#help-17
1 messages · Page 198 of 1
yes
but could i do it like
ohh i know what you mean
lets say cos² is f, and (3x) is g?
So i do d/dx(cos²(3x)) which means d/dx cos² * (3x) + cos2 * d/dx (3x)
?
you committed a sin
💀
that would work if it was cosx*3x
🥲
but here it is a function inside another function
you might like to write $2\cos^2x = \cos2x + 1$
Xetrov
i get stuck recognizing chain rule and basic derivative
unnecessary
if you say so
lots of practice makes the job
ait
I'm just saying that it could be a nicer derivative
...?
whatever ig
Tosi, I've given you a form which allows an easy evaluation of the double derivative
why are you not using that
unnecessary as i said
because?
i still get 0/0
you don need to derivate more
When inserting 0
you're making them do a nasty derivative
do you know what sinx/x as 0 goes to zero does?
im not
.
wait let me translate that real quick
it's one of the classic limits
therfore what do we have to do to get that case
maybe sin2x * sinx?
where did you get that /3x from?
you can multiply on top and bottom by three
and you get yours sin(3x)/3x
which you can eliminate as you know it gives you 1
what isn't clear
english is the problem
can you write it somewhere or?
i have to translate all the time
Ok
first of all you can cancel the 2 on the top with the one on the bottom
dw mister
For my lack of foresight
see it was easier
Where did bro get that -2
(you could have done it in the first step recalling another identity)
but let's not talk about that
which one
in front of sin3x
you had it aswell
i know where - came from, but 2?
is it clear
OOOOOOOOOOOOOOO
where are you from
now i get it
real moi brat
😂
italija
ohh
idk how to spell in your language
Gl on monday
1 am for me aswell
ban this dude
for what
Croatia - Italia
Euros
oh i dont follow that
@plain ledge can you solve this limit for me?
yes
im listening
🥲

I DONT KNOW
HAHAHAH
wasn't Croatia good
it was but its ahh now
Seif where you from?
2 words: zlatko dalić
france
ahh
ur team is african
oh💀
is he that one blonde
yes
was it the world cup that they won
who?
if thats the case i can solve it
i need to solve this limit
bro i already solved it
💀
me and the other guy
we helped you
it needs to be -9
yes
yep
what do you guys study btw?
Amog us
do the hospital rule
|| le persone italiane in sto discord sono n ($n \to 0$) ||
Adversing
Did it
is bro italian
.
he is sharing ads
ye
ban him
ne ho beccato uno il giorno prima della seconda prova di maturità che ho fatto pure io
his name is Advertising
Computer Engineering or Software engineering, it depends by the name it goes in your country
tell
lmfao
figo
no, he's from italy
How did bro get rid od cos up?
I can assure it to you xd
hell nah
cos0=1
I mean up here
Doesnt he have to input 0 in all xs?
yes and cos0=1 anyways
tosi where u from
italy bro
but if he inputs 0 in all xs
bro
Then result is still 0/0
but the sinx/x goes to 1
Im in civil engineering
also limits are multiplicative
mechanics are easier than math ngl
we are 900Km away from each other @hybrid breach
tough shit
yes
I'll do pure maths next year
fr
guess my dinner
jolof rice
$\pi$? (🥧)
Adversing
bro integrals are easier than limits fr....
yes pizza
Easier my ass
bro that's a pie
nah a pizza
nah man, you never saw elliptic functions
@hybrid breach how old r u
18
ive seen enought to kms
Ngl
you say so?
thanks ig
thats a bad thing
xd
that just looks scary tbh
Trying to find a number here
lo farai in Analisi Matematica 2
using numbers in mechanics and statics - 🏝✨️
sincero non è difficile
numbers? what do you mean?
using numbers(letters) in math - 🥲
what is a number?
Ofc
(classic calc 2 student)
like 0 1 2 3 4 5 6 7 8 9
never heard of those
but ig high level math never heard of that
isnt that just a double integral over a surface
yeah I know I was joking
you stop seeing numbers after a certain point
so am i
I've reached a level where if I even find a number in an integral I'm blessed
like I have to thank god
bro at my college physics are easier than math
just fail math class like me
alphabets are not higher level math xd
my little brother knows them
physics for me piece of cake ngl
at the age of 8
will you drop out or will you endure
ah no non fai mate pura hai detto
niente
no non sono così malato
i will drop out if i dont pass this math
io si
tanto calc 1 e 2 li ho già in mano
I hope so
other than uni
i mean
engineer >>>>>>>>>>>>>>> bacc.
aight bois its been pleasure, thanks for help
croatia win italy 3:1, we win euros, modric retires after
bro
i wish you a loving day
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why are real numbers additionally defined as converging sequences of rational numbers?
Rational numbers are nice, but they lack a fundamental property for formally defining analysis, and therefore calculus (among others).
That fundamental property is called completeness, i.e. a guarantee that whenever I have sequence whose terms get arbitrarily close to one another (this is called a Cauchy sequence), then the sequence must have a limit within the set we're investigating.
The rational numbers don't have this property. For instance, we can easily approach pi using its decimal expansion, but doing so makes the limit slip out of the rational numbers, since pi isn't rational.
This property is important, because it allows for us to define limits and functions and all the machinery you need for analysis without fear that we get nonsense out of this.
Now as to why we do it that way, it's because by considering converging sequences in Q, we construct a new set, R, that is in some way the "smallest" set that has this property while containing Q.
Note that there are other ways of defining the real numbers, say with Dedekind cuts, or supremum properties.
the sequences aren't necessarily converging in Q, (for example pi) they are just cauchy
Yes sorry. I think the point remains mostly the same however. (edit : I've fixed my definition of completeness to reflect the more accurate one you pointed out)
@limpid garnet Has your question been resolved?
Thank you,
Are you a teacher?
No
interesting
Only, a massive part of my first class in real analysis was about different equivalent definitions of the real numbers, so it somewhat gets carved into your brain hahah
please excuse me, butI have an additional question, in what order did you (for instance) study formal pure mathematics? I am familiar that there is no concrete order for studying pure math.
I see.
(I am self tutoring, which is why I ask, and I am sort of a perfectionist)
Yes indeed. Contents of degrees vary quite considerably from curriculum to curriculum, so there is no best way, although I think most of them have the same overarching structure.
That is, most start out say, year 1, with some subjects that force you to do proofs, something like real analysis, group theory. All of that is so that you can then take more advanced classes and be able to come up with proofs on you own.
Self studying is a noble endeavor, although it is significantly harder to test your understanding of the material in a rigorous way, as you would by submitting homework and writing exams.
I personally did :
Y1 : group theory, vector calculus, ODEs, combinatorics, abstract algebra, advanced linear algebra, real analysis
Y2 : differential geometry, topology, complex analysis
Y3 : metric spaces, measure theory, fourier analysis, PDEs, numerical analysis.
Some years were more maths oriented and some less, due to my major being split maths and computer science, but I think it's pretty standard. You might want to look into curricula from other colleges, and maybe look into MIT's open courseware, since you can even get yourself some homework sheets and such.
Sorry that was long
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You might've seen it, but there's this video from AlephNaught where they describe a good roadmap to most content seen in an undergraduate degree in mathematics, so in case you're interested, this is the link
This video has a list of books, videos, and exercises that goes through the undergrad pure mathematics curriculum from start to finish.
REAL ANALYSIS
Book: “Understanding Analysis” by Stephen Abbott.
Videos: Lectures by Francis Su (https://www.youtube.com/playlist?list=PL0E754696F72137EC)
LINEAR ALGEBRA
Book: “Linear Algebra Done Right”...
Thank you
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There has to be an easier way to go about this right? does anyone see anywhere I can simplify?
let me write down the unit tangent I got
wouldn't that be difficult to take the derivative of again to find the unit normal?
I'm wondering if I am approaching this the wrong way
I know if the denominator was like sqrt(3), I'd be able to factor that constant out and take the derivative of the vector with just the numerator, can I still do that?
factoring out the denominator
Are these equivalent?
i remember when i had to do these same problems for calc3 in myopenmath
and yes, they were this long iirc
but if theres an easier way? i dont remember
i remember @pale widget helped me with the TNB frame thing
maybe theres some sort of simplification
right now im going to try factoring out the denominator and taking deriative of just the numerator and seeing if that works, I know its possible when the denominator is a constant but not sure when its a function
like this
You should calculate this using N=BxT instead. That’s why it’s called a TNB frame instead of any other ordering of the letters.
is there a formula for just B? we never learned that, we only learned finding T then N and then B = T x N
Yes but you’ll have to google it. There are lots of formulas
ok i'll do that
I think it’s r’(t)Xr’’(t) divided by the norm of that quantity off the top of my head but I don’t know
But you should obviously plug in the value of t after you differentiate but before you calculate the cross product and the norm to make it less notationally complex
Nope
im wondering how your tangent is much more simplified than mine
Anyway it’s called TNB because you can shift the letters in a circular fashion to get other formulas N=BxT and B=TxN
well u can simplify all those sin, cos of 5pi/6 right
and maybe its cuz i had pi instead of 5pi/6
@crisp zenith Has your question been resolved?
@crisp zenith Has your question been resolved?
@crisp zenith Has your question been resolved?
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What did I do wrong here?
@harsh gust Has your question been resolved?
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Matchstick
i dont know how $P_{O_{2}}$ relates to $P_{N_{2}}$
Matchstick
I think they're related by dalton's law
@vast shale do you know dalton's law?
the one that talks of partial pressure summation?
yeah?
i cannot recall any further than that
P1 + P2 + P3 = P(total)
where 1,2,3 are ideal gasses
yes
so you can right it in a useful form
do i use ideal gas equation to proceed further?
,,P_1 = X_i P_t
Wither
X1 is mole fraction of gas
is there a way to do that?
@vast shale Has your question been resolved?
volume percent is same as mole percent
because of avogadro's law
OH YES
I think you can do it now @vast shale
no probs
.close
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you could use the tangent addition rule
$\tan{(A+B)} = \frac{\tan{A} + tan{B}}{1-\tan{A}\tan{B}}$
$\tan{(A-B)} = \frac{\tan{A} - tan{B}}{1+\tan{A}\tan{B}}$
Adversing
I forgot the 1 lmao
can you try it please:C
yes, now I'll try it
on skibidi
@tulip temple Has your question been resolved?
you know you are cooked when it takes 5 quattuordecillion yearsto type it out
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NO WAIT
.reopen
ah yes thank gawd
ok now starting from what I wrote you should have
$$ \frac{\tan{A} + \tan{B}}{1-\tan{A}\tan{B}} = n \cdot \frac{\tan{A} - \tan{B}}{1+\tan{A}\tan{B}} $$
Then I'd multiply both sides by $(1-\tan{A}\tan{B})(1+\tan{A}\tan{B})$ so we obtain:
$$
(\tan{A} + \tan{B})(1+\tan{A}\tan{B}) = n(\tan{A} - \tan{B})(1-\tan{A}\tan{B})
$$
Once you get here and simplify to find both $\tan{A}$ and $\tan{B}$, you should get something like this:
$$
\tan{A} + \tan{B} + \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2 = n(\tan{A} - \tan{B} - \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2)
$$
Here I'm going to use the $\sin{(2\theta)}$ identity ($\sin{(2\theta)} = 2\sin{(\theta)}\cos{(\theta)}$) for both $A$ and $B$. As a consequence of this step, you get:
$$
\frac{\sin{(2A)}}{\sin{(2B)}} = \frac{2\sin{A}\cos{A}}{2\sin{B}\cos{B}} = \frac{\sin{A}\cos{A}}{\sin{B}\cos{B}}
$$
jesus I hate LaTeX
one sec
ong
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no
Adversing
$$
\tan{A} + \tan{B} + \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2 = n(\tan{A} - \tan{B} - \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2)
$$
Adversing
it's too long
you mean in the end?
where you obtain
$$
\frac{\sin{(2A)}}{\sin{(2B)}} = \frac{2\sin{A}\cos{A}}{2\sin{B}\cos{B}} = \frac{\sin{A}\cos{A}}{\sin{B}\cos{B}}
$$
?
Adversing
wait do you even obtain that
where did the n go
in the equation
what im asking is when you simplify tan(A+B) = ntan(A-B) what do you get
you have to distribute $n$ on the right-hand side combining the terms, solving then for $\tan{A}$ and $\tan{B}$
Adversing
so you cross multiply?
the expansion is this, but since it's too long to be rendered I suggest you to copy-paste my message and render it by yourself
i get that
what
do u do after that
is my question
how do you get tan and tan b induvidually
after that you rearrange to solve for tan(A) and tan(B)
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Hi! I was reading an article by Abraham Wald called "method of Estimating Plane Vulnerability Based on Damage of Survivor". https://apps.dtic.mil/sti/tr/pdf/ADA091073.pdf But I didn't really understand the pages 6 and 7 where he makes a hypothetical scenario in which " dummy bullets would have been used" in order to find equation (26) and use it later in the article. He sets the random variable yi as bi - ai. If I am right, yi seems to refer to the proportion of "planes that would have potentially been downed if real bullets had been used". But I have trouble understanding why making a hypothetical scenario in which dummy bullets would have been used helps to provide information about the missing planes? And why set the variable yi = bi - ai when it clearly looks equal to the random variable xi = Ni - ai (the number of planes shot down with i bullet holes is equal to the total number of planes with i bullet holes minus the number of planes with i bullet holes that survived)?
@tender pilot Has your question been resolved?
to reply to your first question imagine you use pretend bullets that don't break the planes. With pretend bullets, every plane, whether hit a lot or a little, makes it back to the hangar because they don’t get broken. By comparing the number of hits with pretend bullets (where all planes come back) to the number of hits with real bullets (where some planes don’t come back), you can guess how many planes got hit but didn’t make it back. So, the pretend bullets help you understand the total number of planes that got hit by giving you a way to see what would have happened if no planes were "broken." This helps you figure out the number of planes that are missing because they were hit too much.
i could be wrong or shit at explaining, this is what i think
(note that i skimmed through it)
to the second question, you use yi = bi - ai because xi = Ni - ai directly represents the number of planes shot down with i bullet holes. It is a straightforward count of the planes that didn’t make it back. On the other hand, yi = bi - ai s not just a direct count of missing planes. Instead, it represents the difference between the hypothetical total hits and the actual observed hits is used to estimate the total number of planes that would have been observed if none were shot down.
@tender pilot
dont take everything i said as truth😭
specifically they are different because, xi directly gives you the count of missing planes but doesn’t help in estimating the total distribution of hits. yi and bi helps you estimate the total hit distribution by considering a hypothetical scenario where no planes are shot down. This helps in understanding the overall picture of plane vulnerability. xi is used to identify how many planes are missing. yi helps to understand how many planes would have been hit in a complete dataset (if no planes were shot down).
this is actually really interesting i'll look into it more
thanks
@tender pilot Has your question been resolved?
well rip wrote an essay for nun😭 DM me if you have questions again @tender pilot
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Lets see question b) find area of shaded region
My question is when I integrate from -1 to 0 do I have to put a modulus?
Because in the answer scheme I had to put a modulus integration of 0 to -1 added with the integration of 0 to 3
To get the correct answer
I dont know in what condition should I put modulus in
area under curve question so ans cannot be negative
cus its an area
otherwise dont mind it
But cant i integrate from -1 to 3 tho
If I integrate from -1 to 3 I dont get the correct answer
It has to be modulus 0 to -1 added with 0 to 3
the b one ?
yeah
oh yeah
just do this one
and if the ans is negative then just modulus it
Thing is idk when should i split when should I not split them
Because this answer is positive
So does that mean the area from 0 to 1 i have to put a modulus for question a)
@fiery maple Has your question been resolved?
<@&286206848099549185>
What is the question?
For a)
Find the area of the shaded region
Do i have to put modulus if the area is below the x-axis?
Yes, split the integral and apply absolute value to each negative outcome
show work
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Sin(xy)= 1/2
-30x^-2
How are these equavilent
Or… however you spell that word
Mhm
so (xy)=?
Dy/dx it
oh, you want to differentiate it
30
Yes
sin(anything real) is always between -1 and 1, never 30
ok $cos(xy)(y + \frac{xdy}{dx})=0$
ƒ(Why am. I here)=I don't Know
Yes i fixed it
can you do it from here?
what is $-30x^{-2}$
ƒ(Why am. I here)=I don't Know
XY=30
yes
=
,w differentiate sin(xy)=1/2 with respect to x
I think this is the derivative only $\in [ 0, \frac {\pi}{2}]$
ƒ(Why am. I here)=I don't Know
I could be wrong though
Hmmmm
Maybe
ping helpers in 5 minutes
I will
<@&286206848099549185>
I call upon you
RISE
RISE GREAT HELPERS RISE
Yall should pay me for this intro
Sin(xy)=1/2
w
Is this paraphrasing or exactly what you've been given
what
Not really
not only 30
youre trying to do what?
[ \left ( x\dv{y}{x} + y\right )\cos(xy) = 0 ]
sin(xy)=1/2, find dy/dx for when xy=30?
Bob l'éponge
Okay I get what you mean now
No, from sin(xy)=1/2 we can conclude that xy=30
no
Why
not necessarily
also thats in degrees
One of the values
Wdym
Why does it have two different answers
Or- why doesnt eork eith degrees
what has two different answers
It does it's just that degrees don't work that well when you're working on the xy plane
Dy/dx (sin(xy)= 1/2)
Relegate degrees to physics
???
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Differentiate it 😭
Does it maje sense now?
what are you trying to differentiate tho
then this is what you get
Indeed xy=30°+360k° or 150°+360k° for integer k, but that has nothing to do with the question and theres nothing to differentiate
Sin(xy)=1/2but thats not my question- i was just wondering why differentiating xy=30 gives us a different solution
d/dx (xy=30) also gives
x dy/dx + y = 0
then dy/dx = -y/x
or alternatively $y=30/x$
ƒ(Why am. I here)=I don't Know
differentaiting that gives a different answer
Yes
I think that's the question
Yes tgats tge question
ah well
btw you're under the impression that sin(xy) = 30 gives you one curve, you get a family of infinitely many curves
d/dx (30/x) = -30/x^2 = -(30/x)/x = -y/x
Hmm not really i just gave out one of tge possible values
OH
Okay
Nice
See 😭 that was tge answer
lol sorry i didnt get it
Idk i feel like everything got so complicated
Nah its my fault i didnt deliever the question properly
Anyways ty u 3
doesn't that imply y=30 
hvm
30/x
lol
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I’m stuck on question 4
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
Are you aware how to do (AB)^-1 ?
It’s b-1 and a-1
So expressed as an equation what would it look like?
i mean this
yea!
-1 being the exponent
So given the hint in your original question, we have that
(ABC)^-1 = (XC)^-1
correct?
X is AB
But ab inverse is b-1 a-1?
Sorry about that
so to reiterate, it seems youve got this; but to make sure.
How would the RHS of this equation look like (XC)^-1 = ?
C-1 X-1 which would be c-1 b-1 a-1
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$A=[a_1,a_2,a_3,a_4], a_1,a_2,a_3,a_3$ are all 4 dim col vectors, a1,a2 are linear indep. If $b=a_1+2a_2-a_3=a_1+a_2+a_3+a_4=a_1+3a_2+a_3+2a_4$, what's the genaral solution of $Ax=b$?
nino
@untold arrow Has your question been resolved?
<@&286206848099549185> any hints?
@untold arrow Has your question been resolved?
@untold arrow Has your question been resolved?
i guess try to simplify the b = ... = ... = ... as it gives relations between the column vectors, try to find a3 and a4 in terms of a1 and a2
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how would i put these on a number line
You mean how to graph (on the number line) the solutions to those inequalities?
yeah
Ok, so first of all we need to solve them, do you agree?
@still summit Has your question been resolved?
First one is null coz mod of something is always more than or eq to 0
Try the 2nd one urself if u can
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how?
sorry u can take this
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1 + 1/4 = 5/4
then:
5/4 + x^2/4 = 1/4 * (5 + x^2)
taking a sqrt of 1/4 you'll get 1/2
and that's all
yes
oh right
dude my brain is cooked
thanks
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I am unable to figure out the two functions for this. I've tried a number of combinations and messed with it on desmos but i just don't know how to solve it; i tried working it out with my tutor but no luck, they're not sure how to find the two functions that cover all the bases
f(2)=g(2) and f'(2)=g'(2)=1.23
What a strange question
every one of my assignments has a question about Rod at the end and it's always nonsensical 😭
I found a stupid example
id be happy to hear it!
Wait they don't even have the rate of change
ugh
Here
Ughhh i forgot the y intercept
hang on
i think this works
how would you prove that it has an instantaneous rate of change of 1.23?
Pseudonium
np
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kisnar
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yes
kisnar
yes
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Hey friends. Just a question about writing maths.
Is it ok to start a series of biconditional statements with the words 'if and only if', then continue by using the symbol, like I've done in the highlighted part on the screenshot? Does that make sense?
i dont know if i can necessarily fault it but it feels iffy to me nonetheless
Hey, yeah I know what you mean. Can I ask, how would you write the same thing? Would you write "The sum above is equal to tan(x) if and only if the following equation holds: "?
Anyone else have an opinion? It's just I struggle to start off series of "if and only if" statements, and I'm trying to figure out how to do it right?
<@&286206848099549185>?
Hey. Is anybody else able to help, please? 🙂
Well, for me it's understandable, I wouldn't look for a problem here
Ok, thanks. I think it's understandable, but I'm not sure if it's technically correct
I'd say so, usage of a symbol "if and only if" after the highlighted part only tells us they're equivalent transformations
It'd clear even without them, that's not a mathematical logic let's be honest
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Difference between these and if any other options I missed
I guess the left one is the confusing one to me
I get that it’s order of operations but
Hmm I guess that’s it really
Yeah that might be why I’m confused tbh idk
You rarely see the right one
I’m doing linear algebra and calculus but for some reason my fundamental order of operations and stuff have gone to hell
For no reason lol
You will be fine
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Hello! I need some help with a probability problem.
I have a set "P" with a bunch of discrete elements. These constitute all of the items in existence.
I also have a very large dataset of multisets, each multiset containing elements from "P".
Given an existing multiset "B", and an item "I", how can I predict the probability of "I" being added as the "next" item in the multiset?
Not enough information to say anything
What information can I add for clarity?
how are objects being selected, what does it mean that we have a multiset with only some items filled out
like, I'm supposed to determine which object is next based on which objects are already in there?
which factors are relevant to the probability
@coral tide Has your question been resolved?
Okay, apologies for the vagueness. Also apologies if any of my terminologies are incorrectly used. I'm essentially doing a fun project on trying to improve deck building for trading card games (Pokemon, MTG, Yugioh, etc). I am trying to find a way to calculate optimal weights of cards in a particular deck. I am looking at using variations of decks (different distributions of card types). At a beginning of a game, we draw five random cards off the top of a deck.
So deck variations are the multiset "B", where cards are "P"
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Do i just have to write to get help ?
ok i see
we have two simple interest formulas: Ct=C0(1+i×t) and I = co x i x t why not just use the following formula: Ct=C0+I after using the formula to find the interest?
they are the same thing
so i can feel free to use what i want ?
also, this looks like chatgpt, which you should not use (because it does things like this, with unclear explanations)
what they did is start with the calculation for simple interest
add it to the initial cost, to get total cost
then rewrite total cost
ye
there was no actual computation happening.
when you ask "why not just use the following formula" the answer is they are the same formula
one just has an extra level of abstraction, by using the variable I
hahaha i see thanks my mind was blowing up thx mate and do you know the formula for the compound interest
depends, continuous or based on a period of time?
based on a period of time
i mean wdym by continuous ? like untill i take back the money ?
[C_t=C_0(1 + i)^{\frac{t}{p}}]
Astral
for t multiple of period p
alternatively you can say floor(t) instead of just t
continuous means instead of interest accruing regularly in one bunch at a time, at the end of every period
p= exemple 365 days
thx
in red we have interest that accrues every 1 unit of x
it jumps up in increasingly large steps
in blue, we have the continuous interest equivalent in rate to periodic interest
which accrues at every moment of time
oh i see thanks mate
may i ask another question i mean no relation to this
let me just write it
the probability that today will be a sunny day is 1/3 if it's sunny today the probability that it will rain tomorrow is 1/2 if it's raining today the probability that it will rain tomorrow is 2/3 : the probability of having two days of rain, for example? how do I find that out?
take it one step at a time
logically, the two components to whether it will rain on day 1 and day 2, are the odds it will rain on day 1, and the odds it will rain on day 2
hmm if this is not over the course of a very constrained number of days then I can't help you
we can't find a probability with these information?
to find the probability of having two days of rain
are you talking about these two days both being rainy, yes. If you are talking about any two days in a row of a larger sequence, I have no idea
these two days being rainy
then it's the odds of the first day being rainy, combined with the odds of the second day being rainy if the first day is rainy, no?
why are you confused
you can write it as a fraction
yes thats what i want to know how can i do that if you don't mind sir
what are the odds that the first day will be rainy?
1/3
.... no
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You have to divide n in the denominator by n^2 as well
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How do i find out the range of the logarithmic function, whats the way, the answer was option B
do you know the range of x^2 + 1?
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I tried to do this but i stuck at this part
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?
factorize it
oh gawd that handwriting
and for the other one is (x-3)(x-3)
yeah
my handwriting is bad
I think the common factor is (x-3)(x-3)
But it can't be
Beacuse the factor for 4
Is x(x-3)
Even chatgpt got it wrong
it should be 4/x(x + 3)
nvm
thats right
Oh
ok then transform the equation and reduce it
let em see
ur suppose to show that LHS is equal to RHS?
what
yea i got 2 answers
wait let me reduce the equation
ok
my method
mhm
wait how did you reduce it if its not the same factor
oh
i see
so you did the Multiplication crossover
oh yep thats what i did
but i got it wrong
oh
