help-17

[vast shale]

Do i even want to know what level math you in

[spiral inlet]

I don't go to school anymore

[vast shale]

Oh

you do math stuff for a living?

Like a engineer or something?

[spiral inlet]

various lol

but I do a lot of tutoring

[vast shale]

W man my child brain can only handel so much

Thanks alot

have a good one

[spiral inlet]

np you too 👍

[vocal sleet]

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[blissful garden]

can someone tell me how to do it ?
i dont know how to solve this type of solution, i have got the solution of it by graphing it in desmos

[paper depot]

!status

[vocal sleet]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[blissful garden]

1

[paper depot]

right

you can pull a conjugate trick here

multiply and divide this thing by (sqrt(x^2+10x)+x)

[blissful garden]

ohh ok

lemme do that

so i got 10x/(sqrt(x^2+10x) + x)

then i get 10/(1+ (sqrt(x^2+10x)/x))

[paper depot]

yeah

you can simplify $\frac{1}{x} \sqrt{x^2+10x}$ a bit

[twin meteor]

Ann

[blissful garden]

how ?

i am confused

[vocal sleet]

@blissful garden Has your question been resolved?

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[opaque palm]

I am preaty sure I need to make 2 simultanious equations. But I am not quite sure how to do it

[livid tapir]

do you remember the arc measure formulas

I mean for like central angles and inscribed angles

[vocal sleet]

@opaque palm Has your question been resolved?

[opaque palm]

CAn you elaborate please

Do you mean formula how to find Smaller PR arc? Yea I know how to do that. But what is next?

[livid tapir]

well you got two arcs that sort of cover PR

And you have the angles labeled with y

So set them equal

[trail shoal]

wait

The peripheral angle that rests on the same arc of a central angle is equal to half of it

Do you have answers?

[opaque palm]

IS it what we are looking for?

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[warped chasm]

Need help with part 3 as I have forgotten binomial and poisson over the summer break

so P(x=0)<0.5

But I forgot the formula that would allow me to find this without knowing n

<@&286206848099549185>

oh fine, I'll just ask another question then

Im not sure how to do this at all

6.) i.)

e(x)=(n-11)/2

Var(x)=e(x^2)-((n-11)/2)^2

and im not sure where to go from there

Anyone?

[hybrid flicker]

what's the definition of e(x^2)?

[warped chasm]

the sum on 11^2+12^2....n^2 all over n-11

I guess that sum of (n^2) from r=11 to n

[short acorn]

Hi

[warped chasm]

I mean I messed up somewhere but thank you for your help

I will probs close this is no one can find where I went wrong

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[fluid comet]

guys can you help me with these

[honest ridge]

Do you know a property of lengths of the sides of a right triangle?

[delicate stirrup]

do you know Pythogoras?

[honest ridge]

@fluid comet Are you here?

[fluid comet]

yes

[fluid comet]

yea

wait i send the wrong pic

sorry

[honest ridge]

we can do 3 then

[fluid comet]

yea

[honest ridge]

Just to be sure, this?

[fluid comet]

yes

[honest ridge]

First of all, how do you calculate distance?

[fluid comet]

i dont understand by the sentence like "billy has cycled in kilometres"?

[fluid comet]

speed times time

[honest ridge]

I guess they mean jogging (I found this wierd too)

[fluid comet]

yea and then they say the total distance jogged is 18 km?

does they mean x tho?

[honest ridge]

I think so.
otherwise the answer would be in the question.

Btw, is this the full problem?

Maybe there was something about cycling said earlier

[fluid comet]

yea

can u do q1?

[honest ridge]

Sadly, I came for 2 and 3

[fluid comet]

what about this

[fluid comet]

oh np

[honest ridge]

In this, you need to calculate how many workers/month are needed for the entire building.
By this wierd unit I mean how many people working per month would finish the construction.

[honest ridge]

This feels like it's too junky, so
Calculate what portion of the building would 1 worker finish in 1 month.
See how many of those units of work are needed for the whole building.
Work out how many are still needed.
Calculate how much time the workers remaining need.
(at least that's how I'd approach this)

[honest ridge]

Do you know roughly what to do?

[fluid comet]

wait

let me think first

[honest ridge]

When you encounter a problem, remember to text here

[fluid comet]

yep i will

[fluid comet]

1 worker = 3024 months?

it seem too many

idk

damn i think i m wrwong

[honest ridge]

Well, if 126 workers finish in 84 months, 1 worker is 126 times slower,
thus we have to multiply 84*126
which gives us ||10584 units for the whole building||

[honest ridge]

Do you want me to clarify something from this stage?

[fluid comet]

em yea

but we need to find the months

[honest ridge]

If you use this terminology, 1 worker finishes in 10584 months.

I was simply using units I talked about earlier

[fluid comet]

let me try to count by using this

damn i still can't find the answer

[grizzled musk]

do you understand the relationship between number of workers and months

@fluid comet

[fluid comet]

i think no

like what

it takes 84 months for 126 workers

i only know that

[grizzled musk]

esentially, it has an inverse relationship

can u see that?

if there are less workers, takes longer to finish
if there are more workers, takes shorter to finish

[fluid comet]

oh yea, i see it

[grizzled musk]

so now can you find out how much of the building they've finished constructing after 28 months?

[fluid comet]

idk wait for a while

let me think

[fluid comet]

1/2?

they did like half of the building

[grizzled musk]

wrong

[fluid comet]

oh

then how

[grizzled musk]

126 workers complete it in 84 months, therefore they complete 1/84 of the building per month

can you see that

[fluid comet]

w8 what how did u get 1/84?

[grizzled musk]

because they complete the entire thing in 84 months, so they complete 1/84 of the building per month

[twin meteor]

REUBENOOB

$\frac{1}{84}\x84$
```Compilation error:```! Undefined control sequence.
l.57 $\frac{1}{84}\x
                    84$
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined.

Preview: Tightpage -1310720 -1310720 1310720 1310720
[1{/usr/local/texlive/2020/texmf-var/fonts/map/pdftex/updmap/pdftex.map}]```

[fluid comet]

oh i see

[grizzled musk]

ignore that

but now can you find out how much of the building they've completed?

[fluid comet]

28/84?

is it like this

[grizzled musk]

yes!

ok so now they lost 30 workers

can you find the rate they are working at?

[fluid comet]

ok so they lost 30, which means we had to minus it and then it is 96 left

[grizzled musk]

yes

[fluid comet]

but then i had to find the months when it is 96 left, that means we need more months

but the thing is idk how to find it

[grizzled musk]

no, we find the rate of the 96 workers

if 126 workers ---> build 1/84 every month
96 workers ---> build ? every month

[fluid comet]

1/144

[grizzled musk]

wrong

the number of workers and months have an inverse relationship

for e.g., when you divide the number of workers by 2, the number of months increases by 2x

126 workers ---> 84months
1 worker ---> 84*126 months
96 workers ---> ? months

[fluid comet]

its comma tho

110.25

[grizzled musk]

so what is the rate of 96 workers?

if they take 110.25 months to finish, how much do they finish per month?

[fluid comet]

1/110.25

[grizzled musk]

good

can u remove the decimal in the denominator

[fluid comet]

1/110?

[grizzled musk]

no

remove it while keeping the value the same

[fluid comet]

oh 4/441

like this

[grizzled musk]

good

so from earlier, what is the remaining fraction of the building that is left to be completed

[fluid comet]

56/84

[grizzled musk]

okay

can u continue from here?

[fluid comet]

em let me see first

is it 56/84 divide by 4/441

so the answer is 73.5 which means 74?

[grizzled musk]

you should keep it at 73.5

[fluid comet]

Oh ok thanks

Can u do the q1?

and this

<@&286206848099549185>

[delicate stirrup]

1st?

[fluid comet]

yea

[delicate stirrup]

have you got the line equation for that yet?

[fluid comet]

this is 1st questins

[fluid comet]

yes i found the answer but its wrong

[delicate stirrup]

i think you need a perpendicular from BD which passes thorugh C

[fluid comet]

btw for this i got 16.667

[fluid comet]

let me see

[delicate stirrup]

so BC/18 = CE/27?

[fluid comet]

wait this is the question

[delicate stirrup]

right

and BC/CD = CE/AC?

[fluid comet]

nah its impossible i think cus its not parallel

[delicate stirrup]

...

look closely

it's not BC/18 and AC/27

[fluid comet]

oh yea

its possible

sorry

[delicate stirrup]

no problem

but anyways

can't see the way of solving this

wait

BA = 11

[fluid comet]

yea

CE=33

[delicate stirrup]

How you got that?

Then isn't every side defined?

[fluid comet]

BC/18=CE/27

BC=2/3CE, then AB= 1/3CE

like this

[delicate stirrup]

Ok

[fluid comet]

but i can't continune it

i can't find the next one

its quite difficult

[delicate stirrup]

Yeah

[fluid comet]

what about the coordinate, did u find the answer?

[delicate stirrup]

You mean this?

[fluid comet]

yep

[fluid comet]

wait i think i m wrong about this, ignore it

[delicate stirrup]

ok, so CA/27 = CD/18

CB/18 = CE/27

and CB/CD = CE/CA

CB/CD = CE/(11+CB)

[fluid comet]

yea

[delicate stirrup]

how we use the area?

[fluid comet]

idk tbh, i m still thinkin about it

[delicate stirrup]

i think area ACE = CBD*27/18

and ACE = CBD + 900

CBD * 3/2 = CBD + 900

CBD/2 = 900

CBD = 1800?

i think i know how to do this

cause CBD = 1800 = 18 * h / 2

where h = 200

h should be the answer here

but 200 is extreme

[fluid comet]

the answer is 80

[delicate stirrup]

ok

nvm then

it's not

geometry is about finding ways, drawing lines

finding relations

but you got the point?

how to solve it

[fluid comet]

maybe its not, but its about logic doing geometry

[fluid comet]

no, i m still finding it how the answer is 80

[delicate stirrup]

ok

i think i know where i got wrong

triangle lines relation is 2/3

so area relation is 4/9?

[fluid comet]

oh i found the solution

i did it

[fluid comet]

i dont seem to understand this

whic one

[delicate stirrup]

awesome

[fluid comet]

thanks for helping me along the way

do u understand about this ?

[delicate stirrup]

yes

it's final/orig = 0.6

in terms of area it is 0.6^2

so 143.3 * 0.6 * 0.6?

,w 143.3 *0.6^2

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by tim_oder

[fluid comet]

the answer is 10

idk how, its like really far from my answer, and i think i misunderstand the questions or i dont understand it at all

[delicate stirrup]

here $\frac{actual}{map} = \frac{2.4km}{15cm}$

[twin meteor]

TimK

[delicate stirrup]

= 240000/15

,calc 240000/15

[twin meteor]

Result:

16000

[delicate stirrup]

so actual / map = 16000

and actual^2 / map^2 = 16000^2

so actual^2 / 143.3 = 16000^2

[twin meteor]

Result:

1.9153276482106e+5

[delicate stirrup]

wait

[long yew]

Scale:
24000/15

Taking x as size in original map
40x/100=143.3
x=179.125

So final area = 179.125*1600 sq. cm

[delicate stirrup]

it is photocopied

,calc 143.3 * 1/0.4

[twin meteor]

Result:

358.25

[delicate stirrup]

yeah

[long yew]

Oh wait it has a mistake

Ah well the method works anyway

[fluid comet]

so the answer is 1600?

[fluid comet]

358.25?

[long yew]

573200

[fluid comet]

oh

[long yew]

Do you get my method?

Wait no I'm making loads of mistakes in multiplication

[fluid comet]

idk i m confused cus there isnt 573200 in the chats b4 u send it

[long yew]

Yeah I'll rewrite it

[fluid comet]

ok thanks

[long yew]

Scale of the map
Size of original route/size of route in map

So 15cm/24000cm = 1/1600
Is the scale

Scale is reduced by 40%

So the new scale is (60/100)*(1/1600)

Which is 0.000375

To find the area,
143.3/0.000375 sq.cm should the answer

[vocal sleet]

@fluid comet Has your question been resolved?

[vocal sleet]

@fluid comet Has your question been resolved?

[vocal sleet]

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[vast shale]

Do you know you can get rid of the logs on both sides?

What's the opposite of taking the log?

Actually, here's a better question: How do you turn log7(4x-6) into 4x-6?

Yeah

Well you basically got your solution

Unless you don't see how to apply it to your equation

Why wouldn't it be possible?

Oh I see

Because you can't take the log of a negative number

However you're not taking the log of x, you're taking the log of- nevermind

hmmm

,calc 4*(-1)-6

[twin meteor]

Result:

-10

[vast shale]

,calc 2*(-1)-4

[twin meteor]

Result:

-6

[vast shale]

@karmic ember You made a sign mistake somewhere

[delicate stirrup]

hey guys

isn't x = 1 here?

[vast shale]

!nosols

[vocal sleet]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[vast shale]

Wha-

[minor marten]

But youre correct that its an extraneous solution

[vast shale]

@karmic ember Have you seen negative numbers yet?

[delicate stirrup]

does it?

[vast shale]

@minor marten @delicate stirrup By the way can any of you take over?

[minor marten]

After solving these you plug in the x value into the original equation to check if its valid

[delicate stirrup]

what do you mean?

[minor marten]

First try solving 4x-6=2x-4 again

[obtuse sierra]

you are the official helpers now

[minor marten]

There is a valid solution

[obtuse sierra]

[delicate stirrup]

4x-6 = 2x-4 -> 2x-6 = -4 -> 2x = 2 -> x=1

not -1

[vast shale]

Take over the help channel

[delicate stirrup]

solved?

[vast shale]

As in help them instead of me helping them

It seems that's already happening, I'm out

[delicate stirrup]

??

so empty set

[magic surge]

[log7(4x-6) = log7(2x-4) <=> 7^(4x-6) = 7^(2x-4)] => (4x-6=2x-4 <=> 2x=2 <=> x=1)

[minor marten]

Dont focus on the log now

Whats the x value you got? @karmic ember

[delicate stirrup]

Sorry, i don't get it

[obtuse sierra]

it was a joke

[delicate stirrup]

x=1

log{7}{-1} is undefined

so ∅

[magic surge]

this wrong i forgot definition of log

[delicate stirrup]

...

[vast shale]

@karmic ember Have you guys learned about complex numbers?

[magic surge]

log7(2x-4) = log7(4x-6) <==> 7^log7(2x-4) = 7^log7(4x-6) <==> 2x-4 = 4x-6 <==> x = 1
and log7(-1) does equal itself

[vast shale]

,w log_7(-1)

[twin meteor]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by labyrinthsplash

[vast shale]

Whatever this is

[minor marten]

Only in complex numbers

If were talking about real numbers then theres no solutions

Usually when you first learn about logs youre only focused on real numbers

[vocal sleet]

@karmic ember Has your question been resolved?

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[brisk bison]

Hi, I am trying to understand how tiling on a plane works, I see online that "For shapes to tile the plane edge to edge without gaps or overlaps, their angles, when arranged around a point, must have measures that add to exactly 360 degrees" but I dont really understand that explaination, what does it mean to arrange a shape around a point?

[delicate stirrup]

tesselation?

[brisk bison]

My motivation behind this question is that in image processing, if you have a bounded signal in the frequency domain, if you can show that the signal in the frequency domain can tile the plane, you can say that you can sample the image with 100% efficiency without aliasing

[brisk bison]

let me look that up

yes thats what i am talking about

[delicate stirrup]

i think it typically means it has to be full shape

[brisk bison]

hmm so this wouldnt be considered a full shape?

although this is a simple example, i was wondering if it can be more generalized to different examples

[delicate stirrup]

no

i guess

that angles should be divisable by 360

like 4 squares, with angles 90

revolve the square around one of it's angles, so it makes a full shape

[brisk bison]

well in this example there are two triangles with 180 degrees each so wouldnt that satisfy the 360 degree criteria?

[delicate stirrup]

no

wait

yes

it does

although not every shape in this criteria can create a tesselation

[brisk bison]

does it matter that its in that particular shape? Can two triangle connected by at least one point tile the plane without any gaps or overlaps?

[delicate stirrup]

yes

[brisk bison]

ok thank you

[delicate stirrup]

no problem

[vocal sleet]

@brisk bison Has your question been resolved?

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[worldly folio]

lim x->infinity of (1-x^2)/(x^3-x+1)

[rugged vortex]

Use end behavior

[worldly folio]

i've tried

[rugged vortex]

Show me your work

[worldly folio]

it's like a oblique asymptote

i haveno work that's the thing

[rugged vortex]

It's not an oblique asymptote

[worldly folio]

it isnt'?

[rugged vortex]

No

[worldly folio]

what is it then

i thought

[rugged vortex]

Well look at the numerator and denominator's leading term

[worldly folio]

n<m

wait

if it's n<m is that 0

or is that oblique/slanted

assuming n is the numerator

and m is the denominator

[rugged vortex]

Oblique asymptotes are when the order of the numerator is larger than the denominator's

[worldly folio]

ohh

mb

[rugged vortex]

Well the order is 1 more than the denominator's

If it's any more you get a curvilinear asymptote

[worldly folio]

oh i see

so then the asymptote is 0

so this would be equal to 0?

[rugged vortex]

Mmhm

[worldly folio]

alright ty

.close

[vocal sleet]

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[formal dome]

How do I solve this?

[hushed pewter]

Do you remember your limits identites? Sums, products, compositions?

[formal dome]

No not really

What r those

[formal dome]

What does C E R mean?

[hushed pewter]

any value c that is in the set of all real numbers

[formal dome]

Oh

[hushed pewter]

$c \in \mathbb{R}$ means "c is any real number"

[twin meteor]

SWR

[hushed pewter]

$\in$ is the "set inclusion operator" $A \in B$ means that "A is in the set B"

[twin meteor]

SWR

[formal dome]

I’m not gonna lie, all I see are shapes and numbers

Nothing looks or makes sense to me man I’m sorry

[hushed pewter]

sorry for overly technical bits, I just copied my old analysis notes.

But I'll break it down

The idea of limits is that we ask ourselves, what result does a function approach as its input variable approaches some value?

$\lim_{x\rightarrow a} f(x)=L$ says that, for the function $f(x)$, as $x$ gets really close to $a$ (without necessarily being AT $x=a$), $f(x)$ will get closer and closer to $L$

[twin meteor]

SWR

[formal dome]

Okay

[hushed pewter]

This first identity says that, if $f(x)=c$ is a function that maps to the constant value $c$ for any input $x$, then the limit as $x$ approaches any value $a$ will ALWAYS be $c$

[twin meteor]

SWR

[hushed pewter]

This says that if $f(x)=x$, then $\lim_{x\rightarrow a} f(x)=a$

[formal dome]

Ur using $ to replace ( right?

[twin meteor]

SWR

[hushed pewter]

I'm using $ to write Latex math

[formal dome]

Ahhh

[hushed pewter]

Do you understand this one?

[formal dome]

Nah not really, I’m headed to the store currently. Can I comeback to this later?

[vocal sleet]

@formal dome Has your question been resolved?

[formal dome]

Hey

I’m back

<@&286206848099549185>

How do I solve this?

My guess is to plug in the 3 where f(x) is and the -2 where g(x) is

[dreamy tulip]

using limit rules you can separate, (lim x ->c of (f(x)-5)^2) (lim x ->c of g(x) ^(3/2))

yeah basically just plug in

[desert needle]

just plug in

[dreamy tulip]

just leave the square root as a square root dont simplify

[formal dome]

Ok

1 sec please

What do the [ mean?

[]

[desert needle]

it means paranthesis between paranthesis

[formal dome]

Ahhh

This is where I’m currently at. Sorry for back handwriting

[desert needle]

oui c'est ça

it's written like so (-2)^(1/3)

[formal dome]

Oh

Wait what happened to the

I mean square root

[desert needle]

the little three means it's not a square root

[formal dome]

It’s cubed, right?

[desert needle]

instead of the 3, there is a 2 that nobody writes when you're talking about square root

sqr(a) = a^(1/2)

get it ?

[formal dome]

Uhhh, yea

[vocal sleet]

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[vast shale]

How this function can exist ? Here is the exercise :

[vast shale]

A function f is a ratio of quadratic functions and has a vertical asymptote x = 4 and just one x-intercept, x=1. It is known that f has a removable discontinuity at x = -1 and lim_x->-1 f(x) = 2. Evaluate f(0) and lim_x->infinity f(x)

---

From the fact that x = 4 is a vertical asymptote we know that (x-4) is a factor of the denominator

From the fact that x=1 is the only x-intercept we know that (x-1)^2 is the only factor containing x in the numerator

[outer warren]

wrong conclusion

[vast shale]

Why ?

[outer warren]

you didn't consider the removable discontinuity there

[vast shale]

I was just writing about it

But if there is a removable discontinuity at x=-1 (x+1) must be a factor of both the numerator and the denominator right ?

[outer warren]

yes

[vast shale]

but then -1 will be a x intercept

[outer warren]

no

[vast shale]

and x=1 will not be the only one

why ?

[outer warren]

it's undefined at x=-1

because division by 0

[vast shale]

wow

[outer warren]

removable discontinuity

[vast shale]

🤯

[outer warren]

you have a hole there

[vast shale]

I see

I will try again

So f(x) is of the form c times ((x+1)(x-1))/((x-4)(x+1)) ?

where c is a constant

I found

the constant is 5

Thank you for the answer Ram()n()v

.close

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[swift brook]

what part are you stuck on?

What class is this?
If this is at the Middle School/HS level then I'm assuming this is a pen and paper assignment and you need to plot each point, you'll probably have 3 different colors
If this is a university assignment meant to be plotted with a computer look into Normal Equations

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@vast shale Has your question been resolved?

[magic ember]

hi

[vocal sleet]

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[void badger]

Question

[void badger]

My textbook seems to define "the tangent plane" is two different places

Once in the chapter about linear approximation, where the tangent plane can be derived by computing the partial derivatives along the x and y axes, computing their normal, and defining the surface

Then it discusses the plane again when talking about the gradient in a later chapter. The gradient of course being perpendicular to all tangents at a given point on a surface

Are these the same tangent planes?

.close

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[twin meteor]

Joseph.P

[hybrid flicker]

Two polynomials are equal if their coefficients are equal

[solemn cape]

Oh right

.close

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[solemn cape]

Sorry didn’t say thanks

[vocal sleet]

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[vocal sleet]

Please don't occupy multiple help channels.

[split heart]

!onechannel

[vocal sleet]

Please stick to your channel.

[bold juniper]

Want

What

[split heart]

You have two open help channels sir

[bold juniper]

Oh sorry

You can help me ?

[split heart]

I could

[bold juniper]

Ok

[split heart]

What do you think is the strategy here?

You were given B

close the other channel btw

[bold juniper]

He want to know the matrice A

[split heart]

Right, but you have B on the left-hand side

How can you eliminate that

maybe turn that into an identity or something

how would you do that

[bold juniper]

Give me one second pls

[split heart]

sure

[bold juniper]

I forgot to give you this

[split heart]

,rccw

[bold juniper]

What

[bold juniper]

What that mean

[split heart]

I just rotated the picture

[bold juniper]

Oh ok

[split heart]

Also I don't think your B inverse is correct

can you double check that

try $B * B^{-1}$

[twin meteor]

TooManyCooks

[bold juniper]

No I can’t

[split heart]

Why not

[formal gazelle]

Ur pfp is …

[bold juniper]

Because the question is AB=B transposed

And find the value of the matrice A

[split heart]

Sure, but I just want you to checkif you got the inverse of B right

and what better way than to actually multiply it with B

[split heart]

That's a dog

[bold juniper]

You can make a exemple on a paper and send to me pls

[split heart]

https://tenor.com/view/how-about-no-sloth-chill-nope-no-gif-6121955

[formal gazelle]

I know

[split heart]

Come on man. It's just a matrix multiplication

All you have to do is check if you get identity back

[bold juniper]

Yes I

[split heart]

I can tell you right now that that is not B inverse

[split heart]

,rccw

[bold juniper]

On the up

[split heart]

Where's the inverse

I only see transpose

and the original B

[bold juniper]

What do you mean by inverse

When you transpose you inverse the original matrice

[split heart]

Transpose is not the same as inverse

not always

[bold juniper]

Ok

And inverse it’s mean I inverse the line and the column of the matrix ?

[split heart]

oh shit

there

[bold juniper]

I know this

,rccw

[split heart]

That's not right though

[bold juniper]

Why

[split heart]

You didn't change matrix

you just put -1/4 in front

look carefully at the formula, there are some changes that needed to be made to get the inverse

[split heart]

sorry but no

[bold juniper]

Why

[split heart]

because you have the wrong numbers. how about this - can you identify what a b c and d are in the matrix B so we can find the inverse together

[bold juniper]

Now it’s correct

[split heart]

Yes! Good

Now use that

[split heart]

use that B inverse here

[bold juniper]

Yes

I make this calcul ?

[split heart]

wait

[bold juniper]

Ok

,rccw

[split heart]

wait I just realized you messed up the off-diagonal elements

you swapped 2 and 1

[bold juniper]

Yes I miss up on the B^-1

Give me one second

[split heart]

sure

[bold juniper]

That correct ?

[split heart]

your off-diagonal element is still flipped

[bold juniper]

What do you mean

[split heart]

You're taking the inverse of the transpose

You're suppsoed to take the inverse of B

not the inverse of the transpose of B

[bold juniper]

Oh ok

Give me one second

[split heart]

you still have 2 and 1 flipped on the off-diagonal

you're not supposed to flip them

just change the sign

the only thing that flips are the diagonal elements

so that should be ((-2 -1), (-2,1))

[bold juniper]

That the correct one

Sorry

I am so dumb

[split heart]

No don't say that. That's why we're practicing

So simplify that and you finally have B inverse

[bold juniper]

Let me 4 min to resolve this

And find the matrix A

[split heart]

THEN you can multiply $B^T B^{-1}$

[twin meteor]

TooManyCooks

[bold juniper]

Thank bro

[split heart]

Yep that's it

Good job

[bold juniper]

Thank

[vocal sleet]

@bold juniper Has your question been resolved?

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[bold juniper]

Yes

[vocal sleet]

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[quartz gull]

What is the difference in domain for between ln(x^2), 2ln(x) and ln(x)^2 (also kinda confused why these functions have all different graphs)

[sly sierra]

what values you can you legally feed to ln?

[quartz gull]

0

[sly sierra]

yes

[vast shale]

<@&286206848099549185>

[sly sierra]

so consider ln(x^2), is x^2 always positive?

[quartz gull]

Yes

[sly sierra]

why are you pinging helpers in someone else's channel

[sly sierra]

what if x=0

[quartz gull]

So the domain is always positive

[vast shale]

wait there is one here

mb

it died for a bit

thats why

i rlly need help

[quartz gull]

all reals except 0

[sly sierra]

yes

correct

[quartz gull]

Okay but why in like algebra 2 the teachers tell you the log properties are

Like are they out there to confuse you later in life

[sly sierra]

what's wrong with those properties

[quartz gull]

log (x^2) != 2log(x) in domain

[sly sierra]

no

those properties hold assuming that all the numbers (m,n etc) are positive

[quartz gull]

OHhh okay

[sly sierra]

what you can do for log(x^2) is to recognize that x^2 = |x|^2

then log(x^2) = log(|x|^2) = 2log(|x|)

as long as x is nonzero, that works

[quartz gull]

oh okay

okay

then why is ln(x)^2 different

I really don't get that one

[sly sierra]

ln(x)^2 and ln(x) have the same domain

x>0

[quartz gull]

So is ln(x - 3)^2 = ln(x^2 -6x + 9)?

[sly sierra]

well it depends what your notation means

are you squaring first, or are you taking the log first

to avoid ambiguity, you could write either
(ln(x-3))^2
or
ln((x-3)^2)

[quartz gull]

the second one

and the domain would be all reals but 3 right?

[sly sierra]

yes

[quartz gull]

Okay, that makes more sense

Thank you so much!!

[sly sierra]

sure, yw

[quartz gull]

.close

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[worldly folio]

idk how to start

[sly sierra]

hint to get started, $t\sqrt{t} = t^{3/2}$

[twin meteor]

Bungo

[worldly folio]

multiply by conjugate?

no

that doesn't work

@sly sierraI can't cancel anything out, idk what i can multiply by

maybe if i look at it like a rational function

[sly sierra]

try dividing num and denom by the highest power of t

because as it stands you'll get an indeterminate form

[worldly folio]

is that not t^1

or just t

[sly sierra]

t^(3/2) is a higher power than t

[worldly folio]

oh true

[sly sierra]

3/2 is bigger than 1

so try dividing by t^(3/2)

[pallid mirage]

what is 1+1

[karmic imp]

Don't troll

[worldly folio]

ok

i def did something wrong

but i got

(t-t^2)/t^2+3t√t-5√t

it def wrong though

$t(t-t^2)/t^2-3tsqrt{t}-5sqrt{t}$

[twin meteor]

eidan
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[worldly folio]

oh

well sorry first time using this bot

lol

@sly sierra

<@&286206848099549185>

.close

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[worldly folio]

.close

[void badger]

Why is it that when I compute local extreme for multivariate functions I only consider the region, but for absolute extreme I also consider the boundary?

[vocal sleet]

@void badger Has your question been resolved?

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[paper zephyr]

would a likert scale be quantatitive data?

[paper zephyr]

for ap statistics

<@&286206848099549185>

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

@paper zephyr Has your question been resolved?

[vocal sleet]

@paper zephyr Has your question been resolved?

[vast shale]

yes

ap stats

or ap cauuu?

[vast shale]

qualitative

[vocal sleet]

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[full vessel]

if a polynomial is divisible by 1 plus sqrt 3 is it also always divisible by 1 - sqrt 3

how did it know to go to 1 - sqrt 3

or did it just test it out to see

[dull maple]

Because coefficients of the polynomial are rational.

So irrational roots will occur with their conjugate.

[dull maple]

Also, i suppose you meant to say that polynomial is divisible by (x - (1 + sqrt(3)). Same for (1-sqrt(3)).

[full vessel]

what does this mean ;-;

[full vessel]

oh yep my bad

[dull maple]

That is to say that whenever $a + \sqrt{b}$ is a root, $a - \sqrt{b}$ will be a root too.
Mind you - only for polynomials with rational coefficients.

[twin meteor]

Enemagneto

[full vessel]

ohh thank you !

got itt

adios

:)

[dull maple]

Good. Make sure that you understand it.

[full vessel]

i do now thanks :D

.close

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[deep light]

Im stuck on trying to figure out what to do for part c)

[deep light]

Do we need to substitute the previous augmented matrix in place of w1 w2 w3 and then find A? Or do we just equate LHS w(x, Y) as the augmented matrix then solve for A?

[flat whale]

,rotate

[vocal sleet]

@deep light Has your question been resolved?

[vocal sleet]

@deep light Has your question been resolved?

[plucky rock]

That's only for natural coeff ig

[dull maple]

No.

Take $k(x^2 - 7x -3)$ and choose k to be any rational number which is not a natural number.

[twin meteor]

Enemagneto

[vocal sleet]

@deep light Has your question been resolved?

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[vital heron]

Out of 40 athletes, 21 plays basketball, 19 plays volleyball, 13 plays soccer, 4 plays soccer and volleyball, 10 plays volleyball and basketball, 6 plays basketball and soccer, and 2 plays all three. How many athletes doesn't play any of these sports?

[vital heron]

I got 5😭 is that correct?

[dull maple]

Yes

[vast shale]

draw a venn diagram id recommend, if you want to verify

[vital heron]

I did! But I'm not sure if I did it right..

[vital heron]

Thank you💛

[vocal sleet]

@vital heron Has your question been resolved?

[vocal sleet]

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[versed night]

what is it

[thin vale]

<@&268886789983436800>

[paper depot]

how old is grade 4?

then you're too young to be on discord at all, sorry!

come back in 3 years.

you don't care but we do.

discord's terms of service do not allow people under 13 years old.

<@&268886789983436800>

[fair plover]

Yeah you are definitely a 4th grader

[paper depot]

<@&268886789983436800>

[fair plover]

[lost yarrow]

.close

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[sleek perch]

how do i get the 10%

[sleek perch]

the other is the answer but yeah i dont understand how to get 207 000

[vocal sleet]

@sleek perch Has your question been resolved?

[sleek perch]

<@&286206848099549185>

[vocal sleet]

@sleek perch Has your question been resolved?

[sleek perch]

<@&286206848099549185>

[inner solstice]

Yes

Divide by 10 i guess

[inner solstice]

×100/10

[sleek perch]

what?

[inner solstice]

Idk

[sleek perch]

https://tenor.com/view/ugh-shame-no-shy-embarrassed-gif-14727283

someone pls help

[vocal sleet]

@sleek perch Has your question been resolved?

[quick maple]

Please don't put memes in this server, it is only for help and study

<@&268886789983436800>

[vocal sleet]

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[vast shale]

Is this correct

[neat iron]

Not quite imo

I interpret the statement as: for any (arbitrary) odd natural number, there exists a natural number that is larger

That already tells you that you should probably use a $\forall$ somewhere in the statement

[twin meteor]

(R / I) / (J / Inuyasha

[vast shale]

Hmm

[neat iron]

You're almost there, but the odd condition is applied at the wrong place

What you've written down now is: for any (arbitrary) natural number, there exists an odd natural number that is larger

(Which is also a true statement btw )

[vast shale]

Is the odd(y) i need to change place

[neat iron]

Not just that, it's the x that is supposed to be odd in what you've written down

[vast shale]

Ah i see

This should be right

[neat iron]

It's actually wrong for multiple reasons

[vast shale]

What is wrong here this time

[neat iron]

First of all, where did the oddness condition go

Second of all... that statement doesn't even make mathematical sense

"There exists a natural number x such that for all natural numbers y, we have that x > y is true"

That's clearly impossible

[vast shale]

??

[neat iron]

[vast shale]

Could I write

This shoud be right, but the quantifier should be changed at x ?

??

.close

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[steady kraken]

what is the right equation for this problem?
7.50+0.12(30-25) or 7.50(5)+0.12(30-25)?

[steady kraken]

.close

[vocal sleet]

Channel closed

Closed by @steady kraken

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[fiery egret]

how to solve?

[fiery egret]

is it A?

[formal gazelle]

!status

[vocal sleet]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[outer warren]

what's your reasoning for option A

[fiery egret]

if (x-5) goes to rhs y=0 and if y goes then x=5

so i thought x=5

[outer warren]

wdym by goea to the right side

[fiery egret]

0/(x-5)

=0

[outer warren]

bad idea, also overcomplicating

you've solved quadratic equations before right?
applied zero product property / null factor?

[fiery egret]

yeah

[fiery egret]

yes

[outer warren]

apply that here directly

[fiery egret]

oh yes

thanks

.CLOSE

.close

[vocal sleet]

Channel closed

Closed by @fiery egret

Use .reopen if this was a mistake.

[fiery egret]

.reopen

[vocal sleet]

✅

[fiery egret]

is the ANSWER A?

it must be D ?

[outer warren]

which one, A or D

explain your reasoning

as well

[fiery egret]

d as x-5 =5 then x=0 as well and y=0 was considered making and one case both 0 then x=5 as well

[outer warren]

can you rephrase that?

very hard to udnerstand what you mean there

[fiery egret]

i said d as if x-5 =-5 we get x=0 and y=0 was considered making C. but in one case only y = 0 and (x-5)=0 then x=5 as wells

[outer warren]

wording is still bad

wdym by if
x-5 = 5 we get x=0

[fiery egret]

i mean (x-5)=-5

[outer warren]

() make no difference tehre

why's x-5 being set equal to 5

[fiery egret]

like if it were that

and y=0 is there

can you get it?

[outer warren]

no

i still don't udnerstand what you're trying to say

[fiery egret]

ok i send a pic

[outer warren]

ahk.

so you're showing that when
y=0, is there are more than one possible value for x

which is fine. you can deduce option D from that.

though you can reach that conclusion directly from zero product property

no need for multiple cases

if y=0,
0 * (x-5) = 0
doesn't matter what (x-5) is

[fiery egret]

right

got it

thanks a lot!!

.close

[vocal sleet]

Channel closed

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[vocal sleet]

@slate plume Has your question been resolved?

[vocal sleet]

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[native kiln]

HI

[native kiln]

$/\int \left(4-3X\right)^{-3}/$

$\int \left(4-3X\right)^{-3}$

[twin meteor]

svnset

[night radish]

Hi

[native kiln]

THIS IS AN INDEFINITE INTERGAL

I NEED HELP SOLVING IT

[night radish]

im pretty sure you can refer to expression in the brackets as the X in the integral

[strong grove]

multiply and divide the derivative of that which would be -3 and then use the integral power rule

[obtuse sierra]

u-sub if you are new to this

[copper cloak]

can somone solve this 2 questions plss

[vocal sleet]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[night radish]

how the bot knows he asking a question?

[obtuse sierra]

I know everything.

[native kiln]

integral power rule

$-\frac{1}{3}\int \left(4-3X\right)^{-3}$

[twin meteor]

svnset

[obtuse sierra]

nah

also why is there a 1/3

you just changed the expression

[strong grove]

he meant to do this

[native kiln]

u = 4-3x

du = -3dx

[obtuse sierra]

oh forgot to multiply

[strong grove]

yes

[native kiln]

du/-3 = dx

now what do i do

[harsh canopy]

Sub in the U

[strong grove]

use those values in the question , integral (u)^-3

[native kiln]

$-\frac{1}{3}\int \left(4-3X\right)^{-3}$

[twin meteor]

svnset

[native kiln]

like this one

[strong grove]

no?

[harsh canopy]

Sub in U