#help-17
1 messages · Page 145 of 1
like
what you need to know is that y = mx + b describes a linear equation
everything else does not
thats all they are trying to say pretty much
im not very good at math since im a slight bad kid so im never in class i havent actually even been inside of a math lesson this entire year
I'm actually learning the same, how do you deal with the negative numbers?
but i still want to try to understand some stuff
$a^b = c$ here is an exponential, b is the exponent.
Please dont ask questions in other people's channels. Open your own channel to avoid clutter and confusion
! What the hell am I doing here?
i dont think this is something we can really help you with from what you are saying lol
i think you should watch something like khan academy
i end up getting zoned out im a lot better whenever somebody explains it
when im abel to ask questions too
its why i joined this
honestly you have not asked a specific question at all yet so its really hard to explain anything yet
like i can never really focus on it then i get confused and i forget everything that i learned
can you like
whenever i look at equations i get confused on the letters and stuff i dont understand what they want me to do ever
thats context dependent
wait ill pull up more math work
im so going to fail my math test 😭
heres something
im not sure if this is competely what will be on the test but this assignemnt is the only one thats open
im always confused by the letters and stuff
i dont know what im supposed to do here
okay
here is a rule of thumb for you
a linear equation describes the equation of a line and it usually comes in two forms
y = mx + b
or
Ax + By = C
As an example
y = 3x + 4
what do the letters stand for though
this is a linear equation
what makes it not a linear equation
[ \c b y= \c g m \c o x + \c p b ]
where:
$\c b y$: this is the dependent variable. It changes when $\c o x$ changes.
$\c o x$: this is the independent variable. It describes what $\c b y$ will be
$\c g m$: this is the slope. You can find it by the equation $\ds m = \f{y_2 - y_2}{x_2-x_1}$
$\c p b$: this is the $y$-intercept. It is what you get when you set $\c o x = 0$ in your equation
oohh i was told awhile ago that the numbers are just like inplace of the answer it may be for a different type of math
thats why ive been confused
i will be totally frank with you: There is a lot of foundational knowledge you are missing and you should really backtrack a bit and start learning from the start
i know that
i havent really fully attempted on learning in a couple years
and
since im awlays getting suspended or getting iss
i can never actually sit in a class room and try
and when i do try i end up getting confsued then overwhelmed so just give up
thats why im so behind
and its nearly impossible to really learn years of math
but i cant backtrack since id be learning stuff that isnt even on tests
ive made attempts in the past
You really don't have to justify yourself or something to me
im not im just explaining why i aint smart
ok
Middle school mathematics.
im in middle school
start with prealgebra
@fast moth I'll try to help.. do you know what graph looks like? With y and x?
okay good
Maybe. I don't know your curriculum
I'd advice to study all of it because you will need it now or in the future anyways
okay
well basically, the functions you sent can represent a graph
y = (something in terms of x)
ooohh
so like
am i able to look at it as if its a graph
or will that make it harder
a linear function is something that represents a line! hence the term linear
I suggest you to take a piece of paper now and draw a y and an x axis
y is a vertical while x is horizontal
and maybe, you can annotate that graph and give it numbers
i think i understand
oh yea i saw that in the beginning of the year
okay
okay done
and do you see the numbers on the x-axis?
what happens to y, if x=0, x=1, x=2, x=3, etc?
in y = 2x
if x=0, then y = 2 x (0) = 0
if x=1, then y = 2 x (1) = 2
etc
right?
just substitute x for the values you see on the graph
why would y= 2
oh wait i get that now
y = 2, when x=1, because in y = 2x, if we replace the x by 1, then y = 2
get it?
yea i do
okay
can you do that on your graph
and make a dot
for like the first three values of x for example
thats what im about to do
good! 👍
donee
what do you mean?
yes
i was confused how ud find out how it would be linear or not
yea i believe so
if I gave you y = x^2 , do you know if it it's linear or not?
wait i need to think
okay
draw it!
do the same thing
play around
draw another graph with y and x
and plug in some numbers
x to the power of 2, do you know what powers are?
okay powers are basically just a simpler way of saying
i sound so dumb omg
I'll give you an example, it's easier to visualise:
okay
2^3 = 2 x 2 x 2 = 8
3^2 = 3 x 3 = 9
4^3 = 4 x 4 x 4 = 64
basically
how many times I multiply the number
so its for multiplying?
so x would go up by 2 or 4?
wait, not so fast
oh i dont go there yet
are you use you understand powers
so
let's say you have 2^3, we want to multiply 2, 3 times!
so 2 x 2 x 2
another example would be 2^4, 2 x 2 x 2 x 2
you mean like x^2?
yea i do
well, to find out, you have to substitute values of x=0, x=1, x=2 etc
try it yourself
math is so confusing
i feel bad that i dont really understand still
yea i do
for y = 2x
i have bad memory anytime i attempt to learn i get it 1 try they i totally forget again
let's try the same thing, but for
y = x^2, so instead of x, we will try various numbers such as x=0, x=1, x=2
the good thing about math is that there's not much memory, it's all logic!
okay do you need to attmept a couple numbers or is there a way to know first try
try it first and then I'll give you the way to know first try
not when u need to do a ton of stuff that u need to remember..
okay
I know that you have a lot of stuff to remember but it's life, it doesn't get better after middle school trust me
so if you want to have an easier high school and university, bare with me
yes exactly, it's now or never to understand that
ik
give it a try
i used to be good at math so i thought i didnt need to focus
til
i ended up so so so behind
i will now
let's think about this
okay
x =1, right
yes
you go one line to the right from the center
when x=1, and we said y = x^2
we replace the x in the function y, by x=1
did i do the wrong thing?
so effectively, y = 1^2 = 1 x 1 = 1
okay let's try another way
I don't feel like you understand
math isnt my strong suit so its surprising when i do understand
could you annotate the axis? with numbers from 1-10
the y and the x axis
no one is born bad at math, it is just different for everyone
focus on maths for now, you'll get satisfaction if you do well on the test
its a benchmark btw
like u want me to number them all like u did?
oh ive been just doing it in my head
oh god
I'm afraid
but
don't be afraid, maths is good when you know what you're doing
if you focus now you'll make your life so much easier
does math really play apart of life out of school
yes, in almost every field
even majors like psychology where you wouldn't necessarily expect it to be
yes, focus
i think ill actually need to do this on paper now that im doing numbers since its hard to do placing
yes
ill grab my math notebook ill be here in a second
maths pen and paper like the good old days
np
i am back
i havent really looked inside my bookbag since i dont bring it to school but i found a book for what im working on that i forgot my teacher handed me
okay
its unit 3 linear relationships or whatever
it's okay, paper is paper
i grabbed it too not sure if i was supposed too
if you understand by experimenting yourself, then you'll understand better anyway
draw that graph
done
okay
now
you remember what we did with y = 2x a while ago, right?
try for y = x^2, the same way, by substituting values of x with the numbers of the x axi
and when you get a value, draw a dot on the graph
i sadly will not be able to take a photo since i am on my laptop mainly why i decided to use one online
okay
can you tell me how to like
figure out what x is going to =
u said i would after i made an attempt
x will always be the values at the bottom, on your x axis
what we want to know is
"What will y be, when x is a certain number?"
my friend is so shocked that im attempting math rn
we could try by asking ourselves, what will y be, when x=0? for example
when x=0?
yea
let's compute it:
In the function y = x^2
let x = 0, so y = 0^2 = 0 x 0 = 0
then if its 1 then it can go up bc 1x2 is 2 or whatever right
oh wait
so if its on 10 would it be 20..
let x = 1, so y = 1^2 = 1 x 1 = 1
oh
thats confusing
why don't you steal this sentence from me and try for x=1,x=2,x=3
let x = ... , so y = x^2 = ... x ... =
just substitute the values of x and and see what happens
so it can be any substitute that isnt important?
it doesn't matter, but I doubt that you managed to have space to write
x= 99 on your graph xDD
your graph isn't that big hopefully
I think just for simplicity we can still for small values of x
yep, just try for the first 3-4 values of x
wym 3-4
ohh
wouldnt it be 2 up from those numbers or would i mulitiple whatever number i pick by 2?
try it and see for yourself
how would i know if im correct or not tho
I'll show the correct answer when you're done
oh okay
so that you can compare
well i put 2 lines down
i mean
2 dots down
like
one that is just 2 above and one that is 2x3
origin?
well, good, because it's not meant to be!
oh
y = x^2 is a non-linear function
OMG I COPIED OFF THIS ONE BOY IN CLASS ONCE I THINK HE WAS DOING THIS STUFF
lmao
do it yourself from now on, you're smarter than that ;)
let me show you what your graph should look like
well when i had that teacher when i asked what to do she was just like
"um read the paper"
does your graph look like that?
oh it does not
In the function y = x^2
at x = 0
we have y = 0^2, which is 0 x 0 = 0
at x = 1
we have y = 1^2, which is 1 x 1 = 1
at x = 2
we have y = 2^2, which is 2 x 2 = 4
do you get what I mean
oh so i was supposed to do 1 for each number
yep
is it supposed to be 3 dots?
i did itt
so each values of x, represents a value of y
but, in our case, we want to find out what that value of y is
that's why we have functions in the form y = something
we want to know what these values of y are
can you draw a line that passes through all dots?
I'm assuming that these are the dots that you have
it is
check if the coordinates match
oh they dooo
good!
hip hip hooray i did sometihng right
if you connect the dots, you should get something that looks like this
i did connect them
yea i did realise that
OH WAIT SO TO DO THE FIRST THING I WAS LOOKING AT B4 LIKE
this is what i used as an example of what im confused on
yesss
is there a way to know without solving them?
uh
for all functions where the x is not raised to an exponent/ power
it is a linear function!
what..
okay will do
so the first one is linear then the second one is nonlinear?
unsure how to do number 3
is number 2 linear?
or is there something im missing there
number 2 is not linear
ah
number 3 is linear, because it has a coefficient of x only
you could sketch it to visualise
number four is nonlinear right bc it has the thing next to the x?
then 5 is linear and 6 is nonlinear?
In an equation check the highest degree of x
Like felix said if it's one i.e., x it's linear
okayy
to answer your doubt about y = (-1/2)x
this is what it looks like if you were to skecth it
okayy
so it looks like a line, just the mirrored way
im a lil confused on the next question on this random thing im working on
i mean its simple but its wrote a little bit different
and play around with it
my teachers talk about it a lot
can you show me
im trying to see if i can understand it first since theres a chance i can
but here u go
i think its linear but i cant tell
its simple but
Check the highest degree of x
I don't think a middle schooler would know what a degree means
yea i dont..
but 2 is before x, no?
yep
so it is an linear?
i just realised
this is the first assignment im going to turn in to my new teacher
shes going ot assume im smart..
lmao
😭
well actually the first day she saw me she saw me try to walk out of class and the entire class i had my earbuds in while i played flappy bird and i put the paper she gave to me behind me..
most of the time i only study for tests
you can watch youtubers such as Khan academy or the organic chemistry teacher to learn maths, they're really good at explaining
think about it
it doesn't change the logic
i was focused on the confusing nnumber
can you open https://www.desmos.com/calculator ?
okay
i just heard her cough 😭
learn as much as you can while you still can
how do i do that
go on
"graphing calculator"
and on the left you should have a panel
you can just write y = 0.46x there
it should give you a nice little graph
oh so its linearrrr
yes
you might have noticed that
the only thing that changed
is how steep the line is
yea i did
its a lot better to know that
you're right
im a lil confused on the 2 line thing is it still linear if theres 2 different lines???
omg
I would be tempted to say nonlinear
yes, go for nonlinear
okay
oh god its getting harder
haha
well idk if this is harder or im just dumb
nah probably harder
the teacher is trying to see to what extend you understand the concept
not really
I think you will have to watch videos for that, but for now, keep in mind that taking the square root a number (the symbol you have on the picture in front of), is like raising to the power of 1/2
so x is raised to a power
a power, also known as exponent, is repeated multiplication
let's say I have 2^3, then I'm gonna repeat and multiply 2 three times
so 2 x 2 x 2
if I have 2^1000 ( then it's 2 x 2 x 2 x 2 x 2 x..... x 2 until I do it 1000 times)
a huge number
oh my
the symbol you have on the picture
is just a fancy symbol for the exponent 1/2
so x, has a power
hence it is.. nonlinear
i was kinda thinking it was linear
it has an exponent though
thanks
I hope she can picture it now
tne coefficient affects the steepness of the function as you saw before, but it does not change whether a function is linear or not
you played around before with y = 0.46x if you remember and played with the coefficient
it does not change whether the function is linear or not however
whether a function is linear or not
yes and no
yes as long as it's reasonable guesses but maths is a science of precision and you need to be very clear in your head to do anything
okay
that's one good thing about maths
in the past i kinda just glimmed over the question and picked what felt like what would work
unlike English, if you understand everything then you'll get 100% on your test
in English, it's more subjective
since you can just read the questions ifrst then the story and highlight the important parts
then its all there
oh
my brother is 19 when i ask him to help he always says he forgot what that is or tells me the high school way to do it
then im all confused bc he just told me like 40 different ways
time to be smarter than your brother
yes
work hard
it pays off
maths is particularly rewarding
either you understand, or you don't
it's never too late to catch up
until it's too late
maybe start watching some youtube videos
idk how to explain it but im better at learning from reading stuff
whenever im listening
i zone out
then
i get bored
and i start doing other stuff
yeah it's fine
hi
The teacher is trying to make their students understand in every way possible
I know
this one is a particular one!
if you're unsure, use the technique we used at the very start, where we plugged in values of x to see the behaviour of y
In this video where we're going to graph of the equation y=1/x.
We'll start with the completed graph on-screen and we're going to work backwards. That means the graph for y = 1/x has already been completed and we're going to try and understand how it was constructed.
Let's start with the equation y=1/x. One thing to note about this equation is...
with the grap
watch this video
ignore her
ill js turn on captions nvm
she is 17 and shes about as dumb as me
done
did you understand?
yea the 1/x bascially makes it an half rfor the y or whatever and it would be nonlinear
turns out that 2/x is just 2 x 1/x
so no matter what the numerator is, the top of the function, it would always be nonlinear
not bad!
keep on improving
it's okay
the best way to learn is by making mistakes
the more mistakes you do, if you learn from then, then you'll improve significantly
i thought i understood the tables so i was attempting them myself but ig not
those are the wrong ones btw
oh
x^(2) is the same as the exponent thing by the way
that's why you got them wrong
okayyy
not bad! keep on working and do well for that test
I'll study some maths myself too now
it was fun teaching you, promise me to try and do your best on that test
watch as many youtube videos and graph on Desmos if unsure
okay ill try to do as much as possible today
u toooo
bye
@fast moth Has your question been resolved?
Closed by @fast moth
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how do i solve this
ok i will try it
i did the same thing as this but i put subtraction in denominator instead of addition lol
@olive herald Has your question been resolved?
Closed by @olive herald
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how is this 47 and not -58
actually so confused
what ive done is found the deriv of F(x)
then subed the numbes with f'(-1)
i got -58
how is it 47
yes
i got -58
for the deriv?
(x^11)(h')+(h)(10x^10)
what
help a sad kid | desi
wait even then it would still be -55 - 8
yeah
wait am i doing some math wrong here when im subbing
11(-1)^10 equals -11
no?
wait how
wait im so slow
i put -1^11 in the graphing calculator to make sure
but i forgot graphing calculators are always going to make sure its a negative
when its actually a positive
it says -1^10 is -1 as well
its still showing up as -1
oh
LOL
its been a long time since ive done math
okay lets start over
new numbers
its practice
i got 3
no wait
okay
its -12
im actually super dumb
no i got it right
i just messed up my numbers LOL
@empty meteor Has your question been resolved?
Closed by @empty meteor
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
In a trapezoid the bases big angles bisectors cut each other to the second base the trapezoids hight is 12 and the bisector lenghs are 13 and 15 i need to find all the sides of the trapezoid
@rain hollow Has your question been resolved?
.close
Closed by @rain hollow
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
The right triangle △ABC has AB = 12, and AC = 16. Let (AD bisector of the angle ∠BAC, D ∈ (BC), DE ⊥ AB, E ∈ (AB), and DF ⊥ AC, F ∈ (AC). a) What is the nature of the quadrilateral AEDF? b) Shown that DE/AC + DF/AB = 1.
Notice that BED is similar to BAC
Same with DFC
That allows you to rewrite your problem statement
So if k is the simmilarity coeficient
ED is k*AC
No, it isn't, but you don't need that
You don't even need the fact that AD is a bissector
DF = k*AB
Really?
I was gonna use the bisector theorem
this is the first step, you can do something similar to DFC as well
@lethal plank Has your question been resolved?
Got stuck again...
So, DF/AB = DC/BC
Substitute both this one as well
@lethal plank Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
For each node v on the right side, there should be a directed edge to another node u on the right side if and only if the set corresponding to v is a subset of the set corresponding to u. So in short, what funcitons are subsets and to which? I dont really get if the operators in front of the functions play any role? My thought process would be, for example that in the first one (sqrt of n) given that its O, has everything in its subset thats smaller this would be (if im allowed to multiply with sqrt (n)) everything thats in the right quadrants?
@sullen lotus Has your question been resolved?
@sullen lotus Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
For a) what does it mean for the slope if the tangent is horizontal?
It means the slope is undefined.
Nope
?
So you calculate the derivative
Yes those added is the derivative
Since this is the derivative (slope) we just need to find when f’=0
f’(x)= 4/3x^1/3+ 4/3x^-2/3 is your calculated derivative
So slope 0 means f’(x)=0
That’s the meaning of the derivative it’s the slope of the tangent line of your function f
So basically I solve for x?
Yeah
And then your point/s is/are (x,f(x))
For the b) look what happens for f’(x) when x is close to 0
What happens to the slope close to zero
Vertical Tangent would intuitively mean slope is some kind of “infinty”
Interesting
Oh so there are no vertical lines
I'm so idiot smh
.close
Closed by @rigid falcon
Use .reopen if this was a mistake.
What do you mean
There are vertical lines it’s just not a function
This function actually has a vertical tangent
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
What type of data is represented?
Univariate categorical
Bivariate categorical
Univariate numerical
Bivariate numerical
Sorry I did not see this.
@normal imp Has your question been resolved?
<@&286206848099549185>
is the distrbution over categories or numbers?
categories
and how many modes are there (bumps)?
bumps?
how many peaks are there?
i think you’re confusing unimodal with univariate
oh wait, I am, sorry about that 
univariate means that the outcome depends on one variable
bivariate means it depends on two
categorical vs numerical is based on the outcome (is it a number or not?)
so does the distribution depend on one or two variables?
and is the distribution about a number?
one right?
yup
its categorical right
cause we're going based on colour not numbers
that’s actually the thing that it depends on
the result we want is the number of candies from each color
.close
Closed by @normal imp
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
i got cos(2x) to be 24, is that right?
how did you get 24? remember that the range of cosine is only the closed interval [-1,1].
It would be helpful to draw a triangle
you are right that tan = sin/cos
but this doesn’t mean that the numerator of the fraction is the sine and the denominator is the cosine
-12/5 is just their ratio, not their actual values
so how shud i find cos x
do you know how to construct a triangle using the given?
okay
okay do you remember soh cah toa?
yes
okay so now what is o and a in this case?
12 is o and -5 is a
yes
okay
let’s go back to your identity for cos(2x)
what identity do you want to use?
prob the cos^2x-1 oen
can you review that one? you’re missing one constant
yes
yes!
exactly!
Closed by @marble harbor
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
i made an error somewhere in number 2 but im not sure where
Notice how the bottom limit is larger than the bottom one, so you basically multiply your answer by -1
As you have that $\int_9^0 f(x) \dd x = -\int_0^9 f(x) \dd x$, with the latter integral being what you thought it was
@dull bear
i got an answer of (-6.63) so then i multiplied by -1 and got (6.63) and it was wrong
am i missing something?
humm
becasue for pi i just used 3.14,i suppose i could try using full pi.
anything else look off other than that
As in you rounded to the hundredth rather than thousandth, no?
But otherwise looks fine to me in method! 
no i mean for pi i did not use the full pi, like 3.14159265359 etc
@unique sluice Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
maybe ask on the site's own forums
@rough zenith Has your question been resolved?
Closed by @rough zenith
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
sqrt (u^2/x)100
@eternal marsh Has your question been resolved?
Closed by @eternal marsh
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
i need help finding out what i did wrong here, i dont know which parts are oficially a b and c
you are the one who designates which is a b and c
i dont know what i did wrong then
the answer is 64
and i got 2.144
did i use the wrong formula
yep i got 64 too hang on
your sides are wrong
your c side should be the side that is opposite facing to the angle
yea
that's the important side
i did it wrong again
i dont know what im doing wrong
Is your calculator in degree or radian
um idk
scientific calculator victor 940
should i be using the other formula
or isnt that to find the side length
make sure your calculator is set to degrees
and type it again