#help-17
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if a tower was leaning at an angle and i want to consider the triangle formed by the point at the top of the tower, the base of the tower, and a point due west of the tower which has an angle of elevation to the top of the tower at 45. is this triangle a right angled triangle? i could draw it up if you are unable to visualise
It's not right angled
Since the tower is leaning
For it to be right the tower must be straight
Even if the top view looks like this
I'm not sure how to explain it but it would be a face of a triangular pyramid I know that OC isn't vertically upward but does that mean COB isn't a right angle where B is On level ground
Yes
There's another point due south of the base of the building ( on level ground)
Alright so it's non right angle?
Is OC perpendicular to BO
yep on the groun bc B is due west to O and A is due south
But you just said CO isnt vertical
yes OC is a leaning tower
but im assuming it is due north in the top view
to O
as B is due west and A is due south
Ok and
How does this result in the fact that angle COB is right
Think about it
Since CO isnt vertical
Angle COB will always either be <90 or >90
It will never be 90
@digital veldt Has your question been resolved?
lol wdym youre the one who asked?
ok thanks?
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I meant your explanation made no sense
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You and a friend take different flights in opposite direction but leave from the same airport.
Your flight starts out 210 miles due south and then turns 70 degrees west and goes another
80 miles. Your friend’s flight starts out traveling 80 miles due north and then turns 50
degrees to the east before traveling 210 mile. Explain how the Hinge Theorem would help
you find out whether you or your friend’s flight is farthest from the airport. Use the compass
for reference and provide a sketch.
sorry for the block of text
ive done the sketch, and i think they are the same distance away??
Hmm
so the Hinge theorem states that if two sides of two triangles are congruent, the third side of the triangle with larger included angle is longer than the triangle with smaller included angle
so compare the angle to find out who is farther
so 70 degrees and 50 degrees
yes
wdym by compare them
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why is the answer not 3x-2
which one?
Show us how you found 3x-2
i plotted the points down in desmos
then i counted how far apart it is on the y axis
the points i mean
and then how far apart they are on the x axis
It's correct, but in exams you will not have desmos 😛
You should learn to do it on paper!
i can do it on paper
Awesome!
How the hell is 3x-2 wrong, it's correct
i want to cry 
@vast shale Has your question been resolved?
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given that sin(40) = a, express cos(50), tan(-50) and sin(220) in terms of a
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@vast shale Has your question been resolved?
idk how to start
how can you re-write sin(x) as cos(x)
sin x = cos (pi/2 - x)?
wait can it be cos(x + pi/6)?
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Question in English : Which function has the following variation table?
!status
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@native dagger Has your question been resolved?
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wait
1/sin^2* cos ^2 a
how do i make this into cos^2a - cos^4a
Write $\sin^2(a) = 1 - cos^2(a)$
coldtee
i did
that would just make it 1/1-cos^2a * cos2 a
and if i take common it would make
1/(1-1)cos^2a
nothing but but 1?
coldtee
coldtee
Distributive property
Yeah
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im i ryt
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-1/m
its for this if need context
oh cool, how so though, hard imagining it
[
m_{\text{tan.}} = -\f1{m_{\text{nor.}}}
]
so its just a thing to remember in math
you can prove it using some geometry
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\textbf{Question:} Show that if $G$ is a self-complementary simple graph with $v$ vertices, then $v\equiv 0$ or $1;(\bmod 4)$
\vs{3 mm}
\textbf{My solution:} If $G$ is self complementary, then $G$ and $\overline G$ are isomorphic, meaning they both have the same amount of edges
\vs{2 mm}
When we have $v$ vertices, there can be at most $\f{v(v-1)}2$ edges
\vs{2 mm}
Since that can be at most $\f{v(v-1)}2$ edges and $G$ and $\overline G$ have the same amount of edges, the number of edges in $G$ is half of the maximum number of edges :[
G \textss{has} \f{v(v-1)}4 \textsx{edges}
]
And since since the number of edges has to be an integer: [
v(v-1) \equiv 0 ; (\bmod 4)
]
We can note that $v$ is odd and $v-1$ is even, or vice versa. The product of the two integers will surely be a multiple of 4 in this case if either terms is a multiple of 4 [
v \equiv 0 ; (\bmod 4) \textss{or} v-1 \equiv 0 ; (\bmod 4)
]Adding one to both equations:
[
v \equiv 0 ; (\bmod 4) \textss{or} v\equiv 1 ; (\bmod 4)
]
is my reasoning right here?
you are talking about "at most edges". why does this "at most" have to be attained
Because every vertex out of the $v$ vertices can connect to the other $v-1$ vertices, and when adding all connections to all the vertices, we count each edge twice and so the number of edges have to be $\ff{v(v-1)}2$
well again, at most
yes, at most
why is this "at most" number relevant
you arent using the definition of complementary graph anywhere
that should be a sign that you cant be completely right

@vast shale Has your question been resolved?
try to think how many edges will the complementary graph have
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oh rip
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This is finding the common denominator of two fractions
That common denominator being sin(θ)cos(θ)(sin(θ)-cos(θ))
doesnt the sintheta - cos theta in denominators get canceled?
no, it does not.
can u explain what is happening here using the bot?
abbreviating $\cos(\theta)$ and $\sin(\theta)$ with $c$ and $s$ respectively, you have:
$\frac{s^2}{c(s-c)} - \frac{c^2}{s(s-c)} = \frac{{\color{red}s} \cdot s^2}{{\color{red}s} \cdot c(s-c)} - \frac{{\color{red}c} \cdot c^2}{{\color{red}c} \cdot s(s-c)} \ = \frac{s^3}{sc(s-c)} - \frac{c^3}{sc(s-c)}$
Ann
doesnt it become sin^3theta (sintheta - cos theta) - cos^3 theta (sin theta - cos theta)/ cos (sintheta - cos theta) (sin theta (sin theta -cos theta)
i dindt get it
all i did
was take lcm
well cross multip;y
and do it
The product of the denominators isn't the lcm in this case, which is why what they did is better
Cross multiplying is fine just less efficient
sin^3theta (sintheta - cos theta) - cos^3 theta (sin theta - cos theta)/ cos (sintheta - cos theta) (sin theta (sin theta -cos theta)
sin^3 theta - cos^3 theta (sin thetea - cos theta)/
(sin theta * cos theta ) (sin theta - cos theta)
i took sintheta - cos theta common in both
does this work? @worthy citrus
You'll know if it works as you'll end up with the same as this
it ends up the same, but then i just want to know if im doingsome wrong shit to make it correct? @worthy citrus
Cross multiplying will always work fine, can just be more difficult/inefficient
is it possible for u to justonce
cross mulitply
using the bot?
,w sin^2 theta
,w sin^2theta
,w (sin^2theta - cos^2theta / costheta (sin theta - cos theta) ) - cos^2theta/sin theta /sin theta (sin theta - cos theta)
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online
...
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(XY problem alert ⚠️)
Find c such that the probability that 1 >= c is 1/2
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.coose*
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how to find circumfrance and area?
of the circle segment
sector minus triangle
sector?
why do i do sector - triangle?
That’s the area of the circular segment
but is there a reason behind it?
Sector ACB-triangle ACB
Yes, look at it visually
sorry, i am dumb, how do i do that?
but what is the reason? can you please tell me
I don’t know how to explain it
Look at the picture
If you take the triangle out of the circular sector
You get the segment
i think i skipped a chapter, what rule is that?
I don’t think you are understanding what I’m saying
no i don't sorry
Do you see sector ACB?
wait yes, the triangle?
what is a arc?
like the segment?
arc is curved line
so the segment?
Segment is straight line
ok the arc
Ok do you see the sector?
what is definition of sector?
I’ll send a picture
thank you
here
so a pizza slize shape?
x/360*area?
this is 30 60 90 triangle?
but how do i know its 60 degrees?
It says it right here
i mean its a half circle right?
No you are looking at the wrong sector
?
Look at the sector on the right
circle segment right?
The yellow part here
are we talking about your picture?
Sorry I’m bad at communicating
i never thought about this in that way
i am the problem, not you
If you have weird areas find a way to express them as two different areas
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What do I do now?
@ebon ocean Has your question been resolved?
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bit of a silly question but how would I write -6^7 on a ti-84
whenever I start with a - it defualts to my last answer-6^7
you should have a button other than the subtract button to add negative signs
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Is this right?
Didn't you forget a square while derivating t^3?
^
oh yes my bad
but is the process right
Yes absolutely
I did not understand i'm sorry 😅
this form for example
cuz sometimes u write vectors
as ijk
oh sorry i wrote right and not write
I would say that both forms are fine
this is for breaking it down into a sum of its components
v=<... , ...> is expressing it explicitly as a vector quantity
both are correct
It begins to really make sense when u start algebra
like when u do cross product and stuff?
yeah there is a way/trick of remembering how to get the cross product using ijk unit vectors
yeah i know because its really weird
our professor
taught us all that before
and for some reaosn
the last module is this stuff
which is really weird
this module should have been before that imo
but whatever
Yaah and when u see what a basis is
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can someone pls help me with this
I dunno what to do after this
" what percent is made on the cost?" this is confusing me
@short notch Has your question been resolved?
You are not trying to find the cost %
You want to find the profit percentage on cost
should it be 10/60 * 100 ?
if selling price is 50, and profit is 10, then cost price 60..?
...
Oh you added those
Ok so when we sell something
and have a selling price
Ideally we want the selling price to cover at least the whole cost of it
and then a bit of profit
Right?
is the selling price what the retailer bought it for?
No
The selling price is the price they are selling the product for
ah okay
that's why it's a selling price
so this means whatever the selling price is the store is making 20% more..?
okayy so 20% of the s.p was profit...?
And profit is how much they are earning in profits based on a percentage of the revenue
Yes
So 20% of the selling price is profit right?
yepp
That means the rest of it goes into the cost
So let's use $100 as an example
If they have a selling price of $100 (they earned revenue of $100)
They only made a profit of $20 (20% profit)
so cost = selling price - profit or cost = selling price - 0.2 * selling price
in other words, the remaining 80% is the cost
which is usually referred to as cost of goods sold
The question is asking what percentage of profit is made on the cost
ahhhh soo 20/80 * 100?
If you multiply by 100 that's the actual number of profit made on cost
20/80 by itself is the percentage value
0.25?
Yes
and you don't really need an example number to figure it out
You can think of selling price as the max number
it's not that simple but for the sake of this we can just say selling price is the max
or 100%
if the percentage of profit (given in the question) is 20%
then we can just divide it by the cost percentage
100%-20%
is the value we use for percentage and cost suppoussed to be in terms of % or in terms of $?
so 20%/80%
Wdym?
like is it different if i write 20%/80% vs 20/80?
Yes
a percentage is expressed in decimals
100% = 1
so if you did 20% / 80% it would be 0.20 / 0.80
but if you use 20 / 80 you have to put that into the perspective of actual values (not percentage)
like your example of SP = $50 and profit = $10
cost = 50-10
So we can say 10 / 40
does that make sense
np 👍
I think you have to close the channel out
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anyone mind helping me
are you able to find the area of the circle
yes
how about the square surrounding it
dont know how for that
what is the area of a square
how do i find out teh side length?
look at what you were given in the picture
show your work
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If I have a function for all line segments in R^2 space, can I apply it to a closed curve? And how? What related mathematics knowledge I would need to use? Differential Geometry? Tysm
what do you mean by "a function for all line segments in R^2"
and what do you mean by "apply it to a closed curve"
do you have a specific question in mind
A function that by giving coordinates of two points of a line segment, then it will return a value
And can a closed curve be divided into a collection of infinitesimally small line segments, so this function can be applied to this curve?
Thx you!
what are these functions on the line segments like
what kind of functions are we working with
also you can always do the second thing you mentioned, but that limit might not converge
Just a combination of some inversed trigonometric functions and inversed hyperbolic functions
May be using arcoth and arctan
the function should be heavily depend on the length of the line segment
can you give me an example of a function on a line segment
Ok pls wait a moment, thx u so much btw
ArcCoth[Length of the line segment/Height of its center from the x-axis]
well this isn't defined for all line segments
if you did have a function that was defined for all line segments, or say some convex set containing the curve, then you could definitely do what you said in your second question
but it may not converge
and it may go as far as to depend on how you split up the line segments that approximate the curve
you may be able to characterize this as "functional analysis"
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**If it take 1hours for two people to do some work in 240/11 days then how many hours they would have to work to get the work done in 5 days only? **
@empty minnow Has your question been resolved?
(2 ppl)×(1 hr)×(240/11 days) = (480/11 work)
(2 ppl) × (x hr) × (5 days) = (480/11 work)
Solve for x hr
I belive
(The units maybe vaguely described)
Sry for that
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im taking the derivative of this
do
i combine the 2.0+3.0t before taking derivative?
and if not that means the 2.0 is gone right?
wait why not
They are not like-terms
Like for $x^2 + x + 6$ you can't just transform that to $x^2 + 7t$ or something using your logic
Yes
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i appreciate the help a ton
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idk
do they mean vertical or horizontal
there's no concept of vertical or horizontal in the question
@craggy hamlet Has your question been resolved?
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would i choose (0,0) as my origin
or (0,100)?
because later in the question i used -100
0,0 because 100 is the vertical distance of the rock from the ground
And this is a nonsense is physics
Distances can't be negative
And here we are talking about distance
i see
But you can't say "my rock is at -100m of altitude"
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Can someone check if this is correct?
yep, x4 is free
@cobalt imp Has your question been resolved?
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I got pretty far but im stuck
Could you post your work?
Yes sry im typing it 1 moment
A/(x+2) + B/(x-2)
A(x-2) + B(x+2)
Ax - 2A + Bx - 2B
(A+B)(x-2) = 7
Normally at this point in the question I get the form (A+B)(x) + n, but this time the 2 factors out, so I dont really know what to do next
Why are you
ing me? 
(x+4)(x-4) isn't (x^2-4)
(A+B)(x-2)
7
Could you maybe try values of x to eliminate unknowns ?
Random with a purpose
If you eliminate A but B is still in the equality you can solve for it
Do you not see values of x that allow us to do that?
One note here is that the left side has to equal the right side for every value of x
A(x-2) +B(x+2) = 7 for all values of x, so you can choose some "random" value of x, and the equation will still remain true. So you probably want to choose some value of x, that would eliminate either A or B from the equation
oh so +2 or -2 right?
Combo haha
So 4b = 7
And solve for A and B
Thats it right?
Okok I think I can manage that
Thank you everyone!
❤️
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✅
Sry I got stuck on something again
A(x-2) +B(x+2) = 7
-4A = 7 so A= -7/4
4B = 7 so B = 7/4
(7/4)(x-2) + (-7/4)(x+2) = 7
0 = 7????
How did you get -4A = 4B = 7 ?
(A+B)x + 2(B-A) = 7
Is this an equation in x or is it supposed to hold for all x ?
Im not really sure what either of those mean, A and B dont have a definite value yet, I just made them up
A/(x+2) + B/(x-2)
A(x-2) + B(x+2)
Ax - 2A + Bx - 2B
(A+B)(x-2) = 7
Oh you're doing PFD
yeye
So it must hold for all x
Hence A+B = 0 and B-A = 7/2
A+B=0?
A constant can't depend on x, can it?
Ah oke
Hence 2B = 7/2 so B = 7/4 and A = -B = -7/4
yeye
So did you also get 0 = 7? When you tried to work it out
Or did I make a mistake
I didn't
In general if you find a contradiction, you made a mistake. Unless you made some assumptions, then they shall also be questioned
But here the assumptions are correct because it's known from the theory of PFD
So what did I do wrong sry?
What are these random expressions for ?
What are they equal ?
What do they represent?
Can't proofread work I can't begin to try to understand
7/(x^2 - 4)
It needs to be split into 2 fractions A and B to make integration possible
A/(x+2) + B/(x-2)
To work out A and B I set them equal to the numerator
A(x-2) + B(x+2) = 7
Ax - 2A + Bx + 2B = 7
(A+B)(x-2) = 7
Then I tried to work out A and B using substitution but it didnt work...
like substitution -2 and 2 for x into A(x-2) + B(x+2) = 7
You expand wrong on the second-to-last line
It's +2B
Then you get where I was
Does thit just mean that its (-7/4)/(x+2) + (7/4)/(x-2)?
Or its not allowed because of the 7 = 0?
There's no 7=0
Oh
That's the bullshit you made by mistake
Forget it
If it comes from an error, it doesn't hold. Then it can't object to anything
ok sorry
Unless ofc it happens to hold for some other reason. But not in this case, since it's clearly wrong
I thought I had it but its wrong
(-7/4)/(x+2) = -ln(x+2), no?
And (7/4)/(x-2) = ln(x-2)?
Clearly off by a constant at least
Awful use of the = sign
Can't approve of that
-7/4 /(x+2) -> -7/4 ln(x+2)
Simple linearity
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what do the different shadings mean? i think one's greater than and one's greater than/equal to but i don't know which is which
i don't think they're different
greater than is represented with dotted line
while greater than equal to is represented by a solid line
the way the area is shaded doesn't matter
i see
makes sense i dont think theyd throw in a new thing on a test when we didnt learn it
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im just unsure of how to solve this one. i know its an easy proportion but ive never had to solve one with a variable
18 is to 12x as 5 is to __
Result:
3.3333333333333
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np
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First thing for any of these questions is to get the roots right? How do I get the roots of sin(x/2)?
Equate it to 0
So like sin^-1(0) = x/2
pi(k) = x/2
2pi(k) = x?
What do I do next?
Ah wait I think I see it
Yeye I can do this
Thank you!
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Hello again
doing it now one second
i might have troubles with yp more lemme write down yc and add here
i think yc will have the complex root thing right?
@vast shale is this correct?
The particular integral yp = Asint + Bcost
Sorry lemme see
hehe sure np
Yeah that should be fine
is this correct?
Yes
im blind haha
this correct?
i think a & b would be 0 eventually but is yp correct??
@vast shale is yp correct
also the username with flowers is nice hehe!
Yeah that should be right
Haha ty
Differentiate twice and plug into the equation and solve for the coefficients
See what you get out of that I guess
Lemme see
oki
hehe okie
lemme cont
i got A = 2/5 e^t
i thought a and b wld become 0 oml
i feel smth is sus o.0
mhmm haha
Sorry I can't see it rn lmao I believe there should be a repeated root for ur particular solution tho
oh lemme try looking through again
im not so sure also lmaoo
shld i ask the helpers??
Yeah I believe there should have been a t in there
wait where o.0
im lost
i think yc is right o.0 yp seems screwed?
Yeah go for it. I gtg
for ur complementary solution, you got e^t[blah + blah]
r = 1 is a root
mhm
np
it looks wrong lol so complicated?
<@&286206848099549185> anyone can help me with yp
oh hey again!
Looks like we have "Case 2".
time to pull out the magic math book
oh wow
which page is case 2 on
theres alot
It's in Chapter 21.
oh ye that book is huge i was reading it
yp = Asint + B cost
this is what i had at first
but now i think its not so right?
Q(t) = 2e^t sin(t) contains a term u(t) of y_c(t) which, when ignoring constant coefficients, is t^0 times a term of Q(t).
so one time of Q(t)
hm so yp shld have the 2e^t sin t in it?
im still not so familiar with the cases still tryna digest it
I said earlier than you could choose which is u(x) but I think you actually have to consider both. You would arrive at a contradictory result if you use e^t cos(t) instead of e^t sin(t) as one would use Case 1 and one would use Case 2.
oh wow sounds complicated o.0
Set Q(t) = 2e^t sin(t).
y_c(t) = c_1 e^t sin(t) + c_2 cos(t).
We can now see that y_c(t) contains a term t^0 times a term of Q(t), namely, Q(t) = t^0 u(t), where u(t) = e^t sin(t).
Hence by Case 2,
y_p(t) is equal to the linear combination of
t e^t sin(t) and it's finite number of linearly independent derivatives.
It is a bit tricky for this one, for sure.
It looks like y_p(t) is going to get pretty big.
No.
y_p(t) is equal to the linear combination of
t e^t sin(t) and it's finite number of linearly independent derivatives.
o.0 i think im quite lost on this question
okayy
Essentially, you need to find all of the different terms when you differentiate t e^t sin(t).
i am really sorry to dissappoint but i dont understand
Just add a t to your original guess and call it a day.
okay ill try
Atsint + Btcost
@main spade am i right o.0
i think i lost the final brain cell oml im sorry if i sound a 100% dumb
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what is the answer to C and is B AAn
B is indeed A1An (which is what i think you meant to write...)
that one i don't know

"polygonal chain rule"??? idk lmfao
thats the only thing i can think of
in any event this is not math but just vocabulary
is vectors part of linear algebra
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don't reply-ping me on a message irrelevant to what you are saying
if you just wanted to get my attention you could plain ping me lol
reply-ping suggests that what you're saying has to do with that message and confuses us because we try to find a connection
well
its an emoji
i dont think there exists a connection between linear algebra & emojis, but i digress
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unrelated note: why does this work
same slope -> parallel
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what about taylor expansion?
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Do you mean the ratio |AB| to |BY|?
Ohhhh
Ok
Do you know the 45-45-90 triangle?
If no, you can use the pythagorean theorem
Does ^2 mean the square root of 2?
yeah sorry too lazy to grab symbols
I usually do sqrt(2)
Yeah that's right
What's the larger triangle for though?
wdym
I mean the triangle XYZ
i got a handful of these practice problems theres probably another question abt the other bits
Oh ok
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whats the area of triangle xwz?
where do i start here, is there a formula or something i can use 
,tex .plane geom
Hayley
yeah
couple options
first and my favorite is that the big triangle is an equilateral one (do you see why?) so you can figure out the length of the slanted side
Do you know any trig
you don't really need trig here
once you have the slanted side you can use Pythagorean theorem to get the height
i js started trig
ohhhhh
@glacial meadow Has your question been resolved?
i take it back lol, i dont understand how to get the slanted side ._.
the big triangle is equilateral
do you know the length of any of its sides?
or what lengths do you know?
base is 24 good
so one side of length 24
and it's an equilateral triangle
meaning all of its lengths are the same
oh
so itd be 24*24
,calc 12*sqrt(3)
Result:
20.784609690827
yeah
ZY- 24 since equilateral
using pythag theorem h-= 20.78
then solving for area using the formula,
area= 249.36
hows this?
,calc 12*20.78
Result:
249.36
looks good!
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How do I go from the bottom step to the top step? Why is this not (aa+ba)(ba+bb)?
treat a+b as one thing
let's introdue c=a+b
so we get
ac+bc=(a+b)c
otherwise we could get:
(aa+ab)+(ba+bb)
but we can't just switch the + to a * here
a(a+b)+b(a+b)
c = a+b
a(c)+b(c)
ac+bc
c(a+b)
(a+b)(a+b)
that is
weird
so we're basically turning the things in parenthises into a variable temporarily?
yeah we're treating them as one unit
yes, exactly
nothing wrong with that
And the same thing is being done here?
*something similar
c = 5a+2
5a(c)+2(c)
5ac+2c
c(5a+2)
(5a+2)(5a+2)
ok that is pretty cool and weird, thank you!
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another question:
why is 2a^3-250 factored not 2(a^3-125). Why is it 2(a-5)(a^2+5a+25)?
In the picture like why even do this? Why not just leave it?
I mean 2(a^3-125) works, it's just that you can factor a bit further if you wish
a^3-125 = a^3 - 5^3 and there's a nice identity for that
if you're looking for roots and stuff, you might want to factor your polynomial as much as you can
So we're doing this to break it down further into the absolute simpliest terms because 2(a-5)(a^2+5a+25) is actually in simplier terms than 2(a^3-125)?
"simplest terms" is relative
factored form is useful for some things
like solving equations like polynomial = 0
So we're doing this to break it down further into the absolute simpliest terms factored form because 2(a-5)(a^2+5a+25) is actually in simplier terms more factored than 2(a^3-125)?
And this can be used in certain things like, your example, polynomial = 0?
ye3ah
i will note that you asked for "2a^3 - 250 factored"
not "2a^3 - 250 in simplest terms"
Sorry if this is a stupid question what would the difference be?
Got it that makes sense
To fully factor a polynomial like this one I could use "grouping" right?
I'm not super great at this but I think you have to split the middle term in two and the third term must be divided by one of it and have no remainder?
(I.e. a+b = -31x. 9/b = integer)?
Sorry, I keep forgetting to ping
you want uh
two numbers a and b that multiply to 9*12 and add to -31
and then yes split the middle term in two and group them
@pearl coyote Has your question been resolved?
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Does B and D sound right?
Yes
What is the frequency of the screen lol
the screen has a rainbow gaussian curve
Still?
ahah
no its better
Ok cool
where are you stuck


