help-17

[frozen shuttle]

i think so yeah

[terse forum]

okay

[frozen shuttle]

never really used this formula so im learning as much as you are hahaha

[terse forum]

yeah thats good to hear at least

plus yours was new to me as well

anyway thank you for your help

.close

[vocal sleet]

Channel closed

Closed by @terse forum

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[astral sparrow]

it’s so easy but i don’t know how im getting it wrong and im doing the right steps

[astral sparrow]

idk where i’m going wrong

[loud walrus]

Well if you don’t show those right steps we can’t know either

[vocal sleet]

@astral sparrow Has your question been resolved?

[astral sparrow]

those are literally the steps

that’s the question

find the probability

the first step is so make a venndiagram which gives u the answer

but when i make the venndiagram and extract the integers to get the probability, its somehow wrong

[astral sparrow]

help

[vocal sleet]

@astral sparrow Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[naive hatch]

Need help determining the net change and average rate of change in this function.
f(t)=4t^2, t=5, t=5+h

[naive hatch]

I'm stuck with

(100 + 20h + 4h^2+ 100)/h

But this doesn't seem right?

And I'm not sure how that would even translate to net change or av roc

[thin vale]

!original

[vocal sleet]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[naive hatch]

sorry!

having a hard time with any of these net change or rate of change equations that aren't "solvable"

[thin vale]

The net change between 5, and 5+h will be |f(5+h)-f(5)|

[naive hatch]

this doesn't seem to work

I'm not sure how you got to that either

[thin vale]

The net change will be the difference in the values of the function at those 2 points

I thought it would want the net change to not be sign dependent, so added absolute values

[naive hatch]

I tried without as well

[thin vale]

Do you have a definition of net change in your notes or book somewhere?

[thin vale]

Can you show your work

[naive hatch]

i can show what i have yeah one sec

[thin vale]

Why the division?

[naive hatch]

It was the formula that the guidance in the assignment utilized

[thin vale]

I’m confused, do you think this is you doing what I suggested above?

[naive hatch]

Like I said it's what the assignment offered up as guidance when I did another practice problem

[thin vale]

Have you tried what I suggested above though?

[naive hatch]

your answer?

yes

it did not work

[thin vale]

Can I see that work

[naive hatch]

this is the guidance

[naive hatch]

I did not know how you got that answer

[thin vale]

This is for average rate of change?? You’re trying to find the net change? And those are different things…

[thin vale]

I explained how already

[naive hatch]

yeah but i do need both. I tried your answer for net change and it did not work, and I am unsure how you got it

[thin vale]

Please show me what you tried

For the net change

Based on my suggestion

[naive hatch]

No like I literally just inputted it

as the answer

to then ask how

you got it

[thin vale]

Well then no wonder it’s wrong

That’s not the answer

I was telling you how to do it

[naive hatch]

ohhh my bad

[thin vale]

You have to evaluate the function

[naive hatch]

apologies

[thin vale]

It should’ve said f(5+h) and f(5) as-well

I typoed t(5+h) / t(5)

[naive hatch]

i got ht

i'm unsure

[thin vale]

Unsure of what?

[naive hatch]

I don't think I dealt with t(5+h) properly

would i have to factor that

[thin vale]

Like I said, it’s f(5+h)

f not t

[naive hatch]

then i get hf

which still doesn't work and I think is wrong

[thin vale]

What

??

Do you know how functions work

f(t)=4t^2

So f(5)

You plug in t=5

It’s 4(5)^2

[naive hatch]

yes

100

[thin vale]

Then what is this?

[naive hatch]

but then you're left with 4h^2

errr

20h^2

[thin vale]

Okay so instead of just saying that, work it out properly

Of course you’ll be left with an answer in terms of h

[naive hatch]

i didn't know how the formula you gave me worked so i tried

[thin vale]

That doesn’t make it wrong

[naive hatch]

yeah i'm not sure how to work it out properly past that point

[naive hatch]

ignore this

its 4h^2+40h+100

i got it

ok

i figured it out

[thin vale]

Good

[naive hatch]

i didn't realize that it could be in terms of h for a net change

[thin vale]

Since the input is in terms of h

It will of course depend on h

Think about

What if h was 0?

[naive hatch]

yes this makes sense

[thin vale]

Then you’re taking the net change between two of the same points

and it would be 0 then

But if h=100

Then the net change will be big

So it depends on h

[naive hatch]

Yes

now how would i solve for avg rate of change

with this expression

[thin vale]

I’d follow your example you showed me earlier now

And be careful with your algebra

Then post your work if you get it wrong, and someone can check

[naive hatch]

okie dokie

thanks

okay i tried and i failed

NVM I got it

this channel is good

idk how to close it

!close

[surreal basin]

.close

[naive hatch]

.close

[vocal sleet]

Channel closed

Closed by @naive hatch

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unreal dove]

b>2. describe how you would determine ab > 2a

[glossy maple]

That's a very weird question

"Describe how you would determine"

[unreal dove]

yea right

so um what do i put

[glossy maple]

Do you understand why it's true?

Also it's only for positive a

No idea why they didn't mention that

[unreal dove]

yeah if b>2 it’s always gonna be greater than when ur multiplying by positive a

because ab is gonna be greater than just b so it’s gonna be greater than 2

[glossy maple]

maybe rephrase that

[unreal dove]

okay erm

ab>b and b>2 so ab>2

[glossy maple]

That isn't related

and ab > b is not necessarily true

If a = 1/2 for example, then ab < b

[unreal dove]

oh

then what am i supposed to say

[glossy maple]

You have a number bigger than 2, b

You multiply b by a, and you multiply 2 by a

which one is gonna be bigger if a is positive?

try to explain which one and why

intuitively

[unreal dove]

OH ok

thank you

b is greater than 2 so when it is multiplied by a, and if 2 is multiplied by the same amount, then b would still be greater

[glossy maple]

Not "b would still be greater"

It's not b anymore

say "a * b" would still be bigger than 2a

or something

[unreal dove]

ok

[glossy maple]

This is a very poorly written question

[unreal dove]

yeah she’s confusing

.ose

.close

[vocal sleet]

Channel closed

Closed by @unreal dove

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frosty tundra]

why does finding theta equal zero give me an area of 14?

[opal acorn]

Ik it’s graded already but I need to study that question for an exam, anyone know what I did wrong?
WITH QUESTION C

[frosty tundra]

.close

[vocal sleet]

Channel closed

Closed by @frosty tundra

Use .reopen if this was a mistake.

[regal slate]

!occupied

[vocal sleet]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[opal acorn]

?

.reopen

[frosty tundra]

i closed it because you also posted a question

.close

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty portal]

<@&286206848099549185>

cant get no help here

!close

.close

[vocal sleet]

Channel closed

Closed by @dusty portal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[waxen hawk]

I’m trying to solve “24.”

I’m shocked when my manipulation didn’t get me a value of x at the end.

[steel snow]

unfortunately you can't get a value of x

[waxen hawk]

Mickey (without cigarette) is the area of shaded region

[waxen hawk]

Why

[steel snow]

because the area is in terms of x

[waxen hawk]

Because these Mickeys stand for the same thing?

[steel snow]

???

[waxen hawk]

At the very bottom, I connected these two Mickeys using a equation

[steel snow]

that's because those mickeys are created from each other

[waxen hawk]

They both stands for the area of shaded area

[steel snow]

if that makes sense

[waxen hawk]

Yes

[steel snow]

so you're basically saying x=x

which you can't solve for

[waxen hawk]

So what I have to do here, is using two different “characteristics of the graph” and finding the relation between them

[steel snow]

can't really describe the 'rule' but basically you need to find 2 different equations

systems of equations

kinda

[waxen hawk]

Two different Expression and their relation to each other

[steel snow]

if I told you what the area was, you could solve for x

[steel snow]

yeah, so
y = 50
and y = x^2, you could solve for x

[waxen hawk]

Exactly, the value of Mickey, that is

[steel snow]

well you can't

the area is a function

[waxen hawk]

I suppose I have no choice but trying manipulate these length measured by x and find a relation between the length and some area.

[waxen hawk]

That feels impossible

Length and area are different things (units)

[steel snow]

no

the final answer

is in terms of x

dont try finding x lol

[waxen hawk]

I see

[waxen hawk]

Why?

How do you know x is not a constant

[steel snow]

because x is a variable

x is x

[waxen hawk]

Then I think I already got the answer, which is denoted as Mickey in the picture I posted.

[steel snow]

the answer is wrong tho

11x^2 - 20x is correct

[waxen hawk]

Then Sth wrong in the calculation I think

It is solved, thank you mooncake

.close

[vocal sleet]

Channel closed

Closed by @waxen hawk

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grizzled dome]

Hi

[grizzled dome]

So Im trying to learn how to find zeros of a function using a graph and a table

and while I was looking for a video

I came across this

I was wondering if grouping (the method he is teaching) is different from using a graph and a table

[steel snow]

grouping is a method used to factor

[grizzled dome]

How should I solve question 2-4

[steel snow]

graph the equations

or use a table

??

[grizzled dome]

??

how do i use that

My teacher doesn't teach at all so im very behind

Im trying to learn this on my own

please be patient

[steel snow]

well do you know how to graph functions

[grizzled dome]

I think kinda

[grizzled dome]

yes

Help

[steel snow]

so input values of x and grpah them

[grizzled dome]

I can do any number?

[steel snow]

uh

I would do numbers near 0

[grizzled dome]

https://www.youtube.com/watch?v=TJNonQWYjkI

@steel snow

would this video be helpful for me

?

[steel snow]

yes

[grizzled dome]

kk

imma watch it and be back

[grizzled dome]

Hi

so i have smht like this

I would just plug in

all of the values I have on the x side

and solve?

What i got

@steel snow Is this corredt

[steel snow]

check the y value for x = 0

[grizzled dome]

I dont see anything wrong can you explain?

[steel snow]

0^2 + 4(0) -5

[vocal sleet]

@grizzled dome Has your question been resolved?

[grizzled dome]

But everything else is right

?

[steel snow]

yes

[grizzled dome]

hmm

[steel snow]

wait

x = -1 is wrong also

[grizzled dome]

hmm

the guy in the video said

[steel snow]

that's because the line of symmetry is at x=0

[grizzled dome]

https://youtube.com/clip/Ugkx2uV4HTAxeexdRS4V7UM7BSIKOnkNzDQb?si=pKzOd0boOo4p3B2f

[steel snow]

you determine the line of symmetry with the formula y = -b/2a

but you don't learn that until later

basically he could only say that because he knew the line was symmetrical at that value

[grizzled dome]

So how am i supposed to solve my equation?

[grizzled dome]

x^2 + 4x - 5

[steel snow]

i would use -b/2a to find the line of symmetry

[grizzled dome]

oh wait

he mentions how to solve my

type of equations

in standard form

one sec

[steel snow]

yaya

[grizzled dome]

@steel snow

He says 1 and 3 will have same y value

is that correct?

(2,5) is the vertex

Doesnt seem right

How can I trust taht those are the same??

its not the same so wtf

[steel snow]

????

did he tell you about -b/2a

@grizzled dome

[grizzled dome]

yes

to find the vertex

[steel snow]

yes

so the parabola is symmetrical to that x value

btw -b/2a is the Line of symmetry not the vertex

[grizzled dome]

I thought thats the x coordinate of the vertex

?

When I plug in -3 into the fucntion I get something different from when I plug in -1

this doesnt make sense

[steel snow]

yes

the x coordinate of the vertex

is the line of sy mmetry

[steel snow]

you calculated wrong then

[grizzled dome]

what did u get for it

[steel snow]

@grizzled dome -8

[grizzled dome]

U got that for -1 too?

[steel snow]

-1^2 -4-5 = -8

[grizzled dome]

wtf

[steel snow]

wait

[grizzled dome]

no its -5

[steel snow]

9-12-5

1-4-5

@grizzled dome it checks out

[grizzled dome]

what tha fuckkkk

okay

shoot

okay cool

that works

https://www.youtube.com/watch?v=kKE4t7R_KWc

@steel snow

Would that video work to solve questions 5-10

[civic hound]

use sum and product

[grizzled dome]

So it would work?

[civic hound]

well

the general equation is $$ax^2+bx+c$$

[twin meteor]

Giovyx

[civic hound]

you need to find two numbers that
their sum is b
their product is ac

after you find those numbers (let's call them s and p)
you can factor the equation to $$(x+p)(x+s)$$
make sure to not forget the minus if theres one.

Also, after that, u can put the single brackets equal to 0
and the roots are -p and -s

[twin meteor]

Giovyx

[civic hound]

thats it

[vocal sleet]

@grizzled dome Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime lintel]

i have a question so in the equations absolute value x+1=1-sqrt2

[prime lintel]

would x+1 withtout absolute value be equal to sqrt2-1?

[sly sierra]

can you clarify the equation, is it:
|x + 1| = 1 - sqrt(2)

[prime lintel]

yes

what will x+1 be equal to

[sly sierra]

there's no solution to this

the right hand side is negative

[prime lintel]

well the full equation from the beginning is 18(x+1)^2=(3sqrt2*6)^2

how do I solve it?

[sly sierra]

that would be equivalent to:
sqrt(18)|x+1| = 3sqrt(2)*6

assuming the sqrt is only covering the 2

[prime lintel]

but how

it's 3sqrt2*6 all to the power of 2

[sly sierra]

yea, take square roots of both sides

[prime lintel]

ahhhh

ok

but how do you solve it further?

[sly sierra]

well, let's see, that would become:
|x + 1| = sqrt(18)sqrt(2)

which you would solve however you usually solve |x + 1| = c
where c is positive

another option, if you don't want to take square roots:

[prime lintel]

but wait

[sly sierra]

just multiply out the (x + 1)^2

and rearrange to a quadratic equation and use the quadratic formula

[prime lintel]

how do you do that

sorry im so annoying but i have a test today

[sly sierra]

(x + 1)^2 = what

when you multiply it out

[prime lintel]

(x+1)(x+1)

[sly sierra]

right, but now distribute it

[prime lintel]

2x+x+x+1

?

[sly sierra]

x^2 + x + x + 1

which is x^2 + 2x + 1

[prime lintel]

ok

but

[sly sierra]

and then you'll have 18^2 in front

[prime lintel]

x^2+2x+1 needs to equal 0?

[sly sierra]

so 18^2(x^2 + 2x + 1)

no it equals (3sqrt2*6)^2

which you can also multiply out

[prime lintel]

Ok

so from the beginning 18(x+1)^2=(3sqrt2*6)^2

to

18|x+1|=3sqrt2*6

|x+1|=(sqrt18*6)/18

is it good?

or I did something wrong

[sly sierra]

wait, where did the sqrt(2) go

[prime lintel]

well

i converted 3sqrt2 into sqrt18

[sly sierra]

and on the left it should have been sqrt(18)|x+1| after taking square roots of 18(x+1)^2

[prime lintel]

Ohhh

that's right

[sly sierra]

ok

[prime lintel]

so

sqrt(18)|x+1|=3sqrt(2)*6

[sly sierra]

yea in fact all the 18 crap cancels

you can cancel before you even take square roots:

[prime lintel]

so |x+1|= 6?

[sly sierra]

18(x+1)^2 = (sqrt(18)*6)^2
18(x+1)^2 = 18*36
(x+1)^2 = 36```

[prime lintel]

so |x+1|=6 in the end?

and x+1=6

[sly sierra]

|x+1| = 6 yes

[prime lintel]

and x=5 or -7

[sly sierra]

but that means:
x + 1 = 6
or
x +1 = -6

[prime lintel]

oh

[sly sierra]

i.e. there are two solutions

[prime lintel]

so 5 and -7

[sly sierra]

yep

[prime lintel]

Ok

but wait

[vocal sleet]

@prime lintel Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rough zenith]

is there a faster way to do this than slowly calculating the area of each part

[surreal basin]

the circular portions can be pieced to fit a complete circle for sazz and tazz

that leaves you with rectangles which only end up being the perimeter * 1km

this is not slow

[rough zenith]

can u explain this please i dont really understand

[surreal basin]

do you see the circular corners of tazz

[rough zenith]

oh yeah

[surreal basin]

do you see when it starts and stops bending

[rough zenith]

yeah

[surreal basin]

draw lines to separate the circular and rectangular portions of the area

[rough zenith]

i got pi+12 for both sazz and tazz

is that correct

[surreal basin]

yes

what about razz

[rough zenith]

the radius of the big circle is (6+pi)/pi right

[surreal basin]

thats an odd way to write it but yes

[rough zenith]

an the area is (36+pi^2)/pi

[surreal basin]

what's (2 + 1)^2

[rough zenith]

9

[surreal basin]

what's 2^2 + 1^2

[rough zenith]

5

[surreal basin]

so (6 + π)^2 isnt the same as 6^2 + π^2

expand (6 + π)^2 instead

(6+π)(6 + π)
(6+π)6 + (6+π)π
36 + 6π + 6π + π^2
36 + 12π + π^2

[rough zenith]

so the area of 12pi + 36

[surreal basin]

also,

you cant just divide one of them by π^2 and call it done

the radius is (6+π)/π

the radius squared is (6+π)^2/π^2 or (36 + 12π + π^2)/π^2

π times the radius squared is (36 + 12π + π^2)/π

so 36/π + 12 + π is the area

[rough zenith]

minus 144/4pi?

[surreal basin]

no

36/π + 12 + π is the area

[surreal basin]

look at what I said here to know how I got it

[rough zenith]

i mean minusing the small circle

[surreal basin]

whoops I forgot to include that

theres a shortcut you can take to make razz's area faster to find

[rough zenith]

i got 12+pi

so they all same

yeah whats the shortcut

[surreal basin]

π(6/π + 1)^2 - π(6/π)^2
π((6/π + 1)^2 - (6/π)^2)
π((6/π + 1 + 6/π)(6/π + 1 - 6/π))
π(12/π + 1)(1)
12 + π
I think you found the shortcut

[rough zenith]

isnt that just how u solve it normally

[surreal basin]

you can also expand (6/π + 1)^2

which is slightly slower

isntead of using difference of squares

its more direct so difference of squares is a shortcut compared to that

[rough zenith]

ok thanks

ik ohw to do it now

.close

[vocal sleet]

Channel closed

Closed by @rough zenith

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

i need help

[tawny nacelle]

do you know the formula for a slope?

[vast shale]

I think?

[drifting jackal]

You don't really need that, honestly, you can just count

Given the graph

[vast shale]

i know but there are so many points i dont know which to use

[tawny nacelle]

fair enough, but you cant always

[drifting jackal]

Just pick any two

[tawny nacelle]

if you wish to use the slope formula, any 2 is good

[drifting jackal]

The slope is between any two points along that line

[vast shale]

so do you think -1/-2 would work or 1/2

[drifting jackal]

As what?

The slope?

[vast shale]

yes

[tawny nacelle]

the slope is going downwards, so is that a positive slope or negative slope?

[vast shale]

negative?

[drifting jackal]

And as a rule of thumb, if you are counting up or right, that's positive number, and down or left, it's a negative number

[vast shale]

okay thanks!

[drifting jackal]

So using whatever method you want, what is the rise?

[vast shale]

well i'm using these to points so i think its -1

[drifting jackal]

Do you know how to find slope between two points?

[vast shale]

i count the boxes or something im not sure

[drifting jackal]

Yes

Slope is rise over run, correct?

[vast shale]

yes

[drifting jackal]

So what is the "rise"?

[vast shale]

-1

i dont know

[drifting jackal]

And the "run"?

[vast shale]

-2

[drifting jackal]

No

Not -2

[vast shale]

2

[drifting jackal]

Do you understand why?

[vast shale]

no

[drifting jackal]

It goes back to what I said before
if you are counting up or right, that's positive number, and down or left, it's a negative number

[vast shale]

OH

[drifting jackal]

Because you counted right, it's positive

[vast shale]

okay

OMG

THANK YOU

[vast shale]

nobody told me this this is so smart THANK YOU

[drifting jackal]

It's also how the graph works

Notice how you start at -6 and move to -4 in the x direction. You moved two units right

And right is normally positive

[vast shale]

yes

[drifting jackal]

Is that all you had?

[vast shale]

yeah! thanks! it really helped me with my other questions

[vocal sleet]

If you are done with this channel, please mark your problem as solved by typing .close

[vast shale]

.close

[vocal sleet]

Channel closed

Closed by @strong timber

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine trout]

can you help me with this

[sharp lynx]

!status

[vocal sleet]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[alpine trout]

ok so i know the area for each one , i think

triangle = 1/2bh

square and rectangle = l*w

and circle = pi r^2

thats where im up too

[sharp lynx]

so using those formulae (or otherwise), compute the area of each garden

[alpine trout]

well

here's the thing

a doesnt give me a base of height

just lengths of each side

[vocal sleet]

@alpine trout Has your question been resolved?

[inner osprey]

the side lengths of the 18-24-30 triangle all have a factor of 6

it may be easier to visualize by constructing a similar triangle by dividing each of the side lengths by 6

[alpine trout]

ah i got the answer already

its a b and d

i used pythagoream theorem

so 18^2+24^2=c^2

and c=30

which is true

so i used 1/2 18*24

and then for b

14*14

for c

12*15

and for d

pi * 8^2

@inner osprey

is it correct??

[inner osprey]

seems so

[alpine trout]

alright

this is my next question

i assume its 5:6

hence d

i cross multiplied

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[alpine trout]

.reopen

[vocal sleet]

✅

[alpine trout]

ping me when you guys answer it <@&286206848099549185>

[flat whale]

,calc (1/2)/(3/5)

[twin meteor]

Result:

0.83333333333333

[flat whale]

Yes it's d

[alpine trout]

okk

here's my next question

i think its e

because its a negative exponent

and c would not make sense

d**

so e has to be the answer

[tranquil hull]

E because the ^- make it into under the 1

[alpine trout]

Indeed

so am i correct

[tranquil hull]

i think E is a correct ans

[alpine trout]

ok perfect!

next question.. this one i might have a tough time with

$

so let me try it

so in general the max number is 56

thats what i got so far

Lol

so 45:56

.close

[vocal sleet]

Channel closed

Closed by @alpine trout

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy whale]

The scale factor of two similar polygons is 5:8. The perimeter and area of the smaller polygon are 95 cm and 175 cm^2, respectively. Find the perimeter and area of the larger polygon.

[worthy whale]

I need help setting up a proportion to solve for perimeter and area

.close

[vocal sleet]

Channel closed

Closed by @worthy whale

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tropic brook]

Number 13

[tropic brook]

Im not sure what to do after that

Do you draw a triangle?

[vocal sleet]

@tropic brook Has your question been resolved?

[tropic brook]

.close

[vocal sleet]

Channel closed

Closed by @tropic brook

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant spear]

I'm having issues solving this

[buoyant spear]

I keep getting this answer. I have been finding the ratio between the length of the original vector and the new length. Then I multiply the ratio by each of the numbers in the vector. but idk where I am going wrong

[spiral inlet]

Should be something in terms of t, no?

it seems that you assumed t=1

[buoyant spear]

accounting for that i now got this

but it's still incorrect

[spiral inlet]

First component seems off

can you show your work?

[buoyant spear]

i got it

[spiral inlet]

[buoyant spear]

thank you

.close

[vocal sleet]

Channel closed

Closed by @buoyant spear

Use .reopen if this was a mistake.

[spiral inlet]

no problem 👍

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

Hello! I'm having trouble finding the domain of a function. I've tried several times but I'm not sure if I'm on the right track

[vast shale]

I'm going to send my procedure in a second

I've gotten this far

[tribal moss]

convert it into png please

[vast shale]

One sec

[tribal moss]

look:

[tribal moss]

that is, to designate the domain of your function, two conditions must be met

so you have to solve them

both

first one is an immediate one

and the second one is of the form of rational inequality

please write them both in your exercise book and start to solve them , you show it in a moment

[vast shale]

EXACTLY!

YES!

Thank you!

I will .close , try again, and if have any problem I'll come back

.close

[vocal sleet]

Channel closed

Closed by @latent nova

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[toxic anchor]

I am unsure on how to solve this question. Where could i start?

[vocal sleet]

@toxic anchor Has your question been resolved?

[toxic anchor]

.close

[vocal sleet]

Channel closed

Closed by @toxic anchor

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide badge]

could use some help on this idk if I did it right

hey

[finite swallow]

I would approach this question like the way you did as well

[wide badge]

do the probabilities I chose make sense tho?

I think P(A) is 1/3 but my friend thinks it’s 1/4

@finite swallow

[finite swallow]

Yes I'm here, im thinking

[wide badge]

oh sorry

[finite swallow]

All good

[finite swallow]

P(A) = 1/2 * 1/2 = 1/4.

I think you mistook it as 1/3

[wide badge]

why is it 1/2 * 1/2, aren't the three options BG, GG, BB?

[finite swallow]

GB, because kids aren't identical

[wide badge]

oh

okay wait that makes sense

[finite swallow]

Never take your kids as identical 😭

[wide badge]

the 2/3 still makes sense though right

[finite swallow]

P(B|A)?

[wide badge]

because given that its two girls, the only 3 possibilities are

GaGb
GaGa
GbGb

yeah

or would that be 3/4

cause GaGb =/ GbGa

[finite swallow]

3/4 yes

[wide badge]

how would you calculate that without writing out all the possibilities

[finite swallow]

Some things like P(B|A), it's better to calculate by writing down all the possibilities

P(A) was easy because it's just P(G)×P(G)

[wide badge]

okay that makes sense

Would P(A complement) just be the probability BG, GB, BB?

i'm sorry for all the questions btw 😭

[finite swallow]

Yes correct. We need GG so others are its complement

[finite swallow]

All good dw

[wide badge]

i'm quickly recalculating P(B|Ac) i am still here

i got 1/3

[finite swallow]

I think that's correct, is the answer 3/7?

[wide badge]

cause the sample size is 12 combinations, you can ignore the combinations with just boys, and 2 of BG and GB will have a G born in afternoon

uh let me compute 🤓

thats what I got!

[finite swallow]

🫡

[wide badge]

i have another question if you're free!

[finite swallow]

Go on

[wide badge]

its really similar to this one in the misconception of logic i had with the 3/4 1/3 thing

while i get the ss from my ipad

i'm curious, what do you study?

[finite swallow]

I am an informatiks and business studies student

[wide badge]

smort

[finite swallow]

So yeah I'm alright at math

[wide badge]

i'm comp sci but i never did grasp the basics of statistics

i know my part a is correct, but i'm more interested in 7/12

i wrote out all the combinations

11
12
13
14
15
16

which would be 7/12

but do i need to do the reverse as well?

11
12
21
13
31
14
41
15
51
16
61

[finite swallow]

Two dice are identical

7/12 as P(A|B) is correct for me, give me a little more time to think about this one. I think I did the same problem last year in high school

[finite swallow]

Ohhh okay, they are recording the numbers on different slips of paper and after that we take out the paper with a 1/2 probability

So I would write the reverse cases as they have put emphasis on "different" slips of paper, personally. But yeah I would recommend clarifying it with the others too as I might be wrong

[wide badge]

got it

do you have it in you for one more significantly harder question

[finite swallow]

I'll see 😂

Just send it here

[wide badge]

i know this is wrong

i just need help on figuring out P(E|Gc)

the professor said it was P(ABO), but i don't really understand how to compute that

[finite swallow]

How do you handle prior probabilities in a total probability problem?

[wide badge]

i just set P(G) equal to the prior probability

[finite swallow]

This is a mess, I think my knowledge isn't enough for this problem. I'll recommend asking someone else here, im sorry

[wide badge]

yeah no worries

its hardly covered in class

i have a slightly easier question 😂

or

[finite swallow]

Ah I see 😂

[wide badge]

actually nah i think its pretty similar

its kind of like a counting problem

[finite swallow]

Are you in the first year of your computer science degree

[wide badge]

second year

[finite swallow]

Ahhh probability 1?

[wide badge]

this class isn't for CS ironically its for a math minor

yeah

intro 😭

[finite swallow]

😭😭😭

[finite swallow]

This is the intro 😭 actually I have only done probability at high school as of now

Are you at an American University?

[wide badge]

yeah

[finite swallow]

I see, that's good

[wide badge]

Why?

WBY***

[finite swallow]

German university

[wide badge]

oh dope

have you ever considered coming to an american uni?

[finite swallow]

[finite swallow]

I did, in my 12th grade but after my SAT and ielts I decided to do it in Germany

MIT and the Ivys are just way too hard for me to get into lol

[wide badge]

oh i just go to a state school

nothing crazy

you're helping me out with stats so i think you're pretty smart 😂

[finite swallow]

I am decent at math 🤓

[finite swallow]

There are many good state schools too tbf

[wide badge]

i did great in calc 3 fwiw

[finite swallow]

W

[wide badge]

did you get to take a look at this

yeah calc stuff just made sense to me

the stats thing i need to just get accustomed to

[finite swallow]

Calculus is my favorite as well

[wide badge]

@finite swallow apparently it was just 2 * P(O) * P(AB) for P(E|Gc)

[finite swallow]

Is the 2 in the equation because of the prior probability?

[wide badge]

in the event that the suspect is not guilty, that means that the blood types they found at the site do not correlate with the suspect, but its kind of like how we did the girls problem ahead of time, BLOODo and BLOODab does not equal BLOODab and BLOODo

so there are two cases

[finite swallow]

Ahhh this makes sense

Finding AB suspect at 1 and finding O suspect at 2 is different from finding O suspect at 1 and finding AB suspect at 2

[wide badge]

whereas if the suspect WAS guilty, that means the blood type AB was the suspect, and P(E|G) would just be the probability of finding O blood

[finite swallow]

Yeah I feel this is correct

[wide badge]

okay cool

[wide badge]

still thinking about this one 😔

should i ping helpers

[finite swallow]

Yep it's been more than 15mins

[wide badge]

you've been the best helper though penguin thank you

<@&286206848099549185> does 7/12 make sense in the context of this problem?

[finite swallow]

Ah no problem man, happy to help :) have a good day/night

[vocal sleet]

@wide badge Has your question been resolved?

[vocal sleet]

@wide badge Has your question been resolved?

[wide badge]

<@&286206848099549185>

[vocal sleet]

@wide badge Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hidden stone]

Hi, explain me please how i can find the general equation of line if x-intercept only given

[civic otter]

You can't, you need an extra info

[hidden stone]

So, i can say that slope is undefined?

[civic otter]

Yep

[hidden stone]

And it means that line passing only x

Thank you

[civic otter]

You're welcome

[vocal sleet]

@hidden stone Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dry quarry]

Hey, is this correct

[vocal sleet]

@dry quarry Has your question been resolved?

[slender gazelle]

find the extremes of function

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal sleet]

@ember cloak Has your question been resolved?

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[buoyant notch]

For f(x)=sinx I need to find when x=0.5 for 0 less than equal to y less than equal to 360

[buoyant notch]

So is what I do is

sin0.5

And use cast to find the other point

So I have two

And using the period

360

I add 360 to each point

But that’s outside my range

So I only have two points

Is that right

Think so

No

Nevermind

I have to do 0.5=sinx

Take inverse of sin on 0.5

And do cast

[hushed agate]

Its $\arcsin 0.5=30$

[twin meteor]

Miyagi

[buoyant notch]

Why 30

[hushed agate]

And then find the other point

30 degrees

You didn't know that?

[buoyant notch]

Oh

I remember special angle yes

So the other point 210

[hushed agate]

Then use $\sin(180-\theta) =\sin{\theta}$

[buoyant notch]

Oh right

2nd quadrant

150

My bad am preparing for exam

Haven’t done in months

[twin meteor]

Miyagi

[hushed agate]

Lmao yes

Thats okay you know the answer now

[buoyant notch]

Tyty

.close

[vocal sleet]

Channel closed

Closed by @buoyant notch

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cursive crystal]

need help for this

[cursive crystal]

actually this just rechecking 1 and 2

<@&286206848099549185>

[vocal sleet]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[outer warren]

and if you concerns about your work, show it

[cursive crystal]

okay

[cursive crystal]

no i just need help how to solve num 3 i forgot how to solve it

way hard

our math teacher rushed us

[outer warren]

factorise the numerator

[cursive crystal]

so

1a3b/15

?

alsko 4 and 5

@outer warren

[outer warren]

show your work

[cursive crystal]

i'm in a laptop

[outer warren]

draw your work on paint
or show it in some mathtype program

[cursive crystal]

3x3ab^3+10a^5b/5x3a^3b^3

cancel the 3

3ab^3+1-a^5b/5a^3b^3

[hushed agate]

Use latex

$3ab^3+1-a^5b/5a^3b^3$

[twin meteor]

Miyagi

[cursive crystal]

yes

then a^4-3 and b^4-3

[hushed agate]

You typed it without brackets so that's incorrect i think

[cursive crystal]

i'm left with 3a^3b/5

,3a^3b/5

[hushed agate]

Is this question 5?

[cursive crystal]

3

[outer warren]

impossible to decipher your work

but it feels like you're doing a lot of illegal stuff

[cursive crystal]

i just need solutions for num 3 and i'm done

[outer warren]

you shouldn't end up with just one term like that on the numerator

[hushed agate]

The denominator should be 15a^2b^2

[outer warren]

forget about the denominator for now\
if you were asked to just factorise
$$-9ab^3 + 10a^5b$$
what would you do?

[twin meteor]

ℝαμΩℕωⅤ

[cursive crystal]

do the distributive property? ab(-9b^2+10a^4)

[vocal sleet]

@cursive crystal Has your question been resolved?

[outer warren]

yes

after that you'll have
$$\frac{\blue{ab}(-9b^2 + 10a^4)}{15a^3b^3}$$

[twin meteor]

ℝαμΩℕωⅤ

[outer warren]

then cancel the factor of ab in the numerator with the ab in the denominator

[vocal sleet]

@cursive crystal Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solar geyser]

alr so I have yet another problem
On a table, there is n stones, n is an even number. Players A and B take turns removing stones from the table. players can either remove exactly one third, exactly one half, or exactly two thirds. If that is not possible, the other player wins.
For which numbers n can player A force a win, for which numbers n can B force a win.

My idea was to factorize n and ignore all factors other than 2 and 3. players can now remove a three, convert a three into a two or remove a two.

If you get a two and a three, you can make the three into a two. the other player is now forced to take away a two, you take the other one away and he loses
if you get a single two or a single three, you just remove it and the other player loses.
If you get an odd number of twos, you each remove a two until the other player doesn’t have anything to do anymore.

That’s all I have. any ideas on how to continue?

[vocal sleet]

@solar geyser Has your question been resolved?

[solar geyser]

<@&286206848099549185> anyone?

come on <@&286206848099549185>

[vocal sleet]

Helpers are just people volunteering their time to help you. Be polite and patient.

[magic wasp]

You found that an odd number of 2s and no 3s is a winning position

Consider the total number of both 2s and 3s. Using a 3 can either reduce that total number by one (remove the 3) or not change it (convert into a 2)

The goal is just to remove all the 3s and at the same time leave the position with an even number of 2s

Figure out what to do in a position where there is one 3 left (depending on the number of 2s left), then same thing when there are two 3s left (again depending on the number of 2s left), and so on

[solar geyser]

that might help @magic wasp , thank you

.close

[vocal sleet]

Channel closed

Closed by @solar geyser

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit hound]

hold on let me write what i have so far

soo i have the shell radius but now i need hell height

idk whether its x + (-x/2)

or whether it should be subtraction

not sure

@graceful ibex

pls

<@&286206848099549185>

[twilit hound]

LMFAOO wrong ping

helpers save me!!!

<@&286206848099549185>

[carmine charm]

https://www.wolframalpha.com/

use this

[twilit hound]

i don't need help calculating

i need help finding the values

but i got it

.close

[vocal sleet]

Channel closed

Closed by @twilit hound

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shut storm]

i need help understanding what was done to this to get 64x12-729y18

divided by the other side

steps on how to solve this problem would be much appreciated

[mild flower]

,tex .exp rules

[twin meteor]

hayley!

[mild flower]

used distributivity and power of power

[shut storm]

Thanks so much @mild flower

[vocal sleet]

@shut storm Has your question been resolved?

Channel closed

Closed by @shut storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brazen perch]

Would I use the assignment rule for these types of problems? Or could I just trace the variable values back from the post to the pre condition?

[mild flower]

i think you can just consider the range of each variable at each step

[vocal sleet]

@brazen perch Has your question been resolved?

[brazen perch]

Like 6 for example, if I went post to pre condition

y= 0
y = z - 1
z = 2x+1
2x+1 = 0 or x = 0

Would that be sufficient proof?

[mild flower]

that doesn't make sense

if 2x+1=0 then x can't be 0

[brazen perch]

Whoops

y= 0
y = z - 1
z = 2x+1
2x+1 = 1 or x = 0

[mild flower]

i guess? idk why you don't go pre to post though

[brazen perch]

2x+1 = 1 or x = 0
z = 2x+1
y = z - 1
y= 0

This is better?

[mild flower]

x = 0
z = 2x + 1 = 2(0) + 1 = 0 + 1 = 1
y = z - 1 = 1 - 1 = 0

[brazen perch]

Oh I see

That would prove the correctness of the statement then?

[mild flower]

yeah it proves that IF x=0 at the start, THEN y=0 at the end

[brazen perch]

Awesome thank you

.close

[vocal sleet]

Channel closed

Closed by @brazen perch

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal sleet]

@wary mantle Has your question been resolved?

[wary mantle]

.close

[vocal sleet]

Channel closed

Closed by @wary mantle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[golden imp]

can anyone please tell why i got this wrong??

[golden imp]

i was trying to prove limx->0 sin(x)/x equals 1

[hushed pewter]

I cannot make out what you writing

Are you numbering each line?

On line 2, did you square everything and shorten sin to just s?

[golden imp]

oh yep

it was actually just a scribble of mine to solve it but i guess i had to clear that out before posting this

[hushed pewter]

Is this 4²*x²?