#help-17

1 messages · Page 6 of 1

solemn spear
#

now what does this mean for the derivative

chrome kite
#

if a function is decreasing in an interval then f`(x)<0 considering that the function can be derivated in all points

#

the opposite being true as the function increases f`(x)>0

solemn spear
#

so it would be greater than or equal to 0 for my first drop down box?

tidal marlin
#

It’s never 0 at x>0

#

The derivative is 0 at x=0

solemn spear
#

my only 2 options are greater than or equal to 0

#

and less than or equal to 0

tidal marlin
#

Damn

#

Greater or equal then I guess

chrome kite
solemn spear
chrome kite
#

its deffinetly not less than

solemn spear
#

so what happens at this one?

#

same options for all these

chrome kite
#

is that an increasing or decreasing function?

solemn spear
#

looks like its increasing?

chrome kite
#

yah

chrome kite
solemn spear
#

so maybe the other 2 will be less than or equal to 0 ?

tidal marlin
#

Yes

chrome kite
#

exactly

solemn spear
#

so in words that would be...

#

the derivative of the function is less than or equal to 0 when x is less than 0, and f(x) is greater than 0

#

its less than zero because its a negative slope?

solemn spear
#

only for this function?

chrome kite
#

the derivative of the function is less than or equal to 0 when if u consider x1>x2 it results that f(x1) is <f(x2) which means the function decreasees as x gets bigger

tidal marlin
chrome kite
solemn spear
#

ahhh

#

,close

#

.close

vocal sleetBOT
#
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vast shale
#

lets say i want to move a remote control car that weighs 30kg

vast shale
#

how do i calculate the force needed for this. would we account gravity into this or no

dim quail
#

we have a lot to account for

#

some are: air friction, rolling friction, heat loss, gravity etc

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#
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light panther
#

Help

vocal sleetBOT
light panther
#

I’ve been told the 4 digit code is 0441

#

Why tho

regal slate
#

the code?

light panther
#

It’s a puzzle

#

Math related

regal slate
#

i dont see the need for a code but the steps dictate:

the hour hand seems to move +1
the minute hand seems to move +2
the seconds hand seems to move +3

#

idk tho

vocal sleetBOT
#

@light panther Has your question been resolved?

vocal sleetBOT
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vocal sleetBOT
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vast shale
#

hello, just a quick question because i somehow always forget

rose raft
#

🥴

vast shale
#

what is the difference between [
\subsetne \textss{and} \subsete
]s

rose raft
#

uh

vast shale
#

uhh

pale perch
#

hmm

rose raft
#

still hm

torpid talon
vast shale
#

why am i forgetting the command now

rose raft
hard atlas
#

One is explicitly a proper subset, the other can be a proper subset or the whole thing

vast shale
#

its the one with the dash underneath

hard atlas
#

\subsetneq ?

twin meteorBOT
vast shale
#

oh yep okay

vocal sleetBOT
#
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hard atlas
#

It's like < vs <= just that with sets also some use < to mean the other so there is a more explicit notation

blissful saffron
#

lix caught

vast shale
#

oh sorry

blissful saffron
#

using \subset to mean \subseteq is such cursed notation

vast shale
#

i meant like

cobalt crypt
vast shale
#

.reopen

vocal sleetBOT
#

cobalt crypt
#

$\lneq$

twin meteorBOT
blissful saffron
vast shale
#

difference between [
\subsetneq \text{and} \subset
]

twin meteorBOT
vast shale
#

aren't they technically the same

blissful saffron
#

sure

hard atlas
#

Yes but only psychos use the second

torpid talon
#

only psychos use the first

vast shale
#

\subset is when you want to be ambiguous af

hard atlas
#

Cause it's ambiguous

blissful saffron
#

maybe in some cursed way it could also mean its not a subset at all

#

how is it ambiguous

#

\subset clearly means proper subset

torpid talon
#

it's not ambiguous at all imo

#

just like < isn't ambiguous

blissful saffron
#

well i know rudin uses that

#

accursed notation

hard atlas
#

No, a lot of people also use it to mean both proper subset or equal

blissful saffron
cobalt crypt
#

a lot of people devastation

#

those people have ruined the notation for everyone else devastation

blissful saffron
#

fr

#

horrendous notation

vast shale
#

so whats the consensus boys, first one or second one

blissful saffron
#

please just use \subset to denote proper subset

vast shale
#

oh but i heard something from my teacher that went like

#

one of them includes the empty set the other doesn't

#

but i am preetty sure i misheard that

#

$\smash{{}^{\not\subset}_{-}}$

blissful saffron
#

wot

twin meteorBOT
torpid talon
cobalt crypt
#

because the notation doesnt suggest it at all

#

if you want it to not be the empty set its best to just write it explicitly like $A \ne \emptyset$

twin meteorBOT
hard atlas
#

Or just say "let A subseteq X be nonempty"

blissful saffron
#

just don't use notation that will make your readers come to your house at 2am and shove a hachet into your eyeballs

#

define your notation at the start if you're using anything ambiguous

#

\section{Notation}

blissful saffron
#

textbook authors be like

cobalt crypt
#

thats exactly what everyone does

#

nobody will read your notation section devastation

#

so just use more intuitive notation

blissful saffron
#

In this textbook, \bN means {2,3,4...}

vast shale
#

oh yeah guys another question

#

let epsilon be a big number

#

because like

#

i forgot this too

blissful saffron
#

then there exists M > 0 such that when

vast shale
#

whats the difference between [
A \longrightarrow B \textss{and} a \mapsto b
]

twin meteorBOT
plain minnow
#

I usually just let the interpretation of notation be an exercise for the reader

vast shale
cobalt crypt
twin meteorBOT
blissful saffron
vast shale
vast shale
# twin meteor

,tex $1i\rotatebox[origin=c]{180}{w}{o\leftarrow f}x(\text{f})=\rotatebox[origin=c]{180}{7}$ $\Leftarrow\hspace{-15pt}\raisebox{1pt}{$\implies$}$ \rotatebox[origin=c]{180}{A}$\in\gneq O$, {\Huge\rotatebox[origin=c]{180}{$\in$}}6$\not\leq$O, such\tHat f,\rotatebox[origin=c]{-90}{$w$},\rlap{b}\rotatebox[origin=c]{-180}{$d$}$\phantom{.}\delta$($\emptyset$) $\rlap{=}>$ $|\mid \times(f)-\rotatebox[origin=c]{180}{7}||<\epsilon$

twin meteorBOT
blissful saffron
#

ive seen the mapsto be used when they dont want to define an explicit function

#

for example

#

$x \mapsto xN$ to denote the canonical projection from a group to the quotient group

twin meteorBOT
cobalt crypt
#

i use mapsto when im too lazy to write function notation

#

$f : A \to B, a \mapsto b$

twin meteorBOT
vast shale
#

oh so like

#

[
f: \R \longrightarrow \R\setminus\set{0}\quad x \mapsto \f 1x
]

plain minnow
cobalt crypt
#

why do you use \longrightarrow hmmGe

plain minnow
#

Because it's l o n g

twin meteorBOT
vast shale
#

better

cobalt crypt
vast shale
#

\to is beta \longrightarrow

vast shale
cobalt crypt
#

well technically it is

plain minnow
#

Yes

vast shale
#

it should it be

cobalt crypt
#

but like

plain minnow
#

Domain and codomain needs to be switcherooni

vast shale
#

[
f: \R\setminus\set{0} \longrightarrow \R\quad x \mapsto \f 1x
]

cobalt crypt
#

too lazy to correct you rn opencry

vast shale
#

LMAO

twin meteorBOT
vast shale
#

there

#

i mean u can bullshit the codomain to be anything

#

as long as it is bigger or equal to the defined range

#

right

cobalt crypt
#

well maybe

#

but then you might care about properties of the codomain

#

like

#

vector space structure

#

group structure

#

topological structure

#

etc etc

vast shale
#

so big brain stuff idk about yet

#

got it

cobalt crypt
plain minnow
#

[
f :
\begin{array}{c}
\R\setminus\set{0} \to \R \
x \mapsto \frac{1}{x}
\end{array}
]

vast shale
#

begin array cheeto

plain minnow
#

I don't know how to LaTeX

vast shale
#

its okay i dont either

#

i just yoink the stuff @cobalt crypt does

cobalt crypt
#

i got this

twin meteorBOT
#

Mikkel
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

cobalt crypt
#

<tikz-cd>\begin{tikzcd}[column sep=0pt]
f & {{}:{}} & \R\setminus\set0 & \R \
&& x & \f1x
\arrow[from=1-3, to=1-4]
\arrow[maps to, from=2-3, to=2-4]
\end{tikzcd}

#

oh thats shocking

twin meteorBOT
cobalt crypt
#
\[ \begin{array}{@{}c@{}c@{}c@{}c@{}c@{}} f & {}:{} & \R \setminus \set 0 & {}\longrightarrow{} & \R \\ && x & {}\longmapsto{} & \f1x \end{array} \]
plain minnow
#

Almost there glassescat

vast shale
twin meteorBOT
vast shale
#

so boys like

#

\begin{tabular}{cc}
$f: \R \setminus \set{\pm \s 2} \longrightarrow \R$ &\quad $f: \R \longrightarrow \R$ \
$x \mapsto \f{x}{x^2-2}$&$x \mapsto \f{x}{x^2-2}$\
is a function &is not a function
\end{tabular}

twin meteorBOT
vast shale
#

basically

plain minnow
#

I should probably continue my analysis revising instead of this... devastation devastation

cobalt crypt
#

wdym, this is excellent use of your time

#
\[ \def\arraystretch{1.2} \begin{array}{@{}c@{}c@{}c@{}c@{}c@{}} f & {}:{} & \R \setminus \set [\big] {\s2, -\s2} & {}\longrightarrow{} & \R \\ && x & {}\longmapsto{} & \f x {x^2 - 2} \end{array} \]
twin meteorBOT
cobalt crypt
vast shale
#

Uhm I need to compose myself

#

this isn't the right server

vast shale
#

.e snowunmasked

cobalt crypt
vast shale
plain minnow
#

I'm stuck at this one question. The book wants me to find a very specific upper bound for |Δf| of a function f bleakkekw bleakkekw

cobalt crypt
#

post it here we'll help bleakkekw

vast shale
#

yeah go for it

#

my channel is a free for all dw about it xd

plain minnow
#

It's a logistic function f(x) = exp(x)/(1 + exp(x))

vast shale
plain minnow
#

It wants be to find an upper bound of |Δf| <= 3exp(a)|Δx| for |Δx| where a is just a fixed point, that is Δf = f(a + Δx) - f(a)

plain minnow
cobalt crypt
plain minnow
#

I'm different like that monkey

cobalt crypt
twin meteorBOT
vast shale
#

please refrain from advertising your channel in other channels

#

:)

cobalt crypt
plain minnow
#

Sorry catthumbsup

vast shale
#

ohwoops

#

forgot this channel

#

.close

vocal sleetBOT
#
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sage dust
#

Hello, so i'm searching on the internet for an equation to calculate quartile 1,2 and 3 but when i found it, i was left asking why is the equation for counting quartile in an odd single data different ? since for the others it's simple enough you just add 1 or just repeat it in the nearly same equation

vocal sleetBOT
#

@sage dust Has your question been resolved?

vocal sleetBOT
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vocal sleetBOT
#

Please don't occupy multiple help channels.

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verbal turtle
#

Can anyone help me with understanding with 2-norm of x comes from?

vast shale
#

any context?

#

maybe there was |x_1| ≤ |x| somewhere

verbal turtle
vast shale
#

then what is |x|

#

,tex .original

twin meteorBOT
verbal turtle
vast shale
#

what is x

verbal turtle
vast shale
#

ah ok, that makes a lot more sense

#

so you want to show that |x_1| ≤ |x|

#

write out the definition of the 2 norm

#

and write |x_1| as sqrt(x_1^2)

verbal turtle
vast shale
#

triangle inequality

verbal turtle
#

I get it, thanks

#

.close

vast shale
#

np

vocal sleetBOT
#
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vast shale
#

how do find eulers method for delta t

vocal sleetBOT
vast shale
#

like

#

how do you know what delta t is

lime gorge
#

Show an example problem

vast shale
#

can i show you my data

#

so i am modeling newtons law of cooling

#

with a cup of coffee

#

and so this is what I came up with

#

after doing that

#

i measured the room temp

#

which was 22.65

#

and got a diff eq

#

of

#

42.81e^(-.0171)x +22.65

#

but I want to use eulers method to come up with an approximation

#

but im confused on how

#

you calculate the change in x

#

does that make sense

#

oh and

#

I wanna know the time for which the coffee is 57.8 C

#

and i figured out the time for that now im just stuck on how i would implement eulers method

#

or how i could

#

use it

rugged bolt
#

Okay so you have the differential equation y(t) = 42.81 e^(-0.181t) + 22.65 and now you want to come up with approximations of y(5), y(10), etc?

vast shale
#

yeah

rugged bolt
#

Your "x" is just "t" for time, right?

vast shale
#

yeah yeah

#

my b

rugged bolt
#

Uh wait, mb, did you already solve the differential equation and got the solution y(t) = 42.81 e^(-0.181t) + 22.65 or is this the differential equation and should be y'(t) = 42.81e^(0.181t) + 22.65?

vast shale
#

i solved it

#

yeah

#

i sovled for the differential equation

rugged bolt
#

What was the differential equation?

#

Cause in Euler's method we need that

vast shale
#

oh

#

ohhh

#

um

#

dT/dt=-k(T-A)

#

A being the

#

room temp

rugged bolt
#

What are the constants and all?

vast shale
#

-k being constant of proportionality

#

to the difference of the temperature of the coffee and the room temp

#

its the diff eq for Newtons law of cooling

rugged bolt
#

Did you find out the constants?

vast shale
#

oh yeah

#

42.81e^(-.0171)x +22.65

#

oh my b

#

it was

#

A =22.65

rugged bolt
#

Just the differential equation with the constants plugged in

vast shale
#

K=-.0171

rugged bolt
#

Okay so dT/dt = -0.171(T - 22.65)

vast shale
#

yes

rugged bolt
#

Okay so by Euler's method, we have T_(n+1) = T_n + h * f(t_n, y_n), where f(t,y) = 0.171 * (T - 22.65)

vast shale
#

yeah

rugged bolt
#

And we know the initial temperature right?

vast shale
#

but what does h mean

vast shale
#

i collected

rugged bolt
#

h is the difference in the time values

#

Yes so your h here is 5

vast shale
#

ahhh

#

okay okay

#

LOL

#

IM SO STUPID

#

😭

rugged bolt
#

So we already know T_0, it is 65.466667

vast shale
#

yeah

rugged bolt
#

And then you just continue on from here

vast shale
#

okay im going to try it

#

i was just confused on what h

#

meant

#

thank you so much

#

you have no idea 😭

rugged bolt
#

np

vocal sleetBOT
#

@vast shale Has your question been resolved?

vast shale
#

wait si

#

so

#

uhh

#

for t_o

#

i got 62.26

#

is that right

#

or am i doing it correctly

#

can i ping sup? because he was helping me or is that not allowed

vocal sleetBOT
#
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vast shale
#

.reopen

vocal sleetBOT
#

vast shale
#

or

rugged bolt
#

you can I don't mnid

vast shale
#

OH REaLLY

rugged bolt
#

You only got to t_0?

vast shale
#

thank you g

rugged bolt
#

T_0 is already given...

vast shale
#

ohhhh

#

okay okay

#

so i dont have to plug in anything

#

for t_o

rugged bolt
#

You need to find T_1 or the temperature at t = 5

#

Or basically T(5)

#

Then T_2, which is T(10)

#

Then T_3, which is T(15)

#

and so on

vast shale
#

oh okay

#

so

#

nvm

#

i got to T_5 and T_10

rugged bolt
#

so it's pretty simple

#

you use the previous T_n to find the next T_(n+1)

vast shale
#

and got 62.257 for T_5 and 58.87 for T_10

#

does that look right

rugged bolt
#

you have the differential equation solved 🙂

#

plug in t = 5 and t = 10 to check

vast shale
#

into the diff eq is olved for right

rugged bolt
#

Yes

#

if the results are far off you probably did something wrong

vast shale
#

how much error is fine

rugged bolt
#

Well..

#

im not sure about that

vast shale
#

off by .305

vocal sleetBOT
#

@vast shale Has your question been resolved?

rugged bolt
#

Works I guess

vast shale
#

nvm i messed up on calculations is much lower

#

is there an app where i can have one data set be plotted while the other is a line

#

google sheets doesnt seem to let me do that

rugged bolt
#

you can try desmos

#

but you'll have to plug in the equation of the line and the points in the data set

vocal sleetBOT
#
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uncut oar
#

im guessing we convert the limits into polar coordinates where x^2 + y^2 = r^2 therefore the inner limits are defined as 1<=r^2<=4 but how do i get the outer limits

uncut oar
#

or do we even hjave to convert to polar coordinates?

uncut oar
flat whale
#

draw the region

uncut oar
#

it would be a circle right?

#

so 2pi and 0?

river minnow
#

The region is a ring

flat whale
vocal sleetBOT
#

@uncut oar Has your question been resolved?

rugged vortex
#

You're gonna have to change to polar paper yeah

vocal sleetBOT
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mellow rampart
#

What is the problem here?

vocal sleetBOT
mellow rampart
#

Why is two eigenvectors corresponding to the same eigenvalue a problem?

mellow rampart
#

hm ok

#

ty

#

.close

vocal sleetBOT
#
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vast shale
#

whats the latex cmnd so i can display a proof

regal slate
vast shale
#

uh i want to ask a question

#

For all $a, b, c \in Z^+$, gcd(a, bc) $|$ gcd(a, b) times gcd(a, c)\

Let x = gcd(a, bc), let y = gcd(a, b), and let z = gcd(a, c)\
Breaking x = gcd(a, bc) down, we have that $x | a$ and $x | bc$, which implies that $a = xm_1$ and $bc = xm_2$ for $m_1, m_2 \in \mathbb{Z}$.\\

Next we will look at y = gcd(a, b) and z = gcd(a, c). First we have that y = gcd(a, b) which implies that $y = ak_1 + bk_2$ for $k_1, k_2 \in \mathbb{Z}$. We also have that z = gcd(a, c) which implies that $z = al_1 + cl_2$ for $l_1, l_2 \in \mathbb{Z}$\\

Now lets look at gcd(a, b) gcd(a, c). This is equivalent to:\
$(ak_1 + bk_2)(al_1 + cl_2)$\
$(a^2k_1l_1 + al_1bk_2 + ak_1cl_2 +bk_2cl_2)$\
$a(ak_1l_1 + l_1bk_2 + k_1cl_2) + bc(k_2l_2)$\
As defined earlier, we have $a = xm_1$ and $bc = xm_2$:\
$xm_1(ak_1l_1 + l_1bk_2 + k_1cl_2) + xm_2(k_2l_2)$\
$x(m_1(ak_1l_1 + l_1bk_2 + k_1cl_2)) + m_2(k_2l_2)$\
gcd(a, bc) $|$ gcd(a, b) gcd(a, c), as desired \qed \

#

rip

twin meteorBOT
#

forgetmenot

vast shale
#

oh wait it worked

#

i wanted to ask if there was a better way to do my proof

#

because this is gross

vocal sleetBOT
#

@vast shale Has your question been resolved?

vocal sleetBOT
#

@vast shale Has your question been resolved?

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real stone
vocal sleetBOT
real stone
#

Does this look right for finding the values of x for which the series converges?

vast shale
#

yrp

#

yep

#

looks right to me!

#

[
I = (-\infty , \infty), \quad R = \infty
]

twin meteorBOT
vocal sleetBOT
#

@real stone Has your question been resolved?

real stone
#

Not sure what to do here. Is n=2 as the lower bound a significant detail? Because I’ve only encountered n=0 so far

#

I know I’m supposed to set this <1, but how do I find the limit?

#

Am I doing something wrong?

vast shale
#

recheck your x

#

redo the entire thing in fact

real stone
#

oh the x^(n+1) should be an x, my bad

vast shale
#

yes

#

also

#

what u did with the ln's is not correct either

real stone
#

how? I don’t understand

vast shale
#

[
\map \ln{\f x y} = \map \ln x - \map \ln y {\c r {}\ne{}} \map \ln{x-y}
]

twin meteorBOT
vast shale
#

also it is better u don't do that either, you will see why after you fix up your original expression

real stone
real stone
vast shale
#

okay so you were on the right path with what u were doing with the ratio test

#

so just redo your simplification and tell me what the new expression you have is

real stone
#

I can just take |x| out of the limit

#

oh do I use l’hopital?

vast shale
#

yes

#

you can in fact l'hopital it

real stone
#

but how do I deal with the absolute value?

#

ln(n)/ln(n+1) would still be infinity/infinity

#

but how do I differentiate |ln(n)| and |ln(n+1)|

vast shale
#

see

#

i want you to look back at your series

#

what is the first index of your series?

#

as in, where does it start from?

real stone
#

OH that’s why the 2 is significant

vast shale
#

yep

#

so the absolute value is unnecessary

#

because those ln's are always positive anyhow

#

so u can drop it completely except for the x

real stone
#

I got this far

#

.close

vocal sleetBOT
#
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hearty storm
#

Am I being stupid or what? How is it convergent? What am I doing wrong?

hearty storm
#

Or are we saying integral of g(x) is the same range as f(x) so 0 and 1/2 rather than the usual 1 and infinity?

#

So in our case g(x) is actually convergent

vocal sleetBOT
#

@hearty storm Has your question been resolved?

vocal sleetBOT
#

@hearty storm Has your question been resolved?

vocal sleetBOT
#

@hearty storm Has your question been resolved?

vast shale
#

$\frac{1}{x^{something} - x^{something}}$

twin meteorBOT
#

hibyehibye

vocal sleetBOT
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ripe wedge
vocal sleetBOT
ripe wedge
#

where in the hell

#

is the extra one coming from

#

im so confused

outer warren
#

the index starts at -1

ripe wedge
#

yea so 16 + 9 = 24 + 4 = 28

#

+1

#

= 29

#

+1

#

=30

outer warren
#

don't chain equations,
your work is unclear

ripe wedge
#

my bad

outer warren
#

also 16 + 9 isn't 24

ripe wedge
#

it's 25

#

im

#

so sorry

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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round widget
#

Can I have a clue on where to begin with this question

round widget
#

I drew the graph

#

I think x will be 2pi bc that’s the only way u can get the area to be 0

#

But I’m not sure how to solve for t

half imp
#

solve for t?

vast shale
#

is sin t = x

#

???

half imp
#

no, you can't solve for t

#

It doesn't have a value, idk what you mean

round widget
half imp
#

Solve for x

#

More specifically, find how many solutions there are for x

round widget
#

X=2pi is that the only solution?

half imp
#

seems to be

round widget
#

Oh that question wasn’t too bad then I thought I had to solve for t

#

.close

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#
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mystic hare
vocal sleetBOT
mystic hare
#

,rotate

twin meteorBOT
mystic hare
#

hello uh- i just want to see out whether my way is right- for d- i think its 64 too as they have the same arch

#

:]

astral pilot
#

8.d)?

mystic hare
#

yea-

#

i have been erasing over time to do it individually btw :D

#

why is it not-

astral pilot
#

wait

#

lemme see it properly

mystic hare
#

sure sure

#

if it aint clear- ill do another photo for u :]

astral pilot
#

ya u r right

mystic hare
#

FR?

#

DAMN MY BRAIN IS DOING WELL

#

:D

mystic hare
astral pilot
#

pls send it again

mystic hare
#

ah sure sure

astral pilot
#

im missing something

mystic hare
#

,rotate

twin meteorBOT
astral pilot
#

how did you find<ACB

mystic hare
#

i used the 2x method

#

from the 26 degree

#

26 divided by 2

#

into 13

astral pilot
#

<OBC isnt 64 for sure now

mystic hare
#

thingy-

mystic hare
#

i uh

astral pilot
#

can u tell how did u find it?

mystic hare
#

its the angle thingy

#

they r related

astral pilot
#

who are related

mystic hare
#

same arch

astral pilot
#

that is is only when co was a diameter

#

your logic is wrong

mystic hare
#

owh-

mystic hare
astral pilot
#

yes

#

CO isnt a seg

mystic hare
#

owh

#

lemme just erase that part-

astral pilot
#

to find <OBC first find <OCB

mystic hare
#

i uh-\

astral pilot
#

can u find <OCB

mystic hare
#

one moment

#

forgive me how do i find it :]

astral pilot
#

you know m<oca

mystic hare
#

uh no-

#

only ACB

astral pilot
#

find <OCA

mystic hare
#

i uh

#

forgive me i died

astral pilot
#

R.I.P.

mystic hare
#

:]

astral pilot
#

⚰️

mystic hare
#

do u have any clue abt it

#

:-]

astral pilot
#

AOC is isoceles

mystic hare
#

wait they r ?-

#

its also a 64?

astral pilot
#

yes

#

now what is <OCB

mystic hare
#

13 plus 64 is 77-

astral pilot
#

now can u find <OBC?

mystic hare
#

uh-

#

:]

#

🙅‍♂️

astral pilot
#

obc is also isoceles

mystic hare
#

77- wait-

#

77 too?!

astral pilot
#

why is obc isocels>

mystic hare
#

they've got two equal sides?- :]

#

lemme just

#

go :]]

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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summer spade
#

What is the greatest integer k such that 80! is divisible by 45^k?

vocal sleetBOT
#

@summer spade Has your question been resolved?

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unreal sparrow
#

Did i answer this question correctly?

vocal sleetBOT
vocal sleetBOT
#

@unreal sparrow Has your question been resolved?

unreal sparrow
#

<@&286206848099549185>

unreal sparrow
#

<@&286206848099549185>

boreal vector
unreal sparrow
#

<@&286206848099549185>

unreal sparrow
#

<@&286206848099549185>

#

Can someone help check my work

serene frost
#

Yes.

#

What can I help you with?

unreal sparrow
vocal sleetBOT
#

@unreal sparrow Has your question been resolved?

unreal sparrow
#

<@&286206848099549185>

vocal sleetBOT
#

@unreal sparrow Has your question been resolved?

unreal sparrow
#

<@&286206848099549185>

#

Can someone please help

unreal sparrow
#

<@&286206848099549185>

final rover
lone niche
#

probably don't ping multiple times

final rover
#

yea

lone niche
#

is the 3.1 mph relative to the river or the bank

#

assuming it's relative to the river

#

because if it's relative to the bank than the 75° angle thing is not really possible

#

yeah I get 0.83 mph

unreal sparrow
#

.close

vocal sleetBOT
#
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narrow hamlet
#

B) do I need to use two line notation to do this or just use the cycle notation?

vocal sleetBOT
#

@narrow hamlet Has your question been resolved?

narrow hamlet
#

.close

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dusky osprey
#

i'm on my last attempt

vocal sleetBOT
dusky osprey
#

i think I got it

#

5x- 3 arctan x +C

#

but idk what to put for arctan 1 to get C

mental falcon
#

well plug in x = 1 and y = 0 and solve for C

#

F(1) = 0 just tells you when x is 1, y (aka the value f(x) is 0 )

dusky osprey
#

what's arctan 1

mental falcon
#

pi/4

dusky osprey
#

it's been a while since i took math sorry

mental falcon
#

i believe

dusky osprey
#

ighty so

#

5-3pi/4

mental falcon
#

remember tan = sin \ cos which is basically slope of rise \ run

dusky osprey
#

-(5-3pi/4)

mental falcon
#

so slope from 0, 0 to a point on the unit circle is 1 when the angle is at 45 degrees or pi / 4

#

or 3pi/ 4 but range of arctan is -pi/2 to pi/2

dusky osprey
#

but that doesn't matter bc it's multiplied by a constant after

#

so is C = -(5-3pi/4)

#

i would like someone to double check

#

<@&286206848099549185>

vocal sleetBOT
#

@dusky osprey Has your question been resolved?

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#
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alpine trout
#

hey

vocal sleetBOT
alpine trout
#

do you know why thi is equal to x/r

#

rather than x^'/r

#

this is the question

vocal sleetBOT
#

@alpine trout Has your question been resolved?

flat whale
vocal sleetBOT
#

@alpine trout Has your question been resolved?

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last umbra
#

Hi

vocal sleetBOT
last umbra
#

Okay so my Qn is expand the following equation

#

log9(3x^3/y)

#

I am confused with the 3x part

#

<@&286206848099549185>

balmy yacht
last umbra
#

wsg

vocal sleetBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

last umbra
#

my bad

vocal sleetBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
last umbra
#

1

cursive turret
#

what exactly is the question?

last umbra
#

it is to expand this

#

log9(3x^3/y)

#

the brackets is the product of the log

#

the argument

#

and the 9 is the base

cursive turret
last umbra
#

Yes but the 3x^3 part is confusing me

#

it is log9(3x^3)

cursive turret
#

productrule as you have 3 times something and then powerrule for x^3.

last umbra
#

so does it mean it is 3log9(3x)?

karmic imp
#

Is that 0 suppose to be there?

karmic imp
#

But you can expand even more

last umbra
cursive turret
last umbra
#

Because in 3x^3 the ^3 is for x and not for the 3 as well

#

Oh wait

#

is it log9(3)+3log9(x)-log9(y)?

last umbra
cursive turret
karmic imp
last umbra
#

hmm

karmic imp
#

log9(3x^3) does equal 3log9(3x)

last umbra
#

how tho

#

the ^3 is for only the x variable not the entire 3x

cursive turret
last umbra
#

so is my answer right?

cursive turret
last umbra
#

okayy thankss man

#

how to close the channel?

karmic imp
last umbra
#

.close

vocal sleetBOT
#
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karmic imp
vocal sleetBOT
last umbra
#

.closee

#

.close

vocal sleetBOT
#
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molten rain
vocal sleetBOT
molten rain
#

how to do this question

#

im not sure how to continue

lone niche
# molten rain

well you know the slope
can you find the equation of the tangent line (y = f(x))

molten rain
#

i dont think so

#

I cant really understand the question

lone niche
#

meanwhile, the normal line is the line perpendicular to the curve at the same point

molten rain
#

perpendicular

#

it mean

#

its a verticle line?

lone niche
#

perpendicular means right angles

#

the tangent and normal are 90° apart

molten rain
#

ohhhh

#

yes

#

now wha

regal slate
lone niche
#

well that's not always true..

molten rain
#

i know what a tangent is-

#

now wha

lone niche
molten rain
#

o

regal slate
#

or is it not

#

hmm

lone niche
#

well

#

there are infinite infinities of functions

#

so not really a way to say "most functions are..."

#

unless there are only a finite number of cases where it's not true

regal slate
#

well most functions that are taught at this level

lone niche
#

you mean like quadratics?

#

parabolas?

regal slate
#

i guess

molten rain
#

the

#

equation of normal is y=x+6

#

tangent is y=-x+12

#

now wha

lone niche
#

find the points it told you about

#

where they intersect the x axis

molten rain
#

o

#

ok

#

how do i do this question now

lone niche
#

ah this is what I was talking about

#

kind of

molten rain
#

ye

#

i uh

#

dont know how to find the point

#

i tried

#

this is part 2

lone niche
molten rain
#

uh

#

yes

#

y=x+6

lone niche
#

the normal is the one perpendicular to the tangent

molten rain
#

wha

lone niche
#

it makes sense that the tangent has only one intersection here

molten rain
#

what

#

oh

#

OIH

#

OH

#

OMG

#

ahaha

lone niche
#

lol

molten rain
#

lemme try again

#

found it

#

thank you

lone niche
#

bot summon is your question resolved

molten rain
#

i will close now

#

.close

vocal sleetBOT
#
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vocal sleetBOT
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real gale
vocal sleetBOT
real gale
#

I considered the numbers to be a_1<a_2<a_3<...a_50(=100)

#

So, (a_26+a_27+...a_50)/25=((a_1+a_2+...a_25)/25)+50

#

I'm stuck

urban edge
#

start by considering the largest possible arithmetic mean of 25 distinct integers each less than or greater than 100

paper depot
#

less than or greater than 100

urban edge
#

i meant equal to whoops

real gale
#

thonkzoom Hmm

paper depot
#

might as well multiply through by 25

real gale
#

I did that

paper depot
#

$a_{26} + \dots + a_{50} = a_1 + \dots + a_{25} + 1250$

#

wait no

#

1250 sorry

real gale
#

Yeah

twin meteorBOT
real gale
#

,calc ((100101)/2)-((7576)/2)

twin meteorBOT
#

Result:

2200
real gale
#

Is this the maximum possible sum of 25 distinct integers each being less than 100

paper depot
#

so it would appear.

urban edge
#

,w sum integers 76 to 100

twin meteorBOT
urban edge
#

sounds good

real gale
#

So, the maximum possible sum of a_i for i in {1,2,3,..25} will be 2200-1250

paper depot
#

so it would be.

#

or would it?

real gale
#

and hence a_1+a_2+a_3+...a_50=2*2200-1250

paper depot
#

that works out to 950 -- can we achieve such a sum?

#

,calc 950/25

twin meteorBOT
#

Result:

38
paper depot
#

ok, we can

real gale
#

,calc 4400-1250

twin meteorBOT
#

Result:

3150
real gale
#

This was easy

#

.close

vocal sleetBOT
#
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vocal sleetBOT
#
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frigid raven
#

quickest way to find x intercepts?

vocal sleetBOT
stiff sandal
#

there is no quick way, you gotta solve it

prime spear
#

indeed

frigid raven
#

quadratic?

#

formula

prime spear
#

it's not a quadratic

#

it's a cubic

stiff sandal
#

cubic in this case

prime spear
#

since its with a ^3 term

frigid raven
#

a,b,c

#

differnece quotient

#

i mean

#

?

prime spear
#

you use the rational root theorem to find the first factor of the function

frigid raven
#

2/1?

prime spear
#

you just sub in factors of 2

#

into the equation

#

and see whcih one gives you 0

frigid raven
#

are these the possiblities?
-1/-1 =1
1/-1 = -1
2/-1 = -2
2/1 = 2

#

for a i got -1,1
for c i got -2,-1,1,2 ?

#

then you do c/a and find out best fit?

prime spear
#

after you found the factor

#

you do long diviosn

frigid raven
#

long division of what

prime spear
#

divide the factor

#

by

#

the equation

#

you can do any type of diviosn

#

synthetic, long, short

#

you just divide it

prime spear
#

ok so

#

what are factors of 2

#

theres

#

2

#

-2

#

1

#

and -1

#

you plug those values into the equation

#

and see which = 0

frigid raven
#

ok

#

ty

#

is this

#

the best way

#

?

#

what if i used

#

different quotient

#

what would that help find

prime spear
#

wdym diff quotient

frigid raven
#

what does using dif quotient

#

achieve

#

if i were to use it

#

in here, for example

#

i plug in h-> 0

#

then set = 0 ?

#

and i should get +- sqrt 1?

prime spear
#

i have no idea what difference quotient is

#

you asked for x intercepts

#

so

frigid raven
#

yes

#

and oyu helped me

#

thank very much

#

just wanted to know this stuff here

prime spear
#

oh ok

vocal sleetBOT
#

@frigid raven Has your question been resolved?

#
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rain nacelle
silk comet
#

the cross product distributes over addition

#

and is anticommutative

gray yarrow
#

alternatively you can write the vectors like u=(u1,u2,u3) etc and then just simplify that

rain nacelle
#

yes thx

#

I got it now

#

.close

vocal sleetBOT
#
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vale palm
#

I need help solving part (b)

#

<@&286206848099549185>

astral pilot
#

!15m

vocal sleetBOT
#

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vale palm
#

hello???

vocal sleetBOT
#

@vale palm Has your question been resolved?

vale palm
#

.....

vocal sleetBOT
#

@vale palm Has your question been resolved?

vocal sleetBOT
#

@vale palm Has your question been resolved?

vocal sleetBOT
#
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safe cedar
vocal sleetBOT
safe cedar
#

so they were explaining how the opposite of differentiation is integration

chrome hornet
#

Yuo

safe cedar
#

and till x^n+1 makes sense to balance the equation

chrome hornet
#

Yup

gray yarrow
#

and it is so much more ❤️

safe cedar
#

but why are they doing n+1

gray yarrow
#

try doing it in reverse

#

to see if it works out

safe cedar
chrome hornet
#

Derivative it if you get x^n then your integration is right

gray yarrow
# safe cedar :")

in physics we use integration alot as an infinitely "narrow" summation
works wonders

chrome hornet
#

Derivation of answer is the question

safe cedar
#

i just started calculus, dont know anything

safe cedar
chrome hornet
#

Hmm you want a brief or a summary?

chrome hornet
safe cedar
#

anything

rose raft
safe cedar
#

i dont feel so good ive been struggling with calculus forever

rose raft
#

it is nx^n-1

chrome hornet
rose raft
#

ya

safe cedar
#

.close

vocal sleetBOT
#
Channel closed

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Use .reopen if this was a mistake.

safe cedar
#

ty everyone

vocal sleetBOT
#
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silk canopy
#

is -12/-7 basically 12/7

vocal sleetBOT