#help-17
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i mean theres no sheet
im not sure its wrong
actually it might be right
but i still want to make sure
Well, it's possible that your teacher interpreted the question differently, like treating c, (a, b), d as the different grouping, as the grouping labels are not interchangeable.
But in this situation, there is no way to find out.
the teacher didnt solve it
and its explicitly stated that they are
but whats not clear is whether all the groups can be empty or not
but i asked 2 classmates and they both came up with (n choose 2) + 1
so that seems to be right
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Can someone help me with this qn
first think about all the ways you can arrange the vowels into the 8 letter positions
I mean how to ensure that U comes before the other vowels?
you have to put the 3 vowels somewhere
once you choose 3 places for them, there is only one order they can be in
Hmmm so we need to consider each possibility separately?
Isn't there like a gen sol?
we don't need to "consider each possibility separately" for this
just need to know how many of them are
But they need to be in a certain order right
yes, but that's no trouble
right
Wait so (56 times 5 factorial/2)-1 ?
Lol ok that was pretty simple
So dumb of me
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Thanks for ur help @brisk moss
Who

u didnt sleep? ๐ญ
nope
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well in MVT it just states that there exist a point 1 < x < 5 such that f'(x) = f(5) - f(1) / 4
in this question it asks specifically for f'(3)
so MVT doesn't apply
have you tried plotting it on a graph?
And i just realized, the 2nd derivative > 0 means always concave up right
0.7
convex you mean
that must be it then
it asks you to approximate after all
if you really wanna know the exact answer, you can try to fit a polynomial through it using polynomial regression
but I think that's beyond your course
ya, anyway, thanks!
you are welcome !!
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where does the *2^x at the end come from?
They multiplied the whole equation by 2^x
why
to get rid of that 2^x in the denominator
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I'm having a hard time trying to understand how subtracting the 2 functions would result in a function that then can be integrated to find the area? why subtract it?
Think of it as subtracting areas
but how would subtracting g(x) from f(x) give me the function that I need?
$\int_{a}^{b}f(x)-g(x)dx = \int_{a}^{b}f(x)dx - \int_{a}^{b} g(x)dx \newline$= Area under f in [a,b] - Area under g in [a,b]
$\newline$
=Area between f and g in [a,b]
quickdoom
@gritty isle does this make sense?
This calculus video tutorial provides a basic introduction in finding the area between two curves with respect to y and with respect to x. It explains how to set up the definite integral to calculate the area of the shaded region bounded by the two curves. In order to find the points of intersection, you need to set the two curves equal to eac...
@signal pendant thank you for explaining it. I think I'll watch this video.
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$\int \frac{x}{x^2+3x+5}$
Norman Price
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
I'm trying to do 2x+3=x to find the solutions but I know that's not the case
2
Is substitution used?
I have to have the derivative above so I have the logarithm
It appears that this is how it is done
Yes.Heres a hint:
$\newline \frac{x}{x^2+3x+5}=\frac{1}{2}\frac{2x+3-3}{x^2+3x+5}=\frac{1}{2}\left(\frac{2x+3}{x^2+3x+5} -3 \frac{1}{x^2+3x+5} \right)$
bathroom mug
Read the image
Why are you doing this?
To do the derivative
But what are you doing?
I need an instant method
Bro you're just making him get into trouble, I understand what he wants to do
Listen to me
Ok
You have to take the derivative up
Yes
2x+3
Im not, lol.$\int \frac{x}{x^2+3x+5} = \int \frac{1}{2}\left(\frac{2x+3}{x^2+3x+5} -3 \frac{1}{x^2+3x+5} \right)=\newline ln(2x+3)-3\int \frac{1}{x^2+3x+5}$. Its the fastest way
Wtf
Nice
bathroom mug
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
Now you have to find a number that when Is multiplied by the derivative gives you x
Yes
(only for the first x)
1/2
the ln(2x+3) is wrong here lmao from this it should be 1/2 ln(x^2 + 3x + 5)
I hate it when people don't understand help, and do their own thing
This guy was using another method, and here he was, he did something completely different
Of course one doesn't understand anything
what are you trying to have him do? partial fractions?
@lethal heart
Yes
So?
I have to subtract 3/2
Why
So I didn't alter the integral
Can you write in latex what you mean?
?
$(2x+3)*1/2-3/2$
Norman Price
All this in numerator
The derivative part only goes on the number that has x
Yes
Now I have to separate the fraction
Yes
So on one side the logarithm comes out
Mm wait
On the other hand I have to see the โ of the denominator
Wait
๐คฆ
Let me see
I said wait
Ok
Because the numerator is the derivative of the denominator
This
What
$\frac{\ln|x^2+3x+5|}{2}$
You have to put the denominator part in the absolute value
?
๐คฆ
Edit the message
Norman Price
This
Ok
If the โ is negative the arctangent comes out
Ok
In this case it is negative
๐
So this is used
Are you done ?
Yes
Okay , bye!
Thank you

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I forgot
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How do i do this
Consider taking the reciprocal of both sides
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Anyone know how to do this?
specifically 35)
@vocal falcon Has your question been resolved?
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help?
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Confused on what I need to do here
@hot heath Has your question been resolved?
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can someone help me figure out how to algebraically solve this limit
the main thing thats messing with me is that x is an exponent
what does this limit remind you of
im honestly not sure
oh
what is x in this case
the n
2 lol
ive never seen this before
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The square root of 416-210i can be expressed as a+bi, where a and b are integers. Find a and b, without a calculator or computer.
what have you tried?
nothing. no idea how to do this problem
i'm currently solving this https://artofproblemsolving.com/wiki/index.php/2012_AIME_II_Problems/Problem_8
and im confused on that specific step
okay, note that we should have (a+bi)^2 = 416 - 210i
that's the first thing we should observe
does this make sense to you?
if not, I can elaborate
yeah, but doing that seems like a lot of work is there a better solution
as a mathematician im lazy

I can't think of a better way...
there might be one, but this method is what I would do personally
the fact that the solution didn't even explain this means there is a really easy solution im ignoring
This one is easy
a^-b^2= 416
2ab=-210
That's it
tbf, it's not that complicated
you can just substitute and solve
oh, wait
you don't have a calculator
ahhh

not even 4 func
my apologies; I don't know of any other method to solve this 
maybe somebody else will come by and help you out
Lol, not that much
no calculator
?
calculator is not allowed
How do you even use a calculator for this
we have to take square root of 217156
i have a 12 min time limit to do this problem
if i were to do this problem on a test
so that does not work
I see
Square root of 217156 will take at least a min to find
Hmm, but idk if there is a easier method
@naive heron Has your question been resolved?
<@&286206848099549185>
question is find square root of 416-210i WITHOUT A CALCULATOR, given result is in the form of a+bi where a and b are integers
Ok wait
don't just give me the answer pls explain because im self studying this isnt homework lol
you have 2ab = -210
so ab = -105
find divisors of 105
since a,b are integers
they're divisors of 105
it's a good candidate
a=21 b=-5 or a=-21 and b=5
though it's not the only one, you can start with those
Hmm like u can directly apply formula tho
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I am a bit confused on this question
What I did was use the fact that the unit vector is <cos(2pi/3), sin(2pi/3)>
then multiplied that by 14
so I'd have got 14(-(1/2)i + (sqrt(3)/2)j )
which would give me the components -7, 14sqrt(3)/2
I also tried it with pi/3
which would just make the 7 positive
but it was still wrong
any thoughts?
It looks like the angle is pi/2+pi/3=5pi/6?
So just flip your i j components around?
@crisp zenith Has your question been resolved?
hmm that wasnt correct
was given a similar one after exhausting my attempts ill let you know if I get it
though I am still curious on why this one is wrong
Got this one right
if someone could let me know why this was wrong that would be great
@crisp zenith Has your question been resolved?
@crisp zenith Has your question been resolved?
@crisp zenith Has your question been resolved?
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I need help deriving this: (I have always find it difficult deriving things with a square root of or similar things like that)
I first got it to 0,5 (2x-1)^-0,5
But that is of course wrong
on my answersheet is says:
,,\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
Renz
and chain rule from there
I need to check what you mean, because I am not familiar with the english terms of stuff. Hold up
I guess I don't really know?? Because I am quite new to drivative
ye just show the formula
he will know how to do
Note that F(x) = f(g(x))
ok I let you to help him then
I am hella confused right now. There is so many helping rn ๐ฅฒ
๐ฎโ๐จ
Apparantly not
lol
I cannot prosses anthing hahhaa, why is there new people coming here
Where did you get g(x)
you mean this?:
then no I do not get it
Oh okay, then I am mixing stuff uf
up
Yeah okay
I am trying to process the information
okay I got
Yeah I figured it out rn
4x would be the derivative for it?
righhtt??
And how is that done
..,,
But how do you seperate them?
..,,
h'(g(x)) is simply defined as h' exaluated at g(x), i think u meant to set f(x)=h(g(x)) and use f'(x) rather than h'(g(x))
Ngl this made me kinda more confused. Is there any server where someone can help you with vc, because I do not understand this though text. It looks so weird.
really?
yeah sure, let me just get my mic
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i dont understand why mod 16 is used here
im under the impression binary is mod 2
for the last digit, sure
but think about how in base 10, the last 2 digits are given by the number mod 100
and the last 3, mod 1000
it's similar here just with powers of 2 instead of powers of 10
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does there exist a function which has the property $f(0) \to \infty$ and $f(1) \to - \infty$ or vice versa?
I dont really care about its values in between 0 and 1, or beyond 0 and 1, or continuity in general
can a function ever equal infinity
No there isnโt
how can that be a real valued function
real valued function means the codomain is a subset of R
equal as in limit ๐
nvm should remove that
The definition of a function is whenever you plug in a certain value, it gives you an another in feedback
rakยณen
yeah why not ?
sure, f:{0,1}->{infty, -infty} given by your two points. thats a function
waw
...i mean a closed form thought that was obvious?
are you asking for a function $f:\bR\setminus{0,1}\to\bR$ such that $\lim_{x\to 0}f(x) = \infty$ and $\lim_{x\to 1} f(x)= -\infty$
slayla
the $R \setminus{0,1}$ isn't necessary
rakยณen
,w interpolate infinity, -infinity
you meant it maybe, sure. but thats not what you wrote. closed form isnt even a precisely defined thing
it seems like it is...
function and "formula" arent the same things either
was wondering what it would say
its stupid to ask something if a function like that exists thats easy to assure, my question is what the function's definition would look like
nvm
something like tanx
maybe ?
look, its not my fault that you wrote a question but you actually meant a different question. this is an exercise about being precise about what you want
so you want a function $f:\bR\to\bR$ such that $\lim_{x\to 0}f(x) = \infty$ and $\lim_{x\to 1} f(x)= -\infty$
slayla
Yeah
you can easily have 1/|x| for the x->0 and -1/|x-1| for the other one
alright, sorry
and then build something piecewise between those
but presumably thats not closed form enough?
I see..any other ideas?
I mean, sure its fine ig
it just doesn''t look good to me ๐
some rational function probably works
and you can define f(0) = f(1) = 0 or whatever
if you want the domain to be R
$\frac{1}{x^2}-\frac{1}{(x-1)^2}$
Denascite
o that looks nice
of course if your closed form is supposed to include f(0) and f(1) then you are a bit fucked
cause most things we can write down are continuous
yes
no its not necessary
might be interesting to look into the conditions such that P(x)/Q(x) satisfies the given limits
well thank you for all the ideas everyone
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hi! could someone please explain how to solve this question?
without a calculator
1/2 ab sin(c)=7.5
let's set cosA=-0.8
yup
wait why?
cosA<0,agree?
yes
so b=c
how is sinA 0.6
sinA=โ๏ผ1-cosA^2๏ผ
yess i got it
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J is the midpoint of line segment HL. I and K are on HL such as that HI = IJ and JK = KL. what percent of HI is HK
Draw it out
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Hi, I have an exercise like this:
The sides of the triangle are 15 cm, 18 cm, and 21 cm. The triangle is cut by a line parallel to the shortest side, forming a trapezoid whose shorter base is 10 cm. Calculate the perimeter of the trapezoid.
I made a drawing of it and got the shorter base of 10 and the longer base of 15, but how am I supposed to find the other 2 sides? :)
since the line you drew to make the triangle is parallel to one of the sides, it'll create a smaller similar triangle
like that
don't draw a separate diagram for the trapezoid
this triangle is similar to the original one
so you might want to draw it a bit bigger
you're not buying that they're similar?
yeeah I do
or you're just not sure how to continue given that they are similar
yeah im not sure how to continue
So you're given the smaller base of the trapezoid is 10
okay so what are the two other sides of the trapezoid then

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Set $I := [0, 1]$, denote the set of continuous real valued functions on I by $C(I)$, let d1 be the L1 metric on C(I), and let d2 be the supremum metric on C(I). Are d1 and d2 equivalent? prove your answer.
I know that they are equivalent iff for every $x \in X$ and ${xn}{n=1}^\infty \subset X$ we have $x_n \overset{n} \to x$ in(X,d1) if and only if $x_n \overset{n}\to x$ in(X,d2).
I feel like it should be false, and there should be some example, but not sure how. Any help?
mtr123
I think if you take the constant zero function, then define f_n to be a piecewise linear "spike" of height 1 and width 1/n (and is zero outside of the spike), then the supremum distance between them will always be 1, but you can make the L1 distance arbitrarily small
in the supremum metric, (f_n,0) -> 0, so there is no constant C such that C d_2(f_n,0) <= d_1(f_n,0) so they're not equivalent metrics
basically, any pair of functions that bound vanishing area between them but remain at least a fixed distance apart at some point should work as a counterexample
@opal flare Has your question been resolved?
actually the defintion they gave us for equivalent is whether an open set with respect to d1 is open with respect to d2
and not that C constant you used here
I saw that defintion too online
but that's not what I got to work with sadly haha, it looks easier
lipchitz is stronger than topological though ๐ญ
I was thinking about spike function too, cuz the integral should converge to 0 if I recall correctly as n goes to infinity, and the supermum gonna still to 1 so fn gonna converge in L1 but not in the supermum thingy
can you just say that the metrics are topologically equivalent iff the same sequences converge?
well I'm suppose to prove that in another question ๐
since you can define convergence purely in terms of open sets, if they're topologically equivalent, they'll have the same set of convergent sequences
๐ญ
oh, well
that's before this question
so if you prove that first you can use it ๐
just need to figure out how to construct those spikes ๐
that was quick lol
I knew I had it lying around somewhere
I think the argument might be clearer if you have the spike centred on 1/2 constantly though
but the modification should be similar
I think it gonna be easier for me to just use this one honestly
thanks ๐
Just need to prove that other question now haha
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I made one that's centred for on 1/2 just in case ๐ญ
oh wow, much appreciated!!! I might use it, just need to focus on the other question now because im relying on it!
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thank you @round plover

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can i get some help please
im sorry
i cant think about it
can i get some help by you , please?
@ebon silo
oh yeah ik that
just that , in bulgaria its explained diffrently
(x-1) (x-1)-1
down its (2-x)(2+x) am i right
oh thanks
(x-1)(x-1)-1
(2-x)(2-x)
(x-1)^2
same thing
x^2 - 1^2
?
she means make it a trinomial
I dont understand what trinomal means thats the thing
Not my first launglage
sorry abt that
a expression/equation with 3 terms
okay
tha thing is
i know the stuff
just cant understand the way to do it
thanks for the help
yes but in a different way
wait
idk about the convertion right at the top tho
oh wait dw about it
i missundestood
so it becomes x(x-1)
x^2 - 1
no wait
x^2 - x
got it
let me solve the entire thing
(2-x)^2 is 4-x^2
right
sorry am back got banned for some reason
no
wait really?
4-2x+x^2
squared of the first term
multiply everything inside the bracket and then ny the exponent which is 2 the square the second term
alr
i know the formula
good luck
okay
second term?
the thing i just send
the entire thing
i gotta go tho
tommorow
im going to tell what i got on my exam
lemme solve and give u
x=2
he gone
@austere arrow Has your question been resolved?
im here
no
can you add me on here?
on discord
i have to ask u something
@delicate oracle check dms
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Hey, I completely don't know how to do this. Someone is able to explain more or less exactly how to do it?
@low trail Has your question been resolved?
I didn't count
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I just want to make sure that im on the right path so this is what I got for one of the cases:
Case 1: 3, 4, 5, 6, 7 (3 to 7 diamond) (discard 5) need 1 of each
Honestly u dont even have to read the question
the second, third, fourth image is enough
oh also in the 4th image I meant to divide all of that by (26C5)
but basically this is what I was thinking
Ik we need 1 of each for case 1 because we dont have any of those cards in the hand
so to get atleast 1 3 diamond the prob would be
(3C1)(3C1) (3 cards to choose 3 from)(3 suits to choose diamond 3 from)
oh wait is it suppose to be all of them multiplied instead of adding each
because we need 1 of each not 1 of 3 or 1 of 4 and so on
dude balatro isnt that hard

(i dont know math sorry) < i just always build 2 pair
i dont even play poker I just discovered abt this recently
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<@&286206848099549185>
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@elfin pendant Has your question been resolved?
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How would I do this problem?
@leaden crane Has your question been resolved?
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Alberto Z.
This one
Yes
Yep exactly
Easy enough, what would happen if there's two points though and no slope? @civic otter
a robust way to do problems like these is to write the line as y = mx + b and then use the information given to determine m and b. so here for example, we have 17 = m(-2) + b
and you can get another equation from the other point and determine m and b
if you are given slope, you can just put that right in for m and then determine b with a point on the line
you don't have to remember different "forms" for writing lines if you do it like this
either works but probably easier to solve for b because no fractions
(15,6) is also on the line so we have 6 = m*15 + b as well
sorry i messed that up
yep
what shall i do next?
the only thing i can think of is setting both b's to each other lol
yea you can do that
if you mean put -15m+6 = 2m+17
fuck
sorry messed that up again lol
yeah, that's what i meant
you can solve for m from there
m=-11/17
would i need to do it to both?
you can use either equation but don't need to use both
they should give the same thing
then i just plug in 3+t for x
hmm, any ideas? @brisk moss
I've tried that +
$\frac{1308}{119}-\frac{11}{7}t$
Someone
yea it appears we made an algebra error somewhere

i take that back, we did not make an algebra error
11/17, not 11/7
i typo'd here again
for like the 3rd time
sorry lol
sorry i was never any good at algebra
np :3
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Can anyone help me with antiderivates that consist of trignometry?
just ask the question
u-substitution?
I dont know how to do it
as in you haven't learned substitution or you don't know what to substitute?
a good place to start is usually something in the denominator
you can try that (or something similar) and see if it works
In my cb it is like that ok
What abiut du
The numerator is 1/2 sin2x
How did he solve that
<@&286206848099549185>
Where did he get the 4 from
1/4
Helppp
jandro
?
jandro
I think your doubt Is this
jandro
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
jandro
jandro
jandro
Substituting backwards
So the result is
jandro
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I suppose it's because sqrt(-6) is an imaginary number, so you can't really compare it to a real number in the real plane
I'm not exactly sure what you mean by the square root should be as well
Yea, good analysis, if f(x) is never negative then the square root of f(x) is also defined for the domain of f(x)
By solving it algebraically are you referring to quadratics only or other functions too?
Well you can't always solve for the variable in every radical equation, i mean technically you can but it might not always be real. Functions like radical quadratics and quintics for example don't always go below the x axis so all x values work
Just know that if you ever get an imaginary value that means either it's domain is all x values or no x values
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Given $f(x)$ differentiable and positive on $(0,+\infty)$ such that [
f(x)\ln f(x)=x(2f(x)-f'(x)),\forall x \in(0,+\infty)
]
Given $f(1)=f(3)$, calculate $f(2)$
not sure how to approach this
@jagged cargo Has your question been resolved?
use the fact that $f$ is positive to make a substitution
[ f(x) = e^{x + g(x)} ]
hm, thats smart
alright let me try, ill notify when i encounter another problem
thanks!
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Why is the angle 90 - alpha?
because the total angle at X is 180
wait actually
they don't show anything about reflection
if the incoming and outgoing rays are parallel that would make sense
if they aren't then it cannot be correct
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$2^{\log_2 x}=x$ for $x>0$ if thatโs what youโre asking
Civil Service Pigeon
what does that mean exactly
?
for x>0
so I cancels out so long as I add the it to other side?
idk what the formula means
Meaning thatโs only true for positive x
Okay I see
Because if x is zero or negative, the logarithm in the exponent is undefined (over the reals)
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hiii i need help , it's to do with basic logs but im kinda confused lol
no
$x^3 = 3x$
artemetra
no idea how to do this?
do u do 3logx=3x?
let's use t as the variable to not confuse the names
yes, i let t = log(x)
so what you get is t^3 = 3t
now, solve for t
hint: move 3t to the other side and factor
but here you can't multiply on both sides with 1/x?
uh. t^2=3?
careful: ||what if x=0 ?||
0=0
correct, but by doing this you are missing one of the possible solutions, namely t=0
so if t is NOT 0, t^2 = 3 applies
would u square root 3 at the end?
yes, $\pm$
artemetra
I agree
no -\sqrt(3) is useless here
I saw
you cannot do that, since multiplying logs is not the same as multiplying the results of logs
lmao they are saying let x = log(whatever)
pprob shouldn't have used x
but it's wtv
Ok I found a way to do it
I suggest to start by bringing the right side to the left, and then take one common log as a factor
that's what i did broski
yeah woops
i thought OP was confused by the use of t
Bringing the 3x to the left and factoring?
artemetra
yes
awesome
but wait why there 0 as well?
ah, sorry guys, didn't understand that you substituted originally, thought you just wanted to cancel out the logs
$x\cdot(x^2 -3)=0$
Gordon Ramsey
Is this right?
can i just help on my own guys
