#help-17

1 messages · Page 198 of 1

umbral swift
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Ok

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So i got a question

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in cos²(3x) i use chain rule right?

hybrid breach
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yes

umbral swift
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but could i do it like

hybrid breach
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ohh i know what you mean

umbral swift
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lets say cos² is f, and (3x) is g?

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So i do d/dx(cos²(3x)) which means d/dx cos² * (3x) + cos2 * d/dx (3x)

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?

hybrid breach
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you committed a sin

umbral swift
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💀

hybrid breach
#

that would work if it was cosx*3x

umbral swift
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🥲

hybrid breach
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but here it is a function inside another function

odd helm
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you might like to write $2\cos^2x = \cos2x + 1$

twin meteorBOT
#

Xetrov

umbral swift
#

i get stuck recognizing chain rule and basic derivative

hybrid breach
odd helm
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if you say so

hybrid breach
umbral swift
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ait

odd helm
#

I'm just saying that it could be a nicer derivative

hybrid breach
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he already got it

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now

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since we have this one

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how would you continue

odd helm
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...?

umbral swift
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Hmmm

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Let me think

odd helm
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whatever ig

umbral swift
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I would insert 0 instead x

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To see if i get result

hybrid breach
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ok

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try

umbral swift
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If not then again LH

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Ok

hybrid breach
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there is a way easier way

odd helm
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Tosi, I've given you a form which allows an easy evaluation of the double derivative

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why are you not using that

hybrid breach
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unnecessary as i said

odd helm
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because?

umbral swift
#

i still get 0/0

hybrid breach
#

you don need to derivate more

umbral swift
#

When inserting 0

odd helm
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you're making them do a nasty derivative

hybrid breach
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do you know what sinx/x as 0 goes to zero does?

hybrid breach
umbral swift
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ok so

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how do i continue now?

umbral swift
#

wait let me translate that real quick

hybrid breach
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it's one of the classic limits

umbral swift
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oh

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sinx/x = 1

hybrid breach
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exactly

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but yours is sin(3x) on top

umbral swift
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yes

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down its 2x

hybrid breach
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therfore what do we have to do to get that case

umbral swift
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maybe sin2x * sinx?

hybrid breach
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no

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sin(3x)/3x is still 1

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this is the trick

umbral swift
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where did you get that /3x from?

hybrid breach
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you can multiply on top and bottom by three

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and you get yours sin(3x)/3x

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which you can eliminate as you know it gives you 1

umbral swift
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well

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i didnt understand

hybrid breach
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what isn't clear

umbral swift
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english is the problem

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can you write it somewhere or?

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i have to translate all the time

hybrid breach
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also

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wait

umbral swift
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Ok

hybrid breach
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first of all you can cancel the 2 on the top with the one on the bottom

odd helm
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I owe you an apology Tosi

hybrid breach
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dw mister

odd helm
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For my lack of foresight

hybrid breach
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see it was easier

umbral swift
#

Where did bro get that -2

hybrid breach
# odd helm

(you could have done it in the first step recalling another identity)

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but let's not talk about that

hybrid breach
umbral swift
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in front of sin3x

hybrid breach
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you had it aswell

umbral swift
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i know where - came from, but 2?

hybrid breach
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you had it

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.

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from the power rule

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are you still here

umbral swift
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Yes

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Translating power rule🥲

hybrid breach
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is it clear

umbral swift
#

OOOOOOOOOOOOOOO

hybrid breach
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where are you from

umbral swift
#

now i get it

umbral swift
#

Its 1am and im stuck on this limit

hybrid breach
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real moi brat

umbral swift
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😂

hybrid breach
#

ia ne govoriu pa hrvatski

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im going by the small Russian i know

umbral swift
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odakle si ti?

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Where are you from?

hybrid breach
#

italija

umbral swift
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ohh

hybrid breach
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idk how to spell in your language

umbral swift
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l'hai detto bene

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Conosco un po' l'italiano

plain ledge
hybrid breach
#

1 am for me aswell

umbral swift
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ban this dude

hybrid breach
umbral swift
#

Croatia - Italia

plain ledge
#

Euros

hybrid breach
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oh i dont follow that

umbral swift
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@plain ledge can you solve this limit for me?

terse cipher
#

croatia guy

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can u explain me something

umbral swift
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yes

terse cipher
umbral swift
#

im listening

umbral swift
terse cipher
umbral swift
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I DONT KNOW

terse cipher
#

HAHAHAH

hybrid breach
#

wasn't Croatia good

terse cipher
umbral swift
#

Seif where you from?

plain ledge
terse cipher
#

france

umbral swift
#

ahh

hybrid breach
#

ew french

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banned

umbral swift
#

ur team is african

terse cipher
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im african xd

umbral swift
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oh💀

hybrid breach
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good good

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bro is like the football team

terse cipher
#

yes

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yes

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100%

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yo tell modric that old head ahh to retire bro xd @umbral swift

umbral swift
#

this is his last

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he is goat

hybrid breach
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is he that one blonde

umbral swift
#

yes

hybrid breach
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ye he was good

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I remember

terse cipher
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u sure its x^2?

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not just x

umbral swift
#

@terse cipher the only frencg player i know is like

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pavard

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thats it

hybrid breach
#

was it the world cup that they won

terse cipher
#

nah

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one goal wonder

umbral swift
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who?

terse cipher
#

pavard

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go check

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i think its x not x^2

umbral swift
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bro

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lets discuss footbal later

terse cipher
#

if thats the case i can solve it

umbral swift
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i need to solve this limit

terse cipher
#

yes

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the under part

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is it x^2 or x

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verify it

hybrid breach
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bro i already solved it

umbral swift
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💀

hybrid breach
#

me and the other guy

umbral swift
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got lost sorry

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Just a sec

hybrid breach
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we helped you

terse cipher
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bro

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dont throw random words croation guy xd

hybrid breach
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mon frere

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silence

terse cipher
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it needs to be -9

umbral swift
#

yes

hybrid breach
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yep

umbral swift
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what do you guys study btw?

warped cobalt
#

Amog us

terse cipher
#

do the hospital rule

wanton thunder
twin meteorBOT
#

Adversing

umbral swift
hybrid breach
umbral swift
terse cipher
#

he is sharing ads

wanton thunder
terse cipher
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ban him

hybrid breach
# wanton thunder ye

ne ho beccato uno il giorno prima della seconda prova di maturità che ho fatto pure io

terse cipher
#

his name is Advertising

wanton thunder
# umbral swift .

Computer Engineering or Software engineering, it depends by the name it goes in your country

umbral swift
#

wait i have another question

hybrid breach
#

tell

wanton thunder
terse cipher
#

not italia

wanton thunder
umbral swift
#

How did bro get rid od cos up?

wanton thunder
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I can assure it to you xd

terse cipher
umbral swift
hybrid breach
umbral swift
#

I mean up here

umbral swift
hybrid breach
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yes and cos0=1 anyways

terse cipher
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tosi where u from

hybrid breach
#

italy bro

umbral swift
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but if he inputs 0 in all xs

terse cipher
umbral swift
#

Then result is still 0/0

hybrid breach
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but the sinx/x goes to 1

hybrid breach
umbral swift
#

mechanics are easier than math ngl

terse cipher
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we are 900Km away from each other @hybrid breach

wanton thunder
umbral swift
#

yes

hybrid breach
#

I'll do pure maths next year

umbral swift
#

fr

terse cipher
hybrid breach
wanton thunder
twin meteorBOT
#

Adversing

terse cipher
#

how

umbral swift
#

bro integrals are easier than limits fr....

terse cipher
#

yes pizza

plain ledge
wanton thunder
terse cipher
#

nah a pizza

hybrid breach
terse cipher
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@hybrid breach how old r u

hybrid breach
#

18

terse cipher
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u seem old a

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af

hybrid breach
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BRO LMAO

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why

terse cipher
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yeah u sound 30

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ngl

umbral swift
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Ngl

wanton thunder
hybrid breach
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thanks ig

terse cipher
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thats a bad thing

umbral swift
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Ok not this one

wanton thunder
#

xd

hybrid breach
plain ledge
wanton thunder
umbral swift
#

using numbers in mechanics and statics - 🏝✨️

hybrid breach
wanton thunder
umbral swift
#

using numbers(letters) in math - 🥲

wanton thunder
#

what is a number?

umbral swift
#

Ofc

wanton thunder
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(classic calc 2 student)

plain ledge
umbral swift
#

never heard of those

plain ledge
#

but ig high level math never heard of that

terse cipher
#

isnt that just a double integral over a surface

wanton thunder
hybrid breach
#

you stop seeing numbers after a certain point

plain ledge
#

so am i

wanton thunder
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I've reached a level where if I even find a number in an integral I'm blessed

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like I have to thank god

umbral swift
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bro at my college physics are easier than math

plain ledge
#

just fail math class like me

terse cipher
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my little brother knows them

umbral swift
#

physics for me piece of cake ngl

terse cipher
#

at the age of 8

hybrid breach
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ah no non fai mate pura hai detto

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niente

wanton thunder
umbral swift
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i will drop out if i dont pass this math

hybrid breach
terse cipher
#

never rely on the university

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always do things abroad it

hybrid breach
#

tanto calc 1 e 2 li ho già in mano

terse cipher
#

everyone gets a degree

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what matters is what u do

umbral swift
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I hope so

terse cipher
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other than uni

umbral swift
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i mean

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engineer >>>>>>>>>>>>>>> bacc.

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aight bois its been pleasure, thanks for help

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croatia win italy 3:1, we win euros, modric retires after

terse cipher
#

bro

umbral swift
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i wish you a loving day

terse cipher
#

even if u win 99 against italia

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ull not qualify

umbral swift
#

yes we will

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bc albania gonna lose agaist spain

terse cipher
umbral swift
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@terse cipher ill see you on monday

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.close

vocal sleetBOT
#
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vocal sleetBOT
#
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limpid garnet
#

why are real numbers additionally defined as converging sequences of rational numbers?

gaunt sparrow
#

Rational numbers are nice, but they lack a fundamental property for formally defining analysis, and therefore calculus (among others).

That fundamental property is called completeness, i.e. a guarantee that whenever I have sequence whose terms get arbitrarily close to one another (this is called a Cauchy sequence), then the sequence must have a limit within the set we're investigating.

The rational numbers don't have this property. For instance, we can easily approach pi using its decimal expansion, but doing so makes the limit slip out of the rational numbers, since pi isn't rational.

This property is important, because it allows for us to define limits and functions and all the machinery you need for analysis without fear that we get nonsense out of this.

Now as to why we do it that way, it's because by considering converging sequences in Q, we construct a new set, R, that is in some way the "smallest" set that has this property while containing Q.

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Note that there are other ways of defining the real numbers, say with Dedekind cuts, or supremum properties.

junior forum
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the sequences aren't necessarily converging in Q, (for example pi) they are just cauchy

gaunt sparrow
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Yes sorry. I think the point remains mostly the same however. (edit : I've fixed my definition of completeness to reflect the more accurate one you pointed out)

vocal sleetBOT
#

@limpid garnet Has your question been resolved?

limpid garnet
#

Are you a teacher?

gaunt sparrow
#

No

limpid garnet
#

interesting

gaunt sparrow
#

Only, a massive part of my first class in real analysis was about different equivalent definitions of the real numbers, so it somewhat gets carved into your brain hahah

limpid garnet
#

please excuse me, butI have an additional question, in what order did you (for instance) study formal pure mathematics? I am familiar that there is no concrete order for studying pure math.

limpid garnet
gaunt sparrow
# limpid garnet please excuse me, butI have an additional question, in what order did you (for i...

Yes indeed. Contents of degrees vary quite considerably from curriculum to curriculum, so there is no best way, although I think most of them have the same overarching structure.
That is, most start out say, year 1, with some subjects that force you to do proofs, something like real analysis, group theory. All of that is so that you can then take more advanced classes and be able to come up with proofs on you own.

Self studying is a noble endeavor, although it is significantly harder to test your understanding of the material in a rigorous way, as you would by submitting homework and writing exams.
I personally did :
Y1 : group theory, vector calculus, ODEs, combinatorics, abstract algebra, advanced linear algebra, real analysis
Y2 : differential geometry, topology, complex analysis
Y3 : metric spaces, measure theory, fourier analysis, PDEs, numerical analysis.

Some years were more maths oriented and some less, due to my major being split maths and computer science, but I think it's pretty standard. You might want to look into curricula from other colleges, and maybe look into MIT's open courseware, since you can even get yourself some homework sheets and such.

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Sorry that was long

vocal sleetBOT
#
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limpid garnet
#

.reopen

vocal sleetBOT
#

gaunt sparrow
#

You might've seen it, but there's this video from AlephNaught where they describe a good roadmap to most content seen in an undergraduate degree in mathematics, so in case you're interested, this is the link

This video has a list of books, videos, and exercises that goes through the undergrad pure mathematics curriculum from start to finish.

REAL ANALYSIS

Book: “Understanding Analysis” by Stephen Abbott.
Videos: Lectures by Francis Su (https://www.youtube.com/playlist?list=PL0E754696F72137EC)

LINEAR ALGEBRA

Book: “Linear Algebra Done Right”...

▶ Play video
limpid garnet
#

.close

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vocal sleetBOT
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crisp zenith
#

There has to be an easier way to go about this right? does anyone see anywhere I can simplify?

crisp zenith
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let me write down the unit tangent I got

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wouldn't that be difficult to take the derivative of again to find the unit normal?

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I'm wondering if I am approaching this the wrong way

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I know if the denominator was like sqrt(3), I'd be able to factor that constant out and take the derivative of the vector with just the numerator, can I still do that?

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factoring out the denominator

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Are these equivalent?

lime gorge
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i remember when i had to do these same problems for calc3 in myopenmath

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and yes, they were this long iirc

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but if theres an easier way? i dont remember

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i remember @pale widget helped me with the TNB frame thing

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maybe theres some sort of simplification

crisp zenith
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right now im going to try factoring out the denominator and taking deriative of just the numerator and seeing if that works, I know its possible when the denominator is a constant but not sure when its a function

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like this

pale widget
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You should calculate this using N=BxT instead. That’s why it’s called a TNB frame instead of any other ordering of the letters.

crisp zenith
pale widget
#

Yes but you’ll have to google it. There are lots of formulas

crisp zenith
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ok i'll do that

pale widget
#

I think it’s r’(t)Xr’’(t) divided by the norm of that quantity off the top of my head but I don’t know

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But you should obviously plug in the value of t after you differentiate but before you calculate the cross product and the norm to make it less notationally complex

lime gorge
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@pale widget

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remember this

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prob not but still lol

pale widget
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Nope

crisp zenith
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im wondering how your tangent is much more simplified than mine

pale widget
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Anyway it’s called TNB because you can shift the letters in a circular fashion to get other formulas N=BxT and B=TxN

lime gorge
lime gorge
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and maybe its cuz i had pi instead of 5pi/6

vocal sleetBOT
#

@crisp zenith Has your question been resolved?

lime gorge
#

this is what i got upon simplifying urs @crisp zenith

vocal sleetBOT
#

@crisp zenith Has your question been resolved?

vocal sleetBOT
#

@crisp zenith Has your question been resolved?

vocal sleetBOT
#
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#
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harsh gust
#

What did I do wrong here?

vocal sleetBOT
#

@harsh gust Has your question been resolved?

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proven whale
#

.reopen

vocal sleetBOT
proven whale
#

2nd one please

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help

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please

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this is where i got

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.close

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proven whale
#

.reopen

vocal sleetBOT
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proven whale
#

nvm i got it

#

.close

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vocal sleetBOT
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vast shale
vocal sleetBOT
vast shale
#

i know henry's law

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$P_A = K_H\times S_A$

twin meteorBOT
#

Matchstick

vast shale
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i dont know how $P_{O_{2}}$ relates to $P_{N_{2}}$

twin meteorBOT
#

Matchstick

plain minnow
#

@vast shale do you know dalton's law?

vast shale
plain minnow
vast shale
#

i cannot recall any further than that

plain minnow
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where 1,2,3 are ideal gasses

vast shale
#

yes

plain minnow
#

so you can right it in a useful form

vast shale
#

do i use ideal gas equation to proceed further?

plain minnow
#

,,P_1 = X_i P_t

twin meteorBOT
#

Wither

plain minnow
#

X1 is mole fraction of gas

vast shale
#

oh okay

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but i know percentage by volume

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how do i get to mole fraction

vast shale
vocal sleetBOT
#

@vast shale Has your question been resolved?

plain minnow
#

because of avogadro's law

vast shale
#

OH YES

plain minnow
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I think you can do it now @vast shale

vast shale
#

thank you

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i understand

plain minnow
vast shale
#

.close

vocal sleetBOT
#
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vocal sleetBOT
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tulip temple
vocal sleetBOT
tulip temple
#

How can i find this using compund angles concept?

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also the answer is n-1/n+1

wanton thunder
#

you could use the tangent addition rule

$\tan{(A+B)} = \frac{\tan{A} + tan{B}}{1-\tan{A}\tan{B}}$

$\tan{(A-B)} = \frac{\tan{A} - tan{B}}{1+\tan{A}\tan{B}}$

tulip temple
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yeha i tried

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i dont quite get it

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prolly cuz im so dumb

twin meteorBOT
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Adversing

wanton thunder
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I forgot the 1 lmao

tulip temple
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can you try it please:C

wanton thunder
#

yes, now I'll try it

tulip temple
#

on skibidi

vocal sleetBOT
#

@tulip temple Has your question been resolved?

tulip temple
#

you know you are cooked when it takes 5 quattuordecillion yearsto type it out

vocal sleetBOT
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tulip temple
#

NO WAIT

wanton thunder
#

.reopen

tulip temple
#

ah yes thank gawd

wanton thunder
#

ok now starting from what I wrote you should have

$$ \frac{\tan{A} + \tan{B}}{1-\tan{A}\tan{B}} = n \cdot \frac{\tan{A} - \tan{B}}{1+\tan{A}\tan{B}} $$

Then I'd multiply both sides by $(1-\tan{A}\tan{B})(1+\tan{A}\tan{B})$ so we obtain:

$$
(\tan{A} + \tan{B})(1+\tan{A}\tan{B}) = n(\tan{A} - \tan{B})(1-\tan{A}\tan{B})
$$

Once you get here and simplify to find both $\tan{A}$ and $\tan{B}$, you should get something like this:

$$
\tan{A} + \tan{B} + \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2 = n(\tan{A} - \tan{B} - \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2)
$$

Here I'm going to use the $\sin{(2\theta)}$ identity ($\sin{(2\theta)} = 2\sin{(\theta)}\cos{(\theta)}$) for both $A$ and $B$. As a consequence of this step, you get:

$$
\frac{\sin{(2A)}}{\sin{(2B)}} = \frac{2\sin{A}\cos{A}}{2\sin{B}\cos{B}} = \frac{\sin{A}\cos{A}}{\sin{B}\cos{B}}
$$

#

jesus I hate LaTeX

#

one sec

tulip temple
#

ong

vocal sleetBOT
#
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tulip temple
#

no

vocal sleetBOT
tulip temple
#

dont steal my channel bruh

#

maybe you can ask chatgpt how to render it

twin meteorBOT
#

Adversing

wanton thunder
#

$$
\tan{A} + \tan{B} + \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2 = n(\tan{A} - \tan{B} - \tan{A}^{2}\tan{B} + \tan{A}\tan{B}^2)
$$

twin meteorBOT
#

Adversing

tulip temple
#

uhhhh

#

like what did u do

wanton thunder
tulip temple
#

after expanding the terms

#

what do you get at the end after simplifying that

wanton thunder
#

you mean in the end?

#

where you obtain

$$
\frac{\sin{(2A)}}{\sin{(2B)}} = \frac{2\sin{A}\cos{A}}{2\sin{B}\cos{B}} = \frac{\sin{A}\cos{A}}{\sin{B}\cos{B}}
$$

?

twin meteorBOT
#

Adversing

tulip temple
#

wait do you even obtain that

#

where did the n go

#

in the equation

#

what im asking is when you simplify tan(A+B) = ntan(A-B) what do you get

wanton thunder
#

you have to distribute $n$ on the right-hand side combining the terms, solving then for $\tan{A}$ and $\tan{B}$

twin meteorBOT
#

Adversing

tulip temple
#

so you cross multiply?

wanton thunder
wanton thunder
#

exactly

tulip temple
#

i get that

#

what

#

do u do after that

#

is my question

#

how do you get tan and tan b induvidually

wanton thunder
#

after that you rearrange to solve for tan(A) and tan(B)

tulip temple
#

rearrange?

#

how do i solve both from one equation

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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tender pilot
#

Hi! I was reading an article by Abraham Wald called "method of Estimating Plane Vulnerability Based on Damage of Survivor". https://apps.dtic.mil/sti/tr/pdf/ADA091073.pdf But I didn't really understand the pages 6 and 7 where he makes a hypothetical scenario in which " dummy bullets would have been used" in order to find equation (26) and use it later in the article. He sets the random variable yi as bi - ai. If I am right, yi seems to refer to the proportion of "planes that would have potentially been downed if real bullets had been used". But I have trouble understanding why making a hypothetical scenario in which dummy bullets would have been used helps to provide information about the missing planes? And why set the variable yi = bi - ai when it clearly looks equal to the random variable xi = Ni - ai (the number of planes shot down with i bullet holes is equal to the total number of planes with i bullet holes minus the number of planes with i bullet holes that survived)?

vocal sleetBOT
#

@tender pilot Has your question been resolved?

nova willow
#

to reply to your first question imagine you use pretend bullets that don't break the planes. With pretend bullets, every plane, whether hit a lot or a little, makes it back to the hangar because they don’t get broken. By comparing the number of hits with pretend bullets (where all planes come back) to the number of hits with real bullets (where some planes don’t come back), you can guess how many planes got hit but didn’t make it back. So, the pretend bullets help you understand the total number of planes that got hit by giving you a way to see what would have happened if no planes were "broken." This helps you figure out the number of planes that are missing because they were hit too much.

#

i could be wrong or shit at explaining, this is what i think

#

(note that i skimmed through it)

#

to the second question, you use yi = bi - ai because xi = Ni - ai directly represents the number of planes shot down with i bullet holes. It is a straightforward count of the planes that didn’t make it back. On the other hand, yi = bi - ai s not just a direct count of missing planes. Instead, it represents the difference between the hypothetical total hits and the actual observed hits is used to estimate the total number of planes that would have been observed if none were shot down.

#

@tender pilot

#

dont take everything i said as truth😭

#

specifically they are different because, xi directly gives you the count of missing planes but doesn’t help in estimating the total distribution of hits. yi and bi helps you estimate the total hit distribution by considering a hypothetical scenario where no planes are shot down. This helps in understanding the overall picture of plane vulnerability. xi is used to identify how many planes are missing. yi helps to understand how many planes would have been hit in a complete dataset (if no planes were shot down).

#

this is actually really interesting i'll look into it more

#

thanks

vocal sleetBOT
#

@tender pilot Has your question been resolved?

nova willow
#

well rip wrote an essay for nun😭 DM me if you have questions again @tender pilot

vocal sleetBOT
#
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fiery maple
#

Lets see question b) find area of shaded region

My question is when I integrate from -1 to 0 do I have to put a modulus?

fiery maple
#

Because in the answer scheme I had to put a modulus integration of 0 to -1 added with the integration of 0 to 3

#

To get the correct answer

#

I dont know in what condition should I put modulus in

rough spruce
#

area under curve question so ans cannot be negative

#

cus its an area

#

otherwise dont mind it

fiery maple
#

But cant i integrate from -1 to 3 tho

rough spruce
#

yeah

#

but if you get negative ans

#

then just modulus it

fiery maple
#

If I integrate from -1 to 3 I dont get the correct answer

#

It has to be modulus 0 to -1 added with 0 to 3

rough spruce
#

the b one ?

fiery maple
#

yeah

rough spruce
#

oh yeah

rough spruce
#

and if the ans is negative then just modulus it

fiery maple
#

Thing is idk when should i split when should I not split them

fiery maple
#

So does that mean the area from 0 to 1 i have to put a modulus for question a)

vocal sleetBOT
#

@fiery maple Has your question been resolved?

fiery maple
#

<@&286206848099549185>

fiery maple
#

For a)

#

Find the area of the shaded region

#

Do i have to put modulus if the area is below the x-axis?

somber yew
#

Yes, split the integral and apply absolute value to each negative outcome

sudden compass
fiery maple
#

ah right nvm i got it

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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vagrant sable
#

Sin(xy)= 1/2

vocal sleetBOT
vagrant sable
#

Dy/dx =?

#

With implicit differentiation

#

We grt -y/x

#

With xy=30

scenic ravine
#

wait, what

#

-y/x

#

where did that come from

#

ah

#

I see

#

continue

vagrant sable
#

How are these equavilent

#

Or… however you spell that word

vagrant sable
vagrant sable
#

Wait

#

This is 1/2

#

Sin(xy)=1/2

scenic ravine
#

so (xy)=?

vagrant sable
scenic ravine
#

oh, you want to differentiate it

vagrant sable
vagrant sable
brittle cipher
#

sin(anything real) is always between -1 and 1, never 30

scenic ravine
#

ok $cos(xy)(y + \frac{xdy}{dx})=0$

twin meteorBOT
#

ƒ(Why am. I here)=I don't Know

vagrant sable
scenic ravine
#

can you do it from here?

vagrant sable
#

Isnt it -y/x

scenic ravine
#

oh

#

sorry

#

yes

#

it is

vagrant sable
#

Aha

#

So why is it -30x^-2

#

With xy=30

scenic ravine
#

what is $-30x^{-2}$

twin meteorBOT
#

ƒ(Why am. I here)=I don't Know

vagrant sable
#

XY=30

scenic ravine
#

yes

vagrant sable
#

Y=30/x

#

Dy/dx

vagrant sable
scenic ravine
#

hmm

#

I'm not too sure, sorry

vagrant sable
#

👍

#

Its okay

scenic ravine
#

,w differentiate sin(xy)=1/2 with respect to x

scenic ravine
twin meteorBOT
#

ƒ(Why am. I here)=I don't Know

scenic ravine
#

I could be wrong though

scenic ravine
#

ping helpers in 5 minutes

vagrant sable
#

I will

#

<@&286206848099549185>

#

I call upon you

#

RISE

#

RISE GREAT HELPERS RISE

#

Yall should pay me for this intro

viral copper
#

something's not right here

#

can we have the original question though

vagrant sable
digital lake
#

w

viral copper
#

Is this paraphrasing or exactly what you've been given

vagrant sable
#

Implicit differentiation says -y/x

#

Xy= 30 says otgerwise

viral copper
#

what

vagrant sable
scenic ravine
drifting terrace
#

youre trying to do what?

viral copper
#

[ \left ( x\dv{y}{x} + y\right )\cos(xy) = 0 ]

drifting terrace
#

sin(xy)=1/2, find dy/dx for when xy=30?

twin meteorBOT
#

Bob l'éponge

viral copper
#

Okay I get what you mean now

vagrant sable
viral copper
#

no

vagrant sable
#

Why

drifting terrace
#

also thats in degrees

vagrant sable
viral copper
#

assuming you're in degrees

#

right uh

#

what is your question

vagrant sable
drifting terrace
#

so are you just trying to solve for dy/dx

#

because yes its just -y/x

vagrant sable
#

Or- why doesnt eork eith degrees

viral copper
#

what has two different answers

#

It does it's just that degrees don't work that well when you're working on the xy plane

vagrant sable
viral copper
#

Relegate degrees to physics

viral copper
vagrant sable
#

I fixed it

#

I FIxED It

viral copper
#

it still doesn't make sense

#

!xy

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

drifting terrace
#

not sure why youre trying ro solve sin(xy)=1/2

#

it has nothing to do with dy/dx

vagrant sable
#

Does it maje sense now?

drifting terrace
#

what are you trying to differentiate tho

viral copper
drifting terrace
#

Indeed xy=30°+360k° or 150°+360k° for integer k, but that has nothing to do with the question and theres nothing to differentiate

vagrant sable
drifting terrace
scenic ravine
#

or alternatively $y=30/x$

twin meteorBOT
#

ƒ(Why am. I here)=I don't Know

scenic ravine
#

differentaiting that gives a different answer

vagrant sable
scenic ravine
#

I think that's the question

vagrant sable
#

Yes tgats tge question

drifting terrace
#

ah well

viral copper
#

btw you're under the impression that sin(xy) = 30 gives you one curve, you get a family of infinitely many curves

drifting terrace
#

d/dx (30/x) = -30/x^2 = -(30/x)/x = -y/x

vagrant sable
vagrant sable
#

Okay

#

Nice

#

See 😭 that was tge answer

drifting terrace
#

lol sorry i didnt get it

vagrant sable
#

Idk i feel like everything got so complicated

vagrant sable
#

Anyways ty u 3

scenic ravine
#

hvm

scenic ravine
#

*nvm

#

yeah

drifting terrace
#

lol

scenic ravine
#

got it

#

sorry

vagrant sable
#

.close

vocal sleetBOT
#
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vocal sleetBOT
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bold scarab
#

I’m stuck on question 4

vocal sleetBOT
tawny hollow
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
bold scarab
#

1

tawny hollow
#

Are you aware how to do (AB)^-1 ?

bold scarab
#

It’s b-1 and a-1

tawny hollow
#

So expressed as an equation what would it look like?

bold scarab
#

B-1A-1C-1

#

I think

#

But the c is at the back?

tawny hollow
bold scarab
#

Oh

#

Uh that equals B-1 A-1

tawny hollow
#

yea!

bold scarab
#

-1 being the exponent

tawny hollow
#

So given the hint in your original question, we have that

#

(ABC)^-1 = (XC)^-1

#

correct?

bold scarab
#

Yea

#

OH

#

and then it would be c-1 and x-1

#

X being ba

tawny hollow
#

X is AB

bold scarab
#

But ab inverse is b-1 a-1?

tawny hollow
#

yea!

#

i guess thats what you meant, but it wasnt clear

bold scarab
#

Sorry about that

tawny hollow
#

so to reiterate, it seems youve got this; but to make sure.

How would the RHS of this equation look like (XC)^-1 = ?

bold scarab
#

C-1 X-1 which would be c-1 b-1 a-1

tawny hollow
#

yup!

#

hope that helped

bold scarab
#

That helped a lot Thankyou!!

#

.close

vocal sleetBOT
#
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wary mantle
vocal sleetBOT
wary mantle
#

Where did I mess up? WA gives something different

signal blaze
#

not x²+16x+16

white acorn
#

yup 8x not 16x

wary mantle
#

Thanks

#

.close

vocal sleetBOT
#
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untold arrow
#

$A=[a_1,a_2,a_3,a_4], a_1,a_2,a_3,a_3$ are all 4 dim col vectors, a1,a2 are linear indep. If $b=a_1+2a_2-a_3=a_1+a_2+a_3+a_4=a_1+3a_2+a_3+2a_4$, what's the genaral solution of $Ax=b$?

twin meteorBOT
vocal sleetBOT
#

@untold arrow Has your question been resolved?

untold arrow
#

<@&286206848099549185> any hints?

vocal sleetBOT
#

@untold arrow Has your question been resolved?

vocal sleetBOT
#

@untold arrow Has your question been resolved?

normal heath
vocal sleetBOT
#
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still summit
vocal sleetBOT
still summit
#

how would i put these on a number line

civic otter
#

You mean how to graph (on the number line) the solutions to those inequalities?

still summit
#

yeah

civic otter
#

Ok, so first of all we need to solve them, do you agree?

vocal sleetBOT
#

@still summit Has your question been resolved?

vast shale
# still summit

First one is null coz mod of something is always more than or eq to 0

#

Try the 2nd one urself if u can

vocal sleetBOT
#

@still summit Has your question been resolved?

#
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frail dew
wheat garnet
#

sorry u can take this

vocal sleetBOT
#
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frail dew
#

wait wha

shadow raft
#

channel has closed

#

go to a new one

whole oasis
#

1 + 1/4 = 5/4
then:
5/4 + x^2/4 = 1/4 * (5 + x^2)

#

taking a sqrt of 1/4 you'll get 1/2

#

and that's all

frail dew
#

but the last part

#

how did they derive sqrt(5+x^2)

whole oasis
#

well

#

you're integrating over dy

frail dew
#

yes

whole oasis
#

then sqrt(5+x^2) is a constant

#

integral of a constant is y then bounds 2x - 0 = 2x

frail dew
#

oh right

#

dude my brain is cooked

#

bleakkekw thanks

#

i guess this channel is already closed so no need to close it...

vocal sleetBOT
#
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waxen bough
vocal sleetBOT
waxen bough
#

I am unable to figure out the two functions for this. I've tried a number of combinations and messed with it on desmos but i just don't know how to solve it; i tried working it out with my tutor but no luck, they're not sure how to find the two functions that cover all the bases

shadow raft
#

f(2)=g(2) and f'(2)=g'(2)=1.23

atomic forum
#

What a strange question

waxen bough
#

every one of my assignments has a question about Rod at the end and it's always nonsensical 😭

waxen bough
#

id be happy to hear it!

atomic forum
#

Wait they don't even have the rate of change

#

ugh

#

Here

#

Ughhh i forgot the y intercept

#

hang on

#

i think this works

waxen bough
#

how would you prove that it has an instantaneous rate of change of 1.23?

atomic forum
#

Differentiate

#

Evaluate at $x = 2$

twin meteorBOT
#

Pseudonium

waxen bough
#

oh okay!

#

thank you for the help btw :-)

atomic forum
#

np

waxen bough
#

.close

vocal sleetBOT
#
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vocal sleetBOT
twin meteorBOT
#

kisnar
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

#

kisnar

#

kisnar
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

#

kisnar
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

#

kisnar

#

kisnar

#

kisnar

hard atlas
#

yes

twin meteorBOT
#

kisnar

hard atlas
#

yes

vocal sleetBOT
#
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mental wedge
#

Hey friends. Just a question about writing maths.

Is it ok to start a series of biconditional statements with the words 'if and only if', then continue by using the symbol, like I've done in the highlighted part on the screenshot? Does that make sense?

pale perch
#

i dont know if i can necessarily fault it but it feels iffy to me nonetheless

mental wedge
#

Anyone else have an opinion? It's just I struggle to start off series of "if and only if" statements, and I'm trying to figure out how to do it right?

#

<@&286206848099549185>?

#

Hey. Is anybody else able to help, please? 🙂

whole oasis
#

Well, for me it's understandable, I wouldn't look for a problem here

mental wedge
whole oasis
#

I'd say so, usage of a symbol "if and only if" after the highlighted part only tells us they're equivalent transformations

#

It'd clear even without them, that's not a mathematical logic let's be honest

mental wedge
#

.close

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#
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desert edge
#

Difference between these and if any other options I missed

formal pond
#

left most and right most are the same thing , -4

#

middle is 4

desert edge
#

I guess the left one is the confusing one to me

#

I get that it’s order of operations but

#

Hmm I guess that’s it really

formal pond
#

yea

#

unfortuantly usually people use left the most as its the easiest to write

desert edge
#

Yeah that might be why I’m confused tbh idk

formal pond
#

You rarely see the right one

desert edge
#

I’m doing linear algebra and calculus but for some reason my fundamental order of operations and stuff have gone to hell

#

For no reason lol

formal pond
#

You will be fine

desert edge
#

It’s like I’m overthinking and confusing myself unnecessarily

#

Thank you

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
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coral tide
#

Hello! I need some help with a probability problem.
I have a set "P" with a bunch of discrete elements. These constitute all of the items in existence.

I also have a very large dataset of multisets, each multiset containing elements from "P".

Given an existing multiset "B", and an item "I", how can I predict the probability of "I" being added as the "next" item in the multiset?

half imp
#

Not enough information to say anything

coral tide
#

What information can I add for clarity?

half imp
#

how are objects being selected, what does it mean that we have a multiset with only some items filled out

#

like, I'm supposed to determine which object is next based on which objects are already in there?

#

which factors are relevant to the probability

vocal sleetBOT
#

@coral tide Has your question been resolved?

coral tide
#

Okay, apologies for the vagueness. Also apologies if any of my terminologies are incorrectly used. I'm essentially doing a fun project on trying to improve deck building for trading card games (Pokemon, MTG, Yugioh, etc). I am trying to find a way to calculate optimal weights of cards in a particular deck. I am looking at using variations of decks (different distributions of card types). At a beginning of a game, we draw five random cards off the top of a deck.
So deck variations are the multiset "B", where cards are "P"

vocal sleetBOT
#
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half imp
#

.reopen

vocal sleetBOT
#

half imp
#

click the X next time bot asks if the question is resolved or it'll close again

vocal sleetBOT
#

@coral tide Has your question been resolved?

vocal sleetBOT
#
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stuck hawk
#

Do i just have to write to get help ?

vocal sleetBOT
stuck hawk
#

ok i see

#

we have two simple interest formulas: Ct=C0(1+i×t) and I = co x i x t why not just use the following formula: Ct=C0+I after using the formula to find the interest?

stuck hawk
#

so i can feel free to use what i want ?

weary sentinel
#

also, this looks like chatgpt, which you should not use (because it does things like this, with unclear explanations)

#

what they did is start with the calculation for simple interest

#

add it to the initial cost, to get total cost

#

then rewrite total cost

stuck hawk
#

ye

weary sentinel
#

there was no actual computation happening.

stuck hawk
#

thats what i used to do

#

i mean the method is not wrong right ?

weary sentinel
#

when you ask "why not just use the following formula" the answer is they are the same formula

#

one just has an extra level of abstraction, by using the variable I

stuck hawk
#

hahaha i see thanks my mind was blowing up thx mate and do you know the formula for the compound interest

weary sentinel
#

depends, continuous or based on a period of time?

stuck hawk
#

based on a period of time

#

i mean wdym by continuous ? like untill i take back the money ?

weary sentinel
#

[C_t=C_0(1 + i)^{\frac{t}{p}}]

twin meteorBOT
#

Astral

weary sentinel
#

for t multiple of period p

#

alternatively you can say floor(t) instead of just t

#

continuous means instead of interest accruing regularly in one bunch at a time, at the end of every period

stuck hawk
#

p= exemple 365 days

weary sentinel
#

it increases at every moment

#

lemme graph the difference

stuck hawk
#

thx

weary sentinel
#

in red we have interest that accrues every 1 unit of x

#

it jumps up in increasingly large steps

#

in blue, we have the continuous interest equivalent in rate to periodic interest

#

which accrues at every moment of time

stuck hawk
#

oh i see thanks mate

#

may i ask another question i mean no relation to this

#

let me just write it

#

the probability that today will be a sunny day is 1/3 if it's sunny today the probability that it will rain tomorrow is 1/2 if it's raining today the probability that it will rain tomorrow is 2/3 : the probability of having two days of rain, for example? how do I find that out?

weary sentinel
#

take it one step at a time

#

logically, the two components to whether it will rain on day 1 and day 2, are the odds it will rain on day 1, and the odds it will rain on day 2

#

hmm if this is not over the course of a very constrained number of days then I can't help you

stuck hawk
#

to find the probability of having two days of rain

weary sentinel
#

are you talking about these two days both being rainy, yes. If you are talking about any two days in a row of a larger sequence, I have no idea

weary sentinel
#

then it's the odds of the first day being rainy, combined with the odds of the second day being rainy if the first day is rainy, no?

#

why are you confused

stuck hawk
#

I don't need a percentage ? of luck

#

like the % odds

#

that happen

weary sentinel
#

you can write it as a fraction

stuck hawk
#

yes thats what i want to know how can i do that if you don't mind sir

weary sentinel
#

what are the odds that the first day will be rainy?

stuck hawk
#

1/3

weary sentinel
#

.... no

stuck hawk
#

0%

#

?

vocal sleetBOT
#

@stuck hawk Has your question been resolved?

vocal sleetBOT
#
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vocal sleetBOT
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vocal sleetBOT
safe wharf
#

You have to divide n in the denominator by n^2 as well

vocal sleetBOT
#
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vocal sleetBOT
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shrewd jacinth
#

How do i find out the range of the logarithmic function, whats the way, the answer was option B

surreal basin
vocal sleetBOT
#

@shrewd jacinth Has your question been resolved?

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wanton shuttle
#

I tried to do this but i stuck at this part

wanton shuttle
#

Its not the same factor

#

And I don't have a clue how can I do this

shrewd jacinth
#

.reopen

wanton shuttle
#

?

digital lake
#

factorize it

wanton shuttle
#

I did

#

But its can't be

#

Its x(x-3)

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for 4

digital lake
#

oh gawd that handwriting

wanton shuttle
#

and for the other one is (x-3)(x-3)

#

yeah

#

my handwriting is bad

#

I think the common factor is (x-3)(x-3)

#

But it can't be

#

Beacuse the factor for 4

#

Is x(x-3)

#

Even chatgpt got it wrong

digital lake
#

it should be 4/x(x + 3)

wanton shuttle
#

yeah i know

#

thats what i said

#

oh

#

+3

digital lake
#

nvm

wanton shuttle
#

Howe

#

How

digital lake
#

thats right

wanton shuttle
#

Oh

digital lake
#

ok then transform the equation and reduce it

wanton shuttle
#

but i can't reduce it

#

i don't have a common factor

digital lake
#

let em see

undone aurora
#

ur suppose to show that LHS is equal to RHS?

digital lake
#

what

wanton shuttle
#

i need to get two x

#

like x1 and x2

digital lake
#

yea i got 2 answers

wanton shuttle
#

its a quadratic equation

#

how

digital lake
#

wait let me reduce the equation

wanton shuttle
#

ok

digital lake
#

my method

wanton shuttle
#

mhm

wanton shuttle
#

oh

#

i see

digital lake
#

epic

#

then just solve that equation

wanton shuttle
#

so you did the Multiplication crossover

#

oh yep thats what i did

#

but i got it wrong

digital lake
#

oh

wanton shuttle
#

let me check if you are right

#

its should be x = 3, x= -4

#

mhm

#

nope

#

3x-20