it's okay there are mewing videos
#help-17
hollow acorn
it's okay there are mewing videos
THATS WHAT IM TALKING ABOUT! YESSSS
π
Its okay
Youre smart and thats all that matters
crude arrow
I feel like ur tryna be that jordan guy
hollow acorn
I feel like ur tryna be that jordan guy
WHAT
zenith pollen
I will help you
hollow acorn
I will help you
OMG
zenith pollen
@hollow acorn
zenith pollen
What's your issue?
crude arrow
apply implicit diff on both sides f(g(x)) = x
hollow acorn
What's your issue?
I just dont know how to solve for inverse derivative
crude arrow
and then get the formula for g;(x)
zenith pollen
What's the question you want resolved
hollow acorn
apply implicit diff on both sides f(g(x)) = x
Ohh okay
crude arrow
What's the question you want resolved
I think sophia almost got it
but
basically
^
hollow acorn
This is the question
crude arrow
Ohh okay
do this
and you basically get
f'(g(x)) * g'(x) = 1
so g'(x) = 1/f'(g(x))
in this case, we plug in x = 2
zenith pollen
Interesting. Yes, try to apply g() to the function
hollow acorn
so g'(x) = 1/f'(g(x))
OMG thats the formula i used for the last questions
crude arrow
in particular @hollow acorn what is f'(x)
hollow acorn
YESS
crude arrow
now what is 1/f'(1)
hollow acorn
now what is 1/f'(1)
OH MY GOD
YOURE A GENIUS
OH MY GOD
THATS THE ANSWER
SHUT UP
OMG
hollow acorn
OH MY GOD
crude arrow
I was just guessing
crude arrow
NOT LIKE I went through all the steps π
crude arrow
why is bro so surprised
hollow acorn
OH MY GOD
hollow acorn
why is bro so surprised
Im genuinely tearing up
Thank you
Im so thankful
I was going crazy
Oh my god
SEEUOUSLY THANK YOU SO MUCH
OMG
crude arrow
π
crude arrow
NO STOP IT
okay
crude arrow
Nosqldb came and saved the day
π
hollow acorn
i think i owe you my life
crude arrow
i think i owe you my life
can you put that in monetary terms (I'm broke)
hollow acorn
Why is whatever u did so much easier than what ive been doing
hollow acorn
can you put that in monetary terms (I'm broke)
I only have 50 dollars to my name
Oh my god
crude arrow
I only have 50 dollars to my name
lowkey $50 is at least 7 meals
hollow acorn
Im actually crying rn thank you so much π
crude arrow
Why is whatever u did so much easier than what ive been doing
what have u been doing
hollow acorn
Why are you the best
hollow acorn
what have u been doing
I DONT KNOW
ITS CRAZY
i like
I solve for x by making it equal to the a value
Then
I find the derivative and then i use some crazy formula
But
crude arrow
I solve for x by making it equal to the a value
yeah that's finding x s.t that f(x) = a
hollow acorn
Sometimes i get two answers if i do it like thatβ¦.
crude arrow
and since it is injective, it's unique x
hollow acorn
and since it is injective, it's unique x
Im giggling
Idk what that means
But thank you.
crude arrow
Im giggling
average canadian education
hollow acorn
I feel like youve actually saved my life
crude arrow
I feel like youve actually saved my life
if you lived in america, you wouldn't need me to save ur life
π
we got the best education system
hollow acorn
if you lived in america, you wouldn't need me to save ur life
Its also my fault i gave up on my hw because it was too hard
crude arrow
Its also my fault i gave up on my hw because it was too hard
nah don't blame urself
hollow acorn
And now im getting the amazing experience of dealing w the consequences
crude arrow
And now im getting the amazing experience of dealing w the consequences
just whatever you do
don't go to the university of waterloo or u of t
hollow acorn
don't go to the university of waterloo or u of t
π
I was gonna go to ubc
But im giving up on calculus because i choose happiness.
So i dont wanna go there anymore
β€οΈ
crude arrow
But im giving up on calculus because i choose happiness.
dawg what
hollow acorn
U made me solve for f(1) and then fβ(x) and then fβ(1)
And then inverse? Is that right?
crude arrow
And then inverse? Is that right?
in general
hollow acorn
go to the university of toronto
π€
crude arrow
if g is the inverse of f, then g(f(x)) = f(g(x)) = x
hollow acorn
Sure!
hollow acorn
if g is the inverse of f, then g(f(x)) = f(g(x)) = x
sophia nods yes yesβ¦ that DOES indeed seem to make sense! π€
crude arrow
so g'(x) = 1/f'(g(x))
crude arrow
*sophia nods* yes yesβ¦ that DOES indeed seem to make sense! π€
this is a math server π
hollow acorn
so g'(x) = 1/f'(g(x))
Youre too good.
I feel like youre the creator of this concept tbh
Thats how good u are
crude arrow
I feel like youre the creator of this concept tbh
ty but no π
hollow acorn
ty but no π
Trust me⦠i know the truth.
Omg
IM GONNA TRY UR METHOD FOR THE NEXT QUESTION
but it looks kind of crazy
Im actually scared
hollow acorn
extremely brutal exams
Omg you want me dead
I just wanna β¦
I just wanna become a professional esports player
crude arrow
I just wanna become a professional esports player
my friend could prob beat u in both val and fortnite
hollow acorn
my friend could prob beat u in both val and fortnite
OMG FORTNITE
IM SO BAD yet so goodβ¦
WAIT
crude arrow
back in my glory days
hollow acorn
This is kind of embarrassing.. but
crude arrow
like when fortnite dropped
hollow acorn
I have to ask.
hollow acorn
What is tan(pi/2) π
hollow acorn
What is tan(pi/2) π
Its iver for me
crude arrow
What is tan(pi/2) π
let's go through this q
crude arrow
what's tan(x) = ? in terms of sin and cos
hollow acorn
what's tan(x) = ? in terms of sin and cos
Uhhh π€ sinx/cosx! (IS THAT WHAT UR ASKING IDKh
crude arrow
Uhhh π€ sinx/cosx! (IS THAT WHAT UR ASKING IDKh
yes
now what's sin(pi/2)/cos(pi/2)
hollow acorn
undefined fr
You got me there!
Yes!
Perfectβ¦
Omg
Oky
Okay
So
THEN F(1) IS 4 FOR THIS NEXT QUESTION
crude arrow
S lowkey instead of 10 messages
you can use one
to say the whole thing π
that's why lowkey u of t can be a good fit
hollow acorn
Im sorry nosqldb
Ill do better.
Lemme find the derivative
Ohhhh
Uhh
Ive got a rllllyyy good question
crude arrow
π
crude arrow
^
hollow acorn
WHATS THE DERIVATIVE OF TAN OH NOOO
wait. Ill check my derivatives sheet.
Sec^2x
OKAY NEXT STEP
fβ(1)
crude arrow
WHATS THE DERIVATIVE OF TAN OH NOOO
lowkey sophia (S)
S just finish up the problem and lmk when ur done
you can send me a dm
vocal sleetBOT
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Available help channel!
latent citrus
a group of spirtiners ran for 10km on a bearing of 30 degress to a finsh line
find the ditsance north and east they ran
vast shale
10 km is the diagonal and 30degrees is the bottom left angle at start then use soh cah toa to figure out the other distances
finite mist
Use trigonometry
latent citrus
oh ok how do i figure out what trig to use if i only have the hypotenuse?
vast shale
U have the hypotenuse and an angle
latent citrus
wait is it the h
finite mist
U have the angle
vast shale
Ye
finite mist
The north bearing...
latent citrus
Yeah but how do i know idk which SOH CAH TOA
vast shale
Think about what you have and what youβre trying to find
latent citrus
Thats a basic skill
no need to be rude π
vast shale
Itβs ok Rita this is how men who like math are unfortunately
But I will help you β€οΈ
finite mist
Sorry if that come out as rude but like its really a basic skill π
latent citrus
But I will help you β€οΈ
Thank you!
latent citrus
Sorry if that come out as rude but like its really a basic skill π
ok for u it is but not everyone is good at math bro
vast shale
Rita what year of math r u in
latent citrus
Year 11
finite mist
As in 11/12 or 11/13 (UK)
latent citrus
im trying to get help not talk about how bad i am at math
vast shale
@finite mist Were u the one helping me before w numerical analysis
finite mist
Here's
vast shale
im trying to get help not talk about how bad i am at math
U need to use two out of SOH CAH TOA because youβre trying to find two more sides of the triangle
Or you can find one and then use Pythagorean theorem
finite mist
I hope this help
vast shale
To find the third side
finite mist
vast shale
Did u read what I said
vast shale
Do u know what soh cah toa stand for
latent citrus
yes
vast shale
And what sides do you not have relative to the hypotenuse
latent citrus
O and A
vast shale
Ya
latent citrus
great! Thank u
vast shale
finite mist
Question: u know cos60 * 10 and sin60 * 10 but which one result in north and east?
latent citrus
cos 60 X 10?\
why when i put this into my caucloat it turns into a decimal
vast shale
Itβs 60 he made a mistake
latent citrus
why when i put this into my caucloat it turns into a decimal
i mean MINUS
MINUS NUMBER
vast shale
are you in degrees or radians
latent citrus
are you in degrees or radians
im not sure
vast shale
Wait
finite mist
Cos 60
vast shale
Itβs a 30 60 90 triangle
latent citrus
Huh
finite mist
Check ur angle unit
vast shale
Do yk the properties of a 30 60 90 triangle
latent citrus
No
latent citrus
Check ur angle unit
what is that
vast shale
Did u take geometry
finite mist
what is that
its in ur calculator setting
vast shale
Send a pic of ur calculator
finite mist
cos 60 deg = 0.5; cos 60 rad = -0.9 thats why u get negative
vast shale
Like fully I wanna see all the buttons
finite mist
Press MENU
latent citrus
vast shale
Click shift and then menu
latent citrus
finite mist
finite mist
Change the angle from rad to deg or degree
vast shale
To deg
vast shale
A
latent citrus
latent citrus
Ok
vast shale
slim oracle
vocal sleetBOT
slim oracle
3d
tidal dock
i think you should start with polynomial long division and then go with $\omega = re^{2\pi/n}$
twin meteorBOT
artemetra
vocal sleetBOT
@slim oracle Has your question been resolved?
vocal sleetBOT
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Available help channel!
torn spoke
Are trigonometric functions not functions? They have more than output. Eg cos(0)=2 pi*n which is an infinite set
vocal sleetBOT
Are trigonometric functions not functions? They have more than output. Eg cos(0)...
river minnow
,w cos(0)
twin meteorBOT
left lichen
Are trigonometric functions not functions? They have more than output. Eg cos(0)...
they are called trignometric ratios
river minnow
No idea what you meant by cos(0) = 2pin being an infinite set
torn spoke
Oh
vocal sleetBOT
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Available help channel!
tough onyx
I'm not sure how the solution is obtained
vocal sleetBOT
I'm not sure how the solution is obtained
tough onyx
So what I have so far is, f^-1(5) = 3
and f'(x) = cos(cos(4))^3
Derivative of inverse function is 1/f'(x)
What is the value of derivative of the inverse function at f^-1(5)? i.e. 1/f'(3)
vast shale
Derivative of inverse function is 1/f'(x)
is it?
It should be [
\9{\6{f^{-1}}x}' = \41{\6{f'}{\6{f^{-1}}x}}
]
twin meteorBOT
vast shale
so use the fact that $\6f3 = 5 \Implies 3 = \6{f^{-1}}5$ and the answer to a) should be direct
twin meteorBOT
vast shale
Okay second part
g(5) = f(3) = 5
is it though? they are saying g(x) = f(x+2)
so 5 + 2
tough onyx
g(3) = f(5)
vast shale
ye
tough onyx
f^-1(5) = 3
I don't know how to relate it to g^-1(5)
g(x)=f(x+2)
g^-1(x) = f^-1(x+2)
vast shale
if the functions are equal then their inverses are equal too yes
tough onyx
g(x)=f(x+2)
g(5) will mean f(3 + 2)
tough onyx
π«
vast shale
if they did intend to make it mean that
vast shale
supposedly but you dont know anything about 7 here, so not sure what they want u to do
oh wait
vast shale
So $g^{-1}(5) = x$ which implies that $5 = \6gx$ but we also know that $\6gx = \6f{x+2} = 5$ and $\6f{x+2}$ is equal to 5 when $x = 3$. So $g^{-1}(5) = 3$
twin meteorBOT
tough onyx
mind blowing stuff
vast shale
yea took me a bit too
vast shale
sorry i messed up this i meant x = 1, because f(1 +2) = f(3) 
So $g^{-1}(5) = x$ which implies that $5 = \6gx$ but we also know that $\6gx = \6f{x+2} = 5$ and $\6f{x+2}$ is equal to 5 when $x = 1$, because $\6f3 = 5$. So $g^{-1}(5) = 1$
twin meteorBOT
vast shale
this is definitely correct now
vast shale
is this understandable by you though jasmine?
tough onyx
g^-1(5) will equal some value x.
So g(x) will equal 5. (Inverse function property)
g(x) = f(x+2) = 5
We know f(3) = 5 so that particular x = 1
I guess so
vast shale
g^-1(5) will equal some value x.
So g(x) will equal 5. (Inverse function propert...
yeah
exactly
alright so now
we differentiate g(x)
we have g'(x) = f'(x+2)
we know $f'(x) = \6\cos{\6\cos{x+1}}^3$ so $f'(x+2) = \6\cos{\6\cos{x+3}}^3 = g'(x)$
twin meteorBOT
tough onyx
g'(1) = f'(3)
vast shale
is this fine as well
vast shale
g'(1) = f'(3)
ye sure
tough onyx
function transformation basically
twin meteorBOT
vast shale
do yk how to solve this now
tough onyx
Let me recap it
g inverse of 5 will produce some value of x.
By using property of inverse functions, g of this value of x will equal 5.
vast shale
yes
tough onyx
i.e. g(x) = 5
But we know that g(x) = f(x+2)
vast shale
yes
tough onyx
Equating f(x+2) = 5 and given that f(3) = 5,
x+2 = 3
x = 1
vast shale
yeppie
tough onyx
We have found this value of x = 1 such that g^-1(5) = x
So now the derivative part.
g(x) = f(x+2)
vast shale
yeah
vast shale
yeeeee :D
tough onyx
The question went over my head the first few times bruh
oh well
Thanks
upvote
.close
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Available help channel!
thin gull
Hello, i need help with this system i made to find a function, and the result isnt possible nor making sense, and i keep unnable to find whats wrong
g should be between 10^6 and 10^12, for example 400*10^6, and a/b should be equal to b/c (c is 50) so on this example it would be 2500/400 = 400/50 of course, this doesnt work its an example, but thats what i want to find: a, b and g, and i have 3 equations. But g keeps getting to 50^(1/3) which isnt even possible, and i dont know whats wrong
plss help
vocal sleetBOT
Hello, i need help with this system i made to find a function, and the result is...
@thin gull Has your question been resolved?
thin gull
<@&286206848099549185>
bronze osprey
Hello, i need help with this system i made to find a function, and the result is...
Where do these equations come from?
,w 10^12 / g * 10^6 / (2 * 10^4) = (g/10^6)^2
twin meteorBOT
bronze osprey
Ok g is definitely between 10^6 and 10^12 though
I did ac = b^2 and then substituted a, b, c in
thin gull
I made them for the function i want to find
I only know that info of 10^12 and 10^6 having a,b and the c and ratios part
Apart from that nothing more, but it shouldnt be needed since its 3 equations
When i put the a/b=b/c => a=b^2/50 and later replace it it goes to a number that doesnt make sense, and a, b and c cant be zero so i dont get it
thin gull
Wait is this the answer
bronze osprey
Wait is this the answer
Yes
thin gull
Oh okay thx
But i dont get it
bronze osprey
When i put the a/b=b/c => a=b^2/50 and later replace it it goes to a number that...
I can do it from here if you want, a = b^2/50
$\frac{10^{12}}{g} = \frac{g^2 / 10^{12}}{50}$
twin meteorBOT
south
bronze osprey
$10^{12} \cdot 10^{12} \cdot 50 = g^2 \cdot g$
thin gull
Yeah, doesnt it mean g3 = 50^(1/3)
twin meteorBOT
south
bronze osprey
Yeah, doesnt it mean g3 = 50^(1/3)
Nope
bronze osprey
Multiplying both sides by 10^(12) gets rid of the fraction, then you need to multiply by 50
Yeah ok
thin gull
Ahaha ofc 10^12 will multiply not nullify
bronze osprey
Yep
thin gull
Yeah i get it, thank u so much!!
bronze osprey
No worries!
thin gull
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vocal sleetBOT
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karmic zenith
hi
vocal sleetBOT
@karmic zenith Has your question been resolved?
vocal sleetBOT
@karmic zenith Has your question been resolved?
vagrant solar
vocal sleetBOT
vagrant solar
For question 2 the answer key did 80 + 5 and 0.2 + 9.8 then multiples them to get 850N
In other words sum of acceleration and mass but surely the acceleration is in two different directions, down for 9.8 and up for 0.2? So why isnβt it subtract
vocal sleetBOT
@vagrant solar Has your question been resolved?
vagrant solar
<@&286206848099549185>
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@vagrant solar Has your question been resolved?
daring dagger
How to solve q 15 with
vocal sleetBOT
How to solve q 15 with
vocal sleetBOT
@daring dagger Has your question been resolved?
daring dagger
No
cunning plaza
@daring dagger not the integral test, thereβs a way easier test for that q
cunning plaza
Itβs the easiest one
cunning plaza
Yup
daring dagger
Brooo
Thanks so muchjj
I was stuck on this for so lomggg
Idk how this flew over my head
Lmk I'm so lost on this Taylor stuff
cunning plaza
The integral is unsolvable haha
cunning plaza
No
daring dagger
ye i get infinite, so its divergent, so it cant be convergent
i eliminated nth term bc it doesnt tell me about convergent, but i didt think about it this way
so same process for 17 right
wait i think integral of 17 is e
so that means its also divergent
cunning plaza
The the integral of 17 is a bit complicated
Like you can do it
But why not divergence test it again?
cunning plaza
Itβs -k not k
vocal sleetBOT
@daring dagger Has your question been resolved?
eternal glacier
vocal sleetBOT
eternal glacier
simple algebra question here
did I mess up the sign somehow with the +20/3?
that entire fraction needs the distrubution of the - sign?
winter thistle
that entire fraction needs the distrubution of the - sign?
yes
eternal glacier
dang
how do you prevent that simple error from happening?
wrap the entire fraction in brackets for step 2?
winter thistle
how do you prevent that simple error from happening?
uhh, practise and learnt from mistakes
eternal glacier
whenever you have a fraction, it has invisible brackets around it, doesn't it
maybe that's a good way to imagine it
i can't just seperate fractions like that, i need to distribute first
winter thistle
you can, at the end of the day, you find whatever that helps you the most
a lot of ppl developed their own "trick/technique" through experience
eternal glacier
negative sign (-) distribution catches me all the time
maybe I can replace -(fraction) with + (-1)(fraction)
that might be a safer way to think about it too
to distrubute first, then add
since multiplication comes before addition
eternal glacier
a lot of ppl developed their own "trick/technique" through experience
also, for intuition with solving math problems:
do you ever run into this issue where your calculation "feels off" like a spidey sense, that maybe something is wrong
but it's a false positive?
winter thistle
also, for intuition with solving math problems:
do you ever run into this issue ...
sometimes
when the numbers look ugly
eternal glacier
and do you just double check your work to resolve that? or just ignore that feeling sometimes
i wanna be 100% sure my answer is correct, but I also don't wanna waste time on exams by double or triple checking work
winter thistle
sometimes I take a quick look at my work but I'll ignore it until I finish the question then check
winter thistle
i wanna be 100% sure my answer is correct, but I also don't wanna waste time on ...
that comes from experience
eternal glacier
OK
winter thistle
when you've done smth hundreds of times, you build the confidence of not making stupid mistakes
eternal glacier
sometimes a solution "feels off" like the craziest rational numbers in existence, but then when the exam marks are posted I got it right, so sometimes ugly numbers are the actual answer I guess
winter thistle
yh, sometimes it's just hard to give questions with nice number soln, but a lot of the time your teacher prob just lazy to do so/want to knock your confidence off
eternal glacier
i remember a cramer's rule question was like that, i was for sure thinking my determinant was off
but i had enough time last 10 mins of exam to check my work, it holded true
exams are so stressful lol, i always wish they gave more time
gotta be accurate, make no mistakes, but also FAST
otherwise a simple mistake during the first step can fuck up the next 30 minutes of your life
i try to just get through the easiest questions first, leave the harder ones for last
our exams need to be written in pen which doesn't help, and the worst questions are the ones that are not printed on the same piece of paper, half and half between two pages
so not only do you hear the noise of the entire exam room page flipping back and forth but also prone to more copy error
i feel like they do that on purpose to troll
.close
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ancient patio
E(x) = (x+1)Β² + (x-3)Β² - (7+xΒ²)
Show that E(n) is a multiple of 8
scenic ravine
what about it?
ancient patio
what about it?
I am stuck at the (7+xΒ²) part , ik the first 2 () are formulas , but the 3th () isnt
scenic ravine
you don't have to apply any formula for the third part
ancient patio
So what do i do then? I get E(x) = xΒ² + 2x + 1 + xΒ² - 6x + 9 - (7 + xΒ²)
Do i just invert the + and - and take out the ()?
scenic ravine
the last two terms become -7-x^2 yes
keen kite
In a rectangle ABCD, AD = BC and β DAB = β DCB and BD connects both the triangles ABD and BCD
Is it possible to use a theorem to prove congruence between ABD and BCD? If so, what theorem would be applied to prove ABD is congruent to BCD?
I'm not sure how to do this one so I'd like to know
vocal sleetBOT
In a rectangle ABCD, AD = BC and β DAB = β DCB and BD connects both the triangles ...
keen kite
Well no actually I just had to pick a shape, ignore the way it's done
Sorry about that
keen kite
If it was a rectangle, I know it would be HL
scenic ravine
so it;s an arbitrary quadrilateral ?
keen kite
But I need to know the answer to how I phrased it instead
keen kite
so it;s an arbitrary quadrilateral ?
Yes
scenic ravine
in that case , I don't think so
keen kite
Would it be not enough information in that case?
scenic ravine
yes, at least that's what I think
keen kite
Alright one last scenario
If AD were to be parallel to BC, and there's no information on AB and DC being parallel, then is there a theorem that can be used to prove congruence?
scenic ravine
then ASA congruence
keen kite
Exterior Angles?
scenic ravine
interior alternate angles
vocal sleetBOT
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rancid pier
Whats the minimum velocity along the 31 degree ramp that wouldnt result in hitting the 1.8 m tall guys head 3.1 meters away? the ramp is 2 meters tall. Imagine a car or something like that is driving off it
https://cdn.discordapp.com/attachments/1227314509002178581/1227314509425676361/IMG_0092.jpg?ex=6627f4b5&is=66157fb5&hm=02e6a4838c99aa6b93222881a2afcd51491cd6834ee04b7dc6d699b5dcbfe1f7&
vocal sleetBOT
Whats the minimum velocity along the 31 degree ramp that wouldnt result in hitti...
vast shale
Whats the minimum velocity along the 31 degree ramp that wouldnt result in hitti...
probably something really slow that just drops off the edge really anticlimactically
like 0.1mph π
cedar kernel
are we launching something off the ramp
or are we going to launch the ramp
just making sure
dry yacht
Use x=v0t cos(theta), to find time. And use the y formula.
rancid pier
or are we going to launch the ramp
yesss
vast shale
Whats the minimum velocity along the 31 degree ramp that wouldnt result in hitti...
Consider the vertical/horizontal velocity
rancid pier
so we launching the ramp at 37 degree angle , no rotation?
im looking for the velocity along the 37 degree angle
vast shale
read what he said originally βimagine like a car driving off of itβ
rancid pier
no rotation (like centripetal force??) andd i think throwing motion or kinematics stuff would be useful
vast shale
somethings gettinf launched off it
rancid pier
yess
vast shale
Are we assuming that theres no frictional forces and that it takes place in a uniform gravitational field?
rancid pier
no friction
rancid pier
Are we assuming that theres no frictional forces and that it takes place in a un...
yes
vast shale
And it takes place on earth?
vast shale
Okay if we break up the velocity into its 2 horizontal and vertical components
rancid pier
yess and i got an expression for it but geogebra said it was impossible to solve
nova ingot
9.82 for G or 9.81
just take it as 9.8
vast shale
just take it as 9.8
depends on if the question states to do so or not
rancid pier
just take it as 9.8
yeah that works too. but honestly i just wanna know howw to find the velocity along the ramp π
nova ingot
depends on if the question states to do so or not
i suppose but if it doesnt id say its better to take it as 9.8 instead of 9.81
vast shale
i suppose but if it doesnt id say its better to take it as 9.8 instead of 9.81
yeah ig so
depends on level of education
high school normally sticks to 9.8
@rancid pier Okay so youre gonna have a vertical velocity and a horizontal velocity, your horizontal velocity will stay constant due to no frictional forces
But your vertical velocity will have gravity acting on it
acceleration due to gravity is constant so you just consider the acceleration acting on the vertical velocity to be -9.8
vast shale
use suvat equations to form equations
The time taken for horizontal velocity to travel 3.1m is the same time it takes for vertical velocity to fall by 0.2m
vast shale
vast shale
s=ut+1/2at^2
This for vertical velocity
vast shale
i havent done it but yes that probably would be it
rancid pier
nvm is not
the answer is 5.6 hmm
my friend solved it and got 5.6
If X is the velocity, and t is time, wouldnt this be correct?
vast shale
-2?
rancid pier
its
s=vt+(1/2)*at^2
vast shale
try again with -0.2
vast shale
yep that looks correct to me
rancid pier
yess, i wrote t 10 times larger than it was, and yes 0.2 as 2 instead
thanks so much
vast shale
np!!
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stray vortex
For this question why isn't there als a ciritcal point at (1, -1)? If you plug in x = 1 to y^2 and solve doesn't that give you -1 and 1 using the fact that y^2 = x
vocal sleetBOT
For this question why isn't there als a ciritcal point at (1, -1)? If you plug i...
bitter pilot
For this question why isn't there als a ciritcal point at (1, -1)? If you plug i...
y=xΒ²
x=yΒ² are two parabolas that have two intersections
stray vortex
y=xΒ²
x=yΒ² are two parabolas that have two intersections
mhm
stray vortex
you say y=-1
yeah
bitter pilot
xΒ² = y
xΒ² is never negative x)
xΒ² = -1 not possible
You gotta always look out if your solutions satisfy both equations
stray vortex
ohh i think I see what you are saying thank you!
sharp ivy
vocal sleetBOT
sharp ivy
Can someone check if my work is correct
I am trying to find x bar and y bar
I assumed that p is a constant
sharp ivy
I am trying to find x bar and y bar
Trying to find the center of mass of this triangle
vocal sleetBOT
@sharp ivy Has your question been resolved?
sharp ivy
No
wraith python
Looks good so far.
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@sharp ivy Has your question been resolved?
sleek maple
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sleek maple
what is 3b supposed to be? is the 5 in degrees or radians?
vast shale
radians since they didn't add Β°
radians is a unitless quantity so there is no need ti add it
vast shale
yes
sleek maple
and it'll cancel out to (5)(180)
vast shale
uh where did the pi disappear
sleek maple
the pi on the bottom and (invisible) pi with 5 cancel out don't they?
vast shale
your answer will be in terms of pi since 5 radians in degrees is irrational
vast shale
is it (5)(180/pi)= (180x5)/pi
yes
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austere sundial
I need help with this problem
vocal sleetBOT
I need help with this problem
edgy sapphire
those sorts of equations mean "start at 5 in the middle, then go at a -1/3 slope"
austere sundial
oh i was going down 3 and across 1
edgy sapphire
yea it has to be one of those, but the fraction means it's a small number and so it goes down only slightly
austere sundial
wraith python
When x = 0, what does y equal?
wraith python
y = -1/3 *(0) + 5
wraith python
What is -1/3 times 0?
austere sundial
0
wraith python
And then you add 5 to 0.
austere sundial
5
wraith python
So when x = 0, y = 5.
That gives you the x and y values of the coordinate (x,y) = (0,5).
austere sundial
wraith python
No.
austere sundial
im not able to put the y on 5
wraith python
That's fine so far. Now you just need to place another point to make a line. Calculate another (x,y) pair by choosing some value for x and then solve for y.
Let's say x = 3, what would y equal?
edgy sapphire
gl broski
vocal sleetBOT
How do I do this?
vocal sleetBOT
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austere sundial
can i get some guidence with this equation
vocal sleetBOT
can i get some guidence with this equation
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sharp ivy
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graceful plover
Howdy Guys!
sharp ivy
Howdy π€
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@sharp ivy Has your question been resolved?
sharp ivy
No
rugged orchid
hi friends i need a little help connecting the dots here
vocal sleetBOT
hi friends i need a little help connecting the dots here
rugged orchid
im looking at this
and it's awfully like some sort of fourier transform
i know that $\mathcal F \left{\frac{d^p}{dt^p}\phi_X\right}(t) = (-it)^p\hat\phi(x)$
twin meteorBOT
Frosst
rugged orchid
oh wait hold up, if $X$ admits a pdf $f_X(x)$, then $\mathbb E[X^p] = \int_\mathbb R x^pf_X(x), dx$ if we take the fourier transform of the inside bit, we get $\int_\mathbb R (-i)^p\frac{d^p}{dt^p}\hat f_X(t), dx$
twin meteorBOT
Frosst
rugged orchid
ok but now we've lost the x
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rugged orchid
Hmm if I look at say $\mathbb E[e^{ikX}] = \int_\mathbb R e^{ikx},dP_X = \int_\mathbb R e^{ikx} \frac{dP_X}{d(\lambda + \delta_A)}, d(\lambda + \delta_A)$
twin meteorBOT
Frosst
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desert moth
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desert moth
You can define a rod length L
You can define the key for length and price
ex:
Length : Price
1 : 2
2 : 5
3 : 7
4 : 9
5 : 13
etc
And then you have to show that the algorithm where you just find the length smaller than L which has the highest price/length ratio and just cut as many of those rods as you can, and then perform the algorithm again on whatever size piece u have left.
The goal is to maximize profits, and you have to show that this algorithm is not always correct
but i cant think of a counter example
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molten jasper
I actually know the vienn diagram method of solving it ,
can you guys please help me solve it with equations
vocal sleetBOT
I actually know the vienn diagram method of solving it ,
can you guys please he...
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thorny coyote
(Theory of Computation / Formal langs)
Can someone confirm if this logic holds:
G' is a grammar constructed by eliminating chain rules from a context-free grammar G=(Ξ£, V, Ξ΄, S), show that the language G defines, L(G), is equal to the language L(G'). So I wanna prove xβL(G) βΊ xβL(G'), right? Can I just point to the method for chain rule elimination and say:
Let xβL(G)
βΊ S ββΊ_{G} x
1. Derivations in G that don't have any subderivations using chain rules are identical in G' (by definition of chainrule elimination)
2. Derivations in G that have some subderivations that consist of chain rules have corresponding production rules in G' (by definition of chainrule elimination):
Let K be the set of chain rules in G.
The derivation of x from G is of the form:
S β*_{G} A β*_{K} B β_{G} Ξ² β*_{G} x
G' has corresponding production rules and x can be derived by substituting all chain derivations like so:
S β*_{G'} A β_{G'} Ξ² β*_{G'} x
βΉ S βΉβΊ_{G'}
So xβL(G) βΉ xβL(G')
Now the other way.
Let xβL(G')
βΊ S ββΊ_{G'}
1. Derivations in G' that don't have any subderivations using chain rules are identical in G (by definition of chainrule elimination)
2. Derivations in G' that have some subderivations consisting of the production rules produced by chainrule elimination have corresponding chain rules in G (by definition of chainrule elimination):
Let K be the set of chain rules in G, and K' be the set of production rules in G' (and not in G) produced by chainrule elimination.
The derivation of x from G' is of the form:
S β*_{G'} A β_{K'} Ξ² β*_{G'} x
G has corresponding production rules and x can be derived by substituting all subderivations consisting of rules from K' like so:
S β*_{G} A β*_{K} B β_{G} Ξ² β*_{G} x
βΉ S ββΊ_{G} x
So xβL(G) βΊ S ββΊ_{G} x βΊ S ββΊ_{G'} βΊ xβL(G')
@thorny coyote Has your question been resolved?
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@thorny coyote Has your question been resolved?
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@thorny coyote Has your question been resolved?
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vast shale
not sure how to start with question b, sketched them out and drew some circles around x1, x2, x3 but don't know exactly how to sketch the areas
vocal sleetBOT
not sure how to start with question b, sketched them out and drew some circles a...
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tiny island
over here
tiny island
how did htey notice
that a restriction was y <= -1/9
why do they not use the not equal to sign??
lone linden
Hint: find the range of the denominator
And consider ||what taking the reciprocal of that does||
tiny island
And consider ||what taking the reciprocal of that does||
I'm still confused
lone linden
I was referring to doing this
The range is the set of outputs, not the distance between the roots
tiny island
oh yeah that I know how to do
so the distance between the quadratic of this would be -infinity to infinity
lone linden
If youβre referring to the domain, then yes, itβs the set of all reals
tiny island
the range is anything above a specific point
not sure how it would work in this case
lone linden
Hint: find the range of the denominator
.
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whole gale
can someone tell me the binomial expansion of (1 + x)^n
vocal sleetBOT
can someone tell me the binomial expansion of (1 + x)^n
whole gale
in terms of combinations
graceful canopy
can someone tell me the binomial expansion of (1 + x)^n
generalized?
whole gale
yes
whole gale
no not this
graceful canopy
arctic mantle
that's... what is written
whole gale
is my handwriting bad π
fuck I forgot almost everything from binomial
should've revised it
graceful canopy
just tell me if its right or nah
should it not start from nC0?
whole gale
oh
graceful canopy
with that, there wont be a 1+... term
graceful canopy
yeah
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vast shale
Need help
tepid plinth
what with
vast shale
what with
is the question
like how do i get it in the form they want, when iwas doing this i didn't read the second part of the question
frigid merlin
like how do i get it in the form they want, when iwas doing this i didn't read t...
complete the square, or reverse complete the square
one of those is how you get it into the correct form
frigid merlin
mmmm
vast shale
which i did in the thing
so where do i
get it in that form
because i need to find C too
which i did, if it's right
near tartan
@vast shale
Did u by any chance forget to bring the 1 in the next step
It's not visible so I'm not sure
near tartan
vast shale
<:catking:812386361297862747>