#help-17
1 messages · Page 46 of 1
I thought it would be 1 but it is 4
Because the limit doesn't exist
Can anyone clear this doubt
consider the one sided limits
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we have integers x,y,z where 17x+5y-2z=0
Please don't occupy multiple help channels.

closed the other
prove that A∈N
and that A is a perfect square
honestly hardcore 💀
got any idea on this one?
do your natural numbers include 0?
good
so A cannot be 0
not true
what?
y=-3 z=1 x=1. Then 17x+5y-2z=0. Then (3x+y)=0 then A=0
if x = z then A = 0
nu uh
yu uh
HAH!
slander
alr stop fighting
Sorry, Hayley gets like that sometimes. super distracting
i'm suing
mhm
and i have no idea how
use induction
I think you prove each one is a multiple of a diff factor of 210
yes, the perfect square 210
210 aint a perfect square
twas sarcasm
well the sarcasm was directed at garlic
you were supposed to jump in
like we did to Hayley
How long is your forehead??
💀
the real solution here is to get a longer forehead I think
gotta go to walmart for that
well
I have a tidbit
your problem boils down to proving A is a perfect square
because that implies that A is a natural number
agreed?
yep
so you must show that A=n^2 for some n in N
yep
why did you prime factorize 210
why not
fair
You’re so close
but also nothing
maybe we should apologize to garlic and hayley and beg them for their help again
this hurts my eyes
It tickles my eyeballs
@mild flower
Dear Hayley,
I want to sincerely apologize from the depths of my heart for any hurt or pain I have caused you. My words or actions may have crossed boundaries, disregarded your feelings, or let you down in some way. I deeply regret my behavior and the impact it has had on you.
Please know that I take full responsibility for my actions and I understand the importance of acknowledging and learning from my mistakes. I am genuinely sorry for any distress I may have caused you, and I want you to know that it was never my intention to hurt you.
I value our relationship and the connection we share, and I truly hope that you can find it in your heart to forgive me. I am committed to making amends and working towards being a better person. Your happiness and well-being are important to me, and I will do everything in my power to ensure that I never repeat the same mistakes again.
now help me finish this exercise please 🙏
what was the gpt prompt
doesn't matter
NoOoO
Dear [Sender's Name],
Thank you for reaching out and expressing your sincere apology. I appreciate your willingness to take responsibility for your actions and acknowledge the hurt they may have caused me. It takes courage to admit when we have crossed boundaries and hurt someone we care about.
While I cannot deny the pain that I experienced, I believe in the power of forgiveness and personal growth. It's important for us to learn from our mistakes and strive to become better individuals. Your commitment to making amends and working towards personal improvement is commendable.
Forgiveness is a process, and it may take time for me to fully heal and rebuild trust. However, I want you to know that I value our relationship too, and I'm open to the possibility of moving forward. I hope that we can both learn from this experience and create a healthier, more respectful connection.
Let's communicate openly and honestly about our feelings and expectations moving forward. It's crucial for us to establish boundaries, address any concerns, and foster a supportive and understanding environment. Together, we can work towards building a stronger relationship based on trust, empathy, and mutual respect.
Thank you for your apology and your commitment to personal growth. I believe in the potential for positive change, and I hope that we can find a path towards healing and strengthening our connection.
Sincerely,
Hayley
that's menacing

[Sender's name]
slender's name
Can we find x,y,z in terms of a common variable?
i think it's also not very kosher to pass off gpt-written apologies as your own
Using CRT?
critical race theory doesn't belong here
btw i have no idea how to do this problem
same
yum geo
best guess is solve that 17 equation for [pick a variable] and then substitute it in and hope
First let’s do this tho
What I was thinking, maybe it will reveal some symmetry
i'll think about it
anyways, here's the other problem
Let ABC be an acute-angled triangle with angle ACB = 50 and angle ABC = 70. The bisector of angle ACB intersects side AB at point D. The circumcircle of triangle ADC intersects side BC at distinct points C and E. The line parallel through B to line AE at intersects point F .Prove that FA=FB.
Ok let me try it
There’s nothing special about this problem. Just angle chasing
Do you know properties of cyclic quads?
@lethal plank
yep
ill try
the problem is the same as showing FBA=FAB (angles)
the thing is that we don't know that ADEC is a cyclic quad
i gotta prove that
??
like
By definition it’s cyclic
it's not in the ipothesis
4 points lie on a cirvlhe?
yes, but that's in the drawing
“Circumcircle of ADC intersects BC at E”
That means E lies on circle ADC
yep
Big hint: ||BAE=FBA so FBAC is cyclic|| @lethal plank
Hey maybe this might work too
You could prove FARB is a rhombus
By showing the triangles are congruent
Since diagonals of a rhombus divide it into 4 congruent triangle
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latex banzai
$\int_{0}^{\frac{\pi}{2}} \sqrt{(4sin(t)cos(t))^{2} + (3cos^{2}(t)sin(t))^{2} + (3sin^{2}(t)cos(t))^{2}} \delta t$
dt where
yep
You can factor some stuff out
shah821
umm and take into the parts formula?
Factors some stuff out first
also how do i distance that dt thing? it almost seems inside the root
It will work out really nicely
i tried that once sin^2(t)cos^2(t) then out of the root
and use integration by parts but no end in sight
Show your work
i kinda cut it all; what should i do abt the root tho?
Please read #❓how-to-get-help
You were right in factoring out the sin^2(t)cos^2(t)
ok wait my work is utterly wrong; i literally ignored the root
You get $\sqrt{sin^2(t)cos^2(t)} \times \sqrt{4^2+(3sin(t))^2+(3cos(t))^2}$
garlicbredfries
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I need to ascertain whether $\mathbb{Z}_2\times\mathbb{Z}_2$ and $\mathbb{Z}_4$ are isomorphic but the question doesn't give the exact operation that defined on both of these groups. Given groups $(G,\ast)$ and $(H,\circ)$, the question defines the operation on the direct product of two groups $G\times H$ as $(g_1,h_1)(g_2,h_2)=(g_1\ast g_2,h_1\circ h_2)$. I got an idea for a bijective map $\phi:\mathbb{Z}_2\times\mathbb{Z}_2\rightarrow\mathbb{Z}_4$ defined $\phi((x,y))\coloneqq 2x+y$ but I need to know the exact operation of the individual groups to prove the map is homomorphic
apologies i miswrote the question hang on
bostock123
it says $\mathbb{Z}_n$ is the cyclic group of order $n$
bostock123
if you think about it for non-prime n, (Z_n, *) isn't even cyclic
so the name would make no sense if the group was multiplicative
or just by definition I guess
i see that makes sense
...(Z_n, *) isn't even a group for any n > 1
or at least not if you're counting 0 as being an element of Z_n
that's what i thought of
what you can do is take the group of integers coprime to n with multiplication mod n as the operation
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Closed due to the original message being deleted
@tight isle I mean we haven't even gotten to the heart of your question tbf
but my question was about the operation on the individual groups
i've got the rest of it down, i think
ah alright, I thought you wanted help for the whole thing
btw they're not isomorphic
i'm confident about homomorphy
in another chan tho, cause you deleted your message again :/
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how did this professor get the points for sin and cos?
theres no triangle to work with either so
i cant use pythagorean property
ive been stuck on this since yesterday
directly plugging in t. For example y = cos(t), when t = 0, then cos(0) = 1. Similarly, y = sin(t), when t = 0, then sin(0) = 0.
these are commonly used
the values can be read off the unit circle
Expected a professor not to know those?
Knowing those by heart usually is a result of happening to use them quite frequently
On top of that they're using known identities found in the unit circle on the top right:
cos(t) gives the x coord on the unit circle at that angle
sin(t) gives the y coord on the unit circle at that angle
yeah but
howd they get the sqroot 3/2
i only got that answer when a triangle was involved
with a hyp of 1
And yeah the symmetry helps with memorisation, it's then narrowed down to knowing just 3-4 values if not less
as in you want to know how the values on the unit circle itself come from?
yeah, and how their values related to the graph to plot points
should we first convert the radians to degrees, then find the sin of that degree?
because pi/6 is 30 degrees
i got the decimal values for the fractions but
idk how they got the fraction
wait
the exact values can be derived from special triangles
yeah but i was confused since there was no triangle
because i got those fractions when a triangle was involved
but refer to the unit circle defintions of sine and cos
with a hyp of 1
i mentioned above
OHHHH WAIT
on the unit circle definitions
the hypotenuse is 1
so i can just do sin(theta) = opp/hyp
then use pythag theorem to find the opposite
i feel more comfortable working with degrees, so i convert pi/6 to 30 deg
sin(30)^2 + x^2 = 1
wait
i feel like somethings wrong
0.5^2 + x^2 = 1
that looks better
ok so now i figured out how to get the values but
instead of sqroot 3/2
wait
wait no something isnt right
ok so i got 0.5 for sin 30
should i convert that to fraction?
that would be ideal
yeah because i ended up getting sqroot 0.75 when i solved it with decimals
ill make sure to convert to fractions right away
the decimals can work but the fractions are more ideal
since 0.75 for sin(30) is incorrect
thats the value for cos(30)
well, i think i kinda get it now
thanks for the help
ok so...
i tried the same method with 11pi/12
and my answer was way off
show work
i cant, im using a pc
the most i can do is type it down
11pi/12 = 165 degrees
sin(165) = 0.25819045
their values for 11pi/12 are wrong btw
for some reason, my calculator couldnt convert it to a fraction
so i just went with it as it is
0.2581905^2 + x^2 = 1
it was probably a typo and they intended
11pi/6
x^2 = 1-0.2581905^2
i see
then i squarerooted it
there are ways to get exact values for sin(11pi/12), cos(11pi/12)
which involve stuff like compound angle / half angle identites which you probably aren't up to yet
and got 0.9695 to 4 decimal places
but i feel like this is the value for cos(t) and not sin(t)
not up to that part yet
im only at graphing special angles of sin and cos
pre calc
sin(165°) is approx 0.2581905...
cos(165°) is approx **-**0.9695
beware of signs (note that cos is negative in Q2)
wait a minute
so whyd i get the cosine value when i did sin(t)?
because you're not keeping track of what's what
0.2581905^2 + x^2 = 1
how did you even obtain that value of0.2581905
i did sin(165) on the calculator
thats all?
using y for the sine value
x is the cosine value
and if you have access to the calculator...
you could use to to calculate cos(165°) as well
though it won't give you exact values here
(unless you have a really good one)
i know chatgpt isnt the most reputable source but
yeah it got many of my questions wrong haha
anyways
if i have the calculator, just plug in the values for t and thats all, right?
depends if you want and/or are expected to give exact values
but what if i dont have a calculator
or rather
the question said to not use it
i should just assume that the value for sin(t) is actually cos(t)?
if you have access to a unit circle, you can literally just read the common values off it
if you know quadrant 1 and properties / symmetry of the unit circle, you can derive values in other quadrants applying those
if you don't know Q1, those can be derived from special 30,60,90 and 45,45,90 triangles and the right triangle definitions of sine and cos
sin(t) is sin(t),
cos(t) is cos(t)
if you tell a calc to calculate sin(whatever) that's what the calculator gives you
ait
wait
i think i know why
i know why i got to that conclusion
i mustve used the pythag property by mistake
this is basiclly saying sin^2 + cos^2 = 1
its applicable, you're just not keeping track of what your variables represent and reaching the wrong conclusions
yeah
as mentioned earlier
mhm
now that i think about it
i really shouldve memorized the special angles
ill do that right away
i was going through the lecture video too quickly
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if x lies between [0, 2 pi], then find the number of solutions of the equation sin 2x = cos 3x
maybe you can use a phase shift identity?
wrong image
you could try sketching it
i dunno that identity
that's what i tried.
i got 2x lies between [0, 4 pi]
and 3x lies between [0, 6 pi]
yes, but this is just the domain
you know a few important points for cos and sin
cos(0) = 1
sin(0) = 0
and so on
the 2 and 3x multipliers just get you there a bit faster
should i draw their individual graphs and get their intersection points?
alr
u mean like, $cos 3x = cos(\frac{\pi}{2} - 2x)$ ?
omniscientzenith
@digital wave Has your question been resolved?
alr tq
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I am stuck
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Where are you stuck @vast shale? Any work you have done so far?
im on step 1
^
Do you know how to isolate for a variable?
not really
I suggest watching something like https://www.youtube.com/watch?v=fDMxOiS5g7k&ab_channel=MikeDeVor
Solving basic linear equations with variables on both sides of the equation.
I also found some good advice for harder one! Might wanna look at them
sure
@vast shale Has your question been resolved?
@vast shale Has your question been resolved?
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Solution
3b - 5 = 7 (2-3b)
3b -5 = 14 - 21b
14 + 5 = 21b + 3b
19 = 24b
b = 19/24
ya?
It’s not good to give solutions like that
why?
It’s cuz it’s not conducive to peak learning
oo
It’s okay I forgive you 👍
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
@vast shale Has your question been resolved?
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Hey so we have a lottery which has P(Win)=25% and P(loss)=75%.
If I spin 9 times, what would be the number of wins apporximately? 9*0.25 right
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I don't understand how he got 17.5, and 7.5
i have a slightly different version of this problem but if i can understand how he got that i can do the rest
i cant grasp what he did that resulted in 17.5
from the 100 plus minus 40 over 8
what step are you confused on?
iirc im up to the same part as he is but i dont understand how he got 17.5 and 7.5
well you just explained it lol..
i swear i checked it and it wasnt right
maybe im just tired
Ok I feel like an idiot now
I am definitely tired
thank u
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help
i need help in solving a math problem

make a sketch
im confused if i should be using cosine or sine method to use it
do u know how to solve it
i do, make a sketch and visualize it
looks right
and the other right angle would be automatically 90
oooh ok
wait
no
the 34 degree angle is in the other corner
cause its from the boat
and youre looking up at the base of the lighthouse
it would still be opp/adj though
yeah
34 C/ 150?
wait is it like
what trig function is opp/adj
tangent
sohcahtoa
right
so tan(39) = opp/adj
plug in your opp and adj and solve for C as you denoted it
so i get the tan(34) and then multiply is to 150
adj=opp/tan34
Hayley
^
they didnt really specify
i found a solution online
and they subtracted 37-45
= -8
and added 360
i dont really get why they added 360 tho
they added 360 because negative headings aren't a thing
the way headings work is that north = 0° = 360° and it goes clockwise, so east is 90°
ah
ooh ok
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yes thank u
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hello i need help again hjhfd
they meant ms^-1=m/s=meters per second
so it just means meters per second right?
yes
ooh thanks
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why is it xln(x) and not xln(2) ??
Should be xln 2
can i send link to the vid?
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Subsc...
6:30
is it a mistake then?
is nvm he then rewrite it
thanks
.close
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can anyone help me@with these two i’m really bad at questions like this
what have you tried?
i’ve tried imaging them into three separate triangles to find the similar sides but it just isn’t working for me
n i always get confused about which leg matches up with what
try using angles to prove similarity
for the first one idk how to solve it cus
ik the hypotenuse of the biggest triangle is 15
To get the correct similarity let one angle be x and find rest of angles in terms of x
huh
the three from the little triangle has no corresponding side length we know in the bigger triangle
or better show your work
alright so take the 2nd picture and label all the right angles
then pick any of the remaining angles and assign it the variable x
this may help
place the two triangles (for eg: ADB and DBC) in such a way that their x angle would coincide when superposed and same with the angle (90-x)
@unique musk Has your question been resolved?
yeah thanks bro i did what u said earlier and i figured it out
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I need help with 4 I found my answer but it has multiple values
@marble kettle Has your question been resolved?
.close
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What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
@vast shale Has your question been resolved?
@vast shale Has your question been resolved?
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Ann

$\norm{proj_{B}(A)}=\norm{\frac{A^T B}{A^T A}} = \abs{\frac{1}{A^T A}} \norm{A^T B} = 5$
@paper depot Is that correct?
that now looks more sensible.
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Not really sure what to do here
Normally I would just divide all of the terms by x and then get the answer that way, but the numerator already has -5/x so I dont really know if thats the correct way to do it?
I thought that they were both y=0, so I tried that but only the first one was correct
do you see the horizontal and vertical asymptotes here
Ye I see them
oh
I tried to solve without looking at the graph
the function isn't even defined at negative values of x
so i don't understand the question
Like just solving it with the maths to make sure I understand it
last sentence
But how do you know that its none sry?
Ohhh
I see now haha
Okok makes sense
Thats all I wanted to ask thank you!
❤️
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im not sure where to start
find a k such that f(f(x))=1 for every x
you mean f(f(x)) = x
first try to simplify the expression f(f(x))
plugging 2/(x-k) - 1 into the function as the input
then equate that to x
Oops right. Thanks
👍
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snlsmsmsmsmla
hiya
Turkish 
oop
tell me if you'd translate differently
oh
i suppose other people might have difficulty as well then
i'll write again
on my pc
here we go
so i'll explain my thought process
since dividing by 12 means
wait-
it doesn't divide 12...
oke oke so the last digit should be one more...
3A4B are just the digits of a number?
yep
tho i got it nevermind
wait it's not right??
i got 17+1 = 18
but the answer is 9
not one of them a+b
the question asks a+b
if it divides 12 then it has to divide 3 and 4
dividing by 3 means
3+a+4+b= 3k
and by 4 means:
4b=4k
with this k=b=0,4,8
and if b=8,
15+a=3k
a can be 9
so 3948
a=9,b=8 a+b= 9+8 = 17
but since its one more (see the division)
should be 18
well that's what i thought
@granite wing Has your question been resolved?
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@granite wing Has your question been resolved?
@granite wing Has your question been resolved?
no botty no
<@&286206848099549185>
at least tell me if you're getting the same answer guys anyone?
just look at this:
QUESTION:
And my trial:
Is this prove right
Ques: σ(p^m) = 1 + p * σ(p^(m−1))
Ans: 1 + p*(p^(m-1)) = 1+p^m
!help
Please read #❓how-to-get-help
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help me solve please
try to do some algebra with janet's solution and check if it s the same with antonio's
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can someone explain this please
Basically, it has to do with scale as n gets bigger and bigger. When I was learning this I would consider "which one of these are growing faster"? e^n grows so much faster than n^2 that as it increases to infinity, it diverges.
As an example, let's use n = 100 in their example.
e^100 = 2.69 x 10^43 and (100)^2 = 10000. It grows sooooo much faster that it doesn't converge
because power is more powerful than a regular nubmer getting squared
raising something to infinity will go faster than squaring infiity
think of an exponential graph
and then think of a quadratic
exponential grows faster
so infinity is correct because anything greater or equal to 1 its positive and it allows it to "grow fast"
1 is not entirely correct but can be used instead of 100?
well you have to be careful there
with the limit going to infinity, we're looking at "end behavior"
right? becasue of 0 < |r|<1 ?
for example, consider which one grows faster: x^2 or x^10?
If you were to check values from 0 < x < 1, then x^2 would be larger than values of x^10, but for x > 1, that behavior changes.
you're plugging in infinity for the limit
so basically the explanation they gave they were using 100 as an example
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Open.
Do you know how to determine if a quadratic has a (edit: real) root?
You also need to know approximately where that root is. Huh.
well first, do you know how to see if it has a real root?
Yes. Discriminant must be greater or equal zero.
Oh lol nvm it's not so bad. Remember that you can plug a root into the equation.
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i cannot confirm that
converges absolutely means that abs(an) converges for the LHS and it means that abs((-1)^n*an) converges for the RHS, but abs((-1)^n an)=abs(an)
what do you get if you take the absolute values of the terms in each series?
the same series
so it s just asking you "If abs(an) converges , then abs(an) converges"
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Help
@thin vale
if the right side is square root x-4 you would just substitute values for x and solve
so for example 4-4=0
then square root 0 = 0
what 21 savage is suggesting is that you pick values for x and plug them into sqrt(x-4)
Need to perfect square right?
preferably
where did 12 come from
also what you want to be a perfect square is the thing under the square root
16myb
ok let me ask a different question, do you know what the graph of sqrt(x-4) - 2 looks like
No
No
We haven’t learned something like that yet
We just using the table like this to graph
ok so
when x = 0
fill in the equation with x being 0
so its 0 on the right side after solving
or when x=1
fill in ur equation replacing x with 1
them solve
are u able to write it on a paper so its more clear?
@vast shale Has your question been resolved?
@vast shale Has your question been resolved?
@vast shale Has your question been resolved?
A few people have already offered help to you
either be more clear in what your issue is, or stop pressing the ❌
You want to graph this?
get a few points
and then connect them
$$\sqrt{x-4}-2=0$$
austinu
I think it wants you to compare the graphs of $$y=\sqrt{x-4}$$ and $$y=2$$
austinu
you should very easily be able to graph y=2. It is a horizontal line
Now, to graph the top equation, you know that nothing under a square root can be negative, so x must be greater than or equal to 4
start with x=4 and grab a few points. When x=4, you get y=0, and then can plot the point (4, 0)
now grab some more points
@vast shale are you even there?
try ones that will make the thing under the square root easy to evaluate
I recommend that you next try x=8
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2 to go
let's goooooo
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How do u even grab more points?
I went to sleep bro
I need help with part (i) not sure how to diffentiate it
It was like 1:20am
yep
yes
u= 2x
v= e^(2x)
differentciate the power
the power remains the same
put the differenciated power infront
dv/dx = 2e^(2x)
u do
then send me
ill check
🦅
product rule is
u x dv/dx + v x du/dx
x is times here
cool-
<@&268886789983436800>
thanks
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bernoulli
im stuck at this
@vast shale
btw its wrong qn
its dis one
homogenuous?
dk how to spell
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,rotate
it doesnt matter
its better to just go left to right since division and multiplication have the same level of priority
but your answer will still be the same
k ty
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5.4.7, the highlighted text, the x<=y+\epsilon is abit strange right since
If x=y+\epsilon for some \epsilon, then the hypothesis wouldn't hold anymore
yes, but it’s for all epsilon
so you can pick a smaller epsilon and it should still be true
Pre-exercise: prove the result doesn't change if you make the inequality strict
Could you elaborate abit
If you take the exercise and replace <= by < (in the epsilon part), show it doesn't change anything (i.e. the 2 hypotheses are equivalent)
If x=y+\epsilon, then wouldn't a smaller epsilon make the hypothesis false since x>y+\epsilon/2 for e.g.
Oh thought you mean
Use exercise 6
Yes
Then epsilon/2 shows it's an impossible case
But then wouldn't it be better to just leave the exercise x<y+epsilon for all epsilon?
Since the x=y+epsilon doesn't do anything
I understand the result will still hold eitherway
Yes. It doesn't matter.
Oh wait that's what you mean by hypothesis ar equivalent
Ah okay got it thanks
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✅
Wait just to confirm, this will mean that the statements x<=y+epsilon for all epsilon, and x<y+epsilon for all epsilon are exactly the same for all scenarios?
So:
x<=y+epsilon for all epsilon iff x<y+epsilon for all epsilon
Yes
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help finding a please
are you sure that should be f ' (0) = -1/sqrt3?
and not f (0)?
to me this looks like an initial value problem
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Question is a simplifiable rationale expression with 2 restrictions
i did $\frac{x^2+4x+4}{x^2-81}$
deviousglxy
it turned out that it is not simplifiable
so what equation can be simplifialbe with 2 restrictions?
Do you mean an equation with two "holes" in it? Basically so you have two things that cancel from the equation. You can construct one if you do something like: (x+1)(x+2)(x+3)/[(x+2)(x+3)]. x can't equal -2 or -3 but the equation can be simplified to x+1.
@spark cloak Has your question been resolved?
ya
that works
Thanks
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Find 𝑑𝑦/𝑑𝑥 in terms of 𝑥 and 𝑦 if 3𝑥𝑦+4𝑥+𝑦=13
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
so originally i tried taking derivative of left side and right side so i did product rule to split 3xy and got everything down to ( ((3)(y)+(3x)(y')) + 4 + y') = 0 then i got rlly confused and im questioning if i approached it correctly
northsteve
idk what to do about the two y' since the 3x is being multiplied to y'
factor it out!
o snap
First get all the terms with a y’ on one side and all the others on the other side
Then proceed with what bunny said
now how do you get the y' by itself?
div by 3x+1
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Also this question is very complicated I think
IDK
Read it all first though plz
Also the phsyics thing was for a diffrent discord server
Thats why I said physics which still was math but also science and you know
this is a lot of words
can you ask ONE math question?
stars and black holes have nothing to do with how infinity is defined
Yeah I'll explain more in a second
Well basically the summary is that I think that ∞ should be able to be added, subtracted or whatever other things you could use and Hilbert's hotel paradox because I believe that if you add 1 to ∞ or in the paradox's case if you add 1 to a ∞ long hotel that's fully occupied you would just have to move all the guest one room over but I think that while they say it's still infinity it could be because the mind can't comprehend it and despite being well ∞ there's still more to it that you can add technically but it would still just be counted as ∞ and for the quasi stars it's just that a fraction of infinity could be possible even in the real world because we still don't know the rules of infinity and quasi-stars is a black hole with a star becoming a black hole but the black hole in the star is pushing back which should be infinitely forceful I guess you could say because of newtons and all that jazz but its only in power and since everything travels at the speed of light it took less long to create a black hole in the middle of the star then on the outside since the star would have to fully collapse in on itself to do so. that means also that the quasi-star is in a way semi-infinitely forceful like 0.5*∞. and black holes are negatively infintely forceful or powerful however you wanna describe it in the amount of newtons that gets pushed outwards. white holes have to do with this because there like black holes but opposite where they create things and one of the theories is that the create things that black holes destroy so they could be positively infitely powerful and that about sums it up.
NGL this definintly is a phsyics problem hes right.
great go to #old-network for physics server
ok
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I chose the x intercept to be 1,0 and the asymptote to be 2
And then y approaching 2 as well
But im confused on how to continue
what about the rest
likeee how would i do the y approching 2 part?
how is it possible for a function to have both a vertical asymptote and only 1 x intercept whilst being odd or even

it sounds impossible
it doess
you need it to either be odd or even
which means either f(-x) = f(x) or f(-x) = -f(x)
i can cancel the odd or even part and explain that its impossible?
soo f(1) = -f(1), for the 5th point?
do you know what i mean by it's impossible
that the graph wont work out?
how about a rational function with x-intercept at 0,0
hmm how would that work?
yea
hmm
but then you cant have an asymptote on the same point as an x-intercept
yea, theres that too
