#help-17

1 messages · Page 52 of 1

river sierra
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digital veldt
#

if a tower was leaning at an angle and i want to consider the triangle formed by the point at the top of the tower, the base of the tower, and a point due west of the tower which has an angle of elevation to the top of the tower at 45. is this triangle a right angled triangle? i could draw it up if you are unable to visualise

hushed tree
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It's not right angled

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Since the tower is leaning

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For it to be right the tower must be straight

digital veldt
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Even if the top view looks like this

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I'm not sure how to explain it but it would be a face of a triangular pyramid I know that OC isn't vertically upward but does that mean COB isn't a right angle where B is On level ground

hushed tree
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Yes

digital veldt
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There's another point due south of the base of the building ( on level ground)

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Alright so it's non right angle?

hushed tree
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Yes

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Wdym by the pyramid

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You should show the entire problem

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@digital veldt

digital veldt
hushed tree
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Is OC perpendicular to BO

digital veldt
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yep on the groun bc B is due west to O and A is due south

hushed tree
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But you just said CO isnt vertical

digital veldt
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yes OC is a leaning tower

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but im assuming it is due north in the top view

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to O

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as B is due west and A is due south

hushed tree
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Ok and

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How does this result in the fact that angle COB is right

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Think about it

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Since CO isnt vertical

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Angle COB will always either be <90 or >90

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It will never be 90

vocal sleetBOT
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@digital veldt Has your question been resolved?

digital veldt
digital veldt
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hushed tree
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N

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No

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Dont close

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Your question isnt answered

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@digital veldt

hushed tree
vocal sleetBOT
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glacial meadow
#

You and a friend take different flights in opposite direction but leave from the same airport.
Your flight starts out 210 miles due south and then turns 70 degrees west and goes another
80 miles. Your friend’s flight starts out traveling 80 miles due north and then turns 50
degrees to the east before traveling 210 mile. Explain how the Hinge Theorem would help
you find out whether you or your friend’s flight is farthest from the airport. Use the compass
for reference and provide a sketch.

glacial meadow
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sorry for the block of text

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ive done the sketch, and i think they are the same distance away??

tall atlas
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Hmm

glacial meadow
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wait no

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i forgot about degrees

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yeah idk

proven garden
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so the Hinge theorem states that if two sides of two triangles are congruent, the third side of the triangle with larger included angle is longer than the triangle with smaller included angle

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so compare the angle to find out who is farther

glacial meadow
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so 70 degrees and 50 degrees

proven garden
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yes

glacial meadow
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wdym by compare them

proven garden
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the one with larger angle is farther

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using the Hinge theorem

glacial meadow
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ohhh

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thank you!!

#

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vast shale
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why is the answer not 3x-2

vocal sleetBOT
proven garden
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which one?

upper iron
vast shale
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i plotted the points down in desmos

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then i counted how far apart it is on the y axis

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the points i mean

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and then how far apart they are on the x axis

upper iron
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It's correct, but in exams you will not have desmos 😛

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You should learn to do it on paper!

upper iron
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You are right

vast shale
upper iron
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Awesome!

vast shale
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i dont understand though

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why is it rejecting my answer

upper iron
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How the hell is 3x-2 wrong, it's correct

vast shale
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no clue

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im set up for failure

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they did this to me on purpose smh

upper iron
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it's their mistake, don't worry

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prolly won't get counted

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it's on them

vast shale
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i want to cry monkey

upper iron
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Try +3x-2

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or -2+3x

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Anythin

vocal sleetBOT
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@vast shale Has your question been resolved?

vocal sleetBOT
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vast shale
#

given that sin(40) = a, express cos(50), tan(-50) and sin(220) in terms of a

vast shale
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help

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!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
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@vast shale Has your question been resolved?

vast shale
vast shale
#

sin x = cos (pi/2 - x)?

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wait can it be cos(x + pi/6)?

vocal sleetBOT
#

@vast shale Has your question been resolved?

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native dagger
#

Question in English : Which function has the following variation table?

paper depot
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
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@native dagger Has your question been resolved?

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silk canopy
#

wait
1/sin^2* cos ^2 a
how do i make this into cos^2a - cos^4a

civic drift
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Write $\sin^2(a) = 1 - cos^2(a)$

twin meteorBOT
#

coldtee

silk canopy
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i did

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that would just make it 1/1-cos^2a * cos2 a

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and if i take common it would make

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1/(1-1)cos^2a

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nothing but but 1?

civic drift
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Uh

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It's $(1-cos^2(a))cos^2(a)$

twin meteorBOT
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coldtee

silk canopy
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yes

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and u can take cos^2 a common

civic drift
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No

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There is a bracket

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$a(b + c) = ab + ac$

twin meteorBOT
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coldtee

civic drift
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Distributive property

silk canopy
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oh yeah

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so it will beocme

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cos^2a -cos^2 a*cos^2 a

civic drift
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Yeah

silk canopy
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cos^2a -cos^4a?

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oh

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thats the proof

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im stpud

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thank you

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modest grove
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im i ryt

vocal sleetBOT
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ivory violet
vocal sleetBOT
ivory violet
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wait so is this true

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that if gradiant is -21

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the gradient of the normal is 1/m

civic otter
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-1/m

ivory violet
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its for this if need context

ivory violet
vast shale
#

[
m_{\text{tan.}} = -\f1{m_{\text{nor.}}}
]

twin meteorBOT
ivory violet
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so its just a thing to remember in math

vast shale
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you can prove it using some geometry

ivory violet
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true

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vast shale
#

\textbf{Question:} Show that if $G$ is a self-complementary simple graph with $v$ vertices, then $v\equiv 0$ or $1;(\bmod 4)$

\vs{3 mm}
\textbf{My solution:} If $G$ is self complementary, then $G$ and $\overline G$ are isomorphic, meaning they both have the same amount of edges

\vs{2 mm}
When we have $v$ vertices, there can be at most $\f{v(v-1)}2$ edges

\vs{2 mm}
Since that can be at most $\f{v(v-1)}2$ edges and $G$ and $\overline G$ have the same amount of edges, the number of edges in $G$ is half of the maximum number of edges :[
G \textss{has} \f{v(v-1)}4 \textsx{edges}
]
And since since the number of edges has to be an integer: [
v(v-1) \equiv 0 ; (\bmod 4)
]
We can note that $v$ is odd and $v-1$ is even, or vice versa. The product of the two integers will surely be a multiple of 4 in this case if either terms is a multiple of 4 [
v \equiv 0 ; (\bmod 4) \textss{or} v-1 \equiv 0 ; (\bmod 4)
]Adding one to both equations:
[
v \equiv 0 ; (\bmod 4) \textss{or} v\equiv 1 ; (\bmod 4)
]

twin meteorBOT
vast shale
#

is my reasoning right here?

hard atlas
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you are talking about "at most edges". why does this "at most" have to be attained

vast shale
twin meteorBOT
hard atlas
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well again, at most

vast shale
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yes, at most

hard atlas
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why is this "at most" number relevant

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you arent using the definition of complementary graph anywhere

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that should be a sign that you cant be completely right

vast shale
vocal sleetBOT
#

@vast shale Has your question been resolved?

glossy maple
#

try to think how many edges will the complementary graph have

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glossy maple
#

oh rip

vocal sleetBOT
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silk canopy
vocal sleetBOT
silk canopy
#

i didnt understand this step

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can someone help in detail using the alpha bot

worthy citrus
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This is finding the common denominator of two fractions

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That common denominator being sin(θ)cos(θ)(sin(θ)-cos(θ))

silk canopy
paper depot
#

no, it does not.

silk canopy
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can u explain what is happening here using the bot?

paper depot
#

abbreviating $\cos(\theta)$ and $\sin(\theta)$ with $c$ and $s$ respectively, you have:

$\frac{s^2}{c(s-c)} - \frac{c^2}{s(s-c)} = \frac{{\color{red}s} \cdot s^2}{{\color{red}s} \cdot c(s-c)} - \frac{{\color{red}c} \cdot c^2}{{\color{red}c} \cdot s(s-c)} \ = \frac{s^3}{sc(s-c)} - \frac{c^3}{sc(s-c)}$

twin meteorBOT
silk canopy
#

doesnt it become sin^3theta (sintheta - cos theta) - cos^3 theta (sin theta - cos theta)/ cos (sintheta - cos theta) (sin theta (sin theta -cos theta)

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i dindt get it

silk canopy
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was take lcm

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well cross multip;y

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and do it

worthy citrus
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The product of the denominators isn't the lcm in this case, which is why what they did is better

silk canopy
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caan i do it in this way too?

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one min

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let me type it out

worthy citrus
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Cross multiplying is fine just less efficient

silk canopy
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sin^3theta (sintheta - cos theta) - cos^3 theta (sin theta - cos theta)/ cos (sintheta - cos theta) (sin theta (sin theta -cos theta)

sin^3 theta - cos^3 theta (sin thetea - cos theta)/
(sin theta * cos theta ) (sin theta - cos theta)

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i took sintheta - cos theta common in both

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does this work? @worthy citrus

worthy citrus
# silk canopy

You'll know if it works as you'll end up with the same as this

silk canopy
#

it ends up the same, but then i just want to know if im doingsome wrong shit to make it correct? @worthy citrus

worthy citrus
#

Cross multiplying will always work fine, can just be more difficult/inefficient

silk canopy
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no they

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dont end up the same

silk canopy
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cross mulitply

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using the bot?

worthy citrus
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You are capable of doing it yourself

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,w a/b + c/d

silk canopy
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what is this?

#

.w sin^2theta

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,w sin^2 theta

silk canopy
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,w sin^2 theta

silk canopy
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,w sin^2theta

silk canopy
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,w (sin^2theta - cos^2theta / costheta (sin theta - cos theta) ) - cos^2theta/sin theta /sin theta (sin theta - cos theta)

twin meteorBOT
silk canopy
#

...

vocal sleetBOT
#

@silk canopy Has your question been resolved?

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sudden compass
#

(XY problem alert ⚠️)
Find c such that the probability that 1 >= c is 1/2

sudden compass
#

Waif

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That's stupis

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.close

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paper depot
#

.coose*

vocal sleetBOT
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vague root
#

how to find circumfrance and area?

vocal sleetBOT
vague root
#

of the circle segment

glad python
#

sector minus triangle

vague root
#

sector?

vague root
glad python
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That’s the area of the circular segment

vague root
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but is there a reason behind it?

glad python
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Sector ACB-triangle ACB

glad python
vague root
glad python
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Uh

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Use your eyes?

vague root
glad python
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I don’t know how to explain it

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Look at the picture

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If you take the triangle out of the circular sector

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You get the segment

vague root
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i think i skipped a chapter, what rule is that?

glad python
#

I don’t think you are understanding what I’m saying

vague root
glad python
#

Do you see sector ACB?

vague root
#

the triangle?

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nvm

vague root
glad python
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No sector is like a pizza slice

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So A with arc BC

vague root
#

what is a arc?

vague root
glad python
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arc is curved line

vague root
glad python
#

Segment is straight line

vague root
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ok the arc

glad python
#

Ok do you see the sector?

vague root
#

what is definition of sector?

glad python
#

I’ll send a picture

vague root
#

thank you

glad python
vague root
#

so a pizza slize shape?

glad python
#

Yes

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Do you know how to find the area of this?

vague root
#

x/360*area?

glad python
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Yes

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So what is area of sector ACB

vague root
#

never thought about this

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15.7+x

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let me calculate it

vague root
glad python
#

No a sector is part of the circle

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What’s the area of the pizza slic

vague root
#

but what is the area

glad python
#

No

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1/6 * area of the big circle

vague root
glad python
vague root
glad python
#

No you are looking at the wrong sector

vague root
#

?

glad python
#

Look at the sector on the right

vague root
glad python
vague root
glad python
#

No

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Look at this picture

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Can you understand this?

vague root
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yes

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ahh

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i am so dumb

glad python
#

Sorry I’m bad at communicating

vague root
#

i never thought about this in that way

vague root
glad python
#

If you have weird areas find a way to express them as two different areas

vague root
#

thank you, your teaching will be ingrained into my brain

#

.close

vocal sleetBOT
#
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glad python
vocal sleetBOT
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ebon ocean
#

What do I do now?

vocal sleetBOT
ionic hedge
#

Use this formula instead of 1-cos^2x

vocal sleetBOT
#

@ebon ocean Has your question been resolved?

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full flume
#

bit of a silly question but how would I write -6^7 on a ti-84

full flume
#

whenever I start with a - it defualts to my last answer-6^7

hidden kelp
#

you should have a button other than the subtract button to add negative signs

full flume
#

ohhhhhh

#

.close

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viral galleon
#

Is this right?

vocal sleetBOT
viral galleon
#

I need velocity and acceleration and vectors

steady helm
iron flame
#

^

viral galleon
#

but is the process right

steady helm
#

Yes absolutely

viral galleon
#

do we right it as like ijk

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Or is this form just fine

steady helm
viral galleon
#

this form for example

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cuz sometimes u write vectors

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as ijk

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oh sorry i wrote right and not write

steady helm
#

I would say that both forms are fine

iron flame
#

v=<... , ...> is expressing it explicitly as a vector quantity

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both are correct

steady helm
viral galleon
#

like when u do cross product and stuff?

iron flame
#

yeah there is a way/trick of remembering how to get the cross product using ijk unit vectors

viral galleon
#

yeah i know because its really weird

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our professor

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taught us all that before

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and for some reaosn

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the last module is this stuff

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which is really weird

#

this module should have been before that imo

#

but whatever

steady helm
vocal sleetBOT
#

@viral galleon Has your question been resolved?

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short notch
vocal sleetBOT
short notch
#

can someone pls help me with this

#

I dunno what to do after this

#

" what percent is made on the cost?" this is confusing me

vocal sleetBOT
#

@short notch Has your question been resolved?

clear stirrup
#

You want to find the profit percentage on cost

short notch
clear stirrup
#

Why do you think CP is 60?

short notch
#

if selling price is 50, and profit is 10, then cost price 60..?

clear stirrup
#

...

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Oh you added those

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Ok so when we sell something

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and have a selling price

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Ideally we want the selling price to cover at least the whole cost of it

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and then a bit of profit

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Right?

short notch
#

is the selling price what the retailer bought it for?

clear stirrup
#

The selling price is the price they are selling the product for

short notch
#

ah okay

clear stirrup
#

that's why it's a selling price

short notch
# short notch

so this means whatever the selling price is the store is making 20% more..?

clear stirrup
#

No

#

The selling price is like the revenue they are getting

short notch
#

okayy so 20% of the s.p was profit...?

clear stirrup
#

And profit is how much they are earning in profits based on a percentage of the revenue

#

Yes

#

So 20% of the selling price is profit right?

short notch
#

yepp

clear stirrup
#

That means the rest of it goes into the cost

#

So let's use $100 as an example

#

If they have a selling price of $100 (they earned revenue of $100)

#

They only made a profit of $20 (20% profit)

#

so cost = selling price - profit or cost = selling price - 0.2 * selling price

#

in other words, the remaining 80% is the cost

#

which is usually referred to as cost of goods sold

#

The question is asking what percentage of profit is made on the cost

short notch
#

ahhhh soo 20/80 * 100?

clear stirrup
#

so once you figure out cost, you want to find (profit / cost)

#

for just percent

clear stirrup
#

20/80 by itself is the percentage value

short notch
#

0.25?

clear stirrup
#

Yes

#

and you don't really need an example number to figure it out

#

You can think of selling price as the max number

#

it's not that simple but for the sake of this we can just say selling price is the max

#

or 100%

#

if the percentage of profit (given in the question) is 20%

#

then we can just divide it by the cost percentage

#

100%-20%

short notch
clear stirrup
#

so 20%/80%

short notch
#

like is it different if i write 20%/80% vs 20/80?

clear stirrup
#

Yes

#

a percentage is expressed in decimals

#

100% = 1

#

so if you did 20% / 80% it would be 0.20 / 0.80

#

but if you use 20 / 80 you have to put that into the perspective of actual values (not percentage)

#

like your example of SP = $50 and profit = $10

#

cost = 50-10

#

So we can say 10 / 40

#

does that make sense

short notch
#

yess

#

thank uu

clear stirrup
#

np 👍

clear stirrup
short notch
#

yepp

#

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austere hearth
#

anyone mind helping me

vocal sleetBOT
austere hearth
lyric fossil
#

are you able to find the area of the circle

austere hearth
#

yes

lyric fossil
#

how about the square surrounding it

austere hearth
#

dont know how for that

lyric fossil
#

what is the area of a square

austere hearth
#

since all i got is the area of the circle

#

thats what i need to find out

lyric fossil
#

im asking you the area of a square

#

what is the formula

#

(based on side length)

austere hearth
#

how do i find out teh side length?

lyric fossil
#

look at what you were given in the picture

austere hearth
#

oh im dumb

#

7.7 right

lyric fossil
#

show your work

austere hearth
#

broo

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midnight locust
#

If I have a function for all line segments in R^2 space, can I apply it to a closed curve? And how? What related mathematics knowledge I would need to use? Differential Geometry? Tysm

lyric fossil
#

what do you mean by "a function for all line segments in R^2"

#

and what do you mean by "apply it to a closed curve"

#

do you have a specific question in mind

midnight locust
#

A function that by giving coordinates of two points of a line segment, then it will return a value

And can a closed curve be divided into a collection of infinitesimally small line segments, so this function can be applied to this curve?

#

Thx you!

lyric fossil
#

what kind of functions are we working with

#

also you can always do the second thing you mentioned, but that limit might not converge

midnight locust
#

May be using arcoth and arctan

midnight locust
lyric fossil
#

can you give me an example of a function on a line segment

midnight locust
midnight locust
lyric fossil
#

well this isn't defined for all line segments
if you did have a function that was defined for all line segments, or say some convex set containing the curve, then you could definitely do what you said in your second question

#

but it may not converge

#

and it may go as far as to depend on how you split up the line segments that approximate the curve

#

you may be able to characterize this as "functional analysis"

midnight locust
#

Ok thx you so much, I gonna explore more about this topic

#

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empty minnow
#

**If it take 1hours for two people to do some work in 240/11 days then how many hours they would have to work to get the work done in 5 days only? **

vocal sleetBOT
#

@empty minnow Has your question been resolved?

trim walrus
#

(2 ppl)×(1 hr)×(240/11 days) = (480/11 work)

(2 ppl) × (x hr) × (5 days) = (480/11 work)

Solve for x hr

#

I belive

#

(The units maybe vaguely described)

#

Sry for that

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twin meteor
#

im taking the derivative of this

vocal sleetBOT
twin meteor
#

do

#

i combine the 2.0+3.0t before taking derivative?

#

and if not that means the 2.0 is gone right?

mild flower
#

you can't combine the 2.0 and 3.0t

#

and the derivative of a constant is 0

twin meteor
#

wait why not

vast shale
#

They are not like-terms

twin meteor
#

becayse one has t

#

and one doesnt

#

i see

vast shale
#

Like for $x^2 + x + 6$ you can't just transform that to $x^2 + 7t$ or something using your logic

twin meteor
#

now if i had 2.0t and 3.0t i could combine

vast shale
twin meteor
#

thank you so much

#

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vocal sleetBOT
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craggy hamlet
vocal sleetBOT
craggy hamlet
#

do they mean vertical or horizontal

mild flower
#

there's no concept of vertical or horizontal in the question

vocal sleetBOT
#

@craggy hamlet Has your question been resolved?

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vocal sleetBOT
twin meteor
#

would i choose (0,0) as my origin

#

or (0,100)?

#

because later in the question i used -100

dapper meteor
#

0,0 because 100 is the vertical distance of the rock from the ground

dapper meteor
#

Distances can't be negative

#

And here we are talking about distance

twin meteor
#

so my delta y cant be -100m?

#

change in y = -100m

dapper meteor
#

Delta y can because it's not really a distance

#

Like it's a change in the altitude

twin meteor
#

i see

dapper meteor
#

But you can't say "my rock is at -100m of altitude"

twin meteor
#

that makes sense thank you

#

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cobalt imp
#

Can someone check if this is correct?

vocal sleetBOT
spiral inlet
#

yep, x4 is free

vocal sleetBOT
#

@cobalt imp Has your question been resolved?

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bleak prawn
vocal sleetBOT
bleak prawn
#

I got pretty far but im stuck

full arch
#

Could you post your work?

bleak prawn
#

Yes sry im typing it 1 moment

#

A/(x+2) + B/(x-2)
A(x-2) + B(x+2)
Ax - 2A + Bx - 2B
(A+B)(x-2) = 7
Normally at this point in the question I get the form (A+B)(x) + n, but this time the 2 factors out, so I dont really know what to do next

#

Why are you devastation ing me? sully

full arch
#

Second line

#

What is that equal to

half imp
#

(x+4)(x-4) isn't (x^2-4)

bleak prawn
#

Oh

#

Ah ok I see, but my problem is still the same

full arch
#

What is the second line of your working now equal to

#

The entire thing

bleak prawn
#

(A+B)(x-2)

full arch
#

A(x-2) +B(x+2) this bit

#

What is the Equality not just the RHS

bleak prawn
#

7

full arch
#

Could you maybe try values of x to eliminate unknowns ?

bleak prawn
#

What do you mean sry?

#

Like plug in random values?

full arch
#

Random with a purpose

#

If you eliminate A but B is still in the equality you can solve for it

#

Do you not see values of x that allow us to do that?

half imp
#

One note here is that the left side has to equal the right side for every value of x

peak matrix
#

A(x-2) +B(x+2) = 7 for all values of x, so you can choose some "random" value of x, and the equation will still remain true. So you probably want to choose some value of x, that would eliminate either A or B from the equation

bleak prawn
#

oh so +2 or -2 right?

#

Combo haha

#

So 4b = 7

#

And solve for A and B

#

Thats it right?

#

Okok I think I can manage that

#

Thank you everyone!

#

❤️

#

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bleak prawn
#

.reopen

vocal sleetBOT
#

bleak prawn
#

Sry I got stuck on something again

#

A(x-2) +B(x+2) = 7
-4A = 7 so A= -7/4
4B = 7 so B = 7/4
(7/4)(x-2) + (-7/4)(x+2) = 7
0 = 7????

wraith venture
#

How did you get -4A = 4B = 7 ?

#

(A+B)x + 2(B-A) = 7

#

Is this an equation in x or is it supposed to hold for all x ?

bleak prawn
#

Im not really sure what either of those mean, A and B dont have a definite value yet, I just made them up

#

A/(x+2) + B/(x-2)
A(x-2) + B(x+2)
Ax - 2A + Bx - 2B
(A+B)(x-2) = 7

wraith venture
#

Oh you're doing PFD

bleak prawn
#

yeye

wraith venture
#

So it must hold for all x

wraith venture
bleak prawn
#

A+B=0?

wraith venture
#

A constant can't depend on x, can it?

bleak prawn
#

Ah oke

wraith venture
#

Hence 2B = 7/2 so B = 7/4 and A = -B = -7/4

bleak prawn
#

yeye

#

So did you also get 0 = 7? When you tried to work it out

#

Or did I make a mistake

wraith venture
#

In general if you find a contradiction, you made a mistake. Unless you made some assumptions, then they shall also be questioned

#

But here the assumptions are correct because it's known from the theory of PFD

wraith venture
#

Can't proofread work I can't begin to try to understand

bleak prawn
#

7/(x^2 - 4)
It needs to be split into 2 fractions A and B to make integration possible
A/(x+2) + B/(x-2)
To work out A and B I set them equal to the numerator
A(x-2) + B(x+2) = 7
Ax - 2A + Bx + 2B = 7
(A+B)(x-2) = 7

bleak prawn
#

like substitution -2 and 2 for x into A(x-2) + B(x+2) = 7

wraith venture
bleak prawn
#

Ax - 2A + Bx + 2B = 7

#

(A+B)(x) - 2A + 2B = 7, right?

wraith venture
#

Then you get where I was

bleak prawn
#

Then -2A + 2B = 7

#

And A + B = 0

#

So B = 7/4 and A = -7/4

bleak prawn
#

Or its not allowed because of the 7 = 0?

wraith venture
#

There's no 7=0

bleak prawn
#

Oh

wraith venture
#

That's the bullshit you made by mistake

#

Forget it

#

If it comes from an error, it doesn't hold. Then it can't object to anything

bleak prawn
#

ok sorry

wraith venture
bleak prawn
#

I thought I had it but its wrong

#

(-7/4)/(x+2) = -ln(x+2), no?
And (7/4)/(x-2) = ln(x-2)?

wraith venture
#

Clearly off by a constant at least

wraith venture
#

Can't approve of that

#

-7/4 /(x+2) -> -7/4 ln(x+2)

#

Simple linearity

bleak prawn
#

Ah yeye

#

Ok I got it

#

Thanks!

#

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quartz mauve
#

what do the different shadings mean? i think one's greater than and one's greater than/equal to but i don't know which is which

shut briar
#

i don't think they're different

#

greater than is represented with dotted line

#

while greater than equal to is represented by a solid line

#

the way the area is shaded doesn't matter

quartz mauve
#

i see

#

makes sense i dont think theyd throw in a new thing on a test when we didnt learn it

#

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vast shale
#

im just unsure of how to solve this one. i know its an easy proportion but ive never had to solve one with a variable

18 is to 12x as 5 is to __

hushed tree
#

solve this

#

18/12x = 5/y

#

find y in terms of x

vast shale
#

3.3x?

hushed tree
#

yes

#

3.(3)

#

,calc 10/3

twin meteorBOT
#

Result:

3.3333333333333
vast shale
#

OK thank you

#

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#
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hushed tree
#

np

vocal sleetBOT
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bleak prawn
vocal sleetBOT
bleak prawn
#

First thing for any of these questions is to get the roots right? How do I get the roots of sin(x/2)?

viral copper
#

Equate it to 0

bleak prawn
#

What do I do next?

#

Ah wait I think I see it

#

Yeye I can do this

#

Thank you!

#

❤️

#

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verbal merlin
vocal sleetBOT
vast shale
#

Hello again

verbal merlin
#

oh he lexqal

#

helloo

vast shale
#

Start with the complementary solution

#

What have you tried for that

verbal merlin
#

doing it now one second

#

i might have troubles with yp more lemme write down yc and add here

#

i think yc will have the complex root thing right?

#

@vast shale is this correct?

#

The particular integral yp = Asint + Bcost

vast shale
#

Sorry lemme see

verbal merlin
#

hehe sure np

vast shale
#

Yeah that should be fine

verbal merlin
vast shale
#

Oh wait

#

You have e^x written, it's meant to be e^t

verbal merlin
#

Oh my bad it should be xc right

#

cus its x not y here

#

OHH

#

e ^ t

#

my bad

vast shale
#

Yes

verbal merlin
#

im blind haha

verbal merlin
#

i think a & b would be 0 eventually but is yp correct??

#

@vast shale is yp correct

#

also the username with flowers is nice hehe!

vast shale
vast shale
#

Differentiate twice and plug into the equation and solve for the coefficients

#

See what you get out of that I guess

verbal merlin
#

okie

#

is my current progress correct?

vast shale
#

Lemme see

verbal merlin
#

oki

vast shale
#

Yeah all is good

#

I think

verbal merlin
#

hehe okie

#

lemme cont

#

i got A = 2/5 e^t

#

i thought a and b wld become 0 oml

#

i feel smth is sus o.0

vast shale
#

Yeah I believe we messed up somewhere

#

Let's see

verbal merlin
#

mhmm haha

vast shale
#

Sorry I can't see it rn lmao I believe there should be a repeated root for ur particular solution tho

verbal merlin
#

oh lemme try looking through again

verbal merlin
#

shld i ask the helpers??

vast shale
#

Yeah I believe there should have been a t in there

verbal merlin
#

im lost

#

i think yc is right o.0 yp seems screwed?

vast shale
verbal merlin
#

okay

#

<@&286206848099549185>

vast shale
#

r = 1 is a root

verbal merlin
#

mhm

vast shale
#

the nonhomogenous part of your equation has 2e^tsin(t)

#

r = 1 also being a root here

verbal merlin
#

oh yes mhm

#

ok

#

oh hi again oml

#

oooh i see

#

u mean yp right?

vast shale
#

yes

#

wait sorry aa i will just go i dont think i can do this rn

verbal merlin
#

np

#

it looks wrong lol so complicated?

#

<@&286206848099549185> anyone can help me with yp

main spade
#

,w y''-2y'+2y=0

verbal merlin
#

oh hey again!

main spade
#

Looks like we have "Case 2".

verbal merlin
#

oh wow

#

which page is case 2 on

#

theres alot

main spade
#

It's in Chapter 21.

verbal merlin
#

oh ye that book is huge i was reading it

#

yp = Asint + B cost

#

this is what i had at first

#

but now i think its not so right?

main spade
#

Q(t) = 2e^t sin(t) contains a term u(t) of y_c(t) which, when ignoring constant coefficients, is t^0 times a term of Q(t).

verbal merlin
#

so one time of Q(t)

main spade
verbal merlin
#

hm so yp shld have the 2e^t sin t in it?

#

im still not so familiar with the cases still tryna digest it

main spade
#

I said earlier than you could choose which is u(x) but I think you actually have to consider both. You would arrive at a contradictory result if you use e^t cos(t) instead of e^t sin(t) as one would use Case 1 and one would use Case 2.

verbal merlin
#

oh wow sounds complicated o.0

main spade
#

Set Q(t) = 2e^t sin(t).
y_c(t) = c_1 e^t sin(t) + c_2 cos(t).
We can now see that y_c(t) contains a term t^0 times a term of Q(t), namely, Q(t) = t^0 u(t), where u(t) = e^t sin(t).
Hence by Case 2,
y_p(t) is equal to the linear combination of
t e^t sin(t) and it's finite number of linearly independent derivatives.

#

It is a bit tricky for this one, for sure.

#

It looks like y_p(t) is going to get pretty big.

verbal merlin
#

is this correct for yp then?

#

ye i think so too

main spade
#

No.

#

y_p(t) is equal to the linear combination of
t e^t sin(t) and it's finite number of linearly independent derivatives.

verbal merlin
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o.0 i think im quite lost on this question

main spade
#

Essentially, you need to find all of the different terms when you differentiate t e^t sin(t).

verbal merlin
#

i am really sorry to dissappoint but i dont understand

main spade
#

Just add a t to your original guess and call it a day.

verbal merlin
#

okay ill try

verbal merlin
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@main spade am i right o.0

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i think i lost the final brain cell oml im sorry if i sound a 100% dumb

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.close

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boreal path
#

what is the answer to C and is B AAn

vocal sleetBOT
mild flower
#

B is indeed A1An (which is what i think you meant to write...)

boreal path
#

yes

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what’s c

mild flower
#

that one i don't know

paper depot
#

"polygonal chain rule"??? idk lmfao

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thats the only thing i can think of

#

in any event this is not math but just vocabulary

boreal path
#

ofc

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mainly wanted to verify b

boreal path
mild flower
#

yeah

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pretty central to it

boreal path
#

oh cool

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so i’m doing uni math

#

thanks

#

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paper depot
#

don't reply-ping me on a message irrelevant to what you are saying

#

if you just wanted to get my attention you could plain ping me lol

boreal path
#

im not sure as to the differrence

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other than semantics

mild flower
#

reply-ping suggests that what you're saying has to do with that message and confuses us because we try to find a connection

boreal path
#

well

#

its an emoji

#

i dont think there exists a connection between linear algebra & emojis, but i digress

vocal sleetBOT
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boreal path
vocal sleetBOT
boreal path
#

unrelated note: why does this work

mild flower
#

same slope -> parallel

boreal path
#

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lone bridge
vocal sleetBOT
lone bridge
#

I tried substituion

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and LH

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no success

flat whale
#

what about taylor expansion?

lone bridge
#

havent tried

#

yeah it works with tayloe

#

thanks

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glacial meadow
vocal sleetBOT
glacial meadow
#

im looking for the ratio of aby

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i think its 1:1:^2

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or maybe 3

west raptor
#

Do you mean the ratio |AB| to |BY|?

glacial meadow
#

no like

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the ratio of the sides of the triang;e

west raptor
#

Ohhhh

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Ok

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Do you know the 45-45-90 triangle?

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If no, you can use the pythagorean theorem

glacial meadow
#

yes

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that was my thinking for 1:1:^2

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but i think i might be wrong..

west raptor
#

Does ^2 mean the square root of 2?

glacial meadow
#

yeah sorry too lazy to grab symbols

west raptor
#

I usually do sqrt(2)

west raptor
glacial meadow
#

thats probably better

#

oh??

west raptor
#

What's the larger triangle for though?

glacial meadow
#

wdym

west raptor
#

I mean the triangle XYZ

glacial meadow
#

i got a handful of these practice problems theres probably another question abt the other bits

west raptor
#

Oh ok

glacial meadow
#

yeah

#

thank youu!

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glacial meadow
#

whats the area of triangle xwz?

vocal sleetBOT
glacial meadow
#

where do i start here, is there a formula or something i can use nameitpls

mild flower
#

,tex .plane geom

twin meteorBOT
#

Hayley

glacial meadow
#

oook

#

so a= 1/2bh

mild flower
#

yeah

glacial meadow
#

now wait

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how do i find the height catThink

mild flower
#

couple options

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first and my favorite is that the big triangle is an equilateral one (do you see why?) so you can figure out the length of the slanted side

glacial meadow
#

ok i see its equilateral

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how does figuring out a slanyed side help though?

flat whale
mild flower
#

you don't really need trig here

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once you have the slanted side you can use Pythagorean theorem to get the height

glacial meadow
vocal sleetBOT
#

@glacial meadow Has your question been resolved?

glacial meadow
mild flower
#

the big triangle is equilateral

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do you know the length of any of its sides?

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or what lengths do you know?

glacial meadow
#

the baseis 24

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and i have a couple angles

mild flower
#

base is 24 good

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so one side of length 24

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and it's an equilateral triangle

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meaning all of its lengths are the same

glacial meadow
#

oh

glacial meadow
mild flower
#

this triangle is equilateral

glacial meadow
#

yep

#

so with pythag

#

20.78

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for the height?

mild flower
#

,calc 12*sqrt(3)

twin meteorBOT
#

Result:

20.784609690827
mild flower
#

yeah

glacial meadow
#

ZY- 24 since equilateral
using pythag theorem h-= 20.78
then solving for area using the formula,
area= 249.36

#

hows this?

mild flower
#

,calc 12*20.78

twin meteorBOT
#

Result:

249.36
mild flower
#

looks good!

glacial meadow
#

thanks!!

#

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pearl coyote
#

How do I go from the bottom step to the top step? Why is this not (aa+ba)(ba+bb)?

gray yarrow
#

treat a+b as one thing

#

let's introdue c=a+b

#

so we get

#

ac+bc=(a+b)c

#

otherwise we could get:
(aa+ab)+(ba+bb)
but we can't just switch the + to a * here

pearl coyote
#

a(a+b)+b(a+b)

c = a+b
a(c)+b(c)
ac+bc
c(a+b)
(a+b)(a+b)

#

that is

#

weird

#

so we're basically turning the things in parenthises into a variable temporarily?

mild flower
#

yeah we're treating them as one unit

gray yarrow
#

yes, exactly
nothing wrong with that

pearl coyote
#

And the same thing is being done here?

#

*something similar

#

c = 5a+2
5a(c)+2(c)
5ac+2c
c(5a+2)
(5a+2)(5a+2)

#

ok that is pretty cool and weird, thank you!

#

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pearl coyote
#

another question:

why is 2a^3-250 factored not 2(a^3-125). Why is it 2(a-5)(a^2+5a+25)?

pearl coyote
cyan talon
#

I mean 2(a^3-125) works, it's just that you can factor a bit further if you wish

#

a^3-125 = a^3 - 5^3 and there's a nice identity for that

#

if you're looking for roots and stuff, you might want to factor your polynomial as much as you can

pearl coyote
#

So we're doing this to break it down further into the absolute simpliest terms because 2(a-5)(a^2+5a+25) is actually in simplier terms than 2(a^3-125)?

mild flower
#

"simplest terms" is relative

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factored form is useful for some things

#

like solving equations like polynomial = 0

pearl coyote
#

So we're doing this to break it down further into the absolute simpliest terms factored form because 2(a-5)(a^2+5a+25) is actually in simplier terms more factored than 2(a^3-125)?

And this can be used in certain things like, your example, polynomial = 0?

mild flower
#

ye3ah

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i will note that you asked for "2a^3 - 250 factored"

#

not "2a^3 - 250 in simplest terms"

pearl coyote
mild flower
#

simplest terms is relative

#

and kinda subjective

#

"fully factored" is objective

pearl coyote
#

Got it that makes sense

#

To fully factor a polynomial like this one I could use "grouping" right?

I'm not super great at this but I think you have to split the middle term in two and the third term must be divided by one of it and have no remainder?

(I.e. a+b = -31x. 9/b = integer)?

pearl coyote
mild flower
#

and then yes split the middle term in two and group them

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serene hazel
vocal sleetBOT
serene hazel
#

Does B and D sound right?

dull maple
#

Yes

serene hazel
grave falcon
serene hazel
#

Can someone help walk me through 17. This is extremely confusing to me?

hasty pulsar
#

the screen has a rainbow gaussian curve

serene hazel
#

Still?

grave falcon
#

ahah

serene hazel
#

Even on the second picture?

#

For me the second one is fine

grave falcon
#

no its better

serene hazel
#

Ok cool

near island
#

where are you stuck

serene hazel
#

Ya I’m losing my mind with 17

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The current

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I have the work