#help-17
1 messages · Page 231 of 1
der blaue Vektor, das ist ja nicht der Normalenvektor, sondern einer, der parallel ist zum Normalenvektor
Also ein Vektor der in der Ebene liegt
und deswegen kannst du einen der beiden Richtungsvektoren auswählen
Habe (-4,-2,9)v gewählt
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✅
Also du hattest Recht mit dem Normalenvektor
Das Problem mit den Richtungsvektoren werde ich an einem Beispiel zeigen
Das Problem ist, wenn man irgendeinen Richtungsvektor nimmt man dann unterschiedliche Winkel bekommt
Man gut sehen, wenn man einmal um den Uhrzeigersinn einen Richtungsvektor dreht, dass der Winkel sich vergrößert
Bei dem Normalenvektor ist es aber so, dass er überall konstant ist, was das ganze Problem easy löst
bacc
Hoffe das erkennt man hier
alpha ist der Winkel zwischen dem Normalenvektor und der z-Achse
du willst aber den Winkel zwischen der z-Achse under Ebene
Das gesamt ist ja also 90° davon nehmen wir alpha weg, um beta zu kriegen
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Could I get some help on the steps when it comes to doing Average Rate of Change problems but in word form?
So here's the problem
Where
I'm typing it out hold on 🙂
Sorry
In 1991 the moose population was measured to be 580 by 1999 the population was measured again to be 6020 if the population continues to change linearly. Find a formula for the moose population P in terms of t, the years since 1990 P(t)=
I know how to do average rate of change but I need help on how to do it with a word problem
there we go
Is this the full problem? It doesnt seem to ask about average rate it's talking about linear change
Oh yeah that's the full problem then that's my fault
Do you need help with it anyway?
Yes
Okay, what are you struggling with about the problem
Okay so first of all Linear change is the difference between two functions right or is that Average? and if so what's the difference?
Linear change just means the slope will be constant, the function P will be written in point slope or slope intercept form
A "straight line" so to speak
Yes, all slopes are constant, but when I say that the slope will be constant I mean that the slope will remain the same for the whole function
Oh Okay regardless of what values I input?
y=x is a linear function, the slope is always 1
The slope will always be something for all of function P
Oh okay
So if I go p(3) or p(4) if the function is linear the slope will be the same regardless?
Yes
At all points the slope will be the same
But this isn't helping you solve the problem
I'm just clarifying
okay so what would the formula be for finding the slope of a linear function? and is that what the problem want's me to solve?
You need to find the slope to solve the problem yes. The answer to the problem will be a function
The slope is needed to form the function
The slope is
$\frac{P(t_2)-P(t_1)}{t_2-t_1}$
mari
You need to know two coordinates on P to find the slope
Can you think of how to find those points
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hello anyone know how to work out the value of k without technology: (k+1)e^2k = 4
lambert W
ok... so true
oh we dont have that in our study design
yea thats like way ahead like wtf even is this
this is pre-uni
we're not meant to know lambert w
and if we do use it we have to prove it and im not gonna memorise the proof if i dont understand it yet
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@forest rock Has your question been resolved?
*part a isn't needed but helps antidiffing part d
.close
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Is this a trick question
"Antiderivative" applies to f'(x)
the anti derivative of f'(x) is f(x)
can you integrate x with respect to x and tell me what you get?
let f(x) = g'(x), then g(x) is the antiderivative of f(x)
f(x) is already in its barest form
Oh
I thought it was the other way around
antiderivarice is when you undo a derivative
this is true
this is also true
So it's false how do you get the antiderivative of f(x)
I dont get it
"antiderivative" is also the same as "indefinite integral"
oh hold up I interpreted the question as "is f(x) an antiderivative"
Well isn't it always unique then
Cause of + C
yes
but that's just vertical translation
really? I thought the point of + C is that we don't know if there was a constant
And that if there was we don't know the value
Cause it could've been + 2 or + 2583953
that is true
that means that every value of C produces a different antiderivative
that is true
That C can be a random value we have no idea
so what determines uniqueness?
If + C doesn't
could it be you don't know what the word unique means?
One of a kind? Idk 😭
something is unique when there exists only one of it, or one possilibity of such a thing
ok good then we're on the same page there
2x + 1 is a different function from 2x+ 2
so that means that g(x) = 2x + 2 is an antiderivative of f(x) = 2, and h(x) = 2x - 7 is another antiderivative of f(x) = 2, and 2x + C is an expression that tells us the form an antiderivative should take
and both of these are antiderivatives of 2, as you've stated
so there exists multiple 2x
nvm
so 2x is contingent on the C value to make it unique?
Im getting confused what is the logic supposed to look like
the idea is that the presence of the + C makes the antiderivative non-unique
C is not a variable that has a 'value', so to speak. rather, it is an indication that the antiderivative is only defined up to an additive constant
I was interpreting it is as a placeholder
i see
(it's typically defined using the phrase 'arbitrary constant', i.e. it could take any value but it'd be meaningless to assign it one)
these assertions are correct yes
I keep interpreting it as unique cause my textbook illustrated it as a function with multiple vertical translations
so say f(x) = 2x. The derivative of 2x is 2, and only one f'(x) = 2 exists
Am I on track?
yes the derivative is unique
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Could I get help with the left and rule hand rules ?
I don’t know why the rotations work the way they do
Starting in the original position with thumb pointing left, index pointing up, and middle pointing out , why am I not rotating my hand downwards if my thumb represents the axis of rotation? Unless I am wrong
I guess in my scenario the z axis should become the -y axis
But instead I’m rotating my hand right and down ish ? Idk
@knotty wyvern Has your question been resolved?
What is the definition of zero angle
Like no rotation?
U r drunk
@rigid wind dont be rude to others. come back in 24h
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Does anyone know how to find the range of this function algebraically?
g(x) = x+3/x^2+1
$(x+3)/(x^2+1)$
bruhomomento
@spice grove Has your question been resolved?
Not algebraicly. I know how to do it with differential calculus though.
assume it to be y, you get a quadratic, it should have positive discriminant
Oh! Smart!
And the zeroes of the discriminant are the extreme points of the range.
oh I see
I don't understand this part tho...
@spice grove start by setting g(x) = y and finding a quadratic in x.
Your answer should be ax^2 + bx + c = 0, where a, b, and c are possibly functions of y.
For instance (not the actual answer just an example) 2y x^2 + (6+y) x - y+2
In the above example, a = 2y, b = (6+y), and c = (2-y)
Maximum/minimum values
Now imagine I pick a particular y value. I can find all the points (x, y) that correspond to that y value by substituting it into the quadratic equation, and then solving for x.
If my y value is too high or too low, then I only get imaginary solutions.
If I choose one somewhere in the middle of the range, then that's all well and good, most of the time I'll get exactly two solutions
But at the maximum and the minimum, I'll only get one solution.
One solution corresponds to when the determinant is 0
So essentially, find the quadratic, construct the discriminant, set equal to 0, then solve.
The solution will be the y values you seek.
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Show that the equation x ^ 2 + y ^ 2 + z ^ 2 + t ^ 2 = 2 ^ 2004, where 0 <= x <= y <= z <= t has exactly two solutions in Z
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@glacial zealot Has your question been resolved?
<@&286206848099549185>
hi
.
I found the solutions, but idk how to show that there are only 2
x = y = z = 0, t = 2 ^ 1002
x = y = z = t = 2 ^ 1001
to prove this, use (mod 8)
a perfect square is 0, 1 or 4 (mod 8)
ohh so all of them have to be even
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can anyone help me with this question? the power source wasn't provided so how could I find the rest?
Were you told if they are connected in series
Probably
If they are then the current is the same
yea my teacher said use formula but I assume it is impossible without any given clues?
I meant finding those appliances in your home and then checking
feel like need to ask teacher for further clarification, thanks for the help
.close
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for rational functions the domain restrictions come from the denominator
they happen when a value of x results in division by zero
at x = 0 it's 0 and at x = infinity it's 1, so 0 <= y < 1
i thought this was asking for domain?
No lol
I don't understand what it means by boundaries
range
]0, 1[
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I dont understand how to simplify and calculate this lim
lim (x->inf) (1/x^{2}+2/x^{2}+...+(x-1)/x^{2})
Danya
i need a hint
whats 1+2+...+(x-1)?
use sigma n=n(n-1)/2
you can factor out the x^2 stuff
oh im freak
thats all thx
fr fr
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The input range is between 0 and 1, and so is the output range. The probability density function pr(r)= ar^2 of the input image is quadratic, while the probability density function pz(z)=bz of the output image is linear (where a and b are unknown constants).
Find the transformation function z=Q(r) analytically using the relationship between the input and output PDFs.
can you please verify my solution
can anyone help me with bearings?
what do u mean
bearing in geometry
please ask in another thread, this room for specific question i raised
<@&286206848099549185>
Your cdf looks wrong. Follow the definition
which lines you mean can you elaborate
"get cdf of input" top left
||use /spoiler for this secret method||
Is this correct?
Yes
Show the original question
here
@feral drift Has your question been resolved?
@feral drift Has your question been resolved?
@feral drift Has your question been resolved?
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I know this is a VERY dumb question
but I haven’t done this in a long time
and I know how to do it the long way
but is there a short method to work out the LCM of 2 numbers
With or without calculator (namely one that can return fractions)?
<@&286206848099549185>
Open a new channel, this one is no longer yours
One I can think of is
For lcm(a, b), put a/b in its simplest form (let it be c/d), then ad=bc=lcm(a, b)
yes
I know this
how about
3 numbers?
Shouldn’t rinse and repeat work?
hmm lemme try
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factor the numerator and denominator
there's a common factor that can be cancelled from both expressions
ye, try that and see if it works
Denominator is still 0
okay this needs a bit of extra explaining
6/0
if a limit statement from direct evaluation results in both the numerator AND denominator being 0
it is an "indeterminate form"
like 0/0
but since now the numerator is 6 and the denominator is 0 it is no longer indeterminant
But its not indeterminate i think
yes
because of this
so the answer is simply infinity
Ohh okay
Why
Im not sure hhe
!status
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
6/0 is inf doesnt make a sense to me
no
in the context of limit statements yes
bacc
If x < 4 then that expression is negative
hmm wait youre right
is there a specific method to instantly determining that
because if you square the entire expression ((x+2)/(x-4))^2 the limit all of a sudden exists
We can make a substitution $x = u+4$ to see that it has the form of $\frac{1}{x}$ [ \lim_{u \to 0} \frac{u+6}{u} = \lim_{u \to 0} 1 + \frac{6}{u} ]
cause the square makes it from both side approaching +inf
yes ofc
the rule is if your linear factor has an odd power in the denominator then it changes sign around the vertical asymptote, but if the power is even it doesn't
well thats just a logical statement to make though
i cant remember but i couldve sworn there was another thing
not sure what it is tho
ig i forgot about it now
bacc
I hate the formatting sometimes
lol just type it normally its fine
alright then well good luck
,w plot y=(x^2-2x-8)/(x^2-8x+16) between 0 and 8
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Does not exist
From the right you approach a different limit then from the left
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
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Can i get some help
Okay thanks
Its statitsc
Statistics
So for 1i dont understand how x^2f
Im tryinng to find the phito
So apprently the correct answer for x^2f is this bottom photo
And i dont get how its that
@vast shale Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
it seems there's outright refusal to help with stats on this server
@vast shale Has your question been resolved?
could anyone help me with micro
pls
I’m having a hard time
<@&286206848099549185>
<@&286206848099549185>
So not sigma
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$\int {{2xsin{x}} \over {3 + cos{2x}}}dx$
daniel_zein
how am I supposed to do this?
,w int (2x sin(x))/(3+cos(2x))
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
oh dear lord
holy hell
pov you forgot the bounds
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How do I verify if this is true: column space of AB is a subspace of column space of A
@warped prairie Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185> 
lol
Either check for the definition of subspace using what it means to be in the column space of AB or find a counter example

That's exactly my question, what does it mean when we talk about a column or row space of AB
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What are the root(s) of x²=0 ?
just 0
,tex .quadratic formula
riemann
Put it in standard form
Howww
Get x by itself
@flat whale
Did you read this
<@&286206848099549185>
Welp I'm being ignored

You can solve for x not x²
you can technichally just square it :3
anyways use thos
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
noted
you should delete it
@little isle Has your question been resolved?
what
@little isle your question is this
solve for 3mx² +mnx - 3nx -n² =0
To solve any quadratic equation you need to convert it into form
ax²+bx+c=0
Once you do that use this formula to find values of x
Guys ..
Guys what is the function of this
Quadratic function for that graph
Equation
Maybe paste a screenshot of your actual question
That way others can understand what's your actual doubt
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what approximation techniques have you learned in class
newton's method comes to mind
no no this is not calculus
its precalculus
there is no method to approximate square roots yet
oh interesting? not sure if we can help without knowing the method then
are you meant to use a calculator?
not much of an approximation then is it
it's still approximate if you round it(?)
you could round everything down to just a whole number, but thats probably not what you're supposed to do
my consern is that why authir nit allowed to use calculator here ?
i guess you could binary search
but again i'm not sure what the context of this question is
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Simply: why do we need the assumption of the AoC here?
iirc, you need Zorn’s lemma to find a maximal linearly independent set in this proof
which is equivalent to AoC
in finite dim, you don’t need it
but in inf dim, you do
oh wait, I literally misread the question lol
I thought this was every vsp has a basis for some reason zz
I mean it trivally proves every vector space has a basis
the vector space spans itself ofc
I thought that it was just by definition of a vs that they all had bases but thinking back on it, that's not an axiom 
Could you elaborate a bit on that pls, we thought that normally you'd consider some basis which would be a subset of V that spans V
I'm just making the observation that "every spanning set contains a basis" implies "every vector space has a basis" since you can take the vector space itself as the spanning set.
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hello can someone help me get the common ratio or common difference in this..
and can you check if this is correct
we were tasked to identify of it was either arithmetic or geometric sequence, and then we will put the common difference or ratio
<@&286206848099549185>
Hello
I have no clue as I haven’t done this yet
Correct
Process is the same
but i dont seem to find a common difference and ratio in them
isnt this what we should do to get the ratio
i dont get it huhu
i need helpp
@hel
<@&286206848099549185>
if so then question 7 fails right ?
i cant aeem to get the common ratio or difference for no. 4 and 8
<@&286206848099549185>
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Is this an quadratic equation?
Can I just put
a = 1
b = -4 +2i
c = 12-4i
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can we write
f_0cos(wt) as F_0e^(iwt)?
if you put a real part somewhere in there, sure
this is the differential equation
and the solution we get is Bcos(wt-phi)
which we can express in exponential form
which I get
i dont get what happened after that
can you please help me out
@hard atlas
so is this right
this is what i understand
e^i*y = cos(y) + i sin(y)
the only real part is cos(y)
where y = wt-phi
so Re(e^iy) = cos y
thats it right
yes
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why are the limits in a miltiple integral called the rectangular region
integrating a function is finding the area under the curve
yes
rectangular region refers to the limits of integration over a rectangular shaped area?
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does this proof work?
what are all those reacts for 
An admiration to JEE 🫡
Tldr: tldr

Nah I'm just here to add to the reacts 

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damn i didnt know jee had proofd
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can someone explain how to do this without expanding the brackets completely
Maybe try
(1+x²)^5=(1+x²)^4*(1+x²)=
Then you can bring (1+x²)^4 with (2+x)^4
Apply law of indices
And next binomial theorem
I hope this makes sense 😅😔
Alternatively,
The only way you can get x^3 is as
x^0 * x^3
x^1 * x^2
x^2 * x^1
x^3 * x^0.
So find the coefficients of x^0, x^1, x^2, x^3 in (2+x)^4 and (1+x^2)^5 seperately
im worried that you'll get a trinomial

how are you gonna apply binomial theorem to that
Sub
sounds painful
wait do you get my approach or not?
it might be unclear
I do
Since you are only concerned about the power "3" on x so you only need to find the coefficients and add them right
yes
Yep
so you need to find coefficients of
x^0 * x^3
x^1 * x^2
x^2 * x^1
x^3 * x^0
where the first x comes from (2+x)^4 and the second x comes from (1+x^2)^5
so find x^3 coefficient for both brackets ?
I'll temporarily adapt notation Ca(x^n) for coefficient of x^n in the first multiplicand (2+x)^4 and Cb(x^n) for the coefficient of x^n in the second multiplicand (1+x^2)^5
Then the coefficient of x^3 in the result should be:
Ca(x^0) * Cb(x^3) + Ca(x^1) * Cb(x^2) + Ca(x^2) * Cb(x^1) + Ca(x^3) * Cb(x^0)
you will need coefficients of x^0, x^1, x^2 and x^3
because x^3 can be written in all those 4 ways
once you find the coefficients, the result can then be written as
(a + bx + cx^2 + dx^3 + [useless...]) * (e + fx + gx^2 + hx^3 + [useless...])
and if you were to expand that out, the coefficient of x^3 will be
ah + bg + cf + de
,w (2+x)^4(1+x^2)^5
,w expand (2+x)^4(1+x^2)^5
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is there a way to solve this algebraically
no matter what u do u would need some kind of estimation
well i estimated the first 10 and turns out n. = 10
took me 9 whole mins
9 minutes?
ye when doing smth like this u might consider some rough argument to start at a later number instead of doing all of n = 1, 2, etc until u find the ans
yea :/
Did you evaluate the binom as-is?
i did n = 1 first then n = 100 just to get a rough idea
no i just suck at arithmetic
i dont know how to get better
wt about this
its dragging me down and i feel depressed
did u simplify the binomial coefficient
no i estimated
how did u estimate?
maybe you could do something with stirling’s approximation first to get a place to start
stirling?
what is that
note (10n + 2) - (10n - 1) = 3
so did use property n C k = n C (n - k)
10n + 2 (10n +1 (10n
ok very good
divdide by 6
ye nice ok
how do i
get better at arithmetic
i tried doing worksheets
idk if im getting faster or not
if ur issue is only ‘arithmetic’, then nothing but practice will help i think
but for this problem in particular i think some bit of intuition may help you
also i would probably approximate this as 1/6 * (10n + 1)^3
stirling approximation is a way to approximate the factorial function
o
it is typically used when u have limits involving factorials
(i do not see use for it here)
is that like taylor serie or something
is this
in most cases where stirling approximation is necessary, you would use this statement and that would be sufficient
i see
thanks
!
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yw
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how did we go from step 1 to step 2
Divide by 4^n
Both numerator and denominator
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(1+2)^2006=a+b√2. calculate a^2-2b^2
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can i get some help identifying the handedness of a 3d coordinate system either with maybe a resource or given questions?
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Does anyone know what kind of question this would be called? I'm trying to find videos for it on khanacademy but googling "how to make a fraction/division problem undefined" really isn't getting the videos I want.
something like "domain of a rational function"
that seems similar I'm not sure if that is what the problem is called
very close though because it's algebra 1
@ocean shale Has your question been resolved?
poles, singularities of functions
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where did 12 come form
like the 12.0000 g/mol part?
its the bottom part
the 1 amu=1.9927e-23
/12
like i know its the mass number/ avvogadro number to get gram but the second part of it is confusing
1 amu is supposed to be roughly the weight of 1 proton or 1 neutron, a carbon atom has 12 (6 protons and 6 neutrons)
just wanted to really quickly say that fractions become undefined when there's a zero in the denominator
omg ty
@alpine trout Has your question been resolved?
I know they but my issue is that it wants me to find a number that would make the fraction undefined
although what you are saying is giving me a brainblast currently and I think I almost get what you are saying
in your question, it just means you have to solve x^2+2x = 0
of which the solutions are x = 2, 0
hence the answer is i and iii
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I needed help with this differential equation and these type in general
L and C are constants
And I need to solve for I
Can anyone give a basic idea to solve these , I will try to adapt , I have not exactly studied differential equation of these types before but came across it while doing physics
second order de
In this chapter we will start looking at second order differential equations. We will concentrate mostly on constant coefficient second order differential equations. We will derive the solutions for homogeneous differential equations and we will use the methods of undetermined coefficients and variation of parameters to solve non homogeneous d...
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how would i start this (assignment title is induction and binomial theorem)
please @ me if u have an answer
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$4^x + 4^{x+1} = 4^x + 4^1 \cdot 4^x = 4^x + 4 \cdot 4^x = 4^x (1 + 4) = 5 \cdot 4^x$
Emily
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does this mean that the answer of km/h and m/s should have 5 significant figures? because of 86400?
yes
so does the two 0's after 4 also count?
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how many 50 x 50 grids of white and black cells are there such that
- no two white cells touch
- every black cell touches a white cell
(diagonal touching by corners counts as touching)
we've solved it for nx1 grids
gonna update this over time:
f(m, n) = f(n, m)
f(1, 1) = 1
f(2, 1) = 2
f(3, 1) = 2
f(4, 1) = 3
f(5, 1) = 4
f(n, 1) = f(n - 1) + f(n - 5)
@brisk moss
so
for nx2 grids
f(2, 1) = 2 (W/B, B/W)
f(2, 2) = 4 (WB/BB and rotations)
now how to extend
if last column is W/B or B/W you can do B/B
if it's B/B you can do W/B or B/W
i'm making the recursion for f(n, 2) not f(n, 1)
was this something u came up urself or did it come from somewhere?
this is not a traditional help channel question, layla found a problem and a few of us started working on it, we realized that we were clogging up discussion so we made a help channel
wt else would i be referring to 👀
ok
ur recursion for f(n, 1) is not right
how
layla found a problem
not quite the correct lore but ok lol
lol
if it ends in B you can add W, if it ends in W you can add B, if it ends in B you can add WBBWB
there
computer verified up to n = 20
lol
i think it's ok? it might be different than ours but offset
can you post, say, 50 values?
my school chromebook isn't powerful enough to run that
ok i can do it
for tests up to n = 50 we need a good computer
it would still take several days tho
no i meant with your recursion
oh
ok that is true
if the last column is WB or BW you can add BB and (WB or BW), if it's BB you can add WB or BW
ok nvm that if mqnic agrees now
does this produce everything?
this produces f(n, 2) = f(n - 1, 2) + f(n - 2, 2)
actually
lemme try computer generation
||incorrect buzzer sound||
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.reopen
✅


🫵



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Why did they move pho out? Isn't the inner integral related to pho? Then why can pho be moved out
That's not phi or pho
I mean rho
that's rho
its rho
icannotdoanymorecauchy
rho rho rho your boat
gently down the stream
bro's getting bullied 💀
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does this make sense
💀
<@&268886789983436800>
<@&268886789983436800>
he got smayed out
?
No, it doesn't
i think ur lacking words basically
sometimes i talk too much
each one of your inequalities is unjustified (and incorrect, even)
to be a bit direct
i ren away from my problems
why
The first inequality might be okay
why is |x-1|/|x| less than delta/|x|
basically i'm kinda confused what ur trying to do
why is |x-1| < delta?
seriously
we're taking the limit as x -> 0, not 1
oh
anyways, one hint for why your proof couldn't work is that you didn't use any properties of sin
i.e. the same reasoning could be applied to x^2/x, which goes to 0
or sqrt(x)/x, which diverges
you sometimes have to do something like delta = min{eps, 1}
it helps to think about this a bit more loosely
|sin x| is going to be close to |x|
how
well that's what you're trying to prove, no?
oh
so (|sin x| + |x|)/|x| is going to be close to 2 for small |x|, loosely speaking
so it doesn't really help to bound by that
I mean it should converge to exactly 2, if what you're proving is correct
it's either this or really cheat and use taylor expansion
i actually thought about taylor expansion and then i imagined how everybody would flame me
doing this problem deserves flaming when you already know squeeze theorem and trig
I do this specifically with epsilon delta cause I never did it really
and I wanna practice that
do real problems for practice
I mean you need properties of sin for this
a good exercise is to prove that arithmetic of limits works
should warn u that q14 is like really hard
(actually idk how to do the latter part of 14, and i don't think i know anyone who does)
@bitter pilot Has your question been resolved?
Here’s another approach, if you agree 0<cos(x)<sin(x)/x<1 when x is close to zero the proof becomes much easier. This is easy to show using trig.
@bitter pilot Has your question been resolved?
Y'all ain't ready for this
yo guys i have a problem with this im in the first year baccalaureate so please can some one help me to solve this
bro delete this
thats my channel
<@&268886789983436800>
bro if you have solution give it to me please
my poor proof
open your own help channel please
use one of these
Ask qna
I know I disappointed you, but would you mind taking another look please
that was for the spam earlier that got nuked 💀
why use alpha and omega instead of epsilon and delta
😕
🥺
why should that first inequality work?
a < b doesn't imply |a - c| < |b - c|
also if you're ok with using the fact that sin' = cos then you can just use the definition of the derivative with sin'(0) = cos(0) = 1.
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