#help-17

1 messages · Page 46 of 1

vocal sleetBOT
elfin moon
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I thought it would be 1 but it is 4

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Because the limit doesn't exist

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Can anyone clear this doubt

keen umbra
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L Hopitals' rule

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🏥

elfin moon
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Read my doubt first

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@keen umbra

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|sinx|/x limit x tends to 0

outer warren
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consider the one sided limits

elfin moon
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Yes 1=-1

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.close

vocal sleetBOT
#
Channel closed

Closed by @elfin moon

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#
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lethal plank
#

we have integers x,y,z where 17x+5y-2z=0

vocal sleetBOT
#

Please don't occupy multiple help channels.

thin vale
lethal plank
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closed the other

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prove that A∈N

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and that A is a perfect square

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honestly hardcore 💀

lethal plank
thin vale
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do your natural numbers include 0?

lethal plank
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yeah

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but x/y cannot be 0

thin vale
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good

lethal plank
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so A cannot be 0

thin vale
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not true

lethal plank
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what?

thin vale
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y=-3 z=1 x=1. Then 17x+5y-2z=0. Then (3x+y)=0 then A=0

mild flower
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if x = z then A = 0

thin vale
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beat you

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and my example is better

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loser

mild flower
thin vale
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this is lies

lethal plank
thin vale
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HAH!

mild flower
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slander

lethal plank
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alr stop fighting

thin vale
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Sorry, Hayley gets like that sometimes. super distracting

worldly crow
mild flower
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i'm suing

lethal plank
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so I have to prove that (3x+y)(z-y)(2x+2y+z)(3y+3z-x)/210

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is a natural number

thin vale
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mhm

lethal plank
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and i have no idea how

thin vale
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use induction

urban edge
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I think you prove each one is a multiple of a diff factor of 210

lethal plank
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because if I break the parentheses

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it'd be a calculus longer than my forehead

thin vale
lethal plank
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210 aint a perfect square

thin vale
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twas sarcasm

lethal plank
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blud

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i'm trying to learn, sarcasm isn't helpful 💀

thin vale
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well the sarcasm was directed at garlic

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you were supposed to jump in

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like we did to Hayley

lethal plank
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once again i have no idea how to solve this

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it's also the last one

worldly crow
lethal plank
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💀

thin vale
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the real solution here is to get a longer forehead I think

lethal plank
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gotta go to walmart for that

thin vale
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well

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I have a tidbit

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your problem boils down to proving A is a perfect square

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because that implies that A is a natural number

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agreed?

lethal plank
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yep

thin vale
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so you must show that A=n^2 for some n in N

lethal plank
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yep

thin vale
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okay

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that's all I got

lethal plank
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210=2⋅3⋅5⋅7=2^1⋅3^1⋅5^1⋅7^1

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so uh

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maybe that helps

thin vale
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why did you prime factorize 210

lethal plank
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why not

thin vale
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fair

lethal plank
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i'm at my last resort

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doing everything

worldly crow
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You’re so close

lethal plank
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but also nothing

worldly crow
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I believe

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Forehead man

thin vale
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maybe we should apologize to garlic and hayley and beg them for their help again

thin vale
worldly crow
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It tickles my eyeballs

lethal plank
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@mild flower

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Dear Hayley,

I want to sincerely apologize from the depths of my heart for any hurt or pain I have caused you. My words or actions may have crossed boundaries, disregarded your feelings, or let you down in some way. I deeply regret my behavior and the impact it has had on you.

Please know that I take full responsibility for my actions and I understand the importance of acknowledging and learning from my mistakes. I am genuinely sorry for any distress I may have caused you, and I want you to know that it was never my intention to hurt you.

I value our relationship and the connection we share, and I truly hope that you can find it in your heart to forgive me. I am committed to making amends and working towards being a better person. Your happiness and well-being are important to me, and I will do everything in my power to ensure that I never repeat the same mistakes again.

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now help me finish this exercise please 🙏

mild flower
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what was the gpt prompt

lethal plank
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doesn't matter

paper depot
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well you still used GPT

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which is like

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toeing the line of rule-breaking

lethal plank
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NoOoO

thin vale
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not really, that rule is for math is it not?

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passing off GPT as your own math

mild flower
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Dear [Sender's Name],

Thank you for reaching out and expressing your sincere apology. I appreciate your willingness to take responsibility for your actions and acknowledge the hurt they may have caused me. It takes courage to admit when we have crossed boundaries and hurt someone we care about.

While I cannot deny the pain that I experienced, I believe in the power of forgiveness and personal growth. It's important for us to learn from our mistakes and strive to become better individuals. Your commitment to making amends and working towards personal improvement is commendable.

Forgiveness is a process, and it may take time for me to fully heal and rebuild trust. However, I want you to know that I value our relationship too, and I'm open to the possibility of moving forward. I hope that we can both learn from this experience and create a healthier, more respectful connection.

Let's communicate openly and honestly about our feelings and expectations moving forward. It's crucial for us to establish boundaries, address any concerns, and foster a supportive and understanding environment. Together, we can work towards building a stronger relationship based on trust, empathy, and mutual respect.

Thank you for your apology and your commitment to personal growth. I believe in the potential for positive change, and I hope that we can find a path towards healing and strengthening our connection.

Sincerely,
Hayley

lethal plank
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that's menacing

thin vale
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[Sender's name]

lethal plank
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slender's name

glad python
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Can we find x,y,z in terms of a common variable?

paper depot
glad python
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Using CRT?

thin vale
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critical race theory doesn't belong here

mild flower
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btw i have no idea how to do this problem

lethal plank
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sheesh

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let's go!

lethal plank
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i've got a geometry one

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if you wanna see that

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gave me brain damage

glad python
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yum geo

mild flower
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best guess is solve that 17 equation for [pick a variable] and then substitute it in and hope

glad python
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First let’s do this tho

glad python
lethal plank
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i'll think about it

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anyways, here's the other problem

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Let ABC be an acute-angled triangle with angle ACB = 50 and angle ABC = 70. The bisector of angle ACB intersects side AB at point D. The circumcircle of triangle ADC intersects side BC at distinct points C and E. The line parallel through B to line AE at intersects point F .Prove that FA=FB.

glad python
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Ok let me try it

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There’s nothing special about this problem. Just angle chasing

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Do you know properties of cyclic quads?

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@lethal plank

lethal plank
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yep

glad python
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Use them

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Mixed with transversals cutting parallel lines, we are done

lethal plank
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ill try

glad python
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the problem is the same as showing FBA=FAB (angles)

lethal plank
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i gotta prove that

glad python
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??

lethal plank
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like

glad python
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By definition it’s cyclic

lethal plank
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it's not in the ipothesis

glad python
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4 points lie on a cirvlhe?

lethal plank
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yes, but that's in the drawing

glad python
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“Circumcircle of ADC intersects BC at E”

lethal plank
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a

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ale

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alr

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thanks

glad python
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That means E lies on circle ADC

lethal plank
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yep

glad python
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Big hint: ||BAE=FBA so FBAC is cyclic|| @lethal plank

civic drift
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Hey maybe this might work too

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You could prove FARB is a rhombus

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By showing the triangles are congruent

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Since diagonals of a rhombus divide it into 4 congruent triangle

vocal sleetBOT
#

@lethal plank Has your question been resolved?

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vocal sleetBOT
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obtuse radish
#

latex banzai

vocal sleetBOT
obtuse radish
#

$\int_{0}^{\frac{\pi}{2}} \sqrt{(4sin(t)cos(t))^{2} + (3cos^{2}(t)sin(t))^{2} + (3sin^{2}(t)cos(t))^{2}} \delta t$

urban edge
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dt where

obtuse radish
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yep

urban edge
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You can factor some stuff out

twin meteorBOT
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shah821

obtuse radish
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umm and take into the parts formula?

urban edge
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Factors some stuff out first

obtuse radish
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also how do i distance that dt thing? it almost seems inside the root

urban edge
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It will work out really nicely

obtuse radish
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and use integration by parts but no end in sight

urban edge
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Show your work

verbal wing
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Guys can u spot the mistake in the question?

obtuse radish
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i kinda cut it all; what should i do abt the root tho?

vocal sleetBOT
urban edge
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You were right in factoring out the sin^2(t)cos^2(t)

obtuse radish
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ok wait my work is utterly wrong; i literally ignored the root

urban edge
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You get $\sqrt{sin^2(t)cos^2(t)} \times \sqrt{4^2+(3sin(t))^2+(3cos(t))^2}$

twin meteorBOT
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garlicbredfries

obtuse radish
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my god that too neat; i utterly ruined the factoring part

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mb

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thanks

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.close

vocal sleetBOT
#
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vocal sleetBOT
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tight isle
#

I need to ascertain whether $\mathbb{Z}_2\times\mathbb{Z}_2$ and $\mathbb{Z}_4$ are isomorphic but the question doesn't give the exact operation that defined on both of these groups. Given groups $(G,\ast)$ and $(H,\circ)$, the question defines the operation on the direct product of two groups $G\times H$ as $(g_1,h_1)(g_2,h_2)=(g_1\ast g_2,h_1\circ h_2)$. I got an idea for a bijective map $\phi:\mathbb{Z}_2\times\mathbb{Z}_2\rightarrow\mathbb{Z}_4$ defined $\phi((x,y))\coloneqq 2x+y$ but I need to know the exact operation of the individual groups to prove the map is homomorphic

tight isle
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apologies i miswrote the question hang on

twin meteorBOT
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bostock123

tight isle
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it says $\mathbb{Z}_n$ is the cyclic group of order $n$

twin meteorBOT
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bostock123

cyan talon
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Z_n is additive yes

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going from Z^n to Z_n lol

tight isle
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ha a bit silly

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why is it not multiplicative

cyan talon
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if you think about it for non-prime n, (Z_n, *) isn't even cyclic

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so the name would make no sense if the group was multiplicative

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or just by definition I guess

tight isle
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i see that makes sense

empty frigate
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...(Z_n, *) isn't even a group for any n > 1

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or at least not if you're counting 0 as being an element of Z_n

tight isle
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that's what i thought of

empty frigate
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what you can do is take the group of integers coprime to n with multiplication mod n as the operation

tight isle
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1 is the identity but 0 would have no inverse

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thanks for the help

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.close

vocal sleetBOT
#
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cyan talon
#

why did you close ?

vocal sleetBOT
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Channel closed

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cyan talon
#

@tight isle I mean we haven't even gotten to the heart of your question tbf

tight isle
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but my question was about the operation on the individual groups

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i've got the rest of it down, i think

cyan talon
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ah alright, I thought you wanted help for the whole thing

tight isle
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no no it's fine i need to do it myself

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thanks anyways

cyan talon
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btw they're not isomorphic

tight isle
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huh?

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i've got a bijective homomorphism tho

cyan talon
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you sure about that ?

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let's see

tight isle
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i'm confident about homomorphy

cyan talon
#

in another chan tho, cause you deleted your message again :/

tight isle
#

damn it

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sorry

vocal sleetBOT
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empty linden
#

how did this professor get the points for sin and cos?

empty linden
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theres no triangle to work with either so

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i cant use pythagorean property

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ive been stuck on this since yesterday

ornate ember
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directly plugging in t. For example y = cos(t), when t = 0, then cos(0) = 1. Similarly, y = sin(t), when t = 0, then sin(0) = 0.

cobalt stream
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these are commonly used

outer warren
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the values can be read off the unit circle

river minnow
#

Expected a professor not to know those?
Knowing those by heart usually is a result of happening to use them quite frequently

ornate ember
outer warren
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cos(t) gives the x coord on the unit circle at that angle
sin(t) gives the y coord on the unit circle at that angle

empty linden
#

howd they get the sqroot 3/2

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i only got that answer when a triangle was involved

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with a hyp of 1

river minnow
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And yeah the symmetry helps with memorisation, it's then narrowed down to knowing just 3-4 values if not less

outer warren
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as in you want to know how the values on the unit circle itself come from?

empty linden
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yeah, and how their values related to the graph to plot points

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should we first convert the radians to degrees, then find the sin of that degree?

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because pi/6 is 30 degrees

outer warren
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conversion doesn't matter

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its the same value

empty linden
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i got the decimal values for the fractions but

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idk how they got the fraction

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wait

outer warren
#

the exact values can be derived from special triangles

empty linden
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because i got those fractions when a triangle was involved

outer warren
#

but refer to the unit circle defintions of sine and cos

empty linden
#

with a hyp of 1

outer warren
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i mentioned above

empty linden
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OHHHH WAIT

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on the unit circle definitions

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the hypotenuse is 1

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so i can just do sin(theta) = opp/hyp

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then use pythag theorem to find the opposite

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i feel more comfortable working with degrees, so i convert pi/6 to 30 deg

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sin(30)^2 + x^2 = 1

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wait

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i feel like somethings wrong

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0.5^2 + x^2 = 1

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that looks better

empty linden
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instead of sqroot 3/2

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wait

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wait no something isnt right

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ok so i got 0.5 for sin 30

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should i convert that to fraction?

outer warren
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that would be ideal

empty linden
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yeah because i ended up getting sqroot 0.75 when i solved it with decimals

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ill make sure to convert to fractions right away

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the decimals can work but the fractions are more ideal

empty linden
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thats the value for cos(30)

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well, i think i kinda get it now

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thanks for the help

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ok so...

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i tried the same method with 11pi/12

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and my answer was way off

outer warren
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show work

empty linden
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i cant, im using a pc

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the most i can do is type it down

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11pi/12 = 165 degrees

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sin(165) = 0.25819045

outer warren
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their values for 11pi/12 are wrong btw

empty linden
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for some reason, my calculator couldnt convert it to a fraction

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so i just went with it as it is

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0.2581905^2 + x^2 = 1

outer warren
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it was probably a typo and they intended
11pi/6

empty linden
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x^2 = 1-0.2581905^2

empty linden
outer warren
#

there are ways to get exact values for sin(11pi/12), cos(11pi/12)
which involve stuff like compound angle / half angle identites which you probably aren't up to yet

empty linden
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and got 0.9695 to 4 decimal places

empty linden
empty linden
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im only at graphing special angles of sin and cos

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pre calc

outer warren
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sin(165°) is approx 0.2581905...

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cos(165°) is approx **-**0.9695
beware of signs (note that cos is negative in Q2)

empty linden
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so whyd i get the cosine value when i did sin(t)?

outer warren
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because you're not keeping track of what's what

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0.2581905^2 + x^2 = 1
how did you even obtain that value of 0.2581905

empty linden
outer warren
#

yeh exactly

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that's the value of sin(165°)...

empty linden
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thats all?

outer warren
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using y for the sine value
x is the cosine value

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and if you have access to the calculator...

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you could use to to calculate cos(165°) as well

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though it won't give you exact values here

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(unless you have a really good one)

empty linden
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i know chatgpt isnt the most reputable source but

outer warren
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BUT no

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i see chatgpt math, i stop reading

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and you should too

empty linden
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yeah it got many of my questions wrong haha

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anyways

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if i have the calculator, just plug in the values for t and thats all, right?

outer warren
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depends if you want and/or are expected to give exact values

empty linden
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but what if i dont have a calculator

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or rather

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the question said to not use it

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i should just assume that the value for sin(t) is actually cos(t)?

outer warren
#

if you have access to a unit circle, you can literally just read the common values off it
if you know quadrant 1 and properties / symmetry of the unit circle, you can derive values in other quadrants applying those
if you don't know Q1, those can be derived from special 30,60,90 and 45,45,90 triangles and the right triangle definitions of sine and cos

outer warren
#

if you tell a calc to calculate sin(whatever) that's what the calculator gives you

empty linden
#

wait

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i think i know why

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i know why i got to that conclusion

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i mustve used the pythag property by mistake

empty linden
outer warren
#

its applicable, you're just not keeping track of what your variables represent and reaching the wrong conclusions

empty linden
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and i plugged in the value of sin^2 to get cos

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and put cos as x^2

outer warren
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as mentioned earlier

empty linden
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mhm

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now that i think about it

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i really shouldve memorized the special angles

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ill do that right away

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i was going through the lecture video too quickly

vocal sleetBOT
#

@empty linden Has your question been resolved?

#
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gaunt apex
vocal sleetBOT
gaunt apex
#

i need some help with homogenous dimmensional analysis

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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digital wave
#

if x lies between [0, 2 pi], then find the number of solutions of the equation sin 2x = cos 3x

pallid zenith
#

wrong image

shrewd dagger
#

you could try sketching it

digital wave
digital wave
pallid zenith
#

this is just my thought

shrewd dagger
#

you know a few important points for cos and sin

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cos(0) = 1

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sin(0) = 0

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and so on

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the 2 and 3x multipliers just get you there a bit faster

digital wave
shrewd dagger
#

i would recommend so yes

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it gets a bit involved at the end but its not too bad

digital wave
#

alr

digital wave
twin meteorBOT
#

omniscientzenith

pallid zenith
#

yea

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youre gonna have domain problems with the inverse

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but simplifies it a lil

vocal sleetBOT
#

@digital wave Has your question been resolved?

vocal sleetBOT
#
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vast shale
vocal sleetBOT
vast shale
#

I am stuck

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
sterile trail
#

Where are you stuck @vast shale? Any work you have done so far?

karmic imp
#

Do you know how to isolate for a variable?

vast shale
#

not really

karmic imp
sterile trail
#

I also found some good advice for harder one! Might wanna look at them

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

#
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vast shale
# vast shale

Solution
3b - 5 = 7 (2-3b)
3b -5 = 14 - 21b
14 + 5 = 21b + 3b
19 = 24b
b = 19/24

lime gorge
#

hey man

#

@vast shale

vast shale
#

ya?

lime gorge
#

It’s not good to give solutions like that

vast shale
#

why?

lime gorge
#

It’s cuz it’s not conducive to peak learning

vast shale
#

oo

lime gorge
#

It’s okay I forgive you 👍

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
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sudden compass
#

Hey so we have a lottery which has P(Win)=25% and P(loss)=75%.
If I spin 9 times, what would be the number of wins apporximately? 9*0.25 right

sudden compass
#

eh nvm

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ah right thx

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dark sleet
vocal sleetBOT
dark sleet
#

I don't understand how he got 17.5, and 7.5

#

i have a slightly different version of this problem but if i can understand how he got that i can do the rest

#

i cant grasp what he did that resulted in 17.5

#

from the 100 plus minus 40 over 8

dense stump
#

what step are you confused on?

dark sleet
#

iirc im up to the same part as he is but i dont understand how he got 17.5 and 7.5

dense stump
dark sleet
#

i swear i checked it and it wasnt right

#

maybe im just tired

#

Ok I feel like an idiot now

#

I am definitely tired

#

thank u

vocal sleetBOT
#

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.closed

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north glacier
#

help

vocal sleetBOT
north glacier
#

i need help in solving a math problem

dreamy viper
north glacier
#

for these 2 problems

dreamy viper
#

make a sketch

north glacier
#

im confused if i should be using cosine or sine method to use it

#

do u know how to solve it

dreamy viper
#

i do, make a sketch and visualize it

north glacier
#

would it be like that?

dreamy viper
#

looks right

north glacier
#

and the other right angle would be automatically 90

dreamy viper
#

wdym other

#

its opp/adj trig ratio

north glacier
#

oooh ok

dreamy viper
#

wait

#

no

#

the 34 degree angle is in the other corner

#

cause its from the boat

#

and youre looking up at the base of the lighthouse

#

it would still be opp/adj though

north glacier
#

so the new sketch would be

dreamy viper
#

yeah

north glacier
#

34 C/ 150?

dreamy viper
#

other way around

#

opp/adj

north glacier
#

wait is it like

dreamy viper
#

what trig function is opp/adj

north glacier
#

tangent

dreamy viper
#

sohcahtoa

#

right

#

so tan(39) = opp/adj

#

plug in your opp and adj and solve for C as you denoted it

north glacier
#

so i get the tan(34) and then multiply is to 150

dreamy viper
#

adj=opp/tan34

north glacier
#

why is 150 on opposite side i thought adjacent was on this side

mild flower
#

adjacent / opposite depend on which angle you're talking about

#

,tex .sohcahtoa

twin meteorBOT
#

Hayley

dreamy viper
#

^

north glacier
#

ooh ok ok thank u

#

i interchanged them

#

is this one also about ratios

dreamy viper
#

37 degrees from the y axis?

#

im assuming 90 degrees would also be 0?

#

or no

north glacier
#

they didnt really specify

#

i found a solution online

#

and they subtracted 37-45

#

= -8

#

and added 360

#

i dont really get why they added 360 tho

mild flower
#

they added 360 because negative headings aren't a thing

mild flower
dreamy viper
#

ah

north glacier
#

ooh ok

vocal sleetBOT
#

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north glacier
#

yes thank u

vocal sleetBOT
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north glacier
#

hello i need help again hjhfd

vocal sleetBOT
north glacier
#

what does ms-1 mean

next sleet
north glacier
#

so it just means meters per second right?

next sleet
#

yes

north glacier
#

ooh thanks

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idle yoke
#

why is it xln(x) and not xln(2) ??

vocal sleetBOT
viral copper
#

Should be xln 2

idle yoke
#

can i send link to the vid?

#

🤩 Hello everyone, I'm very excited to bring you a new channel (SyberMath Shorts).
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▶ Play video
#

6:30

#

is it a mistake then?

#

is nvm he then rewrite it

#

thanks

#

.close

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unique musk
vocal sleetBOT
unique musk
#

can anyone help me@with these two i’m really bad at questions like this

merry python
#

what have you tried?

unique musk
#

i’ve tried imaging them into three separate triangles to find the similar sides but it just isn’t working for me

#

n i always get confused about which leg matches up with what

calm light
#

try using angles to prove similarity

unique musk
#

for the first one idk how to solve it cus

#

ik the hypotenuse of the biggest triangle is 15

merry python
unique musk
#

huh

#

the three from the little triangle has no corresponding side length we know in the bigger triangle

unique musk
#

so i lost

#

i’m

calm light
#

alright so take the 2nd picture and label all the right angles

#

then pick any of the remaining angles and assign it the variable x

merry python
#

this may help

#

place the two triangles (for eg: ADB and DBC) in such a way that their x angle would coincide when superposed and same with the angle (90-x)

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#

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marble kettle
#

I need help with 4 I found my answer but it has multiple values

marble kettle
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vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
#

@vast shale Has your question been resolved?

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@vast shale Has your question been resolved?

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real gale
vocal sleetBOT
real gale
#

||A||=10 and ||B||=8

#

I don't know how to proceed

paper depot
#

$\nrm{\mathrm{proj}_B(A)} = 5$

#

find A·B from this

#

fuck i mixed them up sorry

twin meteorBOT
paper depot
#

edit not coming through fsr

#

oh there it goes

real gale
#

$\norm{proj_{B}(A)}=\norm{\frac{A^T B}{A^T A}} = \abs{\frac{1}{A^T A}} \norm{A^T B} = 5$

twin meteorBOT
real gale
#

@paper depot Is that correct?

paper depot
#

A^T B / A^T A is a scalar

#

this scalar times B is proj_B(A)

real gale
#

Ah yes

#

A·B = 40

paper depot
#

that now looks more sensible.

real gale
#

I think I can get to the answer now

#

||proj_{A}(B)|| = 4

#

.close

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bleak prawn
vocal sleetBOT
bleak prawn
#

Not really sure what to do here

flat whale
bleak prawn
#

Normally I would just divide all of the terms by x and then get the answer that way, but the numerator already has -5/x so I dont really know if thats the correct way to do it?

#

I thought that they were both y=0, so I tried that but only the first one was correct

flat whale
# flat whale

do you see the horizontal and vertical asymptotes here

bleak prawn
#

Ye I see them

flat whale
#

oh

bleak prawn
#

I tried to solve without looking at the graph

flat whale
#

the function isn't even defined at negative values of x

#

so i don't understand the question

bleak prawn
#

Like just solving it with the maths to make sure I understand it

flat whale
#

last sentence

bleak prawn
#

But how do you know that its none sry?

bleak prawn
#

I see now haha

#

Okok makes sense

#

Thats all I wanted to ask thank you!

#

❤️

#

.close

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floral crow
#

im not sure where to start

vocal sleetBOT
hushed pewter
glossy maple
#

you mean f(f(x)) = x

#

first try to simplify the expression f(f(x))

#

plugging 2/(x-k) - 1 into the function as the input

#

then equate that to x

hushed pewter
glossy maple
#

👍

floral crow
#

thanks :)

#

.close

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granite wing
#

snlsmsmsmsmla

vocal sleetBOT
granite wing
#

hiya

terse forum
#

Turkish catKing

granite wing
granite wing
terse forum
#

I can't understand your handwriting

#

Also I have forgotten this

granite wing
#

i suppose other people might have difficulty as well then

#

i'll write again

#

on my pc

#

here we go

#

so i'll explain my thought process

#

since dividing by 12 means

#

wait-

#

it doesn't divide 12...

#

oke oke so the last digit should be one more...

worthy citrus
#

3A4B are just the digits of a number?

granite wing
#

yep

#

tho i got it nevermind

#

wait it's not right??

#

i got 17+1 = 18

#

but the answer is 9

worthy citrus
#

How could one of them be 17

#

They have to be from 0 to 9

granite wing
#

the question asks a+b

#

if it divides 12 then it has to divide 3 and 4

#

dividing by 3 means
3+a+4+b= 3k

#

and by 4 means:
4b=4k

granite wing
#

and if b=8,
15+a=3k

#

a can be 9

#

so 3948

#

a=9,b=8 a+b= 9+8 = 17

#

but since its one more (see the division)

#

should be 18

#

well that's what i thought

vocal sleetBOT
#

@granite wing Has your question been resolved?

granite wing
#

<@&286206848099549185>

vocal sleetBOT
#

@granite wing Has your question been resolved?

vocal sleetBOT
#

@granite wing Has your question been resolved?

granite wing
#

no botty no

#

<@&286206848099549185>

#

at least tell me if you're getting the same answer guys anyone?

#

just look at this:

#

QUESTION:

#

And my trial:

topaz sparrow
#

Is this prove right
Ques: σ(p^m) = 1 + p * σ(p^(m−1))
Ans: 1 + p*(p^(m-1)) = 1+p^m

vocal sleetBOT
#

@granite wing Has your question been resolved?

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iron flax
vocal sleetBOT
iron flax
#

help me solve please

waxen harness
#

try to do some algebra with janet's solution and check if it s the same with antonio's

vocal sleetBOT
#

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mossy mantle
#

can someone explain this please

vocal sleetBOT
mossy mantle
#

im not sure by its explaination

austere storm
#

ok

#

e^ infinity will grow infinitely fast than

#

inifnity squared

ornate ember
#

Basically, it has to do with scale as n gets bigger and bigger. When I was learning this I would consider "which one of these are growing faster"? e^n grows so much faster than n^2 that as it increases to infinity, it diverges.

As an example, let's use n = 100 in their example.
e^100 = 2.69 x 10^43 and (100)^2 = 10000. It grows sooooo much faster that it doesn't converge

austere storm
#

because power is more powerful than a regular nubmer getting squared

#

raising something to infinity will go faster than squaring infiity

#

think of an exponential graph

#

and then think of a quadratic

#

exponential grows faster

mossy mantle
#

so infinity is correct because anything greater or equal to 1 its positive and it allows it to "grow fast"

#

1 is not entirely correct but can be used instead of 100?

ornate ember
#

well you have to be careful there

#

with the limit going to infinity, we're looking at "end behavior"

mossy mantle
ornate ember
#

for example, consider which one grows faster: x^2 or x^10?

If you were to check values from 0 < x < 1, then x^2 would be larger than values of x^10, but for x > 1, that behavior changes.

austere storm
#

you're plugging in infinity for the limit

ornate ember
#

so basically the explanation they gave they were using 100 as an example

austere storm
#

so just plug in infinity

#

and u gotta know what grows faster than what

mossy mantle
#

oh okay

#

thank you guys for your explanations :)

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#

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pastel swan
#

Open.

vocal sleetBOT
pastel swan
cyan shadow
regal bane
#

You also need to know approximately where that root is. Huh.

sly sierra
#

well first, do you know how to see if it has a real root?

pastel swan
regal bane
#

Oh lol nvm it's not so bad. Remember that you can plug a root into the equation.

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sly sierra
#

i cannot confirm that

waxen harness
#

converges absolutely means that abs(an) converges for the LHS and it means that abs((-1)^n*an) converges for the RHS, but abs((-1)^n an)=abs(an)

covert salmon
#

oh

#

So the second series only converges conditionally?

#

so it is false?

sly sierra
#

what do you get if you take the absolute values of the terms in each series?

covert salmon
#

the same series

waxen harness
#

so it s just asking you "If abs(an) converges , then abs(an) converges"

covert salmon
#

oh

#

so it would be true then ofc?

#

ye ty!

#

.close

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vast shale
#

Help

vocal sleetBOT
vast shale
#

How do i do the right side?

#

For the tablev

#

?

#

Please hellppp

lyric fossil
#

@thin vale

cobalt imp
#

if the right side is square root x-4 you would just substitute values for x and solve

#

so for example 4-4=0

#

then square root 0 = 0

lyric fossil
#

what 21 savage is suggesting is that you pick values for x and plug them into sqrt(x-4)

lyric fossil
#

preferably

vast shale
#

So like it must be 4, 9, 16

#

Cuz 2x2 3x3

lyric fossil
#

where did 12 come from

#

also what you want to be a perfect square is the thing under the square root

vast shale
#

16myb

lyric fossil
#

ok let me ask a different question, do you know what the graph of sqrt(x-4) - 2 looks like

vast shale
#

No

vast shale
#

We haven’t learned something like that yet

#

We just using the table like this to graph

tulip forge
# vast shale

ok so
when x = 0
fill in the equation with x being 0

#

so its 0 on the right side after solving

#

or when x=1
fill in ur equation replacing x with 1

#

them solve

vast shale
vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

thin vale
thin vale
#

A few people have already offered help to you

#

either be more clear in what your issue is, or stop pressing the ❌

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You want to graph this?

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get a few points

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and then connect them

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$$\sqrt{x-4}-2=0$$

twin meteorBOT
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austinu

thin vale
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I think it wants you to compare the graphs of $$y=\sqrt{x-4}$$ and $$y=2$$

twin meteorBOT
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austinu

thin vale
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you should very easily be able to graph y=2. It is a horizontal line

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Now, to graph the top equation, you know that nothing under a square root can be negative, so x must be greater than or equal to 4

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start with x=4 and grab a few points. When x=4, you get y=0, and then can plot the point (4, 0)

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now grab some more points

brittle minnow
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@vast shale are you even there?

thin vale
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try ones that will make the thing under the square root easy to evaluate

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I recommend that you next try x=8

thin vale
vocal sleetBOT
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Channel closed

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brittle minnow
thin vale
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2 to go

brittle minnow
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let's goooooo

vocal sleetBOT
#
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lost swift
vocal sleetBOT
molten rain
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wait what

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allow me

vast shale
vast shale
lost swift
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I need help with part (i) not sure how to diffentiate it

vast shale
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It was like 1:20am

molten rain
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allow me

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how to differenciate a product rule do u know?

lost swift
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yep

molten rain
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yes

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u= 2x

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v= e^(2x)

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differentciate the power

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the power remains the same

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put the differenciated power infront

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dv/dx = 2e^(2x)

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u do

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then send me

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ill check

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🦅

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product rule is

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u x dv/dx + v x du/dx

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x is times here

lost swift
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cool-

merry python
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<@&268886789983436800>

molten rain
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thanks

lost swift
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.close

vocal sleetBOT
#
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verbal merlin
vocal sleetBOT
verbal merlin
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bernoulli

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im stuck at this

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@vast shale

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btw its wrong qn

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its dis one

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homogenuous?

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dk how to spell

vocal sleetBOT
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@verbal merlin Has your question been resolved?

verbal merlin
#

.close

vocal sleetBOT
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glad mirage
vocal sleetBOT
glad mirage
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should i do the of first

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or division first

hasty pulsar
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,rotate

twin meteorBOT
royal kestrel
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its better to just go left to right since division and multiplication have the same level of priority

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but your answer will still be the same

glad mirage
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k ty

vocal sleetBOT
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@glad mirage Has your question been resolved?

vocal sleetBOT
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marsh coyote
vocal sleetBOT
marsh coyote
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5.4.7, the highlighted text, the x<=y+\epsilon is abit strange right since

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If x=y+\epsilon for some \epsilon, then the hypothesis wouldn't hold anymore

lyric fossil
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yes, but it’s for all epsilon

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so you can pick a smaller epsilon and it should still be true

wraith venture
wraith venture
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If you take the exercise and replace <= by < (in the epsilon part), show it doesn't change anything (i.e. the 2 hypotheses are equivalent)

marsh coyote
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Oh thought you mean

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Use exercise 6

wraith venture
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Yes

wraith venture
marsh coyote
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But then wouldn't it be better to just leave the exercise x<y+epsilon for all epsilon?

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Since the x=y+epsilon doesn't do anything

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I understand the result will still hold eitherway

wraith venture
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Yes. It doesn't matter.

marsh coyote
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Oh wait that's what you mean by hypothesis ar equivalent

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Ah okay got it thanks

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.close

vocal sleetBOT
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Channel closed

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marsh coyote
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.reopen

vocal sleetBOT
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marsh coyote
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Wait just to confirm, this will mean that the statements x<=y+epsilon for all epsilon, and x<y+epsilon for all epsilon are exactly the same for all scenarios?

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So:
x<=y+epsilon for all epsilon iff x<y+epsilon for all epsilon

wraith venture
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Yes

marsh coyote
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Ok thanks again

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.close

vocal sleetBOT
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vocal sleetBOT
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trail shoal
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help finding a please

vocal sleetBOT
mild flower
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are you sure that should be f ' (0) = -1/sqrt3?

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and not f (0)?

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to me this looks like an initial value problem

vocal sleetBOT
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@trail shoal Has your question been resolved?

trail shoal
#

.close

vocal sleetBOT
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spark cloak
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Question is a simplifiable rationale expression with 2 restrictions

spark cloak
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i did $\frac{x^2+4x+4}{x^2-81}$

twin meteorBOT
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deviousglxy

spark cloak
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it turned out that it is not simplifiable

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so what equation can be simplifialbe with 2 restrictions?

ruby vapor
vocal sleetBOT
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@spark cloak Has your question been resolved?

spark cloak
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that works

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Thanks

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.close

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.close

vocal sleetBOT
#
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vocal sleetBOT
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still anvil
#

Find 𝑑𝑦/𝑑𝑥 in terms of 𝑥 and 𝑦 if 3𝑥𝑦+4𝑥+𝑦=13

vocal sleetBOT
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
still anvil
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so originally i tried taking derivative of left side and right side so i did product rule to split 3xy and got everything down to ( ((3)(y)+(3x)(y')) + 4 + y') = 0 then i got rlly confused and im questioning if i approached it correctly

lime gorge
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Yes keep going

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ur fine

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$3y + 3xy’ + 4 + y’ = 0$

twin meteorBOT
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northsteve

still anvil
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idk what to do about the two y' since the 3x is being multiplied to y'

cyan shadow
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factor it out!

still anvil
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o snap

lime gorge
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First get all the terms with a y’ on one side and all the others on the other side

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Then proceed with what bunny said

still anvil
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alright

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@lime gorge y'(3x+1)=-3y-4 ?

cyan shadow
still anvil
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div by 3x+1

cyan shadow
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sure do

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that is indeed your answer

still anvil
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alr i got it thank you guys

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.close

vocal sleetBOT
#
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steady prawn
vocal sleetBOT
steady prawn
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Also this question is very complicated I think

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IDK

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Read it all first though plz

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Also the phsyics thing was for a diffrent discord server

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Thats why I said physics which still was math but also science and you know

flat whale
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can you ask ONE math question?

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stars and black holes have nothing to do with how infinity is defined

terse forum
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ngl I feel this is a physics problem

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cool pfp and name btw

steady prawn
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Yeah I'll explain more in a second

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Well basically the summary is that I think that ∞ should be able to be added, subtracted or whatever other things you could use and Hilbert's hotel paradox because I believe that if you add 1 to ∞ or in the paradox's case if you add 1 to a ∞ long hotel that's fully occupied you would just have to move all the guest one room over but I think that while they say it's still infinity it could be because the mind can't comprehend it and despite being well ∞ there's still more to it that you can add technically but it would still just be counted as ∞ and for the quasi stars it's just that a fraction of infinity could be possible even in the real world because we still don't know the rules of infinity and quasi-stars is a black hole with a star becoming a black hole but the black hole in the star is pushing back which should be infinitely forceful I guess you could say because of newtons and all that jazz but its only in power and since everything travels at the speed of light it took less long to create a black hole in the middle of the star then on the outside since the star would have to fully collapse in on itself to do so. that means also that the quasi-star is in a way semi-infinitely forceful like 0.5*∞. and black holes are negatively infintely forceful or powerful however you wanna describe it in the amount of newtons that gets pushed outwards. white holes have to do with this because there like black holes but opposite where they create things and one of the theories is that the create things that black holes destroy so they could be positively infitely powerful and that about sums it up.

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NGL this definintly is a phsyics problem hes right.

flat whale
steady prawn
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ok

vocal sleetBOT
#

@steady prawn Has your question been resolved?

vocal sleetBOT
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vast shale
vocal sleetBOT
vast shale
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I chose the x intercept to be 1,0 and the asymptote to be 2

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And then y approaching 2 as well

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But im confused on how to continue

rugged orchid
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what about the rest

vast shale
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likeee how would i do the y approching 2 part?

rugged orchid
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how is it possible for a function to have both a vertical asymptote and only 1 x intercept whilst being odd or even

vast shale
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RIGHT

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the questions is legit so confusing

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that's why im so stuck on what to do

rugged orchid
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it sounds impossible

vast shale
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it doess

rugged orchid
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you need it to either be odd or even

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which means either f(-x) = f(x) or f(-x) = -f(x)

vast shale
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i can cancel the odd or even part and explain that its impossible?

vast shale
rugged orchid
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do you know what i mean by it's impossible

vast shale
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that the graph wont work out?

regal slate
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how about a rational function with x-intercept at 0,0

rugged orchid
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the roots of this function should be symmetric

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but so should the asymptotes

vast shale
rugged orchid
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but you only have 1 of each

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which means they must be at the origin

vast shale
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yea

regal slate
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hmm

rugged orchid
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but then you cant have an asymptote on the same point as an x-intercept

vast shale
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yea, theres that too