help-17

[paper depot]

are you absolutely definitely 100% sure about this

[strong olive]

100%

[paper depot]

ok then where are you going to get three solutions to this quadratic equation?

[strong olive]

oh not sure

its x^3

[paper depot]

thought so...

[strong olive]

-5x -1

[paper depot]

so your equation is x^3 - 5x - 1 = 0.

ok

[strong olive]

nice you are good

[paper depot]

do you know vieta's formulas

[strong olive]

no but interested

[paper depot]

sum and product of roots?

no?

not even for quadratics?

[strong olive]

=-b/a?

[paper depot]

partial recall...

[strong olive]

for quadratics = -b/a

right?

[paper depot]

you're still recalling it only partially

and with conflicting notation vs. our problem

https://en.wikipedia.org/wiki/Vieta's_formulas

anyway give this a read

and/or look up "vieta's formulas" elsewhere

cause you forgor

[strong olive]

we have studied math in french but i'll try

we dont even know him

i 've taked a look

and i guess here a+b+c=0

[paper depot]

a+b+c = 0, ab+bc+ca = -5, abc = 1.

in principle, your problem can be bashed with these alone.

[strong olive]

i have find those too

so how could i get advantage of them

[barren falcon]

reduce E to a fraction

[paper depot]

$\frac{1+a}{1-a} = 1 + \frac{2a}{1-a}$, so $E = 3 + 2 \paren{\frac{a}{1-a} + \frac{b}{1-b} + \frac{c}{1-c}}$

[twin meteor]

Ann

[paper depot]

maybe combine a/(1-a) + b/(1-b) + c/(1-c) into one fraction

[strong olive]

ok i will see

ive got 13

which is not one of the correct answers

one of them are right : -1 , -7, 0 ,3

@paper depot

[paper depot]

show your work?

$10 says you fucked up your algebra somewhere.

[strong olive]

i dont have camera

in pc

[paper depot]

if you cannot send me your work, i cannot tell you where you screwed up.

[strong olive]

i want to see how you solve it

@paper depot did you try it or should i close?

thank you for your help

[flat whale]

People aren't going to do problems for you

[paper depot]

no, i did not do it myself

[strong olive]

thank you very much for the vieta 's formulas

.close

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[rough pine]

why does the top mean that it never equals 0

[empty frigate]

well if it is equal to 0, then $n = -\frac1{4\pi^2}(\pi\pm2\sqrt{(-1)^n})$

[twin meteor]

bee [it/its]

[rough pine]

yh

[empty frigate]

and given all of the $\pi$s there that's not going to be an integer

[twin meteor]

bee [it/its]

[rough pine]

oh yh

true

cuz we defined n to be an integer

makes sense

thanks

.close

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[vast shale]

yo can someone explain this please it's kinda complex

[worthy citrus]

what exactly dont you understand

[vast shale]

the whole upper bounds of a,b,c thing

i understood this at first then i lost it lol

[worthy citrus]

well whats the definition of an upper bound of a set

[vast shale]

read it 10 times its not coming

[worthy citrus]

just read the definition of upper bound, you dont need the rest for this question

last sentence in first paragraph of second image

[vast shale]

yeah but like how tf u implement that to find out that e,f,j,h are all upper bounds

[worthy citrus]

well is e bigger than or equal to all of a,b,c?

[vast shale]

yes

[worthy citrus]

then its an upper bound

do the same for all nodes of the hasse diagram

[vast shale]

ok lemme solve this

it's g and b

lowest lower bound was a but we're looking for the highest so b

and g because were looking for the lowest upper bound

ok got it now

@worthy citrus thx

@worthy citrus isn't the lower bound of B and C, a?

[worthy citrus]

uh yea

[vast shale]

no it isn't

why

[worthy citrus]

can you show the full question

[worthy citrus]

you asked what the lower bound was

the middle paragraph is making an argument about the least upper bound

[vast shale]

why is there no least upper bound

its not like they're unique

[worthy citrus]

what do you think the least upper bound would be?

[vast shale]

d or e

there can be more than one right

[worthy citrus]

but d is not less than e

and e is not less than d

so neither can be the least upper bound

least upper bounds and greatest lower bounds are unique

[vast shale]

@worthy citrus can you draw the hasse diagram of ({1, 2, 3, 4, 5}, |)

[worthy citrus]

you should try and do it yourself

[vast shale]

im tryin rn

[worthy citrus]

is the partial order meant to be "divides"?

[vast shale]

yh

[worthy citrus]

that looks fine to me

[vast shale]

ight im moving onto the last years exam questions ill report back

[vocal sleet]

@vast shale Has your question been resolved?

[vocal sleet]

@vast shale Has your question been resolved?

[vocal sleet]

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[dusk orchid]

What percentage is 50 of 174?

[dark rune]

,w What percentage is 50 of 174?

[dusk orchid]

Thx

[twin meteor]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by someone1010

[dusk orchid]

w, What percentage is 14 of 148?

[civic oracle]

just do (14 divided by 148) x 100

[dusk orchid]

It’s that simple?

[civic oracle]

yes

[dusk orchid]

Huh

Nice

It’s getting me a weird number

[civic oracle]

this?

[dusk orchid]

It’s not loading for me but

95.59459459

More or less

[civic oracle]

you probably multiplied by 1000 instead of 100

[dusk orchid]

No that was just the dividing part of it

I don’t get how to do it ig

[civic oracle]

if you want to know what percent x is of y, you just do (x/y) times 100

that's it

[dusk orchid]

Oh wait

Hold on

My slow brain is starting to get this

148/14 x 100/1

[civic oracle]

no

14 divided by 148

then you get that

and you multiply it by 100

that's your percentage

[dusk orchid]

But 14/148

[civic oracle]

yes

[dusk orchid]

Is 94.59459459

Etc

[civic oracle]

no it's not

[dusk orchid]

Sorry my calculator is kinda broken

It’s like 10 years old

[civic oracle]

you have to get a new calculator if it's telling you that 14/148 is 94 lol

[dusk orchid]

So it would be 9.4%?

[civic oracle]

yes

sry 9.5

or not

it depends on how much it asks you to round

[vocal sleet]

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[deft vault]

Need help understanding this

[deft vault]

I like loosely understand it but I’m not getting the right answers

[vocal sleet]

@deft vault Has your question been resolved?

[sweet flower]

!status

[vocal sleet]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[deft vault]

2

[sweet flower]

So what have you tried?

[deft vault]

I know that m = 3.28 ft

And that the S thing is 10.8 Y

[sweet flower]

$\delta = 10.8\gamma$

[twin meteor]

Pixelius

[deft vault]

Mhmm

[sweet flower]

So if you plug those values in what do you get?

[deft vault]

35.424

[sweet flower]

How?

[deft vault]

3.28 x 10.8

[sweet flower]

Can you plug them directly into the equation given?

[deft vault]

Um

I don’t know how

[sweet flower]

$130 \frac{m}{\delta} = ? \frac{ft}{\gamma}$

[twin meteor]

Pixelius

[sweet flower]

We know what m and delta are, so just replace those values with what we said above

[deft vault]

Okay

So then 130
3.28
———
10.8

[sweet flower]

130 * (3.28 ft / 10.8 g) = ? Ft/g

[deft vault]

What would ft/g be then

[sweet flower]

ft/g is the units of the answer

[deft vault]

Would they also be 3.28 and 10.8

[sweet flower]

If you were trying to convert 130m to ft how would you do that?

[deft vault]

Um

[sweet flower]

Knowing that the conversion rate is 1m = 3.28 ft

[deft vault]

426.4

[vocal sleet]

@deft vault Has your question been resolved?

[sweet flower]

Yeah exactly

And if we want to convert 1 d into g we do the same thing, and divide out the new conversion rate

$$130 \frac{m}{\delta} = 130\frac{m=3.28 ft}{\delta=10.8 \gamma} = 130 \frac{3.28}{10.8} \frac{ft}{\gamma} = 130 * .3037 \frac{ft}{\gamma} = 39.48 \frac{ft}{\gamma}$$

[twin meteor]

Pixelius

[deft vault]

Aha

That is the correct answer that it had wanted

this is good but I should try to solve another question as practice

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[twilit rampart]

Is this right ?

[vocal sleet]

@twilit rampart Has your question been resolved?

[vocal sleet]

@twilit rampart Has your question been resolved?

[twilit rampart]

<@&286206848099549185>

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[dusky wasp]

Is this the correct equation?

<@&286206848099549185>

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[tribal moss]

all ok

[desert hornet]

looks good

[tribal moss]

ofc

[desert hornet]

just to make sure, the function is $\ln(\sqrt{x(x+1})$?

[twin meteor]

kheerii

[desert hornet]

what does your book say?

[desert hornet]

and are you 100% sure that this is the exact function given in the question?

then you're correct, there shouldn't be a square root there

[tribal moss]

the book answer suggests lack of logarithm

[desert hornet]

,w derivative of log(sqrt(x^2+x))

[twin meteor]

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Upgrade to WolframAlpha Pro!

Requested by shikhargupta1207

[tribal moss]

in book they show only some part

[desert hornet]

even if you don't use log properties to bring that 1/2 down, it should still give you the same answer

[tribal moss]

$\left( \sqrt{x^{2}+x} \right)'=\frac{2x+1}{2\sqrt{x^{2}+x}}$

[twin meteor]

Joanna Angel

[desert hornet]

so you were not telling us the entire question

!xy

[vocal sleet]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[desert hornet]

after taking the ln of both sides (and differentiating) what do you get?

yes

no

wait

$y=\sqrt{x^2+x}$

[twin meteor]

kheerii

[desert hornet]

$\log y=\frac1{2}\log(x^2+x)$

[twin meteor]

kheerii

[desert hornet]

now differentiate both sides and tell me what you get

[tribal moss]

the logarithmic mehtod takes a way much more time, then classical method

[desert hornet]

yeah, sounds like a weird exercise

yes

wait no

why is there a square root now

in the denominator on the right hand side

so we have $\frac1{y}\frac{dy}{dx}=\frac{2x+1}{2(x^2+x)}$

[twin meteor]

kheerii

[desert hornet]

but what we want, is just the derivative of y (or dy/dx)

yes

and what is y?

correct

yes

yeah, just simplify the result

you should get the same thing that's given to you

yes

yes, logarithmic differentiation is only really necessary for problems like these

or for problems of the form $y=f(x)^{g(x)}$

[twin meteor]

kheerii

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✅

[desert hornet]

you will absolutely have to use the chain rule

and that derivative is wrong

it multiplies that by 2x after

due to the chain rule

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[undone trail]

The average speed of a train in the onward journey is 25% more than that of the retum journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and fro journey is 16 h covering a distance of 800 km. The speed of the train in the onward journey, is

I don't need an answer please explain

[vocal sleet]

@undone trail Has your question been resolved?

[undone trail]

No sir

<@&286206848099549185>

[inland cargo]

How much time is spent traveling

@undone trail

[undone trail]

Total 16 hr

[inland cargo]

No

Traveling

Like for how long is the train moving

[undone trail]

Yes 16 hr

[inland cargo]

No it says it halts for 1 hour

so 16 trip total - 1 hour resting

is what

[undone trail]

Total 17 hr without rest is 16

[inland cargo]

Okay thats not what you sent in the chat but if you traveled for 16h

Do you know if you are assuming the distance to and back are equal?

If the only information you are given is what you sent then you have to

So you have 400km there and 400km back

[undone trail]

Honestly Yes that's not even in the question when I Googled the answer they all added 1hr and made 17 hr

[inland cargo]

Can you send the actual question

You wouldnt add an hour in the question you sent

[undone trail]

Wait I send picture

[inland cargo]

alr

[undone trail]

That's sure

[inland cargo]

Yes please send question though so I can help because what you typed is not the question that you googled the answer for

[undone trail]

Fr I am confused same as you

[inland cargo]

Where did you get the answer you googled from?

[undone trail]

Yes

But I need explanation

[inland cargo]

No I mean where did you get it

[undone trail]

From google

[inland cargo]

What website

Because it could be wrong

[undone trail]

Lol google question you find more Websites with answer

I seen 10+ websites

With same answer

I didn't understand a single thing

[inland cargo]

Ill solve it give me a sec

[undone trail]

Ok

Np

Take your sweet time

[inland cargo]

Answer is 56.25 right?

@undone trail

In the websites that you saw I mean

[undone trail]

Yes

[inland cargo]

Alright

So

[undone trail]

But I don't need the answer I need clear explanation

[inland cargo]

I will call distance to d1 and distance from d2, time spent onward t1 and time spent returning t2 alright?

Velocity to v1 and velocity from v2

[undone trail]

Ok

[inland cargo]

What is relationship between v1 and v2

[undone trail]

I don't know

[inland cargo]

Speed and velocity will be same thing for this question

if the speed on the onward journey is 25% more than that of the return journey

[undone trail]

Yes

[inland cargo]

if you were to have an equation k(v1)=v2

what would k be?

[undone trail]

I am an arts student I don't know much please explain go on

[inland cargo]

25% more means you take 25% of the value and add it to the value right?

[undone trail]

Yes

[inland cargo]

so 25% more of 10 is equal to 10 + (0.25)10

or 12

So you can generalize it

[undone trail]

Wait 1min

[inland cargo]

to 25% more of x is equal to x +(0.25)x

?

[undone trail]

Where 10 come from

[inland cargo]

Just a random example

but 25% more of x is equal to x+(0.25)x right?

x+0.25x = 1.25x

[undone trail]

Why are we making 25% to 0.25%?

[inland cargo]

how would you find 25% of something?

do you know or no

[undone trail]

No

[inland cargo]

do you know what 25% of 100 is?

[undone trail]

25

[inland cargo]

Yes

How did you get that though

Is it just memorized or did you go through a process

[undone trail]

Common knowledge?

[inland cargo]

ok

Does it make sense to you that 25% of something is equal to 1/4 of something?

[undone trail]

I didn't do any process

Yes it's 1/4

[inland cargo]

Okay

1/4 = 0.25

[undone trail]

Ok

[inland cargo]

so back to the thing

25% more of x is equal to x + 0.25x

right?

[undone trail]

One more how x become 1?

[inland cargo]

because its more

[undone trail]

Yes

[inland cargo]

Alright

That makes sense to you?

[undone trail]

No

[inland cargo]

Okay

25% more means you take 25% then add it to the original value

what is 25% more than 100?

[undone trail]

I have no idea

Sorry

125%

Right

[inland cargo]

Yes

so whats 125% of 100?

[undone trail]

-25?

[inland cargo]

you can break it up into 125% of 100 is equal to 100% of 100 + 25% of 100

[undone trail]

Can you simplify more sorry lol

[inland cargo]

When you said 125% you took 100% and addded 25% right?

or did you just guess

[undone trail]

Yes

Added it

[inland cargo]

okay

so 125% of something is equal to 100% + 25% of it right?

so what is 100% of 100

[undone trail]

100

[inland cargo]

• 25% of 100 is what?

[undone trail]

125

[inland cargo]

Yeah

Do you see what we did?

[undone trail]

Yes

[inland cargo]

When doing 25%

more

we took 100% of the number + 25% of the number

right?

[undone trail]

Yes

What is 100 , 125%?

[inland cargo]

What do you mean

what is 125% of 100?

[undone trail]

So what's 125% of 100?

[inland cargo]

125

125% of 100 is equal to (100% of 100) + (25% of 100)

100% of 100 is 100
25% of 100 is 25

100+25 = 125

[undone trail]

So 425% of 200 is - 425

Right?

[inland cargo]

uhhh

did you mean 425% of 100 is 425?

where did the negative sign come from?

[undone trail]

What will be 425% of 200 is?

[inland cargo]

Well

[undone trail]

Nothing just clarifying something

[inland cargo]

If you were to break it up like how I broke it up

into 100%s and then the remainder

how many 100%s would there be

and what would the remaining % be

[undone trail]

What is the answer bro?

[inland cargo]

Well you should be the one answering I already know

the answer should be 850

If you were to break it up like how I broke it up

like 425% of something

[undone trail]

Can you explain this one

[undone trail]

.

[inland cargo]

it is 4*(100%) of the thing

• 25% of the thing

425 = 4(100) + 25

right?

[undone trail]

Ok

[inland cargo]

so what is 100% of 200

[undone trail]

Before that your showing 425 how it becomes 850?

[inland cargo]

Yes

[undone trail]

200

[inland cargo]

Okay

what is 25% of 200

[undone trail]

50

[inland cargo]

Good

so we have 4(100% of 200) + (25% of 200)

we said 100% of 200 is 200 and 25% of 200 is 50

so we have 4(200) + (50)

which is 800 + 50

or 850

right?

[undone trail]

Few min

Ok understand

[inland cargo]

Yes

So

Going back to the question

125% of x is equal to 100% of x + 25% of x right?

[undone trail]

Yes

[inland cargo]

100% of x = x right?

[undone trail]

Yes

[inland cargo]

25% of x is 1/4 of x right?

or 0.25 of x

[undone trail]

Yes

Both or same

[inland cargo]

Same thing

1/4 = 0.25

125% of x is equal to 100% of x + 25% of x
100% of x = x, 25% of x = 0.25x

[undone trail]

Hmm

Yes

[inland cargo]

so 125% of x is equal to x+0.25x

[undone trail]

Yes

[inland cargo]

x+0.25x simplified is what?

[undone trail]

125%

[inland cargo]

in terms of x what is it?

not looking at % anymore

[undone trail]

100%

[inland cargo]

just x+0.25x

not a %

just x+0.25x

[undone trail]

1

Or 100

[inland cargo]

No

[undone trail]

Then?

[inland cargo]

Ill rewrite it like this

1x+0.25x

is what?

[undone trail]

1.25x

I am right?

[inland cargo]

Yes

Good

Remember x = 1x right?

so x+0.25x is equal to 1.25x

[undone trail]

Ok sir

[inland cargo]

Alright

Can I ask if English is your first language? Because if it is not it might be more worthwhile to wait for someone who speaks your first language to help you

[undone trail]

No problem you can continue

I will never find my first language people here and I am sorry for my english

[inland cargo]

Your English is fine its just that I think it is probably much harder on you to learn math and my English explanations as well

But anyways

so the speed there is 25% more than the speed back right?

[undone trail]

No problem sir thanks for understanding but I have to go through

[undone trail]

Yes

[inland cargo]

Okay

so if we call the speed there v1 and the speed back v2

[undone trail]

Ok

[inland cargo]

what would be the relationship between v1 and v2?

[undone trail]

Yes

[inland cargo]

Sorry read it wrong

[undone trail]

?

[inland cargo]

v1 is 25% more than v2

[undone trail]

Ok

[undone trail]

Mm

[inland cargo]

so v1=1.25v2

[undone trail]

Yes

[inland cargo]

Alright so because they both travel the same distance

[undone trail]

Yes 400km

[inland cargo]

their time is related as well

[undone trail]

Yes 8hr

[inland cargo]

if someone drives 25% faster they will get there 25% faster right?

[inland cargo]

No

[undone trail]

Oops sorry they drive 25% fast right

[undone trail]

Yes

[inland cargo]

25% faster yes

[undone trail]

Yes sir

[inland cargo]

Okay

So for some random number x

if someone drives x% faster how much faster will they get there as a %?

[undone trail]

Ok

[undone trail]

Should I calculate?

[inland cargo]

No it is not a calculation

Ill rephrase

Let me think how to put it

[undone trail]

Ok sir

[inland cargo]

I might have phrased it badly

So

are you comfortable with units?

I can try and explain like that

[undone trail]

Ok

No problem

[inland cargo]

So what are the units of velocity?

[undone trail]

S=D/T

[inland cargo]

Yes

So we want to convert the two speeds into units of time

[undone trail]

Ok

[inland cargo]

v1 and t1 will represent the speed and time spent going there, v2 and t2 will represent the time spent coming back

v1=1.25v2 is what we said earlier

and v1=(D/T) is what you said

they both travel the same distance of 400M

so v1=(400/t1)

[undone trail]

Yes

[inland cargo]

v2=(400/t2)

so now we substitute them both back into the equation v1=1.25v2

[undone trail]

Yes

[inland cargo]

(400/t1) =(1.25)(400/t2)

Divide both sides by 400

to get

(1/t1)=(1.25)(1/t2)

[undone trail]

Yes right

[inland cargo]

Multiply both sides by (t1) and (t2)

to get

t2=1.25t1

Makes sense or nah?

[undone trail]

Yes perfectly i understand now

[inland cargo]

Nice

So total time it says is 16 right?

[undone trail]

Yes

[inland cargo]

total time = (time spent traveling to) + (time spent traveling from)

total time also = 16

so

16 = (time spent traveling to) + (time spent traveling from)

16 = (t1) + (t2)

[undone trail]

Yes

[inland cargo]

so we have
t2=1.25t1
16 = t1 + t2

Can you solve that for t1 and t2 for me please?

Tell me what you et

get

[undone trail]

2.25 ?

[inland cargo]

alright let me rephrase it a little bit

I think my notation might be confusing

instead of t1 i write x, and instead of t2 i write y okay?

[undone trail]

Ok no problem sir

[inland cargo]

so we have
y = 1.25x
16 = x + y

can you solve that?

what is
x=

[undone trail]

1

[inland cargo]

and what is
y=

[undone trail]

1.25

Right?

[inland cargo]

No

so y = 1.25x right?

so 16 = x + y and y = 1.25x

[undone trail]

Yes

[inland cargo]

so 16 = x + (1.25)x

16 = 2.25x

Divide both sides by 2.25

[undone trail]

..

[inland cargo]

No

16 = 2.25x does not mean x = 2.25

you have to divide both sides by 2.25

(16/2.25) = x

[undone trail]

7.11

Wrong sir?

[inland cargo]

No

is right

But to be more accurate

Because it has infinite .11111 right?

its not 7.11 its 7.1111111...

[undone trail]

Yes

[inland cargo]

so we just say x=(16/2.25)

[undone trail]

Ok

[inland cargo]

going back to S=(D/T) for your speed equation right?

[undone trail]

Yes (my😅)

[inland cargo]

S = (400)/(16/2.25)

Calculate that

[undone trail]

I need a few minutes

Should I calculate like this

[inland cargo]

Sure

[undone trail]

Should I divide it with 7.11 or 7.1111111 infinite

[inland cargo]

when you have a fraction divided by a fraction

lets say (a)/(b/c)

it is equation to

(ac)/b

so

calculate

400(2.25)/16

[undone trail]

Thanks for the tip

56.25

[inland cargo]

yes

that is the answer

56.25

[undone trail]

Thank you so much ❤ sir

[inland cargo]

No problem

Good luck

[undone trail]

If you don't mind you can write it all at once

So I can remember this method

Sorry for troubling you and thanks once again

[proven knot]

400/(16/2.25)

= 400 * (2.25/16)

= [400*2.25]/16

[inland cargo]

I think he meant the whole thing

[undone trail]

Yes

[proven knot]

Oh sorry xD all you

[undone trail]

No problem ty for trying to help

[inland cargo]

So you find an equation relating the two speeds, k(a) = b where a is the speed there and b is the speed back

you find k by doing the % faster thing we talked about

for instance if it was 50% faster, k = 1.5

if it was 200% faster, k = 2

[undone trail]

Yes sir

[inland cargo]

250% faster, k = 2.5

267% faster, k = 2.67

and so on

so you have

k(a) = b where a is the speed there and b is the speed back

assuming the distance there and back are equal (This is not neccesarily true, you have to check in the context of the problem)

using S = (D/T)

I will call the time spent going there x and the time spent coming back y

S = (D/T)

a = (D/x), b = (D/y)

subtituting those back into the equation

k(D/x) = (D/y)

then multiply both sides by x and y, divide both sides by D giving you

ky = x

y + x = the total time which I will call T

y + x = T
ky = x

substitute ky = x into y + x = T

y + ky = T

then

[undone trail]

Lol I feel guilty 😔 to tell again write all this

[inland cargo]

Its fine

factor out y

to get

y(1+k) = T

divide by (1+k)

y = T/(1+k)

substitute this back in y + x = T

T/(1+k) + x = T

x = T-(T/1+k)

x or y will be your answer depending on what they ask for (speed going there or speed coming back)

[undone trail]

Thank you for your sweet time God bless you bro

[inland cargo]

Yeah good luck with your stuff God bless you too

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[wary dirge]

Can anyone help me write the solving code of this integral in Matlab/Octave? im not really sure how to solve it

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@wary dirge Has your question been resolved?

[gritty sage]

Are you sure that's not a typo?

x^2 will be positive, as will the numerator.

You can convert the numerator into |cos(2n + 1)| |x|.

Then, |cos(2n + 1)| is a constant with respect to the integral, so you can move it in front of the integral.

The integral will evaluate to a constant.

And then the limit of |cos(2n + 1)| as n goes to infinity doesn't exist.

As far as Matlab, see https://www.mathworks.com/help/symbolic/limits.html, infinity can be written as Inf, https://www.mathworks.com/help/symbolic/sym.int.html, and https://www.mathworks.com/help/matlab/ref/abs.html.

[wary dirge]

alright, ill look into it. thank you!

[gritty sage]

No problem.

[wary dirge]

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[carmine badge]

Can someone please help me with this question I’ve been stuck on it for the past two hours

[sweet birch]

<@&268886789983436800> troll

[lost yarrow]

Don't abuse help channels

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[vast night]

I need help deriving this.

[vast night]

This is all ive gotten to so far, i dont know how to move forward.

[paper depot]

do you know how to differentiate x^(1/2)?

[vast night]

1/x ?

[paper depot]

incorrect

do you know the power rule?

[vast night]

I think so

[paper depot]

can you state it in full

[vast night]

I have a formula sheet with power rules

[paper depot]

"power rule" refers to one rule

in the context of differentiation specifically

[vast night]

Then i do not know in the context of differentiation

[paper depot]

what is the derivative of x^n?

[vast night]

n*x^n-1

[paper depot]

n * x^(n-1), but yes.

apply this to x^(1/2), so n = 1/2.

[vast night]

Oh ok. so 1/2*x^(1/2-1) = 1/2x^(-1/2)

?

[paper depot]

yes

or $\frac{1}{2\sqrt{x}}$.

[twin meteor]

Ann

[paper depot]

now take the derivative of $2\sqrt{x-2}$ with this and the chain rule.

[twin meteor]

Ann

[vast night]

I do what i just did with x with the other constants ?

[paper depot]

i don't 100% like that wording but yes ig...

you should know the chain rule tho.

[vast night]

My first language is not english sorry.

I dont think my teacher has gone through the chain rule

[paper depot]

then what is?

[vast night]

Swedish

[paper depot]

ok nevermind

[vast night]

is this what your referring to?

[regal slate]

yes, that is the chain rule

[vast night]

Never seen before

[regal slate]

you can’t differentiate that expression without the chain rule

[outer warren]

or in other notation:
$$\dv{y}{x} = \dv{y}{u} \dv{u}{x}$$

[twin meteor]

ℝαμΩℕωⅤ

[vast night]

Not ideal.

[regal slate]

i’d recommend learning the basics of differentiation first, you won’t get far without learning the chain rule

[vast night]

Okay. Any recommended videos or pages to look at?

[regal slate]

khan academy

[vast night]

Okay thanks.

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[fast quarry]

Ive done i and ii, i dont know how to approach iii as I dont know how to represent the I vector in sumamtion form

A = a_ij

[marsh fog]

what year are you in

[fast quarry]

2nd year

[marsh fog]

oh uni

[fast quarry]

university

[marsh fog]

australia?

[fast quarry]

this is just a prerequisite sheet for linear algebra, which im starting right now

uk

how do i represent the identity vector in summation notation

[worthy citrus]

You can use a kronecker delta: δ_ij = 1 if i=j and 0 if i != j

[fast quarry]

i havent heard about that before

strange let me check the notes

maybe its further ahead

that isnt mentioned anywhere in our lecture notes, is there another way of doing this question?

maybe with linear maps actually they gave that option in the question

but id be unsure how to approach it with linear maps

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@fast quarry Has your question been resolved?

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[mild carbon]

someone please help me with c

I'm not sure where to get started

[scenic ravine]

try simplifying the numerator to find out what values x can't assume

you effectively have to find it's domain

[mild carbon]

come again?

[civic oracle]

Denominator is not equal to 0

There are two values of x which make x^2-1 equal 0

[sweet flower]

same process as a and b, factor the top and bottom and divide what you can

[mild carbon]

oh wait now i get it

im a little stupid my bad

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[edgy orchid]

the equation 4(x-2) = 200 is a true equation for a particular value of x. explain why 2(x-2)=100 is also true for the same value of x

[vocal sleet]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[edgy orchid]

1

[tidal dock]

okay, well first of all

do you just intuitively see why that is true?

[tranquil trellis]

4(x-2) = 200
2(x-2)=100

What do you notice changes from the 1st equation to the 2nd

[edgy orchid]

since the first number is smaller in the 2nd equation it makes the number at the end smaller aswell

[tidal dock]

pretty much lol

but

by how much it is smaller on the left side and by how much it is smaller on the right side?

[edgy orchid]

2 and 100

[tidal dock]

what about not subtraction-wise but division-wise?

[edgy orchid]

uhhhh

i’m lost what am i dividing

[tidal dock]

well

both sides got divided by 2

this is what happened

200/2 = 100

4/2 = 2

[edgy orchid]

ohhhhh

so i’m just a dumbass

[atomic glen]

Nah friend, silly mistakes happen to everyone, thats how we learn

[vast shale]

@edgy orchid if you want to find out if it's really true, then you can just solve the given

4(x-2)=200
4x-8=200
4x=200+8
4x/4=208/4
x=52

2(x-2)=100
2x-4=100
2x=100+4
2x/2=104/2
x=52

~True ✓

[edgy orchid]

oh shoot that does work

thanks you guys

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[jade stone]

In the set of real numbers, the relation is defined this way:

[jade stone]

I have to define the cardinality of the set of each of these classes:

afaik those are equivalence relations on S

so it's all y's that are in relation with 2

or all (-y)'s

I think it translates to 2-y?

Help

using this definition

I think they are infinitely many?

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@jade stone Has your question been resolved?

[jade stone]

<@&286206848099549185>

[civic field]

Yes

Do u need help?

@vocal sleet

.close

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[jade stone]

yes. please

[civic field]

What do u need help with

[jade stone]

with the problem above

I'm trying to figure out the quotient set for the relation S

[civic field]

It's infinte

[jade stone]

alr

ig

[jade stone]

I also have to find the index for S

and idk how to do that

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[dusky trellis]

I have a question. If we say k is a nature number which is not even. Is that meaning k is odd?

[loud walrus]

That is what it looks like

[daring bolt]

yeah

[hot lark]

Well if you define even as divisible by two and odd as not -divisible by two you cant have both at the same times

[dusky trellis]

Ok, thanks guys

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[strong olive]

A*B = C

[strong olive]

And the other aren't important

[dusky trellis]

1 * a + 7 * b + 3 * c + 5 *d = 0
And other lines are same as well

This is given by the first line

[strong olive]

That's right

I think that find a,b,c,d will not be the idea

It will take time and the exam is only 1hour and 25 questions

[dusky trellis]

Well, that will not take 4m, 2m is enough.

[strong olive]

To find a b c d?
But the calculator is not allowed

And how can I even get them

@dusky trellis

. close

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[waxen flame]

Could I get some help with numbers: 9, 11, 17, 21, 23 and 25

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@waxen flame Has your question been resolved?

[waxen flame]

?

[vocal sleet]

@waxen flame Has your question been resolved?

[languid berry]

for 17, 21, 23, 25 all of them have some pattern that you have to find

it's hard to help without straight up telling you the answer

17 21 and 25 all involve exponents

[waxen flame]

i believe i got

17: {2^x : x ∈ ℕ}

21: {x ∈ ℕ : x^2}

am i correct?

[languid berry]

notice that natural numbers do not include 0 and 0 is in the set

[waxen flame]

ah gotcha so its Z

or integers

[languid berry]

it would be $Z^+$

[twin meteor]

accialto

[languid berry]

alternatively you could use N and (x-1)^2

but Z+ is more standard

[waxen flame]

this my second week of the class so far we just say like N, Z, R

[languid berry]

alright ignore the Z+

just do N and (x-1)^2

that way, every number will be -1 so it begins 0, 1, 2, ...

[waxen flame]

ok thanks thats all!

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[modest valley]

Can someone help me answer a question about pre calculus

[modest valley]

<@&286206848099549185>

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[ashen shoal]

Other than plugging in x and y values, is there any way to solve this? Obviously we'll get the right answer if we just input the x values (the answer will be A). But if it wasn't multiple choice, how can you solve it? Like, does just knowing the two coordinates allow us to write an equation that satisfies it?

[lean beacon]

You can solve it by using slope formula.

[late ingot]

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

[twin meteor]

b0ngl0rd

[lean beacon]

Yes

thanks

[ashen shoal]

Oh, okay! It's been so long that I forgot it existed. Thanks a bunch

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[verbal wraith]

do these two look correct?

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[rancid otter]

I'm supposed to look at images of three graphs and order them based on:

• Original function
• Derivative
• Second Derivative

[rancid otter]

i already found that the derivative of III is II

nvm im stupid

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[oblique rune]

curently making a probability game.

How would i go about calculating the expected value of the following game?

[oblique rune]

bet $2
roll 2 dice and draw 1 card

card value: 1-13
dice sum value: 2-12

if card value is equal to sum of dice win $6

if card value is less than sum of dice win $3

if card value is more than sum of dice win $0

[lusty rapids]

you can start by calculating the probability of each possible sum of the dice and the probability of drawing a card with those values.

[lusty rapids]

then combine those probabilities with these possible outcomes

then multiply the win amount by the probability of each outcome and sum them up.. and then u can subtract that amount with the original $2

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[verbal folio]

you want to design a 12-hour clepsydra, with height 4ft, radius of the top 1ft. it has a hole in the bottom of radius 1 inch. assuming that the clepsydra is created by revolving a function about the y-axis, find the function that makes the given clepsydra. (clepsydra is a water clock that drains, starts full with water)

[verbal folio]

,tex -A\sqrt{2gh}=\pi f(h)^2\frac{dy}{dt}

[twin meteor]

dolphn
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[verbal folio]

i've gotten to this relationship and know that i can plug in values to solve for f(h), but it doesn't obey the restriction that the top of the clepsydra needs to have a radius of 1 foot

is it some sort of initial value thing

here's where the relationships come from

i switched y with h cause it makes more sense

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[flat whale]

what are you solving for

what's f(h)?

[verbal folio]

the function which when revolved creates the water clock

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[lavish river]

by derive, do you mean find the derivative of?

e^(0,5x) * e^x = e ^ (1.5x)

combining powers

then use, [e^(f(x))]' = f'(x)e^(f(x))

yep.

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[lavish river]

no problem.

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[atomic lance]

How would I find the values of a,b and c

[atomic lance]

for an equation of a line G1 given by ax + by = c intersecting another line G2 at a right angle given by 2x + 8y = 15 if the point (3,9) is on the line

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[modest dirge]

You can get three equations, one by using the point on the line and plugging that in, another by using the fact that the lines are at right angles (switch to point slope form maybe?) and a third by finding the point where they intersect. Then with those three equations you can solve for the three variables using any method you want, matrices, substitution, etc.

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[slender cosmos]

gradient of g(a) = 0

what exactly does thgat mean

i have my gradient to (2x,-1) which can never be (0,0) since -1 isnt depended on x nor y but that isnt the number 0, that is (0,0) not 0

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