#help-17
1 messages · Page 35 of 1
are you asking if that's angle B?
yes
that's not what I get
let me fill in the values for you
$\frac{\sin(0.71)}{1.912} = \frac{\sin B}{2.7}$
kitten.in.a.teacup
so now we can solve for sin(B)
uh, no - what did you do?
kitten.in.a.teacup
yes
now can you solve for sin B?
yeah, that's what I get, okay so that's sin B, now let's get rid of the sin
so we have:
$\cancel{\sin B = 1.1693}$
wait no you already did that didn't you
because I get that sin(B) = 0.9204, and B = 1.17 rad
yeah great okay, so that's angle B
idk, does it say how many decimal points to use? It gave you angle C in 2 decimal places so you could use that 
can you do the same thing to solve angle A? I can write out the equation for you if you want
$\frac{\sin A}{1.3} = \frac{\sin(0.71)}{1.912}$
kitten.in.a.teacup
Do you see where I'm pulling those numbers from?
yeah
thats A
what's a DNE?
does not exist
idk what D is
i kind of have to submit something since im running out of time
so DNE it is
Hey guys, I've been stuck on this problem for quite some time. It falls under Linear Algebra, specifically Finding the Cross Product for vectors
running out of time how?
Here is my work
My bad, thanks
@old schooner Has your question been resolved?
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A wire is wound on the cylinder x^2 + y^2 = 4 with initial point (2,0,0), so that the height z of each point of the wire is a linear function of the angle t of winding up to the point. Suppose that in one revolution the wire reaches a height of 2pi. Calculate the mass of the first turn of the wire, if at each point the linear mass density is equal to the height z of point
I find the parametric equation, but, I don't know how to find the density function
@median sun Has your question been resolved?
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Hello.
howdy what's your question?
that looks like a trig identity: $cos(a + b) = cos(a)cos(b) - sin(a)sin(b)$
MellowDramaLlama
so what would our a and b be here?
those two expressions are not equivalent, looks like a typo to me
but yes that trig identity is useful for solving it
Are there other trig identities I should know?
I'm just now learning about them.
Nvm, found the sheet in class.
Thanks.
.close
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hi i need help

where are the numbers
i think i have to find it but i dont know how to solve do you know how?
I mean that in the first question it says A=
cause in number 1 the measurement of angle A is missing and angle B
oh
is there something else above?
no😔😔
Are you reading a Word document on mobile?
yeah my teacher sent this and told us that we have to answer and didnt give any examples
can’t believe I guessed right, you’re really reading a word document on mobile?
try with computer
the spacing gets messed up sometimes on mobile
i opened this on comp and it shows the answer lol
thanks
You can try drawing them
or use sine rule and cosine rule
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why is this the case
Raise a to the power of both sides
then what do i do next
a^(log_a b)=b
Then you use $a^{\log_a{b}}=b$
frosst
Me too
listening to all too well 10 min rn
A masterpiece I tell you
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Can someone help me
Thats not what u ask here 💀😂😂 only for problems here bro
@north glacier Has your question been resolved?
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Let $d$ be the distance function defined on $\mathbb{R}^n$ by the correspondence $d(x,y) = \max_{1\leq i \leq n} {d_i(x_i,y_i)}$ for $x = (x_1,x_2,\hdots,x_n),y=(y_1,y_2,\hdots,y_n)\in \mathbb{R}^n,$ let $d'$ be the euclidean distance function $d'(x,y) = \sqrt{\sum_{i=1}^n(x_i-y_i)^2}$, and let $d''$ be the distance function $d''(x,y) = \sum_{i=1}^n |x_i-y_i|.$ Then, for each pair of points $x,y \in \mathbb{R}^n$, $$d(x,y) \leq d'(x,y) \leq \sqrt{n} * d(x,y).$$
That is, $$\max_{1\leq i \leq n} {d_i(x_i,y_i)} \leq \sqrt{\sum_{i=1}^n(x_i-y_i)^2} \leq \sqrt{n}*\max_{1\leq i \leq n} {d_i(x_i,y_i)}.$$
My question is, how can the max distance $d$ be leq than the euclidean distance if it is defined to be the maximum of the distances?
deimos the wizard
are you asking about this inequality?
I am
oh wait true, the maximum distance only spits out the one result that is greater than the others whereas the actual euclidean distance is that and all the other stuff
okay I think I kind of had that in the back of my head but you saying it made it click
alright imma close this if that's cool
sure haha
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Are you trying to solve for area
Do you know how to integrate along the y-axis
But idk how to find the intersected coordinate
Ohh
Do i need to find the y or x
Just y
y^2=5x
2y=-x
Set both y values equal
If youre integrating along y
Multiply the second equation by -5 so they both equal 5x
That way you can set them equal to each other and solve
?
y² = 5x
2y * -5 = 5x
Y² = -10y
Unable to open this for some reason
Yes but then you would have to solve for two variables
And wouldn't potentially get all negative answers
I get x=0 though
You need to have two pts
This works but then you're solving for x and then having to substitute it back in to solve for y
Since you're integrating along the y axis
Unless you want to integrate along the x-axis, both work but y is easier given these equations
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How can I prove that $(x_i-y_i)^2 \leq \max_{1\leq i\leq n} \left{\sum_{i=1}^n (x_i-y_i)\right}$ for all $1 \leq i \leq n$?
that expression on the right doesn’t parse?
o u right
holup
really it's just the euclidean metric inside the maximum squared, hence just the sum part
that looks worse
oh shit
max 1 <= i <= 1?
deimos the wizard
does it make sense to square the maximum?
i don’t get the “for all 1 <= i <= n” part
as a note, this is still the earlier problem about the metric inequality, $d$ is the maximum as defined #help-17 message here, I asked the question on stack exchange and had the comment: "(x_i-y_i)² \leq d(x,y)^2" for all 1 \leq i \leq n
deimos the wizard
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
which is somehow supposed to help
Bot doesn’t like # :/
ah it's cool, I think it would be okay if someone just helped me understand how the euclidean distance is less than or equal to the maximum of the euclidean distance times the square root of n
in R^n
this
there are n things being summed
each of them is less than or equal to the max
so sum((x_i - y_i)^2) <= n*max(x_i - y_i)^2
but one of them must be the max, no?
sorry, less than or equal to
taking square roots here gives the inequality
okay that gives me something to ponder
Imma close the channel again if that's cool
will come back again if I get stuck on the third part too
sure lol
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I am stuck on how to find convert the rectangular coordinates (4,-3) into polar coordinates.
ok hi
I used the formula (x^2)+(y^2) = (r^2)
you can find the magnitude by doing root(4^2 + (-3)^2)
this is your ‘r’ value
to find theta, you can do tan^-1(y/x) = tan^-1(-3/4)
then you should get 5cis(arctan(-3/4))
@vast shale
cis lol
cis 😍
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✅
I am a bit stuck on how to solve this problem
How are polar coordinates and cartesian coordinates related?
The Cartesian coordinates are general coordinates on what points the graphs passes?
$$\left{\begin{aligned}
r&=\sqrt{xy}\
\theta&=\tan\left(\frac ab\right)
\end{aligned}\right.$$
Hokkaydo
Probably easier to just notice $$x=r\cos \theta , y = r\sin \theta$$
rcatalang
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Propositional Logic question:
Knowing that p -> q = ~p v q, prove that p -> ~q = ~(p ^ q) = ~p v ~q.
What I tried:
First, I saw a solution to the following problem in a website that goes like this:
Problem: knowing that p -> q = ~p v q, prove that ~p -> q = p v q
Their solution:
p -> q = ~p v q
just replace, in p -> q = ~p v q, the proposition p by its negation. Look:
(~p) -> q = ~(~p) v q
~p -> q = p v q
Now, for the problem I want help to solve it:
We want to prove that p -> ~q = ~(p ^ q) = ~p v ~q
p -> q = ~p v q
replacing the proposition q by its negation:
p -> (~q) = **~**p v ~q
p -> ~q = ~p v ~q
So using the same method I didn't prove correctly what the question told me to, since p -> ~q is not equal to p ^ q. How can I solve it?
@rich cargo Has your question been resolved?
<@&286206848099549185>
Using De Morgan's property in p and not q, we get:
~(p ^ ~q) = ~p v q
right, the question is not posed correctly
read your first 2 lines again
p ^ -q does not equal -p v q
what I meant there was that p -> q = p ^ ~q, and p -> q = ~p v q, sorry about that
well again, p -> q is not equal to p ^ -q
Ohh, that's true, ~(p -> q) = p ^ ~q. I'll edit the question where I made this mistake
is it correct now?
looks fine
Ok, so from p -> ~q = ~p v ~q I can use Morgan's property and find that
~p v ~q = ~(p ^ q)?
yes
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So apparently I messed up so bad that I got the answer right. Can someone pls explain how to actually do the problem?
Like correctly
use $\tan(x)=\f{\sin(x)}{\cos(x)}$ and then use the unit circle to find what sin and cos are
duhhello
Looks correct. Figure may be wrong
Ok ty
.close
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Is there any simple method of solving indices
depends on the quesiton
u got an example??
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If I have this definition of the floor function, is correct to say that the definition of the ceiling function is f(t) := { n if n-1 < t <= n, for n belongs to naturals numbers}?
integers, not just naturals
and n-1 ≤ t < n
the ceil of any integer is that integer itself still
ah uh
shit no you're riht
right*
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Hi can someone please explain what happens, how the (1-e^-s)/s appears?
Factor out e^(-ns)
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@wide rapids Has your question been resolved?
did 600 somehow turn into 60?
oo typo
otherwise yeah it's right (and you can get an actual value out of it)
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sorry but i honestly have no clue what is happening here
what is the thing on the right?
like r, the radius of the circle
the radius
r^2 then no?
yeh but i got rid of the squared
Should be 2xy/sqrt(x^2 + y^2)
????
true if it's 1
(x^2 + y^2)^2 squared is x^2 + y^2?
u have to un square it right
cause its r^2
(x^2 + y^2)^2 is r^2?

x^2 + y^2 = r^2
Here yeah
But it still means 2xy will get divided by the root
Whatever you name x^2 + y^2
i dont get it
if r^2 here is (x^2+y^2)^2
then r
is
(x^2+y^2)
What do you get after dividing both sides by x^2 + y^2?
rhs is x^2 + y^2
lhs is some weird stuff?
Whatever it is, you'll have (2xy)^2/(x^2 + y^2), right?
bean can u tell me where i went wrong
from the picture
ok fine
x^2+y^2=(x^2+y^2)^2
is this correct
Not in general
Let x = 1 and y = 1
ok
The equation then fails
.
i calculated x^2+y^2 in this context
and my answer was
(x^2+y^2)^2
so now why dont i square root it
How are you getting (x^2 + y^2)^2?
Oh
Why did you cross the ^2 ??
In the end
Yeah you are right
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.close
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Can someone check if both those questions are right
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no
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Hello
I'm reading this proof of the Riesz theorem but I don't understand some things
- Why do we set x_l as the product of the complex conjugate of l(hat x) and hat x
- What are those l(x)/l(hat x) popping out of nowhere ?
Its coming from this vid https://www.youtube.com/watch?v=rKiy6wEiQIk
yey i know but i don't understand the proof at all :x
you want the conjugate because it looks like your inner product is conjugate linear in the first slot
when you pull l(x^hat) into the first slot of the inner product you pick up a conjugate, motivating the choice of x_l
similar idea here:
https://math.uchicago.edu/~may/REU2021/REUPapers/Adler.pdf
try reading the proof backwards
when you pull l(x^hat) into the first slot of the inner product you pick up a conjugate
what is the reason of that ? (probably stupid question but i feel dumb)
do you know the definition of inner product
I don't see where complex involves in it :x
oh wait
i never used the inner product in complex space so didnt know that <x,y>= conjugate of <y,x>
in my head it just was <x,y>=<y,x> :o
you should probably do some inner product calculations on complex numbers
like <1 + i, 3>
never tried indeed
if you haven't, i recommend taking complex analysis before functional analysis
i got already but surpringly i didnt come to my mind
idk how i never had to use that property
.close
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my calculator says the answer is -1/2y. what am i doing wrong? https://i.imgur.com/1p5ZapH.png
show what you input into the calculator
do you know what implicit_diff does when you give it both x, y arguments at the end
yeah x is the dependent, y is the independent
oh wait i fixed it
okay it was just some weird glitch with the -xy there
.close
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x is a positive real number , f(x) is a function, there is an equation in the pic, it asks f(1/e^3)
We need to try to get an expression for f(x), any idea how?
You use the natural logarithm to drop down the exponents
x^x = e^(xf)
ln(x^x) = ln[e^(xf)]
x.ln(x) = x.f
ln(x) = f
So, f(x) = ln(x)
could've let them try it themself
I mean, it's gonna be hard to discuss it with him, he is clearly Turkish
Prolly does not speak eng
So I showed him how to do it right away
Therefore doesn't deserve to learn maths!
Fantastic
If they have come into a majority English speaking discord I'm sure they're comfortable speaking English man
@timber gale Has your question been resolved?
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Why the derivative of inverse of B is 1/(B'(B^-1(x))?
Consider that $(B^{-1})(B(x))=x$
Civil Service Pigeon
then apply ||chain rule||
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help pls
have you been able to show this for any of the pairs?
for the first three, you can easily find counterexamples using a set of two elements
please explain that
well, for example, if the set is {1,2} then here is a relation that is reflexive but not symmetric: {(1,1), (2,2), (1,2)}
do you see why?
i get why it is reflexive but not why it aint symmetric
it contains (1,2) but not (2,1)
wait wait
you know what can you explain me what exactly symmetric, anti symetric and transitive are
don't you have definitions in your book or whatever resource you're using?
nope nothing we get resources day after tomorrow
we got pre homework
OKAY I GOT IT
so for symmetric relations
it needs to have the opposite set for every unequal set
so like (a,b) needs to be paired with (b,a)
yep that's right
and reflexive needs to contain every (a,a)
and antisymmetric?
antisymmetric must not contain (b,a) if it contains (a,b), where a and b are different
can you give me an example?
yeah, if the set is {1,2}, then an example of an antisymmetric relation would be {(1,1)}
okay got it
so like {(1,1),(2,2)} is a symmetric relation of {1,2}
yes
okay cool thanks
*asymmetric
yes it's actually both
well it's asymmetric because it contains no (a,b) with a,b distinct
so it doesnt need to have (b,a) in the first place
and it's symmetric because there are no mismatched (a,b)
yea, transitive means: if it contains (a,b) and (b,c) then it must contain (a,c)
in words: "if a is related to b, and b is related to c, then a is related to c"
so if the original set is {1,2,3} and its relation is {(1,2),(2,3)} it wont be transitive yeah?
okay okay so thats all ?
ok yes
and so is (2,2)
okay
find an example of a relation that is the first but not the second
findi an example of a relation that is the second but not the first
do that for each pair
can you give me an example for just the first 2
yea
say we are working with the set {1,2} again
reflexive but not symmetric: {(1,1), (2,2), (1,2)}
because (2,1) is missing
symmetric but not reflexive: {(1,2), (2,1)}
because (1,1) and (2,2) are missing
can you give an example about the same except without using numbers
what should i use instead?
the numbers are just placeholders for whatever you call the two elements in the set
okok
could call them {a,b} instead if you like
can you also possibly give me an example of (a,b) where it is not antisymmetric and symmetric at the same time?
i cant figure out a relation which is reflexive but not symmetric, asymmetric and transitive?
yeah, how about {(1,2), (2,1)} - that's symmetric but not antisymmetric
{(1,2)} is antisymmetric but not symmetric
this
i found one where it is symmetric but none of the others
reflexive but not symmetric: {(1,1), (2,2), (1,2)}
reflexive but not asymmetric: {(1,1), (2,2), (1,2), (2,1)}
for reflexive but not transitive, i think you will need three elements
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Help
Do you know how to get the perimeter of a circle?
No
Btw perimeter of a circle is another way to describe circumference
This is one of the ways to do it right?
💀
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I need help with this integral
I tried u-sub and partial fractions
But the partial fractions way is very very long and I think there’s a better way to do this
The nominator is x-2
mb
numerator*
not without grueling partial fraction shit i dont
@deft leaf Has your question been resolved?
you can split it into two fractions
one will come out nicely, but the other one will require partial fractions
not only partial fractions but complex partial fractions since x^2 - 4x + 5 has no real roots
that's a Mathematica Moment™️
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
@hasty token Has your question been resolved?
well i suppose it's motion is characterised parametrically
if you got a composite function you'll js wanna spam the chain rule
start by finding the first derivative
first derivative is 2 cos πt right?
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when you integrate this, are the C's different for each component?
C1 for x
C2 for y
C3 for z ?
yes, though in principle you could also package them all into one vector
ty
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Find the dimension of the subspace
U = {(x1, x2, x3, x4, x5)∈ R^5: x1 − 4x2 − x4 + 3x5 = 0} ⊆ R^5
this question is just 1 mark
What is the dimension of the space it is living inside?
U is a subspace of a space, what dimension is that space
the space i guess is 5 dim
Indeed
it says R^5
And we can see that by requiring '5 different coordinates' to describe a vector
But now we have a single linear equation
So, for example, x_1=4x_2+x_4-3x_5
Well the point is that in restricting from R^5 to this subspace, x_1 is no longer a free variable
In all of R^5, all of x_1, ..., x_5 are free variables
But on U we reduce the number of free variables by 1 using our linear constraint
so dim is 4??
Indeed
ok tysm
The general prescription is 'n dimensional space subject to m linearly independent linear constraints has dimension n-m'
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!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
ok
well you should know where to begin
Well yeah I sorta do
if you're clueless about anything related to solids of revolution
idk what my limits of integration will be
at the very least you can draw a diagram
probably should paste it here
can you use mspaint or similar to shade the region that's being rotated?
sure, one sec
okay now can you identify the axis of rotation?
The x-axis.
can you sorta visualize what the solid looks like?
It will be a sphere but cut in half with a hole in the middle.
it won't be a sphere
it sorta looks like half a donut, yeah?
half a squished donut
so you asked about the bounds of integration
imagine you're stacking washers to make the thing
well actually first
what variable are you going to integrate with respect to
okay so the washers are sorta going to be up on their sides yeah?
yes
so your original question was asking where the bounds of integration will be
at what x coordinate are you going to put the first washer if you imagine you're stacking them up to make the shape?
At x = 0
and the last one is at x = 4
yeah
so that answers your question there
are you now interested in the radii of the two circles?
yes
Well, the radius of the semi circle is 4, yes
that's not the same thing as what I was saying
the outer and the inner radius are going to change with x
hmm ok
wdym by this?
what part don't you understand
Is he y-coordinate of the top of the semi circle 8?
can you figure out how it changes with respect to x?
Well we represent that using the integrals we need to find?
What about the small area under the semi-circle that causes the hole?
yeah
I honestly don't know what's hanging you up, except for maybe the actual task of determining the y coordinate of the top of the washer
but that's not terribly hard to do if you draw a horizontal line through the center of the semicircle
Well I need an outer and inner radius
and I just gotta subtract the two integrals using the disk integral formula
you need to review what the actual washer method is
not just divining out of thin air some stuff to put into the formula
the outer radius is literally where the ends of the washers are
draw the washers
oh
the outer radius is 8?
Wait no... the outer radius is 4
but how can my outer and inner radii be the same?
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how do I do this
sin(2pi)/tan(pi/3) = 0 so we can ignore that term
the summand simplifies via evaluation
Yes
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I'm not sure how to continue.
"parallel to the x-axis" means y' = 0. So I used that to obtain an expression for y in terms of x. But I don't know how to use it.
@vast shale Has your question been resolved?
I haven't run the numbers but it will probably be a lot easier to do implicit differentiation
but you can use what you have, just differentiate y and set y' = 0 then solve for x
Well yeah I used the implicit function theorem
oh I should actually read what you wrote sorry
That's a rewrite of what I said, not what I asked
Oh no worries
so you have that eqn and you have your original one
you should be able to set them together and find two solutions
two cases
because y isn't a function of x
but also you can start with that y^2 eqn
it'll be a lot simpler that way
should just be a rational equation in x
Well let me know if you solved it without a calculator
@vast shale Has your question been resolved?
yeah it's not that bad
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a stone is dropped from a 75-m high building. WHen this stone has dropped 15m, a second stone is thrown downward with an intial velocity such that the two stones hit the gound at the same time. What was the initial velocity of the second stone
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Hi, I've been unable to tackle the following problem, I am probably using the wrong relation, since I'm pretty sure a doesn't directly correspond to the distance the man has walked. Not sure what relation should be used, tried the law of sines/cosines. It is probably not something complex but I fail to point at it
the actual solution is 0.633ft/sec from what I've been able to find
@uneven hamlet Has your question been resolved?
@uneven hamlet Has your question been resolved?
@uneven hamlet Has your question been resolved?
I think you have the right idea, the relation is the pythagorean theorem. The problem seems to be that you're not being careful about the values of a,b, and c. These are all functions of time!! This is very important, since as the man moves horizontally the values of a,b, and c change drastically and b->0 eventually.
Did I take the derivatives incorrectly? I treated each side a,b&c as functions and took their derivatives using the chain rule (derivative of a/b/c with respect to itself * the derivative with respect to time), I think my issue lies where I treated a (the length between the man and the tip of the weigh) as being equal to the distance the man has walked which is incorrect. I think the length between the tip of the weigh and the ground needs to be accounted for as well (let's call that distance y), thus c = 60-b-y, though I am still not sure how to relate that
Okay so you're just having trouble finding a relation?
I mean I did try to plug it into a pythagorean identity, i.e (10^2) + (b+y)^2 = (60-b-y)^2, though after expanding I'm left with y+b=29.16 which is not different from what I've calculated in the picture and it doesn't provide me any convenient info for finding dy/dt
Yeah I think that's the most important part of this question
there's a pretty simple relation between the rate that the weight moves and the rate at which the man moves
and it has to do with the rope and the pulley
isn't that the supposedly that they change at an opposite rate? (when c increases b decreases at the same rate)
It's close but we're looking for the rate at which the length change so the direction of change is irrelevant
Found it!
Can't believe it was this simple
nice job
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probs a past paper
The key to solving this is using the rule that $log_b(a^c) = c \cdot log_b(a)$
MellowDramaLlama
how would i do that...
I'll give you the first log term
okok
$log_bx^{\frac{2}{3}} = \frac{2}{3} log_bx\\$
Now we know that $log_bx = 0.1$, so we get $\frac{2}{3}log_bx = \frac{2}{3}(0.1) = \frac{2}{3}\left(\frac{1}{10}\right) = \frac{2}{30} = \frac{1}{15}$
MellowDramaLlama
just do the same with the remaining terms and then add them all up
yep go for it!
i got 1/12 as my final answer
yep that's what I got too 🙂 Nice work
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Hey I need help with this word problem:
A man is 5 times as old as his son. Four years ago, the product of their ages was 52. Find their present ages.
Try to write the informations the problem gave using maths.
I dont think this this can be solved with the model method.
I don't know what you mean by "model method".
I will give a start point:
we know the man has some age in the present and his age is five times the age of his son. We could write this like:
(man's age) = (son's age)*5
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0 isnt real
It means nothing
Yes it represents nothing
But
It doesnt sct like a number either
what makes you think 0 isn't real?
It definitely acts like a number, it can be added and multiplied, etc
Sure it can! It just makes 0
you cant do log base 1, does that make 1 not real?
0 is a special number
in fact, it's incredibly special
Its nothing
What defines a number
Its represents nothing so its nothing
What level of education are you at?
Doesnt matter because youre just gonns judge me based on my answer to ur q
No I’m not
??~?~?~?~
lol wut? They said that to ask you where your education level is.
"Number" means many different things and it gets more complicated
Its irrelevant
It’s because as you go higher into math you will start thinking about what are numbers, and it’s called group theory
higher level math you do some deeper dives into properties of 0
actually it's relevant
Wheel theory :D
-1 is even less real then!
It’s perfectly valid to ask what are numbers
Math got theories
They certainly do!
in fact I would say it's the basis of a good math education. Question everything
why?
So what are numbers
Numbers are representations of quantities
I don’t think “numbers” themselves have a mathematical definition
0 represents nothing no quantity so nothing
But you could perhaps look at fields
It represents the lack of quantity
In a way, quantity itself would be poorly defined as well
Wait until you learn about the empty set lmao
real numbers are just elements in the unique ordered field that has the least upper bound property and contains the rational numbers
"Hey look in my hands, I have 0 dollars in my hand" holds out empty palm. It represents the lack of a quantity.
I mean, my bank tells me I have $0 in the bank, lol
Numbers themselves aren’t too useful, it’s what you can do with them
Ok that makes them useful
Makes sense
A set with no elements
Riht
Why u laughing st him? U said to question everything so he questioned your statement
It doesn’t change
It was a joke
No humor
Ig
0 is also special because if we multiplied it by anything we get 0
If you lack a sense of humor in mathematics, you would lose half the experience
But then 1 is also pretty special, because 1 multiplied by something gives you something
Yea
There are names for these
But I’m sure you’ll learn them down the line if you’re interested
Ok
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i just need a walk through and i’ll understand
form an eqn for y in terms of x
y = x + 5 + (green counters)?
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how did they conclude that $G$ is not commutative?
well known fact about S_3
oh i see okay
try to find two elements in S_3 with ab != ba
like, swapping the first two elements and then swapping the last two gives a different result then swapping the last two and then the first two is what you are trying to say right?
like
[
(1 2)(2 3) = (1 3 2)\
(2 3)(1 2) = (1 2 3)
]
those products are wrong
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oh?
you have to do them from the right
you plug stuff in on the right and then evaluate step by step
(12)(23) [1] = (12)[1] = 2
where I use [] for evaluation brackets
(12)(23)[2] = (12)[3] = 3
(12)(23)[3] = (12)[2] = 1
so 1->2, 2->3, 3->1, ie. (123)
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Lixera is now white 
whitewashed 
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For a i ve to find intersection point of plane and line and this is my solution is this correct?
@gusty plume Has your question been resolved?
<@&286206848099549185>
euuh qu'est-ce que t'entends par 3d-2 ? @gusty plume
parce que d c'est le nom d'un plan
3 fois un plan je vois moyen ce que ça veut dire
ah ok c'est pour les points du plan l'équation paramétrique
donc c bon?
oui c'est ok
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merci bcp et j avais encore une 2eme question
yup
c possible d'avoir les reponses different quand on cherche l'intersection entre plan et droite
il y a plusieurs scénarios possible ouep
cmt ca se fait car ils s'intersect en un point nn?
ça dépend
quand t'as 2 droites en 2d, si elles sont parallèles (et pas identiques) t'as 0 intersection par exemple
oui logique
là c'est un peu pareil
- soit ta droite est pas parallèle au plan, là t'as une seule intersection
- soit ta droite est parallèle au plan
- si ta droite est contenue dans le plan, l'intersection c'est la droite entière
- sinon t'as 0 intersection (parallèle mais pas dedans)
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