#help-17
1 messages · Page 110 of 1
so itsj ust g/4pi^2
yes
,w 9.8/(4pi^2)
you want this?
i think so?
then if you've got a calculator, you just put that in
okk
with g=9.8
yeah
so L=0.25
sure
it's a right angled triangle, so pythagoras' theorem would be good
but how do i do that wiht just z
*x
if you let the longest side be y, then y^2=(2x)^2+x^2?
(i would work on the area first though)
how tho?
area = 1/2 x base x height?
so x=square root of 30
so that gives you the two shorter sides, and then you can use pythag for the longest side
so its 2*square root of 30?
so i right 2√30?
yes, for the second side
can u check for me?
,w sqrt150
looks good
ok but it doesnt exactly equal 30
how do i do that
,w 2sqrt30
same way you rounded x?
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For proving that gcd(m_1, n) = 1 and gcd(m_2, n) = 1 ==> gcd(m_1m_2, n) = 1, would you use Bezout's identity?
It'd give us
1 = a_1m_1 + b_1n
1 = a_2m_2 + b_2n
Now multiply these two together?
But that wouldn't lead us where we want
if m_1 doesn't have any common factors with n, and neither does m_2, then their product can't have any common factors with n
if p is a prime s.t. p|n and p|m1m2 then p|m1 or p|m2 ...lets say p|m1 then we get a contradiction because p|m1 and n ...
now a common divisor of n and m1m2 will not have any prime factors... so only +-1 could be a common divisor
and so it's 1? Thanks
so all you need is actually Gauss's lemma
Wait, contradiction to p|n and p|m1m2 means not p |n or not p|m1m2
or, not and
you can also just do it constructively, it turns into letter salad but it works
if ar + bx = 1 and cs + dx =1
ars + bsx = s
ars = s(1 - bx)
acrs = cs(1-bx)
acrs = (1-dx)(1-bx)
(ac)rs + (b+d-x)x = 1
so we're done
Thanks!
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gauss have done a lot of lemmas in his life
Some call it Euclid's lemma too
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Im trying to understand how to go about this.
@lime tartan Has your question been resolved?
@lime tartan Has your question been resolved?
You know someone who can perhaps
chatgpt seems to get this stuff wrong
If you Will learn how to solve it I can help
I know how the thing works
But I cant solve it
Okay I'm back, I found nothing else to do.
Bruh
Is that your uncle
What?
It's okay, and no, sorry, I'm not on that level of maths yet, though I am intrieged by it, in other words, I love maths.
I am trying but I cant understand how it works
this is discrete math / combinatorics if that helps
And I'm only a Year 6 learner that does Year 7 maths ( by a small fraction).
i was doing algebra in 8th grade. wtf
In the way of saying it from where I am, I'm a Year 6 pupil.
I am doing everything that I wnat in 8th grade
I can do algebfa
But I need to know
What is n!
I have a strong intrest about algebra.
But I like Pi more
n! = n * n-1 * n-2 * n-3 * n... * 1
I like n- infiniti
its n times every integer below n
Ah, okay.
n factorial
I am really interest in goniometric funcitions algebra I am learning cyclometric functions I am trying to understand Quantum physics maxwells equations And More!
In my school, I was the only one that realised my school has been doing algebra for YEARS.
i wrote a paper using maxwell equations
Oooooooo~ sounds interesting.
Ayo young sheldon mindset
let me try to find it. i still need help though with my problem
Who has the Young Sheldon mindset may I ask?
if you guys know someone id greatly appreciate
You
?
not you too...
My parents call me Young Sheldon all the time because I'm 'Too smart!'
One of my classmates called me him aswell
Like I know it is a iracional number
But I think if you are good at it
It is good for you
3.14159265358979323826460338327950288419716939937510582097494459230781640628620898628034825342117067
Is that right?
I hope so.
Remebering pi is useless. What does pi represent?
Hold on, I have a book near me about this brb
It is 3.14159265359
You rounded that last digit
?
Who?
Dominik
Its irrational.
Which means you cannot represent it in a finite sequence of digits
I dont know every english word
Its ok
3.1415926535 8979323846 2643383279 5028841971 6939937510 5820974944 5923078164 0628620899 8628034825 3421170679 ...
Yes it goes on forever
Like plank constant
Oml
Yes
My handy-dandy math book is MISSING.
Anthony
Actually no, it is not like planks constant. Plank constant is rational
I SPENT A YEARS WORTH OF MATHS IN THERE AND IT'S VANISHED OUT OF THIN AIR...
BRO
I will scream rn
I have my book And it is only 2 monhts old
At least you have the entire internet
No worries
I understand the operations but I cant do equations with it I am really sorry
Know the e And the !
Dont worry
Dont worry my quiz on this stuff is on monday so it will be too late by then
Show me pic
I mean it'll do for now I guess
Anthony
@lime tartan
K! = 1 is it right
Anthony
I can help but I need your help too
Please
What are we solving for?
If k is arbitary n is too
Yes
No lol
But why is There k=1
What are you talking about?
Yes.
look up summation
This is a bit more advanced than what you know and thats ok. Dont worry
No
No
It represents the number of distinct subsets of size k of a set of size n
in other words, it is the number of ways you can choose k things from a collection of n of them
I am totally lost
But I know that if k is something n is something too
I think the solition might something do with the times two
No
But the set can be empty right?
What grade are you
University
Hmm
My brain is not braining but I Will help
Math is helping me get oit of my problems
its ok cause there is a lot of stuff you need to know to be able to understand this
you need to know summation factorials binomial theorem set theory combinators and number theory
When I am doing math I forgot that I am ridiculed
keep doing math math is good
I heard of every one of the teories
But I dont know what they are about
Oh
We need the binomial theorem to proof the equation
Am I right?
Yea its part it
It Will do something with the sets I think
We need the Pascal's triangle
But , sum of exponents is always equal to n
But in the equation There is subtracion
What Will we do?
Anthony what Will we do
No worries
N must be an sum of something
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Nooo
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what is 2+2?
or 3+3?
depends on what group or ring ur working in
@vast shale Has your question been resolved?
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why do they create another set C to solve this? none of any my other questions involved making a new set
or is C just an example for all A
You have to prove that B is a subset of the intersection of the elements of F. This is equivalent to saying that B is a subset of each element of F : C acts as an arbitrary element of F
If B is a subset of C, for C an arbitrary element of F, then B is a subset of the intersection of the elements of F
okay, thank you for clarifying. i'll try to solve the question further because that confused me
.close
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why isnt the answer for ycm 1?
wdym with ycm?
@signal river Has your question been resolved?
Why do you think it should be
@signal river Has your question been resolved?
Show the formula
Your class doesn't have textbook?
not that i know of
Then how are you learning formulas
Like from here
do you happen to know it
Calculus textbook should have it
what free textbooks
wow
i found it
you could have just told me i needed to add the 1/2
instead of telling me to google it
That's also wrong?!
Working for one function doesn't mean it works for all
oh and squared to teh x
Telling you the answer is against server rules
Having a textbook means you won't get formulas wrong anymore
right
Giving away answers usually isn't as helpful as guiding
#book-recommendations also should have calculus book recommendations
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Hi
hey 😄
Is the Stewart calculus 7th edition early transcendental book good
I am trying to pre learn calculus
So I was wondering if it is a good book
Hello?
hey man i am learning calculus 3 now i have this book do know if it helps you
Ok
sorry i am not advanced in this topic !!
THOMAS’
CALCULUS
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could someone help me with solving sin(1/x)=1/sin(x) i have no idea how i would do this
is this a hw question
its not
i saw it in a blackpenredpen vid and wanted to try but i didnt get very far
i got to this
e^{ix}-e^{-ix}=\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)
idk how the bot works?
put dollar signs on both sides
$e^{ix}-e^{-ix}=\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)$
DaanHun
,w expand (exp(i/x) - exp(-i/x)) * (exp(ix) - exp(-ix))
this is false
hmm what
then im just trash
this should be true:
$\frac{2i}{\left(e^{ix}-e^{-ix}\right)}=\frac{\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)}{2i}$
DaanHun
what are you doing
yes those are right
add those to each other
it doesnt
1 sec
A viewer wanted me to try the trig equation involving tangent: tan(1/x)=1/tan(x). This seems to be a fake trig identity but it turns out to be a very interesting trig equation. We will use some trig identities to simplify this equation and also the quadratic formula to actually solve this equation.
Try this precalculus challenge sin(x)=sin(pi*x...
at the very end he puts sin(1/x)=1/sin(x) up as a challenge
try putting sin into exponential form
they did
I remember trying this problem and I found that there were no solutions
im just not sure how to get any further than this:
$\frac{2i}{\left(e^{ix}-e^{-ix}\right)}=\frac{\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)}{2i}$
DaanHun
wolframalpha gives 6 solutions
,w solve 2i / (exp(iz) - exp(-iz)) = (exp(i/z) - exp(-i/z)) / (2i)
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online
all complex
right 4 answers that are like a square and some other points very far away idk how that even happens
,w plot 1/sin(x) - sin(1/x) for -100 < x < 100
the difference never intersects the x axis
but there are complex answers no?
or maybe i have to increase the domain
,w expand (exp(i/z) - exp(-i/z)) * (exp(iz) - exp(-iz))
,w (exp(i/z) - exp(-i/z)) * (exp(iz) - exp(-iz)) = 2cos(z + 1/z) - 2cos(-z + 1/z)
from here you just need to solve $-4 = 2 \cos(z + 1/z) - 2\cos(z-1/z)$
,tex .sum diff trig
probably won't be helpful
hmm
riemann
i can do that i think
so solving that would work?
ohh i know what i duid wrong i thjink
would this work? :
$-4=\left(e^{\frac{i}{x}}-e^{-\frac{1}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)$
DaanHun
i meant i/x
$-4=\left(e^{\frac{i}{x}}-e^{-\frac{i}{x}}\right)\cdot\left(e^{ix}-e^{-ix}\right)$
DaanHun
i think i put down the exact same just exponential and not cos
@blazing atlas Has your question been resolved?
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Is the 3 in front of the absolute value multiplying the inner contents of it?
just 3 times whatever the output of that abs value is
so if x=1 the abs value of x-2 will be 1 multiplied by 3
i think
So for the two equations it would be $3(x-2)-3$ and $-3(x-2)-3$
Matt
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How am I supposed to know what the equations are
What exactly is f’’(x) on the graph there?
And how do I find f(0)
With no equation given
How am I supposed to know that tho
f'(x) is the gradients of f, the rate of change of f
Yeah I understand the first derivative
f''(x) is the gradients of f', the rate of change of f'
because the gradient is negative yeah but its increasing
???
its negative (going down)
but its increasing, it eventually becomes 0 at B, then it goes up
it becomes less steep
Then how is E negative for f’’(x)
because the gradient is getting more negative, the graph of f is getting steeper downwards
the gradients are negative yes, so f'(x) is negative
Yeah
its becoming more positive
it could be going something like
-5, -3, -2 ,-1, 0 (at B), 1, 2, 3
it was negative but it was increasing
Ohh
like look on f
at C f is negative but its increasing
Yeah
similar relationship with f' and f''
youd be looking at the region by the y axis, we can tell f is p off the bat
i think f' being positive is also obvious
as for f'', you can see how f is getting less steep as it approaches D? That means the gradient is decreasing
yeah
,rcw
do you mean for c?
it will be a point where f''(x)=0 yeah
Not f’(x) = 0 right
thats M
maxima and minima occur when f'(x)=0
p.o.i occur when f''(x)=0 and the sign of f''(x) changes on each side
sure, you didnt really need to do the second derivative test for finding M though,
the x most negative would be M just from the graph
but i like it
nice work
So -5 is M and -2 is N?
yeah, seems about right
would you be able to get the gradient at x=3?
I just plug it into f’(x) to get the gradient without variables right
And then use y - y1 = m(x - x1)?
seems like a good plan to me
looks good
So f’(x) = 0 is for finding the x-cords of turning points?
yeah
And f’’(x) = 0 is for finding the x-cord of inflexion?
p.o.i occur when f''(x)=0 and the sign of f''(x) changes on each side
dont forget the additional condition
then its not a p.o.i
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find range of : 3x^2/(x^2-25)
um x cant be 5?
so look at the demonimator
yes, actually x != +-5
it cannot be positive/negative 5
yea but isnt that for domain
oh wait mb
didnt see the question
sry
lets try again
so actually
there is a little trick
so basically you find the coefficient of the x^2's
3?
which, in this case, are 3,1
and you find the ratio of it, which should be 3
and then, you find the constant numbers
which is 0, -25
and the ratio of it is obviously 0
so, (3, 0]
uh huh
wait actually
[0, 3)
that might be wrong, however i use it
like the range of x^2+3/x^2+1 is (1,3]
well glad you got the right answer
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part c
the solution https://www.calcchat.com/book/Calculus-11e/10/3/91/
CalcChat.com is a moderated chat forum that provides interactive calculus help, calculus solutions, college algebra solutions, precalculus solutions and more.
What question do you have about the solution
@idle coyote Has your question been resolved?
@idle coyote Has your question been resolved?
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A cell phone manufacturer produces 145,000 phones a year. It costs $3.25 to store each phone for one year and $230 to produce each batch Find the number of batches that should be produced annually
Status 1
Is this the entire question?
Yea
So the total is 145,000
Its a calc problem
Anyways there’s definitely a way to find out what’s considered a batch
no i think there is actually formula of that
ive see similar questions before
lemme see
no
i think its like square root and something, there is definitely a formula for that
and im searching it in my memory
Same
and im just a poor middle school student. anyway im searching for it
Im like a 14 year old in college 😂
Im thinking since its
3.25 store for one year
And the total is 145,000 for the whole year
Yea im not sure about that one
Isn’t that to calculate the flow rate?
- Q represents the flow rate (in units of volume per unit of time, e.g., liters per second).
- D is the coefficient of discharge, which accounts for the efficiency of the orifice.
- S is the cross-sectional area of the orifice.
- H is the head, which is typically the height of the fluid above the orifice.
<@&286206848099549185>
D: Annual Quantity Demanded
Q: Volume per Order
S: Ordering Cost (Fixed Cost)
C: Unit Cost (Variable Cost)
H: Holding Cost (Variable Cost)
i: Carrying Cost (Interest Rate)
From web
im not actually sure
Yea i dont think thats the right formula
Cuz thats for
Liken
Ima kms
This problem seems so simple 😭
Idk why my brains struggling
A cell phone manufacturer produces 145,000 phones a year. It costs $3.25 to store each phone for one year and $230 to produce each batch Find the number of batches that should be produced annually
wait i think I found the right formula
Hm
N = EOQ/D
N should be stand for replenishment cycle
so, find EOQ, which is sqrt(2 * 145000 * 230/3.25), according to the formula EOQ = sqrt(2DS/H)
in this case D means demand rate, which is 145000 phones/yrs
S is 230dollars per batch
s means setup cost
and H(holding cost) is $3.25 phone/yrs
so we actually have D,S,H
and plug them in we have sqrt(20523076.9)
which is 4530.3
and its a rational number
and use the formula, N=D/EOQ, which is N=145000/4530.3
maybe that is the right answer, idk
Says its wrong rip😭
bruh I have no idea
Lmao yea no worries
those problems are tough to me
Definitely had me believing tho😂
Says the answer should be under triple digits
triple digits???
Under so double digits
😭
Tbh if u read the question it actually makes sense it wouldn’t be in the thousands 😭😭
Idkk ima kns
Kms
My last hope
Is
@zinc quail
Yk him?
Seems like he’s famous
<@&286206848099549185> someone help me before i end it all
yeah kinds
kinda
alight i gotta sleep, and I hope someone can answer ur question
cya
its 1:05 AM
@torpid kite Has your question been resolved?
<@&286206848099549185>
Idk thats the whole question
Someone got the right answer
But idk how they did it
They used the formula km/2(a)
Yea but a girl
Somehow did it
But she had to go
3.25(145,000)/2(230)
Idk what she used
I would ask your professor to clarify the question.
Tell them it’s not possible to solve without more information. For example
- What is a batch?
A batch has no meaning without numbers or substance
A batch could be mean 2 bats
10 cookies
Who knows
I know I am not giving any answers. But that problem is unsolvable without assumption.
Your saying the exact thing i told my teacher
Just said re read the question
About to kms
did this jessica girl get her answer checked by the prof
Probably not considering this problem appears unsolvable
Well she must have assumed or used other information.
There’s something obvious that im not seeing
i dont there is
I would recommend talking to your professor again. I apologize for inconclusive solutions but I don’t see any way this is possible.
yeah pretty much
i mean i guess theres a possibility the prof specified something beforehand
?
I am headed to bed. I hope you find a solution!
well i need any type of attempt
One of you guys makeup something
Thats gets me the answer 32
And hopefully he wont look at my work too carefully
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how to solve this question?
what is nice here is that youve been given two different x values where $f(x_1)+3 = f(x_2) + 3$
jan Niku
well, actually, i guess even this isnt really necessary, but i think this makes it easier to visualize 
given 3 points you should be able to determine the quadratic anyways
actually, yea, using the thing i was talking about is fastest
say this was the unknown function
if you were told that f(-2)=f(2) = 0
and then some point precisely between these two
no its easiest to solve for the full quadratic
sorry im babbling, are you there @empty fern
yeah
so
you can write your function out
ax^2+bx+c
three unknowns
youre given 3 points
so for example, the middle one
it tells you that a(24)^2+b(24)+c+3=8
you can create 3 equations here
your points happen to give you the vertex though 
24,8 is vertex?
well, 24,5
your table gives you f(x)+3
the thing is your general vertex form is what
ahh
$y=a(x-h)^2+k$
jan Niku
jan Niku
so youre awful close on the y-intercept
but you need a
maybe you can get it from one of the other points 
f(28)+3=-72
@empty fern have i trailed off too much 
hmm its not long i guess
this is step 1
step 2 is solving for a
but thats fine, you can do it with any of the other pieces of information
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is phi not almost trivially injective?
since for two matrices to be equal, each of their entries have to be equal, and if each of their entries are equal then the complex number that mapped to those entries under phi have to be the same?
it is not hard to show that it is injective.
just assume phi(z1)=phi(z2) where z1=a+bi and z2=c+di
then (a,b; -b,a)=(c,d; -d,c), but matrices are only equal if each of their entries are equal, so a=c and b=d and so a+bi=c+di then z1=z2 ? or am i missing anything?
no, you're not.
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An isomorphism is more than an injection though
yes i know! thank you for making sure though!
okay
I was just doing the bijectivity first and i was like, this seems way too easy lol
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When you have a tangent plane to a 2 variable function
And it’s equation is
P = F(a,b) + Fx(a,b)(x-a) + Fy(a,b)(y-b)
Is that just explaining how z changes in terms of x and y
Together
yes, z = F(x, y)
In a very local area of course
Near the point (a,b)
I’m only asking
Because apparently this is how you can understand differentials
Right?
Because if you wanna do df
You just say it’s equal to
yeah, its analagous to the tangent line for a 1 variable function approximating the function locally
(PDF/Dx)d/dx + (PDF/Dy)d/dx
And essentially df is just the change in height for a 2 variable function
yeah, just like if you zoom in really far into a 1 variable function, it starts to "look like a straight line" more and more, if you zoom in to a 2 variable graph it starts to look more and more flat
and the tangent plane becomes a good approximation
And when you say that df = Fx(DeltaX) + Fy(deltaY)
Are you basically finding
The change in Z in the x change
And the change in Z with the Y change
And adding together
Which then tells you how much Y chnaged overall?
Ah got it
I’m trying to visual this
And basically if I were to just compartmentalization
This
its a little funny because youre kind of looking at the change in z at point A by combining the changes at points B and C right?
Should I just see the height change in the direction
and if you travel diagonally instead of in straight lines in x / y directions, z can change differently
BUT the idea works of looking at as a linear combination IF you're talking about the limits as dx and dy -> 0
I consider how Z increases/decrease as you change X
So either z goes up or down
And then
Once I moved that point around
I then move it in the y direction
And see how much additional height has been gained
Appreciate it so much
the math kinda all magically works out to be like this when taking the limits as dx, dy -> 0 its quite beautiful
It really is
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Can someone explain me why the period Fourier series are represented with functions on a circle.
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hello
,w solve y = 300 + 0.9(y - 1000) + 200 + 2000

Yeah how did you get 2410 there
0.9 * 1000 is 900 so you had 300 - 900 + 200 + 2000
No
oh wtf
It's -900
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,rotate
(x-a)^2+(y-b)^2=r^2 have center of (a,b) and radius r
The center is just 0,6
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i’m asking how they find the centre @proven garden
do they subtract the radius from something
i remember doing something like that
im still quite confused @obtuse scroll
Hi stig
Did you see the 2 messages I sent
Just use that, that's pretty standardized
Gimme a sec let me log on my computer
oh god
We're given $x^2+y^2-12y-13=0$
diaas_(yt)
Convert this to $(x-a)^2+(y-b)^2=r^2$
diaas_(yt)
We get $(x)^2+(y-6)^2=7^2$
diaas_(yt)
Alternatively you can just take the original equation and compare it with this
can you teach me how to convert
also thank you for taking the time to help me
do we just square everything
Meh, In my board I only use the form in the first image
So I have no idea how to convert from form A to form B
form A being $x^2+y^2+2gx+2fy+c=0$
like see how it’s -6 in the equation but in reality it’s 6 as the coordinate
diaas_(yt)
No issues
when it looks cool
BTw
You want a trick for circles?
Trust me, JEE makes me study way more than a 11th grader should.
Bro you might wanna close the channel
sure
So here's the thing
refer to this
If a circle is given to you in this form, the center is -g,-f