#help-17

1 messages · Page 217 of 1

vast shale
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That means the last one is

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Aight I'm done

maiden blade
#

xD

vast shale
#

It’s 1,3

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Yeah

radiant bone
vast shale
radiant bone
#

Let them think through the problems

vast shale
#

There's only one other option

vast shale
#

why is it that answer

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It’s not because you said so, that won’t work

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Uh

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basically

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You can input the answers and see which one makes sense

#

Because the first number is x and the second is y

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For the second one, if you inputted 6,1 into it, there’s already another 6,1 in there

#

which means, that can’t be true

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I see

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Wait

#

wait a second

#

No it’s right

#

No

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Wait I’m tweaking

#

😭

#

My eyes were thinking you didn’t use -7,6 alr

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@oak magnet type faster

oak magnet
#

Well you cant have the first number twice with two differents output (second number)

oak magnet
vast shale
#

Took 2 centuries to type that dawg

oak magnet
#

Be polite, we are helping you

civic otter
vast shale
#

It's a practice problem my guy

#

Take a breather

civic otter
#

Then why did you want him to type faster??

vocal sleetBOT
#

@vast shale Has your question been resolved?

hallow crescent
#

no reason to take it seriously

#

@vast shale did u solve the original problem or do you still need help

#

nvm im an idiot

vocal sleetBOT
#
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vocal sleetBOT
#
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warm horizon
vocal sleetBOT
warm horizon
#

did i do smth wrong here ?

#

im solving $\cos4x=\sin2x$ for the domain $-\pi\leq x \leq\pi$

twin meteorBOT
woeful igloo
#

in your quadratic, you have x = sin2x right?

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still you have written you substitute x = sin^2(2x)

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when going from step 2 to 3

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thats why ur backsubstitution is wrong

warm horizon
#

oh shoot ur right

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,rotate

twin meteorBOT
warm horizon
#

is this right?

#

oh it should be pi/8 and 3pi/8 instead of pi/4 and 3pi/4 in the final line

#

and 3pi/4 instead of 3pi/2

woeful igloo
#

you still took 1/sqrt 2 instead of half for the first part

#

your sin2x has to be +/- 1/2 or +/- 1

warm horizon
#

geez my brain is not working today lmfao

woeful igloo
#

so x would be family of pi/12 and pi/4

warm horizon
#

ok i got it thank you

#

.close

vocal sleetBOT
#
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#
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vocal sleetBOT
velvet zephyr
#

let the distance be d

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do the speed of train A = d/5
for train B it's = d/7
Now multiply both of these by a certain time
Add those and equate them for d

ebon idol
#

i am getting that they will meet after 175 minutes

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9:55 am

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which is wrong

velvet zephyr
#

what is correct?

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which answer is correct?

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what is the correct asnwer?

ebon idol
#

10;45

velvet zephyr
#

did you take my advice/

#

?

woeful igloo
#

track the positions of both trains as a function of time

ebon idol
#

i did that only

ebon idol
woeful igloo
#

so for train one it would be x = speed of train 1 * time past 7am

velvet zephyr
#

ok so

n(d/5+d/7) = d
n(1/5 + 1/7) = 1
n = 35/12
n = 35*5 = 175 minutes

#

oh

#

Nvm

woeful igloo
#

and for train 2 would be d - x = speed of train 2 * (time past 7 am - 2 hours)

velvet zephyr
#

they don't start at the same time

velvet zephyr
#

,w n(d/5)+(n-2)*(d/7) = d

woeful igloo
#

x is distance where they meet

velvet zephyr
#

yes, the answer 3 hours 45 minutes = 10:45

ebon idol
woeful igloo
#

distance between the stations

ebon idol
#

ok

#

how can i do this

velvet zephyr
#

,w ((2^(1/5) + 3^(1/5))^15

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viola

ebon idol
#

bro

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i want to know how to do it not the answer

#

i can get the answer by any calculator

velvet zephyr
#

ikr

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Wehere did you get that question?

ebon idol
#

somewhere

velvet zephyr
#

Okay.

ebon idol
#

do u know how to do it?

velvet zephyr
#

nope.

woeful igloo
#

there is binomial expansion for any (a+b)^c if c is a +ve integer

ebon idol
#

whats the expansion

woeful igloo
ebon idol
#

nothing else can be done?

vocal sleetBOT
#
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velvet zephyr
velvet zephyr
vocal sleetBOT
#
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serene pawn
#

Does anyone have any idea how to solve this? Can someone please give an explanation and an answer.

vocal sleetBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

peak matrix
#

also, was that your solution?

velvet zephyr
#

Tlaking about me?

peak matrix
#

yeah

velvet zephyr
#

Yes? I was very lazy to solve them myself

peak matrix
#

It was wrong though lol

velvet zephyr
#

o

peak matrix
velvet zephyr
#

That was the number of rosese that sam has in total

peak matrix
peak matrix
#

Hint #1:
||Introduce 2 variables, S and K. S will be the total number of roses sam has and K will be the total number of roses kim has||

#

Hint #2:
||Make 2 equations with those variables, one of them will equate the number of white roses they have to 23, and the other one will equate all roses they have to 32||

serene pawn
peak matrix
#

There are 32 roses in total

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how can we express that in an equation with s and k?

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Hint: think about what is s+k

serene pawn
#

I’m not really sure

peak matrix
#

correct

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s is the number of roses sam has

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k is the number of roses kim has

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s + k is the number of roses they both have, and we know that that's 32

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Now, can you express how many white roses does same have in terms of s?

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Hint: he has 1/4 s red roses

serene pawn
#

2.25

peak matrix
serene pawn
#

9 red roses 1/4x9

peak matrix
#

With my hint i was refering to this line

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one quarter of sam's roses were red

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but not one quarter of total number of roses

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(1/4)s roses were red

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s is the number of sam's roses, and 1/4 of that was red

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so how many sam's roses were white? Again in terms of s

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or what fraction of his roses?

serene pawn
#

15

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
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grave acorn
#

this question requires me to solve using quadratics and im stuck on how to solve it

hybrid flicker
#

i don't think you need quadractics

grave acorn
#

the questions designed so that eventually you end up with x^2 and so

hybrid flicker
#

just factor 18 and go through cases

grave acorn
#

yeah but i have to use quadratics to work it out

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like

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or i lose marks

hybrid flicker
#

ok

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so replace y by its value in second equation

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and multiply everything by x

grave acorn
#

hold on lemme do that

#

oh yeah that works

#

thank you 🙏

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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waxen hawk
#

Ayy

vocal sleetBOT
waxen hawk
#

There are two plales shown in the system

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The question asks to find a point of intersection of these planes

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There’s a common way to solve it, right?

waxen hawk
#

<@&286206848099549185>

bitter pilot
#

so you will end up with one free variable which basically implies an intersection line

bitter pilot
#

sorry

waxen hawk
short pilot
bitter pilot
short pilot
#

Fr

#

Always bro

bitter pilot
#

you just arrived in time

short pilot
#

Planes?

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Interesection of planes?

waxen hawk
bitter pilot
short pilot
#

See I am thinking it would be better to use the concept of

bitter pilot
#

I'd like to call it free variable than "any number" but yea

short pilot
#

unit area vector of the plane

bitter pilot
#

x,y and z would depend on t

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for example

short pilot
#

Do u all know vector ?

bitter pilot
#

if you chose z=t or some

short pilot
#

And 3d geometry?

earnest nymph
#

I don't know vector

short pilot
#

💀

earnest nymph
#

Nor 3d geometry

short pilot
#

Then we do generally then

earnest nymph
#

Ok brother

short pilot
#

two equations

waxen hawk
#

No

short pilot
#

Eliminate one variable

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See

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Take x,y,z one of these as t

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And then find the rest two in terms of t

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I hope it will work

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👍

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Cz see

earnest nymph
#

Ok brother

short pilot
#

Two equations 3 variables

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Not feasible else we eliminate a variable

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Any doubt ?

bitter pilot
waxen hawk
short pilot
#

Oh u used that colour hand

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Oh

bitter pilot
#

it's indeed any number

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you defined the free variable to be in R

short pilot
#

You can say

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We take x

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Where the planes intersect each other and find t

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And then we find y and z

bitter pilot
short pilot
bitter pilot
short pilot
#

Certified bro is proud moment

bitter pilot
#

You are the coolest helper to exist

short pilot
#

After u

#

Fr 💀

#

U 1.

earnest nymph
#

😂

short pilot
#

Me 2nd

#

Lol

waxen hawk
short pilot
#

Bro

waxen hawk
#

I will explain the picture

short pilot
#

I k

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Two planes

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Intersect perpendicularly

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Right?

bitter pilot
short pilot
#

Please correct my grammae

waxen hawk
short pilot
#

Grammar*

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How did u consider or get

bitter pilot
short pilot
#

That these two planes intersect perpendicularly

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Like they form a 90.degree angle

short pilot
#

Bro do u know bout unit area vectors and all tell this too?

waxen hawk
# waxen hawk I

the intersection of the line stands at a particular position of the xy plane

short pilot
#

See imma explain this simply

waxen hawk
short pilot
#

When two lines intersect we get a point

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When two planes intersect

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We get a line of intersection

waxen hawk
#

Stop that’s not my question

short pilot
#

So u need to solve the planes and get that line

bitter pilot
#

let him cook

short pilot
#

@waxen hawk that's you question right you need the intersection points right?

bitter pilot
#

but like

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two planes either are parallel

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or have an intersection line

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in R^3

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so there are like infinite many

short pilot
#

Yes

bitter pilot
#

on that line

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you can choose any

short pilot
#

Yes

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That's why we were taking a variable as t

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And writing the rest two

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In terms of that variable

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Cz that will represent a line

waxen hawk
short pilot
#

you can take infinite no of values of t

short pilot
#

we will get a line by the intersection of these planes

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Every point that satisfies on that line is a point of intersection

bitter pilot
#

t can be anythng and based on your solution, you will get an according x and y that is on the line

short pilot
#

See please correct my grammer when u take a variable t

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So can find other variables in terms of that variable

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So u eventually get a equation of line

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Where each point of intersection of the planes lies

waxen hawk
# bitter pilot no

Let’s get into the algebra, I assume these two planes I shown on the picture are ax+by+cy+d=0 and qx+wy+ez+r=0. And of course these a,b,c… are of real numbers

short pilot
#

Okok

waxen hawk
bitter pilot
#

,, \left [ \begin{array}{ccc|c} 1 & -2 & 1 & -4 \ 2 & 1 & 3 & 1 \ \end{array} \right ]

twin meteorBOT
#

𝔸dωn𝓲²s

waxen hawk
short pilot
#

Okok

bitter pilot
waxen hawk
short pilot
#

Lol fr

#

@bitter pilot bro is goated at latex

bitter pilot
#

you write the coefficients of your variables

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you have 3 unknowns and 2 rows

short pilot
#

See grammar

#

The best idea is

bitter pilot
#

grandma

short pilot
#

Lop

#

Lol

#

The best idea is

#

To substitute a variable

waxen hawk
short pilot
#

And get the variable in terms of that variable

#

So we can get the intersection line

bitter pilot
waxen hawk
#

I’m out, you guys are tripping

short pilot
#

See

#

Let's begin from start

waxen hawk
#

.close

vocal sleetBOT
#
Channel closed

Closed by @waxen hawk

Use .reopen if this was a mistake.

short pilot
#

Wait

#

Pls

#

One chance

#

Let me tell

#

Waut

#

Wait*

waxen hawk
bitter pilot
#

what was the problem

waxen hawk
#

.reopen

vocal sleetBOT
#

short pilot
#

@waxen hawk do u agree that when the planes intersect we get a line of intersection
Yes/no

waxen hawk
#

.close

vocal sleetBOT
#
Channel closed

Closed by @waxen hawk

Use .reopen if this was a mistake.

short pilot
#

Answer imma tell why this is important to solve your question

#

Wait pls

#

Imma clear it in 1 sec

#

Just type yes or no

#

Pls

waxen hawk
#

You should read my question

short pilot
#

Imma coming onto it in 1 sec

#

The general way of solving

bitter pilot
short pilot
#

Imma come on ut

#

It*

#

First pls type yes/no it's crucial

#

Pls

bitter pilot
#

lmao i realized why you wrote grammar

short pilot
#

@waxen hawk

bitter pilot
#

oppailol 😭

short pilot
#

Okok

#

Don't tell

#

Atleast clearly explain

#

what problem is there

#

In taking x,y,z any of these =t

waxen hawk
#

.reopen

vocal sleetBOT
#

short pilot
#

And finding other in terms of that variable

#

Like we take x=t

bitter pilot
#

let OP first type their Q

#

maybe they are overwhelmed from your energy 😄

short pilot
#

Fr

#

Thanks Adonis for calming me

waxen hawk
#

Let’s start again

short pilot
#

Ok

#

!original

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

short pilot
#

Ok let's see it

waxen hawk
#

.close

vocal sleetBOT
#
Channel closed

Closed by @waxen hawk

Use .reopen if this was a mistake.

short pilot
#

Ok so what do u want do with the matrice

bitter pilot
#

i think OP is trolling wtf

waxen hawk
#

No, I’m just so mad

mellow void
bitter pilot
#

You said you had a question

short pilot
bitter pilot
#

and you post a claim

short pilot
#

You are correct

waxen hawk
short pilot
#

But cz we have a line we have such type of infinite points

#

Your claim is correct

waxen hawk
short pilot
bitter pilot
#

oh bruh

#

you meant your two plane equations

short pilot
#

💀

waxen hawk
#

.reopen

bitter pilot
#

of course x,y and z cannot be random

vocal sleetBOT
#

bitter pilot
#

they have to be so that they satisfy both constraints

short pilot
bitter pilot
#

that's it

short pilot
#

Yes

bitter pilot
#

lmao

short pilot
#

Yes

#

Yes

#

Lol

bitter pilot
#

oppai you are king

short pilot
#

No

#

Aah

short pilot
waxen hawk
#

He’s the king without doubts

short pilot
#

Bro is talking sarcastically fr

mellow void
#

a tyrant

short pilot
#

No

#

But at the end

#

The true king is @waxen hawk

#

His claim was correct

#

But untouched by us

mellow void
#

all I can say is sully

bitter pilot
waxen hawk
bitter pilot
#

you got like 10000000000+ aura

short pilot
short pilot
#

Please correct my grammar ok so now?

bitter pilot
#

yea

waxen hawk
short pilot
#

Any doubt remains?

waxen hawk
#

No

bitter pilot
#

we can all be friends now 😄

short pilot
#

Bro should be please correct your grammar fr

bitter pilot
short pilot
#

Lol

mellow void
#

this is terrible banter

waxen hawk
short pilot
#

Let's solve the equations for a better idea

bitter pilot
#

use wolfram

#

your software

short pilot
#

,w solve
x-2y+z+4=0,
2x+y+3z-1=0

#

What

short pilot
#

They have eliminated x sirs

bitter pilot
#

goated

short pilot
#

they have written y and z in terms of x

#

💀

bitter pilot
#

you deserve ultra helpful

short pilot
#

Bro is taunting me fr 🔥🔥

#

Lol bro

bitter pilot
#

NO

short pilot
#

OK

bitter pilot
#

bro

#

you dont realize

short pilot
#

Thanks i appreciate it sir

bitter pilot
#

how you make me laugh

short pilot
#

Lol

short pilot
#

💀

bitter pilot
#

LMAO

#

it's also your pfp

#

inf/10

short pilot
#

Lol

#

,av @short pilot

fervent wasp
twin meteorBOT
#
oppailol.'s Avatar

Click here to view the image.

short pilot
#

Lol

fervent wasp
#

Creepy asf

short pilot
bitter pilot
#

who are you

#

do you know oppa

short pilot
fervent wasp
short pilot
#

U broke me bro fr

#

U don't know me

bitter pilot
#

one day you realize

#

and that day is now

short pilot
#

No

#

You are goated my guy

#

Fr big brain guyz

#

My brain smol 💀

#

@fervent wasp even this guy

#

Lies that he is bad at maths but is goated

bitter pilot
short pilot
#

🥲😭bearlain aah

short pilot
#

Bro talking bout the neuron density fr

#

Lol

bitter pilot
#

or are you a school student

short pilot
#

No

#

Imma going to uni

#

This fall

bitter pilot
#

and what you gonna do

short pilot
#

Nothing

#

Fr lol 😂

bitter pilot
#

math?

short pilot
#

Yes

bitter pilot
#

frfrfr?

short pilot
#

Ofc bro

bitter pilot
#

damn

short pilot
#

But I plan do some side job too

bitter pilot
#

yea do that

short pilot
#

Yes

bitter pilot
#

you will need that money

short pilot
#

So that I can manage

bitter pilot
#

uni robs you fr

short pilot
#

My expenses

#

Fr fr

#

Imma work at a drive thru

bitter pilot
bitter pilot
short pilot
#

Lol

#

💀

bitter pilot
#

or probability shit calculate the average occurence of drivers

short pilot
#

The OP has not closed this channel

bitter pilot
#

.close

vocal sleetBOT
#
Channel closed

Closed by @bitter pilot

Use .reopen if this was a mistake.

sleek orchid
#

.

bitter pilot
#

let's go

short pilot
#

I was saving someone from saying that

#

But it is closed lol

bitter pilot
#

they seemed to disappear anyway

#

and their doubt was cleared so

short pilot
#

Okok

#

Fine

#

Imma come in 5 mins

vocal sleetBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dire harbor
#

why is my solution wrong

vocal sleetBOT
dire harbor
#

the question was write a power series represetation for f(x)

short pilot
#

High

dire harbor
#

hiii

short pilot
#

Hi*

#

Yes

#

So u wrote it in power series form

#

then u integrated it

#

,w maclaurian expansion of ln(1-x^2)

short pilot
#

@dire harbor does it match

#

Your result check pls

dire harbor
#

i think it does match lol

short pilot
#

Then it's good

dire harbor
#

i made a small mistake and wrote the series of the derivative from n=1 not n=0

short pilot
#

Oh

#

Oh

dire harbor
#

but everything is equivalent if you sub n+1 instead of n

short pilot
#

Okok

#

Okok

#

Enjoy

dire harbor
#

thank you i will

#

.close

vocal sleetBOT
#
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short pilot
#

Welcome np

vocal sleetBOT
#
Available help channel!

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bold laurel
#

.close

vocal sleetBOT
#
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fallow sphinx
vocal sleetBOT
fallow sphinx
#

Help on question 16-17

#

I need to turn it into a IB Standard form

#

@ me when you are here to help

proven whale
#

@fallow sphinx could u send the entire Question

#

its kinda cut

fallow sphinx
#

Alrighty

#

Is this good???

proven whale
#

nice

fallow sphinx
#

Alrighty 👍

proven whale
#

im guessing what they mean by standard form is the most simplified version of the eqaution

fallow sphinx
#

📝

proven whale
#

so get everything on one side and zero on the other?

fallow sphinx
#

Ohhhhh

#

Big brain bro

#

Big brain

#

Like this???

proven whale
#

yeah ig

fallow sphinx
#

This one correct too???

#

@proven whale ??

proven whale
#

u made a calc error

fallow sphinx
#

Where

proven whale
#

it should be y+2x-18=0

fallow sphinx
#

Wait how

proven whale
#

my bad

fallow sphinx
#

What happend

proven whale
#

u forgot to add the +4 on the RHS

#

and u turned the -y to +y on RHS

fallow sphinx
#

What’s the RHS

proven whale
#

right hand side of the equation

fallow sphinx
#

I don’t forget to add the four

#

But I did forget about the y

proven whale
#

+14 + 4 = +18

fallow sphinx
#

Ohhh shoot

#

I forgot the 18

#

Thank bro

proven whale
#

lol

fallow sphinx
#

Dab me up

#

🫲

proven whale
#

🫲

fallow sphinx
#

🤝

#

Ok peace ✌️

#

.close

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#
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proven whale
#

see ya4

fallow sphinx
#

I’ll come back if I have not trouble

#

More

vocal sleetBOT
#
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lapis ember
#

Hello, I’m new to this server, I haven’t started learning Calculus at all, but I do know algebra, I wanna learn calculus from scratch, on my own. What should I do? How should I begin?

outer warren
#

start with difference quotients/average rate of change (essentially slope between two points)

and limits

mellow oyster
#

paul's online notes

#

there's probably a khan academy

outer warren
#

you'd also need knowledge of stuff like trig, exponents, logs

inner osprey
outer warren
#

also how much of algebra?
have you done stuff with functions

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#

@lapis ember Has your question been resolved?

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sleek pasture
#

What dose this converge to? (Wolfram alpha said it converges but not what to)

brisk moss
#

what is prod_{p = prime}^k? the first k primes?

sleek pasture
#

<@&286206848099549185>

vocal sleetBOT
#

@sleek pasture Has your question been resolved?

brisk moss
#

there are links you can look at here

#

it does not look like anyone has found any way to write it terms of common functions/constants

sleek pasture
#

Wait it’s less than 1?

brisk moss
#

yea

#

it's strictly less than $\sum_{k=1}^\infty \frac{1}{2^k}$

twin meteorBOT
#

:bending_skull:

brisk moss
#

so that makes sense

sleek pasture
#

Wait then maybe I’m doing something wrong lol

#

Because ~30% of natural numbers can’t just not have prime factors lol

#

Welp

brisk moss
#

what

sleek pasture
#

Don’t ask I’m probably doing my already strange things incorrectly

brisk moss
#

every integer >= 2 has a prime factor

sleek pasture
#

Yea exactly why I clearly did something wrong

#

Unless those implies 30% of the prime factors of infinity are not finite

#

But idk

brisk moss
#

what are you talking about eeveethink

sleek pasture
#

I’m probably just wrong though

inner osprey
sleek pasture
#

Well the sum was to about 70%

#

So the left over part is 30%

hard atlas
#

if you summed over 1/n for all natural numbers the sum would diverge. so with that logic no natural numbers have prime factors

sleek pasture
#

No

#

In fact that would just mean that every number (or maybe even more than every number????) has a factor (even if the only factor it itself)

#

Which is true

#

Ok this definitely implies something about prime numbers but I ain’t sure what

vocal sleetBOT
#

@sleek pasture Has your question been resolved?

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vast shale
vocal sleetBOT
vast shale
#

Can anybody help me w this question?

gentle thicket
vocal sleetBOT
# vast shale Can anybody help me w this question?
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
gentle thicket
#

Hint: Trig substitution

vast shale
#

Umm.. Okay.. Lemme try

vocal sleetBOT
#

@vast shale Has your question been resolved?

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gentle thicket
#

?

vocal sleetBOT
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warm horizon
#

i posted this q earlier today for a different part, but now idk how to do part d

warm horizon
#

i tried drawing a triangle in which x=cos(pi/18) to find tan^2 of the same angle, but that just gives me an expression in terms of x which i dont think helps

hushed pewter
warm horizon
#

oh my gosh the identity i completely forgot abt that

vast shale
vocal sleetBOT
#

@warm horizon Has your question been resolved?

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warm horizon
#

thank you @hushed pewter

vocal sleetBOT
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opaque herald
vocal sleetBOT
stable acorn
#

Did you try using LHopitals rule

opaque herald
#

Actually,lhopitals rule will be taught to me in grade 12 and I'm currently studying in grade 11 so neither I can use it it nor I know how to use it(sorry for bad grammar)

stable acorn
#

Maybe try to expand the definition of cosec and cot

opaque herald
#

It always ends up in undefined but my teacher did the same question in class and the answer came 1/2 same as answer written in the book but I can't figure it out on my own

stable acorn
#

$\frac{1}{\sin(x)}$-$\frac{\cos(x)}{\sin(x)}$}

opaque herald
#

Ywah

#

Yeah*

twin meteorBOT
#

Bendover
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

stable acorn
#

so it will be $\frac{1-\cos(x)}{sin(x)x}$

twin meteorBOT
#

Bendover

opaque herald
#

Yeah

dry orchid
#

use submultiple angle formula

opaque herald
#

Oh yeah right

#

Thanks I got it

#

Thank youu for thee help 🙇🏻‍♂️

#

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fallen mulch
vocal sleetBOT
fallen mulch
#

I can use x, y, z right

#

cause they're just dummy variables

vocal sleetBOT
#

@fallen mulch Has your question been resolved?

fallen mulch
#

<@&286206848099549185>

keen wasp
vocal sleetBOT
#

@fallen mulch Has your question been resolved?

fallen mulch
fallen mulch
#

or should i use abc

#

<@&286206848099549185>

heady ibex
#

What is the question?

#

Are you asking if using x, y, z in the sum is allowed?

fallen mulch
heady ibex
#

on wikipedia they use indices

#

but i don't see why using xyz wouldn't be allowed

#

as long as you show what you mean like you did

#

If you write what you wrote

#

and then continued on just writing the lhs

#

it would work

#

it would be clear (at least to me) what you mean

#

this is how wikipedia does it

#

although they have 4C3 terms

#

so abc = bca

#

in their thing

#

they are the same thing and not counted twice

#

while you do count them as different things

#

which gives 4P3

vocal sleetBOT
#

@fallen mulch Has your question been resolved?

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cunning raven
#

Is there any law where I can determine log a * log b using algebra?

cunning raven
#

Just for example lets say log 5 * log 3

short pilot
#

I don't think

#

So

gentle thicket
short pilot
#

Lol

gentle thicket
#

but I don't think there's any method to get exact result

cunning raven
short pilot
#

,w log(a)*log(b)

cunning raven
#

but yea thought so

gentle thicket
#

☠️

short pilot
#

We do not have

gentle thicket
#

wth was that

cunning raven
#

that certainly was an integral of all time

short pilot
#

Ok

#

Wait till u see

#

,w int zeta(1+e^(it)) from 0 to 1

urban edge
#

unless youre extremely lucky in a scenario where the base cancels out, youre out of luck

urban edge
#

what

short pilot
#

And see this

cunning raven
short pilot
#

,w 2π(euler-macheroninconstant)

urban edge
#

e.g. log_3(7)ln(3)

#

that becomes ln(7)

cunning raven
urban edge
#

can you move this to bots @short pilot

cunning raven
#

i think i get it but not that sure

urban edge
#

recall a log(b) = log(b^a)

short pilot
cunning raven
short pilot
#

Check the original question sir

#

!original

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

urban edge
#

you get ln(3^(log_3(7))

desert hornet
urban edge
#

the 3^ and log_3 cancel out nicely

cunning raven
#

(log7/log3 )*ln3 right

#

ahhhh ok

short pilot
#

Forgot bout it

#

Lol

short pilot
#

!done

vocal sleetBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

urban edge
#

chill out

cunning raven
#

.close

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#
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tender isle
#

Could we solve this limit with L'Hospirals rule, if f(c) = 1 and | g(x) | --> infinity, when x --> c? The rule says that the limit has to be 1^infinity type, as seen in the second screenshot at the start, ignore the slovenian text
I'm mostly not if f(c) should be = 1 or = 0. Someone please help

tender isle
#

.close

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#
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full bobcat
vocal sleetBOT
full bobcat
#

Find c such that this is true

short pilot
#

Bernoulli integral?

full bobcat
#

So far I dont know what to do

#

all i know is that c is between 0 and 1 cuz the integral from 0 to 1 is greater than 1

short pilot
#

Try expressing as a power series?

full bobcat
#

Let me show what i did so far one sec

short pilot
#

Ok

full bobcat
#

not much

short pilot
#

Good

full bobcat
#

wait a min

#

omg

#

nvm

#

c is greater than 1

#

i thought the integral from 0 to 1 wasnt alternating

#

1<c

short pilot
#

Oh

#

Okik

#

Okok*

full bobcat
short pilot
#

What's better than realising one's mistake by oneself

#

How do u know c is not less than 1

#

?

full bobcat
#

because the integral from 0 to 1 is 0.7 something

short pilot
#

Okok

#

So see

#

U can evaluate

full bobcat
#

i asked wolfram

short pilot
#

See

full bobcat
#

to solve for c

#

but it didnt udnerstand the query

full bobcat
short pilot
#

(x^n)(lnx)^n

#

See

#

this

#

Pls

full bobcat
#

but it could be less than 1

short pilot
#

,w d/da (int x^a from 0 to 1)

full bobcat
#

wait nvm let me think

short pilot
#

Wait do u know differentiating under the integral sign

full bobcat
#

ok c is greater than 1

#

ya

full bobcat
#

this is why again i said it again just to confirm

#

and the integral is increasing

short pilot
#

Answer pls what i asked

full bobcat
full bobcat
#

the alternating sum of 1/n^n

#

this is what i know so far

vocal sleetBOT
#

@full bobcat Has your question been resolved?

full bobcat
#

<@&286206848099549185>

short pilot
#

Ok

#

See imma out

#

Imma help later

vocal sleetBOT
#

@full bobcat Has your question been resolved?

vocal sleetBOT
#

@full bobcat Has your question been resolved?

vocal sleetBOT
#
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latent rivet
#

sorry for the dirty paper idk why its like that but i have no idea how to do this 🙁🙁
i gotta find x and y and z
ik how to do find x and y when theres no z but wtf is this tutor? 😔

onyx juniper
latent rivet
#

i think yes idk my titor wrote it and said its homework

onyx juniper
#

i think they might have meant for one of the terms in the last equation to be y but if its correct right now, you can group the terms with z together and solve for x, and then plug it into the other two

latent rivet
#

okay

#

wait what

lyric kestrel
#

You can add the two terms in the last equation

#

Duh

latent rivet
#

yes

#

i get that

#

but

lyric kestrel
#

But

latent rivet
#

what now

lyric kestrel
#

Try substituting

#

Try substituting the values of one variable from an equation to same the variable in another equation

#

You know how?

latent rivet
#

yes

lyric kestrel
#

Try it then

#

And tag me if you get stuck

latent rivet
#

thanks

lyric kestrel
#

Or maybe you can dm

#

If I go offline

#

So basically there are several methods to solve linear equations in multiple variables

#

You have substitution elimination and cross multiplication

#

You can also search it up on yt

latent rivet
#

thanks

lyric kestrel
#

That could also help

#

I also want you try something

#

Something with this equation

#

You there?

#

@latent rivet

vocal sleetBOT
#

@latent rivet Has your question been resolved?

cosmic cloud
#

You can use

#

Matrix Method

vocal sleetBOT
#
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vocal sleetBOT
#
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hardy jewel
#

I'm working on this problem: You roll a fair 6 sided dice 10 times. What is the probability that you roll all numbers 1-6 in these 10 rolls.

noble heath
vocal sleetBOT
#

@hardy jewel Has your question been resolved?

hardy jewel
#

yeah I do @noble heath

noble heath
#

what do you think this is?

#

@hardy jewel

hardy jewel
#

combinations?

#

@noble heath

#

order doesn't really matter we just need 1-6

lone linden
#

Principle of inclusion and exclusion moment

vocal sleetBOT
#

@hardy jewel Has your question been resolved?

hardy jewel
#

@lone linden can you show me how to do it with inclusion-exclusion

#

I heard that you're supposed to use that

#

<@&286206848099549185>

hardy jewel
junior roost
#

Yeah sorry , i just realised it's way more complicated then that .

night aurora
#

since it is fair, rolling a number between 1 to 6 should be 1/6

#

and then if ten times, should be just the probability to the power of 10

#

if I am not mistaken

hardy jewel
#

no it's not 1/6^10 @night aurora

night aurora
#

oops

#

ohh i see now

hardy jewel
#

thats just the probability of getting a number 10 times

junior roost
#

P(A1∩A2∩A3∩A4∩A5 ∩A
6 )=0 i think that is the formula ?

hardy jewel
#

= 0?

#

what

#

sorry lol

short pilot
#

Yo

hardy jewel
#

no the actual answer is $\frac{38045}{139968}$

twin meteorBOT
#

thewatermelonbaker

hardy jewel
#

.close

vocal sleetBOT
#
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marble badger
#

For this question, I selected 10 since the values in the table add up to 30 and not the total amount of 40. It said the answer was wrong and the actual answer was 12. Is this a mistake with the system, or am I missing something?

outer warren
#

the question makes no sense

marble badger
#

I assumed it meant how many students' responses were not in the table

outer warren
#

there are no missing values in the table, and based on the pic given, they're all wrong except for green

marble badger
#

oh it's not how many of that color is in the pattern

#

its how many out of 40 students chose that color as their favorite

#

wait

#

you're right

#

so is it an issue with the problem itself?

outer warren
#

yes

marble badger
#

hmm ok

outer warren
#

pic and table appear to be mismatched
table seems to be for a different problem

marble badger
#

ohk

#

ty

#

.close

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#
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livid comet
#

how come we can guess it will probalby diverge?

magic wasp
#

What about the given explanation don't you understand?

livid comet
#

that part

#

becasue 1/n converges to 0

#

which means by divergence test it will converge?

magic wasp
#

It's not talking about the sequence 1/n, it's talking about the series (sum) of 1/n

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The harmonic series diverges

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$\sum_{n=1}^{\infty} \frac{1}{n}$

livid comet
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Ohhhh

twin meteorBOT
magic wasp
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That's what the "as a series" means

livid comet
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that makes sense

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thank you for your help 🙂

magic wasp
vocal sleetBOT
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@livid comet Has your question been resolved?

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lime smelt
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I'm a little confused by this. If you use this method to calculate the electric field inside a uniformly polarised sphere, D is obviously 0 since there's no free charge, so E=-P/epsilon, which is clearly not the case. What am I missing here?

short pilot
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Gauss law

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Can u explain clearly what u have a doubt in

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Like what are u finding electric flux / field or stuff?

short pilot
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See

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U know definition of gauss law

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Volume integral of E.da=q inclosed/ epsilon not

lime smelt
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yeah so i'm applying it in the middle of a polarised sphere, which doesn't have any free charge. since the sphere is a gaussian surface i can remove the dot product and i get |D|=0

short pilot
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By polarised sphere u are talking bout a non conductor right?

lime smelt
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yep

short pilot
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So see

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Is the charge distribution uniform

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Or do we have it as a function of distance from the centre

lime smelt
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there's no free charge

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so it's 0

short pilot
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What

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For conductors charge resides over the surface right?