#help-17

1 messages · Page 145 of 1

fast moth
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nono i was confused about what i was explaining

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the exponents idk what that is

vast shale
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like

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what you need to know is that y = mx + b describes a linear equation

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everything else does not

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thats all they are trying to say pretty much

fast moth
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im not very good at math since im a slight bad kid so im never in class i havent actually even been inside of a math lesson this entire year

vast shale
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I'm actually learning the same, how do you deal with the negative numbers?

fast moth
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but i still want to try to understand some stuff

astral shadow
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$a^b = c$ here is an exponential, b is the exponent.

vast shale
twin meteorBOT
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! What the hell am I doing here?

fast moth
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all of the numbers confuse me sm 😭

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and letters

vast shale
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i dont think this is something we can really help you with from what you are saying lol

fast moth
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oohhh

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well like

vast shale
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i think you should watch something like khan academy

fast moth
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i end up getting zoned out im a lot better whenever somebody explains it

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when im abel to ask questions too

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its why i joined this

vast shale
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honestly you have not asked a specific question at all yet so its really hard to explain anything yet

fast moth
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like i can never really focus on it then i get confused and i forget everything that i learned

vast shale
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can you like

fast moth
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oohh

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okay ill explain what im confsued on

vast shale
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point out something in particular

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okay great

fast moth
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whenever i look at equations i get confused on the letters and stuff i dont understand what they want me to do ever

vast shale
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thats context dependent

fast moth
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wait ill pull up more math work

vast shale
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ok

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great

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provide problems instead of like talking about it abstractly

fast moth
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im so going to fail my math test 😭

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heres something

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im not sure if this is competely what will be on the test but this assignemnt is the only one thats open

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im always confused by the letters and stuff

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i dont know what im supposed to do here

vast shale
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ok first of all like

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calm down it is only difficult if you tell yourself that it is

fast moth
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okay

vast shale
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here is a rule of thumb for you

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a linear equation describes the equation of a line and it usually comes in two forms

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y = mx + b
or
Ax + By = C

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As an example

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y = 3x + 4

fast moth
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what do the letters stand for though

vast shale
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this is a linear equation

fast moth
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what makes it not a linear equation

vast shale
# fast moth what do the letters stand for though

[ \c b y= \c g m \c o x + \c p b ]
where:

$\c b y$: this is the dependent variable. It changes when $\c o x$ changes.

$\c o x$: this is the independent variable. It describes what $\c b y$ will be

$\c g m$: this is the slope. You can find it by the equation $\ds m = \f{y_2 - y_2}{x_2-x_1}$

$\c p b$: this is the $y$-intercept. It is what you get when you set $\c o x = 0$ in your equation

twin meteorBOT
fast moth
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oohh i was told awhile ago that the numbers are just like inplace of the answer it may be for a different type of math

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thats why ive been confused

vast shale
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i will be totally frank with you: There is a lot of foundational knowledge you are missing and you should really backtrack a bit and start learning from the start

fast moth
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i know that

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i havent really fully attempted on learning in a couple years

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and

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since im awlays getting suspended or getting iss

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i can never actually sit in a class room and try

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and when i do try i end up getting confsued then overwhelmed so just give up

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thats why im so behind

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and its nearly impossible to really learn years of math

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but i cant backtrack since id be learning stuff that isnt even on tests

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ive made attempts in the past

vast shale
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You really don't have to justify yourself or something to me

fast moth
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im not im just explaining why i aint smart

vast shale
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ok

fast moth
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where do you think i should start then

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i believe my math test is in 2 days

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maybe 3

astral shadow
fast moth
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im in middle school

vast shale
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start with prealgebra

fast moth
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okay

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will i be able to learn it all in 1 day

silent lark
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@fast moth I'll try to help.. do you know what graph looks like? With y and x?

fast moth
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i skipped school today to study

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i do

silent lark
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okay good

fast moth
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okay

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do i need to look at the rest

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or is it not important

vast shale
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Maybe. I don't know your curriculum

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I'd advice to study all of it because you will need it now or in the future anyways

fast moth
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okay

silent lark
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well basically, the functions you sent can represent a graph
y = (something in terms of x)

fast moth
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ooohh

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so like

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am i able to look at it as if its a graph

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or will that make it harder

silent lark
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a linear function is something that represents a line! hence the term linear

silent lark
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y is a vertical while x is horizontal

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and maybe, you can annotate that graph and give it numbers

fast moth
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i think i understand

silent lark
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something that looks like that

fast moth
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oh yea i saw that in the beginning of the year

silent lark
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okay

fast moth
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i think thats what my teacher was trying to teach us

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b4 she quit

silent lark
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oh

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okay

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graph that

fast moth
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okay done

silent lark
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okay now

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let's say you have

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y = 2x

silent lark
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what happens to y, if x=0, x=1, x=2, x=3, etc?

fast moth
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yea i can

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um

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wait im thinking

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im not sure

silent lark
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in y = 2x

if x=0, then y = 2 x (0) = 0
if x=1, then y = 2 x (1) = 2
etc

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right?

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just substitute x for the values you see on the graph

fast moth
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why would y= 2

silent lark
fast moth
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oh wait i get that now

silent lark
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get it?

fast moth
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yea i do

silent lark
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okay

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can you do that on your graph

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and make a dot

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for like the first three values of x for example

fast moth
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thats what im about to do

silent lark
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good! 👍

fast moth
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donee

silent lark
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okay

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now

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what happens

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if you draw a line through all the points

fast moth
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it would make a line right?

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which would be uh

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linear

silent lark
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yep, precisely

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yes!

fast moth
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OOHHH

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so if it doesnt equal 1 line then it isnt linear

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that makes sense omg

silent lark
fast moth
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like

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if on the graph if isnt a line then that makes it isnt linear

silent lark
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yes

fast moth
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i was confused how ud find out how it would be linear or not

silent lark
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yep

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do you know how graphs look like?

fast moth
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yea i believe so

silent lark
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if I gave you y = x^2 , do you know if it it's linear or not?

fast moth
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wait i need to think

silent lark
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okay

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draw it!

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do the same thing

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play around

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draw another graph with y and x

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and plug in some numbers

fast moth
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okay

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omg im confused again

silent lark
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okay it's okay don't worry

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have you drawn a graph?

fast moth
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what does x^2 mean

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yes i have

silent lark
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x to the power of 2, do you know what powers are?

fast moth
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slightly

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ive heard of them

silent lark
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okay powers are basically just a simpler way of saying

fast moth
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i sound so dumb omg

silent lark
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I'll give you an example, it's easier to visualise:

fast moth
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okay

silent lark
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2^3 = 2 x 2 x 2 = 8
3^2 = 3 x 3 = 9
4^3 = 4 x 4 x 4 = 64

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basically

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how many times I multiply the number

fast moth
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so its for multiplying?

silent lark
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it uses multiplication

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basically, it's repeated multiplication

fast moth
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so x would go up by 2 or 4?

silent lark
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wait, not so fast

fast moth
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oh i dont go there yet

silent lark
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are you use you understand powers

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so

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let's say you have 2^3, we want to multiply 2, 3 times!

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so 2 x 2 x 2

fast moth
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oohh

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but what if it has an x?

silent lark
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another example would be 2^4, 2 x 2 x 2 x 2

silent lark
fast moth
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yea i do

silent lark
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well, to find out, you have to substitute values of x=0, x=1, x=2 etc

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try it yourself

fast moth
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math is so confusing

silent lark
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haha

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when you get it, it's very satisfying

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give it a try

fast moth
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i feel bad that i dont really understand still

silent lark
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it's okay

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okay

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you remember the y = 2x dots we drew?

fast moth
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yea i do

silent lark
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for y = 2x

fast moth
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i have bad memory anytime i attempt to learn i get it 1 try they i totally forget again

silent lark
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let's try the same thing, but for
y = x^2, so instead of x, we will try various numbers such as x=0, x=1, x=2

silent lark
fast moth
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okay do you need to attmept a couple numbers or is there a way to know first try

silent lark
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try it first and then I'll give you the way to know first try

fast moth
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okay

silent lark
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I know that you have a lot of stuff to remember but it's life, it doesn't get better after middle school trust me

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so if you want to have an easier high school and university, bare with me

fast moth
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i go to highschool next year

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😭

silent lark
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yes exactly, it's now or never to understand that

fast moth
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ik

silent lark
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give it a try

fast moth
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i used to be good at math so i thought i didnt need to focus

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til

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i ended up so so so behind

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i will now

silent lark
fast moth
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btw i used an online graph

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and drew it on there

silent lark
fast moth
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okay

silent lark
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x =1, right

fast moth
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yes

silent lark
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you go one line to the right from the center

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when x=1, and we said y = x^2

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we replace the x in the function y, by x=1

fast moth
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did i do the wrong thing?

silent lark
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so effectively, y = 1^2 = 1 x 1 = 1

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okay let's try another way

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I don't feel like you understand

fast moth
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math isnt my strong suit so its surprising when i do understand

silent lark
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the y and the x axis

silent lark
fast moth
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i wish math was as easy as ela

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i havent ever failed an ela test

silent lark
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focus on maths for now, you'll get satisfaction if you do well on the test

fast moth
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its a benchmark btw

fast moth
silent lark
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yes

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it will make it easier for us to work with

fast moth
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oh ive been just doing it in my head

silent lark
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no

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math needs to be concise

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write everything down

fast moth
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is this math even supposed to be hard

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or is this supposed to be easy 😭

silent lark
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this

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is

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as easy as it gets

fast moth
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oh god

silent lark
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I'm afraid

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but

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don't be afraid, maths is good when you know what you're doing

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if you focus now you'll make your life so much easier

fast moth
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does math really play apart of life out of school

silent lark
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yes, in almost every field

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even majors like psychology where you wouldn't necessarily expect it to be

fast moth
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oh god

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okay ill write it down

silent lark
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yes, focus

fast moth
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i think ill actually need to do this on paper now that im doing numbers since its hard to do placing

silent lark
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yes

fast moth
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ill grab my math notebook ill be here in a second

silent lark
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maths pen and paper like the good old days

fast moth
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i am back

silent lark
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okay

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do the graph with y and x and write down numbers

fast moth
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i havent really looked inside my bookbag since i dont bring it to school but i found a book for what im working on that i forgot my teacher handed me

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okay

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its unit 3 linear relationships or whatever

silent lark
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it's okay, paper is paper

fast moth
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i grabbed it too not sure if i was supposed too

silent lark
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if you understand by experimenting yourself, then you'll understand better anyway

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draw that graph

fast moth
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done

silent lark
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okay

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now

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you remember what we did with y = 2x a while ago, right?

try for y = x^2, the same way, by substituting values of x with the numbers of the x axi

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and when you get a value, draw a dot on the graph

fast moth
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i sadly will not be able to take a photo since i am on my laptop mainly why i decided to use one online

silent lark
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it's okay

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as long as you do it

fast moth
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okay

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can you tell me how to like

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figure out what x is going to =

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u said i would after i made an attempt

silent lark
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x will always be the values at the bottom, on your x axis

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what we want to know is

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"What will y be, when x is a certain number?"

fast moth
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my friend is so shocked that im attempting math rn

silent lark
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we could try by asking ourselves, what will y be, when x=0? for example

fast moth
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it would be on the y line right?

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next to the number 2

silent lark
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when x=0?

fast moth
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yea

silent lark
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let's compute it:
In the function y = x^2

let x = 0, so y = 0^2 = 0 x 0 = 0

fast moth
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oh so it would be on 0

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i didnt think of that

silent lark
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yep!

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at x=0, the function y = x^2 would be at the origin, that's how we call it

fast moth
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then if its 1 then it can go up bc 1x2 is 2 or whatever right

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oh wait

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so if its on 10 would it be 20..

silent lark
fast moth
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oh

silent lark
fast moth
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thats confusing

silent lark
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why don't you steal this sentence from me and try for x=1,x=2,x=3

let x = ... , so y = x^2 = ... x ... =

fast moth
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ohh

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okayokay

silent lark
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just substitute the values of x and and see what happens

fast moth
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so it can be any substitute that isnt important?

silent lark
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it doesn't matter, but I doubt that you managed to have space to write
x= 99 on your graph xDD

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your graph isn't that big hopefully

fast moth
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it is not

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i dont have time for that..

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i only did 10

silent lark
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I think just for simplicity we can still for small values of x

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yep, just try for the first 3-4 values of x

fast moth
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wym 3-4

silent lark
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like, x=0, x=1, x=2, x=3

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just these 4

fast moth
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ohh

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wouldnt it be 2 up from those numbers or would i mulitiple whatever number i pick by 2?

silent lark
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try it and see for yourself

fast moth
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how would i know if im correct or not tho

silent lark
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I'll show the correct answer when you're done

fast moth
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oh okay

silent lark
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so that you can compare

fast moth
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ill just pick 3 then

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donee

silent lark
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does it look like a line to you

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if you were to connect the dots

fast moth
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well i put 2 lines down

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i mean

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2 dots down

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like

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one that is just 2 above and one that is 2x3

silent lark
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but

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you also have the origin

fast moth
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origin?

silent lark
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the point when we set x=0

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we found out that y was also equal to 0

fast moth
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OH

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well what ive drawn is not a straight line

silent lark
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well, good, because it's not meant to be!

fast moth
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oh

silent lark
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y = x^2 is a non-linear function

fast moth
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OMG I COPIED OFF THIS ONE BOY IN CLASS ONCE I THINK HE WAS DOING THIS STUFF

silent lark
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lmao

fast moth
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i just realised bc he had a random line w dots

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on this

silent lark
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do it yourself from now on, you're smarter than that ;)

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let me show you what your graph should look like

fast moth
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well when i had that teacher when i asked what to do she was just like

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"um read the paper"

silent lark
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does your graph look like that?

fast moth
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oh it does not

silent lark
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oh, check your calculations

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so let's think about this

fast moth
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the fact im grounded and i stole my laptop back while my mom is asleep for this

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okay

silent lark
#

In the function y = x^2

at x = 0
we have y = 0^2, which is 0 x 0 = 0

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at x = 1
we have y = 1^2, which is 1 x 1 = 1

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at x = 2
we have y = 2^2, which is 2 x 2 = 4

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do you get what I mean

fast moth
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oh so i was supposed to do 1 for each number

silent lark
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yep

fast moth
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is it supposed to be 3 dots?

silent lark
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yep

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you have to do one for each

fast moth
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i did itt

silent lark
#

so each values of x, represents a value of y

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but, in our case, we want to find out what that value of y is

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that's why we have functions in the form y = something

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we want to know what these values of y are

fast moth
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theres multiple dots thouhg

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do u add them

silent lark
#

can you draw a line that passes through all dots?

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I'm assuming that these are the dots that you have

fast moth
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it is

silent lark
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check if the coordinates match

fast moth
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oh they dooo

silent lark
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good!

fast moth
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hip hip hooray i did sometihng right

silent lark
#

if you connect the dots, you should get something that looks like this

fast moth
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i did connect them

silent lark
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good

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you will notice that

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that does not look like a line

fast moth
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yea i did realise that

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OH WAIT SO TO DO THE FIRST THING I WAS LOOKING AT B4 LIKE

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this is what i used as an example of what im confused on

silent lark
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yesss

fast moth
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could i use what ive learned so far for this

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?

silent lark
#

ofc

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you could solve all of them already actually, but it would be time consuming

fast moth
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is there a way to know without solving them?

silent lark
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yep! there's a trick

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so

fast moth
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uh

silent lark
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for all functions where the x is not raised to an exponent/ power

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it is a linear function!

fast moth
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what..

silent lark
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ignore them

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focus

fast moth
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okay will do

silent lark
#

if y = is composed of something that is just in x

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then it is a linear function

fast moth
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so the first one is linear then the second one is nonlinear?

silent lark
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yes!!!!!

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well done

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you could graph it to prove it, but you get the idea

fast moth
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unsure how to do number 3

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is number 2 linear?

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or is there something im missing there

silent lark
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number 2 is not linear

fast moth
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i meant

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number 3

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it was a mistype

silent lark
#

ah

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number 3 is linear, because it has a coefficient of x only

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you could sketch it to visualise

fast moth
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number four is nonlinear right bc it has the thing next to the x?

silent lark
#

yes

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you're right

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we call them exponents, or powers

fast moth
#

then 5 is linear and 6 is nonlinear?

sonic valley
fast moth
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omg i learned something knew

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new

silent lark
#

well done

silent lark
#

to answer your doubt about y = (-1/2)x

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this is what it looks like if you were to skecth it

fast moth
#

okayy

silent lark
#

so it looks like a line, just the mirrored way

fast moth
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im a lil confused on the next question on this random thing im working on

silent lark
#

show me, and I'll try and help

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also, before we move on

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try this website

fast moth
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i mean its simple but its wrote a little bit different

silent lark
#

and play around with it

fast moth
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my teachers talk about it a lot

silent lark
fast moth
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im trying to see if i can understand it first since theres a chance i can

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but here u go

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i think its linear but i cant tell

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its simple but

silent lark
#

apply the same logic

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is there any exponents to x?

sonic valley
fast moth
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um

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is 2 an exponent

silent lark
#

I don't think a middle schooler would know what a degree means

fast moth
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yea i dont..

silent lark
#

but 2 is before x, no?

fast moth
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yea thats why i was confused

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so theres no exponent?

silent lark
#

yep

fast moth
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so it is an linear?

silent lark
#

no exponent

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yep

fast moth
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i just realised

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this is the first assignment im going to turn in to my new teacher

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shes going ot assume im smart..

silent lark
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lmao

fast moth
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😭

silent lark
#

good

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start on good basis!

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and try to improve your maths, trust me it pays off

fast moth
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well actually the first day she saw me she saw me try to walk out of class and the entire class i had my earbuds in while i played flappy bird and i put the paper she gave to me behind me..

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most of the time i only study for tests

silent lark
#

you can watch youtubers such as Khan academy or the organic chemistry teacher to learn maths, they're really good at explaining

fast moth
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okay

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idk what this is..

silent lark
#

think about it

fast moth
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i thought i sent it b4 mb

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i tried to

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but

silent lark
#

is the number

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before or after the x

fast moth
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its not a full number

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OH WAIT

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oml im so dumb

silent lark
#

it doesn't change the logic

fast moth
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i was focused on the confusing nnumber

silent lark
fast moth
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yea

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there

silent lark
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can you give desmos the function

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and you'll see how the function graph behaves

fast moth
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i may randomly leave since im on my laptop secretely

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i stole it out of my moms room

silent lark
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okay

fast moth
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i just heard her cough 😭

silent lark
#

learn as much as you can while you still can

fast moth
silent lark
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go on

fast moth
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oh nvm

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isee it

silent lark
#

"graphing calculator"

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and on the left you should have a panel

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you can just write y = 0.46x there

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it should give you a nice little graph

fast moth
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oh so its linearrrr

silent lark
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yep!

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now

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change the value of 0.46

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to something else

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just for fun

fast moth
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it stayed a line?

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so

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no matter what number it is

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it will be a line?

silent lark
#

yes

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you might have noticed that

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the only thing that changed

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is how steep the line is

fast moth
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yea i did

silent lark
#

yep! but it will

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always be linear

fast moth
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its a lot better to know that

silent lark
#

you're right

fast moth
#

im a lil confused on the 2 line thing is it still linear if theres 2 different lines???

silent lark
#

omg

fast moth
#

huh

#

whats wrong

silent lark
#

I would be tempted to say nonlinear

fast moth
#

thats what i was thinking

#

but at the same time

#

they r two straight lines

silent lark
#

yes, go for nonlinear

fast moth
#

okay

silent lark
#

because

#

it's not a straight line

fast moth
#

oh god its getting harder

silent lark
#

haha

fast moth
#

well idk if this is harder or im just dumb

silent lark
#

nah probably harder

fast moth
#

well

silent lark
#

the teacher is trying to see to what extend you understand the concept

fast moth
#

its not harder harder

#

but

silent lark
#

oh! interesting one

#

so

#

do you know what a square root is?

fast moth
#

not really

silent lark
#

I think you will have to watch videos for that, but for now, keep in mind that taking the square root a number (the symbol you have on the picture in front of), is like raising to the power of 1/2

#

so x is raised to a power

fast moth
#

whats a power again i think you told me but im not sure

#

my memory is so bad

silent lark
#

a power, also known as exponent, is repeated multiplication

let's say I have 2^3, then I'm gonna repeat and multiply 2 three times

#

so 2 x 2 x 2

fast moth
#

oh its thattt

#

exponent is how i remember it

silent lark
#

if I have 2^1000 ( then it's 2 x 2 x 2 x 2 x 2 x..... x 2 until I do it 1000 times)

#

a huge number

fast moth
#

oh my

silent lark
#

is just a fancy symbol for the exponent 1/2

#

so x, has a power

#

hence it is.. nonlinear

fast moth
#

i was kinda thinking it was linear

silent lark
#

it has an exponent though

fast moth
#

yea ik

#

i meant

#

at the smart

#

start

sonic valley
silent lark
#

thanks

sonic valley
#

I hope she can picture it now

silent lark
#

tne coefficient affects the steepness of the function as you saw before, but it does not change whether a function is linear or not

#

you played around before with y = 0.46x if you remember and played with the coefficient

#

it does not change whether the function is linear or not however

fast moth
#

oh yea

#

linearity?

silent lark
#

whether a function is linear or not

fast moth
#

okay

#

question

#

is it dumb to ever go with your gut with math

silent lark
#

yes and no

#

yes as long as it's reasonable guesses but maths is a science of precision and you need to be very clear in your head to do anything

fast moth
#

okay

silent lark
#

that's one good thing about maths

fast moth
#

in the past i kinda just glimmed over the question and picked what felt like what would work

silent lark
#

unlike English, if you understand everything then you'll get 100% on your test

#

in English, it's more subjective

fast moth
#

yea i like it more when the answer is just

#

infront of me..

silent lark
#

lol

#

you should train your brain to think, it will help you a lot in life

fast moth
#

since you can just read the questions ifrst then the story and highlight the important parts

#

then its all there

silent lark
#

enjoy the fact that you're still young

#

to delve deeper

#

and see it as an advantage

fast moth
#

how old are you

#

is that a weird question

silent lark
#

I am 18

#

haha

fast moth
#

oh

#

my brother is 19 when i ask him to help he always says he forgot what that is or tells me the high school way to do it

#

then im all confused bc he just told me like 40 different ways

silent lark
#

time to be smarter than your brother

fast moth
#

😭

#

omg

#

i want to be smarter than him

silent lark
#

yes

#

work hard

#

it pays off

#

maths is particularly rewarding

#

either you understand, or you don't

fast moth
#

yea ig

#

i regret when

#

i started bumming school

#

i blame covid 😭

silent lark
#

it's never too late to catch up

#

until it's too late

#

maybe start watching some youtube videos

fast moth
#

idk how to explain it but im better at learning from reading stuff

#

whenever im listening

#

i zone out

#

then

#

i get bored

#

and i start doing other stuff

silent lark
#

yeah it's fine

fast moth
#

thats why videos never help

#

thats linear right?

silent lark
#

try graphing it

#

on desmos

mystic barn
#

hi

fast moth
#

um

#

it made a weird screen

silent lark
#

haha

#

it looks weird right

fast moth
#

yes

#

very

sonic valley
silent lark
#

I know

#

this one is a particular one!

#

if you're unsure, use the technique we used at the very start, where we plugged in values of x to see the behaviour of y

fast moth
#

hmm

#

the paper technique thing

silent lark
fast moth
#

with the grap

silent lark
#

watch this video

fast moth
#

oh

#

ughghhgh my sister is being annoyed about me playing something

silent lark
#

ignore her

fast moth
#

ill js turn on captions nvm

silent lark
#

stay focused

#

captions are fine too

fast moth
#

she is 17 and shes about as dumb as me

silent lark
#

don't say that

#

you're sleeping less stupid tonight already

#

you're learning

fast moth
#

done

silent lark
#

did you understand?

fast moth
#

yea the 1/x bascially makes it an half rfor the y or whatever and it would be nonlinear

silent lark
#

yep

#

pretty much so

silent lark
#

so no matter what the numerator is, the top of the function, it would always be nonlinear

fast moth
silent lark
#

not bad!

fast moth
#

yea ig

#

i was hoping for an 100 😭

silent lark
#

keep on improving

#

it's okay

#

the best way to learn is by making mistakes

#

the more mistakes you do, if you learn from then, then you'll improve significantly

fast moth
#

i thought i understood the tables so i was attempting them myself but ig not

#

those are the wrong ones btw

silent lark
#

oh

#

x^(2) is the same as the exponent thing by the way

#

that's why you got them wrong

fast moth
#

yea maybe i clicked the wrong one

#

bc ik that

silent lark
#

ah

#

yes, stay focused and double check next time if you can

fast moth
#

okayyy

silent lark
#

not bad! keep on working and do well for that test

#

I'll study some maths myself too now

fast moth
#

okayyy

#

ill try my best

silent lark
#

it was fun teaching you, promise me to try and do your best on that test

#

watch as many youtube videos and graph on Desmos if unsure

fast moth
#

okay ill try to do as much as possible today

silent lark
#

good luck with that

#

have fun

fast moth
#

u toooo

silent lark
#

bye

fast moth
#

ty

#

bye

vocal sleetBOT
#

@fast moth Has your question been resolved?

#
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vocal sleetBOT
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olive herald
#

how do i solve this

vocal sleetBOT
tribal moss
olive herald
#

i did the same thing as this but i put subtraction in denominator instead of addition lol

vocal sleetBOT
#

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empty meteor
vocal sleetBOT
empty meteor
#

how is this 47 and not -58

#

actually so confused

#

what ive done is found the deriv of F(x)

#

then subed the numbes with f'(-1)

#

i got -58

#

how is it 47

#

yes

#

i got -58

#

for the deriv?

#

(x^11)(h')+(h)(10x^10)

#

what

twin meteorBOT
#

help a sad kid | desi

empty meteor
#

wait even then it would still be -55 - 8

#

yeah

#

wait am i doing some math wrong here when im subbing

#

11(-1)^10 equals -11

#

no?

#

wait how

#

wait im so slow

#

i put -1^11 in the graphing calculator to make sure

#

but i forgot graphing calculators are always going to make sure its a negative

#

when its actually a positive

#

it says -1^10 is -1 as well

#

its still showing up as -1

#

oh

#

LOL

#

its been a long time since ive done math

#

okay lets start over

#

new numbers

#

its practice

#

i got 3

#

no wait

#

okay

#

its -12

#

im actually super dumb

#

no i got it right

#

i just messed up my numbers LOL

vocal sleetBOT
#

@empty meteor Has your question been resolved?

#
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rain hollow
#

In a trapezoid the bases big angles bisectors cut each other to the second base the trapezoids hight is 12 and the bisector lenghs are 13 and 15 i need to find all the sides of the trapezoid

vocal sleetBOT
#

@rain hollow Has your question been resolved?

rain hollow
#

.close

vocal sleetBOT
#
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lethal plank
#

The right triangle △ABC has AB = 12, and AC = 16. Let (AD bisector of the angle ∠BAC, D ∈ (BC), DE ⊥ AB, E ∈ (AB), and DF ⊥ AC, F ∈ (AC). a) What is the nature of the quadrilateral AEDF? b) Shown that DE/AC + DF/AB = 1.

lethal plank
#

I need help with point b, i've proved point a.

lapis marten
#

Notice that BED is similar to BAC

#

Same with DFC

#

That allows you to rewrite your problem statement

lethal plank
#

ED is k*AC

lapis marten
#

Yeah, or DE/AC = BD/BC

#

( = k)

lethal plank
#

right, yeah

#

But is the simmilarity coeficient of BED, BAD and DFC the same?

lapis marten
#

No, it isn't, but you don't need that

lethal plank
#

I see.

#

Anyways, DE = k*AD

lapis marten
#

You don't even need the fact that AD is a bissector

lethal plank
#

DF = k*AB

lethal plank
#

I was gonna use the bisector theorem

lapis marten
vocal sleetBOT
#

@lethal plank Has your question been resolved?

lethal plank
#

Got stuck again...

lapis marten
#

So, DF/AB = DC/BC

lapis marten
vocal sleetBOT
#

@lethal plank Has your question been resolved?

vocal sleetBOT
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sullen lotus
#

For each node v on the right side, there should be a directed edge to another node u on the right side if and only if the set corresponding to v is a subset of the set corresponding to u. So in short, what funcitons are subsets and to which? I dont really get if the operators in front of the functions play any role? My thought process would be, for example that in the first one (sqrt of n) given that its O, has everything in its subset thats smaller this would be (if im allowed to multiply with sqrt (n)) everything thats in the right quadrants?

vocal sleetBOT
#

@sullen lotus Has your question been resolved?

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#

@sullen lotus Has your question been resolved?

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vast shale
vocal sleetBOT
vast shale
#

<@&286206848099549185>

formal charm
#

For a) what does it mean for the slope if the tangent is horizontal?

vast shale
formal charm
vast shale
formal charm
#

For example this would be a horizontal tangent

#

So we have slope 0

vast shale
#

0

formal charm
#

So you calculate the derivative

vast shale
#

4/3x^1/3

#

4/3x^-2/3

#

@formal charm

formal charm
#

Yes those added is the derivative

#

Since this is the derivative (slope) we just need to find when f’=0

formal charm
#

f’(x)= 4/3x^1/3+ 4/3x^-2/3 is your calculated derivative

#

So slope 0 means f’(x)=0

#

That’s the meaning of the derivative it’s the slope of the tangent line of your function f

formal charm
#

Yeah

#

And then your point/s is/are (x,f(x))

#

For the b) look what happens for f’(x) when x is close to 0

formal charm
#

Vertical Tangent would intuitively mean slope is some kind of “infinty”

vast shale
#

Oh so there are no vertical lines

#

I'm so idiot smh

#

.close

vocal sleetBOT
#
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formal charm
#

What do you mean

#

There are vertical lines it’s just not a function

#

This function actually has a vertical tangent

vocal sleetBOT
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normal imp
#

What type of data is represented?

Univariate categorical
Bivariate categorical
Univariate numerical
Bivariate numerical

vast shale
vocal sleetBOT
#

@normal imp Has your question been resolved?

normal imp
#

<@&286206848099549185>

soft walrus
normal imp
#

categories

soft walrus
#

and how many modes are there (bumps)?

normal imp
#

bumps?

soft walrus
#

how many peaks are there?

civic lintel
#

i think you’re confusing unimodal with univariate

soft walrus
civic lintel
#

univariate means that the outcome depends on one variable

#

bivariate means it depends on two

#

categorical vs numerical is based on the outcome (is it a number or not?)

#

so does the distribution depend on one or two variables?

#

and is the distribution about a number?

civic lintel
#

yup

normal imp
#

cause we're going based on colour not numbers

civic lintel
#

the result we want is the number of candies from each color

normal imp
#

ooh okay

#

gotcha

#

thank you

civic lintel
#

no

#

np*

normal imp
#

.close

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#
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marble harbor
#

i got cos(2x) to be 24, is that right?

vocal sleetBOT
icy pagoda
#

how did you get 24? remember that the range of cosine is only the closed interval [-1,1].

#

It would be helpful to draw a triangle

marble harbor
#

tan x = sinx/cosx, tanx = -12/5

cos x = 5
cos(2x) = cos^2x-1

5^2-1 = 24

#

idk

icy pagoda
#

you are right that tan = sin/cos

#

but this doesn’t mean that the numerator of the fraction is the sine and the denominator is the cosine

#

-12/5 is just their ratio, not their actual values

marble harbor
#

so how shud i find cos x

icy pagoda
#

do you know how to construct a triangle using the given?

marble harbor
#

hmm lemme

#

try

icy pagoda
#

okay

marble harbor
#

actually

#

ngl

#

i dont think im doing this right

icy pagoda
#

okay do you remember soh cah toa?

marble harbor
#

yes

icy pagoda
#

okay so now what is o and a in this case?

marble harbor
#

12 is o and -5 is a

icy pagoda
#

correct so now let’s draw a triangle with legs 5 and 12

#

and also mark where x is

marble harbor
#

pythag triple

#

the hyp wud be

#

13

#

right

icy pagoda
#

yes

#

okay

#

let’s go back to your identity for cos(2x)

#

what identity do you want to use?

marble harbor
#

prob the cos^2x-1 oen

icy pagoda
#

can you review that one? you’re missing one constant

marble harbor
#

whoops

#

2cos^2x-1

icy pagoda
#

great!

#

what is cosx?

marble harbor
#

a/h

#

5/13

#

25/169

#

*2

icy pagoda
#

yes

marble harbor
#

50/169

#

-1

icy pagoda
#

yes!

marble harbor
#

-119/169

#

is that the answer

icy pagoda
#

exactly!

marble harbor
#

great

#

lol

#

.close

vocal sleetBOT
#
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unique sluice
#

i made an error somewhere in number 2 but im not sure where

dull bear
#

Notice how the bottom limit is larger than the bottom one, so you basically multiply your answer by -1

#

As you have that $\int_9^0 f(x) \dd x = -\int_0^9 f(x) \dd x$, with the latter integral being what you thought it was

twin meteorBOT
#

@dull bear

unique sluice
#

i got an answer of (-6.63) so then i multiplied by -1 and got (6.63) and it was wrong

#

am i missing something?

dull bear
#

Oh, maybe "nearest thousandth"

#

@unique sluice

unique sluice
#

humm

#

becasue for pi i just used 3.14,i suppose i could try using full pi.

anything else look off other than that

dull bear
#

As in you rounded to the hundredth rather than thousandth, no?

#

But otherwise looks fine to me in method! SCgoodjob2

unique sluice
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@unique sluice Has your question been resolved?

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rough zenith
vocal sleetBOT
rough zenith
#

Does anhybody how to add solutions on aops

#

i want to add my own solution

mental falcon
#

maybe ask on the site's own forums

vocal sleetBOT
#

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eternal marsh
#

sqrt (u^2/x)100

vocal sleetBOT
vocal sleetBOT
#

@eternal marsh Has your question been resolved?

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vast shale
#

i need help finding out what i did wrong here, i dont know which parts are oficially a b and c

vast shale
#

you are the one who designates which is a b and c

#

i dont know what i did wrong then

#

the answer is 64

#

and i got 2.144

#

did i use the wrong formula

#

yep i got 64 too hang on

edgy gulch
#

your c side should be the side that is opposite facing to the angle

vast shale
#

yea

#

that's the important side

#

i did it wrong again

#

i dont know what im doing wrong

#

Is your calculator in degree or radian

#

um idk

#

scientific calculator victor 940

#

should i be using the other formula

#

or isnt that to find the side length

edgy gulch
#

and type it again

vast shale
#

give me a sec

#

omg

#

i dont know what i doing

#

im

vast shale
#

yeah its the wrong answer

#

Can u use the a^2 = b^2 + c^2 -2bccosA formula?

#

Not that yours is wrong but I've never used the formula in fraction form b4

#

So its confusing lmao

edgy gulch
#

i got 64?

vast shale
#

ya me too

#

Great

#

idk what else i was doing wtf

#

oh i

#

i didnt do the inverse function

#

Lmao