
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Available help channel!
hardy jewel
As an impatient driver, I often switch lanes in a traffic jam. A certain highway has two lanes in my direction.
Whenever traffic moves, if I'm in the left lane I switch to the right with a probability 50%.
If I'm in the right lane I switch back to the left with a probability 70%, because it's supposed to be faster.
Over the long term, what fraction of time do I expect to spend in the left lane?
vocal sleetBOT
As an impatient driver, I often switch lanes in a traffic jam. A certain highway...
lime gorge
show ur PTM
hardy jewel
PTM?
lime gorge
probability transition matrix
lime gorge
so this is ur state transition diagram
its correct
but do u know how to model this with a matrix
what class is this for
hardy jewel
nope
this isn't for a class
I saw this problem online and I'm just trying to learn it
I thought it was a regular markov chain problem
lime gorge
it is
hardy jewel
oh ok
I'm unsure how to factor the time part
like I was thinking maybe do somethign like E_left = 1/2(E_left + 1) + 1/2(E_right)
and get the E_left/(E_left + E_right)
idk actually lol
i looked up what a probability transaction matrix is tho and can model it like that now
lime gorge
heres how i'd do it:
state space: {0,1}
0 := left lane
1 := right lane
set up our PTM
lemme do this on paint rq
hardy jewel
lime gorge
hardy jewel
lol nw thanks
lime gorge
so now we set up a system of equations
lime gorge
ill do it on paint and send it here, gimme some time
hardy jewel
pi*P = pi?
lime gorge
now, we can solve this system for pi_0, which is the long term proportion of time spent in left lane
@hardy jewel
lime gorge
look at column 1 of matrix
p_00 = 0.5
p_10 = 0.7
then the way we solve for our long run proportion is done with the formula on that line
\sum \pi_i * p_i0
its an i0 btw, not 10
hardy jewel
oh it's the weighted sum of the probabilities of transitioning into that state
I was trying to understand it intuitively
lime gorge
i see, yes
lime gorge
lime gorge
what level of math have you taken up to?
i took a class on this last semester haha
im just a undergrad actuarial student
hardy jewel
oh lol
i didn't take any other than calc 3
i should prob take some more prob classes
lime gorge
what major r u
hardy jewel
biology
hardy jewel
lol I'm comp bio so a little CS + mainly bio
lime gorge
ah gotcha
hardy jewel
but yeah I should take one of these stochastic prob classes
lime gorge
yea believe it or not theres actually some cool stochastic stuff in bio as well
somethig to do with proteins, and also stuff with cancer
hardy jewel
yeah after looking at this it makes sense
can see some applications already
thanks so much for the help
lime gorge
sure
vocal sleetBOT
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agile mango
vocal sleetBOT
bitter pilot
unborn quail
isnt the formula for arc length this
agile mango
yeah
bitter pilot
The 1s cancel
agile mango
they do?
bitter pilot
Leaving you with 1/x^2/3
Also you forgot a minus in dy/dx
But that gets squared away anyway
covert lantern
Idk if it's been a while since i've worked with integrals, but i can't seem to simplify?
vocal sleetBOT
Idk if it's been a while since i've worked with integrals, but i can't seem to s...
flat whale
Factor out as much as you can from the root
covert lantern
Factor out as much as you can from the root
Looks like I can only factor out a sintcost?
flat whale
Use sin^2 + cos^2=1
covert lantern
but the 10?
flat whale
but the 10?
What about it
flat whale
Try it and see
vocal sleetBOT
@covert lantern Has your question been resolved?
vocal sleetBOT
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Available help channel!
outer hemlock
i need help
vocal sleetBOT
i need help
outer hemlock
with an assignment
mellow birch
Wspp
modern storm
with an assignment
show
vocal sleetBOT
@outer hemlock Has your question been resolved?
vocal sleetBOT
@outer hemlock Has your question been resolved?
modern storm
this is a stupid theorical idea of mine, but lets say you have a keyboard with 3 keys (dumb keyboard i know)
How many keybinds could you have, considering you could combine each key for a single keybind with 1, up to 3 keys
yeah, so, (a), (b), (c), (a+b), (a+c), (b+c), (a+b+c)
theres a good way to calculate this for higher amounts of "keys"
vocal sleetBOT
this is a stupid theorical idea of mine, but lets say you have a keyboard with 3...
modern storm
So basically, with n number of options, you can create a number of sets up to n-set. ( a set is a list of elements in which order doesnt matter, since here a+b = b+a )
surreal basin
look up "power set", this is not a stupid idea but has already been done to death years ago
the textbook answer is to think about whether you are or are not allowing a key as a keybind
modern storm
yeah, i figured
surreal basin
the textbook answer is to think about whether you are or are not allowing a key ...
since this is 2 options, and you have n keys, you have a total of ||2^n - 1|| possibilities
surreal basin
np
modern storm
.close
vocal sleetBOT
surreal basin
maybe with a null keybind itd be the full 2^n
modern storm
maybe with a null keybind itd be the full 2^n
my keyboard performing a bind 24/7
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Available help channel!
gentle thicket
here is it valid to substitute 1-x = y, transforming right hand side into 2x+y?
vocal sleetBOT
here is it valid to substitute **1-x = y**, transforming right hand side into **...
gentle thicket
so we get f(x)+f(1/y) = 2x+y
hard atlas
well its only valid for those y which are 1-x
so this seems more dangerous than useful
gentle thicket
so this seems more dangerous than useful
I knew it was something crazy
even though I got the correct answer it seemed wrong
thanks for clearing the doubt
.close
vale frigate
can anyone explain how is marginal cost a derivative but not a differential equation
vocal sleetBOT
can anyone explain how is marginal cost a derivative but not a differential equa...
fervent stream
marginal cost is a derivative because it shows the rate of change of total cost with respect to quantity. It is not a differential equation because it doesn't require solving an equation involving both the function (total cost) and itss derivative
vocal sleetBOT
@vale frigate Has your question been resolved?
vocal sleetBOT
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Available help channel!
vast shale
vocal sleetBOT
uneven flicker
!status
vocal sleetBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
What-
vale frigate
can u say what uve done so far and where u r stuck?
uneven flicker
honestly what is your doubt?
vast shale
number 3
twin meteorBOT
uneven flicker
thats not 110 deg @vast shale
vast shale
idk... how to use a scale...
vast shale
A weighing scale..?
vast shale
How do I use that..?
uneven flicker
💀
vast shale
Can you stop with the skulls?
uneven flicker
Can you stop with the skulls?
im sorry but one should know how to make circles
way before radians
vast shale
You don't have to be so mean about it?
I seriously don't have the same compass as that guy? I'm not your interpeter to know everything you say. I don't even know why your a helper if all your going to come back with an idiot like me is judgement.
Like I'm sorry I don't understand???
vast shale
No it's fine
vast shale
You don't have to be so mean about it?
<@&268886789983436800> Is it okay to have another helper?
vast shale
💀
Wait. Am I suppose to understand as quickly as possible? That's not learning? I could have used ChatGPT so that you'll be satisfied with your own speed and well satisfaction rather than this type of attitude.
Has anybody ever done this behind your back?
Because I feel like every session I just felt like there will come a time they would much rather deal with your satisfaction than their learning skills.
Although I could have used ChatGP, I still won't get it.
So mainly this is for your satisfaction and to just remove you as quickly as possible.
limber falcon
<@&268886789983436800> Is it okay to have another helper?
you can just ignore them if you really wanted, though in this case I believe they were trying to help but kinda at disbelief of knowing someone who's never used a compass
irregardless of that I'd ask y'all to keep it respectful
every person helping out there is volunteering their time
vast shale
you can just ignore them if you really wanted, though in this case I believe the...
I know how to use a compass but only for making circles. These types of question I would analyze as solving radius like that but never labelling it.
vast shale
every person helping out there is volunteering their time
Well can't you see the conversation? They are using the skull emoji for no reason.
That's not an appropriate response.
We all have different experiences so technically there are times people are unique or has been taught not the same as them and they should learn to be patient about it not this type of response?
Are you really reading the conversation? That is improper of them to do so and as an honest person, I would never use anything I'd much rather learn than to use ChatGPT for his satisfaction of answering whatever he wants correctly.
limber falcon
💀
alright last week you had alr been timed out for making fun of helpees, seriously stop the condescending attitude
consider this a warning
uneven flicker
kk sorry
limber falcon
Are you really reading the conversation? That is improper of them to do so a...
was on that, am on phone sorry
vast shale
alright last week you had alr been timed out for making fun of helpees, seriousl...
and I don't know if the helpers role is like an optional case but I would suggest to have someone atleast proper or patient enough to help helpees not someone that clearly has been timed out and still managed to keep that role just to do it again.
dark kiln
of course, skull emoji is the opposite of condescending
you need to start being somewhat condescending
vast shale
Although I respect his help. I honestly do @uneven flicker but someone could be sensitive as me now. Someone who desperately needs help without that improper response.
uneven flicker
i guess my skull emoji wanst appropriate
but when i saw rads and stuff
i wasnt expecting the other person to not know about compass and all
tho i think the problem is helping online
like a physical helper might be more useful for you
vast shale
you need to *start* being somewhat condescending
That is.. literally not a good way because why are you getting superior over someone who needs help or someone who wants to learn? Are they threatening you or do you feel like they are trolling you? Ask up and if they did not respond properly you can start ending the conversation immediately.
Isn't that valid than being condescending?
limber falcon
and I don't know if the helpers role is like an optional case but I would sug...
the "helpers" role is opt-in (you get it in #info iirc), "helpful" is attained after a while. we're looking into this
I agree that it's not an appropriate response for a legitimate question
limber falcon
Then where do I use the scale?
hopefully someone else can pick it up from here <@&286206848099549185>
vast shale
Thanks
vast shale
https://youtu.be/87JhveImhoU?si=I3p2VrtFkesjb3P0
From this video. Should it be at the center of the paper or... can I choose where I want the circle to be?
dark kiln
That is.. literally not a good way because why are you getting superior over som...
the relationship between equals involves a lot of mocking
vast shale
the relationship between equals involves a lot of mocking
Like I said ask. Because I experience someone who sounds like they are mocking, they are actually influence on how they are sounding as whether it be a family, friends (mainly toxic environment) You never know they might have a "Blind Self" by johari window
limber falcon
the relationship between equals involves a lot of mocking
yes, with people you know and once theres some degree of trust. this is different
vast shale
Like I said ask. Because I experience someone who sounds like they are mocking,...
and if they do it again end a conversation not some words of superiority.
But if you were moderators, There is always a ban, kick or timeout button - Explain first what happened and do that like ban or kick or etc.
tawny nacelle
I haven’t been following, so I apologize for asking, but which question are you stuck on?
tawny nacelle
!!
tawny nacelle
what's an endpoint?
it’ll be the point at the end of the line segment
the line segment starts at the centre, C, and ends at the endpoint, D
tawny nacelle
it won’t be outside the circle, it’ll be on the circle 
tawny nacelle
the line segment ends at the circle, so the endpoint should lie on it
so B shouldn’t be outside the circle, it should be on it 
if you’ll excuse my poor drawing
vast shale
OHHH
vast shale
Okeh ez number 3 but... how does a terminal ray look like?
tawny nacelle
Okeh ez number 3 but... how does a terminal ray look like?
ray, line segment, same thing
vast shale
Answer is 110π/180?
tawny nacelle
Answer is 110π/180?
you can reduce that fraction, but yes 
tawny nacelle
how?-
well, both the numerator and denominator are divisible by 5 
so you can reduce that fraction
vast shale
sooo 22π/36?
tawny nacelle
sooo 22π/36?
oh, darn, I made an error
that is correct, but it can be reduced further
namely, by dividing both the numerator and denominator by 2
vast shale
so many @~@
tawny nacelle
sorry, I should’ve asked you to divide by 10 from the getgo 
vast shale
11π/18
tawny nacelle
there you go!
vast shale
sorry, I should’ve asked you to divide by 10 from the getgo <:pandaohno:51307026...
T~T it's fine
Is that the answer or am I not yet done?
vast shale
Great where do I put it in the circle?-
tawny nacelle
you gotta draw a line segment from the centre to the circle such that the angle between the two line segments is 110 degrees
vast shale
Okay..? where do I put that?-
tawny nacelle
here’s a rough sketch, in the case when the angle is 60 degrees
I free handed this, but you should use a protractor
tawny nacelle
here’s a rough sketch, in the case when the angle is 60 degrees
you gotta do the same thing, but for 110 degrees
tawny nacelle
what about this one?
that’s the same angle haha
it’s just 110 degrees, in disguise
just a different name for the same thing!
vast shale
so.. which one do I put the degrees or the radians? Can I pick which one?
tawny nacelle
so.. which one do I put the degrees or the radians? Can I pick which one?
you should use degrees, because that’s
- what the question is asking for
- protractors usually only have degrees
vast shale
@tawny nacelle Is this correct?
tawny nacelle
looks good! 
vast shale
which is..?
tawny nacelle
sorry, give me a few minutes! >.<
vast shale
okay
vast shale
So part 2
-23π/30 x 360?
Similar to how you multiplied by pi/180 to convert from degrees to radians
you multiply by 180/pi to convert from radians to degrees
vast shale
Similar to how you multiplied by pi/180 to convert from degrees to radians
you ...
Oh
Sooo
180 x -23π/30 ?
almost! you forgot the /pi
huh?
you multiply by 180/pi, not just 180
180 x -23π/30 / π?
yeah, assuming you intended to say 180 ×(-23pi/30)/pi because parentheses matter over text
yes...
is thatcorrect?
yeah
evaluate it
...
how
might be easier to see if you write it as [
\4{180}\pi\by\4{-23\pi}{30}
]
Which is exactly the same as what you wrote
twin meteorBOT
vast shale
110 x π/180?
do you remember when you did this?
it's actually the same thing, but in reverse
you flip it from pi/180 to 180/pi
-138π/π?
vast shale
-138π/π?
good answer??
yeah!
but you can simplify pi/pi
what do you think is that?
....
1
yeah
so what should be your final result
-137?
Oh you don't subtract from the 138
it's just that [
-\4{138\pi}\pi = -138
] because $\5\pi\pi = 1$
twin meteorBOT
vast shale
I don't get it
which part confuses you?
\def\CancelColor{\tc r}
[
-\4{138\pi}\pi = -\4{138\cancelto{=1}\pi}{\cancelto{=1}\pi} = -138 \by 1 = -138
]
twin meteorBOT
vast shale
So thats the answer?
sure is
NEXTT
oh actually just a small thing
but, it should be -138°
just to show the unit
Okay okay ez ez
tawny nacelle
you just calculated the angle in degrees!
now you just gotta draw it on your diagram 
vast shale
How..?
tawny nacelle
same thing as we did earlier!
vast shale
gotta use a protractor
if you're looking for precision, that is
OHHHH
Done
Okay guys it's 12 am midnight
I need to sleep I need to go to school tomorrow
Tysm guys this is really helpful
tawny nacelle
Okay guys it's 12 am midnight
good night, I hope you sleep well
but you should probably close this channel before you do >.<
vocal sleetBOT
tawny nacelle
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Available help channel!
lament oasis
Hi
tawny nacelle
hello, do you have a question?
also, you shouldn't occupy more than one channel at a time 
lament oasis
Ho
spiral turtle
It's the exact same question
tawny nacelle
spiral turtle
please go back to your other help thread.
tawny nacelle
^
spiral turtle
.close
vocal sleetBOT
tawny nacelle
tawny nacelle
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Available help channel!
limpid summit
Need some help on sets
vocal sleetBOT
Need some help on sets
limpid summit
not sure what to do for 5b
I’ve started by assuming that for all real x, A<=B
so (A=B or A<B)
Idk how I’m supposed to get the set C into the picture here
vocal sleetBOT
@limpid summit Has your question been resolved?