#help-17
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In the exercise 6.9
I tried resolving it in 2 different ways shown in the orange color
In the second tried I used change of variables
I know the right answer is 3) a= being any number you want and b<0
But idk if my way of solving it is right
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how to do chi square?
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i need to basically do the opposite of factoring and find out what addition of two fractions made this. I understand it for the most part, but the answer has a C in it and im really confused where the C came from
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can someone walk me thru this
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What exactly are you stuck on? As I mentioned before, surface area is just the sum of the areas of the faces
So you need to find the area of each face, then add them
I’m thick tho
Can you find the area of each side?
Where is 108 from?
It's a triangular prism
So the top face is the same shape as the one on the bottom, the hidden one
The top face I'm referring to is this
That's a triangle
The bottom face is the same, a triangle
the triangle formula is 1/2b*h
9x6
wait sorry i cant even see the picture correctly my eyes are a bit blury 😭
22.5
The 9 and 6 relate to these sides
That's the area of 1 of the triangles, you have 2
Then you need the area of the other sides
45
Where is 45 from?
Also that is not the area of the triangle btw
I dont know then
Do you know the formula for area of a triangle?
You know the height and the base
I pointed it out here
Yes and that equals?
27.5
X2
Find the area of the rest of the faces then sum them up
Why did you multiply by 2?
There are two
263
Yes that's it
You just need to find the areas of each face then add them up, that's it
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sum and difference
im not sure where to start and/or how my answer is supposed to come out
i know im supposed to make triangles and use x^2+y^2=r^2
if im to do cosa=4/5 with a in QIV then where do i start
is theta the origin on the graph?
if im supposed to find the missing sides then subtract the coinciding answers, then do i need to use a ton of math here?
because wouldn't my answer lie on 0 if the remaining sides equal to 3 and -3 (just a guess)
or am i completely off track
@tribal pond Has your question been resolved?
by far I have learned that the DMV moves faster than this train
in the meantime, I've been doing other things but i'm still waiting on this
took a crack at it see if this works
could you take a snip of it using the snipping tool instead of that?
i can get it in a different format one sec
took a picture from my phone is only problem
ah
so am i taking cosine
and turning the values into triangles
then with the missing side values i use those and throw it into a sine function?
basically the formula you need is sin(a-b) = sinacosb - cosasinb
so you need to use the cos you are given
to find sin
so one quick question
I have a sum and difference thingy
if you have any knowledge on this please do tell
sorry mate i know i learned this at one point but im completely blanking
it's like the secrets of the pentagon to me
i'll give it a shot but someone may need to tag in lol
ive been tryin
that bottom part needs to be -sinx so i can do an odd/even thing to it and then quotient it to make it cotx
that part might not make any sense
sorry give me a sec
okay figured it out
so basically i figured out the value of both cos(pi + x) and cos(3pi/2 -x)
cos(pi + x) is -cosx (you found this)
for cos(3pi/2 - x):
use the formula cos(A + B) = cos(a)cos(b) - sin(a)sin(b)
subbing 3pi/2 in for a
and -x for b
yeah so at that stage its pretty simple
you literally just calculate what cos(3pi/2) is and what sin(3pi/2) is
and multiply
then simple stuff is always too complex for me
its what always trips me up as well
this all must equal cotx
yeah trust me on this
cos(3pi/2) = 0
sin(3pi/2) = -1
so the bottom simplifies to -sinx
ooooooh
and then you just do what you said earlier
good job : )
basically same thing
go for it
i feel like this is basically the same lol
if u just use sin(a+b) and sin(a-b) formula and follow that through you should get there in the end
do you still need help with this?
yah
just to make sure csc(x) is 1/sinx right?
yes
never seen it written like that
lol
okie
next you need to get the number on the bottom the same so you can add them to make one fraction
so you end up with sin^2x/sinxcosx + cos^x/sinxcosx
which makes sin^2x + cos^2x/sinxcosx
do you think you can figure it out from there ?
so cosx = sinx+1 and sinx = cosx+1
if i split it up better it may become clearer
my meds are wearing off
im becoming more defocused by the minute but im trying
its alright take your time
it may help to think about it like this
you are trying to find cosecx * secx
this is equal to (1/sinx)(1/cosx)
which multiplies to 1/sinxcosx
so we need to go from (sin^2x + cos^2x) / (sinxcosx)
to 1 / (sinxcosx)
what rule can we use
ive just used quotient so then i have to use pythagorean
thats correct
but how do i apply it to the two separate fractions?
do i make them all applied to pythagorean or just the top
okay basically
the theorem you need to use is sin^2x + cos^2x = 1
i might write out the question to make it clearer
so
sinx/cosx + cosx/sinx
sinx+cosx=1
or no
because im getting wrapped around this part
how do i get sin^2x from sinx
give me one sec im just writing it out
thats right
thamk
screw you math gods
i spoke too soon
i need this
^this must equal "siny"
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I want to know what I'm doing wrong/how to work out the total time
7.25 isnt a length of time
oh wait
i see i see
its the .25
25 minutes isnt .25 of an hour
.25 of an hour is 15 minutes
So then would I say that the total time is 7.40?
,calc 25/60
Result:
0.41666666666667
Do I calculate what that is and then put that in?
if youre using a calculator, you could just type (600)/(7+5/12)
unless your calculator can store answers from the previous line to use, in which case you could, sure
So I calculated this and it came up with 80.8988764045
,calc 600/(7+5/12)
Result:
80.898876404494
seems so
Don't I have to round it out?
3 significant figures seems safe
Alright, so that means the total time is 80.8 right?
.9
Oh! Okay mb-
so then if 600 divided by 80.9 is 7.416563658838072, thats the average speed?
the 80.9 is the average speed
Wait so whats the total time???
Cause I just asked if 80.9 was the total time and you said yes
the total time was the 7+5/12
So then the total time is 7.41666666667 so what would I round that to?
3 is also fine again
So I round it to 7.41?
.42
Okay so dividing the 600 by the 7.42, I get 80.86253369272237
rounding it off would make it 80.9?
i mean yeah, but why would you use a rounded value in your calculations when you have the exact value
I figured it would be too long, wouldn't it?
why? the exact value is literally (7+5/12) thats not that long to write
using rounded values will screw up your answers in the future if you make that a habit
Wait okay okay okay, so what do I put as the Average speed? Exactly 80.86253369272237?
no you can round when you have your answer, i just mean dont round mid working
What is 7+5/12?
I apologise I believe we were done and that was the answer
the time in hours from 11:50 am to 7:15pm
yeah the answer is the 80.9, im more referring to using '7.42' here
yeah but why? i counted the hours and got 7.416 hours and i used that value
when you get to questions that are longer in the future, if you use rounded values during your working theres a possibility for huge discrepancy in your final answers
so its generally good practice to just keep things exact until youre done
yeah but why? i counted the hours and got 7.416 hours and i used that value
i know. my question is why did you write time by meand of 7+5/12
7 is the number of whole hours, 5/12 represents the additional 25 minutes
i first counted minutes and divided by 6o to get th time
how 5/12 is 25 minutes? whats does it refer to?
,calc 25/60
Result:
0.41666666666667
ah i see, think i may have understood your question, my bad
but yeah, its just the 25/60
Sooo.. Where do I go from here??
So this is the right answer?
thanks
pretty much
Pretty much? So that means it isnt?
its just my way of saying theres not much else you could be expected to do
thats the answer
sure
The answer would be census, right?
I just want to double check
Then I'll be out of your hair
statistics
I assume you're not good at them? Thats totally fine-
Alrighty, please, no rush
seems more like a sample
if the population is the class
and she is surveying only the year 9's in said class then thats a sample of a population
(idk why there would be more than one year group in a class though)
no worries
Have a good one
you too
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Aight, why?
idrk
WHY
😭 😭 😭
WHY DID YOU KILL THAT WOMAN
Cuz the n and n prime look kinda right
*slams desk* FACE THE REALITY
huh?
Idk
It just looks
Correct
I think it wouldn't shifted down
If it were something else
Should've called them N and M and the right point L, that would've been an easy question 💯
depends
It can be either
Technically not doing anything is also a dilation
But I digress
Wahr
It's, like... You dilate, but the amount you dilate is nothing
It's not relevant just forget about it
"dilation" is actually often used to clarify that it can either make things bigger or smaller
But in this case N' is bigger than N
So it must be outward
Why C?
That's the gist of it, yeah
Looks like A, B, and D have been strategically placed to confuse
Interesting
@fallen sandal Do you get the idea now?
Soo it's C
Dilation just scales everything in or out (or not at all, which technically counts) from a point without any change in shapes or any rotation
So yeah, C
You can figure out the point by drawing lines like I did
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hello, what's the least upper bound of $\frac{x+y}{1+xy}$ when x and y in $]-1, 1[$?
lilisworld
Does it have a finite one? 
Well just looking at it, seems like the closer you choose x to 1 and the closer y is to -1 that you'd get something that just grows, no?
Though I may be missing something
i also might be wrong but i guess it's 1 cause it implies inequality (x+y)/(1+xy) <= 1 or (1-x)(1-y)>=0 which is obvious from x, y <= 1
That's what I was thinking
Oh no my brain's gone, thought of the numerator as x - y 
Consider what would happen if you pick x and y to be as close to 1 as possible
i don't really know
i don't get the "it implies inequality"
if it's the limit then it's 1
if sup=1, then for any -1 <= x, y <= 1 inequality (x+y)/(1+xy) <= 1 holds and there exist such (x, y) that (x+y)/(1+xy) = 1
so it's 1?
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can someone walk me through the algebra for this step please? Thank you!
$(n^2+n-2)=((n^2+n)-2)$
IV
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is $\frac{\infty}{\infty-\infty}$ an eligible form to use lhopitals rule
Jash
@velvet cove Has your question been resolved?
@spice sun
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
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I honestly have no clue; if someone could help me going through these four problems I would be super appreciative!
do you see the pattern of the function
so the period would be the distance between the same points on two successive "patterns"
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Ask
can someone help me with these math problems
@golden dagger Has your question been resolved?
Do you know what a gcf is
Greatest common factor
Do you know how to do that for Q24
Would the Gcf be 12?
Can you divide 28 by 12 without remainder
No
So it can’t be 12
2?
Yeah 2 sounds good
Alright then what
Actually 4 is the hcf
Alright
It becomes 4(3x^2+7x-6)
Ok
Now do you know how to factorise that quadratic
No
Multiply 3 by -6, now find numbers that multiply to give -18 and add to give 7
Ok
What are they
3x-6 like u said?
What do you get when you sum them though
-18
Sum as in addition
How do you sum them ?
3 + -6
So it can’t be those two because they don’t add up to 7
So can it be any numbers?
Yes as long as their product is -18 and their sum is 7
4x-8?
4 x -8 is -32 and they add up to -4 so both the conditions are not met
List out all the factors of 18, that should help
1,2,3,6,9,18
Ok now what
Rewrite the first and last terms like this:
3x^2 -6
And inbeteeen you put the two numbers you found multiplied by x
3x^2+9x-2x-6
Now group them:
So is it 3x^2+9x and -2x+6
There will be one for each group
So I think for -2x+6 the factor is 2 and for the other is 1?
Always take out the negative, so it would be -2 for that one, but for the other group it’s not 1
Oh
Would it be -2x? For the factor
3x(x+3)-2(x+3)
This becomes
(3x-2)(x+3)
And don’t forget toe 4 from before
4(3x-2)(x+3)
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I was wondering how this question (attached below, #8) was solved, given all the information provided. Mainly, my brain is breaking up on the explanation "The area beyond z for Zx=-.83 is .2033". How is that figured out? What set of numbers can you use to figure this out? My mind is shattered I have been staring at this for like an hour now.
Sorry for the low quality pictures.
Can repost the pics to be more clearer if needed
<@&286206848099549185>
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@atomic zephyr Has your question been resolved?
for z score you have a standardized normal distribution
Using integration gives area, or you can use a z table instead
wouldn't Table B be the z table?
?
z table tells you the area given a z value
table B is just a table of z values, it doesn't tell you the area
Ah, I'm sorry, missed a couple classes and I feel lost regarding z-scores lol. So, say I figure out the z-score of -.83, what exactly would be my next step? Where should I be looking?
Omg I didn't know z table was just like something I could look up lmao
I'm so dumb
I'm sorry
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
have you ever solved an equation like this before
ik quadrants and like
how to do it
i just need a refresher
and the way i remember doing it i keep getting it wrong
!show
Show your work, and if possible, explain where you are stuck.
, rotate
okay well one thing is
-0.444
you shouldn't be rounding probably
ik its -0.444 mbmb
and that is another thing
0.4444....44...?
that's still rounding if you leave it as 0.444
but if it is 0.444000..
then that's fine
anyways
,w -6.4/14.5
it is definitely rounded
why did you think that was -0.44 repeating?
the dot above the 4 😭
no clue why there is a dot
yeah same
but ignore it
that was why i was cvonfused okok
so try without rounding see if that works
i got
-26.19191972
so that = 5x+12
i got
x = -7.638383945
and then i add 180
for the 3rd quadrant
Find the other dot, it means that whole part from dot to dot repeats
what i do wrong?
however
it says there all answers
yeah ik that part with the period adding and all that
so i got
x = 29.856751
and then
bc its negative
180-29.856...
= 150.143...
and then surely thats one
of the answers
hmmm
but its apparently wrong
yes
since x is between 0 and 270
when u did arccos you shoudve figured out what 134.427004 degrees would be in the first quadrant
oh yes
may i know what is the correct answer
if i reveal the answer i gotta do a new question
ohhh
hold on
yeah fucking exactlt
idk how they get that
bc i feel like i do everything correctly
so 40.786 = (5x+14)
wtf do i do next bc thats where it seems to go all wrong
i normally take 14
subtract both side by 14
so i get 26.768 = 5x
no this is degrees
we have to keep
in degrees
radian is the other part
wait lemme try convert to radian
how tf i do that
wrong
i did this
before
and i forgot
and i cant find my fucking notes
for
the
subject
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How to solve it? I am probably missing some crucial thing
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Hi guys
Part b of the question is cut off
Part a seems fine but be careful with handwriting as this looks like $e^{\frac{2t}{2}}$, which isn’t the same as $\frac{e^{2t}}{2}$, which it appears you meant from the following work you did
@dull bear
Part c seems fine too, though you might want to show a tiny bit more working possibly
It said hour
Yes please, how can I do it more detailed
Is this better?
<@&286206848099549185>
Just showing [some more of] the manipulations you'd do to get to that final answer I think, though of course it depends on how much they're assigning to that question 
In that case seems fine to me 
And yep, better, less likely to be misinterpreted 
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Which one is wrong any why?
I'm certain the last 4 are right but I don't see how I'm wrong
actually that's fair, but it's disturbing for a second
absolute, convergent, divergent
Debatable but arguable
anyways
Why did you answer D ?
Well because I used the ratio test for it, to be fair I didn't get that far in so I stoped at a certain point and tried to find the limit as(i used x) approches infinity and found it was greater than 1
Though I tried all options and got them wrong so I assume one of the others is wrong
I see, how so
2^n / 5^2n
That decreases geometrically
Adding a factor 1/n in front only helps to make it convergent
Okay fair, but would that make it converge conditionally?
I need to invest in a new keyboard
did I need the help of the (-1)^n to assert convergence ?
Yes because without it, it decreases gemetrically like you said
Ah, so that's the condition
Hm, okay but I'm pretty certain ono the others, which one else could be wrong
No I didn't
I said it went to 0 remarkably fast
So I don't need it to alternate to converge
Okay
Wait, if decreading geometrically means you multiply by a constant to get a lower term
is that constant 2/25?
Wait no
and it decreases even faster because of the leading rational function
Oh okay
that should have been the result of your ratio test
Ah, okay
And because that is less than 1, it's absolutly convergent?
the ratio test can only see the obvious
it will never tell you something is conditionally convergent
that is far too obscure for it
Because L=1 is inconclusive?
For the test, you either have L>1 which is divergent or L<1 which is convergent
okay I see
Alright, I understand it now, I just need to try out the others again to see where i went wrong
@rose pike Has your question been resolved?
Well I have one more question
coming back to this, which one(the first one was resolved) is wrong
3
ty, redoing it rn
wait, isn't L=1/4
For 3
Cool, so it should be A
YES
cool, finished the worksheet, thank you very much
I'll do more practice to get the hang of both tests
thanks a bunch, I apologize for the trouble I caused
you caused no trouble
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What ways do you know how to find slope?
Do you know the slope formula?
Do you know the formula for it?
this
I'm talking about the exact formula
then no
Like $m = \frac{y_2-y_1}{x_2-x_1}$
Check 2 points where line crossing corner and use this formula between those points
CaptainNova22
i have no idea what that is sorry
That's the formula for slope
oh ok
In your class, if you were given a graph, how were you asked to find the slope?
Were you asked to count the rise over run or to use a formula?
https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:linear-equations-graphs/x2f8bb11595b61c86:slope/v/slope-of-a-line
This is the method you can use, just by counting the units between two points
@vast shale Has your question been resolved?
You have a line with some slope.
Find two places where the line crosses a + on the grid.
Count how many squares up and down you need to go to get from one point to the other in order to get the rise (in this example it is 1) and how many squares to the left or right you need to go to get the run (in this example it is 3).
If the line goes from the top right to the bottom left, the slope will be positive (like in this example), but if it goes from the top left to the bottom right, it will be negative.
The slope is the rise/run.
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How do you find the derivative of the function f(x) = 4x^3 + 2x + 7
do you know how to take derivatives in general?
I am trying to learn
do you know the power rule?
could you explain it?
oh boy
ok wait hang on
can you tell me what you DO know about derivatives? im struggling to get a footing here
Its about how the value changes
Do you know about finding the slope/gradient of a line connecting two points?
no
<enumitem>
For your information, you should know those two properties of the derivative:
\env{enumerate}[[1.]]{
\ii $\ds\bm[\bigg]{\dv x}{\m fx + \m gx} = \bm[\bigg]{\dv x}{\m fx} + \bm[\bigg]{\dv x}{\m gx}$
\ii $\ds\bm[\big]{\dv x}{x^n} = nx^{n-1}, \q n\in \R$
}
did your textbook or teacher show you how to work out derivatives? like did you see any derivative worked out at least once?
the one you came here with isnt terribly tough but for a complete beginner it is not trivial.
I did, but i understood nothing
This calculus video tutorial provides a basic introduction into derivatives for beginners. Here is a list of topics:
Derivatives - Limit Definition: https://www.youtube.com/watch?v=-aTLjoDT1GQ
Derivatives - Alternate Limit Definition: https://www.youtube.com/watch?v=6yzaEpacZkg
Derivatives - The Constant Rule: ...
watch this maybe
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Is my answer correct?
.close
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ok so first of all I know I over complicated things
but I was studying the subject of average and the tutor says the function for the average of two numbers is $$ \frac{a+b}{2}$$
ok i havent ise this channle for a long time so do I use math here again?
eitiel
oh here
so anyway, since this formula is the private case of $$\frac{a_1+a_2+a_3...+a_n}{n}$$
(bacause any two given numbers (0>a<b) i s like adding the whole numbers in between right?
eitiel
so if you write it as a function you can say that would be
never mind I'm an idiot
.close
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So I need to find the derivative of f(x)=Cos(x)+x and i’m stuck. My prof hasn’t taught us L’Hopitals and we haven’t learned how do use d/dx. We’ve been using the trig sum formulas and I know I have to use cosine sum formula but after i do and group like terms, I get stuck.
and also since i’m doing the top of the fraction I just left out the denominator.
so your question is just how to differentiate f(x)?
Yes. How can i get f'(x)
so the adition rule says d/dx f(x) + g(x) = f'(x) + g'(x)
and the derivative of cos(x) is -sin(x)
and the derivative of x is just 1
Okay so then it would be f'(x)=-sin(x)+1
yes
Okay that makes sense is there any hint you could give me in respect to my paper? I dont know hwta my next step would be im a bit stuck.
but that does make sense that it will be -sinx+1
what next step do you mean?
Like im not sure how to get there from where I am right now. You mentioned using d/dx but we havent learnt that yet.
ohhh okay sorry
and you would not take the derivative using limits
we've just started this unit so im still learning
you generally use the derivative rules
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this proof should be super easy
but im not sure if im doing it correct
i mean the tldr is that
if you multiply 2 diagonal matricies you get a diagonal matrix
and multiplication of components is associative
is that literlaly i
it
yeah just expand both multiplications and then like
like make 2 abitrary vectors with n and m on the diagonal respectively
and then show that like
idk m x n is the same as n x m
you will get something that resolves into axioms of normal multiplication
because of associativity
this sentence makes no sense to me sorry
like this
yes you can multiply them out from both ways
then you can show they would be equal
oh like show M x N and N x M
yes
okay i just had this beautiful moment in math
you use part a in part b
thats so cool
does this look ok?
I would maybe also suggest stating that the fact that there are the n independent eigenvectors implies that A and B are diagonalisable but otherwise 
Looks okay except the fact that you’ve grouped P inv * P = 1, since P * P inv = 1 as matrix multiplication is NOT commutative
Probably someone whose seen this question for longer has better context but that’s something I just noticed
However the fact that P^{-1} is the inverse of P, that part is still fine (it's usually shown elsewhere that both P^{-1}P and PP^{-1} are the identity matrix)
Matrix multiplication is associative but not commutative, consider that as a clue
wait i need to show this?
It's likely that either the definition of an invertible matrix $A$ is such that there's another matrix $B$ such that $AB = BA = I$, or that when you create the inverse matrix, you show that either way you multiply them, you get the identity matrix back
@dull bear
yes this is what i origanlly thought which is why i just moved things around like that
Yea that's all fine to do when it comes to a matrix and its inverse 
is it okay if i ask another question?
Sure 
what exactly is lambda and X in this context
is X a matrix containing all the eigenvectors
I’m not quite sure, do they not define it somewhere?
I would think so, but don’t quote me on that one!
I’d guess the other one is the diagonal matrix of eigenvalues 
i dont know if lambda always represents the same thing
this makes sense i think...
A=PDP−1 right
D is the diagonal matrix of values? P is the matrix of eigenvectors?
Yep, if you have P and D as you’ve stated
cool
did i make a mistake here?
Take a look at the last line of your calculation
Up until there everything seems fine
here?
i think its lambda^2 - 0.7 lambda -0.42
No
What’s 0.06-0.36
Oui
so i guess the diagonal matrix of eigen values is
[1 0, 0 -0.3]
i think i am stuck again
.close
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hilpeleepl