#help-17
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r u edecel too
nah OCR
2 Astars one A but im aiming for as high as posible
damn
A*AAA for my firm
cool what degree
havent decided yet got till June 8th i knwo its last minute
distance
they must be pretty selective unis tho if you need 2 A*
tbh atm im most focused on getting a good grade in econ
essay subjects arent my favourite
fair enough i gotta get back ti my revision lmao gl with your exams
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Hello, I am trying to practice more with problems like this one, involving 3D dimensions and using concepts like, trigonometric ratios with right angle triangles and sine and cosine law. Does anyone know where I can find challenging problems like these?
Perhaps ask #book-recommendations ?
Can't send images there
Send a link to this image?
Or just the text of the question, as its enough to understand what kind of questions you are looking for
Where did this even come from? That "prince" looks like it was ripped from a political cartoon lol
My teacher made it lol
She didnt give any similar questions though and I can't find any.
<@&286206848099549185>
@steady heart Has your question been resolved?
@steady heart Has your question been resolved?
@steady heart Has your question been resolved?
@steady heart Has your question been resolved?
you don't really need specific matching examples
these types of problems are just a combination of smaller problems
i.e. two right triangle trig problems
and an application of cosine rule
focus on understanding the basics, which are applicable to such problems
that way regardless of how the problem is structured, you'd be able to do it
@steady heart Has your question been resolved?
check class 10 ncert
chapter of trigonometric distances or smthn
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Hi does anyone know where the teacher got 3/18 from?
haha np
Bro i was like is this man pulling numbers out his ass
lmao
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Show your work, and if possible, explain where you are stuck.
$\frac{p^7}{p^{-2}} \neq p^5$
Ann (glomed)
and likewise $\frac{q^{-2}}{q^{-5}} \neq q^{-7}$
Ann (glomed)
and also $\frac{-3}{2} \neq \frac{1}{6}$
Ann (glomed)
we dont give out answers
you should think about this yourself first
think about exponent laws
as well as addition and subtraction of integers
keep this in mind too
can you transmogrify 3/2 into 6?
yeah so
-2p^9q^3/3?
Wait hold on
You canβt do that I think because all indices have to be positive?
ππ?
btw why did the two and three switch places
You canβt do that I think because all indices have to be positive?
tell me: do you know what an index is
the way you're referring to them
bc i think you've broadened the scope of that too much in your head
WAIT OH
π
So the answer is literally just
-3p^9q^3/2
because only indices have to be positive
Oh my god π€¦π»ββοΈπ€¦π»ββοΈπ€¦π»ββοΈ
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if cosec x + cot x =y, find value cosec x -cot x
i am confused right from the start
Do you know the relation between cosec^2(x) and cot^2(x)
yes
what is it?
cosec^2(x- cot ^2(x=1
how do i introduce square then?
can you factor?
yes
difference of squares
Noo
a^2-b^2=(a+b)(a-b)
so (cosec(x)+cot(x))(cosec(x)-cot(x))=1
are u sure but?
(a-b)^2+4ab = a^2+b^2-2ab+4ab=a^2+b^2+2ab=(a+b)^2
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how do we approach these types of questions
try to multiply the equations
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Need help with this sum. This is the second half of the question but I don't think the first half is necessary. Answers say A and B are 4 and 3 respectively. Please ping me π
could you share the first half
not enough context without first half
What are the values of a and d
Write the general term
And then take sigma
And compare a and b
What is this general term, if you don't mind me asking?
If you mean the formula for Sn
One sec
Oh so in cases like this we're supposed to use the formula for nth term
If I'm understanding things right
Yes
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I need help on the last two questions
It uses Trigonometry
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
2
Show your work, and if possible, explain where you are stuck.
i guess we use calculators,
what have you done
Well, i do know to find x, you'll need to label the rectangle, C=D is opposite, am I right?
no, just angles are equal
ah
rectangle
yes please thanks
You'll need to label the sides whether it is opposite, hypotenuse or adjacent then you'll know which trig equation to use-
oh
do you know cosine theorem
yes.
could you find the value of bisect sides
you know angle and value of 1 side
by cosine theorem
wut
use sin50 to derive the x?
doesnt calculation of sin 65 still require a calculator
fair
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so i was reviewing some notes for a test next week, and i was on the confidence interval for variance comparison tests
Pokerface.exe
i understand F means the snedecor f-distribution, but just to re-understand: how do i get Finf and Fsup?
what specific values do those pinpoint to?
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how do you work a i
Before I give my solution, is it 0.16?
i dont have the solutions
Oh nvm
Hint: The corresponding complementary event is "There are some passenger(s) who turn up cannot get a seat". Then when will this happen?
if they all come then is the probabilty 0
im confused
drop the answer maybe i could work back to front
@dark field Can you help me
<@&286206848099549185> can someone help
But what is the probability that they all come?
@fringe venture Has your question been resolved?
0.7^9
then what do you do after that
Then you notice that either "everybody gets their seat" or "someone doesn't get their seat". Which means that P(everybody gets their seat) + P(someone doesn't get their seat) = 1
And since "someone doesn't get their seat" happens only when all passengers come, that means that :
P(everybody gets their seat) = 1 - 0.7^9
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when i apply Lhopital's rule to the left side, do i also have to differentiate the right side?
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Why aren't these equal
,rotate
there's a physics server in #old-network
But... This is dynamics
since when was dynamics no physics
Since when didn't dynamics belong to maths
because it isnt math
iirc isn't m*v momentum
yes
then that's why they're not equal
Mechanics is more physics related than math
And dH/dt = force no?
i think so
Newton's second law only works with constant mass https://en.wikipedia.org/wiki/Newton's_laws_of_motion#Second
f=ma is only true for constant acceleration and mass
yes what toby said
otherwise you are dealing with complicated differential equations
I thought f = ma, but it seems the actual definition is rate of change of momentum, which is ma when m or a is constant, so ig I should always do dH/dt
Idk man my physics teachers do electricity and light and stuff I never knew they can use integrals
Ok thanks for help, ig I will try to utilize the original definition of whatever I want to find instead of the written rule
Physics can apply math concepts
This server, most people are pure maths or applied maths, like linear algebra, calculus, etc, while physics uses those concepts. There are some people who knows physics but it ne more limited compared to math concepts
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hello can someone help me with this
,rccw
ok so
you set up the ratios correct
now instead of x + y + z = 100
you want to rewrite it in terms of one variable
Oeh
like we take the sum of x + y + z as a variable ?
oeh like x =100 - y - z
yeah
similarly, x = 2z so z = x/2
Oehh yeah i tried doing it i didn't get the asnwer for for reason
yeah i did that
wot
Oh sht
LMAO
I was diving the 2 with 100 instead of multiplying
π
thanks for the help lol
gah damn i was like what the heck am i doing wrong all this time
and didn't see that
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Algebra 1 question
the question is 12xΒ²+13x=5x
the solutions are 0,β or 0,-β
I need to know how to solve it with the quadratic formula
is it 5 or 5 x
5x
oh
yeah
ok so now lemme plug it in
do you have to solve it using the formula, because there is a quicker way
yes
ok then
or do I use the completing the square method..
alr
dont do that
you can use formula
but personally i'd just factor the x out
yeh
2/3 is not a solution.
i thought there's a + or - sign so
lemme solve some stuff and I'll show u what I got so far
i too only got -2/3 but maybe
well there is in the sense that the solutions are "1/3 +- 1/3"
I feel like this is wrong
nono its right
that's correct, but it can be simplified more
yep
but now I have this
so its either 0 or -16/24 which simplifies to -2/3
OHHHH
bruhhh
thats what I forgot
the minus
im so dumb
so the solution
is indeed
0,-β
Actually, plug them back in and double check
Sometimes, we get extraneous solutions
ye ye
just dont use quadratic formula, ez
x(12x+8) = 0 therefore x = 0, x = -8/12 = -2/3
I think
but rn
all I pretty much know is the formula
im studying algebra too its not that hard but i keep makin stoopid mistakes
plus
I think all i can use
wait
no
but if I use that formula
the entire final test
I should get every solution right
just as long as I simplify it right
sure
I can use other ways which like
If you're preparing for a test, you should also know other methods to save your time. The quadratic formula is kind of slow
I have 2 hrs
If you can factor it, factor it
2 hours on a quadratics test π
That was our final, like 16 pages?
is 2 hrs bad?
like 30 questions
all about finding zeros? damn
depends, 2 hours on purely quadratics is a bit much
better get back to studyin then π
like its good time?
But yes, just try to use other methods
yeah you have plenty of time
I think 2 hrs is just enough
And worry about extraneous solutions too
each question should take me 5
assuming all 30 questions is solving quadratic equations, you'll be more than fine with 2 hours
what's extraneous
Solutions that seem like the answer, but they're not
Yeah
freshman too
They teach extraneous solutions in freshmen / algbera 2
in college π
well its good to always double check
Oeh
first year of highschool
I'm doing matricies rn, it's fun
its been a experience
Yeah, so plug in the values and check if the equation IS zero
If it's not, then... it's an extraneous solution π
ah i see
to equal 0
Well, when you're finding the solutions. And it's an "extraneous" solution (which just means that you have PUt that value of x into the equation and it DIDN'T become 0), you say "it's not a solution"
or like "there's only one solution, it's this:"
...wait does the quadratic formula ever actually produce extraneous solutions?
No idea. but I'm saying for the whole test. Assuming they don't just use the formula all the time
@empty frigate actually, does it? I don't know for sure
when using quadratic formula i never check for extraneous solutions lol
i doubt quadratic formula ever produces extraneous solutions
unless a domain is specified or whatever
u right
also on a solution
like -5(x+6) - 2
and it asks for the maximum or minimum
its a maximum
@vast shale What are you majoring in at uni and how it is going
double majoring in math and economics
going great
Danggg
that's so cool
I'm planning on going into CS as my major and math as minor
the sign on the first term determines whether the quadratic is facing up or down
is b/2
so yeah it can tell you whether it has a max or min point
thats awesome
i'm considering minoring in cs
positive means there is a min yes
if it's negative, it'll go down. So it will have a "max" and not a "min"
negative goes up
Just think about it
I think
it makes sense
π
negative faces down
what? negative goes up? wdym
?
it does??
you mean a min?
it can't have a min but a max yes
well idk what the function is but yeah just find the points of x when y is 2
yes
π«‘
good luck
gl homie
you got this
Goodnight guys ty for all the help
yw
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idk how to explain or prove
write out all the multiples of 79 below 1000 and see if any of them has a multiple of 41 two units below
or a multiple of 19 one unit below
i'm assuming GPF stands for greatest prime factors as i remember seeing this EXACT question (with these particular numbers) a few days ago.
because the idea i am promoting here is to rule out all possibilities of the third number in your sequence being less than four digits long
i.e. less than 1000
ic
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Hi Math fellows, a quick question about absolute/relative maxima/minima of a func.
In following graph, the hole(point) at (1,2) could be an absolute/relative maxima?
if there was a relative maximum at 1, that would mean you can find an interval around 1 where the function values are all less than or equal to f(1)
is there such an interval?
similarly...
if there was a relative minimum at 1, that would mean you can find an interval around 1 where the function values are all greater than or equal to f(1)
Hi, I think the interval is supposed to be [0,2]
So based on definition given, as left limit of x=1 is not equal to right limit and f(1), then this means a hole in a graph like above is not a relative/absolute max/min?
no, that is not always the case
also i think you misunderstood
Hmm, so if hole and point get swapped, then 1 could be a relative max than?
yea sure in that picture
in the green interval, all the function values are bigger than f(1)
so it has a local min there
or relative min whatever you wanna call it
Great, so in original question, the same story, (1,2) could be a relative/abs maxima it it was a point not a hole
well...
(1,2) is not in the graph of the function
so your question doesn't really make sense
is there an original question that yours is based off?
I meant this, so x=1 could be a max now?
Now it makes sense, I really really appreciate your time explained this, math bless us all.
haha np :)
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its asking you to solve an equation
factorise
how
the same way you'd approach the factorisation of anything else
Then equate the the two product constituents to 0
first identify if there are factors common in both(all) terms,
and if such factors exist, factor them out
common factor would be the 4 right?
4 is common factor yes,
you can first factor that out
and then continue to search for more
what else is there outside of 4?
take a harder look
don't overthink
would you be able to factorise something like
6p + 9pq
3p(2+3q)
yes, same idea for what you have
i take out x...?
no
2sin(x) is just the product of 2 and sin(x)
2sin(x)cos(x) is the product of 2, sin(x) and cos(x)
sin, cos aren't values being multiplied to x
4sqrt(3)cos(x) is the product of 4, sqrt(3) and cos(x)
i take out 2 cos(x)?
8sin(x)cos(x) is the product of 8,sin(x) and cos(x)
try factoring that out and see what you get
and show me
2cos(x) (sin(x) 2sqrt3) ?
i dont know man i give up, being up at 4:30am reviewing is just gonna drive me insane
would you be able to factorise something like
$$4\sqrt{3}p - 8pq$$
βamonov
4p (root3 - 2q)
and the idea is exactly the same for what you have,
i just used p and q instead of cos(x) and sin(x)
the math aint mathing, thanks for trying to salvage my dumpster fire of a brain
$4\sqrt{3}\red{\underbrace{\cos(x)}{p}} - 8\red{\underbrace{\cos(x)}{p}}\blue{\underbrace{\sin(x)}_{q}}$
βamonov
ur supposed to treat 8cos(x)sin(x) as one unit?
well yeh...
the same way you treated 8pq
and the idea is exactly the same for what you have,
i just used p and q instead of cos(x) and sin(x)
yes
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How do I solve d^2 = t^2 -7t+16 (t = x^2) without complex numbers?
I actually don't know why it's giving me complex numbers because it should work...
what's the original question
what is d^2 ?
was there words that the question had
show the original question
It's the general function to find the distance between parabola y=x^2 and point (0, 4)
1 sec
i mean you pretty much already have it
You still havent given us rhe original question
Find the minimum distance
Ah thought so
oh.
i think the question is what is the distance from the parabola to point
like the function
always show the original question in its entirety asap
so people don't have to speculate and/or play a guessing game
sry
before sub, you'd have
$$d = \sqrt(x^4 - 7x^2 + 16)$$
for the min you could do stuff like complete the square
βamonov
The discriminant is negative
That's where I'm stuck
@outer warren What do you suggest?
for the min you could do stuff like complete the square
What do you mean?
complete the square is a well known term
Not to me. English isn't my first language.
look that up
Thanks for the help
@rustic junco Has your question been resolved?
Hmm nvm that didn't work
Uchi
i mean
if discriminant of something is negative just means the graph doesn't touch the x axis
what was your question again
Okay nvm I found the problem lol
I did need to differentiate.
I don't know why I thought I didn't need to at first
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I could only find the circle in the middle. thanks!!!
show work
so radius = 4 ( middle one )
becuase the circle touches x = 0 and touches x = 8
so diameter = 8 units
and whats your equation for that circle
4^2 = (x-4)^2 + (y-4)^2
so what are the coordinates of the centre
(4,4)
have you tried determining the radius of the outer circle
I can't find the value becuase it's not a whole number
I just looked at the graphs and see that it's in between two numbers
show work
doesn't matter if the number is whole or not, its still a number
it still has a value
show work
umm..
I can't find the value becuase it's not a whole number
supposedly you did some work, that led to some non-whole number
you have the centre,
and point(s) on the circumference
you can apply the distance formula
to determine the radius
yes
but I don't know the points on the circumference tho
you are literally given them in the question
in fact for the outer circle, you are given 3 of them
you only need to use one of them for the calculation of the radius
oh
sorry
and then after I foudn the raduis of outer circle how do I find the inner circle?
do I use this
ohhhh
I understand
tysm for your help
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I found that both of these 2 formulas are used for the negative binomial distribution (pmf)
But they arenβt the same they give 2 different valuesβ¦
@proud igloo Has your question been resolved?
@proud igloo Has your question been resolved?
@proud igloo Has your question been resolved?
@proud igloo Has your question been resolved?
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hey yall i got some linear algebra hw, and i only need to confirm the solution
im given that this set is a basis of a vector space V
and im asked to show that
is also a basis of V
is this correct?
(ignore the greek and please tell me if you can't make out the image, ill try and take a better one )
any help would be greatly appreciated
this is only a proof of linear independence right?
righttt how do i do that again?
show you can write anything in the vector space as a linear combination of vectors in your list
write im a bit rusty on that, ill do a quick google search and if im still confused ill ask for more details
thank you though in advance
so im looking at this
do i have to set up the matrix and do gaussian elimination to find the dimension or is that unecessary
wait no nvm
i just remembere dhow
well thanks again
whatever you do will end up basically being the same as setting up the matrix and reducing
because you are indeed just trying to see if a linear system always has solutions
just find Cn such that the nth element of the each basis set is equal ?
im not really sure what you mean by that
uh im not really sure either now
okie so
right yeah i just dont know how to do that
the vector space is V and i have to show that it's a linear combination of
im sure it's simple i just dont see it
take $v \in V$, you can write it as $\sum b_n a_n$
Ξ£AC
then find some c_n that make v a linear combination of these guys
your c_n will depend on the b_i
is that b_i / (b_{i-1}+b_{i})
um
cause it would turn this
into
wait what
im fried
i mean a_i
on a scale of 1 to 10 how much am i overcomplicating it
wait so
In the EDIT of the first answer
i quote
" if we have n independent vectors, they must span the vector space. "
if only it's of dimension n
so the only thing left is to show that V is of dimension n?
which is kind of obvious i guess? since there are n basis?
or is that not how that works
yo you there? @worthy citrus
yeah this is a way to avoid a lot of the work
if you dont want to directly check
maximal linearly independent sets are automatically spanning
the dimension of a space is t he number of vectors in any basis yeah
soo ill just say that dim(V)= n since there are n basis and get on with my life
i guess that is a yes
thank you again
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Hello, why is this the solution? I don't really know how to calculate the conditional expectation
Someone else took this channel just before you did, you need to open a different one
yeah i saw my bad
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(x+3y)^5 pascals triangle
im stuck on the 3y, when do i have to multiply
i also dont know where to put the exponents
i have this so far
,rotate
don't understand what the problem is
this is mostly correct, you have 2y for some reason.
Recall that $(ab)^n = a^nb^n$
dldh06
so would i put the exponent on the x as well?
I'm saying for your 3y, you have $(3y)^n$. If you apply what I stated above, the $(3y)^n = 3^ny^n$
dldh06
wait so lemme write this out
would the exponent always be 5?
through out the who equation for each 3y?
or would the number -1 / +1 each time
No
You apply it for each term
You have a term that is (3y)^2
And a different one that is (3y)^3
And so on
Apply the rule I stated above
You can expand that more, like 5(x^4)3y, you can do 5 * 3, correct?
How did you get 9 for the 3rd term?
And that should be it
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yo
is it possible to factor $a^2-b^2-c^2$
Jash
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where does the 4x^3, 3x^2y and -y^2 come from?
then whats wrong
do the reverse
times in that bracket
with 2xy^2
and get the question
ohhhh I see
so just do whatever is needed to multiply by the GCF to equal the original expression
thanks
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that is because arctan has a domain restriction
AustinU
tangent is opposite over adjacent (SOHCAHTOA ?)
so either, the opposite side length is negative
or the adjacent side length is negative
this puts you in two situations
-2/1
or 2/-1
which puts you in two different quadrants
and arctan, will only give you the resulting angle for one of the quadrants, because it wants to be a function
so, it's your job to know what quadrant you are actually in, so you may shift the angle accordingly, if arctan lies to you
Wouldn't it be that either the opposite side length is negative or the HYPOTENUSE side length is negative?
Since we're looking at tangent O/H
π true
I wrote it wrong originally, my bad if that threw you off haha
Well our original coordinate gave us a -x and a positive y, so it must be that we are in the 2nd quadrant in the xy-plane, correct? So it is 2/-1
How do I know by how much to shift arctan to correct the angle
arctan's restricts you to [-pi/2, pi/2]
react from me
