#help-17

1 messages · Page 231 of 1

bitter pilot
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Du willst ja den Winkel, die die Ebene mit der z-Achse einschließen

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der blaue Vektor, das ist ja nicht der Normalenvektor, sondern einer, der parallel ist zum Normalenvektor

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Also ein Vektor der in der Ebene liegt

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und deswegen kannst du einen der beiden Richtungsvektoren auswählen

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Habe (-4,-2,9)v gewählt

tardy peak
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ach so

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danke schön

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.solved

vocal sleetBOT
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tardy peak
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.reopen

vocal sleetBOT
#

bitter pilot
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Also du hattest Recht mit dem Normalenvektor

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Das Problem mit den Richtungsvektoren werde ich an einem Beispiel zeigen

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Das Problem ist, wenn man irgendeinen Richtungsvektor nimmt man dann unterschiedliche Winkel bekommt

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Man gut sehen, wenn man einmal um den Uhrzeigersinn einen Richtungsvektor dreht, dass der Winkel sich vergrößert

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Bei dem Normalenvektor ist es aber so, dass er überall konstant ist, was das ganze Problem easy löst

twin meteorBOT
bitter pilot
tardy peak
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aber warum 90-alpha

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könnten wir nicht einfach alpha schreiben

bitter pilot
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alpha ist der Winkel zwischen dem Normalenvektor und der z-Achse

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du willst aber den Winkel zwischen der z-Achse under Ebene

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Das gesamt ist ja also 90° davon nehmen wir alpha weg, um beta zu kriegen

tardy peak
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ach so

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jetzt verstehe ich

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.solved

vocal sleetBOT
#
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gleaming owl
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Could I get some help on the steps when it comes to doing Average Rate of Change problems but in word form?

gleaming owl
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So here's the problem

blazing wigeon
gleaming owl
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I'm typing it out hold on 🙂

blazing wigeon
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Sorry

gleaming owl
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In 1991 the moose population was measured to be 580 by 1999 the population was measured again to be 6020 if the population continues to change linearly. Find a formula for the moose population P in terms of t, the years since 1990 P(t)=

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I know how to do average rate of change but I need help on how to do it with a word problem

gleaming owl
blazing wigeon
gleaming owl
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Oh yeah that's the full problem then that's my fault

blazing wigeon
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Do you need help with it anyway?

gleaming owl
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Yes

blazing wigeon
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Okay, what are you struggling with about the problem

gleaming owl
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Okay so first of all Linear change is the difference between two functions right or is that Average? and if so what's the difference?

blazing wigeon
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Linear change just means the slope will be constant, the function P will be written in point slope or slope intercept form

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A "straight line" so to speak

gleaming owl
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one moment

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so what is a constant slope? aren't all slopes constant?

blazing wigeon
gleaming owl
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Oh Okay regardless of what values I input?

blazing wigeon
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y=x is a linear function, the slope is always 1

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The slope will always be something for all of function P

gleaming owl
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Oh okay

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So if I go p(3) or p(4) if the function is linear the slope will be the same regardless?

blazing wigeon
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At all points the slope will be the same

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But this isn't helping you solve the problem

gleaming owl
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I'm just clarifying

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okay so what would the formula be for finding the slope of a linear function? and is that what the problem want's me to solve?

blazing wigeon
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The slope is needed to form the function

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The slope is

$\frac{P(t_2)-P(t_1)}{t_2-t_1}$
twin meteorBOT
blazing wigeon
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You need to know two coordinates on P to find the slope

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Can you think of how to find those points

vocal sleetBOT
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@gleaming owl Has your question been resolved?

vocal sleetBOT
#
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vocal sleetBOT
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forest rock
#

hello anyone know how to work out the value of k without technology: (k+1)e^2k = 4

forest rock
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here are the original qu

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(k+1)e^2k = 4 is what i got up to

silk osprey
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lambert W

forest rock
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ok... so true

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oh we dont have that in our study design

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yea thats like way ahead like wtf even is this

silk osprey
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lambert w function

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that’s how you can solve it

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the analytical way

forest rock
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this is pre-uni

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we're not meant to know lambert w

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and if we do use it we have to prove it and im not gonna memorise the proof if i dont understand it yet

vocal sleetBOT
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@forest rock Has your question been resolved?

crude wing
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.reopen

vocal sleetBOT
#

@forest rock Has your question been resolved?

forest rock
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*part a isn't needed but helps antidiffing part d

forest rock
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.close

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vocal sleetBOT
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short kraken
vocal sleetBOT
short kraken
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Is this a trick question

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"Antiderivative" applies to f'(x)

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the anti derivative of f'(x) is f(x)

inner osprey
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can you integrate x with respect to x and tell me what you get?

heavy yoke
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let f(x) = g'(x), then g(x) is the antiderivative of f(x)

short kraken
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f(x) is already in its barest form

short kraken
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I thought it was the other way around

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antiderivarice is when you undo a derivative

inner osprey
inner osprey
short kraken
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I dont get it

heavy yoke
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"antiderivative" is also the same as "indefinite integral"

short kraken
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oh hold up I interpreted the question as "is f(x) an antiderivative"

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Well isn't it always unique then

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Cause of + C

heavy yoke
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yes

short kraken
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but that's just vertical translation

inner osprey
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the + C indicates non-uniqueness

short kraken
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really? I thought the point of + C is that we don't know if there was a constant

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And that if there was we don't know the value

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Cause it could've been + 2 or + 2583953

inner osprey
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that is true

heavy yoke
short kraken
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can you give an example

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like the antiderivative of 2 is 2x + C for example

inner osprey
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that is true

short kraken
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That C can be a random value we have no idea

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so what determines uniqueness?

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If + C doesn't

inner osprey
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could it be you don't know what the word unique means?

short kraken
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One of a kind? Idk 😭

inner osprey
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something is unique when there exists only one of it, or one possilibity of such a thing

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ok good then we're on the same page there

short kraken
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2x + 1 is a different function from 2x+ 2

heavy yoke
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so that means that g(x) = 2x + 2 is an antiderivative of f(x) = 2, and h(x) = 2x - 7 is another antiderivative of f(x) = 2, and 2x + C is an expression that tells us the form an antiderivative should take

inner osprey
short kraken
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nvm

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so 2x is contingent on the C value to make it unique?

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Im getting confused what is the logic supposed to look like

inner osprey
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C is not a variable that has a 'value', so to speak. rather, it is an indication that the antiderivative is only defined up to an additive constant

short kraken
inner osprey
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i see

short kraken
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So the derivative is unique

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but the antiderivative isn't

inner osprey
# inner osprey i see

(it's typically defined using the phrase 'arbitrary constant', i.e. it could take any value but it'd be meaningless to assign it one)

inner osprey
short kraken
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I keep interpreting it as unique cause my textbook illustrated it as a function with multiple vertical translations

short kraken
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Am I on track?

inner osprey
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yes the derivative is unique

short kraken
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K so false

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ty

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.close

vocal sleetBOT
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inner osprey
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yw

vocal sleetBOT
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knotty wyvern
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Could I get help with the left and rule hand rules ?

knotty wyvern
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I don’t know why the rotations work the way they do

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Starting in the original position with thumb pointing left, index pointing up, and middle pointing out , why am I not rotating my hand downwards if my thumb represents the axis of rotation? Unless I am wrong

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I guess in my scenario the z axis should become the -y axis

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But instead I’m rotating my hand right and down ish ? Idk

vocal sleetBOT
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@knotty wyvern Has your question been resolved?

rigid wind
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What is the definition of zero angle

knotty wyvern
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Like no rotation?

rigid wind
knotty wyvern
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Are you an actual helper ?

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<@&268886789983436800>

winter hawk
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@rigid wind dont be rude to others. come back in 24h

vocal sleetBOT
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@knotty wyvern Has your question been resolved?

knotty wyvern
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.close

vocal sleetBOT
#
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flat steppe
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.reopen

vocal sleetBOT
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spice grove
#

Does anyone know how to find the range of this function algebraically?

g(x) = x+3/x^2+1

spice grove
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$(x+3)/(x^2+1)$

twin meteorBOT
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bruhomomento

vocal sleetBOT
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@spice grove Has your question been resolved?

spiral turtle
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Not algebraicly. I know how to do it with differential calculus though.

fickle rose
spiral turtle
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And the zeroes of the discriminant are the extreme points of the range.

spice grove
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oh I see

spice grove
spiral turtle
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@spice grove start by setting g(x) = y and finding a quadratic in x.

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Your answer should be ax^2 + bx + c = 0, where a, b, and c are possibly functions of y.

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For instance (not the actual answer just an example) 2y x^2 + (6+y) x - y+2

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In the above example, a = 2y, b = (6+y), and c = (2-y)

cosmic cloud
spiral turtle
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Now imagine I pick a particular y value. I can find all the points (x, y) that correspond to that y value by substituting it into the quadratic equation, and then solving for x.

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If my y value is too high or too low, then I only get imaginary solutions.

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If I choose one somewhere in the middle of the range, then that's all well and good, most of the time I'll get exactly two solutions

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But at the maximum and the minimum, I'll only get one solution.

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One solution corresponds to when the determinant is 0

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So essentially, find the quadratic, construct the discriminant, set equal to 0, then solve.

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The solution will be the y values you seek.

vocal sleetBOT
#

@spice grove Has your question been resolved?

vocal sleetBOT
#
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glacial zealot
#

Show that the equation x ^ 2 + y ^ 2 + z ^ 2 + t ^ 2 = 2 ^ 2004, where 0 <= x <= y <= z <= t has exactly two solutions in Z

vocal sleetBOT
#

@glacial zealot Has your question been resolved?

vocal sleetBOT
#

@glacial zealot Has your question been resolved?

glacial zealot
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<@&286206848099549185>

rare elbow
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hi

glacial zealot
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I found the solutions, but idk how to show that there are only 2

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x = y = z = 0, t = 2 ^ 1002

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x = y = z = t = 2 ^ 1001

inner osprey
glacial zealot
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a perfect square is 0, 1 or 4 (mod 8)

inner osprey
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that is true

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now consider parity of x, y, z, t

glacial zealot
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ohh so all of them have to be even

inner osprey
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also true

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then u can proceed with this info

glacial zealot
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yea

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think i got it from here

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thanks!

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.close

vocal sleetBOT
#
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inner osprey
#

yvw

vocal sleetBOT
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hoary warren
#

can anyone help me with this question? the power source wasn't provided so how could I find the rest?

cosmic cloud
#

P(power) = V*I

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I think you have to find it on your own

twin horizon
#

Were you told if they are connected in series

twin horizon
twin horizon
hoary warren
cosmic cloud
#

I meant finding those appliances in your home and then checking

hoary warren
#

feel like need to ask teacher for further clarification, thanks for the help

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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hollow plinth
vocal sleetBOT
hollow plinth
#

Hello

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I need to study the boundaries of this function

outer panther
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for rational functions the domain restrictions come from the denominator

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they happen when a value of x results in division by zero

hollow plinth
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Yes?

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It says for x greater than 0

outer panther
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well

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then there's no restriction other than x>0

hearty jungle
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at x = 0 it's 0 and at x = infinity it's 1, so 0 <= y < 1

outer panther
#

i thought this was asking for domain?

hollow plinth
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No lol

hearty jungle
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the domain is given

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x > 0

cosmic cloud
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I don't understand what it means by boundaries

hearty jungle
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range

cosmic cloud
#

for range put y= x/(x+1)

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then solve for x

hollow plinth
#

Like sup and inf

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This first year university real analysis

hearty jungle
#

]0, 1[

hollow plinth
#

Yea

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#
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vocal sleetBOT
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polar hawk
#

I dont understand how to simplify and calculate this lim

lim (x->inf) (1/x^{2}+2/x^{2}+...+(x-1)/x^{2})

twin meteorBOT
polar hawk
#

i need a hint

dim pumice
#

whats 1+2+...+(x-1)?

polar hawk
#

?

azure flame
gentle sleet
#

you can factor out the x^2 stuff

polar hawk
#

thats all thx

#

fr fr

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.close

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#
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feral drift
#

The input range is between 0 and 1, and so is the output range. The probability density function pr(r)= ar^2 of the input image is quadratic, while the probability density function pz(z)=bz of the output image is linear (where a and b are unknown constants).
Find the transformation function z=Q(r) analytically using the relationship between the input and output PDFs.

feral drift
#

can you please verify my solution

visual canyon
#

can anyone help me with bearings?

feral drift
visual canyon
#

bearing in geometry

feral drift
#

<@&286206848099549185>

flat whale
feral drift
flat whale
#

"get cdf of input" top left

rocky lichen
#

||use /spoiler for this secret method||

feral drift
#

Is this correct?

flat whale
feral drift
#

but is it true that z = square root of r power3?

#

do i have to do inverse here?

flat whale
vocal sleetBOT
#

@feral drift Has your question been resolved?

feral drift
#

@open sundial

vocal sleetBOT
#

@feral drift Has your question been resolved?

feral drift
#

question, 2 please also check if my histogram is correct for the input and output

vocal sleetBOT
#

@feral drift Has your question been resolved?

vocal sleetBOT
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mild trench
#

I know this is a VERY dumb question

vocal sleetBOT
mild trench
#

but I haven’t done this in a long time

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and I know how to do it the long way

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but is there a short method to work out the LCM of 2 numbers

cedar burrow
cedar burrow
cedar burrow
# mild trench both

One I can think of is

For lcm(a, b), put a/b in its simplest form (let it be c/d), then ad=bc=lcm(a, b)

mild trench
#

I know this

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how about

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3 numbers?

cedar burrow
#

Shouldn’t rinse and repeat work?

mild trench
#

hmm lemme try

vocal sleetBOT
#

@mild trench Has your question been resolved?

vocal sleetBOT
#
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tardy peak
vocal sleetBOT
vast shale
#

there's a common factor that can be cancelled from both expressions

tardy peak
#

Ohh i see

#

What should i do after this. (X+2)/(X-4)

vast shale
#

ye, try that and see if it works

tardy peak
#

Denominator is still 0

vast shale
tardy peak
#

6/0

vast shale
#

if a limit statement from direct evaluation results in both the numerator AND denominator being 0

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it is an "indeterminate form"

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like 0/0

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but since now the numerator is 6 and the denominator is 0 it is no longer indeterminant

tardy peak
#

But its not indeterminate i think

vast shale
#

yes

vast shale
#

so the answer is simply infinity

tardy peak
#

Yeah

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So can i just directly write 0

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As an answer

vast shale
#

no no no

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0/6=0

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6/0= infinity

tardy peak
#

Ohh okay

vast shale
#

@tardy peak does that make sense??

#

oop sorry

tardy peak
#

Why

tardy peak
vast shale
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vast shale
#

shoot

#

ok what part doesnt make sense??

tardy peak
#

6/0 is inf doesnt make a sense to me

vast shale
#

hmm okay

bitter pilot
vast shale
#

in the context of limit statements yes

bitter pilot
#

1/x

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the limit DNE

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from the left you get -inf from the right +inf

twin meteorBOT
bitter pilot
#

If x < 4 then that expression is negative

vast shale
#

hmm wait youre right

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is there a specific method to instantly determining that

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because if you square the entire expression ((x+2)/(x-4))^2 the limit all of a sudden exists

bitter pilot
#

We can make a substitution $x = u+4$ to see that it has the form of $\frac{1}{x}$ [ \lim_{u \to 0} \frac{u+6}{u} = \lim_{u \to 0} 1 + \frac{6}{u} ]

bitter pilot
bitter pilot
#

the rule is if your linear factor has an odd power in the denominator then it changes sign around the vertical asymptote, but if the power is even it doesn't

vast shale
#

well thats just a logical statement to make though

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i cant remember but i couldve sworn there was another thing

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not sure what it is tho

#

ig i forgot about it now

twin meteorBOT
bitter pilot
#

I hate the formatting sometimes

vast shale
#

lol just type it normally its fine

bitter pilot
#

no

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khishi needs this

vast shale
#

alright then well good luck

bitter pilot
#

,w plot y=(x^2-2x-8)/(x^2-8x+16) between 0 and 8

vast shale
#

beautiful

#

!done

vocal sleetBOT
#

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tardy peak
#

Then what is the answer?

#

Is it 0?

bitter pilot
#

From the right you approach a different limit then from the left

tardy peak
#

I see

#

Thanks

#

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inland sail
vocal sleetBOT
inland sail
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
inland sail
#

2

#

Simplify

#

I’ll show my work

#

i got it

#

.solved

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vast shale
#

Can i get some help

vocal sleetBOT
inland sail
vast shale
#

Okay thanks

#

Its statitsc

#

Statistics

#

So for 1i dont understand how x^2f

#

Im tryinng to find the phito

#

So apprently the correct answer for x^2f is this bottom photo

#

And i dont get how its that

vocal sleetBOT
#

@vast shale Has your question been resolved?

vast shale
#

<@&286206848099549185>

vast shale
#

<@&286206848099549185>

broken glacier
#

it seems there's outright refusal to help with stats on this server

vocal sleetBOT
#

@vast shale Has your question been resolved?

plush tinsel
#

could anyone help me with micro

#

pls

#

I’m having a hard time

#

<@&286206848099549185>

#

<@&286206848099549185>

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carmine cedar
#

$\int {{2xsin{x}} \over {3 + cos{2x}}}dx$

twin meteorBOT
#

daniel_zein

carmine cedar
#

how am I supposed to do this?

flat whale
#

,w int (2x sin(x))/(3+cos(2x))

flat whale
vocal sleetBOT
# carmine cedar $\int {{2xsin{x}} \over {3 + cos{2x}}}dx$

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

pale perch
#

oh dear lord

carmine cedar
#

holy hell

bitter pilot
vocal sleetBOT
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warped prairie
#

How do I verify if this is true: column space of AB is a subspace of column space of A

vocal sleetBOT
#

@warped prairie Has your question been resolved?

warped prairie
#

<@&286206848099549185>

warped prairie
#

<@&286206848099549185> hmmcatfone

cunning basin
#

lol

flat whale
#

Either check for the definition of subspace using what it means to be in the column space of AB or find a counter example

cunning basin
warped prairie
#

That's exactly my question, what does it mean when we talk about a column or row space of AB

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#

@warped prairie Has your question been resolved?

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little isle
#

What are the root(s) of x²=0 ?

vocal sleetBOT
torn oracle
#

just 0

little isle
#

solve for x² in 3mx² +mnx - 3nx -n² =0

#

howw

#

<@&286206848099549185>

#

How

flat whale
twin meteorBOT
#

riemann

little isle
#

tex.?

#

but like its not in standard form..

#

What will I do

flat whale
little isle
#

Howww

flat whale
little isle
#

@flat whale

flat whale
little isle
#

<@&286206848099549185>

flat whale
#

Welp I'm being ignored

pine hull
pine hull
kind light
#

you can technichally just square it :3

kind light
vocal sleetBOT
# noble gyro

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

kind light
#

you should delete it

vocal sleetBOT
#

@little isle Has your question been resolved?

little isle
#

what

pine hull
#

@little isle your question is this
solve for 3mx² +mnx - 3nx -n² =0
To solve any quadratic equation you need to convert it into form
ax²+bx+c=0

pine hull
little isle
#

Guys ..

#

Guys what is the function of this

#

Quadratic function for that graph

#

Equation

pine hull
#

That way others can understand what's your actual doubt

vocal sleetBOT
#
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twin citrus
vocal sleetBOT
twin citrus
#

do we have to do this by hand?

#

and if so how to do that without pain ?

fading plume
#

what approximation techniques have you learned in class

#

newton's method comes to mind

twin citrus
#

no no this is not calculus

#

its precalculus

#

there is no method to approximate square roots yet

fading plume
#

oh interesting? not sure if we can help without knowing the method then

heavy yoke
#

are you meant to use a calculator?

fading plume
#

not much of an approximation then is it

heavy yoke
#

it's still approximate if you round it(?)

edgy gulch
twin citrus
#

my consern is that why authir nit allowed to use calculator here ?

fading plume
#

i guess you could binary search

#

but again i'm not sure what the context of this question is

twin citrus
#

tnx all

#

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vocal sleetBOT
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prisma parcel
#

Simply: why do we need the assumption of the AoC here?

tawny nacelle
#

iirc, you need Zorn’s lemma to find a maximal linearly independent set in this proof

#

which is equivalent to AoC

#

in finite dim, you don’t need it

#

but in inf dim, you do

#

oh wait, I literally misread the question lol

#

I thought this was every vsp has a basis for some reason zz

dense moon
#

I mean it trivally proves every vector space has a basis

#

the vector space spans itself ofc

prisma parcel
prisma parcel
dense moon
#

I'm just making the observation that "every spanning set contains a basis" implies "every vector space has a basis" since you can take the vector space itself as the spanning set.

prisma parcel
#

Ahhhh

#

Okay that makes sense

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@prisma parcel Has your question been resolved?

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formal nymph
#

hello can someone help me get the common ratio or common difference in this..

formal nymph
#

and can you check if this is correct

#

we were tasked to identify of it was either arithmetic or geometric sequence, and then we will put the common difference or ratio

#

<@&286206848099549185>

wise cape
#

Hello

formal nymph
#

hello

#

can u check my answers 😿

#

i dont have an answer for 4, and 8

wise cape
#

I have no clue as I haven’t done this yet

cunning ingot
cunning ingot
formal nymph
#

isnt this what we should do to get the ratio

#

i dont get it huhu

#

i need helpp

#

@hel

#

<@&286206848099549185>

dull fjord
#

hi

#

what you need

spice kestrel
formal nymph
#

<@&286206848099549185>

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.close

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verbal coyote
#

Is this an quadratic equation?

vocal sleetBOT
verbal coyote
#

Can I just put
a = 1
b = -4 +2i
c = 12-4i

neat dawn
#

Yes, with complex co-efficient

#

Yes

verbal coyote
#

Alright I will try! Thank you so much :))

#

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ionic marlin
#

can we write

vocal sleetBOT
ionic marlin
#

f_0cos(wt) as F_0e^(iwt)?

hard atlas
#

if you put a real part somewhere in there, sure

ionic marlin
#

this is the differential equation

#

and the solution we get is Bcos(wt-phi)

#

which we can express in exponential form

#

which I get

#

i dont get what happened after that

#

can you please help me out

#

@hard atlas

#

so is this right

#

this is what i understand

#

e^i*y = cos(y) + i sin(y)

#

the only real part is cos(y)

#

where y = wt-phi

#

so Re(e^iy) = cos y

#

thats it right

hard atlas
#

yes

ionic marlin
#

cool

#

.close

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whole gale
#

why are the limits in a miltiple integral called the rectangular region

full summit
#

integrating a function is finding the area under the curve

whole gale
#

yes

full summit
#

rectangular region refers to the limits of integration over a rectangular shaped area?

whole gale
#

uhhh

#

alr thanks

#

!close

#

?close

#

.close

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tawny nacelle
#

does this proof work?

vocal sleetBOT
tawny nacelle
#

what are all those reacts for pandaohno

fervent wasp
#

An admiration to JEE 🫡

tawny nacelle
#

@dull bear please help cat_happycry

#

I see you here

dull bear
#

Nah I'm just here to add to the reacts kek

tawny nacelle
dull bear
#

I'll take a look thonkg

#

I'm happy happyCat

tawny nacelle
#

thank you chartbit for your services happy

#

have this GIF as compensation

#

.solved happy

vocal sleetBOT
#
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torn timber
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latent eagle
#

can someone explain how to do this without expanding the brackets completely

twin horizon
#

Maybe try

#

(1+x²)^5=(1+x²)^4*(1+x²)=

#

Then you can bring (1+x²)^4 with (2+x)^4

#

Apply law of indices

#

And next binomial theorem

#

I hope this makes sense 😅😔

peak matrix
peak matrix
twin horizon
peak matrix
#

how are you gonna apply binomial theorem to that

twin horizon
#

Sub

peak matrix
#

sounds painful

twin horizon
#

That's the word

#

Lol

peak matrix
#

it might be unclear

twin horizon
#

Since you are only concerned about the power "3" on x so you only need to find the coefficients and add them right

latent eagle
#

yes

peak matrix
#

so you need to find coefficients of
x^0 * x^3
x^1 * x^2
x^2 * x^1
x^3 * x^0

where the first x comes from (2+x)^4 and the second x comes from (1+x^2)^5

latent eagle
#

so find x^3 coefficient for both brackets ?

peak matrix
#

I'll temporarily adapt notation Ca(x^n) for coefficient of x^n in the first multiplicand (2+x)^4 and Cb(x^n) for the coefficient of x^n in the second multiplicand (1+x^2)^5

Then the coefficient of x^3 in the result should be:
Ca(x^0) * Cb(x^3) + Ca(x^1) * Cb(x^2) + Ca(x^2) * Cb(x^1) + Ca(x^3) * Cb(x^0)

peak matrix
peak matrix
#

once you find the coefficients, the result can then be written as
(a + bx + cx^2 + dx^3 + [useless...]) * (e + fx + gx^2 + hx^3 + [useless...])

#

and if you were to expand that out, the coefficient of x^3 will be
ah + bg + cf + de

latent eagle
#

yeah i got 168x^3

#

168

peak matrix
#

,w (2+x)^4(1+x^2)^5

twin meteorBOT
peak matrix
#

,w expand (2+x)^4(1+x^2)^5

twin meteorBOT
peak matrix
#

yep

#

168

latent eagle
#

👍

#

.close

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thick niche
vocal sleetBOT
thick niche
#

is there a way to solve this algebraically

inner osprey
#

no matter what u do u would need some kind of estimation

thick niche
#

took me 9 whole mins

knotty lynx
#

9 minutes?

inner osprey
# thick niche took me 9 whole mins

ye when doing smth like this u might consider some rough argument to start at a later number instead of doing all of n = 1, 2, etc until u find the ans

thick niche
#

yea :/

knotty lynx
#

Did you evaluate the binom as-is?

thick niche
thick niche
#

i dont know how to get better

inner osprey
thick niche
#

its dragging me down and i feel depressed

inner osprey
#

did u simplify the binomial coefficient

thick niche
#

no i estimated

inner osprey
#

how did u estimate?

thick niche
#

A * 10^ ...

#

i compared LHS and RHS

brisk moss
#

maybe you could do something with stirling’s approximation first to get a place to start

inner osprey
#

stirling?

inner osprey
#

note (10n + 2) - (10n - 1) = 3

thick niche
#

yeah

#

i just did

inner osprey
#

so did use property n C k = n C (n - k)

thick niche
#

10n + 2 (10n +1 (10n

inner osprey
#

ok very good

thick niche
#

divdide by 6

inner osprey
#

ye nice ok

thick niche
#

how do i

#

get better at arithmetic

#

i tried doing worksheets

#

idk if im getting faster or not

inner osprey
#

if ur issue is only ‘arithmetic’, then nothing but practice will help i think

#

but for this problem in particular i think some bit of intuition may help you

thick niche
#

oke

#

thanks

#

btw whats the stirling approximathing thing

#

is it useful

inner osprey
inner osprey
thick niche
#

o

inner osprey
#

it is typically used when u have limits involving factorials

#

(i do not see use for it here)

thick niche
#

is that like taylor serie or something

inner osprey
#

in most cases where stirling approximation is necessary, you would use this statement and that would be sufficient

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#
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inner osprey
#

yw

vocal sleetBOT
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short rover
vocal sleetBOT
short rover
#

how did we go from step 1 to step 2

sullen shoal
#

Divide by 4^n

sullen shoal
short rover
#

oh

#

wait let me try

#

okay tysm

#

.close

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#
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pallid trout
#

(1+2​)^2006=a+b√2​. calculate a^2-2b^2

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#
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knotty wyvern
#

can i get some help identifying the handedness of a 3d coordinate system either with maybe a resource or given questions?

knotty wyvern
#

.close

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ocean shale
#

Does anyone know what kind of question this would be called? I'm trying to find videos for it on khanacademy but googling "how to make a fraction/division problem undefined" really isn't getting the videos I want.

heavy yoke
#

something like "domain of a rational function"

ocean shale
#

that seems similar I'm not sure if that is what the problem is called

#

very close though because it's algebra 1

vocal sleetBOT
#

@ocean shale Has your question been resolved?

oblique kettle
#

poles, singularities of functions

vocal sleetBOT
#
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alpine trout
#

where did 12 come form

vocal sleetBOT
red ridge
alpine trout
#

its the bottom part

#

the 1 amu=1.9927e-23

#

/12

#

like i know its the mass number/ avvogadro number to get gram but the second part of it is confusing

heavy yoke
#

1 amu is supposed to be roughly the weight of 1 proton or 1 neutron, a carbon atom has 12 (6 protons and 6 neutrons)

storm terrace
vocal sleetBOT
#

@alpine trout Has your question been resolved?

ocean shale
#

although what you are saying is giving me a brainblast currently and I think I almost get what you are saying

storm terrace
vocal sleetBOT
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cedar kernel
#

I needed help with this differential equation and these type in general

cedar kernel
#

L and C are constants

#

And I need to solve for I

#

Can anyone give a basic idea to solve these , I will try to adapt , I have not exactly studied differential equation of these types before but came across it while doing physics

lavish river
#

second order de

cedar kernel
#

Oh wait this is just shm

#

I'm dumb my bad

heavy yoke
cedar kernel
#

I will go through it

#

Thanks a lot !!

#

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vast shale
#

how would i start this (assignment title is induction and binomial theorem)

vast shale
#

please @ me if u have an answer

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@vast shale Has your question been resolved?

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@vast shale Has your question been resolved?

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@vast shale Has your question been resolved?

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@vast shale Has your question been resolved?

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@vast shale Has your question been resolved?

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random ice
vocal sleetBOT
random ice
#

How do you factor out 4^x if its 4^x +4^x * 4^1 = 40

#

There is still a 4^1

oblique kettle
#

$4^x + 4^{x+1} = 4^x + 4^1 \cdot 4^x = 4^x + 4 \cdot 4^x = 4^x (1 + 4) = 5 \cdot 4^x$

twin meteorBOT
vocal sleetBOT
#

@random ice Has your question been resolved?

random ice
#

oh I see

#

Thanks a lot

vocal sleetBOT
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sturdy crag
#

does this mean that the answer of km/h and m/s should have 5 significant figures? because of 86400?

warm vine
#

yes

sturdy crag
#

so does the two 0's after 4 also count?

warm vine
#

oh sorry didnt notice you wrote 5

#

it should be 3

sturdy crag
#

thank you for your help! :)

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livid prairie
#

how many 50 x 50 grids of white and black cells are there such that

  1. no two white cells touch
  2. every black cell touches a white cell
    (diagonal touching by corners counts as touching)
livid prairie
#

we've solved it for nx1 grids

#

gonna update this over time:

#

f(m, n) = f(n, m)
f(1, 1) = 1
f(2, 1) = 2
f(3, 1) = 2
f(4, 1) = 3
f(5, 1) = 4
f(n, 1) = f(n - 1) + f(n - 5)

#

@brisk moss

#

so

#

for nx2 grids

#

f(2, 1) = 2 (W/B, B/W)

#

f(2, 2) = 4 (WB/BB and rotations)

#

now how to extend

#

if last column is W/B or B/W you can do B/B

#

if it's B/B you can do W/B or B/W

inner osprey
#

joy

#

wait that is not the recursion lol

livid prairie
#

i'm making the recursion for f(n, 2) not f(n, 1)

dense eagle
livid prairie
#

this is not a traditional help channel question, layla found a problem and a few of us started working on it, we realized that we were clogging up discussion so we made a help channel

inner osprey
livid prairie
#

ok

inner osprey
#

ur recursion for f(n, 1) is not right

livid prairie
#

how

brisk moss
#

layla found a problem
not quite the correct lore but ok lol

livid prairie
#

lol

#

if it ends in B you can add W, if it ends in W you can add B, if it ends in B you can add WBBWB

#

there

#

computer verified up to n = 20

#

lol

brisk moss
brisk moss
livid prairie
#

my school chromebook isn't powerful enough to run that

brisk moss
#

ok i can do it

livid prairie
#

for tests up to n = 50 we need a good computer

#

it would still take several days tho

brisk moss
#

no i meant with your recursion

livid prairie
#

oh

inner osprey
livid prairie
#

if the last column is WB or BW you can add BB and (WB or BW), if it's BB you can add WB or BW

brisk moss
livid prairie
#

does this produce everything?

livid prairie
#

actually

#

lemme try computer generation

brisk moss
#

||incorrect buzzer sound||

vocal sleetBOT
#

@livid prairie Has your question been resolved?

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#
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brisk moss
#

.reopen

vocal sleetBOT
#

inner osprey
brisk moss
inner osprey
#

🫵

brisk moss
flat whale
brisk moss
vocal sleetBOT
#

@livid prairie Has your question been resolved?

vocal sleetBOT
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untold arrow
#

Why did they move pho out? Isn't the inner integral related to pho? Then why can pho be moved out

vast shale
#

they didnt

#

they integrated it

bronze osprey
#

btw it's phi, not pho

#

or are you hungry for food

spiral turtle
#

That's not phi or pho

bronze osprey
#

I mean rho

spiral turtle
#

that's rho

outer warren
#

its rho

vast shale
#

lol

#

$\rho$

twin meteorBOT
#

icannotdoanymorecauchy

bronze osprey
#

rho rho rho your boat
gently down the stream

bitter pilot
#

bro's getting bullied 💀

untold arrow
#

lol yea brain moment for this question and pho rho

#

.close

vocal sleetBOT
#
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bitter pilot
vocal sleetBOT
bitter pilot
#

does this make sense

cobalt crypt
#

💀

dense moon
#

<@&268886789983436800>

dense eagle
#

<@&268886789983436800>

bitter pilot
#

he got smayed out

arctic mantle
#

?

dense moon
dense eagle
bitter pilot
#

sometimes i talk too much

dense moon
#

each one of your inequalities is unjustified (and incorrect, even)
to be a bit direct

bitter pilot
dense moon
#

I mean you haven't justified them

#

But even just thinking loosely

bitter pilot
#

-1 <= sin(x) <= 1 trivially

#

|1-x| = |x-1|

#

then use my assumption with delta

dense moon
#

The first inequality might be okay

bitter pilot
#

then i wanna bound |x|

#

1/|x| < 1/(1-delta)

#

then i somehow got lost

dense moon
#

why is |x-1|/|x| less than delta/|x|

dense eagle
#

why is |x-1| < delta?

bitter pilot
#

seriously

dense eagle
#

we're taking the limit as x -> 0, not 1

bitter pilot
#

oh

dense moon
#

would be a very surprising result if it were x -> 1

#

sin(1) = 1 qed

bitter pilot
#

😂

#

i will try new

dense moon
#

anyways, one hint for why your proof couldn't work is that you didn't use any properties of sin

#

i.e. the same reasoning could be applied to x^2/x, which goes to 0

#

or sqrt(x)/x, which diverges

bitter pilot
#

I have made progress but I struggle with 1/|x|

flat whale
#

you sometimes have to do something like delta = min{eps, 1}

dense moon
#

it helps to think about this a bit more loosely

bitter pilot
#

yea ik

#

min is basically cheating

dense moon
#

|sin x| is going to be close to |x|

bitter pilot
#

how

dense moon
#

well that's what you're trying to prove, no?

bitter pilot
#

oh

dense moon
#

so (|sin x| + |x|)/|x| is going to be close to 2 for small |x|, loosely speaking

#

so it doesn't really help to bound by that

#

I mean it should converge to exactly 2, if what you're proving is correct

flat whale
bitter pilot
#

i actually thought about taylor expansion and then i imagined how everybody would flame me

flat whale
#

doing this problem deserves flaming when you already know squeeze theorem and trig

bitter pilot
#

I do this specifically with epsilon delta cause I never did it really

#

and I wanna practice that

flat whale
#

do real problems for practice

dense moon
#

I mean you need properties of sin for this

dense moon
#

a good exercise is to prove that arithmetic of limits works

dense eagle
#

should warn u that q14 is like really hard

#

(actually idk how to do the latter part of 14, and i don't think i know anyone who does)

vocal sleetBOT
#

@bitter pilot Has your question been resolved?

bitter pilot
#

It's honestly impossible

#

triangles hate me

#

I will make my own method

mystic tide
#

Here’s another approach, if you agree 0<cos(x)<sin(x)/x<1 when x is close to zero the proof becomes much easier. This is easy to show using trig.

vocal sleetBOT
#

@bitter pilot Has your question been resolved?

bitter pilot
#

Y'all ain't ready for this

twin meteorBOT
bitter pilot
#

This is the alpha omega method

#

@short pilot Yo

tight hearth
#

yo guys i have a problem with this im in the first year baccalaureate so please can some one help me to solve this

bitter pilot
#

thats my channel

tight hearth
#

what why ?\

#

bro if you have solution give it to me please

bitter pilot
#

<@&268886789983436800>

tight hearth
bitter pilot
#

my poor proof

tight hearth
#

bro lock im a new in this server

#

i don't now what im gonna do

limber falcon
#

use one of these

bitter pilot
chilly prawn
bitter pilot
cobalt crypt
#

that was for the spam earlier that got nuked 💀

flat whale
#

why use alpha and omega instead of epsilon and delta

bitter pilot
#

😕

dense moon
#

a < b doesn't imply |a - c| < |b - c|

#

also if you're ok with using the fact that sin' = cos then you can just use the definition of the derivative with sin'(0) = cos(0) = 1.

vocal sleetBOT
#

@bitter pilot Has your question been resolved?

vocal sleetBOT
#
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