help-17

[delicate stirrup]

btw

i guess it has chatgpt API in it

[vocal sleet]

@vast shale Has your question been resolved?

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[modest cedar]

How should I begin to approach this problem?

[mild flower]

distribute it out and then combine like terms

wait hang on

you're supposed to find $\f{f(x_2) - f(x_1)}{x_2 - x_1}$ here

[twin meteor]

hayley!

[modest cedar]

wait it's sideways

ok nvm idk whats going on

[mild flower]

that's right

[modest cedar]

is that it?

[mild flower]

yea

[vocal sleet]

@modest cedar Has your question been resolved?

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[vast shale]

what is the way to solve this

[vast shale]

i keep getting wrong answers

[fathom drum]

first, you can remove the terms with the coefficients 0

[fathom drum]

oh wait, are you supposed to use matrices to solve it

[vast shale]

no

i can remove the 0's i put them myself

this is a physics problem

but the math is the problem here

[fathom drum]

do you want to use matrices to solve it?

[grand ledge]

can you use equation systems?

[fathom drum]

you don’t have to

[vast shale]

i tried to just solve for one and insert in the other

but that doesnt seem to get me anywhere

i rly only need to find either a or b, since they will be same number but with +/- and then i can find c right afterwards

[paper depot]

a + c = 0
2a + b = 2
-a - b = 0

to strip away the unnecessary fluff

you get that b = c = -a from the first and last eqs

[vast shale]

yes

[fathom drum]

you can get b and c in terms of a

[fathom drum]

and then you can substitute into the second equation

[vast shale]

yes but i get like 1-b/2

i would like to find an actual number

[paper depot]

2a - a = 2 ...

[vast shale]

2

[fair plover]

You need to find the value of a, b and c?

[vast shale]

yh

[fair plover]

What is the value of a?

[vast shale]

2

b = -2

c = -2

[fair plover]

Then?

[vast shale]

i can get it to work with algebra

[fair plover]

You are correct

[vast shale]

cant*

[vocal sleet]

@vast shale Has your question been resolved?

[fathom drum]

You just used algebra to do it

[vocal sleet]

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[upbeat plaza]

I do not know what it means by express roots in the form of a+-bsqrtc

[fathom drum]

have you solved it

[upbeat plaza]

well like i know how to solve it

[fathom drum]

it means exact form

[upbeat plaza]

wait what?

what do u mean by exact form fraction

Do u want me to solve it and let u know the answer?

[fathom drum]

Yes

[upbeat plaza]

ok give me a sec

@fathom drum

[fathom drum]

@upbeat plaza

Have you got it

[upbeat plaza]

My teacher asked me to use trial and error method for the first step to find one of the x value. But regardless of how many values I substitute I can't find the answer

[merry python]

Hint:||Try fractional values||

[upbeat plaza]

yeah i found it now -0.5

How can i find the value in first try itself?

Instead of multiple tries

[fathom drum]

there is no guarantee

[upbeat plaza]

then will i have to substituting millions of numbers to find the answer?

[merry python]

well for such questions, you need to test multiple values. Generally the roots are smaller numbers tho

[upbeat plaza]

yeah

[fathom drum]

not millions of numbers

it takes days to even count to a million

usually less than 4

[upbeat plaza]

its sarcasm man

okay

oh yeah

also guys

i am getting a remainder when im doing the polynominal long division

is it right or i am doing it wrong

@fathom drum ?

oops my bad

sorry to ping u

but pls answer me quick

thx

[fathom drum]

it’s ok, if I don’t respond, ping me

I may have forgotten

[fathom drum]

can you show your work

[upbeat plaza]

ah sure

[upbeat plaza]

there u go

[fathom drum]

Looks correct

What did you get when you substituted 0.5 in

[upbeat plaza]

-0.5

not 0.5,-0.5

wait a sec

let me check smth

[fathom drum]

then the corresponding factor is x + 0.5, not x - 0.5

[upbeat plaza]

Yeah I noticed

ok i get a divisible answer of 2x^2+8x-18

previously i mistakened the +0.5 with -0.5

i'll proceed with the next step @fathom drum

OK so the next step I did was f(x)=(x+1/2)(2x^2+8x-18)

They're asking to solve so (x+1/2)=0 so x=-0.5

And for the step 2x^2+8x-18=0
I get 2 answers which are -2 -sqrt 13 and -2+sqrt 13

@fathom drum

Hello dude???

When solving quadratic equation

i get roots

@fathom drum

or someone please help me would be very glad

@fathom drum @fathom drum ??

@merry pythonHello?

guys i got all the answer but what is a+-b sqrt c

​

actually i found the answer

thanks

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[steep inlet]

Watch me do this and guide me, send a cat if i made a mistake

[steep inlet]

No.1

[delicate stirrup]

is d an increment number?

[steep inlet]

This is generating patterns

[delicate stirrup]

if so, 5+4*10

[steep inlet]

Yo holup

Ur supposed to guide me and watch

[delicate stirrup]

ok

if d is what i think

then you have to add it to a1 until u get to the n=11

or in other words do it ten times

it is 5, 9, 13, ....

[steep inlet]

Broo

Holup

[delicate stirrup]

where 5 is n=1

?

[steep inlet]

a11 = 5 + (11-1)4

[delicate stirrup]

so

you got it?

[steep inlet]

45

[delicate stirrup]

sure

[steep inlet]

Ight, no.2

a25 = 14 + (25-1)-3

[delicate stirrup]

🐱

[steep inlet]

Ok.. hint?

[delicate stirrup]

you multiply

[steep inlet]

It says 21 if i multiply -3 to 24

Or (24)-3

[delicate stirrup]

-3*24

[steep inlet]

-72!

-72

Which is -58

The final answer

For no.2

@delicate stirrup

[delicate stirrup]

yes

[steep inlet]

Nice

Now no.3

a16 = 12 (16- 1)0.5

[steep inlet]

Oh yeah the plus sign on 12

Then the answer is 39/2

[delicate stirrup]

yeah

[steep inlet]

Or i choose 19.5?

Ight 39/2

No.4

I already made it so that it's
a1=-10 ; d=4 ; n=27

-10 + (27-1)4

[delicate stirrup]

yeah

[steep inlet]

94

[delicate stirrup]

ye

[steep inlet]

Nicee now no.5

It goes like a1=3 ; d= -0.5 ; n=28

3+(28-1)-0.5

[delicate stirrup]

🐱

[steep inlet]

Woah!

What gives?

It has to be -.5

[delicate stirrup]

yes

but..

[steep inlet]

Btu??

[steep inlet]

I got -10.5

[delicate stirrup]

yeah

i guess

[steep inlet]

That's enough answer for me

Thanks

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• Show your work, and if possible, explain where you are stuck.
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[patent slate]

s(x) = x² - 4x - 21

r(x) = x + 3

f(x) = 2x - 1

well um

uh

[split wind]

yea?

[patent slate]

so yeah, I'm having a hard time doing this

[delicate stirrup]

is first 4?

cause 2*1-1 = 1

1 + 3 = 4

[patent slate]

wat

this is operation on functions btw

[delicate stirrup]

so?

1 min...

[royal kestrel]

right so (f o r)(1) is equal to f(r(1))

just go right to left

r(x) = x + 3

ur output of r(1) will be ur input for f(x)

[delicate stirrup]

then 2*4 - 1?

[patent slate]

well, i got like
s/r = (x) = s (x) ÷ r (x)
= x² - 4x - 21
over
x +3

[delicate stirrup]

wait

[royal kestrel]

wait what question r we doing

10?

[patent slate]

i already got 10 😭

[royal kestrel]

11?

OH

okay

[patent slate]

need 11 & 12

sorry 😭

[delicate stirrup]

isn't f * r(x) = f(x) * r(x)?

[royal kestrel]

(s/r)(x) is equal to s(x)/r(x)

[royal kestrel]

yup

try factoring your numerator now

try middle term split

[patent slate]

yes

[royal kestrel]

$x^2 - 4x - 21$, split the middle term such that you have two numbers where $mn = -21$, and $m + n = -4$

then you can simplify afterwards

not simplify

i meant factor

[patent slate]

hm

lemme see

[twin meteor]

taro

[patent slate]

wat

im so sorry 😭

[royal kestrel]

okay

lets

recall our monic factorising

do you know how to factorise monic trinomials?

[patent slate]

no

sadly

im too dumb at math

[royal kestrel]

its weird ur doing functions before quadratics ngl

but its okay

give me 30 secs ill find something that should help

[patent slate]

AHSGAHSGAHS it's just

my teacher

told us so

yeah

[royal kestrel]

so in example a

they split 7x

into two terms

[patent slate]

oh

[royal kestrel]

that multiplied to give 12

and added to give 7

then you can factor it from there

[royal kestrel]

ur doing that here too

we have s(x)/f(x)

which we now have $\frac{x^2-4x-21}{x+3}$

[twin meteor]

taro

[patent slate]

yes

[royal kestrel]

this is a monic trinomial

and we want to do the same thing here

[patent slate]

So i have to

[royal kestrel]

we split the -4

into two numbers

that multiply to give -21

[patent slate]

so i have to split it right

[royal kestrel]

yup

recall the factors of 21

find the two factors which has a difference of 4

[patent slate]

1

3

7

is the factors?

HAHAHAH

[royal kestrel]

right so we have our factors (ur missing 21 but that won't matter)

one of our groups is 7 * 3

[patent slate]

yeah sorry for not including that

[royal kestrel]

which gives 21

but note that

we need to multiply to give -21

[patent slate]

hm

[royal kestrel]

and it has to add to **-**4

7 * 3 = 21

7 - 3 = 4

so we have to make one of the terms negative

to satisfy both equations

[patent slate]

so -7?

[royal kestrel]

great

[patent slate]

is that right?

[royal kestrel]

wait

yes

tahts right

[patent slate]

okay okay

[royal kestrel]

because -7 + 3 = -4

and -7 * 3 = -21

[patent slate]

so i have to

[royal kestrel]

so now we have

$\frac{x^2-7x+3x-21}{x+3}$

[twin meteor]

taro

[royal kestrel]

now we can group in pairs

actually ngl we can just skip the whole step

we have the two numbers

-7 and +3

i can just immediately factor in as so

$\frac{(x-7)(x+3)}{x+3}$

[twin meteor]

taro

[royal kestrel]

now do you see a common term here

[patent slate]

wait what 😭

[royal kestrel]

okay nvm

lets go back lmao

$\frac{x^2-7x+3x-21}{x+3}$

[patent slate]

im so sorry 😭

[twin meteor]

taro

[royal kestrel]

no dont be

its okay

we're back here right

[patent slate]

yes

[royal kestrel]

now let's factor the x^2 - 7x

what's the common term

that i can take out

[patent slate]

common term

hm

[royal kestrel]

like what do they have in common

[patent slate]

x

[royal kestrel]

great

[patent slate]

the variables right?

[royal kestrel]

$\frac{x(x-7)+3x-21}{x+3}$

[twin meteor]

taro

[royal kestrel]

now factor 3x - 21

what's a common term

in 3x and -21

[patent slate]

uh

[royal kestrel]

its not x this time

but theres something else they have in common

theyre both divisible by a number

that we can factor out

[patent slate]

factors?

Idk

🥲

[royal kestrel]

if i said

[patent slate]

gosh

[royal kestrel]

factor 2x + 4

they have

a 2 in common

they are both divisible by 2

[patent slate]

oh

[royal kestrel]

so i can factor out the 2

and it becomes 2(x + 2)

[royal kestrel]

now here

[patent slate]

3

[royal kestrel]

perfect

[patent slate]

i

guess

[royal kestrel]

so ill factor out a 3

$\frac{x(x-7)+3(x-7)}{x+3}$

[twin meteor]

taro

[royal kestrel]

agree

?

[patent slate]

wait

im tryna process everything

[royal kestrel]

so what we did

is factored the x from x^2 - 7x

then we factored the 3 from 3x - 21

[patent slate]

okay i don't understand now

[royal kestrel]

where'd u get lost

[patent slate]

so yeah, we have to split the -4 right?

so the -4 become

[royal kestrel]

yup

we split into -7 and 3

which satifies the equations we need

-7 + 3 = -4

-7 * 3 = -21

[royal kestrel]

which gave us this

then we factored the two left terms

then we factored the two right terms

[patent slate]

so it's now splitting, into x² - 7 + 3x -21 right?

[royal kestrel]

well

-7x

but other than that yes

[patent slate]

oh yeah sorry

[royal kestrel]

yup

[patent slate]

so 7 and 3 is the factor of 21

then

[royal kestrel]

yup

x² - 7x --> factor the x --> x(x - 7)
+3x - 21 --> factor the 3 --> 3(x - 7)

you factored those pairs

[patent slate]

i don't understand

omg

what's wrong with me 😭

[royal kestrel]

its okay

uhhh

when you factor something

[patent slate]

no really I'm sorry

[royal kestrel]

you take out a common term

its okay dont worry

do you know how to expand

like 3(x + 2)

for example

[patent slate]

no

i don't listen when it comes to math that's why

[royal kestrel]

so you dont know the

distributive property

?

a(b+c) = ab + ac

[patent slate]

no

😭😭😭

[royal kestrel]

shitttt

okay

with the distributive property

essentially

u multiply the number outside of the bracket

with each term inside

so

3(x+2)

is saying

[patent slate]

oh yeah

[royal kestrel]

3 * x + 3 * 2 = 3x + 6

thats the distributive property

expanding brackets

now factorising

[patent slate]

oh

[royal kestrel]

is putting it into that form

a(b + c)

$x^2 - 7x$

[twin meteor]

taro

[royal kestrel]

if i factor out the x here

it becomes

$x(x-7)$

[twin meteor]

taro

[royal kestrel]

then when i expand it

using the distributive property

i will get x * x

• x * -7

so i get x^2 - 7x

[patent slate]

oh

yeah

[royal kestrel]

yee u get how factoring works now?

great so when i do the second one

3x - 21

i take out the common 3

$3(x-7)$

[twin meteor]

taro

[royal kestrel]

then to test it, i can use the distributive property

which gives 3 * x - 3 * 7

so i get 3x - 21

which is what we started with

[patent slate]

yep

[royal kestrel]

$\frac{x(x-7)+3(x-7)}{x+3}$

now we got back to here, which was our $s(x)/f(x)$

[twin meteor]

taro

[royal kestrel]

now

what im going to do next

is a bit confusing

what do you notice in common

with

x(x-7) and 3(x-7)

[patent slate]

the 7

[royal kestrel]

what else

[patent slate]

and the variables

[royal kestrel]

they both have what?

[patent slate]

negative sign too

[royal kestrel]

what im looking for is that

they both have

(x-7)

in them

agree?

[patent slate]

well yeah

[royal kestrel]

now what im gonna do is

i can actually factor out the whole thing

i will factor the whole (x-7)

[patent slate]

yeah cancel right?

[royal kestrel]

nope ill factor it

[patent slate]

oh

okay

[royal kestrel]

think of $x^2 - 7x$, we factored the x, but in $x(x-7) + 3(x-7)$, i can factor the (x-7)

[twin meteor]

taro

[royal kestrel]

so i factor it out

which gives me $(x+3)(x-7)$

[twin meteor]

taro

[royal kestrel]

the two terms outside the bracket go into one bracket

then the (x-7) is factored out

it seems confusing

but as long as you know the process

its fine for now

THE MUCH EASIER WAY TO DO IT THOUGH

is

$\frac{x^2-4x-21}{x+3}$

[twin meteor]

taro

[patent slate]

it does

[royal kestrel]

when we were all the way back here

we found the two numbers -7 and 3

[patent slate]

yep

[royal kestrel]

we can immediately put it in

as (x-7)(x+3)

we can skip all of the

factoring in pairs

and everything

[patent slate]

so it's like

[royal kestrel]

its fine if u dont necessarily understand how you can factor out the (x-7) but as long as u get the process its fine

anyway so now we have $\frac{(x+3)(x-7)}{x+3}$

[twin meteor]

taro

[royal kestrel]

now

we have a common term

in the numerator and denominator

which is?

[patent slate]

x+3 and the other one under it

[royal kestrel]

great

[patent slate]

so we have to cancel it right?

[royal kestrel]

all we need to do

is cancel it

yes perfect

which leaves us with?

[patent slate]

X-7

[royal kestrel]

great

[patent slate]

so that's the answer?

[royal kestrel]

now because that was a lot of steps

[patent slate]

or

[royal kestrel]

ill quickly rundown what we did

[patent slate]

what's a rundown

[royal kestrel]

first we had $\frac{s}{r}(x)$ which we changed into $\frac{s(x)}{r(x)}$

[twin meteor]

taro

[royal kestrel]

we subbed s(x) and r(x)

which gave

$\frac{x^2-4x-21}{x+3}$

[twin meteor]

taro

[royal kestrel]

we then factorised by splitting the middle term

which gave

$\frac{x(x-7)+3(x-7)}{x+3}$

[twin meteor]

taro

[royal kestrel]

then factored the (x-7)

$\frac{(x+3)(x-7)}{x+3}$

[twin meteor]

taro

[royal kestrel]

then canceled the x + 3

leaving us with x - 7

as our final answer

[patent slate]

can I right it down?

[royal kestrel]

yeah

[patent slate]

it's for my report tomorrow and yk, i need it

so i have to right it down like this right

[royal kestrel]

mhm then next line we factored the x-7

[patent slate]

or

😭😭😭

[royal kestrel]

so (x+3)(x-7)

[royal kestrel]

yup

[patent slate]

sorry for the bad penmanship btw

is this right

[royal kestrel]

yep

[patent slate]

okay onto the next one

#12

this one

not x anymore

it's now -4

so i have to substitute the x's to -4 right?

[royal kestrel]

yup

so we have s(x)/r(x) again

$\frac{x^2-4x-21}{x+3}$

[twin meteor]

taro

[royal kestrel]

which was this i believe from last question

[patent slate]

yes

[royal kestrel]

then all x

[patent slate]

but the (x) is now -4

[royal kestrel]

replace with -4

yup

[patent slate]

yes

wait lemme right it rq

[royal kestrel]

$\frac{(-4)^2-4(-4)-21}{(-4)+3}$

[twin meteor]

taro

[royal kestrel]

evaluate this and lemme know what u get

then if u get stuck lemme know

[patent slate]

is this even right 😭

[royal kestrel]

very close

one error

its -4(-4)

[patent slate]

oh

so

[royal kestrel]

remember that

a double negative

gives a positive

so instead of 16 - 16

it should be 16 + 16 (as 16 - - 16 is 16 + 16)

[patent slate]

OHHH

right

[royal kestrel]

other than that

looks fine

then continue from there

$\frac{16+16-21}{-1}$

[twin meteor]

taro

[patent slate]

here

[royal kestrel]

👍🏻

neat handwriting

[patent slate]

it's not even that good handwriting

[royal kestrel]

nah its pre good

better than mine at least

anyway that's it

[patent slate]

well, it's done now

[royal kestrel]

great

have a good day then :)

[patent slate]

thank you so much for your help!

[royal kestrel]

use .close when solved

[royal kestrel]

no worries happy to help :)

[patent slate]

.close

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• Show your work, and if possible, explain where you are stuck.
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[plain aurora]

does anyone know what phi(33) is?

is it euler's totient functino?

[gaunt sparrow]

For RSA since it's the product of two primes (the keys), phi(n)=(p-1)(q-1) where n=pq and p,q are prime

But it is indeed the totient function

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@plain aurora Has your question been resolved?

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[little isle]

hi

[little isle]

where did I went wrong

[somber harbor]

What is the question originally

[river minnow]

It's really unclear what you are trying to do there

[little isle]

3

[turbid forum]

it is (2a+b)(2a+b)

Not (2a+b)(2a-b)

[little isle]

Why

but it says the square of sum anf difference?

OH YAH

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[timber wagon]

It's not really a question but is the correct answer for this b)n²

[timber wagon]

@reef grove sorry for pinging y'all

Nvm i got it

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[golden lake]

im confused on number 2

[golden lake]

because of "2f" and "3g"

should i write it as 2(x-2)

and g(x) = 3(x^2-1)

[river minnow]

Yeah you are just gonna simplify 2f(x) - 3g(x)

[golden lake]

so i just need to distribute those numbers?

before subtraction both

[river minnow]

Yes

[golden lake]

thank you : )

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[eternal glacier]

is this correct in assuming x_2 = s, x_5 = t, and x_6 = u?

or did I write the free variables incorrectly in general form?

[paper depot]

i mean if your goal's to write down the general solution of this system then you haven't quite done so yet, for precisely one reason:

your expression for x_1 still has x_3 in it, which it shouldn't. and it's an easy fix.

[eternal glacier]

yes I think what I am finding is that my answer for x_1 does not account for x_3

is that what you mean?

[paper depot]

i uh

no not quite?

[eternal glacier]

I just replace x_3 with -t - 2u

so -2(-t-2u)

[paper depot]

i just wanted you to substitute your expression for x_3 into that of x_1, and simplify

watching out for sign and arithmetic errors

[eternal glacier]

OK thanks

[paper depot]

im gonna take all this on faith.

[eternal glacier]

hopefully this should work now, when I plug in the entries into the input boxes

i will give it a try

[paper depot]

just be sure not to fuck up which coeffs go where, lol.

[eternal glacier]

woot woot

tyty

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[rain vale]

<@&286206848099549185>

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[delicate stirrup]

a) acceleration is change of speed

in this case m/s/s

[rain vale]

i just need 1c

[delicate stirrup]

what is the half distance?

[rain vale]

90

[delicate stirrup]

umm

isn't it 215?

[rain vale]

how

[delicate stirrup]

15*30/2

[rain vale]

OH

right

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@rain vale Has your question been resolved?

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[late parrot]

Need some help with the first question, I’ve got up to turning it into the square root of 4x^3 but im stuck there

[grand ledge]

how did you get it to 4x^3?

[late parrot]

Square root of 4x^3

But I did the fractional index law/exponent

[grand ledge]

what happens if you multiply ^3 with the ^1/2

[late parrot]

Am I meant to do that?

[grand ledge]

yea you dont need to turn these into square root

[grand ledge]

does it tell you what to do next?

[late parrot]

Tells me all the way to the answer, I’m just trying to make sense of the steps

This is the next step

I don’t understand why the base is 2

[grand ledge]

right ok, i guess thats a different way of doing it, sorry im not used to it that way

wall square root of 4 is 2

so the answer you should get it 2x^3/2 right?

[late parrot]

But the square root is still there

Alright well if u know another way pls explain that because I don’t understand this one anyway

[grand ledge]

whats the next stop? does it still keep the square root with 2 ?

[late parrot]

If u think ur way is easier id rather learn that instead

[grand ledge]

Sorry I confused myself, but the way we do it here is the rule (a^b)^c=a^b*c)

so the (4x^3)^1/2 would become 2x^{3/2}

I dont know why its keeping the square root there

[late parrot]

Do yk how to use @twin meteor ?

[grand ledge]

I think so

[late parrot]

Can u pls try it? I find it difficult to visualise things like that

[grand ledge]

I think its better someone else answer that uses the method you are using tho

[late parrot]

Well I’ve never done this kind of question so I don’t have a method

That method was from Photomath

[grand ledge]

ok

[late parrot]

Wait this is just the index law right?

[grand ledge]

its one of the potent law

so the potent rule is $$a^b)^c=a^b*c$$

[twin meteor]

Totalani

[grand ledge]

wops

[late parrot]

Ah yes I understand that but

I could understand what you’d written

[grand ledge]

ok

[late parrot]

So where did the 3/2 come from?

[grand ledge]

so you use that rule to multiply the $$^3$$ with the $$^{1/2}$$

[twin meteor]

Totalani

[grand ledge]

and you get 3/2

[late parrot]

Oh ok

So what’s the next step? Or is the final answer 2x^(3/2)

[grand ledge]

yea you cant simplify beyond that

you could say 2x^{1.5} but thats the same thing

what answer do you get from the site?

[late parrot]

2x square root x

I think that’s cuz it kept the square root the whole way thru

[grand ledge]

yea thats fine I guess

it keeps the half as square root

[late parrot]

Ah I see

I prefers urs

[grand ledge]

yea I think it looks better

[late parrot]

I think I understand that now but do you mind just helping with 1e) to check I understand it?

[grand ledge]

sure

[late parrot]

So 3 * 1/3 = 1

So is the answer just 8x?

Wait I forget the cube route

2x

[grand ledge]

what you can do is simplify 8

so it has the same potens as the x

[late parrot]

But x doesn’t have any

3 * 1/3 = 1 so it’s just x

[grand ledge]

you said e?

which question

[late parrot]

Question 1 e

[grand ledge]

yea

simplify 8 into 2^3

[late parrot]

Is that the first thing to do?

[grand ledge]

sure

then you can multiply both with the outside potent

[late parrot]

(2^3 * x^3)^(1/3)

[grand ledge]

so $$(2^3*x^3)^{1/3}$$

[late parrot]

?

[twin meteor]

Totalani

[grand ledge]

yea

[late parrot]

So then 3 * 1/3?

[grand ledge]

yea on both

[late parrot]

On the 2 and the x?

[grand ledge]

yea

[late parrot]

So then what would I write after that?

2x?

[grand ledge]

that would be the answer yea

multiplying 3 with 1/3 would be1

[late parrot]

The final answer is 2x?

[grand ledge]

thats what im getting yea

[late parrot]

But the 3 and 1/3 kinda cancel out so if it had been ^1/2 would the answer be 2^3/2 * x^3/2?

[grand ledge]

well it doesnt cancel out

its still multiply

[late parrot]

Yh but it makes the answer quite simple so if it was 1/2 instead of 1/3 would the answer be what i said there?

[grand ledge]

if it was 1/2 and you multiplied with 3 you would get 3/2, im not sure I understand what you mean

[late parrot]

Yeah you’d get 3/2 so how would you display that in your answer?

[grand ledge]

in this case its 1/3 so the answer is 1

which you dont need to write

and the answer should be just 2x

[late parrot]

Yeah but if it had been 1/2 or anything that didn’t equal 1, how would I show it in an answer?

Cuz they won’t always equal 1

[grand ledge]

right

you could write ^3/2 or ^1,5

whats waht we got on the first question remember?

2x^3/2

[late parrot]

So you’d only put it on the x?

Or would it be (2x)^3/2?

[grand ledge]

in that case it has nothing to do with the 2

just the x

[late parrot]

Ah ok

[grand ledge]

you already simplified the 2 from 4

[late parrot]

I see now

Well that’s all, thank you very much for the help, was great

[grand ledge]

my tip is to see the ^1/3 as how many times do I multiply to get that number

look at f

what number can you multiply itself 3 times to get 125?

[late parrot]

5

[grand ledge]

yea

same with x^6

multiply x^2 3 times you get x^6

and that is the answer to f

5x^2

🙂

[late parrot]

Ah I see

Tyvm

[grand ledge]

np good luck

[late parrot]

Ty 🙂

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[timber gale]

I NEED some assistance pls

[timber gale]

I can’t do basic log

Shoot it’s sideways

[tardy dagger]

convert 3 in terms of log

use log properties and equate

[timber gale]

Can you elaborate on convert 3 in terms of log pls

[tardy dagger]

well

log 10^2 (base 10) is?

[timber gale]

10^x = 2?

I think I’m wrong

[tardy dagger]

no

10^x = 100

what is x

[tough valve]

Easier method is take logx =t and log10 base x = 1/t

[timber gale]

X is 10

[tardy dagger]

oh right thats way easier

[tardy dagger]

its 2

10^2 =100

[timber gale]

Ah yep I can’t do maths Sox

[tardy dagger]

10^10 is very big

[timber gale]

ah yes

[tardy dagger]

100million i think

idk

[timber gale]

I realised

[tardy dagger]

anyways do what he said

take log x as t

make equation

[timber gale]

Guys let me saturate the info for a sec I just self learnt log

Ok

[timber gale]

Umm I though i was tripping out but isn’t it 10^x = 2 in exponential form

Or we aren’t looking into that

[tardy dagger]

wait imma write it down coz base and stuff

[timber gale]

Something like this?

[timber gale]

And for the other one

[tardy dagger]

yes

[tardy dagger]

yes

[timber gale]

So I just make 3 = log(1000)

[tardy dagger]

yes

base is 10 right?

[timber gale]

Yes

Damn

[tardy dagger]

but but

[timber gale]

Yes?

[tardy dagger]

take logx as t

and solve

its just better

[timber gale]

Ah

Wait let me saturate that in

[timber gale]

Wait wdym by log x

Like the base?

[tardy dagger]

the whole term

make it t

then solve it like a normal equation

[timber gale]

So like Logb= t

[tardy dagger]

this would basically become 5t=3+2t

[timber gale]

What happens next lol? Solve for t?

T=1

Bro I swear if it’s just that simple

[tardy dagger]

it is....

[timber gale]

Duck

Thanks man I’m ngl I have an exam in 5 hours and it’s 3 am and I didn’t do a single log homework that helped thanks

A 2 hour exam aswell but it’s fine

thanks again

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[tardy dagger]

np

[timber gale]

Lol

[tardy dagger]

revise properties u will ace it

[timber gale]

It’s a yearly exam

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[timber gale]

Wait @tardy dagger

[tardy dagger]

yes

[timber gale]

Product rule yes?

So just times it

Or t again

No it’s not an equation

Nvm I just did it it’s simple

Mb for pinging you again

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[tardy dagger]

its ok

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[vast shale]

is the first is wrong first of all

second is wrong as well

unsure about third yet

but lets see

[worthy citrus]

i think theyre all wrong hence the red

[stiff ivy]

I agree

[worthy citrus]

oh or does the red just mean one in that group is wrong

either way this is just going to be arithmetic and sign errors

do them again slowly and carefully

[eternal glacier]

did I mess up the order?
1,1 * 1,1
1,2 * 2,1
1,3 * 3,1

row, column

[vast shale]

this is wrong

-18-42+36 is not equal to -60

[eternal glacier]

OOPS

that would kill them

ty

[vast shale]

otherwise ur multiplication is correct i believe

not for the second lets see

-45+15+64 is not equal to -30

but yeah its like what sigma said its simple arithmetic mistakes

just go over them slowly

[eternal glacier]

ty

[vast shale]

i will leave the last one for you to attempt to debug and find the problem with

[eternal glacier]

i should probably use calculator next time just to be sure i don't mess up

[vast shale]

Always good practice to do arithmetic in your head regardless though

[eternal glacier]

ty

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[glass jewel]

Can you folks help with maple?

Why does my graph look so weird?

[glass jewel]

it is supposed to look like this

[flat whale]

uh just plot in desmos

[late grove]

Both of the functions you're plotting have 1/0 discontinuities at roughly the same location

[glass jewel]

the functions are supposed to be identical?

[glass jewel]

I have to use maple, sadly

oh i forgot to include the functions for the last pic

[late grove]

sqrt(6) is an irrational, so you can't fully write it in decimal expansion, so the two functions would not be exactly equal

[glass jewel]

Yes, but that's not the point, I guess I didn't explain it well, first picture is me graphing two functions, second picture is the answer to the exercise graphing the same functions, but they look much different?

here are the functions graphed in the 2nd pic

[flat whale]

Answer your question in desmos first

[glass jewel]

you want me to make the graphs in desmos?

[late grove]

Using Desmos helps to double check what's going on

[glass jewel]

so it looks like this one i guess

so it seems to me like something weird is going on with my maple

[vocal sleet]

@glass jewel Has your question been resolved?

[somber portal]

thats finite precision artifacts. You're zooming in way too much.

[glass jewel]

the exercise literally told me to zoom like this and in the solution to the exercise they zoom the same and it looks normal?

so like, it should be possible to zoom like that somehow?

[glass jewel]

whatever

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[vast shale]

What is the exponential function formula for this f(x)

[vast shale]

I cant put it correctly in desmos

[grand ledge]

um

a(0,88)^x since its 12%

x is years

a is value of car

[vast shale]

thanks it works

[grand ledge]

please close