#help-17

1 messages · Page 108 of 1

knotty kestrel
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yea that too

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usually thats how u show it mathematically

misty surge
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ah okay thanks

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daring kiln
vocal sleetBOT
daring kiln
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In the exercise 6.9

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I tried resolving it in 2 different ways shown in the orange color

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In the second tried I used change of variables

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I know the right answer is 3) a= being any number you want and b<0

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But idk if my way of solving it is right

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dusty siren
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how to do chi square?

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@dusty siren Has your question been resolved?

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tawny shoal
vocal sleetBOT
uncut storm
tawny shoal
# tawny shoal

i need to basically do the opposite of factoring and find out what addition of two fractions made this. I understand it for the most part, but the answer has a C in it and im really confused where the C came from

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@tawny shoal Has your question been resolved?

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@tawny shoal Has your question been resolved?

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slate plover
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can someone walk me thru this

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slate plover
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vast shale
vocal sleetBOT
drifting jackal
# vast shale

What exactly are you stuck on? As I mentioned before, surface area is just the sum of the areas of the faces

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So you need to find the area of each face, then add them

vast shale
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I’m thick tho

drifting jackal
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Can you find the area of each side?

vast shale
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108

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48

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144

drifting jackal
vast shale
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9x6

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x2

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300m

drifting jackal
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It's a triangular prism

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So the top face is the same shape as the one on the bottom, the hidden one

vast shale
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Exactly

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That’s what I did

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9x6

drifting jackal
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The top face I'm referring to is this

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That's a triangle

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The bottom face is the same, a triangle

indigo cove
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the triangle formula is 1/2b*h

vast shale
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9x6

indigo cove
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wait sorry i cant even see the picture correctly my eyes are a bit blury 😭

drifting jackal
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It's a triangle

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The hieght is 5, base is 11

vast shale
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22.5

drifting jackal
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The 9 and 6 relate to these sides

drifting jackal
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Then you need the area of the other sides

vast shale
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45

drifting jackal
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Where is 45 from?

vast shale
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22.5 x two

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Tek triangles

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Two

drifting jackal
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Also that is not the area of the triangle btw

vast shale
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I dont know then

drifting jackal
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Do you know the formula for area of a triangle?

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You know the height and the base

drifting jackal
vast shale
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5 x11

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Then half it

drifting jackal
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Yes and that equals?

vast shale
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27.5

drifting jackal
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Yes that's better

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Continue the rest of the steps I provided

vast shale
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X2

drifting jackal
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Find the area of the rest of the faces then sum them up

vast shale
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55

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48

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72 x2

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144

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247

drifting jackal
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Why did you multiply by 2?

vast shale
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There are two

drifting jackal
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Of the 9 x 8 side?

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Because there's only one

vast shale
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263

drifting jackal
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Yes that's it

vast shale
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Fonally

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Tjank you

drifting jackal
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You just need to find the areas of each face then add them up, that's it

vocal sleetBOT
#

@vast shale Has your question been resolved?

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tribal pond
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sum and difference

vocal sleetBOT
tribal pond
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im not sure where to start and/or how my answer is supposed to come out

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i know im supposed to make triangles and use x^2+y^2=r^2

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if im to do cosa=4/5 with a in QIV then where do i start

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is theta the origin on the graph?

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if im supposed to find the missing sides then subtract the coinciding answers, then do i need to use a ton of math here?

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because wouldn't my answer lie on 0 if the remaining sides equal to 3 and -3 (just a guess)

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or am i completely off track

vocal sleetBOT
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@tribal pond Has your question been resolved?

tribal pond
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by far I have learned that the DMV moves faster than this train

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in the meantime, I've been doing other things but i'm still waiting on this

wheat imp
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took a crack at it see if this works

tribal pond
wheat imp
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i can get it in a different format one sec

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took a picture from my phone is only problem

tribal pond
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ah

wheat imp
tribal pond
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so am i taking cosine

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and turning the values into triangles

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then with the missing side values i use those and throw it into a sine function?

wheat imp
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basically the formula you need is sin(a-b) = sinacosb - cosasinb

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so you need to use the cos you are given

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to find sin

tribal pond
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so one quick question

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I have a sum and difference thingy

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if you have any knowledge on this please do tell

wheat imp
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sorry mate i know i learned this at one point but im completely blanking

tribal pond
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it's like the secrets of the pentagon to me

wheat imp
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i'll give it a shot but someone may need to tag in lol

tribal pond
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ive been tryin

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that bottom part needs to be -sinx so i can do an odd/even thing to it and then quotient it to make it cotx

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that part might not make any sense

wheat imp
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sorry give me a sec

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okay figured it out

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so basically i figured out the value of both cos(pi + x) and cos(3pi/2 -x)

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cos(pi + x) is -cosx (you found this)

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for cos(3pi/2 - x):

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use the formula cos(A + B) = cos(a)cos(b) - sin(a)sin(b)

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subbing 3pi/2 in for a

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and -x for b

tribal pond
wheat imp
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yeah so at that stage its pretty simple

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you literally just calculate what cos(3pi/2) is and what sin(3pi/2) is

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and multiply

tribal pond
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then simple stuff is always too complex for me

wheat imp
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its what always trips me up as well

tribal pond
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this all must equal cotx

wheat imp
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yeah trust me on this

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cos(3pi/2) = 0

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sin(3pi/2) = -1

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so the bottom simplifies to -sinx

tribal pond
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ooooooh

wheat imp
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and then you just do what you said earlier

tribal pond
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i got another one

wheat imp
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good job : )

tribal pond
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basically same thing

wheat imp
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go for it

tribal pond
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we did half the work equally

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now it's flipped but im gonna see

wheat imp
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i feel like this is basically the same lol

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if u just use sin(a+b) and sin(a-b) formula and follow that through you should get there in the end

tribal pond
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true true

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finished it

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last one is going to be tricky

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nevermind

wheat imp
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do you still need help with this?

tribal pond
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yah

wheat imp
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just to make sure csc(x) is 1/sinx right?

tribal pond
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yes

wheat imp
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never seen it written like that

tribal pond
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actually wait

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I did that one

wheat imp
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lol

tribal pond
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Im wrong here and i know it

wheat imp
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okay figured it out

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so your first step is correct

tribal pond
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okie

wheat imp
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next you need to get the number on the bottom the same so you can add them to make one fraction

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so you end up with sin^2x/sinxcosx + cos^x/sinxcosx

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which makes sin^2x + cos^2x/sinxcosx

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do you think you can figure it out from there ?

tribal pond
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do i use sum and difference?

wheat imp
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nope

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you need to use one of the pythagorean identities

tribal pond
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so cosx = sinx+1 and sinx = cosx+1

wheat imp
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if i split it up better it may become clearer

tribal pond
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my meds are wearing off

wheat imp
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(sin^2x + cos^2x)

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/ sinxcosx

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i can make it a little clearer if need be

tribal pond
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im becoming more defocused by the minute but im trying

wheat imp
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its alright take your time

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it may help to think about it like this

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you are trying to find cosecx * secx

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this is equal to (1/sinx)(1/cosx)

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which multiplies to 1/sinxcosx

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so we need to go from (sin^2x + cos^2x) / (sinxcosx)

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to 1 / (sinxcosx)

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what rule can we use

tribal pond
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ive just used quotient so then i have to use pythagorean

wheat imp
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thats correct

tribal pond
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but how do i apply it to the two separate fractions?

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do i make them all applied to pythagorean or just the top

wheat imp
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okay basically

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the theorem you need to use is sin^2x + cos^2x = 1

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i might write out the question to make it clearer

tribal pond
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so

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sinx/cosx + cosx/sinx

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sinx+cosx=1

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or no

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because im getting wrapped around this part

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how do i get sin^2x from sinx

wheat imp
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give me one sec im just writing it out

tribal pond
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oh hey wait

wheat imp
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thats right

tribal pond
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oh good lord

wheat imp
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haha i think someone else might need to handle this i gotta go

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good luck though

tribal pond
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thamk

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screw you math gods

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i spoke too soon

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i need this

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^this must equal "siny"

vocal sleetBOT
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@tribal pond Has your question been resolved?

vocal sleetBOT
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icy cedar
#

I want to know what I'm doing wrong/how to work out the total time

pale perch
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7.25 isnt a length of time

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oh wait

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i see i see

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its the .25

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25 minutes isnt .25 of an hour

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.25 of an hour is 15 minutes

icy cedar
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So then would I say that the total time is 7.40?

pale perch
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,calc 25/60

twin meteorBOT
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Result:

0.41666666666667
pale perch
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ish

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id just use the exact number

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which is 7+5/12

icy cedar
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Do I calculate what that is and then put that in?

pale perch
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if youre using a calculator, you could just type (600)/(7+5/12)

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unless your calculator can store answers from the previous line to use, in which case you could, sure

icy cedar
pale perch
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,calc 600/(7+5/12)

twin meteorBOT
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Result:

80.898876404494
pale perch
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seems so

icy cedar
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Don't I have to round it out?

pale perch
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3 significant figures seems safe

icy cedar
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Alright, so that means the total time is 80.8 right?

pale perch
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.9

icy cedar
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Oh! Okay mb-

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so then if 600 divided by 80.9 is 7.416563658838072, thats the average speed?

pale perch
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the 80.9 is the average speed

icy cedar
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Wait so whats the total time???

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Cause I just asked if 80.9 was the total time and you said yes

pale perch
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the total time was the 7+5/12

icy cedar
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So then the total time is 7.41666666667 so what would I round that to?

pale perch
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3 is also fine again

icy cedar
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So I round it to 7.41?

pale perch
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.42

icy cedar
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Okay so dividing the 600 by the 7.42, I get 80.86253369272237

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rounding it off would make it 80.9?

pale perch
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i mean yeah, but why would you use a rounded value in your calculations when you have the exact value

icy cedar
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I figured it would be too long, wouldn't it?

pale perch
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why? the exact value is literally (7+5/12) thats not that long to write

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using rounded values will screw up your answers in the future if you make that a habit

icy cedar
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Wait okay okay okay, so what do I put as the Average speed? Exactly 80.86253369272237?

pale perch
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no you can round when you have your answer, i just mean dont round mid working

pastel herald
icy cedar
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I apologise I believe we were done and that was the answer

pale perch
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the time in hours from 11:50 am to 7:15pm

pale perch
pastel herald
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yeah but why? i counted the hours and got 7.416 hours and i used that value

pale perch
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when you get to questions that are longer in the future, if you use rounded values during your working theres a possibility for huge discrepancy in your final answers

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so its generally good practice to just keep things exact until youre done

pastel herald
pale perch
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because the exact time is 7.416666666666666......

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not just 7.416

pastel herald
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i know. my question is why did you write time by meand of 7+5/12

pale perch
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7 is the number of whole hours, 5/12 represents the additional 25 minutes

pastel herald
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i first counted minutes and divided by 6o to get th time

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how 5/12 is 25 minutes? whats does it refer to?

pale perch
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,calc 25/60

twin meteorBOT
#

Result:

0.41666666666667
pale perch
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25 minutes in hours

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25/60

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5/12

pastel herald
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ohh ok so you make 25/60 smaller by fractions

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did not know tata

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that

pale perch
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ah i see, think i may have understood your question, my bad

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but yeah, its just the 25/60

icy cedar
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Sooo.. Where do I go from here??

pale perch
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nowhere, youre done

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80.9km/h

icy cedar
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So this is the right answer?

pale perch
icy cedar
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Pretty much? So that means it isnt?

pale perch
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its just my way of saying theres not much else you could be expected to do

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thats the answer

icy cedar
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Alright, tyvm

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Could you maybe confirm one more thing for me while I'm here?

pale perch
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sure

icy cedar
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The answer would be census, right?

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I just want to double check

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Then I'll be out of your hair

pale perch
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statisticsded

icy cedar
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I assume you're not good at them? Thats totally fine-

pale perch
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just been a long time

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one minute

icy cedar
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Alrighty, please, no rush

pale perch
#

seems more like a sample
if the population is the class
and she is surveying only the year 9's in said class then thats a sample of a population
(idk why there would be more than one year group in a class though)

icy cedar
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Hmm-

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Alrighty! Thank you for that, I have no further questions

pale perch
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no worries

icy cedar
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Have a good one

pale perch
#

you too

icy cedar
#

.close

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fallen sandal
vocal sleetBOT
fallen sandal
#

Is this correct fr

#

I got it right

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.close

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fallen sandal
vocal sleetBOT
fallen sandal
#

I'm thinking like

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A

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Fr

vast shale
fallen sandal
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idrk

vast shale
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WHY

fallen sandal
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😭 😭 😭

vast shale
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WHY DID YOU KILL THAT WOMAN

fallen sandal
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Cuz the n and n prime look kinda right

vast shale
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*slams desk* FACE THE REALITY

vast shale
fallen sandal
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Idk

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It just looks

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Correct

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I think it wouldn't shifted down

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If it were something else

vast shale
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Should've called them N and M and the right point L, that would've been an easy question 💯

fallen sandal
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Wait does it dilate inward or outward

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Idk how it works I forgor

vast shale
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Well N' is bigger than N

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So...

fallen sandal
#

Like from a pont

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Point

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I mean

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Away

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Or towards

vast shale
#

depends

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It can be either

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Technically not doing anything is also a dilation

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But I digress

fallen sandal
#

Wahr

vast shale
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It's, like... You dilate, but the amount you dilate is nothing

fallen sandal
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O k

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Anyways

vast shale
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It's not relevant just forget about it

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"dilation" is actually often used to clarify that it can either make things bigger or smaller

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But in this case N' is bigger than N

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So it must be outward

fallen sandal
#

Oh

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So is it C

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Then

vast shale
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Why C?

fallen sandal
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Cuz like

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It would move away from it

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And get bigger

vast shale
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That's the gist of it, yeah

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Looks like A, B, and D have been strategically placed to confuse

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Interesting

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@fallen sandal Do you get the idea now?

fallen sandal
#

Soo it's C

vast shale
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Dilation just scales everything in or out (or not at all, which technically counts) from a point without any change in shapes or any rotation

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So yeah, C

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You can figure out the point by drawing lines like I did

fallen sandal
#

Oki

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.close

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mellow geode
#

hello, what's the least upper bound of $\frac{x+y}{1+xy}$ when x and y in $]-1, 1[$?

twin meteorBOT
#

lilisworld

dull bear
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Does it have a finite one? catThink

mellow geode
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no idea

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probably?

dull bear
#

Well just looking at it, seems like the closer you choose x to 1 and the closer y is to -1 that you'd get something that just grows, no?

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Though I may be missing something

vast shale
#

i also might be wrong but i guess it's 1 cause it implies inequality (x+y)/(1+xy) <= 1 or (1-x)(1-y)>=0 which is obvious from x, y <= 1

dull bear
twin pumice
# mellow geode ?

Consider what would happen if you pick x and y to be as close to 1 as possible

mellow geode
mellow geode
vast shale
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mellow geode
#

.reopen

vocal sleetBOT
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mellow geode
#

is that really how i show that the sup is 1?

#

<@&286206848099549185>

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.close

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vast shale
#

can someone walk me through the algebra for this step please? Thank you!

ancient knoll
#

$(n^2+n-2)=((n^2+n)-2)$

twin meteorBOT
vast shale
#

oh

#

my lord

#

than you

#

i get it

#

.close

vocal sleetBOT
#
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velvet cove
#

is $\frac{\infty}{\infty-\infty}$ an eligible form to use lhopitals rule

twin meteorBOT
vocal sleetBOT
#

@velvet cove Has your question been resolved?

velvet cove
#

@spice sun

flat whale
#

!original

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

vocal sleetBOT
#

@velvet cove Has your question been resolved?

vocal sleetBOT
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spiral frost
vocal sleetBOT
spiral frost
#

I honestly have no clue; if someone could help me going through these four problems I would be super appreciative!

hoary blaze
#

do you see the pattern of the function

#

so the period would be the distance between the same points on two successive "patterns"

vocal sleetBOT
#

@spiral frost Has your question been resolved?

vocal sleetBOT
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golden dagger
#

Ask

vocal sleetBOT
golden dagger
#

can someone help me with these math problems

vocal sleetBOT
#

@golden dagger Has your question been resolved?

karmic crane
#

Do you know what a gcf is

golden dagger
#

Greatest common factor

karmic crane
#

Do you know how to do that for Q24

golden dagger
#

Would the Gcf be 12?

karmic crane
#

Can you divide 28 by 12 without remainder

golden dagger
#

No

karmic crane
#

So it can’t be 12

golden dagger
#

2?

karmic crane
#

Yeah 2 sounds good

golden dagger
#

Alright then what

karmic crane
#

Actually 4 is the hcf

golden dagger
#

Alright

karmic crane
#

It becomes 4(3x^2+7x-6)

golden dagger
#

Ok

karmic crane
#

Now do you know how to factorise that quadratic

golden dagger
#

No

karmic crane
#

Multiply 3 by -6, now find numbers that multiply to give -18 and add to give 7

golden dagger
#

Ok

karmic crane
#

What are they

golden dagger
#

3x-6 like u said?

karmic crane
#

What do you get when you sum them though

golden dagger
#

-18

karmic crane
#

Sum as in addition

golden dagger
#

How do you sum them ?

karmic crane
#

3 + -6

golden dagger
#

Do u add 18 and 7?

#

-3

karmic crane
#

So it can’t be those two because they don’t add up to 7

golden dagger
#

So can it be any numbers?

karmic crane
#

Yes as long as their product is -18 and their sum is 7

golden dagger
#

4x-8?

karmic crane
#

4 x -8 is -32 and they add up to -4 so both the conditions are not met

#

List out all the factors of 18, that should help

#

1,2,3,6,9,18

golden dagger
#

Ok

#

9 and -2

karmic crane
#

Yeah

#

So now

golden dagger
#

Ok now what

karmic crane
#

Rewrite the first and last terms like this:

#

3x^2 -6

#

And inbeteeen you put the two numbers you found multiplied by x

#

3x^2+9x-2x-6

#

Now group them:

golden dagger
#

So is it 3x^2+9x and -2x+6

karmic crane
#

Yeah

#

Now find gcf of each group

#

Or basically factorise each group

golden dagger
#

Ok

#

So can there be left overs?

#

Is the factor 2

karmic crane
#

There will be one for each group

golden dagger
#

So I think for -2x+6 the factor is 2 and for the other is 1?

karmic crane
#

Always take out the negative, so it would be -2 for that one, but for the other group it’s not 1

golden dagger
#

Ok

#

3?

karmic crane
#

Close

#

it’s 3x

golden dagger
#

Oh

karmic crane
#

So now

#

For each group, put the left over stuff in a bracket next to it like:

golden dagger
#

Would it be -2x? For the factor

karmic crane
#

3x(x+3)-2(x+3)

#

This becomes

#

(3x-2)(x+3)

#

And don’t forget toe 4 from before

#

4(3x-2)(x+3)

golden dagger
#

So u bring back the gcf?

#

What are the leftover?

vocal sleetBOT
#

@golden dagger Has your question been resolved?

#
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vocal sleetBOT
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atomic zephyr
#

I was wondering how this question (attached below, #8) was solved, given all the information provided. Mainly, my brain is breaking up on the explanation "The area beyond z for Zx=-.83 is .2033". How is that figured out? What set of numbers can you use to figure this out? My mind is shattered I have been staring at this for like an hour now.

atomic zephyr
#

Sorry for the low quality pictures.

#

Can repost the pics to be more clearer if needed

#

<@&286206848099549185>

vocal sleetBOT
#

@atomic zephyr Has your question been resolved?

vocal sleetBOT
#
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atomic zephyr
#

.reopen

vocal sleetBOT
#

vocal sleetBOT
#

@atomic zephyr Has your question been resolved?

proven garden
#

for z score you have a standardized normal distribution

#

Using integration gives area, or you can use a z table instead

atomic zephyr
proven garden
#

?

#

z table tells you the area given a z value

#

table B is just a table of z values, it doesn't tell you the area

atomic zephyr
#

Omg I didn't know z table was just like something I could look up lmao

#

I'm so dumb

#

I'm sorry

vocal sleetBOT
#

@atomic zephyr Has your question been resolved?

#
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safe cove
vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
safe cove
#

1

thin vale
#

have you ever solved an equation like this before

safe cove
#

ik quadrants and like

#

how to do it

#

i just need a refresher

#

and the way i remember doing it i keep getting it wrong

thin vale
#

!show

vocal sleetBOT
#

Show your work, and if possible, explain where you are stuck.

safe cove
#

alr lemme grab my phone

thin vale
#

, rotate

twin meteorBOT
safe cove
#

and then ik to do sin-1(0.444)

#

= 5x + 12

#

but i keep getting it wrong apparently

thin vale
#

okay well one thing is

safe cove
#

-0.444

thin vale
#

you shouldn't be rounding probably

safe cove
#

ik its -0.444 mbmb

thin vale
#

and that is another thing

safe cove
#

its 0.444 recuring

thin vale
#

0.4444....44...?

#

that's still rounding if you leave it as 0.444

#

but if it is 0.444000..

#

then that's fine

#

anyways

safe cove
#

wait lemme show u my calculator

#

bc its weird

thin vale
#

,w -6.4/14.5

thin vale
#

it is definitely rounded

safe cove
thin vale
#

why did you think that was -0.44 repeating?

safe cove
#

the dot above the 4 😭

thin vale
#

no clue why there is a dot

safe cove
#

yeah same

thin vale
#

but ignore it

safe cove
#

that was why i was cvonfused okok

thin vale
#

so try without rounding see if that works

safe cove
#

i got

#

-26.19191972

#

so that = 5x+12

#

i got

#

x = -7.638383945

#

and then i add 180

#

for the 3rd quadrant

worthy citrus
#

Find the other dot, it means that whole part from dot to dot repeats

safe cove
#

okay right i got it wrong

#

where did i go wrong tho istg

#

hello?

safe cove
waxen cobalt
#

hmmmm

#

hold on

safe cove
#

new question

#

ran outta time

#

i got

#

cos-1(-0.7)

#

=

#

134.427004

waxen cobalt
#

correct

#

however

safe cove
#

however

waxen cobalt
#

it says there all answers

safe cove
#

yeah ik that part with the period adding and all that

#

so i got

#

x = 29.856751

#

and then

#

bc its negative

#

180-29.856...

#

= 150.143...

#

and then surely thats one

#

of the answers

waxen cobalt
#

hmmm

safe cove
#

but its apparently wrong

waxen cobalt
#

yes

safe cove
#

where tho

#

where do i go wrong

waxen cobalt
#

since x is between 0 and 270

safe cove
#

yeah

#

i got that tho

waxen cobalt
#

when u did arccos you shoudve figured out what 134.427004 degrees would be in the first quadrant

safe cove
#

but its negative

#

bc y = -0.7

#

so its 3rd

#

and

#

4th

#

quadrant

waxen cobalt
#

oh yes

safe cove
#

so i did

#

180 - x

#

or do i do

#

180 -134

waxen cobalt
#

may i know what is the correct answer

safe cove
#

if i reveal the answer i gotta do a new question

waxen cobalt
#

ohhh

safe cove
waxen cobalt
#

hold on

safe cove
#

i did it idm restarting

#

i just dk

#

where the fuck

#

you get those numbers from

waxen cobalt
safe cove
#

yeah fucking exactlt

#

idk how they get that

#

bc i feel like i do everything correctly

waxen cobalt
#

-10.95456094

#

to find its corresponding angle, we add 360 degrees

safe cove
waxen cobalt
#

bitch

#

restriction

safe cove
#

i did sin-1(0.653)

#

got

#

40.768

waxen cobalt
#

cool

#

is it correct

safe cove
#

so 40.786 = (5x+14)

#

wtf do i do next bc thats where it seems to go all wrong

#

i normally take 14

waxen cobalt
#

subtract both side by 14

safe cove
#

so i get 26.768 = 5x

waxen cobalt
#

sounds correct

#

then divide by 5

safe cove
#

5.3536

#

AND ITS WRONG

waxen cobalt
#

no

#

girl

#

should be in radian

#

convert it

#

its in degrees

safe cove
#

no this is degrees

#

we have to keep

#

in degrees

#

radian is the other part

#

wait lemme try convert to radian

#

how tf i do that

waxen cobalt
#

0.0934379468

#

try it

safe cove
#

wrong

waxen cobalt
#

bitch

#

show the correct answer

safe cove
#

i did this

#

before

#

and i forgot

#

and i cant find my fucking notes

#

for

#

the

#

subject

#

.close

vocal sleetBOT
#
Channel closed

Closed by @safe cove

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#
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wet tendon
#

How to solve it? I am probably missing some crucial thing

wet tendon
#

Nvm I got it

#

.close

vocal sleetBOT
#
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sonic hatch
#

Hi guys

vocal sleetBOT
sonic hatch
#

Can someone please check my work

dull bear
#

Part b of the question is cut off

#

Part a seems fine but be careful with handwriting as this looks like $e^{\frac{2t}{2}}$, which isn’t the same as $\frac{e^{2t}}{2}$, which it appears you meant from the following work you did

twin meteorBOT
#

@dull bear

dull bear
#

Part c seems fine too, though you might want to show a tiny bit more working possibly

sonic hatch
sonic hatch
#

Is this better?

#

<@&286206848099549185>

dull bear
dull bear
dull bear
sonic hatch
#

I have another question to check

vocal sleetBOT
#

@sonic hatch Has your question been resolved?

vocal sleetBOT
#
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rose pike
#

Which one is wrong any why?

vocal sleetBOT
rose pike
#

I'm certain the last 4 are right but I don't see how I'm wrong

wraith venture
#

who makes the choices A, C and D

#

so why does 1) diverge ?

wraith venture
rose pike
#

I'm use to A B C

wraith venture
wraith venture
rose pike
# wraith venture anyways Why did you answer D ?

Well because I used the ratio test for it, to be fair I didn't get that far in so I stoped at a certain point and tried to find the limit as(i used x) approches infinity and found it was greater than 1

#

Though I tried all options and got them wrong so I assume one of the others is wrong

wraith venture
#

indeed

#

but 1 is also wrong

rose pike
#

I see, how so

wraith venture
rose pike
#

Okay fair, but would that make it converge conditionally?

#

I need to invest in a new keyboard

wraith venture
rose pike
#

Yes because without it, it decreases gemetrically like you said

#

Ah, so that's the condition

#

Hm, okay but I'm pretty certain ono the others, which one else could be wrong

wraith venture
wraith venture
rose pike
#

Okay

#

Wait, if decreading geometrically means you multiply by a constant to get a lower term

#

is that constant 2/25?

#

Wait no

wraith venture
#

and it decreases even faster because of the leading rational function

rose pike
#

Oh okay

wraith venture
rose pike
wraith venture
#

the ratio test can only see the obvious

#

it will never tell you something is conditionally convergent

#

that is far too obscure for it

rose pike
#

Because L=1 is inconclusive?

#

For the test, you either have L>1 which is divergent or L<1 which is convergent

#

okay I see

#

Alright, I understand it now, I just need to try out the others again to see where i went wrong

vocal sleetBOT
#

@rose pike Has your question been resolved?

rose pike
#

Well I have one more question

#

coming back to this, which one(the first one was resolved) is wrong

wraith venture
#

3

rose pike
#

ty, redoing it rn

#

wait, isn't L=1/4

#

For 3

#

Cool, so it should be A

#

YES

#

cool, finished the worksheet, thank you very much

#

I'll do more practice to get the hang of both tests

#

thanks a bunch, I apologize for the trouble I caused

wraith venture
#

you caused no trouble

rose pike
#

Alright man, thanks again, I'll close the channel now

#

.close

vocal sleetBOT
#
Channel closed

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vast shale
vocal sleetBOT
vocal sleetBOT
# vast shale

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

drifting jackal
#

Do you know the slope formula?

vast shale
#

rise/run

#

but i dont know how to do that with the points already graphed

drifting jackal
vast shale
drifting jackal
#

I'm talking about the exact formula

vast shale
#

then no

drifting jackal
#

Like $m = \frac{y_2-y_1}{x_2-x_1}$

vast shale
#

Check 2 points where line crossing corner and use this formula between those points

twin meteorBOT
#

CaptainNova22

vast shale
#

i have no idea what that is sorry

drifting jackal
#

That's the formula for slope

vast shale
#

oh ok

feral oxide
drifting jackal
vast shale
#

i think looking visually will help to understand the formula for beginners

drifting jackal
#

Were you asked to count the rise over run or to use a formula?

drifting jackal
# vast shale i have no idea what that is sorry
Khan Academy

Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a free, world-class education for anyone, anywhere.

vocal sleetBOT
#

@vast shale Has your question been resolved?

tall shuttle
#

You have a line with some slope.

#

Find two places where the line crosses a + on the grid.

#

Count how many squares up and down you need to go to get from one point to the other in order to get the rise (in this example it is 1) and how many squares to the left or right you need to go to get the run (in this example it is 3).

#

If the line goes from the top right to the bottom left, the slope will be positive (like in this example), but if it goes from the top left to the bottom right, it will be negative.

#

The slope is the rise/run.

vocal sleetBOT
#
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swift surge
#

How do you find the derivative of the function f(x) = 4x^3 + 2x + 7

paper depot
#

do you know how to take derivatives in general?

swift surge
#

I am trying to learn

paper depot
#

do you know the power rule?

swift surge
#

could you explain it?

paper depot
#

so that's a no...

#

ok, do you know that the derivative of x^n is n x^(n-1)?

swift surge
#

damm

#

no i did not know

#

how did you get that answer?

paper depot
#

oh boy

#

ok wait hang on

#

can you tell me what you DO know about derivatives? im struggling to get a footing here

swift surge
#

Its about how the value changes

lucid bane
#

Do you know about finding the slope/gradient of a line connecting two points?

vast shale
#

<enumitem>
For your information, you should know those two properties of the derivative:
\env{enumerate}[[1.]]{
\ii $\ds\bm[\bigg]{\dv x}{\m fx + \m gx} = \bm[\bigg]{\dv x}{\m fx} + \bm[\bigg]{\dv x}{\m gx}$
\ii $\ds\bm[\big]{\dv x}{x^n} = nx^{n-1}, \q n\in \R$
}

twin meteorBOT
paper depot
#

did your textbook or teacher show you how to work out derivatives? like did you see any derivative worked out at least once?

#

the one you came here with isnt terribly tough but for a complete beginner it is not trivial.

swift surge
paper depot
#

watch this maybe

swift surge
#

Alraight.

#

.close

vocal sleetBOT
#
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vestal comet
#

Is my answer correct?

vocal sleetBOT
vestal comet
#

.close

vocal sleetBOT
#
Channel closed

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normal badge
#

ok so first of all I know I over complicated things

normal badge
#

but I was studying the subject of average and the tutor says the function for the average of two numbers is $$ \frac{a+b}{2}$$

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ok i havent ise this channle for a long time so do I use math here again?

twin meteorBOT
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eitiel

normal badge
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oh here

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so anyway, since this formula is the private case of $$\frac{a_1+a_2+a_3...+a_n}{n}$$
(bacause any two given numbers (0>a<b) i s like adding the whole numbers in between right?

twin meteorBOT
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eitiel

normal badge
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so if you write it as a function you can say that would be

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never mind I'm an idiot

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.close

vocal sleetBOT
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fresh jolt
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So I need to find the derivative of f(x)=Cos(x)+x and i’m stuck. My prof hasn’t taught us L’Hopitals and we haven’t learned how do use d/dx. We’ve been using the trig sum formulas and I know I have to use cosine sum formula but after i do and group like terms, I get stuck.

fresh jolt
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and also since i’m doing the top of the fraction I just left out the denominator.

true estuary
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so your question is just how to differentiate f(x)?

fresh jolt
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Yes. How can i get f'(x)

true estuary
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so the adition rule says d/dx f(x) + g(x) = f'(x) + g'(x)

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and the derivative of cos(x) is -sin(x)

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and the derivative of x is just 1

fresh jolt
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Okay so then it would be f'(x)=-sin(x)+1

true estuary
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yes

fresh jolt
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Okay that makes sense is there any hint you could give me in respect to my paper? I dont know hwta my next step would be im a bit stuck.

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but that does make sense that it will be -sinx+1

fresh jolt
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Like im not sure how to get there from where I am right now. You mentioned using d/dx but we havent learnt that yet.

true estuary
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d/dx is just another notation for the derivative

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d/dx f(x) = f'(x)

fresh jolt
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ohhh okay sorry

true estuary
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and you would not take the derivative using limits

fresh jolt
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we've just started this unit so im still learning

true estuary
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you generally use the derivative rules

fresh jolt
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okay ui get uit.

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Thank you I appreciate it.

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old niche
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this proof should be super easy

vocal sleetBOT
old niche
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but im not sure if im doing it correct

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i mean the tldr is that

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if you multiply 2 diagonal matricies you get a diagonal matrix

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and multiplication of components is associative

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is that literlaly i

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it

vast shale
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yeah just expand both multiplications and then like

old niche
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like make 2 abitrary vectors with n and m on the diagonal respectively

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and then show that like

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idk m x n is the same as n x m

vast shale
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you will get something that resolves into axioms of normal multiplication

old niche
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because of associativity

vast shale
old niche
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like this

vast shale
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then you can show they would be equal

old niche
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oh like show M x N and N x M

vast shale
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yes

old niche
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okay i just had this beautiful moment in math

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you use part a in part b

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thats so cool

vast shale
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did you get enlightened

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lmaoo

old niche
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this has never happened before

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eveer

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i dont like math like that

vast shale
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@old niche

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did u get the answer tho

old niche
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i think

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give me a second

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trying to finish proof

old niche
vast shale
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good job

dull bear
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I would maybe also suggest stating that the fact that there are the n independent eigenvectors implies that A and B are diagonalisable but otherwise SCgoodjob2

noble lily
# old niche

Looks okay except the fact that you’ve grouped P inv * P = 1, since P * P inv = 1 as matrix multiplication is NOT commutative

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Probably someone whose seen this question for longer has better context but that’s something I just noticed

old niche
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hmm

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how else do you cancel out tho

dull bear
noble lily
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Matrix multiplication is associative but not commutative, consider that as a clue

dull bear
# old niche wait i need to show this?

It's likely that either the definition of an invertible matrix $A$ is such that there's another matrix $B$ such that $AB = BA = I$, or that when you create the inverse matrix, you show that either way you multiply them, you get the identity matrix back

twin meteorBOT
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@dull bear

old niche
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yes this is what i origanlly thought which is why i just moved things around like that

dull bear
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Yea that's all fine to do when it comes to a matrix and its inverse catThumbsUp

old niche
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is it okay if i ask another question?

dull bear
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Sure OathLove

old niche
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what exactly is lambda and X in this context

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is X a matrix containing all the eigenvectors

dull bear
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I’m not quite sure, do they not define it somewhere?

dull bear
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I’d guess the other one is the diagonal matrix of eigenvalues catThink

old niche
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i dont know if lambda always represents the same thing

old niche
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A=PDP−1 right

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D is the diagonal matrix of values? P is the matrix of eigenvectors?

dull bear
old niche
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sorry diagonal matrix of eigenvalues

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not of values

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im going to start trying this

noble lily
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cool

old niche
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uh im kinda worried

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idt you can factor what i got

old niche
noble lily
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Take a look at the last line of your calculation

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Up until there everything seems fine

old niche
noble lily
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Yes

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Actually nvm

old niche
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oh shoot 0.6 x 0.1

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is 0.06

noble lily
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Its def a calculation error with the det

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Yes

old niche
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i think its lambda^2 - 0.7 lambda -0.42

noble lily
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No

old niche
noble lily
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What’s 0.06-0.36

old niche
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ahhh okay

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ok quadratic formula time

noble lily
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Oui

old niche
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so i guess the diagonal matrix of eigen values is

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[1 0, 0 -0.3]

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i think i am stuck again

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.close

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#
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bleak rampart
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hilpeleepl

vocal sleetBOT