#help-17
1 messages Ā· Page 155 of 1
but holy moly
that was a lot of math
but i see the correlation now
thanks for all ur help appreciate it š
ik u hv to sleep but can u really quickly tell me what im supposed to look for the oither part of this question
really quickly
Express Tn for n ā„ 3 using some number from the previous questions
do u know from the top of ur head which number its referring to?
or no
its fine if u dont its pre vague imo
is this for finding closed form?
You preshot it somehow, it's kinda like fibonacci sequence
Now that you got Tn+2 = 2Tn + 2Tn-1
You solve the characteristic equation
r² = 2r + 2
is that golden ratio * 2?
It's not twice the golden ratio I'm afraid
At least I think
No the roots are $1 \pm\sqrt{3}$
rafilou2003
Name them $r_1,r_2$
rafilou2003
The general solution will look like $T_n = Kr_1^n + Lr_2^n$
rafilou2003
Find K and L using the values you got of T1, T2
mhhm
ok
where did u get this again:
r² = 2r + 2
because ik roots of 2r² = 2r + 2
are the same as the ones u mentioned abpve
so did u mean 2r² = 2r + 2
When you have recurrence $T_{n+2} = aT_{n+1} + bT_n$, the characteristic equation is $r^2 = ar + b$
rafilou2003
So for fibonacci, a=b=1 and you get r² = r + 1
In this case, a=b=2, so different roots
oh ok
but i believe 2r² = 2r + 2
works too
but anyways
u gotta sleep
ill let you go lool
You mean what?
dont wanna take too much of ur time
im pre sure 2r² = 2r + 2 works instaed r² = 2r + 2
"Works" as in "the roots are golden ratio and inverse"?
Idk what "works" mean for you
as in we get same roots
2r² = 2r + 2 has the same roots as r² = r + 1
It's called "multiplying by 2"
Ya know the thing we did here
?
Those 2 do not have the same roots
For a good cause
u said r² = 2r + 2 has these roots
Yep
2r² = 2r + 2 has same ones
No
ik cuz i did it in a question before the one we did
2r² = 2r + 2 has golden ratio as root
$2r^2= 2r + 2$ has for roots $\frac{1\pm\sqrt{5}}{2}$
rafilou2003
If r² = 2r + 2
Twice that quantity will NOT be 2r + 2
It will be 4r + 4
Double of that
ohh im trolling i did have x^2 = 2x + 2
Bruv
Alr gtg
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How would you solve for this problem?
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idk where to begin
i dont understand the problem
Use similar triangles
Look at the triangle with the pole. You know the ratio of pole height : pole shadow height.
That's the same ratio as tower height : tower shadow height
There are two triangles, a big triangle with the tower, and a small triangle with the pole.
The two triangles are similar because one of the angles is a right angle, and another angle is shared between the two triangles.
In similar triangles, the ratio of corresponding sides are the same.
im not understanding the question i reread it like 5 times
ik its simple like you find the ratio then mutiply
What part of the question do you not understand?
The question says 4.75 but yes.
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how could I set this up to find the answer by hand using u substitution
hmm like normal u sub? the first thing that comes up to mind is trig sub
like i tried this and got stuck
How I would approach this, you can find out sec3 theta bydoing integration by parts
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oh my
ty
i bout to watch a video on trig sub
oh did you not learn it.... i feel like its best not to use it if you have never seen it
possibly but if I did I forgot since my integration chapter
why are you able to set x to tan theta?
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i never knew too much in detail why its like that, in general if the integral involves sqrt(a^2+x^2) you use x as: atan(theta)
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$\int \frac{x^2}{1-ax}dx$ need help figuring out if im doing this correctly
Triaxyz
I used poly long division and got $\frac{x^2}{1-ax}=\frac{1}{a^2(1-ax)}-\frac{x}{a}-\frac{1}{a^2}$
Triaxyz
which could then be integrated normally
,w [1/(a^2(1-ax)-x/a-1/(a^2)]
plotted both on desmos with a as slider and showed the same thing with different a values
but it's the integration part that gets a different answer from wolfram
an easier way would be to let u = 1 - ax
different how
could try that if you're not confident with this method
let me write it 1s
might just be a constant thing
Couldn't partial fractions be used?
not quite no
integrating this gave $\int \frac{x^2}{1-ax}=a^2 (\frac{1}{a}\ln(1-ax))-\frac{x^2}{2a}-\frac{x}{a^2}$
Triaxyz
degree of numerator is higher than denominator
nope
Oh, i see
$\int \frac{x^2}{1-ax}=a^2 (\frac{-1}{a}\ln(1-ax))-\frac{x^2}{2a}-\frac{x}{a^2}$
Triaxyz
missed negative sign
should be -1/a^3 no?
^
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I was wondering if someone could walk me through this problem, Iām not even sure where to start
A spherical rain drop of radius R and mass M falls vertically through a cloud layer. The drop enters the cloud layer at a height H from the ground and exits the cloud at a height h. While inside the cloud the drop accumulates water molecules so that its mass and size grow with time. The mass of the rain drop at time t when inside the cloud is given as follows: m(t) = M + αt with t = 0 at the time the drop enters the cloud, and α the rate at which water molecules accumulate.
a) Write an expression for the acceleration in the vertical direction of the raindrop, as a function of time and the velocity v. Choose a coordinate system in which downwards is positive.
!status
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1
There was a hint that said you should think of this problem as a rocket with a constant external force but instead of losing mass it is gaining mass. So maybe itās something like
acceleration = aln(M/(at+M))
but it says it wants it as a function of velocity and time
@crisp zenith Has your question been resolved?
@crisp zenith Has your question been resolved?
Let the "force" be F and the acceleration be A, then:
v=(MA)/(M+at)
MA= v(M+at)
MA= vM+vat
A=v+[(vat)/M]
So, you know by Newton's second Law that $ F_ext = \frac{dp}{dt}$
$$ F_{ext} = \frac{dp}{dt}$$
The Mad Pirate
where p(t) = M(t)*v(t) , therefore :
$$ F_{ext} = \frac{dM}{dt} \cdot v(t) + M(t) \cdot \frac{dv}{dt}$$
The Mad Pirate
The Mad Pirate
being g the acceleration due to gravity
so
$$ a(t) = g - \frac{\frac{dM}{dt}}{M(t)} \cdot v(t) $$
The Mad Pirate
@crisp zenith There , I corrected the sign
@crisp zenith Now it makes sense, if the mass increases, then the drop will decelerate.
@crisp zenith when a(t) becomes zero, the drop will reach terminal velocity and move with constant terminal velocity v_tm from there
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How would i express #4
Do you know the definition of definite integral
The area under the curve is defined
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how do I quickly find what function fits a table the best?
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Do I need to convert the radians to cos/sin coordinates? Like for a) theta = pi/4.
should I do X = 5cos(sqrt(2)/2)? Or X = 5cos(pi/4)
well, if you do so, you'll have the coordinates of P, yeah?
How does $x = 5\cos(\frac{1}{\sqrt{2}})$ make sense
ColdTee
How is that different
Oh Iām thinking of a unit circle
Even tho l = 5?
$r\cos(\theta) = x$
ColdTee
$r\sin(\theta) = y$
ColdTee
,w 5\sqrt{2}/2
I guess it makes sense tho cause a^2 plus b^2 = c^2?
Wait thatās different then mine
If you do 5cos(pi/4) you get 4.999
I did it in demos
,w 5cos(pi/4)
,w 3.5^2 + 3.5^2
,w 5^2
Wait Iām still kinda lost on how i can get that with a calculator
Bc even on my calc i got 4.998
That would make sense wut am I doing wrong
Change it to radian
Click stuff till you see rad
Legit did all of them
lol
Perhaps
We havenāt done grade yet idk wut that is
I have no idea
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@civic drift wait I donāt think Iām allowed to use a calc
Is it possible to do this without a calculator
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Does the question need to specify the number of bits in the adder?
Because if that's the case I can solve it, but this without anything idk
yes overflow usually occurs when resulting bits are more than the bits that register can handle
so i believe according to definitions you are correct
All three, yea?
yea since no size is given and definitions fits correctly it seems correct
Ok and for b and c, since they're unsigned, there's always no overflow?
Overflow happens when there's a problem with the signs according to what my professor said
Since we have no signs in unsigned then in this case (no size) always no overflow
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I need help with this question
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@agile onyx Has your question been resolved?
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I have a question
What is this chapter called in english so I can search it up on youtube? I tried searching for "rotation around an axis" but i found very little
hi
hey
i need help on math im not good
make separate channel
u gotta go to an unoccupied help channel
where
https://discord.com/channels/268882317391429632/488120190538743810
go here @pale escarp
ty
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$f(x) = (x - 1)^2(x + 1)$
GMDennis
i have absolutely no clue as to how i'm supposed to do this
i think that it can theoretically become
$(x - 1)(x - 1)(x + 1)$
GMDennis
i need to sketch it
im trying to find all the correct x ints
so that it can be easy to graph
ofc
ie. (x+1)(x-1)^2 = 0
but ab = 0 only if a = 0 or b = 0
so (x+1) = 0 or (x-1)^2 = 0
does that help
uhh
i figured out that if there's two x ints that are the same then it's basically just 1 one of them, i.e. it doesn't go throught x-axis at that point, it just touches it
$0=(x-1)(x-1)(x+1) therefore (x-1)=0 or (x+1)=0$
marcus
is this right?
Sry first time using the bot
dude i got it alright
all right*
im getting the hang of this
im so excited
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are divergence and curl defined for scalar valued functions ?
no
and is the multivariable chain rule defined for vector valued functions ??
the multivariable chain rule is used in computing derivatives, which may be useful for computing a differential operator like divergence and curl
is there a specific problem or context for this?
last question is unrelated to divergence and curl
i just want to know if the multivariable chain rule is defined for vector valued fcts
what is the derivative of a vector function?
Adam Chebil
then if x, y are functions of some variable t, then the total derivative with respect to could be calculated with the multivariable chain rule in each component
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I wanna know if I did it right
looks good
but just for next time
dont make it so messy
you can write $\frac{1}{x-1} as (x-1)^-1$
sin
sin
aigh fsfs
u good w calculus or-?
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yeah
$y = [(x-1)^-1]-[9(x-5)^-1]$
sin
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Np
btw I need some more help
if ur free
can I dm you?
sure if i can help
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Does anyone know how to take the inverse of a matrix using elementary row operation?
Start with the identity matrix on the left side and row reduce until you get the identity matrix on the right
Wait what I thought the identity matrix went on the right of the original matrix
Doesn't really matter
If you thought that then clearly you know this method already
When in doubt, write it in form of a system of linear equations
@terse granite Has your question been resolved?
I forgot how to row reduce by hand -_- um do you swap r1 with r2
Lol, still, when in doubt, come back to the associated system of linear equations. The "operations" are simply the way you manipulate and solve the systems, put more rigorously
I'm sure if I ask you to solve
0x + 2y + 3z = a
1x - 1y - 2z = b
2x + 2y + 3z = c
then you'll have no issue
then you can translate how you solve that system to appropriate operations
Thank you!
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curious if im doing something wrong
This is a quadratic function word problem correct?
thats what im thinking, the assignment is called "Solving Real Life Exponential & Logarithm Problems"
their "time" is continuous and not in units of years
So you need to use continuous compounding formula or something
N * exp(rt)
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I'm wondering what I missed here about it being surjective. I can't see why this is "not quite"
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recall the formula for area of trapezium
1/2(sum of lengths of the parallel sides)
x height
what does GR equal
ohh
nvm
i got it
its 168
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<@&286206848099549185>
could you translate to english?
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@mild fog Has your question been resolved?
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I need some guidance in figuring the length and width of the rectangle in order to find the area of the complete square
Iām confused as to how I can used the given information that the area is 18 of the rectangle cause I know the length and width wonāt be the same as a square š
Why no one willing to save him. heās in urgent situation, that he might lost his home, composed by ice, if we do not take any action towards the deteriorating weather pattern.
@serene viper Has your question been resolved?
I will help you then
Thanks I appreciate it, cause Iām confused how to approach in finding the sides of the rectangle
Does the final answer include ālā and āomegaā?
Ohh
Nope according to my friend is 324 but he couldnāt explain it cause he had to go to sleep
Yea since its a square finding one side of the inner rectangle would be enough to find the whole area of the room
I thought it is solved?
Let me ran on that poor system of equations
I found omega = 6 and l =3
Which, after we plotting them into the lengths of the square room, gives us 324 aka 18^2 as the area of the room
The top equation is derived from the property of square (the wide and height are the same in such a shape)
Ah I see now makes sense
While the bottom is derived from the given information that the rectangle tile has an area of 18
Damn did not think of system equation lol
Remember that once youāre given to variables
Let me think how to phrase my words
if there are ārā variables in a situation, then you would need ārā of equations to solve them
And r is numbers
For instance, given you have l and omega, that is, two variables
Then you need to find 2 equations in order to solve them
And, noted that, it is 2 ādifferentā equations involved these 2 variables ālā and āomegaā
Makes sense for sure now, at first I had in mind creating 15 + s and 12 + w but wasnāt sure how to use it because the chapter the book is based on polynomials lol
And forgot system equations were a thing to help solve situations like these where you have 2 missing variables
Thank you so much for the explanation, I can definitely sleep well tonight in my igloo š
No problem, now you can sleep well in your ice home.
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heya, can anyone help explain this one
been here for a solid hour
so i know the first step is to take the partial derivatives
and i get
$f_x1=2_x1-4_x2=0$
The Lean Monster
$f_{x_1}=2x_1-4x_2=0$
Aā¤Ć
okay, sure
ye mb i was tryin to figure out the latex notation
so i have the partial derivatives for x_1 and x_2
as far as i'm aware, we set these equal to 0 and solve
indeed
i just get x_1=0 and x_2=0 so i'm assuming i did something wrong
$f_{x_2}=-4x_1+4x_2=0$
$$x_2=x_1$
$$2x_2=x_1$$
$$x_2=2x_2\implies x_2=0 \implies x_1=0$$
Aā¤Ć
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seems fine
there is such a thing, i just need to go find it, been a while
ye
this is totally new to me lol
prof dropped this on my class without explaining
probably assumed we knew it
anyway here's what i get
$f_{x1x1}=2$
$$f_{x2x2}=4$$
The Lean Monster
yeeee
both my second partial derivatives are above 0
so looks like we have a minimum?
oh wait
i didn't read lmfao
looks like a saddle
so 2*4-some term i don't know how to calculate
is that last term basically a partial derivative but i take the derivative of both variables
the last term is just the x partial derivative of the y partial derivative
for your purposes its $f_{x_2 x_1}$
Aā¤Ć
(-4)^2 yeah
ye so we get 4*2*(-4)^2
alright epic
so does that mean i'm done lol
the goal here is to find the optimum but i can't think of any other place where the tangent will equal 0
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!status
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2
Show
so I differentiated it
to get 2mx x>=1
and 6x + k/2(x+1) when 0 < x < 1
but after putting 8 and 1/8 it doesn't cancel to a value
^^
as simple as it gets
just do the continuity and differentiability tests, you will get 2 equations in m and k to solve them
then u can simply find both of those derivatives to get the value
can you gimme a sample or solve one of em?
@shrewd elbow Has your question been resolved?
<@&286206848099549185>
kya hua
jaha f(8) lena hain , waha x >= 1 ki function ki value lagao
aur f(1/8) lena hain waha woh 0<x<1 ki value lagao
@shrewd elbow Has your question been resolved?
so I differentiate it then put the values?
I've done something wrong ig
I differentiated and put the values in but it's wrong.
<@&286206848099549185> can someone check this solution?
@shrewd elbow Has your question been resolved?
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what test can I use here?
Please don't occupy multiple help channels.
to find if it converges absolutey/conditionally
i thought if we take absolute value then it becomes 1/log(n)^n
and then i thought we oculd use some kind of comparision test
Please stick to your channel.
sounds promising, any thoughts on what to compare it with?
i thought we could do it with 1/log n
but then we need to prove 1/log n converges for which we can use ratio test
but does the sum(1/log n) converge?
yeaaa i dont know how to prove if it does or not
i am stuck there
oh so you want to compare it with 1/n??
well sum(1/n) doesn't converge either (it's the harmonic series)
sum((-1)^n / n) converges, but not absolutely, so the comparison test can't be used with it
but since sum(1/n) doesn't converge, sum(1/log(n)) can't converge, so i wouldn't use either one for the comparison
what about sum(1/n^2)?
yeaa that converges
so
something like:
1/log(n)^n < 1/log n < 1/n^2 and since 1/n^2 converges 1/logn^n also?
the 1/log n in the middle isn't correct, try just directly comparing
1/log(n)^n < 1/n^2
got it
thankyouu for all the help
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Hey
I want to know how and from where does the extra 1 revolution come from ( the answer is 4, i looked yt videos but didnt understand a thing
The center of circle A is what travels around circle B.
The coin rotation paradox is the counter-intuitive math problem that, when one coin is rolled around the rim of another coin of equal size, the moving coin completes not one but two full rotations after going all the way around the stationary coin, when viewed from an external reference frame. The problem can be generalized to coins of different...
i read the entire thing.
but i still didnt understand how
i don think so
The center of circle A moves, right?
nope
OK, get two coins.
it travels like the coins in the above link ( gif)
i did
i want to know, how does the extra 1 come from ( in mathematical sense
Yes, and I'm telling you that.
i already did that,
it came out to 2 rotations
I don't care what it came out to.
Did the center of the circle that you moved move?
umm yes ig
How far?
i dont get what u are trying to tell.
the centre moved in the respect to the 2nd plane ( table) i put it on
but it didnt move if i take the respect of the coin itself
So what?
werent u going somewhere with it?
Obviously one circle moved regardless of your frame of reference.
yes
so?
Pick one of them and tell me how far the center went.
^^ why is this neccesary
How am I supposed to lead you to the answer without taking the steps to lead you to the answer?
Do you want me to lead you to the answer before I can continue leading you to the answer?
Right, now trace the center of the moving circle.
I know that.
Since you know how it moves, trace the movement of the center of the moving circle.
like this
OK, what's the radius of the traced circle?
How an SAT question became a mathematical paradox. Head to https://brilliant.org/veritasium to start your free 30-day trial, and the first 200 people get 20% off an annual premium subscription.
I invented Snatoms, a molecule modeling kit where the atoms snap together magnetically. Try it at https://ve42.co/SnatomsV
Huge thanks to Dr. Doug Jung...
3x+ x = 4x
i alr said i watched the vid and didnt understand.
OK, so what's the circumference of the circle?
wait no that's wrong
mb
no i am right
Yes, if x is the radius of the small circle.
2 pi 4x
OK, what's the circumference of the moving circle?
OK, so you have a circle with a circumference of 2 pi x and you need to travel 8 pi x along its edge.
That will be 4 rotations.
You're welcome.
this applies to circles with any measures right? ( even equal
oh yeah
it does
thanks so much fr
Yes, it will always need 1 extra rotation.
You can see that by doing the same exercise with 3 replaced by m.
The radius of the traced circle will be mx + x = (m + 1)x.
And then you can continue from there.
alright
The idea behind it is that you can take your traced circle, cut it at one place and then lay it out in a straight line.
Then you have the circle rotate to get it to move along that straight line.
if i take the circle ( with 3x as radius)
and lay it out in a straight line the answer comes to 3
oh the one traced by the centre
Right.
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How do u write an equation using this
Does the half life matter?
$\frac{d\left[R\right]}{dt}=k\left[R\right]$
Why am. I here
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Idk what that is
How do u find the initial value
That is the whole question
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bit of a terminology question here
what does "complementary" mean here?
dropped a word maybe? probably meant to be complementary cumulative distribution function
so 1 - P( X <= k) = P( X > k) which looks like the form you have
the Pr{} is acting like a CDF right?
and also then what's a complementary cumulative distribution function
oh
the cdf goes from -inf to some k
complementary cdf as in going from k to infinity
is that right?
yes
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@vast shale Has your question been resolved?
,rccw
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@vast shale
1
So there are 12 months in a year, right?
So let's call the original function, f(x) = 1000(1.08)^x
alright
And we want to find g(x), such that g(12x) = f(x)
yes
g(x) = f(x/12)?
What is f(2)?
dont we divide the whole equation by 12?
f2 is 200
oh wait
nvm
f(2)= 1000(1.08)^2
exactly
so f(x) = 1000(1.08)^x
f(2) = 1000(1.08)^2
f(12928) = 1000(1.08)^12928
f(30/19) = 1000(1.08)^(30/19)
what is f(x/12)?
f(x)=1000(1.08)^1/12X?
yes
yes
well, sorry,
oh ok
I don't understand why you put x in the denominator
so what can i put as the final equation?
If you're asking me this, then it doesn't sound like you understood any of the work.
so
here is what I'm going to ask from you
please start here #help-17 message , and go back through the work, and if you get the a point where you don't understand something that I did or the reason why I did something, link me it and ask me about it.
alright thank you
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Can someone help explain this limit? I'm confused on why 3 when pulled out from the square root is just 3. I understand, that since the limit is to negative inf, the absolute value of x is -x. But why is 3 just 3, and not sqrt(3). Wouldnt the answer be 2/-sqrt(3) ?
when you pull constants out of roots they dont need an absolute value
it should still be in a square root
that too
looks like a mistake.
Okay so it's just wrong lol. I see
Yeah, the fact the 3 wasnt in the square root was my only question. I understand the absolute value stuff
I started thinking Im insane and that you only need to root the x if it's multiplied together
@frozen bobcat sir please help me in 37
what is 37
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Help.
f(x) =(a + b)² -1
whats the question
maybe take a screenshot or smn?
Can you explain how I solve it Iām asking for a friend
Is it like a graph or something
we cant solve it without the question
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is Z5 x Z5 x Z5 -> Z25 x Z5 isomorphic?
no, one of them has an element of order 25 (namely (1,0)) and the other doesn't (anything multiplied by 5 is (0,0,0))
f((a,b,c))=(5a+b, c)
f(mod 5, mod 5, mod 5) = (mod 25, mod 5)
well that's a bijection, but you said "isomorphic" so i assumed you were talking about some sort of structure
they are isomorphic as sets because they both have cardinality 125, but no isomorphism preserves + or *, assuming that the structure on Zn is modular arithmetic
Oh sorry maybe its a different question then,. the original q was Prove or disprove: Z5 x Z5 x Z5 is isomorphic to Z25 x Z5
Zn is addition mod n
f((0,2,0)+(0,3,0)) = f((0,0,0)) = (0,0)
f((0,2,0))+f((0,3,0)) = (2,0) + (3,0) = (5,0)
so that's not a homomorphism
the issue is that Z25 x Z5 has elements like (1,0) in it, that are still not zero when you multiply by 5, and Z5 x Z5 x Z5 doesn't
so they're not isomorphic
is this a theorem? I want to disprove it then since you convinced me
how to write a formal disproof*
that's pretty much a proof, you might just want some extra details
namely that isomorphisms preserve order, if you haven't already proven that
i might know that isomorphisms need to have the same orderfrequency to be isomorphic but idk if it is the same thing ur talkin about
and then just like
every element of Z5 x Z5 x Z5, if you multiply it by 5 you end up with (5a,5b,5c) = (0,0,0)
and then if you assume something gets mapped onto (1,0) in Z25 x Z5 you get a contradiction
"order" as in the number of times you have to add the element to itself to get 0
yep
in Z5 x Z5 x Z5, everything is order 5 (except (0,0,0) which is already 0 and therefore has order 1)
in Z25 x Z5, (1,0) is order 25
i don't think it really has a specific name? it's kind of just an instance of the general principle where isomorphisms tend to preserve basically everything
but it should be fairly simple to just like
you can prove by induction that f(nx) = nf(x), for a natural number n and an element x and f any homomorphism
and then you can just take the definition of order and apply that to it
nx = 0 iff f(nx) = 0 iff nf(x) = 0
the first one because f is an isomorphism, the second one because this
and then from that you get that the order of x and the order of f(x) are the same
Thoughts ? Sorry Im simple minded I do not want to remind myself of induction haha
Z5 x Z5 x Z5:
ord((0,0,0))=1
anything else is ord 5
Z25 x Z5:
ord((0,0))=1
ord((1,0))=25, which is not in Z5 x Z5 x Z5
Since isomorphisms must preserve order, they are not isomorphic.
yep that works
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Linear Algebra Question: If I get the kernel of a matrix to be the zero vector, what is its dimension?
do you know how dimension is defined?
number of independent column vectors
but yea
maybe think about it geometrically
say we're in 3 dimensional space
what does a 2-dimensional subspace look like?
nope, that's one dimensional
so a plane
yep
so a point would be zero dimensional
now you have a vector space which is just the origin basically
yep zero dimensional is correct
sure, cheers
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can someone explain me this pls š
<@&286206848099549185>
.
yea i dont know how to do it, its really confusing i need someone to explain it to me
when you expand it out you get that. when n=0 or 1 it's obvious. from there just inductively multiply by a+b and you'll get the next one thus it holds for all n. you can look at the binomial expansion, each term is the sum of the two above it
basically
do u know the pascal triangle
yes i did expand it and apparently we have to take "n" value as K and multiplying both sides with (a+b)^1 we i get (a+b)^k+1
yea
well c is each position for the pascal triangle
so if (a+b) is adding then every part of the equation is positivo
POSITIVE
and then for the left side of the equation (a) u start from n and every time u substract 1 to the exponent until u reach b^n
in here ur gonna take for C n+1 rows
so if n = 2
ur gonna take the 3rd row
1 2 1
those are the values of C
and then if u got (x+y)^3 for instance
u would use the 4th row 1 3 3 1
followed by the eeuqations
this shi
ALRIGHT WHAT AM I WATCHING
ITS WHAT IM TELLING U THERE IS NO OTHER WAY
the first pic, look under (a+b)^k (a+b)
this is so fucking confusing, ive been breaking my head over this for so long š
here u do x^3
then u do 3x^2 * y
u substract the exponent of one variable and add it to the other one
ahhhh i see
follow
what would be the rest of the equation
i gave u 2 components
give me the rest
but is it necessary to write so fucking much like in the pic ive shown you or can i shorten it
Man thatās theory
it depends on the number of n
until the second component (in ur case b) reaches b^n
do this one
so can i write it as KC0a^k+1+KC1a^k+KC2a^k-2.......+KCkb^k+1
first of all, you should have said at the beginning that you were talking about the inductive proof of the binomial theorem, this is clear from your pictures that you pasted here. You will find a lot of exactly such proofs written on the Internet, I don't think anyone here would spend two hours writing such a proof, which is not difficult, but it is time-consuming.
aight got it

well sorry i didnt mention it clearly, mb
alr wait
u donāt need to add the 3 dots
and u can replace the Cs for the fourth row of this triangle
since itās n+1
also when u reach a^0 ur done donāt continue
and donāt wirte the a because anything ^0 is 1 so donāt matter
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wouldnt the first equation be on top?