#help-17

1 messages · Page 100 of 1

river minnow
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E.g., let the opposite side be of length 1 and the adjacent side be of length 2

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What's the hypotenuse in that case?

cursive fern
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Sqrt 5

river minnow
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Right

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So what's cosine then?

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Given that cos = adj/hyp

cursive fern
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2/sqrt5

river minnow
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Yes, that's it

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,w cos(arctan(1/2))

cursive fern
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And what would be arctan1/2

river minnow
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I don't think there is a nice solution to that

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,w arctan(1/2)

river minnow
#

Yeah finding its closed form would be challenging

cursive fern
#

Alright thanks

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.close

vocal sleetBOT
#
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pliant eagle
vocal sleetBOT
pliant eagle
#

Hi, I have no idea how to do these types of problems. Could someone help me with #1 and I'll try the others on my own?

rose heart
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HEY I WAS TYPING HERE

pliant eagle
paper depot
rose heart
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just rude

outer warren
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if you need help, stop arguing and move on

pliant eagle
karmic mica
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not enough info

pliant eagle
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If anyone can help I'd be grateful

karmic mica
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how u supposed to get f(x)

pliant eagle
pliant eagle
karmic mica
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when the only thing u know is f'(c)

pliant eagle
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I think

paper depot
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i mean yeah it is not uniquely detrmined

pliant eagle
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Well there has to be enough

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Idk

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It's cengage

paper depot
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but like ig you're supposed to look at the limit itself and how it's written

pliant eagle
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They wouldn't just give you an impossible problem

paper depot
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it's a sucky problem

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but it is doable

pliant eagle
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I tried simplifying it

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And got 4

paper depot
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no

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that's not what you are supposed to do here

pliant eagle
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Yeah that was wrong

paper depot
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not wrong. pointless.

pliant eagle
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I'm not sure what exactly to do

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So uh

paper depot
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like you're supposed to know $f'(c) = \lim_{\Delta x \to 0} \frac{f(c+\Delta x) - f(c)}{\Delta x}$

twin meteorBOT
paper depot
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and match that to the fraction in the limit

pliant eagle
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Yep

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But I don't get how the problem above fits this at all

paper depot
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6 - 4(1+Δx) is supposed to be f(c+Δx)

pliant eagle
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Oh I see

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  • f(c)
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Minus*

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So f(x) should equal 2

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F(c)*

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What about x itself?

paper depot
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what is x itseelf

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itself*

pliant eagle
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Are we given enough info?

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You mean c?

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Nvm f(x) is not 2

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@paper depot I'm unsure, sorry

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Maybe we can try the second one?

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It looks easier

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C = -3

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Ohhhh!

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And y = x^3

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Ok but #1 is still confusing me

outer warren
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focus on the component in ()

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compare $(1 + \Delta x)$ to $(c + \Delta x)$ \
similar to how you would've compared $(-3 + \Delta x)$ to $(c + \Delta x)$

twin meteorBOT
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ℝαμΩℕωⅤ

pliant eagle
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If I simplify the parenthesis I get 2 - h

outer warren
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...

pliant eagle
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Ok I'm sorry

outer warren
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not listening to what i'm saying

pliant eagle
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I'm trying my best

pliant eagle
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I was trying to simplify it to see how to compare it

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😭

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Ok can u explain it?

outer warren
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don't simplify / manipulate the expression given

pliant eagle
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Ok

outer warren
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look at it as is

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focus on the component in ()

pliant eagle
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Mhm

outer warren
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compare $(1 + \Delta x)$ to $(c + \Delta x)$

twin meteorBOT
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ℝαμΩℕωⅤ

outer warren
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c = ?

pliant eagle
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1

outer warren
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yes

pliant eagle
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What about the 6 - 4() part?

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That's what's confusing me

outer warren
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$\lim_{x\to0} \frac{\overbrace{[6-4\red{(1+\Delta x)}]}^{f\red{(c+\Delta x)}} - \overbrace{2}^{f(c)}}{\Delta x}$

twin meteorBOT
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ℝαμΩℕωⅤ

pliant eagle
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Oh ok

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I think I get ur

#

It

outer warren
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$f\red{(1+\Delta x)} = 6-4\red{(1+\Delta x)} \
f(x) = ?$

twin meteorBOT
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ℝαμΩℕωⅤ

pliant eagle
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6 - 4x

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Oh

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Ty

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I'm also unsure how to do this one

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$7 \sqrt{x}$

twin meteorBOT
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Gravitational Joey

pliant eagle
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This time there's no addition

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If I simplify it with conjugated I get

$\frac{49}{7\sqrt{x} + 21}$

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@outer warren

twin meteorBOT
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Gravitational Joey

outer warren
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what's with the conjugation

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you're not required to do that here

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in the questions you're essentially being asked to compare what you have to certain limit definitions

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$f'(c) = \lim_{x\to c} \frac{f(x)-f(c)}{x-c}$

twin meteorBOT
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ℝαμΩℕωⅤ

pliant eagle
pliant eagle
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I thought it was f(x + h)

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Not just f(x)

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So I didn't know how to compare hem

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Then

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Them

outer warren
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yes, f(x) = 7sqrt(x)

pliant eagle
pliant eagle
outer warren
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no

pliant eagle
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Sqrt(x) = 3?

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Oh

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Nvm

outer warren
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f(c) is the amount being subtracted which is just 21

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the value of c can also be idenified directly from the denominator

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you could get it from solving f(x) = 7sqrt(x) = 21
but that's just more work

pliant eagle
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Right?

outer warren
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yes

vocal sleetBOT
#

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Please don't occupy multiple help channels.

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high seal
#

.close

vocal sleetBOT
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errant granite
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I need some explaination on what restricted values are.

errant granite
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Ill give this equation for example

onyx totem
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,rccw

twin meteorBOT
errant granite
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Any idea?

warped relic
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1/0 is undefined. so the value which will result in the denominator of a fraction being 0 will be a restricted valoe

warped relic
# twin meteor

in this case, -4 and 2 and restricted values of x since inputting those will make the denominator 0

errant granite
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Ohhhhh

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I see

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Tysm

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For the lcd

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Do i have to multiply each sides?

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Multiply the lcd on each sides

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Cuz im transforming it to a quadratic equation

vocal sleetBOT
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@errant granite Has your question been resolved?

vocal sleetBOT
#

@errant granite Has your question been resolved?

vocal sleetBOT
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vast shale
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I messed up

vocal sleetBOT
vast shale
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Can someone help

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Ignore the C

haughty narwhal
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its Bx+c not B

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you need a linear term in numerator if you have quadratic in denominator

vast shale
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Ohh

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Bet ty

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.close

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distant umbra
vocal sleetBOT
distant umbra
#

Is this correct I'm finding behavior around vertical asymptote

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My function is 1/x-3

split wind
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looks okay

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,w plot 1/(x-3)

vocal sleetBOT
#

@distant umbra Has your question been resolved?

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inland totem
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HELP IS NEEDED

vocal sleetBOT
inland totem
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alright

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so

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what is the teraction of 12?

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it's like the power sign but it is put at the top left

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unlike the power sign

trail mesa
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do you mean tetration?

inland totem
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yes*

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sorry for that spelling mistake

trail mesa
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what is the little number in the top left

inland totem
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4

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oh shoot, it's gonna be big

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but math is math

trail mesa
inland totem
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yes

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that's what i meant

trail mesa
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?

inland totem
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i'm currently doing my English homework

river minnow
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Right, so it's gonna be $12^{12^{12^{12}}}$

twin meteorBOT
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A Lonely Bean

river minnow
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Does that answer your question?

inland totem
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yes

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i just wanted to know what it would look like if i wanted to multiply it by 2^12^12

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no need to calculate the value, just keep the power sign up there

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$2^{12^{12$

twin meteorBOT
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Evan-H/ø/X

$2^{12^{12$
```Compilation error:```! Missing } inserted.
<inserted text> 
                }
l.57 $2^{12^{12$
                
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
inland totem
#

alr

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would it be like this: $12^{12^{12^{12}}} * 2^{12^{12}} = 24^{12^{12^{12}}}??$

twin meteorBOT
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Evan-H/ø/X

inland totem
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ig?

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hwy

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heyyy

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does anybody wants to help?

vocal sleetBOT
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@inland totem Has your question been resolved?

inland totem
#

No, nobody's been answering me

vocal sleetBOT
#

@inland totem Has your question been resolved?

vocal sleetBOT
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idle temple
#

Should hopefully be an easier question:
Say that I roll a 6 sided dice, we know that I have 1/6 chance of rolling a six
Say I also roll an 10 sided dice every half second, meaning I have 1/10 chance of rolling a six, but it happens twice as often
How would I know which dice to expect to roll a 6 first?

mild flower
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think about rolling two d10s every second if that's simpler

idle temple
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$1-(\frac{1}{10})^2$

twin meteorBOT
#

KirbysGames

idle temple
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@mild flower would this be right then?

mild flower
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99/100?

idle temple
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wait not that can't be right

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(I haven't taken an ounce of statistics sully)

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$(1-(\frac{9}{10})^2)=19%$

idle temple
mild flower
#

yeahh that looks much better!

idle temple
#

.close

vocal sleetBOT
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twin meteorBOT
#

KirbysGames

vocal sleetBOT
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vestal vessel
#

hi

vocal sleetBOT
vestal vessel
#

is this the correct triangle?

soft walrus
vestal vessel
#

it is?

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alright thanks

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how about this?

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ques 8

soft walrus
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not quite, do you know your properties of the transversal?

vocal sleetBOT
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@vestal vessel Has your question been resolved?

vestal vessel
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I think its 1

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you know what just tell me if this is right

vocal sleetBOT
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@vestal vessel Has your question been resolved?

vocal sleetBOT
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@vestal vessel Has your question been resolved?

vocal sleetBOT
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proper igloo
#

i just need help on setting up the integral

proper igloo
#

work is integral of force so am i just integrating the c/ (x^2 + y^2)^3/2

vocal sleetBOT
#

@proper igloo Has your question been resolved?

proper igloo
#

<@&286206848099549185>

vocal sleetBOT
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@proper igloo Has your question been resolved?

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craggy aurora
#

any idea how to solve this?

vocal sleetBOT
silk comet
#

integration by parts

craggy aurora
#

how would i start?

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@iron stone

silk comet
#

let u = (arcsin x)^2 and dv = dx

craggy aurora
#

is also doing the question

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ah okay

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how would you know when you have to use integration by parts?

silk comet
#

usually when nothing else works

craggy aurora
#

can you explain what dv = dx means

silk comet
#

look at the integration by parts formula

craggy aurora
#

okay 👍

silk comet
#

In calculus, and more generally in mathematical analysis, integration by parts or partial integration is a process that finds the integral of a product of functions in terms of the integral of the product of their derivative and antiderivative. It is frequently used to transform the antiderivative of a product of functions into an antiderivative...

#

${\displaystyle \int u,dv\ =\ uv-\int v,du.}$

twin meteorBOT
#

Tushar

vocal sleetBOT
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half compass
vocal sleetBOT
half compass
#

How do u know if this is true

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What’s the reason why it is true

fleet helm
#

I need help😭

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Can anyone divide this
3x³+4x²+8 ÷ x+2

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Long division

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Division of polynomials is so hard for me😭

dark kiln
#

you can't get help in an occupied channel

fleet helm
#

Oh

dark kiln
#

scroll up, and look for available

fleet helm
#

Okay

dark kiln
#

what you're showing is just a specific case, with z = 0

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and integers

vocal sleetBOT
#

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fallen sandal
vocal sleetBOT
fallen sandal
#

Is this correct

#

Ty

#

.close

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shadow spindle
#

Need to prove the Infimum is of this set is -2

shadow spindle
#

I already showed that -2 is a lower bound as it follows: (Consider n is even)
3 > 1/n
2 + 1 > 1/n
2 + (-1)^n > 1/n
2 > 1/n - (-1)^n
-2 < (-1)^n - 1/n

#

been stuck on how to prove that -2 is the Infimum of this set

ancient knoll
#

you’re pretty much there, a proof by contradiction would work

vocal sleetBOT
#

@shadow spindle Has your question been resolved?

shadow spindle
ancient knoll
#

suppose the infimum is some number greater than -2…

#

and go from there

shadow spindle
#

∃δ>0; ∀y∈Set; y ≥ -2 + δ

shadow spindle
# ancient knoll and go from there

Not quite sure if this works: (Define the set as C)
Suppose by contradiction that ∃δ>0; ∀y∈C; y ≥ -2 + δ
Then

(-1)^n - 1/n ≥ -2 + δ
(-1)^n - 1/n + 2 ≥ δ

Take n = 1, so:

-1 -1 + 2 ≥ δ
0 ≥ δ

Which is a contradiction because we supposed δ>0

ancient knoll
#

that will do

shadow spindle
#

thaaanks

vocal sleetBOT
#

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verbal birch
#

I need help on whether the limit exists or not.

verbal birch
#

I think the answer is that it exists because at x = 3, it’s 12

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But I’m not sure

brittle wasp
#

well, at x=3, the function is -12

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but you're right that the limit exists

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and the limit is 12 because the limit doesn't care about the value at the point.

verbal birch
brittle wasp
#

correct. The limit doesn't care.

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Continuity does care, though.

verbal birch
#

Yeah I was thinking of that

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Thank you.

#

.close

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wise sable
vocal sleetBOT
wise sable
#

can anyone help with this

#

I was thinking it would be
a) yes
b) yes
c) no
d) yes
e) yes

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also can a graph be homeomorphic to a surface?

vocal sleetBOT
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@wise sable Has your question been resolved?

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@wise sable Has your question been resolved?

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@wise sable Has your question been resolved?

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@wise sable Has your question been resolved?

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snow moth
vocal sleetBOT
snow moth
#

what am i doing wrong here?

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trying to solve for the system of linear equations at the top

#

im pretty sure im not supposed to end up at 56/10x = 428/10

#

<@&286206848099549185> could anyone help me?

flat whale
snow moth
#

yeah

#

the x is supposed to be 7

flat whale
#

Plug the solution into every step and see which one is wrong first

snow moth
#

wouldnt is be wildly off base if x is wrong in the first place anyways?

snow moth
#

ohh

#

from the website?

#

it uses a different method of solution from elimination so

#

its not rlly the same

flat whale
#

...

#

The solution can be obtained in multiple ways

#

The way you get the solution doesn't change the solution

snow moth
#

yah but i cant plug my steps into theirs to see what went wrong

flat whale
#

You don't plug your steps

#

You plug the correct answer

#

Into every one of your steps

snow moth
#

i see

flat whale
#

And see where your equation is false

snow moth
#

13x - 10y = 1
29x - 18y = 41

#

these are correct

#

y = 13/10x - 1/10

#

this is right

#

29x - 18(13/10x - 1/10) = 41

#

correct

#

29x - 234/10x - 18/10 = 41

#

but this is wrong

#

but why is it wrong?

#

oh

#

,- is supposed to be +

#

thank u for ur time that fixed it

#

.close

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tired jewel
#

Suppose f is continous function on [10, infinity) and that f(x) >=1 for all x>=10 what can u say about the integrals?

tired jewel
#

i think this is a direct comparison type of problem where if the integral of f(x) converges integral of g(x) will converge too or diverge and diverge

#

I believe that 0< Integral A< Integral B

#

I believe both of these integrals diverge if you consider f(x) a constant greater than 1 but my homework is telling me im wrong

#

do these actually converge? or maybe is there not enough info?

regal bane
#

Yes both integrals can diverge. Like you said, f(x) = 1 and both are divergent

#

A is less than B

tired jewel
#

so here are the answer options i originaly putt both are divergent and i got it wrong so im wondering if its something else

regal bane
#

Well, both could also converge.

#

For a choice of f(x) that shrinks fast enough

#

The only thing I think we can say for certain, is that there's no f(x) that will cause A to diverge and B to converge

tired jewel
#

thank you so much that helps me!

regal bane
#

OH f(x) ≥ 1

tired jewel
#

haha i put in that they could be either convergent or divergent and it said that that was right

regal bane
#

Well wait, that doesn't matter. f(x) is in the denominator

#

Okay cool lol. Weird how little we can say about these integrals. What a strange question

tired jewel
#

yeah the questions on this assignment were super theoritcal and not striaght forward at all thanks so much

#

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quaint lynx
#

How do I figure out (G o F)? i'm having trouble multiplying x-3/2 into 2x + 3, do I just multiply all of it by 2??
i.e.

2(x-3/2) + 3

2x-6/4 + 3

quaint lynx
#

whoops, i messed up

#

I just wanna double check if i'm doing it right

river kettle
#

Put 2x + 3 wherever you see an x in f(x)

river kettle
#

Oops other way around

#

That’s fog mb

spice anvil
#

you'd need to distribute the 2 to the terms of the numerator, leaving the denominator alone

river kettle
#

put f(x) wherever you see an x in g(x)*

spice anvil
#

$2(\frac{x-3}{2}) \implies \frac{2(x-3)}{2}$

twin meteorBOT
#

a disappointing son

quaint lynx
#

OOOoohhh

spice anvil
#

though in this specific example you don't need to expand, note what you can do with the two in both the numerator and denominator

quaint lynx
#

simplify?

spice anvil
#

you can, how so?

quaint lynx
#

i'd cancel the 2 from both sides so it'd end up as x-3?

spice anvil
#

right

#

then don't forget that +3 at the end, simplify once more, then you're good

quaint lynx
#

so the answer would be just x?

spice anvil
#

👍

quaint lynx
#

omg awesome thank you so much!

#

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vast shale
#

What is 2x x tanx

vocal sleetBOT
vast shale
#

Simple question just forgot

tidal umbra
#

uh?

#

$2x \times \tan{x}$ this?

twin meteorBOT
#

!Yajat!

vast shale
vast shale
#

2xtanx??

tidal umbra
#

can you post the original question, this is already in the simplified form

vast shale
#

2xtanx??

#

@tidal umbra

tidal umbra
#

So your original question was to find the derivative of $x^2\tan{x}$?

twin meteorBOT
#

!Yajat!

tidal umbra
#

i barely have any knowledge about calculus, but do you know the product rule?

vocal sleetBOT
#

@vast shale Has your question been resolved?

tender leaf
twin meteorBOT
#

% Openglobe %

tidal umbra
tender leaf
vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
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pine lodge
#

how would i solve for x: x^(2)+x+y=y^(2)

vocal sleetBOT
kind light
#

does it want to find x in tdrms of y?

pine lodge
#

yea

#

helo?

kind light
#

idk sorry

pine lodge
#

ur name

kind light
#

but like using logic there is a possible answer of x=-y, but im pretty sure there are 2 possible answers

kind light
pine lodge
#

u in 8th too
/

kind light
#

wait i got it

#

you could bring all of the equations to the left side and get x²-y²+x+y=0

#

and you can factor it

pine lodge
#

thats my problem

#

how tf do u factor that

kind light
#

do you know how to factor x²-y²?

pine lodge
#

$\sqrt(x-y$

kind light
#

what

twin meteorBOT
#

Xanimates
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

pine lodge
#

that

kind light
#

$\sqrt{x-y}$

twin meteorBOT
#

Skill_Issue

kind light
pine lodge
#

but that square x and y (was to lazy) then square the other side?

somber path
#

ok i got it

kind light
#

that is x^2+y^2 btw if you accidentally skimmed the ^2

somber path
kind light
#

brb

pine lodge
#

$\sqrt{x^2-y^2+x+y}=\pm\sqrt{0}=0$

twin meteorBOT
#

Xanimates

somber path
#

$x^{2}-y^{2}=-x-y$

twin meteorBOT
somber path
#

heres your hint

pine lodge
#

so -x-y+x+y=0, just combine like terms to get 0-0=0

#

so x^2-y^2=0

somber path
#

no. factor out the left side

pine lodge
#

i thought i did

#

or is factoring the one wher u have to us ethe parenthesis like like grandmas with their strawberry candy

kind light
#

ye

pine lodge
#

(x+y)(x-y)?

kind light
kind light
pine lodge
#

ig i was thinking simplify

somber path
#

now factor out the right side

pine lodge
#

y*y

somber path
#

no. factor out a -1

pine lodge
#

or is it just y^2

pine lodge
somber path
#

should be -1 (x + y)

pine lodge
#

that would be -x-y

somber path
#

yup.

pine lodge
somber path
#

oh shoot 😅

somber path
kind light
pine lodge
#

so $(x+y)(x-y)=-1(x+y)$

twin meteorBOT
#

Xanimates

kind light
#

yep

somber path
#

yes

kind light
#

do you see the way to continue?

pine lodge
#

no

somber path
#

one of your expression is going to cancel out

pine lodge
#

so x-y=-1

somber path
#

yes

#

now solve for y

pine lodge
#

y=x+1

somber path
#

yup

kind light
#

i mean

pine lodge
#

would 2x+y=0 then too?

kind light
#

$(x-y)(x+y)=-1(x+y)
x-y=-1$ would be technichally correct but it would remove the other factor

twin meteorBOT
#

Skill_Issue

pine lodge
#

then y=-x right

kind light
#

yes

pine lodge
#

how can both be true

somber path
#

remember the original equation had a y squared.

pine lodge
#

4=3+1 is true but 4=-3 is not

kind light
#

$(x-y)(x+y)=-1(x+y)$
$(x-y)(x+y)+1(x+y)=$
$(x-y+1)(x+y)=0$

twin meteorBOT
#

Skill_Issue

kind light
#

do you get it now?

pine lodge
#

ye

#

.close

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#
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vast shale
kind light
#

sure?

vast shale
#

i have to find the 5 number summary for a data set and i got 10, 10, 11, 12, 14

tender leaf
#

Find what

vast shale
#

the whole data set is 10, 10, 10, 10, 10, 11, 11, 11, 11, 12, 12, 12, 13, 13, 14

vast shale
kind light
#

i have no idea what 5 number summary is sry, openglobe probably does

tender leaf
vast shale
#

for the 5 number summary is it fine if numbers repeat?

tender leaf
#

The max and min can repeat

#

Q1 Med and Q3 are never outliers

vast shale
#

the min and q1 are both 10

#

everything else is different

tender leaf
#

Then the min isn’t an outlier

vast shale
#

but it is repeated

tender leaf
#

Still not an outlier because 10 is Q1

vast shale
#

so it's fine that both values are 10?

tender leaf
#

Absolutely

vast shale
#

i still dont really understand how to find the outlier

tender leaf
#

Wait

vast shale
#

are the outliers 8.5 and 13.5 then

tender leaf
#

I think I swapped it

#

Outlier<Q1-1.5(IQR)
Outlier>Q3+1.5(IQR)

vast shale
#

iqr is 2

tender leaf
#

Yes

#

So 1.5x is 3

vast shale
#

is it 10-1.5 (2)

tender leaf
#

That works

vast shale
#

i got 7

tender leaf
#

And any number less than the calculated value is an outlier

tender leaf
#

Now we have to perform the other string

vast shale
#

it asks for potential outliers

#

so should i put 7 in the "values below" blank?

tender leaf
#

Potential outlier<7

vast shale
#

for the other one i got 15

tender leaf
#

Outlier>15

vast shale
#

it also asks me to draw a box plot, do i need to plot the outliers too?

tender leaf
#

There are no outliers

vast shale
#

do i still need to plot the potential outliers?

tender leaf
#

All are between 7 and 15 inclusive

vast shale
#

should the box plot go from 7 to 15?

#

without plotting outliers

tender leaf
#

No

#

Lowest to highest

#

Given

#

Lowest is 10 highest is 14

vast shale
#

does the box go from 10-12 and the whisker to 14?

tender leaf
#

Yes

#

With median being 11

vast shale
#

i drew this but i didnt know how to draw the whisker for 10

tender leaf
#

There is no whisker for 10

#

Because 10 is minimum

vast shale
#

ok can i also get help with a stocks question?

tender leaf
#

I ran out of time

#

😦

#

Colon open parenthesis gave me that?

vast shale
#

its fine i can find someone else on my own

#

thx for the help

tender leaf
#

🙂

#

Oh my gosh

#

Why does discord do that

lost briar
#

6 numeros de 48 con mayor probabilidad de ser elegidos?

vocal sleetBOT
#

@vast shale Has your question been resolved?

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turbid charm
vocal sleetBOT
turbid charm
#

can someone please let me know if ive done this right

#

<@&286206848099549185>

flat whale
vocal sleetBOT
# turbid charm <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

turbid charm
#

sorry

vocal sleetBOT
#

@turbid charm Has your question been resolved?

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#

@turbid charm Has your question been resolved?

vocal sleetBOT
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quartz helm
#

How do I answer this? I've tried rationalizing the top, but I'm not sure what I can do from that.

obsidian stream
#

I doubt you will need to rationalize anything if you follow the hint instead.

quartz helm
obsidian stream
#

Rewrite it as t^6 = x

quartz helm
#

I'm getting t^3 - 1 / t^2 - 1

#

I'm going to try expanding them

#

Thanks I got it sunglas

#

.close

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unreal nest
#

how would i solve linear transformations like this

unreal nest
#

and also these questions

vocal sleetBOT
#

@unreal nest Has your question been resolved?

vocal sleetBOT
#

@unreal nest Has your question been resolved?

vocal sleetBOT
#

@unreal nest Has your question been resolved?

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@unreal nest Has your question been resolved?

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kind light
#

the distance between town A and town B is 36km, Alan left town A for town B and at the same time Betty left from town B for town A, after they met, Alan took 2h 30m to get to town B while Betty took another 1h 36m to reach town A, find Betty's speed

kind light
#

choices are A.6 B.7 C.8 D.9 E.10

#

using dmthe distance formula i get
D=S×T
36=A(alans speed)×(W1+5/2) (W1 is the time for alan and betty to meet)
36=B×(W1+16/10) but idk how to continue after that

#

heres like a diagram for it

#

36-AX=A×5/2
AX=B×16/10
36=5A/2+16B/10
360=25A+16B

vocal sleetBOT
#

@kind light Has your question been resolved?

kind light
#

<@&286206848099549185>

vocal sleetBOT
#

@kind light Has your question been resolved?

vocal sleetBOT
#

@kind light Has your question been resolved?

vocal sleetBOT
#

@kind light Has your question been resolved?

lament sandal
#

Oh you need help man

#

@kind light did they meet in the exact middle?

kind light
#

no

lament sandal
#

When did they meet?

#

And where?

#

It says “after they met”

#

@kind light

kind light
lament sandal
#

Ok so if at constant speed then they meet in middle

kind light
#

no

#

they have diffrent speeds

lament sandal
#

Oh so they meet at a different place

kind light
#

yea

lament sandal
#

But we don’t know what speed they were travelling before they met, nor do we know the speed before they met, nor the time too

kind light
#

yeah

#

thats why im asking how to

lament sandal
#

Are you sure that’s the question?

kind light
#

yeah

lament sandal
#

Send the picture

kind light
#

i dont have the exact papers on me, so its abit blurry (this was for a diffrent thing) but here

lament sandal
#

It’s ok I can read

#

I see now

twin meteorBOT
kind light
lament sandal
#

Maybe it’s trial and error?

kind light
#

how would you trial and error that

lament sandal
#

Betty
Time = 1h36m
Let Speed = 6
Distance = 1h36*6= 1.6 * 6 = 9.6km

#

Betty
Time = 1h36m
Let Speed = 7
Distance = 1.6 * 7 = 11.2km

Time = 1h36m
Let Speed = 8
Distance = 1.6 * 8 = 12.8km

Time = 1h36m
Let Speed = 9
Distance = 1.6 * 9 = 14.4km

Time = 1h36m
Let Speed = 10
Distance = 1.6 * 10 = 16km

#

Idk I’m lost too now

kind light
#

oh wait

#

you could check alan's speed for each betty speed and find if the time for alan from point x to town b matches the question

lament sandal
#

But how

kind light
#

wait

lament sandal
#

We only know Alan’s time and distance for each of the choices

#

So what will we do with the speed

kind light
#

Betty
Time = 1h36m
Let Speed = 7
Distance = 1.6 * 7 = 11.2km from a (24.8km from b)

Time = 1h36m
Let Speed = 8
Distance = 1.6 * 8 = 12.8km from a (23.2km from b)

Time = 1h36m
Let Speed = 9
Distance = 1.6 * 9 = 14.4km from a (21.6km from b)

Time = 1h36m
Let Speed = 10
Distance = 1.6 * 10 = 16km from a (16km from b)

#

wait

#

Betty
Time = 1h36m
Let Speed = 6
Distance = 1h366= 1.6 6 = 9.6km from a (26.4km from b)

lament sandal
#

36-16=20km
20km/2.5h=8kmph

36-14.4=21.6km
21.6/2.5h=8.64 kmph

kind light
#

if we use speed=6 we can get that the distance Alan traveled 26.4km took 5/2h

#

yeah basically trial and error

#

tysm!

lament sandal
#

I’m making a Python code for it lol

kind light
#

ok ima just let this open cause i wanna see

lament sandal
#

Yeah

#

I wanna too

#

NOO I LOST THE CODE

lament sandal
#

‘ ‘ ‘
import math
BettyDistance=[]
for speed in range(6,11):
BettyDistance.append(speed*16/10)
print (BettyDistance)

AlanDistance=[]
for x in range(len(BettyDistance)):
AlanDistance.append((BettyDistance[x] - 36)*-1)
print(AlanDistance)

AlanSpeed = list(Distance/0.25 for Distance in AlanDistance)
for speed in AlanSpeed:
speed = speed/10
print (f"When Alan's speed is {speed}, Betty's speed is {(36-speed*2.5)/1.6}")
‘ ‘ ‘

#

import math
BettyDistance=[]
for speed in range(6,11):
    BettyDistance.append(speed*16/10)
print (BettyDistance)

AlanDistance=[]
for x in range(len(BettyDistance)):
    AlanDistance.append((BettyDistance[x] - 36)*-1)
print(AlanDistance)

AlanSpeed = list(Distance/0.25 for Distance in AlanDistance)
for speed in AlanSpeed:
    speed = speed/10
    print (f"When Alan's speed is {speed}, Betty's speed is {(36-speed*2.5)/1.6}")

#

[9.6, 11.2, 12.8, 14.4, 16.0]
[26.4, 24.8, 23.2, 21.6, 20.0]
When Alan's speed is 10.56, Betty's speed is 6
When Alan's speed is 9.92, Betty's speed is 7
When Alan's speed is 9.28, Betty's speed is 8
When Alan's speed is 8.64, Betty's speed is 9
When Alan's speed is 8.0, Betty's speed is 10

#

Thanks this was a good project! @kind light

#

Ping me if you need

#

Going now bye

vocal sleetBOT
#

@kind light Has your question been resolved?

lament sandal
#

Still?

vocal sleetBOT
#
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lament sandal
#

.reopen

#

.reopen

lament sandal
#

@vocal sleet reopen

vocal sleetBOT
#
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vague vessel
vocal sleetBOT
vague vessel
#

? How’s this wrong

thin vale
vocal sleetBOT
vague vessel
#

X^3(x^2-16)

#

X=0,-4,4

wide fiber
#

Potentially try “0” 3 times

#

^ try that first

vague vessel
#

Bruh doesn’t work

#

On top it says enter all answers using the appropriate multiplicities

#

Idk what that means

fleet blade
#

pls help me

#

Jasim has seven cards numbered 2 to 8
2345678
Jasim takes at random three of these cards.
He works out the sum of the numbers on the three cards and records the result.
Work out the probability that the result is an odd number.

vague vessel
#

Webassign is literal L website I pay $40 for this

vocal sleetBOT
#

@vague vessel Has your question been resolved?

spiral inlet
#

x^3(x^2-16)

#

notice that you have x=0 three times

#

webassign is probably looking for 0, 0, 0, -4, 4

vocal sleetBOT
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static ore
vocal sleetBOT
static ore
#

Can I get some help

karmic crane
#

First of all they state that 0<a<1, so which of the three equations should you choose

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frosty robin
vocal sleetBOT
frosty robin
#

How do u get from the second arrow to the third

#

Where didnthe 1/(3y)^1/3 come from

vocal sleetBOT
#

@frosty robin Has your question been resolved?

ebon rapids
#

Think the solution factored out the thing so that you wouldn’t have fractions in the square root

frosty robin
#

@ebon rapids how does that get factored

#

I see that they how they got rid of the fraction inside the square root

#

But where did the outside fraction come from

twin meteorBOT
#

CST (please ping when replying)

ebon rapids
#

Does this make sense?

frosty robin
#

@ebon rapids yes but why do we need that 1/(3y)^(1/3) outside the square root

ebon rapids
#

Again, the solution just doesn’t want fractions inside the square root

#

It’s a style choice more than anything

twin meteorBOT
#

CST (please ping when replying)

frosty robin
#

OH

#

Lol okay got it thanks

#

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velvet cove
#

$\int d(x+2)$

vocal sleetBOT
twin meteorBOT
pale perch
#

whats up

#

youre integrating 1 wrt (x+2)

velvet cove
#

ye

velvet cove
pale perch
#

indeed

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wooden stump
vocal sleetBOT
wooden stump
#

I went about the proper way to find the derivative and used quotient rule on both df/dx and dy/dx

#

but it resulted in (x^2+y^2)^2 in the denominator which is 0 when (x,y) = (0,0)

#

so i thought maybe the partial derivative doesn't exist

#

but the answer is literally just

#

i feel like you can't just use that right? something feels wrong, like how in considering if a limit exists, you have to think of infinite ways to approach the point, not just along the x and y axis

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#

@wooden stump Has your question been resolved?

wooden stump
#

got it, using definition of partial derivative so $\frac{\partial f}{\partial x}|{(x,y) = (0,0)} = \lim{h \to 0} \frac{1}{h} f(h,0) - f(0,0)$

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#

omgatriple

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sullen dragon
#

i don't know how to keep doing this problem

sullen dragon
#

is dv/dt 1/sqrt(v)?

#

(0,0)
(2,9)

#

<@&286206848099549185>

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thorny rapids
#

@viscid halo

vocal sleetBOT
#

Please don't occupy multiple help channels.

viscid halo
#

@thorny rapids hey!

#

@thorny rapids just wondering if I can help with the final problem on this order of operations sheet

#

It's the bottom one I can't solve

viscid halo
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fallow gorge
#

I am unsure what to do with this problem, it's a linear expression problem

fallow gorge
#

.close

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pliant urchin
#

Hi

vocal sleetBOT
pliant urchin
#

(1-cosx)/(1+tan^2x)^2 = 1/((1+cosx)(3+cot^2x+3tan^2x+tan^4x))

#

Prove it

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timber marlin
#

I'm getting 625.1 years for c but the answer is 6251 years where am I losing a power

flat whale
#

Did you do a correctly

timber marlin
#

I thought I did till you said that lol

#

Is that not the correct formula?

flat whale
#

Idk I'm asking

#

Since you have the answers

timber marlin
#

I don't think so

#

Thanks though

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south ruin
#

I'm trying so solve for -k because it's the constant I need in order to find the rest of the problem, but I'm stuck on what to do after I get to the point where it's shown on my paper. I included the original problem in case I left out any information

mild flower
#

use the fact that after 10 minutes it's at 240F

south ruin
#

I tried that on my first attempt but it didn't work, I tried dividing 240 by 365 and using that as the constant but it said I was wrong

#

I'm pretty sure it wants me to simplify the original equation and then take the natural log but idk how to do that or steps after that

mild flower
#

but like set up your equation of cooling

#

like set up $T = T_s + (T_0 - T_s)e^{-kt}$ for the time from 0 to 10 minutes

twin meteorBOT
#

hayley

mild flower
#

and you'll get your answer for k

south ruin
#

Oh ok that makes a lot more sense than what I was doing

#

Oh yeah 0.0556 there it is, thank you so much!

#

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elfin moon
vocal sleetBOT
elfin moon
#

Is this true?

peak axle
#

Looks good to me

#

I can't think of any column operations, I don't think they exist in a capacity in which they would be useful

elfin moon
#

I see

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Thanks

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pliant urchin
#

Prove
(1-cosx)/(1+tan^2x)^2 = 1/((1+cosx)(3+cot^2x+3tan^2x+tan^4x))

regal parrot
#

[ \frac{1-\cos x}{(1+\tan^2x)^2} = \frac{1}{((1+\cos x)(3+\cot^2x+3\tan^2x+\tan^4x))} ]

twin meteorBOT
#

daniGhost (ping reply in help)

regal parrot
#

This?

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graceful marlin
#

Hello what's the most significant term between these two?

in our module, it says that both of them are equally significant. but how come they are?

hard atlas
#

!original

vocal sleetBOT
#

Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

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chrome peak
#

can anyone help me with this problem? I have no idea where to start, I already found the derivative in a previous part to be -y/x+y

heavy yoke
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@chrome peak Has your question been resolved?

chrome peak
heavy yoke
#

yes

chrome peak
#

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dull blade
#

How do I plot this in Excel?

vocal sleetBOT
dull blade
#

What I mean by that is

#

I have the data and I know my plot is supposed to look like that

#

Just dk how to get that plot

#

Here's the data

#

with a correspondence between flowrates of 1 - 10, 2 - 13, and 3 - 16

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.close

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pliant urchin
#

Prove

vocal sleetBOT
pliant urchin
#

[ \frac{1-\cos x}{(1+\tan^2x)^2} = \frac{1}{((1+\cos x)(3+\cot^2x+3\tan^2x+\tan^4x))} ]

twin meteorBOT
tidal umbra
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
#

@pliant urchin Has your question been resolved?

pliant urchin
#

(1+tan^2)^2=1/cos^4

tidal umbra
#

!show

vocal sleetBOT
#

Show your work, and if possible, explain where you are stuck.

pliant urchin
#

Can't

#

Send photos

#

<@&286206848099549185>

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placid osprey
#

[ \int_0^{\infty} \frac{2x - 4}{x^3 + 1} dx ]

I am attempting to demonstrate that this integral is convergent. I have been considering the comparison test for integrals, particularly comparing the given expression with (\frac{1}{x^2}) for (x \geq 1), as (x^3 + 1) grows faster than (x^2) as (x) approaches infinity.

For (x \geq 1), I've established the following:
[0 \leq \frac{2x - 4}{x^3 + 1} \leq \frac{2x}{x^3} = \frac{2}{x^2}]

Now, I am looking to integrate these expressions from 1 to infinity, and I am aware that the integral of (\frac{2}{x^2}) from 1 to infinity converges to 2.

However, I would appreciate any insights, suggestions, or alternative approaches that might help me solidify this conclusion and effectively demonstrate the convergence of the given integral.

twin meteorBOT
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@placid osprey Has your question been resolved?

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@placid osprey Has your question been resolved?

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@placid osprey Has your question been resolved?

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hushed flint
vocal sleetBOT
hushed flint
#

Anyone understand this? I'm confused as I thought R^2 would be like x, y but this question has x, y, z

sly sierra
#

T takes a vector in R^3 and maps it to a vector in R^2
that's what the notation T : R^3 --> R^2 means

#

(x y z) is the "input" vector from R^3

#

(x+y, y-z) is the "output" vector in R^2

hushed flint
#

I was thinking not since I have 3 values at the right side ?

cyan talon
#

you just need to take two vectors not 3 yeah

#

also you forgot to apply the transformatin

#

that's not T(x+y+z)

#

@hushed flint

hushed flint
#

do I need to multiply it by that other matrix or something?

cyan talon
#

wym mutiply

#

you still don't know the matrix of T

#

T(x, y, z) is (x+y, y-z), with (x, y, z) is one vector

hushed flint
#

oh..

cyan talon
#

also calling your 3d vectors x, y and z might be confusing

hushed flint
#

I thought T(x, y, z) was my T(x + y) and then the (x+y, y-z) was the T(x) + T(y)

#

In my textbook the only example similar is this, is this what I’m trying to do ?

cyan talon
#

yes

#

it's pretty much exactly the same question

hushed flint
#

So I’m a bit confused why mine is wrong haha

cyan talon
#

T(3d vector) is a 2d vector in your new question

cyan talon
#

you straight up just recopied x+y+z

#

it's like if I say f(x) = 2x+5, and I ask you what f(2) is and you tell me it's 2

hushed flint
#

How do u know what matrix to apply to the T(x y z) to turn it into x+y, y-z

cyan talon
#

ofc I know

#

you don't need to find the matrix to show it's a linear transformation tho

hushed flint
#

But how do I show it without multiplying by the matrix

cyan talon
#

you straight up have the defnition of what T(x, y, z) is

#

use it

#

if $a = \begin{bmatrix} a_1\a_2\a_3\end{bmatrix} $ and $b = \begin{bmatrix} b_1\b_2\b_3\end{bmatrix}$ then $$T(a+b) = T\left(\begin{bmatrix} a_1+b_1\a_2+b_2\a_3+b_3\end{bmatrix}\right) = \begin{bmatrix} (a_1+b_1) + (a_2+b_2)\(a_2+b_2)-(a_3+b_3)\end{bmatrix}$$

twin meteorBOT
#

aPlatypus

cyan talon
#

it's like you forgot the T was even there

#

T is a function taking 3d vectors and outputting 2d vectors

#

@hushed flint

hushed flint
#

@cyan talon

cyan talon
#

it doesn't prove it

#

I'm just correcting your algebra

#

from there you can go on

cyan talon
#

be mindful of your notation

hushed flint
#

Ohh I get it now I think

#

Why do the textbooks have to overcomplicate the explanations tho

#

I didn’t even know that transformations were just functions

cyan talon
#

just a fancy name for function

#

T : R^3 -> R^2