#help-17

1 messages · Page 35 of 1

mild flower
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so can you solve for the missing one?

old schooner
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how lol

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I'm so lost im sorry lol

mild flower
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okay, start with that equation

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and put in the values you know (C, c, b)

old schooner
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k

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¯¯¯¯¯¯¯¯¯¯¯¯
769230
sin
(
C
)

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0.769?

mild flower
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are you asking if that's angle B?

old schooner
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yes

mild flower
#

that's not what I get

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let me fill in the values for you

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$\frac{\sin(0.71)}{1.912} = \frac{\sin B}{2.7}$

twin meteorBOT
#

kitten.in.a.teacup

mild flower
#

so now we can solve for sin(B)

old schooner
#

0.34091724

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would that be it?

mild flower
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uh, no - what did you do?

old schooner
#

i did sin(0.71)/1.912

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and got

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that

mild flower
#

okay, so now you have this:

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$0.3409 = \frac{\sin B}{2.7}$

twin meteorBOT
#

kitten.in.a.teacup

old schooner
#

yes

mild flower
#

now can you solve for sin B?

old schooner
#

1.16929816

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?

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that it

mild flower
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yeah, that's what I get, okay so that's sin B, now let's get rid of the sin

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so we have:

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$\cancel{\sin B = 1.1693}$

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wait no you already did that didn't you

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because I get that sin(B) = 0.9204, and B = 1.17 rad

old schooner
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this is what I have so far

mild flower
#

yeah great okay, so that's angle B

old schooner
#

would I input 1.17

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or 1.1693

mild flower
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idk, does it say how many decimal points to use? It gave you angle C in 2 decimal places so you could use that shrug

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can you do the same thing to solve angle A? I can write out the equation for you if you want

old schooner
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yes plz

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can you write the equation

mild flower
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$\frac{\sin A}{1.3} = \frac{\sin(0.71)}{1.912}$

twin meteorBOT
#

kitten.in.a.teacup

mild flower
#

Do you see where I'm pulling those numbers from?

old schooner
#

yes

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0.45915681

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that it

mild flower
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yeah

old schooner
#

thats A

mild flower
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yeah

old schooner
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heres what I have

mild flower
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what's a DNE?

old schooner
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does not exist

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idk what D is

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i kind of have to submit something since im running out of time

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so DNE it is

pearl lynx
#

Hey guys, I've been stuck on this problem for quite some time. It falls under Linear Algebra, specifically Finding the Cross Product for vectors

mild flower
pearl lynx
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Here is my work

old schooner
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thx though

pearl lynx
vocal sleetBOT
#

@old schooner Has your question been resolved?

vocal sleetBOT
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median sun
#

A wire is wound on the cylinder x^2 + y^2 = 4 with initial point (2,0,0), so that the height z of each point of the wire is a linear function of the angle t of winding up to the point. Suppose that in one revolution the wire reaches a height of 2pi. Calculate the mass of the first turn of the wire, if at each point the linear mass density is equal to the height z of point

I find the parametric equation, but, I don't know how to find the density function

vocal sleetBOT
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@median sun Has your question been resolved?

median sun
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crisp python
#

Hello.

vocal sleetBOT
ornate ember
#

howdy what's your question?

crisp python
#

How does problem 15 turn into cos15cos135-sin15cos135?

ornate ember
#

that looks like a trig identity: $cos(a + b) = cos(a)cos(b) - sin(a)sin(b)$

twin meteorBOT
#

MellowDramaLlama

ornate ember
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so what would our a and b be here?

mild flower
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but yes that trig identity is useful for solving it

crisp python
#

Are there other trig identities I should know?

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I'm just now learning about them.

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Nvm, found the sheet in class.

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Thanks.

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alpine crown
#

hi i need help

vocal sleetBOT
patent nymph
alpine crown
#

idk how to solve this

patent nymph
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where are the numbers

alpine crown
patent nymph
alpine crown
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cause in number 1 the measurement of angle A is missing and angle B

patent nymph
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oh

alpine crown
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yeah

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can you help me?

patent nymph
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is there something else above?

alpine crown
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no😔😔

patent nymph
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Are you reading a Word document on mobile?

alpine crown
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yeah my teacher sent this and told us that we have to answer and didnt give any examples

patent nymph
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can’t believe I guessed right, you’re really reading a word document on mobile?

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try with computer

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the spacing gets messed up sometimes on mobile

alpine crown
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oh really let me try

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how bout this?

alpine crown
alpine crown
patent nymph
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or use sine rule and cosine rule

alpine crown
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okay thank you sm🤍🤍

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flint charm
vocal sleetBOT
flint charm
#

why is this the case

rugged orchid
#

Raise a to the power of both sides

flint charm
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then what do i do next

merry python
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a^(log_a b)=b

rugged orchid
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Then you use $a^{\log_a{b}}=b$

twin meteorBOT
#

frosst

flint charm
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cool thanks

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btw love taylor as wel

rugged orchid
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Me too

flint charm
#

listening to all too well 10 min rn

rugged orchid
#

A masterpiece I tell you

flint charm
#

love your profile

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alright thanks man for the help

#

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north glacier
#

Can someone help me

vocal sleetBOT
north glacier
#

Study for a math test

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Its mostly about physics i think i can send the handbook

midnight cape
#

Thats not what u ask here 💀😂😂 only for problems here bro

vocal sleetBOT
#

@north glacier Has your question been resolved?

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vast shale
#

Let $d$ be the distance function defined on $\mathbb{R}^n$ by the correspondence $d(x,y) = \max_{1\leq i \leq n} {d_i(x_i,y_i)}$ for $x = (x_1,x_2,\hdots,x_n),y=(y_1,y_2,\hdots,y_n)\in \mathbb{R}^n,$ let $d'$ be the euclidean distance function $d'(x,y) = \sqrt{\sum_{i=1}^n(x_i-y_i)^2}$, and let $d''$ be the distance function $d''(x,y) = \sum_{i=1}^n |x_i-y_i|.$ Then, for each pair of points $x,y \in \mathbb{R}^n$, $$d(x,y) \leq d'(x,y) \leq \sqrt{n} * d(x,y).$$
That is, $$\max_{1\leq i \leq n} {d_i(x_i,y_i)} \leq \sqrt{\sum_{i=1}^n(x_i-y_i)^2} \leq \sqrt{n}*\max_{1\leq i \leq n} {d_i(x_i,y_i)}.$$
My question is, how can the max distance $d$ be leq than the euclidean distance if it is defined to be the maximum of the distances?

twin meteorBOT
#

deimos the wizard

brisk moss
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are you asking about this inequality?

vast shale
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I am

brisk moss
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the thing on the right is like

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sqrt(max{d_i(x_i,y_i)}^2 + other stuff)

vast shale
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oh wait true, the maximum distance only spits out the one result that is greater than the others whereas the actual euclidean distance is that and all the other stuff

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okay I think I kind of had that in the back of my head but you saying it made it click

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alright imma close this if that's cool

brisk moss
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sure haha

vast shale
#

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zealous wren
vocal sleetBOT
violet prawn
#

Are you trying to solve for area

zealous wren
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Yeah

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Ik how to integrate

violet prawn
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Do you know how to integrate along the y-axis

zealous wren
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But idk how to find the intersected coordinate

violet prawn
#

Ohh

zealous wren
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Do i need to find the y or x

violet prawn
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Just y

merry python
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y^2=5x
2y=-x
Set both y values equal

violet prawn
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If youre integrating along y

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Multiply the second equation by -5 so they both equal 5x

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That way you can set them equal to each other and solve

zealous wren
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The fiest equation will have surd though

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First

violet prawn
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?

zealous wren
violet prawn
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y² = 5x
2y * -5 = 5x
Y² = -10y

violet prawn
zealous wren
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Can i just let one y on the other side

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On both equation

violet prawn
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Yes but then you would have to solve for two variables

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And wouldn't potentially get all negative answers

zealous wren
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I get x=0 though

violet prawn
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You need to have two pts

violet prawn
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Since you're integrating along the y axis

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Unless you want to integrate along the x-axis, both work but y is easier given these equations

vocal sleetBOT
#

@zealous wren Has your question been resolved?

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vast shale
#

How can I prove that $(x_i-y_i)^2 \leq \max_{1\leq i\leq n} \left{\sum_{i=1}^n (x_i-y_i)\right}$ for all $1 \leq i \leq n$?

brisk moss
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that expression on the right doesn’t parse?

vast shale
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o u right

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holup

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really it's just the euclidean metric inside the maximum squared, hence just the sum part

brisk moss
#

that looks worse

vast shale
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oh shit

brisk moss
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max 1 <= i <= 1?

twin meteorBOT
#

deimos the wizard

vast shale
#

does it make sense to square the maximum?

brisk moss
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i don’t get the “for all 1 <= i <= n” part

vast shale
#

as a note, this is still the earlier problem about the metric inequality, $d$ is the maximum as defined #help-17 message here, I asked the question on stack exchange and had the comment: "(x_i-y_i)² \leq d(x,y)^2" for all 1 \leq i \leq n

twin meteorBOT
#

deimos the wizard
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vast shale
#

which is somehow supposed to help

rugged orchid
#

Bot doesn’t like # :/

vast shale
#

ah it's cool, I think it would be okay if someone just helped me understand how the euclidean distance is less than or equal to the maximum of the euclidean distance times the square root of n

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in R^n

brisk moss
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there are n things being summed

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each of them is less than or equal to the max

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so sum((x_i - y_i)^2) <= n*max(x_i - y_i)^2

vast shale
brisk moss
#

sorry, less than or equal to

brisk moss
vast shale
#

okay that gives me something to ponder

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Imma close the channel again if that's cool

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will come back again if I get stuck on the third part too

brisk moss
#

sure lol

vast shale
#

.close

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vast shale
#

I am stuck on how to find convert the rectangular coordinates (4,-3) into polar coordinates.

jolly epoch
#

ok hi

vast shale
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I used the formula (x^2)+(y^2) = (r^2)

jolly epoch
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you can find the magnitude by doing root(4^2 + (-3)^2)

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this is your ‘r’ value

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to find theta, you can do tan^-1(y/x) = tan^-1(-3/4)

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then you should get 5cis(arctan(-3/4))

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@vast shale

jagged gorge
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cis lol

jolly epoch
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cis 😍

vast shale
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Alright got it. Thank you!

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vast shale
#

.reopen

vocal sleetBOT
#

vast shale
#

I am a bit stuck on how to solve this problem

rose kiln
#

How are polar coordinates and cartesian coordinates related?

vast shale
#

The Cartesian coordinates are general coordinates on what points the graphs passes?

wary flame
#

$$\left{\begin{aligned}
r&=\sqrt{xy}\
\theta&=\tan\left(\frac ab\right)
\end{aligned}\right.$$

twin meteorBOT
#

Hokkaydo

rose kiln
#

Probably easier to just notice $$x=r\cos \theta , y = r\sin \theta$$

twin meteorBOT
#

rcatalang

vast shale
#

Got it

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rich cargo
#

Propositional Logic question:
Knowing that p -> q = ~p v q, prove that p -> ~q = ~(p ^ q) = ~p v ~q.

What I tried:
First, I saw a solution to the following problem in a website that goes like this:

Problem: knowing that p -> q = ~p v q, prove that ~p -> q = p v q
Their solution:
p -> q = ~p v q
just replace, in p -> q = ~p v q, the proposition p by its negation. Look:
(~p) -> q = ~(~p) v q
~p -> q = p v q

Now, for the problem I want help to solve it:

We want to prove that p -> ~q = ~(p ^ q) = ~p v ~q
p -> q = ~p v q
replacing the proposition q by its negation:
p -> (~q) = **~**p v ~q
p -> ~q = ~p v ~q

So using the same method I didn't prove correctly what the question told me to, since p -> ~q is not equal to p ^ q. How can I solve it?

vocal sleetBOT
#

@rich cargo Has your question been resolved?

rich cargo
#

<@&286206848099549185>

lyric fossil
#

how does p and not q = not p or q

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@rich cargo

rich cargo
#

Using De Morgan's property in p and not q, we get:
~(p ^ ~q) = ~p v q

lyric fossil
#

right, the question is not posed correctly

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read your first 2 lines again

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p ^ -q does not equal -p v q

rich cargo
#

what I meant there was that p -> q = p ^ ~q, and p -> q = ~p v q, sorry about that

lyric fossil
#

well again, p -> q is not equal to p ^ -q

rich cargo
#

Ohh, that's true, ~(p -> q) = p ^ ~q. I'll edit the question where I made this mistake

lyric fossil
#

also the first line of your proof is wrong

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p -> q is not equal to -(p ^ q)

rich cargo
#

is it correct now?

lyric fossil
#

looks fine

rich cargo
#

Ok, so from p -> ~q = ~p v ~q I can use Morgan's property and find that
~p v ~q = ~(p ^ q)?

lyric fossil
#

yes

rich cargo
#

thank u very much

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fr

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dusky flax
#

So apparently I messed up so bad that I got the answer right. Can someone pls explain how to actually do the problem?

dusky flax
#

Like correctly

cerulean harbor
#

use $\tan(x)=\f{\sin(x)}{\cos(x)}$ and then use the unit circle to find what sin and cos are

twin meteorBOT
#

duhhello

errant briar
#

Looks correct. Figure may be wrong

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neat hearth
#

Is there any simple method of solving indices

formal pond
#

u got an example??

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median sun
#

If I have this definition of the floor function, is correct to say that the definition of the ceiling function is f(t) := { n if n-1 < t <= n, for n belongs to naturals numbers}?

paper depot
#

integers, not just naturals

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and n-1 ≤ t < n

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the ceil of any integer is that integer itself still

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ah uh

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shit no you're riht

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right*

median sun
#

okay okay, thank you <3

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median sun
#

Hi can someone please explain what happens, how the (1-e^-s)/s appears?

silk kindle
#

Factor out e^(-ns)

median sun
#

Yes, I already understand what happens, thank you

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wide rapids
vocal sleetBOT
wide rapids
#

is this right

#

i think so

vocal sleetBOT
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@wide rapids Has your question been resolved?

mild flower
#

did 600 somehow turn into 60?

wide rapids
mild flower
#

otherwise yeah it's right (and you can get an actual value out of it)

wide rapids
#

yeh special angle

#

ty

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wide rapids
vocal sleetBOT
wide rapids
#

is this correct

#

is 4 correct too cause i think they both are

vast shale
# wide rapids

sorry but i honestly have no clue what is happening here

#

what is the thing on the right?

wide rapids
#

the radius

river minnow
#

r^2 then no?

wide rapids
river minnow
#

Either way

wide rapids
#

toby def has a crush on me

river minnow
#

Should be 2xy/sqrt(x^2 + y^2)

wide rapids
#

bean are u trolling

#

(x^2 + y^2)^2

#

squared

#

is (x^2 + y^2)

desert hornet
#

????

mild flower
#

true if it's 1

river minnow
#

(x^2 + y^2)^2 squared is x^2 + y^2?

wide rapids
#

cause its r^2

#

(x^2 + y^2)^2 is r^2?

river minnow
#

No

#

Like I said

wide rapids
river minnow
#

x^2 + y^2 = r^2

wide rapids
#

the r^2 here is (x^2+y^2)^2?

#

no?

river minnow
#

Here yeah

#

But it still means 2xy will get divided by the root

#

Whatever you name x^2 + y^2

wide rapids
#

if r^2 here is (x^2+y^2)^2

#

then r

#

is

#

(x^2+y^2)

river minnow
# wide rapids

What do you get after dividing both sides by x^2 + y^2?

wide rapids
#

lhs is some weird stuff?

river minnow
#

Whatever it is, you'll have (2xy)^2/(x^2 + y^2), right?

wide rapids
#

from the picture

river minnow
#

Just say x^2 + y^2 = r^2

#

Instead of how you defined r

wide rapids
#

x^2+y^2=(x^2+y^2)^2

#

is this correct

river minnow
#

Not in general

wide rapids
#

like in here

river minnow
#

Let x = 1 and y = 1

wide rapids
#

ok

river minnow
wide rapids
#

BEAN< just where i went wrong

#

why fail

#

why failo

river minnow
wide rapids
#

i calculated x^2+y^2 in this context

#

and my answer was

#

(x^2+y^2)^2

#

so now why dont i square root it

river minnow
#

How are you getting (x^2 + y^2)^2?

#

Oh

#

Why did you cross the ^2 ??

#

In the end

#

Yeah you are right

wide rapids
#

AHHH

#

BEAN BRO

#

WUT

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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median sun
#

.close

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chilly rampart
#

Can someone check if both those questions are right

vocal sleetBOT
#
Channel closed

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chilly rampart
#

5 and 6

empty frigate
#

this channel is closed, you need to get a new one

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worthy citrus
#

no

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wary flame
#

Hello
I'm reading this proof of the Riesz theorem but I don't understand some things

  • Why do we set x_l as the product of the complex conjugate of l(hat x) and hat x
  • What are those l(x)/l(hat x) popping out of nowhere ?
wary flame
flat whale
#

they worked backwards

#

that's a pretty standard proof in riesz represesentation

wary flame
#

yey i know but i don't understand the proof at all :x

worthy citrus
#

you want the conjugate because it looks like your inner product is conjugate linear in the first slot

#

when you pull l(x^hat) into the first slot of the inner product you pick up a conjugate, motivating the choice of x_l

flat whale
flat whale
wary flame
#

when you pull l(x^hat) into the first slot of the inner product you pick up a conjugate
what is the reason of that ? (probably stupid question but i feel dumb)

flat whale
#

do you know the definition of inner product

worthy citrus
#

the definition of your inner product

#

or atleast an immediate consequence of it

wary flame
#

oh wait

#

i never used the inner product in complex space so didnt know that <x,y>= conjugate of <y,x>

#

in my head it just was <x,y>=<y,x> :o

flat whale
#

you should probably do some inner product calculations on complex numbers

#

like <1 + i, 3>

wary flame
#

never tried indeed

flat whale
#

if you haven't, i recommend taking complex analysis before functional analysis

wary flame
#

i got already but surpringly i didnt come to my mind

#

idk how i never had to use that property

#

.close

vocal sleetBOT
#
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iron flame
flat whale
iron flame
flat whale
#

do you know what implicit_diff does when you give it both x, y arguments at the end

iron flame
#

yeah x is the dependent, y is the independent

#

oh wait i fixed it

#

okay it was just some weird glitch with the -xy there

#

.close

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timber gale
#

x is a positive real number , f(x) is a function, there is an equation in the pic, it asks f(1/e^3)

livid grotto
#

We need to try to get an expression for f(x), any idea how?

upper iron
#

You use the natural logarithm to drop down the exponents

#

x^x = e^(xf)

#

ln(x^x) = ln[e^(xf)]

#

x.ln(x) = x.f

#

ln(x) = f

#

So, f(x) = ln(x)

worthy citrus
#

could've let them try it themself

upper iron
#

I mean, it's gonna be hard to discuss it with him, he is clearly Turkish

#

Prolly does not speak eng

#

So I showed him how to do it right away

livid grotto
#

Therefore doesn't deserve to learn maths!

#

Fantastic

#

If they have come into a majority English speaking discord I'm sure they're comfortable speaking English man

vocal sleetBOT
#

@timber gale Has your question been resolved?

timber gale
#

this way its better

#

thanks it helped

#

.close

vocal sleetBOT
#
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nova zodiac
#

Why the derivative of inverse of B is 1/(B'(B^-1(x))?

lone linden
#

Consider that $(B^{-1})(B(x))=x$

twin meteorBOT
#

Civil Service Pigeon

lone linden
#

then apply ||chain rule||

nova zodiac
#

OK understand!

#

.close

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#
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storm arrow
#

help pls

vocal sleetBOT
sly sierra
#

for the first three, you can easily find counterexamples using a set of two elements

sly sierra
#

do you see why?

storm arrow
#

i get why it is reflexive but not why it aint symmetric

sly sierra
#

it contains (1,2) but not (2,1)

storm arrow
#

wait wait

#

you know what can you explain me what exactly symmetric, anti symetric and transitive are

sly sierra
#

don't you have definitions in your book or whatever resource you're using?

storm arrow
#

we got pre homework

#

OKAY I GOT IT

#

so for symmetric relations

#

it needs to have the opposite set for every unequal set

#

so like (a,b) needs to be paired with (b,a)

sly sierra
#

and reflexive needs to contain every (a,a)

storm arrow
#

and antisymmetric?

sly sierra
#

antisymmetric must not contain (b,a) if it contains (a,b), where a and b are different

storm arrow
#

can you give me an example?

sly sierra
#

yeah, if the set is {1,2}, then an example of an antisymmetric relation would be {(1,1)}

storm arrow
#

so like {(1,1),(2,2)} is a symmetric relation of {1,2}

sly sierra
#

yes

storm arrow
#

okay cool thanks

storm arrow
sly sierra
#

yes it's actually both

storm arrow
#

wait how

#

oh is it because it doesnt contain (a,b)

sly sierra
#

well it's asymmetric because it contains no (a,b) with a,b distinct

storm arrow
#

so it doesnt need to have (b,a) in the first place

sly sierra
#

and it's symmetric because there are no mismatched (a,b)

storm arrow
#

okay okay im getting the hang of it

#

and can you explain transitive too?

sly sierra
#

yea, transitive means: if it contains (a,b) and (b,c) then it must contain (a,c)

#

in words: "if a is related to b, and b is related to c, then a is related to c"

storm arrow
sly sierra
#

right

#

because it is missing (1,3)

storm arrow
#

okay okay so thats all ?

sly sierra
#

similarly, {(1,2), (2,1)} is not transitive

#

because (1,1) is missing

storm arrow
#

ok yes

sly sierra
#

and so is (2,2)

storm arrow
#

got it

#

what exactly does this question mean

#

"implies any other" ?

sly sierra
#

basically just take each pair of bullet items

#

say reflexive and symmetric

storm arrow
#

okay

sly sierra
#

find an example of a relation that is the first but not the second

#

findi an example of a relation that is the second but not the first

#

do that for each pair

storm arrow
#

can you give me an example for just the first 2

sly sierra
#

yea

#

say we are working with the set {1,2} again

#

reflexive but not symmetric: {(1,1), (2,2), (1,2)}

#

because (2,1) is missing

#

symmetric but not reflexive: {(1,2), (2,1)}

#

because (1,1) and (2,2) are missing

storm arrow
#

can you give an example about the same except without using numbers

sly sierra
#

what should i use instead?

#

the numbers are just placeholders for whatever you call the two elements in the set

storm arrow
#

okok

sly sierra
#

could call them {a,b} instead if you like

storm arrow
#

can you also possibly give me an example of (a,b) where it is not antisymmetric and symmetric at the same time?

#

i cant figure out a relation which is reflexive but not symmetric, asymmetric and transitive?

sly sierra
#

{(1,2)} is antisymmetric but not symmetric

storm arrow
#

i found one where it is symmetric but none of the others

sly sierra
#

reflexive but not symmetric: {(1,1), (2,2), (1,2)}

#

reflexive but not asymmetric: {(1,1), (2,2), (1,2), (2,1)}

#

for reflexive but not transitive, i think you will need three elements

vocal sleetBOT
#

@storm arrow Has your question been resolved?

vocal sleetBOT
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open mango
vocal sleetBOT
hollow raptor
#

Do you know how to get the perimeter of a circle?

open mango
#

No

karmic imp
# open mango No

Btw perimeter of a circle is another way to describe circumference

open mango
#

💀

#

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deft leaf
#

I need help with this integral

vocal sleetBOT
deft leaf
#

I tried u-sub and partial fractions

#

But the partial fractions way is very very long and I think there’s a better way to do this

#

The nominator is x-2

#

mb

paper depot
#

numerator*

deft leaf
#

Ye sorry

#

Do you know how to solve?

paper depot
#

not without grueling partial fraction shit i dont

vocal sleetBOT
#

@deft leaf Has your question been resolved?

indigo jay
#

you can split it into two fractions

#

one will come out nicely, but the other one will require partial fractions

mild flower
#

not only partial fractions but complex partial fractions since x^2 - 4x + 5 has no real roots

indigo jay
#

actually, scratch my previous comment

#

it looks painful lol

mild flower
#

that's a Mathematica Moment™️

vocal sleetBOT
#

@deft leaf Has your question been resolved?

vocal sleetBOT
#
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hasty token
vocal sleetBOT
dark field
#

!status

vocal sleetBOT
#
What step are you on?
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3. I got an answer but I'm told it's wrong
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6. None of the above
hasty token
#

no idea where to start mate

#

idek how to find the second derivative of this

vocal sleetBOT
#

@hasty token Has your question been resolved?

gaunt pendant
#

well i suppose it's motion is characterised parametrically

#

if you got a composite function you'll js wanna spam the chain rule

mild flower
hasty token
#

first derivative is 2 cos πt right?

thin basin
#

chain rule

vocal sleetBOT
#
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gaunt pendant
#

.reopen

vocal sleetBOT
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thin root
#

when you integrate this, are the C's different for each component?

thin root
#

C1 for x
C2 for y
C3 for z ?

paper depot
#

yes, though in principle you could also package them all into one vector

vocal sleetBOT
#
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oblique rivet
#

Find the dimension of the subspace
U = {(x1, x2, x3, x4, x5)∈ R^5: x1 − 4x2 − x4 + 3x5 = 0} ⊆ R^5

oblique rivet
#

this question is just 1 mark

livid grotto
#

What is the dimension of the space it is living inside?

oblique rivet
#

??

#

nothing else is given

livid grotto
#

U is a subspace of a space, what dimension is that space

oblique rivet
#

the space i guess is 5 dim

livid grotto
#

Indeed

oblique rivet
#

it says R^5

livid grotto
#

And we can see that by requiring '5 different coordinates' to describe a vector

#

But now we have a single linear equation

#

So, for example, x_1=4x_2+x_4-3x_5

oblique rivet
#

yes

#

and then x2 x4 x5 become free variables??

livid grotto
#

Well the point is that in restricting from R^5 to this subspace, x_1 is no longer a free variable

#

In all of R^5, all of x_1, ..., x_5 are free variables

#

But on U we reduce the number of free variables by 1 using our linear constraint

oblique rivet
#

so dim is 4??

livid grotto
#

Indeed

oblique rivet
#

ok tysm

livid grotto
#

The general prescription is 'n dimensional space subject to m linearly independent linear constraints has dimension n-m'

oblique rivet
#

ah ok

#

tysm

#

.clsoe

#

.close

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#
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vocal sleetBOT
covert salmon
#

!status

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
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6. None of the above
covert salmon
#

wrong channel, delete ur message please

royal tapir
#

ok

rapid swift
#

well you should know where to begin

covert salmon
#

Well yeah I sorta do

rapid swift
#

if you're clueless about anything related to solids of revolution

covert salmon
#

idk what my limits of integration will be

rapid swift
#

at the very least you can draw a diagram

covert salmon
#

in this case

#

I got the diagram

rapid swift
#

probably should paste it here

#

can you use mspaint or similar to shade the region that's being rotated?

covert salmon
#

sure, one sec

rapid swift
#

okay now can you identify the axis of rotation?

covert salmon
#

The x-axis.

rapid swift
#

can you sorta visualize what the solid looks like?

covert salmon
#

It will be a sphere but cut in half with a hole in the middle.

rapid swift
#

it won't be a sphere

#

it sorta looks like half a donut, yeah?

#

half a squished donut

covert salmon
#

ye ye half donut

#

yes

rapid swift
#

so you asked about the bounds of integration

#

imagine you're stacking washers to make the thing

#

well actually first

#

what variable are you going to integrate with respect to

rapid swift
#

okay so the washers are sorta going to be up on their sides yeah?

covert salmon
#

yes

rapid swift
#

so your original question was asking where the bounds of integration will be

#

at what x coordinate are you going to put the first washer if you imagine you're stacking them up to make the shape?

covert salmon
#

At x = 0

rapid swift
#

and the last one is at x = 4

covert salmon
#

yeah

rapid swift
#

so that answers your question there

covert salmon
#

that's a start

#

but now i'm confused as to what my outer and inner radius are

rapid swift
#

are you now interested in the radii of the two circles?

covert salmon
#

yes

rapid swift
#

okay

#

so the outer radius is the y coordinate of the top of the semicircle, right?

covert salmon
#

Well, the radius of the semi circle is 4, yes

rapid swift
#

that's not the same thing as what I was saying

#

the outer and the inner radius are going to change with x

covert salmon
#

hmm ok

rapid swift
covert salmon
rapid swift
#

no

#

as i said before

#

it changes with respect to x

covert salmon
#

ah ok

#

ye

rapid swift
#

can you figure out how it changes with respect to x?

covert salmon
#

Well we represent that using the integrals we need to find?

rapid swift
#

no

#

try drawing some lines representing the washers

#

in the diagram

covert salmon
#

What about the small area under the semi-circle that causes the hole?

rapid swift
#

that would be the purpose of the inner radius

#

there is a hole in a washer, no?

covert salmon
rapid swift
#

I honestly don't know what's hanging you up, except for maybe the actual task of determining the y coordinate of the top of the washer

#

but that's not terribly hard to do if you draw a horizontal line through the center of the semicircle

covert salmon
#

Well I need an outer and inner radius

#

and I just gotta subtract the two integrals using the disk integral formula

rapid swift
#

you need to review what the actual washer method is

#

not just divining out of thin air some stuff to put into the formula

#

the outer radius is literally where the ends of the washers are

#

draw the washers

covert salmon
#

oh

#

the outer radius is 8?

#

Wait no... the outer radius is 4

#

but how can my outer and inner radii be the same?

vocal sleetBOT
#

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covert salmon
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vast shale
vocal sleetBOT
vast shale
#

how do I do this

#

sin(2pi)/tan(pi/3) = 0 so we can ignore that term

#

the summand simplifies via evaluation

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vast shale
vocal sleetBOT
vast shale
#

I'm not sure how to continue.

"parallel to the x-axis" means y' = 0. So I used that to obtain an expression for y in terms of x. But I don't know how to use it.

vocal sleetBOT
#

@vast shale Has your question been resolved?

mild flower
#

I haven't run the numbers but it will probably be a lot easier to do implicit differentiation

#

but you can use what you have, just differentiate y and set y' = 0 then solve for x

vast shale
mild flower
#

oh I should actually read what you wrote sorry

vast shale
vast shale
mild flower
#

so you have that eqn and you have your original one

#

you should be able to set them together and find two solutions

vast shale
#

what do I do with this

#

these set equal to each other?

mild flower
#

two cases

#

because y isn't a function of x

#

but also you can start with that y^2 eqn

#

it'll be a lot simpler that way

vast shale
#

I didn't get anywhere

#

And yes I used y^2

mild flower
#

should just be a rational equation in x

vast shale
vast shale
vocal sleetBOT
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mild flower
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gritty zenith
vocal sleetBOT
gritty zenith
#

Are these two correct?

#

.close

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naive elbow
#

a stone is dropped from a 75-m high building. WHen this stone has dropped 15m, a second stone is thrown downward with an intial velocity such that the two stones hit the gound at the same time. What was the initial velocity of the second stone

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uneven hamlet
#

Hi, I've been unable to tackle the following problem, I am probably using the wrong relation, since I'm pretty sure a doesn't directly correspond to the distance the man has walked. Not sure what relation should be used, tried the law of sines/cosines. It is probably not something complex but I fail to point at it

uneven hamlet
#

the actual solution is 0.633ft/sec from what I've been able to find

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#

@uneven hamlet Has your question been resolved?

vocal sleetBOT
#

@uneven hamlet Has your question been resolved?

vocal sleetBOT
#

@uneven hamlet Has your question been resolved?

summer lichen
uneven hamlet
# summer lichen I think you have the right idea, the relation is the pythagorean theorem. The pr...

Did I take the derivatives incorrectly? I treated each side a,b&c as functions and took their derivatives using the chain rule (derivative of a/b/c with respect to itself * the derivative with respect to time), I think my issue lies where I treated a (the length between the man and the tip of the weigh) as being equal to the distance the man has walked which is incorrect. I think the length between the tip of the weigh and the ground needs to be accounted for as well (let's call that distance y), thus c = 60-b-y, though I am still not sure how to relate that

summer lichen
uneven hamlet
#

I mean I did try to plug it into a pythagorean identity, i.e (10^2) + (b+y)^2 = (60-b-y)^2, though after expanding I'm left with y+b=29.16 which is not different from what I've calculated in the picture and it doesn't provide me any convenient info for finding dy/dt

summer lichen
#

Yeah I think that's the most important part of this question

#

there's a pretty simple relation between the rate that the weight moves and the rate at which the man moves

#

and it has to do with the rope and the pulley

uneven hamlet
#

isn't that the supposedly that they change at an opposite rate? (when c increases b decreases at the same rate)

summer lichen
#

It's close but we're looking for the rate at which the length change so the direction of change is irrelevant

uneven hamlet
#

Can't believe it was this simple

summer lichen
#

nice job

uneven hamlet
#

Ty for the help and encouragement!

#

.solved

#

.close

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glad pendant
vocal sleetBOT
glad pendant
#

i need someone to help me with 13

#

i am so lost

ornate ember
#

test?

livid grotto
#

probs a past paper

ornate ember
# glad pendant

The key to solving this is using the rule that $log_b(a^c) = c \cdot log_b(a)$

twin meteorBOT
#

MellowDramaLlama

glad pendant
#

ohhh i see

glad pendant
ornate ember
#

I'll give you the first log term

glad pendant
#

okok

ornate ember
#

$log_bx^{\frac{2}{3}} = \frac{2}{3} log_bx\\$
Now we know that $log_bx = 0.1$, so we get $\frac{2}{3}log_bx = \frac{2}{3}(0.1) = \frac{2}{3}\left(\frac{1}{10}\right) = \frac{2}{30} = \frac{1}{15}$

twin meteorBOT
#

MellowDramaLlama

ornate ember
#

just do the same with the remaining terms and then add them all up

glad pendant
#

ohhh ok i see

#

im gonna try and can u tell me if i did it right?

ornate ember
#

yep go for it!

glad pendant
#

i got 1/12 as my final answer

ornate ember
#

yep that's what I got too 🙂 Nice work

vocal sleetBOT
#

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flint gulch
#

Hey I need help with this word problem:

A man is 5 times as old as his son. Four years ago, the product of their ages was 52. Find their present ages.

fast cipher
flint gulch
#

I dont think this this can be solved with the model method.

fast cipher
#

I don't know what you mean by "model method".

fast cipher
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vast shale
#

0 isnt real

vocal sleetBOT
vast shale
#

It means nothing

#

Yes it represents nothing

#

But

#

It doesnt sct like a number either

ornate ember
#

what makes you think 0 isn't real?

vast shale
#

If it represents nothing then its nothing

#

Its not a thing

hollow raptor
#

It definitely acts like a number, it can be added and multiplied, etc

vast shale
#

It cant be diviced

#

And it doesnt act like normal numbers

hollow raptor
#

Sure it can! It just makes 0

urban edge
#

you cant do log base 1, does that make 1 not real?

rugged orchid
#

0 is a special number

vast shale
#

My point is

#

0 means nothing

ornate ember
#

in fact, it's incredibly special

vast shale
#

Its nothing

vast shale
#

Its represents nothing so its nothing

rugged orchid
#

What level of education are you at?

vast shale
#

Doesnt matter because youre just gonns judge me based on my answer to ur q

rugged orchid
#

No I’m not

vast shale
ornate ember
urban edge
#

"Number" means many different things and it gets more complicated

rugged orchid
#

It’s because as you go higher into math you will start thinking about what are numbers, and it’s called group theory

ornate ember
#

higher level math you do some deeper dives into properties of 0

#

actually it's relevant

urban edge
#

Wheel theory :D

hollow raptor
#

-1 is even less real then!

rugged orchid
#

It’s perfectly valid to ask what are numbers

rugged orchid
#

They certainly do!

ornate ember
urban edge
#

why?

vast shale
#

So what are numbers

urban edge
#

Numbers are representations of quantities

rugged orchid
#

I don’t think “numbers” themselves have a mathematical definition

vast shale
#

0 represents nothing no quantity so nothing

rugged orchid
#

But you could perhaps look at fields

urban edge
#

It represents the lack of quantity

#

In a way, quantity itself would be poorly defined as well

hollow raptor
brisk moss
#

real numbers are just elements in the unique ordered field that has the least upper bound property and contains the rational numbers

ornate ember
#

"Hey look in my hands, I have 0 dollars in my hand" holds out empty palm. It represents the lack of a quantity.

#

I mean, my bank tells me I have $0 in the bank, lol

rugged orchid
#

Numbers themselves aren’t too useful, it’s what you can do with them

vast shale
#

Makes sense

rugged orchid
#

Like addition!

#

No one said we could add numbers together

hollow raptor
#

A set with no elements

rugged orchid
#

Now 0 is special because if we add 0 to something

#

We get the something

vast shale
# urban edge why?

Why u laughing st him? U said to question everything so he questioned your statement

rugged orchid
#

It doesn’t change

vast shale
#

No humor

vast shale
rugged orchid
#

0 is also special because if we multiplied it by anything we get 0

urban edge
#

If you lack a sense of humor in mathematics, you would lose half the experience

vast shale
#

No i wont

#

Ok im going tot sleep

rugged orchid
#

But then 1 is also pretty special, because 1 multiplied by something gives you something

vast shale
#

Yea

rugged orchid
#

There are names for these

#

But I’m sure you’ll learn them down the line if you’re interested

vast shale
#

Ok

vocal sleetBOT
#

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vocal sleetBOT
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vocal sleetBOT
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vocal sleetBOT
#

Show your work, and if possible, explain where you are stuck.

primal knot
#

i just need a walk through and i’ll understand

vast shale
primal knot
#

how would i do that

#

any way u could show ?

vast shale
#

y = x + 5 + (green counters)?

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vast shale
#

how did they conclude that $G$ is not commutative?

twin meteorBOT
hard atlas
#

well known fact about S_3

vast shale
#

oh i see okay

hard atlas
#

try to find two elements in S_3 with ab != ba

vast shale
#

like

#

[
(1 2)(2 3) = (1 3 2)\
(2 3)(1 2) = (1 2 3)
]

twin meteorBOT
vast shale
#

so it cant be commutative at all i guess

#

fair enough

#

ty

#

.close

hard atlas
#

those products are wrong

vocal sleetBOT
#
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hard atlas
#

.reopen

vocal sleetBOT
#

vast shale
#

oh?

hard atlas
#

you have to do them from the right

#

you plug stuff in on the right and then evaluate step by step

#

(12)(23) [1] = (12)[1] = 2

#

where I use [] for evaluation brackets

#

(12)(23)[2] = (12)[3] = 3

#

(12)(23)[3] = (12)[2] = 1

#

so 1->2, 2->3, 3->1, ie. (123)

vast shale
#

oh okay thonk thanks for noting that, will keep a closer eye

#

.close

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#
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real gale
#

Lixera is now white pandaHmm

vast shale
#

whitewashed xd

vocal sleetBOT
#
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gusty plume
#

For a i ve to find intersection point of plane and line and this is my solution is this correct?

gusty plume
vocal sleetBOT
#

@gusty plume Has your question been resolved?

gusty plume
#

<@&286206848099549185>

cyan talon
#

euuh qu'est-ce que t'entends par 3d-2 ? @gusty plume

#

parce que d c'est le nom d'un plan

#

3 fois un plan je vois moyen ce que ça veut dire

gusty plume
#

oui mais d ca peut etre n'importe quel variable

#

je choisis au hazard

cyan talon
#

ah ok c'est pour les points du plan l'équation paramétrique

gusty plume
#

jai trouver equation para

#

voila

cyan talon
#

c'est juste qu'il y avait l'équation de droite au dessus c'est confusant

#

okok

gusty plume
#

donc c bon?

cyan talon
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#
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cyan talon
#

.reopen

vocal sleetBOT
#

cyan talon
#

tu peux toujours check en mettant ton point dans les deux équations

#

et ça marche

gusty plume
#

merci bcp et j avais encore une 2eme question

cyan talon
#

yup

gusty plume
#

c possible d'avoir les reponses different quand on cherche l'intersection entre plan et droite

cyan talon
#

il y a plusieurs scénarios possible ouep

gusty plume
#

cmt ca se fait car ils s'intersect en un point nn?

cyan talon
#

ça dépend

#

quand t'as 2 droites en 2d, si elles sont parallèles (et pas identiques) t'as 0 intersection par exemple

gusty plume
#

oui logique

cyan talon
#

là c'est un peu pareil

#
  1. soit ta droite est pas parallèle au plan, là t'as une seule intersection
#
  1. soit ta droite est parallèle au plan
#
  • si ta droite est contenue dans le plan, l'intersection c'est la droite entière
#
  • sinon t'as 0 intersection (parallèle mais pas dedans)
gusty plume
#

ah c vrai merci bcp

#

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