#help-17
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oblique wolf
i got 9 just wanna check
hushed pewter
!show
vocal sleetBOT
Show your work, and if possible, explain where you are stuck.
oblique wolf
!show
vocal sleetBOT
Show your work, and if possible, explain where you are stuck.
vocal sleetBOT
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rustic chasm
hello
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vast shale
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vast shale
genuinely have no idea how to get x
since no other information is given
theres a quadrilateral
look closely
wait actually nvm
are the lines that r drawn there given or u just made them
dull bear
(You may want to think about the angles within ADEF: you can label them all with one variable)
vast shale
are the lines that r drawn there given or u just made them
they are given
original pic
hushed pewter
since no other information is given
you are incorrect. Some equal lengths are marked, you can use isosceles triangle properties
vast shale
but in order to use isosceles triangle properties i have to find atleast one of then angles
BFC=30, BCF=90, EFB=45
hushed pewter
Use unknowns
vast shale
i cant find EBF since EF and EB are not equal
vast shale
if DEF=y, EDF would be 180-y/2 and i cant do much with that info😭
vast shale
180-x???
vast shale
x/2?
vast shale
180-x/2
vast shale
75-x/2
vast shale
the same as DFA
vast shale
would i make an equation like 2(75-x/2)+ 180+x/2=180
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waxen sonnet
Where did I make a mistake here
waxen sonnet
Okay so I changed it to be ln7 instead of log7 but still got the wrong answer
lone linden
$35e^{-2k} \neq (35e)^{-2k}$
twin meteorBOT
Civil Service Pigeon
waxen sonnet
What
lone linden
Your equation is $7 =35 \cdot e^{-2k}$
twin meteorBOT
Civil Service Pigeon
lone linden
so you need to divide both sides by 35 before you take the log
b/c the base is only the e, the 35 isn't included
waxen sonnet
Okay thank you
vocal sleetBOT
@waxen sonnet Has your question been resolved?
vast shale
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vast shale
How do I solve this
I wasn’t there in class those answers are from someone else imagine it was blank lol
random solstice
I wasn’t there in class those answers are from someone else imagine it was blank...
So, do you know why the person who sent this circled those points on the graph?
vast shale
-2, -1, 1, and 2.5 are all local extrema?
random solstice
Yes. Why?
random solstice
No
Like a local maximum is a maximum because locally everything closer to it is smaller
vast shale
ahh ok
random solstice
Like look at x = -1. Locally it is just the biggest one
It turns out that this is the same as saying the tangent line is flat at that point
So ur curve idea is kind of correct lol
Anyways that's how you get (a)
random solstice
Do you know what an inflection point is?
vast shale
ik inflection points are in between concavity
and ik how to find them with functions*
i just dont know with graphs
vast shale
-1.5?
random solstice
You wouldn't know the actual value
and the function has a shape of an upwards U, right? So it would be concave up
random solstice
-1.5?
Oh yeah this would be the inflection point (x value)
Sorry i misunderstood what you answered
That's because it change from upwards U to downwards U around that point
vast shale
yeah
so it would just be -1.5, 0, and 2?
so the middle between the 2 Us would be the inflection points
?
.close
bleak ginkgo
how is this gguy cancelling 2^x and 2^-2x i dont think that should wrork
desert hornet
bleak ginkgo
vocal sleetBOT
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mystic hare
Help guide me do this
vocal sleetBOT
Help guide me do this
river minnow
Have you tried factoring the numerator and the denominator?
frank bison
Help guide me do this
(a+b)(a-b) = a^2 - b^2
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@mystic hare Has your question been resolved?
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quaint coral
looking for help on 8a
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looking for help on 8a
fading plume
i'd say step 1 is multiply the whole thing by (x-2)
quaint coral
n then
fading plume
simplify and show what you get
fading plume
(x-6)(x-3)/x-2
i believe this is good
fading plume
your zeroes are right at least
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languid tapir
Hey I have a basic question is value of any trignometric function in -ve degrees equal to its value if degrees was positive? for example is sin(-x)=sin(x) and for all other trigonometric ratios?
vocal sleetBOT
Hey I have a basic question is value of any trignometric function in -ve degrees...
safe wharf
nope only true for cos iirc
vast shale
and sec
safe wharf
yeah
languid tapir
sorry i do not understand it ,we were just told how to find them out using graph, which quadrant has what positive
nvm i have class tomorrow just gonna ask the teacher thank you for the help though at least i will be able to attempt the questions
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languid tapir
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brazen depot
Im looking for a sequence of elements (functions) in the space C([0,1]) (so continuous that is) that satisfies two conditions: the supremum norm ->inf and the 1 norm (abs integral in the interval) ->0 for n-> inf. My idea is a triangle function with peak in 1/2 so something that kinda approaches dirac delta distribution (shifted by 1/2). So something like n^2(1-n^3|x-1/2|) with f(x)= 0 if the former is negative. Im not sure wether this properly converges though and wolfram alpha is of no help, because of the specific conditions
vocal sleetBOT
Im looking for a sequence of elements (functions) in the space C([0,1]) (so cont...
vocal sleetBOT
@brazen depot Has your question been resolved?
brazen depot
<@&286206848099549185>
granite cloud
<@&286206848099549185>
?
brazen depot
The question is whether it will work with the specified function or alternative solutions
vocal sleetBOT
@brazen depot Has your question been resolved?
vocal sleetBOT
@brazen depot Has your question been resolved?
vocal sleetBOT
@brazen depot Has your question been resolved?
edgy sapphire
Im looking for a sequence of elements (functions) in the space C([0,1]) (so cont...
yea it makes sense to me that a delta-like thing should work if it's thin enough
brazen depot
In order to prove that the integral is 0 I would split the integral up and only evaluate where the function is 0 and then let the upper and lower bound respectively converge alongside the spike
Would that work?
edgy sapphire
In order to prove that the integral is 0 I would split the integral up and only ...
I think the function you gave goes negative really fast and become negative infinity, but just like have a triangle that hits (0,0) and (1,0) that rises half as fast as it horizontally shrinks so the area is like 2^-n and goes to 0
brazen depot
I defined the function to be 0 whenever the expression would be negative
vocal sleetBOT
@brazen depot Has your question been resolved?
spiral turtle
So the Dirac delta would have a regular integral of 1, so a 1-norm of 1 as well.
What if you made a function sequence with the following property. It is a box function parameterized as follows. The width is 2^-n and the height is n, centered on 1/2. This would have an area of n 2^-n which goes to 0 as n -> inf
@brazen depot ^
You don't need anything negative, and negative doesn't help because it's abs integral
sonic laurel
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sonic laurel
lost on why this is a and not c
rugged orchid
How can you get a negative number
sonic laurel
-5 x -5 = 25
rugged orchid
What’s the square root of 25
rugged orchid
Not unless you know about Complex numbers
vocal sleetBOT
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tulip osprey
how do i find height here
vocal sleetBOT
how do i find height here
tulip osprey
of the trapezium
vertical height not slant height
i have both bases and both slant heights but problem is i have the whole base not just of one side
fading plume
is that a right triangle with hyp = 9.49?
tulip osprey
yes
okay nvm i couldnt figure it out for 2 hours just realized i can use sin rule
cause i have the right angle there
thanks
.close
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vocal sleetBOT
Differential calculus
rugged orchid
Can you find f’
tender solar
,rotate
hasty pulsar
apply the rotation matrix to it
sturdy quarry
i think i can
solar needle
apply the rotation matrix to it
so apply $\begin{bmatrix}0&-1\1&0\end{bmatrix}$ to the whole thing?
twin meteorBOT
Ham
hasty pulsar
yeah theta=-90
vocal sleetBOT
@ivory otter Has your question been resolved?
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placid osprey
In how many ways can 3 apples and 4 oranges be distributed to 6 students?
white whale
In many ways /jk
What is the restriction?
white whale
Don't show the answer first, please?
placid osprey
@dark kiln
I know it's stars and bars method
But don't know how to setup the equation
Is 6 on the RHS, and x1, x2, etc. on the LHS?
dark kiln
x1 x2 is apples that you give to student 1,2...
placid osprey
what's the stars portion here
dark kiln
apples
placid osprey
so (5+3-1, 3)?
vocal sleetBOT
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sick swan
What do i do with x?
sick swan
Oop srry
flint idol
u=x^2-4, so u+4=x^2
we sub u+4 for x^2
and then we can just apply normal power rule
flint idol
yw!
sick swan
Got it
I'll just have to compute the definite
Int
Forgot to put the lower and upper bound
Anyways, i got it now
royal grove
vocal sleetBOT
royal grove
What do they mean? I cant understand. Can someone explain please?
brisk cloak
yeah i think thats what they mean too
basically to write it in the form of (x-a)(x-b)
royal grove
thats all?
brisk cloak
because its two linears that multiply into a parabola
i mean dont take my word for it, if it makes sense to you as well then go for it
again, crappy english
idk
viral copper
basically to write it in the form of (x-a)(x-b)
thats the only interpretation i can think of when they say "2 lines"
royal grove
why are they referring it to as "2 lines"
brisk cloak
because if you put each of the factors in a graph by itself then it represents a line
royal grove
Aaahhhhhh
makes sense okay
yea
linear factors
thats what you said in the start
i am a bit dumb sorry
iron parrot
Let $z$ be a complex number with $|z|=2$. Let $P$ be the polygon in the complex plane whose vertices are $z$ and every $w$ such that
[\frac{1}{z+w}=\frac{1}{z}+\frac{1}{w}.]Find the area enclosed by $P.$
vocal sleetBOT
Let $z$ be a complex number with $|z|=2$. Let $P$ be the polygon in the complex ...
twin meteorBOT
Dork9399
vocal sleetBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
bro idk where to start
i mean maybe we can sub z = a+bi and w = c=di
but that seems to complicate the problem like way too much
vocal sleetBOT
@iron parrot Has your question been resolved?
shrewd sapphire
hey, i have an idea how to help with it
[\frac{1}{z+w}=\frac{z+w}{zw}]
so we can say that $zw = (z+w)^2$
[zw = z^2 + 2zw + w^2]
[z^2 + zw + w^2 = 0]
twin meteorBOT
Безумный Трактирщик
shrewd sapphire
since $|z| = 2$, we can divide it by $z^2$ and if $x=\frac{w}{z}$, this this equasion turns into this: $x^2+x+1=0$
twin meteorBOT
Безумный Трактирщик
shrewd sapphire
it follows that $x = -\frac{1}{2} \pm i\frac{\sqrt{3}}{2}$
twin meteorBOT
Безумный Трактирщик
shrewd sapphire
or else $x = \cos{\left( -\frac{2\pi}{3} \right)} + i \sin{\left( -\frac{2\pi}{3} \right)}$
twin meteorBOT
Безумный Трактирщик
vocal sleetBOT
@iron parrot Has your question been resolved?
shrewd sapphire
okay, we've got:
[\frac{w}{z} = \cos{\left( -\frac{2\pi}{3} \right)} + i \sin{\left( -\frac{2\pi}{3} \right)}]
[w = z\cos{\left( -\frac{2\pi}{3} \right)} + i \sin{\left( -\frac{2\pi}{3} \right)}]
thus the point $w$ is obtained by rotating $z$ by $\frac{2\pi}{3}$ clockwise and counterclockwise
twin meteorBOT
Mad Tavernkeeper
iron parrot
nice
i got it
i just assumed z = 2
bcuz the way the question is phrased it should work for all |z| = 2
shrewd sapphire
yes
shrewd sapphire
**Mad Tavernkeeper**
P is a regular triangle, inscribed in a circle of radius 2 with the center at the origin
vocal sleetBOT
iron parrot
ty!
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plain aurora
Are constant maps linear transformations?
vocal sleetBOT
Are constant maps linear transformations?
plain aurora
chatgpt says yes, but my proof says no
river minnow
Only if it's the zero map
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@plain aurora Has your question been resolved?
drowsy light
Hey, need some help.
Given a point A=(3,4), determine the coordinates of point B if point S is the midpoint of the segment AB S=(1,5)
finite mist
since S is the midpoint of AB, The coord of B can be obtained by 2 * vector AS
drowsy light
Dont get it
rugged orchid
Try drawing it
hybrid flicker
ok, let AS be the vector between A and S
Since S is halfway between A and B
start from A
add AS
dense jay
take coordinates of b as (x,y) and use section formula
drowsy light
hybrid flicker
you're now halfway from B
add AS again, where are you now?
shadow cliff
i dont think they meant where you live lol
drowsy light
In home
vocal sleetBOT
@drowsy light Has your question been resolved?
elfin terrace
It means axis
vocal sleetBOT
It means axis
elfin terrace
But isn’t conjugate of this hyperbola y=k
So there should be (y-10)^2 in one right?
hushed nebula
,rotate
twin meteorBOT
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@elfin terrace Has your question been resolved?
mortal holly
Hello. I normally can find the area if the curves pass origin. But i don't know what are the limits of the integral for that polar curve and how to find them
vocal sleetBOT
Hello. I normally can find the area if the curves pass origin. But i don't know ...
turbid zodiac
what's the function?
mortal holly
r(\theta)=\theta+\sin(2\theta)
the answer says limits of the integral is 0 and pi but i don't know how to get that answer
mortal holly
i get why is it 0 because it passes origin but i don't know the pi
turbid zodiac
so when u integrate in polar coordinates, ur integrating with respect to the angle usually
mortal holly
and i also don't know why it is zero when it passes origin i just memorized it 😦
mortal holly
so when u integrate in polar coordinates, ur integrating with respect to the ang...
yes
mortal holly
0
turbid zodiac
when theta = π/2, what is r(theta)?
and then can u draw it on a polar graph
and then when theta = π, what is r(theta)?
and draw that on a polar graph
Its more like building intuition of how the curve behaves when theta changes
mortal holly
Ohhhh so when it is pi it just becomes the left side of the x axis
turbid zodiac
ye
mortal holly
and that is the limit
mortal holly
yes r(pi) equals pi
mortal holly
now i see
turbid zodiac
but what happens if for example hypothetically
r(pi) is -pi
then what would that point map to?
mortal holly
but what happens if for example hypothetically
it shades the area in the 3th and 4th quadrants
turbid zodiac
ye
I would say do more curve sketching questions
for r(theta)
for different r(theta)
and u'll build an understanding about what happens
and how to find limits
mortal holly
I would say do more curve sketching questions
i got 17 days to AP calc bc exam and i still didn't start AP statistics so i am just rushing it
turbid zodiac
oh ok
mortal holly
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mortal holly
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mortal holly
sorry for interrupting again but can someone help on this one also?
r(\theta)=1-2\theta
How can i find the limits of the integral of this shaded area
mortal holly
The second is kinda obvious if you look closely
it probably is but i don't know according to what we are deciding the limits of the integral
copper crypt
Wdym
It’s with respect to theta
The question is at what angle do you start and stop
mortal holly
the answer says it's boundries are 1/2 and pi/2
mortal holly
Then it’s wrong lol it should be 3pi/2
can you explain how did you got it?
mortal holly
not at all
copper crypt
The region you care about starts when r is 0
One sec I think you need to understand what you’re summing
You know how in rectangular coordinates you’re summing f(x)dx
That’s cause that’s the area of their rectangles
Width of dx height of f
mortal holly
yes
copper crypt
Here you’re doing basically the same thing like this
Width of d theta, height of r
But that’s the general idea
copper crypt
Well what is the first theta that you want to look at
If you start with Theta = 0 you would have to shade in that other region too
To the right of origin
copper crypt
sorry for interrupting again but can someone help on this one also?
Here
copper crypt
Instead you only start shading when the curve crosses 0
So when r is 0
Which is when theta is 1/2
copper crypt
The curve crosses through the origin when r is 0
mortal holly
The curve crosses through the origin when r is 0
oh yes
that is where we start shading
copper crypt
And r is 0 when theta is 1/2
mortal holly
Cause it doesn’t cross through 2
then how can we get the upper limit?
copper crypt
And if we’re careful, we could notice that it’s actually -2
mortal holly
yes it was not
mortal holly
Yea never use degrees
oh okay
copper crypt
3pi/2
So that’s what I was saying at first
But actually once theta exceeds 1/2, r becomes negative
So it’s actually pi/2, with a negative r
mortal holly
so correct me if i am wrong. Since r is a length and we are summing it it can't be negative. We are taking the clockwise angle instead to make it pozitive
copper crypt
No
R is a length but we can be a bit handwavey
It’s like how we have negative area
copper crypt
So the region is probably negative area cause r is negative for the whole thing
copper crypt
can you explain again why did you take pi/2 instead of 3pi/2
Because uh
Imagine how the point (pi/2,-1) is the same as (3pi/2,1)
In polar cords
mortal holly
yes
it took me a while
but yes
so i have 1 last question
for the lower limit we found it by setting r to zero
in the upper one we used it by the angle
so we can use either way right?
.close
vast shale
vocal sleetBOT
vast shale
I need help with 10
vocal sleetBOT
@vast shale Has your question been resolved?
lime jacinth
i will help
so basically you multiply t by the number of years
-100(2) + 600 = 400
-100(4) + 600 = 200
vocal sleetBOT
@vast shale Has your question been resolved?
lime jacinth
have t on intervals of .5
and have v on intervals of 100
and just graph for the ordered pairs
vast shale
Wdym
lime jacinth
(0.5, 550)
vast shale
What’s intervals
lime jacinth
(1, 500)
vast shale
I don’t get it
lime jacinth
vast shale
What’s this
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vast shale
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raven breach
Quick question. At the bottom with the arrow, how does 4/(-3*f’(2)) =4 turn into -12f’(2)=4?
vocal sleetBOT
Quick question. At the bottom with the arrow, how does 4/(-3*f’(2)) =4 turn into...
vast shale
Quick question. At the bottom with the arrow, how does 4/(-3*f’(2)) =4 turn into...
gang
open a diff channel
raven breach
I legit went to help, opened a channel and this is where it sent me.
raven breach
Also you did .open, to reopen ur channel you need to do .reopen
vast shale
ma fualt
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soft slate
$\sum_{n=1}^\infty \frac{1}{ \sqrt{n} e^{ \sqrt{n} } }$
vocal sleetBOT
$\sum_{n=1}^\infty \frac{1}{ \sqrt{n} e^{ \sqrt{n} } }$
hallow plover
LaTeX sure doesn't wanna respond, eh?
subtle helm
no spaces before/after $
soft slate
i tried to apply direct comparison test with bn being 1/e^sqrt(n) but it doesn't seem to work.
twin meteorBOT
Zalamancer
iron parrot
will this converge?
soft slate
thats what I am asking\
hallow plover
according to numerical computation : yes
soft slate
what test would i use for this
hallow plover
Idk if this is something that can even be done but could you introduce a substitiution like m = sqrt(n) to get rid of the square or something?
I mean the root
soft slate
i don't know what m = means
maybe thats a future topic
but i beleive we could do integration test
soft slate
Idk if this is something that can even be done but could you introduce a substit...
what is the integration of e^-u
hallow plover
you mean in general or?
soft slate
yes
hallow plover
shouldn't it be -e^-u
soft slate
-e^-u
hallow plover
ye
hallow plover
Here's the numerical solution for reference
soft slate
hallow plover
soft slate
remind me of integration test again
if the integration results in 0
no to a constant it is convergent
and if it is inf divergent right
soft slate
is there any conditions that must be checked before doing integratin test?
inner osprey
is there any conditions that must be checked before doing integratin test?
the sequence is monotonic decreasing after a certain point (in this case, the point you picked x = 1 works perfectly fine)
so yes you can apply integral test here (and yes you correctly conclude that the summation converges)
soft slate
the sequence is monotonic decreasing after a certain point (in this case, the po...
i don't understand its def
dumb it down for me
soft slate
i made the sentence to be it is constant like x=constant
hallow plover
or not and
soft slate
"a function.... that... never decreases or never increases"
but he says decreasing constantly so you disagree
if a function never decreases then it can't decrease constantly
inner osprey
i said "monotonic decreasing" in my message
soft slate
the definition is wrong
inner osprey
the definition is correct
inner osprey
no
inner osprey
so it means it is either decreasing or increasing
what is "it"
hallow plover
isn't this monotonic increasing though?
inner osprey
well
a "monotonic decreasing" function is one that never increases
this means it can be constant
soft slate
so it is always ether constant or decreasing
inner osprey
yes
soft slate
hmmmmmm
inner osprey
that's the condition for applying integral test
soft slate
deep knowledge here
hallow plover
I hate technicalities
soft slate
me too
so @inner osprey could you summarize in what tests we can conclude what the series converges to
inner osprey
none
soft slate
not like whether or not it converges but what it converges
hallow plover
So based on the graph wth is this sum doing now?
inner osprey
tests are tests for convergence
the process of testing for convergence is different from the process of solving a summation (which in most cases a summation does not have a nice solution)
soft slate
and the only way we can find the sum is geometric
soft slate
and arithmetic
inner osprey
and arithmetic
well there are many more sums that have nice solutions
but in general you are not supposed to solve them
hallow plover
(and numeric, but mathematicians hate that)
soft slate
so calc 2 i don't need more than geometric a1/1-r and arithmetic which i forgot
inner osprey
an "arithmetic series" is like not a thing in calculus
inner osprey
that's a pretty unfortunate formula to remember
soft slate
yes
soft slate
that's a pretty unfortunate formula to remember
anyways I appreciate the help and feedback @hallow plover and @inner osprey
inner osprey
yw
soft slate
.close
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floral haven
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dull bear
what is g here?
.[you probably have it but they're related if such a g from G exists]
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untold girder
Find the zeros of the function
h(x) = 8x^2 - 8
vocal sleetBOT
Find the zeros of the function
h(x) = 8x^2 - 8
rugged vortex
What have you tried
rugged vortex
Okay. What the concept
Because if you haven't tried anything, what am I supposed to do
I'm not here to give you answers
willow bridge
do you know any factoring methods?
rugged vortex
You don't need to factor tbh. You could but I wouldn't
So you have 0 = 8(x^2 - 1)
You wanna isolate the x term
inner osprey
You don't need to factor tbh. You could but I wouldn't
i would
this is the more precise way of finding zeroes of polynomial equations
factoring is a good idea generally as it prevents confusion in cases of repeated roots
untold girder
so is 8(x^2-1) the right way to factor it?
inner osprey
you've made progress by factoring out the 8
but you can also factor x^2 - 1 (do you know how?)
untold girder
by factoring out 1?
inner osprey
there's multiple ways you can do this but in the case of x^2 - 1 you can apply "difference of squares", which is:
untold girder
would it be something like (x+1)(x-1)
inner osprey
v good
vocal sleetBOT
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waxen hawk
If two triangles have two sides that are the same
vocal sleetBOT
If two triangles have two sides that are the same
jagged cargo
only 2 sides doesnt suffice
heavy yoke
how do you define "same"?
waxen hawk
how do you define "same"?
Same length
heavy yoke
then no
waxen hawk
How
lime jacinth
you must have three sides that are the same, or 2 sides and an angle
you can't do a proof with 2 sides
lime jacinth
There are four proofs for congruence:
- Side-Side-Side
- Angle-Side-Side
- Angle-Angle-Side
- Hypotenuse-Leg
Side-side-side needs no explanation
heavy yoke
waxen hawk
Terrific
vocal sleetBOT
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silk wind
"Calculate the value of the generalized integral"
vocal sleetBOT
"Calculate the value of the generalized integral"
silk wind
can i use arctan here somhow?
Okay do I start with integrating wrt y?
Because the bound are from 6 to 1 and from x to 1 right?
lime gorge
Arctan works yea
hybrid flicker
the final result needed should look like f(y) + C right?
silk wind
Yes
hybrid flicker
so integrate wrt x first I would say
and yes arctan works for the first integral
and for the second integral you will have something that looks like arctan(y)...
I'll let you guess on how to integrate that
silk wind
Okay so we have 1/x arctan(cy) + C first?
hybrid flicker
Okay so we have 1/x arctan(cy) + C first?
you integrated wrt y or x?
oh wait
it's kinda the same thing
but integrating wrt x first makes you not worry about "+ C"
silk wind
Oh okay
Do I integrate 1/1+x^2y^2 or did we say that I should turn it into arctan first?
vocal sleetBOT
@silk wind Has your question been resolved?
stone gazelle
Do I integrate 1/1+x^2y^2 or did we say that I should turn it into arctan first?
Integrating that will get you arctan,
Consider the substitution u = xy
stone gazelle
Integrate wrt x so x = 1 -> x = 6
silk wind
Does that not become 0?
stone gazelle
There will still be y terms in the arctan
silk wind
1/2 (arctan(6y))^2 -1/2( arctan(y))^2
stone gazelle
1/2 should be 1/y since du/dx = y
silk wind
Ohh oops
dawn elm
Can someone solve
5.76 + 3.72 x 20
I js need someone to confirm I gotthe right answer
hard atlas
just use a calculator
dawn elm
oh yeah
stone gazelle
,calc 5.76 + 3.72 *20
twin meteorBOT
Result:
80.16
fervent geyser
write down 0.0385 to 4 significant figures
vocal sleetBOT
write down 0.0385 to 4 significant figures
fervent geyser
write down 0.0385 to 4 significant figures
what do u think should be the answer to this
this is whats in the answer sheet
but i do not understand
vale frigate
write down 0.0385 to 4 significant figures
how many significant figures does this have?
lavish wing
@fervent geyser whats yhe issue?
That seems right
Ah yea
The dot states that it’s reoccurring
Often an overline is used to portray this but both are commin
fervent geyser
<@629344714021404687> whats yhe issue?
theres no issue can u like explain it to me why
fervent geyser
also one other question why do like for eg if a number if 1.15 if we correct it to 2s.f. it becomes 1.2 right
fervent geyser
my quesiton is isnt the entire different between rounding and significant figures that for a number to be significant it has to be as high on a minimum to that value
then is there no difference between rounding and sf only the format for both are different
im not complaining im just asking if this is the situation?
lavish wing
Sf is just targeted rounding
If i said round 1549
You wouldnt know if i meant to 2000
fervent geyser
Sf is just targeted rounding
thank you
fervent geyser
now i can finally no longer have any respect for significant figures
lavish wing
Gotchu
vast shale
How exactly did they know to integrate here?
vocal sleetBOT
How exactly did they know to integrate here?
grand rune
because you want to know how much sonya can paint in 3 hours
vast shale
because you want to know how much sonya can paint in 3 hours
so you use a definite integral for it because it has bounds?
grand rune
you use definite integral because you need a number. Indefinite integral only gives you function not numbers
vast shale
you use definite integral because you need a number. Indefinite integral only gi...
alright i see, but how do they know to use integration in the first place?
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fleet estuary
Vertex on the line 2x - 3y +8=0 focus on the line 4x + y-1= 0 directrix y=-1
fleet estuary
Bruh
No idea
I know that the line that would go over those 2 lines would have to be parallel to y=-1
i have an answer now by graphing in desmosb
But howww
(x+1)^2=60(y-2)
.close
grave rampart
Hi can I have help answering this and doing his question with the process
stoic mica
I feel like I know how to answer it but I want a more mathematical answer
do you know what is expected value
grave rampart
hold up lemme calc
oh wait isnt fairness determined by being more or less of one or something?
the score is 2.44
stoic mica
oh wait isnt fairness determined by being more or less of one or something?
More or less than zero
stoic mica
the score is 2.44
Assuming there's an equal probability of hitting the target zero times, one time, two times, etc
There are 6 cases, so each one has 1/6 probability of happening
Sum the gains for each case and multiply the result by 1/6
i.e. 1/6 * (-4) + 1/6 * (-3) + ...
grave rampart
Ohh theres a part a table that has the prob distribution and basically it goes like this: x(amount of times target is hit) 0 1 2 3 4 5 and p(probability of it being hit) 0.16 0.26 2k(.12 i believe) 0.15 k(0.06 i believe) and 0.25
For part a
stoic mica
Oh okay
Well then instead of 1/6 multiply each value by its probability
Sum altogether
If result = 0 the game is fair
If result > 0 you have an advantage
If result < 0 you have a disadvantage
grave rampart
Isnt this 2.44 from earlier basically and wouldnt that be an advantage, or i guess you could say a disadvantage in winning money in this game?
Appreciate it alot by the way
vocal sleetBOT
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tacit agate
Hey, I'm just wondering if this is correct
vocal sleetBOT
Hey, I'm just wondering if this is correct
tacit agate
Also is this a server where I can just get confirmation of problems, it's hard studying on my.own and not having anyone to help check
dull bear
,rccw
vocal sleetBOT
@tacit agate Has your question been resolved?
vocal sleetBOT
@tacit agate Has your question been resolved?
mighty stone
this is a right triangle, right? if so does where would the theta sign lie?
finite mist
?
copper crypt
the notion of using right triangles for trig functions kind of breaks down for values above pi/2
you can see the theta in the picture
mighty stone
you can see the theta in the picture
yea but where would it be in the triangle
to find sin cos and tan
finite mist
Not sure if this where u stuck, but let say u can find phi, then the theta is just 180 - phi'
copper crypt
the notion of using right triangles for trig functions kind of breaks down for v...
@mighty stone
stop worrying about triangles
because the "triangle" in this scenerio has a negative side length
mighty stone
because the "triangle" in this scenerio has a negative side length
but we can get radius doing x^2+y^2=c^2
no?
copper crypt
sure
copper crypt
copper crypt
i got c=53
👍
copper crypt
sin is y value cos is x valkuye
mighty stone
sin is y value cos is x valkuye
so sin if 45
and cos is -28?
but it has to be sign of theta
copper crypt
what
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forest plume
https://i.imgur.com/PcFj72r.png is the origin at (0,0), if so, how can the origin of vector v times two equal (0,0)? it seems that the question is confusing. does the vector begin at (0,0), or at point B?
vocal sleetBOT
https://i.imgur.com/PcFj72r.png is the origin at (0,0), if so, how can the origi...
forest plume
vector v is centered at the origin and is 0 somehow, point C is 1v, point B is 2v, my best understanding..
forest plume
OB?
crimson jetty
O is usual notation for the origin
crimson jetty
vector v is centered at the origin and is 0 somehow, point C is 1v, point B is 2...
points are not vectors, I think that is a large misunderstanding here.
forest plume
points are not vectors, I think that is a large misunderstanding here.
well, the vector has a coordinate and B = (2x, 2y) from my understanding
the coordinate is its magnitude afaik
crimson jetty
you shouldnt confuse this.
I can draw an arrow from (1, 1) to (2, 2)
and this represents a vector
forest plume
yeah
crimson jetty
this vector is also equal to the one from (2, 2) to (3, 3)
drawn in different places, but they are equal as vectors
they differ by translation when drawn, but they are 'equal' as vectors.
crimson jetty
the coordinate is its magnitude afaik
A vector having its start point at (0, 0) lets you think about the coordinates of its endpoint, but dont confuse this with the vector itself
forest plume
right, understood, their value is the same,
to get from O to B...
they multiplied by 2?
I just don't understand, since there are no numbers
crimson jetty
Just checking, what stage are you
in school
math
vectors are understood differently
forest plume
not in school. this is khan academy. pre calculus. currently subtracting vectors
forest plume
a vector is a variable that represents magnitude and direction
forest plume
magnitude is like force/length/size and direction can be any way right north south bla bla and ||v|| = just magnitude
crimson jetty
on paper right
forest plume
ll v ll = just magnitude
forest plume
how do you add 2 vectors
add their coordinates
or magnitude I guess
if v = 5 feet I guess 2v = 10 feet
crimson jetty
or magnitude I guess
since we werent talking about coordinates
you shouldnt talk about them when adding
crimson jetty
a vector is a variable that represents magnitude and direction
stick to these ideas
and no, you dont add their magnitudes.
to give an example
if I gave you this picture, how would you add these 2 vectors
forest plume
hold on, finding arrows on paint
crimson jetty
im asking to see what you understand btw, maybe you have not been introduced to the geometrical idea
but i think vectors are much easier to understand through pictures
forest plume
crimson jetty
ok so?
forest plume
or do their end points have to clash :S
crimson jetty
first of all, are we clear translating the arrow does not change the vector
forest plume
translating?
forest plume
yeah I suppose so yes