#help-17
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Sqrt 5
And what would be arctan1/2
Yeah finding its closed form would be challenging
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Hi, I have no idea how to do these types of problems. Could someone help me with #1 and I'll try the others on my own?
HEY I WAS TYPING HERE
sigh have some respect for others please
ok and? just go to a different channel.
just rude
if you need help, stop arguing and move on
Anyways here's my questions
not enough info
If anyone can help I'd be grateful
how u supposed to get f(x)
There is enough
when the only thing u know is f'(c)
I think
i mean yeah it is not uniquely detrmined
but like ig you're supposed to look at the limit itself and how it's written
They wouldn't just give you an impossible problem
Yeah exactly
Yeah that was wrong
not wrong. pointless.
like you're supposed to know $f'(c) = \lim_{\Delta x \to 0} \frac{f(c+\Delta x) - f(c)}{\Delta x}$
Ann
and match that to the fraction in the limit
6 - 4(1+Δx) is supposed to be f(c+Δx)
Are we given enough info?
You mean c?
Nvm f(x) is not 2
@paper depot I'm unsure, sorry
Maybe we can try the second one?
It looks easier
C = -3
Ohhhh!
And y = x^3
Ok but #1 is still confusing me
focus on the component in ()
compare $(1 + \Delta x)$ to $(c + \Delta x)$ \
similar to how you would've compared $(-3 + \Delta x)$ to $(c + \Delta x)$
ℝαμΩℕωⅤ
...
Ok I'm sorry
not listening to what i'm saying
I'm trying my best
I was
I was trying to simplify it to see how to compare it
😭
Ok can u explain it?
don't simplify / manipulate the expression given
Ok
Mhm
compare $(1 + \Delta x)$ to $(c + \Delta x)$
ℝαμΩℕωⅤ
c = ?
1
yes
$\lim_{x\to0} \frac{\overbrace{[6-4\red{(1+\Delta x)}]}^{f\red{(c+\Delta x)}} - \overbrace{2}^{f(c)}}{\Delta x}$
ℝαμΩℕωⅤ
$f\red{(1+\Delta x)} = 6-4\red{(1+\Delta x)} \
f(x) = ?$
ℝαμΩℕωⅤ
Gravitational Joey
This time there's no addition
If I simplify it with conjugated I get
$\frac{49}{7\sqrt{x} + 21}$
@outer warren
Gravitational Joey
what's with the conjugation
you're not required to do that here
in the questions you're essentially being asked to compare what you have to certain limit definitions
$f'(c) = \lim_{x\to c} \frac{f(x)-f(c)}{x-c}$
ℝαμΩℕωⅤ
Would this be f(x)
I know I was just confused
I thought it was f(x + h)
Not just f(x)
So I didn't know how to compare hem
Then
Them
Ohh ok
I'll read this
So if f(c) = -21
no
f(c) is the amount being subtracted which is just 21
the value of c can also be idenified directly from the denominator
you could get it from solving f(x) = 7sqrt(x) = 21
but that's just more work
That's what I did
Oh
9
yes
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I need some explaination on what restricted values are.
,rccw
Any idea?
restricted values are just values which will make your result undefined
1/0 is undefined. so the value which will result in the denominator of a fraction being 0 will be a restricted valoe
in this case, -4 and 2 and restricted values of x since inputting those will make the denominator 0
Ohhhhh
I see
Tysm
For the lcd
Do i have to multiply each sides?
Multiply the lcd on each sides
Cuz im transforming it to a quadratic equation
@errant granite Has your question been resolved?
@errant granite Has your question been resolved?
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I messed up
its Bx+c not B
you need a linear term in numerator if you have quadratic in denominator
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Is this correct I'm finding behavior around vertical asymptote
My function is 1/x-3
@distant umbra Has your question been resolved?
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HELP IS NEEDED
alright
so
what is the teraction of 12?
it's like the power sign but it is put at the top left
unlike the power sign
do you mean tetration?
what is the little number in the top left
?
i'm currently doing my English homework
Right, so it's gonna be $12^{12^{12^{12}}}$
A Lonely Bean
Does that answer your question?
yes
i just wanted to know what it would look like if i wanted to multiply it by 2^12^12
no need to calculate the value, just keep the power sign up there
$2^{12^{12$
Evan-H/ø/X
$2^{12^{12$
```Compilation error:```! Missing } inserted.
<inserted text>
}
l.57 $2^{12^{12$
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
Evan-H/ø/X
@inland totem Has your question been resolved?
No, nobody's been answering me
@inland totem Has your question been resolved?
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Should hopefully be an easier question:
Say that I roll a 6 sided dice, we know that I have 1/6 chance of rolling a six
Say I also roll an 10 sided dice every half second, meaning I have 1/10 chance of rolling a six, but it happens twice as often
How would I know which dice to expect to roll a 6 first?
think about rolling two d10s every second if that's simpler
$1-(\frac{1}{10})^2$
KirbysGames
@mild flower would this be right then?
99/100?
wait not that can't be right
(I haven't taken an ounce of statistics
)
$(1-(\frac{9}{10})^2)=19%$
this numver makes more sense if I'm not mistaken?
yeahh that looks much better!
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KirbysGames
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hi
is this the correct triangle?

not quite, do you know your properties of the transversal?
@vestal vessel Has your question been resolved?
No not on top of my head?
I think its 1
you know what just tell me if this is right
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@vestal vessel Has your question been resolved?
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i just need help on setting up the integral
work is integral of force so am i just integrating the c/ (x^2 + y^2)^3/2
@proper igloo Has your question been resolved?
<@&286206848099549185>
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any idea how to solve this?
integration by parts
let u = (arcsin x)^2 and dv = dx
is also doing the question
ah okay
how would you know when you have to use integration by parts?
usually when nothing else works
can you explain what dv = dx means
look at the integration by parts formula
okay 👍
In calculus, and more generally in mathematical analysis, integration by parts or partial integration is a process that finds the integral of a product of functions in terms of the integral of the product of their derivative and antiderivative. It is frequently used to transform the antiderivative of a product of functions into an antiderivative...
${\displaystyle \int u,dv\ =\ uv-\int v,du.}$
Tushar
@craggy aurora Has your question been resolved?
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I need help😭
Can anyone divide this
3x³+4x²+8 ÷ x+2
Long division
Division of polynomials is so hard for me😭
you can't get help in an occupied channel
Oh
scroll up, and look for available
Okay
if a = bc + z, then a/2 = (b/2)c + z/2
what you're showing is just a specific case, with z = 0
and integers
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Need to prove the Infimum is of this set is -2
I already showed that -2 is a lower bound as it follows: (Consider n is even)
3 > 1/n
2 + 1 > 1/n
2 + (-1)^n > 1/n
2 > 1/n - (-1)^n
-2 < (-1)^n - 1/n
been stuck on how to prove that -2 is the Infimum of this set
you’re pretty much there, a proof by contradiction would work
@shadow spindle Has your question been resolved?
how would that be?
∃δ>0; ∀y∈Set; y ≥ -2 + δ
Oh
Not quite sure if this works: (Define the set as C)
Suppose by contradiction that ∃δ>0; ∀y∈C; y ≥ -2 + δ
Then
(-1)^n - 1/n ≥ -2 + δ
(-1)^n - 1/n + 2 ≥ δ
Take n = 1, so:
-1 -1 + 2 ≥ δ
0 ≥ δ
Which is a contradiction because we supposed δ>0
that will do
thaaanks
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I need help on whether the limit exists or not.
well, at x=3, the function is -12
but you're right that the limit exists
and the limit is 12 because the limit doesn't care about the value at the point.
Wait so for a limit, it doesn’t matter if the point is included or not as long as it’s being approached from both sides?
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can anyone help with this
I was thinking it would be
a) yes
b) yes
c) no
d) yes
e) yes
also can a graph be homeomorphic to a surface?
@wise sable Has your question been resolved?
@wise sable Has your question been resolved?
@wise sable Has your question been resolved?
@wise sable Has your question been resolved?
@wise sable Has your question been resolved?
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what am i doing wrong here?
trying to solve for the system of linear equations at the top
im pretty sure im not supposed to end up at 56/10x = 428/10
<@&286206848099549185> could anyone help me?
Did you check your answer
This calculator solves system of three equations with three unknowns. It will generate a detailed explanation.
What about y and z
Plug the solution into every step and see which one is wrong first
y is 9 and z is 5
wouldnt is be wildly off base if x is wrong in the first place anyways?
Did you do this
ohh
from the website?
it uses a different method of solution from elimination so
its not rlly the same
...
The solution can be obtained in multiple ways
The way you get the solution doesn't change the solution
yah but i cant plug my steps into theirs to see what went wrong
i see
And see where your equation is false
13x - 10y = 1
29x - 18y = 41
these are correct
y = 13/10x - 1/10
this is right
29x - 18(13/10x - 1/10) = 41
correct
29x - 234/10x - 18/10 = 41
but this is wrong
but why is it wrong?
oh
,- is supposed to be +
thank u for ur time that fixed it
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Suppose f is continous function on [10, infinity) and that f(x) >=1 for all x>=10 what can u say about the integrals?
i think this is a direct comparison type of problem where if the integral of f(x) converges integral of g(x) will converge too or diverge and diverge
I believe that 0< Integral A< Integral B
I believe both of these integrals diverge if you consider f(x) a constant greater than 1 but my homework is telling me im wrong
do these actually converge? or maybe is there not enough info?
Yes both integrals can diverge. Like you said, f(x) = 1 and both are divergent
A is less than B
so here are the answer options i originaly putt both are divergent and i got it wrong so im wondering if its something else
Well, both could also converge.
For a choice of f(x) that shrinks fast enough
The only thing I think we can say for certain, is that there's no f(x) that will cause A to diverge and B to converge
thank you so much that helps me!
OH f(x) ≥ 1
haha i put in that they could be either convergent or divergent and it said that that was right
Well wait, that doesn't matter. f(x) is in the denominator
Okay cool lol. Weird how little we can say about these integrals. What a strange question
yeah the questions on this assignment were super theoritcal and not striaght forward at all thanks so much
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How do I figure out (G o F)? i'm having trouble multiplying x-3/2 into 2x + 3, do I just multiply all of it by 2??
i.e.
2(x-3/2) + 3
2x-6/4 + 3
Put 2x + 3 wherever you see an x in f(x)
not quite everything
you'd need to distribute the 2 to the terms of the numerator, leaving the denominator alone
put f(x) wherever you see an x in g(x)*
$2(\frac{x-3}{2}) \implies \frac{2(x-3)}{2}$
a disappointing son
OOOoohhh
though in this specific example you don't need to expand, note what you can do with the two in both the numerator and denominator
simplify?
you can, how so?
i'd cancel the 2 from both sides so it'd end up as x-3?
so the answer would be just x?
👍
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What is 2x x tanx
Simple question just forgot
!Yajat!
Yeah
can you post the original question, this is already in the simplified form
So your original question was to find the derivative of $x^2\tan{x}$?
!Yajat!
i barely have any knowledge about calculus, but do you know the product rule?
@vast shale Has your question been resolved?
Someone told me its 2xtanx
$\frac{d}{dx}[f(x)g(x)]=f’(x)g(x)+g’(x)f(x)$
% Openglobe %
yea ik, i just have not studied calculus yet, i only some of it through physics
That’s part of the answer, but not the full answer
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how would i solve for x: x^(2)+x+y=y^(2)
does it want to find x in tdrms of y?
idk sorry
ur name
but like using logic there is a possible answer of x=-y, but im pretty sure there are 2 possible answers
exactly
u in 8th too
/
wait i got it
you could bring all of the equations to the left side and get x²-y²+x+y=0
and you can factor it
do you know how to factor x²-y²?
$\sqrt(x-y$
what
Xanimates
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
that
$\sqrt{x-y}$
Skill_Issue
are you sure?
but that square x and y (was to lazy) then square the other side?
ok i got it
that is x^2+y^2 btw if you accidentally skimmed the ^2
its this
brb
$\sqrt{x^2-y^2+x+y}=\pm\sqrt{0}=0$
Xanimates
$x^{2}-y^{2}=-x-y$
Danny
heres your hint
no. factor out the left side
i thought i did
or is factoring the one wher u have to us ethe parenthesis like like grandmas with their strawberry candy
ye
(x+y)(x-y)?
whats your way of doing it? i caught all the terms in the left side and completely factored it
yes
ig i was thinking simplify
now factor out the right side
y*y
no. factor out a -1
or is it just y^2
a-1?
should be -1 (x + y)
that would be -x-y
yup.
OHH WAIT THIS I THOUGHT U WHERE TALKING ABT THE WHOLE PROBLEM
oh shoot 😅
yeah i meant factor out the left hand side and the right hand side
i mean danny said to factor out the right side
so $(x+y)(x-y)=-1(x+y)$
Xanimates
yep
yes
do you see the way to continue?
no
one of your expression is going to cancel out
so x-y=-1
y=x+1
yup
i mean
would 2x+y=0 then too?
$(x-y)(x+y)=-1(x+y)
x-y=-1$ would be technichally correct but it would remove the other factor
Skill_Issue
then y=-x right
yes
how can both be true
remember the original equation had a y squared.
4=3+1 is true but 4=-3 is not
$(x-y)(x+y)=-1(x+y)$
$(x-y)(x+y)+1(x+y)=$
$(x-y+1)(x+y)=0$
Skill_Issue
do you get it now?
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yo can i ask a quantitative reasoning question here?
sure?
i have to find the 5 number summary for a data set and i got 10, 10, 11, 12, 14
Find what
the whole data set is 10, 10, 10, 10, 10, 11, 11, 11, 11, 12, 12, 12, 13, 13, 14
i need to find outliers but are numbers allowed to repeat in the 5 number summary?
i have no idea what 5 number summary is sry, openglobe probably does
Outlier>1.5(IQR)+Q1
Outlier<Q3-1.5(IQR)
for the 5 number summary is it fine if numbers repeat?
Then the min isn’t an outlier
but it is repeated
Still not an outlier because 10 is Q1
so it's fine that both values are 10?
Absolutely
i still dont really understand how to find the outlier
are the outliers 8.5 and 13.5 then
iqr is 2
is it 10-1.5 (2)
That works
i got 7
And any number less than the calculated value is an outlier
If no numbers are below 7, there are no outliers on this end
Now we have to perform the other string
Potential outlier<7
for the other one i got 15
Outlier>15
it also asks me to draw a box plot, do i need to plot the outliers too?
There are no outliers
do i still need to plot the potential outliers?
All are between 7 and 15 inclusive
No
does the box go from 10-12 and the whisker to 14?
i drew this but i didnt know how to draw the whisker for 10
ok can i also get help with a stocks question?
6 numeros de 48 con mayor probabilidad de ser elegidos?
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sorry
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How do I answer this? I've tried rationalizing the top, but I'm not sure what I can do from that.
I doubt you will need to rationalize anything if you follow the hint instead.
I'm not too sure on how to use the hint though
Rewrite it as t^6 = x
I'm getting t^3 - 1 / t^2 - 1
I'm going to try expanding them
Thanks I got it 
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how would i solve linear transformations like this
and also these questions
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the distance between town A and town B is 36km, Alan left town A for town B and at the same time Betty left from town B for town A, after they met, Alan took 2h 30m to get to town B while Betty took another 1h 36m to reach town A, find Betty's speed
choices are A.6 B.7 C.8 D.9 E.10
using dmthe distance formula i get
D=S×T
36=A(alans speed)×(W1+5/2) (W1 is the time for alan and betty to meet)
36=B×(W1+16/10) but idk how to continue after that
heres like a diagram for it
36-AX=A×5/2
AX=B×16/10
36=5A/2+16B/10
360=25A+16B
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<@&286206848099549185>
@kind light Has your question been resolved?
@kind light Has your question been resolved?
@kind light Has your question been resolved?
no
they are at a constant speed and meet as in them being at the same place in the road
Ok so if at constant speed then they meet in middle
Oh so they meet at a different place
yea
But we don’t know what speed they were travelling before they met, nor do we know the speed before they met, nor the time too
Are you sure that’s the question?
yeah
Send the picture
i dont have the exact papers on me, so its abit blurry (this was for a diffrent thing) but here
,rccw
so?
Maybe it’s trial and error?
how would you trial and error that
Betty
Time = 1h36m
Let Speed = 6
Distance = 1h36*6= 1.6 * 6 = 9.6km
Betty
Time = 1h36m
Let Speed = 7
Distance = 1.6 * 7 = 11.2km
Time = 1h36m
Let Speed = 8
Distance = 1.6 * 8 = 12.8km
Time = 1h36m
Let Speed = 9
Distance = 1.6 * 9 = 14.4km
Time = 1h36m
Let Speed = 10
Distance = 1.6 * 10 = 16km
Idk I’m lost too now
oh wait
you could check alan's speed for each betty speed and find if the time for alan from point x to town b matches the question
But how
wait
We only know Alan’s time and distance for each of the choices
So what will we do with the speed
Betty
Time = 1h36m
Let Speed = 7
Distance = 1.6 * 7 = 11.2km from a (24.8km from b)
Time = 1h36m
Let Speed = 8
Distance = 1.6 * 8 = 12.8km from a (23.2km from b)
Time = 1h36m
Let Speed = 9
Distance = 1.6 * 9 = 14.4km from a (21.6km from b)
Time = 1h36m
Let Speed = 10
Distance = 1.6 * 10 = 16km from a (16km from b)
wait
Betty
Time = 1h36m
Let Speed = 6
Distance = 1h366= 1.6 6 = 9.6km from a (26.4km from b)
36-16=20km
20km/2.5h=8kmph
36-14.4=21.6km
21.6/2.5h=8.64 kmph
if we use speed=6 we can get that the distance Alan traveled 26.4km took 5/2h
yeah basically trial and error
tysm!
I’m making a Python code for it lol
ok ima just let this open cause i wanna see
‘ ‘ ‘
import math
BettyDistance=[]
for speed in range(6,11):
BettyDistance.append(speed*16/10)
print (BettyDistance)
AlanDistance=[]
for x in range(len(BettyDistance)):
AlanDistance.append((BettyDistance[x] - 36)*-1)
print(AlanDistance)
AlanSpeed = list(Distance/0.25 for Distance in AlanDistance)
for speed in AlanSpeed:
speed = speed/10
print (f"When Alan's speed is {speed}, Betty's speed is {(36-speed*2.5)/1.6}")
‘ ‘ ‘
import math
BettyDistance=[]
for speed in range(6,11):
BettyDistance.append(speed*16/10)
print (BettyDistance)
AlanDistance=[]
for x in range(len(BettyDistance)):
AlanDistance.append((BettyDistance[x] - 36)*-1)
print(AlanDistance)
AlanSpeed = list(Distance/0.25 for Distance in AlanDistance)
for speed in AlanSpeed:
speed = speed/10
print (f"When Alan's speed is {speed}, Betty's speed is {(36-speed*2.5)/1.6}")
[9.6, 11.2, 12.8, 14.4, 16.0]
[26.4, 24.8, 23.2, 21.6, 20.0]
When Alan's speed is 10.56, Betty's speed is 6
When Alan's speed is 9.92, Betty's speed is 7
When Alan's speed is 9.28, Betty's speed is 8
When Alan's speed is 8.64, Betty's speed is 9
When Alan's speed is 8.0, Betty's speed is 10
Thanks this was a good project! @kind light
Ping me if you need
Going now bye
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Still?
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? How’s this wrong
!show
Show your work, and if possible, explain where you are stuck.
Bruh doesn’t work
On top it says enter all answers using the appropriate multiplicities
Idk what that means
pls help me
Jasim has seven cards numbered 2 to 8
2345678
Jasim takes at random three of these cards.
He works out the sum of the numbers on the three cards and records the result.
Work out the probability that the result is an odd number.
Webassign is literal L website I pay $40 for this
@vague vessel Has your question been resolved?
multiplicities
x^3(x^2-16)
notice that you have x=0 three times
webassign is probably looking for 0, 0, 0, -4, 4
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Can I get some help
First of all they state that 0<a<1, so which of the three equations should you choose
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@frosty robin Has your question been resolved?
Think the solution factored out the thing so that you wouldn’t have fractions in the square root
@ebon rapids how does that get factored
I see that they how they got rid of the fraction inside the square root
But where did the outside fraction come from
CST (please ping when replying)
Does this make sense?
@ebon rapids yes but why do we need that 1/(3y)^(1/3) outside the square root
Again, the solution just doesn’t want fractions inside the square root
It’s a style choice more than anything
CST (please ping when replying)
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$\int d(x+2)$
Jash
ye
so is it just x+2+C
indeed
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I went about the proper way to find the derivative and used quotient rule on both df/dx and dy/dx
but it resulted in (x^2+y^2)^2 in the denominator which is 0 when (x,y) = (0,0)
so i thought maybe the partial derivative doesn't exist
but the answer is literally just
i feel like you can't just use that right? something feels wrong, like how in considering if a limit exists, you have to think of infinite ways to approach the point, not just along the x and y axis
@wooden stump Has your question been resolved?
got it, using definition of partial derivative so $\frac{\partial f}{\partial x}|{(x,y) = (0,0)} = \lim{h \to 0} \frac{1}{h} f(h,0) - f(0,0)$
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omgatriple
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i don't know how to keep doing this problem
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@viscid halo
@thorny rapids hey!
@thorny rapids just wondering if I can help with the final problem on this order of operations sheet
It's the bottom one I can't solve
And exponentiation is allowed on any of the numbers
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I am unsure what to do with this problem, it's a linear expression problem
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Hi
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I'm getting 625.1 years for c but the answer is 6251 years where am I losing a power
Did you do a correctly
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I'm trying so solve for -k because it's the constant I need in order to find the rest of the problem, but I'm stuck on what to do after I get to the point where it's shown on my paper. I included the original problem in case I left out any information
use the fact that after 10 minutes it's at 240F
I tried that on my first attempt but it didn't work, I tried dividing 240 by 365 and using that as the constant but it said I was wrong
I'm pretty sure it wants me to simplify the original equation and then take the natural log but idk how to do that or steps after that
but like set up your equation of cooling
like set up $T = T_s + (T_0 - T_s)e^{-kt}$ for the time from 0 to 10 minutes
hayley
and you'll get your answer for k
Oh ok that makes a lot more sense than what I was doing
Oh yeah 0.0556 there it is, thank you so much!
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Is this true?
Looks good to me
I can't think of any column operations, I don't think they exist in a capacity in which they would be useful
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Prove
(1-cosx)/(1+tan^2x)^2 = 1/((1+cosx)(3+cot^2x+3tan^2x+tan^4x))
[ \frac{1-\cos x}{(1+\tan^2x)^2} = \frac{1}{((1+\cos x)(3+\cot^2x+3\tan^2x+\tan^4x))} ]
daniGhost (ping reply in help)
This?
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Hello what's the most significant term between these two?
in our module, it says that both of them are equally significant. but how come they are?
!original
Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.
If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.
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can anyone help me with this problem? I have no idea where to start, I already found the derivative in a previous part to be -y/x+y
you need the derivative inverse formula https://math.libretexts.org/Bookshelves/Calculus/Calculus_(OpenStax)/03%3A_Derivatives/3.07%3A_Derivatives_of_Inverse_Functions
@chrome peak Has your question been resolved?
okay so would I just find f prime of 2 because (2 , 1) would be the points on the inverse function?
yes
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How do I plot this in Excel?
What I mean by that is
I have the data and I know my plot is supposed to look like that
Just dk how to get that plot
Here's the data
with a correspondence between flowrates of 1 - 10, 2 - 13, and 3 - 16
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Prove
[ \frac{1-\cos x}{(1+\tan^2x)^2} = \frac{1}{((1+\cos x)(3+\cot^2x+3\tan^2x+\tan^4x))} ]
Radin
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
@pliant urchin Has your question been resolved?
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[ \int_0^{\infty} \frac{2x - 4}{x^3 + 1} dx ]
I am attempting to demonstrate that this integral is convergent. I have been considering the comparison test for integrals, particularly comparing the given expression with (\frac{1}{x^2}) for (x \geq 1), as (x^3 + 1) grows faster than (x^2) as (x) approaches infinity.
For (x \geq 1), I've established the following:
[0 \leq \frac{2x - 4}{x^3 + 1} \leq \frac{2x}{x^3} = \frac{2}{x^2}]
Now, I am looking to integrate these expressions from 1 to infinity, and I am aware that the integral of (\frac{2}{x^2}) from 1 to infinity converges to 2.
However, I would appreciate any insights, suggestions, or alternative approaches that might help me solidify this conclusion and effectively demonstrate the convergence of the given integral.
dgh
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Anyone understand this? I'm confused as I thought R^2 would be like x, y but this question has x, y, z
T takes a vector in R^3 and maps it to a vector in R^2
that's what the notation T : R^3 --> R^2 means
(x y z) is the "input" vector from R^3
(x+y, y-z) is the "output" vector in R^2
Ah thanks so would this look correct for first half of the proof?
I was thinking not since I have 3 values at the right side ?
you just need to take two vectors not 3 yeah
also you forgot to apply the transformatin
that's not T(x+y+z)
@hushed flint
the transformation?
do I need to multiply it by that other matrix or something?
wym mutiply
you still don't know the matrix of T
T(x, y, z) is (x+y, y-z), with (x, y, z) is one vector
oh..
also calling your 3d vectors x, y and z might be confusing
I thought T(x, y, z) was my T(x + y) and then the (x+y, y-z) was the T(x) + T(y)
In my textbook the only example similar is this, is this what I’m trying to do ?
So I’m a bit confused why mine is wrong haha
T(3d vector) is a 2d vector in your new question
that's not even the case in your working
you straight up just recopied x+y+z
it's like if I say f(x) = 2x+5, and I ask you what f(2) is and you tell me it's 2
How do u know what matrix to apply to the T(x y z) to turn it into x+y, y-z
ofc I know
you don't need to find the matrix to show it's a linear transformation tho
But how do I show it without multiplying by the matrix
you straight up have the defnition of what T(x, y, z) is
use it
if $a = \begin{bmatrix} a_1\a_2\a_3\end{bmatrix} $ and $b = \begin{bmatrix} b_1\b_2\b_3\end{bmatrix}$ then $$T(a+b) = T\left(\begin{bmatrix} a_1+b_1\a_2+b_2\a_3+b_3\end{bmatrix}\right) = \begin{bmatrix} (a_1+b_1) + (a_2+b_2)\(a_2+b_2)-(a_3+b_3)\end{bmatrix}$$
aPlatypus
it's like you forgot the T was even there
T is a function taking 3d vectors and outputting 2d vectors
@hushed flint
Ohh but then how does that prove that T(x, y) = T(x) + T(y)
@cyan talon
T(x+y) = T(x)+T(y)
be mindful of your notation