#help-17

1 messages · Page 88 of 1

karmic imp
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One test isn't going to ruin everything.

slim lily
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that's what i told shah, but apparently this whole server is just about maths, maths and maths

obtuse radish
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1 test never ruins anything bro; but either way dont discourage him @karmic imp check yt and khan acad bro; doesnt seem like we can help

blissful sentinel
azure zinc
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my math scores in the past hasnt been the best already

karmic imp
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Schools look at your gpa, if you have a 4.0 and you fail one test in one subject, you won't get knocked down to a 1.0

obtuse radish
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wow bro u just wasting ur time here at this point; just going to sleep or messaging a classmate is better bro

slim lily
azure zinc
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...

vocal sleetBOT
slim lily
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but can't understand everything because i don't know all the math terms in english

azure zinc
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Pls tell me what you don’t understand I’ll try to translate or even simplify it

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Well I don’t want to be wasting my time, I actually want to get a good grade at this test

obtuse radish
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am i supposed to somehow care abt ur little story? @slim lily i think u've already helped quite a lot this past 20min

azure zinc
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Please it’s already really late for me and I have to wake up early

obtuse radish
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if u not gonna trust me its fine but bro this place isnt guaranteed help; msg a friend; wake up early and study

slim lily
azure zinc
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Mehdi can you help me out

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I think these questions are the most important

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If I can at least get them right I might be able to achieve a decent grade

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This is question 8 graph

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By my friend

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Hello?

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<@&286206848099549185>

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Please

blissful sentinel
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I can help I guess

azure zinc
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Tysm

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All I need to do is the second part

blissful sentinel
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What is the question though? I don't understand what you've written down

azure zinc
blissful sentinel
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Right but I don't understand those questions lol

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Can you type them here in complete sentences

azure zinc
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Sure

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Wait let me ask for more clear ss

blissful sentinel
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Is this homework that you're getting from a friend?

vocal sleetBOT
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@azure zinc Has your question been resolved?

blissful sentinel
#

Ping me whenever you reply

vocal sleetBOT
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foggy shore
#

how can I prove easily that sqrt(5) + sqrt(7) is irrational. I tried to assume for the sake of the contradiction that it was, in fact, a rational number, so that:

sqrt(5) + sqrt(7) = a/b, where a and b have no common factors. got some weird result in regards to a being equal something with b, but it also contained a on the other side.

river wagon
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Try squaring

shadow spindle
foggy shore
shadow spindle
foggy shore
shadow spindle
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Suppose sqrt(5) + sqrt(7) is a rational number, what do you get when you multiply it by sqrt(5) - sqrt(7)?

foggy shore
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5-7

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-2

shadow spindle
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Exactly, now take sqrt(5) + sqrt(7) to the other side of the equation

foggy shore
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what do you mean?

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to the equation: sqrt(5) + sqrt(7) = a/b, or?

shadow spindle
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No, we won't use that definition for this proof, since it will be hard to find a contradiction

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(√5 + √7)(√5 - √7) = -2
(√5 - √7) = -2/(√5 + √7)

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This shows that (√5 - √7) is also a rational (Since division by 2 rationals is a rational, and we supposed that √5 + √7 is a rational)

foggy shore
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oh, I see

shadow spindle
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Now if you sum them what do you get?

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I mean, (√5 + √7) + (√5 - √7)

foggy shore
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2sqrt(5)

shadow spindle
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Yep, sum of two rationals is also a rational

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and if you divide that result by 2, it should also be a rational (since 2∈ℚ)

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but we know that √5∉ℚ, which is a contradiction

foggy shore
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right, but from the get-go, we also knew that sqrt(7) is also not a part of Q.

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and don't we also know that the sum of two irrational numbers is also irrational?

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so from that point, it's easy to prove

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expect for like sqrt(2) + (-sqrt(2)), or something like that

foggy shore
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what if we write sqrt(5) + sqrt(7) as an x, where we assume that x is a rational number

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and do the calculations

shadow spindle
foggy shore
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technically, we could get to a form where we have x on one side and an irrational number on the other side, which would prove that it is not true to say that sqrt(5) + sqrt(7) is a rational number

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right?

shadow spindle
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Yep, but you would have to manage to get that result in the first place

foggy shore
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[Proving that sqrt(7) + sqrt(5) is irrational]

Certainly, let's use a different approach to prove that (\sqrt{5} + \sqrt{7}) is irrational without explicitly introducing the ratio (a/b).

Proof:

Assume for the sake of contradiction that (\sqrt{5} + \sqrt{7}) is rational.

Square both sides of the equation (\sqrt{5} + \sqrt{7} = x), where (x) is a rational number:

[(\sqrt{5} + \sqrt{7})^2 = x^2]

Expand the left side of the equation using the FOIL method:

[5 + 2\sqrt{35} + 7 = x^2]

Combine the constants on the left side:

[12 + 2\sqrt{35} = x^2]

Now, we have:

[2\sqrt{35} = x^2 - 12]

Rearrange the equation:

[\sqrt{35} = \frac{x^2 - 12}{2}]

Now this, we do know that is irrational. [\sqrt{35}] is not part of Q, we know that already.

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This is what I got from my good old pal, GPT

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here is a better picture

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calculations seem legit

shadow spindle
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Yep, I supposed it would be easier to get a good proof with √5 rather than √35, since it should have been proven before

cunning shale
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hi

vocal sleetBOT
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@foggy shore Has your question been resolved?

vocal sleetBOT
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limber tiger
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What is the difference between the slope of a tangent line and secant line and how do you identify when to use each?

vocal sleetBOT
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@limber tiger Has your question been resolved?

vocal sleetBOT
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@limber tiger Has your question been resolved?

flat whale
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Lines only have one slope

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But a curve may have different tangent lines at different points on the curve

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And a secant line isn't a tangent line

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It's a line that's formed by two points on the curve

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Whereas tangent lines are formed only by one point on the curve

vocal sleetBOT
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@limber tiger Has your question been resolved?

vocal sleetBOT
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vast shale
vocal sleetBOT
vast shale
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can someone proof read my work

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for some reason it’s not adding to 0

west raptor
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What's the original question?

vast shale
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create 5 vectors that will create a state of equilibrium with the given equillbrant (13N N27degreesW)

vocal sleetBOT
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@vast shale Has your question been resolved?

west raptor
vast shale
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yeah 13 newtons and then north 27 degrees west

west raptor
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Ok so we need 5 vectors that when added up with the 13N N 27° W vector we have 0?

vast shale
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yeah

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and when we make the vectors they can’t be parallel or perpendicular

vast shale
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i have a copy of the assignment that i can send in a bit

vocal sleetBOT
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halcyon plover
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Slope of Secant line = f(2) - f(0) / 2 - 0

halcyon plover
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(0 , f(0)) (2,f(2))

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f(x) = distanced travelled in km , x = 0 at start of the race

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how can I find the slope without an equation, I have no idea what the graph should look like

urban edge
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You know the average velocity

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Which is the slope of the secant line

halcyon plover
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I guess f(0) = 0 since at the beginning of the race he travelled nothing

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I know the average velocity at the first 2 hours mark and the average velocity

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so would I just do 45 - 39 / 2?

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6/2 = 3

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but that doesn't sound right

urban edge
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Lets start here: whats f(2)?

halcyon plover
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39

urban edge
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Not quite

halcyon plover
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x = 0 at start of the race? so I'm guessing 2 is 2 hours after

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which gives my average velocity to 39 no?

urban edge
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Reread the problem

halcyon plover
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time in x (in hours)

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I'm not sure what to look for

urban edge
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Two hours after the start ... a cyclist passes the 78-km mark

halcyon plover
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correct

urban edge
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So what is f(2)

halcyon plover
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oh no way

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f(2) = 78

urban edge
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Indeed

halcyon plover
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I thought it was the velocity

urban edge
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Can you figure out the slope of the secant line from there?

halcyon plover
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like I found it, it's 39

urban edge
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Yeah

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Avg velocity is slope of secant line

halcyon plover
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assuming f(0) is the start of the race which should be 0 right?

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if f(0) is just 0, it would just be 78 / 2 = 39

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... I'm kind of upset at myself for not seeing it earlier

urban edge
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It happens, glad you could get it fixed

halcyon plover
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Also because it basically asked the same thing twice that I didn't think it could be the same answer

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but thanks a lot for the help

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.close

vocal sleetBOT
#
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urban edge
#

Youre welcome

vocal sleetBOT
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dusty void
vocal sleetBOT
dusty void
#

can someone help me

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answer this question

cold hedge
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Ok wow that took a second to do in my head

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!status

vocal sleetBOT
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
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@dusty void Has your question been resolved?

dusty void
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What

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I’m still confused

vocal sleetBOT
#

@dusty void Has your question been resolved?

solemn cape
# dusty void What

So to know the speed the plane goes you can use $s=\frac dt$ where $d$ is the distance and $t$ the time he took to do the distance.

twin meteorBOT
#

Joseph.P

dusty void
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okay

solemn cape
#

And s is the speed

solemn cape
vocal sleetBOT
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finite anvil
vocal sleetBOT
finite anvil
#

i'm not really sure what to do here

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do I distribute the t, then set one vector equal to the other to find that t value? then what?

pale perch
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i assume youre aware of the dot product?

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you only need to focus on the direction vectors and find the angle between them

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thats equivalent to finding the angle between the lines

finite anvil
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are the direction vectors the ones with a t next to them?

pale perch
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t and s, yes

finite anvil
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so I do the dot product of <6,2,8> and <-3,-6,-1>?

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like the one with the cos theta in it

pale perch
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cos, but yeah

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solve for theta

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check its the smallest angle though, it can help to draw a diagram for that

finite anvil
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How would I check that?

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like if it's 340 do I say the smallest is 20

pale perch
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youll either get the b or the a

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note they will sum to 180 so you can subtract one from 180 to get the other

finite anvil
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ah

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okay let me try part a...

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r(t) dot r(s) = -18+-12+8 = -22

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-22 = |r(t)| |r(s)| cos(theta)

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-22 = sqrt(104)*sqrt(46)*cos(theta)

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arccos(-22/(sqrt104*sqrt46)) = 108.55

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180-108.55 = 71.75

pale perch
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check your last line

finite anvil
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hmm, am I not supposed to subtract from 180? It is the larger angle...

pale perch
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what youre doing is fine

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the result is wrong

finite anvil
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oh wait

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71.45

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heh

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so how come I use the direction vector here?

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What do the first set of vectors (without the t/s) indicate?

pale perch
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the first set of vectors are a position vector for some point that lies on the line
the direction vector is a vector that determines the direction of the line, you can get any point on each line by changing the value of s or t respectively

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so for any two lines, the angle between the direction vectors is the angle between the lines when extended infinitely

finite anvil
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Ah, gotcha

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Thanks!

pale perch
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i should probably note you can only find the angle between lines that will actually intersect at some point, but that may be obvious

finite anvil
#

yea makes sense

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.close

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forest plume
#

What's another way to write out 42 times 57? At first I tried (40x50) + (2x7) and realized it's wrong. What is an easy way to think it out like this? Thx

pale perch
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40x57+2x57?

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which is also 4x10x57+2x57

halcyon wing
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7* 6 *57 = (44.5-2.5)(44.5+2.5)= 44.5^2-2.5^2

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(40+2)(50+7)

forest plume
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Thanks

#

.close

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blazing trail
#

Not sure what steps to take from here to get the final answer

blazing trail
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No?

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:/

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#

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cunning saddle
#

help

vocal sleetBOT
cunning saddle
#

with this

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why out 3/2?

karmic imp
vocal sleetBOT
#

@cunning saddle Has your question been resolved?

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vast shale
#

would anyone know how to do this porblem (linalg)

unborn coral
#

Find the nullspace (kernel or whatever you call it) of the matrix formed by [v1 v2 v3] and then just scale it so that the first entry is 1

vast shale
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ah ok

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thanks

#

.close

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halcyon plover
vocal sleetBOT
halcyon plover
#

I found average velocity in A by substituting 1 and 4 into x^2 + x

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which gave me 20 and 2

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so the change would be 20 - 2 / 4 - 1 = 18 / 3 = 6

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but for B, f(1) = 2 and f(1+h) = h^2 + 2h + 1

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so the velocity would be h^2 + 2h + 1 - 2/1+ h - 1 which really just h

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h^2 + 2h -1 / h is not factorable

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so how can I proceed?

unborn coral
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Isn't f(1) = 2 and f(1+h) = h^2 + 3h + 2? It's y = f(x) = x^2 + x

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But your answer seems to be based off just f(x) = x^2

halcyon plover
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let me check

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ah

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I see

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yes you are right

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so it should be h^2+3h/h

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which I can factor out an h

unborn coral
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yup!

halcyon plover
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but that doesn't give me the average velocity right?

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at least entering 3 gives me the wrong answer

unborn coral
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It's not 3, it's h + 3

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It will depend on h

halcyon plover
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but h approaches 0

unborn coral
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Not yet

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Thats at part c

halcyon plover
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ok so I can't just plug that in

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and is instantaneous velocity just the derivative?

unborn coral
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well yes but also that's exactly when you let h approach 0

halcyon plover
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even thought it says x = 1?

unborn coral
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the average velocity between t = 1 and t = 1+h is h+3, so instaneous is let h = 0

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I guess I mean x, not t, but yes we have from x = 1 to x = 1+h right

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so you just set h = 0 for instaneous velocity at x = 1

halcyon plover
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which would be 3

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ok thank you! I always try to plug in 0 at h when I see limit approaching 0

unborn coral
#

Haha no limits in averages! only instantaneous

halcyon plover
#

thanks a lot!

#

.close

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#
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vast shale
#

Many income tax systems are calculated using a tiered method. Under
a certain tax law, the first $100 000 of earnings are subject to a 35%
tax; earnings greater than $100 000 and up to $500 000 are subject to
a 45% tax. Any earnings greater than $500 000 are taxed at 55%.
Write a piecewise function that models this situation.

vocal sleetBOT
vast shale
#

Find the value of k that makes the following function continuous.
Graph the function.
f (x)= { x^2-k, if x <-1
2x -1, if x >= -1

twin meteorBOT
#

Statufi
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vocal sleetBOT
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@vast shale Has your question been resolved?

vast shale
#

no

twin meteorBOT
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Statufi

vast shale
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thats not what the questons asking lol

twin meteorBOT
#

Statufi

vocal sleetBOT
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@vast shale Has your question been resolved?

vast shale
#

BOI. WHATS LIM

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ive never heard of it

turbid glade
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Limit

vast shale
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nah im not doing limits

turbid glade
#

Sorry for that, i don't know your math background

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That's ok

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You just have to find a k that makes the two expression of your function coincides at -1, so replace x by -1 and solve

vast shale
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can u explain a lil. more

turbid glade
#

You want to have k such that $x^2-k=2x-1$ for $x=-1$

twin meteorBOT
#

Statufi

turbid glade
#

Because you know how f behaves to the left of -1 and to the right, and you want these two pieces to be connected at -1 so there values must be equal

vocal sleetBOT
#
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mental furnace
#

anyone here has a video that can teach me in about 2-3 days Analytic Trigonometry II (SummDiff, Mult Angle, Power Red, ProdSum, SumProd) and fundational trigonometric identities 😄 we got exam in a week
by teach i mean master that shit 😄

flat whale
#

Khan academy

mental furnace
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anymore?

karmic imp
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Youtube

mental furnace
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no i mean either a channel name or a website..

flat whale
#

You're not gonna watch all of Khan videos in 3 days

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Help channels are for specific problems. Come back when you start doing them

karmic imp
#

Like look up that topic in youtube, watch the videos

mental furnace
#

aye thx

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crisp agate
#

Im in calculus 3 and I just want to know if my answers are correct to my questions?
I tried to graph both of these and i can show my sketches so im unsure 😓

crisp agate
#

pulling up my phone to show sketches

#

sorry for the bad sketched

#

this is byfar my worst math

#

💀

#

ignore #3, i'm working on that one rn

#

@high abyss

#

<@&286206848099549185>

#

uh

#

😭

#

Ig while I wait I'l lzoom the questiosn in

#

^ I updated to a Family of Circles

#

<@&286206848099549185>

spiral inlet
crisp agate
#

@spiral inlet the first question looks like 2 parabolic graphs on the xy plane right??

spiral inlet
crisp agate
#

hyperbolas*

spiral inlet
#

yeah, it's a set of hyperbolas. the two different directions come from if f(x,y) is positive or negative

crisp agate
#

so x^2 - y^2 would also be correct

spiral inlet
#

but x^2-y^2 = z gives hyperbolas with a vertical or horizontal axis of symmetry

#

no, x^2 - y^2 gives a hyperbola, but one with a horizontal or vertical line of symmetry

#

not the diagonal ones like we see in that graph

#

a diagonal hyperbola is like xy = 1

#

or like, you're probably more familiar with it in the form y = 1/x

crisp agate
#

yep that is more recognaizable

#

so that means

#

f(x,y) = xy

#

would be the correct answer as it is not horizontal line of symmetry nor vertical

#

this one is diagonal

spiral inlet
#

yes

crisp agate
#

@spiral inlet may i check my work with one more question?

#

i already finished it and can send neat outlined work

spiral inlet
#

sure

crisp agate
#

Question/:

crisp agate
spiral inlet
#

for the ln, you should have 2-y > 0, not just 2-y not equal to 0

crisp agate
#

oh 💀

spiral inlet
#

ln(x) is not defined in the reals for negative x

crisp agate
#

so y > 2

#

that also changes the graph so i need to resketch it

spiral inlet
#

y < 2

crisp agate
#

the -

#

right

spiral inlet
#

yeah

#

Your graph looks mostly right, you just shouldn't have the bigger area on the top right

#

just the bit by the origin

crisp agate
#

so my update graph

#

should just be that section?

#

or both of the secitons

spiral inlet
#

that's where y > x^2 (above the parabola) but y < 2 (below the line)

#

and yeah x being positive or negative doesn't make a difference

crisp agate
#

👍

#

if you dont mind as well soryr to hold oyu

#

could you explain the 2nd question furtheR?

#

i just completely wildly guessed with the x^2 + y^2 and the 2x

#

Repost as to not scroll @spiral inlet

spiral inlet
#

oh yeah sure

#

seems like you are pretty familiar with the general equations for conic sections?

#

you recognized x^2 - y^2 as a hyperbola

crisp agate
#

iffy but yeah that's the unit we're working on

spiral inlet
#

are you pretty comfortable with like the equation of a circle, ellipse, etc

crisp agate
#

yes

spiral inlet
#

so the equation of the curve given is $z = \frac{2x}{x^2+y^2}$ where $z$ is the height of the function where we're taking the level curve

twin meteorBOT
#

tatpoj

spiral inlet
#

$$z = \frac{2x}{x^2+y^2}$$
$$z(x^2+y^2) = 2x$$
$$zx^2 + zy^2 = 2x$$

twin meteorBOT
#

tatpoj

spiral inlet
#

if you gather the x terms, and gather the y terms (there's only one in this case), and complete the square on each, you will find an equation for a circle

crisp agate
#

so it would be
(zx^2 + 2x + 1) + zy^2 = 2x + 1?

spiral inlet
#

not quite, I haven't actually done it out on paper yet, one sec

#

are you comfortable with completing the square?

crisp agate
#

yes

#

i understand how to do it and the lesson itself, i think here just the z is throwing me off 😵‍💫

spiral inlet
#

well we just have to treat z as a constant

#

since, for any single level curve, it is a constant

crisp agate
#

ok so treating z as a constant i like ot think of any constant as just "1" in the scenario

#

x^2 + y^2 = 2x

(x^2 - 2x + _ ) + (y^2 + 0y + 0) = 0

(x^2 - 2x + 1) + (y^2) = 1
(x-1)^2 + (y)^2 = 1

add back in z i believe

(zx-1)^2 + (zy)^2 = 1?

spiral inlet
#

well, you can interpret z as 1z, but you can't just interpret it as 1

#

$$zx^2 + zy^2 = 2x$$
$$(zx^2 - 2x) + zy^2 = 0$$
$$z(x^2 - \frac{2}{z}x) + zy^2 = 0$$

twin meteorBOT
#

tatpoj

spiral inlet
#

this is how I would start

crisp agate
#

so then i would get

#

z(x^2 - 2/z*x + 1/z^2) + zy^2 = 1/z

spiral inlet
#

yes 👍 awesome

crisp agate
#

and to make it look like the circle equation fomr of (x-h)^2 + (y-k)^2 = r^2

#

i need to simplify the first part of the circle equation

spiral inlet
#

well just finish completing the square, yeah

crisp agate
#

would you re-distribute the z back in to help with this part?

spiral inlet
#

$x^2 - \frac{2}{z}x + \frac{1}{z^2} = (x-\frac{1}{z})^2$

crisp agate
#

zx^2 - 2x + 1/z

(zx - 1/z)^2?

twin meteorBOT
#

tatpoj

spiral inlet
#

sorry, bad at tex lol

#

leave the z out of it

crisp agate
#

ok

#

yeah that makes sense

#

i would double check the answer with foil to mkae sure too

#

so with level curves, z would be treated as a constant

#

then try to get it to fit within a certain type of equation shape

#

whether it's a sphere, ellipse, circle, cone, etc

spiral inlet
#

well it'll be 2d so not a cone or sphere

#

but yeah

crisp agate
#

oh hence the 2d answers

spiral inlet
#

it's a 2d curve formed at a specific level (value of the function)

#

yeah

crisp agate
#

yeah sorry my professor was sick during this stuff

#

so we had to teach ourselves 💀

spiral inlet
#

oof that's never good

crisp agate
spiral inlet
#

yeah and

#

even as far back as zx^2 + zy^2 = 2x

#

you can already kind of see that it's going to be a circle

crisp agate
#

yuh that's how i guessed

#

circle

spiral inlet
#

since the x^2 and y^2 terms both have the same coefficient: z

#

they are scaled by the same amount

crisp agate
#

just didnt know the math to actually get to the formula like in case it was an FRQ and not MCQ like the last one

spiral inlet
#

oh yeah I gotcha

crisp agate
#

so a scenario to look out for hyperbola

spiral inlet
#

completing the square like we did here should always work, but you might have to do it on both the x and y parts

crisp agate
#

is to get it to be 1/x and 1/y

and parabola would be different coefficients of x and y?

spiral inlet
#

hm

#

I think you'll recognize hyperbolas like that if you can make the x's and y's multiply with each other

#

like y = 1/x

#

xy=1

#

no other conic section is going to have a term like xy

crisp agate
#

okok

#

and what abt parabolas?

#

just one of them is x^2

#

and the other is to a degree of 1

#

right

spiral inlet
#

yes

crisp agate
#

ty for the advice

#

abt just treat z

#

as a constant

#

i was not told that 💀

spiral inlet
#

well, do you have sort of a picture in your head of what a level curve is?

crisp agate
#

it's like

#

you have a 3d curve on the plane

#

the 3d curve's projection onto the xy axis

#

is the level curve

#

i think

spiral inlet
#

well, i wouldn't quite describe it as a projection

#

like imagine you have this function f(x,y) = whatever

#

every point has a (x,y) input that determines the output z

crisp agate
#

mhm

spiral inlet
#

right, so the height of the surface represents the output z

crisp agate
#

z = height of surface

spiral inlet
#

imagine chopping this with a horizontal plane, like at a height of 0.4

#

do you see that the cross section would be a circle?

crisp agate
#

yeah

spiral inlet
#

that is the level curve for z=0.4

#

we chose a "level" of 0.4

#

and that circle is specifically defined to have a z of 0.4

#

so z is constant: 0.4

crisp agate
#

so the level curve at 0 would be kind of like 2 circles?

spiral inlet
#

yeah, even 3 maybe

#

hard to tell how high that ripple comes

#

but yeah

crisp agate
#

so what's the purpose and stuff of finding domain for level curves??

spiral inlet
#

well essentially it's the set of values that satisfies an equation like f(x,y) = 0.4

#

if you want your function to output a certain value, the level curve is the set of all inputs (x,y) that give that value

crisp agate
#

Does finding the domain only tell us like

#

how the graph would look like on a 3d plane?

spiral inlet
crisp agate
#

so wherever the graph was

#

or has a z value

#

it's shaded

spiral inlet
#

yeah, wherever z is defined

crisp agate
#

okay tysm for ur help tn!

#

.close

vocal sleetBOT
#
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hearty dragon
#

I don’t really know how to start on this either

merry python
#

if a+b is a factor of the equation, then setting a=-b in the polynomial must yield zero

twin meteorBOT
hearty dragon
#

How do I factorise it tho

merry python
#

divide it by (a+b)

vocal sleetBOT
#

@hearty dragon Has your question been resolved?

hearty dragon
#

Ok lemme try

#

Wait how do I divide it

#

Ohh ok I get it now

#

Thanks

#

.close

vocal sleetBOT
#
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chrome sail
#

Help please

vocal sleetBOT
#

Please don't occupy multiple help channels.

chrome sail
#

Math 124 it’s algebra

cyan shadow
chrome sail
cyan shadow
#

could you take a screenshot instead of a picture of your screen

chrome sail
#

No I can’t it’s a practice test

#

It’s locked

#

Sorry

#

I could take a better photo tho

#

As good as it gets

#

?

#

<@&286206848099549185>

vocal sleetBOT
#

@chrome sail Has your question been resolved?

grizzled halo
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
#
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vocal sleetBOT
#
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viral quarry
#

Why here when i add 60 degrees it counts up to 330 but the correct answer is 300

viral quarry
twin meteorBOT
viral quarry
#

Here i add 30 and its righr but why is. the 60 wrong

twin meteorBOT
viral quarry
#

<@&286206848099549185>

neat wave
#

sorry, I can't read your handwriting. What is the problem to solve

viral quarry
#

let me log into pc its easier to thpe there one sec

neat wave
#

np

viral quarry
#

so basically, in second picture, i have complex number -sqrt(3)-i, and then i get that the angle is -30 and -30, and Re<0 Im>0 so i draw the angle 30 in the third sector anticlokcwise, and i get 180+30 = 210 degrees and thats right

#

but in first, i have complex number 1/2 - sqrt(3)/2 * i , and i get that sin angle = -60 and cos angle = 60, and as re < 0 , and im > 0 its fourh sector so i draw the angle in fourth sector and i get angle 270+60=330 but thats not what i should get, so i want to know did i draw it wrong or what

neat wave
#

you mean 270 + 60?

viral quarry
#

yes

#

sorry

neat wave
#

ok hmm

#

ill have to work it for a few min

viral quarry
#

idk should i even draw it there, someone explained to me yesterday and i did understand it but on this one i get trick

#

okay thank u

#

maybe i should have drawn the angle different way, so then i get 270+30 , but i think it should be drawn anticlockwise right?

neat wave
#

ok im getting it now

#

the values of cos and sin tell u its Q4, that's definitely right. So you can be safe to say that the angle of theta is a form of pi/3 in the 4th quadrant

#

it's not really a matter of matching a pattern of where to rotate the angles, but you're basically using the given info to deduce where and what angle theta is

viral quarry
#

So i should just use -Pi/3 and not add anything to that?

neat wave
#

yeah, there's no pattern to the problems or anything if that's what you were thinking before. You just need to figure out the quadrant and angle based on the given formula. If its in quadrant 2 and sin and cos tell you it's a pi/4 angle, you would deduce that it was 3pi/4. Get it?

#

Always keep a unit circle handy if you don't have it memorized already too 😉

viral quarry
#

we have Pi/4 in second, and then we add value of the one behind it ( first only ) and we get Pi/4+ Pi/2

#

I understood that, but i didnt know why i dont add the 270 to 60

#

so this is this circle, and as Re>0 and Im<0 , i can just say its -60 as it belongs in the right quadrant right?

neat wave
#

That's what I would think. What does the exact question ask?

viral quarry
#

I just need to convert to complex trigonometric form

#

Like r(cos angle + i sin cos angle)

neat wave
#

yeah that should be fine then. do you know if the answer needs to be in radians or degrees

viral quarry
#

I think in radians

#

So -60 is -Pi/3 right?

#

Then its 1(cos (-Pi/3) + i sin (-Pi/3)

viral quarry
# twin meteor

Also here, would it be right if i just used the value of -30 degrees ( -Pi/6) instead of 210 ( 7Pi/6) ?

neat wave
#

you should use the actual angle

viral quarry
#

what would the actual angle mean

neat wave
#

well you can say it's pi/6 but that doesn't tell you what quadrant it's in really

#

if you say 7pi/6 you know exactly where that is

viral quarry
#

So its important to mention the quadrant?

neat wave
#

no because the angle tells you what quadrant its in

#

pi/3 is in the first quad

#

7pi/6 is in the 3rd quad i believe

viral quarry
#

Y

#

Yes

#

Does it stand for like

#

-Pi/3 is in fourth?

#

Or i need to write it as 5Pi/3 ( 300 )

neat wave
#

no you need to write it as the whole 5pi/3 thing

crimson jetty
#

measure angles in radians anticlockwise from the positive x-axis

neat wave
#

if that's the case then you need to find what that angle is if you rotate it the opposite direction

#

like forwards vs backwards

crimson jetty
#

the usual one.

viral quarry
neat wave
#

oh omg im so dumb i totally misinterpreted that

crimson jetty
#

that -60 is good

viral quarry
#

and then it makes sense, 270 + 30 = 300

neat wave
#

yes -60 will work lol

crimson jetty
#

i havent seen the original question

viral quarry
#

On my first try i did it opposite

#

-60 down and 30 up

viral quarry
viral quarry
neat wave
#

for that one u either write 210 degrees in the counterclockwise direction or 150 degrees in clockwise direction

viral quarry
#

so i did 30 and then +90+90 its 210

vocal sleetBOT
#

@viral quarry Has your question been resolved?

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vocal sleetBOT
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mortal kite
#
  1. Find the probability that x < 30.
    X ~ N(54, 8)
mortal kite
#

z score is so confusing

strong rain
#

Never seen this notation. But is this what it means
μ=54
σ=8

mortal kite
#

yea

#

it's like

#

(x-54)/8

#

but it's confusing finding Z score because it's like

#

the same formula

#

but u come out w a decimal place number

#

and then you randomly find the Z from that?

#

idk

#

. X ~ N(4, 5)
Find the maximum of x in the bottom quartile

#

this one also confuses me

vocal sleetBOT
#

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#

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long oriole
#

quick q, can I use ln properties to move the ^2 so that it becomes 2xlnx?

wide lark
#

Nah u can't

#

If it was ln(x²) then u could

long oriole
#

ok I see

#

ty

#

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vocal lodge
#

Hello! Could you help me with this fraction division? The result should be 68.

vocal lodge
#

But even though I double-check and redo the exercise, it still gives me 17/3 divided by 27/16.

cobalt ocean
#

i think the problem must be here

#

(5/10) * (2/9) should be like (10/90) = (1/9)

#

@vocal lodge

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cursive fern
#

can someone please help me understand the solutions of this exercise?

cursive fern
#

One of my main questions is about the boundsof the first integral which I dont understnad

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@cursive fern Has your question been resolved?

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tranquil trellis
#

Hi! I'm still a bit confused on this delta stuff for limits. Could someone help me approach this problem?

lapis marten
#

The distance between (x,y) and (5,1) should be less then delta

#

(x - 5, y - 1) lies inside a circle centered around the origin with radius delta

tranquil trellis
#

right

lapis marten
#

But for all points in this circle the x coordinate is between -delta and delta, right?

#

I should say disk btw

tranquil trellis
#

so that's basically the problem?

lapis marten
#

Yeah

#

I think you can prove this more rigorously with the triangle inequality, haven't figured out the exact details though

tranquil trellis
#

That's a good idea I'll try that. Thanks!

lapis marten
#

or the pythagorean theorem maybe

#

triangle inequality is not gonna work I think

tranquil trellis
lapis marten
#

You need to prove that if a^2 + b^2 < delta^2 then a^2 < delta^2 => |a| < delta

tranquil trellis
#

Ok

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gleaming hare
#

You have a road that is 1 mile and a car that only has 30 meters before it hits the travelling limit, how much of the could the car cross before hitting the limit? (the limit makes the car stop even at full fuel)

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prisma imp
vocal sleetBOT
prisma imp
#

Need help pls

#

Anyone ??

#

??

#

] pls

#

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vast shale
#

helppp

vocal sleetBOT
vast shale
#

<@&286206848099549185>

tame raptor
#

y=kx

#

input 2,3,5

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output 5,7.5,12.5

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5=2k

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k=5/2

vast shale
tame raptor
#

weird

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let me see

barren radish
#

since it's pr then you know it's what kind of function?

tame raptor
#

nevermind

vast shale
#

bro what

tame raptor
#

what is the name of the function

barren radish
#

you've already drawn it, right

vast shale
#

idk

#

yeah

vocal sleetBOT
# vast shale <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

tame raptor
#

if the function goes through orgin

#

what is the function called

vast shale
#

point of origin?

tame raptor
#

ye

#

orgin

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which it means when you input 0

#

you get 0

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there is no intercept

vast shale
#

what’s a-e

tame raptor
#

direct proportional function

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the equation is y=kx

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I don't know if you graph it the right way

barren radish
#

so when I said function and that you've drawn it I meant that it's a line. the relationship of $ to amount is a line with non-zero slope

vast shale
#

just tell me what to wright please

barren radish
#

and it' a + slope meaning it point up and to the right like you've drawn

tame raptor
#

2 pounds of candies=5 dollar

#

5=2k

#

It's kinda weird that the slope aren't the same

#

my bad

vast shale
tame raptor
#

it is

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it is

#

5/2

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the function expression will be y=5/2x

#

how

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you just graph it bro

vast shale
#

thanks!

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bye!

tame raptor
#

you see the top of the pounds to which it coast right?

#

good

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
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swift brook
#

What does this mean? conv is for convex hull, I don't know what is the bar above conv or what cl is (I think its closure)

sly sierra
#

yes, the closure of the convex hull

swift brook
#

so the conv bar is just notation for the closure of convex hull? but what does that mean (closure)?

vocal sleetBOT
#

@swift brook Has your question been resolved?

swift brook
#

I don't get how closure is different from convex hull

vocal lodge
vocal sleetBOT
#

@swift brook Has your question been resolved?

vocal sleetBOT
#

@swift brook Has your question been resolved?

vocal sleetBOT
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cyan lagoon
vocal sleetBOT
cyan lagoon
#

#6. x = 7(3-y)

#

Idk what to do next

soft walrus
#

that's a Diophantine Equation, do you know how to solve them? :)

cyan lagoon
#

I remember hearing about those

#

thank you that’s the hint I needed

regal bane
#

It's a very basic one. I saw in the other chat you outlined your strategy and it's good

cyan lagoon
#

.close

vocal sleetBOT
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oblique raven
#

T

vocal sleetBOT
oblique raven
#

The top problem with C

#

ok so I plug in 6 for the original function but then I got a weird decimal number. but I continue that and plugged that answer into the inverse function and it not work. so I try the inverse of 2 first, got that answer and plug in for the original equation and that one makes sense

soft walrus
#

Little fact about inverses, which is what this exercise was trying to show you $f^{-1}(f(x))=f(f^{-1}(x))=x$

twin meteorBOT
#

MrFancy

soft walrus
#

albeit they could've chosen a better function to introduct such a concept

oblique raven
#

who is that in ur profile picture btw

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was he a president

soft walrus
#

Augustin Louis Cauchy :)

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famous mathematician

oblique raven
#

oh yea

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u like him?

soft walrus
#

indeed, one of my favorites!

oblique raven
#

to constraint a domain / range whatever ?

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or that maybe one of the function isn’t a function

soft walrus
#

$f^{-1}(f(x))=x$

twin meteorBOT
#

MrFancy

soft walrus
#

take some value and put it into f(x)

oblique raven
#

ok

soft walrus
#

then plug that result into f^-1(x)

#

and you get the same value you plugged into f(x)

oblique raven
#

Oh yea

#

That makes sense for f(f-1(2)) but the one with the 6 just doesn’t

soft walrus
#

try keeping in terms of the radical

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$f(6)=\sqrt[3]{6}+2$

oblique raven
#

ok

twin meteorBOT
#

MrFancy

soft walrus
#

plug this into $f^{-1}(x)$

twin meteorBOT
#

MrFancy

oblique raven
#

,rotate

twin meteorBOT
oblique raven
#

dang so u gotta do it like that

brisk moss
#

it should almost work if you decimal anyway

oblique raven
#

yes I was just deadly weirded out by the 6.000000000001

brisk moss
#

like it might give you 6.00000000 something but it should be really close still

oblique raven
#

Thx

#

.close

vocal sleetBOT
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elder burrow
#

for "which of the following could be the graph of y=-2(x)^2" the graph would open downward right?

elder burrow
#

site says it's incorrect

somber gorge
#

I think that the one opening downward would be right

#

I would ask you professor becuase the website may be wrong

elder burrow
#

yeah

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it's like

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gaslighting me

#

thanks

#

.close

vocal sleetBOT
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regal stirrup
#

how can i figure this out, im pretty clueless rn

somber gorge
#

was any more details given about ABCD?

#

nevermind I was going to ask whether it was a parallelogram but the answers don't line up with that

regal stirrup
#

abcd is a paralelogram

somber gorge
#

oh it is

regal stirrup
#

but im so confused i tried everything ik i just dont know how to do it

somber gorge
#

ok so a parallelograms area is base times height

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and we have the base of 30 already so we need to find out its height

regal stirrup
#

yea thats where im stuck

somber gorge
#

yeah me to

regal stirrup
#

and i have no idea

somber gorge
#

let me think about this lol

regal stirrup
#

any ideas?

somber gorge
#

ok i think i may have it

#

give me a second

#

ok i got it

#

so

#

we have the base but we need the height

#

so notice that angle NDC equals angle DAB

#

(i'm assuming that they are equal but I think my assumption was right)

#

but do you see why finding angle NDC/ angle DAB would be useful?

#

@regal stirrup do you still need help?

vocal sleetBOT
#

@regal stirrup Has your question been resolved?

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fleet salmon
#

,rotate 270

vocal sleetBOT
twin meteorBOT
fleet salmon
#

,rotate 270

twin meteorBOT
fleet salmon
#

how di i do

#

d

#

the inverse h

#

(3)

#

😭

#

.close

vocal sleetBOT
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desert spindle
#

I’m trying to complete the square but idk where to go from here.

soft walrus
#

$(a+b)^2=a^2+2ab+b^2$

twin meteorBOT
#

MrFancy

soft walrus
#

I feel like I've helped you like 5 times today kekw

desert spindle
#

Teacher wasn’t here today and I got so confused during class

desert spindle
soft walrus
#

its how we learn

desert spindle
#

do I need to factor it first in order to do the perfect square trinomial equation? bc if I do, idk how to do that

soft walrus
#

that's going to be our a^2, right?

desert spindle
#

Yea

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But what about the b/ax

soft walrus
#

well is x=a

#

ooo

#

I could see where this could be confusing

#

ok

#

so bear with will me for a sec kekw

desert spindle
#

ok lol

soft walrus
#

so imma do a new binomial expansion (d+e)^2=d^2+2ed+e^2 right?

#

same thing just different letters you'll see why in a sec

desert spindle
#

ok

soft walrus
#

so since d^2=x^2 this means d=x

#

all good?

desert spindle
#

Yep

soft walrus
#

do that middle term 2ed just becomes 2xe, right?

desert spindle
#

Yes

soft walrus
#

now compare that with b/a*x and you'll get e :)

minor marten
desert spindle
#

Like this? sadcat

soft walrus
minor marten
#

Whats the side length of the square?

desert spindle
soft walrus
#

close

desert spindle
minor marten
desert spindle
#

Wouldn’t it be equal to what’s written on the right side of the equation ?

minor marten
#

The area of that is what you are trying to factor

desert spindle
#

yes

minor marten
#

So take a look at the side lengths of that square

desert spindle
#

b/2a * x ?

#

sorry I’ve never done perfect squares b4 until rn, I’m rlly confused and them

minor marten
#

You need to add not multiply

desert spindle
#

So just b/2a + x ?

minor marten
#

Yep

#

Thats the side length

#

And area = (side length)^2

#

We know the area is x^2 + b/a*x + b^2/(4a^2) and we can rewrite that as the side length squared (since we know the side length!)

desert spindle
#

Would the right hand side of the equation still be -c/a + b^2/4a^2 ?

minor marten
#

Yes

#

Since you havent done anything to both sides, just factored the left side

desert spindle
#

can you please check if I did this right

vocal sleetBOT
#

@desert spindle Has your question been resolved?

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vocal sleetBOT
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loud elk
vocal sleetBOT
loud elk
#

i got it

#

need some help

tacit belfry
#

<@&286206848099549185>

blissful fable
loud elk
#

yeah and prob 5

blissful fable
#

product rule on the left

loud elk
#

definently 5 as well actually

#

product rule on the xe^y?

blissful fable
#

d/dx [xe^y] = d/dx[x] * e^y + d/dx[e^y] * x

blissful fable
#

then for d/dx[e^y] it's just chain rule

loud elk
#

workin in out'

#

is deriv. of e^y just e^y

#

i need some more help

blissful fable
#

that's chain rule

#

see since y is a function of x

#

you have to apply the chain rule

#

so

#

d/dx [e^y] = e^y * dy/dx

loud elk
#

is that right?

#

@vocal sleet

#

<@&286206848099549185>

blissful fable
#

you have to differentiate both sides when doing implicite differentiation

#

oh you did it later

#

fine

#

the derivative of y with respect to x wont be y dy/dx

#

it's just dy/dx

#

(on the RHS)

loud elk
#

thank you

#

got it right

#

'can u help with next 1?

#

i messed up somewhere

blissful fable
#

for the LHS, use chain rule, and for the RHS use quotient rule

loud elk
#

i got number 4 correct

#

this one i missed

#

nvm go it

vocal sleetBOT
#

@loud elk Has your question been resolved?

vocal sleetBOT
#

@loud elk Has your question been resolved?

vocal sleetBOT
#

@loud elk Has your question been resolved?

vocal sleetBOT
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vocal sleetBOT
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craggy granite
#

log 8 =0.90
, find the value of log√32

vocal sleetBOT
long jackal
craggy granite
#

its 10

long jackal
craggy granite
long jackal
#

Ok you can say that 8 =2^3

#

Right?

craggy granite
#

yea

long jackal
#

Try to do the same thing to √32

craggy granite
#

thts it 2^5

long jackal
craggy granite
#

so 2^5*1/2

long jackal
#

So you know that log 2^3 =0.9
Try to figure out what log(2^(5/2)) will look like

#

@craggy granite to solve this problem you need to know this

craggy granite
long jackal
#

No its 5/2

craggy granite
#

ohh yeaa

#

5/2 log 2

long jackal
#

Yup

craggy granite
#

.close

vocal sleetBOT
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shell laurel