#help-17

1 messages · Page 191 of 1

uncut tendon
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Sorry if I'm being slow

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Okay here is how far I've gotten without not knowing what to do next.

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Can you see it?

tranquil trellis
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yes

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it looks like you just copied down the vector field given 😵

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let's start from here

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I'm just breaking down the vector field $\vec F$ into $L \ dx + M \ dy$

twin meteorBOT
tranquil trellis
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Since that's the setup for Green's Theorem

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And then I evaluate these partial derivatives to get what's on the right hand side under the double integral

uncut tendon
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Okay thanks! I'll check if it works in a few minutes!

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What is dx and dy? Do we solve in relation to t?

tranquil trellis
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we're just separating the vector field $\mathbf{F}(x,y) = (e^{-x}+y^2, e^{-y}+x^2)$.

twin meteorBOT
tranquil trellis
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the left one is dx, the right one is dy

uncut tendon
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Okay!

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What are the bounds?

tranquil trellis
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that'll help you see the bounds of the double integral

uncut tendon
tranquil trellis
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yes

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so what are the bounds

uncut tendon
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So for dy it is probably 0 to cos(x) and for dx it is probably -pi/2 to pi/2 right?

uncut tendon
uncut tendon
tranquil trellis
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the integral is a bit of a pain to solve but it evaluates nicely in the end

uncut tendon
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Okay thanks!

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Now I got it, thanks for the help!

tranquil trellis
vocal sleetBOT
#

@uncut tendon Has your question been resolved?

vocal sleetBOT
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vast shale
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help

vocal sleetBOT
vast shale
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my original thought would be to say that let (xn) be some sequence of an in (an). Then (xn) is either a permutation, subsequence and thus must converge to a

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someone told me that was wrong and to split it into two cases: when image of (xn) is infinite and when it's finite

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when it's finite, assume the limit of xn isn't in the set and then say something about two epsilon balls

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<@&286206848099549185>

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barren bay
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This kind of question can be solved by factoring right? You only use the quadratic formula when there is an equal sign present ( someone pls confirm this)

tawny nacelle
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you can factor yes

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the quadratic formula is used to find roots of a quadratic polynomial, but it can technically be used here too

vestal heart
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you can use quad formula

tawny nacelle
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there's nothing wrong with using it

vestal heart
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find critical values and do a numberline test

tawny nacelle
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for this particular problem though, you can just factor

barren bay
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🙏 thanks ygs

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barren bay
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🙏 I’ve lowk been asking the same question but I js wanna make sure: for question 1, using the quadratic formula would be easier bc the = makes it easier to verify by having a variable on both sides. But you could still use the X factor method to find x values
For question 2, factoring using the x method would be easier, but there’s nothing wrong with using the quadratic formula
Let me know if my question is confusing 🙏

vocal sleetBOT
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prisma dragon
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bro that's $$ (x+3).(x-5)<= 0

vocal sleetBOT
prisma dragon
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which ultimately led to (x+3).<=0 and (x-5) <=0.. now it seems to be solved

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prisma dragon
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oops.

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tnkx

vocal sleetBOT
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finite trout
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I am getting the wrong answer for (b)

vocal sleetBOT
finite trout
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sending my working in 1 min

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the correct answer is 48 but i am getting 62 over and over again

prisma dragon
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bro that 2a is in addition on the RHS how can you cancel 2s by that 2

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did you get it ?

vocal sleetBOT
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@finite trout Has your question been resolved?

prisma dragon
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just for simplification... don't move the variables at first.. just put values in first eqn then after try to solve

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and find value for a

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if you didn't get it show me your work.

vocal sleetBOT
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@finite trout Has your question been resolved?

vocal sleetBOT
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fallow igloo
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If a man had walked 2 km/h faster , he would have taken 40 minutes less to walk 5 km.
find the walking speed.

fallow igloo
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i got an equation which has no real roots

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help pls

exotic dagger
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I think you should convert minutes into hours

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40 minutes = 2/3 of an hour

fallow igloo
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but would that really matter

exotic dagger
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yes

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try again you will get the answer

fallow igloo
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ok let me try

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yep got it

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speed is 3

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@exotic dagger thx

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exotic dagger
vocal sleetBOT
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solemn crystal
vocal sleetBOT
solemn crystal
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the answer is C

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but i have no idea how

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its just logic btw, x:y dont have any special meaning i think.

rugged orchid
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Well

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Looks like the angle between the minute and hour hand

subtle helm
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420 feelshighman

solemn crystal
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thanks

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also struggling to figure out the logic in this one

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I tried to check number of letters between each pair, but i dont see any pattern

outer warren
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check for each respective position

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hmm

solemn crystal
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ah i got the answer

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i kinda googled it

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pretty odd tho, wouldnt have gotten it on my own

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anyways solution if anyone was curious

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.close

vocal sleetBOT
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harsh gust
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$$\int \frac{cos(\sqrt{t})}{\sqrt{t}} $$

vocal sleetBOT
twin meteorBOT
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Nerdy_Coder

harsh gust
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How to find this?

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My book sugggested $$ u = \sqrt(t) $$

twin meteorBOT
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Nerdy_Coder

harsh gust
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but when I tried it I got

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$$ \int cos(u) u^{-5/2} $$

twin meteorBOT
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Nerdy_Coder

fallow wyvern
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I know how to solve the Fibonacci sequence!

quartz beacon
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du = 1/2*t^(-1/2) dt

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2du = t^(-1/2) dt

harsh gust
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Uhh...hold on...

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Why 1/2t

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no makes sense

quartz beacon
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the u = sqrt(t) is right

harsh gust
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fine

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uhh

quartz beacon
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and then you derive it using chain rule

harsh gust
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What's dx

quartz beacon
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there’s no dx if you’re using t

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then it’s dt

twin meteorBOT
harsh gust
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That isn't much better

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now what?

vestal heart
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???

harsh gust
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Do I do u sub twice?

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Is that what I'm expected to do?

vestal heart
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dt=2sqrt(t) du

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=2udu

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then the u cancels nicely

harsh gust
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how?

vestal heart
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u=sqrt(t)

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du/dt = 1/2sqrt(t)

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dt=2sqrt(t)du=2udu

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change dt to du

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you get 2ucos(u)/u

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=2cos(u)

vast shale
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What's the derivative of √t?

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@harsh gust

vestal heart
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1/2√t

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??/

vast shale
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Let him answer

harsh gust
vast shale
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Correct

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Now if you let u = √t

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du/dt is 1/(2√t)

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You can also look like this

vestal heart
vast shale
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$\int cos(u) du = \int cos(u) \frac{du}{dt}dt$

twin meteorBOT
vast shale
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And u = √t here

vast shale
# twin meteor **iuck**

Warning though you can treat du/dt as a fraction but technically it isn't

It's not "cancelling the dt" here to be specific

harsh gust
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Where did the other u go?

vast shale
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What u?

harsh gust
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2u?

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cos(u)/u

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that is what the substiution gives

vast shale
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Just put u=√t in RHS

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And you'll get the question

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du/dt is 1/(2√t)

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Basically if I substitute u=√t, I'll get the LHS

harsh gust
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So wait I was supposed to subtitute u for dt?

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...you can do that?

vast shale
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Substitute √t as u

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You can if it works

harsh gust
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Wait u substitution is supposed to be applied to dt?

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or du?

vast shale
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Don't memorize like that

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We're simply changing the variables here, from √t to u

vast shale
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To perform the u sub

harsh gust
vast shale
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Of course there are some parts that may not feel intuitive

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But practicing more problems will help

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Like for example at this stage one cannot show (du/dt)dt = du (requires advanced math)

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We just do this in u sub

vast shale
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What I am saying is

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Practice more

harsh gust
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I have been practicing and uhh couldn't do this problem

vast shale
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Let's do a simpler one then

harsh gust
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The stewart one?

harsh gust
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I did them actually

vast shale
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I never did Stewart sorry

harsh gust
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Then I just failed badly

vast shale
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Happens

harsh gust
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I have lost my confidence to teach myself math but I have too

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I suck at it and need to learn it for my degree

vast shale
twin meteorBOT
harsh gust
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It doesn't

vast shale
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So at what part are you getting confused

harsh gust
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u substition applying to a non-integral

vast shale
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"non-integral"?

harsh gust
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Well nothing actually lose of confidence to learning math

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I tried practice and uhh not going anywhere

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idk what to do

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but I need to study

vast shale
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Take a small break then

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An hour break

harsh gust
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practice makes perfect...is clearly not working

vast shale
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Take a walk outside

vast shale
harsh gust
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tried that already

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Issue is...

vast shale
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Not a short term one

harsh gust
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I suck at this

vast shale
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I did as well

harsh gust
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Should I just give up on learning from my textbook?

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or just ask for help on any problems I cannot do?

vast shale
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Not give up for sure, but you can try other textbooks as well

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Of course you can ask for help here

harsh gust
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I understand the concepts at a basic level at least

hushed pewter
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textbook is best resource most times. Doing exercises is next step. Asking questions is next step after that. Repeat

vast shale
harsh gust
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As with coding I can just pick up a book read it go thru it read the reference gitgud

hushed pewter
vast shale
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It's best when done like that, of course you can self study math as well

harsh gust
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...math I tried that only works for basic algebra

harsh gust
hushed pewter
harsh gust
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Are there those that can?

hushed pewter
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I self study

harsh gust
hushed pewter
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But I love math

vast shale
hushed pewter
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And I'm good at it.

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And I'm very patient

harsh gust
harsh gust
vast shale
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as I said, I never did Stewart sorry

hushed pewter
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Reading about topology. I'm at chapter 12.

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Slow, but I'm always going forward

vast shale
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Nor did I self study calculus as well

harsh gust
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Did you teach yourself real analysis?

vast shale
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Because I didn't had time due to my entrance exams

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I didn't even do real analysis yet

hushed pewter
vast shale
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Don't pressurize yourself that much, there is time pressure for sure but don't get too anxious

vast shale
harsh gust
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...Should I do that?

vast shale
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By the end of the day, visit this problem again

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Ofc you can

harsh gust
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I keep getting stuck and losing all confidence

vast shale
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Don't leave it, skip it for now

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Patience and practice is the key

harsh gust
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Should go back and study algebra?

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I uhh forget analytic geometry

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and uhh made mistakes with equations all the time

vast shale
harsh gust
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I lost all confidence in myself to learn math

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Is this jsut an excuse?

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To do what?

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Guess have fun and but I want to study

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uhh

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....

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When I get stuck do I just go to someone else for help

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because videos and other resources have stopped working?

vast shale
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It's about understanding the concept. The book/resources can excellently show the concept and its working, but it also depends upon the person as well to understand it

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Sometimes the person can have a brainfog/get tired to digest more concepts

vast shale
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That's why at times like this I take a small break, or skip the problem to revisit them at the end of the day

harsh gust
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So...just ask for help right?

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Because it seems I am no longer able to self-study math

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as...I have hit the wall that people in other fields say people who self-teach hit...

vast shale
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Try the problem a few times yourself then ask. Try all the possible methods you have learned before asking

harsh gust
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Wait maybe that's my answer?

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Yea I should stop trying to just teach myself

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I should be asking for help all the time until i can self-stufy again and repeat...

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I don't like this idea but this is likely the only way

vast shale
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Try to join a study group as well if possible and if it works out for you

harsh gust
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Study group

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does that happen in colleges?

vast shale
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A friend circle can be a study group as well

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Need not to be "official"

harsh gust
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...hmm well my college does have a tutoring system

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I should set up 2 meetings every week if possible

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right?

vocal sleetBOT
#

@harsh gust Has your question been resolved?

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@jolly wadi Has your question been resolved?

vocal sleetBOT
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@jolly wadi Has your question been resolved?

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@jolly wadi Has your question been resolved?

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brazen sluice
#

does anyone know how to graph this in one equation?

scenic ravine
#

probably $-20e^{\frac{-x^2}{2}}$

twin meteorBOT
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ƒ(Why am. I here)=I don't Know

scenic ravine
#

,w graph $-20e^{\frac{-x^2}{2}}$

twin meteorBOT
scenic ravine
brazen sluice
#

I want to be able to control like

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the minimum of this

scenic ravine
#

then $ne^\frac{-x^2}{a}$

twin meteorBOT
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ƒ(Why am. I here)=I don't Know

scenic ravine
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where n is the amplitude of the minima

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and a is a constant of your choice

brazen sluice
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how could i make this one function

vocal sleetBOT
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@brazen sluice Has your question been resolved?

brazen sluice
#

<@&286206848099549185>

brazen sluice
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@brazen sluice Has your question been resolved?

vocal sleetBOT
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ancient kettle
#

hello! can someone help me w this?

vocal sleetBOT
wary mantle
ancient kettle
#

but idk what g(x) is

vast shale
#

Let g(x) = t, you could get f(t)

wary mantle
#

As it is

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$f(g(x)) = g(x)^2 - 4 \overset ! = 4x^2 - 8x$

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Right?

ancient kettle
#

oh ok

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yep

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thanks!

wary mantle
#

And this has to be what they gave as the first expression

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4x^2 - 8x

twin meteorBOT
wary mantle
#

Now solve for g(x)

ancient kettle
#

thanks!

vocal sleetBOT
#

@ancient kettle Has your question been resolved?

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viscid sky
#

Got this question here asking about critical points. The options are : there are no critical points and the others are what kind of critical point is (0, 0). My intuition is it is a saddle point, but I'm not sure of the best way to verify my intuition.
I don't need to get to deep into analytical methods since it is a MCQ

hardy vector
#

Then you will need determine when grad f is the zero vector

viscid sky
#

Those are done, it is the point (0,0)

hardy vector
#

Followed by that you need to know the theorem related to the hessian matrix

viscid sky
#

Ok, I was trying to avoid doing using the hessian matrix

viscid sky
hardy vector
#

maybe

vocal sleetBOT
#

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brave spade
#

(A) will arrive in a restaurant in X time and (B) will arrive in Z time. The joint probability density function of 𝑋 and 𝑍 is constant over the set of values 𝑆. Determine the joint probability density function of 𝑋 and 𝑍 and find the marginal probability density functions of 𝑋 and 𝑍.

brave spade
#

something isnt right

#

<@&286206848099549185>

analog galleon
#

im not a helper but 1 question why is the integral from 0 to x?

brave spade
#

bro really i dont understand this, in my course this is how in the lectures i have seen this

analog galleon
#

it doesnt work like that

brave spade
#

the fz(z) looks fine to you?

analog galleon
#

nope 😭

brave spade
#

how would you do it

analog galleon
#

im a bad explainer but i'll try

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do you know the fundamental theorem

brave spade
#

is fz(z)=integral from 0 to 2 of 1/2?

brave spade
analog galleon
#

are you questioning about a multivariable

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like 3 dimensional?

brave spade
#

what do u mean

analog galleon
#

thats all i needed to hear lol

brave spade
#

how can i find fx(x) and fz(z)?

analog galleon
#

first of all its called f(x) only thats it

brave spade
#

the proffesor write it fx(x)

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lol

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its a probability problem

analog galleon
#

what grade are you?

brave spade
#

uni first year

analog galleon
#

hmm then its probably multivariable

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i cant help you with that its hard

brave spade
#

thank u for your time

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<@&286206848099549185>

vocal sleetBOT
#

@brave spade Has your question been resolved?

brave spade
#

.close

vocal sleetBOT
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abstract pumice
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manic lance
#

can someone explain why when calculating pi you need to make sure the following statement needs to be true:
x^2 + y^2 <= 1.0

manic lance
#

at least for this quarter example

left sparrow
peak matrix
# manic lance can someone explain why when calculating pi you need to make sure the following ...

Point (x, y) is inside of a circle (centered at origin) iff the distance from origin to the point (x, y) is less than or equal to the radius (in this case 1). The picture below shows that the formula for distance of point (x,y) from origin is sqrt(x^2 + y^2) (pythagorean theorem was applied there). So we are looking for points where distance from origin <= 1, that is sqrt(x^2 + y^2) <= 1. But if we square both sides we get just x^2 + y^2 <= 1, which is the condition

manic lance
#

@left sparrow @peak matrix thank you so much guys, I understand now

#

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ocean fiber
#

what does it mean by is a perfect square

vocal sleetBOT
ocean fiber
#

like does the formula equal like a square??

tawny nacelle
#

if a quadratic is a perfect square, that means it has a double root

#

a perfect square is a positive number that is the square of another number

#

for example, 4 is a perfect square because 2^2 = 4

#

and 64 is a perfect square because 8^2 = 64

ocean fiber
#

ohh

tawny nacelle
#

hello Moosey

ocean fiber
#

oh yea so only 1 solution

#

ok

#

.close

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#
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lucid bane
#

you can also think of it as ax^2+bx+c=(x+k)^2

ocean fiber
#

thanks

tawny nacelle
hushed pewter
vocal sleetBOT
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trim cobalt
#

I'm doing some exercise with interest and stumbled with this problem. I did two ways to solve it which is a shortcut i just found out which is the correct answer and a traditional one. For the shortcut one i just simply divide the non zero and then i will move the decimal place of the answer(0.6) based on how many zero is left so I got 0.06. On my second attempt, I added 2 zeros because you can't divide 3 with 50 and then I got the same 0.6 as answer and I think I messed up with decimal places on my 2nd attempt.

vocal sleetBOT
#

@trim cobalt Has your question been resolved?

trim cobalt
#

<@&286206848099549185>

#

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faint wigeon
#

Can someone please show me how to do this, the function is “y = x^2 + x - 6”

faint wigeon
#

I’m mainly struggling with finding the difference between task 2 and task 3 and also the fact that drawing the secants is hard because of how steep the line is

#

You can see here that i drew it but you can barely even tell the difference betwen the secant and the actual graph

#

<@&286206848099549185>

vocal sleetBOT
#

@faint wigeon Has your question been resolved?

faint wigeon
#

<@&286206848099549185>

vocal sleetBOT
#

@faint wigeon Has your question been resolved?

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sacred yew
#

I dont understand how to do this

vocal sleetBOT
sacred yew
#

I do the partial derivatives, and get the critical point (1,0)
and solve for that, which gives me -1

#

then I am lost

hybrid flicker
#

you now need to look at f on the boundary of D

#

and find the min/max from the boundary points

#

then compare with the critical points you got on the inside

sacred yew
#

I dont understand what that means

#

I dont understand what my next step is

hybrid flicker
#

meaning
extremas are either on the inside or on the contour of D

sacred yew
#

Ok, I kinda understand that

#

I still dont understand what my next step is

hybrid flicker
#

well you have a few options

#

for example, you could express f(x,y) as f(x) when (x,y) is on the segment between points (2,0) and (0,2)

sacred yew
#

so any point between (2,0) and (0,2)

hybrid flicker
#

and find the abs minimum of "f(x)" on [0,2]

hybrid flicker
#

(so just find equation of a line)

sacred yew
#

so I could use (1,1) for that?

#

and do that for each line segment?

vocal sleetBOT
#

@sacred yew Has your question been resolved?

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#

@sacred yew Has your question been resolved?

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floral bone
#

is 1/2 greater, smaller or equal to -4/x

vocal sleetBOT
floral bone
#

i just need the answer

subtle helm
#

depends what x is

floral bone
#

the question is like saying use < or > or = and like assume that each variable is positive

#

so i would assume that x could be 1

subtle helm
#

well

#

if x is +ve

#

and -4 is -ve

#

then -4/x is always...

floral bone
#

so issit < or > or =

subtle helm
#

yes Starej

floral bone
#

wdym

spring stratus
#

xd

subtle helm
#

sorry sir, we don't just give you the answer despairjj

spring stratus
#

can you help me

#

pls

subtle helm
vocal sleetBOT
#

@floral bone Has your question been resolved?

calm kiln
#

can anyone explain to me how do i study maths

#

do i study the concepts?

vocal sleetBOT
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brittle talon
#

In R^n, if a set S is composed of n linearly independent vectors, does that mean S spans R^n?

river minnow
#

Yes

hard atlas
#

yes

#

damnit

cyan talon
#

damnit

river minnow
#

In general for finite-dimensional vector spaces, any linearly independent set with the number of vectors equal to the dimension is a spanning set

desert hornet
#

yes

#

damnit

white whale
sharp nymph
#

this can be proven using the steinitz exchange lemma if you want to know more about

vocal sleetBOT
#

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tulip lantern
#

Can someone help me with this

vocal sleetBOT
tulip lantern
#

13.11

#

I don’t know how to continue

#

Or whether if i am doing is correct

desert hornet
#

Do you know of any sum or difference identities regarding ANY of the inverse trig functions?

bleak whale
#

Guys, this is an acute isosceles right?

pallid forge
#

!occupied

vocal sleetBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

#

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tulip temple
vocal sleetBOT
tulip temple
#

How do I solve the 3rd question🙏

dire cave
tulip temple
#

It us

#

Is

#

Greatest integer

#

Bracket

#

How do I solve problems like these

dire cave
#

Mind if I ask

tulip temple
#

Yes sire

dire cave
#

Why the result is not an integer

tulip temple
#

Oh yeah mb

#

The answer

#

Is null

#

This one actually wait

#

The fifth one

#

$$[x/2 + 5/3] = 2$$

twin meteorBOT
#

SusGusInaBus

tulip temple
#

Hoho there

bleak lintel
#

whats the brackets for ?

dire cave
tulip temple
#

Greatest Integer func

bleak lintel
#

ah alright

#

im sorry im not able to help

tulip temple
#

No problem

gentle totem
dire cave
gentle totem
dire cave
#

Like[3.9]=3

#

Right

gentle totem
#

2 included, 3 not included

#

Try to make an inequality

sleek tinsel
#

need some help with this integral please

tulip temple
dire cave
sleek tinsel
#

yea

tulip temple
#

.close

vocal sleetBOT
#
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sleek tinsel
#

been struggling with this one

#

@dire cave

gentle totem
sleek tinsel
#

old exams from my university

gentle totem
#

And does it want a numerical value?

sleek tinsel
#

no it asks me to check if it exists

gentle totem
#

Oh okay

sleek tinsel
#

(converges or diverges ig)

#

he has many simpler problems and i have no idea how to aproach them

gentle totem
sleek tinsel
#

the derivative yea i guess i could with some time

#

but how would that be useful?

#

this type of question is always the last question on his exams, must be the "super hard" one

gentle totem
sleek tinsel
#

this is the derivative

gentle totem
# sleek tinsel

Maybe a comparison test could work though now that I think of it

sleek tinsel
#

such as?

gentle totem
#

The top is always between 2 and 3

#

Set it to 3, which will give a larger area/integral

#

If that integral is convergent, so is this one

sleek tinsel
#

oh yea that could work

vocal sleetBOT
#
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viscid sky
vocal sleetBOT
viscid sky
#

It is a multivariable chain rule question

#

I'm just starting with this, it came out very complicated, so I wanted to check what is the best way to tackle it, if there are any techniques or details I am missing

#

As a more concrete question: when I reach the end of the chain rule I've got an expression with x,y,z and r,st. Do I need to change everything to r,s,t or can I just evaluate x,y,z at the point and substitute that?

#

Here is my solution

vocal sleetBOT
#

@viscid sky Has your question been resolved?

vocal sleetBOT
#

@viscid sky Has your question been resolved?

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civic bolt
vocal sleetBOT
civic bolt
#

.close

vocal sleetBOT
#
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vocal sleetBOT
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serene viper
#

are these rules true? If yes do they have a name?

heavy yoke
#

these are a consequence of logarithms being the inverse operation of exponentiation

twin meteorBOT
#

MethIsAlwaysRight

peak matrix
#

These are the main 4 rules

#

the names sometimes vary

serene viper
#

Thanks! ❤️

#

!close

peak matrix
#

. instead of !

serene viper
#

.close

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#
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scarlet bough
#

i intergrated and got $\frac{1}{2}ln(b^2+4)-\frac{1}{2}ln(4)=ln(\sqrt{5})$ then $4^{0.5}$ is $2$ so i just wrote it as $ln(2)$ so $ln(\sqrt{5})+ln(2)=\frac{1}{2}ln(b^2+4)$ then i did $ln(2\sqrt{5}) = ln((b^2+4)^{\frac{1}{2}})$ then $ 2\sqrt{5} = \sqrt{b^2+4}$ then 2\sqrt{5}=b+2$ and finally $2\sqrt{5}-2=b$. where did i go wrong?

twin meteorBOT
#

morphine_addiction
Compile Error! Click the errors reaction for more information.
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river minnow
scarlet bough
river minnow
#

Still no

scarlet bough
river minnow
#

It's itself, you can't simplify it further

scarlet bough
#

should i square 2srt(5) instead?

river minnow
#

Yes

scarlet bough
#

so 20 - 2 = b?

#

b^2

river minnow
#

b^2 + 4 = (2sqrt(5))^2

#

So b^2 = 20 - 4

scarlet bough
#

so sqrt(20-4)=b

#

so 4=b

river minnow
#

Yes

vocal sleetBOT
#

@scarlet bough Has your question been resolved?

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queen chasm
#

I need help I dont understand how to factor at all in relation to algebraic formulas

warm scarab
#

Post an example

queen chasm
#

6x^4-7x^2+2=0

#

I understand that u would take its place

#

I get all the way to 6u^2-7u+2= 0 and dont understand anything about factoring

#

or how to factor a problem

#

12

#

then 3 and 4 give you 7

#

see I have tried this but for some reason and I dont know why but my math always ends up wrong

#

and how do you know what coefficient in front of the (u-3) (u-4) is supposed to be

twin meteorBOT
#

faiyrose

queen chasm
#

how do you factor by grouping?

#

(3u-3) (3u-1)

#

for the first term

#

yes

#

the ^2

#

yes

#

idk

#

how cna you tell if it can be factored?

twin meteorBOT
#

faiyrose

#

faiyrose

queen chasm
#

u

#

3

#

2u?

twin meteorBOT
#

faiyrose

#

faiyrose

queen chasm
#

I'm sorry I'm really confused

#

why is it in a fraction now and why do we have some many 3u's

twin meteorBOT
#

faiyrose

#

faiyrose

queen chasm
#

yes

#

is the ? the value of u?

#

or x

#

ok

#

isnt it just 3u

#

oh

#

no

#

cause 3 x 3 is 9

#

so its 2u

#

is 0

#

well 1

twin meteorBOT
#

faiyrose

queen chasm
#

yes

twin meteorBOT
#

faiyrose

queen chasm
#

one second I am writing this down

#

ok ready

#

is it going to be -2u(2u+1)

#

oh

#

-2u(2u-1)

#

wait but how would you get 4u+2 with u(2u+1)?

#

oh I see

#

cause

#

that would be 4u^2

#

so it would be 2(2u-1)

#

oh yeah

#

cause you want a positive

#

2

#

and negative 4u

twin meteorBOT
#

faiyrose

#

faiyrose

queen chasm
#

one second

#

so how are you factoring out only 1 of the 2u-1's

#

ok because its the product of us factoring 6x^2

#

-3u

grim lotus
#

what's 2u*3u?

queen chasm
#

6u^2

grim lotus
#

yep

queen chasm
#

I haven't done it yet because I dont understand where the (3u-2) came from

twin meteorBOT
#

faiyrose

#

faiyrose

queen chasm
#

(2u-1)(3u)-(2u-1)(2) =(2u-1)(3u-2)

#

shouldn't it look like that?

#

ok I am following now why does that make (2u-1)(3u-2)

#

I dont thinks so right?

#

4x^4-1

#

2x^2

#

3x^2-2

twin meteorBOT
#

faiyrose

#

faiyrose

#

faiyrose

queen chasm
#

what is the zero product property?

#

ok so how do I solve for x with that ?

#

that just means that x=0

twin meteorBOT
#

faiyrose

queen chasm
#

so

#

X= root of 1/2 or X= root of2/3 ?

twin meteorBOT
#

faiyrose

#

faiyrose

#

faiyrose

queen chasm
#

they want it in a solution set

#

so (+- the root of 1/2 , +- the root of 2/3) ?

#

i2/3, i1/2

twin meteorBOT
#

faiyrose

queen chasm
#

????

#

how did we get that 1/2 and 2/3?

twin meteorBOT
#

faiyrose

queen chasm
#

where just saying the product was (+-the root of 1/2, +- the root of 2/3)

queen chasm
#

what does that mean

#

why is the denominator irrational ?

#

yes why is the 2 the only thing being squared?

twin meteorBOT
#

faiyrose

queen chasm
#

yes

#

but you only had the 2 rooted

twin meteorBOT
#

faiyrose

queen chasm
#

1

twin meteorBOT
#

faiyrose

vocal sleetBOT
#

@queen chasm Has your question been resolved?

vocal sleetBOT
#
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waxen hawk
#

Q

vocal sleetBOT
waxen hawk
#

What’s a translation in terms of transformation

heavy yoke
#

for a function y = f(x) then a vertical translation "b" units up is y = f(x) + b and a horizontal translation "a" units right is y = f(x - a)

vocal sleetBOT
#

@waxen hawk Has your question been resolved?

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waxen hawk
#

Hello

vocal sleetBOT
waxen hawk
#

Hello

tawny nacelle
#

hi

waxen hawk
#

I’m an expert of high school trigonometry

#

Today I encountered a problem that seems to be beyond my ability to solve

#

I’m astonished

#

I’m endowed with the ability to graph any given trig function in my head within a second

#

But

#

I failed on this one

waxen hawk
#

It should be deemed as a violation against the wisdom of humanity to neglect the question from a supreme trigonometry master

#

Oh it is solved

#

It is indeed 20 btw

#

.close

vocal sleetBOT
#
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vital depot
#

What’s up

vocal sleetBOT
vital depot
#

I need help solving this

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I don’t understand how to do it

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Nvm I’m dumb

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cedar linden
#

hii guys

vocal sleetBOT
cedar linden
#
\begin{align*}
\pi \int_{-1}^{3} [8 + 2y - y^2]^2 \, dy &= \pi \int_{-1}^{3} [64 + 32y - 4y^2 - 4y^3 + y^4] \, dy \\
&= \pi \left( \int_{-1}^{3} 64 \, dy + \int_{-1}^{3} 32y \, dy - \int_{-1}^{3} 4y^2 \, dy - \int_{-1}^{3} 4y^3 \, dy + \int_{-1}^{3} y^4 \, dy \right) \\
&= \pi \left( 64y + 16y^2 - \frac{4y^3}{3} - y^4 + \frac{y^5}{5} \Bigg|_{-1}^{3} \right) \\
&= \pi \left[ (192 + 144 - 36 - 81 + \frac{243}{5})- (-64 + 16 - \frac{4}{3} -1 -\frac{1}{5})\right] \\
&= \pi \left[ (267.6) - (-50.53) \right] \\
&= \pi (318.13) \\
&= 999.435
\end{align*}```
twin meteorBOT
cedar linden
#

im doing something wrong dont know why, im sure until the y replacement im right

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but dont know after

#

the asnwer should be

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,w \pi \int_{-1}^{3} [8 + 2y - y^2]^2

cedar linden
#

at least that wolfram say

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756.5

vocal sleetBOT
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safe tundra
#

could you please help me understand"forming algebraic expression
And teach me how to do 1 and to 2 step Operation

warm scarab
#

Post the question

cedar linden
#

yes and wht you have tried so far

safe tundra
#

Ok sorry for the late reply

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This is the forming algebraic expression

vocal sleetBOT
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@safe tundra Has your question been resolved?

past thicket
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@safe tundra Has your question been resolved?

safe tundra
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Sorry my wifi is a bit laggy

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I think I can chat again 6 mins

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molten condor
#

I know finance is a sensitive topic and there are always strong opinions about it but I just really want to keep it simple to the logic i'm hoping to achieve if it's possible. Just been struggling with it for a while now and I know people who have a stronger background in math can do provide some good perspective. I want to keep it brief and as simple as I can but I need to give a background to hopefully give some perspective on what i'm hoping to achieve.

I'm trying to create what they call a "dynamic trading range" that can be represented by supports/resistances. A support is basically an area where the price generally seems attractive to buy at, so a lot of people will be buying a stock at that price which will consequently prevent a price from going lower. A resistance is the opposite where people would be more inclined to sell. I do believe that the support/resistance areas are of higher predictability (lower entropy) in general so I am trying to run a test to prove my hypothesis based on real data. In order to do this, I need a way to automatically map out these areas and the logic to do this is what I need guidance on. The term dynamic is because the trading range is updated every day as soon as new data is added.

The current data which I only have and will ever have access to are the daily stock quotes which generally describe the average behavior of the stock during that day. They are represented by Open (what the price was when the market opened), High (maximum price made within that day), Low (lowest price made within that day), Close (what price the market closed at), and Volume (total number of shares made on that day) for each stock/security. The nature of the data set is already not ideal because making an analysis on these is similar to the concept of taking an average of an average so the conclusions that will be made from these will be suboptimal at best. But it’s better than nothing.

molten condor
#

The trading range will also be a function of price, volume, and time. Since it is hard to capture the relevance of the price data due to the nature of the data as mentioned earlier (Open, Low, High, Close) most people just use the either the “Close” price or what they call the typical price which is (Low, High, Close) divided by 3.

The volume is an essential component when defining a trading range because it provides context to price movements and helps validate the strength of the range. An example can be a math class with 100 students and if 95 students scored 33 points, and only 5 students scored 99 points then the average would only be 36.3 points. The price can be represented by the student’s points and volume can be represented by the number of students.

There can be an infinite number of ways to set up the beginning point and end point of the trading range. So this ramps up the complexity of the model a lot because there has to be some way for the model to decide for itself which among all the possible combinations out there are the relevant ones.

#

This example shows one that only use mininum and maximum values, but this is oversimplified and is of no use at all. I asked AI models a hundred times to iterate it cannot seem to come up with something robust (with respect to the infinite number of zooms). Trying to determine how to mathematically come up with the rule/criteria

#

These are just examples of where a support and resistance may be at based on today's latest data for a single stock

vocal sleetBOT
#

@molten condor Has your question been resolved?

molten condor
#

<@&286206848099549185>

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@molten condor Has your question been resolved?

molten condor
#

.close

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vocal sleetBOT
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finite fern
vocal sleetBOT
finite fern
#

Help solve this pls

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<@&286206848099549185>

#

@summer sierra help pls

open sundial
#

Have you tried the sine rule?

finite fern
#

I just need help in this

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Please

open sundial
#

Apply A/ sin(A) = B/ sin(B)

scenic ravine
#

Is this from an exam

finite fern
#

yeah

scenic ravine
#

sorry, we can't help you in that case

finite fern
#

Bruhhhhhh

#

Pleasee

vocal sleetBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

left dew
#

🤣

finite fern
#

this is not an exam

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thats my homework

south tapir
#

Real

viral copper
#

bro tried to use obliviate

scenic ravine
#

stop trying to dm me

solemn marten
#

💀💀

#

dawg messed up

vocal sleetBOT
# finite fern
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
fervent wasp
finite fern
#

but forgot

fervent wasp
#

Sure

finite fern
#

And now im going to fail

fervent wasp
#

Memorize it

#

@finite fern Are you there?

vocal sleetBOT
#

@finite fern Has your question been resolved?

fervent wasp
#

@finite fern Hey, if you’re here to get the answer to that question directly, I’m afraid that no one would help you. You may either sit down and answer my question or just leave since you’re not going to get anything good for waiting here:)

fervent wasp
#

Nothing, I’m just notifying you that you’re wasting your time waiting for the answer

#

That’s it, it’s up to you

vocal sleetBOT
#

@finite fern Has your question been resolved?

vocal sleetBOT
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hushed briar
#

can i get some help on sloving this, i am completely stuck on this

snow hedge
hushed briar
#

yes

snow hedge
#

Apply it here

hushed briar
#

so 6 is adjacent?

snow hedge
#

We can't say it directly
It depends upon the angle which you are taking
But that doesnt matter here

snow hedge
plucky trout
#

a^2+b^2=c^2, plug the corresponding values in and solve

hushed briar
#

would there be like a formula like $6^2+x^2=3x-1^2$?

twin meteorBOT
#

Bahnies

snow hedge
#

Yes (3x-1) ^2

empty mauve
hushed briar
#

oh thanks for the solution

#

.close

vocal sleetBOT
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empty mauve
#

you're welcome

vocal sleetBOT
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proven nebula
vocal sleetBOT
proven nebula
#

i know that 6561 can be factorized as 3^8, but is there a easier trick to it?

empty frigate
#

given that it's an 8th root you could just start taking small numbers and raising them to the power of 8, if that's any easier than just staring at 6561 and trying to factorise it

#

there isn't really going to be anything that doesn't go through somehow concluding 6561 = 3^8 since that is essentially what they're asking you to determine

proven nebula
#

so there is not a easy trick to do the factorization?

empty frigate
#

well given that you're expecting the answer to be an integer, you can notice that 6561 is a multiple of 3, and then just keep dividing it by 3 to see if it's 3^8

#

it would be pretty weird if they asked you to find, like, (3^7*5)^0.125, because then the answer is going to be some weird irrational number, and there isn't much you can do about that without a calculator

proven nebula
#

how do u know that the base is 3?

empty frigate
#

well you just start trying numbers until you find a factor of 6561

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it's not even, so 2 doesn't work

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it doesn't end in 0 or 5, so 5 doesn't work

#

there's a fairly easy trick to check if a number is divisible by 3: add up its digits, and check if the result is a multiple of 3

#

6 + 5 + 6 + 1 = 18, which is a multiple of 3, so 6561 also is

proven nebula
#

yes ik about it

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will they give bases of higher numbers?

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like 21 or 23

empty frigate
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well if you get numbers that big then i'd say, start computing 8th powers of things just to get a sense of how large it is

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like if you want to find the 8th root of 208827064576

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10^8 is too small, so it's bigger than 10

#

20^8 is still too small

#

but 40^8 is bigger so it's somewhere in between those

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30^8 is bigger

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etc.

#

and eventually you'll try something that happens to be the right answer

empty frigate
#

the first thing you should do is notice that it's even

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and divide it by 2^8, just to make it a smaller number

#

since 815730721 is at least somewhat easier to deal with

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but also yeah i would not expect numbers this big to come up

proven nebula
empty frigate
proven nebula
#

so i dont need to worry?

empty frigate
#

yeah i don't think you need to worry

#

i mean you might be asked to find square roots of things like 23^2 because that's actually a pretty reasonable number, it's 529

#

but also like, that's just way easier because the numbers are smaller

#

20^2 is 400 which is too small, 25^2 is 625 which is too big, we can skip the even numbers, 21^2 is 441 which isn't right, so it must be 23^2 and indeed it is

proven nebula
#

yes thanks

#

.close

vocal sleetBOT
#
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kind light
#

need help

vocal sleetBOT
kind light
#

i literally just don’t understand how to do this at all

#

oh wait

gilded osprey
# proven nebula

If you are out of ideas, use the definition of
$x^a = exp(a ln(x))$

twin meteorBOT
#

Daddy_314

proven nebula
gilded osprey
gilded osprey
proven nebula
kind light
gilded osprey
#

"need" is a strong word

#

You "can"

#

Do whatever you want

#

If you have a good approach

vocal sleetBOT
#

@kind light Has your question been resolved?

gilded osprey
#

I already gave you a suggestion

kind light
#

what does it mean to “express” tan(27) and tan(39)?

gilded osprey
#

The red triangle is a right triangle

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Therefore tan(39) = h/d

#

Tangent is the best choice because we have the adjacent side to the angle and we want an information about the opposing side

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There is no point in using cos or sin

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The second step is to do the same thing we did in another right triangle

gilded osprey
kind light
#

so tan(27) = h/25+d??

gilded osprey
#

Almost

#

Tan(27) = h/(25+d)

kind light
#

alright

gilded osprey
#

And now the magic happens because we have two equations and two unknowns

#

This is a system of linear equations to solve

#

tan(39°) = h/d
tan(27°) = h/(25+d)

#

Tan(39) and tan(27) are just two numbers

#

Like any other number

kind light
#

so do we convert tan(39) and tan(27) into actual numbers

#

???

vocal sleetBOT
#
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weary dune
#

(Regarding my electricity bill) Q: What is the period of this bill and how many days of usage did it cover?

weary dune
#

hi im kinda struggling with these word problems, ive figured out the first part of the question

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billing period: 11 jan - 9 april

#

is the second part asking how many days are in between those dates or is it asking about some other info

brisk cloak
#

im pretty sure thats what its asking

weary dune
#

ok then ill trust u

#

thanks bill

brisk cloak
#

no problem angela

vocal sleetBOT
#

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vocal sleetBOT
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sage pulsar
#

hello I am new. so is there a help that helps with precalc or is any help fine?

thick lantern
#

There are also more topic specific channels below, you could ask there as well. Whatever works for you.

vocal sleetBOT
#

@sage pulsar Has your question been resolved?

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tribal crater
vocal sleetBOT
warm scarab
#

Want us to grade it

tribal crater
#

Yes plz

#

Sorry if you can’t read some parts it’s messy

warm scarab
#

What confuses you about #12

#

Its the same as the others

tribal crater
#

Nothing I’m gonna do it this pic was b4

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I’ll send here aswell give me 5 mins

#

I did the other question I’m done don’t need help on that one it’s fine jus lmk abt these questions if they seem correct

#

I have to take shower and get ready for math class brb

vocal sleetBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).