#help-17
1 messages · Page 151 of 1
not really
Well i thought i saw something but nope
for 4 strings 16 of them start with a
How did you get 9?
i counted
Isnt it 6 a (something) (3 options)
aba , abb , abc , aca , acb , acc
Where did you find the other 3?
First 3 are not the ones we are looking for
oh right
They are not aa free
So 1 , 2 , 6
Its like its sum of all the previous ones times 2
we could verify that once we get T4
Get for T_4 then ig
You sure?
abab , abac , abba , abbb , abbc , abca , abcb , abcc , acab , acac , acba , acbb , acbc , acca , accb , accc
maybe that would help
Try it
try what
Idk. I mean all those questions basically require you to solve the past ones. I cant quite follow all of it because im not solving them. If you understand the solution of that question then you should be able to somehow solve this one.
ive done all and i didnt do them in order and still solved idk what u mean lol
Then i suggest you do them in order ig
... what ? ive done all of them thats the last one
Oh ...
so im guessing you got no clue with this yea?
Well my brain is currently not really working at max speed. Believe it or not me being in this server is just procrastinating on doing math by doing easier math.
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is my answer correct
My work
I'm pretty sure the derivative of f(x)g(x) would be f'(x)g(x)+f(x)g'(x) because of product rule and it seems you've written it as (f(x)g(x))'
I'm not sure if that would work
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The only thing I know about this set of points is that the distance from D to B is larger than the distance from A to C, I need help proving that it's impossible to draw a circle around D and B without that circle also containing either A or C
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Show your work, and if possible, explain where you are stuck.
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Question about the Gaussian method for linear systems: I'm trying to understand why when we do Gaussian elimination for a system like Ax = b the operations we do on each row are reflected on the known terms b, but NOT when we are trying to do an A=LU decomposition.
@devout lion Has your question been resolved?
well when we do a LU decomposition we record the row operations in the matrix L
and then when we want to use the LU decomposition we have to solve two systems
first Ly=b and then Ux=y
and in the first step we basically apply the row operations to b
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to remove it don't I want to factor numerator and cancel out?
it would be x+3
so f(x) = 8?
yep
@restive tinsel Has your question been resolved?
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
Do yk the expansion for sin(a+b)?
I do not
No this would be my first time working with this
Oh
Any chance u could solve it and show me your work? Maybe I can work another one off using a similar problem
This is all you've to use
Hmm I’ll try watching YouTube videos
@bleak sphinx Has your question been resolved?
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im not sure how to differntiate this, i asuume it would be using U sub? answer is B
yes
my u would be 1 + 4x^2 ?
yes
B. Option is correct
dont u mean integrate?
ye
ok but u didnt do the actual integration lol
would i have to distrubute the 1/2 first and then integrate
Wrong
you have [
\int \f x{\s{1+4x^2}} \dd x \overset{u=1+4x^2}= \f18\int\f{\dd u}{\s u}
]
so integrate the 1/sqrt(u)
yes, and sqrt u is = to u^1/2
so uh
hum
use the fact that [
\int x^n \dd x = \f{x^{n+1}}{n+1} + C \qq n \in \R\setminus\set{-1}
]
oh wiatt
waht
No you missing integral sign
ye im not sure where i am goign wrong
you did it wrong
you set u to 4x^2
and then do it from there
you will get a inverse trig integral
but there is also a plus 1 under the sqrt
thats fine
just do it and then you will get it
you will get the 1/8
but you will have integral of 1/sqrt(1+u)
oh wait
im too dumb
you got to set u to 2x
and have it with a square
wait wait what, where
this has 1/8 times the integral of du over sqrt(u)
and the you integrate it to get 1/8(2sqrt(u))
your mom
my bad its 35
but the 1/8 is a constant on the outside
im not sure that is meant to be integrated
oh well yeah you can pull that out
but it would simplify to that
cause integral of $1/(s{x}) is just 2(s{u})$
memeprime.
oop
i suck at this
either way you do that and then you plug in 1 + 4x^2 to get the result
which would be 1/4(sqrt(1+4x^2))
ok, i folllow along with most of this. i just dont understand this. how do we go from 1/8 to 1/4
because 1/8 * 2 = 1/4
from the integration
because we need the 2 from the 2sqrt(2)
if you differentiate 2sqrt(2) you will get 1/sqrt(2)
and vice verse with integration
how do we get this
so we were supposed to integrate that like that
you dont integrate after you plug u back in?
you integrate before?
you are just reversing the process then
i think thats what i needed to hear
that was helpfull
thank you
👍
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I have this graph and i’m asked for the local minimum
,rccw
in this instance it would be -1,-3 but what would happen if the point were the lowest
What do you mean if it were the lowest?
if it were the lowest it would be the min
ah ok
Do you know the definition of a local minimum?
uhh yes but i need clarification because my teacher said “it is and isnt”
intuition tells me it would be but i’m not sure why it wouldn’t be one
https://en.m.wikipedia.org/wiki/Maximum_and_minimum
You can read about it here.
In mathematical analysis, the maximum and minimum of a function are, respectively, the largest and smallest value taken by the function. Known generically as extremum, they may be defined either within a given range (the local or relative extrema) or on the entire domain (the global or absolute extrema) of a function. Pierre de Fermat was one of...
From my undestanding (hope it true) it is not because there are no values left of it.
Like there doesnt exist a single $\epsilon > 0$ such that $f(-4) \leq f(-4 - \epsilon)$
casework
Because well it isnt defined there
it depends on the interval you're talking about
if you're talking about $x\in\mathbb{R}$ then (-4,-5) would be considered as a global extrema
Anonymous
alr thanks
while for example if you considered the function for $x\in[-2,1]$ then (0,0) is also a local minimum
Anonymous
he said it really didn’t matter if we considered it to be one or not i was just confused why it wouldn’t ever not be
ya they probably arent picky abt it
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Claim
@vast shale Has your question been resolved?
<@&286206848099549185>
Start with the rational roots
Yo how?
<@&286206848099549185>
mhm what type of math is this
I'll try
Quadratic
I believe
Tho i took questions for sequence and series and straight line 🥴
so first find the root of
so did algebra yk?
with adding 2 first of all I think
could be wrong tho
Naw
Dont
You have to do all this
Without a calculator
Pen and paper
3 minutes max
I dont think they want me to solve from roots
That would be too long
since m is a non zero integer, it's a integer (whole number) and is either negative or positive
Positive or negative
Integer
Right mb
except zero of course
Yeah
I'm thinking of this problem with you no worries 😭
Yo thanks 😭
Cuz im giving a test simultaneously
Cuz i have a test tomorrow 😭
And this was from the last test
😭
Im depressed af
no other common factors than one is relatively prime numbers
this is about math, not a vent channel 💀
since prime numbers can't be negative, m and r are probably positive
this is for me lmao
nah I moved all from that after you said it wouldn't work
these type of things are for me and you for you to follow along with my thinking yk
Yep
Sure
one root of the equation 2000x^6 + 100x^5 + 10x^3 + x - 2 = 0 is of the form m + sqrt n divided by r
BRO WE GOT THIS
I FOUND A QUESTION LIKE THE ONE YOU ASKED ON AN OLD FORUM
Yoooo
Send the soln
@vast shale
lmao I was reading through the question to try and explain it to you
Lmao
Try that
since it's just math speak atp
Send the link atleast
To the solution 😭
-1+ 161= 160 divided by 40 equals 4 ohh it's 4
lmao I was just thinking about the solution ngl
I go blind
Those are too many letters
IKKK that was why I was reading it so that I could condense it
but the math checks out
I have one more
I'll just explain it to you
Naww i got it
I just put the problem in google
I understood whats written
I did not get any results ☹️
how did you get it though? I just gave you the answer
I mean i saw the solution and understood it?
That was what i was meaning to say
And in the future, i would use this technique to get answers for similar questions?
I failed in solving this particular question, but not the next time!
yea but you have to understand it so that you could do the problem without seeing the solution yk
so that you won't bomb your test
I did understand the working
okay I hope so
thats gonna happen nevertheless 😭
Yeah
Thanks man
One more question?
gosh this feels like probability 😭
Naww 😭😭
This is probably binomial theorem
is that like pre calc or something?
what type of math is that
Idk wht type
Of course the binomial theorem is taught in pre-university algebra courses. It is part , for example, of the Common Core curriculum which is broadly used in the US nowadays
Says quora
Lmao i gtg
DM me if you get an answer or want a solution
Thanks for helping
.close
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yea bye bye
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help anyone?
Sorry, I don't know vectors.
oh okay
anyone else?
<@&286206848099549185>
<@&286206848099549185>
someone?
<@&286206848099549185>
What does it mean by increasing order?
ecah of the scalar factors increases in numerical order
like how we know that c is the smallest because x has to be flipped around in the v vector
hi
or you?
^
@rare oyster Has your question been resolved?
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hey guys, a little help
@graceful ibex
r, w, and u
you just have to check the amount of times you need to travel along the x vector lines
and make sure that they are like 2.3 away from their starting point
I don't think thats correct..
it shouldn't be based on that
because you have to look at the actual grid
what are you talking about we are looking at the actual grid by doing this analysis
c is a variable that's free
which means what you need to analyze is the x vectors of the grid
yeah, your logic makes sense actually... it's just not showing up as correct when I'm plugging this into the verification system 💀
that should be correct according to the above analysis
yeah exactly
but it is still not working
idk what to do now
@gusty beacon any ideas
oh that makes sense
yeah it should fall on the same parallel line to the y-vector lines
yeah because it satisfies the parallelogram formatio
wait I had another question, it's a little harder but do you think you can help
oh sure
oh shoot I didn't get that far in linear algebra yet sorry idk if I can help with this one
@rare oyster Has your question been resolved?
Let vector u=(ux, uy) and vector v=(vx, vy)
Construct the matrix using these as rows, what does it look like?
@rare oyster Has your question been resolved?
like a series of rhombuses?
^
is that it
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this is for homework, ive been stuck on trying to solve this problem using the identities but i dont know what im doing wrong... i dont know how to solve this. i only got the last one right cause of inverting tan
trigonometric problem
imo just use sin^2+cos^2=1
I've tried but for some reason it gets it wrong so I was trying to mess around
I don't know if I'm doing it wrong though
I tried using tan^2=1+ sec^2 as well
Yeah I got something like that too, although I put it as 3/sqrt13
Or wait
Maybe I forgot to put negative
My computer is messing up rn, i'll have to try it again later, but thanks for the help
wait, i realize i misunderstand
why is it 2/3 ? isnt that tan not sin?
or theres other identities
wait so then how is this implemented into the equation? it just turns to 2/3 is sin or?
oh wait
ok i see the x
idk how to solve that though
nvmind im stupid. i figured it out
thanks
how do i do the sin part of it?
i see that cos= sin/tan, but how do i solve that in the equation
@thin wave Has your question been resolved?
@thin wave Has your question been resolved?
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im not sure, my intial idea was to plug in 12 and 15 for t and then subtract the outcomes
im not even sure
Your limits are right, but not the rest. You have to use the integral.
im not sure i understand what you mean, are you saying do this
𖤍
differnce in time hummm
fancy
but the time would not be starting at 0
thats where the equations we are solving begins yes
well in thta problem it tells you from 9 am to 9 pm. so you are starting at 9 am. it tells you your starting point, which a starting point would be 0
my starting point is stated as midnight in the problem
meaning start at 12 and count up till noon and 3 pm
which would be 12 and 15
wait im still confused how to solve my probelm tho
𖤍
@unique sluice Has your question been resolved?
uh
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help where do go from here
@silent linden Has your question been resolved?
@silent linden Has your question been resolved?
😭
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@silent linden Has your question been resolved?
@silent linden it's been quite a long time for me and QM, but if I recall this problem correctly, the trick will come down to using the definition of the matrix exponential.
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What is the simplest rational function that has a removable discontinuity at 𝑥=−2 and an infinite discontinuity at 𝑥=0?
you can just create these features
use a product
so create one with the one feature
then one with the other
what is a feature
their product will have both
a given discontinuity, here
whats the simplest rational fn with an infinite discontinuity at x=0?
f(x) = 1/x ?
there is
its at x=0
but, its removeable
(we can just write x/x=1/1=1)
so, with that template
what fn has a removeable discontinuity at x=-2?
yea
this isnt defined
so, it follows that if you want to make a rational function with a discontinuity like this
we want something like f(x)/f(x)
where f(c)=0 at whatever c where you want the discontinuity to be
make sense?
we want 0/0 at some x=c
so make f/f where f(c)=0
$\frac{(x+2)}{x(x+2)}$
jan Niku
try: what if x=0? what if x=-2?
np
now kinda a weird question
when im graphing it
it shows the same when i put f(x) = and without it
is it good practice to put f(x) = in desmos
even though it dosent change the product
like
these give the same thing
but is it better practice to do the first one?
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it dont matter
sometimes its convenient
✅
@wise marten Has your question been resolved?
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rearrange 3.75 = ar to a = 3.75/r
then you can substitute it into the other formula and solve for r
or the other way around
where did you get up to
\begin{align*}
\frac{15}{4}&=ar\
20&=\frac{a}{1-r}\
\
a&=\frac{15}{4r}\
20&=\frac{\frac{15}{4r}}{1-r}\
&=\frac{15}{4r-4r^2}
\end{align*}
do you have this at least
Desync
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How would I write an equation for Y1?
@shy pond Has your question been resolved?
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that just hurts my eyes
who allowed that
$\frac{\sqrt{2}}{5} - \left(1-\frac{1}{5}\right) \cdot \frac{2}{5}$
AℤØ
have you tried anything?
.close
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I’m doing trinomial factoring by grouping and I see that I don’t have the same numbers in the parenthesis like I’m supposed to (5x + 2*6) and (5x + 2) what should I do?
Forgot to circle a 3 btw
Wait where am I dividing …
15x^2/3x=5x
i just say divided while you are really factoring out
because its not just factoring out the x, its also the 3
(15x^2+6x)
((3x)(5x)+(3x)(2))
(3x)(5x+2)
From your second line to the last one, you circled one of the 3s but not the other, yet you factored out a 3
Both terms have a 3, you didn't factor it out of the second term
is there anything else you need help with?
@rancid kestrel Has your question been resolved?
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Why is the tension equal to the weight? Should it be the sum of the gravity and electric forces?
the electrical forces are pushing the balls apart and thus making them be higher than they otherwise would, which is why the tension is very slightly less than the weight
the tension is .049N, which is mg
it doesnt say, but 9.8 and 9.801 shouldnt make too much of a difference
my point is it might be 10
unless the electric force is pieces compared to gravity
this is from a book right?
yes
pieces?
negligible
does it say at the start of the questions to use any particular value of g
the tension force should be more, not less
hmm
wait
hold on
why is the answer giving you the tension when the question only asks for sign and magnitude of the charges?
T is required to solve this though isn't it ?
Because you don't know the electrostatic force you need it to balance components
since the verticals got to counteract grav
just calculated, its like a 0.0002 difference
not enough to round
thanks for your help
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I need help proving a bijection between any two ordered fields with LUBP is order isomorphic
I have a map $f\colon F_1\to F_2$ defined by $f=\alpha_1\circ\beta_1$ where $\beta_1\colon F_1\to DC$ and $\beta_1(f) = { q\in\mathbb{Q} \mid i_1(q) < f }$ where $i_1$ is the unique injective map from $\mathbb{Q}\to F_1$ and $\alpha_2\colon DC\to F_2, \alpha_2(S) = \sup S$
94tj
I (think) I know how to do it from $\mathbb{R}\to F$ but not sure when its abstracted like this
94tj
For example for $f(a+b)=f(a)+f(b)$ I have something like the dedekind cut $\beta_1(a+b) = {q\in\mathbb{Q} \mid i_1(q)<a+b}$ but how do I find the supremum of this in $F_2$?
94tj
I'm pretty sure I need to apply $\sup (A+B) = \sup A+\sup B$ but I don't know when to do that and also how to consider the supremum in $F_2$ since this DC "represented" by things in $F_1$ if that makes sense
94tj
@silver kettle Has your question been resolved?
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specifically part 2
and the multiples of 3 and 5
aand then remove the common terms which were counted twice
so i know that i need to sum the multiples of 3 and the multiples of 5
and the common term is 15
but i dont know how to make it a function of JUST n
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whats the reasoning behind this being false
Product rule for derivatives
are you fimilar with rieman sums
i dont think riemann sums are needed for this
?
What does your problem have to do with Riemann sums
im not sure
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@languid apex Has your question been resolved?
The A comes from the term $x^2/x+1$
The Mad Pirate
the idea behind partial fractions is to transform an algebraic equation in terms of a sum of algebraic terms
in true what you actually end up calculating are the residues in the complez plane for each pole, in this case the pole in z= 0 with multiplicity 2 and z= -1 with multiplicity 1
the equation will be Ax(x+1)+B(x+1)+Cx^2 = 3x^2+x-1 whch leads to the linear equations A+C = 3 , A+B = 1 and B = -1 , so the end result is B = -1 . A = 2 and C = 1
Basically you would end up with and unsolvable set of linear equations if you didnt had the A/x term
since you would had more unknowns than equations in that case
Are you planning on doing a stem carreer in college ?
$\frac {3x^2+x+1} {x^2*(x+1)} = \frac{2}{x} + \frac{-1}{x^2} + frac{1}{x+1}$
The Mad Pirate
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Please help
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hi does anyone know where i went wrong?
it doesn’t factorise
Can't you just solve for y with the quadratic equation or by completing the square?
Yep
thanks
You can probably start from the initial equation and multiply everything by sin
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Can anyone help me solve this i
,rotate
Please i have a test tomorrow <@&286206848099549185>
😭nah cause I am going to fail
lol same i have test tomorow
nah this seems hard i dont want to help u
You are in high school?
<@&286206848099549185>
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<@&286206848099549185>
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Um can someone help me solve this, my teacher said that this is going to have something like this on quiz,
If G varies inversely with (2h+3) and g=4 when h=1, find G when h=3
I dont get the question, i think imma find the K, but do i need substitute it
The question is this
If G varies inversely with (2h+3) and g=4 when h=1, find G when h=3
@languid ridge Has your question been resolved?
do you know what does G varies inversely with (2h+3) means mathematically?
like can you write an equation about them?
nah
What do you do then?
e.g.
if x varies directly with y, then x=ky
if x varies inversely with y, then x=k/y
for some k that you'll have to find
using this can you write an equation about G and (2h+3)?
Maybee
let's try
Okayy what to do first?
try to understand which to use first
yes?
It inversely so x=k/y?
This said inversely so? X=k/y?
Next, what is x and y in this case?
nope
Ummm
Okay
Sentence 1:
If G varies inversely with (2h+3)
Sentence 2:
If x varies inversely with y
what will be the x and y in this question?
read carefully how I place the varibles in the sentence
Y is (2h+3)
read vertically on which is pairing to which
X is h3?
x is G
I thought we gunna find G
so, since now we know that the x is G, and y is (2h+3)
So? K is missing?
we can plug those expressions into
Let's rewrite this sentence from:
"If x varies inversely with y, then x=k/y"
to:
"If G varies inversely with (2h+3), then G=k/(2h+3)"
all good till here?
Yeahh
K=xy?
use the bottome one from now on
so that we can get rid of x and y
Then what will we do with h3?
The question has 3 parts
"If G varies inversely with (2h+3)"
"and g=4 when h=1,"
" find G when h=3"
we have done the first part, now we need to use the information in the 2nd
Part 1, we have:
G=k/(2h+3)
and Part 2, we have
G=4 when h=1
so we plug in those numbers into the equation we found in part 1
We do what nextt?
from all the info till Part 2, we can rewrite the equation into:
G=20/(2h+3)
yep
Waitty
that is rounded to the hundredths place
Can i ask you to give me one question ill solve it my self
Just to be suree
If a varies inversely with (5b-2), and a=2 when b=2, find a when b=-1
yes
??
Waitttt
I thought i was wronggg for a second
Whyyy?
finish this first and I'll tell
,calc -16/7
Result:
-2.2857142857143
since it's -2.285... it will be rounded to -2.29
Ohh right
Now
it's because you'll have the formula x and the question x
same for y
e.g.
If (2x+1) varies inversely (y-1)
Y= y-1
there we go
Wait lemme fixx
X= y-1 and y= 2x+1
you can't do that too, you'll still mix them up
the point is you can try get rid of the formula x and y
but if it's too hard for you
you can just plug in weird symbols
lol
so that you won't be using your teacher's symbols in the exams
Thennn what to do?
like we have $x=\frac{k}y$
Hat symbol
Biscuity
if the question is
(2x+1) varies inversely with (y-1)
then we can write $(2x+1)=\frac{k}{(y-1)}$
Biscuity
and then as you have suggested eariler
Wait what is x then?
$(2x+1)(y-1)=k$
Biscuity
we don't know yet, since this question doesn't have the 2nd part
Ohhhh okay
Then what to do?