#help-17

1 messages · Page 111 of 1

obtuse scroll
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the radius is $\sqrt{g^2+f^2-c}$

twin meteorBOT
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diaas_(yt)

obtuse scroll
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So you can just rewrite it as $(x+g)^2+(y+f)^2=r^2$

twin meteorBOT
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diaas_(yt)

obtuse scroll
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That's pretty much it

tepid fossil
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thanks

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alpine cipher
#

Hi, I need some help with Polynomial Vector subspaces

alpine cipher
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Specifically, how you'd calculate one whose condition (I think that's the correct term?) is a differential equation

cyan talon
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if you show the question sure

alpine cipher
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yeah just figuring out how to type it in here

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one sec

cyan talon
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pics are fine no problem

alpine cipher
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hopefully this is readable

cyan talon
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yeah np

alpine cipher
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I've done the existence of a zero vector part already, bc that was pretty easy, but I'm stuck on how I'd show the closure under vector addition and scalar multiplication parts

cyan talon
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well how do you start to show closure under vector addition ?

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in general

alpine cipher
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in general I'd show that for any two vectors that satisfy the condition, call them x and v, the vector (x + v) also satisfies the condition

cyan talon
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yea exactly

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so let's do that

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we have a polynomial p with p''(-8) +3p(-8) = 0, and q with q''(-8) + 3p'(-8) = 0

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and we wanna show p+q also satisfies that condition i.e. (p+q)''(-8) + 3(p+q)'(-8) = 0

alpine cipher
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yeah

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I get stuck trying to show that

cyan talon
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yeah what do you get ?

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you're stuck at (p+q)''(-8) + 3(p+q)'(-8) = ... directly ?

alpine cipher
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mostly I get stuck at trying to find a way to express p" and p' in terms of p

cyan talon
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yeah you don't need to

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you prolly know from calculus that the derivative is a linear operator

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i.e. the derivative of a sum of two functions is the sum of the derivatives

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& that (c*f)' = c*f'

alpine cipher
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where c is a constant?

cyan talon
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yes

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that solves the whole question pretty much

cyan talon
alpine cipher
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ok

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thank you

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from that, how would I word it?

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like, would I just say that for some p in S, since the derivative is a linear operator, np where n is in the set of all Real numbers satisfies the condition as
(np)"(-8) - 3(np)'(-8) = 0
n(p"(-8) - 3p'(-8)) = 0
substitute p"(-8) - 3p'(-8) = 0 as p is in S
n(0) = 0

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and that's scalar multiplication, and a similar wording for vector addition

cyan talon
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yeah

alpine cipher
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sweet

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thank you so much

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you just did in like 15 minutes what 2ish hours of google and rereading course notes couldn't

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vast shale
vocal sleetBOT
vast shale
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im not sure what i'm doing incorrectly. the expected final answer is 48.41

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help

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!status

vocal sleetBOT
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placid osprey
#

Hi there,

I have a question about vector decomposition. The vectors $u$ and $v$ are given as shown in the figure below. I need to break down vector $u$ into the sum of two components, namely $u_{|v}$ (parallel to $v$) and $u_{\perp v}$ (perpendicular to $v$).

Could someone please help me with this decomposition and provide the coordinates in the form of column vectors like $\left[\begin{array}{l}a \ b\end{array}\right]$?

twin meteorBOT
vocal sleetBOT
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@placid osprey Has your question been resolved?

vocal sleetBOT
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@placid osprey Has your question been resolved?

vocal sleetBOT
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@placid osprey Has your question been resolved?

vocal sleetBOT
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@placid osprey Has your question been resolved?

vocal sleetBOT
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@placid osprey Has your question been resolved?

vocal sleetBOT
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@placid osprey Has your question been resolved?

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vapid wedge
#

Isn't this the same as doing 1/squareroot(3) * 1/squareroot(2) ?

flat whale
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Yes

paper depot
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yes

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btw you should write sqrt for square root in plaintext.

vapid wedge
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so 1/squreroot(6)?

paper depot
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1/sqrt(6), yes.

vapid wedge
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Aah thanks was gonna ask that haha

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But i have a question regarding that

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This is the original question that i am on

paper depot
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🙃

vapid wedge
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My first guess would be to move sqrt(3) to the right hand side by dividing, right?

vapid wedge
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however, my first problem comes when trying to do that since it's (-) between them, does that mean Asin(x-phi) ?

paper depot
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but also you should not be describing this stuff as "moving" between sides

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also no the minus sign doesnt really affect much

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you just have b = -1 here

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and a = sqrt(3)

vapid wedge
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aaahy

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OH

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yeah neat

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we can keep the sqrt(3)

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didn't think of that

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Is this correct so far?

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What happens with the (-1/2)? Do i add 30* on both sides so x = 60 + n360? @paper depot

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hearty wigeon
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Is there anything wong with my notation ?

median crane
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What’s beh bew

hearty wigeon
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Beh means "claim", bew means "proof"

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Those are annotations for German words

median crane
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I wouldn’t write second to last line

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And just skip to the last line

hearty wigeon
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Ok thx.

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eager elbow
#

hello

vocal sleetBOT
eager elbow
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By making good use of the trigonometry form, simplifies the following expressions and gives their domains. ...

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cos(Arctan(x))

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need help i dont know how to start

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i do this then i do what

mental falcon
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so what is the domain of arctan function, and what is its range?

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(starting from the inside of the nested functions, going out)

eager elbow
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its R --> ]-pi/2 ; pi/2[

mental falcon
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yes (-pi/2, pi/2) open interval

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now cos is accepting inputs from that output of the arctan, but what is the domain of cos? it's R so it can handle any output from arctan

eager elbow
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i need to restrict the cos or no ?

mental falcon
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nope

eager elbow
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cos is R --> [-1;1]

mental falcon
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it can handle any of those inputs

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spat out by the arctan

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if it was something with a more restrictive domain for the outer function then you would

eager elbow
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i need to do this ?

mental falcon
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what is that? 🤔

eager elbow
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i need to reunite the dom of arctan and the dom of cos ?

mental falcon
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well both their domains are R

eager elbow
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yes

mental falcon
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i don't think in general you would simply take intersection of their domains...you would need to uh take the subset of the domain of arctan (inner function) such that its output is in the domain of cos (outer function) or something

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like for example say you have:

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$\sqrt{x-5}$

twin meteorBOT
mental falcon
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thing of sqrt as the outer function and (x-5) as the inner function

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square root only accepts positive numbers, while domain of (x-5) is R

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so we want domain such that x -5 > 0

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i.e. the codomain of x - 5 is within the domain of square root

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but honestly just thinking about it logically is easier than adding all this terminology on it, go from inside function to outeside one

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you still with me? 😐

eager elbow
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yes

mental falcon
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ok

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so yeah it would just be x > 5 there 🤷‍♂️

eager elbow
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i try to understand what ur writing because im not good at english

mental falcon
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ah, sorry i dont know math in other languages

eager elbow
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but how i find the domaine of cos(arctanx) ? the domaine is just R

mental falcon
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yes that's it...

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there's nothing else to it :p

eager elbow
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but why its R how i show it mathematicly

eager elbow
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Okey

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last thing how i simplify cos(arctanx)

mental falcon
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there is a theorem that says (here i will copy and paste it), so you can always use that to "show it mathematically" if you are trying to prove something:

The domain of a composite function f(g(x)) is the set of those inputs x in the domain of g for which g(x) is in the domain of f.

eager elbow
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Okey

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but how i simplify cos(arctan(x))

mental falcon
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hm

eager elbow
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i need to use trigonometry formul

mental falcon
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i think you can do with some trick but i dont remember

eager elbow
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yeah trigonometry formula maybe

mental falcon
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you might be able to draw a picture and think about it on the unit circle, or yeah with some trig identity playing around

eager elbow
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hmm

mental falcon
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i found this weird proof online but i never would've thought to write that first line out of thin air 😂

eager elbow
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but what is "sec"

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i never learnt that

mental falcon
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sec function

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sec (x) = 1 / cos(x)

eager elbow
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Ok

mental falcon
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there is the identity 1 + tan ^ 2 = sec ^ 2

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which is why theyre writing the first line, and using arctan x as the input

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anyway its weird but i honestly dont know how i would do that myself

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seems like a tricky proof

eager elbow
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tany=x cos(arctan(x))

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i will try to find

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arctan(x) is an angle so to simplify i need to find the value of cos(x)

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i need to use a formula with tan that gives cos

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cos²(y)=1/1+tan²(y)

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tan(y)=x

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so cos²(x)=1/1+x²

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cosx=1/sqrt(1+x²)

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like that @mental falcon ?

mental falcon
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why does tan x = x?

eager elbow
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yeah tan(y)=x

mental falcon
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i dont know you lost me

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tany=x cos(arctan(x))
and also
tan y = x
?

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so cos (arctan(x)) = 1 ?

eager elbow
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no

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arctan(x) => tany=x

mental falcon
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sorry im not following but also my brain is tired rn and i need to go, maybe you can ask someone else to take a look if you arent satisfied with it

eager elbow
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ok

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bye

mental falcon
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take care

eager elbow
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yep

vocal sleetBOT
#

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lime gorge
vocal sleetBOT
lime gorge
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did i do this right

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wait a second...

cyan talon
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yea there's no X=0

lime gorge
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yepppp

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ok i got 7/30

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is that correct?

cyan talon
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yea, just those 3 cases

lime gorge
#

ty platypus

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rare belfry
#

i need help with a problem it goes like this

Write a squared(quadratic) equation, one solution of which is the sum, and the other is the product of the solutions of the equation
3x² - 2x - 7 = 0
( i dont understand where to start or anything)

rare belfry
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i dont wanna be mean but i already posted in this chanel go to avalible math help thank you mr robin

unreal pagoda
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sry mb

rare belfry
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np

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<@&286206848099549185>

slim oar
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sup

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So let the two equations be a and b

rare belfry
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im listening

slim oar
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You want to find an equation with roots ab and a+b

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which is: (x-ab)(x-(a+b))

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expanding: x^2-x(ab+a+b)+(ab)(a+b)

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ab is -7/3

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a+b is 2/3

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Now substitute them to get the final equation

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which is x^2+5/3x-14/9

rare belfry
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aight i underrstand everything but how is ab -7/3 and a+b 2/3

slim oar
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This is equal to 9x^2+15x-14

rare belfry
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yes thats correct that is said in my mathbook

slim oar
rare belfry
#

thank you so much

#

.close

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unreal pagoda
#

In this exercise, we want to specify a non-Archimedean Field. To do this, we consider rational
functions. If there are polynomials (image 1)

with coefficients a0, . . . , an, b0, . . . , bm ∈ R and bm ̸= 0, we call f =p/q rational. Let f be defined on a
suitable subset of the real numbers (namely R without the zeros of q).

Let R := {f is rational function} be the set of rational functions. In the following you may use that R is a
body with respect to the following addition and multiplication: For rational functions f =p/qand g = r/s

we set
f +R g :=(ps + rq)/qs (image 2)

and f *R g := pr/qs (image 2)

On R we define an order <R by
f <R g : ⇐⇒ there exists M ∈ R with f(x) < g(x) for all x ≥ M. (image 3)
Where < is the known order on the real numbers.

I have a problem with proving that <R is an order on the field R.
Do I just need to prove that the set R is ordered and fulfills the Field axioms?

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#

@unreal pagoda Has your question been resolved?

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tropic anchor
#

How do i do b

vocal sleetBOT
tropic anchor
#

.close

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warped chasm
vocal sleetBOT
warped chasm
#

How do I do this?

hushed pewter
# warped chasm

I would separate $\int \frac{3x+1}{1+4x^2}dx$ into $\int \frac{3x}{1+4x^2}dx+\int \frac{2}{1+4x^2}dx$

twin meteorBOT
warped chasm
#

then what?

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robust heron
#

could someone explain how to do this question for me

robust heron
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i am not entirely sure but I think this is a bernoulli trial type question

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or maybe its geometric

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not really sure

raven owl
robust heron
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ok

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so i have started with defining p, q and X

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but im not exactly sure how to set it up from there

raven owl
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How have you defined them

robust heron
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p=0.02, q=0.98, X=# of products checked

raven owl
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p is good, q is good but I do not think it will be needed. For X, I would add "until a defective item is found"

robust heron
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ok

raven owl
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You have identified its geometric, do you know what to do next?

robust heron
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thats where im a little stuck

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i know im going to have to do the summation and convergence stuff
but im not sure how to get there first

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oh wait isnt there a property that says P(X>=k)=(1-p)^k

raven owl
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Yeah

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There is also one that says P(X=k)=(1-p)^(x-1)p when X is geometric

robust heron
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ok but in this case i need the > right?

raven owl
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oh yeah true

robust heron
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so should i just sub in k=85?

raven owl
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yeah

robust heron
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or would it be 84

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no i think 85 is right

raven owl
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Nvm im looking at the reverse

robust heron
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ok well it ended up being wrong so maybe it is 84?

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but that doesnt make sense the way ive defined it

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wait im reading that the random variable X is the number of failures UNTIL the first success

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therefore i need ATLEAST 84 ?

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and then maybe the 85th is defective

raven owl
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I think it would be 84. Lets look at the formula P(X>=k)=(1-0.02)^k. If we atleast 1 item, we would except a 100% probability, so we would have to plug in 1-1. Following this pattern, for 85 you would plug in 85-1

robust heron
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ok right

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let me try that

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ok yes it was 84

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thank you

raven owl
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np

robust heron
#

.close

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proper igloo
#

for series

vocal sleetBOT
proper igloo
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how do you determine what type of series they are and what style to solve them?

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for example I had these two

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which isnt hard in nature but finding the right method to solve is confusing to me

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I solved these by trial and error, and on a test or something trial and error might not cut it lol

worthy citrus
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just sort of takes practice and experience. the first one definitely looks like its in the form where you should consider doing partial fraction decomposition as the denominator is a product of two linear terms

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a natural thing to do in the second one is split the fraction up into two and see what you get as a result

proper igloo
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right

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for the first one, I just split up A/(n+4) and b/(n+2) = 2

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lemme send my work

worthy citrus
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if you try a technique that doesnt work out for you, this is still useful in the long run as it lets you gather information as to why this method wasn't that good for this series

proper igloo
worthy citrus
proper igloo
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Yea i solved it that way idk if my math was off but in the end i got like 23/84 which is wayyyy off

worthy citrus
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i think your A and B are off

proper igloo
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ok ill check again

livid tapir
worthy citrus
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wait nvm

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looks fine

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so the issue must be when you "telescoped" the sum

livid tapir
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But a book with proofs might be overkill for calc

proper igloo
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thats what my book says

worthy citrus
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yeah i would write out a few terms and spot the pattern of cancellation

proper igloo
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ok

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wait are these telescopic sums just solving until the first and last sum are left? b

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cuz i left like 2 terms that didnt cancel in there which might be the error now that I think about it

worthy citrus
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not always, see how you have n+2 and n+4

#

these are 2 apart

proper igloo
#

right

worthy citrus
#

so terms will be cancelling with things further in the series than if you just had n and n+1 appearing

#

as a consequence more than one term should survive

proper igloo
#

I see

worthy citrus
#

and with any luck those two terms that didnt cancel should add up to 7/12

proper igloo
#

ok coool

#

thank you!

#

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frail spruce
#

i need help on number 88

vocal sleetBOT
frail spruce
#

<@&286206848099549185>

dull bear
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# frail spruce <@&286206848099549185>

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frail spruce
#

ok, sorry

frail spruce
obtuse monolith
#

Do you just need to simplify

frail spruce
#

no it says to find the value

obtuse monolith
#

find the value of p? there is no = sign so there is no equation, some expressions may simplify to a number though

frail spruce
#

oh my textbook is weird p means pi

flat whale
#

wot

frail spruce
#

yeah it’s weird

flat whale
#

,tex .sum diff trig

twin meteorBOT
#

riemann

obtuse monolith
#

alright well thats just the unit circle and you square the answers u get and add them

#

sin(11pi/6) = -1/2 and cos(4pi/3) = -1/2

#

simply now that you know that calculate (sin(11pi/6))^2 + (cos(4pi/3)^2

#

that would be basic plugging in

#

@frail spruce is this resolved

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#

@frail spruce Has your question been resolved?

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shut zinc
#

I am trying to find this laplace with this given f(t) but i am getting stuck. Im finding myself in a loop where i am having multiple integrations by parts. is this normal? I assume i messed up I am just lost on where

shut zinc
#

oh nvm. i forgot the t power rule (idk the name of the theorem). got it now

#

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vast shale
#

silly question but is there a way for desmos to only have the grey points when the 2 functions intersect

vast shale
#

im calculating tangents and im going to be zooming around so its annoying to see all the other points

formal pond
#

hover above it should get you the coords

#

and just type the coords on the left

vast shale
#

oh wow LOL

#

thanks a lot lol

#

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rocky valley
#

Hey, I need help with this question

vocal sleetBOT
rocky valley
#

Someone please :(

random shore
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
rocky valley
#

Uh

#

1

random shore
#

ok

rocky valley
#

I just don't know man!

random shore
#

relax

#

well get there

#

what is the question asking you

#

in terms of variables

rocky valley
#

Uhhh

#

OH

#

Sorry

random shore
#

right

#

in terms of variables

rocky valley
#

?

random shore
#

you have x and y agree?

rocky valley
random shore
#

i meant in the question, but good catch

#

so we have to find x

#

which x do we want to find?

rocky valley
#

Uhm

#

I don't know

random shore
#

reread the question

#

its there

#

last sentence

rocky valley
#

Okay

#

So I'm finding the poinst where it's intersecting the 52m, right?

random shore
#

perfect!

#

y=-0.0021x^2+1.06x

#

and you have to find when y is 52

rocky valley
#

So I plug 52 in for y?

random shore
#

perfect

rocky valley
#

So

#

-0.0021x^2+1.06x - 52 = 0

random shore
#

mhm

rocky valley
#

And

#

Where do I go from there?

random shore
#

have you learnt bhaskaras?

rocky valley
#

No, I'm in AA2 if that helps

random shore
#

idk what that is, sorry

#

quadratic eqution formula?

rocky valley
#

Advanced Algebra 2

rocky valley
random shore
#

yes

#

fun fact, that is named bhaskaras

#

so you know where to go?

rocky valley
#

Uhh

#

This right?

random shore
#

yep

#

when ax^2+bx+c=0 can you see how your formula fits that

rocky valley
#

I'm ngl

#

I'm so lost

random shore
#

relax

#

again

#

you understand how you got to -0.0021x^2+1.06x - 52 = 0?

rocky valley
#

Yes

#

Y is 52

random shore
#

ok

rocky valley
#

bring it to other side

random shore
#

now to solve that you must use this formula

random shore
rocky valley
#

-0.0021 = a 1.06= b -52 = c

#

Right?

random shore
#

-52 is c

#

perfect

rocky valley
#

Still lost

#

But

#

Not really

random shore
#

wdym

#

did you solve it?

rocky valley
#

I think I messed up

#

Idk

#

Can you walk me through this please...

#

Actually brb in 5

#

Alright

random shore
rocky valley
#

Sooo

random shore
random shore
rocky valley
#

Ok, so I got x=55 and x=450

random shore
#

want me to check is that it?

rocky valley
#

Well

#

Yeah I guess check it

#

I mean I don't know how it's wrong

random shore
#

i think you rounded wrong

rocky valley
#

449.69856528667304

#

Is the exact answer

random shore
#

nope

#

i got 447

rocky valley
#

Oh?

random shore
#

actually i rounded a ton

#

sec

rocky valley
#

no, you're right

#

Ty man

#

Now I can go toi bed

#

It's in embarassing to admit

#

But I'm leaving school early so I don't have to take this test tommorow

#

I actually don't understand these concepts

random shore
#

youll end up having to take it anyways

rocky valley
#

Yeah

random shore
#

so study up

rocky valley
#

But I'm a day b day

#

So I can an extra 2 days

#

and thursdays a half day

random shore
#

you got this

rocky valley
#

So I won't have "adequte time"

random shore
#

dont stress man

rocky valley
#

So Prolly not till next monday

random shore
#

since youre leaving early tomorrow

#

you can study

rocky valley
random shore
#

im not american but im sure thats not bad

rocky valley
#

I have an 87

#

Anyway ba-bye!

#

.close

vocal sleetBOT
#
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oblique raven
#

T

vocal sleetBOT
terse forum
#

!original

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

oblique raven
#

,rotate

twin meteorBOT
oblique raven
#

Ok

#

I need help with answering is “(x-2) a factor of x^4-3x^3+5x-10”

#

I think it is but my explanation is not good lol

#

I was going to write “yes because it multiplies”

drifting jackal
#

You can say that for anything, but to determine if it's a factor, when you divide and you don't have a remainder, that's when you know it's a factor

oblique raven
#

hmm

#

ok but I have a remainder?

#

what do u mean

#

did I do my math wrong I think I might’ve

#

polynomial divisions btw

#

we do synthetic and long divisions later

drifting jackal
#

The question asks if " (x-2) is a factor of x^4-3x^3+5x-10" and when you do the division, if you end up with a remainder, it's not a factor

oblique raven
#

ok

#

ok

drifting jackal
#

For it to be a factor, you should not have a remainder

oblique raven
#

so it’s not a factor because we have a remainder

drifting jackal
#

Yes

oblique raven
#

Need help with this

#

Oh wait

#

.close

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#
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vast shale
#

i really need help on what exactly i'm supposed to input here. i've found that it's a geometric series where a = 1/4, r = 1/16, and sum is 4/15, does not work despite verifying on wolfram. i can use alternating series test if i rewrite using (-1)^(n+1), which eliminates the negative sign on the bottom, but it's still not correct

vast shale
#

at least if i simplify it, i get the form (1/4)(1/16)^n but even then it's not right unless my sum isn't correct

cobalt ocean
#

ah

#

it says 'pick the first applicable test in the list'

#

so it's surely meant to be geometric

#

and in the geometric case r should surely be negative

#

yeah i get a different a and r

vast shale
#

let me redo my work

#

okay this time i got -1/4 as a and -1/16 as r, but i evaluated the (-4) term with it instead of applying alternating series

#

i'm getting the same exact answer if i input the same number to both, with a sum of (-4/17)

#

still not right

#

calculated my infinite sum as (-1/4)/(1+1/16)

#

wish i got at least some partial credit to see what i'm not doing right..

#

boutta rip my hair out

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

vast shale
#

.close

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#
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hearty crystal
#

Consider a sample of 8 hypertensive smoking adults. Their serum cholesterol level readings are as follows:

220, 230, 235, 225, 223, 218, 220, 233

What is the margin of error, rounded off to two decimal places, of a 99% confidence interval for the mean serum cholesterol level of hypertensive smoking adults? Use one decimal place for both sample mean and sample standard deviation.

hearty crystal
#

Consider a sample of 8 hypertensive smoking adults. Their serum cholesterol level readings are as follows:

220, 230, 235, 225, 223, 218, 220, 233

What is the margin of error, rounded off to two decimal places, of a 99% confidence interval for the mean serum cholesterol level of hypertensive smoking adults? Use one decimal place for both sample mean and sample standard deviation.

vocal sleetBOT
#

@hearty crystal Has your question been resolved?

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frail lantern
#

the correct answer is showing as A, but i dont understand how 8 and d+2 are the solutions

raven owl
#

When d=8, 2x-16=0 for left, and (x-8)=0 on right so entire right side is 0, hence they are equal

#

If you plug in d+2, the (x-d) term evaluates to 2, and 2x-16=2(x-8)

frail lantern
#

wait but all the answer choices have 8 as a solution

#

except C

ivory yarrow
frail lantern
#

and thats why i picked C but idk it doesnt accept that

ivory yarrow
frail lantern
ivory yarrow
#

yes

frail lantern
#

my god

ivory yarrow
#

Then formed a quadratic with the x on one side

frail lantern
#

that makes alot of sense

#

yeah i got it now thanks alot @raven owl and @ivory yarrow

ivory yarrow
#

no worries

#

Close it if you're done

frail lantern
#

oh mb this was my first time asking, i forgot

#

.close

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cloud harness
vocal sleetBOT
cloud harness
#

how is x = 44? evaluating logarithim equations

#

yellow pad is what i did, i got 15 because i removed the common loga bases

#

ohhh

#

product fucking rule

#

omfg

hollow heron
#

is there a ques

cloud harness
#

i added 4 and 11 instead of multiplying the bitch

#

cause product rule

slate herald
#

@cloud harness ?

#

stop swearing randomly and tell if u have any doubts regarding the question
I got 44 as well

cloud harness
#

essentially

#

i added instead of multiplying

#

thats why i got 15 instead of 44

pallid forge
#

unless you have a question, you can close this now

vocal sleetBOT
#

@cloud harness Has your question been resolved?

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austere lantern
#

Is that exercise on limits right?

vocal sleetBOT
#

Please don't occupy multiple help channels.

austere lantern
#

I mean, it confuses me because of the e^(10/M)

#

.close

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finite hatch
#

Hey

vocal sleetBOT
finite hatch
#

Is this right?

vocal sleetBOT
#

@finite hatch Has your question been resolved?

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@finite hatch Has your question been resolved?

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@finite hatch Has your question been resolved?

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dull scaffold
#

pls help

vocal sleetBOT
dull scaffold
#

3rd one

#

<@&286206848099549185>

vocal sleetBOT
#

@dull scaffold Has your question been resolved?

dull scaffold
#

<@&286206848099549185>

#

.close

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weak frigate
#

can someone help me why 2/15 is factored out when simplifying this?

weak frigate
#

im confused why 2?

#

whats the process to easily get 2 when factoring out these trinomials?

slim oar
#

Then use standard factoring methods

weak frigate
slim oar
#

Factor out 1/15 forst

#

Then the coefficients are 18, 20, and 30

#

Then factor 2 out as 2 divides all three

weak frigate
#

ooh okk thank youu, ill use this when simplifying integrals 🫶

#

this made more sense now

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#

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gaunt quest
vocal sleetBOT
gaunt quest
#

is this also a partial fraciton with nonrepeated linear factors?

urban valley
#

then do quadratic type

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#

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dense rune
#

<@&286206848099549185>

vocal sleetBOT
ivory yarrow
#

you don't need to ping helpers as soon as you post your issue

#

and this is pretty basic if you understand how quadrants work

#

in the first quadrant, your value is θ
in the second, it is π - θ
in the third, its θ - π
in the fourth, its -θ

#

or since you're dealing with 0,2π, just know that sin(90+θ) = -cosθ, sin(180-θ) = sinθ, cot(90+θ) = tanθ and so on

dense rune
#

Wait can u just tell me what to do step by step

#

i understand the quadrants btw

ivory yarrow
#

I won't spoon feed you. just know that sin 301 = sin(270 + 31)

#

and sin of 270 + θ = -cosθ

dense rune
#

what is this topic called

ivory yarrow
#

trigonometry

dense rune
ivory yarrow
#

I don't think trigonometry has a subtopic for this

dense rune
#

what is the question asking for

ivory yarrow
#

try figuring it out

dense rune
#

ok i do some u tell me if im going to the correct direction

ivory yarrow
#

"express whatever (...) in terms of single trigonometric functions with the range 0, 45

#

sure go ahead

dense rune
#

so can i place that into the sinx cosy - siny cosx

dense rune
#

ty

#

for not spoonfeeding

ivory yarrow
#

You don't need to get into sinxcosy - sinycosx

#

Take the hint from this

sin 320° = sin(270°+50°) = -cos50°

#

sin(0+-¢) or sin(π+-¢) will result in sin itself

#

But sin(π/2 +-¢) or sin(3π/2+-¢) would give it in terms of cos

#

Adjust the signs according to the quadrants

vocal sleetBOT
#

@dense rune Has your question been resolved?

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golden sapphire
#

I still can't get this domain right

#

any idea what am I doing wrong?

vocal sleetBOT
golden sapphire
#

nvm it's because I didn't do the parabola

#

.close

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#
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solar forge
#

can somebody please tell me where did i made a mistake? there should be a + not -

solar forge
#

for context i am calculacting a group velocity from a dispersion relation, co cg is a group velocity and cf is a phase velocity

flat whale
#

not really enough context to check your entire work

solar forge
twin meteorBOT
#

marejak023

solar forge
#

*mistake in the derivative

flat whale
#

yea there's no way to tell your equation for c_g is even correct

#

or c_f

#

or if alpha and rho depend on k

solar forge
flat whale
#

what's that supposed to say?

solar forge
#

this is correct answer, they just force the k into the square root but that doesnt matter, the important thing is why is there the plus sign? it just derivative so dont look for any context behind it

#

nvm, ill figure it out differently

#

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young cosmos
#

Shouldnt there be three functions inside of each other, like shouldnt 2x also be one

thick sky
#

just wondering if i can get some quick help on a question. I'm completely unsure how I would solve this and there really isnt anymore information added

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ornate ember
ornate ember
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tidal surge
vocal sleetBOT
tidal surge
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
tidal surge
#

2

median crane
#

What’s the question in English

tidal surge
#

@median crane I need to check if f(x) etc. are solutions to dy / dx. I don't know where to go from here when solving the differential equation. Do I substitute f(x)=e^x+x+1 in y and then do: dy / dx = e^x+x+1-x etc?

median crane
#

Yeah if you have to verify then just plug in

#

And check if RHS = LHS

tidal surge
#

But how is it a solution?

#

it becomes dy / dx = e^x +1 ?

median crane
#

When you solve an differential equation you look for a function y that satisfies the given equation

#

If you plug y into the equation dy/dx = y-x does the equality hold

tidal surge
#

Yeah it does actually, thanks

#

Thanks a lot, have a nice day/night 😃

#

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median crane
#

You too

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weak sandal
#

How do i get AB?

vocal sleetBOT
astral shadow
#

BD is 3.93?

weak sandal
#

yes

astral shadow
#

That's given, yeah?

#

Then cosine formula.

#

Should work.

weak sandal
#

thank you very much man

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lean forge
#

If we're using frenet frame, with s being the lenght of arc, what would be (ds/dt)*ds ?

lean forge
#

We didn't do it yet

#

We just said it was the lenght of arc

#

I'm just wondering if there's some derivative identity in this instance though

flat whale
#

how are you supposed to find ds/dt without s?

lean forge
#

Well if you can't that answers my question

#

thx

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grave mason
#

can somebody help me graph this?

vocal sleetBOT
grave mason
#

they want us to solve us by finding the focus, vertex, and the p value

#

see the orange sheet to reference how my teacher used wants us to solve it

#

my main question is how do i know if it faces up or sideways?

vast shale
#

what are you struggling on?

grave mason
#

i think I can do it if I find out the direction of the graph but I don’t know if it’s up or sideways and I don’t remember how to figure out if it’s one or the other

vast shale
#

hmm

vocal sleetBOT
#

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@grave mason Has your question been resolved?

lean forge
#

And up if the square is on the x

grave mason
#

thank you!

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kindred marsh
#

I need help with optimization. I am not sure if it wants me to add x and y.

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@kindred marsh Has your question been resolved?

ruby vapor
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@kindred marsh Has your question been resolved?

kindred marsh
#

@ruby vapor Sorry for the delay, that would get you 3600 which I don't believe is the answer (600+4(750))=3600

ruby vapor
kindred marsh
#

Isn't 6000 suppose to be the perimeter?

ruby vapor
#

and requiring the least amount of fence means perimeter

kindred marsh
#

nvm, i got help from my brother.

#

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celest nacelle
#

Hello, currently learning about centroids.

I understand how to find the centroid of a right triangle, but what about a non right triangle?

In my book I have this, but how would you go about finding x̄?

celest nacelle
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gleaming eagle
#

Thought I knew how to do this, but I ammm stuck

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@gleaming eagle Has your question been resolved?

gleaming eagle
#

<@&286206848099549185>

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hasty token
vocal sleetBOT
hasty token
#

how do you prove this?

astral shadow
#

Do you know what |z| is?

hasty token
#

|z| is √(x^2 + y^2) right?

#

ik that the left side is √(x^2 + y^2)(a^2 + b^2)

#

but how do you show that it equals the right side without splitting the right side into |z| x |w|

astral shadow
#

Well you can find the complex number zw

#

By multiplying

#

Then write it in the form x + iy

#

Then again find its absolute value.

#

But I'd recommend not doing any of this and consider:
$z = r_1 e^{i \alpha}, |z| = r_1$
Similarly for w and then prove that.

twin meteorBOT
#

! What the hell am I doing here?

hasty token
#

so zw = (ax - by) + (bx - ay)i

astral shadow
#

Alright.

#

Now consider the abs value

hasty token
#

yeah makes sense

#

thanks mate

#

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tulip karma
#

my algebra teacher says that (-125)^(2/3) is 25 (cube root of -125 is -5 squared is 25) but according to jula and wolfram alpha and my own understanding, the answer is a complex number. Am I wrong? If im right, whats a good intuitive reason why this method doesn't work in this case?

grand frigate
#

so, you're asking if

#

,,\sqrt[3]{-125}

twin meteorBOT
#

lovelorn math enthusiast.

grand frigate
#

is complex or not?

tulip karma
#

no

#

im asking if (-125)^(2/3) is complex

grand frigate
#

why would it be though?

#

it's basically
[ \sqrt[3]{(-125)^2} ]

twin meteorBOT
#

lovelorn math enthusiast.

grand frigate
#

right?

tulip karma
#

thats my issue, it seems like it should be real based on what I'm being taught,
but based on my own intuitive understanding of complex numbers, and two math programs which I would trust with my life, the answer is complex.

#

try putting (-125)^(2/3) into julia or wolfram alpha

grand frigate
#

yes it is real

#

it should be real

tulip karma
#

the important thing is that it simplifies it first to (-1)^(2/3) * (125)^(2/3)

grand frigate
#

so??? which one is complex?

tulip karma
#

-1^(2/3)

grand frigate
#

,,\sqrt[3]{-1}

tulip karma
#

it should be between -1 and i

grand frigate
#

this is not complex

twin meteorBOT
#

lovelorn math enthusiast.

tulip karma
#

:|

grand frigate
#

try cube-ing square root of -1

#

the result is not -1

tulip karma
#

i never said it was -1

grand frigate
#

okay so... how is cube root of -1 complex?

tulip karma
#

-1^1 = -1 and -1^(1/2) = i so -1^(2/3) must necessarily be between -1 and i but not either of them.

#

which is confirmed by both julia and wolfram alpha

#

as expected the angle of the answer lies in the second quadrant

#

obviously this method is an oversimplification which does not work for negative or complex numbers

tulip karma
#

which is completely different

grand frigate
#

why must it be between -1 and i but not either of them?

tulip karma
#

im saying the method you are using (that being that a ^ b/c = (c root a)^b) does not work in all cases

#

because 2/3 is between 1 and 1/2

#

and is not 1 or 1/2

grand frigate
#

i am not understanding it well, maybe wait for someone else tbh.

tulip karma
#

just look at this and it will make sense

tulip karma
#

you're extending my argument past where it makes sense, since -1^x oscilates you cannot make that argument over a range which goes up and then back down

#

between (-1)^1 and (-1)^(1/2) both the real and immaginary components only move in one direction

grand frigate
#

btw is this the plot you mean?

tulip karma
#

yes

#

the reason -1^a goes between -1 and 1 is because its actually a squished cos wave, with a sin wave which makes the complex value 0 at all integer inputs. integer inputs are therefore the only inputs which yield real numbers.

#

also for -1^(1/2) you can see that the real goes to 0 and the imaginary to 1

#

it got the graph by doing the math correctly

#

obviousy since the graph must be continuous it will be some complex value at x = 2/3

#

the right way to calculate (-1)^x where x is real is
cos(pi times x) + i times sin(pi times x)

#

notice how at any integer the second term becomes zero

grand frigate
#

@tulip karma
there are complex and real values
credit to daniStuffing

#

depends on which -1 you pick.
e.g. -1= e^((2npi + pi)*i)
also credit to GarlicB

frail sinew
#

(-1)^0.5 = i

tulip karma
#

its true, 25^(3/2) = 125 or -125 and also (12.5 + 21.65i)^(3/2) ≈ 125 or -125

#

if you are asked to either give an answer or say the answer is complex, is it expected to disregard complex answers if a real answer exists?

grand frigate
#

if you're interested in this stuff, you can look up "roots of unity" and "demoivre's theorem"
-daniStuffing

tulip karma
#

hmm, reminds me of how in the mandelbrot set it often counts while increasing the number of spokes in its patterns

regal parrot
#

The point here is that an n degree polynomial has exactly n roots (with multiplicity) in the complex numbers

#

so x^2 - 1 = 0, this has two real solutions, x=1 and x=-1

#

x^2 + 1 = 0 has no real solutions, but it does have two complex solutions: i and -i

#

(This is the motivation for complex numbers, actually. It is an algebraic closure of R meaning that all roots of real polynomials lie in the complex numbers)

#

This is practically what asking what (-1)^(2/9) is

#

forgetting about the 2, its equivalent to asking
what are the roots of x^9 +1 = 0

tulip karma
regal parrot
#

some of them are complex numbers!

tulip karma
#

this is really interesting, I never thought we could both be right 😂

#

it seems like if i do (-1)^(a/b) as i make a and b larger to approach pi there are more and more solutions, shouldn't an irrational like (-1)^(pi) have infinite solutions?

#

anyway, thanks for the help, I guess I should close the issue.

#

.close

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gleaming eagle
#

is this just gallon ??

vocal sleetBOT
tulip karma
#

rate of change is slope which means rise/run. if you imagine the graph, the rise is dollars and the run is years. therefore the unit should be dollars per year.

#

which makes sense intuitively also, if the price of milk is changing at some rate, that rate would be however many dollars it changes by in a year.

gleaming eagle
#

.... o h

#

wow I'm sleep deprived xD

tulip karma
#

me too, lets both get some sleep :)

#

nighty night

gleaming eagle
#

niiight

#

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rose shard
#

I keep thinking of this as X <= 15 AND x >= 30 and so my head thinks I have to multiply them since is there any good tips on how to think of it as?

rose shard
#

Just saw this formula where he moves it to the left side and that made a lot more sense hahha

hard atlas
#

for what reason do you flip the inequality signs?

#

the picture is a pretty decent way to think about it

rose shard
#

Yeah, and then he just moves it to the other side

#

to isolate P(15<=X<=30)

#

and he gets P(15<=X<=30)=1- ....

#

So that helped a lot I guess I just had to be patient and watch the video 😂

#

Thanks for the help tho!

#

🫶

#

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winter monolith
#

how do I do geometry problems faster?

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left sail
#

@summer lichen my question from earlier expired, but I say your message

left sail
#

I ended up converting to polar because I couldn’t figure out my mistake but im interested to know how my bounds were incorrect if you know

#

The question, for reference

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spare portal
#

could anyone help me find the domain of a function?

spare portal
#

I forgot how to do it because we had a 2 week school break and I just played elden ring

mental falcon
#

so what would prevent you from putting in any real number x for the input?

spare portal
#

wdym?

#

I remember that i had to set the value of x to zero

mental falcon
#

any places where this function would be undefined \ problematic?

spare portal
#

but there are 2 x's

#

so idk what to do now

mental falcon
#

so the inputs to avoid with a rational function like this, are ones that would make denominator be 0, because that would be division by 0 which is undefined

#

so to find the x values that create that problem we set the denominator equal to 0 and solve: $x^2 - x = 0$
does that make sense?

twin meteorBOT
spare portal
#

oh okok

#

so i have to isolate the x

#

or am i wrong?

#

fk

#

ill stop playing elden ring'

mental falcon
#

... 😐

spare portal
#

1?

mental falcon
#

that's the only one?

spare portal
#

0, 1?

#

idk man

mental falcon
#

yes

#

thats actually correct even though you seem to be half guessing 😂

#

if you have an equation that equals 0, always remember to factor:

#

$$x^2-x=0$$
$$x(x-1) = 0$$

twin meteorBOT
spare portal
#

yeah im just trying to squeeze any remaining knowledge i have left

#

ahh

#

okokok

mental falcon
#

and then you can set individual factors = 0, as in x = 0, x -1 = 0 and get the solutions: x = 0, and x = 1

spare portal
#

OK now i understand

#

tysm

mental falcon
#

anyway so the domain of the function is all numbers except x = 0 and x = 1, you can either write that in words or something like $x \neq 0, 1$

twin meteorBOT
mental falcon
#

because all other numbers keep the equation happy, but 0 and 1 make it explode with division by 0

spare portal
#

Understood!

#

tysm

mental falcon
#

!done

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#

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spare portal
#

.close

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spare portal
#

are the vertical Asymptotes of a function allways the same with its domain?