help-17

[short pilot]

11/2(40)

11*20

Is 220

Wait what

[finite hatch]

wat

um

[short pilot]

U put d=1 right?

[finite hatch]

-1

[short pilot]

Yes

[finite hatch]

ya

[short pilot]

Shit I forgor that

Okok let's check again

[finite hatch]

oke

[short pilot]

11/2(30+(11-1)-1

11/2(20)

11*10

110

Yea n=11 is corresct

[finite hatch]

wow

[short pilot]

Correct*

[finite hatch]

how come it give me 2 answer

if one is incorrect!

idiot maths

[short pilot]

I checked manually

Wait let's check

N=20 also

[finite hatch]

oki

[short pilot]

20/2(30+(20-1)-1

Na this wrong

No bro

This correct as well

Fr

See

Bro

@finite hatch

[finite hatch]

wtf.

[short pilot]

20/2(30-19

20/2(11)

10*11

110

[finite hatch]

um

how do i know which is correct then

wait let me ask my tutor hes right next to me

[short pilot]

Listen

Understand

That n is correct in which terms do not become -ve

@short pilot

@finite hatch

Check in which a+(n-1)d is not -ve

[finite hatch]

they both +ve

[short pilot]

No bro

15+(20-1)-1

15-19

-4

15+(11-1)-1

15-10

5

11 is correct the logic is that no of logs can't be -ve

U can't keep -ve logs

@finite hatch

@finite hatch

[river kettle]

Bum chickeb

[harsh wyvern]

hey it's an ap with summation given and first term given difference is -1

110 = n/2{2x15 + (n-1)x-1}

on solving you'll get a quadratic
further solving n^2 will be equal to 189
which is not a perfect square but it basically means that there'll be 13 such steps and we won't have log left

[short pilot]

I explained bro

But np

We'll done

[harsh wyvern]

sorry

[short pilot]

No no

[harsh wyvern]

didn't see

[short pilot]

We'll done

His tutor is beside him

He gone for asking him

[harsh wyvern]

fair

[short pilot]

Yes

[finite hatch]

he did this

:D

Ok thx i get it now

Bai guys

[short pilot]

Bro I did the same thing above

Check

And even raiden did the same

@finite hatch .close

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[agile star]

Hello how do I find the area of this shape

I know its either sin rule consine rule

But how do I divide it

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@agile star Has your question been resolved?

[late crescent]

Find BC w/ cos rule

Then find area of triangle BCD with heron formula

.5(22)(18)sin65degree-area of triangle BCD

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[earnest yoke]

hi

[earnest yoke]

ive used impDiff on my cas to find the derivative

and i was just wondering how i solve it with those coordinates on cas

[meager shoal]

cas?

what cas

[meager shoal]

just evaluate at that value

[earnest yoke]

casio fx-CP400

by hand its easy

[twin meteor]

:D

[earnest yoke]

i just wanna know how to do on my calc

for harder questiopns

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[vast shale]

help

[vast shale]

ike how does y=x^2 equal that shape when you dont know the x-values? it could be only positive x-values, or it could be in sequence of odd numbers or idk..

like linear eqaution y=mx+b, you cant just graph the equation because you need some kind of hint or clue to graph it so like y=2x+2, but what about ofr y=x^2? the only clue is that its quadratic
but it doesnt say anything that it shoul dbe graphed like

[grand cipher]

the x value is based on the X-axis

[vast shale]

yea but they dont mention the x values like if the x values were like -2.-1.0.1.2 and were like just 1,2,3,4 then it wouldnt be symmetrical. right?

was it just chosen to be shown like that..?

[grand cipher]

no, you don't choose the x value.

x-value is the x-axis

you only choose x-value when you want to know a point

[vast shale]

what do you mean x- axis

just constant

1,2,3,4,5,6,7?

[grand cipher]

that bolded line is called axis

the vertical one is y-axis
horizontal one is x-axis

[vast shale]

but then what do you mean by the x value is based on the x axis

[grand cipher]

look when the x-axis is at 2

it put the x into the function

as such the it become (2,4)

and so on

it's same for all range of the x axis

[vast shale]

and three equals nine

[grand cipher]

yes

[vast shale]

so (2,4)(3,9)(4,16)

just in order of numbers

oh okay thankky ouuu

so is y=x^2 always symmetrical or not.

[grand cipher]

uh... if it like f(-x) =f(x) then yes

[vast shale]

okay thank you

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[cunning raven]

hi. how can I convert the inequality 78<= x <= 86 into the form |x-a| <= b where a and b are integers?

[outer warren]

as written you can't

do you mean:
|x-a| <= b

[cunning raven]

yes, my bad, sorry. edited to do the needful

[outer warren]

a will be the value halfway between 78 and 86

and b the distance from a to either of those

[cunning raven]

how do we know that?

[outer warren]

do you know what |x-a| represents geometrically?

[cunning raven]

a transformation of |x| a units to the right?

[oak magnet]

Not in graph thinking, like on a line what is |x-a|

[cunning raven]

not sure

[oak magnet]

Its the distance between x and a

[cunning raven]

how so?

[outer warren]

on a number line,
plot two random points

how would you find the distance between the red and blue point

(i don't care about the final value, i want the how)

[cunning raven]

id take the absolute value of the red point and the absolute value of the blue, and add them together

[outer warren]

that doesn't work in general

like here

the distance between 3 and 7 isn't |3| + |7|

[cunning raven]

oh

so id subtract the 2 points and take the absolute value

[outer warren]

yeh

[cunning raven]

i see

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[untold arrow]

I think i'm confused about the subspace topogy and the subset of a metric space...Like this example ↓, can anyone walk me thru this

[dusty ice]

In the subset metric, we use the same distance function. However: we work with a different set, and so the balls can look pretty different

For example, pick r in Q. The 1-ball in R is the points in R that are distance less than 1 from r, which is the interval (r-1, r+1)

The 1-ball in Q is the points in Q that are distance less than 1 from r, which is not the interval (r-1, r+1), because we are only talking about points in Q

So it's just the elements of that interval that are in Q, i.e. the intersection (r-1,r+1) n Q

This is a subset of (r-1, r+1), which is what the bigger/smaller thing at the end is about, and this subset thing will hold in general i.e. for a space Y a subset of X, if the r-ball in X with centre x is B(x,r) then the r-ball in Y with centre x (which makes sense only when x is in Y) is B(x,r) n Y

[untold arrow]

you mean that we use the same distance function in set Q and set R separetly

[dusty ice]

Yes

I would note that the intersection of an open X-ball with Y is always open as a subset of Y, but not neccesarily an open Y-ball

This is for subset metric

[untold arrow]

what do you mean open set here

[dusty ice]

It's a union of open balls

I've just reread your original question

Is this a question about the subspace topology or subspace metric

Or I guess what I actually want to know is what course this is

[untold arrow]

I want to learn Banach fixed point theorem, metric space is a pre-requisite knowledge

[dusty ice]

Ah ok

Then yeah the point is you're using the same function

Just restricted

And so you're throwing away some elements of the balls because they're no longer in the set you care about

[untold arrow]

restricted that the points must be in the subset?

[dusty ice]

Yes

So in this case we have a metric d: R x R to R+, and the subset metric is the same d restricted to Q x Q

So for elements x, y in Q we say d(x,y) is the same as in R

[untold arrow]

Thank you, i understood the most, but still confused abouth this : An open set in Y may not necessarily be an open ball in Y? can you give me an example maybe?

[vocal sleet]

@untold arrow Has your question been resolved?

[dusty ice]

An set $U$ is open in a matric space if for every $x\in U$ there is a $\epsilon>0$ such that $B(x,\epsilon)$ is a subset of $U$. This is equivalent to being a union of open balls. (just providing the definition if you haven't seen it)

[twin meteor]

Edward II

[dusty ice]

So the obvious examples of open sets that aren't open balls are disjoint unions of balls

What I'm saying is more subtle: the set $(\sqrt2-1, \sqrt2+1)\cap\mathbb Q$ is open in $\mathbb Q$, and is the intersection $B(\sqrt2,1)\cap\mathbb Q$, where $B(\sqrt2,1)$ is an open ball in $\mathbb R$. It is not however an open ball in $\mathbb Q$, because the centre point would have to be in $\mathbb Q$ for that to be the case, but it also has to be $\sqrt2$.

[twin meteor]

Edward II

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@untold arrow Has your question been resolved?

[vocal sleet]

@untold arrow Has your question been resolved?

[untold arrow]

.close

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[icy pendant]

I don't understand how |x| / x = -x / x

[viral copper]

definition of |x|

[ \abs x = \begin{cases} x \quad x \geq 0 \ -x \quad x < 0 \end{cases} ]

[twin meteor]

argon
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[viral copper]

i don't even know what broke

[heavy yoke]

,,\abs x = \begin{cases} x & x \geq 0 \ -x & x < 0 \end{cases}

[twin meteor]

cloud

[icy pendant]

I still don't understand it. Say my x is 5 or whatever, absolute would still be 5. Say my x is -5, absolute would still be 5.

[viral copper]

yes

and the way -5 turns into 5 is -(-5)

[icy pendant]

I get that

But I don't know how that applies to my example

5/5 != (-5)/5

I mean, the absolute is always positive so how can it be -x?

[vocal sleet]

@icy pendant Has your question been resolved?

[icy pendant]

I mean what I understand is you're telling me that |x| = -x, and I don't see that. Absolute is always positive, no?

[tidal dock]

if x is negative, -x is positive

and so is |x|

[icy pendant]

Ah so I can only do this because I’m taking the left limes, right?

[tidal dock]

yep

[icy pendant]

.close

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[vast shale]

Can someone help me recap on degree coefficients and constants I keep confusing my self

if they say beans the coefficient and degree I would get confused

[pale perch]

coefficients are the numbers in front of variables, like the 5 in 5x
degree of a polynomial is the highest power of the variable that appears
in quadratics its 2, in cubics 3 etc

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[vast shale]

What if there no power in the equation for degree ? And what about constants

[pale perch]

if there is an x then that would be x^1 ie degree 1

constants, you can consider them degree 0

[vast shale]

So how do I find constants

[vast shale]

Like 5x-2 degree is one cause the x is one ?

[pale perch]

yeah

[vast shale]

So degree is one

Wha if there’s 2 variables

3xy

Does tha means 1+1

?

[pale perch]

that would be degree 2

[vast shale]

Ohh

Xy Yx is like 1+1?

[pale perch]

if you have that situation its the highest sum of powers in any one term

like x^3y+2x+3y^3 is degree 4

[vast shale]

Do u add powers in tha situation it jus the higher in e

[vast shale]

Oh

The 9c^3 one the coefficients are 9c^3 c^2 4c?

[pale perch]

coefficients are the numbers in front, not the variable also

just 9,1 and -4

[vast shale]

Where 1?

[vocal sleet]

@vast shale Has your question been resolved?

[pale perch]

the c^2

has coefficient 1

[vast shale]

Why’s that

Cause c is one

?

[vocal sleet]

@vast shale Has your question been resolved?

[pale perch]

no, any variable by itself has coefficient of 1

because you have 1 of them, x=1*x

[vocal sleet]

@vast shale Has your question been resolved?

[vocal sleet]

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[rocky widget]

hello need help

[rocky widget]

https://rasmussenedu-my.sharepoint.com/:w:/r/personal/raven_beaulieu_smail_rasmussen_edu/Documents/RBeaulieu_Module03Assignment-Encryption_.docx?d=waac2f1b93a8c449b911d12ccf2ffb894&csf=1&web=1&e=g5YNrZ

i dont know whats wrong

or what i did wrong

(number 5)

[steep ravine]

Can't access what you linked

I could answer you if I knew the link you make between characters and numbers

[rocky widget]

https://rasmussenedu-my.sharepoint.com/:w:/r/personal/raven_beaulieu_smail_rasmussen_edu/Documents/RBeaulieu_Module03Assignment-Encryption_.docx?d=waac2f1b93a8c449b911d12ccf2ffb894&csf=1&web=1&e=YaLr3Q

see if this works

[steep ravine]

Can't acess the link. I need sort of an account

[rocky widget]

ohh

does this look right ?

like no errors ?

checked 2 times already it looks good but maybe im missing something

[steep ravine]

What a joy, I do this and I resume my Coding theory work. Wait a sec

[rocky widget]

okay😭

matrixs got so much work

[steep ravine]

Please, respect linear algebra XD

This is hell, Linear algebra is not ❤️

[rocky widget]

i got 3 pages of work just for 5 questions

[steep ravine]

In your computations

On the third caracter of the line

You do the wrong line

you use [1 3 2]

while its

[1 0 2]

e.g.

[rocky widget]

YO TY

its that little shit i miss bro😭

[steep ravine]

Ping me if something goes wrong later

[rocky widget]

okay ty

[rocky widget]

okay i checked it 2 times again does everything add up okay

holy shit found a another error

this error might fix it wait

[vocal sleet]

@rocky widget Has your question been resolved?

[vocal sleet]

@rocky widget Has your question been resolved?

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[vast shale]

Struggling with linear independence. Can someone help?

[vocal sleet]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[vast shale]

One trival solution.

[steep ravine]

What's the trouble with that grand notion

[vast shale]

I learned 3 theorems and I understood nothing.

[steep ravine]

Which ones

[vast shale]

So if we comparing 2 vectors

It has to be in the same direction..

I understand that.

No away we scale a diff dir to give 1 dir.

[steep ravine]

Yep indeed

And for more vectors you don't get it ?

[vast shale]

For 2 vectors i kinda get it.

Since we can multiply in such numbers that it can change dir through . neg or positive.

But since last lessons i havent quite visualised 3 thingd

[steep ravine]

Basically, a family of vectors is linearly independent if you can't obtain one from all the others by additions and multiplication by scalars.

[vast shale]

Many times my matric row reduced last line ends up with this:

[000│0] [001│0] [0002│0]

What can we say about those?

[steep ravine]

So in the particular case where you have two vectors a and b as you said, to get b from a lindar combination from the rest, a, its just to say that b is not a multiplication of a.

[vast shale]

Understood this...

[steep ravine]

Your matrices have not the same size

[vast shale]

These are diffrent situations

Just ik that the third one has no solution. (We imagine that these matrices are 3 X3 just investigating last row.)

so third one has no solution.

2x cant equal 0

for whatever x value

[steep ravine]

Well x=0 works.

[vast shale]

Yeah..

I did that and after this i broke up..

[steep ravine]

I think you're confusing multiple things...

[vast shale]

Yeah..

[steep ravine]

Do you want me to explain first the independence of vectors, then I move to matrices stuff ?

[vast shale]

Can't explain independence if you don't explain free variables basic ones, and these other cases..

non trival solution...

[steep ravine]

Whats "free variables" ? I have a definition but i'm sure you don't mean this

Oh

[vast shale]

they say "Put whatever you want and it works"

[steep ravine]

So ok you want me to talk first about system resolution.

Ok

So

Lets consider the equation $2x + y = 0$. This one i'm sure you can solve, you expres $y$ in terms of $x$ so the solutions are $(x, -2x)\ varrying \ x$. Finding those "free variables" in your system reduction is the same thing as saying "the best we can do is express $y$ in terms of $x$, after that, the $x$ may varry.

[vast shale]

y = -2x

?

[twin meteor]

LucienF

[steep ravine]

Sorry

Yes

Then you so the same principles for more variables, you express as much variables in terms of a few others in your systems

[vast shale]

still..

[steep ravine]

In other words

You search for the linearly independent rows in your matrix if you remember what i have said above.

Its the same coin

[steep ravine]

Reduction is just a fancy wah to do it algorithmically

[vast shale]

still dont understand

[steep ravine]

Want to do an example?

[vast shale]

y=-2x is an example

[steep ravine]

A lame one

[vast shale]

what is free variable here

[steep ravine]

$x$ is free since you have no coerton on it

[twin meteor]

LucienF

[steep ravine]

You let it varry to express all the solutions

Lool for the other example:

[vast shale]

what do you mean by varry?

y = -2x x = -y/2

y is free?

[steep ravine]

To find ALL solutions (x,y) such that y=-2x, then you have the solution (0,0) for x=0, (-1,2) for x=-1,... To have it all you have to "free" $x$ let it express everything, but $y$ is not free as fixing $x$ fixes $y$>.

[twin meteor]

LucienF

[vast shale]

y = -2x

y = -2 (10)

y= -20

Same as:

20 = -2x

x = 10

Both free variables/.

[steep ravine]

Freeing $x$ is the choice made when you express $y$ interms of $x$. If we did the converse, the solutions would be $(-0.5y,y) \ varrying \ y$, so $y$ is free here, not $x$.

[twin meteor]

LucienF

[steep ravine]

You choose one to be free to express all the solutions in terms of it.

If the equation was $x+y-z=0$, then you can express $z= x+y$, so you can free $x$ and $y$, and give the solution in terms of those, so the solutions are $(x,y,x+y)\ varrying \ x,y$.

[twin meteor]

LucienF

[steep ravine]

You choose the free variables

The only thing you don't choose is the NUMBER of free variables if you think about it

Like when you have a line, you choose a vector on it.

Its the same

Just different languages

[vast shale]

X= 0 is a free?

Why?

[steep ravine]

👀

Where did you see it ?

[vast shale]

I mean if you see this...0|0 is free

Right?

Thats why i asked you the question you didnt answear...

[000│0] [001│0] [0002│0]

What can we say about those.

[steep ravine]

If you solve the equation is "x=0" then no $x$ is not free since you fix it as zero.

[twin meteor]

LucienF

[steep ravine]

You don't let it varry

[vast shale]

Yea.

Now lets take a matric

What can we say?

X3 is?

[steep ravine]

So

[vast shale]

Its already row reduced to unit matric...

[steep ravine]

If you solve a matrix system AX=B and you have [000|0] at your third line, then it means 0x +0y +0z =0, thats just 0=0, its an equation which is always true. So youe solutions only depend on the rest of the matrix.

[vast shale]

This is called smth...

[steep ravine]

Do you agree with that?

[vast shale]

Yes but, this form is called smth

What is it called?

[steep ravine]

Gaussian reduction ?

[vast shale]

Nooo..

[steep ravine]

by the way i need to sleep also its 3am ahahah

[vast shale]

When you see in the end that some eq is 0= 0 2 =2

Bruhhh

[steep ravine]

Well it means that the inital equations were NOT linearly independent.

So your matrix is not invertible.

What else could be called.

[vast shale]

Anyaways...

[steep ravine]

No pivot on a line

[vast shale]

Idk maby its brain fog in 4 : 30 am.

[steep ravine]

Idk whats in your mind.

[vast shale]

Now whats trival form

AX=0

[steep ravine]

Idk what that means i'm french i never encountered the term trivial form 🤣

Oh

[vast shale]

Ok now i have to browse the papers...

[steep ravine]

0=0 is a trivial equation

👀

[vast shale]

Yeahhhhhhhhhh

[steep ravine]

Ok

[vast shale]

So why???

[steep ravine]

Trivial because all solutions are solutions

[vast shale]

Any visualisation?

[steep ravine]

Pick any numbers x,y,z. Then you can check on your computer that 0x +0y + 0z =0.

So (x,y,z) is a solution

That what it means

[vast shale]

...

Go sleep... Thanks.

<@&286206848099549185>

[vocal sleet]

@vast shale Has your question been resolved?

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@vast shale Has your question been resolved?

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[acoustic spindle]

gys this would be 6 right? or is it 5

[dusk trail]

so anything raised to 0 becomes 1

[acoustic spindle]

yeah

[dusk trail]

5(1) = 5

[acoustic spindle]

oh my days ims tupid as shit i was tryna add it together lol

my bad

.close

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[dusk trail]

it's okayy, u got itt

[vocal sleet]

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[untold arrow]

\begin{aligned}
&\text{Let }f(x)\text{ be a non-negative continuous function on }[0,+\infty)\text{. Consider the following three propositions:}\
&\text{1. If }\int_{0}^{+\infty}f^{2}(x)\text{ converges, then }\int_{0}^{+\infty}f(x)\text{ converges.}\
&\text{2. If there exists }p>1\text{ such that }\lim_{x\to+\infty}x^{p}f(x)\text{ exists, then }\int_{0}^{+\infty}f(x)\text{ converges.}\
&\text{3. If }\int_{0}^{+\infty}f(x)\text{ converges, then there exists }p>1\text{ such that }\lim_{x\to+\infty}x^{p}f(x)\text{ exists.}\
\end{aligned}

[twin meteor]

nino
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[untold arrow]

which one is correct?

status 1

[mellow oyster]

try to think of simple counterexamples

[untold arrow]

i cannot think of any

[dapper condor]

harmonic series for the first one

[mellow oyster]

though 1/x^2 doesn't converge either so i don't think that works

[dapper condor]

actually yea

also bounds are messed up cause it should be 1 to Inf

[mellow oyster]

but same reasoning for 2, if you consider p = 2 and f(x) = 1/x^2, then the limit exists but the integral diverges

[vocal sleet]

@untold arrow Has your question been resolved?

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[next burrow]

my calculator got 0.302 but my calculator says its wrong so idk what to do

[next burrow]

there is also this one which i dont know how to calculate

[short pilot]

Don't open two channels close one

[next burrow]

i tried

i did .close and !close

plus the bot said this so "Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock."

[next burrow]

so ya idk what to do

[next burrow]

i tried it again, and got a different result "0.154"

but thats also wrong

[next burrow]

ok i got 0.303

[next burrow]

having trouble with this though

[vocal sleet]

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[waxen hawk]

Can someone do the calculation for me

I’m not really a fan of arithmetic

I don’t want it to ruin my day

Save me

[short pilot]

Can u not do the double derivative of it

And find a and b first from the details

Then

[waxen hawk]

smart people

[waxen hawk]

I do not have the derivative.

[short pilot]

Can't u find the derivative

d/dx

No I am saying

[waxen hawk]

of course I can differtiate it.

but it is of no use.

[short pilot]

Do the double derivative simplify the equation

Then use the values.given

[waxen hawk]

I do not know any value of f'(x)

[short pilot]

What values you have

Tell

[waxen hawk]

6 points that are upon the function.

[short pilot]

Graph?

[waxen hawk]

no, just six exact point of the 3 degree polynomial.

[short pilot]

Ok

Then u used only 4

Where rest two

[waxen hawk]

I only need 4

to solve it out

[short pilot]

U tell me first

The rest two

[waxen hawk]

we have to negotiate

[short pilot]

Tell me bro

[waxen hawk]

If I tell you the rest two.

alright

[short pilot]

Tell me bruh

Bro

[waxen hawk]

the cut piece is of the original question

[short pilot]

U have 6 points for 12

[waxen hawk]

for sure.

save me

[short pilot]

That means function attain same values at these points

[waxen hawk]

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

[short pilot]

What

Chill wait

[waxen hawk]

save me from the arithmetic purgatory

[short pilot]

Chill

[waxen hawk]

should I spoil you the solution

[short pilot]

No

Wait

[short pilot]

Let me tell

[waxen hawk]

no is counted as an affimative in my region.

[short pilot]

Oof

I think we need to

[waxen hawk]

do the math

fk

[short pilot]

We need to cook 🗣️🔥

[waxen hawk]

please.

cook it

chef

cook the system.

[short pilot]

Have you been taught

Lagrange and rolled?

Rolle's

[waxen hawk]

ohhh

[short pilot]

It says

If f(x) is continuous on [a,b]

[waxen hawk]

you means a(x-p)^3+b(x-p)^2+....

some stuff

like that.

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

shit

[short pilot]

And differentiable on (a,b) and f(a)=f(b)
Then f'(c)=0

B/w a and b

I can say that u have 6 poinys

Where f(x) is same

[waxen hawk]

what is c, bro

what is c

[short pilot]

So f'(x) will be zero at two points at is quadratic

[waxen hawk]

broooooooooooo

broooooooooooooooo

[short pilot]

Bro I feel there is other way

[waxen hawk]

ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

[short pilot]

No one wants you to solve a system of 4 linear equations

Wait

[waxen hawk]

ahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

[short pilot]

Chill my guy

Chill

[waxen hawk]

I do not think theres other more effiecient way to solve it than simply do the arimetic stuff

[short pilot]

Then compute it only bro

,w find a,b,b,d

[twin meteor]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by oppailol.

[waxen hawk]

even the robot wouldnt do this shit.

[short pilot]

,w evaluate a+b+c+d=12
8a+4b+2c+d=12
27a+9b+3c+d=12
125a+25b+5c+d=12

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by oppailol.

[short pilot]

The f

Aah

It took as into

Wait I will compute it

,w solve system of linear equations a+b+c+d=12
8a+4b+2c+d=12
27a+9b+3c+d=12
125a+25b+5c+d=12

[twin meteor]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by oppailol.

[short pilot]

Thenf

w,solve a+b+c+d=12
8a+4b+2c+d=12
27a+9b+3c+d=12
125a+25b+5c+d=12

,w solve a+b+c+d=12
8a+4b+2c+d=12
27a+9b+3c+d=12
125a+25b+5c+d=12

[twin meteor]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by oppailol.

[short pilot]

Aah

@waxen hawk

Aah

[waxen hawk]

i cannot breathe

i'm overwhelmed.

[short pilot]

,w solve a+b+c+d=12 ,
8a+4b+2c+d=12 ,
27a+9b+3c+d=12 ,
125a+25b+5c+d=12

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by oppailol.

[short pilot]

Lol

@waxen hawk

Lmao

Now what can I do

[waxen hawk]

ohh so the answer is

12

[short pilot]

Lol

No no

Wait I am come with answer

[waxen hawk]

it is 72

since d=72

it is provided on the book

no

I'm dying.

[short pilot]

Bro

See

[waxen hawk]

i'm so mad

[short pilot]

That's why you need 6 equations

[waxen hawk]

why

[short pilot]

You need to take pairs

[waxen hawk]

why

why

[short pilot]

You need pairs to simplify

[waxen hawk]

there's only 4 unknown constant

[short pilot]

Lol

[waxen hawk]

I only need 4 equations to solve it

[short pilot]

The whole equation is unknown my guy

[waxen hawk]

no

[short pilot]

I went on the site it says d=12

[waxen hawk]

I'm so mad

[short pilot]

see u need 6 equations to get 2 equation with only c or d

Or a or h

B*

So that you can find them

[waxen hawk]

i'm so mad.

[short pilot]

Imma come later

Gtg

Battery 4

[vocal sleet]

@waxen hawk Has your question been resolved?

[vocal sleet]

@waxen hawk Has your question been resolved?

[short pilot]

Yo

@waxen hawk

Lol

[waxen hawk]

hello kitty

[random ice]

Can somebody help me wtih graphing in desmos?

I'm tryna visualize

[short pilot]

Yo

Lol

[random ice]

wait oops

[short pilot]

Tell which graph

Tell

Imma plot it

[random ice]

alr

not sure if its right

but yeah

[short pilot]

,w plot [(y-2)^2=16(y+1)]

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by oppailol.

[random ice]

is this supposed to be correct?

[short pilot]

No wait let me write in expanded form

y^2+4-4y=16y+16

y^2-20y-12=0

ok we got it

@random ice

[random ice]

yeah

[short pilot]

,w plot y^2-20y-12=0

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by oppailol.

[short pilot]

This is correct

Enjoy*

[random ice]

but y^2 opens rightward right?

[short pilot]

Aaj

Aah*

It took it as x

Wait let me plot it as function

Wait

Wait

@random ice u can just rotate the graph 90 degree

[random ice]

oh

aigh

[short pilot]

Rotate your phone 90

Degree and see it

[random ice]

Though if I was gonna graph this in desmos

how so

[short pilot]

Wait imma give u correct graph

See

,w plot x=y^2-20y-12

[twin meteor]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by oppailol.

[short pilot]

@random ice

This is correct

[random ice]

alr

[short pilot]

wait

,w plot y=x^2-20x-12

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by oppailol.

[short pilot]

@random ice

This is graph of y=x^2-20y-12

Wolfram is shifting axes

Type on Desmos

@random ice

x=y^2-20y-12

[random ice]

ok

[vocal sleet]

@waxen hawk Has your question been resolved?

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[jade zenith]

I need help with statistics

[jade zenith]

@vocal sleet

@vocal sleet what do we do?

agsian?

.close

[vocal sleet]

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[short pilot]

.reopen

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[bleak prawn]

Really quick question

When I bring the u^2 into the numerator by making it u^-2 is it multiplied by the -2u-7? Or added to it?

[outer warren]

multiplied

[bleak prawn]

Thx

❤️

.close

[vocal sleet]

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[outer warren]

a/b isn't a + b^-1

[bleak prawn]

Ah true haha

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[storm finch]

<@&286206848099549185>

Someone please help me with this question cause I can't

I don't know where to begin

<@&286206848099549185>

<@&286206848099549185>

[tender cypress]

Hello

[storm finch]

Hi

[gentle thicket]

Do you know about Vieta's formula?

Like for a quadratic equation it is like:-
Consider a quadratic equation $Ax^2+Bx+C=0% with alpha and beta being it's roots. Then sum of roots = -B/A and product of it's roots is C/A

If you know then this question is piece of literal brownie

[storm finch]

Ya ik

[gentle thicket]

so just expand the equations and apply the formula

after that it's just simple algebra

[gentle thicket]

btw, is this question somewhat related to that Joint Entrance Examination?

[storm finch]

Ig

I got it from my friend

He's doing coaching for jee

[gentle thicket]

okok
these kind of problems are common in Mains\

[storm finch]

Really

[gentle thicket]

yeah

[storm finch]

It's a NTSE question

I didn't knew that ntse helps in jee mains

[gentle thicket]

I mean government bodies are almost similar

In which grade you are currently if you are comfortable to share?

[storm finch]

10th

[gentle thicket]

okok
damn

[storm finch]

I think you're also preparing for jee

[gentle thicket]

somewhat yes

[storm finch]

In which grade are you in

[gentle thicket]

just cleared 12th this year

[storm finch]

Wow

Did you appeared for mains this session?

[gentle thicket]

yeah

even qualified for advanced but Advanced showed me my place😶

[storm finch]

Wow

You're too intelligent

Jee is such a tough exam

[gentle thicket]

I find it really strange

[storm finch]

Did you joined a coaching or something?

[gentle thicket]

It's more friendly for those who want to become engineers

[storm finch]

Ya

[gentle thicket]

PW online

[gentle thicket]

people like me with with ambitions in pure science suffer🥲

[storm finch]

Wow you sure have studied a lot then

[storm finch]

Fr

There is such a massive competition there

[gentle thicket]

what are you interested in engineering or pure science?

[gentle thicket]

or none?

[storm finch]

Wdym by pure science? Research?

[gentle thicket]

yeah

[storm finch]

Yes I'm interested in research

Aspiring for ISRO

[gentle thicket]

ooh same

[storm finch]

Which equation to be expanded?

The alpha one?

[gentle thicket]

expand both of them

[storm finch]

Ok

[gentle thicket]

find the value of sum and product of roots for the first one and use it for the second

[storm finch]

Ok

.close

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Channel closed

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[vocal sleet]

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[placid totem]

I'm graphing parabolas and nothing was covered when there is a coefficient on the left like 4p on the right

[tawny nacelle]

nothing should change

you still should solve for y

[twin horizon]

What are you trying to get?

[placid totem]

focus and directrix

and I have to graph it

up until now it hasn't had a coefficient on both sides, so it was just a matter of dividing 4p and then getting the vertex

No clue what to do here because there's a coefficient on both sides and none of the material covered graphing parabolas this way

[tawny nacelle]

how have you been doing it thus far?

and what is 4p?

[placid totem]

x^2 = 4py or y^2 = 4py

Whichever is squared dictates the direction the parabola opens

[twin horizon]

(x+5)²=-⅘(y+5)

[placid totem]

That's what I did first but wasn't sure

Can you just divide away the -5 like that?

Don't you also have to divide everything in the parentheses by -5 as well?

[twin horizon]

What?

[placid totem]

oh nevermind it would still be the same if you distributed 4 to (y+5) then divided by -5

or wait

yeah I'm confused lol

whenever you do something to one side, don't you have to do it to everything on the other?

So how do you just divide the right by -5 while ignoring (y+5)?

.close

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Channel closed

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[ivory berry]

Why isn't my second answer correct? I also tried rounding it to 5 deci places and inputting it as an equation pi - arcsin(.75) None of those things seem to be considered correct by the website

[ivory berry]

I am beginning to think the website's answer key might just be wrong as I asked chatgpt and a friend of mine who both said I was right

[lime garden]

Checks out for me, my course websites have had this error in the past.

[ivory berry]

Alright thank you, I might email my prof then.

how do I end this help form, I'm new here, is there some sort of comand?

.end

[drifting jackal]

.close

[ivory berry]

Thank you

.close

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[dire harbor]

can anyone lmk what test id use for proving convergence for this series

[vocal sleet]

@dire harbor Has your question been resolved?

[dire harbor]

<@&286206848099549185>

[lone linden]

Integral test works

[dire harbor]

that’s what i was thinking

do i make whole denominator u for usub

[lone linden]

Uh

You can find the anti derivative explicitly if you want to

But that’s a lot more effort than it’s worth

I gtg, but I’d use ||a comparison argument||

[dire harbor]

i see

.close

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[gleaming owl]

If I have two sides of a right triangle and I don't have the 3 side and they don;t tell me the Pythagorean result what can I do to find the third side?....

[gleaming owl]

any ideas on how to figure it out?

[drifting jackal]

To use Pythagorean theorem

If it's a right triangle

[gleaming owl]

Okay

but if I don't have c then OH OH

[oak magnet]

Do you have one angle ?

[gleaming owl]

No

but I got it

so get the value for c on one side

[drifting jackal]

You don't need an angle though if it's a right triangle

[gleaming owl]

subtract and solve for c

right?

[drifting jackal]

Pythagorean theorem applies to right triangles

[gleaming owl]

so the answer I got is 13

[drifting jackal]

Can you screenshot the problem please?

[oak magnet]

Oh i understood it wasnt a right triangle mb

[drifting jackal]

Hard to check your answer without the values

[gleaming owl]

there's the problem

[drifting jackal]

Yeah, then you did it correctly

[gleaming owl]

so I got 13 for my answer just know that the pythagorean theorem is a^2+b^2+c^2 so I don't have c so add up the values for a and b put c on one side subtract the sume of a and b so that c^2 is by itself and then find the square root

thanks!

[drifting jackal]

a^2+b^2+c^2
Not quite

a^2+b^2=c^2

It's equals

[gleaming owl]

oh okay

[vocal sleet]

@gleaming owl Has your question been resolved?

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[vagrant lynx]

I need help calculating the limits, I already answered a few but I cant seem to figure out how to find the limit as x approaching negative and positive infinity

[little adder]

@vagrant lynx The answer to the h and i is DNE

since you can not determine the exact limit

[vagrant lynx]

Thank you dawg and how did you find that answer I dont really know how to figure that out

[little adder]

I took calculus so i know that but even I dont know how to do it

Also a few answers of yours is wrong so dont close this channel yet

[vagrant lynx]

which ones?

[vagrant lynx]

lol

[little adder]

i am checking but i can sense that some are wrong

L is wrong since f(-1) is a hole so the answer is -30

Keep in mind the hole

I think thats it really

[vagrant lynx]

how is it -30? I understand that the circle is open but is it because it curves downwards?

[lusty snow]

Because it cant be -10

[little adder]

Thanks @lusty snow you take it over

[lusty snow]

At the point -1 it is 30

[vagrant lynx]

I understand that it cant be -10 but how is it -30 if there is no dot there

[lusty snow]

Hmaybe just mistype

[drifting jackal]

He typoed, he meant 30

[vagrant lynx]

oohhh

I was so confused dawg

thank youu

could you look over my work again on the left side of my answers and see if there is anything I need to fix please?

[little adder]

Nothing else

I also need help on calculus as well curve sketching and stuff

[vagrant lynx]

how about if x approaches 4 on the graph, would it be 4 since the left and right meet near -20

[drifting jackal]

Btw the answer to H is wrong here, you can see what it approaches

[lusty snow]

Ye

h -30

[vagrant lynx]

so h is -30

[lusty snow]

I -∞

J -40

[little adder]

You both are just confusing him 😕

[vagrant lynx]

h is -30 and i -inf

[vocal sleet]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[drifting jackal]

Technically you are since you gave the wrong answer to H

[little adder]

Ok i guess

[vagrant lynx]

I think i got the right answers now the only question i got is if x approaches 4 on the graph, would it be 4 since the left and right meet near -20? there are two dots there so I kind of dont know which one it would be

[drifting jackal]

The circle that isn't filled in means it's a hole

[lusty snow]

g?

[vagrant lynx]

yeah

its blurred out so i just wrote it out

[lusty snow]

It should be -20 something but im not sure

[vagrant lynx]

thats what i thought but since there are two dots at 4 would it be DNE because it doesnt specify which one right?

[lusty snow]

Like

f(4)=-10

But lim x to 4 might be -20+

[vagrant lynx]

hmm so it should just be lim x approaches 4 = -22

around there

[lusty snow]

Logically yes but it may not have logic so i dont know

Argh or it is just -10

cuz i dont know

[vagrant lynx]

I thought so too but it doesnt say f(-10)

[drifting jackal]

Limits is what the value approaches, not what the value is

So as the limit approaches 4 from both sides, what is the value it approaches?

[vagrant lynx]

so -22 since the limits are equal

[drifting jackal]

Correct

Now if it asked for f(4), that's a different answer

[vagrant lynx]

Thank you bro I really appreciate it!

I was stuck on this homework for a while!

[drifting jackal]

Because it's not approaching 4, but asking for what is the value when x = 4

In that case, f(4) = -10, if that makes more sense

[vagrant lynx]

yes I understand

Thank you so much dawg

.close

[vocal sleet]

Channel closed

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Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[iron parrot]

what is $ -7 + (- 8)$

[shy walrus]

-15

[iron parrot]

is bot dead?

anyway

what is b + 9 + + 3?

[shy walrus]

b+12?

[iron parrot]

yes

[shy walrus]

and next one is c+34?

[iron parrot]

good job!

[shy walrus]

do i have to do anything next?

[iron parrot]

what number can take b's place?

so that b+12=-15?

[shy walrus]

-27

[iron parrot]

can you do the same thing to find the value for c?

[shy walrus]

would it be -49?

its that simple,,>

?

[iron parrot]

yes

you don't even need help!

[shy walrus]

im going to try another question, i will send answer

[iron parrot]

sure!

[shy walrus]

e = -12 and f= -20

[iron parrot]

explain how you got them

what is -9 - + 3

[shy walrus]

so e-20 =-12

wait

hold on

[shy walrus]

-12?

[iron parrot]

yes that is correct

[iron parrot]

what does this give you for e

[shy walrus]

then e-20 would equal to -12

so when we bring it across, e= -12+20

sorry

+20

and i got 8

[iron parrot]

yes, e=8

[shy walrus]

and the other one i got 32