help-17

[sage gazelle]

hm

I'd have to show why

We're doing basic number theory so I can use | for factors and I can look at prime numbers. I can't use modulo (which would've been useful for some other questions) and I can't really use anything without showing why

[vocal sleet]

@sage gazelle Has your question been resolved?

[sage gazelle]

wait that's slightly wrong because 3u-4v cannot be -5.

The factor -1 just there because an integer with a set of positive factors will always have an identical set of factors, except they're negative

right?

I mean just 3uk-4vk>0 <-> 3u-4v > 0 <-> 3u>4v

[sage gazelle]

pls I know this might seem intimidating but trust me it'd make my day if you helped

as you can see in the message I'm replying to, I've also solved this another way. If this proof isn't correct, pls let me know if the one in that message is.

@hybrid brook since ur name is helpful and ur description is "Ask me math questions" im pinging u. You'd make me very happy if you could help

[sullen moon]

bruh don't ping people

[hybrid brook]

Math machine broke

[sage gazelle]

ok

[sage gazelle]

.close

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[umbral turret]

So basically, I need to find the value of parameter m for which the two roots of this equation are eachothers opposites

[umbral turret]

I just do not know where to start

I guess that I should turn into 'standard form' (I have never had Math in English sorry), but that does not seem to work

.close

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[umbral turret]

.reopen

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✅

[umbral turret]

<@&286206848099549185>

[umbral turret]

It is such a basic question but I think that i am missing something important

[vast shale]

Gebruik dat het product van de 2 oplossingen 16 is

[umbral turret]

Hoe komen we aan 16?

[vast shale]

Je kan het zien als je (x-a)(x-b)=0 hebt, waarbij a en b de nulpunten zijn

Of wacht laat maar

Er staat nog een coëfficiënt voor de x^2

[umbral turret]

mmm

Maar voor dat te gebruiken moet ik het toch in de standaardvorm omzetten

[vast shale]

Ja ik denk dat ik hem heb

Je kan het omschrijven naar $(m+8)x^2+(m^2-1)x-16=0$

[twin meteor]

Ryanstaal2006

[vast shale]

Als a een nulpunt is, dan is dus -a ook een nulpunt

Dus $(m+8)a^2+(m^2-1)a-16)=(m+8)(-a)^2-(m^2-1)a-16=0$

[twin meteor]

Ryanstaal2006

[vast shale]

Dan moet gelden dat $(m^2-1)a=-(m^2-1)a$

[twin meteor]

Ryanstaal2006

[vast shale]

Dus m^2-1=0

Dus m=1 of m=-1

[umbral turret]

omg bedankt man echt

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[vast shale]

So when inputting the numbers to the problem to see which would equal zero I tried 1 and it didn’t work

Then I input -1 and it worked I got zero

But for the factor would it be (x + 1)?

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[mild raven]

can anyone walk me thru optimization?

[vocal sleet]

@mild raven Has your question been resolved?

[mild raven]

plox awnsewr

[west raptor]

First of all, you have two variables: the height and the length

[mild raven]

right and we have 2 givens

width and volume

[west raptor]

But they are constrained by 4hl=36 because the volume is 36

[mild raven]

yes the volume equation L * 4 * h = 36

[west raptor]

Can you find the total cost in terms of l and h?

[mild raven]

so you want me to solve for l and h using that equation

or should i create an equation

for that

[west raptor]

We'll put that equation aside for a bit

[mild raven]

okay

in order to find the total cost of the tank we first need to find the best dimensions with the given formula though right

[west raptor]

We first have to find the cost function if we want to minimize the cost

[mild raven]

right

so thats 10 dollars ( lw ) for the bottom

and 5 dollars ( 2(L * H) + 2 ( w * h))

[west raptor]

Yes

[mild raven]

so its c = 10(LW) + 5( 2L * 2H + 2W * 2H)

[west raptor]

So now in order to minimize we have to convert c into a function of 1 variable and differentiate it

Here we will use that equation to solve l in terms of h (or h in terms of l)

This equation: 4lh=36

[mild raven]

right which is simply just h = 36/4l

[west raptor]

Also, 2(LH) is 2LH, not 2L*2H

[mild raven]

really? is that because they are techically "one" variable

or together rather

[west raptor]

That's the associative property of multiplication

[mild raven]

right

[west raptor]

So if you plug this into c (also note w=4), then we have c in terms of just l

[mild raven]

right

ive got that plugged in

[west raptor]

Do you know how to differentiate it?

[mild raven]

yes, set it to 0 and differentiate with respect to L im assuming

[west raptor]

Close, but you first differentiate, then set it to 0

[mild raven]

right right

this equation is a mess right now though so differentating it is a nightmare

its like

[west raptor]

I suggest simplifying it

[mild raven]

so obviously the left side of that addition is 40L

but then the right side is a mess man, im terrible at multiplying fractions especially with variables

i dont really know why they always throw me off like that

[west raptor]

For the middle term, you can simplify 36/4L as 9/L, and 2(L) becomes 2L, so 2L*9/L = 18 because the L's cancel out

For the rightmost term, the 2*4 becomes 8, 36/4L is 9/L, so it turns into 72/L

[mild raven]

so its just the whole term times the numerator

or the constant

i thought u had to do some dumb shit like

idek

fractions r horrible

i thought you had to find a common denominator in order to multiply fractions

or is the common denominator just L

so we just multiply the tops

considering L doesnt really affect the top half of the new fraction

yeah

that makes sense

[west raptor]

Common denominators are for adding and subtracting fractions, for multiplying it's just c(a/b)=(ca)/b

[mild raven]

oh my god, well i probably could have looked that up

but that makes so much more sense

anyways

u diff and get

0 = 40 + 5(-(72/L^2))

or we can simplify that to -360/L^2

[west raptor]

Yes

[mild raven]

now just solve for L

?

[west raptor]

Yeah

[mild raven]

i get .33333333333333

sub 40

mutliply by -1/360

square it

[west raptor]

You mean square root?

Then you would get 1/l, not l

[mild raven]

correct

just plug .3 into my oiriginal and then i have my optimized cost

well i should probably plug in the non sqrt one so i dont get some rounding error

or accuracy

[west raptor]

Well an alternative way is to add 360/l^2 to both sides, then multiply l^2, divide 40 and sqrt

That way you can get l without using approximations

[mild raven]

?

u mean l^2/360

also why not the negative

[west raptor]

How did you get l^2/360?

[mild raven]

oh i see what u said

nvm

😂

[mild raven]

so instead of that other wonky thing its just sqrt(360/40)

which is 3

[west raptor]

Yes

[mild raven]

that helped me alot

thankyou man

i think i understand these optimizations way better now

[west raptor]

One more thing

You have to prove this is a global minimum

[mild raven]

1st der test i can just plug in something negative and positive and see if this number lies in the middle right

[west raptor]

Because l∈(0,∞), you do that by taking the limit as l -> ∞ and as l -> 0+

[mild raven]

well

i think first derivative doesnt work here

because you cant divide by 0

[mild raven]

ur saying here plug in any number above L and see if its positive and then plug in 0

you cant plug in 0 here

[mild raven]

yes right

but in this case

you cant use 0

it gives an div by 0 error

[west raptor]

That's why you use a limit instead of plugging 0 and ∞ in

[mild raven]

so just something close to 0

like .1

[west raptor]

The limit is a bit different from just plugging values in

[mild raven]

well from what i remember

its a number line

and you literally just plug in something positive and something smaller and see what side of the line it falls on

[west raptor]

Instead of limits think of this: we can take c arbitrarily large by taking l very large or very close to 0

[mild raven]

if it pos to neg its a max

if its neg to pos its a min

yeah so exactly what i said no? a value approching 0 from the positive side

so .1

or any integer larger than 330 in this case

or i could use 1

to keep integers the same

or 2

or 3

doesnt matter as long as its smaller than 330

wait

yeah

or no

this is rather a question than me arguing against you

lol

[west raptor]

That's the first derivative test, but that can only find if it's a local min or max

[mild raven]

ohhhhhh right global is different

it doesnt ask for that tho

question only asks for the cheapest tank

[west raptor]

You can observe that c' is negative for l<3 and positive for l>3, so taking any l other than 3 is not optimal

[mild raven]

yeah thats what i did right?

im confuse now lol

proving its a global min or max would reqire finding critical points

[west raptor]

Yes but the first derivative test asks for ther derivative near 3

[mild raven]

so first derivative test will only prove the min or max close to 3 or whatever value we find in a given problem

[west raptor]

Yes

[mild raven]

so this problem is done it seems

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[tough bison]

Multivarialbe calculus

trajectory

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[tiny tulip]

hello i need help

[tiny tulip]

im in 8th grade algebra 1

and i have a test tomorrow and i dont know how to do a section of it

[glass galleon]

lemme see

[tiny tulip]

k do u just want a picture?

or i can c and p the probelm

[glass galleon]

yuhh that's fine

[tiny tulip]

At a particular restaurant, each onion ring has 40 calories and each chicken wing has 75 calories. A combination meal with onion rings and chicken wings has a total of 19 onion rings and chicken wings altogether and contains 970 calories. Write a system of equations that could be used to determine the number of onion rings in the combination meal and the number of chicken wings in the combination meal. Define the variables that you use to write the system.

[glass galleon]

pics good

[tiny tulip]

oh ok

hol up thas blurry

[ancient knoll]

man has a curved monitor and discord open and still decides to take a photo with phone

[tiny tulip]

everytime i take it with my pc it crashes

can someone pls help me

[vast shale]

Can someone help me

[tiny tulip]

yo i aint trna fail this test tmrw someone help me

[glass galleon]

have u tried brainly

[tiny tulip]

what is that

[glass galleon]

theres so many of them

[glass galleon]

lifesaver site ngl

https://www.wyzant.com/resources/answers/747590/please-help-me-find-the-equation-to-solve-this

heres a similar question

just follow the method

[tiny tulip]

alr ty

[glass galleon]

found urs

should be right

[vocal sleet]

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[green root]

I need to check my understanding of the coverup method

[green root]

I did it and i wanna know if i did it correctly or not

[crude arrow]

oh I can help with that

[green root]

Using the coverup method

[crude arrow]

if you need assistance

[green root]

Ya bro go ahead

[crude arrow]

so for B

if x = -1

we have( 2(-1) + 5)/(-1-2)

yes?

[green root]

Hold

Ya

Ye

[crude arrow]

,w partial fraction \frac{2x+5}{(x-2)(x+1)}

[twin meteor]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nosqldb

[crude arrow]

so we have -1 instead

[green root]

Hold on how

[crude arrow]

compute this ( 2(-1) + 5)/(-1-2)

[green root]

For b i mean

[crude arrow]

this should be a -1

[green root]

So

(2(-1)+5)/(-1-2)

Okok

Is that all

[crude arrow]

mhm

'".close" when ur finished

[green root]

Okay bet

.close

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Channel closed

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[green root]

.reopen

[vocal sleet]

✅

[green root]

@crude arrow I feel like i made a slight error because im not getting “1”

I did like you said but my result remains

[crude arrow]

hmm

can you copy and paste the expression

I gave you

[green root]

For B right

[crude arrow]

yep

[green root]

(2(-1)+5)/(-1-2)

It becomes 3/-1

OH I MADE THAT MISTAKE

now im doubting A

A is correct yes

[crude arrow]

mhm

".close" when ur done

[green root]

Alright thank u

.close

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[crude arrow]

ofc

[chrome steeple]

Can someone explain to me what parent function is?

Haven't been to school in months due to surgery, and I have a lot of math assignments to catch up on. I have a one-page sheet that I need to finish, but I don't understand a single thing about it, not one bit. I have to turn it in by Friday, so I'm looking for help to finish it. I'm willing to take anyone that can explain the work to me. Thank you.

[crude arrow]

I would consider in person tutoring or support from your school, but I can provide with support

https://www.onlinemathlearning.com/parent-functions.html

[green root]

Its the simplest form of any given function

[crude arrow]

mhm

these are examples of parent functions

[green root]

Theres 11 as u see

[chrome steeple]

Mhm are all the names there to diffirentiate the lines on the graph?

[green root]

You can identify how it will look like based on its function

Yea its js to show the different functions

For example

F(x) means function of X

If f(x)=x we can identify this as a linear function

Its just a straight line that goes from bottom left to top right

[chrome steeple]

Question: Does f(x)=x always mean linear?

[green root]

Yea

[vocal sleet]

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[green root]

Unless its squared then it becomes a quadratic function

[chrome steeple]

I think I get how the function works but another question

[green root]

Ya wsp

[chrome steeple]

and its about equation

What is domain

in parent function

[green root]

Domain in parent functions is quite literally all real numbers (or R) that are NOT 0

[chrome steeple]

Then why do they put infinite symbols in it

infinity*

[green root]

Because infinity is basically all real numbers

Infinite amount of real numbers that are not 0

Remember

All real numbers EXCEPT 0

Infinity applies to all real numbers

Literally any number that isnt 0

[chrome steeple]

Got it

I'm still trying to wrap my head around it because it is new to me so bear with me

[green root]

Ya dw i learned this not too long ago so its still a slight struggle

[chrome steeple]

How would you write an equation on parent functions

[green root]

Wym

[chrome steeple]

like domain of negative infinity and positive infinity

[green root]

Yea idk that one chief 💀

[chrome steeple]

My teacher gave me page of those type of question to write their equations

[green root]

Itd say like

[chrome steeple]

My sister have the same class as me but diff teacher and she doesn't learn what i'm learning

[green root]

F(x)^2=x

Which is a quadratic

Thats the best i can do to answer your questions

Also itd show u ona graph

[chrome steeple]

Well alright i'll look online for more explanation

[chrome steeple]

I don't have a a graph

sadly

[green root]

Goodluck on that i gotta do some math too

[chrome steeple]

this is what i have to work o

on

[green root]

Yikes

Ok so

[chrome steeple]

Ikr

but it is what it is

[green root]

Neg inf and pos inf depends on what direction the line is going

If the line goes down forever thats neg infinity

Same rules apply for positive infinity

If the line goes up forever no matter how fast or slow it will be positive infinity

[chrome steeple]

Its tricky since I don't have a graph I can't picture it

[green root]

If a function presents (0,inf) that means the function starts from 0 and goes up infinitely

[chrome steeple]

I would assume

neg infinity is going down

[green root]

Si

[chrome steeple]

i see

what is range.

[green root]

Thats kinds hard for me to explain holup

[chrome steeple]

wouldn't it be cubic

[chrome steeple]

alright

[green root]

Range is any number or numbers between a big and small number

Its like saying “pick a number 1-100”

Thats a form of range

Same stuff applies when working in a graph

Youl learn about discontinuities soon enough those will be painful

[chrome steeple]

50 not too small not too big

[green root]

It can be any

[chrome steeple]

except for 0

[green root]

Exactly

Yk why

[chrome steeple]

https://tenor.com/view/tkt-smart-gif-20642718

[green root]

Bc thats not within the range

1-100

[chrome steeple]

LOL i figured

[green root]

0 isnt included

-1 isnt included

Hope that helps

[chrome steeple]

math is only fun when you understand it i swr

[green root]

IT ISSS

[chrome steeple]

to make sure i understand it can you walk me through 3 questions or so

I'll figure the rest when i get the hang of it which won't take long

[green root]

Alr

[chrome steeple]

Like we talked about we would assume that neg infinity is either going up or down right so i understand that but since there's no graph or nothing to help picture the question how would I go about writing the equation

[green root]

What equation

[chrome steeple]

first

[green root]

Ok so basically to know inf and neg inf you gotta know the function at hand

So

Linear is a function that is (-inf,inf)

Because it literally is going both directions infinitely

Remember what we said

Neg inf is going down

Inf is going up

No matter how fast or slow it is going

[chrome steeple]

Yes

[chrome steeple]

like that ?

[green root]

Thats infinite on both sides

Its going both ways infinitely

[chrome steeple]

right just wanted to make sure i was picturing it right i'm bad with visualizing

[green root]

Yea its hard for me too

[chrome steeple]

geometry was a pain for me

[green root]

But theres something you need to know

[chrome steeple]

But i stilled passed with a B

[chrome steeple]

which is

[green root]

If youre given a function f(x)=3x

What do you think that means

[chrome steeple]

Elaborate

or I mean explain the question a lil

i can answer i think

[green root]

You know how a horizontal axis works right

[chrome steeple]

horizontal line

[green root]

Ya

[chrome steeple]

yes

Y is up X is just in the middle ig

[green root]

Actually bad description

Basically

Yk f(x)= x is linear right

3 is added to it

The line will then point to where 3 is

Il show it visually

Its pointing to (1,3)

Thats the best i can do

I gotta hop back to doing work

[chrome steeple]

Well thank you for time, you helped quite a bit even though I haven fully grasped it compare to when i got the work sheet I didn't know anything about it.

So yeah thanks i'll get back to looking into it more online

[chrome steeple]

someone gave me a link to check out so i'll do that

Nevermind I'm done for today 💀

[vocal sleet]

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[craggy mango]

I wanted to confirm if this was correct

And if it is, do I have to plug my x back into V

[vocal sleet]

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[craggy mango]

.close

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[outer wigeon]

is a line like this discrete?

[outer wigeon]

make it fast pls

<@&286206848099549185>

dawg i was waiting 3 mins for this

4

its a yes or no

it takes two seconds

<@&286206848099549185>

[digital drift]

No I am pretty sure it is not

Is that all you need?

[outer wigeon]

its not discrete?

[vocal sleet]

@outer wigeon Has your question been resolved?

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[vast shale]

why are the adjacent angles = to each other

[vast shale]

is that a property of rhombuses

bc angle 1 is apparently 35 as well

all rhobuses are parallelograms

opp angles is same

i thought it was for the entire angle

not just a portion of it is the same

oh

bc u can see line MP splitting angle 1 and the 35 degree angle

QP||MN

so

i dont really get what parallel has to do with this

[vocal sleet]

@vast shale Has your question been resolved?

[vast shale]

but opp sides are parallel

alternate interior angle

partial angle M also equal to 35

@vast shale

diagonals of rhombus

bisect

it forms isocelles triangles

nd 90 degrees

oh so the iscoles triangle have the congruent angles

[vast shale]

they bisect but theyre not congruent

but

isocelles triangles subtend equal angles opp to those equal sides

[gloomy prawn]

I have some math stuff that in class I couldnt understand,
could you teach me the formula of how to solve these types of problems?
basically I have a number and every certain ammount of time i loose a number of that
can you help me?

[vast shale]

how r they iso triangles tho

[vast shale]

yuo do have a point

see triangle QP and center point
acc to a theorem all angle sum is 180 degree

$35+90+x=180$
$125+x=180$

[twin meteor]

peekaboo!

[vast shale]

$x=55$

[twin meteor]

peekaboo!

[vast shale]

deg

@vast shale

angle NQP = 55

angle MNQ = 55

alternate interior

triangle QOP =triangle MON

angle 3 = 90

angle 4 =90

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[obsidian lark]

Need some help with projectile motion

[obsidian lark]

i can’t screenshot on pc and send to discord so i’ll have to be annoying sorry

you can see the formula i used for the Vx component

but as you can see the Sy component when it equals 0 should be the final result of the Sx component, which should align with the Vx component i would’ve thought?

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[unborn quail]

how do i find the intersection point between $log_a{x} = a^{x} = x$

[twin meteor]

Big Chicken

[vocal sleet]

@unborn quail Has your question been resolved?

[unborn quail]

<@&286206848099549185>

[worthy citrus]

They don't intersect

[vocal sleet]

@unborn quail Has your question been resolved?

[vast shale]

They do, if a is less than 1 and greater than 0

And if a is greater than 1 and less than around 1.6

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[flint sapphire]

I'm trying to caculate a projectile motion of a canon, and I'm having problems.
Given the distance, maximum height and duration of the projectile motion, how can I calculate its y at any given time?
Since I already have the distance and duration, I can easily calculate the x at any given time because horizontal acceleration is constant, but I'm not sure how to get y.
Wikipedia uses Θ and initial velocity as part of the calculation for y, but I don't have that data. And Θ uses initial velocity to be calculated, but I also don't have it, or can I infer that with my current data?

[tidal umbra]

what is y and x here sorry

[flint sapphire]

Current horizontal and vertical values at a given time

[crimson jetty]

displacement is the word

[vast shale]

What's the degree of that canon btw

[dense stump]

Well are you given any info as to how/where it’s launched?

[vast shale]

And on what height

[flint sapphire]

I'm programing a creature for a game that can jump, so I already have the initial position and target position. I want to calculate the position of the creature during the entire jump.
Since I need more data, I thought can I set the duration and maximum height of jumps, and use that to calculate the rest, isn't it?

[vast shale]

Not really

[flint sapphire]

Oh

[vast shale]

I mean

[flint sapphire]

Which data I need then and which one can I calculate?

[vast shale]

does it jump in straight line or like, in a parabolr

How does it jump

[flint sapphire]

Parabola, like if it has gravity

[vast shale]

I'll help u in a sec, busy atm sorry

Okay im back

So how do you know the height of the jump

[flint sapphire]

I was thinking I could hardcode a fixed value, so all jumps has the same maximum height, thought that doesn't sound very nice

[vast shale]

hmmm

[flint sapphire]

Unless there is a way I could calculate that also

[vast shale]

You want it to be realistic? What I mean by that is thay the jump resembles "jumps" in our world

[flint sapphire]

Yeah, when people jump they do an small parabola due to gravity, right?

[vast shale]

Only if they jump on a certain angle

sorry for bad english lol im from poland

[flint sapphire]

It never jumps in place, but always at some target, so the jump always have some horizontal component

[vast shale]

Oh

does it stop at nax heighy

[flint sapphire]

No problem, I'm from Argentina haha

[vast shale]

height

Or does it fall back to thr ground

[flint sapphire]

It does fall back to the ground

[vast shale]

okay

Let me finish eating and I'll write the formula, hopefully

I'm kinda sick so don't take my answers with cerntainty btw

💀

sick in the neaning ill...

[flint sapphire]

Yeah, I inferred that. Hope you cure quickly. 2 days ago I catch a cold, I still have a sore throat haha

[vast shale]

can you give me the max height so i can work on real numbers to check for dumb mistakes?

and the angle you want your character to jump on

[flint sapphire]

Oh, I have not yet determined those values, I was going to tests with different ones after got the formula to get the one that looks better

[vast shale]

Ahhh okay, im writing it down

[flint sapphire]

So I would have to set a fixed angle?

[vast shale]

Hmm well, to achieve a max height you can manipulate 2 factors, initial velocity or the angle of the jump

[flint sapphire]

I see

[vast shale]

Oh also I made an assumption here
it has an initial velocity and no force except for gravity interferes

[flint sapphire]

After the creature jumps, no additional forces (apart from gravity) are applied

[vast shale]

cool

so basically the character gets a velocity on an angle
We know what's the velocity and the angle so we calculate horizontal and vertical values with trigonometry (v vertical = sina × the velocity, v horizontal = cosa × velocity) This way we can calculate at what time it would reach the max height (vertical velocity - gt = 0 (note it's only the timr to hit max height)) This way we can set a formula for y in any place before it starts falling down
so y = v vertical × current time (x/horizontal velocity) - gt²/2
That's for the part it's going upwards
hold on though, I feel like something's wrong, let me test it

$y\ =v_{1}\ \cdot\ \frac{x}{v_{2}}-9.81\cdot\left(\frac{x}{v_{2}}\right)^{2}$

[twin meteor]

Kostek

[vast shale]

https://www.desmos.com/calculator/07zzzabx03

Hope I helped and it's not faulty

[flint sapphire]

Ok, thanks

.close

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[woeful mesa]

can someone look at these answers because im super not confident in probability

[vocal sleet]

@woeful mesa Has your question been resolved?

[woeful mesa]

<@&286206848099549185>

[vast shale]

Yo sorry I'm not into probability

I think you've answered the 1st question right but in the second one

if there are x ways of choosing 6 numbers, and 1 combination wins, the probability should be 1/x, no? @woeful mesa

[woeful mesa]

uhhh yessss but the combination doesnt matter

the 6 numbers can be in any order

[vast shale]

oh ur right

[woeful mesa]

should I have used 50c6 instead?

choose*

[vast shale]

It still should be the same answer I think though

[woeful mesa]

no its way smaller D:

[vast shale]

wdym, it's the same

[woeful mesa]

oh no tis the same

lmao

[vast shale]

lol

[woeful mesa]

okay

well i guess its right then

.close

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[undone aurora]

so

cos(theta) = (v * w)/(|v| |w|)

which will be

$\frac{5(5) + 7(6) + 9(1)}{(5 + 7 + 9)(5 + 6 + 1)}$ right?

[twin meteor]

Calc II Victim

[undone aurora]

wait omg

im so dumb

i forgot what |v| rlly was

.close

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[true mica]

this is an infinity/infinity form
I tried to solve it with L-Hospitals rule but It seems like it cant be done that way

[true mica]

or am I just doing something wrong?

[vocal sleet]

@true mica Has your question been resolved?

[median crane]

Try $\ln \left({7^x \left(\frac{2^x}{7^x} + \frac{3^x}{7^x} + \frac{5^x}{7^x} + 1 \right)} \right)$

@true mica

[twin meteor]

$Pure$

[true mica]

oh yes, it works

thank you very much

[median crane]

Np

[true mica]

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[empty stag]

!occupied

[vocal sleet]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[empty stag]

.close

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[empty stag]

.close

aaa

.reopen

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✅

[empty stag]

.close

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[pale leaf]

How do I solve a?

[flat whale]

Find the vertex and x intercepts

Plug them into the parabola equation in vertex form

https://www.cuemath.com/geometry/parabola/

[vocal sleet]

@pale leaf Has your question been resolved?

[pale leaf]

I'm having trouble with the x intercept

[flat whale]

What unit is each square

[pale leaf]

The x is the price change

Doesn't tell the unit of each square

[flat whale]

Right

You infer it from the graph

And the x values labeled on the x axis

[vocal sleet]

@pale leaf Has your question been resolved?

[pale leaf]

!close

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[snow burrow]

for which natural n>=3 is C_n Eulerian, how about K_n

[snow burrow]

for Cn isnt it all natural numbers

[mild sierra]

Well what do you know about eulerian paths?

What about them might you relate to C_n and K_n?

[snow burrow]

its a closed trail with all edges

isnt it also all natural numbers for Kn as well

since Kn is connected

and Cn is practically a Eulerian path in itself

?

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[tawny shoal]

where did i go wrong on number 4? answer key says it’s 10

[sand hedge]

Should be plus 2

@tawny shoal

[tawny shoal]

ah

thank you

alright i’ve checked this one like 5 times to make sure i didn’t swap a sign and i can’t see what i did wrong either

it’s supposed to be -169

,rotate

[tawny shoal]

@sand hedge

[sand hedge]

It’s minus 3 plus 2

Oh I see

Minus 3 minus 2

When you’re expanding co factors it alternates between plus and minus

[tawny shoal]

can you explain that a lil more idrk what cofactors means my teacher didn’t teach it so i’ve just been figuring it out

[sand hedge]

Co factors are the 1 3 and -2 you picked

It could of been any row or column but the numbers in them are your co factors

I believe

When you pick the co factors their signs follow a pattern like that

[tawny shoal]

and if it alternates ebteeen plus and minus why does the -2 stay negative

[sand hedge]

No because then it’s plus negative 2

And the three is negative negative 3

[tawny shoal]

ohhh so you keep the signs of the original co factors but you add the plus or negative onto them@

multiply them on whatever

[tawny shoal]

okay i didnt know that at all

are there any other weird matrice rules?

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[hoary mortar]

wait is it a or b?

[hoary mortar]

i think a

but some are saying b

i really dont know

<@&286206848099549185> pls i just need u to confirm if its a or b

[tepid beacon]

why do you think its a

[vocal sleet]

@hoary mortar Has your question been resolved?

[hoary mortar]

i just dont know between what - infinity its approach

[tepid beacon]

wdym?

[hoary mortar]

like i just dont know

if its -k or postive k when approaching - infinity

[hoary mortar]

is it b then?

[tepid beacon]

try substituting in values of k, a and b and then graphing the function

what does it look like?

[hoary mortar]

looks like this

[tepid beacon]

so what seems plausible?

[hoary mortar]

as x > infinity, f(x) = k?

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[hoary mortar]

.reopen

[vocal sleet]

✅

[hoary mortar]

so its b?

[tepid beacon]

youre not going to learn anything from asking for the answer

decide for yourself

[hoary mortar]

omg eeek

i think b now

am i correct

As x -> -∞, the values of the a * b^x term will go towards zero, so the value of the function will just be k

[hoary mortar]

so it has to be B.

[tepid beacon]

good!

[hoary mortar]

DUBS

ty

thanks so much

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[forest haven]

Need help with this

[left talon]

!show

[vocal sleet]

Show your work, and if possible, explain where you are stuck.

[forest haven]

I just need to confirm I did it wrong

[left talon]

and what is the question?

[forest haven]

Or I typed it wrong

[left talon]

its not clear

[forest haven]

G(n) in summation form then first 4 non zero values

[left talon]

are you familer with taylor series?

[forest haven]

Yes

[left talon]

you need to write tylor series for g(x) then

[forest haven]

Ok

[left talon]

u can find out taylor series for :
g(y) = ln(y)
then instead of y put y = 1 -10x

[forest haven]

Ok let me try it

I tried it

But it’s still saying that

[left talon]

saying wut?

[vocal sleet]

@forest haven Has your question been resolved?

[forest haven]

No

Unable to understand formula

That’s what it’s saying

[vocal sleet]

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[steep merlin]

https://media.discordapp.net/attachments/1159631456407134259/1174817039991447602/image.png?ex=6568f8a1&is=655683a1&hm=f3164f7fa6e0d1c62a6dfa0c7075855482986a11cb0b458d4d634297394470c1&= How would i Proceed with this?

[steep merlin]

Im under the influence ill be using the 1/f'(a) formula

so i set that parent function equal to 3 and solved for x =2

but im not sure how to go past there

[hushed pewter]

Oh, do you mean "you're assuming you'll be using that formula"?

[steep merlin]

yes

[hushed pewter]

"under the influence" is colloquially understood to mean that you are drunk or high on drugs

[steep merlin]

yeah lmao

i didnt know how else to word it

[hushed pewter]

"I'm assuming I'll be using..."

[steep merlin]

Am i correct with this assumption however.

[hushed pewter]

Yes, you are

You could solve for x, if you really wanted to get the inverse

[steep merlin]

i thoguht i needed that?

so i could derive the parent function and proceed with the 1/f'(a)

[hushed pewter]

parent function?

[hushed pewter]

Oh, I see what you are asking.

Yes, proceed with that

[steep merlin]

i derived and plugged in the x value (3) and used the formula and got -1

would that be correct?

.close

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[crimson sedge]

can someone explain how that is the sum of integers between 1 and 600?

[outer warren]

arithmetic series formula

[crimson sedge]

n/2(2a+(n-1)d)?

[outer warren]

yes, and for sum of first n integers,
a = d = 1
giving what they've written

[lavish river]

you could consider sum from 1 to 600 minus 3 to 600 in increments of 3

[crimson sedge]

n would be 601 woudn't it i?

[outer warren]

why would it be 601

[crimson sedge]

oh wait no

600

[cyan shadow]

for what its worth, that formula is a "top of the head" kind of formula and you should probably just know it

it is the arithmetic series formula, but the sum from 1 to n form is super common

[crimson sedge]

oh is it

1/2n(n+1) is the sum of a number from 1 to a number?

.close

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[stiff void]

Q: Infomation for 20 students is used to investigate the hypothesis that there is a correlation between intelligence quotient and results in a Maths test. Data are collected and the p-value for the correlation coefficient is 0,00218. What is the conclusions of the hypothesis test at the 5% significance level?

[stiff void]

I keep coming to the conclusion of insignificant evidence, do not reject H0 but apparently thats wrong, can anyone help me understand where im going wrong

[crimson sedge]

so its saying that "hypotehses that there is a correleation between intellegance"

so that means h1 : p=/=0

meaning its gonna be a two tailed test

[stiff void]

with ya

[crimson sedge]

since its a two tailed test, the sg level gonna be halved

so sg level gonna be 2.5%

[stiff void]

so r = 0.4438?

[crimson sedge]

if you look on the table 2.5% two tailed will be 0.4438

yes

[stiff void]

but 0.00218 < 0.4438 so is that not insignificant?

[crimson sedge]

so yh, but its better to say "0.00218< 0.4438 therefore, there is not enough evidence to reject H0 (basically saying that we are accepting H0) suggesting that there Isn't any correlation betweeen intelligence quotient and results in a maths test"

[stiff void]

i thought H0: p = 0

[crimson sedge]

sorry, yes ur right

so h0:p =0 theres is no correlation h1 : p=/= 0 suggesting there is a correlation

[stiff void]

the book says reject h0 but it's not uncomman for a book to be wrong

[crimson sedge]

so yeah ur right

hmm

is this A level?

[stiff void]

yes OCR

year 13

[crimson sedge]

might have to ask ppl here

<@&286206848099549185>

im yr 13 aswll lmao

[stiff void]

lol you do further maths i guess?

[crimson sedge]

nah

just normal bang average maths

[stiff void]

hell yeah,big up my confused maths students

[tepid beacon]

hi guys

i did a level maths

whats up

[stiff void]

hi bruhh

maths

we think the book may be wrong

[crimson sedge]

we need to check if my explaination is right

[tepid beacon]

which explanation

[tepid beacon]

this one?

[crimson sedge]

try to do the question see if u get the same answer

[tepid beacon]

it looks like you should reject Ho to me

[crimson sedge]

why??

[tepid beacon]

ok whats your H_0

[stiff void]

p = 0

[crimson sedge]

p=0

[tepid beacon]

wait hold up my dumbass didnt clock p wasnt a probability when i was skimming the q

[stiff void]

lol i always get rho and p confuse

[crimson sedge]

wait 0.00218 is pmcc right?

[stiff void]

i belive so

[tepid beacon]

in that case this looks right?

[crimson sedge]

<@&286206848099549185> book wrong or me wrong?

[grizzled swift]

Hey what problemo

[crimson sedge]

check original question

apparently the book has a different answer than what we got

[vocal sleet]

@stiff void Has your question been resolved?

[stiff void]

gonna go i'll ask at college tomorrow, cheers guys

[vocal sleet]

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[vocal sleet]

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[candid kernel]

Can someone help I don’t know if I’m right

[terse forum]

you forgot to divide both sides by 2

[candid kernel]

Do I not square x

[terse forum]

you can

[candid kernel]

Is that right

[terse forum]

why did you add log_a^2x^2?

[candid kernel]

$$2logax = loga^2x^2$$no?

[twin meteor]

decode.exe

[terse forum]

no

you divide both sides of the equation by 2 to isolate $\log_a ​x$ on one side

[twin meteor]

Akira E-Girl

[candid kernel]

That’s the question

So would it be isolate $$\frac {log_a x {25/9} $$

[terse forum]

is this for a test

[candid kernel]

No it’s revision

It’s a past exam question

[terse forum]

ok ill explain it

[twin meteor]

decode.exe
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[candid kernel]

My LaTeX skills lack severely

[terse forum]

you almost got the answer correct but can you do this?

[candid kernel]

Error number one is that they didn’t put it into a fraction

They broke one of the rules of logs

[terse forum]

$\log_a x = \log_a \left(\frac{25}{9} \right)^{\frac{1}{2}}$

[twin meteor]

Akira E-Girl

[terse forum]

I meant like this

[candid kernel]

So would the answer be log_a 5/3

[terse forum]

exactly!

,w 2log_a x= log_a 25-log_a 9

[twin meteor]

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[candid kernel]

Would you figure out the value of a using natural logs?

That’s not part of the question but im just curious

[terse forum]

[candid kernel]

Uhoh

[terse forum]

ok then what makes you it's equal to log_a 5/3 then?

[terse forum]

.

[candid kernel]

That’s what I mean

We solved for x which was 5/3

[terse forum]

yea it's right

[candid kernel]

Acc nvm we can’t solve it

We don’t have a base or power

Anyways what was the second error

[terse forum]

we said that the student got the right answer is 8, which is wrong because it's equal x=5/3. so they did error in applying logarithm properties I guess?

[candid kernel]

That’s the first error

What’s the second one

Would it be the fact they divided by 2 instead of square root

[terse forum]

well, lets say that then, first one was solving for the x right?

make this as second error

[candid kernel]

Yes

[terse forum]

but ill explain the first error

it should be $2 \log_x = \log(\frac{25}{9})$ because $\log_a - \log_b = \log(\frac{a}{b})$

[twin meteor]

Akira E-Girl

[terse forum]

how about that?

[candid kernel]

Yes

That makes sense

So would error number 2 be the fact they divided 2log_a x by 2 instead of square rooting both sides

[terse forum]

no just say error in applying logarithm properties

[terse forum]

for this

and for the second one incorrect solution for x

[candid kernel]

Irish exam marking schemes are very strict

I don’t know if saying that they gave the wrong answer will give you fullmarks

[terse forum]

[candid kernel]

Its very stupid ik

[terse forum]

!done

[vocal sleet]

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[candid kernel]

.close

[vocal sleet]

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[candid kernel]

Thank you

[terse forum]

you're welcome

[vocal sleet]

Available help channel!

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[mild raven]

this is my setup for this question

does it look like im on the right track

[vocal sleet]

@mild raven Has your question been resolved?

[vocal sleet]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[jagged cargo]

solve this inequation

[jagged cargo]

i found that no real roots, but just to be safe i wanna check

[cyan shadow]

you can use wolfram to check your work

,w (log(x^2-9))/(log(3-x) )<= 1

[twin meteor]

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[cyan shadow]

i have some bad news

[vocal sleet]

@jagged cargo Has your question been resolved?

[vocal sleet]

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[bleak oak]

I'm not sure if this belongs here, but I'm having some trouble with Calc 3/4 stuff, sophomore engineering math

[vast shale]

all math belongs here for the most part

just post a picture of whatever ur struggling with

[bleak oak]

I’m having trouble understanding polar regions

Would anyone have an example problem I could look at that fits this formula?

[hasty lark]

Your textbook should have problems where they use this transformation

[bleak oak]

I don’t actually get a textbook
This is from the lecture notes

[hasty lark]

ok, one sec

https://tutorial.math.lamar.edu/classes/calciii/dipolarcoords.aspx

There are several examples here

[vocal sleet]

@bleak oak Has your question been resolved?

[bleak oak]

Thank, this is great

[vocal sleet]

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Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tribal geode]

question 2g

this is what ive tried

Im just having problems finding the lsope

I end up getting -65/8

this is what the answer key says

[tribal geode]

i forgot to add a y' in the last term

[ornate ember]

hi your derivation looks good (except for that missing y')

it might make it easier on you to actually solve for y' first then plug in your values

when you start pluggin in values that's when the error starts