#help-17

1 messages ยท Page 189 of 1

white whale
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(Also, please do ping me)

languid spruce
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i mean theres no sheet

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im not sure its wrong

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actually it might be right

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but i still want to make sure

white whale
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Well, it's possible that your teacher interpreted the question differently, like treating c, (a, b), d as the different grouping, as the grouping labels are not interchangeable.

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But in this situation, there is no way to find out.

languid spruce
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the teacher didnt solve it

languid spruce
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but whats not clear is whether all the groups can be empty or not

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but i asked 2 classmates and they both came up with (n choose 2) + 1

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so that seems to be right

white whale
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If you think the question is solved, please close it with .close

languid spruce
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ah right sorry

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.close

vocal sleetBOT
#
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vocal sleetBOT
#
Available help channel!

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Remember:
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โ€ข Type the command .close to free the channel when you're done.
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robust tide
vocal sleetBOT
robust tide
#

Can someone help me with this qn

brisk moss
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first think about all the ways you can arrange the vowels into the 8 letter positions

robust tide
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I mean how to ensure that U comes before the other vowels?

brisk moss
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you have to put the 3 vowels somewhere

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once you choose 3 places for them, there is only one order they can be in

robust tide
#

Hmmm so we need to consider each possibility separately?

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Isn't there like a gen sol?

brisk moss
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just need to know how many of them are

robust tide
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But they need to be in a certain order right

brisk moss
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yes, but that's no trouble

robust tide
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Hmm that is 56

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I figured that

brisk moss
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right

robust tide
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Wait so (56 times 5 factorial/2)-1 ?

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Lol ok that was pretty simple

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So dumb of me

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robust tide
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Thanks for ur help @brisk moss

vast shale
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uhm

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how tf is she still here

robust tide
#

Who

brisk moss
vast shale
#

u didnt sleep? ๐Ÿ˜ญ

brisk moss
#

nope

vocal sleetBOT
#
Available help channel!

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
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Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

carmine root
vocal sleetBOT
carmine root
#

how am I supposed to proceed

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nvm I got it

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.close

vocal sleetBOT
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vocal sleetBOT
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Available help channel!

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
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Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lapis sentinel
vocal sleetBOT
lapis sentinel
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I am stuck

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I was thinking MVT but i got 0.75, which isnt an anser

deft vapor
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well in MVT it just states that there exist a point 1 < x < 5 such that f'(x) = f(5) - f(1) / 4

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in this question it asks specifically for f'(3)

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so MVT doesn't apply

lapis sentinel
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ah ok

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so how do i do then?

deft vapor
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have you tried plotting it on a graph?

lapis sentinel
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No

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lemme try

lapis sentinel
deft vapor
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it looks pretty linear to me

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what's closest to 0.75

lapis sentinel
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And i just realized, the 2nd derivative > 0 means always concave up right

lapis sentinel
deft vapor
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it asks you to approximate after all

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if you really wanna know the exact answer, you can try to fit a polynomial through it using polynomial regression

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but I think that's beyond your course

lapis sentinel
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ya, anyway, thanks!

deft vapor
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you are welcome !!

lapis sentinel
#

.close

vocal sleetBOT
#
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vocal sleetBOT
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Remember:
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โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sly summit
vocal sleetBOT
sly summit
#

where does the *2^x at the end come from?

civic otter
#

They multiplied the whole equation by 2^x

sly summit
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why

ember ledge
sly summit
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ohhhh

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aightt thanks

#

.close

vocal sleetBOT
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#
Available help channel!

Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gritty isle
#

I'm having a hard time trying to understand how subtracting the 2 functions would result in a function that then can be integrated to find the area? why subtract it?

signal pendant
#

Think of it as subtracting areas

gritty isle
signal pendant
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$\int_{a}^{b}f(x)-g(x)dx = \int_{a}^{b}f(x)dx - \int_{a}^{b} g(x)dx \newline$= Area under f in [a,b] - Area under g in [a,b]
$\newline$
=Area between f and g in [a,b]

twin meteorBOT
#

quickdoom

signal pendant
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@gritty isle does this make sense?

gritty isle
# signal pendant <@535155458143420476> does this make sense?

This calculus video tutorial provides a basic introduction in finding the area between two curves with respect to y and with respect to x. It explains how to set up the definite integral to calculate the area of the shaded region bounded by the two curves. In order to find the points of intersection, you need to set the two curves equal to eac...

โ–ถ Play video
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@signal pendant thank you for explaining it. I think I'll watch this video.

vocal sleetBOT
#

@gritty isle Has your question been resolved?

#
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#
Available help channel!

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lethal heart
#

$\int \frac{x}{x^2+3x+5}$

vocal sleetBOT
twin meteorBOT
#

Norman Price

twin parrot
vocal sleetBOT
# twin meteor **Norman Price**
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
lethal heart
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I'm trying to do 2x+3=x to find the solutions but I know that's not the case

twin parrot
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You haven't really begun tbh

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2x+3=x accomplishes nothing

lethal heart
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Is substitution used?

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I have to have the derivative above so I have the logarithm

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It appears that this is how it is done

twin parrot
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Yes.Heres a hint:
$\newline \frac{x}{x^2+3x+5}=\frac{1}{2}\frac{2x+3-3}{x^2+3x+5}=\frac{1}{2}\left(\frac{2x+3}{x^2+3x+5} -3 \frac{1}{x^2+3x+5} \right)$

twin meteorBOT
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bathroom mug

lethal heart
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What

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What is this thing

twin parrot
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Read the image

lethal heart
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But it's a disaster

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I'll never finish

lethal heart
grand linden
lethal heart
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I need an instant method

grand linden
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Bro you're just making him get into trouble, I understand what he wants to do

grand linden
lethal heart
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Ok

grand linden
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You have to take the derivative up

lethal heart
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Yes

grand linden
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Whats the derivative

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Its Easy

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Do you need help ?

lethal heart
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2x+3

twin parrot
grand linden
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Wtf

grand linden
twin meteorBOT
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bathroom mug

lethal heart
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!nosols

vocal sleetBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

grand linden
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Now you have to find a number that when Is multiplied by the derivative gives you x

lethal heart
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Yes

grand linden
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(only for the first x)

lethal heart
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1/2

grand linden
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Nice

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But now you also have to multiply this number by 3

mellow oyster
grand linden
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This guy was using another method, and here he was, he did something completely different

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Of course one doesn't understand anything

mellow oyster
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what are you trying to have him do? partial fractions?

grand linden
lethal heart
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Yes

grand linden
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So?

lethal heart
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I have to subtract 3/2

grand linden
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Why

lethal heart
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So I didn't alter the integral

grand linden
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Can you write in latex what you mean?

lethal heart
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I mean

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Return to the x

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Like

grand linden
lethal heart
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$(2x+3)*1/2-3/2$

twin meteorBOT
#

Norman Price

lethal heart
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All this in numerator

grand linden
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The derivative part only goes on the number that has x

lethal heart
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Yes

grand linden
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Nice

#

Now ?

lethal heart
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Now I have to separate the fraction

grand linden
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Yes

lethal heart
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So on one side the logarithm comes out

grand linden
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Mm wait

lethal heart
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On the other hand I have to see the โˆ† of the denominator

grand linden
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Wait

lethal heart
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๐Ÿคฆ

grand linden
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Let me see

lethal heart
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The logarithm(derivate)/2 comes out

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Im stupid

grand linden
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I said wait

lethal heart
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Ok

grand linden
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I have a doubt

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How did you know it was a log?

lethal heart
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Because the numerator is the derivative of the denominator

grand linden
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Ok

#

Then ?

lethal heart
grand linden
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?

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I'm not understanding

lethal heart
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What

grand linden
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You can write it in LaTeX

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Pls

lethal heart
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$\frac{\ln|x^2+3x+5|}{2}$

grand linden
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Mmm

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It's wrong

lethal heart
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?

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Why๐Ÿ˜ญ

grand linden
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You have to put the denominator part in the absolute value

lethal heart
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?

grand linden
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Like 1/x Is log |x|

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Is not log (1)

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Okay?

lethal heart
#

๐Ÿคฆ

grand linden
#

Edit the message

twin meteorBOT
#

Norman Price

grand linden
#

Nice !

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Then ?

grand linden
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Ok

lethal heart
#

If the โˆ† is negative the arctangent comes out

grand linden
#

Ok

lethal heart
#

In this case it is negative

grand linden
#

๐Ÿ‘

lethal heart
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So this is used

grand linden
#

?

#

What

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@lethal heart

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I didnt understand

lethal heart
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Nice !

grand linden
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Are you done ?

lethal heart
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Yes

grand linden
#

Okay , bye!

lethal heart
#

Thank you

grand linden
lethal heart
#

All clear

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vital loom
#

I forgot

vocal sleetBOT
vital loom
#

how do u work this out

#

wait shit

#

thats just 0.3 x 80

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๐Ÿคฆโ€โ™‚๏ธ

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

thorny rain
#

How do i do this

vocal sleetBOT
lone linden
thorny rain
#

thanks

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vocal falcon
#

Anyone know how to do this?

vocal sleetBOT
vocal falcon
#

specifically 35)

vocal sleetBOT
#

@vocal falcon Has your question been resolved?

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mighty stone
vocal sleetBOT
#

@mighty stone Has your question been resolved?

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Available help channel!

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

hot heath
vocal sleetBOT
hot heath
#

Confused on what I need to do here

vocal sleetBOT
#

@hot heath Has your question been resolved?

vocal sleetBOT
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Available help channel!

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

desert glen
#

can someone help me figure out how to algebraically solve this limit

desert glen
#

the main thing thats messing with me is that x is an exponent

crude arrow
desert glen
#

im honestly not sure

crude arrow
desert glen
#

oh

crude arrow
#

what is x in this case

desert glen
#

the n

crude arrow
#

2 lol

desert glen
#

oh

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yeah lol

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i was looking at the n

desert glen
crude arrow
#

well now you seen it

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you get it?

desert glen
#

yes

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i guess thank you lol

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

naive heron
#

The square root of 416-210i can be expressed as a+bi, where a and b are integers. Find a and b, without a calculator or computer.

naive heron
#

and im confused on that specific step

tawny nacelle
#

okay, note that we should have (a+bi)^2 = 416 - 210i

#

that's the first thing we should observe

tawny nacelle
#

if not, I can elaborate

naive heron
#

yeah, but doing that seems like a lot of work is there a better solution

#

as a mathematician im lazy

tawny nacelle
#

I can't think of a better way...

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there might be one, but this method is what I would do personally

naive heron
#

the fact that the solution didn't even explain this means there is a really easy solution im ignoring

sharp frost
#

a^-b^2= 416

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2ab=-210

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That's it

naive heron
#

that causes a billion complicated square roots

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remember we dont have calc

tawny nacelle
#

tbf, it's not that complicated

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you can just substitute and solve

#

oh, wait

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you don't have a calculator

#

ahhh

naive heron
#

not even 4 func

tawny nacelle
#

my apologies; I don't know of any other method to solve this bearlain

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maybe somebody else will come by and help you out

naive heron
#

hm okk dw its a hs math comp problem

#

ping me if someone appears

sharp frost
naive heron
sharp frost
#

?

naive heron
#

calculator is not allowed

sharp frost
#

We know ab, and a^2-b^2

#

Sub b as -105/a

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You'll get a quadratic equation

sharp frost
naive heron
#

i have a 12 min time limit to do this problem

#

if i were to do this problem on a test

#

so that does not work

sharp frost
#

I see

#

Square root of 217156 will take at least a min to find

#

Hmm, but idk if there is a easier method

vocal sleetBOT
#

@naive heron Has your question been resolved?

naive heron
#

<@&286206848099549185>

#

question is find square root of 416-210i WITHOUT A CALCULATOR, given result is in the form of a+bi where a and b are integers

vast shale
naive heron
#

don't just give me the answer pls explain because im self studying this isnt homework lol

hybrid flicker
#

you have 2ab = -210

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so ab = -105

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find divisors of 105

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since a,b are integers

#

they're divisors of 105

naive heron
#

where a^2-b^2=416

#

ohhhh

#

OHH then you have 21,5

hybrid flicker
#

it's a good candidate

naive heron
#

a=21 b=-5 or a=-21 and b=5

hybrid flicker
#

though it's not the only one, you can start with those

vast shale
naive heron
#

wait thats literally the solution

#

tysmmmmm

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crisp zenith
#

I am a bit confused on this question

vocal sleetBOT
crisp zenith
#

What I did was use the fact that the unit vector is <cos(2pi/3), sin(2pi/3)>

#

then multiplied that by 14

#

so I'd have got 14(-(1/2)i + (sqrt(3)/2)j )

#

which would give me the components -7, 14sqrt(3)/2

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I also tried it with pi/3

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which would just make the 7 positive

#

but it was still wrong

#

any thoughts?

sweet flower
#

So just flip your i j components around?

vocal sleetBOT
#

@crisp zenith Has your question been resolved?

crisp zenith
#

was given a similar one after exhausting my attempts ill let you know if I get it

crisp zenith
crisp zenith
#

Got this one right

crisp zenith
vocal sleetBOT
#

@crisp zenith Has your question been resolved?

vocal sleetBOT
#

@crisp zenith Has your question been resolved?

vocal sleetBOT
#

@crisp zenith Has your question been resolved?

vocal sleetBOT
#
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vocal sleetBOT
#
Available help channel!

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Remember:
โ€ข Ask your math question in a clear, concise manner.
โ€ข Show your work, and if possible, explain where you are stuck.
โ€ข After 15 minutes, feel free to ping <@&286206848099549185>.
โ€ข Type the command .close to free the channel when you're done.
โ€ข Be polite and have a nice day!

Read #โ“how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vast shale
#

I need help deriving this: (I have always find it difficult deriving things with a square root of or similar things like that)

vast shale
#

I first got it to 0,5 (2x-1)^-0,5

#

But that is of course wrong

#

on my answersheet is says:

brisk tinsel
#

,,\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}

twin meteorBOT
brisk tinsel
#

and chain rule from there

vast shale
#

I need to check what you mean, because I am not familiar with the english terms of stuff. Hold up

small quarry
#

umm

#

composite function is like f(g(x))

vast shale
#

I guess I don't really know?? Because I am quite new to drivative

small quarry
#

ye just show the formula

#

he will know how to do

#

Note that F(x) = f(g(x))

#

ok I let you to help him then

vast shale
#

I am hella confused right now. There is so many helping rn ๐Ÿฅฒ

river kettle
#

๐Ÿ˜ฎโ€๐Ÿ’จ

vast shale
#

Apparantly not

small quarry
#

lol

vast shale
#

I cannot prosses anthing hahhaa, why is there new people coming here

#

Where did you get g(x)

#

you mean this?:

#

then no I do not get it

#

Oh okay, then I am mixing stuff uf

#

up

#

Yeah okay

twin meteorBOT
vast shale
#

I am trying to process the information

#

okay I got

#

Yeah I figured it out rn

#

4x would be the derivative for it?

#

righhtt??

#

And how is that done

twin meteorBOT
vast shale
#

But how do you seperate them?

twin meteorBOT
vast shale
#

But 22x is not the same as 4x or am I trippin

#

oh okay

atomic pine
#

h'(g(x)) is simply defined as h' exaluated at g(x), i think u meant to set f(x)=h(g(x)) and use f'(x) rather than h'(g(x))

vast shale
#

Ngl this made me kinda more confused. Is there any server where someone can help you with vc, because I do not understand this though text. It looks so weird.

#

really?

#

yeah sure, let me just get my mic

vocal sleetBOT
#

@vast shale Has your question been resolved?

#
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vast shale
#

i dont understand why mod 16 is used here

vocal sleetBOT
vast shale
#

im under the impression binary is mod 2

brisk moss
#

for the last digit, sure

#

but think about how in base 10, the last 2 digits are given by the number mod 100

#

and the last 3, mod 1000

#

it's similar here just with powers of 2 instead of powers of 10

vocal sleetBOT
#

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sudden compass
#

does there exist a function which has the property $f(0) \to \infty$ and $f(1) \to - \infty$ or vice versa?

sudden compass
#

I dont really care about its values in between 0 and 1, or beyond 0 and 1, or continuity in general

kind wadi
#

can a function ever equal infinity

fervent wasp
#

No there isnโ€™t

brisk moss
#

how can that be a real valued function

#

real valued function means the codomain is a subset of R

sudden compass
sudden compass
fervent wasp
#

The definition of a function is whenever you plug in a certain value, it gives you an another in feedback

twin meteorBOT
#

rakยณen

vast shale
#

yeah why not ?

hard atlas
#

sure, f:{0,1}->{infty, -infty} given by your two points. thats a function

lavish river
#

waw

sudden compass
brisk moss
#

are you asking for a function $f:\bR\setminus{0,1}\to\bR$ such that $\lim_{x\to 0}f(x) = \infty$ and $\lim_{x\to 1} f(x)= -\infty$

twin meteorBOT
#

slayla

sudden compass
#

the $R \setminus{0,1}$ isn't necessary

twin meteorBOT
#

rakยณen

kind wadi
#

,w interpolate infinity, -infinity

hard atlas
brisk moss
#

it seems like it is...

hard atlas
#

function and "formula" arent the same things either

kind wadi
sudden compass
brisk moss
vast shale
#

something like tanx
maybe ?

hard atlas
#

look, its not my fault that you wrote a question but you actually meant a different question. this is an exercise about being precise about what you want

brisk moss
#

so you want a function $f:\bR\to\bR$ such that $\lim_{x\to 0}f(x) = \infty$ and $\lim_{x\to 1} f(x)= -\infty$

twin meteorBOT
#

slayla

sudden compass
#

Yeah

hard atlas
#

you can easily have 1/|x| for the x->0 and -1/|x-1| for the other one

hard atlas
#

and then build something piecewise between those

#

but presumably thats not closed form enough?

sudden compass
#

I see..any other ideas?

sudden compass
#

it just doesn''t look good to me ๐Ÿ˜

brisk moss
#

some rational function probably works

#

and you can define f(0) = f(1) = 0 or whatever

#

if you want the domain to be R

hard atlas
#

$\frac{1}{x^2}-\frac{1}{(x-1)^2}$

twin meteorBOT
#

Denascite

sudden compass
#

o that looks nice

hard atlas
#

of course if your closed form is supposed to include f(0) and f(1) then you are a bit fucked

#

cause most things we can write down are continuous

sudden compass
sudden compass
#

well thank you for all the ideas everyone

#

.close

vocal sleetBOT
#
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bitter sequoia
vocal sleetBOT
bitter sequoia
#

hi! could someone please explain how to solve this question?

#

without a calculator

pale perch
#

1/2 ab sin(c)=7.5

hidden bloom
#

let's set cosA=-0.8

bitter sequoia
#

yup

hidden bloom
#

then,A is obtuse angle

#

right๏ผŸ

bitter sequoia
#

wait why?

hidden bloom
#

cosA<0,agree?

bitter sequoia
#

yes

hidden bloom
#

so b=c

bitter sequoia
#

ahaa

#

yes

hidden bloom
#

S=1/2bcsinA=7.5

#

and

#

sinA=0.6

#

and

#

b=c

bitter sequoia
#

how is sinA 0.6

hidden bloom
#

so you can solve it

#

sinA^2+cosA^2=1

hidden bloom
bitter sequoia
#

yess i got it

vocal sleetBOT
#

@bitter sequoia Has your question been resolved?

vocal sleetBOT
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graceful spoke
#

J is the midpoint of line segment HL. I and K are on HL such as that HI = IJ and JK = KL. what percent of HI is HK

left sparrow
#

Draw it out

vocal sleetBOT
#

@graceful spoke Has your question been resolved?

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@graceful spoke Has your question been resolved?

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gentle kayak
#

Hi, I have an exercise like this:
The sides of the triangle are 15 cm, 18 cm, and 21 cm. The triangle is cut by a line parallel to the shortest side, forming a trapezoid whose shorter base is 10 cm. Calculate the perimeter of the trapezoid.
I made a drawing of it and got the shorter base of 10 and the longer base of 15, but how am I supposed to find the other 2 sides? :)

tranquil trellis
#

since the line you drew to make the triangle is parallel to one of the sides, it'll create a smaller similar triangle

gentle kayak
#

like that

tranquil trellis
#

don't draw a separate diagram for the trapezoid

gentle kayak
#

hmmm

#

imma need to brain for a sec

tranquil trellis
#

this triangle is similar to the original one

#

so you might want to draw it a bit bigger

gentle kayak
#

so it's similarity

#

my brain doesn't take it

tranquil trellis
gentle kayak
#

yeeah I do

tranquil trellis
#

or you're just not sure how to continue given that they are similar

gentle kayak
#

yeah im not sure how to continue

tranquil trellis
#

So you're given the smaller base of the trapezoid is 10

gentle kayak
#

correct

#

that gives me the value of one side of the smaller triangle, doesn't it?

tranquil trellis
#

yes

#

so the side ratio of these similar triangles is 10:15, or 2:3

gentle kayak
#

wait

#

yeah

#

but what next?

tranquil trellis
#

so the top side is 18, the bottom side is 21

#

what are 2/3 of each of those

gentle kayak
#

2/3 of 18 is 12 and 2/3 of 21 is 14

#

so 12 and 14

#

oh

tranquil trellis
#

okay so what are the two other sides of the trapezoid then

gentle kayak
#

well 18-12 = 6
and 21 - 14 = 7

#

niiice

#

6+7+10+15=38

tranquil trellis
gentle kayak
#

thanks ๐Ÿ˜‡

#

.close

vocal sleetBOT
#
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opal flare
#

Set $I := [0, 1]$, denote the set of continuous real valued functions on I by $C(I)$, let d1 be the L1 metric on C(I), and let d2 be the supremum metric on C(I). Are d1 and d2 equivalent? prove your answer.

I know that they are equivalent iff for every $x \in X$ and ${xn}{n=1}^\infty \subset X$ we have $x_n \overset{n} \to x$ in(X,d1) if and only if $x_n \overset{n}\to x$ in(X,d2).

I feel like it should be false, and there should be some example, but not sure how. Any help?

twin meteorBOT
#

mtr123

round plover
#

I think if you take the constant zero function, then define f_n to be a piecewise linear "spike" of height 1 and width 1/n (and is zero outside of the spike), then the supremum distance between them will always be 1, but you can make the L1 distance arbitrarily small

#

in the supremum metric, (f_n,0) -> 0, so there is no constant C such that C d_2(f_n,0) <= d_1(f_n,0) so they're not equivalent metrics

#

basically, any pair of functions that bound vanishing area between them but remain at least a fixed distance apart at some point should work as a counterexample

vocal sleetBOT
#

@opal flare Has your question been resolved?

opal flare
#

and not that C constant you used here

round plover
#

oh, topological equivalence

#

I was using lipschitz equivalence I think

opal flare
#

I saw that defintion too online

#

but that's not what I got to work with sadly haha, it looks easier

round plover
#

lipchitz is stronger than topological though ๐Ÿ˜ญ

opal flare
round plover
#

can you just say that the metrics are topologically equivalent iff the same sequences converge?

opal flare
#

well I'm suppose to prove that in another question ๐Ÿ˜›

round plover
#

since you can define convergence purely in terms of open sets, if they're topologically equivalent, they'll have the same set of convergent sequences

#

๐Ÿ˜ญ

opal flare
round plover
#

oh, well

#

that's before this question

#

so if you prove that first you can use it ๐Ÿ™‚

opal flare
#

just need to figure out how to construct those spikes ๐Ÿ™‚

round plover
#

how's this

opal flare
#

that was quick lol

round plover
#

I knew I had it lying around somewhere

#

I think the argument might be clearer if you have the spike centred on 1/2 constantly though

#

but the modification should be similar

opal flare
#

I think it gonna be easier for me to just use this one honestly

#

thanks ๐Ÿ™‚

#

Just need to prove that other question now haha

#

.close

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#
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round plover
opal flare
round plover
#

.close

vocal sleetBOT
#
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opal flare
#

thank you @round plover

round plover
vocal sleetBOT
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austere arrow
vocal sleetBOT
#

Please don't occupy multiple help channels.

austere arrow
#

can i get some help please

#

im sorry

#

i cant think about it

#

can i get some help by you , please?

#

@ebon silo

#

oh yeah ik that

#

just that , in bulgaria its explained diffrently

#

(x-1) (x-1)-1

#

down its (2-x)(2+x) am i right

#

oh thanks

#

(x-1)(x-1)-1

#

(2-x)(2-x)

#

(x-1)^2

#

same thing

#

x^2 - 1^2

#

?

delicate oracle
#

she means make it a trinomial

austere arrow
#

I dont understand what trinomal means thats the thing

#

Not my first launglage

#

sorry abt that

delicate oracle
austere arrow
#

im lost

#

thanks for the help , god bless

delicate oracle
#

no

#

don't go

#

wait

austere arrow
#

okay

#

tha thing is

#

i know the stuff

#

just cant understand the way to do it

#

thanks for the help

#

yes but in a different way

#

wait

#

idk about the convertion right at the top tho

#

oh wait dw about it

#

i missundestood

#

so it becomes x(x-1)

#

x^2 - 1

#

no wait

#

x^2 - x

#

got it

#

let me solve the entire thing

#

(2-x)^2 is 4-x^2

#

right

delicate oracle
#

sorry am back got banned for some reason

delicate oracle
austere arrow
#

wait really?

delicate oracle
#

4-2x+x^2

#

squared of the first term

#

multiply everything inside the bracket and then ny the exponent which is 2 the square the second term

delicate oracle
#

understand?

austere arrow
#

yes

#

thank you

delicate oracle
#

u sure

#

100% understand

austere arrow
#

not reallyisleep

#

jk jk

#

yes bro

delicate oracle
#

alr

austere arrow
#

i know the formula

delicate oracle
#

good luck

austere arrow
#

wait

#

one more thing

delicate oracle
#

okay

austere arrow
#

what was the formula when +

#

this one

delicate oracle
#

second term?

austere arrow
#

ik i can use a calculator

#

but i dont want to

delicate oracle
#

don't use 1

#

are u talking about x+1

austere arrow
#

the thing i just send

delicate oracle
#

ther's 3 + signs

#

which 1 are you talking about

austere arrow
#

the entire thing

#

i gotta go tho

#

tommorow

#

im going to tell what i got on my exam

delicate oracle
#

lemme solve and give u

austere arrow
#

ok thanks

#

imma be back in a seccond

random musk
#

x=2

delicate oracle
#

he gone

vocal sleetBOT
#

@austere arrow Has your question been resolved?

austere arrow
#

im here

austere arrow
#

on discord

#

i have to ask u something

#

@delicate oracle check dms

#

.close

vocal sleetBOT
#
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low trail
#

Hey, I completely don't know how to do this. Someone is able to explain more or less exactly how to do it?

vocal sleetBOT
#

@low trail Has your question been resolved?

worn bobcat
#

well have you computed the length of v cross w?

#

that's where I would begin

low trail
#

I didn't count

vocal sleetBOT
#

@low trail Has your question been resolved?

low trail
#

<@&286206848099549185>

#

.close

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#
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undone aurora
#

I just want to make sure that im on the right path so this is what I got for one of the cases:

Case 1: 3, 4, 5, 6, 7 (3 to 7 diamond) (discard 5) need 1 of each

undone aurora
#

Honestly u dont even have to read the question

#

the second, third, fourth image is enough

#

oh also in the 4th image I meant to divide all of that by (26C5)

#

but basically this is what I was thinking

#

Ik we need 1 of each for case 1 because we dont have any of those cards in the hand

#

so to get atleast 1 3 diamond the prob would be

(3C1)(3C1) (3 cards to choose 3 from)(3 suits to choose diamond 3 from)

#

oh wait is it suppose to be all of them multiplied instead of adding each

#

because we need 1 of each not 1 of 3 or 1 of 4 and so on

jolly flame
#

dude balatro isnt that hard

undone aurora
jolly flame
#

(i dont know math sorry) < i just always build 2 pair

undone aurora
#

i dont even play poker I just discovered abt this recently

vocal sleetBOT
#

@undone aurora Has your question been resolved?

undone aurora
#

<@&286206848099549185>

undone aurora
#

smh

#

.close

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#
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elfin pendant
vocal sleetBOT
elfin pendant
#

Why is this bijective?

vocal sleetBOT
#

@elfin pendant Has your question been resolved?

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#

@elfin pendant Has your question been resolved?

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@elfin pendant Has your question been resolved?

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#

@elfin pendant Has your question been resolved?

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leaden crane
#

How would I do this problem?

vocal sleetBOT
#

@leaden crane Has your question been resolved?

leaden crane
#

<@&286206848099549185>

civic otter
#

Do you know slope-point formula?

#

$$y - y_P = m(x - x_P)$$

twin meteorBOT
#

Alberto Z.

civic otter
leaden crane
#

I see

#

y-(-10) = -5(x-(-14))? @civic otter

civic otter
#

Yes

leaden crane
#

that gives me y=-5x-80

#

then we sub in (1+t) for x?

#

y=-85-5t

civic otter
#

Yep exactly

leaden crane
#

Easy enough, what would happen if there's two points though and no slope? @civic otter

brisk moss
#

and you can get another equation from the other point and determine m and b

#

if you are given slope, you can just put that right in for m and then determine b with a point on the line

#

you don't have to remember different "forms" for writing lines if you do it like this

leaden crane
#

I see, okay

#

so 17=m(-2)+b

#

do i solve for b or m?

brisk moss
#

either works but probably easier to solve for b because no fractions

leaden crane
#

fair

#

b=2m+17

#

with that, what's the next step?

brisk moss
#

(15,6) is also on the line so we have 6 = m*15 + b as well

leaden crane
#

right

#

b=-6m+15

brisk moss
#

sorry i messed that up

leaden crane
#

ah that makes more sense

#

b=-15m+6

brisk moss
#

yep

leaden crane
#

what shall i do next?

#

the only thing i can think of is setting both b's to each other lol

brisk moss
#

yea you can do that

#

if you mean put -15m+6 = 2m+17

#

fuck

#

sorry messed that up again lol

leaden crane
#

yeah, that's what i meant

brisk moss
#

you can solve for m from there

leaden crane
#

m=-11/17

brisk moss
#

yep

#

now you can determine b from b=-15m+6 or whatever

leaden crane
#

would i need to do it to both?

brisk moss
#

you can use either equation but don't need to use both

#

they should give the same thing

leaden crane
#

ah

#

267/17 is what I got

brisk moss
#

yea that's right

#

sooo you have y = -(11/17)x + 267/17

leaden crane
#

then i just plug in 3+t for x

#

hmm, any ideas? @brisk moss

#

I've tried that +

#

$\frac{1308}{119}-\frac{11}{7}t$

twin meteorBOT
#

Someone

brisk moss
#

yea it appears we made an algebra error somewhere

#

i take that back, we did not make an algebra error

brisk moss
brisk moss
#

for like the 3rd time

#

sorry lol

leaden crane
#

xD

#

ahh that's it

#

lemme resubmit, one sec

brisk moss
#

sorry i was never any good at algebra

leaden crane
#

xD all good, i'm not either

#

thank you so much for your help!

brisk moss
#

np :3

leaden crane
#

.solved

vocal sleetBOT
#
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vocal sleetBOT
#
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vast shale
#

Can anyone help me with antiderivates that consist of trignometry?

lavish river
#

just ask the question

vast shale
#

How to solve this

heavy yoke
#

u-substitution?

vast shale
heavy yoke
#

as in you haven't learned substitution or you don't know what to substitute?

vast shale
#

I have learned substitute

#

Let u be โ€ฆ

#

And du โ€ฆ

#

Sinxcosx is 1/2 sin2x

heavy yoke
#

a good place to start is usually something in the denominator

vast shale
#

Cos^2 2x is U?

#

U squared?

heavy yoke
#

you can try that (or something similar) and see if it works

vast shale
#

In my cb it is like that ok

#

What abiut du

#

The numerator is 1/2 sin2x

#

How did he solve that

#

<@&286206848099549185>

#

Where did he get the 4 from

#

1/4

#

Helppp

grand linden
#

What is written in the denominator?

#

@vast shale

twin meteorBOT
#

jandro

grand linden
#

?

twin meteorBOT
#

jandro

grand linden
#

Use this formula

#

With

twin meteorBOT
#

jandro

#

jandro

grand linden
#

I think your doubt Is this

twin meteorBOT
#

jandro
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

#

jandro

#

jandro

grand linden
#

At n=-2

#

So

#

$\to -\dfrac{1}{4}\cdot\left(-\dfrac{1}{u}\right)=\dfrac{1}{4,u}$

twin meteorBOT
#

jandro

grand linden
#

Substituting backwards

twin meteorBOT
#

jandro

#

jandro

grand linden
#

So the result is

twin meteorBOT
#

jandro

vast shale
#

Thank you dude

#

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vocal sleetBOT
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vocal sleetBOT
urban snow
#

I suppose it's because sqrt(-6) is an imaginary number, so you can't really compare it to a real number in the real plane

#

I'm not exactly sure what you mean by the square root should be as well

#

Yea, good analysis, if f(x) is never negative then the square root of f(x) is also defined for the domain of f(x)

#

By solving it algebraically are you referring to quadratics only or other functions too?

#

Well you can't always solve for the variable in every radical equation, i mean technically you can but it might not always be real. Functions like radical quadratics and quintics for example don't always go below the x axis so all x values work

#

Just know that if you ever get an imaginary value that means either it's domain is all x values or no x values

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jagged cargo
#

Given $f(x)$ differentiable and positive on $(0,+\infty)$ such that [
f(x)\ln f(x)=x(2f(x)-f'(x)),\forall x \in(0,+\infty)
]
Given $f(1)=f(3)$, calculate $f(2)$

twin meteorBOT
jagged cargo
#

not sure how to approach this

vocal sleetBOT
#

@jagged cargo Has your question been resolved?

cobalt crypt
twin meteorBOT
jagged cargo
#

hm, thats smart

#

alright let me try, ill notify when i encounter another problem

#

thanks!

#

.close

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#
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vocal sleetBOT
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tender anvil
vocal sleetBOT
#

@tender anvil Has your question been resolved?

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arctic patio
vocal sleetBOT
arctic patio
#

Why is the angle 90 - alpha?

heady ibex
#

because the total angle at X is 180

#

wait actually

#

they don't show anything about reflection

#

if the incoming and outgoing rays are parallel that would make sense

arctic patio
#

I get it

#

Yeah they are parallel I just saw it

heady ibex
#

if they aren't then it cannot be correct

arctic patio
#

Have a good night

#

.close

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#
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vocal sleetBOT
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daring marsh
vocal sleetBOT
daring marsh
#

I just need to check the rule on this

#

2^log2 cancels each other out?

lone linden
#

$2^{\log_2 x}=x$ for $x>0$ if thatโ€™s what youโ€™re asking

twin meteorBOT
#

Civil Service Pigeon

daring marsh
#

what does that mean exactly

lone linden
#

?

daring marsh
#

for x>0

#

so I cancels out so long as I add the it to other side?

#

idk what the formula means

lone linden
daring marsh
#

Okay I see

lone linden
daring marsh
#

Okay I see

#

thx cs pigeon

#

.clolse

#

.close

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#
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lone linden
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frank pier
#

hiii i need help , it's to do with basic logs but im kinda confused lol

frank pier
#

heres the problem

tidal dock
#

yes/no

frank pier
#

no

tidal dock
#

$x^3 = 3x$

twin meteorBOT
#

artemetra

tidal dock
#

no idea how to do this?

frank pier
#

do u do 3logx=3x?

tidal dock
#

let's use t as the variable to not confuse the names

#

yes, i let t = log(x)

#

so what you get is t^3 = 3t

#

now, solve for t

#

hint: move 3t to the other side and factor

lethal heart
frank pier
#

uh. t^2=3?

tidal dock
lethal heart
#

0=0

tidal dock
#

so if t is NOT 0, t^2 = 3 applies

frank pier
#

would u square root 3 at the end?

tidal dock
#

yes, $\pm$

twin meteorBOT
#

artemetra

crude arrow
lethal heart
#

I saw

tidal dock
#

no need to rush

tight orchid
crude arrow
#

pprob shouldn't have used x

#

but it's wtv

lethal heart
#

Ok I found a way to do it

tight orchid
#

I suggest to start by bringing the right side to the left, and then take one common log as a factor

tidal dock
#

that's what i did broski

crude arrow
#

you shouldn't have used x

#

lol

#

but anyway

tidal dock
frank pier
#

uh

#

๐Ÿ˜ญ

tidal dock
#

i thought OP was confused by the use of t

lethal heart
#

Bringing the 3x to the left and factoring?

tidal dock
#

you should have that $t = 0, \pm\sqrt{3}$

twin meteorBOT
#

artemetra

frank pier
#

yes

tidal dock
#

awesome

frank pier
#

but wait why there 0 as well?

tight orchid
#

ah, sorry guys, didn't understand that you substituted originally, thought you just wanted to cancel out the logs

lethal heart
#

$x\cdot(x^2 -3)=0$

twin meteorBOT
#

Gordon Ramsey

lethal heart
#

Is this right?

tidal dock
#

can i just help on my own guys

lethal heart
#

Okay

#

Sorry