#help-17

1 messages · Page 95 of 1

signal flicker
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so its false right?

merry cosmos
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yes

vocal sleetBOT
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@pliant hinge Has your question been resolved?

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crimson pumice
#

Could someone help to explain the logic of this?

crimson pumice
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ok so if you look at question b line 2 to 3, the teacher does it by flipping the dP/dt to get dt/dP, but what is the thought process for doing that?

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this one more close up

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because I would do it the same as I would do those newton cooling/ heating up questions

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but I know these popualtion questions you need to flip it at some point because

vocal sleetBOT
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@crimson pumice Has your question been resolved?

crimson pumice
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<@&286206848099549185>

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aw man 😦

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anyone?

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welp

#

.close

vocal sleetBOT
#
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wraith pelican
#

can someone help me solve this like, how should i approch solving this? do i like get A into reduced row echleon form ?

vocal sleetBOT
#

@wraith pelican Has your question been resolved?

vocal sleetBOT
#

@wraith pelican Has your question been resolved?

vocal sleetBOT
#

@wraith pelican Has your question been resolved?

heady ibex
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you just have to apply A to x and equate it to b

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you then have 3 solutions of which one does not contain an x_i

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3 equations

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not solutions

noble lily
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^

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RREF for this problem is unnecessarily

vocal sleetBOT
#

@wraith pelican Has your question been resolved?

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tough kraken
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Hello

vocal sleetBOT
tough kraken
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Can someone help me with this problem

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I ain't doing so great with fractions

warped gazelle
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ok

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if you do opposite way, it's way more simple

tough kraken
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opposite way?

warped gazelle
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like you are proving A = B, you could also prove B = A

tough kraken
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Um, a is given to be equal to 3/25 + 3/5*8 + ... + 3/(3n-1)(3n+2)

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And I have to prove that 3/(3n-1)(3n+2) is equal to something or can be rewrited as smth

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there is no b

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also, this is a part of the a, not the whole nr, so, there is no such thing like A = B and opp

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or, am I wrong?

warped gazelle
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hmm?

tough kraken
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hmm?

split wind
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hmm?

warped gazelle
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ok

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it's very satisfying sum

tough kraken
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I don't get, am I wrong with smth?

warped gazelle
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for example

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hmm

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just 3/(3x-1)(3x+2) = 1/(3x-1) - 1/(3x+2) is calculated

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and can get something like this: 3/2*5 = 1/2-1/5

tough kraken
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so, what should we do first?

warped gazelle
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we just change everything in the sum like that

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1/2 - 1/5

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1/5 - 1/8

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1/8 - 1/11

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...

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1/(3x-1) - 1/(3x+2)

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then we sum everything

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1/2 -1/5 +1/5 -1/8 +1/8 -1/11 + ... + 1/(3x-1) - 1/(3x+2)

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all the middle part is gone

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1/2 - 1/(3x+2)

tough kraken
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so it's smth like that, right?

warped gazelle
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now you know the most satisfying sum in math

tough kraken
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Sorry for my bad writing, it's a pc after all

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um, what should I do now?

warped gazelle
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it's plus minus same thing

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results in zero

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except for

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very edge parts of the

tough kraken
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um

split wind
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Well, to prove that $\frac3{(3n-1)(3n+2)}=\frac1{3n-1}-\frac1{3n+2}$, you can start from the Right Hand Side first.

twin meteorBOT
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Biscuity

split wind
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first step would be to find the common denominator and expand the fractions

tough kraken
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wait a bit

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I'm confused at the first part

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how is this 0?

warped gazelle
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ok

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that's not zero

tough kraken
warped gazelle
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oh you confused because of that

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the MIDDLE PART results in zero

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for example

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-1/5+1/5 is 0

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-1/8 + 1/8 is 0

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...

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-1/(3x-1)+1/(3x-1) = 0

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and the only things left are

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1/2 and -1/(3x+2)

tough kraken
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ooh

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this and so on

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got it

split wind
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nice!

tough kraken
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for me, which I ain't dealing so good with this is satisfaying, ain't gonna lie

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so

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what we doin' from now?

warped gazelle
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hmm

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is there anything given for that

tough kraken
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a

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not really

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Oh

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Actually yes

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I have to find a

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this is the 2nd request

warped gazelle
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then what is n

tough kraken
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the first request of the exercise is this

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Omg, I don't know how to express myself

warped gazelle
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wait what

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are you talking about

tough kraken
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Problem 3

warped gazelle
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LOL

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what is the number

tough kraken
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Se considera numarul a means A is given to be equal

warped gazelle
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a = 33/ ?

tough kraken
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at a) we need to prove this equality

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where n is in N without 0

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N*

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b) = to calculate nr a

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and c) find n which makes part of N* with a=33/70

tough kraken
warped gazelle
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then you did everything except c

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you just make equation

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and solve it

tough kraken
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I didn't did a)

warped gazelle
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oh

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let's take a look at a)

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1/(3n-1) - 1/(3n+2)

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is

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(3n+2)/(3n-1)(3n+2) - (3n-1)/(3n-1)(3n+2) right?

tough kraken
warped gazelle
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hmm?

tough kraken
tough kraken
warped gazelle
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yes

tough kraken
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this is where I've stopped

warped gazelle
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something written you showed to me

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said

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if that is equal to 33/70,

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what is the value of n

tough kraken
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c) - Find N who is part of N* knowing that a = 33/70

warped gazelle
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then, do you need help on calculating that equation?

tough kraken
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um

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wait

warped gazelle
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yes

tough kraken
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i hate this writing

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um, now,

warped gazelle
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that's my writing 2 years before 💀

tough kraken
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wait

warped gazelle
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let's work out anyway anyway

tough kraken
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um

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can we do derivate ratios

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right

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?

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I hope this is the thing I'm meaning

warped gazelle
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hmm

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i didn't study math in english

tough kraken
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neither did I

warped gazelle
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unfortunately, that's not possible

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when you are doing that kind of thing,

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it should be like this:

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A/B = C/D

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so

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AD = BC

tough kraken
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so

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then

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let this be the main img

warped gazelle
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ok

tough kraken
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so, what are we doing frm now?

warped gazelle
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we

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just

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uh... what's that called....

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you just do something like this:

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A+B = C

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A = C-B

tough kraken
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a and C being which one

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and B

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A and B *

warped gazelle
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that's just an example of doing that math thingy

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in this case,

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1/2 being A, -1/(3x-2) being -B, 33/70 being C,
A-B = C

A-C = B

tough kraken
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oh

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the thing is I don't really have any Idea how to calculate

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1/2-1/(3n-2)

warped gazelle
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so

tough kraken
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oh

warped gazelle
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you do something transposition ( iguess)

tough kraken
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3n is 3 * 33/70

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right?

warped gazelle
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yes? (sus)

tough kraken
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why sus

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lol

warped gazelle
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goahead

tough kraken
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a

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no

warped gazelle
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lol

tough kraken
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I don't htink I'm right

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think

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I tought n = 30/70

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but this is a

warped gazelle
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ok i'll draw the solution on my computer

tough kraken
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we are finding N

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fuck mslf

warped gazelle
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can you understand this?

tough kraken
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oh

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Yes

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I understand what u did

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I didn't know that was possible

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Or maybe I did but I couldn't associate

warped gazelle
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well, we usually explain this as weight

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if we add something on Left Hand, we also add the exact same thing on Right Hand and it's equal

tough kraken
warped gazelle
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yes good

tough kraken
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still don't know how to calculate

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um

warped gazelle
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you calculate the number first

tough kraken
#

we should amplify first by 45?

warped gazelle
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hmm,

tough kraken
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or it doesn't work like that

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to have a commo n denominator

warped gazelle
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i think you should calculate the number side; Left Hand Side

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can you calculate 7/2 - 33/70?

tough kraken
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this is what am I asking you

warped gazelle
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ok

tough kraken
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how to get the same denom

warped gazelle
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7/2 - 33/70 is

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7x35/2x35 - 33/70

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did you understand what i did?

tough kraken
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isn't it 1/2?

warped gazelle
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no

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fraction is something like this

tough kraken
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oh

warped gazelle
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uh yeah that's true

tough kraken
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I thought u switched 1 by 7 by mistake

warped gazelle
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i think you should have better handwriting 💀

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well,

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that doesn't mean that you should get better writing forms

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you just need to seperate something like 1 and 7

tough kraken
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there is an obv difference from nr to nr in my hwriting

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just saying

warped gazelle
#

e

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ok

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1/2 - 33/70

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anyway

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(trolll)

tough kraken
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are u balkan? srry to task

warped gazelle
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1/2 is

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35/70 right?

tough kraken
#

a

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theoretically yes

warped gazelle
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theoretically :skulll

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ok

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so

tough kraken
#

lmao

warped gazelle
#

1/2 - 33/70
= 35/ 70 - 33/70
= 2/70 right?

tough kraken
#

yes

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affirmative

warped gazelle
#

so

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it is 1/35

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right?

tough kraken
#

yes

warped gazelle
#

wait i am drawing

tough kraken
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this is satisfaying tho

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but I don't know how u get this ideas

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this fast

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Actually, maybe also is just that I never saw exercises like this

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maybe If I'd work more on them, I could do them faster

warped gazelle
tough kraken
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so

warped gazelle
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wait

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i just noticed that

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you mistaked something

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the initial question was 3n+2 but not 3n-2

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so

tough kraken
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hm?

warped gazelle
#

so

tough kraken
#

ooh

warped gazelle
#

1/35 = 1/3n+2

tough kraken
warped gazelle
#

so we do the holy thingy

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35 = 3n+2

tough kraken
#

yea

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u are right

warped gazelle
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i am sure that you can find integar n

tough kraken
#

is the one w +2

warped gazelle
#

lul

tough kraken
#

so

warped gazelle
#

simple simple

tough kraken
#

so

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we have n = 11

warped gazelle
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yay

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finally

tough kraken
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which makes part of N*

warped gazelle
#

after 2.539 eternity

tough kraken
#

so this is good

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hehe

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thank you so much for not feeling to kll yslf after talking w me

warped gazelle
#

ok good bye

tough kraken
#

lmao

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have a nice day

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:))

warped gazelle
#

eeeeeeeeeeeeeeeeeeeee

tough kraken
#

tysm

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are u balkan

#

x2

#

x3

#

x4

warped gazelle
#

no

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x2

#

x3

tough kraken
#

oh

warped gazelle
#

x395302395

tough kraken
#

where are u from

warped gazelle
#

hehe

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somewhere east west

tough kraken
#

Oooooooh

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antractica

#

got it

warped gazelle
#

(wt0

tough kraken
#

antarctica

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srryh

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I misspeled cuz I was worried about the cold air from there

warped gazelle
#

kills myself for 1 consecutive second by sneezing

tough kraken
#

ok bye I love u bye

#

have a nice dayt

warped gazelle
#

.close

tough kraken
#

nono

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I am the one who ends it

tough kraken
vocal sleetBOT
#
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covert ridge
#

which one is correct and why?

vocal sleetBOT
paper depot
#

can a number be equal to 2 and -1 at the same time?

covert ridge
#

No

simple mason
# covert ridge No

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Don't forget to close the channel using
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covert ridge
#

Why is implication true when beginning condition is false?

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Is it set like that by default?

paper depot
#

there are a bunch of different explanations for that concept

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it's called vacuous truth

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but basically like

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imagine that i tell you, "If it rains tomorrow, I'll give you $1000"

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and imagine that the next day it does not rain, and i don't give you the money.

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have i broken my promise?

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@covert ridge

covert ridge
paper depot
#

exactly.

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so in that scenario, my promise is kept.

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i.e. my statement was true.

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do you agree?

covert ridge
#

Yeah.

paper depot
#

right

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in fact, with sunny weather on the following day, i'll have kept my promise no matter what i do.

covert ridge
#

so for the second one in that pic it should be true since those are the only roots possible and false for the first one since a number can't have 2 values?

charred forge
#

Yes

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Also Ann that’s a very good example

covert ridge
#

What if I do this?

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What difference does that left head make?

#

can I replace that double sided arrow with the phrase "if and only if?"

vocal sleetBOT
#

@covert ridge Has your question been resolved?

vocal sleetBOT
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jolly mulch
#

Its a stupid thing but english is not our first language and it has me stomped that I cant answer my kids homework

sand hedge
#

the first part i assume you know means the number is between 56 and 65

jolly mulch
#

Yes

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Is it 64 because it means

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It needs a 4 at the end?

sand hedge
#

yes

jolly mulch
#

Because it the ones god damn it

sand hedge
#

if you want to explain it to your kid, they were taught about how you can splt numbers into 10's, ones etc

jolly mulch
#

I tought it meant it needed 4 one literal 1111

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I was like wtf

sand hedge
#

example:

63 = 6 tens, 3 ones

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or

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152 = 1 100's, 5 10's and 2 1's

jolly mulch
#

Thanks and sorry for taking from your time

sand hedge
#

its better than doing the math im doing rn lol

cyan shadow
#

I only know it means the other way because that way makes no sense

jolly mulch
#

Lol its good that I wasn't the only confused then

sand hedge
#

this could be good practice for him, its just an image i found on the internet

cyan shadow
#

It should say "It has a 4 in the one's place" - that is clear and umambigious

jolly mulch
#

But I get it they are learning that and it was obvious that the ones meant like the single number not literal ones

sand hedge
#

just like you would say 900 has 9 100's

cyan shadow
#

yeah thats right, it just doesn't work for 1s

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once you go to 10 then the meaning switches to the other one

jolly mulch
cyan shadow
#

but i think the persons question was answered regardless

jolly mulch
#

Yes it was answer thank you very much

paper depot
jolly mulch
#

Does this closes automatically or do I have to input something?

cyan shadow
#

.close

vocal sleetBOT
#
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woeful hull
#

Getting stuck, not sure how to complete the proof

woeful hull
#

I don't think I am doing this right

#

Wait

#

if I say f^p is int

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and I write out how exponents work

#

so like d * d *d ... p times

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then i can factor d

#

so n^p = d * k

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which proves it

#

but idk if thats write

#

<@&286206848099549185>

amber bridge
woeful hull
#

thanks

#

just need to write it out

jovial remnant
#

It is just missing more clarification at the end

vocal sleetBOT
#

@woeful hull Has your question been resolved?

woeful hull
vocal sleetBOT
#

@woeful hull Has your question been resolved?

woeful hull
#

.close

vocal sleetBOT
#
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astral notch
#

Is there a way to somehow represent this as a series of dots in desmos?

astral notch
#

Or is desmos only strictly used for functions?

#

Where v is on the y-axis and t is on the x-axis

vocal sleetBOT
#

@astral notch Has your question been resolved?

vocal sleetBOT
#

@astral notch Has your question been resolved?

vocal sleetBOT
#

@astral notch Has your question been resolved?

heady ibex
#

desmos can have points

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and tables

#

afaik

vocal sleetBOT
#

@astral notch Has your question been resolved?

astral notch
# heady ibex and tables

That was what I was asking about, but at the same time, I am asking for a way to place them out efficiently.

#

Like, after the expression that I wrote.

#

And it's not like really a function, what I am doing here is kinda different.

#

You can try placing them out yourself after the pattern I wrote here, and you get exhausted pretty early. There has to be a tool for this, why wouldn't there be?

heady ibex
#

i cannot really read what you wrote

astral notch
astral notch
heady ibex
#

a is just a number?

astral notch
heady ibex
#

you're basically just integrating

#

idk what it's called other than integrating

#

it's numerical integration of differential equations

astral notch
heady ibex
#

you can do it using python

#

idk if you can do it using desmos

astral notch
astral notch
heady ibex
#

for visualization just use matplotlib

astral notch
#

Cause I don't think I can make a nice graph out of this expression like you can with like y = 2^x or something like that

heady ibex
#

for the maths just use python maybe use numpy

#

numerical integration

astral notch
heady ibex
#

is finding the next point using previous points

astral notch
astral notch
heady ibex
#

numerical integration

#

there was a subject in university for using it to solve problems in physics and astronomy in my university

vocal sleetBOT
#
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tardy flint
vocal sleetBOT
tardy flint
#

where am i going wrong 😭

grizzled halo
#

check domain of f as well?

tardy flint
vocal sleetBOT
#

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idle salmon
#

can someone tell me how to prove this question whether it's false/true please? i don't know what kind of formula that i have to use

pallid zenith
pallid zenith
#

yes

#

okay, now i select 2 numbers randomly from the numbers 1 through 7

#

will the average of these two numbers always be higher than 4?

idle salmon
#

Depends? if i choose 1 &2 it's lower than 4

pallid zenith
#

yea

#

and if you choose 6 and 7 then no

#

and if you choose 3 and 5 its exactly 4

idle salmon
pallid zenith
#

so it seems like we could have a case where anything could happen

#

and we cant say for sure

#

you might get unlucky and pick some high numbers or super low ones

#

do you see how this is related to your question?

idle salmon
#

could i answer this question with "false" ?? cause it's not always in a true condition

pallid zenith
#

unless im missing the trick yea

idle salmon
#

okay got this, thanks!!

vocal sleetBOT
#

@idle salmon Has your question been resolved?

vocal sleetBOT
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balmy pulsar
#

guys can someone verify if this statement is true or not?

$a^{p-1} \equiv 1 \mod p$ if a and p are coprime

twin meteorBOT
#

CrazyCuber217

balmy pulsar
#

i know its fermats little theorem but im not sure if it still holds if p isnt necessarily a prime number

#

and the wikipedia page wasn't very clear

proven garden
#

if p is not a prime then it becomes Euler's theorem

balmy pulsar
#

ohh ty

#

but its still always true right?

proven garden
#

if a and n are coprime then $a^{\varphi(n)}\equiv 1 \mod n$

balmy pulsar
#

phi?

#

where'd that come from?

proven garden
#

it's euler's toitient function

balmy pulsar
#

wouldn't it just be n-1 in the exponent?

balmy pulsar
twin meteorBOT
#

WhereWolf(ping if needed)

proven garden
#

phi(n) is the number of natural number coprime to n that is smaller then n

balmy pulsar
#

T-T

proven garden
#

The Euler's formula is a generalization to Fermat's little theorem

balmy pulsar
#

okok

#

i didn't rly understand the phi thing, but as long as a and p are coprime, the theorem holds right?

#

even if p isnt prime

#

for a^(p-1) only

proven garden
#

if p is a prime then a^(p-1) is congruent to 1

balmy pulsar
#

yep

proven garden
#

if p is not a prime then no

balmy pulsar
#

if a and p are coprime?

proven garden
#

then you can only say that a^phi(b) is congruent to 1

balmy pulsar
#

then?

#

u sure? sorry for doubting but google's giving varied results and i wanted to clarify

proven garden
#

I think they assumed p is prime

balmy pulsar
#

ohh ok makes sense

#

tysm!

#

.close

vocal sleetBOT
#
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proven garden
#

no problem

vocal sleetBOT
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balmy pulsar
#

random question

vocal sleetBOT
balmy pulsar
#

related to previous question

#

fermats little theorem is only applicable if a is not a multiple of p, and p is prime

#

but what if a and p are merely coprime?

#

i randomly tried a few examples where p isn't prime but a and p are coprime and all of them still were congruent to 1 mod p

#

is this just a coincedence? if this new conjencture is false, could someone give an example where it's not true?

proven garden
#

what examples have you tried?

balmy pulsar
#

a = 13, p = 6
a = 13, p = 4
a = 2, p = 9

#

oh nvm i found one

#

a = 7, p = 9

#

tysm

#

.close

vocal sleetBOT
#
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noble lynx
vocal sleetBOT
warped gazelle
#

hmm

#

did you learn sum

#

formulas

noble lynx
#

yaya

warped gazelle
#

ok

#

r(r+1) = r^2 + r

#

you can just split them

noble lynx
#

i lied what is that

#

IM SORRY

warped gazelle
#

so

noble lynx
#

what is r^2 + r

warped gazelle
#

hmm

#

$r(r+1) = r^2 + r$

twin meteorBOT
#

A_Note

noble lynx
#

yes makes sense

warped gazelle
#

then

#

you use formulas

#

of

#

r^2

#

and r

noble lynx
#

wait why

#

did you convert it

warped gazelle
#

hmm?

#

let's suppose

#

there's sum called a

#

and another

#

called b

noble lynx
#

just write sigmaew

warped gazelle
#

ok

#

just doing a+b

#

like

#

sigma k=1 (r^2 + r) = sigma k=1 r^2 + sigma k=1 r

noble lynx
#

ya

warped gazelle
#

makes sense?

noble lynx
#

yes

warped gazelle
#

so

noble lynx
#

got it

#

understand

warped gazelle
#

sigma k=1 r^2 = n(n+1)(2n+1) / 6 did you learn that?

noble lynx
#

what

#

okay wait i've learnt everything

#

but i dont understand

#

what method of proving i need to use

#

pmi?

warped gazelle
#

you use something.. called..

noble lynx
#

contradiction?

warped gazelle
#

no

noble lynx
#

what

warped gazelle
#

you dont use contradiction when getting the exact value

noble lynx
#

inductionnn?

warped gazelle
#

k

#

you just some everything of these:

#

suppose you are working out

#

sigma k=1 n (k^2)

#

so

#

$2^2 - 1^2$

twin meteorBOT
#

A_Note

noble lynx
#

THIS'LL TAKE SO LONGGUHUHUHUH

warped gazelle
#

$3^2 - 2^2$

twin meteorBOT
#

A_Note

noble lynx
#

CAN YOU DO IT FOR ME

#

🙏

#

i'll understand from working

#

promisuh

warped gazelle
#

uh

#

i think i'll just write down in my note and show you

#

lol

noble lynx
#

yes ty

#

solve please

#

i have sm work and its all due tom i'm legit crying

#

not really

warped gazelle
#

wait it might take minutes

#

do some other things

noble lynx
#

yesuh ty

warped gazelle
#

ok i'm transporting the image through the device. would take 2 more minute

#

i dont know

#

lol

#

IF you dont understand sigma k=1 n (k) =n(n+1)/2,

#

1,2,...,n the average is (n+1)/2 and the amount is n

noble lynx
#

i

#

i think im gonna cry

warped gazelle
#

uh

noble lynx
#

THANK YOU

#

but i think im gonna go take a nap

warped gazelle
#

lol

noble lynx
#

i'll go through it later yty

warped gazelle
#

i think the last part is a little dark for you

vocal sleetBOT
#

@noble lynx Has your question been resolved?

vocal sleetBOT
#
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vast shale
vocal sleetBOT
autumn quartz
#

Hi

#

oh come on

vast shale
#

Lol sorry

vocal sleetBOT
#

@vast shale Has your question been resolved?

coarse gust
#

So both of the triangles are similar

#

Small triangle with have hypotenuse 5

#

Then what will be the length of n with similar triangles?

#

@vast shale

coarse gust
vocal sleetBOT
#
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ebon idol
#

In the figure, ABCD is a square and △EDC is an equilateral triangle. Prove that
(i) AE=BE
(ii) ∠DAE=15

ebon idol
#

help

#

pls help

#

or i cry

warped gazelle
#

lol

#

△ADE≡△BCE for the first

1, ∠ADE = ∠BCE = 150°
2, AD = BC
3, DE = CE

#

△ADE is isosceles triangle so ∠ADE = 90° + 60° = 150°
∠DAE = (180°-150°)/2 = 15° is for the second

ebon idol
#

how is ade isosceles trianogle

#

tell fast

warped gazelle
#

because

#

AD = DE

#

because

#

AD = DC and DC = DE

#

sorry but i was eating 🍞

ebon idol
vocal sleetBOT
#

@ebon idol Has your question been resolved?

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winter bison
#

Hello! I need help with this exercise:


- There are an infinite number of numbers that belong to the interval```
From my point of view, this statement is true. I think it is true because between the value -2 and -3 for example, there can be -2.5, -2.005, -2.99......

I know that maybe this statement refers to intervals that have the infinity symbol [-∞, +∞], but I'm stuck because maybe the statement can be true in this case.

Thanks!
fleet ember
#

it's true

vocal sleetBOT
#

@winter bison Has your question been resolved?

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winter bison
#

thanks! @fleet ember

vocal sleetBOT
winter bison
#

.close

vocal sleetBOT
#
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thick wolf
vocal sleetBOT
thick wolf
#

Is this correct?

#

Oh

#

First term is 22

#

1150

mint crypt
#

Yes, 1150 is correct

thick wolf
#

Part b

#

First 10 rows at 20 dollars each

#

*40 dollars

#

Got it

#

.close

vocal sleetBOT
#
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warm swift
#

Hey, I'm doing this exercise for Fourier analysis. So far I'm a bit stuck on the hint. Where can I apply this?
(\bf{Exercise:}) Let (f_k : [-\pi, \pi] \to \mathbb{C}) be a sequence of continuously differentiable functions, and let (f'_k \to g) uniformly as (k \to \infty). Suppose (a \in [-\pi, \pi]), (c \in \mathbb{C}), and (f_k(a) \to c) as (k \to \infty). Then, (f_k) converges uniformly to a function (f : [-\pi, \pi] \to \mathbb{C}) with (f' = g).

warm swift
#

So please give me some pointers to get started :)

twin meteorBOT
#

Vepnar

warm swift
#

The hint is to use the fundamental theorem of calculus

#

<@&286206848099549185>

vocal sleetBOT
#

@warm swift Has your question been resolved?

vocal sleetBOT
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proven garden
#

Let ≤ be the relation defined on the set A={1, 4, 13, 17, 221, 52} by the rule: x≤y iffx|y.

proven garden
#

Guys how is this antisymmetric?

vocal sleetBOT
#

@proven garden Has your question been resolved?

heady ibex
#

if x <= y

#

then x | y

#

but if x != y

#

then y !| x

#

so y !<= x

#

$\begin{rcases} x \leq y \Rightarrow & x | y \ & x \neq y \end{rcases} \Rightarrow y \nmid x \Rightarrow y \nleq x$

twin meteorBOT
#

Katharine

heady ibex
#

@proven garden I hope that helps

#

I hope it's clear too

#

cuz idk if it is

proven garden
#

So I am not sure if I can claim this is antisymmetric

heady ibex
#

what's the problem with 17|221

proven garden
#

17/=221

heady ibex
#

i'm not sure i understand what you're saying

proven garden
#

The relation R is antisymmetric, specifically for all a and b in A if R(x, y) and R(y, x), then x = y

heady ibex
#

Exactly

#

Your relation is defined as

#

If xRy then x is a divisor of y

#

Yes?

proven garden
#

yes

heady ibex
#

if x | y then y = nx

#

in order for y | x, x = my

#

y = nm y

#

so n = 1 and m = 1

#

as both need to be natural numbers

#

meaning only when x = y can x | y and y | x both be true

#

and so the same applies for the relation you have

#

unless your relation has some other properties

vocal sleetBOT
#

@proven garden Has your question been resolved?

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nova delta
#

hi

vocal sleetBOT
nova delta
#

im having trouble with induction. let me just grab the photo

#

its mainly the k-3

#

I get this^ but how do i express the formula of C(k+1)

stable sigil
#

its written above?

#

3Ck

nova delta
#

where did you get that answer? i only have one shot at this since webassign allows 5 tries and i used up 4/5 of them lol

#

at first i thought it was 3c+1

vocal sleetBOT
#

@nova delta Has your question been resolved?

nova delta
#

<@&286206848099549185>

vocal sleetBOT
#

@nova delta Has your question been resolved?

gleaming hare
#

r_n+s_0=124 ig

vocal sleetBOT
#

@nova delta Has your question been resolved?

vocal sleetBOT
#

@nova delta Has your question been resolved?

vocal sleetBOT
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sudden pike
#

hi

vocal sleetBOT
ornate ember
#

hi, did you have a question?

sudden pike
#

.rotate

#

anyways i have no clue how to get x

ornate ember
#

,rccw

twin meteorBOT
cold breach
#

um

#

that is 4 squared

#

not 6

sudden pike
cold breach
sudden pike
#

4^2 = 16

cold breach
#

yeah but, you are supposed to square 6, not 4

sudden pike
#

what 6

#

there is o 6 in the image

sudden pike
#

OH

#

FUCK

#

i put 4

#

instead of 6

#

im a dumbass

cold breach
#

yeah

sudden pike
#

thanks for helping me realize

cold breach
#

lol

sudden pike
#

.close

vocal sleetBOT
#
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fiery wasp
#

this author uses nonstandard terminology: he calls a "tower" a chain of sumodules of the form {0} \subset M_0 \subset \dotsb \subset M_n = M and he calls the "height of the jordan-holder tower" the length of the composition series (which he calls a jordan-holder tower). so M being an R-module of finite height means that there exists a (finite) composition series

i can do this problem easily just by using the fact that h(im f) + h(ker f) = h(M), where h(M) is the height of an R-module M and f : M --> N is an R-morphism. i don't need to do what the hint says at all. what is he trying to get me to see with this hint?

fiery wasp
#

maybe this is better in the algebra channel. i didn't think of that

vocal sleetBOT
#

@fiery wasp Has your question been resolved?

vocal sleetBOT
#

@fiery wasp Has your question been resolved?

vocal sleetBOT
#

@fiery wasp Has your question been resolved?

vocal sleetBOT
#

@fiery wasp Has your question been resolved?

valid void
vocal sleetBOT
#

@fiery wasp Has your question been resolved?

vocal sleetBOT
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tribal holly
#

yo

vocal sleetBOT
tribal holly
#

boys

#

fact or cap

strong grove
#

,rccw

twin meteorBOT
tribal holly
hard atlas
#

well ^ is never written out on paper

tribal holly
#

ik but i did because

#

i put the numbers next to

strong grove
#

seems ok, u can simply the power tho

tribal holly
#

too*

viral copper
tribal holly
#

i can simplify more?

hard atlas
#

simplify 4/12

tribal holly
#

by divde by 4

#

1/3

#

?

strong grove
#

yeah

tribal holly
#

,rccw

twin meteorBOT
tribal holly
#

is this fact or cap?

strong grove
#

seems good , u can simplify 2/4 further also

tribal holly
#

but im confused

#

look

#

--?

strong grove
#

same base multiplying , powers add

proven garden
#

why --

#

when multiplying you add

tribal holly
#

oh

real pagoda
#

isnt it +-

tribal holly
#

its not minus

#

because

#

the exponent tihngs

#

isnt in fraction

#

mb

tribal holly
tribal holly
strong grove
#

x^2 . x^3 = x^(2+3)

tribal holly
#

oh ye

strong grove
#

same base (x)

tribal holly
#

when multiply same base and you have powers

#

you can just add

#

ok

#

ty boys

#

.close

vocal sleetBOT
#
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odd scaffold
vocal sleetBOT
odd scaffold
#

How do part ii I don’t know where to start

#

,rotate

twin meteorBOT
proven garden
#

notice that a^2+b^2 can be factored into (a+bi)(a-bi)

odd scaffold
#

Ya

#

Now what?

calm lantern
# odd scaffold Now what?

Another solution involves noticing that |wz| = |w| |z| = 1
In other words, (-33/65)^2 + (56/65)^2 = 1

#

And from this equality, you can deduce 65^2 = ......

odd scaffold
#

Lemme try that

#

Okay

#

I got $33^2 + 56^2 =65^2$

twin meteorBOT
#

Sukiie

odd scaffold
#

But how would I proceed finding the other solution?

calm lantern
#

Well that's a good question 😂

#

Are parts (a) and (b) related?

odd scaffold
#

Yea

calm lantern
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How did you do?

odd scaffold
#

Actually nvm

#

Idk how to get the other one

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<@&286206848099549185>

winter canyon
#

quiz pls

odd scaffold
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Huh

winter canyon
#

mention it

odd scaffold
#

It’s just tutoring homework from a company called Dr du

winter canyon
odd scaffold
#

No

#

Just hw

winter canyon
#

thn

#

bruh

odd scaffold
#

.close

vocal sleetBOT
#
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tropic anchor
#

no.1 I'm stuck halfway

vocal sleetBOT
tropic anchor
#

<@&286206848099549185>

#

<@&286206848099549185>

vocal sleetBOT
#

@tropic anchor Has your question been resolved?

tidal trail
#

Why did you equate your 2 unknowns? (idk y but ended up same as my working so meh)
Ur doing pretty well up till now

Now after ur last line, compare "a" and "b" respectively (compare the coefficient, make sure the signs match)

vocal sleetBOT
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knotty kestrel
vocal sleetBOT
knotty kestrel
#

lemme just work thru it first

#

so its 2(cos(2x-1)) * -sin(2x-1) * 2

#

2 times 2 = 4 times -1 [from the -sin] = -4

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where does the cos go

#

it disappears

livid tapir
#

Sin(2theta) = 2sin(theta)cos(theta)

knotty kestrel
#

oh right

#

ok thx

#

.close

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hollow thorn
vocal sleetBOT
hollow thorn
#

Can somebody teach me part (a)

paper depot
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
hollow thorn
#

I have no idea how to get 15.86 % as well

#

Since I probably know that the probability is 0.1586

#

Oh I knew it 0.5793 - 0.4207

vocal sleetBOT
#

@hollow thorn Has your question been resolved?

hoary arch
#

THEY SAY X IS NORMALLY DISTRIBUTED. THIS MEANS X CAN BE DESCRIBED USING 2 VARIABLES: MEAN, μ = 15 & STANDARD DEVIATION, σ = 5

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hoary arch
vocal sleetBOT
hoary arch
#

~~
IN ORDER TO USE THAT Z-TABLE FOR OUR X-VARIABLE WE NEED TO "STANDARDIZE" IT.
TO STANDARDIZE X INTO Z WE USE:

Z = X - μ / σ

#

FOR YOUR QUESTION, WE NEED TO FIND 2 PROBABILITIES:

  1. P(X < 16) STUDENT GETTING AT LEAST 1 STAR
  2. P(X < 14) STUDENT GETTING 2 STARS
#

TURNING THAT INTO Z:

  1. || P( X - μ / σ < (16-15)/5 ) , P( Z < 0.2 )||
  2. || P( X - μ / σ < (14-15)/5 ) , P( Z <-0.2 )||
#

FROM THERE READ OFF THE Z-TABLE , I ASSUME YOU KNOW HOW TO

#

AND THE QUESTION IS ASKING FOR STUDENTS WHO ONLY GOT 1 STAR , SO ITD BE THOSE WHO GOT AT LEAST 1 STAR - THOSE WHO GOT 2 STARS

#

@hollow thorn

small valley
#

y'+2/x+2 y= 3

vocal sleetBOT
#

@hoary arch Has your question been resolved?

#
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vocal sleetBOT
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mellow rampart
#

Prove that if the limit of a sequence exists, then it is unique

mellow rampart
#

Attempt:

#

Suppose $(x_n) \to a$ and $(x_n) \to b$. Then for all $\epsilon > 0$, there is $N \in \mathbb{N}$ such that for all $n \ge N$, $|x_n - a| < \epsilon$. Similarly, for all $\epsilon > 0$, there is $N \in \mathbb{N}$ such that for all $n \ge N$, $|x_n - b| < \epsilon$.

twin meteorBOT
mellow rampart
#

How can I go about showing some contradiction?

paper depot
#

assume a ≠ b for the sake of contradiction

#

wlog let a < b, or something

mellow rampart
#

If $a < b$, then the $N_a$ such that for all $n \ge N_a$, the sequence should be trapped between $a \pm \epsilon_a$

twin meteorBOT
mellow rampart
#

hm I think I have something else

#

.close

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mighty dust
#

what exactly is a derivative and how do I get it

mighty dust
#

I know these equations
$$ lim_{x\to x_0} \frac{f(x)-f(x_0)}{x-x_0} $$
$$ lim_{h\to 0} \frac{f(x+h)-f(x)}{h} $$

twin meteorBOT
#

N1x1T4

mighty dust
#

But what do they even mean?

pale perch
#

theyre basically the formula m=(y2-y1)/(x2-x1)

mighty dust
#

you mean the slope?

pale perch
#

but as h->0 or x->x_0 youll get the exact derivative of the point (basically) of x

pale perch
#

the derivative of a function gives you the slope of whatever point

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the slope of the tangent to that point to be specific

mighty dust
#

But what is a slope

#

I know it can be seen

pale perch
#

rate of change of y with respect to x

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dy/dx means a small change in y over a small change in x, ie the slope (when i say small i mean infinitesimal)

mighty dust
#

so the derivative is the slope of a specific value in the function

pale perch
#

if you drew a tangent line to any point of a function, the derivative gives you the slope of the tangent of said point

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which is the same as the slope of the function at that point

mighty dust
#

but why would I want to know the slope of a function at a certain point (except for when it's zero i.e. the peak or bottom of the function)

pale perch
#

you basically cant do advanced physics without using derivatives, they come up everywhere

mighty dust
#

Well I know that It is used when calculating acceleration. But so basically it's application is mostly in physics?

pale perch
#

its extremely used in applied maths and physics etc, basically any stem field will have you using derivatives in some way

mighty dust
#

ok, ok

#

well thank you

#

.close

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#
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