But how did they isolate x in the 3rd line
#help-17
river kettle
mental falcon
vocal sleetBOT
vocal sleetBOT
Available help channel!
twin bluff
is p XOR q <-> p if and only if ~q?
it sounds right
for example, happy if and only if ~sad.
which means either you are happy XOR you are sad.
vocal sleetBOT
is p XOR q <-> p if and only if ~q?
it sounds right
for example, happy if and o...
@twin bluff Has your question been resolved?
vocal sleetBOT
@twin bluff Has your question been resolved?
whole gulch
vocal sleetBOT
whole gulch
Can someone check to make sure this is right?
vocal sleetBOT
@whole gulch Has your question been resolved?
little portal
should probably ask this on the physics discord
vocal sleetBOT
@whole gulch Has your question been resolved?
hoary arch
Can someone check to make sure this is right?
WELL,
vocal sleetBOT
vocal sleetBOT
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wicked island
Why sigma is equal to (12)?
vocal sleetBOT
Why sigma is equal to (12)?
wicked island
I totaly don’t know how to deal with it
vocal sleetBOT
@wicked island Has your question been resolved?
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undone aurora
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undone aurora
I dont understand how they got 2i - 2j - 2k
stiff current
Do you know how cofactor expansion works?
undone aurora
Do you know how cofactor expansion works?
is that what we use when we usually calculate the determinant
wait so they just solved the determinant?
i(-2 + 4) - j(-1 + 3) + k(4 - 6)
2i - 2j - 2k
oh shit
stiff current
You got it 😂
undone aurora
vocal sleetBOT
undone aurora
Let
A: (-4, -1, -1)
B: (0, 0, 0)
C: (-4, 1, 1)
then the vectors
AB = 4i + 1j + 1k
AC = 0i + 2j + 2k
right?
.close
plain aurora
wait, does the ordering of the eigenvectors/values matter for diagonisation?
plain aurora
what if I swapped the columns 1,2 and 1,3 in P?
can I do that?
while keeping D as it is
proven garden
if I remember correctly the eigenvalues and the eigenvectors must match
vocal sleetBOT
@plain aurora Has your question been resolved?
glossy maple
yeah they need to match
cobalt ocean
what if I swapped the columns 1,2 and 1,3 in P?
if you swapped them in P you'd need to swap them in D
wraith bear
vocal sleetBOT
wraith bear
,rotate
wraith bear
In the answers sheet there were two cases, one if all of the angles were <90° and one where one angle was >90°
How do i know what to do?
Do all of the formulas work or how should i approach the problem?
wraith bear
These are the formulas i should use
(I solved the first case, but dont know how to solve if the triangle is obtuse)
<@&286206848099549185>
indigo vault
<@&286206848099549185>
what are you trying to find in the question
if its an unknown side the sine formula can suffice
vocal sleetBOT
@wraith bear Has your question been resolved?
wraith bear
what are you trying to find in the question
Solve the triangle
indigo vault
right. thanks for the clarification.
ok
you can find one of the sides with the sine formula
vocal sleetBOT
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Available help channel!
copper holly
Hi, how should I go about in solving this combination: 200 C 99?
dawn kestrel
There is a formula for nCr: n!/[r!(n-r)!]
copper holly
There is a formula for nCr: n!/[r!(n-r)!]
Yeah I tried that one, but I reached a point where I have to get the product of all numbers between 200 to 102, after cancelling out (101!) from the denominator. Am I missing something?
trail stream
inverse variation
inverse function*
dawn kestrel
Yeah I tried that one, but I reached a point where I have to get the product of ...
You would need to use a calculator, unless you aren’t allowed to use one?
copper holly
You would need to use a calculator, unless you aren’t allowed to use one?
It is allowed, but I'm just wondering if there's a formula to it other than manually typing on the calc
trail stream
is this channel free
dawn kestrel
It is allowed, but I'm just wondering if there's a formula to it other than manu...
Because the numbers are too big, it’s best just to use a calculator
dawn kestrel
is this channel free
No sorry
copper holly
Because the numbers are too big, it’s best just to use a calculator
I see. Appreciate your help 🙂
.close
vocal sleetBOT
dawn kestrel
No worries
vocal sleetBOT
Available help channel!
vast shale
If an abscissa or an ordinate is 0 what quadrant will it be at?
vocal sleetBOT
If an abscissa or an ordinate is 0 what quadrant will it be at?
vast shale
What will i write then?
outer warren
points on axes aren't part of the quadrants
outer warren
yeh, so they wrote the axis the point is on
vast shale
She made me check the class's math work
outer warren
(-8,0) is a point on the x-axis
(0,6) is a point on the y-axis
no idea what they wrote in red
vast shale
She checked my other classmate's work she wrote correct to Quadrant 2 on (-8,0)
outer warren
dispute it
vast shale
Im too stupid to do that
grizzled bear
is ordinate short for coordinate or sthng
magic wasp
is ordinate short for coordinate or sthng
"ordinate" is the y value, as opposed to abscissa
vast shale
Ill just put a check on quadrant or axis idc anymore bruh
grizzled bear
"ordinate" is the y value, as opposed to abscissa
ah so they thought saying x and y is too easy and made funny names for them, got it
vast shale
I don't think the teacher wrote anything in blue
I write in blue mfs steal pens in my class
outer warren
i suppose you could write negatve/postive x/y axis to be more specific
vast shale
Thank you
magic wasp
ah so they thought saying x and y is too easy and made funny names for them, go...
You don't say (x,y) every time you want to say "coordinates", do you?
grizzled bear
just say point
magic wasp
Not the same thing
vocal sleetBOT
@vast shale Has your question been resolved?
vast shale
Yuh
fluid ivy
?
bleak prawn
$3x^3 \mid^3_1$
twin meteorBOT
Rootsyl
bleak prawn
$= 3 \cdot 27-3 = 78$
twin meteorBOT
Rootsyl
fluid ivy
i got 78 for my first answer
still said it was wrong
threw it into chat gpt for my 2nd attempt and it gave me 24
pale perch
,w integrate (9x^2) from x=1 to x=3
twin meteorBOT
fluid ivy
idk man both says its wrong 🤷♂️
pale perch
chatgpt
fluid ivy
chatgpt<:bleakkekw:913344117981999125>
fr 😭
oh wait
nah ok i see what i did
human error on my part 💀
bleak prawn
as in typing 78 in the answer box?
fluid ivy
shhh
bleak prawn
xD ok
vocal sleetBOT
fluid ivy
thanks for help
vocal sleetBOT
Available help channel!
waxen hawk
I have a very serious question
vocal sleetBOT
I have a very serious question
magic wasp
Very seriously ask it, then
astral shadow
Scary.
magic wasp
Are you asking "how to draw anything in a graphing software"?
waxen hawk
How to transcribe the iconic circles into number line that people would recognize it as Mickey
In number line, not the plane
magic wasp
I don't understand the question
drifting jackal
How to transcribe the iconic circles into number line that people would recogniz...
What do you mean by "Mickey"
pale perch
youre trying to turn a 2d mickey mouse image, into a 1d line and have that be recognisable?
outer warren
could you show an example of what you'd want/expect with a heavily simplified example
for just two circles?
waxen hawk
waxen hawk
That is Mickey in a plane, which you would recognize immediately when you see it
pale perch
okay
waxen hawk
Is it possible to transcribe the characteristic of Mickey into number line
rain spear
Is it possible to transcribe the characteristic of Mickey into number line
you can write equations for circles in graphing calculators such as desmos
waxen hawk
The characteristic that people would recognize it as Mickey
pale perch
if you 'squash' any 2d thing into 1d, it becomes a line, idk what you want to happen for it to be 'recognisable'
rain spear
The characteristic that people would recognize it as Mickey
you can also color and shade regions for different graphs
drifting jackal
you can write equations for circles in graphing calculators such as desmos
That's not what's being asking, they want a 2d image as a 1d and still be recognizable in 1d
pale perch
at most youd have a line of 3 distinct colours maybe but no one would think 'oh thats mickey mouse'
outer warren
could you show an example of what you'd want/expect with a heavily simplified example
for just two circles?
drifting jackal
That's 2d
outer warren
or even just one circle
magic wasp
@waxen hawk Is this what you mean?https://www.desmos.com/calculator/mcezwauplg
rain spear
<@708594064060055583> Is this what you mean?https://www.desmos.com/calculator/mc...
bro,, from where u got those numbers
outer warren
like what would you do on a line to make me think that its intended to be a circle
and not some other shape like square / rectangle or any other polygon or something else entirely
magic wasp
bro,, from where u got those numbers
I didn't
waxen hawk
> could you show an example of what you'd want/expect with a heavily simplified ...
I’m expected sth like the “barcode” of an item. I mean barcode is sort of a one dimensional stuff but the robotic sensor can recognize it immediately
I want a one dimensional Mickey which people can recognize
magic wasp
Good luck with that
waxen hawk
It doesn’t necessarily have to be the barcode
outer warren
colours/shading might help
based on distance from the x-axis
and you could use that to depict the top of mickeys head
vocal sleetBOT
@waxen hawk Has your question been resolved?
twilit plume
Can someone help me get answers for my algebra 2
vocal sleetBOT
Can someone help me get answers for my algebra 2
ivory yarrow
ayy im watching young sheldon right now
twilit plume
lol
ivory yarrow
you know the basics? what sin, cos, tan, cot, sec, cosec are? their relations?
twilit plume
Gonna be honest I don’t know anything about this math
I’m failing this class I cannot understand this kind of math
twilit plume
I’m drawing a blank
I genuinely don’t think it’s possible for me to understand this
vocal sleetBOT
@twilit plume Has your question been resolved?
vast shale
vocal sleetBOT
vast shale
My work process… the bounds if I replace the xs with us don’t seem right
cursive comet
tranquil trail
what am i doing wrong ?
vocal sleetBOT
@tranquil trail Has your question been resolved?
coarse ridge
Need help with 2.(D)
vocal sleetBOT
Need help with 2.(D)
twin meteorBOT
LordFelix
coarse ridge
Okay let me try
vast shale
use a calculator
coarse ridge
Yeah it's true
$92^{100}+93^{100} < \binom{100}{0} 93^{100} + \binom{100}{1} 93^{99} + ... $ $\$
$92^{100} < 1.something × 93 × 93^{99} + ...$
coarse ridge
use a calculator
Not allowed
somber portal
$92^{100}+93^{100} < \binom{100}{0} 93^{100} + \binom{100}{1} 93^{99} + ...$
twin meteorBOT
LordFelix
somber portal
you forgot the dollar signs
coarse ridge
Yeah
somber portal
$92^{100}+93^{100} < 93^{100} + 100 \cdot 93^{99} + [99 more terms]$
somber portal
if this last one is not obvious, you'd expand the 100 to (93+7)
coarse ridge
hmm we can weite 100 as 93 times 1.something as well where the something is positive
somber portal
so you'd have:
$92^{100} + 93^{100} < 93^{100} + 93^{100} + 7 \cdot 93^{99} + K$
twin meteorBOT
LordFelix
somber portal
where K is the other 99 terms of the expansion
coarse ridge
Alright got it, thanks
somber portal
you could even simplify the 93^100 in both sides and then repeat the algorithm if you want it of the form 0<something
dull basin
hey, could someone help me figure out what I'm doing wrong?
vocal sleetBOT
hey, could someone help me figure out what I'm doing wrong?
dull basin
I'm struggling to find f(u); even if I factor everything out & factor out du, i get (5x^2-2x+5) and i'm not sure if that gets me any closer
calm lantern
u^2 seems good, I don't know why it's marked as wrong (I assume)
But then your last answer is wrong
Why 70 and 45? and why 15 at the denominator?
dull basin
oh because I plugged 5x-5 back into u^2, and solved for the antiderivative (5x-5)^3/15
graceful surge
u^2/5?
calm lantern
Oh yes, that should be u^2 / 5
dull basin
!
calm lantern
My bad 😄
dull basin
where does the /5 come from?
graceful surge
du/5 = dx
calm lantern
From the fact that du = 5dx
dull basin
but when we divide the integral by 5 we don't get (5x-5) (the value of u)
graceful surge
❓
dull basin
ohhhh
nvm, i got it, i think
is it because the function is (u)^2dx, so then we sub in du/5 for dx?
so then we get u^2 / 5
that makes sense
thanks so much!
graceful surge
teal flicker
Hey hello can I get help for mathcad?
vocal sleetBOT
Hey hello can I get help for mathcad?
teal flicker
i had an old mathcad file but I converted it but because I did not define depsj it does not run properly
vocal sleetBOT
Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.
@teal flicker Has your question been resolved?
teal flicker
this is the problem I suppose
depsj seems to be undefined
it works in old mathcad versions but not in new versions (mathcad prime/express)
does anyone know mathcad here
vocal sleetBOT
@teal flicker Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
@visual sonnet Has your question been resolved?
pale perch
,rccw
twin meteorBOT
pale perch
just a picture isnt particularly helpful to us, what exactly do you need help with
vocal sleetBOT
@visual sonnet Has your question been resolved?
iron breach
vocal sleetBOT
vocal sleetBOT
@iron breach Has your question been resolved?
vocal sleetBOT
@iron breach Has your question been resolved?
sweet flower
vocal sleetBOT
sweet flower
I got to the diophantine equation of ABC = A + 2B + C
but i dont know how to solve diophantine equations with 3 variables
ABC - A - 2B - C = 0
A(BC-1) - 2/C * (BC - 1) - 2/C - C = 0
AC(BC-1) - 2 * (BC - 1) - 2 - C^2 = 0
(AC-2)(BC-1)=C^2+2
and then i got stuck
<@&286206848099549185>
acoustic herald
if the number is 999, the A+2B+C is 36, so the numbers are small. so it is possible to try every number order satisfy these condition.
ig
sweet flower
if the number is 999, the A+2B+C is 36, so the numbers are small. so it is possi...
its a counting problem so i doubt they would expect you to try every number
acoustic herald
but only a little number needs to be try
sweet flower
but only a little number needs to be try
but still its in the hundreds in quantity
sweet flower
less than 20 ig
no because numbers from 4-36 are possible to make
so the number needs to be a combination of the factors of that number
thers a lot to try
acoustic herald
ABC is all less than 10
so it can be factorize by 2 3 5 7
2^a * 3^b * 5^c * 7*d, a<=5, b<=3 ,c<=2 ,d<=1
vocal sleetBOT
@sweet flower Has your question been resolved?
woven siren
can someone help me on linear relationship question
vocal sleetBOT
can someone help me on linear relationship question
woven siren
its only year 9 math
i got f h j and l wrong
i was using the formula y2-y1/x2-x1 (sorry i accidentally wrote it wrong the first time)
crude arrow
i was using the formula y2-y1/x2-x1 (sorry i accidentally wrote it wrong the fir...
whatt
pallid zenith
its the formula for the gradient
crude arrow
its the formula for the gradient
the slope?
woven siren
yeah
pallid zenith
gradient of a line is a slope
crude arrow
what I rememberd as gradient
pallid zenith
theyre equivalent here
woven siren
its the formula for the gradient
is the first one always 1 right?
twin meteorBOT
nosqldb
crude arrow
this has to be some british stuff
pallid zenith
no, all components of the formula need to be grabbed from the points
they can all change based on the given information
dull bear
i was using the formula y2-y1/x2-x1 (sorry i accidentally wrote it wrong the fir...
(anyways, how did you use the formula?)
woven siren
(anyways, how did you use the formula?)
ill use question f as an example:
-2-4/1--2
dull bear
You're using the y coordinate in the numerator
woven siren
idk what is a numerator
dull bear
i was using the formula y2-y1/x2-x1 (sorry i accidentally wrote it wrong the fir...
(saw the edit: doesn't matter which way around you do it, as long as you're consistent!)
crude arrow
(saw the edit: doesn't matter which way around you do it, as long as you're cons...
^^
outer warren
numerator is the top part of the fraction
woven siren
You're using the y coordinate in the numerator
yes
i got f and h right, maybe i was just doing it wrong
dull bear
Anyways, the gradient between the points $({\color{red} x_1} , {\color{green} y_1 })$ and $({\color{orange} x_2}, {\color{yellow} y_2})$ is as you've said
[
\frac{ {\color{green} y_1 } - {\color{yellow} y_2} }{ {\color{red} x_1} - {\color{orange} x_2} } = \frac{ {\color{yellow} y_2} - {\color{green} y_1 } }{ {\color{orange} x_2} - {\color{red} x_1} }
]
twin meteorBOT
@dull bear
dull bear
ill use question f as an example:
-2-4/1--2
For this one, you can choose e.g. (x1, y1) to be (-2, 4) and (x2, y2) to be (1, -2)
ornate ember
Anyways, the gradient between the points $({\color{red} x_1} , {\color{green} y_...
I appreciate your dedication to proper coloring
dull bear
how to unnocupy it
You type .close
vocal sleetBOT
dull bear
I appreciate your dedication to proper coloring
why thank you 
vocal sleetBOT
Available help channel!
fast lark
hello I have a question about a random polynomial I came across in my physics research
vocal sleetBOT
hello I have a question about a random polynomial I came across in my physics re...
fast lark
$P_n(x)=e^{-x}\sum_{m=0}^\infty\frac{x^m}{m!} (m+x)^n$
twin meteorBOT
spaghetti
fast lark
I don’t think it’s a hypergeometric function and I’m wondering if anyone has come across a polynomial like this, or if there’s any way to solve it
sorry if this is not allowed, I just joined
crude arrow
hello I have a question about a random polynomial I came across in my physics re...
what kind of physics research if you don't mind me asking
also prob not the place for it
I think it's fine to post it here, but you probably won't get any good replies
vocal sleetBOT
@fast lark Has your question been resolved?
fast lark
what kind of physics research if you don't mind me asking
these are the n-th moments of an energy distribution of a simple harmonic oscillator with a recoil energy (the m labels the SHO quanta and the x is (square of) the momentum transfer, so the recoil energy gives you the +x in the (m+x)^n)
lapis marten
Have you tried using the binomial expansion?
fast lark
Have you tried using the binomial expansion?
I could ‘t see how to get rid of the m^k/m!
maybe there’s an easy trick I don’t know, sorry
I did find this…
$\frac{d}{dx}P_n(x)=nP_{n-1}(x)+\sum_{k=0}^{n-1}\binom{n}{k}P_k(x)$
twin meteorBOT
spaghetti
fast lark
but idk how that helps
fast lark
what kind of physics research if you don't mind me asking
it’s just a simple toy model of a simple harmonic oscillator I was using to check some nuclear physics numerical calculations. But I keep on finding strange mathematical identities hidden in it
vocal sleetBOT
it’s just a simple toy model of a simple harmonic oscillator I was using to chec...
fast lark
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
karmic mica
is there a functional equation calculator
vocal sleetBOT
is there a functional equation calculator
jolly epoch
hybrid mantle
do you mean a function?
karmic mica
no
brisk moss
problems involving functional equations are usually not as algorithmic, procedural, and finite as problems calculators can do
vocal sleetBOT
brisk moss
maybe there are some out there for specific types of problems
vocal sleetBOT
Available help channel!
wintry summit
why cant u just separate them
limx->1 (x/(x-1)) - limx->1 (1/lnx)
apply l'h to both
u get limx->1 (1/1) - limx->1 (x)
and u get
1-1
=0
but answer is 1/2 after u combine the fractions and apply l'h twice
vocal sleetBOT
why cant u just separate them
limx->1 (x/(x-1)) - limx->1 (1/lnx)
apply l'h to b...
hard atlas
if you would separate them then you would have something like infty-infty. which can equal pretty much anything
wintry summit
.close
vast shale
Hello.
I have participated in a geometry competition in my school, and I am currently preparing. I need help solving these 5 problems, please.
patent nymph
,rotate
twin meteorBOT
patent nymph
Hello.
I have participated in a geometry competition in my school, and I am cur...
Have you tried drawing a diagram?
vocal sleetBOT
@vast shale Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
vast shale
A Level Further Mechanics problem, don't really know where to start
vast shale
I have a feeling this is not very difficult, I just need a push
cedar kernel
hm do you know what work energy principle is?
vast shale
Yes, but I covered it about a month ago and am not sure exactly how to apply it here
cedar kernel
in short , change in kinetic energy = sum of work done by all forces
what are the forces acting on the ball as it goes up
unborn wind
isnt this a physics question
cedar kernel
mostly yes
vast shale
isnt this a physics question
Yeah lol but it is one of the topic in A Level Further Maths
Mechanics is a mandatory part of the course
unborn wind
sheesh
cedar kernel
Yeah lol but it is one of the topic in A Level Further Maths
this came in maths?
ah ic
i just learned about it
anyways , can you point out the forces acting on the object
vast shale
anyways , can you point out the forces acting on the object
They are not given
Are they?
cedar kernel
kinda
vast shale
well gravity is obvious
cedar kernel
the balls slows down as it goes up, what makes it do so
cedar kernel
well gravity is obvious
right and one more
vast shale
so the ball's weight, which is 2g
vast shale
right and one more
friction
unborn wind
how would you calculate wrk done by friction if the coefficient is not given
cedar kernel
how would you calculate wrk done by friction if the coefficient is not given
its given
unborn wind
my eyess
cedar kernel
its alr happens
vast shale
In mechanics I mainly have trouble which pieces of info are relevant and which aren't
cedar kernel
now try to see what else you need for aply work energy theorem
vast shale
In mechanics I mainly have trouble which pieces of info are relevant and which a...
for example i dont see how tan a = 7/24 will come up later
cedar kernel
it will be used to take the component of gravitation force acting on the ball as its in 2d motion
cedar kernel
yeah we have initial ke
vast shale
or sum of work done ig
cedar kernel
and we know what we need as final
cedar kernel
or sum of work done ig
ye thats more apropriate
vast shale
it is static
cedar kernel
so what is its speed
vast shale
0
cedar kernel
nice!
now we got all required info for lhs and some from rhs
lets complete rhs
(lhs - left hand side , rhs - right hand side )
cedar kernel
its on an inclined plane
cedar kernel
its on an inclined plane
^
vast shale
so we must find the length of the plane
cedar kernel
grvity always acts downwards
vast shale
using tan a = 7/24 i assume
cedar kernel
yeah we need to find the component of gravity which is responsible for slowing it down
take one component along the inclined plane , and one perpendicular to it , and try to break g into thoese
as the component along the inclined plane will slow the ball down , and the perpendicular will help with friction ( normal force)
vectors?
cedar kernel
i mean you will need sin alpha and cos alpha
so .. just find cos and sin from it ig
vast shale
okay so the normal force is 18.83 N
so the other component will be 2g-18.83
right?
so if alpha = 16.26 deg
vast shale
ok
cedar kernel
hm
i got (7*4)/5 as mgsin alpha
um can you recheck
what fraction you got for sin alpha
( tan alpha = perpendicular / base , sin alpha = perpendicular / hypoteneus , cos alpha = base / hypoteneus ) , we have tan alpha , so we have perpendicular and base , hence we can find hypoteneus using pythagorus theorem
if we know hypoteneus we can find sin and cos
also sometimes you can leave things in fraction ( it simplifies calculations things at the end , and you wont be required to use a calculator!)
vast shale
yes it is allowed
cedar kernel
should work , lemme check
vast shale
and arctan(7/24) = 16.26 deg
vast shale
mg sin(16.26) = 0.559g
so this should check out
cedar kernel
i just didnt do decimal so got confused
yeah mb
i was like thats too small
brain stopped
right continueing
so whats work done by gravity
cedar kernel
thats what we have to find
vast shale
understood
cedar kernel
you see whats happening now?
vast shale
yes i think so
cedar kernel
plug in the values
vast shale
if w = fd, d = w/f
vast shale
gravity is 5.6 g right?
vast shale
yes
cedar kernel
2mg sin alpha
vast shale
work is just 5.6d then
cedar kernel
gravity is 5.6 g right?
*gravitational force on ball acting oposite to the motion of it
yes!
now find work done by fricion
as thats also a force acting on the ball
and it does contribute in the stopping of the ball
cedar kernel
work is just 5.6d then
one more thing , will it be negative work done or positive
vast shale
one more thing , will it be negative work done or positive
negative
cedar kernel
yes cool continue
vast shale
multiply by 1/8 ?
cedar kernel
ye as friction force is mu N right?
vast shale
yes
cedar kernel
this will be negative or positive?
vast shale
negative again?
vast shale
2.3525 J is the work done by friction
cedar kernel
lhs is know and there is one unknown in rhs
cedar kernel
i didnt calculate stuff , but if you followd everything correctly yeah
vast shale
how do you solve linear equations again?
cedar kernel
so 196 = 2.325 - 5.6d
also shoulnt the negative sign be on both work done , and d on both
vast shale
how do you solve linear equations again?
just kidding lol
cedar kernel
oh lmao-
vast shale
also shoulnt the negative sign be on both work done , and d on both
yes true
cedar kernel
work done is force * displancement not just force
vast shale
for the most part
cedar kernel
( do this question once more on your own to check yourself if you want )
vast shale
I will ask my teacher on monday as well
vast shale
( do this question once more on your own to check yourself if you want )
I will
Thank you
.close
vocal sleetBOT
cedar kernel
cool
vocal sleetBOT
Available help channel!
green zenith
hi I need help with this math prublem
vocal sleetBOT
hi I need help with this math prublem
rich kite
erm
cursive comet
Just believe in yourself
cursive comet
You can do it
green zenith
Ok I’m just stumped
uneven forge
Hey id need help from someone who speaks french
vocal sleetBOT
Hey id need help from someone who speaks french
uneven forge
livid tapir
,rotate 180
twin meteorBOT
livid tapir
I don't speak fr*nch of course but I figured I might as well rotate for the next helper who does
uneven forge
Oh yes lol
rich kite
which exercise
rich kite
2nd is solve for n?
uneven forge
- n is a natural number, 𝑛≥ b) p is a natural number such that 0≤𝑝≤𝑛. you show that the number of draws with exactly 𝑝 white balls is (𝑛𝑝)^2.
I thout saying that (n p)=(n n-p)
Bcs it was in the lesson
<@&286206848099549185>
<@&286206848099549185>
🥺
vocal sleetBOT
uneven forge
.reopen
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✅
rich kite
i can solve it for n, I dont understand what the task is asking for
(for the 2nd exercise
uneven forge
i need help with the third x)
vocal sleetBOT
@uneven forge Has your question been resolved?
north ocean
May I know what is exponential
vocal sleetBOT
May I know what is exponential
tidal umbra
that has a exponent in it?
twin meteorBOT
~ ℂ𝕣𝕒𝕗𝕥𝕒𝕥𝕠𝔻𝕦𝕕𝕖𝕤 ~
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
river minnow
Exponential equation just means that a term of the form a^x is present, where a is some constant and x is the unknown
tidal umbra
u can write $3^{x+2}$ as $3^x \cdot 3^2$
twin meteorBOT
🐱!Yajat! 【Catfan1398】🐱
north ocean
u can write $3^{x+2}$ as $3^x \cdot 3^2$
Oh ok thx
tidal umbra
and then u can sub in a value
river tiger
vast shale
vocal sleetBOT
proven garden
when you place pasta, you won't place it perfectly
vast shale
Like it can be 2.1m since its correct to the nearest 0.1m and nearest 0.1m will be 2.1m?
And 11.5 already has 0.5
So its already correct?
I know how to solve dis but im getting 18.2 and the answer is 18
vast shale
What does correct to the nearest mean
And a student said im wrong bout this so i need clarification
proven garden
so 11.5 correct to the nearest 0.5 means from 11.5-0.5 to 11.5+0.5
wait no
11.5-0.25 to 11.5+0.25
proven garden
like
if you have 11.8
we consider 11.5 and 12
and choose the closest
which is 12
vast shale
So how what do i do @proven garden
Is it 2.1m and 12 cm?
NO
ITS 2.1m
Jk
Idk
Isk
Idk
What grade is dis
Bro stop confusing meh
):
U trollin me
Why u do that man
Like thats very
Mean
What grade u is doe
Oof
Same
Beo i aint lyin
So can u help or nah
Igcses
Idek wat ure saying 💀
.close
languid dune
Tried looking for counter examples
vocal sleetBOT
Tried looking for counter examples
cursive comet
For a matrix to be invertible it has to have an inverse
And for it to have an inverse it has to be regular i.e. it has to have determinant ≠ 0
Considering det(AB)=det(A)det(B)
If ST is invertible, then det(ST) ≠ 0
Which means det(S)det(T) ≠ 0
Hence neither S nor T are singular
So they are invertible
hard atlas
!nosols. also, try showing this without determinants. just with injective and surjective
vocal sleetBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
@languid dune Has your question been resolved?
hollow marten
can someone help me with this question?
vocal sleetBOT
can someone help me with this question?
median crane
Use log properties
hollow marten
i am, maybe im doing a mistake somewhere idk
urban valley
i am, maybe im doing a mistake somewhere idk
log x + log y = log(xy)
now
2log(x+y) => log(x+y) ^2
now
both have log
therefore same function
so you can ignore log
now if you expand you will get
desire result
hollow marten
alright ill try once again!! thank you
got it, i read the question wrong earlier!!
vocal sleetBOT
@hollow marten Has your question been resolved?
gloomy shuttle
Hello, I have a question about graph theory.
I need to show that given a graph with [n] vertices, there's (image) possible grpahs such that all the degrees of the vertices are even.
Please help I have been working for hours.
vocal sleetBOT
Hello, I have a question about graph theory.
I need to show that given a graph...
@gloomy shuttle Has your question been resolved?
gloomy shuttle
<@&286206848099549185>
hard atlas
imagine removing one fixed vertex from all such graphs. which graphs do you end up with
vocal sleetBOT
@gloomy shuttle Has your question been resolved?
woeful bough
Probability and Statistics ...
vocal sleetBOT
Probability and Statistics ...
vocal sleetBOT
@woeful bough Has your question been resolved?
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@woeful bough Has your question been resolved?
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@woeful bough Has your question been resolved?
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@woeful bough Has your question been resolved?
flat whale
Can someone tell me why he uses
**Z alpha**
Instead of
**Z alpha/2**
Because he changed the 95% to 97.5%
They're equivalent
vocal sleetBOT
@woeful bough Has your question been resolved?
woeful bough
Because he changed the 95% to 97.5%
But what values changed in his solution by performing that?
flat whale
But what values changed in his solution by performing that?
You already pointed it out. z_alpha instead of z_alpha/2
Nothing else changes
woeful bough
Oh right i see so just the confidence level then. Ty
vocal sleetBOT
@woeful bough Has your question been resolved?
heavy talon
if XYZV is a tetrahedron with an inscribed inside sphere will the centers of the incircles of all the sides meet at the center of the inscribed sphere?
vocal sleetBOT
if XYZV is a tetrahedron with an inscribed inside sphere will the centers of the...
heavy talon
I mean perpendicular rays going through the centers
vocal sleetBOT
@heavy talon Has your question been resolved?
heavy talon
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vestal comet
Is this correct?
vocal sleetBOT
Is this correct?
vast shale
Is this correct?
yep
lean osprey
Am i proving big O correctly here
lean osprey
.close
grizzled bear
This correct?
vocal sleetBOT
This correct?
grizzled bear
,rotate
twin meteorBOT
grizzled bear
Damn my handwriting looks worse on cam
lime gorge
Nah it just looks better in ur eyes
Wait so I get the -2tsin(t^2)
*t
Now all u have to do is differentiate that no?
grizzled bear
Yeah
lime gorge
$\frac d{dt} [t \frac d{dt} \cos (t^2)] = \frac d{dt} [t \cdot -2t\sin(t^2)] = -2\frac d{dt} [t^2 \sin(t^2)]$
This is ur original problem right
grizzled bear
Oh shit well that looks easier
twin meteorBOT
Stephen
lime gorge
Yes
grizzled bear
Same answer
lime gorge
Aigh lemme see
grizzled bear
Same answer
Doing the inner deriv is easier tho, better than having higher derivatives, noted
lime gorge
,w differentiate -2x^2 * sin(x^2)
twin meteorBOT
lime gorge
Ok u good
lime gorge
Np
grizzled bear
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vocal sleetBOT
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Available help channel!
half oak
i have solved α and β i need help with γ dont know where to start
half oak
i know that $\lim _{x\to -1}\left(g\left(x\right)\right)=-3$ and $\lim _{x\to -1}\left(f\left(x\right)\right)=4$
twin meteorBOT
Striker
vocal sleetBOT
@half oak Has your question been resolved?
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half oak
.reopen
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half oak
<@&286206848099549185>
naive mirage
Yo
half oak
can you help
naive mirage
I can’t read the question lol
half oak
i explained it in message i only need γ) the top says let f,g:R->R such that this inequiality is true for all x
and i need to find the limits i have done α,β
pls read above
indigo comet
So just γ unsolved?
You can do it by the definition of derivative
The condition of g(x) in the problem is same thing with g'(-1)=5
And the answer of β is f'(-1)
indigo comet
But if you didn't notice that
You also can do this problem
Rewrite the numerator as
(f(x)-4)(g(x)+3)+4g(x)-3f(x)+24
half oak
pls explain how
indigo comet
Because we need to accord with the form of derivative
half oak
no derivative here man
indigo comet
So just γ unsolved?
You can do it by the definition of derivative
The condition...
I explained there
The limit is equal to the derivative at x=-1
The purpose of rewritting is to accord this form of limit
So we factorize and add/subtract terms
(f(x)-4)(g(x)+3)+4g(x)-3f(x)+24=(f(x)-4)(g(x)+3)+4[g(x)+3]-3[f(x)-4]
So we can decompose the problem to the sum of three limits
Numerator are (f(x)-4)(g(x)+3) 、g(x)+3 and f(x)-4 respectively
The coefficient before the limit is 1、4 and -3, respectively
And the denominators are all x+1
The last two limits are easier
It's equal to 4g'(-1)-3f'(-1)
And some techniques used
in the first one
We use the following property
If k(x)=m(x)n(x)
And lim m(x) and lim n(x) exist when x→a
Then lim k(x) exists when x→a and it is equal to [lim m(x)][lim n(x)] (when x→a)
So we can rewrite the limits again
When x→-1
lim [(f(x)-4)(g(x)+3)]/(x+1)
={lim [(f(x)-4)(g(x)+3)]/(x+1)²}[lim (x+1)]
=[lim (f(x)-4)/(x+1)][lim (g(x)+3)/(x+1)][lim (x+1)]
=f'(-1)g'(-1)(0)
=0
So the final answer is 4g'(-1)-3f'(-1)
2nd method:If you know the definition of derivative
Then you can directly write the answer is [f(x)g(x)]' at x=-1
i.e. f'(-1)g(-1)+f(-1)g'(-1) (using product rule)
vocal sleetBOT
@half oak Has your question been resolved?
indigo comet
I just use the derivative to simplify the expression of limit in the first method
If you didn't notice that the limit given by problem and in part β are equal to the derivative at x=-1, you can also do by that means
I think I should sleep
ivory lichen
Hey js need some clerafication on what these letters mean and how to awnser
median crane
Who do I remember nothing about hypothesis testing
but x bar is like the mean
One of them is the sample mean probably
H0 is the null hypothesis ie the default hypothesis
H1 is the alternative hypthesis
How to answer? Send the whole question
vocal sleetBOT
@ivory lichen Has your question been resolved?
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@ivory lichen Has your question been resolved?
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vocal sleetBOT
Available help channel!
fading spear
vocal sleetBOT
fading spear
Okay so the work is really messy but basically I have to find:
Sin(x/2)
Cos(x/2)
Tan(x/2)
If csc(x)=7 for 90 to 180 degrees (quadrant 2)
I found sin by inverting csc and cos by plugging sin into the pythagorean identity
I'm trying to use the half angle theorem to solve for sin, cos, and tan, but it's pretty messy
I somehow got -1 for tan(x/2) but... I have very little confidence in that answer
vocal sleetBOT
@fading spear Has your question been resolved?
vocal sleetBOT
@fading spear Has your question been resolved?
fading spear
you can't cancel like that
Good to know
lucid bane
$\frac{a-b}{a+b} \ne \frac{-b}{b}$
twin meteorBOT
Moosey
fading spear
Wow
fading spear
$\frac{a-b}{a+b} \ne \frac{-b}{b}$
Do you have this memorized?
lucid bane
wydm
in your case I would multiply numerator and denominator by 7-4sqrt(3)
if you wanted to get rid of the 7+4sqrt(3) in the denominator
this is called multiplying by the conjugate
@fading spear
fading spear
Sorry I'm just looking at my work
That would still leave the denominator as a fraction wouldn't it?
lucid bane
no, cause of difference of squares! (if you multiply it out)
you have $\frac{a-b\sqrt{c}}{a+b\sqrt{c}}$
twin meteorBOT
Moosey
lucid bane
I am telling you multiply numerator and denominator by a-bsqrt(c)
(this is same as multiplying by 1
$\frac{a-b\sqrt{c}}{a+b\sqrt{c}}\cdot\frac{a-b\sqrt{c}}{a-b\sqrt{c}}$
twin meteorBOT
Moosey
lucid bane
note that when you have $(x-y)(x+y)$, it is equal to $x^{2}-y^{2}$
twin meteorBOT
Moosey
lucid bane
this is called difference of squares
do you see how the square root in the denominator would disappear now when we do this?
balmy delta
I can't figure this problem out. logbase3(5)+logbase3(x-4)=2. I simplified it down to logbase3(5x-20)=2 but dont know what to do from here
vocal sleetBOT
I can't figure this problem out. logbase3(5)+logbase3(x-4)=2. I simplified it do...
dull bear
What's the aim, solve for x?
balmy delta
yes
jagged cargo
I can't figure this problem out. logbase3(5)+logbase3(x-4)=2. I simplified it do...
2 can be rewritten as $log_{3}(3^2)$
Move it to the lhs and solve for x normally
jagged cargo
What do you mean?
balmy delta
Im working with base 3 maybe i mistyped it
twin meteorBOT
FungusDesu
jagged cargo
my bad, it was my fault