help-17

[mild flower]

rather than by row like you were looking for

[vernal radish]

even when i change the dim it doesn't give something similar at all

i'm going insane 😭

[mild flower]

looks like you can do diff(performance, 1, 2)

[vernal radish]

oh wait i'll try that

it's working thank you i completely forgot about the input order of diff

tysm

ily

[mild flower]

yw!

[vernal radish]

have a great day

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[azure tide]

why does the square root part keep ending up negative did i do something wrong 🤔

[flat whale]

you're forgetting PEMDAS
https://www.cuemath.com/numbers/pemdas/

[azure tide]

lowkey

idk how to use it

but thank u i will read

[azure tide]

is that why 81 wasnt supposed to be negative?

[flat whale]

yes

,calc (-9)^2

[twin meteor]

Result:

81

[flat whale]

,calc -9^2

[twin meteor]

Result:

-81

[flat whale]

two different numbers

but you have another - sign problem still

[azure tide]

yes 81 - -1600 makes a plus instead

[flat whale]

[azure tide]

i just calculate it with parentheses from now on?

[flat whale]

-a^2 is interpreted as - (a^2) because E comes before M in PEMDAS

so you evaluate 9^2 first

but in math, whenever you have a variable like b^2, it should be interpreted as (b)^2

[azure tide]

OKAY :3 i got it now

[flat whale]

[azure tide]

.close

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[tired sable]

Why does the 2 and 3 place subtraction place get flipped?

[tired sable]

When I look at that equation I think it can't be right because we gon have to square root a negative fraction, nonreal ans

[flat whale]

$\frac{a}{-b} = -\frac{a}{b}$

[twin meteor]

riemann

[tired sable]

I know this

[flat whale]

apply it to the numerator

$-(a-b) = ?$

[twin meteor]

riemann

[tired sable]

How can the square root work then? I thought no square root for a negative

Hmm I suppose, if x = 0, then it can work

or 1

[flat whale]

i don't understand what that has to do with your original question

[tired sable]

I spawned a new question

.solved

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[rustic dragon]

Could someone check if this is right

[rustic dragon]

When I plugged in x and y in 2xy I did get 800

[vocal sleet]

@rustic dragon Has your question been resolved?

[outer warren]

2 * y * 3 is 2400/x
but that 2400 turned into 400 in the following line

[vocal sleet]

@rustic dragon Has your question been resolved?

[rustic dragon]

Wait what

You’re right

I must’ve missed it

It was small

My

Bad

So x = 11.547

When finding price I accidentally dropped the price multipliers

So it was 415.97

[rustic dragon]

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[nimble trench]

would the invariant point for a reciprocal graph on the right be extraneous because its an imaginary number?

[nimble trench]

or do i include the imaginary number and keep going for complex numbers

this is the full thing btw if graph is needed

[pallid zenith]

which one is the one on the right here

[nimble trench]

my fault LOL bad handwriting

[inland sluice]

Hi

[nimble trench]

this is supposed to be when y=-1

whoops

[inland sluice]

If anyone needs help with mod math I’m really good at it and willing to help out

[pallid zenith]

im still confused

whats the graph

[pallid zenith]

you dont have the eqn?

[nimble trench]

x^2+7x+12

[pallid zenith]

invariant here means f(x)=x right

[nimble trench]

yeah

[inland sluice]

I haven’t really learned geometry

At least not complex geometry I mean, I know my Pythagorean theorem

[nimble trench]

this isnt geometry

[inland sluice]

OK, then whatever it is I don’t know and I apologize

[nimble trench]

no worries

[inland sluice]

Sorry, I’m only really good at certain things and aspects of math

[pallid zenith]

,w x^2+7x+12=x

[twin meteor]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by janniku

[inland sluice]

To Be honest honest I’m just a 13-year-old, who is good at some types of math and learn things quickly

If it’s math, I just like to learn it

[nimble trench]

good youre doing it now

[nimble trench]

so for this case it would be finding invariant points for y=1, y=-1

i found y=1

maybe i did something wrong during quadratic formula but idk how to get second invariant point

because there cant be imaginary # on the graph

[vocal sleet]

@nimble trench Has your question been resolved?

[pallid zenith]

sorry, i ran into someone i knew against all odds

[pallid zenith]

i dont think these exist, im not sure how you mean

it does not seem that there are any invariant points

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@nimble trench Has your question been resolved?

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[untold meteor]

Need help with this system of differential equations, particularly the highlighted part of the attached screenshot. Here f(x,y) is x' and g(x,y) is y'

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@untold meteor Has your question been resolved?

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[finite hatch]

for the solution they also got 125 degrees

[finite hatch]

but how did they get 125 degrees when 125 degrees is in sin quadrant

wouldnt it make it negative

[raven zephyr]

tan is also positive in third quadrant

[finite hatch]

isnt third quadrant more than 180 degrees

[raven zephyr]

its for x but the angle is 2x-10

[finite hatch]

oh

wait sorry

i did this a long time ago

but i remember something about

multiplying the domain?

[raven zephyr]

yeah?

[finite hatch]

does this apply to this question

[raven zephyr]

multiplying domain i didnt get that sry

[finite hatch]

wait let em find a pic

[finite hatch]

here they multiplied the domain by 2

but i have 2x - 10

so how would i do it

[raven zephyr]

multiply then subtract by 10

[finite hatch]

ohh ok

thx so much!

:D

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[tropic canyon]

i missed a few classes and im lost

[flat osprey]

@tropic canyon Can you read the graph, if yes, what values of x that makes y = 4?

[tropic canyon]

4?

@flat osprey

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[vast shale]

in the end i got stuck with |g(x)| like how do i even find its bound?

[flat whale]

|g(x) - m| < eps

[vast shale]

yes

right

[flat whale]

Use triangle inequality

[vast shale]

sure

|m| - |g(x)| <= |g(x) - m| < eps

mhm

|m|-eps <= |g(x)|

ah

1/|g(x)| <= 1/|m|-eps

wait

can i just use this

for the |g(x) - m| < eps there will be del3

del = min{d1, d2, d3}

i can take epsilon as small i want for for that d3 will always exists

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[fossil pollen]

So multiply by 1.5 to get probability of success for next trial

[vocal sleet]

Please don't occupy multiple help channels.

[steep crater]

!show

[vocal sleet]

Show your work, and if possible, explain where you are stuck.

[fossil pollen]

In a coin flip

[steep crater]

sorry i dont understand

[fossil pollen]

getting at least 1 tail in 2 flips is 0.5x(1.5)^1 = 0.75 rite

[steep crater]

!original

[vocal sleet]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[fossil pollen]

why does 0.5(1.5)^n exceed 1 for n>1

[steep crater]

no it dosent

[fossil pollen]

Im just asking a general doubt

Its not a qn

[steep crater]

0.5(1.5) = 0.75

[fossil pollen]

huh

For n>1

for n= 2

it exceeds 1

[steep crater]

what

how is 0.75^2 > 1

[fossil pollen]

No

mb

0.5 [(1.5)^n]

[vocal sleet]

@fossil pollen Has your question been resolved?

[vocal sleet]

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[modern steppe]

hi

[modern steppe]

I wanted to know if I translated correctly this sentence "Two whole number of the same parity follow each other"

[mild flower]

i don't see why you're using \forall here

[modern steppe]

me too

Because I wanted to include all numbers

if they said 2 whole number it could be any number from 0 to +inf

and a number could be odd or even

I would need to write this to really include everyone since I need to show that the 2 number I choose is from the same parity

@mild flower ?

[mild flower]

oops sorry i got modpung

yeah so what you're saying is like

there exists a number x, and a number y
such that x and y have the same parity
and y follows x

[modern steppe]

sry !

[modern steppe]

what if x follow y

[modern steppe]

else yes it's wut im saying

[mild flower]

no, y follows x

[modern steppe]

yes u right my bad

[mild flower]

i don't get why the forall though

[modern steppe]

Me either because I need in my exercice to do the negation of it

if I just spawn x or y wihout any qualificator it would be "weird" for the teacher (i think)

I wanted to include all number from N for x and y

[mild flower]

so say \exists x

[mild flower]

no you don't

[modern steppe]

[mild flower]

hang on what do you mean by "two whole numbers of the same parity follow each other"

do you mean there's at least one example?

or every number has a number with the same parity following it

[modern steppe]

I think this

My teacher just wrote this sentence

[mild flower]

oh okay then you do want \forall

i read it as the first case

[modern steppe]

I'm french so perhaps I translated it badly

[modern steppe]

Two integers of the same parity necessarily follow each other

[mild flower]

what's the original in french?

je parle un peux du français

[modern steppe]

Deux eniters de même parité se suivent forcément

[modern steppe]

I prefer this conversation in english

[mild flower]

same

[mild flower]

ok this does seem like the \forall case

[modern steppe]

Nice

[mild flower]

let me go back and look at your original thing now that i know that haha

[modern steppe]

[mild flower]

i would probably write that as uh

[modern steppe]

Yeah I knew there was a simpler way to write this

I hate long sentence like when im programming

[mild flower]

$\forall n: \forall v: v = n+1 \implies \exists k, m: (n = 2k \wedge v = 2m) \vee (n = 2k+1 \wedge v = 2m+1)$

[twin meteor]

hayley is not layla

[mild flower]

using v isn't strictly necessary because we could just say n+1 instead, but i think it looks nicer

[modern steppe]

Indeed

[mild flower]

in particular with this, you need to specify how "v = n+1" is connected, or remove the \forall v entirely (since it's basically a #define)

[modern steppe]

I think it's the best

U don't spawn a other variable for parity check

[modern steppe]

Wait am I forced to use => ?

The other small question I didn't use => at all

For example

[mild flower]

if you want to use \forall v, yeah kinda:
you want v = n + 1 right?

[modern steppe]

Yea

[modern steppe]

The sum of successive integers is necessarily even

I just wrote this

[mild flower]

sure but you're not constraining n or k here apart from being a natural number (you probably meant integer)

[modern steppe]

Yea

But I didn't use =>

I wonder if it's a heavy fault or not

[mild flower]

that's because you're not constraining n or k here apart from being a natural number

[modern steppe]

hmmm

i didn't get it ;-;

Like n and k is kinda free so i'm allowed to write it like this ?

or should I remplace "equal" by "implies" symbol ?

[mild flower]

hmm how would you write "every even integer is less than 7"

[mild flower]

mm no
this says "every natural number is even, and also less than 7"

[modern steppe]

just remplace N by Z

[mild flower]

ok sure but that doesn't fix it

then it says "every integer is even, and also less than 7"

[modern steppe]

oh

so

like this ?

[mild flower]

oh

wait yeah no that's right

sorry it's 4am xD

[modern steppe]

Oooooo

[modern steppe]

FR ?

[mild flower]

yeah lol

but i'm fine

hmm i actually think you need parentheses as well

$\forall n \in \Z: (\exists k \in \Z: n = 2k) \implies n < 7$

[twin meteor]

hayley is not layla

[modern steppe]

Yea it's more beautiful and easier to read

so fuk i need to redo all my exercice AGAIN

at least i learned something new but I got no time to live

[mild flower]

sorry

[modern steppe]

naaa

love u

[mild flower]

<3

[modern steppe]

[modern steppe]

so

can I send u my final result later ?

I will take a long while and this night u ping me ?

i mean

day for u.

[mild flower]

hmm i would say yes but i'm going to be pretty busy getting ready for a flight today
you might be better off opening up a new channel when you're ready

[modern steppe]

noted

Thanks u

Have a good and save trip

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[graceful oriole]

I have no idea where to start. I seperate the right section in the regular formula of a line, but now im stuck

[dull bear]

Do you know what the vertical asymptote being x = -2 implies about your equation?

[graceful oriole]

that x cannot be -2?

is anybody there?

[modern ledge]

are u stuck interpreting what each piece of information tells u?

[graceful oriole]

I just don't how to solve the question given the information

[modern ledge]

ok well lets translate each piece of information int osomething easier to use

we will go from top to bottom

[graceful oriole]

ok

[modern ledge]

what does first line tell u

[graceful oriole]

the y-intercept, which you get when x equals 0 in the equation right?

[raven zephyr]

yeah

[graceful oriole]

which gives me -4=b/c

[modern ledge]

ok nice

what does the second line tell u

[graceful oriole]

x cannot be -2

[modern ledge]

what does that tell u about c

[graceful oriole]

c cannot be -2?

[modern ledge]

no

wait wrong reply

was meant to reply to c cannot be -2

ok do you understand why there is a vertical asymptote

[graceful oriole]

it shows the x value it doenst touch

[modern ledge]

yeah but why

what part of the expression causes this behaviour

[graceful oriole]

x+c

[modern ledge]

ok yeah

it is a division of 0 problem that creates your asymptote

so that implies x+c = 0 when x = -2

what does that make c =?

[graceful oriole]

x=2?

[modern ledge]

no

try again

[graceful oriole]

c=2

[modern ledge]

the asymptote occurs when your denominator is 0 right

[modern ledge]

yes

ok we can sub this back into the first line

[graceful oriole]

ahhh

[modern ledge]

where we got -4 = b/c

what does that make b=?

[graceful oriole]

-8

[modern ledge]

bingo

ok lets go to the third line

what are some things u know about horizontal asymptote

[graceful oriole]

y value it doesnt touch

[modern ledge]

ok but more broadly speaking

where abouts in the graph do u look at usually

when u think about horizontal asymptote

[graceful oriole]

y-axis?

[modern ledge]

maybe its different from person to person but i look at the values of x approaching positive and negative infinites

[graceful oriole]

hmm, sure yeah

[modern ledge]

if it tells u the horizontal asymptote occurs at y = 3

that means that as x approaches negative, or positive infinite, y will be slightly above or under 3

but never 3

[graceful oriole]

uh huh yeah

[modern ledge]

ok so lets think about it intuitively

if u sub in a ridiculously large value for x

like let say x = 10^{1000000} just in ur head

what do u think the expression will aprooximately = to

[graceful oriole]

a+b/c?

[modern ledge]

nope

ok lets try this again

[graceful oriole]

oke

[modern ledge]

$y=\frac{ax+b}{x+c}$ if x is really big, like insanely big

[twin meteor]

Dootud

[modern ledge]

do u think it is reasonable to say the values of b and c is negligble

on what x is

do u think u can tell difference on value between $y=\frac{a(100000000000000000000000000)+b}{(100000000000000000000000000)+c}$ and $y=\frac{a(100000000000000000000000000)}{(100000000000000000000000000)}$ if b and c are relatively small numbers

[twin meteor]

Dootud

[modern ledge]

ok the formatting got absolutely cooked but i hope u can get what im trying to say

[graceful oriole]

umm, not really. as in, you're saying that you'd have a remaining

value a

[modern ledge]

ok that is what im trying to say

[graceful oriole]

ah great :)

[modern ledge]

so if x is approaching infinite

or just think of it as a very large number

and y aproximately = 3

what do u think a might be

[graceful oriole]

y=3?

[modern ledge]

y approximately = 3

not 3 but nearly 3

what does that make a = ?

[graceful oriole]

oh yeah right

[modern ledge]

$y \approx 3 \approx \frac{a(large:number) + b}{(large:number) + c} \approx \frac{a(large:number)}{large:number}$

[twin meteor]

Dootud

[modern ledge]

or equivalently, $3 \approx a$ when x is really large

[twin meteor]

Dootud

[graceful oriole]

ok yeah

[modern ledge]

so really, a = 3

so if u have valeus of a, b, c, u can sub them into original expression

oh wait

i just realised question only asked to find b

[graceful oriole]

oh

[modern ledge]

ok we didnt evne have to do the rest of all this

lol

[graceful oriole]

its fine, i understood a lot

[modern ledge]

ok well whatever, its good practise anyways

[graceful oriole]

you're actually really good at this

thanks :)

[modern ledge]

nw

have a good evening/day

[graceful oriole]

youtoo

.close

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[modern ledge]

.close

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[scenic ravine]

<@&268886789983436800> , spam

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[wheat tide]

ion know how to start

[simple mason]

First define the x values where the sign of the things inside absolute values change like
x=0 a change in the sign of x
x=1 a change in the sign of x-1
x=2 a change in the sign of x-2

[modern ledge]

another tried and true method would be graphing |x-1|, |x-2|, -x all separately and adding them but idk how painful that would be

[simple mason]

Now split the function into a piece wise function that have the conditions
x ≤ 1
1 < x ≤ 2
2 < x

Then graph each part on its own depending on the domain

@wheat tide
Understandable ?

[wheat tide]

im trying to understand it, thanks for the explanation

[simple mason]

What I explained helps you to remove the absolute value and treat the function as if it is a normal function

Like when you treat that x is always less than 1
Then
f(x) = -(x-1) -(x-2) - x

You can rewrite this as
f(x) = -x + 1 -x +2 -x = 3 - 3x {x≤1}

And do the same with other parts

[wheat tide]

then i substitute the x for the numbers and draw the graph?

[simple mason]

Yeah

[wheat tide]

and like, where and which numbers do i need to substitute the x?

or is it like the numbers 0,1,2,3,4 and then i got the graph

[simple mason]

Check the condition of the function and you will know

[simple mason]

Like here f(x) equal that value only if x ≤ 1
So you need to substitute values less than 1

[wheat tide]

oh i get it

[simple mason]

I want to make sure that you understand what I said above so can you calculate the value of f(x) When 1<x≤2

[wheat tide]

so it will be 3 numbers since there are 3 conditions right?

1<x≤2, the value of the x is less than 1, so numbers less than 1 should do the work

[simple mason]

What?

Look
Do you know why in the first place we got the zeros of the parts inside the absolute values in the function

[wheat tide]

no

[simple mason]

You know that the absolute values change the sign of the things inside it from negative to positive

[wheat tide]

oh you mean that

[simple mason]

When we know the zeros of what is inside the absolute value
We can know when that part would be negative and when it would be positive

Like I want to remove the absolute value to make the calculations easier so to do that I need to first know when the things inside the absolute values change sign

For example I have |x-1|
I want to write that without absolute value
To do that I first check the zeros of the part inside it
Which is x=1
When x is smaller than 1, x-1 is negative so I can write it as
-(x-1) when x≤1

And when x is bigger than 1, x-1 is positive so we can write it
(x-1) when x>1

[wheat tide]

ok thanks i understand it now

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[jagged reef]

Can someone help solve this:
sin(a) sin(b) sin(c) sin(d) =cos(a) cos(b) cos(c) cos(d)
For a,b,c,d in Real Numbers

[devout kindle]

a=b=c=d=45°

that's where sinx = cosx = 1/√2

[jagged reef]

Thanks! There must be a way to get an equation for all solution right?

[devout kindle]

uhm try multiplying 4 both sides

,w cosc + cosd

[jagged reef]

If i put sin(x) sin(y) =cos(x) cos(y) in geogebra i get a family of lines. This must be possible in higher Dimension but idk how

[devout kindle]

ysah just compare it with
cosc + cosd & cosc-cosd

after multiplying with 4 both sides

[raven zephyr]

any two pairs must be complement

[jagged reef]

I thought of that but how could i Prove that the solution i get really resembles All solutions?

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[drowsy cypress]

how do i solve this one

[pine hull]

What is property of sides of a square?

[drowsy cypress]

they are equal

[pine hull]

Well there is your answer

2 sides are given in terms of x
Both should be equal

[drowsy cypress]

ah i see simples. thanks

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[ruby nimbus]

Hello am dummy

Dont know thisss. ÷

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[molten anchor]

absolutely struggling with everything in here

this is in my lectures about graph theory for CS and we have looked into stuff abt minimal spanning trees and what not however this q was said to me more abt geometry than graphs

[past anchor]

ik the first answer just not using graph

idk the proper way

[molten anchor]

what's the first answer?

[past anchor]

but the roads will be a diagonal

$20\sqrt{2}km$

[twin meteor]

Newt

[molten anchor]

OH wait yh u can just do that

[past anchor]

idk how to prove it though

[molten anchor]

cos u can travel across the diagonal

[past anchor]

I am still learning graph

[past anchor]

yes

[molten anchor]

i originally thought abt that and then just forgot that they can make a turn in the road to get there 😭

[past anchor]

the second also can use that solution i think

[past anchor]

for b

[molten anchor]

yh three diagonals?

[past anchor]

make 4 diagonal i think

[molten anchor]

that all concur in the middle of the cube

oh wait yh

[past anchor]

make it though middle of cube

[molten anchor]

yh yh yh yh

[past anchor]

I just don't get the implementation of the graph

Idk alot still grad 9 lol

[molten anchor]

icl i'll just prove it via exhaustion

thx tho

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[vast shale]

Hello quick question

[vast shale]

and

are not the same right ?

[pale perch]

theyre indeed not the same

[vast shale]

cool its what i thought

[vale frigate]

one gives the divergence?

what is the other?

[vast shale]

2nd one gives divergnece

[vale frigate]

yeah..im not sure what the other one is

[vast shale]

the other is not fully on the pic

ye actually its a dumb question

ok thanks anyway

!close

!Close

!cmon close

[pale perch]

.close

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[sick path]

I need help to solve d and e. These are all square matrix (nxn) I have to find the exact number of the Determination of the matrix (or formular to calculate the Det base on "n")

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.reopen

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✅

[sick path]

<@&286206848099549185> hi pls help. very appreciate cuz I am really running into a wall rn with these d and e

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@sick path Has your question been resolved?

[simple mason]

determination?

you mean determinant?

[sick path]

ah yes

sr my autocorrect

it is determinant

[simple mason]

you can do that by row reduction

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✅

[sick path]

yes I have been row reductioning but I haven't figured it out how specifically lol. Been stuck there since yesterday

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[strong tartan]

i need help for a)

how to express m in terms of k

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[strong tartan]

bomboclat

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[drifting veldt]

hi guys

can someone help me with this question

i have this so far

[heady ibex]

Do you know what an isosceles triangle is?

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@drifting veldt Has your question been resolved?

[drifting veldt]

yeah

i thought B and C are the same angle

but

answer is 75 apparently

[heady ibex]

that doesn't make any sense

[drifting veldt]

GPT said the same thing

are they both wrong

[heady ibex]

gpt is wrong

lol

it's saying that the angle A is equal to another one and the third one is 30

but AB = AC means A is the third angle

where the other two are equal

[drifting veldt]

and the site?

it's an sat prep site so i didn't expect it to be wrong

[heady ibex]

the site is equally wrong

[drifting veldt]

alr

[heady ibex]

If A was 30 degrees

and you were meant to find the other two

then 75 would be correct

but that's not the question

[brittle cipher]

yeah they're wrong

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[turbid scarab]

Guys

[turbid scarab]

is - X/2 is -X(2)^-1?

[raven zephyr]

yeah

[turbid scarab]

ok

[loud walrus]

No

[turbid scarab]

im doing binomial theorem

[loud walrus]

Sry yeah

[loud walrus]

That parenthesis was weird for me

[turbid scarab]

All good lmao

WAit

its -1/2x i think

nvm just leave it fr

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[young patrol]

can anyone check if it's correct and if there's anything wrong? the topic is solving quadratic equations by extracting the square root

[cursive turret]

you always missed the negative case. 3 (-5)^2 = 75.

[loud walrus]

$\sqrt{x^2} \neq x$

[twin meteor]

Samuel

[loud walrus]

$$\sqrt{x^2} = |x|$$

[twin meteor]

Samuel

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[vast shale]

You can even see this graphically

Thre are two solutions

*there

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[glossy rose]

how do i solve for B i have done this much until now

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[glossy rose]

<@&286206848099549185>

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[glossy rose]

.close

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[dim onyx]

hey uhm

[dim onyx]

i need help again

i need to find the area of the like colored thing

[silver tusk]

show ur work

[dim onyx]

wdym work idk how to get it

[silver tusk]

also what grade is this

😭

[dim onyx]

i’m tryna help my brother with trigonometry uhm but i don’t get it either

it’s 10th grade

[lusty snow]

Prolly square-two triangle innit

[dim onyx]

what…

it’s a square yea

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[pallid notch]

Statistics - Discrete Random Variables:

I initially tried to solve this question by finding the Expected value of the Winnings but I ended up with -4.1666667 and I found the mark scheme to be really confusing could anyone give me a hint on how to solve this as im very confused, thank you.

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@pallid notch Has your question been resolved?

[coral kraken]

hi oli

[pallid notch]

hi

@graceful ibex

[cerulean halo]

hi oli

[pallid notch]

bro get out of my question

[coral kraken]

my friend u pinged a person named helper not the actual helpers

<@&286206848099549185>

[pallid notch]

oh

bro

thats so confusing

[coral kraken]

its ok someone will answer ur question soon

[pallid notch]

they better do, or im gonna get angry - step aside small fry 😼

[coral kraken]

yeah this is why nobody is helping u

[cerulean halo]

this is to funny

[pallid notch]

bro ur ruining my question

get out

[cerulean halo]

someone come help this poor soul

[coral kraken]

guys i apologise on behalf of my friend bredeat / oliver / oli, he has expressed his distress over his mathematic problem which nobody could help with so i advised him to ask this server, plz some ody save him thank u

[pallid notch]

what the yap

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[pallid notch]

Statistics - Discrete Random Variables:

I initially tried to solve this question by finding the Expected value of the Winnings but I ended up with -4.1666667 and I found the mark scheme to be really confusing could anyone give me a hint on how to solve this, thank you.

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.reopen

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[vast shale]

so i was proving lim x -> 0 sinx/x = 1

for e > 0, there exists del such that
|x-0| < del => |sinx/x -1| < e

|sinx/x -1|
|sinx -x|/|x| <= (|sinx| + |x|)/|x| <= (1 + |x|/|x|)

[vast shale]

i am stuck

at the last step

need ideas!!!

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[oblique wolf]

What's the short cut to this

I'm genuinely lost

[compact saddle]

It would be nice if 10000^2 - 19999 was a square, no ?

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[kind narwhal]

at this point tbh i will consider the numerator to be just 10,000^2 cus 1 is really small

and maybe neglect 19999 in sq root

so answer comes just 10,000 aprrox

[oblique wolf]

I thought of breaking the bottom into 10000^2-(20000-1)

Didn't help

[kind narwhal]

any options given?

[oblique wolf]

Yeah

[kind narwhal]

like from what i can see i feel it will be B tbh

[oblique wolf]

Just integers right next to 10,000

The answer was 10001

[kind narwhal]

yeah thats the harsh part every option are very close

[compact saddle]

Hmm, doesn’t that look like an identity you’re familiar with?

||(x+y)^2||

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[soft lodge]

I sub u = 2t+3

du = 2

dt = du/2

what is the integral of e^-t+1?

Is there one ?

[still mica]

Sub -t + 1 = u

[soft lodge]

I have

No 2t+3

U sure ?

I have 2 U's ?

[still mica]

Or another variable

Z = -t + 1

[soft lodge]

So I can sub 2 things ?

so Z = -t+1

and u = 2t+3=

?

ye

so I could do that ?

ohh ok

wont it affect both of them two ?

If i sub Z = -t+1 on the e one

I dont have to apply it to the other integral ?

[twin meteor]

MU (Ping on Reply)

[soft lodge]

u*eû?

u*e^u?

Derivative of the U * E^u

If my u = -t+1

ill show wait

ye exatly

[twin meteor]

MU (Ping on Reply)

MU (Ping on Reply)

[soft lodge]

?

[still mica]

Since you need to replace dt with -dz, you are multiplying by -1 inside and outside the integral

[soft lodge]

ehh Shouldnt dt be = du/-1

[still mica]

Whats the difference?

[soft lodge]

Have i even done the integral yet ?

[soft lodge]

ye its the same

[still mica]

Do you know the integral of e^x

[soft lodge]

No

I dont remember

[still mica]

The derivative of e^x?

[soft lodge]

1*e^x

[still mica]

Okay so what would the integral of e^x?

[soft lodge]

=1 ?

/ 1 ?

e^x / 1 ?

So the integral of e is just the derivative of

e ?

Really

If it was E^2x

Ye

Then it would be 2e^2x / 2 ?

Oh ye sorry

No I just need a refresher, ill solve it, but then the integral of E^u is just e^u / 1 ?

So its just the same

But I did not know we could use different subsitution.

That really helped

Thank you so muc

much

Then this Would be the answer ?

Just a general question! I forgot which one to be F(x) and which one should be g(x)

Do it matter ?

I have to integrate Ln(u) and have to use the by parts formula

Should I let F(x) = Ln(u)

And g(x) = u ?

.close

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[final magnet]

Why is my pumping lemma proof wrong for this question?

L3 := {xy : there are twice as many 1s in x as in y}

[dim pumice]

first of all, whats the alphabet?

[final magnet]

{0,1}

[dim pumice]

ok so, how exactly did you come to this conclusion that in case i≠1, the word is not in the language?

or why does ib-b have to be exactly 0?

[final magnet]

I suppose in the case the exponents don't equal each other?

1^(3p + ib -b )= 1^3p

[dim pumice]

ah ok, but if you look into the pumping lemma, in condition 3 its asked whether xy^iz is in the language for all i, not whether it matches the original word

[final magnet]

oh you're right

bc this proof would only work is the string i chose repersented the entire language

[dim pumice]

now this still isnt the reason why the pumping lemma approach doesn't work for this language in general

[final magnet]

ik the language is regular

i was just wondering where in my proof i went wrong

[dim pumice]

if you look at the definition of the language, it can be simplified a little

[final magnet]

yeah it's like number of 1's % 3 = 0

thanks for the help

[dim pumice]

right, so now if y contains exactly 3 1s for example, then no matter how much you pump, it will always be in the language, thats why it doesn't really work in general

[final magnet]

yeah that makes sense

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[broken apex]

i dont understand what 3b is asking me to do

[brisk cloak]

3a asks you to create a quadratic

for 3b, if you solve that quadratic and then find the x's that correspond to the y's you found, you have a couple of points

its really just asking u to solve the system of equations

[broken apex]

ah

yeah i got i

it

thanks

.close

[vocal sleet]

Channel closed

Closed by @broken apex

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby kernel]

does BE/EC = 2/3 on line BC mean that BE is longer than BC or BC is longer than BE?

[fading cove]

BC longer than BE

think about it lad

is 2>3 ?

[ruby kernel]

I thought so

so

if B(2,3) and C(6,3)

E is (3.6, 3) right

[fading cove]

uh

[ruby kernel]

4.4

(4.4, 3)

no

(3.6, 3)

[fading cove]

x of BE =2 thirds of 4

and y of BE equals 0 ig

[ruby kernel]

does it not equal 4/5*2 + 2

x co ordinate

[fading cove]

BE= 2/3 BC ?

[ruby kernel]

no

BE/BC = 2/3

they are different

[fading cove]

ok then

BE=2/3BC

[ruby kernel]

ah I said it wrong BE/EC = 2/3

[fading cove]

brehhh

[ruby kernel]

on line BC

😆

[fading cove]

draw it

BE = 2/3 BC

[ruby kernel]

no BE = 2/3 EC

[fading cove]

yes

sorry typo

what do you want to find

[ruby kernel]

so im thinking that E has co ordinates 3.6, 3

because difference in x co ordinqates between B and C is 4, so x co ordinate of E is 4/5*2 + 2

but chat bpg says otherwise

@graceful ibex in need of help

<@&286206848099549185>

[fading cove]

bruhhh

[ruby kernel]

what

[fading cove]

think for a sec

yE = 3

[ruby kernel]

yeh

[fading cove]

what equation can you put

you said it before

[ruby kernel]

what?

[fading cove]

BE= 2/3 EC

[ruby kernel]

I trying to work out co ordinates of E

[fading cove]

and you know BE =4

[fading cove]

yes bruh

[ruby kernel]

no

BC is 4

[fading cove]

ok

[ruby kernel]

I am jsut confused about the ratio part

E either has co ordinates (3.6, 3) or (4.4, 3)

[fading cove]

GIVE ME THE GODDAMN QUESTION CLEAR

WITH ALL THE INFOS IN ONE PLACE

[ruby kernel]

Ive said it twice now 😆

[fading cove]

when you ask for help you dont just give random data like that

[fading cove]

say it again

[ruby kernel]

ok

[wicked shard]

So wait

[ruby kernel]

B(2, 3) C(6,3) and BE/EC = 2/3 where E is a point on line BC

work out co ordinates of E

[wicked shard]

well theres infinitely many solutions isnt there

Or like

[ruby kernel]

what 🤣

[wicked shard]

Atleast more than 1

[fading cove]

ok

[wicked shard]

Theres the obvious one where E is in a line with B and C

but what if it’s not

[ruby kernel]

huh 😆

[wicked shard]

wym 😆

[ruby kernel]

wym wym 😆

re iterating the question B(2, 3) C(6,3) and BE/EC = 2/3 where E is a point on line BC
work out co ordinates of E

<@&286206848099549185>

[vast shale]

Stop spamming pinging helpers

It's the third time you have done it

[ruby kernel]

am in need of help

[wicked shard]

Theres 3 people already helping you

[ruby kernel]

2nd

[wicked shard]

so like

[vast shale]

I believe hired was helping

[wicked shard]

You didnt include the in line on bc part before bruv

Anyway

So this is pretty simple

[ruby kernel]

yes I did 😆

[wicked shard]

Why do you keep using the laughing emoji

[ruby kernel]

said it here

[wicked shard]

that message says edited but anyway

[ruby kernel]

I edited the E

[wicked shard]

so let the distance of e from b be x

[fading cove]

xE = 2 and yE = 4

[wicked shard]

we know that x=2/3(4-x)

[fading cove]

uh yE = 3

[ruby kernel]

brev it is either (3.6, 3) or (4.4, 3)

[wicked shard]

How did you get those numbers? Use the way you got them to solve it

[ruby kernel]

.

[fading cove]

is it said in the enunciation ?

[wicked shard]

…

[ruby kernel]

no

[vast shale]

Also its suggested to not use chat gpt

[ruby kernel]

that is what I judt think

[ruby kernel]

why niot

[fading cove]

oh cool !

[wicked shard]

Okay so “its one of these options because either its the wrong math chatgpt did, the wrong math i did, or neither”

[vast shale]

Because it's bad at answering math

[ruby kernel]

no chatgpt got something else

ok

[wicked shard]

ANYWAY

[fading cove]

ok

[ruby kernel]

But i Know one of them right becasue I am me

[wicked shard]

Lets solve this equation

[fading cove]

it's 4.4

[wicked shard]

fym “i am me”

[fading cove]

you are right

[wicked shard]

???

[fading cove]

x = 4.4 y=3

[ruby kernel]

are you sure

[fading cove]

sorry i did my scheme wrong

[ruby kernel]

Surely ratio BE:EC is 2:3

[fading cove]

yes i am sure.

[wicked shard]

okay can we just do the actual MATH

please

[ruby kernel]

is that what BE/EC =2/3 means

[fading cove]

yes

[ruby kernel]

3BE = 2EC?

[wicked shard]

Yes

[ruby kernel]

so EC is longer than BE

[wicked shard]

yes

[ruby kernel]

so it is 3.6

[wicked shard]

okay can we take a step back

Make an equation for it

[ruby kernel]

fellas 🤣

[wicked shard]

Solve it

And then stop GUESSING RANDOM NUMBERS

[ruby kernel]

the last think they are is random 🤣

[wicked shard]

Let x be the distance BE. We know x=2/3(4-x)

Just solve that for x

Then we have the coordinate

[ruby kernel]

you sure

how much you want to bet 🤣

ahhhhhhhh this is a disaster

[wicked shard]

Okay its 3.6

[fading cove]

it means BE = 2/3 EC
xE-xB = 2/3(xC-xE)
5/3xE = 2/3xC + xB
xE = 6/15xc + 3/5xB

[ruby kernel]

does it mean BE:EC = 2:3 or does it mean BE:EC = 3:2

[fading cove]

listen read what i wrote before

[wicked shard]

BE:EC = 2:3

[ruby kernel]

are you sure

[wicked shard]

yes

[fading cove]

read what i said i am sure

[ruby kernel]

so xE = 3.6

[fading cove]

nope

[ruby kernel]

ok all is gut E(3.6, 3)

[wicked shard]

This is a more complicated way to do it but sure it works

[wicked shard]

WHAT YOU MEAN NO

the equation you yourself posted gives 3.6

[ruby kernel]

🤣

what is going on

[wicked shard]

And the equation i posted

its 3.6

[fading cove]

im jokinggg

it is 3.6

[ruby kernel]

is it 🤣

[wicked shard]

No

[fading cove]

it is goddamn IT