What is your question?
#help-17
chrome raptor
vital oxide
What is your question?
vocal sleetBOT
@vital oxide Has your question been resolved?
vocal sleetBOT
@vital oxide Has your question been resolved?
vital oxide
<@&286206848099549185> would someone be willing to solve this
vocal sleetBOT
@vital oxide Has your question been resolved?
vocal sleetBOT
@vital oxide Has your question been resolved?
bleak oak
i think the hint is pretty clear
vast shale
Why is x/y=y-6 not a function?
vocal sleetBOT
Why is x/y=y-6 not a function?
pallid zenith
try graphing it
vast shale
what if i don't want to graph it
dreamy viper
then cope
late grove
Bruh
vast shale
like can i find this algebraically
pallid zenith
like can i find this algebraically
its not a function of x
just multiply by y on both sides
pretend y!=0
its not creating the overall problem here
fading mist
vocal sleetBOT
fading mist
so how am I supposed to figure this out?
fading mist
you mean -1 in the square root thing?
pallid zenith
right
twin meteorBOT
jan Niku
pallid zenith
@fading mist is that helpful?
fading mist
im still abit confused o_o
heres an example im given to help but it just confuses me more
twin meteorBOT
jan Niku
pallid zenith
this is just following the example naively
do you feel you understands the first 3 steps that lead to this?
pallid zenith
you'll want to factor things here
then you'll want to split the root
i mean they use like
$\sqrt{-125} = \sqrt{(-1)(125)} = \sqrt{-1} \sqrt{125}$
twin meteorBOT
jan Niku
pallid zenith
have you simplified radicals like the remaining sqrt(125) before?
fading mist
not that I can remember
fading mist
so like 3x25?
fading mist
can you factor a number
or 5x15 right
thats factoring if im recalling correctly
OHHHHH WAIT
ok so sqrt of 125 gets broken up into sqrt3 sqrt25
which ends up with 5i sqrt3
right?
pallid zenith
sorry man i got super distracted
pallid zenith
pallid zenith
np
fading mist
.close
lethal hornet
How would I solve #10?
vocal sleetBOT
How would I solve #10?
lethal hornet
vocal sleetBOT
@lethal hornet Has your question been resolved?
vocal sleetBOT
@lethal hornet Has your question been resolved?
vocal sleetBOT
@lethal hornet Has your question been resolved?
cobalt ocean
find AB, then multiply it by 3/4, then add that to A
vocal sleetBOT
@lethal hornet Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
hearty lance
Hi guys, it looks simple but I couldn’t figure it out.
vocal sleetBOT
Hi guys, it looks simple but I couldn’t figure it out.
vast shale
You're gonna need to explain what it is
hearty lance
You're gonna need to explain what it is
Isn’t it obvious? matrix is formed according to a certain rule and it’s asking the X ?
paper depot
the words "a certain rule" sure are doing a lot of heavy lifting tbh
how are we meant to know what rule it is?
hearty lance
how are we meant to know what rule it is?
That is the question my friend it’s asking to us to figure out what is the rule between these numbers.
paper depot
well there isn't enough info imo
hearty lance
If you know the rule then it’s very easy to find the answer
paper depot
nothing jumps out to me at all
hearty lance
1+3+3=7 and 2+5+6=13
Yeah but not so simple 🙂
I tried so many thing like squares factorial some equations but I couldn’t
paper depot
then maybe this question is not worth the trouble?
its "intended answer" cannot really be that much enlightening.
hearty lance
then maybe this question is not worth the trouble?
That is just giving up 😄
vast shale
You should try it sometimes
hearty lance
.close
vocal sleetBOT
paper depot
good start 
vast shale
That is just giving up 😄
I'll hand you an unsolved million dollar problem and hope to see you never give up
vocal sleetBOT
Available help channel!
vast shale
vast shale
No
split wind
note that: $\frac{a}a=1$ for $a≠0$
twin meteorBOT
Biscuity
vocal sleetBOT
@vast shale Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
tough cipher
vocal sleetBOT
tough cipher
tough cipher
what is the measure of the angle ACB?
not givrn
whole oasis
I know, but I want you to calculate it
small quarry
am going to help
AE // DC, AB = AC
Solved
Poopus u there right?
So first of all, the finally step I use to find x is using ext. angle of triangle
Let x = angle ABD
x = angle BAC + angle ACB
Ye, this is the tips
Hope u can do it
tough cipher
im getting 70 degrees as the ans
tough cipher
thanks for the help
vocal sleetBOT
@tough cipher Has your question been resolved?
worn garden
im getting 70 degrees as the ans
ansseer is 110
south badge
Hello!
coarse ridge
No
worn garden
What are intervals
coarse ridge
See where the graph is above the x-axis and where it's below the x-axis
coarse ridge
What are intervals
Intervals are intervals.
worn garden
See where the graph is above the x-axis and where it's below the x-axis
hw
so its the 4th option right?
worn garden
🗿 👍
dont get it
Isn't interval like the distance?
Why is it being representated as points (2,inf)
coarse ridge
[a,b] = ${x \in \mathbb{R} : a \leq x \leq b }$
coarse ridge
Square brackets means ends included
worn garden
ic
coarse ridge
Open means ends excluded
Semi open means one end included and other excluded like (7,8]
coarse ridge
so whats the answer?
||1||
coarse ridge
F
twin meteorBOT
Vaffle Man
[a,b] = $\left{x \in \mathbb{R} : a\leq x \leq b \right}$
```Compilation error:```! Missing delimiter (. inserted).
<to be read again>
{
l.57 [a,b] = $\left{
x \in \mathbb{R} : a\leq x \leq b \right}$
I was expecting to see something like `(' or `\{' or
`\}' here. If you typed, e.g., `{' instead of `\{', you
should probably delete the `{' by typing `1' now, so that
braces don't get unbalanced. Otherwise just proceed.
Acceptable delimiters are characters whose \delcode is
nonnegative, or you can use `\delimiter <delimiter code>'.```
Normed
coarse ridge
Finally 
vocal sleetBOT
@south badge Has your question been resolved?
spiral lark
A curve has the function 𝑦 = 𝑥^4 + 8𝑥^2 − 20𝑥 + 8.
Show that the only stationary point for this function is a minimum.
Use mathematical reasoning to justify your response.
spiral lark
I know that I have to get the derivative of the y and resulted in
y = 4x^3 + 16x - 20
and that stationary points mean the gradient is 0
so
0 = 4x^3 + 16x - 20
vast shale
right
outer warren
I know that I have to get the derivative of the y and resulted in
y = 4x^3 + 16...
that should be y'
spiral lark
yea
outer warren
did you do anything after this
spiral lark
y'
I'm not sure what to do after this
I can't find what x is
since it's a cubic function
vast shale
so
0 = 4x^3 + 16x - 20
solve for x here
spiral lark
how
outer warren
first note that all terms have a common factor of 4
spiral lark
sure
outer warren
you should be able to identify a real solution by inspection
spiral lark
x^3 + 4x - 5 = 0
vast shale
there is quite a obvious solution
spiral lark
what on earth is inspection
outer warren
where's 5x^3 coming from
spiral lark
opps
outer warren
inspection is an educated guess based on what you see,
as opposed to random/blind guessing
outer warren
make an educated guess, or just try simple numbers
outer warren
it may be viewed as testing values,
such as in the application of rational root theorem
outer warren
its just that you should be able to able to identify a solution just by looking at this
try not to overthink this
outer warren
yes
outer warren
well i wasn't expecting to spend this much time on this specific step
there is more to do after identifying 1 as a solution
spiral lark
if I know that x = 1 is then I can solve the rest
just plug it into the original
find 2nd derivative
and show that it's a minimum
outer warren
there's still more to do after that
spiral lark
what else ?
outer warren
because the work done so far would only indicate that there's a stationary point at x=1
but you haven't shown that there's only one stationary point
i.e. you'd need to show that
x=1 is the only real solution to
x^3 + 4x - 5 = 0
spiral lark
doesn't the question already state that there's only 1 stationary point ?
spiral lark
the only trouble I'm having is with the educated guess step still
spiral lark
maybe I am, but this is a semester final and I really dun wanna fuk this up
outer warren
it shouldn't be that difficult to recognise that x=1 will be a solution
and especially since you're doing calculus,
you can pretty much state that
when x=1,
x^3 + 4x - 5 = 1^3 + 4 - 5 = 0
spiral lark
alrighty then
if I can just make an educated guess like that and say that's the answer then I don't have a problem anymore
thanks
.close
outer warren
start by introducing a variable to represent the number you want to find
what is the square of that
can you write an expression that represents the square of x
yes
with that, write an equation that represents
A number is added to its square gives 30.
yes
this is a quadratic equation
do you know how to solve these types of equations?
common methods include factorisation / quadratic formula
how old are you?
unfortunately you are in violation of ToS
as the min age for discord is 13
<@&268886789983436800>
outer warren
underage interactions yadayada,
child stuff etc...
sage wind
some people love math and self study alone
outer warren
as a general rule, 13+ only
outer warren
no exceptions, discord policies, not ours
we can get into hot water
sage wind
if he didnt say his age you wouldnt have known and he wouldve been kept since he didnt do childish actions
so...
anyway i cant change anything its the call of the moderators
outer warren
but he mentioned being in grade 5, and as such i was obligated to seek confirmation
sage wind
yea but its clear that he is self studying
in grade 5 and solving equations
when i was in grade 5 they didnt even introduce powers as i remember
outer warren
that isn't the point though
sage wind
anyway if it was my decision i wouldve kept him because the likes of him who study beyond what he is taught in school deserves to get more and more knowledge and help
but its the decision of mods as i said earlier which is something i cant change XD
sage wind
that isn't the point though
it isnt but this action alone shows maturity which is the reason of this rule in this server
outer warren
its discord policy
server is just abiding by that
like someone underage might have sufficient alcohol tolerance,
but laws say, no booze for you.
sage wind
they are but many times just applying the rules set gives worse results than violating it
sage wind
like someone underage might have sufficient alcohol tolerance,
but laws say, no ...
nah booze should be forbidden for everyone because it just drives people crazy and let them without brain
outer warren
bars don't get to go
i know you're underage but it looks like you can take it with no issue so I will go against to gov and sell to you
outer warren
take it up with discord then
sage wind
because i passed by this stage of not being taken care of to grow up my skills in what i love (math)
because my country doesnt care to develop it people skills
so i dont like it when someone gets into this trouble
outer warren
get them to get the manpower to sufficiently analyse stuff case by case to determine whether certain under 13 yr olds project enough maturity / sense of stranger danger to communicate online with others on their own
sage wind
sorry but i gtg now bye cya all have a very nice day
sage wind
get them to get the manpower to sufficiently analyse stuff case by case to deter...
they cant do that
thats why this server can keep this guy
cyaaa
outer warren
on the off chance they catch that we didn't do anything about it,
then goodbye math server
would you prefer that?
vocal sleetBOT
@queen pivot Has your question been resolved?
blissful sentinel
it isnt but this action alone shows maturity which is the reason of this rule in...
This is not the reason of the rule in the server
Discord operates by US law which forbids them from collecting data from people under the age of 13
.close
boreal bane
How is p(x) divided by (x-2)(x+1) left with remainder 3a+b?
vocal sleetBOT
How is p(x) divided by (x-2)(x+1) left with remainder 3a+b?
boreal bane
from all i get (x-2)(x+1) would cancel out the one in the equation, leaving remainder of R(X) + 3a + b
where r(x) go?
vocal sleetBOT
@boreal bane Has your question been resolved?
vast condor
do you need to find what R(x) is or?
boreal bane
do you need to find what R(x) is or?
nope
r(x) is unknon the whole time
b = -10 and a = 4
<@&286206848099549185>
empty timber
EASY
boreal bane
howw 🙏
fallen sable
Do you know the remainder theorem?
boreal bane
Do you know the remainder theorem?
oh yeah thats fine i got the first one easy
but how woul dyou use remainder theorem on (x-2)(x+1)? i didnt think that was possible
fallen sable
Well they're just asking for the remainder (not to use the theorem)
You want to write it as (x-2)(x+1) * q(x) + r(x), where r(x) is your remainder
You can use the division algorithm to do this
boreal bane
(x-2)(x+1)R(x)+a(x+1)+b / (x-2)(x+1)
to my limited understanding cant we just cross out x-2 x+1 in this case?
fallen sable
They kind of have given the answer to you in some sense
(x-2)(x+1) * q(x) + r(x)
r(x) is of degree 1
You can kind of just look for r(x) in the P(x)
fallen sable
but wouldnt remainder just be a(x+1)+b
yes
so you know a and b, so you can just write down the answer
vocal sleetBOT
vocal sleetBOT
Available help channel!
old niche
Why is my LU decomposition incorrect
vocal sleetBOT
@old niche Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
amber turret
Given the polynomial $f(x)=ax^2+bx+c$, where $a, b, c$ are real numbers, $a\neq b$, such that $\forall x\in \mathbb{R}: f(x) \geq 0$. With this information, find the minimum positive value of $E=\frac{a+b+c}{b-a}$
vocal sleetBOT
Given the polynomial $f(x)=ax^2+bx+c$, where $a, b, c$ are real numbers, $a\neq ...
twin meteorBOT
Rho
amber turret
I was looking for problems to help study my 14 year old nephew and found this one
split heart
so if f(x) is strictly nonnegative for all x
then that means parabola is opening upwards
which means a > 0
amber turret
$a$ and $c$ should be positive and $b^2 \leq 4ac$
positive
wait
less or equal, not greater
that's as far as i've gotten
c, not b
sorry
twin meteorBOT
Rho
split heart
Also you can rearrange it so that it's in the form $f(x) = a (x+ \frac{b}{2a})^2 - \frac{b^2}{4a} + c$
twin meteorBOT
TooManyCooks
amber turret
yup
split heart
Well, I'm not sure how that helps haha
amber turret
a is missing a square in the denominator, but yes
split heart
nah it's just a, not squared
amber turret
oh right
forgot to multiply the a outside the parenthesis
assuming $b \geq 0$, $E$ should be minimum for $c= b^2/4a$, if I'm not wrong?
twin meteorBOT
Rho
amber turret
for negative b, i get it wouldn't be possible to get a positive E
also, for positive b, b should be greater than a to keep E positive
vocal sleetBOT
@amber turret Has your question been resolved?
vocal sleetBOT
@amber turret Has your question been resolved?
vocal sleetBOT
@amber turret Has your question been resolved?
amber turret
.close
next urchin
Yo
next urchin
So i have 3 informations
the y and x axis , e^x and the graph x=a are my informations
with a being above 0
I am supposed to let that rotate now
what am i suppose to do
cause im really stuck
The volume = 3pi and i should figure out a
can anyone help me out with this?
lilac plaza
Rotate how?
visual oracle
Around the y or x axis
next urchin
around the x axis
i am supposed to figure out what a is when the volume is at 3pi
Like usually its like V=pi* (integral of the function)²
But i dont know the interval that the function is in
like the borders idk how to say that in english
visual oracle
It’s x=a
visual oracle
Also isn’t it e^x
next urchin
cause i dont know what to understand under that
visual oracle
What is up with the 1/3a^3
next urchin
3pi = pi * integral of (1/3a^3) with 0 to a
next urchin
What is up with the 1/3a^3
that is a² integraled
visual oracle
yes
next urchin
But my borders are still 0 to a?
visual oracle
Yes
next urchin
Oh wow
that makes it 10 times easier doesnt it?
Wait hold on am i suppose to always convert every information i am given?
twin meteorBOT
ed
visual oracle
yes?
next urchin
What is e^x * e^x actually
visual oracle
exponent laws
visual oracle
yea gj
next urchin
Alr hold on let me solve it all
So its 3pi = pi * ( e^2a) right
i divide by pie
and then i got 3= e^2a
Do i use logarythm then or what
@visual oracle
i got 0.5493
But that cant be right tho
Cause at 1.7 = a i got like 7 for volume while 3 pi = around 10
visual oracle
e^0 is 1
next urchin
Oh fuck
next urchin
Also integral of e^2x has a half out the front
what
visual oracle
I can’t do this in my head hold on
next urchin
All good bro
visual oracle
Didn’t you forget that
visual oracle
Oh wait it’s supposed to be ln7
next urchin
that is like 0.97
visual oracle
Is that right
next urchin
Well 3 pi is around 10
That doesnt seem right
Is there anyway to check?
I mean i can check if i just set in for a
i guess
Yea i get like 3pi = pi * 1.31-0,5
We did something wrong i think
visual oracle
I don’t think we did
next urchin
But i tried to proove it and i didnt really added up
im checking rn
nvmm
we had it right
I forgot its 2a
Yea bro i love you
i think we have done it right
vocal sleetBOT
@next urchin Has your question been resolved?
Available help channel!
Available help channel!
tidal fox
vocal sleetBOT
@tidal fox Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
vast shale
Hello, I’m trying to convert metric units of measurement using dimensional analysis, standard high school chemistry. I think I’m writing the equation correctly, but the more I think about it the more stuck I get. The question is: “Convert 15.0 mm to km using dimensional analysis.”
vocal sleetBOT
Hello, I’m trying to convert metric units of measurement using dimensional analy...
@vast shale Has your question been resolved?
fluid ivy
I messed up somewhere
vocal sleetBOT
I messed up somewhere
river kettle
show
fluid ivy
Mb was tryna take a pic with good res
river kettle
Well first you should use y - y1 = m(x - x1) then rearrange everything for y. You’ll make less mistakes that way
fluid ivy
I messed up somewhere
Question asks for slope intercept form
river kettle
I’m aware and when you rearrange for y you get slope intercept
do you know how to get y1 and x1?
fluid ivy
1,1
river kettle
Do you know how to get your gradient m?
fluid ivy
gradient?
river kettle
yes
fluid ivy
m = derivative of the function
fluid ivy
so m = -8x^-9
fluid ivy
so derivative would be -9x^-10
fluid ivy
ye
river kettle
But you got it wrong
river kettle
9(x)^(9-1)
fluid ivy
i mixed up 2 of the questions together on my notebook and was staring at 1/x^8 for my function
🗿
river kettle
Why do you have 1/x^8
fluid ivy
was a previous question
fluid ivy
y=x^9
y prime = 9x^8
river kettle
Okay
Now you want to find the derivative at 1,1 so plug in x=1 into your derivative
fluid ivy
yer
y prime = 43046721
fucked it up agian
oh
💀 💀 💀
no comments
y=9x-8
have a nice night
.close
green sequoia
hello
vocal sleetBOT
@green sequoia Has your question been resolved?
opal obsidian
How do I prove if |G|=4, then G is abelian?
vocal sleetBOT
How do I prove if |G|=4, then G is abelian?
opal obsidian
A way in which we can enumerate and reason out will be helpful
I’ve tried the proof when |G|=3
Here is what I did for 3 elements G={e,a,b},
ab=a, or ab=b cannot happen as e is the unique identity, so ab=e
so identity and inverse commute, so |G|= 3 is ableian
How do I try a same reasoning for |G|=4?
split wind
I am so unfamiliar with this topic that i don't think i can help however i found something online hope this helps!
https://en.m.wikipedia.org/wiki/Klein_four-group
opal obsidian
The proof I need is to show every group with 4 elements is always abelian
opal obsidian
I am so unfamiliar with this topic that i don't think i can help however i found...
So is every group containing 4 elements cyclic?
split wind
"The Klein four-group, with four elements, is the smallest group that is not a cyclic group. There is only one other group of order four, up to isomorphism, the cyclic group of order 4. Both are abelian groups."
iirc there are only 2 kinds of Abelian groups containing 4 elements
split wind
yea, what's giving you trouble with this?
split wind
of course, I'll try my best to explain
but, again, I'm not that familiar with this topic, so i might be tripping lol
opal obsidian
Not an issue
Is it like, we know e,a,b is in G
now we look what happens when we operate it with each other
split wind
yes, and exhaust out all the possibilities
and found that all other cases are not possible except that ab=ba
opal obsidian
ab=e means they are only 3 elements
so ab has to be the 4th element?
Oh, we tried the possibilities of ab
opal obsidian
I suppose we look what the possibilities of ab is
ab=a, impossible, ab=b, impossible, ab=e, means they are only 3 elements
but we have a fourth element
so that 4th element has to be ab
split wind
since you've proved case |G|=3
opal obsidian
yes
ab=e means b is just a^-1, and we still have 3 elements
but a plausible argument is that since ab has to be some element in G as groups are always closed
so given 4 elements, ab has to be the fourth element
i guess so
split wind
looks clear now
split wind
glad you've made it!
vocal sleetBOT
vocal sleetBOT
Available help channel!
wide elbow
subject: calc 2, volumes by shells
vocal sleetBOT
subject: calc 2, volumes by shells
patent nymph
did i draw the shell correctly?
Looks like it
It looks like a rectangle but it could be a cylinder
wide elbow
patent nymph
Yes
wide elbow
Yes
so i figured out that sqrt 2 isnt my f(x), so what is my f(x) if 2 - y^2 is my g(x)?
patent nymph
so i figured out that sqrt 2 isnt my f(x), so what is my f(x) if 2 - y^2 is my g...
What do you mean?
wide elbow
so my h = sqrt 2 - 2 - y^2 is wrong i believe
wide elbow
What do you mean?
i think thats what caused my definite integral being incorrect
so for height its f(x)-g(x)
so what would be my f(x) and g(x) here?
patent nymph
Consider the meaning of f(x) and g(x)
wide elbow
Consider the meaning of f(x) and g(x)
f(y),g(y) i mean
i know that x=2-y^2 is one of them
but what is my other function in this?
vocal sleetBOT
@wide elbow Has your question been resolved?
wide elbow
.close
late jewel
need help with 11
vocal sleetBOT
need help with 11
paper depot
do you know the sin(x)/x limit
late jewel
yes as x -> 0
paper depot
right
multiply top and bottom by 4 here and you will be able to use this limit
in a slightly different form but still
patent nymph
also note that cos x goes to 1 as x goes to 0
late jewel
ok
paper depot
im not following
4(x cos(2x)) is not equal to 4x * 4cos(2x) btw.
$\frac{4x\cos(2x)}{4 \sin(4x)} = \frac{4x}{\sin(4x)}\cdot\frac{\cos(2x)}{4}$
twin meteorBOT
Ann
vocal sleetBOT
@late jewel Has your question been resolved?
scenic ruin
I’m confused about the last two paragraphs of the solution. If you can show that f(x)>0 for all x>r (second paragraph), then why do you still need to prove by contradiction (third paragraph)
vocal sleetBOT
I’m confused about the last two paragraphs of the solution. If you can show that...
@scenic ruin Has your question been resolved?
Available help channel!
slender plover
hey
vast shale
hi you have a question?
twin meteorBOT
vocal sleetBOT
vocal sleetBOT
Available help channel!
vocal sleetBOT
lilac plaza
What does standard designation mean?
lilac plaza
When the vectors are orthogonal, does it mean the dot product should equal to 0?
obtuse sierra
for what?
lilac plaza
So like, I'm supposed to do √((-5)^2 + (-2)^2 + (-3)^2) * √((4)^2 + (12)^2 + (-6)^2) * cos(theta)?
And I equal it to AxBx + AyBy + AzBz
And find cos(theta)?
@obtuse sierra
obtuse sierra
you dont know how to do dot product?
obtuse sierra
you see that |A||B|cos(theta)
lilac plaza
Yea
lilac plaza
Yes
obtuse sierra
so if there's a vector lying in x direction (i) and another lying in y direction (j), what is the angle between them?
lilac plaza
so if there's a vector lying in x direction (i) and another lying in y direction...
90
Which is orthogonal
obtuse sierra
ignore orthogonal
lilac plaza
Okay
obtuse sierra
so cos(90)?
lilac plaza
Yes
obtuse sierra
so their dot product is?
lilac plaza
Oh
Then it's easy
$\left(-5\right)\left(4\right)+\left(-2\right)\left(12\right)+\left(-3\right)\left(-6\right)$
twin meteorBOT
LE SSERAFIM
obtuse sierra
yup
vocal sleetBOT
vocal sleetBOT
Available help channel!
brazen perch
Why do they take the sqrt of (x^2 + 4) here?
vocal sleetBOT
Why do they take the sqrt of (x^2 + 4) here?
hard atlas
$\frac12 \log(c) = \log(c^{1/2}) = \log(\sqrt c)$
twin meteorBOT
Denascite
vocal sleetBOT
@brazen perch Has your question been resolved?
stiff hull
Uranium weighs 238 g per mol (1 mol is 6.02 • 10^23 particles)
a. How much does 3.01 • 10^23 uranium atoms weigh?
b. how much does 6.02 • 10^22 uranium atoms weigh?
c. How much does 6.02 • 10^25 uranium atoms weigh?
d. How much do 4.8 billion uranium atoms weigh?
stiff hull
can someone show me how to do task A
i dont understand anything currently of this task
pale perch
you have the mass/mol, and you know how many atoms compose one mol. So convert the number of atoms into number of mol and then the mass will be 238*(no. of mol)
lucid vapor
238 g uranium = 6.02 • 10^23 uranium atoms
so
3.01 • 10^23 uranium atoms weigh 119 g
6.02 • 10^23 / 2 = 3.01 • 10^23
stiff hull
6.02 • 10^23 / 2 = 3.01 • 10^23
this formula wont work in task b though will it?
or am i misunderstanding?
lucid vapor
It will work
stiff hull
how
lucid vapor
avogadro law
stiff hull
that is something i have never heard about
stiff hull
yes
stiff hull
hm
simple urchin
how the fuck
vocal sleetBOT
how the fuck
simple urchin
isnt it 220
because
cyclic quadrilateral = 360
360 = 140 + x
x = 220
what is it then
x is OAC
im trying to get x
nope
austere star
its not 220
austere star
what
simple urchin
how do i do it
vocal sleetBOT
mild flower
fucking idiot
that's pretty uncalled for
austere star
i agree
river kettle
What the hell is even going on in this channel
wise drift
chaos
austere star
try 20
outer warren
cyclic quadrilateral = 360
this isn't a cylicl quad, note that one of the vertices isn't at the circumference
outer warren
<@&268886789983436800> convo getting toxic
wise drift
and this looks like a parallelogram so, adjacent angles also add to 180°
simple urchin
this isn't a cylicl quad, note that one of the vertices isn't at the circumferen...
thats true
...?
outer warren
consider inscribed angle theorems
mild flower
.reopen
simple urchin
yeha
vocal sleetBOT
✅
simple urchin
i have 3 theorems in mind
if opposite angles in a
quadrilateral
are supplementary
then hte quadrilateral is cyclic
@zealous estuary @pallid turtle you 2 fat fucks couldnt solve it
so please
stfu
austere star
woah waoh woah
outer warren
this isn't a cyclic quad, note that one of the vertices isn't at the circumference
so you shouldn't be trying to apply that directly
austere star
<@&268886789983436800> uts getting toxic
simple urchin
isnt this you
simple urchin
> this isn't a cyclic quad, note that one of the vertices isn't at the circumfer...
oh
outer warren
don't feed the trolls
outer warren
just block them so their messages don't show up
wise drift
the angles subtented by a chord at the centre is half of the angle subtented by the same cord at the circumference of a circle
here the cord is AC
outer warren
you want to more general inscrbied angle theorems, instead of the special case
austere star
55
glad python
lmao
mild flower
nothing that you've said in here makes me want to give you my snapchat
simple urchin
nothing that you've said in here makes me want to give you my snapchat
fr
glad python
L rizz
outer warren
@simple urchinwould you prefer to claim a new uninfected channel?
elfin moon
Hello @sudden compass
vocal sleetBOT
Hello <@717652530061901855>
vocal sleetBOT
@elfin moon Has your question been resolved?
split crater
vocal sleetBOT
paper depot
,rccw
twin meteorBOT
paper depot
i mean you already did didnt you
split crater
i have no idea tbh
paper depot
youve found that x = sqrt(2)/2
split crater
true
paper depot
like you understand the lengths of the horizontal and vertical sides of the pink triangle ARE the coords of A yes?
split crater
i did not know that until now, so the coordinates would be (sqrt2/2, 1)?
vocal sleetBOT
vocal sleetBOT
Available help channel!
proven shard
hii i need help for this problem
vocal sleetBOT
hii i need help for this problem
proven shard
i dont really know how to start factoring in this case
vast shale
how would you make it so the denominator ≠ 0?
proven shard
how would you make it so the denominator ≠ 0?
factor it right
vast shale
have you heard of multiplying by a conjugate
proven shard
i have but i genuinely forgot and never got the hang of it
obtuse sierra
make common denominator in the numerator
proven shard
i think i remember i have to like flip signs and stuff like that
but im not really sure
twin meteorBOT
Dyssrupt
proven shard
This is what I have
im between both of what you guys suggested and the way i understood it
thats why i put that or
vocal sleetBOT
@proven shard Has your question been resolved?
proven shard
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
long flame
i don't really understand the point about the interval
vocal sleetBOT
i don't really understand the point about the interval
long flame
i inverted the function by replacing f with y, then replacing y with x
then i isolated y
this gave me the answer above the accepted answer
somber portal
For the function to have an inverse, it has to be injective.
A parabola is never injective, unless you restrict it to only one side of the vertex
long flame
okay, and for these exercises so far, i guess they have been restricted towards positive infinity, giving what i call the "standard" inverse as in not negative
somber portal
Also, the inverse of the function is the reflection along the y=x line
long flame
i guess maybe this would've been solved more easily through graphing it
i see now why they give the domain
somber portal
probably. But you're asked about the analytical answer
long flame
i had ignored the domain for all previous exercises