#help-17
1 messages · Page 117 of 1
Yeah. It's a bad problem
I sympathize with you, it's so arbitrary
I saw A and C, but answer disagrees with C.
F seems a bit far
Bring this problem up to your teacher. Be sure to use the word "bullshit" a few times
It's a bad problem
As a self diagnosed genius, I will assure you that this problem is not worth the effort.

bro that makes ti worse lmao
ye im with that too
F is a maybe, but I think no
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I have a metric tensor
1 0
0 r^2
which just describes the rate of change of the relative coordinate from polar coordinates to cartessian coordinates right?
So my line element equation would be
ds^2 = 1 * dr^2 + r^2 * dθ^2
Now i simply want to find the length from point r = 1, θ = 0 and r = 2, θ = pi / 2. How would i do that?
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<@&286206848099549185>
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@sly stag Has your question been resolved?
this is higher level stuff i think (tensors), maybe there's a another dedicated channel to this stuff?
@sly stag Has your question been resolved?
I don't know anything about tensors at all but this sounds like a pythagoras theorem problem to me lol
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how can i show that something is a point of inflection using diffrentiation
also point of inflections generally apply to functions with a degree higher than 2
so if i take a degree 3 for example, theres gonna be like 2 concavities formed by 3 x-intercepts
ykwim?
ooohhh okok thanks
the x value you get from f"(x)=0 shows you the point at which the concavity changes
so i just diffrentiate 2 times then show it = 0
correct terminology is "Solve for x when second derivative of function is 0" but yeah you understood
thanks very uch
it wont work for quadratics cuz second derivative becomes a constant n stuff sooo yea
equating it to 0 wont make sense
yeye this is a ^3
ok you'll definitely get an x
np
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"If $f$ is injective and $g$ is surjective, then $g \circ f$ is bijective."
Why?
f is injective, sure
g is surjective, sure?
But not really
What about 0? It should be R_0^+, no?
This is just like what we did before with @median crane
I'm saying we have x -> x^2
And for x = 0, we'll have 0
So why does it say R -> R^+
Shouldn't it say R -> R_0^+
true
Though this is written by a professor so maybe not?
your claim is correct
g(0)=0 not a real positive
the professor is wrong on the codomain
R^+ does include 0
It's somewhat ambiguous but most of the time R_*^+ is used to exclude 0
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Oh
The non-ambiguous notation is R_{>=0}
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How can this rule exist?
could you show the actual rule as it was presented to you
I think you got the rule wrong. Should be if lim g(x) ≠ 0 then lim of f/g = limf/lim g
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yo
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Please help!
I haven't leared this yet so I'm not sure what to do
Just plot the points first
That's the thing idk how
Wdym
Just look at the table
At x=-5 you plot a point 7 units above
(-5,7)
And do that for the rest
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Please don't troll in help channels
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
depends on how you define 1 and +
1 apple and another apple make 2 apples together 🤯🤯🤯🤯🤯
is it a troll tho to prove that 1+1 = 2
you need a lot
Principia Mathematica took over 1000 pages to prove that 1+1=2
yep
I love this one
wonderful
@vast shale here you go
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I know this relates to trigonometry and would require the use of sin, cos, and tan, but am stuck on how to solve the problem.
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(yy')'=5/2(y')^2
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Could somebody please tell me where I'm going wrong
The partial fractions I get don't make sense
A/(x+1) + B/(x+1)² + Cx+D/(x²+1)
= (A(x+1)(x²+1)+B(x²+1)+(Cx+D)(x+1)²)/(x+1)²(x²+1)
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@hearty dragon Has your question been resolved?
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can someone explain?
b/a gives a rational int and the other one shows the relationship between the two numbers and is either true or false
but i still dont understand how that affects these
they are all right except the b is 0
i mean a
b divided by a and a can never be 0
oh and i missed one earlier
wait so can there be decimals or they have to be integers?
🤔 you can do 0/9, but is 9|0 a true statement or a false statement? Technically, 9 divides 0 zero times
i have no clue
the denominator (in this case is a) can never be 0, i dont really know why but its a rule in calculus or sth. It can be understand by you cannot divide anything by 0
ah i see so the first term can never be 0
i dont think so
noooo
the term below
so 9/0 is wrong
since that would imply that there is a number that can be multiplied by 0 to be 9
i meant b|a
but 0/9 is right
exactly
its not 0/9 its 0|9
yes 0|9 is right
yes
@marble kettle Has your question been resolved?
Wow I think you're all confused
0|a is never right (except if a=0, in some contexts)
$n | m \iff \exists k : kn = m$
Nel
@marble kettle Has your question been resolved?
sorry i did not see your message
no
i didnt even know what to google to try and find the answer
lol
like to understand the concept
Do you understand that?
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anyone good with spherical coordinantes to cartesian transformation
given the surface of a spherical coordinates: ρ^2 = sec (2φ) where 0 <= φ <= pi/4 express
this surface in Cartesian coordinates and state what type of surface it is.
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can someone help me with the LDE
i have the final answer but its slightly diferent from what the textbook has
this is the textbook solution
These are the roots I’m getting
I dont understand why I cant do this , to get alpha and beta
I thought I could simplify it like that but is it wrong?
nvm I was confusing my self
i kept misclking in my calcualtor... divided whole thing by 3 and realized i didnt need to sepearte cuz theres no imaginary
thanks anyways
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This is what I have so far, but I feel like I've gone off track.
it might be easier to define a homomorphism Q[x]->Q[sqrtp] and then use the isomorphism theorem
(in general when you see a factor ring in situations like this, the first idea should most of the time be "iso theorem")
alr I'll try that out
I'm curious, whats part (1) of the problem?
ok
It looks deceptively simple, since it's something I could have completed 2 months ago. I feel like there's a catch or something
with iso theorem its not that hard. assuming of course you had that 2 months ago
nah the first part of the problem I mean
oh that
well you only need to find inverses
and you already know how to find those in R. so you can find them there first and show that they are actually already in Q[sqrtp]
@torn tree Has your question been resolved?
I'm trying to find the right function but I'm missing it
This is what I tried
Is writing f as (something) + (something)*sqrtp the right approach or do I need to try something else?
the notation Q[x]->Q[sqrtp] already suggest that we should replace x by sqrtp
in other words, the evaluation homomorphism
I find the notation weird. Is this fine or does it not make sense?
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How to integrate this?
@flat quartz Has your question been resolved?
No
! status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
I tried cosx=u
There is x at the beginnin
1+cos² = u
I thought ain't even worth trying it will give sin*cos etc
Step 1 probably
are you sure there aren't bounds?
$\int_{0}^{\pi}\frac{xsinx}{1+cos^{2}x}dx=\left[ x=\pi-y \right]
=-\int_{\pi}^{0}\frac{\left( \pi-y \right)\sin\left( \pi-y \right)}{1+\cos^{2}\left( \pi-y \right)}dy=\int_{0}^{\pi}\frac{\left( \pi-y \right)\sin\left( y \right)}{1+\cos^{2}y}dy=\pi\int_{0}^{\pi}\frac{\sin\left( y \right)}{1+\cos^{2}y}-\int_{0}^{\pi}\frac{y\sin\left( y \right)}{1+\cos^{2}y}dy\\<=>\\2\int_{0}^{\pi}\frac{xsinx}{1+cos^{2}x}dx=\pi\int_{0}^{\pi}\frac{sinx}{1+cos^{2}x}dx=\left[ t=cosx \right]=\pi\int_{1}^{-1}\frac{-dt}{1+t^{2}}=\pi\left( \frac{\pi}{4}+\frac{\pi}{4} \right)=\frac{\pi^{2}]}{2}\<=>\\\int_{0}^{\pi}\frac{xsinx}{1+cos^{2}x}dx=\frac{\pi^{2}}{4}$
Joanna Angel
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not sure how to begin
@copper pebble Has your question been resolved?
How did you show that
Show your work
i took the determinant of the matrix by expanding from column 1, which got me:
lambda * (lambda * lambda - 1 * 0) = lambda^3
but i write lambda as z normally
so now we have a polynomial, which can be written as:
(lambda-0)(lambda-0)(lambda-0)
which means the multiplicity of 0 is 3
not sure how to progress here since we don't know the value of lambda
This shows the solutions for double root. Try to generalize it to a triple root
https://tutorial.math.lamar.edu/Classes/DE/RepeatedEigenvalues.aspx
@copper pebble Has your question been resolved?
We get a triple root yea
For lambda
🙂
<@&286206848099549185>
Just need help with the question
I got triple root for lambda
not sure what to do now
hi
@copper pebble Professional assistance. <@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
@flat whale
I think maybe most helpers cant solve a qustion of this difficulty
its quite difficult
yes?
Friend request
stop spamming
did you read the double root solution?
I don’t get some of the notation
<@&286206848099549185>
can you just ask a question
and be specific
I just wanted a list of steps to solve it
That’s about it
it's described in the link above
step 1: figure out the solution for double root
step 2: figure out the solution for triple root
I found the triple root
I just want it in a dumbed down way
Because I don’t understand all the notation in your article
.
$\eta$ is a variable
riemann
like x, or y
$\vec{x}$ is notation for a vector. in three dimensions, $\vec{x} = (x_1, x_2, x_3)$
riemann
In this case, your equation can be given as
$\vec{f}' = A \vec{f}$
riemann
Does this look like my exercise?
your exercise is 3 dimensions
this is 2 dimensions
With Eigenvalues on the diagonal
to your problem in 3 dimensions, you should understand 2 dimensions first
right
i still don't understand why we have n ->
and then p ->
what are these variables for
i don't understand your questions. they're all explained in the link
I solved it now
Basically just assuming that f_3(t) = 0 and f_2(t) = 0 while f_1(t) = e^lambda*t
Then assuming that f_3(t) = 0 and f_2(t) = e^lambda*t and then calculating f_3(t)
then doing it again but where f_3(t) = e^lambda*t
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What's the direct translation of the limes superior using propositional calculus? (for sequences)
Limit inferior and limit superior
only superior, inferior is trivial if I know the other
after fiddling a bit, this is how I'd translate it
most sites like wikipedia etc. I stumbled upon offer no direct translation this way but I have to use it for proofs
the sequence doesnt have to be smaller than the limsup
hm is it not correct given n_0 e N?
no
take any converging sequence. then limsup is the limit. but we know it doesnt have to hold then
so the first expression is correct I presume? but how would I rewrite the second for the equivalence to hold
well you could say the standard "and for all s such that there exists a partial sequence converging to s, you have s<=r"
hm yeah although I'm not sure that helps me with the proof for the criteria such as the root criterion
well you could also just write it as the limit of the supremums
and then unpack all those definitions
I'd have to express something like "if that limit isn't the limit of a_n, then the second statement holds"
ah yeah actually I could directly translate that
@hard atlas probably not a work of art, but it'd be in the form I could use for multiple proofs :3
I think it must be exclusive right, if the lim sup is not the limit, then there must exist an n_0 such that the last statement is true
in turn achieving equivalence
no
the converging sequence was just an example
imagine two converging sequence and alternate between them
the limsup will be the bigger of the two limits
but how does that make the expression false
lim(a_n) = r would then be False
hm nvm right they still wouldn't have to be below
ugh so I need an additional variable for an environment
Ok, so now it either converges to r OR a subsequence converges to r and all values must be within the upper-bound epsilon-environment from n_0 onwards
@hard atlas sry for ping, but I hope it's correct now
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who can help me review slopes?
.closee
This algebra video tutorial provides a basic introduction into positive and negative slope.
Access Full-Length Premium Videos: https://www.patreon.com/MathScienceTutor
Algebra For Beginners: https:/...
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can anyone confirm if i got this correct?
@mighty vapor Has your question been resolved?
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Im not sure what the trick is for solving this one
well you have a total of N items in the list (find N)
so the number you're looking for is the Nth item
how many elements will start with 1? will this reach the Nth number?
Im not sure this is what is meant by the question
Lets say for example i have an sorted list of 1000 numbers
Then i am looking for the 501'th number
oh sorry! yes, I was looking at the last number of the smallest part
so yes, you'd be looking for the N+1th number
where N is the total ways you can organise the numbers 12345
also the total number of items is just 5!, which is 120
so i am looking for the 61'th number
but im not quite sure how to determine the 61'th number
yep - and, I am sure there is a "smart" way to do this but I'm afraid I'm not too sure, you can also work out which bucket it falls in - if it's in 1xxxx or in 2xxxx or 3xxxx or 4xxxxx or 5xxxx
once you find it's in the bucket axxxx, you can then work out which abxxx it's in
and so on
hello
need holp?
yup
yeah so the progress so far is that there are 120 numbers in total, and im looking for the 59'th biggest aka. the 61'th smallest
what is 61?
yeah thats what i said
ok i see
the 59'th biggest and the 61'th smallest are the same
how many numbers will start with 1XXXX?
4!?
what is the 59th biggest
wrong
how so
...no, it's 4!.
oh right
please stop spreading misinfo.
lol i didnt see the !
yeah that man is confusing 🤷
well 3xxxx starts at 2*4! and ends at 3*4!-1
well, if 1xxxx has 4! then 2xxxx and 3xxxx and 4xxxx and 5xxxx should have 4! too
yeahj
you can work out how far into 3xxxx it is
and then repeat this for finding the next x
yeah i think i can just do it manually from here on
the longer form is that the number will be a(4!) + b(3!) + c(2!) + d(1!) = 61
knowing each of a-d is >0, it's just finding the largest possible value
@snow dune wanna close this or
.close
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the last one as in, M)?
oh hang on sorry I misread the Q
no my fault
well you can divide the cube root of 2x^2 into two parts, (2)^1/3 and (x^2)^1/3 right
as you already did for taking the x outside the root
and if you have something like $\frac{a}{bx}$ you can instead make $\frac{a}{b} * \frac{1}{x}$
PrettyPrincessKitty FS
i.e. you can take your numerator - just constant number terms - and the part of your denominator with just constant number terms and combine them into one big numerator
and you'll get $\frac{(a/b)}{x}$
PrettyPrincessKitty FS
simplifying only needs to get rid of those yucky root(x) terms, the rest are constants you can combine
no
also root3(4) = root3(2*2) = root3(2)*root3(2)
it's all about simplifying that root3(2x^5) (which you've done!) but also simplifying it a bit more by using the numerator
that seems to be the bit we can't get rid of out of the denominatotr
so yep 🙂
I didn't check them because it looked like you had got them down haha
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hi can someone help me with these problems for calc 2? i solved it but i think i messed up somewhere along the way. i will attach screenshots
opening another channel with the same question does not speed up the process of people answering it
i wasnt sure i thought you had left
my bad
this is my first time using this server
even if i had, there were people probably looking at it trying to help you before you closed it
no worries
someone will help eventually, i promise
i'm just not as well-versed in this math as i used to be, but i can find arithmetic mistakes when i see them
thats alright thank you for trying. hopefully someone can come and take a look at my problems soon! :-)
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In the first picture i think the (n+1) should be at the denominator because n!/(n+1)!=1/(n+1)
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$$
<@&286206848099549185>
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Let
$\mathbf{A}=\begin{bmatrix}1&0&0\6&1&0\9&8&1\end{bmatrix}
\begin{bmatrix}1&2&3&4\0&1&2&3\0&0&1&2\end{bmatrix}$
How would one determine the bases for the four subspaces of A without multiplying these matrices (namely the column and row spaces of A)? This was an assignment on my course last week and the solution started out by writing the 2 matrices and B and C, then showing we can write $A=[Bc_1, Bc_2, Bc_3, Bc_4]$ and stated that the first three columns now are LI since they are linear combinations of LI column vectors of B. The solution is hard for me to understand so im looking for any alternative explanations, im not able to find any similar problems online either
NTK
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Are you saying you want to find the column space of A?
Oh, nvm you said it
row and col, right
yes, technically i need to find C(A), C(A^T), N(A), and N(A^T) but if i can figure out how to work the col and row i can try to work nullspaces on my own
Okay, so the main claim is that row(A)=row(C) and col(A)=col(C)
the intuition i have for C(A) is that if we started multiplying we'd see that we end up with linear combinations of the first matrix, so probably C(A) is that?
yes, C(A) means the column space of A, and C(A^T) means the row space of A
This is a great intuition. You also need to prove that the resulting vectors are linearly independent.
But that is because the map X->BX is bijective, so it must preserve dimension.
Oh, I wrote it wrong earlier. I meant col(A) = col(B)
well for the first matrix its inversible so that should be proof enough that they are LI anyway, but is this enough to say that C(A)=span((1,6,9),(0,1,8),(0,0,1))
and i suppose for the row space you could denote again $A=BC$ and taking the transpose $(BC)^T=C^TB^T=A^T$ and follow similar logic
NTK
Of course you can. However, C^T is not invertible.
if you look at the rows of C, notably the zeros, it should be visible that the vectors are LI and the solution i have just stated as such so i think for independence thats enough proof
Your thoughts are very correct. To formalize them, perhaps you want to use the definitions of row- and column spaces.
Together wit the fact that both B and C^T have left inverses.
sure... how would you work out N(A)? here B is invertible, so Bx=0, so we can look at Cx=0 and find the solution from there, but i was wondering if theres any alternatives there
I don't think so. After all, finding N(C) is quite quick.
alright, i think thats good enough thinking about A being formed of linear combinations of B or C so thanks for your help
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multiplied lhs and rhs with 5-tv
left hand side and right hand side of the equal to sign...
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How do i find the mapping matrix?
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Ida has a package of ice cream, which she puts on a plate. The ice cream is in the shape of a rectangle. She cuts ice cream so that the length of the rectangle first decreases by 20% and then the width decreases by 20%. What percentage of the ice cream is left on the barrel now?
How do I solve it without drawing it up?
I solved it by drawing but I don’t think I’ll get points for it
,rcw
Wait it’s just the top one
The one on the lower half of the page is another question 😅
The idea is to express the length and breadth of the smaller rectangle in terms of the length and breadth of the larger rectangle
assume length of larger rectangle to be 'l' and breadth of the same to be 'b'
Mhm
Now, 20% of l is decreased.
i.e. length of smaller rectangle is basically l-(20/100)l
a similar approach would be applied for the breadth
so what is your answer?
80/100
width of smaller rectangle would be b-(20/100)b
yes
read it again
It decreases to
yes
Ok what now
find area of both the rectangles

😭
original rectangle and the smaller rectangle
percentage of the ice cream left =((area of small rect.)/(area of large rect.))*100
0.64*l*b would be more appropriate
?
area of large rectangle would be l*b
and that of smaller would be 0.64*l*b
sure their ratios would be 1:0.64
The answer is 64 %
yes
kind of
are you sure 'bout that
No
wait let me think of one
Hhhhh
a rectangle has dimensions 30*20. Its length is halved. From the new rectangle formed, its length is decreased by (100/3)%. Find percentage of area reduced. Given Hint:||length>breadth at all times||
Also did you just had a test with this question on it and messed it up?
oh well
are you sure?
IDK
It would be advisable to read the hint
I already know that
and clearly see what the question asks for
yes
And that represents
the new ||name it||
Length 👍👍👍👍👍👍😄
no
well 15<20
20 would become the new length of the rectangle
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You are going to make a shelter for a dog. The enclosure must be shaped like a rectangle and must stand against a house wall. You have 10 meters of fence. We let the short side of the rectangle be x meters. One long side must lie next to the house wall (without a fence).
A) Show that the area A (in square meters of the air space is given by A = 10x - 2x^2
B) How long are the sides of the rectangle when the air space has an area of 12m^2?
C) Investigate whether the shelter space can have an area of 15m^2
An object is composed of a cylinder and a cone as shown in the figure.
The radius of both the cylinder and the cone is r. The cone has height h. The cylinder is three times as tall as the cone.
A) Find the volume V of the object expressed in terms of r and h
B) Find r expressed in terms of V and h
A) Show that the division (2x^3 + 5x^2 - x - 6) : (x+2) goes up without performing the division
B) Solve the equation 2x^3 + 5x^2 - x -6 = 0
C) Factor the expression 2x^3 + 5x^2 - x -6
D) Subtract the fraction (2x^3+5x^2-x-6)/(2x+3)
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How do i prove Triangle Inequality for this term?
Been sittin on it for a very long time and ivenot moved forward at all
nice troll, if any1 canhelp id appreciate^^
Im supposed to check whether that term is a metric
ive proven its symmetric and its always positive
but im stuck on proving triangle equality
Easiest way imo would probably be to show that it’s induced by an inner product
Then all norms induced by inner products satisfy the triangle inequality
Could u ELI5? we just got introduced into this topic and its alot all at once
this phrase
also, yes. and its calcualting the distance of (x1,x2) to (y1,y2) i believe
Basically you have norms on vector spaces, which satisfy similar properties to metrics (and any norm can be used to create a metric)
<@&268886789983436800>
Anyways, not sure whether you’ve seen them before, but similarly there are inner products on vector spaces (and any inner product can be used to create a norm)
For inner products, the norms they create have to satisfy the triangle inequality for norms because of Cauchy Schwartz
So it might be a bit less pain showing that you can create an inner product that would end up forming this metric
(You can do it without it, but if I recall it’s a bit more work to do)
I think without is probably what im supposed to be doing
i mean i would probably do it by supposing a point z
of coordinates (x1,y2)
and assuming x1/=/y1 and x2/=/y2; proving that xyz is a right triangle
then using pythagoras to find the distance
@twin quail Has your question been resolved?
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Can anyone help/walk me throught his please^^
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I can’t figure out how to do #14
Comes from chapter 5.3 of Kreyszig’s advanced engineering mathematics 7th ed
I’ve tried finding a series that I can use in place of the right hand side but I’ve had no luck
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Write the right side as a binomial expansion or Taylor series and you'll see it only has even powers of u
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how does one do this?
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$\log_{16}\frac{1}{128}=x\Leftrightarrow 16^{x}=\frac{1}{128}\Leftrightarrow 2^{4x}=2^{-7}\\\Leftrightarrow 4x=-7\Leftrightarrow x=-\frac{7}{4}\\\log_{16}\frac{1}{128}=-\frac{7}{4}$
Joanna Angel
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chlamydia
as represented by the single red line there that's supposed to be a minus
merging 2 statements by subtracting them
the a gets canceled out, $b - (-b) = b + b = 2b$, and $-1 - 5 = -6$
FungusDesu
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Can't proceed really
are you able to find the bounds of the range
show your diagram. you must've inyerpreted it wrong
Minimum angle 15°, maximum angle 75° but there is an interval 53° between 15° and 75° , which is not allowed for successful shot
This what written in answer
can you now find the minimum and maximum range?
no
Not really
convert it to sin(2x)
well then there must be some misinterpretation or if not then the answer is wrong
oh wait
are you aware of the fact that complementary angles have the same range
@vast shale
Yes
so theta=15 and theta=75 would have the same projections
well you just concluded that minimum angle would be 15 and max would be 75
the only thing left is to prove 53 does not work
but there seems some issue with that point
18.5 and 71.5 will be inside 15 and 75 so it's done
the answer says 53 won't work
Yea
Yeah lol
since they are complimentary
I got a conclusion
Answer will be 15°to 18.5°
And 71.5°to 75°
Even 45 30 60 non gonna work
Including 53
They just didn't wrote answer correctly
What do you say
@merry python
I applied those angles to check answer
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yes
-35
year 10
really?
💀
nah lol
thanks
arent these just with factors
damn
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Good afternoon, colleagues. I'm struggling with specific formula. I have mathematical formulas, which I need to calculate and based on it my question is:
Does anyone know any related to it good analogues for getting calculated steps with explanations?
In Wolfram Alpha and Symbolab, I'm getting the issue as:
No Steps: Steps are currently not supported for this problem - Symbolab
or simply no results related to it.
To clarify:
I'm not asking about 'How to do it/How easy is it', I'm asking:
'What resources can be used for it and why it would be helpful for my use case.'
P.S. If you don't know, at all, this topic and how to help, please, ignore it and don't waste my time on empty talk.
Thank you in advance for your help.
@placid gust Has your question been resolved?
@placid gust Has your question been resolved?
@placid gust Has your question been resolved?
this operation you're showing is called convolution
What resources can be used for itso you're looking for tools than can compute it for you ? just to be sure what you wanthelpful for my use case, what's your use case ? maybe it's important to know
@placid gust
- I‘m looking for a tool which helps to understand how should I calculate it correctly. I‘ll compare it with my theory stuff. I need to understand the principle of calculating it.
-
Under „use case“ I mean this specific formula, @cyan talon
-
I've been given a fairly tight deadline, so I want to speed up my approach to research. My vision of this is to start with an example of a calculation, and then, supported by theory, solve something similar freely.
@placid gust Has your question been resolved?
@placid gust Has your question been resolved?
Btw close it if you're done
Why're you after closing help channels?
.close
???
Nothing
@placid gust Has your question been resolved?
Hello, buddy. I didn't solve it. I'll close it if I don't receive the answer from @cyan talon , at least, today. I'm struggling with it, for this reason, my question is still on hold.
@placid gust I didn't see your ping from yesterday, discord doesn't help very much
- I'm not aware of a tool which would explain you in detail how convolutions are computed, like say wolfram (or another symbolic math tool) understood your query and could tell you the steps, it prolly would just say
ok we have to compute the convolution .... the result is ....with no inbetween. There's a lot of resources explaining convolution though, it's not a completely niche thing, it shows up in quite a few places. (signal processing, probability at least) - ok I thought you had a specific application of that formula in mind already, that's what
use casesounds like to me - I can show you a typical example of a calculation which involves convolutions (with probability), I'll wait for you to come back if you wish to see it
Yes, I'm here, please, write me your thoughts👍
btw you can use some integral transform or the discrete version of it if you want a "tool" for it
for suitable transforms, the convolution becomes an elementwise multiplication and an inverse transform
if you simply want to check your work on it, there are things like numpy.convolve that will compute it for you
but other than that, just follow the mathematical formula I guess
here's a very basic example, let's say I throw two dice (one has 10 sides, from 1 to 10, the other has 12 sides, 1 to 12, the sides on each die show up with equal probability 1/no. of sides).
Now I throw these two dice and I look at the sum of the two numbers I get : are you able to compute the probability that the sum of the two dice is, for example, 14 ?
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what am i supposed to even do here, how do i start approaching this question
is this trig sub?
You can either:
- Evaluate the integral and solve for c
or - Do it geometrically, by showing what kind of area the integral is representing
of course, I advise against the first approach since the equation that yo uare going to solve is not very pretty
and yes, you can use trig sub here
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im so confused
This is a log chapter so were supposed to use logs. But I dont know what to do for question a
Initial mass is 5g
t is 150 years
And half life is 1620 years
Just put in those values
yeah but
isnt M(t) the half life?
And I have to find the remaining mass
Maybe i should say M(t) = (P_f-Pt)^t/h then plug it in to find P_f? which is the final mass
M(t) is mass at time t
oh
Nice
and for b, i should just use logs to find out t, right?
then rearrange to isolate t
alright, thanks
Np
@empty linden Has your question been resolved?
Over here, it should've been n-1 instead of n in the first line
Oh no mb
It's correct
But
2000= 40*10^n
So 10^n = 50
So n= log 50
That's like 1.69
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oh
yeah i forgot about the log outside the 2000/40
Ye
vinland saga!
.
np
Ok
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