#help-17

1 messages · Page 110 of 1

trail notch
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isnt 1^2

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just 1?

grizzled halo
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yes

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but you missed the g

trail notch
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oh

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oops

trail notch
grizzled halo
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yes

trail notch
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okk so now what

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g=9.8m/s^2

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but then what

grizzled halo
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,w 9.8/(4pi^2)

grizzled halo
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you want this?

trail notch
grizzled halo
#

then if you've got a calculator, you just put that in

trail notch
#

okk

grizzled halo
#

with g=9.8

trail notch
#

so 0.25

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?

grizzled halo
#

yeah

trail notch
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so L=0.25

trail notch
#

im just sorta confused

grizzled halo
#

sure

trail notch
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ty

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how do i find the longest side

grizzled halo
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it's a right angled triangle, so pythagoras' theorem would be good

trail notch
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*x

grizzled halo
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if you let the longest side be y, then y^2=(2x)^2+x^2?

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(i would work on the area first though)

trail notch
grizzled halo
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area = 1/2 x base x height?

trail notch
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yes

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30=x*2x/2

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?

grizzled halo
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yes

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then you have x^2=30

trail notch
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so x=square root of 30

grizzled halo
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so that gives you the two shorter sides, and then you can use pythag for the longest side

trail notch
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so i right 2√30?

grizzled halo
#

yes, for the second side

trail notch
trail notch
grizzled halo
#

,w sqrt150

grizzled halo
#

looks good

trail notch
#

ok but it doesnt exactly equal 30

grizzled halo
#

round b and c to nearest tenth and you're done

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what doesn't?

trail notch
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all of them added together

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oh wiat nvm

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area is 30

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not perimeter

trail notch
grizzled halo
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,w 2sqrt30

grizzled halo
#

same way you rounded x?

trail notch
#

ok i did it

#

ty

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.close

vocal sleetBOT
#
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wary mantle
#

For proving that gcd(m_1, n) = 1 and gcd(m_2, n) = 1 ==> gcd(m_1m_2, n) = 1, would you use Bezout's identity?

wary mantle
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It'd give us
1 = a_1m_1 + b_1n
1 = a_2m_2 + b_2n

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Now multiply these two together?

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But that wouldn't lead us where we want

tidal dock
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if m_1 doesn't have any common factors with n, and neither does m_2, then their product can't have any common factors with n

wary mantle
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Yeah

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But we need to rigorously prove it

lyric relic
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if p is a prime s.t. p|n and p|m1m2 then p|m1 or p|m2 ...lets say p|m1 then we get a contradiction because p|m1 and n ...

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now a common divisor of n and m1m2 will not have any prime factors... so only +-1 could be a common divisor

lyric relic
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yes

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because gcd is a positive integer

wraith venture
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so all you need is actually Gauss's lemma

wary mantle
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or, not and

cobalt ocean
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you can also just do it constructively, it turns into letter salad but it works

if ar + bx = 1 and cs + dx =1

ars + bsx = s

ars = s(1 - bx)

acrs = cs(1-bx)

acrs = (1-dx)(1-bx)

(ac)rs + (b+d-x)x = 1

so we're done

vocal sleetBOT
#
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lyric relic
wraith venture
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Some call it Euclid's lemma too

vocal sleetBOT
#
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lime tartan
vocal sleetBOT
lime tartan
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Im trying to understand how to go about this.

vocal sleetBOT
#

@lime tartan Has your question been resolved?

vocal sleetBOT
#

@lime tartan Has your question been resolved?

lime tartan
#

@hollow rampart

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<@&286206848099549185>

quiet whale
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Ayo

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I cant do that

lime tartan
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You know someone who can perhaps

quiet whale
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Yes

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My 80 year old uncle can do it

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Or chat gpt

lime tartan
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chatgpt seems to get this stuff wrong

quiet whale
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If you Will learn how to solve it I can help

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I know how the thing works

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But I cant solve it

lime tartan
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Its a proof

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I just need to prove equivalence

quiet whale
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Hmm

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Ok

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Thag should be easier

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What the (nk) means

lime tartan
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from n choose k

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can i do latex here

woven gull
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Okay I'm back, I found nothing else to do.

quiet whale
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Bruh

lime tartan
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Is that your uncle

woven gull
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What?

lime tartan
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nvm sorry

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Can you help?

quiet whale
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Variable! = infinifinity if we dont know the number

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What is n

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K! = 1

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Or no

woven gull
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It's okay, and no, sorry, I'm not on that level of maths yet, though I am intrieged by it, in other words, I love maths.

quiet whale
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I am trying but I cant understand how it works

lime tartan
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this is discrete math / combinatorics if that helps

woven gull
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And I'm only a Year 6 learner that does Year 7 maths ( by a small fraction).

quiet whale
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You 7th grader

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?

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I am 8th grader

lime tartan
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i was doing algebra in 8th grade. wtf

woven gull
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In the way of saying it from where I am, I'm a Year 6 pupil.

quiet whale
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I am doing everything that I wnat in 8th grade

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I can do algebfa

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But I need to know

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What is n!

woven gull
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I have a strong intrest about algebra.

quiet whale
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I know what is !

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But what is n!

woven gull
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But I like Pi more

lime tartan
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n! = n * n-1 * n-2 * n-3 * n... * 1

woven gull
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So much so, I could write 100 digits of Pi.

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Right. Now.

quiet whale
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I like n- infiniti

lime tartan
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its n times every integer below n

woven gull
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Ah, okay.

lime tartan
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n factorial

quiet whale
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I am really interest in goniometric funcitions algebra I am learning cyclometric functions I am trying to understand Quantum physics maxwells equations And More!

woven gull
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In my school, I was the only one that realised my school has been doing algebra for YEARS.

lime tartan
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i wrote a paper using maxwell equations

quiet whale
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?

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Show me

woven gull
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Oooooooo~ sounds interesting.

quiet whale
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Ayo young sheldon mindset

lime tartan
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let me try to find it. i still need help though with my problem

woven gull
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Who has the Young Sheldon mindset may I ask?

lime tartan
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if you guys know someone id greatly appreciate

quiet whale
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You

woven gull
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...

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DANG IT1

quiet whale
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?

woven gull
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not you too...

quiet whale
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Vector functions?

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Bro

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I am at the same place asi you

woven gull
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My parents call me Young Sheldon all the time because I'm 'Too smart!'

quiet whale
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Me too but in school

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But pí is not that hard

woven gull
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One of my classmates called me him aswell

quiet whale
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Like I know it is a iracional number

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But I think if you are good at it

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It is good for you

woven gull
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3.14159265358979323826460338327950288419716939937510582097494459230781640628620898628034825342117067

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Is that right?

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I hope so.

lime tartan
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Remebering pi is useless. What does pi represent?

quiet whale
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Ayo sheldon

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It is wrong I think

woven gull
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Hold on, I have a book near me about this brb

quiet whale
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It is 3.14159265359

lime tartan
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You rounded that last digit

quiet whale
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?

woven gull
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Who?

lime tartan
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Dominik

quiet whale
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Oh nvm

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It is rounded

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You were right

lime tartan
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Its irrational.

quiet whale
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I know

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I am from Czech republic

lime tartan
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Which means you cannot represent it in a finite sequence of digits

quiet whale
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I dont know every english word

lime tartan
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Its ok

quiet whale
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3.1415926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 3421170679 ...

lime tartan
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Yes it goes on forever

quiet whale
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Like plank constant

woven gull
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Oml

lime tartan
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Yes

woven gull
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My handy-dandy math book is MISSING.

quiet whale
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Anthony

lime tartan
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Actually no, it is not like planks constant. Plank constant is rational

woven gull
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I SPENT A YEARS WORTH OF MATHS IN THERE AND IT'S VANISHED OUT OF THIN AIR...

quiet whale
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BRO

woven gull
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I will scream rn

quiet whale
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I have my book And it is only 2 monhts old

lime tartan
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At least you have the entire internet

quiet whale
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But it is my tresure

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Anthony

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I am not sure if I can help you with your equation

lime tartan
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No worries

quiet whale
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I understand the operations but I cant do equations with it I am really sorry

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Know the e And the !

lime tartan
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Dont worry

quiet whale
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I can help in thursday

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I Will ask my uncle

lime tartan
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Dont worry my quiz on this stuff is on monday so it will be too late by then

woven gull
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GUYS

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I FOUND MY SATS PRACTICE BOOK

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MATHS INCLUDED

quiet whale
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Show me pic

woven gull
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I mean it'll do for now I guess

quiet whale
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Anthony I am sorry but I cant helpi am to dumb for that equation

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@lime tartan

woven gull
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Um, the thing is, I can't send pics,

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I'm on a pc.

quiet whale
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Anthony

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@lime tartan

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K! = 1 is it right

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Anthony

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I can help but I need your help too

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Please

lime tartan
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No

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k is arbitrary

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this isnt algebra were not solving for a value

quiet whale
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What are we solving for?

lime tartan
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Nothing

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We need to prove equivalence

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Its a proof

quiet whale
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If k is arbitary n is too

lime tartan
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Yes

quiet whale
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Ayo

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I think it has something to do with quantum physics

lime tartan
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No lol

quiet whale
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But why is There k=1

lime tartan
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What are you talking about?

quiet whale
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In the equation

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There is k=1

lime tartan
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Yes.

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look up summation

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This is a bit more advanced than what you know and thats ok. Dont worry

quiet whale
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Hmm

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We are prooving thag k=1?

lime tartan
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No

quiet whale
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Ok

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And the (nk) is a set?

lime tartan
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No

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It represents the number of distinct subsets of size k of a set of size n

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in other words, it is the number of ways you can choose k things from a collection of n of them

quiet whale
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I am totally lost

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But I know that if k is something n is something too

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I think the solition might something do with the times two

lime tartan
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No

quiet whale
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But the set can be empty right?

lime tartan
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Thats irrelivent

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$ \frac{1}{2} $

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idk why ltex isnt working

quiet whale
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What grade are you

lime tartan
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University

quiet whale
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Hmm

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My brain is not braining but I Will help

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Math is helping me get oit of my problems

lime tartan
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its ok cause there is a lot of stuff you need to know to be able to understand this

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you need to know summation factorials binomial theorem set theory combinators and number theory

quiet whale
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When I am doing math I forgot that I am ridiculed

lime tartan
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keep doing math math is good

quiet whale
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I heard of every one of the teories

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But I dont know what they are about

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Oh

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We need the binomial theorem to proof the equation

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Am I right?

lime tartan
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Yea its part it

quiet whale
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It Will do something with the sets I think

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We need the Pascal's triangle

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But , sum of exponents is always equal to n

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But in the equation There is subtracion

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What Will we do?

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Anthony what Will we do

lime tartan
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No worries

quiet whale
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N must be an sum of something

lime tartan
#

Thanks for the efforts its appreciatred

#

.close

vocal sleetBOT
#
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quiet whale
#

Nooo

vocal sleetBOT
#
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vast shale
#

what is 2+2?

vocal sleetBOT
vast shale
#

or 3+3?

lyric relic
#

mhh..

#

what have you tried so far?

bleak oak
vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
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sleek sluice
vocal sleetBOT
sleek sluice
#

why do they create another set C to solve this? none of any my other questions involved making a new set

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or is C just an example for all A

tight rampart
#

You have to prove that B is a subset of the intersection of the elements of F. This is equivalent to saying that B is a subset of each element of F : C acts as an arbitrary element of F

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If B is a subset of C, for C an arbitrary element of F, then B is a subset of the intersection of the elements of F

sleek sluice
#

okay, thank you for clarifying. i'll try to solve the question further because that confused me

#

.close

vocal sleetBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
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signal river
vocal sleetBOT
signal river
#

why isnt the answer for ycm 1?

lyric relic
#

wdym with ycm?

signal river
#

ycm

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the answer is 1

#

but

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its not

#

so idk

#

the answer for xcm is correct

vocal sleetBOT
#

@signal river Has your question been resolved?

signal river
#

<@&286206848099549185>

#

<@&286206848099549185>

#

hello

#

can anyone help

flat whale
signal river
#

well

#

1

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or

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-0

#

0

flat whale
#

None of those

#

Use the formula for centroid

vocal sleetBOT
#

@signal river Has your question been resolved?

signal river
#

but

#

uh

#

cant figure it out

flat whale
signal river
flat whale
#

The y one is wrong

#

Use your textbook or notes

signal river
#

uh

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i dont have any notes

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or textbook

flat whale
#

Your class doesn't have textbook?

signal river
#

not that i know of

flat whale
#

Then how are you learning formulas

flat whale
signal river
#

google

flat whale
#

Yea that's wrong

#

Find a textbook or a math website

signal river
#

do you happen to know it

flat whale
#

Calculus textbook should have it

signal river
#

what free textbooks

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wow

#

i found it

#

you could have just told me i needed to add the 1/2

#

instead of telling me to google it

flat whale
signal river
#

idk worked for me

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when i just added the 1/2

flat whale
#

Working for one function doesn't mean it works for all

signal river
#

oh and squared to teh x

flat whale
#

Telling you the answer is against server rules

signal river
#

why

#

isnt this server to help

flat whale
#

Having a textbook means you won't get formulas wrong anymore

flat whale
#

Help channels are for help

signal river
#

right

flat whale
#

Giving away answers usually isn't as helpful as guiding

signal river
#

i mean

#

its alright but

flat whale
signal river
#

.close

vocal sleetBOT
#
Channel closed

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vocal sleetBOT
#
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stuck girder
#

Hi

vocal sleetBOT
candid mountain
#

hey 😄

stuck girder
#

Is the Stewart calculus 7th edition early transcendental book good

#

I am trying to pre learn calculus

#

So I was wondering if it is a good book

#

Hello?

tribal citrus
#

hey man i am learning calculus 3 now i have this book do know if it helps you

stuck girder
#

Ok

candid mountain
stuck girder
#

O

#

Also what do I need to know for calc

stuck girder
#

I’m in 8th rn so

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I’m just wondering

#

.coose

#

.close

vocal sleetBOT
#
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blazing atlas
#

could someone help me with solving sin(1/x)=1/sin(x) i have no idea how i would do this

blazing atlas
#

its not

#

i saw it in a blackpenredpen vid and wanted to try but i didnt get very far

#

i got to this

e^{ix}-e^{-ix}=\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)

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idk how the bot works?

ebon rapids
#

put dollar signs on both sides

blazing atlas
#

$e^{ix}-e^{-ix}=\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)$

twin meteorBOT
#

DaanHun

blazing atlas
#

right thats how far i got

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not sure how to proceed

flat whale
#

,w expand (exp(i/x) - exp(-i/x)) * (exp(ix) - exp(-ix))

flat whale
blazing atlas
#

hmm what

#

then im just trash

#

this should be true:

#

$\frac{2i}{\left(e^{ix}-e^{-ix}\right)}=\frac{\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)}{2i}$

twin meteorBOT
#

DaanHun

flat whale
#

what are you doing

blazing atlas
#

idfk

#

e^i/x = cos(1/x)+i*sin(1/x)

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e^-i/x=cos(1/x)-i*sin(1/x)

flat whale
#

yes those are right

blazing atlas
#

add those to each other

flat whale
#

does the video give an exact solution

#

link the video

blazing atlas
#

it doesnt

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1 sec

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at the very end he puts sin(1/x)=1/sin(x) up as a challenge

oblique saddle
#

try putting sin into exponential form

flat whale
oblique saddle
#

I remember trying this problem and I found that there were no solutions

blazing atlas
#

im just not sure how to get any further than this:

#

$\frac{2i}{\left(e^{ix}-e^{-ix}\right)}=\frac{\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)}{2i}$

twin meteorBOT
#

DaanHun

blazing atlas
#

wolframalpha gives 6 solutions

flat whale
#

,w solve 2i / (exp(iz) - exp(-iz)) = (exp(i/z) - exp(-i/z)) / (2i)

twin meteorBOT
flat whale
blazing atlas
#

right 4 answers that are like a square and some other points very far away idk how that even happens

flat whale
#

,w plot 1/sin(x) - sin(1/x) for -100 < x < 100

blazing atlas
#

so where it touches 0?

flat whale
#

the difference never intersects the x axis

blazing atlas
#

but there are complex answers no?

flat whale
#

or maybe i have to increase the domain

#

,w expand (exp(i/z) - exp(-i/z)) * (exp(iz) - exp(-iz))

flat whale
#

,w (exp(i/z) - exp(-i/z)) * (exp(iz) - exp(-iz)) = 2cos(z + 1/z) - 2cos(-z + 1/z)

flat whale
#

,tex .sum diff trig

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probably won't be helpful

blazing atlas
#

hmm

twin meteorBOT
#

riemann

blazing atlas
#

i can do that i think

#

so solving that would work?

#

ohh i know what i duid wrong i thjink

#

would this work? :

#

$-4=\left(e^{\frac{i}{x}}-e^{-\frac{1}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)$

twin meteorBOT
#

DaanHun

blazing atlas
#

i meant i/x

#

$-4=\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)$

twin meteorBOT
#

DaanHun

blazing atlas
#

i think i put down the exact same just exponential and not cos

vocal sleetBOT
#

@blazing atlas Has your question been resolved?

#
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vast shale
#

Is the 3 in front of the absolute value multiplying the inner contents of it?

blazing atlas
#

just 3 times whatever the output of that abs value is

#

so if x=1 the abs value of x-2 will be 1 multiplied by 3

#

i think

vast shale
#

So for the two equations it would be $3(x-2)-3$ and $-3(x-2)-3$

twin meteorBOT
vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#
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vocal sleetBOT
#
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vast shale
#

How am I supposed to know what the equations are

#

What exactly is f’’(x) on the graph there?

#

And how do I find f(0)

#

With no equation given

pale perch
#

it doesnt ask for any equations

#

it just asks positive, negative, or 0

vast shale
#

How am I supposed to know that tho

pale perch
#

f'(x) is the gradients of f, the rate of change of f

vast shale
#

Yeah I understand the first derivative

pale perch
#

f''(x) is the gradients of f', the rate of change of f'

vast shale
#

How is f’’(x) positive at A

#

That’s what the answer said

#

Isn’t it going down

pale perch
#

because the gradient is negative yeah but its increasing

vast shale
#

???

pale perch
#

its negative (going down)
but its increasing, it eventually becomes 0 at B, then it goes up

#

it becomes less steep

vast shale
#

Then how is E negative for f’’(x)

pale perch
#

because the gradient is getting more negative, the graph of f is getting steeper downwards

vast shale
#

Both the gradient of A and E are negative though

#

I’m still confused

#

💀

pale perch
#

the gradients are negative yes, so f'(x) is negative

vast shale
#

Yeah

pale perch
#

f''(x) is about if the gradients are increasing or decreasing

#

(or 0)

vast shale
#

How is the gradient of A increasing?

#

Even though it’s going down

pale perch
#

its becoming more positive

#

it could be going something like
-5, -3, -2 ,-1, 0 (at B), 1, 2, 3

#

it was negative but it was increasing

vast shale
#

Ohh

pale perch
#

like look on f
at C f is negative but its increasing

vast shale
#

Yeah

pale perch
#

similar relationship with f' and f''

vast shale
#

Ic

#

What about f(0), f’(0) and f’’(0)

#

What do I look at

pale perch
#

youd be looking at the region by the y axis, we can tell f is p off the bat

#

i think f' being positive is also obvious

#

as for f'', you can see how f is getting less steep as it approaches D? That means the gradient is decreasing

vast shale
#

Am I looking at this point

#

On the y axis

pale perch
#

yeah

vast shale
#

Ah

#

To find the coordinates do I have to find the second derivative or smth

pale perch
#

,rcw

twin meteorBOT
pale perch
#

do you mean for c?

vast shale
#

Yeah

#

And M

pale perch
#

it will be a point where f''(x)=0 yeah

vast shale
#

Not f’(x) = 0 right

pale perch
#

thats M

vast shale
#

What

#

💀

pale perch
#

maxima and minima occur when f'(x)=0

p.o.i occur when f''(x)=0 and the sign of f''(x) changes on each side

vast shale
#

Oh

#

Am I doing this right

pale perch
#

sure, you didnt really need to do the second derivative test for finding M though,
the x most negative would be M just from the graph

#

but i like it

#

nice work

vast shale
#

So -5 is M and -2 is N?

pale perch
#

yeah, seems about right

vast shale
#

Alright

#

How would I do d

pale perch
#

would you be able to get the gradient at x=3?

vast shale
#

I just plug it into f’(x) to get the gradient without variables right

#

And then use y - y1 = m(x - x1)?

pale perch
#

seems like a good plan to me

vast shale
#

Alr

#

Like this?

pale perch
#

looks good

vast shale
#

So f’(x) = 0 is for finding the x-cords of turning points?

pale perch
#

yeah

vast shale
#

And f’’(x) = 0 is for finding the x-cord of inflexion?

pale perch
#

p.o.i occur when f''(x)=0 and the sign of f''(x) changes on each side

dont forget the additional condition

vast shale
#

Ohh

#

What if the sign doesn’t change

#

Is that a thing

pale perch
#

then its not a p.o.i

vast shale
#

What would that be

#

(if it even exist)

pale perch
#

dont think it really has a name as far as i know

#

the graph would just wobble a bit

vast shale
#

Ic

#

Alright, tysm for the help

#

🙏

#

.close

vocal sleetBOT
#
Channel closed

Closed by @gusty scroll

Use .reopen if this was a mistake.

#
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knotty kestrel
#

find range of : 3x^2/(x^2-25)

vocal sleetBOT
knotty kestrel
#

i got (-infinity, 0) U (3, infinity)

#

but its wrong

frosty mural
#

um

#

so first you can look at the restriction

knotty kestrel
#

um x cant be 5?

frosty mural
#

so look at the demonimator

#

yes, actually x != +-5

#

it cannot be positive/negative 5

knotty kestrel
#

yea but isnt that for domain

frosty mural
#

oh wait mb

#

didnt see the question

#

sry

#

lets try again

#

so actually

#

there is a little trick

knotty kestrel
#

.-.

#

what is it

frosty mural
#

so basically you find the coefficient of the x^2's

knotty kestrel
#

3?

frosty mural
#

which, in this case, are 3,1

#

and you find the ratio of it, which should be 3

#

and then, you find the constant numbers

#

which is 0, -25

#

and the ratio of it is obviously 0

#

so, (3, 0]

knotty kestrel
#

uh huh

frosty mural
#

wait actually

#

[0, 3)

#

that might be wrong, however i use it

#

like the range of x^2+3/x^2+1 is (1,3]

knotty kestrel
#

OH

#

wait

#

omg i got it

#

i had the right answer but my 0) shouldve been 0]

#

ty

frosty mural
#

well glad you got the right answer

knotty kestrel
#

.close

vocal sleetBOT
#
Channel closed

Closed by @knotty kestrel

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#
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idle coyote
#

part c

vocal sleetBOT
idle coyote
flat whale
idle coyote
#

doesnt sin(x) = 0 for n(pi)

#

dont have a pi symbol

#

sorry

vocal sleetBOT
#

@idle coyote Has your question been resolved?

vocal sleetBOT
#

@idle coyote Has your question been resolved?

#
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torpid kite
#

A cell phone manufacturer produces 145,000 phones a year. It costs $3.25 to store each phone for one year and $230 to produce each batch Find the number of batches that should be produced annually

torpid kite
#

Status 1

flat whale
#

Is this the entire question?

torpid kite
#

Yea

flat whale
#

What does the cost have to do with anything?

#

And how many are considered one batch?

frosty mural
#

wait ive heard that befor

#

e

torpid kite
#

So the total is 145,000

frosty mural
#

i think that is a economic order quantity problem

#

right?

torpid kite
#

Its a calc problem

#

Anyways there’s definitely a way to find out what’s considered a batch

frosty mural
#

no i think there is actually formula of that

#

ive see similar questions before

#

lemme see

torpid kite
#

3.25(145,000)/2(230)

#

Is like what im thinking

frosty mural
#

no

#

i think its like square root and something, there is definitely a formula for that

#

and im searching it in my memory

torpid kite
#

Lmao good luck

#

I need it😭

frosty mural
#

ok ill just ask google

#

i gave up

#

i have small brain to memorize stuff

torpid kite
#

Same

frosty mural
#

and im just a poor middle school student. anyway im searching for it

torpid kite
#

Im like a 14 year old in college 😂

torpid kite
#

3.25 store for one year

#

And the total is 145,000 for the whole year

frosty mural
#

ah wait i found it, Q = sqrt(2DS/H)

#

Q is volume per order

#

ah wait nvm

torpid kite
#

Yea im not sure about that one

#

Isn’t that to calculate the flow rate?

#
  • Q represents the flow rate (in units of volume per unit of time, e.g., liters per second).
  • D is the coefficient of discharge, which accounts for the efficiency of the orifice.
  • S is the cross-sectional area of the orifice.
  • H is the head, which is typically the height of the fluid above the orifice.
#

<@&286206848099549185>

frosty mural
#

D: Annual Quantity Demanded

Q: Volume per Order

S: Ordering Cost (Fixed Cost)

C: Unit Cost (Variable Cost)

H: Holding Cost (Variable Cost)

i: Carrying Cost (Interest Rate)

#

From web

#

im not actually sure

torpid kite
#

Yea i dont think thats the right formula

#

Cuz thats for

#

Liken

#

Ima kms

#

This problem seems so simple 😭

#

Idk why my brains struggling

#

A cell phone manufacturer produces 145,000 phones a year. It costs $3.25 to store each phone for one year and $230 to produce each batch Find the number of batches that should be produced annually

frosty mural
#

wait i think I found the right formula

torpid kite
#

Hm

frosty mural
#

N = EOQ/D

#

N should be stand for replenishment cycle

#

so, find EOQ, which is sqrt(2 * 145000 * 230/3.25), according to the formula EOQ = sqrt(2DS/H)

#

in this case D means demand rate, which is 145000 phones/yrs

#

S is 230dollars per batch

#

s means setup cost

torpid kite
#

You need the setup and holding costs for that equation

#

And i dont think

#

Well

#

Hm

frosty mural
#

and H(holding cost) is $3.25 phone/yrs

#

so we actually have D,S,H

#

and plug them in we have sqrt(20523076.9)

#

which is 4530.3

#

and its a rational number

#

and use the formula, N=D/EOQ, which is N=145000/4530.3

#

maybe that is the right answer, idk

torpid kite
#

Says its wrong rip😭

frosty mural
#

bruh I have no idea

torpid kite
#

Lmao yea no worries

frosty mural
#

those problems are tough to me

torpid kite
#

Definitely had me believing tho😂

frosty mural
#

wait no

#

EOQ = 4530.24027

#

so N = 145000/4530.24027

torpid kite
#

Says the answer should be under triple digits

frosty mural
#

triple digits???

torpid kite
#

Under so double digits

#

😭

#

Tbh if u read the question it actually makes sense it wouldn’t be in the thousands 😭😭

#

Idkk ima kns

#

Kms

#

My last hope

#

Is

#

@zinc quail

frosty mural
#

is not me

#

yes

#

he is the goat

torpid kite
#

Yk him?

#

Seems like he’s famous

#

<@&286206848099549185> someone help me before i end it all

frosty mural
#

yeah kinds

#

kinda

#

alight i gotta sleep, and I hope someone can answer ur question

#

cya

#

its 1:05 AM

torpid kite
#

Yea goodnight

#

<@&286206848099549185>

vocal sleetBOT
#

@torpid kite Has your question been resolved?

torpid kite
#

<@&286206848099549185>

native pagoda
#

What is a batch in this context?

#

@torpid kite

torpid kite
#

Idk thats the whole question

#

Someone got the right answer

#

But idk how they did it

#

They used the formula km/2(a)

native pagoda
#

Simply, not enough information.

#

Very vague question.

torpid kite
#

Yea but a girl

#

Somehow did it

#

But she had to go

#

3.25(145,000)/2(230)

#

Idk what she used

native pagoda
#

I would ask your professor to clarify the question.

torpid kite
#

They js said re read it

#

@golden heart This girl did it

native pagoda
#

Tell them it’s not possible to solve without more information. For example

#
  1. What is a batch?
#

A batch has no meaning without numbers or substance

#

A batch could be mean 2 bats

#

10 cookies

#

Who knows

#

I know I am not giving any answers. But that problem is unsolvable without assumption.

torpid kite
#

Your saying the exact thing i told my teacher

#

Just said re read the question

#

About to kms

lyric night
#

did this jessica girl get her answer checked by the prof

native pagoda
#

Probably not considering this problem appears unsolvable

torpid kite
#

Its a online homework thing

#

And her answer was correct

native pagoda
#

Well she must have assumed or used other information.

torpid kite
#

There’s something obvious that im not seeing

lyric night
native pagoda
#

There isn’t.

#

A batch isn’t defined therefore the problem is unsolvable

lyric night
#

yeah

#

pretty much

torpid kite
#

So whats this equation km/2a all bout

#

Thats what she used n ive never heard of it

native pagoda
#

That could be anything

#

That’s just variables at this is point

torpid kite
#

Well my perfect record is about to take a hit

#

Thanks for trying

native pagoda
lyric night
#

yeah pretty much

#

i mean i guess theres a possibility the prof specified something beforehand

#

?

native pagoda
#

I am headed to bed. I hope you find a solution!

torpid kite
#

well i need any type of attempt

#

One of you guys makeup something

#

Thats gets me the answer 32

#

And hopefully he wont look at my work too carefully

#

.close

vocal sleetBOT
#
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empty fern
#

how to solve this question?

vocal sleetBOT
pallid zenith
#

what is nice here is that youve been given two different x values where $f(x_1)+3 = f(x_2) + 3$

twin meteorBOT
#

jan Niku

pallid zenith
#

can you see how this is related to symmetry?

#

think like...

#

,w graph x^2-4

pallid zenith
#

well, actually, i guess even this isnt really necessary, but i think this makes it easier to visualize thonk

#

given 3 points you should be able to determine the quadratic anyways

#

actually, yea, using the thing i was talking about is fastest

#

say this was the unknown function

#

if you were told that f(-2)=f(2) = 0

#

and then some point precisely between these two

#

thonk no its easiest to solve for the full quadratic

#

sorry im babbling, are you there @empty fern

empty fern
#

yeah

pallid zenith
#

so

#

you can write your function out

#

ax^2+bx+c

#

three unknowns

#

youre given 3 points

#

so for example, the middle one

#

it tells you that a(24)^2+b(24)+c+3=8

#

you can create 3 equations here

#

your points happen to give you the vertex though thonk

empty fern
#

24,8 is vertex?

pallid zenith
#

well, 24,5

#

your table gives you f(x)+3

#

the thing is your general vertex form is what

empty fern
#

ahh

pallid zenith
#

$y=a(x-h)^2+k$

twin meteorBOT
#

jan Niku

pallid zenith
#

so here thatd be

#

$y = a(x-24)^2+5$

twin meteorBOT
#

jan Niku

pallid zenith
#

so youre awful close on the y-intercept

#

but you need a

#

maybe you can get it from one of the other points happy

#

f(28)+3=-72

#

@empty fern have i trailed off too much blobsweat

empty fern
#

ahh

#

never thought this question would be this long

pallid zenith
#

hmm its not long i guess

pallid zenith
#

step 2 is solving for a

#

but thats fine, you can do it with any of the other pieces of information

empty fern
#

okay

#

ty

vocal sleetBOT
#

@empty fern Has your question been resolved?

#
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honest heath
vocal sleetBOT
honest heath
#

is phi not almost trivially injective?

#

since for two matrices to be equal, each of their entries have to be equal, and if each of their entries are equal then the complex number that mapped to those entries under phi have to be the same?

paper depot
honest heath
#

then (a,b; -b,a)=(c,d; -d,c), but matrices are only equal if each of their entries are equal, so a=c and b=d and so a+bi=c+di then z1=z2 ? or am i missing anything?

paper depot
#

no, you're not.

honest heath
#

okay awesome, thanks for always helping!

#

.close

vocal sleetBOT
#
Channel closed

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lapis marten
honest heath
lapis marten
#

okay

honest heath
#

I was just doing the bijectivity first and i was like, this seems way too easy lol

vocal sleetBOT
#
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wooden sphinx
#

When you have a tangent plane to a 2 variable function

wooden sphinx
#

And it’s equation is

#

P = F(a,b) + Fx(a,b)(x-a) + Fy(a,b)(y-b)

#

Is that just explaining how z changes in terms of x and y

#

Together

mental falcon
#

yes, z = F(x, y)

wooden sphinx
#

In a very local area of course

#

Near the point (a,b)

#

I’m only asking

#

Because apparently this is how you can understand differentials

#

Right?

#

Because if you wanna do df

#

You just say it’s equal to

mental falcon
#

yeah, its analagous to the tangent line for a 1 variable function approximating the function locally

wooden sphinx
#

(PDF/Dx)d/dx + (PDF/Dy)d/dx

#

And essentially df is just the change in height for a 2 variable function

mental falcon
#

yeah, just like if you zoom in really far into a 1 variable function, it starts to "look like a straight line" more and more, if you zoom in to a 2 variable graph it starts to look more and more flat

#

and the tangent plane becomes a good approximation

wooden sphinx
#

And when you say that df = Fx(DeltaX) + Fy(deltaY)

#

Are you basically finding

#

The change in Z in the x change

#

And the change in Z with the Y change

#

And adding together

#

Which then tells you how much Y chnaged overall?

mental falcon
#

Which then tells you how much -Z- chnaged overall?

#

yes

wooden sphinx
#

Ah got it

#

I’m trying to visual this

#

And basically if I were to just compartmentalization

#

This

mental falcon
#

its a little funny because youre kind of looking at the change in z at point A by combining the changes at points B and C right?

wooden sphinx
#

Should I just see the height change in the direction

mental falcon
#

and if you travel diagonally instead of in straight lines in x / y directions, z can change differently

wooden sphinx
#

Well here is how I was going to visualize

#

And tell me if it’s valid

mental falcon
#

BUT the idea works of looking at as a linear combination IF you're talking about the limits as dx and dy -> 0

wooden sphinx
#

I consider how Z increases/decrease as you change X

#

So either z goes up or down

#

And then

#

Once I moved that point around

#

I then move it in the y direction

#

And see how much additional height has been gained

mental falcon
#

yeah

#

pretty much

wooden sphinx
#

Appreciate it so much

mental falcon
#

the math kinda all magically works out to be like this when taking the limits as dx, dy -> 0 its quite beautiful

wooden sphinx
#

It really is

vocal sleetBOT
#

@wooden sphinx Has your question been resolved?

vocal sleetBOT
#
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vast shale
#

Can someone explain me why the period Fourier series are represented with functions on a circle.

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#
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#
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umbral snow
vocal sleetBOT
umbral snow
#

hello

river minnow
#

,w solve y = 300 + 0.9(y - 1000) + 200 + 2000

river minnow
umbral snow
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Woah?!

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Woah?!

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Howcome?

river minnow
#

Yeah how did you get 2410 there

umbral snow
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i calculated 0.9 * (-1000) is -90 ?

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not correct?

river minnow
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0.9 * 1000 is 900 so you had 300 - 900 + 200 + 2000

river minnow
umbral snow
#

oh wtf

river minnow
#

It's -900

umbral snow
#

i typed wrong in calculator

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thanks

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.close

vocal sleetBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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tepid fossil
#

i get how they got the radius but how did they get the centre ??

vocal sleetBOT
radiant plinth
twin meteorBOT
proven garden
#

(x-a)^2+(y-b)^2=r^2 have center of (a,b) and radius r

obtuse scroll
#

The center is just 0,6

twin meteorBOT
#

diaas_(yt)

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diaas_(yt)

obtuse scroll
#

@tepid fossil

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That looks so cool

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I love it when math looks cool

vocal sleetBOT
#

@tepid fossil Has your question been resolved?

tepid fossil
#

do they subtract the radius from something

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i remember doing something like that

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im still quite confused @obtuse scroll

obtuse scroll
#

Hi stig

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Did you see the 2 messages I sent

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Just use that, that's pretty standardized

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Gimme a sec let me log on my computer

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oh god

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We're given $x^2+y^2-12y-13=0$

twin meteorBOT
#

diaas_(yt)

obtuse scroll
#

Convert this to $(x-a)^2+(y-b)^2=r^2$

twin meteorBOT
#

diaas_(yt)

obtuse scroll
#

We get $(x)^2+(y-6)^2=7^2$

twin meteorBOT
#

diaas_(yt)

obtuse scroll
#

So we get a=0, b=6 and r=7

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Radius is 7 and center is (0,6)

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@tepid fossil

obtuse scroll
tepid fossil
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can you teach me how to convert

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also thank you for taking the time to help me

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do we just square everything

obtuse scroll
#

So I have no idea how to convert from form A to form B

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form A being $x^2+y^2+2gx+2fy+c=0$

tepid fossil
#

oh i think i understand

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also do we swap the signs

obtuse scroll
#

which signs

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Look, let me tell you something

tepid fossil
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like see how it’s -6 in the equation but in reality it’s 6 as the coordinate

obtuse scroll
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YES

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(x-a)^2 means x coord of center is a

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If it's (x+a)^2 then the x coord is -a

twin meteorBOT
#

diaas_(yt)

obtuse scroll
#

Got it?

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I'll tell you a trick if you want..

tepid fossil
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ah okay

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thanks for the help dias

obtuse scroll
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No issues

tepid fossil
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also i do agree with you

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math is cool

obtuse scroll
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when it looks cool

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BTw

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You want a trick for circles?

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Trust me, JEE makes me study way more than a 11th grader should.

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Bro you might wanna close the channel

tepid fossil
obtuse scroll
#

So here's the thing

obtuse scroll
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If a circle is given to you in this form, the center is -g,-f