thats why i chose different values for both of them
#help-17
vast shale
rugged orchid
@vast shale idk if you actually understand what im saying
vast shale
<@456226577798135808> idk if you actually understand what im saying
i kinda do
rugged orchid
the fact your function needs to be either odd or even means the asymptotes and roots should be symmetric
but if we allow for either 2 roots or 2 asymptotes the question is doable
dapper condor
i think you can allow for two roots
vast shale
OHH, and we can only have 1?
rugged orchid
well i assume so
vast shale
i think you can allow for two roots
it doesnt say that in the question tho-
rugged orchid
there's nowhere that says we can have more than 1 root or asymptotes
but i would say you want to make a case for having 1 root 2 asymptotes
or 2 roots 1 asymptote
vast shale
hm thats true
vast shale
hmm yea that works
rugged orchid
also you just did their question for them
something that should've been their work
dont do that
rugged orchid
make your own function
regal slate
vast shale
<:shiver:934961643643871332>
LMAO
vast shale
make your own function
any?
rugged orchid
x intercepts
rugged orchid
try think about what properties you want your function to have
it's fine to experiement with what different functions look like on a graphing calculator
but really you should try to think about what it looks like instead of guessing
rugged orchid
there is an asymptote on here
vast shale
isn't it a decimal tho?
i meann i think thats fine
it just says value in the question tho, so idrk
regal slate
doesn’t matter if it’s not a whole number, an asymptote is an asymptote
the asymptote just denotes a point where the function is undefined
vast shale
so, this would work?
regal slate
well, i don’t think so
vast shale
😭
regal slate
because the function is never increasing
regal slate
oh
vast shale
hm
regal slate
think about what causes an asymptote then manipulate that information to from an appropriate function
keep in mind: there can be more than one asymptote
or if you want one asymptote then there can be more than one root
vast shale
yeaa im trying
regal slate
one asymptote - two roots or two asymptotes - one root
vast shale
how do i make it decreasing tho?
regal slate
when x increases, y should decrease
vast shale
oh okay
vast shale
wait really, how?
regal slate
vast shale
while being odd/even too?
rugged orchid
the asymptote just denotes a point where the function is undefined
that's not quite right
it's a bit more than undefined
regal slate
regal slate
it's a bit more than undefined
hmm
regal slate
the y-intercept would be a value where x = 0, f(1) is just 1 as the input of the function
vocal sleetBOT
@vast shale Has your question been resolved?
vast shale
the y-intercept would be a value where x = 0, f(1) is just 1 as the input of the...
Ohhh okay, so I put whatever function that I've graphed?
astral pebble
Hey does this look right?
vocal sleetBOT
Hey does this look right?
astral pebble
I tried checking with mathway and symbolabs and both gave different answers
symbolabs was the same as mine
but mathways was 2y-y/x
the base function is ln(xy)=2x
and the question asks for dy/dx
I also dont understand the part b followup
barren dove
a => 2xy
astral pebble
how?
barren dove
this is because the differentiation of ln(xy) is $\frac{dy}{dx} \times \frac{1}{xy}$
twin meteorBOT
zephyrperegrine
barren dove
we will use chain rule to differentiate it
The differentiation of 2x on RHS will become 2
(I am differentiating the equation wrt x)
astral pebble
so taking deriv of ln(xy) you just get 1/xy
barren dove
$\frac{dy}{dx} \times \frac{1}{xy} = 2$
twin meteorBOT
zephyrperegrine
barren dove
so taking deriv of ln(xy) you just get 1/xy
multiplied by dy/dx
barren dove
cross multiply
astral pebble
treat y as the variable right?
astral pebble
cross multiply
oh?
barren dove
$\frac{dy}{dx} = 2xy$
twin meteorBOT
zephyrperegrine
astral pebble
how is that cross multiplication though?
dont you just mean multiply both sides by xy?
barren dove
yes that^^
astral pebble
ok
barren dove
I also dont understand the part b followup
as of part b, the tangent line to the curve will be the differentiation of it
astral pebble
wdym?
barren dove
$y = xe^{2}$
twin meteorBOT
zephyrperegrine
barren dove
the slope
barren dove
not what I really did
barren dove
i made a small error while differentiating ln(xy) = 2x
lemme start from the beginning
barren dove
(1/xy)(xy'+y)= y'/y + 1/x= 2
this is just the differentiation you did
a bit modified
barren dove
y' = (2-1/x)(y)
$\frac{dy}{dx} = (2 - \frac{1}{x})(y)$
twin meteorBOT
zephyrperegrine
barren dove
incase there was any confusion
astral pebble
so just 2y-1/x?
barren dove
yep
barren dove
2y -y/x
astral pebble
right?
barren dove
you have to distribute y
distribute it?
you just gotta multiply y with both terms in the first bracket
so it should become 2y - y/x
this is the first part
the second part is a continuation of this, so you can feel free to ask wherever you dint get me
@astral pebble
astral pebble
so if I have 2y-y/x
I just plug in my x and y?
so 2(e^2)-(e^2)/1
so wouldnt my slope just be 2?
barren dove
no no
the values given in part 2 are the limits fro your differentiation
astral pebble
ln(xy) = 2x
(1/xy)(xy'+y)= y'/y + 1/x= 2
y'/y = 2 - 1/x
y' = (2-1/x)(y)
y'(1,e^2) = e^2
y-e^2 = e^2(x-1) = xe^2 - e^2x
y = xe^2
@barren dove
does that seem right?
barren dove
y' = (2-1/x)(y)
y'(1,e^2) = e^2
what did you do here?
astral pebble
y' = (2-1/x)(y)
y'(1,e^2) = e^2
what did you do here?
tbh im not sure
barren dove
so wouldnt my slope just be 2?
your slope will become e^2
astral pebble
I am exhausted
astral pebble
your slope will become e^2
I figured that out at the end
the tangent should be y=xe^2
barren dove
i did get that
astral pebble
i did get that
ok
also
isnt this just undefined?
like you cant go any further with it
can you
barren dove
hmm
astral pebble
because idk why my professor would add it
barren dove
I am not sure
barren dove
limits and trigonometry are my weak suites
astral pebble
but it wont get me anywhere
astral pebble
limits and trigonometry are my weak suites
the deriv of sinh is cosh
and the deriv of cosh is sinh
barren dove
i know the derivatives
barren dove
and the deriv of cosh is sinh
no
astral pebble
so idek what I can do
barren dove
-sinh
astral pebble
yeah
that
so I cant do anything right?
this feels like a trick question
<@&286206848099549185> any ideas here?
I tried plugging it in to a few calculators and all said undefined
but my professor is not the type to waste time with trick questions
barren dove
what you can do is
substitute x with 1/y
and the limit y will tend to 0
and that might get you somewhere idk
just giving a perspective
astral pebble
hmm
vast shale
<@&286206848099549185> any ideas here?
you can expand both sinh and cosh to their e^x equavalent
vast shale
we were never taught that
you can search more but the short answer is that sinh(ax) = (e^(ax) - e^(-ax))/2
astral pebble
lets say I did all of that
vast shale
cosh(ax) = (e^(ax) + e^(-ax))/2 a is constant
astral pebble
wouldnt it still end up not being solvable for the limit heading to inf?
vast shale
wouldnt it still end up not being solvable for the limit heading to inf?
give me a few minutes to solve it
vast shale
I am so lost
I'm sure it's simple just take your time to solve it
astral pebble
its not though bc to get the limit going to inf I need the variable gone
vast shale
its not though bc to get the limit going to inf I need the variable gone
not exactly you just need to simplify the function then plug in the inf to the variable
vast shale
wouldnt it still end up not being solvable for the limit heading to inf?
after you do that jus split the fraction and simplify you'll find the answer will be inf after all
astral pebble
not exactly you just need to simplify the function then plug in the inf to the v...
I just wrote that the limit is undefined as you no matter how many times you apply l'hoptials rule you still get the lim as x goes to inf is inf/inf
ik it may not technically be right
but I am so lost
barren dove
I just wrote that the limit is undefined as you no matter how many times you app...
but the functions sine and cosine have their limits
astral pebble
I just want to submit and be done
barren dove
sine and cosine are always in the range [-1,1]
vast shale
but I am so lost
not all the functions work with l'hopital
astral pebble
shoot true
vast shale
if it fails try another approach to solve it
vast shale
vocal sleetBOT
vocal sleetBOT
@vast shale Has your question been resolved?
sudden compass
yes it is 4
vast shale
.close
onyx salmon
vocal sleetBOT
clever cave
<@&286206848099549185>
135
357
157
137
So 4 ways
Kinda weird since there are exactly 4 odd integers
onyx salmon
R u sure because my textbook answers say that the answer is 2304
clever cave
Oh wait
They meant all possibilities of arrangement
Also I didn’t see the “at least”
That changes it quite a bit
onyx salmon
Yeah the topic is combinatorics so I’m assuming the qn wants u to use factorials and stuff
<@&286206848099549185>
vast shale
<@&286206848099549185>
you get two scenarios and then you add them up
treat permutation of 3 odds as a solid number, in combination with the rest of the numbers
similarly permutation of 4 odds treated as a group, in combination with the rest of the numbers
add the two scenarios
that should be your answer
covert salmon
This is true right?
vocal sleetBOT
This is true right?
nimble imp
It is true by the Leibniz Test or the Alternating Series Test
vast shale
vocal sleetBOT
vast shale
Does anyone know any good YouTube videos that explain graphing questions like this?
I’m having difficulties
glossy maple
Which one specifically
In order to graph 1/f(x), you just need to know what main changes happen from f(x) to 1/f(x)
How does the increasing/decreasing intervals change?
Intervals where f(x) is positive/negative?
Min/max points?
Points where f(x) = 0?
Those are the main things you need to consider
vocal sleetBOT
@vast shale Has your question been resolved?
vast shale
@glossy maple what about this one?
glossy maple
First, you know it's only gonna be defined when f(x) > 0
and what you wanna know, is when ln(f(x)) is gonna be negative
and when is it gonna be positive
so in general, ln(x) < 0 when 0 < x < 1
and ln(x) > 0 when x > 1
try to continue from here
vocal sleetBOT
@vast shale Has your question been resolved?
vocal sleetBOT
vocal sleetBOT
Available help channel!
royal grove
vocal sleetBOT
royal grove
I was looking to the proof that Euler's phi function is multiplicative
But if s = t (mod n), then gcd(s, n) = 1 if and only if gcd(t, n) = 1.
where did they use this ?
vocal sleetBOT
@royal grove Has your question been resolved?
royal grove
<@&286206848099549185>
fossil ginkgo
What are s and t?
Do they have any significance or are they jused used as dummy variables
Also idk what "rth column" refers to, looks like theres some sort of array that is not shown
royal grove
What are s and t?
they are taken randomly
i cant understand the significance of that line
fossil ginkgo
Ah, i see
So we know that the integers r, m+r, 2m+r, ..., (n-1)m + r are congruent to 0, 1, 2,..., n - 1 in some order
royal grove
yup
fossil ginkgo
Basically what the line is saying is that
royal grove
oooooo
wait
i get it
okay
so the integers r, m+r, 2m+r, ..., (n-1)m + r
reduce to 0, 1, 2, ... , n-1
and still have gcd 1
okay
fossil ginkgo
if jm + r = z (mod n) for some z in {0, ..., n - 1}, then jm + r is relatively prime to n if and only if z is relatively prime to n
royal grove
makes sense
fossil ginkgo
yes
royal grove
yess
royal grove
yeah i got it. i knew what they were saying but just wasn't sure where they were using that
thank you ^^
fossil ginkgo
of course!!
royal grove
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
devout gazelle
vocal sleetBOT
devout gazelle
Anyone?
vocal sleetBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
flat whale
Find A^2 and A^3 and see which answer fits
inner bloom
hi
inner bloom
is there anything that can help me to find A^4 faster?
I mean is there any formula or method to avoid the process
vast shale
A is a matrix given by those entries?
vast shale
you could diagonalise, but the dimension is small enough that square and multiply is effective here
(ie, to find A^4 for a 2x2, do (A^2)^2)
if you wanted to find higher powers, its helpful to do this: https://en.wikipedia.org/wiki/Diagonalizable_matrix#Diagonalization
inner bloom
My question is more general
is the fact that a matrix is upper triangular and lower triangular helpful at all?
vast shale
if the matrix is triangular, its easy to find the eigenvalues, thus makes diagonalisation an attractive method
vast shale
np
inner bloom
.close
true gale
I need to find the limit of sqrt^n(2^n+3^n) and i have no clue how
full hatch
Do you mean the n-th root?
true gale
yes
brittle coral
what is n tending to
twin meteorBOT
true gale
yes mb n goes to inf
full hatch
Try to rewrite it as e^[something] and move the lim to the exponent
true gale
so like e^ln(3n.((n+2)/n))?
full hatch
Still not right
hard atlas
you could also just stay with the root and factor out 2^n inside
true gale
am i not allowed 2 bring the exp out?
full hatch
Don't know if you want to stay with my way or want to do as Den suggested
true gale
i thought we where doing anoter 1 i just looked back at what i aked mb mb but what happens after i factor out the 2^n
full hatch
The 2^n factored out gives us a 2
hard atlas
$\sqrt[n]{2^n+3^n} = \sqrt[n]{2^n\cdot \left( 1+ \left(\frac32\right)^n\right)} = 2 \cdot \sqrt[n]{1+\left(\frac32\right)^n}$
twin meteorBOT
denascite
hard atlas
and now the limit should hopefully be doable
true gale
can I get rid of the n in (3/2)^n?
hard atlas
in what way
glossy maple
another way would be squeeze theorem
brittle coral
I think this is the method to do it
true gale
his awnser is right so idk
glossy maple
its correct, the method is wrong
brittle coral
you can't just evaluate part of the limit
I didnt
glossy maple
well clearly the 1/n is still on the exponent
you cant just say (2/3)^n approaches 0
and let the exponent with 1/n stay there
brittle coral
It is an approximation
2/3^n is very small compared to 1
So we can ignore it
glossy maple
that's not how this works...
hard atlas
if you are gonna handwave it, you could have done that from the beginning
clearly 2^n << 3^n
glossy maple
$\lim_{n \to \infty} \parens{1 + \frac{1}{n}}^{n} = \lim_{n \to \infty} 1^{n} = 1$
by your logic
oops
meant n there
twin meteorBOT
redstoneplayz09
glossy maple
(this is incorrect, just to emphasize)
true gale
so what do i do with the (3/2)^n?
true gale
**denascite**
if i use this
hard atlas
another way would be squeeze theorem
.
glossy maple
i think it's easier to use squeeze theorem when you write it as
(2^n + 3^n)^(1/n)
true gale
idk how srry
glossy maple
i'm not sure how to give a hint here without giving it away
basically, you first want to bound it from above
and then from below
by 2 expressions
obviously (2^n + 3^n)^(1/n) > 0, for example
but that doesn't help you.
you want an expression that has a limit of 3 as n approaches infinity
so try to think
"how can I make this bigger, while not changing much, and still have the limit be 3"
$\sqrt[n]{2^n + 3^n}$
twin meteorBOT
redstoneplayz09
true gale
but how would i know that the limit is 3 in the first plce?
but to awnser i guess just make it n+1 and n-1 i guess
glossy maple
but how would i know that the limit is 3 in the first plce?
well u dont
but now that you do, use it to your advantage lol
true gale
so i add a +1 at the end?
glossy maple
that doesnt help
u want the expressions u want to have limits that are easy to evaluate
currently the limit is hard because it consists of 2^n and 3^n added together
see if you can "fix" that
true gale
can it be something else like 3+1/n or does it have to come from the original thing?
oh would (3^n)^1/n work?
glossy maple
oh would (3^n)^1/n work?
for lower bound, yes
thats great
you "remove" the 2^n which makes the expression smaller
so you know the whole expression is at least 3, which makes the limit also at least 3
upper bound may be a little harder to see though, see if you can get it
true gale
i could make it (3^n+3^n)^1/n?
twin meteorBOT
redstoneplayz09
glossy maple
the limit of this is 3
and you're done
$3 \leq \sqrt[n]{2^n + 3^n} \leq \sqrt[n]{2 \cdot 3^n}$
twin meteorBOT
redstoneplayz09
glossy maple
$\lim_{n \to \infty} 3 = \lim_{n \to \infty} \sqrt[n]{2 \cdot 3^n} = 3$
twin meteorBOT
redstoneplayz09
glossy maple
$\implies \lim_{n \to \infty} \sqrt[n]{2^n + 3^n} = 3$
twin meteorBOT
redstoneplayz09
twin meteorBOT
flat whale
!show
vocal sleetBOT
Show your work, and if possible, explain where you are stuck.
@vast shale Has your question been resolved?
long gale
I need help
vocal sleetBOT
I need help
long gale
I did everything
long gale
but the answer is wrong
long gale
Just plug in
i did that
timber orchid
And what did you get
long gale
(1,-3) and (-1,-11)
timber orchid
Did you check the answer with a graph?
long gale
there is no graph
thats why im confused
can you do it and tell me the anwser so i might understand what i got wrong or maybe the website is just wrong
timber orchid
Just graph the function
long gale
huh?
timber orchid
Which part of graph the function didn't make sense
I can try explaining it as needed 👍
long gale
there is no graph
long gale
Plot y = f(x)
what?
long gale
where f come from
stark plume
f(x) = x^3+3x^2-7
long gale
f(x) = x^3+3x^2-7
that's just over complicated version of the question to me 💀
timber orchid
that's just over complicated version of the question to me 💀
Just graph y = x^3 + 3x^2 - 7
Can you do that?
long gale
i'll try
timber orchid
Just use a graphing calculator
cerulean harbor
,w graph y=x^3+3x^2-7
twin meteorBOT
timber orchid
See? Not that hard
lost blaze
for the first question, is angle EOB equal to DOC and why?
vocal sleetBOT
for the first question, is angle EOB equal to DOC and why?
lost blaze
vocal sleetBOT
@lost blaze Has your question been resolved?
lost blaze
<@&286206848099549185>
zenith seal
I know how to do (2), in case you need help with that, but I dont know (1) (at least not yet)
do you need help with (2)?
lost blaze
nope
i know how to do 1, but im not sure if one info i used is correct
is angle EOB equal to angle DOC
mild lintel
Do you know about vertical angle pairs?
zenith seal
you can derive (1) from (2)
lost blaze
Do you know about vertical angle pairs?
yes, i just wanna confirm
mild lintel
K
lost blaze
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
austere creek
A fair 6
-sided die is rolled 4
times and the resulting sequence of 4
numbers is recorded.
How many different sequences are possible?
1296
How many different sequences consist entirely of even numbers?
q
How many different sequences are possible if the first, third, and fourth numbers must be the same?
austere creek
i am stuck because i thought this: 6 × 1 × 6 × 6 = 216
round plover
you have 6 options for the first number, the second doesn't have any restrictions, so another 6 options there, and the last 2 have to match the first number
wispy lotus
vocal sleetBOT
wispy lotus
plz help me
karmic imp
Do you know what $f \circ g$ means?
twin meteorBOT
dldh06
wispy lotus
nope
actualy
can u just look over my work
and tell me if i did anything wrong plz
<@&286206848099549185>
sleek orbit
Are you just wanting someone to check it?
I checked it and didn’t see anything wrong with it
wispy lotus
ya i just wana check
some1 check
there is no mistakes?
did i do 2 right?
like idk how to show floor or celiling so i did that
is it good?
vocal sleetBOT
@wispy lotus Has your question been resolved?
wispy lotus
.close
fiery ravine
3^(x+2) = y find 3^x in terms of y
vocal sleetBOT
3^(x+2) = y find 3^x in terms of y
fiery ravine
i was wondering what kind of problem this is
ik how to do it just looking for similar practice problem
im good at everything with exponents except this
studying for sar
sat
calm light
these are logarithm problems it looks like
fiery ravine
eiw
calm light
you should just do khan academy and if that isn’t enough just google worksheets
calm light
imo nothing really beats khan academy unless you need more practice tests but you do you
fiery ravine
khan academy kept giving me insanely simple math problems even tho it was individualized to my past tests and even tho i didnt get those types of problems wrong
didnt like it
.close
vast shale
vocal sleetBOT
vast shale
is this right or wrong?
glossy maple
wrong
brisk moss
it's discontinuous at 0 points
dusk python
log(1) = 0
vast shale
but there isnt any zeros in the answer
this is so confusing or rather im so stupid lmao
vast shale
log(1) = 0
so the answer is a?
dusk python
|-1| = 1
vast shale
hmmm
someone told me a is wrong
like the answers you see are my only choices
but when i try to substitute the other numbers they work
im confused rn
@dusk python
vast shale
undefined? @dusk python
dusk python
yea, the same thing happens as when x = 1 because of the absolute value
dusk python
x = 1 and x = -1 are two different points
trim walrus
log(|x|) = 0
|x| = 1
x = 1,-1
vast shale
log(|x|) = 0
|x| = 1
x = 1,-1
oohh yea i get it now
so its technically one bec of the abs value
dusk python
no
trim walrus
ye but it's only when it's in abs values but before you put it it's different points...
vast shale
ok
dusk python
you know that the function is discontinuous when x = 1 and when x = -1
vast shale
yessir
trim walrus
dusk python
think about it as the number of different x values such that the function is discontinuous
vast shale
ok
trim walrus
Let's put it this is
Q) For how many x value the function is discontinuous?
We got x=1 and x=-1? for .... values of x the function is discontinuous
vast shale
Bruh take me to a mental hospital
so its 2
right?
2 points?
YEAAAAAAA
OMG
im sorry yal i have been studying for 7 hours
thank you sooo much
trim walrus
Well
trim walrus
What about x=0?? Log(0) is undefined so 1/log(0) is undefined...??
trim walrus
Alr
alpine tinsel
Can I get someone to look over my work? I've gotten so many answers that some of these questions are correct and that it's also not correct..? Hoping to get a clear answer of where I went wrong If I did. Please Keep In mind this is grade ten math and some of these formulas used were what I was taught so might be a little different. Thank you!!
vocal sleetBOT
Can I get someone to look over my work? I've gotten so many answers that some of...
vast shale
Can I get someone to look over my work? I've gotten so many answers that some of...
hr 10 righttt
regal slate
vast shale
omg its soh cah toaaaa
regal slate
so, third image, part 4
you can't remove values from set notation like that. For example: {1, 2, 3, 4} != {1, 4}
alpine tinsel
Ohh so I need to list the first and last numbers not list all of them..?
I know that's the normal way of doing it, but my instructor told us specifically to list every number. So idk.
regal slate
third image, part 3, incorrect interval notation
regal slate
I know that's the normal way of doing it, but my instructor told us specificall...
listing every number would be the correct way
alpine tinsel
Right, Didn't I do that?
Or do you mean erase the other one?
<@&286206848099549185>
karmic imp
<@&286206848099549185>
That's a lot for people to check over, do you have a specific one that you are stick/unsure about?
alpine tinsel
Yes question 1-3. and the last page mainly.
vocal sleetBOT
@alpine tinsel Has your question been resolved?
alpine tinsel
<@&286206848099549185>
vocal sleetBOT
@alpine tinsel Has your question been resolved?
alpine tinsel
<@&286206848099549185>
late panther
The first one seems right to me
In the 2 I think 330.7 should be the hypotenuse
Therefore you should use sin
In the 3rd a) as far as I know you are asked the angle with vertex in E and edges EB, EC instead of the one with vertex B and edges BE, BC
late panther
In the 3rd a) as far as I know you are asked the angle with vertex in E and edge...
EC is correct
alpine tinsel
In the 3rd a) as far as I know you are asked the angle with vertex in E and edge...
How do you know its asking for angle E instead of angle B for future refrence?
late panther
I was taught that way in math Olympiads and in euclidean geometry
alpine tinsel
Oh I see thank you! are there any other mistakes?
late panther
There is some more in five
Mainly if the domain of the function is {a,b} then X is not all the real numbers
Just if the domain is :
$(-\infty,\infty)$
You can say X is all real numbers
twin meteorBOT
x_dui_x
alpine tinsel
Oh I see so for question IV and ii i need to remove "all real numbers"
alpine tinsel
Oh ok that makes more sense.
late panther
This explains the angle nomenclature
The image is from this video: https://www.youtube.com/watch?v=AuizRpeJMhw, I have to say is just the first thing I found on google, I haven't seen this video myself, but I suppouse it would help
teal mason
vocal sleetBOT
rugged orchid
What have you tried
teal mason
Should I send it here ?
rugged orchid
Of course
teal mason
K
teal mason
.close
humble cypress
humble cypress
sup
paper depot
!onechannel
vocal sleetBOT
Please stick to your channel.
humble cypress
ok
sudden compass
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
dull mural
vocal sleetBOT
dull mural
i am very lost
i made the first eq a quadratic and got 2x-y=5, -1
now idk what to do
vocal sleetBOT
@dull mural Has your question been resolved?
woeful cloak
that's a good starting point, now just find y in terms of x for each cases and then substitute it into the second equation
vocal sleetBOT
@dull mural Has your question been resolved?
dull mural
that's a good starting point, now just find y in terms of x for each cases and t...
oh i didn't even think of that 💀 thanks
is that right
woeful cloak
,rotate
twin meteorBOT
woeful cloak
looks good, did not check for the solutions though. But everything is on track
though solution for first case looks a bit too nice
,w 3x^2-20x+28=0
twin meteorBOT
woeful cloak
I'm sure you can, wfa might be interested enough to provide a complex solution if it can
but if you want to specify, you could add "for complex x, y"
vocal sleetBOT
vocal sleetBOT
Available help channel!
wide rapids
how to do this
vocal sleetBOT
how to do this
wide rapids
glossy maple
honestly im not even sure if thats the right approach but whatever
wide rapids
[
\conj {a + ib} = a - ib \implies (a + ib)(a - ib) = a^2 + b^2 = \abs {a + ib}^2 ]
wow
ok
wtv
alright so eggnote
here is my
idea
vocal sleetBOT
wide rapids
....
vocal sleetBOT
Available help channel!
cerulean dagger
Can I please get some help? Thanks. How do I use similar triangles to prove part a). I have established the rate as dV/dT, but I am unsure where to go with the rest of the question
vocal sleetBOT
Can I please get some help? Thanks. How do I use similar triangles to prove part...
patent nymph
have you done (a)?
vocal sleetBOT
@cerulean dagger Has your question been resolved?
cerulean dagger
have you done (a)?
no
patent nymph
can you take a picture of your working
cerulean dagger
I haven't done much
I tried to make s = 6 and say when H = 0 s = 6
but it says to use similar triangles
patent nymph
s may not be 6
vocal sleetBOT
@cerulean dagger Has your question been resolved?
vocal sleetBOT
@cerulean dagger Has your question been resolved?
vocal sleetBOT
@cerulean dagger Has your question been resolved?
radiant plinth
You can get length of the edges on sides using pythagorean's theorem
Try to get the length of this pink line (part of altitude of pyramid's side) as a function of t
radiant plinth
Can I please get some help? Thanks. How do I use similar triangles to prove part...
Actually nevermind
I have established the rate as dV/dT,
Since you have this rate, calculate the volume of air in time T
(it's just V_all - V(T))
From that measure, since v = 1/3 AH, get A
If you respond I can give more detailed info
vocal sleetBOT
vocal sleetBOT
Available help channel!
wise tendon
Would p be the distance between the focus and vertex/Directrix and vertex?
wise tendon
.close
vocal sleetBOT
vocal sleetBOT
Available help channel!
rough anvil
Hi! sorry for the bother, which would be the right answer? since c is already mixed radical but a is the same thing but in a different form ?
vocal sleetBOT
Hi! sorry for the bother, which would be the right answer? since c is already mi...
rough anvil
square root of 4 is 2x√14
same thing as c
all answers give me the same number when I plug them into the calculator except for d so it can't be that one
worthy citrus
Is a a mixed radical
rough anvil
Is `a` a mixed radical
no it's two entire radicals
worthy citrus
So you know it can't be a
rough anvil
so we can cut off a and b?
worthy citrus
Yes
rough anvil
e is a fraction right
worthy citrus
It's a fraction sure, I don't know your specific definition of mixed radical so I don't know if that counts
worthy citrus
Again, it depends what your definition of mixed radical is
cerulean dagger
If you respond I can give more detailed info
which question is this for?
cerulean dagger
Actually nevermind
> I have established the rate as dV/dT,
Since you have this r...
A = 3v/H and S = sqrt 3v/H ??
rough anvil
Again, it depends what your definition of mixed radical is
I searched on google and this is what comes up for miixed radical
vocal sleetBOT
@rough anvil Has your question been resolved?
twin meteor
silk bridge
vocal sleetBOT
silk bridge
its either 4,1 -4,-1 or 6,7
but i dont think its 6,7 cause thats adding them
and idk if its from u to v or v to u
smoeone pleas help
<@&286206848099549185>
sly sierra
but i dont think its 6,7 cause thats adding them
what is the definition of resultant vector?
sly sierra
yep
sly sierra
cheers
silk bridge
.close
finite temple
370
finite temple
Don't quite understand the question
vocal sleetBOT
@finite temple Has your question been resolved?
finite temple
<@&286206848099549185>
flat whale
Don't quite understand the question
Can p be like 100 for the series to converge?
finite temple
?
finite temple
no
finite temple
ratio test?
finite temple
wdym in terms of p
flat whale
If you can do the ratio test with p=100, you can do it with variable p
finite temple
sry can u show me an example?
flat whale
ratio test?
Just do this again
Show your work for that
Then repeat it with p instead of 100
wherever you see 100, replace it with p
finite temple
Like this?
flat whale
No
flat whale
Like this?
How is that p=100
That's a_n
The ratio test can work, but there's an easier way
Just do the limit / divergence test
What's the limit as n goes to infinity of a_n?
flat whale
Wait a_n is where u sub the p
... what does this even mean
finite temple
I didn't rlly understood the problem sry
flat whale
Show your work for that
.
finite temple
?
finite temple
Did you or did you not find convergence/divergence for p=100
I didn't understand the problem so if u show me an example of this I would get it
flat whale
HOLY CRAP
half imp
@cobalt crypt
finite temple
yea I did
half imp
(ignore me)
finite temple
but not correct so thats y I need ur help
half imp
different snow sorry
shrewd dagger
yeah happens
finite temple
nw
cobalt crypt
<@118663865264242688>
moni Hu
flat whale
Just do the limit / divergence test
Go back to this and don't lie next time
finite temple
for the whole function?
I didn't lie? I did the ratio test but I don't think I did correctly
flat whale
I didn't lie? I did the ratio test but I don't think I did correctly
I asked you to show your work like 5 times. If you don't, how am I supposed to know you don't know what you're doing
If you keep pretending to know what you're doing, I can't help
finite temple
I did show my work
finite temple
Like this?
here
I didn't pretend I was just asking for help cuz I didn't get the question at the first place
flat whale
Instead of p=100
.
flat whale
ratio test?
You said it here
Then didn't show work after I asked multiple times
For p=100
flat whale
Go back to this and don't lie next time
.
finite temple
I didn't know how to do that for the first question u asked I know it's a no because of intuition
finite temple
I didn't say that
I said you can test using ratio test but idk if Im doing it correctly
so can u pls show me how to do it correctly
flat whale
...
Good luck whoever helps you next. I recommend not lying to them and pissing them off
glossy maple
@cobalt crypt
vocal sleetBOT
Available help channel!
steep musk
4i . 3j x 4k
vocal sleetBOT
4i . 3j x 4k
vocal sleetBOT
vocal sleetBOT
Available help channel!
civic drift
vocal sleetBOT
civic drift
How did they do that?
eager swan
taking reciprocal in an inequality should change the sign of equality right?
river minnow
It could help to consider each inequality separately
civic drift
taking reciprocal in an inequality should change the sign of equality right?
I'm sorry, i dont understand.
civic drift
It could help to consider each inequality separately
I tried that
I did get the inequality right but
Is there a rule for this
merry python
These are called results
$$\frac{1}{1}\le\frac{2-\sin3x}{1}$$
$$\frac{1}{2-\sin3x}\le1$$
$$\frac{2-\sin3x}{1}\le\frac{3}{1}$$
$$\frac{1}{3}\le\frac{1}{2-\sin3x}$$
$$\frac{1}{3}\le\frac{1}{2-\sin3x}\le1$$
twin meteorBOT
beard420
merry python
Note: The inequality sign does not change because (2-sin3x) is positive as per the conditions
civic drift
taking reciprocal in an inequality should change the sign of equality right?
Ahhh
I finally get what this means
Thank you all
.close
vast shale
Hello I've got a problem here:
So 28x-8x^2=7x-2x^2-21-6x
-6x^2+27x-21=0
D=(27)^2-4(-6)(-21)
D=225
(-27+sqrt(225))/(-6*2)=1
(-27-sqrt(225))/(-6*2)=3.5
x=1 v x=3.5
This is my answer however my answer sheet does not agree they say it is:
x=-1 v x= 3.5
Can anyone point out the mistake i made```second line should be +6x
hard atlas
interesting that this only results in one wrong sign
vast shale
Yes
hard atlas
next line should also have been a +21
vast shale
right
hard atlas
so I guess your mistakes somehow kind of cancel out