#help-17

1 messages · Page 151 of 1

noble spindle
#

Do you see a pattern

green crystal
#

not really

noble spindle
#

Well i thought i saw something but nope

green crystal
#

for 4 strings 16 of them start with a

noble spindle
#

How did you get 9?

green crystal
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i counted

noble spindle
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Isnt it 6 a (something) (3 options)

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aba , abb , abc , aca , acb , acc

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Where did you find the other 3?

green crystal
noble spindle
#

First 3 are not the ones we are looking for

green crystal
#

oh right

noble spindle
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They are not aa free

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So 1 , 2 , 6

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Its like its sum of all the previous ones times 2

green crystal
#

we could verify that once we get T4

noble spindle
#

Get for T_4 then ig

green crystal
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im getting 8

#

so not that

noble spindle
#

abab , abac , abba , abbb , abbc , abca , abcb , abcc , acab , acac , acba , acbb , acbc , acca , accb , accc

green crystal
#

ah

#

so thats 6+2*2

noble spindle
#

Yea

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Try proving it

green crystal
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T4= 18-8+1=11

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@noble spindle do you remember the 00 free string question

noble spindle
#

Yeah

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Not really but yeah

green crystal
#

maybe that would help

noble spindle
#

Try it

green crystal
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try what

noble spindle
#

Idk. I mean all those questions basically require you to solve the past ones. I cant quite follow all of it because im not solving them. If you understand the solution of that question then you should be able to somehow solve this one.

green crystal
#

ive done all and i didnt do them in order and still solved idk what u mean lol

noble spindle
#

Then i suggest you do them in order ig

green crystal
#

... what ? ive done all of them thats the last one

noble spindle
#

Oh ...

green crystal
#

so im guessing you got no clue with this yea?

noble spindle
#

Well my brain is currently not really working at max speed. Believe it or not me being in this server is just procrastinating on doing math by doing easier math.

green crystal
#

well then

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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fallen sand
#

is my answer correct

vocal sleetBOT
fallen sand
#

My work

dense raven
#

I'm pretty sure the derivative of f(x)g(x) would be f'(x)g(x)+f(x)g'(x) because of product rule and it seems you've written it as (f(x)g(x))'

#

I'm not sure if that would work

fallen sand
#

oh ok

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latent hamlet
#

The only thing I know about this set of points is that the distance from D to B is larger than the distance from A to C, I need help proving that it's impossible to draw a circle around D and B without that circle also containing either A or C

vocal sleetBOT
#
What step are you on?
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
latent hamlet
#

2

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
#

Show your work, and if possible, explain where you are stuck.

latent hamlet
#

6

#

.close

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devout lion
#

Question about the Gaussian method for linear systems: I'm trying to understand why when we do Gaussian elimination for a system like Ax = b the operations we do on each row are reflected on the known terms b, but NOT when we are trying to do an A=LU decomposition.

devout lion
#

row swaps affect b but not operations like R2 - 2*R1 --> R2

#

<@&286206848099549185>

vocal sleetBOT
#

@devout lion Has your question been resolved?

hard atlas
#

well when we do a LU decomposition we record the row operations in the matrix L

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and then when we want to use the LU decomposition we have to solve two systems

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first Ly=b and then Ux=y

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and in the first step we basically apply the row operations to b

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#

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restive tinsel
vocal sleetBOT
restive tinsel
#

to remove it don't I want to factor numerator and cancel out?

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it would be x+3

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so f(x) = 8?

plucky valve
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bleak sphinx
vocal sleetBOT
livid horizon
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
bleak sphinx
#

1

livid horizon
#

Do yk the expansion for sin(a+b)?

bleak sphinx
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I do not

livid horizon
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sin(a+b) = sin(a)cos(b)+sin(b)cos(a)

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Have you seen anything like that before?

bleak sphinx
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No this would be my first time working with this

livid horizon
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Oh

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I don't see any other way tho

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Yeah ig you'll need to know the expansion

bleak sphinx
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Oh

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Any chance u could solve it and show me your work? Maybe I can work another one off using a similar problem

livid horizon
bleak sphinx
#

Hmm I’ll try watching YouTube videos

livid horizon
#

Ok

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You've to just find each of the right side term values and plug it in

bleak sphinx
#

Lemme try and see what I get

#

I got .813

vocal sleetBOT
#

@bleak sphinx Has your question been resolved?

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unique sluice
#

im not sure how to differntiate this, i asuume it would be using U sub? answer is B

vast shale
#

yes

unique sluice
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my u would be 1 + 4x^2 ?

vast shale
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yes

unique sluice
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yes i know im just struggling to get there

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let me try

unique sluice
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ye

unique sluice
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i did not get B

vast shale
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ok but u didnt do the actual integration lol

unique sluice
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would i have to distrubute the 1/2 first and then integrate

vast shale
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no

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also what 1/2?

merry cosmos
vast shale
#

you have [
\int \f x{\s{1+4x^2}} \dd x \overset{u=1+4x^2}= \f18\int\f{\dd u}{\s u}
]

twin meteorBOT
vast shale
#

so integrate the 1/sqrt(u)

unique sluice
#

yes, and sqrt u is = to u^1/2

vast shale
#

yes

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so

unique sluice
vast shale
#

use the fact that [
\int x^n \dd x = \f{x^{n+1}}{n+1} + C \qq n \in \R\setminus\set{-1}
]

twin meteorBOT
unique sluice
#

oh wiatt

vast shale
#

no like

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raise the denominator to the numerator

unique sluice
unique sluice
restive echo
#

help

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help'

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help

#

help

merry cosmos
unique sluice
#

what

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<@&286206848099549185>

woeful cobalt
#

oh

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dang

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you have to do u sub

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oh crap you did that

unique sluice
#

ye im not sure where i am goign wrong

woeful cobalt
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you did it wrong

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you set u to 4x^2

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and then do it from there

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you will get a inverse trig integral

unique sluice
woeful cobalt
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thats fine

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just do it and then you will get it

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you will get the 1/8

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but you will have integral of 1/sqrt(1+u)

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oh wait

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im too dumb

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you got to set u to 2x

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and have it with a square

unique sluice
#

wait wait what, where

woeful cobalt
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or just do it the other way

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nvm

woeful cobalt
#

and the you integrate it to get 1/8(2sqrt(u))

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your mom

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my bad its 35

unique sluice
#

im not sure that is meant to be integrated

woeful cobalt
#

but it would simplify to that

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cause integral of $1/(s{x}) is just 2(s{u})$

twin meteorBOT
#

memeprime.

woeful cobalt
#

oop

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i suck at this

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either way you do that and then you plug in 1 + 4x^2 to get the result

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which would be 1/4(sqrt(1+4x^2))

unique sluice
woeful cobalt
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because 1/8 * 2 = 1/4

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from the integration

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because we need the 2 from the 2sqrt(2)

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if you differentiate 2sqrt(2) you will get 1/sqrt(2)

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and vice verse with integration

unique sluice
woeful cobalt
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cause integral of 1/sqrt(u) is 2sqrt(u)

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try it yourself

unique sluice
#

so we were supposed to integrate that like that

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you dont integrate after you plug u back in?

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you integrate before?

woeful cobalt
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yeah

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and then you plug in u

woeful cobalt
unique sluice
#

that was helpfull

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thank you

woeful cobalt
#

👍

unique sluice
#

better?

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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frosty thorn
#

I have this graph and i’m asked for the local minimum

astral shadow
#

,rccw

frosty thorn
#

in this instance it would be -1,-3 but what would happen if the point were the lowest

twin meteorBOT
wide vector
#

lowest y value

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wym

astral shadow
wide vector
#

if it were the lowest it would be the min

frosty thorn
#

would -4,-5 be local min?

wide vector
#

ah ok

noble spindle
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Do you know the definition of a local minimum?

frosty thorn
#

uhh yes but i need clarification because my teacher said “it is and isnt”

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intuition tells me it would be but i’m not sure why it wouldn’t be one

noble spindle
#

In mathematical analysis, the maximum and minimum of a function are, respectively, the largest and smallest value taken by the function. Known generically as extremum, they may be defined either within a given range (the local or relative extrema) or on the entire domain (the global or absolute extrema) of a function. Pierre de Fermat was one of...

noble spindle
#

Like there doesnt exist a single $\epsilon > 0$ such that $f(-4) \leq f(-4 - \epsilon)$

twin meteorBOT
#

casework

noble spindle
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Because well it isnt defined there

rare pike
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if you're talking about $x\in\mathbb{R}$ then (-4,-5) would be considered as a global extrema

twin meteorBOT
#

Anonymous

frosty thorn
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alr thanks

rare pike
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while for example if you considered the function for $x\in[-2,1]$ then (0,0) is also a local minimum

twin meteorBOT
#

Anonymous

frosty thorn
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he said it really didn’t matter if we considered it to be one or not i was just confused why it wouldn’t ever not be

rare pike
#

ya they probably arent picky abt it

frosty thorn
#

ty

#

.close

vocal sleetBOT
#
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vast shale
#

Claim

vocal sleetBOT
vast shale
#

I dont know where to start

vocal sleetBOT
#

@vast shale Has your question been resolved?

vast shale
#

<@&286206848099549185>

vast shale
vast shale
vast shale
#

<@&286206848099549185>

vast shale
vast shale
#

Quadratic

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I believe

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Tho i took questions for sequence and series and straight line 🥴

vast shale
#

so did algebra yk?

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with adding 2 first of all I think

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could be wrong tho

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Naw

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Dont

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You have to do all this

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Without a calculator

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Pen and paper

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3 minutes max

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I dont think they want me to solve from roots

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That would be too long

vast shale
#

umm

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do you have any ideas 😭

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Nope

vast shale
# vast shale

since m is a non zero integer, it's a integer (whole number) and is either negative or positive

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Positive or negative

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Integer

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Right mb

vast shale
#

Yo thanks 😭

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Cuz im giving a test simultaneously

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Cuz i have a test tomorrow 😭

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And this was from the last test

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😭

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Im depressed af

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no other common factors than one is relatively prime numbers

vast shale
vast shale
#

I dont get you

vast shale
vast shale
vast shale
vast shale
vast shale
# vast shale

one root of the equation 2000x^6 + 100x^5 + 10x^3 + x - 2 = 0 is of the form m + sqrt n divided by r

vast shale
#

I FOUND A QUESTION LIKE THE ONE YOU ASKED ON AN OLD FORUM

#

Yoooo

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Send the soln

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@vast shale

vast shale
#

Lmao

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Try that

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since it's just math speak atp

vast shale
#

To the solution 😭

#

-1+ 161= 160 divided by 40 equals 4 ohh it's 4

vast shale
vast shale
#

I go blind

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Those are too many letters

vast shale
vast shale
#

Im dumb thanks

vast shale
#

I have one more

vast shale
vast shale
vast shale
#

I understood whats written

vast shale
vast shale
vast shale
#

That was what i was meaning to say

#

And in the future, i would use this technique to get answers for similar questions?

vast shale
# vast shale

I failed in solving this particular question, but not the next time!

vast shale
#

so that you won't bomb your test

vast shale
vast shale
vast shale
vast shale
#

Thanks man

#

One more question?

vast shale
#

I solved it btw

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Wanna check

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Answer

vast shale
#

Hint?

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Find coefficient of x^(n-2)

vast shale
#

Naww 😭😭

#

This is probably binomial theorem

vast shale
#

what type of math is that

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Idk wht type

#

Of course the binomial theorem is taught in pre-university algebra courses. It is part , for example, of the Common Core curriculum which is broadly used in the US nowadays

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Says quora

vast shale
#

DM me if you get an answer or want a solution

#

Thanks for helping

#

.close

vocal sleetBOT
#
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vast shale
vocal sleetBOT
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rare oyster
#

help anyone?

vocal sleetBOT
rare oyster
#

<@&286206848099549185>

#

<@&286206848099549185>

north relic
rare oyster
#

oh okay

#

anyone else?

#

<@&286206848099549185>

#

<@&286206848099549185>

#

someone?

#

<@&286206848099549185>

vast shale
#

What does it mean by increasing order?

rare oyster
rare oyster
oblique swift
#

hi

rare oyster
#

can you help me out

rare oyster
rare oyster
vocal sleetBOT
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@rare oyster Has your question been resolved?

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vocal sleetBOT
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@rare oyster Has your question been resolved?

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rare oyster
#

hey guys, a little help

vocal sleetBOT
#

Please don't occupy multiple help channels.

rare oyster
#

@graceful ibex

gusty beacon
#

you just have to check the amount of times you need to travel along the x vector lines

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and make sure that they are like 2.3 away from their starting point

rare oyster
#

I don't think thats correct..

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it shouldn't be based on that

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because you have to look at the actual grid

gusty beacon
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c is a variable that's free

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which means what you need to analyze is the x vectors of the grid

rare oyster
#

yeah, your logic makes sense actually... it's just not showing up as correct when I'm plugging this into the verification system 💀

gusty beacon
#

oh wait my bad

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try z, w, u

gusty beacon
rare oyster
#

still wrong lmao

#

its not your fault I tried many many times before coming here

gusty beacon
#

w, r, z?

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we just need to use the parallelogram law with an x grid length of 2.3

rare oyster
#

yeah exactly

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but it is still not working

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idk what to do now

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@gusty beacon any ideas

gusty beacon
#

w and z should work

rare oyster
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okay yeah

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it was w,z,t

gusty beacon
#

oh that makes sense

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yeah it should fall on the same parallel line to the y-vector lines

rare oyster
#

yeah because it satisfies the parallelogram formatio

gusty beacon
rare oyster
#

wait I had another question, it's a little harder but do you think you can help

gusty beacon
#

oh sure

rare oyster
#

I have some ideas for hwo to solve it based off matrix theorems but honeslty idk

gusty beacon
#

oh shoot I didn't get that far in linear algebra yet sorry idk if I can help with this one

rare oyster
#

oh yeah its fine lol dw abou tit

#

@graceful ibex ^

rare oyster
#

@graceful ibex

vocal sleetBOT
#

@rare oyster Has your question been resolved?

fossil shoal
#

Construct the matrix using these as rows, what does it look like?

vocal sleetBOT
#

@rare oyster Has your question been resolved?

rare oyster
#

like a series of rhombuses?

fossil shoal
#

What

#

What do you mean rhombuses

#

A matrix is a grid of numbers

vocal sleetBOT
#
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thin wave
#

this is for homework, ive been stuck on trying to solve this problem using the identities but i dont know what im doing wrong... i dont know how to solve this. i only got the last one right cause of inverting tan

thin wave
#

trigonometric problem

copper crypt
#

imo just use sin^2+cos^2=1

thin wave
#

I've tried but for some reason it gets it wrong so I was trying to mess around

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I don't know if I'm doing it wrong though

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I tried using tan^2=1+ sec^2 as well

copper crypt
#

Is this what you tried

thin wave
#

Yeah

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I can try it again though

copper crypt
#

I got

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||cosx is -sqrt(9/13)||

thin wave
#

Yeah I got something like that too, although I put it as 3/sqrt13

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Or wait

#

Maybe I forgot to put negative

copper crypt
#

Negative?

#

Oh yea

thin wave
#

My computer is messing up rn, i'll have to try it again later, but thanks for the help

thin wave
#

why is it 2/3 ? isnt that tan not sin?

#

or theres other identities

copper crypt
#

sin/cos=tan=6/9=2/3

#

so sin=(2/3)cos

#

I was using x for cos up there

thin wave
#

oh wait

#

ok i see the x

#

idk how to solve that though

#

nvmind im stupid. i figured it out

#

thanks

#

how do i do the sin part of it?

#

i see that cos= sin/tan, but how do i solve that in the equation

vocal sleetBOT
#

@thin wave Has your question been resolved?

vocal sleetBOT
#

@thin wave Has your question been resolved?

thin wave
#

.close

vocal sleetBOT
#
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vocal sleetBOT
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unique sluice
#

im not sure, my intial idea was to plug in 12 and 15 for t and then subtract the outcomes

unique sluice
#

im not even sure

flat whale
unique sluice
#

im not sure i understand what you mean, are you saying do this

twin meteorBOT
unique sluice
#

differnce in time hummm

#

fancy

#

but the time would not be starting at 0

#

thats where the equations we are solving begins yes

#

well in thta problem it tells you from 9 am to 9 pm. so you are starting at 9 am. it tells you your starting point, which a starting point would be 0

#

my starting point is stated as midnight in the problem

#

meaning start at 12 and count up till noon and 3 pm

#

which would be 12 and 15

#

wait im still confused how to solve my probelm tho

twin meteorBOT
unique sluice
#

what

#

am i usign u sub for this?

#

im pluggin what into what?

vocal sleetBOT
#

@unique sluice Has your question been resolved?

unique sluice
#

uh

twin meteorBOT
unique sluice
#

i quit man

#

.close

vocal sleetBOT
#
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silent linden
#

help where do go from here

vocal sleetBOT
silent linden
#

this is my working so far

vocal sleetBOT
#

@silent linden Has your question been resolved?

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@silent linden Has your question been resolved?

silent linden
#

😭

vocal sleetBOT
#

@silent linden Has your question been resolved?

vocal sleetBOT
#

@silent linden Has your question been resolved?

spiral turtle
#

@silent linden it's been quite a long time for me and QM, but if I recall this problem correctly, the trick will come down to using the definition of the matrix exponential.

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wise marten
#

What is the simplest rational function that has a removable discontinuity at 𝑥=−2 and an infinite discontinuity at 𝑥=0?

pallid zenith
#

you can just create these features

#

use a product

#

so create one with the one feature

#

then one with the other

wise marten
#

what is a feature

pallid zenith
#

their product will have both

pallid zenith
#

whats the simplest rational fn with an infinite discontinuity at x=0?

wise marten
#

f(x) = 1/x ?

pallid zenith
#

and the removeable discontinuity?

wise marten
#

idk how to type is properly

#

the awnser i got is

#

f(x) = x+2/x^2

pallid zenith
#

not quite

#

,w plot x/x

pallid zenith
#

how about this fn

#

x/x

#

wheres the discontinuity

wise marten
#

there isnt one

#

?

pallid zenith
#

there is

#

its at x=0

#

but, its removeable

#

(we can just write x/x=1/1=1)

#

so, with that template

#

what fn has a removeable discontinuity at x=-2?

wise marten
#

tbh im trying to teach myself this and i am super lost

#

i have no idea

pallid zenith
#

so x/x has disc at 0

#

because if we plug in x=0

#

we get 0/0

wise marten
#

yea

pallid zenith
#

this isnt defined

#

so, it follows that if you want to make a rational function with a discontinuity like this

#

we want something like f(x)/f(x)

#

where f(c)=0 at whatever c where you want the discontinuity to be

#

make sense?

#

we want 0/0 at some x=c

#

so make f/f where f(c)=0

wise marten
#

i wish that made sense

#

but unfortuatly not

pallid zenith
#

maybe i can give you the answer

#

i think itll make more sense once you see it

wise marten
#

yea'

#

the whole work backwards thing

#

works better in my head

pallid zenith
#

$\frac{(x+2)}{x(x+2)}$

twin meteorBOT
#

jan Niku

pallid zenith
#

try: what if x=0? what if x=-2?

wise marten
#

ohhhhhhhhhh

#

ohhhhh

#

ok

#

that makes complete sense now

pallid zenith
#

you see what i mean abt the discontinuity?

#

the removeable one

wise marten
#

yea yea

#

your a dog and a half for this

#

<3

pallid zenith
#

np

wise marten
#

now kinda a weird question

#

when im graphing it

#

it shows the same when i put f(x) = and without it

#

is it good practice to put f(x) = in desmos

#

even though it dosent change the product

#

like

#

these give the same thing

#

but is it better practice to do the first one?

#

.close

vocal sleetBOT
#
Channel closed

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pallid zenith
#

sometimes its convenient

wise marten
#

ok

#

thanks

pallid zenith
#

you have an extra x

#

btw

wise marten
#

where

#

wdym

wise marten
#

.reopen

vocal sleetBOT
#

pallid zenith
#

@wise marten

wise marten
#

what

#

is this not the same

#

oh nvm

#

lol

vocal sleetBOT
#

@wise marten Has your question been resolved?

#
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round plover
#

rearrange 3.75 = ar to a = 3.75/r

#

then you can substitute it into the other formula and solve for r

#

or the other way around

#

where did you get up to

#

\begin{align*}
\frac{15}{4}&=ar\
20&=\frac{a}{1-r}\
\
a&=\frac{15}{4r}\
20&=\frac{\frac{15}{4r}}{1-r}\
&=\frac{15}{4r-4r^2}
\end{align*}

#

do you have this at least

twin meteorBOT
#

Desync

round plover
#

sure

#

what next

#

multiply through by r-r^2

#

that yields a quadratic in r

vocal sleetBOT
#
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shy pond
#

How would I write an equation for Y1?

vocal sleetBOT
#

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gleaming shard
vocal sleetBOT
pale perch
#

that just hurts my eyes

#

who allowed that

#

$\frac{\sqrt{2}}{5} - \left(1-\frac{1}{5}\right) \cdot \frac{2}{5}$

twin meteorBOT
#

AℤØ

pale perch
#

have you tried anything?

gleaming shard
#

.close

vocal sleetBOT
#
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pale perch
flat whale
cobalt crypt
vocal sleetBOT
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rancid kestrel
#

I’m doing trinomial factoring by grouping and I see that I don’t have the same numbers in the parenthesis like I’m supposed to (5x + 2*6) and (5x + 2) what should I do?

rancid kestrel
#

Forgot to circle a 3 btw

smoky vale
#

since you are dividing by 3 x the 3 is also removed

#

6x/3x=2

rancid kestrel
#

Wait where am I dividing …

smoky vale
#

15x^2/3x=5x

#

i just say divided while you are really factoring out

#

because its not just factoring out the x, its also the 3

#

(15x^2+6x)
((3x)(5x)+(3x)(2))
(3x)(5x+2)

drifting jackal
#

Both terms have a 3, you didn't factor it out of the second term

rancid kestrel
#

Ohh ok

#

I see now

#

I didn’t circle 3 and messed up bc of that

#

Thanks

smoky vale
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#

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urban edge
#

Why is the tension equal to the weight? Should it be the sum of the gravity and electric forces?

true grail
urban edge
#

the tension is .049N, which is mg

true grail
#

hold on

#

what value have you been told to use for g

urban edge
#

it doesnt say, but 9.8 and 9.801 shouldnt make too much of a difference

true grail
#

my point is it might be 10

urban edge
#

unless the electric force is pieces compared to gravity

true grail
#

this is from a book right?

urban edge
#

yes

true grail
#

pieces?

urban edge
#

negligible

true grail
#

does it say at the start of the questions to use any particular value of g

urban edge
#

the tension force should be more, not less

true grail
#

hmm

#

wait

#

hold on

#

why is the answer giving you the tension when the question only asks for sign and magnitude of the charges?

urban edge
#

extra info ig

#

it also asks for |Q|

true grail
#

yes

#

i said magnituse

#

*magnitude

#

gdi im so out of practice

scenic ravine
#

T is required to solve this though isn't it ?

true grail
#

yeah probably

#

to work out the horiz component

scenic ravine
#

Because you don't know the electrostatic force you need it to balance components

true grail
#

since the verticals got to counteract grav

urban edge
#

just calculated, its like a 0.0002 difference

#

not enough to round

#

thanks for your help

#

.close

vocal sleetBOT
#
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silver kettle
#

I need help proving a bijection between any two ordered fields with LUBP is order isomorphic

sacred tulip
#

oops

#

mb

silver kettle
#

I have a map $f\colon F_1\to F_2$ defined by $f=\alpha_1\circ\beta_1$ where $\beta_1\colon F_1\to DC$ and $\beta_1(f) = { q\in\mathbb{Q} \mid i_1(q) < f }$ where $i_1$ is the unique injective map from $\mathbb{Q}\to F_1$ and $\alpha_2\colon DC\to F_2, \alpha_2(S) = \sup S$

twin meteorBOT
silver kettle
#

I (think) I know how to do it from $\mathbb{R}\to F$ but not sure when its abstracted like this

twin meteorBOT
silver kettle
#

For example for $f(a+b)=f(a)+f(b)$ I have something like the dedekind cut $\beta_1(a+b) = {q\in\mathbb{Q} \mid i_1(q)<a+b}$ but how do I find the supremum of this in $F_2$?

twin meteorBOT
silver kettle
#

I'm pretty sure I need to apply $\sup (A+B) = \sup A+\sup B$ but I don't know when to do that and also how to consider the supremum in $F_2$ since this DC "represented" by things in $F_1$ if that makes sense

twin meteorBOT
vocal sleetBOT
#

@silver kettle Has your question been resolved?

silver kettle
#

<@&286206848099549185>

vocal sleetBOT
#

@silver kettle Has your question been resolved?

silver kettle
#

.close

vocal sleetBOT
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mellow rampart
vocal sleetBOT
mellow rampart
#

Does this seem correct?

#

This is the mapping

#

.close

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vast relic
vocal sleetBOT
vast relic
#

specifically part 2

vocal sleetBOT
#

@vast relic Has your question been resolved?

hoary cypress
#

aand then remove the common terms which were counted twice

vast relic
#

so i know that i need to sum the multiples of 3 and the multiples of 5

#

and the common term is 15

hoary cypress
#

that is mutiples of 15

#

yes

vast relic
#

but i dont know how to make it a function of JUST n

vocal sleetBOT
#
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vast relic
#

.reopen

vocal sleetBOT
#

#

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unique sluice
#

whats the reasoning behind this being false

flat whale
unique sluice
rancid otter
flat whale
unique sluice
#

no

#

but i was asking

flat whale
unique sluice
#

guys

coarse marten
#

im not sure

vocal sleetBOT
#

@unique sluice Has your question been resolved?

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languid apex
vocal sleetBOT
languid apex
#

where does the A/x come from

#

i get the B/x^2 and C/(x+1)

#

<@&286206848099549185>

vocal sleetBOT
#

@languid apex Has your question been resolved?

restive ermine
#

The A comes from the term $x^2/x+1$

twin meteorBOT
#

The Mad Pirate

restive ermine
#

the idea behind partial fractions is to transform an algebraic equation in terms of a sum of algebraic terms

#

in true what you actually end up calculating are the residues in the complez plane for each pole, in this case the pole in z= 0 with multiplicity 2 and z= -1 with multiplicity 1

languid apex
#

i think i got it

#

maybe

restive ermine
#

the equation will be Ax(x+1)+B(x+1)+Cx^2 = 3x^2+x-1 whch leads to the linear equations A+C = 3 , A+B = 1 and B = -1 , so the end result is B = -1 . A = 2 and C = 1

languid apex
#

so if it was x^3

#

would it be x^3, x^2, and x

restive ermine
#

Basically you would end up with and unsolvable set of linear equations if you didnt had the A/x term

#

since you would had more unknowns than equations in that case

#

Are you planning on doing a stem carreer in college ?

#

$\frac {3x^2+x+1} {x^2*(x+1)} = \frac{2}{x} + \frac{-1}{x^2} + frac{1}{x+1}$

twin meteorBOT
#

The Mad Pirate

vocal sleetBOT
#

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sage mirage
#

Please help

vocal sleetBOT
sage mirage
#

How tf is that coming

#

<@&286206848099549185>

vocal sleetBOT
#

@sage mirage Has your question been resolved?

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@sage mirage Has your question been resolved?

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surreal lotus
#

hi does anyone know where i went wrong?

surreal lotus
#

it doesn’t factorise

gaunt sparrow
#

Can't you just solve for y with the quadratic equation or by completing the square?

surreal lotus
#

yeah but it doesn’t give the correct answer

#

i tried

gaunt sparrow
#

Oh wait

#

Second line is not true

surreal lotus
#

oh i see

#

it’s supposed to be (csc + cot)^2 isn’t it

gaunt sparrow
#

Yep

surreal lotus
#

thanks

gaunt sparrow
#

You can probably start from the initial equation and multiply everything by sin

surreal lotus
#

oh yeah that’s probably a faster way

#

thanks!

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#

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fickle snow
#

Can anyone help me solve this i

vocal sleetBOT
cobalt ocean
#

,rotate

twin meteorBOT
fickle snow
#

Please i have a test tomorrow <@&286206848099549185>

woven dragon
#

same lol i aint helping u

#

nanana

fickle snow
#

😭nah cause I am going to fail

woven dragon
#

lol same i have test tomorow

fickle snow
#

I am done fr

#

<@&286206848099549185> Helpppp

woven dragon
#

nah this seems hard i dont want to help u

fickle snow
#

You are in high school?

#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

#

. close

#

.close

vocal sleetBOT
#
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

languid ridge
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.

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Nn

vocal sleetBOT
arctic mantle
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oh hey same nickname

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cool

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anyway whats ur question

languid ridge
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Um can someone help me solve this, my teacher said that this is going to have something like this on quiz,

If G varies inversely with (2h+3) and g=4 when h=1, find G when h=3

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I dont get the question, i think imma find the K, but do i need substitute it

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The question is this

If G varies inversely with (2h+3) and g=4 when h=1, find G when h=3

vocal sleetBOT
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@languid ridge Has your question been resolved?

split wind
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do you know what does G varies inversely with (2h+3) means mathematically?

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like can you write an equation about them?

languid ridge
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Ummm hahahaha

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I did do (2(1)+3) which is 5? Then k=5?

split wind
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nah

languid ridge
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What do you do then?

split wind
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e.g.
if x varies directly with y, then x=ky
if x varies inversely with y, then x=k/y

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for some k that you'll have to find

split wind
languid ridge
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Maybee

split wind
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let's try

languid ridge
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Okayy what to do first?

split wind
languid ridge
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X=ky?

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Waittt

split wind
languid ridge
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It inversely so x=k/y?

languid ridge
split wind
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Next, what is x and y in this case?

languid ridge
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Ummm g4 and h1?

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Maybe

split wind
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nope

languid ridge
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Ummm

split wind
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let's compare both sentences

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imma type

languid ridge
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Okay

split wind
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Sentence 1:
If G varies inversely with (2h+3)
Sentence 2:
If x varies inversely with y

split wind
languid ridge
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(2h+3) and h3?

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Waittt

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Maybe

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H3 and (2h+3)

split wind
languid ridge
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Y is (2h+3)

split wind
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read vertically on which is pairing to which

languid ridge
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X is h3?

split wind
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x is G

languid ridge
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Huhhhh okayyy

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So we gunna find X?

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Wait

split wind
languid ridge
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I thought we gunna find G

split wind
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so, since now we know that the x is G, and y is (2h+3)

languid ridge
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So? K is missing?

split wind
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Let's rewrite this sentence from:
"If x varies inversely with y, then x=k/y"
to:
"If G varies inversely with (2h+3), then G=k/(2h+3)"

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all good till here?

languid ridge
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Yeahh

split wind
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now we have to find k to complete it

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it as in the equation

languid ridge
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K=xy?

split wind
split wind
languid ridge
split wind
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The question has 3 parts

"If G varies inversely with (2h+3)"

"and g=4 when h=1,"

" find G when h=3"

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we have done the first part, now we need to use the information in the 2nd

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Part 1, we have:
G=k/(2h+3)
and Part 2, we have
G=4 when h=1

languid ridge
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Okayy

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Wait

split wind
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so we plug in those numbers into the equation we found in part 1

languid ridge
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So x=4? Then y=5?

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Then times?

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So 20?

split wind
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k=20

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yes

languid ridge
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We do what nextt?

split wind
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from all the info till Part 2, we can rewrite the equation into:
G=20/(2h+3)

languid ridge
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Ohhhhhh

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Okayyyy

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Waitt

split wind
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hence we found the relationship between G and h

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and finally Part 3:

languid ridge
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9/20?

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20/9

split wind
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yep

languid ridge
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Waitty

split wind
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remember the method we have been through

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it's for the exams!

languid ridge
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So answer is 2.22

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Thankkkk youuu

split wind
languid ridge
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Can i ask you to give me one question ill solve it my self

split wind
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sure

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imma type

languid ridge
split wind
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If a varies inversely with (5b-2), and a=2 when b=2, find a when b=-1

languid ridge
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Waittt

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So y=5b-2?

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X=a

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Thenn

split wind
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you can write it down if you want

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go on, I'm reading

languid ridge
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K=xy?

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Waitt

split wind
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yes

languid ridge
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Y = 8?

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And x = 2

split wind
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??

languid ridge
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Waitttt

split wind
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oh yea

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haha

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you are fond of using x and y

languid ridge
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I thought i was wronggg for a second

split wind
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be careful if the real question involves x and y

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you'll mess up a lot if it is

languid ridge
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Whyyy?

split wind
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finish this first and I'll tell

languid ridge
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16/ -7

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Waittt

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2.28?

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Negative

split wind
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hehe

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be careful with rounding

languid ridge
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Whyyy?

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Is 2.28 wronggg

split wind
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,calc -16/7

twin meteorBOT
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Result:

-2.2857142857143
split wind
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since it's -2.285... it will be rounded to -2.29

languid ridge
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Ohh right

split wind
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it's because you'll have the formula x and the question x

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same for y

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e.g.

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If (2x+1) varies inversely (y-1)

languid ridge
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Y= y-1

split wind
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there we go

languid ridge
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Then x = 2x+1

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Let me guess im wrong

split wind
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and you'll mixed up which is which

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no entirely wrong, but... very bad notation

languid ridge
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Wait lemme fixx

split wind
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no worries

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it's not your fault

languid ridge
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X= y-1 and y= 2x+1

split wind
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you can't do that too, you'll still mix them up

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the point is you can try get rid of the formula x and y

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but if it's too hard for you

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you can just plug in weird symbols

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lol

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so that you won't be using your teacher's symbols in the exams

languid ridge
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Thennn what to do?

split wind
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like we have $x=\frac{k}y$

languid ridge
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Hat symbol

twin meteorBOT
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Biscuity

split wind
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if the question is
(2x+1) varies inversely with (y-1)

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then we can write $(2x+1)=\frac{k}{(y-1)}$

twin meteorBOT
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Biscuity

split wind
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and then as you have suggested eariler

languid ridge
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Wait what is x then?

split wind
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$(2x+1)(y-1)=k$

twin meteorBOT
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Biscuity

split wind
languid ridge
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Ohhhh okay

split wind
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it was an incomplete question

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hope you understand!

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so, any question so far?

languid ridge
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Then what to do?

split wind
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well, I didn't complete the question

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so it's just my problem of not giving the full question lol

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I didn't mean to make a new completed question

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just take an example

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of part of a question

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to tell you about situation involving x and y