help-17

[thorn meteor]

can i ask here ?

[long canopy]

u have to pick from the ones available

[obtuse radish]

please look at "available math help"

i doubt u can directly

expand

then use sqaured form

[long canopy]

so its not possible from factored?

@obtuse radish

[outer warren]

you can determine the x-coord of the vertex from the average of roots

[obtuse radish]

ahh yes

[outer warren]

and plug that value in to get the min
without having to do completing the square and/or -b/(2a)

[long canopy]

could u do it with the equation i provided cuz im kinda confused

[outer warren]

can you identify the roots from the factored form?

[long canopy]

yea i have them x=5 and x=-3

[outer warren]

and what's the average of those two values

[long canopy]

1

[outer warren]

that will be the x-coord of the vertex

now plug that into the original equation

[long canopy]

yea i have the vertex

its (1,-32)

[outer warren]

and from the sign of the leading coefficient,
is the parabola facing up or down
and will that be a min or max?

[long canopy]

min , up

[outer warren]

yes

can you identify the range now?

[long canopy]

(-32,infinity)

?

[outer warren]

not quite

why are you exluding -32

[long canopy]

im not sure how to properly identify it

[outer warren]

is -32 in the range?

[long canopy]

yes?

[outer warren]

yes

thus you should have used
[ and not (

[long canopy]

ok

so [-32,infinity]

[outer warren]

no

why are you now putting ] for infinity

[long canopy]

not sure i thought i had to?

what would it be then

[outer warren]

)

infinity isn't a number / an attainable value
so square bracket/inclusion isn't appropriate

[-32,inf)

[long canopy]

ohhhh ok

how would u explain this in simple terms if we already have the vertex and everything

like the steps

[outer warren]

wdym

i've already outlined the general idea already

[long canopy]

i have to explain it to someone and i dont know how to

[outer warren]

try and put what i've said in your own words

[long canopy]

what does the min and max have to do with it?

[outer warren]

tells you the min or max possible value

knowing that the y-coord of -32 is a min
and that you have a parabola,
-32 and every value above that will be in the range
and that values below that aren't

[long canopy]

so its saying -32 and infinity past that is in the range?

[outer warren]

wdym by infinity past

[long canopy]

like what does the infinity mean

[outer warren]

https://en.wikipedia.org/wiki/Infinity

[-32,inf)
is the set of values including and above -32, with no upper bound

think of any number above/including -32,
and that will be in the range

[long canopy]

ok

and what about domain how would we find that

[long canopy]

@outer warren

[outer warren]

is there any real value where
2(x-5)(x+3)
is undefined

[long canopy]

wdym?

[outer warren]

are the any real numbers where
2(x-5)(x+3)
can't be calculated or would result in breaking mathematical laws like division by 0

[long canopy]

no

[outer warren]

thus the domain will be the set of real numbers

and in general the natural domain of polynomials is the set of real numbers

[long canopy]

so (-inf,inf)

[outer warren]

yes

[long canopy]

ok thanks

.close

[vocal sleet]

Channel closed

Closed by @long canopy

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp lynx]

Probably just log squared

(log_4(x))^2

[vocal sleet]

Channel closed

Closed by @fossil falcon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[river kettle]

I don’t know how to find the values for A, C and D. Any ideas

[quasi pond]

There is a mistake here

[river kettle]

Oh where

[quasi pond]

from equation 1, we get $0=5$, which is not possible.

[twin meteor]

clovercat.

[quasi pond]

1. Coefficients of $x^3$: $0 = 5$
2. Coefficients of $x^2$: $A+B = 0$
3. Coefficients of $x$: $-2A-2B+C = 17$
4. Coefficients of constant terms: $5A+5B+D = 6$

[twin meteor]

clovercat.

[river kettle]

It doesn’t work because we get a situation like

B(x^2 - 2x +5) cannot equal 5x^3 + 17x +6?

So you are saying there is no coefficient of B that will make x^2 = x^3?

[quasi pond]

multiplying through by the common denominator, we get:
[A(x^2-2x+5) + B + (Cx+D)(x+1) = 5x^3 + 17x + 6]
expanding and collecting like terms, we get:
[(A+C)x^2 + (-2A+C+D)x + (5A+D+B) = 5x^3 + 17x + 6]
by comparing coefficients of like terms on both sides of the equation, we get the following system of equations:

1. Coefficients of $x^3$: $0 = 5$
2. Coefficients of $x^2$: $A+C = 0$
3. Coefficients of $x$: $-2A+C+D = 17$
4. Coefficients of constant terms: $5A+D+B = 6$
   solving this system of equations will give us the values of A, C, and D, but it still seems like there is a mistake given in the equations or calculations

[twin meteor]

clovercat.

[vocal sleet]

@river kettle Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet steppe]

Need help , prove this is an inner norm if and only if p=2 i proved that p=2 implies that this is an inner norm using the parallelogram equality but am struggling with other side

[fleet steppe]

oh this is above complex plane

.close

[vocal sleet]

Channel closed

Closed by @fleet steppe

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallen agate]

each row is a different persons ratings. What would be ways to predicht the ratings of the bottom person?

[vocal sleet]

@fallen agate Has your question been resolved?

[vocal sleet]

@fallen agate Has your question been resolved?

Channel closed

Closed by @fallen agate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sequoia]

I tried writing z = a+bi, conjugate(z) = a-bi and w = c + di

I tried switching them in and seeing if I get anywhere (I didn't)

I also swapped 1 with | z |

and bought both sides to the common denominator

[astral shadow]

|z|^2 = z * conjugate(z) can be used.

You can use this once you have |z-w| = |1 - w * conjugate(z)|

[crimson sequoia]

should I square everything once I get this?

[astral shadow]

You should. And then use the above-mentioned fact.

[crimson sequoia]

am I allowed to just

swap inside the modulus?

you mentioned |z|^2 = z * conjugate(z)

[crimson sequoia]

but I have several things in the modulus

[astral shadow]

Yes but conjugate of something like z - w isn't exactly hard to calculate.

[crimson sequoia]

-(z - w) I can guess

then I know the left side has to be pozitive, right?

nvm

just gotta turn the signs on the imaginary numbers

[astral shadow]

Wait what?
Conjugate of (z-w) = conjugate(z) - conjugate(w) you can use that.

[crimson sequoia]

wait, why should I calculate the conjugate of (z - w)

[astral shadow]

...

[crimson sequoia]

after calculating that do I prove that the modulus is always positive

[astral shadow]

|z-w|^2 = (z-w) * conjugate (z-w)

It simplifies things once you get |z|^2 and so on.

Because that's just 1

[crimson sequoia]

oh wow

thank you

I managed to solve it

I never knew about these properties, thank you!

[vocal sleet]

@crimson sequoia Has your question been resolved?

Channel closed

Closed by @crimson sequoia

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn sleet]

I need to find the value of the following expression (without manually calculating each term) -

$$\frac{1^2}{1^2-10+50}+\frac{2^2}{2^2-20+50}+....+\frac{9^2}{9^2-90+50}$$

Of course I generalized the series to be $$\sum_{n=1}^{9} \frac{n^2}{n^2-10n+50}$$ but I don't know how to simplify from here.

[twin meteor]

Alacris

[vast shale]

try complete the square on the denominator

[autumn sleet]

What after you write it as (n-5)^2+25?

[vocal sleet]

@autumn sleet Has your question been resolved?

[timber orchid]

What if you reindex the sum perhaps?

Also, I notice some symmetry with (n-5)^2 and n running from 1 to 9

16, 9, 4, 1, 0, 1, 4, 9, 16 <- (n-5)^2 values for n: 1, 2, ... 9

[autumn sleet]

reindex the sum?

[timber orchid]

I'm not sure tbh - I suspect the symmetry may be more helpful

But I'm not sure how to use it, it's just something I noticed

[autumn sleet]

Perhaps the correct way of solving is to take a manual sum, (and use the observed symmetry to make the process faster by clubbing 1st and last terms), and there's no way of generalizing the given series

[timber orchid]

Perhaps yeah

You can group the "like denominators" together

[autumn sleet]

yup

[timber orchid]

But that doesn't feel as "manual" as it should be

[autumn sleet]

yeah, you are making observations to speed up the process

[timber orchid]

ah ok

If that works then yay

Otherwise I'm not sure

[autumn sleet]

I don't really need to solve this question. I was just wondering if there's a way to solve this without calculating terms manually. There generally is in these kind of questions

[timber orchid]

tbh i'm not sure. Maybe

[inner osprey]

yes you are correct that symmetry is very useful here

reindexing could help you see this but not strictly necessary i suppose

[inner osprey]

to arrive at a conclusion, you can subtract the summand from 1

which gives: 1 - 10(n - 5)/(n^2 - 10n + 50), and this second term is very noticeably "odd" about n = 5 (which also is conveniently the middle of the sum)

therefore the second term cancels out as you sum over all 9 terms, and the sum evaluates to 9 * 1 = 9

[inner osprey]

if this helps ^

[autumn sleet]

What's a summand?

[inner osprey]

i use that to refer to whatever is inside the big sigma notation

ah i say "subtract the summand from 1" but what i really mean is "add and subtract 1 to/from the summand"

[autumn sleet]

ok

this makes sense

This is very helpful and solves my query, thanks!

[inner osprey]

glad to hear and welcome 👍

[autumn sleet]

.close

[vocal sleet]

Channel closed

Closed by @autumn sleet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

A student is given the option to drop TWO of the grades that are negatively impacting their mark. Which two grades should the student pick in order to maximize their final mark?
Below are their grades and weightage:
1:Test: 24.5/26 8.6/9.13

2:Test 21.5/24 8.96/10

2:Quiz 9.75/19 4.88/5

3:Test 19.5/23 8.48/10

3:Quiz 11.75/16, 2.94/4

3:Quiz2 9.75/10 5.85/6

[vocal sleet]

@vast shale Has your question been resolved?

Channel closed

Closed by @dapper vale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin tide]

hello

[thin tide]

I am having difficult

with y=mx+c

[lucid dock]

what are you trying to find

[thin tide]

change in y over change in x

but idk where i should draw the triangle

[lucid dock]

well the c is -1 and slope is think 1 up, 3 across so m = 1/3

[heady ibex]

how did you get those numbers and how can rir0 understand why

[thin tide]

how'd u get that?

1/3

[lucid dock]

ok. c is -1 because that is the y intercept. where your middle red dot is

[thin tide]

mhm

that iunderstand

[lucid dock]

1/3 is rise/run or (how many units the point goes up) over points goes across

[thin tide]

ok thats my problem

i just wanna know

from y its going down or up

and from x from right or left

[lucid dock]

it's positive slope because positive line. so it's going up. think about how the line is at an incline" going higher. that shows its going up

[thin tide]

oh so when it goes to top left then negative?

[lucid dock]

yes

[thin tide]

Ok

[lucid dock]

hope that helps

[thin tide]

0-0 thanks this is what i needed

wow tysm

its simple maths

[lucid dock]

it's okay! ur still learning! good luck on your assignments

[thin tide]

ty

let me just do smth

and show u if its like this

[lucid dock]

k

[thin tide]

like this?

or the opposite on the left one?

the arrows

pointing

[lucid dock]

both are correct

like you drew the arrows right to find the slope

[thin tide]

because i think ive seen were the arrows point downwards

[lucid dock]

technically it can point either you. just have to know if it's negative or not.

[thin tide]

so if c = negative

then downwards?

[lucid dock]

cuz the "rise" you can count up or down, but negative line indicates negative line

i mean the m of the equation. the c value doesn't change the negative or positive

Maybe this will help

[silk bridge]

if c is negative then tehres a negative y intercept

[silk bridge]

if "m" is negative then it goes down

[thin tide]

my brain isnt processing this

wait

[thin tide]

does it matter where the rise and run is placed?

[lucid dock]

yes. rise wil always be along y axis.

run always along x

[thin tide]

this

...

[silk bridge]

wut

[silk bridge]

y=mx+b right

b is the y intercept

m is the slope

[thin tide]

in sweden we use y= kx + m

but now i use y = mx + c more

so my brain

is like

ok so how do i know if m is negative?

[lucid dock]

so if you read the graph left to right, if the rise drops down, rather than going up. it is negative

[thin tide]

ok so why is it going down again?.-.

[lucid dock]

because the line is negative. so visually, if line looks like it's touching the top left corner and bottom right corner, it's negative

[thin tide]

what line is negative

[lucid dock]

this one isn't negative

[thin tide]

oh ur talking about mine

omg

sorry

[lucid dock]

no its ok. i misundersstood too

Blue is positive. Red is negative

[lucid dock]

Ok so yeah. Back to your original example. It is positive

[thin tide]

is the bottom arrow

supposed to go left or right?

i think left

or

no

[lucid dock]

would probably want to reverse the direction to count. But you can count either way.

I think for you, pointing right would help show it’s positive

and same for the y axis one, point up

i hope I'm helping. but i do think this video also really explains well https://www.youtube.com/watch?v=pIWIlznkS64

wait no

thats a bad video lol

dont watch it

[thin tide]

no worries

[lucid dock]

just try to associate right and up arrows with positive
and left and down arrows with negative

[thin tide]

ok so this

does the arrow down and right

?

[lucid dock]

yep

you got it 🙂

[thin tide]

so -2/6?

[lucid dock]

yes! but can be simplifid to -1/3

[thin tide]

mhm

oh i see it

ok so i know one more thing and was just wondering something

this

is this just if you only know the cordinates

[lucid dock]

yep.

[thin tide]

between 2? points

[lucid dock]

exactly.

[thin tide]

ok

Sorry for being so dumb I've missed alot of math classes because im sick

[lucid dock]

nah you're not dumb. it's called learning 🙂 but hope you understood now!

[thin tide]

yes I sure did

[lucid dock]

good luck with all your future mathematical endeavors

[thin tide]

Thanks! you too.

[vocal sleet]

@thin tide Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stone panther]

Find sum

<@&286206848099549185>

[hushed pewter]

Don't comment in help channels if you have nothing helpful to offer

[hushed pewter]

!15m

[vocal sleet]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[stone panther]

It's been 15 min now

<@&286206848099549185>

[vocal sleet]

@stone panther Has your question been resolved?

[vocal sleet]

@stone panther Has your question been resolved?

[stone panther]

<@&286206848099549185>

[slim prism]

That sum is just super gross, idk what to say

Probably theres no nice way to deal with it

[vocal sleet]

@stone panther Has your question been resolved?

Channel closed

Closed by @stone panther

Use .reopen if this was a mistake.

[inner osprey]

one might think this

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[knotty shell]

wondering why this is wrong. Did quadratic, checked all points. i dont get it

[knotty shell]

<@&286206848099549185>

[flat whale]

!show

[vocal sleet]

Show your work, and if possible, explain where you are stuck.

[knotty shell]

these are the answer

its literally my choices

[flat whale]

that's not what the message asked for

[knotty shell]

yeah my bad

[flat whale]

your work is what you did to get your answers

[knotty shell]

my work is a little messy

can i explain

what i did

or nio

@flat whale

[flat whale]

you should just show your work

[vocal sleet]

@knotty shell Has your question been resolved?

Channel closed

Closed by @knotty shell

Use .reopen if this was a mistake.

[knotty shell]

.reopen

[vocal sleet]

✅

[knotty shell]

ok so

the values of the points are right

but i swtiched the unstable and stable

[vocal sleet]

@knotty shell Has your question been resolved?

[vocal sleet]

@knotty shell Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager talon]

<@&286206848099549185> can you help me to find the two factors of 667 and sum of the two factors is 132?

[blissful badge]

this equation is not have whole digit root , try using quadratic formula for calcualting roots, >> a= 5, b= 132, c= 667 >> n1= 19.59, n2= 6.809

[meager talon]

Ok

.close

[vocal sleet]

Channel closed

Closed by @meager talon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint root]

hello

[flint root]

I have a question in the chapter 'sets and venn diagrams' in igcse

what is the solution to this?

basically

is the set B based on failing brakes or passing?

and same for L

[true cliff]

i think its passed

because the common area is for passed

so it wouldn't make sense if b and l are for failing and common is for passing

[flint root]

how

[paper depot]

hold on no

if you want to be consistent with the problem

[true cliff]

Oh

[paper depot]

B is the set of brake failures

[flint root]

YES

[paper depot]

L is the ste of light failures

[true cliff]

OH

[flint root]

exactly

[paper depot]

the last bullet point just gives you the number outside both circles

[flint root]

YES THANK YOU

[true cliff]

thats in my syllabus too 😭

[flint root]

sets?

[true cliff]

yes

[flint root]

nice

[true cliff]

i mean it used to be

[flint root]

oh ok

[true cliff]

mhm

[paper depot]

@flint root do you have anything else to ask

[flint root]

eh no not anymore

[paper depot]

!done

[vocal sleet]

If you are done with this channel, please mark your problem as solved by typing .close

[flint root]

its just tht me and my friends were fighting for a whole hour based on tht question

.close

[vocal sleet]

Channel closed

Closed by @flint root

Use .reopen if this was a mistake.

[flint root]

uhhh

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal mesa]

hi

[scenic ravine]

[crystal mesa]

okk one sec

i dont know how to do this

[scenic ravine]

it means $\frac{f(x)}{g(x)}$ unless I've forgotten basic nontation

[twin meteor]

Why am. I here

[lament yew]

I think they want you to do polynomial division

[crystal mesa]

yea thats right but then how do we solve

[lament yew]

do polynomial division

[low pewter]

https://tutorial.math.lamar.edu/Classes/Alg/DividingPolynomials.aspx

[lament yew]

thank you hhh somehow link provider dude

[crystal mesa]

umm

i forgot how

wait

[lament yew]

Brow even sent a link 😮

[crystal mesa]

ITS COMPLICATED

[lament yew]

https://www.youtube.com/watch?v=AKJgo-WR_K4

This video is literally a cheat code 😉

[crystal mesa]

ok whats next

[lament yew]

You watch the video

And then come back

[low pewter]

we aren't going to do it for you

[crystal mesa]

okkkay

[low pewter]

gotta learn

[crystal mesa]

i did watch another video i solved one but this question is different

[lament yew]

Okay, if you watch the video I sent you and still have no clue, then I will help you

[crystal mesa]

ITS AN HOUR LONG!?@>,W

[lament yew]

You can skip to the imortant part

[crystal mesa]

where is the important part

can u just tell me the next step

i understand like that

[lament yew]

Okay, you can try to solve it algebraically, just express $x^2-7x+2=A(x)(x+4)+B(x)$

[twin meteor]

Der Kitzler

[crystal mesa]

im in 11th grade btw

[lament yew]

Good for you

[crystal mesa]

lmaosoddj

[lament yew]

For being so young, you seem to be very reluctant of doing much work

[crystal mesa]

bbru😭

[low pewter]

again, i highly suggest taking 10 minutes to just read this and understand what it's teaching you

[crystal mesa]

ok ill learn it rn

[crystal mesa]

okk

i will

which one am i doing ? Dividing Polynomials?

[lament yew]

Yapp

It is in spirit pretty similar to long division in elementary school

[jagged cargo]

https://en.wikipedia.org/wiki/Synthetic_division

[jagged cargo]

@crystal mesa you might want to look into this

[crystal mesa]

OOHHH I REMEMBER THISSS

[lament yew]

xD

[crystal mesa]

OKOK

[crystal mesa]

ok so are my numbers gna be 1 -7 and 2?

[jagged cargo]

yes

the divisor is the negated coefficient of g(x) without the leading degree

[jagged cargo]

in this case, -4

[crystal mesa]

yesyes

I got this

then its 1x^2-11x+46?

[jagged cargo]

no

the numbers you got are correct, but the conclusion is not

[crystal mesa]

then what is it

[jagged cargo]

46 is the remainder

[crystal mesa]

ohh

[jagged cargo]

you took a second degree to divide a first degree, the result polynomial should also be a first degree

[crystal mesa]

so is it

1x^2-11x

[lament yew]

Almost

Like the remainder remains

Thats the name

[crystal mesa]

what for

[lament yew]

So it is the one constant you could not get rid of

[crystal mesa]

oohh

[lament yew]

SO you have to write something like $\frac{46}{x+4}$

[twin meteor]

Der Kitzler

[jagged cargo]

not even close

[jagged cargo]

what did i say?

[crystal mesa]

😭

[lament yew]

Ohh yeah, I thought you dropped the x^2

[crystal mesa]

where is the 1 and -11

[lament yew]

Just think like this

In the original term you had powers from 2 to 0 (constant term)

And now you divided by an x term

So the x powers will be

a linear term a constant term and a term that is divided by $x+4$

[twin meteor]

Der Kitzler

[lament yew]

So you just go one power less

and write the remainder like I showed you

[crystal mesa]

so its just x

[lament yew]

Maybe

Just rewrite it

[crystal mesa]

rewrite what

1x-11

[lament yew]

$x^2 \to x $ $x \to 1$ $1 \to \frac{1}{x+4}$

[twin meteor]

Der Kitzler

[lament yew]

You still need the remainder term

You forgot the $\frac{46}{x+4}$

[twin meteor]

Der Kitzler

[crystal mesa]

this is frustrating

[lament yew]

After you add the remainder you did it!!

Nono you had it right this time

just add 46/(x+4) to what you already wrote

And you are actually finished

[crystal mesa]

so is the answer

1x-11 46/(x+4)

[lament yew]

Yapp

Good job mate 🙂

[crystal mesa]

ogmghngm

wait

let me write it

Is it just that?

[lament yew]

YOu forgot a plus lol

[crystal mesa]

oh right

[lament yew]

$x-11+\frac{46}{x+4}$

[twin meteor]

Der Kitzler

[crystal mesa]

yes yes

THANK YOUU

can u give me a question

[lament yew]

Nein

Keine Lust

[crystal mesa]

whwat

[lament yew]

I do not have a question to ask at the moment

[crystal mesa]

no i mean

equation

nvm

[lament yew]

I literally wrote the equation out, lol

.close

[crystal mesa]

huh

bbruh

I MEAN

can u give me a new equation to solve

nvmvnmvvmnvmnvm

[lament yew]

hmmm

$\frac{4x^3-8x^2+2x+10}{4x-2}$

[twin meteor]

Der Kitzler

[crystal mesa]

r u sure this is the same lesson

operation of function

[lament yew]

Yeah, why not

[crystal mesa]

ok

[lament yew]

Anyway when your question got solved you should write .close

[crystal mesa]

okk

ty

[lament yew]

np

[crystal mesa]

the number we put on the side is 2/4 right?

@lament yew

Idk if it’s right but sure

Bye

.close

[vocal sleet]

Channel closed

Closed by @crystal mesa

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sage wind]

Let r be the rotation clockwise about the origin through $2\pi/n$ radian,prove that $1,r,r^2,...,r^{n-1}$ are all distinct and $r^n=1$ so that $|r|=n$

[twin meteor]

calculus is fun

[sage wind]

i can argue that r^i is the rotation through 2πi/n for all i in {0,1,2...,n-1}

thus all of the above rotations are distinct

is this sufficient i am not sure

[vast shale]

who can speak Chinese

[vocal sleet]

@sage wind Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

Any resources for studying conic sections with theory? Where I could learn how 3d figure is related to 2d shapes.

[viral copper]

https://tenor.com/view/math-universe-geometry-perception-parabola-gif-18147727

right from the discord gif finder

[vast shale]

no, I want to know the theory. Like how equations of each shape can be generalised using geometrical properties of the cone

I want to make a simulation for this, that's why I need it

[viral copper]

ah i see

[vast shale]

it is also helpful though, thanks. Still I need more help

looks beautiful

any idea?

I can derive the equations, but it will take so much time for me

should I derive myself, or take help? What do u suggest?

nvm. I will derive

.close

[vocal sleet]

Channel closed

Closed by @grizzled osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[merry moss]

can any body help me with physics ?

[merry moss]

this is the question

[vocal sleet]

@merry moss Has your question been resolved?

[lone ocean]

wait

what all is given here

what is pe

[vocal sleet]

@merry moss Has your question been resolved?

[merry moss]

it's the enrgy

pe = 1/2 Q dv

[lone ocean]

no ik that

i didnt know ur variables

ok

so what u could do is

get the equivalent capacitance

in terms of k

that is the dielectric

and then set the net energy

q^2/2c

to that

[merry moss]

how is that ?

[lone ocean]

you know equivalent capacitance

for parallel

[merry moss]

what am i going to do with Ceq

[lone ocean]

dude

what values do u have in the question

net potential energy

a capacitor value

net charge

now pe = Q^2/2c

c is eq capacitance

q is net charge

[merry moss]

this pE is for the second capacity not for the whole net

The capacitance of the capacitor before inserting the insulator is not equal to the capacitance of the capacitor after inserting the insulator

[lone ocean]

ok first of all u must find the voltage then

in terms of c eq

and then u have to use 1/2 cv^2

where

c is only the second capacitor

[merry moss]

this is the same question but we have the k instead of PE2k

[merry moss]

thats what we cant find

[lone ocean]

bro

they gave the value of charge

[merry moss]

because we don't have ceq after inserting the insulator

[lone ocean]

we do

in terms of k

look

[merry moss]

we have it too

[lone ocean]

what im saying is

what happens to a capacitor

when a dielectric is inserted

it becomes k times

right?

[merry moss]

not when it's into a net

[lone ocean]

listen

it becomes k times

right

[merry moss]

yes

[lone ocean]

now

the capacitor becomes

8k

and there is an original capacitor

of 4

so the net is

4 + 8k

right?

[merry moss]

yes

[lone ocean]

now charge is 600 nf

so voltage is q/c

right

[merry moss]

yea

[lone ocean]

doing that we get voltage is 600/(4+8k)

im not bothering about the units btw

now this is the voltage across both the capacitors

cuz it is parallel

[merry moss]

yes

[lone ocean]

now this voltage is what we have in terms of k

now we know

pe = 1/2 c v^2

right

so c = 8k

1/2 * 8k * (600/(4+8k))^2

this is equal to the value given

please check the units carefully

[merry moss]

Well

[lone ocean]

yes?

[merry moss]

lemme try if it works

thank you so veryy much

[lone ocean]

npp

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[raven slate]

A dealer purchases washing machine. He allows a discount of 10% on its marked price and gains ₹400. If he allows a discount of 20% on its marked price, he gains ₹330. Find marked price on the washing machine.

[paper depot]

!status

[vocal sleet]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[raven slate]

4

[paper depot]

show what you've got so far.

[raven slate]

0.9y-x=400

0.8y-x=330

getting y= 700 but not sure

[severe current]

this seems right

[raven slate]

thanks

[paper depot]

this looks like status 4, not 2.

[severe current]

yeah cus 10% of the price is just 70

[raven slate]

i dont have answer key

[severe current]

so 100% is 10x that

[raven slate]

yes sir

[paper depot]

doesn't really matter to my point

your status was not "I got stuck partway". it was "I got an answer but idk if it's right, I want somebody to check"

[raven slate]

we both edited our messages right

[raven slate]

sorry

[paper depot]

ah yes sorry

didnt see until now

[raven slate]

thanks, great server

i think i should close this

.close

[vocal sleet]

Channel closed

Closed by @raven slate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gaunt pendant]

I’ve done part i

Part ii I was to take the same approach as the prev q but it would be tedious and then I wouldn’t know where to go so i chucked it into symbolab to simplify and then onto wa for alternate forms

so ye part ii i’m stuck on i would show my work but i hadn’t completed it and plus I’m not looking for the way I’ve done it need a smarter way

WA spits out many other forms to this so i just left it as is

the x’s are meant to be x_n’s

[vocal sleet]

@gaunt pendant Has your question been resolved?

[gaunt pendant]

<@&286206848099549185>

[blissful badge]

what is problem ?

[gaunt pendant]

?

[blissful badge]

i said what is issue in your question ? part ii .......

[gaunt pendant]

i stated it

read my msgs

[blissful badge]

sorry my bad

[gaunt pendant]

so you able to help or what?

[vocal sleet]

@gaunt pendant Has your question been resolved?

[vocal sleet]

@gaunt pendant Has your question been resolved?

[gaunt pendant]

.close

[vocal sleet]

Channel closed

Closed by @gaunt pendant

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

Find the particular solution to the differential equation dy/dx + xy = e^-x^2/2
where y(0) = 2

how do i even start with this

i went to find the integrating factor

e^ integration xdx

where x = 0

e^ integration 0dx

idk what to do after that

[vocal sleet]

@vast shale Has your question been resolved?

[obsidian ore]

lemme see

@vast shale

can i put my steps here?

for integrating factor, its dy/dx + P(x)y = Q(x) IF = e^integrateP(x) dx

[obsidian ore]

in this case its x

so e^integrate x = e^(x^2/2)

ping me if you don't understand

[vocal sleet]

@vast shale Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[finite hatch]

hello

[finite hatch]

can i have some help

how do i do this

[vast shale]

question number?

[finite hatch]

a

[vast shale]

MA+AD=MD

MA=-a/2; AD=b

[finite hatch]

why is it negative ?

[vast shale]

because MA is in the opposite direction than AB

[finite hatch]

oh i see

ok thank

:D

.close

[vocal sleet]

Channel closed

Closed by @finite hatch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

how can we find a general solution to this equation

[vast shale]

$$y"= 2y' y$$

[twin meteor]

Pip pirrip

[vast shale]

where y is a function of (x)

[river minnow]

You can start by integrating both sides

Notice that the right hand side is clearly a derivative of something involving y

[vast shale]

y^2 +c= y'??

y^2 +c_1 =y'

[river minnow]

Yeah

[vast shale]

so inverse tangent?

[river minnow]

Now that's a separable differential equation

[vast shale]

thanks

.close

[vocal sleet]

Channel closed

Closed by @uneven terrace

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deep bough]

Can anyone help me with this question?

[unique bay]

This look exiting

Where are you stuck

[deep bough]

so for on of my questions
is it correct for me to infer that the restriction of which to W equals alpa to mean alpha (w) = w?

I'm also confused as to how to implement the condition of v in W intersect W'

[hybrid flicker]

ah no this is not necesserally true

you want theta(w) = alpha(w)

and theta(w') = beta(w')

[deep bough]

is that what "the restriction of which to W equals alpha means?"
that theta(w) = alpha (w) and theta (w') = beta(w')

[hybrid flicker]

"that theta(w) = alpha (w)"

yes

and then

"the restriction of which to W' equals beta"

[deep bough]

got it

[hybrid flicker]

means "theta (w') = beta(w')"

[deep bough]

let me try and thinking more about then knowing that

[hybrid flicker]

(of course w in W, w' in W')

[deep bough]

thank you

yes of course

thank you

.close

[vocal sleet]

Channel closed

Closed by @deep bough

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[languid dune]

not sure how this is wrong

[languid dune]

just part b

[ancient knoll]

well, it's not 20 and you didn't show any working out, so i'm not sure why you got it wrong

[languid dune]

My logic is that since we have to move one upwards we need to find lattice paths from (1,0) to (4,3). Which is equal to finding lattice paths from (0,0) to (3,3), which is equal to 6C3 which equals 20. However, it is showing it as incorrect and am I not sure why.

[ancient knoll]

ok, then one of your diagram or your interpretation was wrong

conventionally up step should represent (0, 1)

if you think of a grid as being the x-y plane and right as facing the positive x direction and up as facing the positive y direction

[languid dune]

ah yes mb

silly error

thanks

so should it be 6C2

.close

[vocal sleet]

Channel closed

Closed by @languid dune

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unreal sparrow]

Why is the answer not D? Isn’t the definition of an asymptote a line that never touches the curve?

[stone terrace]

That isnt strictly the definition of an asymptote. The line y = 10, is also a asymptote for the function, well, f(x) = 10.

This is also exactly the clue as to why (C) is the right answer. An asymptote is a line l(x) such that the distance between l(x) and f(x) gets arbitrarily small as x goes to infinity

(If you ignore vertical asymptotes, since what I said doesnt work for vertical lines)

[unreal sparrow]

Forgot to post the question

[unreal sparrow]

It says they never meet though

Assuming the curve is f(x)

[stone terrace]

Oh I see that makes sense, but its not what I am used to.

Not meeting however doesnt meet they cannot touch

[unreal sparrow]

Fr?

So it has to cross the line to “meet”?

[stone terrace]

Hmmm where did you find the definition?

It is a bit vague

[unreal sparrow]

Google

[unreal sparrow]

Which definition would you use?

[stone terrace]

I would say a line is an asymptote if the distance between it and the function f(x) gets arbitrarily small as either y -> inf or x -> inf

Depending on whether youre looking a vertical asymptote or not

But I also have sources saying that an asymptote cannot touch the graph of f.

So in all honestly I think this is just a poor question, unless your book has a clear definition of what an asymptote is

[unreal sparrow]

Ok glad to know thanks

.close

[vocal sleet]

Channel closed

Closed by @unreal sparrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe dagger]

its been a while since i did one of these problems; wanted to make sure i did it right

[severe dagger]

is it as simple as plugging in each B element and seeing which ones are values within A?

so would the final answer be (2,3,4,5,6)

[hard atlas]

thats not a set

[severe dagger]

{2,3,4,5,6}?

[hard atlas]

why do you think so?

[severe dagger]

when you plug 1 in for a you get 6<=5 which isnt possible so its eliminated as a possible element for A

wait

oops

it wouldnt go all the way to 6 hold on

{2,3,4}

[hard atlas]

yes

[severe dagger]

yeah i tripped for a seocnd thanks

[vocal sleet]

@severe dagger Has your question been resolved?

Channel closed

Closed by @severe dagger

Use .reopen if this was a mistake.

[severe dagger]

can anyone confirm for me if the final set would be -2....8?

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar jay]

can anyone explain how you get -2/5 and -8/5 when factorising 16/25? im not sure how to factorise that equation

[magic wasp]

-1 * -1 = 1, 2 * 8 = 16, and 5 * 5 = 25

You need (2+8) / (5+5) = 1 so you can get 2x, and you need the minus signs to get -2x

[cedar jay]

i understand that part but do you do it through trial by error? like my first guess was -4/5*-4/5

for the fractions

OHH wait nvm#

i get it

thank you

.close

[vocal sleet]

Channel closed

Closed by @cedar jay

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert galleon]

I can't really solve this

ive reached until cosec squared theta + sec squared theta + 5

[outer warren]

consider the Pythagorean trig identites

(the ones that involve csc and sec)

[desert galleon]

somehow i got
2 tan squared theta + 8 using that

[outer warren]

show work

[lapis marten]

Could be correct, remember tan^2(theta) + 1 = sec^2(theta)

nvm

I thought the answer had sec instead of cot

[desert galleon]

1s

[outer warren]

what are you doing/applying after
$$5 + \sec^2(\theta)+\csc^2(\theta)$$

[twin meteor]

ℝαμΩℕωⅤ

[desert galleon]

nvm, i can't figure out what to do next

do i write them in sin and cos?

[desert galleon]

i havent been taught any which include both sec and cosec together

[outer warren]

look them up

also you don't need them together

there's one that has sec

and another that has csc

apply both

[desert galleon]

sec squared theta = 1 + tan squared theta
cosec squared theta = 1 + cot squared theta
these?

alright thanks

got it

.close

[vocal sleet]

Channel closed

Closed by @desert galleon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

how is f'x(x,y)=x^2*y
when fx(x,y)=2xy

[flat whale]

!original

[vocal sleet]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[brisk moss]

[vast shale]

a funcktion f of 2 variabels is given by:

[flat whale]

Well that's just awful notation

[vast shale]

sorry

[flat whale]

Not your fault

[vast shale]

rieman i remeber you helped me before thank you for that

you was kind and so patient

[flat whale]

I don't know what ' means in this case

[vast shale]

differentiated

3x^2 obv is a constant that gets too 0

but im not sure how x^2*y gets to 2xy

[flat whale]

$f_x = \frac{\pa f}{\pa x}$

[twin meteor]

riemann

[vast shale]

yess

[flat whale]

since y is a constant when differentiating with respect to x, you can factor out y of the partial derivative

[vast shale]

yes

i agree

[flat whale]

Does that answer your question here

[vast shale]

but wouldnt x^2*c give x^2+1 or is my differentail rules completly wrong

[flat whale]

Your rules are wrong haha

[vast shale]

hehe

[flat whale]

$\frac{d}{dx} x^n = n x^{n-1}$

[twin meteor]

riemann

[vast shale]

$2x^{2-1}*y$

[twin meteor]

Emmychan🫐

[vast shale]

$2x*y$

[twin meteor]

Emmychan🫐

[vast shale]

i was just thinking that a*x=a and in this case a=x^2 and x=y

[flat whale]

Yea partial derivatives with multiple variables require new mental trickery

[vast shale]

i see thank you

[vocal sleet]

@vast shale Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[covert ridge]

(f(x)+g(x))+h(x)=f(x)+(g(x)+h(x))?

[misty belfry]

it has to be true for every x you plug in so function addition must be associative

[river wagon]

Yes, that is true

[covert ridge]

What is identity function?

[river wagon]

f:x->x the function that does not alter the input. Just gives it back

[covert ridge]

identity function of this (possible) group I meant?

[river wagon]

Oh, the zero function f:x-> 0

[covert ridge]

What is inverse of this (possible) group?

[river wagon]

Well, f(x)-f(x)= the zero function

So just -f(x)

[covert ridge]

How can we show that this (possible) group is closed?

Or can we just say that it's a property of differential functions?

[river wagon]

Yeah, that sounds sane

[covert ridge]

Is it a group?

[river wagon]

If you don't like to be sane, use epsilon delta

Spoiler: yes

Well, you needed a lot of help on this one, try doing the next without help. Good luck!

[covert ridge]

.close

[vocal sleet]

Channel closed

Closed by @covert ridge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prime dagger]

Is this right? (11.9 is the answer?)

[vocal sleet]

@prime dagger Has your question been resolved?

[knotty pendant]

yes, I too got 11.9 @prime dagger

[prime dagger]

Ok thank you!

.close

[vocal sleet]

Channel closed

Closed by @prime dagger

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[jaunty hearth]

this is the quotient rule but now how do I simplify this to 30-21x/ (7x + 2)^5?

maybe this can do?

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tribal sapphire]

Hello, I'm watching a video on trig, I was wondering how is it that sin(pi-Θ) = sin(Θ)

[tribal sapphire]

for example if theta was 60, sin120 doesnt equal sin60

oh, so this only works for sine waves

because I'm pretty sure were going to be using this for trig identities

[civic oracle]

@tribal sapphire here i'll show you why

are you aware of which trig ratio is positive in which quadrant

like all students take calculus

[tribal sapphire]

yeah

[civic oracle]

ok

[tribal sapphire]

its in the screenshot lol

[civic oracle]

so look

this is theta

[tribal sapphire]

alr

[civic oracle]

now if we go to pi and subtract the angle

it's still positive

because it's in the quadrant where sin is positive

[tribal sapphire]

yeah

[civic oracle]

ye so that's why sin(pi - theta) = sin(theta)

[tribal sapphire]

I'm still confused though, like sure its still positive, but the angles arent correlated where they look like this

[civic oracle]

i shouldn't have said it's still positive

like it's true but that's not all there is to it

i understand what you're saying and it's a good question

idk if i can answer it lol

[tribal sapphire]

@civic oracle should I just memorise that they equal each other

lol

[civic oracle]

i guess you can but it's better if you understand

[tribal sapphire]

yeah you gotta help me out here

[civic oracle]

you can also think of the sin graph

wait

yeah you can

if you get any point on the sin graph

im working this out lol hold on

[tribal sapphire]

just ping me when youre done

[civic oracle]

you're are right that it's not the same angle, but the angles are equal to each other since theta 2 is the related acute angle @tribal sapphire

[tribal sapphire]

its not the related acue angle though

wait it might be