#help-17

1 messages Β· Page 31 of 1

pulsar scroll
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nice

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what do u need for uni

zinc sequoia
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r u edecel too

pulsar scroll
#

nah OCR

zinc sequoia
#

2 Astars one A but im aiming for as high as posible

pulsar scroll
#

damn

zinc sequoia
#

actually 2 Astars 2 A's

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wbu

pulsar scroll
#

A*AAA for my firm

zinc sequoia
#

cool what degree

pulsar scroll
#

CS

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u?

zinc sequoia
#

Maths

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haha

pulsar scroll
#

ah nice

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may I ask where?

zinc sequoia
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havent decided yet got till June 8th i knwo its last minute

pulsar scroll
#

haha nws

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whats the dilemma

zinc sequoia
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distance

pulsar scroll
#

they must be pretty selective unis tho if you need 2 A*

zinc sequoia
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tbh atm im most focused on getting a good grade in econ

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essay subjects arent my favourite

pulsar scroll
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lmao

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yh I havent written an essay since GCSE

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hated em

zinc sequoia
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fair enough i gotta get back ti my revision lmao gl with your exams

pulsar scroll
#

same take care bro

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thanks for ur help

vocal sleetBOT
#

@pulsar scroll Has your question been resolved?

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steady heart
#

Hello, I am trying to practice more with problems like this one, involving 3D dimensions and using concepts like, trigonometric ratios with right angle triangles and sine and cosine law. Does anyone know where I can find challenging problems like these?

autumn sleet
steady heart
#

Can't send images there

autumn sleet
#

Send a link to this image?

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Or just the text of the question, as its enough to understand what kind of questions you are looking for

spiral inlet
#

Where did this even come from? That "prince" looks like it was ripped from a political cartoon lol

steady heart
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My teacher made it lol

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She didnt give any similar questions though and I can't find any.

pallid zenith
steady heart
#

<@&286206848099549185>

vocal sleetBOT
#

@steady heart Has your question been resolved?

vocal sleetBOT
#

@steady heart Has your question been resolved?

vocal sleetBOT
#

@steady heart Has your question been resolved?

vocal sleetBOT
#

@steady heart Has your question been resolved?

outer warren
#

you don't really need specific matching examples

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these types of problems are just a combination of smaller problems

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i.e. two right triangle trig problems
and an application of cosine rule

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focus on understanding the basics, which are applicable to such problems
that way regardless of how the problem is structured, you'd be able to do it

vocal sleetBOT
#

@steady heart Has your question been resolved?

lavish sluice
#

chapter of trigonometric distances or smthn

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sudden cloud
#

Hi does anyone know where the teacher got 3/18 from?

kind estuary
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-B/A

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(Ax^3+Bx^2+Cx+D)

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-B/A is the sum of the roots of the cubic equation

sudden cloud
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OH MY GOSH

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THANK YOU SO MICH

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IVE BEEN STUCK ON IT

kind estuary
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haha np

sudden cloud
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Bro i was like is this man pulling numbers out his ass

kind estuary
#

lmao

sudden cloud
#

Ty again

#

.close

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fierce prairie
vocal sleetBOT
fierce prairie
#

Simplify

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The answer I got is p^5/6q^7

paper depot
#

looks incorrect on many counts

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do you have work to show for how you got that?

vocal sleetBOT
fierce prairie
paper depot
#

$\frac{p^7}{p^{-2}} \neq p^5$

twin meteorBOT
#

Ann (glomed)

paper depot
#

and likewise $\frac{q^{-2}}{q^{-5}} \neq q^{-7}$

twin meteorBOT
#

Ann (glomed)

paper depot
#

and also $\frac{-3}{2} \neq \frac{1}{6}$

twin meteorBOT
#

Ann (glomed)

fierce prairie
#

πŸ’€

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Wait what should the actual answer be? I’ll try figure it out

paper depot
#

we dont give out answers

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you should think about this yourself first

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think about exponent laws

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as well as addition and subtraction of integers

fierce prairie
#

OH WAIY I SEE

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πŸ’€πŸ’€πŸ’€

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I’ll send my new answer

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P^9 q^3 /6

paper depot
fierce prairie
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?

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Can I move the 2 up?

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So it can be

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6p^9q^3

paper depot
#

can you transmogrify 3/2 into 6?

fierce prairie
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No

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πŸ’€πŸ’€πŸ’€

paper depot
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yeah so

fierce prairie
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Yes

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Oh I see

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2p^9q^3/3

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πŸ’€πŸ’€???

paper depot
#

πŸ’€

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you forgor the minus ☠️

fierce prairie
#

-2p^9q^3/3?

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Wait hold on

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You can’t do that I think because all indices have to be positive?

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πŸ’€πŸ’€?

paper depot
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btw why did the two and three switch places

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You can’t do that I think because all indices have to be positive?

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tell me: do you know what an index is

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the way you're referring to them

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bc i think you've broadened the scope of that too much in your head

fierce prairie
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WAIT OH

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πŸ’€

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So the answer is literally just

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-3p^9q^3/2

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because only indices have to be positive

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Oh my god πŸ€¦πŸ»β€β™€οΈπŸ€¦πŸ»β€β™€οΈπŸ€¦πŸ»β€β™€οΈ

vocal sleetBOT
#

@fierce prairie Has your question been resolved?

vocal sleetBOT
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β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

viscid mantle
#

if cosec x + cot x =y, find value cosec x -cot x

viscid mantle
#

i am confused right from the start

merry python
viscid mantle
#

yes

merry python
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what is it?

viscid mantle
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cosec^2(x- cot ^2(x=1

merry python
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Yes

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It is in the form a^2-b^2

viscid mantle
#

how do i introduce square then?

merry python
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can you factor?

viscid mantle
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yes

merry python
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difference of squares

viscid mantle
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a^2-b^2=

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a-b)^2 + 4ab

merry python
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Noo

viscid mantle
#

then?

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a+b)* (a-B

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?

merry python
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a^2-b^2=(a+b)(a-b)

viscid mantle
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oh

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but this one is also there right?

viscid mantle
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is it correct ass well?

merry python
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+2ab

viscid mantle
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oh

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ok

merry python
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so (cosec(x)+cot(x))(cosec(x)-cot(x))=1

viscid mantle
#

oh

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i get now

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ok thanks

viscid mantle
merry python
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(a-b)^2+4ab = a^2+b^2-2ab+4ab=a^2+b^2+2ab=(a+b)^2

viscid mantle
#

oh

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sad life i wrote it as 4 ab in my test yesterday

#

.close

vocal sleetBOT
#
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gusty berry
vocal sleetBOT
gusty berry
#

how do we approach these types of questions

paper depot
#

true to your pfp there

#

that response would have evoked a gigachad react from me

ripe forge
#

use simplest equation to adjust with others

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you'll catch similarities

merry python
vocal sleetBOT
#

@gusty berry Has your question been resolved?

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Remember:
β€’ Ask your math question in a clear, concise manner.
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sharp steppe
#

Need help with this sum. This is the second half of the question but I don't think the first half is necessary. Answers say A and B are 4 and 3 respectively. Please ping me πŸ™

languid berry
#

could you share the first half

errant briar
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First half is required

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@sharp steppe

languid berry
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not enough context without first half

sharp steppe
#

One sec

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@languid berry

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It's number 6

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The question, I mean

languid berry
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did you solve part a

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@sharp steppe

sharp steppe
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Yes

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a and d were 7 and 4 respectively

errant briar
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Write the general term

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And then take sigma

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And compare a and b

sharp steppe
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What is this general term, if you don't mind me asking?

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If you mean the formula for Sn

errant briar
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a_n = 7+(n-1)Γ—4

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a_n = 3+4n

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a=4, b=3

sharp steppe
#

One sec

sharp steppe
#

If I'm understanding things right

errant briar
#

Yes

sharp steppe
#

Aha

#

Thanks a lot

#

I'll close the channel

#

.close

vocal sleetBOT
#
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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
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β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

timber tangle
#

I need help on the last two questions
It uses Trigonometry

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
timber tangle
#

2

vocal sleetBOT
#

Show your work, and if possible, explain where you are stuck.

ripe forge
#

i guess we use calculators,

what have you done

timber tangle
#

Well, i do know to find x, you'll need to label the rectangle, C=D is opposite, am I right?

ripe forge
#

no, just angles are equal

timber tangle
#

ah

ripe forge
#

btw

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which one are you asking

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rectangle or right triangle

timber tangle
#

rectangle

ripe forge
#

oh sorry

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yes it is dividing it by 2

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lemme draw

timber tangle
#

yes please thanks

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You'll need to label the sides whether it is opposite, hypotenuse or adjacent then you'll know which trig equation to use-

ripe forge
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since there are right-angle triangles in there

timber tangle
#

oh

ripe forge
#

uh wait

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this is trickier than i thought

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call the center O

dot i mean

timber tangle
#

welp

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how?

ripe forge
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firstly you should find OA, right?

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then OC

timber tangle
#

how will that help tho-

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ohh

ripe forge
#

do you know cosine theorem

timber tangle
#

yes.

ripe forge
#

i think you saw this

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the path

timber tangle
#

ah

#

so

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are you meant to label it or what-?

ripe forge
#

could you find the value of bisect sides

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you know angle and value of 1 side

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by cosine theorem

timber tangle
#

wdym?

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sorry I don't understand-

ripe forge
#

i am dumb

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wait

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solve for x by using cosine theorem

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took me 10 mins to realize

languid berry
#

wut

languid berry
#

much simpler

ripe forge
#

true

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lmao

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i dont use calculator ever

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didnt think of it

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πŸ₯² im embarrased

languid berry
#

oh wait

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fair point

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@timber tangle r u allowed a calculator

ripe forge
#

i was going to show it by finding hypotenuse

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then use sin50 to derive the x

languid berry
#

use sin50 to derive the x?

ripe forge
#

i mean

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65

languid berry
#

doesnt calculation of sin 65 still require a calculator

ripe forge
#

ik

#

but i didnt think using tan there

#

so i was showing it by this way

languid berry
#

fair

vocal sleetBOT
#

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vocal sleetBOT
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Available help channel!

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honest spruce
vocal sleetBOT
honest spruce
#

can someone help me pls

vocal sleetBOT
#

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

devout urchin
vocal sleetBOT
devout urchin
#

equation is wrong

#

.close

vocal sleetBOT
#
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Remember:
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pearl halo
#

so i was reviewing some notes for a test next week, and i was on the confidence interval for variance comparison tests

twin meteorBOT
#

Pokerface.exe

pearl halo
#

i understand F means the snedecor f-distribution, but just to re-understand: how do i get Finf and Fsup?

#

what specific values do those pinpoint to?

pearl halo
#

<@&286206848099549185>

vocal sleetBOT
#

@pearl halo Has your question been resolved?

pearl halo
#

is it related to the significance value?

#

<@&286206848099549185>

flat whale
pearl halo
#

.close

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

merry python
#

<@&268886789983436800>

lost yarrow
#

.close

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Available help channel!

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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
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fringe venture
vocal sleetBOT
fringe venture
#

how do you work a i

tranquil silo
fringe venture
#

i dont have the solutions

tranquil silo
#

Oh nvm

fringe venture
#

these are papers the professopr has given to us to solve

#

for our exam

dark field
#

Hint: The corresponding complementary event is "There are some passenger(s) who turn up cannot get a seat". Then when will this happen?

fringe venture
#

if they all come then is the probabilty 0

#

im confused

#

drop the answer maybe i could work back to front

#

@dark field Can you help me

#

<@&286206848099549185> can someone help

normal mango
vocal sleetBOT
#

@fringe venture Has your question been resolved?

fringe venture
#

then what do you do after that

normal mango
#

Then you notice that either "everybody gets their seat" or "someone doesn't get their seat". Which means that P(everybody gets their seat) + P(someone doesn't get their seat) = 1

#

And since "someone doesn't get their seat" happens only when all passengers come, that means that :

P(everybody gets their seat) = 1 - 0.7^9

vocal sleetBOT
#

@fringe venture Has your question been resolved?

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vocal sleetBOT
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Available help channel!

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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

near vigil
#

when i apply Lhopital's rule to the left side, do i also have to differentiate the right side?

near vigil
#

.close

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Remember:
β€’ Ask your math question in a clear, concise manner.
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β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

grizzled bear
#

Why aren't these equal

vocal sleetBOT
grizzled bear
#

,rotate

twin meteorBOT
vast shale
grizzled bear
#

But... This is dynamics

hasty pulsar
#

since when was dynamics no physics

grizzled bear
#

Since when didn't dynamics belong to maths

hasty pulsar
#

because it isnt math

bleak zinc
#

iirc isn't m*v momentum

hasty pulsar
#

yes

bleak zinc
#

then that's why they're not equal

grizzled bear
karmic imp
#

Mechanics is more physics related than math

grizzled bear
bleak zinc
#

i think so

vast shale
#

f=ma is only true for constant acceleration and mass

#

yes what toby said

#

otherwise you are dealing with complicated differential equations

grizzled bear
#

I thought f = ma, but it seems the actual definition is rate of change of momentum, which is ma when m or a is constant, so ig I should always do dH/dt

grizzled bear
#

Ok thanks for help, ig I will try to utilize the original definition of whatever I want to find instead of the written rule

karmic imp
#

This server, most people are pure maths or applied maths, like linear algebra, calculus, etc, while physics uses those concepts. There are some people who knows physics but it ne more limited compared to math concepts

vocal sleetBOT
#

@grizzled bear Has your question been resolved?

vocal sleetBOT
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vocal sleetBOT
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Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

crystal meadow
#

hello can someone help me with this

vocal sleetBOT
crystal meadow
#

i understood this much but i ain't getting the answers :/

vast shale
#

,rccw

twin meteorBOT
vast shale
#

ok so

#

you set up the ratios correct

#

now instead of x + y + z = 100

#

you want to rewrite it in terms of one variable

crystal meadow
#

Oeh

vast shale
#

solve for that variable

#

and substitute back using those ratios

crystal meadow
#

like we take the sum of x + y + z as a variable ?

vast shale
#

no no

#

rewrite y and z in terms of x

#

for example

crystal meadow
#

oeh like x =100 - y - z

vast shale
#

no no

#

you know that x = y/2

#

rearrange that so you get y = 2x

crystal meadow
#

yeah

vast shale
#

similarly, x = 2z so z = x/2

crystal meadow
#

Oehh yeah i tried doing it i didn't get the asnwer for for reason

vast shale
#

now you can write x + y + z = 100 as x + 2x + x/2 = 100

#

solve for x

crystal meadow
#

we get 7x = 50

#

i have to get these as the answers

crystal meadow
vast shale
#

it shouldnt be 7x = 50

#

lol

#

how'd you get that

crystal meadow
#

wot

vast shale
#

its 7x = 200

#

therefore x = 28.57 as shown in the answer

crystal meadow
#

Oh sht

#

LMAO

#

I was diving the 2 with 100 instead of multiplying

#

πŸ’€

#

thanks for the help lol

#

gah damn i was like what the heck am i doing wrong all this time

#

and didn't see that

vast shale
#

haha

#

mistakes happen

crystal meadow
#

.close

vocal sleetBOT
#
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rugged silo
#

Algebra 1 question

vocal sleetBOT
rugged silo
#

the question is 12xΒ²+13x=5x

#

the solutions are 0,β…” or 0,-β…”

#

I need to know how to solve it with the quadratic formula

crystal meadow
#

is it 5 or 5 x

rugged silo
#

5x

crystal meadow
#

oh

rugged silo
#

so I minus 5x

#

12xΒ²+8x=0

#

A=12
B=8
C=0

#

thats all right?

vast shale
#

yeah

rugged silo
#

ok so now lemme plug it in

vast shale
#

do you have to solve it using the formula, because there is a quicker way

vast shale
#

ok then

rugged silo
#

or do I use the completing the square method..

crystal meadow
#

ye i got 0 , 2/3 or -2/3

#

use the quadractic formula

rugged silo
#

alr

vast shale
#

you can use formula

#

but personally i'd just factor the x out

rugged silo
#

dont mind the bad hand writing

#

but is this right

vast shale
#

yeh

ornate ember
rugged silo
#

lets goo

#

alr

crystal meadow
rugged silo
#

lemme solve some stuff and I'll show u what I got so far

crystal meadow
#

i too only got -2/3 but maybe

empty frigate
rugged silo
#

I feel like this is wrong

vast shale
#

why is it wrong

#

sqrt64 is 8

crystal meadow
empty frigate
#

that's correct, but it can be simplified more

rugged silo
#

ik

#

the sqrt is 8

empty frigate
#

yep

rugged silo
#

but now I have this

vast shale
#

so its either 0 or -16/24 which simplifies to -2/3

rugged silo
#

OHHHH

#

bruhhh

#

thats what I forgot

#

the minus

#

im so dumb

#

so the solution

#

is indeed

#

0,-β…”

midnight apex
#

Actually, plug them back in and double check

#

Sometimes, we get extraneous solutions

crystal meadow
vast shale
#

just dont use quadratic formula, ez
x(12x+8) = 0 therefore x = 0, x = -8/12 = -2/3

rugged silo
#

I think

rugged silo
#

all I pretty much know is the formula

crystal meadow
#

im studying algebra too its not that hard but i keep makin stoopid mistakes

rugged silo
#

plus

#

I think all i can use

#

wait

#

no

#

but if I use that formula

#

the entire final test

#

I should get every solution right

#

just as long as I simplify it right

midnight apex
#

Wait

#

weneed

#

do you have to use the formula, or can you use other ways?

vast shale
rugged silo
#

I can use other ways which like

midnight apex
#

If you're preparing for a test, you should also know other methods to save your time. The quadratic formula is kind of slow

midnight apex
#

If you can factor it, factor it

vast shale
#

2 hours on a quadratics test πŸ’€

midnight apex
rugged silo
#

is 2 hrs bad?

rugged silo
midnight apex
vast shale
#

depends, 2 hours on purely quadratics is a bit much

crystal meadow
#

better get back to studyin then πŸ’€

rugged silo
midnight apex
vast shale
#

yeah you have plenty of time

rugged silo
#

I think 2 hrs is just enough

midnight apex
#

And worry about extraneous solutions too

rugged silo
#

each question should take me 5

vast shale
#

assuming all 30 questions is solving quadratic equations, you'll be more than fine with 2 hours

crystal meadow
#

what's extraneous

midnight apex
rugged silo
#

im just a freshman sir 😭

#

ohhh

midnight apex
#

Yeah

vast shale
#

freshman too

midnight apex
#

They teach extraneous solutions in freshmen / algbera 2

vast shale
#

in college 😎

rugged silo
#

well its good to always double check

rugged silo
midnight apex
rugged silo
#

its been a experience

midnight apex
#

If it's not, then... it's an extraneous solution πŸ™‚

rugged silo
#

in order to use the quadratic formula

#

it NEEDS

crystal meadow
#

ah i see

rugged silo
#

to equal 0

crystal meadow
#

so if we do get an extraneous solution

#

what do we do ?

midnight apex
#

Well, when you're finding the solutions. And it's an "extraneous" solution (which just means that you have PUt that value of x into the equation and it DIDN'T become 0), you say "it's not a solution"

#

or like "there's only one solution, it's this:"

empty frigate
#

...wait does the quadratic formula ever actually produce extraneous solutions?

midnight apex
rugged silo
#

im just nervous

#

tbh

#

😭

midnight apex
#

@empty frigate actually, does it? I don't know for sure

rugged silo
#

there is also gonna be questions on finding the vertex

#

and

vast shale
#

when using quadratic formula i never check for extraneous solutions lol

rugged silo
#

x and y values

#

on a graph

vast shale
#

i doubt quadratic formula ever produces extraneous solutions

rugged silo
#

no

#

bc its always right

vast shale
#

unless a domain is specified or whatever

rugged silo
#

the values just gotta be right

#

im worried I might fail the final tho

vast shale
#

keep practicing

#

you got this

rugged silo
#

u right

#

also on a solution

#

like -5(x+6) - 2

#

and it asks for the maximum or minimum

#

its a maximum

midnight apex
#

@vast shale What are you majoring in at uni and how it is going

rugged silo
#

right?

#

the sign on the first number

#

determines the max or min

#

right?

vast shale
#

going great

midnight apex
#

Danggg

#

that's so cool

#

I'm planning on going into CS as my major and math as minor

rugged silo
#

also

#

the completing the square method

vast shale
rugged silo
#

is b/2

vast shale
#

so yeah it can tell you whether it has a max or min point

rugged silo
#

squared

#

negative means max

vast shale
#

i'm considering minoring in cs

rugged silo
#

positive means min

#

?

midnight apex
#

sounds good

#

at it makes sense

vast shale
midnight apex
#

if it's negative, it'll go down. So it will have a "max" and not a "min"

rugged silo
#

I'll remember that

#

also

midnight apex
#

no no wait

#

Don't remember it

rugged silo
#

negative goes up

midnight apex
#

Just think about it

rugged silo
#

I think

midnight apex
#

it makes sense

rugged silo
#

πŸ’€

vast shale
#

negative faces down

midnight apex
rugged silo
#

you cant have a max really

#

if it goes down

midnight apex
#

?

rugged silo
#

it does??

midnight apex
#

you mean a min?

rugged silo
#

ohhh

#

MBBB

#

lmao

midnight apex
#

it can't have a min but a max yes

rugged silo
#

For what value(s) of x does f(x)=2 on a graph

#

x=-1 and x=1

#

and y=2

vast shale
#

well idk what the function is but yeah just find the points of x when y is 2

rugged silo
#

right

#

also

#

a square root cancels out a square ( )Β²

#

right?

vast shale
#

yes

rugged silo
#

ok

#

so I just gotta keep on reviewing this stuff

midnight apex
#

🫑

rugged silo
#

I have one more night to study

#

wish me luck

vast shale
#

good luck

midnight apex
#

gl homie

vast shale
#

you got this

rugged silo
#

Goodnight guys ty for all the help

vast shale
#

yw

rugged silo
#

.close

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#
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gray spruce
#

idk how to explain or prove

paper depot
#

write out all the multiples of 79 below 1000 and see if any of them has a multiple of 41 two units below

#

or a multiple of 19 one unit below

#

i'm assuming GPF stands for greatest prime factors as i remember seeing this EXACT question (with these particular numbers) a few days ago.

gray spruce
#

how would u explain ?

#

ye

paper depot
#

because the idea i am promoting here is to rule out all possibilities of the third number in your sequence being less than four digits long

#

i.e. less than 1000

gray spruce
#

ic

vocal sleetBOT
#

@gray spruce Has your question been resolved?

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#
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

obtuse nest
#

Hi Math fellows, a quick question about absolute/relative maxima/minima of a func.
In following graph, the hole(point) at (1,2) could be an absolute/relative maxima?

brisk moss
#

if there was a relative maximum at 1, that would mean you can find an interval around 1 where the function values are all less than or equal to f(1)

#

is there such an interval?

#

similarly...
if there was a relative minimum at 1, that would mean you can find an interval around 1 where the function values are all greater than or equal to f(1)

obtuse nest
#

So based on definition given, as left limit of x=1 is not equal to right limit and f(1), then this means a hole in a graph like above is not a relative/absolute max/min?

brisk moss
#

no, that is not always the case

brisk moss
brisk moss
obtuse nest
brisk moss
# brisk moss

in the green interval, all the function values are bigger than f(1)

#

so it has a local min there

#

or relative min whatever you wanna call it

obtuse nest
#

Great, so in original question, the same story, (1,2) could be a relative/abs maxima it it was a point not a hole

brisk moss
#

well...

#

(1,2) is not in the graph of the function

#

so your question doesn't really make sense

#

is there an original question that yours is based off?

obtuse nest
brisk moss
#

ok yes that would have a local max at 1

#

and absolute max

obtuse nest
#

Now it makes sense, I really really appreciate your time explained this, math bless us all.

brisk moss
#

haha np :)

obtuse nest
#

.close

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#
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outer warren
#

its asking you to solve an equation

fluid ivy
#

let me rephrase ik its asking for zeroes

#

i dont know how u even start approaching it*

outer warren
#

factorise

fluid ivy
#

how

stiff pumice
#

Take cos common

#

Outside bracket

outer warren
#

the same way you'd approach the factorisation of anything else

stiff pumice
#

Then equate the the two product constituents to 0

outer warren
#

first identify if there are factors common in both(all) terms,
and if such factors exist, factor them out

fluid ivy
#

common factor would be the 4 right?

outer warren
#

4 is common factor yes,
you can first factor that out
and then continue to search for more

fluid ivy
#

what else is there outside of 4?

outer warren
#

take a harder look

#

don't overthink

#

would you be able to factorise something like
6p + 9pq

outer warren
#

yes, same idea for what you have

fluid ivy
#

i take out x...?

outer warren
#

no

#

2sin(x) is just the product of 2 and sin(x)

#

2sin(x)cos(x) is the product of 2, sin(x) and cos(x)

#

sin, cos aren't values being multiplied to x

#

4sqrt(3)cos(x) is the product of 4, sqrt(3) and cos(x)

fluid ivy
#

i take out 2 cos(x)?

outer warren
#

8sin(x)cos(x) is the product of 8,sin(x) and cos(x)

#

try factoring that out and see what you get

#

and show me

fluid ivy
#

2cos(x) (sin(x) 2sqrt3) ?

outer warren
#

no

#

how are you getting that

fluid ivy
#

i dont know man i give up, being up at 4:30am reviewing is just gonna drive me insane

outer warren
#

would you be able to factorise something like
$$4\sqrt{3}p - 8pq$$

twin meteorBOT
#

ℝamonov

fluid ivy
#

4p (root3 - 2q)

outer warren
#

and the idea is exactly the same for what you have,
i just used p and q instead of cos(x) and sin(x)

fluid ivy
#

the math aint mathing, thanks for trying to salvage my dumpster fire of a brain

outer warren
#

$4\sqrt{3}\red{\underbrace{\cos(x)}{p}} - 8\red{\underbrace{\cos(x)}{p}}\blue{\underbrace{\sin(x)}_{q}}$

twin meteorBOT
#

ℝamonov

fluid ivy
#

ur supposed to treat 8cos(x)sin(x) as one unit?

outer warren
#

well yeh...

fluid ivy
#

so its cos(x) (4roo3 - 8sin(x))

#

root3*

outer warren
#

the same way you treated 8pq

#

and the idea is exactly the same for what you have,
i just used p and q instead of cos(x) and sin(x)

fluid ivy
#

oh yeah

#

forgot

#

so its 4cos(x) (root3 - 2sin(x))

outer warren
#

yes

fluid ivy
#

ok noice

#

thanks for helping me review factoring trig stuff

#

gn πŸ‘‹

vocal sleetBOT
#
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rustic junco
#

How do I solve d^2 = t^2 -7t+16 (t = x^2) without complex numbers?

rustic junco
#

I actually don't know why it's giving me complex numbers because it should work...

outer warren
#

what's the original question

rustic junco
#

distance

#

wait lemme write it

#

d = sqrt( x^2 + (x^2-4)^2 )

solid sage
#

was there words that the question had

outer warren
#

show the original question

rustic junco
#

It's the general function to find the distance between parabola y=x^2 and point (0, 4)

outer warren
#

1 sec

rustic junco
#

Crap, maybe I needed to differentiate it?

#

I don't think so.. but

outer warren
#

i mean you pretty much already have it

urban edge
#

You still havent given us rhe original question

rustic junco
urban edge
#

Ah thought so

outer warren
#

oh.

solid sage
#

i think the question is what is the distance from the parabola to point

#

like the function

outer warren
#

always show the original question in its entirety asap

#

so people don't have to speculate and/or play a guessing game

rustic junco
#

sry

outer warren
#

before sub, you'd have
$$d = \sqrt(x^4 - 7x^2 + 16)$$
for the min you could do stuff like complete the square

twin meteorBOT
#

ℝamonov

rustic junco
#

The discriminant is negative

#

That's where I'm stuck

#

@outer warren What do you suggest?

outer warren
#

for the min you could do stuff like complete the square

rustic junco
#

What do you mean?

outer warren
#

complete the square is a well known term

rustic junco
#

Not to me. English isn't my first language.

outer warren
#

look that up

rustic junco
#

Thanks for the help

vocal sleetBOT
#

@rustic junco Has your question been resolved?

rustic junco
#

Hmm nvm that didn't work

twin meteorBOT
solid sage
#

i mean

#

if discriminant of something is negative just means the graph doesn't touch the x axis

#

what was your question again

rustic junco
#

Okay nvm I found the problem lol

#

I did need to differentiate.

#

I don't know why I thought I didn't need to at first

#

.close

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#
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brave remnant
#

I could only find the circle in the middle. thanks!!!

outer warren
#

show work

brave remnant
#

so radius = 4 ( middle one )
becuase the circle touches x = 0 and touches x = 8

#

so diameter = 8 units

outer warren
#

and whats your equation for that circle

brave remnant
#

4^2 = (x-4)^2 + (y-4)^2

outer warren
#

so what are the coordinates of the centre

brave remnant
#

(4,4)

outer warren
#

have you tried determining the radius of the outer circle

brave remnant
#

I can't find the value becuase it's not a whole number

#

I just looked at the graphs and see that it's in between two numbers

outer warren
#

show work

#

doesn't matter if the number is whole or not, its still a number

#

it still has a value

brave remnant
#

oh

#

how do I find it?

outer warren
#

show work

brave remnant
#

umm..

outer warren
#

I can't find the value becuase it's not a whole number
supposedly you did some work, that led to some non-whole number

brave remnant
#

oh nono

#

I just looked at the graph

#

like

outer warren
#

you have the centre,
and point(s) on the circumference

#

you can apply the distance formula

#

to determine the radius

brave remnant
#

what is the distance formular?

#

do you mean this one?

#

ohh

outer warren
#

yes

brave remnant
#

but I don't know the points on the circumference tho

outer warren
#

you are literally given them in the question

#

in fact for the outer circle, you are given 3 of them

#

you only need to use one of them for the calculation of the radius

brave remnant
#

oh

#

sorry

#

and then after I foudn the raduis of outer circle how do I find the inner circle?

#

do I use this

#

ohhhh

#

I understand

#

tysm for your help

#

.close

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#
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proud igloo
#

I found that both of these 2 formulas are used for the negative binomial distribution (pmf)

proud igloo
#

But they aren’t the same they give 2 different values…

vocal sleetBOT
#

@proud igloo Has your question been resolved?

vocal sleetBOT
#

@proud igloo Has your question been resolved?

vocal sleetBOT
#

@proud igloo Has your question been resolved?

vocal sleetBOT
#

@proud igloo Has your question been resolved?

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#
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soft flame
vocal sleetBOT
soft flame
#

I am a little confused on where to start

#

nvm I figured it out

#

.close

vocal sleetBOT
#
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normal peak
#

hey yall i got some linear algebra hw, and i only need to confirm the solution

normal peak
#

im given that this set is a basis of a vector space V

#

and im asked to show that

#

is also a basis of V

#

is this correct?

#

(ignore the greek and please tell me if you can't make out the image, ill try and take a better one )

#

any help would be greatly appreciated

worthy citrus
#

this is only a proof of linear independence right?

normal peak
#

oooohhh right

#

damn

worthy citrus
#

but it is a fine proof of it, showing all the c_n are 0

#

just also prove they span

normal peak
#

righttt how do i do that again?

worthy citrus
#

show you can write anything in the vector space as a linear combination of vectors in your list

normal peak
#

write im a bit rusty on that, ill do a quick google search and if im still confused ill ask for more details

#

thank you though in advance

#

so im looking at this

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do i have to set up the matrix and do gaussian elimination to find the dimension or is that unecessary

#

wait no nvm

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i just remembere dhow

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well thanks again

worthy citrus
#

whatever you do will end up basically being the same as setting up the matrix and reducing

#

because you are indeed just trying to see if a linear system always has solutions

normal peak
#

just find Cn such that the nth element of the each basis set is equal ?

worthy citrus
#

im not really sure what you mean by that

normal peak
#

uh im not really sure either now

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okie so

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right yeah i just dont know how to do that

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the vector space is V and i have to show that it's a linear combination of

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im sure it's simple i just dont see it

worthy citrus
#

take $v \in V$, you can write it as $\sum b_n a_n$

twin meteorBOT
#

Ξ£AC

worthy citrus
#

your c_n will depend on the b_i

normal peak
#

is that b_i / (b_{i-1}+b_{i})

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um

#

cause it would turn this

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wait what

#

im fried

#

i mean a_i

#

on a scale of 1 to 10 how much am i overcomplicating it

#

wait so

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In the EDIT of the first answer

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i quote

#

" if we have n independent vectors, they must span the vector space. "

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if only it's of dimension n

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so the only thing left is to show that V is of dimension n?

#

which is kind of obvious i guess? since there are n basis?

#

or is that not how that works

#

yo you there? @worthy citrus

worthy citrus
#

if you dont want to directly check

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maximal linearly independent sets are automatically spanning

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the dimension of a space is t he number of vectors in any basis yeah

normal peak
#

soo ill just say that dim(V)= n since there are n basis and get on with my life

#

i guess that is a yes

#

thank you again

#

.close

vocal sleetBOT
#
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woeful ember
#

Hello, why is this the solution? I don't really know how to calculate the conditional expectation

karmic imp
#

Someone else took this channel just before you did, you need to open a different one

granite fossil
#

yeah i saw my bad

woeful ember
#

all good πŸ™‚

#

.close

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#
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bronze vector
#

(x+3y)^5 pascals triangle

vocal sleetBOT
bronze vector
#

im stuck on the 3y, when do i have to multiply

#

i also dont know where to put the exponents

#

i have this so far

karmic imp
#

,rotate

twin meteorBOT
serene parrot
#

don't understand what the problem is

frozen bobcat
bronze vector
#

oh wait i wrote that wrong sorry, lemme correct it

#

how would i simplify this

karmic imp
#

Recall that $(ab)^n = a^nb^n$

twin meteorBOT
#

dldh06

bronze vector
#

so would i put the exponent on the x as well?

karmic imp
#

I'm saying for your 3y, you have $(3y)^n$. If you apply what I stated above, the $(3y)^n = 3^ny^n$

twin meteorBOT
#

dldh06

karmic imp
#

n denotes the power

#

So you can expand those terms

bronze vector
#

wait so lemme write this out

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would the exponent always be 5?

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through out the who equation for each 3y?

#

or would the number -1 / +1 each time

karmic imp
#

You apply it for each term

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You have a term that is (3y)^2

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And a different one that is (3y)^3

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And so on

#

Apply the rule I stated above

bronze vector
#

ohhh

#

okok! wait ill write it out

karmic imp
#

Can you expand those terms? Like what is 3^2?

#

Or 3^3?

bronze vector
#

okok

#

this?

karmic imp
#

You can expand that more, like 5(x^4)3y, you can do 5 * 3, correct?

bronze vector
#

ill try

#

is this correct?

karmic imp
#

How did you get 9 for the 3rd term?

bronze vector
#

oh wait sorry that should be 9-

#

90**

karmic imp
#

And that should be it

bronze vector
#

perfect! ur an angel tysm

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
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velvet cove
#

yo

vocal sleetBOT
velvet cove
#

is it possible to factor $a^2-b^2-c^2$

twin meteorBOT
velvet cove
#

.close

vocal sleetBOT
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slate schooner
#

where does the 4x^3, 3x^2y and -y^2 come from?

slate schooner
#

Original

#

I get the greatest common factor being 2xy^2

hushed willow
#

then whats wrong

#

do the reverse

#

times in that bracket

#

with 2xy^2

#

and get the question

slate schooner
#

ohhhh I see

#

so just do whatever is needed to multiply by the GCF to equal the original expression

#

thanks

#

.close

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#
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iron crown
vocal sleetBOT
iron crown
#

Not sure how to solve for theta

#

was told that theta != arctan (-2) so im lost

thin vale
#

that is because arctan has a domain restriction

twin meteorBOT
#

AustinU

thin vale
#

tangent is opposite over adjacent (SOHCAHTOA ?)

#

so either, the opposite side length is negative

#

or the adjacent side length is negative

#

this puts you in two situations

#

-2/1

#

or 2/-1

#

which puts you in two different quadrants

#

and arctan, will only give you the resulting angle for one of the quadrants, because it wants to be a function

#

so, it's your job to know what quadrant you are actually in, so you may shift the angle accordingly, if arctan lies to you

iron crown
#

Wouldn't it be that either the opposite side length is negative or the HYPOTENUSE side length is negative?

#

Since we're looking at tangent O/H

thin vale
#

tan= opp / adj

#

TOA

#

SOHCAH TOA

iron crown
#

πŸ™‚ true

thin vale
#

I wrote it wrong originally, my bad if that threw you off haha

iron crown
#

Well our original coordinate gave us a -x and a positive y, so it must be that we are in the 2nd quadrant in the xy-plane, correct? So it is 2/-1

#

How do I know by how much to shift arctan to correct the angle

thin vale
#

arctan's restricts you to [-pi/2, pi/2]