#help-17

1 messages · Page 117 of 1

languid dune
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i did C and its wrong

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so it cantbe that

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it could be A too the way its moving

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man i hate this problem

hushed pewter
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Yeah. It's a bad problem

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I sympathize with you, it's so arbitrary

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I saw A and C, but answer disagrees with C.

languid dune
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F seems a bit far

hushed pewter
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Bring this problem up to your teacher. Be sure to use the word "bullshit" a few times

languid dune
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lmao

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Ill do A tbh

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its my last attempt on this problem

hushed pewter
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It's a bad problem

languid dune
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oh shit it says select all that apply wtf

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there can be more than one answer

hushed pewter
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As a self diagnosed genius, I will assure you that this problem is not worth the effort.

hushed pewter
languid dune
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bro that makes ti worse lmao

hushed pewter
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Gg

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I vote ECA

languid dune
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ye im with that too

hushed pewter
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F is a maybe, but I think no

languid dune
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same

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lmao ECA is wrong

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cooked

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what a shit problem

hushed pewter
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Does it at least say the answer?

vocal sleetBOT
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@languid dune Has your question been resolved?

languid dune
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sly stag
#

I have a metric tensor
1 0
0 r^2
which just describes the rate of change of the relative coordinate from polar coordinates to cartessian coordinates right?
So my line element equation would be
ds^2 = 1 * dr^2 + r^2 * dθ^2

Now i simply want to find the length from point r = 1, θ = 0 and r = 2, θ = pi / 2. How would i do that?

vocal sleetBOT
#

@sly stag Has your question been resolved?

sly stag
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<@&286206848099549185>

vocal sleetBOT
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@sly stag Has your question been resolved?

vocal sleetBOT
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@sly stag Has your question been resolved?

vocal sleetBOT
#

@sly stag Has your question been resolved?

vocal sleetBOT
#

@sly stag Has your question been resolved?

timber orchid
#

this is higher level stuff i think (tensors), maybe there's a another dedicated channel to this stuff?

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@sly stag Has your question been resolved?

flat quartz
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torpid skiff
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how can i show that something is a point of inflection using diffrentiation

fervent sparrow
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f''(x)=0

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@torpid skiff

fervent sparrow
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so if i take a degree 3 for example, theres gonna be like 2 concavities formed by 3 x-intercepts

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ykwim?

torpid skiff
fervent sparrow
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the x value you get from f"(x)=0 shows you the point at which the concavity changes

torpid skiff
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so i just diffrentiate 2 times then show it = 0

fervent sparrow
fervent sparrow
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it wont work for quadratics cuz second derivative becomes a constant n stuff sooo yea

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equating it to 0 wont make sense

fervent sparrow
torpid skiff
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incase you were wondering lmao

fervent sparrow
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ye so point of inflection's 0.5

torpid skiff
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cheers thanks

fervent sparrow
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np

torpid skiff
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.close

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wary mantle
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"If $f$ is injective and $g$ is surjective, then $g \circ f$ is bijective."

wary mantle
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Why?

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f is injective, sure

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g is surjective, sure?

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But not really

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What about 0? It should be R_0^+, no?

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This is just like what we did before with @median crane

patent onyx
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R^+ does not contain 0

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its all positive real numbers, and 0 is not positive

wary mantle
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And for x = 0, we'll have 0

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So why does it say R -> R^+

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Shouldn't it say R -> R_0^+

patent onyx
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true

wary mantle
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Though this is written by a professor so maybe not?

patent onyx
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your claim is correct

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g(0)=0 not a real positive

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the professor is wrong on the codomain

magic wasp
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R^+ does include 0

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It's somewhat ambiguous but most of the time R_*^+ is used to exclude 0

wary mantle
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Thank you

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wary mantle
magic wasp
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The non-ambiguous notation is R_{>=0}

vocal sleetBOT
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young cosmos
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How can this rule exist?

vocal sleetBOT
pale perch
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could you show the actual rule as it was presented to you

median crane
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visual anvil
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yo

vocal sleetBOT
visual anvil
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Can someone check my work

dire token
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Bruh

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Get another channel

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Nvm

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.close

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@visual anvil Has your question been resolved?

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@visual anvil Has your question been resolved?

visual anvil
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untold comet
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Please help!

vocal sleetBOT
untold comet
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I haven't leared this yet so I'm not sure what to do

river kettle
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Just plot the points first

untold comet
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That's the thing idk how

river kettle
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Wdym

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Just look at the table

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At x=-5 you plot a point 7 units above

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(-5,7)

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And do that for the rest

vocal sleetBOT
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drifting jackal
#

Please don't troll in help channels

vocal sleetBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

tidal dock
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depends on how you define 1 and +

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1 apple and another apple make 2 apples together 🤯🤯🤯🤯🤯

crude arrow
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you need a lot

tidal dock
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here you go

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no problem lmao

crude arrow
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Principia Mathematica took over 1000 pages to prove that 1+1=2

tidal dock
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yep

drifting jackal
tidal dock
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wonderful

tidal dock
crude arrow
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wo-hoo!

waxen portal
#

#rules

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vocal sleetBOT
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red orbit
#

I know this relates to trigonometry and would require the use of sin, cos, and tan, but am stuck on how to solve the problem.

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fiery crest
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(yy')'=5/2(y')^2

vocal sleetBOT
fiery crest
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.close

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haughty warren
vocal sleetBOT
haughty warren
#

Could somebody please tell me where I'm going wrong

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The partial fractions I get don't make sense

fleet ember
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A/(x+1) + B/(x+1)² + Cx+D/(x²+1)
= (A(x+1)(x²+1)+B(x²+1)+(Cx+D)(x+1)²)/(x+1)²(x²+1)

haughty warren
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Oh damn

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I forgot about how u multiply it out weirdly

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Thx

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hearty dragon
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marble kettle
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can someone explain?

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b/a gives a rational int and the other one shows the relationship between the two numbers and is either true or false

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but i still dont understand how that affects these

somber badger
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b|a means b divides a

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b/a is just division

serene cloud
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they are all right except the b is 0

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i mean a

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b divided by a and a can never be 0

marble kettle
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oh and i missed one earlier

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wait so can there be decimals or they have to be integers?

floral pike
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🤔 you can do 0/9, but is 9|0 a true statement or a false statement? Technically, 9 divides 0 zero times

serene cloud
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the denominator (in this case is a) can never be 0, i dont really know why but its a rule in calculus or sth. It can be understand by you cannot divide anything by 0

marble kettle
serene cloud
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the term below

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so 9/0 is wrong

vast shale
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since that would imply that there is a number that can be multiplied by 0 to be 9

marble kettle
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i meant b|a

serene cloud
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but 0/9 is right

marble kettle
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its not 0/9 its 0|9

vast shale
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yes 0|9 is right

marble kettle
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so that means 0|7 is right

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?

vast shale
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yes

serene cloud
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wait

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you are studying logic right?

marble kettle
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yes

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mathematical reasoning

serene cloud
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then i'm not so sure

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cuz that is a bit different from math

vocal sleetBOT
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@marble kettle Has your question been resolved?

magic wasp
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Wow I think you're all confused

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0|a is never right (except if a=0, in some contexts)

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$n | m \iff \exists k : kn = m$

twin meteorBOT
magic wasp
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Can you find a k such that k*0 = 7?

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@marble kettle

vocal sleetBOT
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@marble kettle Has your question been resolved?

marble kettle
marble kettle
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i didnt even know what to google to try and find the answer

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lol

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like to understand the concept

magic wasp
marble kettle
#

.close

vocal sleetBOT
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visual anvil
#

anyone good with spherical coordinantes to cartesian transformation

visual anvil
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given the surface of a spherical coordinates: ρ^2 = sec (2φ) where 0 <= φ <= pi/4 express
this surface in Cartesian coordinates and state what type of surface it is.

vocal sleetBOT
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@visual anvil Has your question been resolved?

visual anvil
#

<@&286206848099549185>

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This is what I've tried

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but I cant get a defininte answer

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fiery bear
#

can someone help me with the LDE

vocal sleetBOT
fiery bear
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i have the final answer but its slightly diferent from what the textbook has

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this is the textbook solution

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These are the roots I’m getting

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I dont understand why I cant do this , to get alpha and beta
I thought I could simplify it like that but is it wrong?

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nvm I was confusing my self

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i kept misclking in my calcualtor... divided whole thing by 3 and realized i didnt need to sepearte cuz theres no imaginary

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thanks anyways

#

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torn tree
vocal sleetBOT
torn tree
#

This is what I have so far, but I feel like I've gone off track.

hard atlas
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it might be easier to define a homomorphism Q[x]->Q[sqrtp] and then use the isomorphism theorem

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(in general when you see a factor ring in situations like this, the first idea should most of the time be "iso theorem")

hard atlas
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I'm curious, whats part (1) of the problem?

hard atlas
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ok

torn tree
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It looks deceptively simple, since it's something I could have completed 2 months ago. I feel like there's a catch or something

hard atlas
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with iso theorem its not that hard. assuming of course you had that 2 months ago

torn tree
hard atlas
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oh that

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well you only need to find inverses

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and you already know how to find those in R. so you can find them there first and show that they are actually already in Q[sqrtp]

vocal sleetBOT
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@torn tree Has your question been resolved?

torn tree
#

This is what I tried

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Is writing f as (something) + (something)*sqrtp the right approach or do I need to try something else?

hard atlas
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the notation Q[x]->Q[sqrtp] already suggest that we should replace x by sqrtp

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in other words, the evaluation homomorphism

torn tree
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oh

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I'm overthinking it too much lol

torn tree
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vocal sleetBOT
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@torn tree Has your question been resolved?

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flat quartz
#

How to integrate this?

vocal sleetBOT
#

@flat quartz Has your question been resolved?

vocal sleetBOT
#

@flat quartz Has your question been resolved?

flat quartz
#

No

unborn wind
#

! status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
flat quartz
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I tried cosx=u

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There is x at the beginnin

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1+cos² = u
I thought ain't even worth trying it will give sin*cos etc

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Step 1 probably

grizzled halo
#

looks like by parts

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,w integrate xsinx/(1+cos^2x)

grizzled halo
#

are you sure there aren't bounds?

tribal moss
#

$\int_{0}^{\pi}\frac{xsinx}{1+cos^{2}x}dx=\left[ x=\pi-y \right]
=-\int_{\pi}^{0}\frac{\left( \pi-y \right)\sin\left( \pi-y \right)}{1+\cos^{2}\left( \pi-y \right)}dy=\int_{0}^{\pi}\frac{\left( \pi-y \right)\sin\left( y \right)}{1+\cos^{2}y}dy=\pi\int_{0}^{\pi}\frac{\sin\left( y \right)}{1+\cos^{2}y}-\int_{0}^{\pi}\frac{y\sin\left( y \right)}{1+\cos^{2}y}dy\\<=>\\2\int_{0}^{\pi}\frac{xsinx}{1+cos^{2}x}dx=\pi\int_{0}^{\pi}\frac{sinx}{1+cos^{2}x}dx=\left[ t=cosx \right]=\pi\int_{1}^{-1}\frac{-dt}{1+t^{2}}=\pi\left( \frac{\pi}{4}+\frac{\pi}{4} \right)=\frac{\pi^{2}]}{2}\<=>\\\int_{0}^{\pi}\frac{xsinx}{1+cos^{2}x}dx=\frac{\pi^{2}}{4}$

twin meteorBOT
#

Joanna Angel

flat quartz
#

Thanks

#

.close

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copper pebble
vocal sleetBOT
copper pebble
#

not sure how to begin

vocal sleetBOT
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@copper pebble Has your question been resolved?

copper pebble
#

with a multiplicity of 3

flat whale
#

How did you show that

copper pebble
#

it was z^3

flat whale
copper pebble
# flat whale Show your work

i took the determinant of the matrix by expanding from column 1, which got me:

lambda * (lambda * lambda - 1 * 0) = lambda^3

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but i write lambda as z normally

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so now we have a polynomial, which can be written as:

(lambda-0)(lambda-0)(lambda-0)

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which means the multiplicity of 0 is 3

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not sure how to progress here since we don't know the value of lambda

flat whale
#

That's not how you find eigenvalues

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You just set the determinant to 0

copper pebble
#

right

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how else would you do it ?

flat whale
#

The eigenvalues of a matrix are the scalars by which eigenvectors change when some transformation is applied to them. Learn how to find the eigenvalues of 2x2 and 3x3 matrices using the characteristic equation with examples.

copper pebble
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right

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the eigenvalue is lambda

flat whale
vocal sleetBOT
#

@copper pebble Has your question been resolved?

copper pebble
#

For lambda

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🙂

copper pebble
#

<@&286206848099549185>

jolly roost
#

Yes

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@copper pebble

copper pebble
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Just need help with the question

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I got triple root for lambda

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not sure what to do now

jolly roost
#

?

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@vocal sleet

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<@&286206848099549185>

#

Hi

copper pebble
#

hi

jolly roost
#

What do you need help with?

#

@copper pebble

copper pebble
#

this

jolly roost
#

@copper pebble Professional assistance. <@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

copper pebble
#

@flat whale

copper pebble
#

its quite difficult

jolly roost
#

@vocal sleet

#

bernie.madoff

copper pebble
#

yes?

jolly roost
#

Friend request

flat whale
flat whale
jolly roost
#

@copper pebble

#

Hi

copper pebble
copper pebble
#

<@&286206848099549185>

flat whale
#

and be specific

copper pebble
#

That’s about it

flat whale
flat whale
#

step 2: figure out the solution for triple root

copper pebble
#

I found the triple root

#

I just want it in a dumbed down way

#

Because I don’t understand all the notation in your article

flat whale
copper pebble
#

The weird N with the arrow

#

Never seen it in my life

flat whale
#

$\eta$ is a variable

twin meteorBOT
#

riemann

flat whale
#

like x, or y

#

$\vec{x}$ is notation for a vector. in three dimensions, $\vec{x} = (x_1, x_2, x_3)$

twin meteorBOT
#

riemann

copper pebble
flat whale
# copper pebble

In this case, your equation can be given as
$\vec{f}' = A \vec{f}$

twin meteorBOT
#

riemann

copper pebble
#

Does this look like my exercise?

flat whale
flat whale
copper pebble
#

With Eigenvalues on the diagonal

flat whale
#

to your problem in 3 dimensions, you should understand 2 dimensions first

flat whale
#

this is the solution for the 2d case

copper pebble
#

i still don't understand why we have n ->

#

and then p ->

#

what are these variables for

flat whale
#

i don't understand your questions. they're all explained in the link

copper pebble
#

I solved it now

#

Basically just assuming that f_3(t) = 0 and f_2(t) = 0 while f_1(t) = e^lambda*t

#

Then assuming that f_3(t) = 0 and f_2(t) = e^lambda*t and then calculating f_3(t)

#

then doing it again but where f_3(t) = e^lambda*t

#

.close

vocal sleetBOT
#
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zinc quail
#

What's the direct translation of the limes superior using propositional calculus? (for sequences)

vernal wigeon
#

Limit inferior and limit superior

zinc quail
#

only superior, inferior is trivial if I know the other

#

after fiddling a bit, this is how I'd translate it

#

most sites like wikipedia etc. I stumbled upon offer no direct translation this way but I have to use it for proofs

hard atlas
#

the sequence doesnt have to be smaller than the limsup

zinc quail
hard atlas
#

no

#

take any converging sequence. then limsup is the limit. but we know it doesnt have to hold then

zinc quail
#

so the first expression is correct I presume? but how would I rewrite the second for the equivalence to hold

hard atlas
#

well you could say the standard "and for all s such that there exists a partial sequence converging to s, you have s<=r"

zinc quail
#

hm yeah although I'm not sure that helps me with the proof for the criteria such as the root criterion

hard atlas
#

well you could also just write it as the limit of the supremums

#

and then unpack all those definitions

zinc quail
#

I'd have to express something like "if that limit isn't the limit of a_n, then the second statement holds"

#

ah yeah actually I could directly translate that

#

@hard atlas probably not a work of art, but it'd be in the form I could use for multiple proofs :3

#

I think it must be exclusive right, if the lim sup is not the limit, then there must exist an n_0 such that the last statement is true

#

in turn achieving equivalence

hard atlas
#

no

#

the converging sequence was just an example

#

imagine two converging sequence and alternate between them

#

the limsup will be the bigger of the two limits

zinc quail
#

but how does that make the expression false

#

lim(a_n) = r would then be False

#

hm nvm right they still wouldn't have to be below

#

ugh so I need an additional variable for an environment

#

Ok, so now it either converges to r OR a subsequence converges to r and all values must be within the upper-bound epsilon-environment from n_0 onwards

#

@hard atlas sry for ping, but I hope it's correct now

hard atlas
#

you dont need the extra condition of it converging

#

but yes now it works

vocal sleetBOT
#

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vast shale
#

who can help me review slopes?

vocal sleetBOT
vast shale
#

.closee

mental falcon
vast shale
#

.close

vocal sleetBOT
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left talon
#

ye

#

u can check by doing this:
3*(x^5y)^(0.25) -2x(xy)^(0.25)

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mighty vapor
#

can anyone confirm if i got this correct?

vocal sleetBOT
#

@mighty vapor Has your question been resolved?

mighty vapor
#

.close

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snow dune
vocal sleetBOT
snow dune
#

Im not sure what the trick is for solving this one

sweet birch
#

well you have a total of N items in the list (find N)
so the number you're looking for is the Nth item

how many elements will start with 1? will this reach the Nth number?

snow dune
sweet birch
#

oh sorry! yes, I was looking at the last number of the smallest part

#

so yes, you'd be looking for the N+1th number

#

where N is the total ways you can organise the numbers 12345

snow dune
#

but im not quite sure how to determine the 61'th number

sweet birch
#

yep - and, I am sure there is a "smart" way to do this but I'm afraid I'm not too sure, you can also work out which bucket it falls in - if it's in 1xxxx or in 2xxxx or 3xxxx or 4xxxxx or 5xxxx

#

once you find it's in the bucket axxxx, you can then work out which abxxx it's in

#

and so on

frank cosmos
#

hi

snow dune
frank cosmos
#

need holp?

snow dune
frank cosmos
#

aight lemme repaste it

#

just so it's not far up

#

oh

snow dune
frank cosmos
#

i see

#

i think its 61

#

so

snow dune
frank cosmos
#

it will be the 61st

#

of all the numbers

snow dune
frank cosmos
#

ok i see

snow dune
#

the 59'th biggest and the 61'th smallest are the same

sweet birch
#

how many numbers will start with 1XXXX?

snow dune
#

4!?

frank cosmos
frank cosmos
snow dune
sweet birch
#

...no, it's 4!.

frank cosmos
#

oh right

sweet birch
#

please stop spreading misinfo.

frank cosmos
#

lol i didnt see the !

snow dune
#

yeah that man is confusing 🤷

frank cosmos
#

i thought he was using it in a non math way

#

sorry

snow dune
#

so 16 in 1xxxx and 16 in 2xxxx, so it must be in 3xxxx i guess

#

or wait no

#

4xxxx

sweet birch
#

well 3xxxx starts at 2*4! and ends at 3*4!-1

frank cosmos
#

well, if 1xxxx has 4! then 2xxxx and 3xxxx and 4xxxx and 5xxxx should have 4! too

snow dune
#

ok im stupid 4!=24

#

so its in 3xxxx

frank cosmos
#

yeahj

sweet birch
#

you can work out how far into 3xxxx it is

#

and then repeat this for finding the next x

snow dune
#

yeah i think i can just do it manually from here on

sweet birch
#

the longer form is that the number will be a(4!) + b(3!) + c(2!) + d(1!) = 61

frank cosmos
#

good luck

sweet birch
#

knowing each of a-d is >0, it's just finding the largest possible value

frank cosmos
#

@snow dune wanna close this or

snow dune
#

.close

vocal sleetBOT
#
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sweet birch
#

the last one as in, M)?

#

oh hang on sorry I misread the Q

#

no my fault

#

well you can divide the cube root of 2x^2 into two parts, (2)^1/3 and (x^2)^1/3 right

#

as you already did for taking the x outside the root

#

and if you have something like $\frac{a}{bx}$ you can instead make $\frac{a}{b} * \frac{1}{x}$

twin meteorBOT
#

PrettyPrincessKitty FS

sweet birch
#

i.e. you can take your numerator - just constant number terms - and the part of your denominator with just constant number terms and combine them into one big numerator

#

and you'll get $\frac{(a/b)}{x}$

twin meteorBOT
#

PrettyPrincessKitty FS

sweet birch
#

simplifying only needs to get rid of those yucky root(x) terms, the rest are constants you can combine

#

no

#

also root3(4) = root3(2*2) = root3(2)*root3(2)

#

it's all about simplifying that root3(2x^5) (which you've done!) but also simplifying it a bit more by using the numerator

#

that seems to be the bit we can't get rid of out of the denominatotr

#

so yep 🙂

#

I didn't check them because it looked like you had got them down haha

vocal sleetBOT
#
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steel zephyr
#

hi can someone help me with these problems for calc 2? i solved it but i think i messed up somewhere along the way. i will attach screenshots

pallid forge
#

opening another channel with the same question does not speed up the process of people answering it

steel zephyr
#

i wasnt sure i thought you had left

#

my bad

#

this is my first time using this server

pallid forge
#

even if i had, there were people probably looking at it trying to help you before you closed it

#

no worries

#

someone will help eventually, i promise

steel zephyr
#

ok

#

thank u

pallid forge
#

i'm just not as well-versed in this math as i used to be, but i can find arithmetic mistakes when i see them

steel zephyr
#

thats alright thank you for trying. hopefully someone can come and take a look at my problems soon! :-)

vocal sleetBOT
#

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#

@steel zephyr Has your question been resolved?

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steel zephyr
#

.reopen

vocal sleetBOT
#

rocky olive
#

In the first picture i think the (n+1) should be at the denominator because n!/(n+1)!=1/(n+1)

vocal sleetBOT
#

@steel zephyr Has your question been resolved?

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@steel zephyr Has your question been resolved?

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vocal sleetBOT
regal parrot
#

.close

vocal sleetBOT
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rugged fjord
vocal sleetBOT
#

@rugged fjord Has your question been resolved?

rugged fjord
#

<@&286206848099549185>

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rough barn
#

Let
$\mathbf{A}=\begin{bmatrix}1&0&0\6&1&0\9&8&1\end{bmatrix}
\begin{bmatrix}1&2&3&4\0&1&2&3\0&0&1&2\end{bmatrix}$

How would one determine the bases for the four subspaces of A without multiplying these matrices (namely the column and row spaces of A)? This was an assignment on my course last week and the solution started out by writing the 2 matrices and B and C, then showing we can write $A=[Bc_1, Bc_2, Bc_3, Bc_4]$ and stated that the first three columns now are LI since they are linear combinations of LI column vectors of B. The solution is hard for me to understand so im looking for any alternative explanations, im not able to find any similar problems online either

twin meteorBOT
vocal sleetBOT
#

@rough barn Has your question been resolved?

vocal sleetBOT
#

@rough barn Has your question been resolved?

river wagon
#

Oh, nvm you said it

#

row and col, right

rough barn
#

yes, technically i need to find C(A), C(A^T), N(A), and N(A^T) but if i can figure out how to work the col and row i can try to work nullspaces on my own

river wagon
#

Okay, so the main claim is that row(A)=row(C) and col(A)=col(C)

rough barn
#

the intuition i have for C(A) is that if we started multiplying we'd see that we end up with linear combinations of the first matrix, so probably C(A) is that?

river wagon
#

wait, I need to think

#

Do you use C to denote the column space?

rough barn
#

yes, C(A) means the column space of A, and C(A^T) means the row space of A

river wagon
#

But that is because the map X->BX is bijective, so it must preserve dimension.

#

Oh, I wrote it wrong earlier. I meant col(A) = col(B)

rough barn
#

well for the first matrix its inversible so that should be proof enough that they are LI anyway, but is this enough to say that C(A)=span((1,6,9),(0,1,8),(0,0,1))

#

and i suppose for the row space you could denote again $A=BC$ and taking the transpose $(BC)^T=C^TB^T=A^T$ and follow similar logic

twin meteorBOT
river wagon
#

Of course you can. However, C^T is not invertible.

rough barn
#

if you look at the rows of C, notably the zeros, it should be visible that the vectors are LI and the solution i have just stated as such so i think for independence thats enough proof

river wagon
#

Your thoughts are very correct. To formalize them, perhaps you want to use the definitions of row- and column spaces.

#

Together wit the fact that both B and C^T have left inverses.

rough barn
#

sure... how would you work out N(A)? here B is invertible, so Bx=0, so we can look at Cx=0 and find the solution from there, but i was wondering if theres any alternatives there

river wagon
#

I don't think so. After all, finding N(C) is quite quick.

rough barn
#

alright, i think thats good enough thinking about A being formed of linear combinations of B or C so thanks for your help

#

!close

river wagon
#

.close

rough barn
#

oh ty

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
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umbral snow
#

guys

vocal sleetBOT
umbral snow
#

what they did

#

to get 2nd row

cedar kernel
#

multiplied lhs and rhs with 5-tv

umbral snow
#

hmmmmmm

#

hmmmmmmmmmmmmm

#

lhs rhs

cedar kernel
#

left hand side and right hand side of the equal to sign...

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brazen scroll
#

How do i find the mapping matrix?

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#

@brazen scroll Has your question been resolved?

brazen scroll
#

<@&286206848099549185>

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vast shale
#

Ida has a package of ice cream, which she puts on a plate. The ice cream is in the shape of a rectangle. She cuts ice cream so that the length of the rectangle first decreases by 20% and then the width decreases by 20%. What percentage of the ice cream is left on the barrel now?

vast shale
#

How do I solve it without drawing it up?

#

I solved it by drawing but I don’t think I’ll get points for it

merry python
#

,rcw

twin meteorBOT
vast shale
#

Wait it’s just the top one

#

The one on the lower half of the page is another question 😅

merry python
#

The idea is to express the length and breadth of the smaller rectangle in terms of the length and breadth of the larger rectangle

#

assume length of larger rectangle to be 'l' and breadth of the same to be 'b'

vast shale
#

Mhm

merry python
#

Now, 20% of l is decreased.
i.e. length of smaller rectangle is basically l-(20/100)l

#

a similar approach would be applied for the breadth

vast shale
#

Wait

#

What

#

Ohhhh

#

I get it now

#

But then

merry python
#

so what is your answer?

vast shale
#

The width is also 20/100

#

? 😅

merry python
#

no

#

width is reduced by 20%

vast shale
#

80/100

merry python
#

width of smaller rectangle would be b-(20/100)b

merry python
vast shale
#

What

#

Then why is the length 20/100

merry python
#

read it again

vast shale
#

It decreases to

merry python
#

i.e. length of smaller rectangle is basically l-(20/100)l

#

l-(20/100)l=(80/100)l

vast shale
#

Ohhhh

#

So it’s the same

merry python
#

yes

vast shale
#

Ok what now

merry python
#

find area of both the rectangles

vast shale
#

What

#

But there’s only one

merry python
vast shale
#

😭

merry python
#

original rectangle and the smaller rectangle

vast shale
#

Ohhhh

#

Uhm

#

0,64

#

And 1

merry python
#

percentage of the ice cream left =((area of small rect.)/(area of large rect.))*100

vast shale
#

Wait wtf

#

How

#

🤩

merry python
vast shale
#

?

merry python
#

area of large rectangle would be l*b

#

and that of smaller would be 0.64*l*b

#

sure their ratios would be 1:0.64

vast shale
#

The answer is 64 %

merry python
#

yes

vast shale
#

So u just multiply 0,8*0,8

#

Or

#

Yeah

merry python
#

kind of

vast shale
#

Wym

#

Can u give me a similar question

#

So I can practice

merry python
#

are you sure 'bout that

vast shale
#

No

merry python
#

wait let me think of one

vast shale
#

Hhhhh

merry python
#

a rectangle has dimensions 30*20. Its length is halved. From the new rectangle formed, its length is decreased by (100/3)%. Find percentage of area reduced. Given Hint:||length>breadth at all times||

merry python
vast shale
#

No

#

I’ll have it on the test tho

#

So I can’t mess it up 😃

merry python
#

oh well

vast shale
#

By 3/100 %

#

U mean 0,03 pro cent?

#

Or 3 pro cent

#

😭

merry python
#

are you sure?

vast shale
#

IDK

merry python
#

It would be advisable to read the hint

vast shale
#

I already know that

merry python
#

and clearly see what the question asks for

vast shale
#

Ok the length is halved

#

So the length is now 15

#

Right 😭

merry python
#

yes

vast shale
#

And that represents

merry python
#

the new ||name it||

vast shale
#

Length 👍👍👍👍👍👍😄

merry python
#

no

vast shale
#

Ughhh idk

#

Ur question is hard

merry python
#

well 15<20

vast shale
#

OMG

#

I wrote that

#

But what does that have to do with it

merry python
#

20 would become the new length of the rectangle

vast shale
#

OH

#

I got a decimal

#

66.67%

merry python
#

yes

#

nice work

vast shale
#

OMGGG

#

thank u

#

.close

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#
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vast shale
#

You are going to make a shelter for a dog. The enclosure must be shaped like a rectangle and must stand against a house wall. You have 10 meters of fence. We let the short side of the rectangle be x meters. One long side must lie next to the house wall (without a fence).
A) Show that the area A (in square meters of the air space is given by A = 10x - 2x^2
B) How long are the sides of the rectangle when the air space has an area of 12m^2?
C) Investigate whether the shelter space can have an area of 15m^2

An object is composed of a cylinder and a cone as shown in the figure.
The radius of both the cylinder and the cone is r. The cone has height h. The cylinder is three times as tall as the cone.
A) Find the volume V of the object expressed in terms of r and h
B) Find r expressed in terms of V and h

A) Show that the division (2x^3 + 5x^2 - x - 6) : (x+2) goes up without performing the division
B) Solve the equation 2x^3 + 5x^2 - x -6 = 0
C) Factor the expression 2x^3 + 5x^2 - x -6
D) Subtract the fraction (2x^3+5x^2-x-6)/(2x+3)

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#

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@vast shale Has your question been resolved?

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twin quail
#

How do i prove Triangle Inequality for this term?

twin quail
#

Been sittin on it for a very long time and ivenot moved forward at all

#

nice troll, if any1 canhelp id appreciate^^

visual coyote
#

i dont exactly know what the question wants

#

are x1 y1 x2 y2 coordimates?

twin quail
#

Im supposed to check whether that term is a metric

#

ive proven its symmetric and its always positive

#

but im stuck on proving triangle equality

dull bear
#

Easiest way imo would probably be to show that it’s induced by an inner product

#

Then all norms induced by inner products satisfy the triangle inequality

twin quail
#

Could u ELI5? we just got introduced into this topic and its alot all at once

twin quail
dull bear
# twin quail this phrase

Basically you have norms on vector spaces, which satisfy similar properties to metrics (and any norm can be used to create a metric)

#

<@&268886789983436800>

#

Anyways, not sure whether you’ve seen them before, but similarly there are inner products on vector spaces (and any inner product can be used to create a norm)

#

For inner products, the norms they create have to satisfy the triangle inequality for norms because of Cauchy Schwartz

#

So it might be a bit less pain showing that you can create an inner product that would end up forming this metric

#

(You can do it without it, but if I recall it’s a bit more work to do)

twin quail
#

I think without is probably what im supposed to be doing

visual coyote
#

i mean i would probably do it by supposing a point z

#

of coordinates (x1,y2)

#

and assuming x1/=/y1 and x2/=/y2; proving that xyz is a right triangle

#

then using pythagoras to find the distance

vocal sleetBOT
#

@twin quail Has your question been resolved?

vocal sleetBOT
#

@twin quail Has your question been resolved?

twin quail
#

Can anyone help/walk me throught his please^^

vocal sleetBOT
#

@twin quail Has your question been resolved?

vocal sleetBOT
#

@twin quail Has your question been resolved?

twin quail
#

.close

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hard wadi
#

I can’t figure out how to do #14

vocal sleetBOT
hard wadi
#

Comes from chapter 5.3 of Kreyszig’s advanced engineering mathematics 7th ed

#

I’ve tried finding a series that I can use in place of the right hand side but I’ve had no luck

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#

@hard wadi Has your question been resolved?

vocal sleetBOT
#

@hard wadi Has your question been resolved?

hard wadi
#

<@&286206848099549185>

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#

@hard wadi Has your question been resolved?

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#

@hard wadi Has your question been resolved?

flat whale
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tribal sapphire
#

how does one do this?

vocal sleetBOT
tribal sapphire
#

nvm

#

.close

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tribal moss
#

.reopen

#

$\log_{16}\frac{1}{128}=x\Leftrightarrow 16^{x}=\frac{1}{128}\Leftrightarrow 2^{4x}=2^{-7}\\\Leftrightarrow 4x=-7\Leftrightarrow x=-\frac{7}{4}\\\log_{16}\frac{1}{128}=-\frac{7}{4}$

twin meteorBOT
#

Joanna Angel

tribal moss
#

.close

vocal sleetBOT
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sinful forge
vocal sleetBOT
sinful forge
#

How did he get 2b=-6

#

im kinda confused

grizzled halo
#

by subtracting the second line from the first

#

$(a+b)-(a-b)=(-1)-(5)$

twin meteorBOT
#

chlamydia

grizzled halo
#

as represented by the single red line there that's supposed to be a minus

jagged cargo
#

the a gets canceled out, $b - (-b) = b + b = 2b$, and $-1 - 5 = -6$

twin meteorBOT
#

FungusDesu

vocal sleetBOT
#

@sinful forge Has your question been resolved?

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vast shale
vocal sleetBOT
vast shale
#

Can't proceed really

merry python
#

are you able to find the bounds of the range

vast shale
#

No

#

I applied the formula but got no where

#

(U²sin2x)/g

merry python
#

yeah that is the formula for range

#

I'd recommend you to draw a diagram

vast shale
#

That didn't helped

#

The answer is

merry python
vast shale
#

Minimum angle 15°, maximum angle 75° but there is an interval 53° between 15° and 75° , which is not allowed for successful shot

#

This what written in answer

merry python
#

disclaimer: I'm on my phone

merry python
vast shale
merry python
#

no

vast shale
#

Not really

merry python
#

the boat is parallel to the man

#

see my diagram

vast shale
#

Oh

#

I see now

#

One comes 3/10 =sinxcosx

#

One Comes sinxcosx =1

merry python
#

convert it to sin(2x)

vast shale
#

One will be theta = 15

#

And one 37/2

#

How that's answer then

#

@merry python

merry python
#

well then there must be some misinterpretation or if not then the answer is wrong

#

oh wait

#

are you aware of the fact that complementary angles have the same range

#

@vast shale

vast shale
#

Yes

merry python
#

so theta=15 and theta=75 would have the same projections

vast shale
#

Yea

#

And for second one it will 37/2 and 90-37/2

#

How that concludes the answer

merry python
#

well you just concluded that minimum angle would be 15 and max would be 75

#

the only thing left is to prove 53 does not work

vast shale
#

Yeah

#

That's what I was asking

merry python
#

but there seems some issue with that point

vast shale
#

18.5 and 71.5 will be inside 15 and 75 so it's done

merry python
#

the answer says 53 won't work

vast shale
#

Yea

merry python
#

but it does not mention anything about 37

#

if 53 does not work then so does 37

vast shale
#

Yeah lol

merry python
#

since they are complimentary

vast shale
#

I got a conclusion

#

Answer will be 15°to 18.5°

#

And 71.5°to 75°

#

Even 45 30 60 non gonna work

#

Including 53

#

They just didn't wrote answer correctly

#

What do you say

#

@merry python

#

I applied those angles to check answer

vocal sleetBOT
#

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flat minnow
vocal sleetBOT
flat minnow
#

yes

#

-35

#

year 10

#

really?

#

💀

#

nah lol

#

thanks

#

arent these just with factors

#

damn

#

.close

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placid gust
#

Good afternoon, colleagues. I'm struggling with specific formula. I have mathematical formulas, which I need to calculate and based on it my question is:

Does anyone know any related to it good analogues for getting calculated steps with explanations?

In Wolfram Alpha and Symbolab, I'm getting the issue as:
No Steps: Steps are currently not supported for this problem - Symbolab

or simply no results related to it.

To clarify:

I'm not asking about 'How to do it/How easy is it', I'm asking:

'What resources can be used for it and why it would be helpful for my use case.'

P.S. If you don't know, at all, this topic and how to help, please, ignore it and don't waste my time on empty talk.

Thank you in advance for your help.

vocal sleetBOT
#

@placid gust Has your question been resolved?

vocal sleetBOT
#

@placid gust Has your question been resolved?

vocal sleetBOT
#

@placid gust Has your question been resolved?

cyan talon
#

this operation you're showing is called convolution

#
  1. What resources can be used for it so you're looking for tools than can compute it for you ? just to be sure what you want
  2. helpful for my use case, what's your use case ? maybe it's important to know
#

@placid gust

sharp chasm
#

ф

#

ффффффффффффффф

placid gust
#
  1. Under „use case“ I mean this specific formula, @cyan talon

  2. I've been given a fairly tight deadline, so I want to speed up my approach to research. My vision of this is to start with an example of a calculation, and then, supported by theory, solve something similar freely.

vocal sleetBOT
#

@placid gust Has your question been resolved?

vocal sleetBOT
#

@placid gust Has your question been resolved?

frail mortar
#

Btw close it if you're done

wicked sonnet
umbral pawn
#

.close

wicked sonnet
umbral pawn
#

Nothing

vocal sleetBOT
#

@placid gust Has your question been resolved?

placid gust
# frail mortar Btw close it if you're done

Hello, buddy. I didn't solve it. I'll close it if I don't receive the answer from @cyan talon , at least, today. I'm struggling with it, for this reason, my question is still on hold.

cyan talon
#

@placid gust I didn't see your ping from yesterday, discord doesn't help very much

  1. I'm not aware of a tool which would explain you in detail how convolutions are computed, like say wolfram (or another symbolic math tool) understood your query and could tell you the steps, it prolly would just say ok we have to compute the convolution .... the result is .... with no inbetween. There's a lot of resources explaining convolution though, it's not a completely niche thing, it shows up in quite a few places. (signal processing, probability at least)
  2. ok I thought you had a specific application of that formula in mind already, that's what use case sounds like to me
  3. I can show you a typical example of a calculation which involves convolutions (with probability), I'll wait for you to come back if you wish to see it
placid gust
rapid swift
#

btw you can use some integral transform or the discrete version of it if you want a "tool" for it

#

for suitable transforms, the convolution becomes an elementwise multiplication and an inverse transform

#

if you simply want to check your work on it, there are things like numpy.convolve that will compute it for you

#

but other than that, just follow the mathematical formula I guess

cyan talon
# placid gust Yes, I'm here, please, write me your thoughts👍

here's a very basic example, let's say I throw two dice (one has 10 sides, from 1 to 10, the other has 12 sides, 1 to 12, the sides on each die show up with equal probability 1/no. of sides).
Now I throw these two dice and I look at the sum of the two numbers I get : are you able to compute the probability that the sum of the two dice is, for example, 14 ?

uncut fossil
onyx flax
#

I'm feelin pretty confident now

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#

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#
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fossil python
#

what am i supposed to even do here, how do i start approaching this question

fossil python
#

is this trig sub?

woeful cloak
#

You can either:

  1. Evaluate the integral and solve for c
    or
  2. Do it geometrically, by showing what kind of area the integral is representing
#

of course, I advise against the first approach since the equation that yo uare going to solve is not very pretty

#

and yes, you can use trig sub here

fossil python
#

ahh okok

#

thank you

#

ill try it, thanks for the multiple answers too

#

.close

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#
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empty linden
#

im so confused

vocal sleetBOT
empty linden
#

This is a log chapter so were supposed to use logs. But I dont know what to do for question a

livid horizon
#

Just put in those values

empty linden
#

isnt M(t) the half life?

#

And I have to find the remaining mass

#

Maybe i should say M(t) = (P_f-Pt)^t/h then plug it in to find P_f? which is the final mass

livid horizon
empty linden
#

oh

livid horizon
#

Yeah

#

Half life is h

#

Which is given

empty linden
#

ah, mb

#

i see that now

livid horizon
#

Nice

empty linden
#

and for b, i should just use logs to find out t, right?

#

then rearrange to isolate t

livid horizon
#

Yeah

empty linden
#

alright, thanks

livid horizon
#

Np

empty linden
#

Also, I solved this one and I want to know if its correct

#

its Q6

vocal sleetBOT
#

@empty linden Has your question been resolved?

livid horizon
# empty linden

Over here, it should've been n-1 instead of n in the first line

#

Oh no mb

#

It's correct

#

But
2000= 40*10^n
So 10^n = 50
So n= log 50

#

That's like 1.69

vocal sleetBOT
#
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empty linden
#

.reopen

vocal sleetBOT
#

empty linden
#

yeah i forgot about the log outside the 2000/40

livid horizon
#

Ye

lyric relic
livid horizon
#

.

empty linden
#

im gonna hop off now

#

thanks for the help

lyric relic
#

np

livid horizon
#

Ok

empty linden
#

.close

vocal sleetBOT
#
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Please don't occupy multiple help channels.

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@blissful smelt Has your question been resolved?

terse forum
#

<@&268886789983436800>

unreal lynx
#

.close

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