#help-17
1 messages · Page 6 of 1
if a function is decreasing in an interval then f`(x)<0 considering that the function can be derivated in all points
the opposite being true as the function increases f`(x)>0
if thats your only option i guess so
its deffinetly not less than
is that an increasing or decreasing function?
yah
u use the same thing
so maybe the other 2 will be less than or equal to 0 ?
Yes
exactly
so in words that would be...
the derivative of the function is less than or equal to 0 when x is less than 0, and f(x) is greater than 0
its less than zero because its a negative slope?
not necessary
only for this function?
the derivative of the function is less than or equal to 0 when if u consider x1>x2 it results that f(x1) is <f(x2) which means the function decreasees as x gets bigger
Derivative is basically the slope of the tangent line of the point
its not true for this function either since in the third quadrant f`(x) is < 0 but f(x) is negative
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lets say i want to move a remote control car that weighs 30kg
how do i calculate the force needed for this. would we account gravity into this or no
we have a lot to account for
some are: air friction, rolling friction, heat loss, gravity etc
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Help
the code?
i dont see the need for a code but the steps dictate:
the hour hand seems to move +1
the minute hand seems to move +2
the seconds hand seems to move +3
idk tho
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hello, just a quick question because i somehow always forget
🥴
what is the difference between [
\subsetne \textss{and} \subsete
]s
uh
uhh
hmm
still hm

why am i forgetting the command now

One is explicitly a proper subset, the other can be a proper subset or the whole thing
its the one with the dash underneath
\subsetneq ?
oh yep okay
oh okay thank you
.close
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It's like < vs <= just that with sets also some use < to mean the other so there is a more explicit notation
lix caught
oh sorry
using \subset to mean \subseteq is such cursed notation
i meant like

.reopen
✅
$\lneq$

difference between [
\subsetneq \text{and} \subset
]
aren't they technically the same
sure
Yes but only psychos use the second
only psychos use the first
\subset is when you want to be ambiguous af
Cause it's ambiguous
maybe in some cursed way it could also mean its not a subset at all
how is it ambiguous
\subset clearly means proper subset
No, a lot of people also use it to mean both proper subset or equal

so whats the consensus boys, first one or second one
please just use \subset to denote proper subset
oh but i heard something from my teacher that went like
one of them includes the empty set the other doesn't
but i am preetty sure i misheard that
$\smash{{}^{\not\subset}_{-}}$
wot
Toby

this is also cursed
because the notation doesnt suggest it at all
if you want it to not be the empty set its best to just write it explicitly like $A \ne \emptyset$
Or just say "let A subseteq X be nonempty"
just don't use notation that will make your readers come to your house at 2am and shove a hachet into your eyeballs
define your notation at the start if you're using anything ambiguous
\section{Notation}
textbook authors be like

thats exactly what everyone does
nobody will read your notation section 
so just use more intuitive notation
In this textbook, \bN means {2,3,4...}
oh yeah guys another question
let epsilon be a big number
because like
i forgot this too

then there exists M > 0 such that when
whats the difference between [
A \longrightarrow B \textss{and} a \mapsto b
]
I usually just let the interpretation of notation be an exercise for the reader
one is maps into, the other is maps to
let $\epsilon < 0$
oh hmmgee
,tex $1i\rotatebox[origin=c]{180}{w}{o\leftarrow f}x(\text{f})=\rotatebox[origin=c]{180}{7}$ $\Leftarrow\hspace{-15pt}\raisebox{1pt}{$\implies$}$ \rotatebox[origin=c]{180}{A}$\in\gneq O$, {\Huge\rotatebox[origin=c]{180}{$\in$}}6$\not\leq$O, such\tHat f,\rotatebox[origin=c]{-90}{$w$},\rlap{b}\rotatebox[origin=c]{-180}{$d$}$\phantom{.}\delta$($\emptyset$) $\rlap{=}>$ $|\mid \times(f)-\rotatebox[origin=c]{180}{7}||<\epsilon$
Toby
ive seen the mapsto be used when they dont want to define an explicit function
for example
$x \mapsto xN$ to denote the canonical projection from a group to the quotient group
i use mapsto when im too lazy to write function notation
$f : A \to B, a \mapsto b$

why do you use \longrightarrow 
Because it's l o n g
idk i find it
better

\to is beta \longrightarrow
wait this is wrong 
well technically it is
Yes
it should it be
but like
Domain and codomain needs to be switcherooni
[
f: \R\setminus\set{0} \longrightarrow \R\quad x \mapsto \f 1x
]
too lazy to correct you rn 
LMAO
there
i mean u can bullshit the codomain to be anything
as long as it is bigger or equal to the defined range
right

well maybe
but then you might care about properties of the codomain
like
vector space structure
group structure
topological structure
etc etc

[
f :
\begin{array}{c}
\R\setminus\set{0} \to \R \
x \mapsto \frac{1}{x}
\end{array}
]

begin array 
I don't know how to LaTeX
i got this
Mikkel
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
<tikz-cd>\begin{tikzcd}[column sep=0pt]
f & {{}:{}} & \R\setminus\set0 & \R \
&& x & \f1x
\arrow[from=1-3, to=1-4]
\arrow[maps to, from=2-3, to=2-4]
\end{tikzcd}
oh thats shocking
\[ \begin{array}{@{}c@{}c@{}c@{}c@{}c@{}} f & {}:{} & \R \setminus \set 0 & {}\longrightarrow{} & \R \\ && x & {}\longmapsto{} & \f1x \end{array} \]
Almost there 
should there be a colon between the R and the x?
so boys like
\begin{tabular}{cc}
$f: \R \setminus \set{\pm \s 2} \longrightarrow \R$ &\quad $f: \R \longrightarrow \R$ \
$x \mapsto \f{x}{x^2-2}$&$x \mapsto \f{x}{x^2-2}$\
is a function &is not a function
\end{tabular}
basically
I should probably continue my analysis revising instead of this...


wdym, this is excellent use of your time
\[ \def\arraystretch{1.2} \begin{array}{@{}c@{}c@{}c@{}c@{}c@{}} f & {}:{} & \R \setminus \set [\big] {\s2, -\s2} & {}\longrightarrow{} & \R \\ && x & {}\longmapsto{} & \f x {x^2 - 2} \end{array} \]
I will array stretch ur m-



I'm stuck at this one question. The book wants me to find a very specific upper bound for |Δf| of a function f

post it here we'll help 
It's a logistic function f(x) = exp(x)/(1 + exp(x))
It wants be to find an upper bound of |Δf| <= 3exp(a)|Δx| for |Δx| where a is just a fixed point, that is Δf = f(a + Δx) - f(a)
I like to break the rules

I'm different like that 


Sorry 
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Hello, so i'm searching on the internet for an equation to calculate quartile 1,2 and 3 but when i found it, i was left asking why is the equation for counting quartile in an odd single data different ? since for the others it's simple enough you just add 1 or just repeat it in the nearly same equation
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Please don't occupy multiple help channels.
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Can anyone help me with understanding with 2-norm of x comes from?
Not really, x1 and x2 can be any real numbers.
Toby
2-norm of x
what is x
x= (x1,x2)^T
ah ok, that makes a lot more sense
so you want to show that |x_1| ≤ |x|
write out the definition of the 2 norm
and write |x_1| as sqrt(x_1^2)
Ah, ok, so sin(x_2) gets its own absolute value first.
triangle inequality
np
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how do find eulers method for delta t
Show an example problem
can i show you my data
so i am modeling newtons law of cooling
with a cup of coffee
and so this is what I came up with
after doing that
i measured the room temp
which was 22.65
and got a diff eq
of
42.81e^(-.0171)x +22.65
but I want to use eulers method to come up with an approximation
but im confused on how
you calculate the change in x
does that make sense
oh and
I wanna know the time for which the coffee is 57.8 C
and i figured out the time for that now im just stuck on how i would implement eulers method
or how i could
use it
Okay so you have the differential equation y(t) = 42.81 e^(-0.181t) + 22.65 and now you want to come up with approximations of y(5), y(10), etc?
yeah
Your "x" is just "t" for time, right?
Uh wait, mb, did you already solve the differential equation and got the solution y(t) = 42.81 e^(-0.181t) + 22.65 or is this the differential equation and should be y'(t) = 42.81e^(0.181t) + 22.65?
What are the constants and all?
-k being constant of proportionality
to the difference of the temperature of the coffee and the room temp
its the diff eq for Newtons law of cooling
Did you find out the constants?
Just the differential equation with the constants plugged in
K=-.0171
Okay so dT/dt = -0.171(T - 22.65)
yes
Okay so by Euler's method, we have T_(n+1) = T_n + h * f(t_n, y_n), where f(t,y) = 0.171 * (T - 22.65)
yeah
And we know the initial temperature right?
but what does h mean
So we already know T_0, it is 65.466667
yeah
And then you just continue on from here
okay im going to try it
i was just confused on what h
meant
thank you so much
you have no idea 😭
np
@vast shale Has your question been resolved?
wait si
so
uhh
for t_o
i got 62.26
is that right
or am i doing it correctly
can i ping sup? because he was helping me or is that not allowed
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.reopen
✅
or
you can I don't mnid
OH REaLLY
You only got to t_0?
thank you g
T_0 is already given...
You need to find T_1 or the temperature at t = 5
Or basically T(5)
Then T_2, which is T(10)
Then T_3, which is T(15)
and so on
into the diff eq is olved for right
how much error is fine
off by .305
@vast shale Has your question been resolved?
Works I guess
nvm i messed up on calculations is much lower
is there an app where i can have one data set be plotted while the other is a line
google sheets doesnt seem to let me do that
you can try desmos
but you'll have to plug in the equation of the line and the points in the data set
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im guessing we convert the limits into polar coordinates where x^2 + y^2 = r^2 therefore the inner limits are defined as 1<=r^2<=4 but how do i get the outer limits
or do we even hjave to convert to polar coordinates?
try it
how will i get the values for theta?
draw the region
The region is a ring
Nope. Draw the region
@uncut oar Has your question been resolved?
You're gonna have to change to polar paper yeah
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What is the problem here?
Why is two eigenvectors corresponding to the same eigenvalue a problem?
"unique solution"
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whats the latex cmnd so i can display a proof
uh i want to ask a question
For all $a, b, c \in Z^+$, gcd(a, bc) $|$ gcd(a, b) times gcd(a, c)\
Let x = gcd(a, bc), let y = gcd(a, b), and let z = gcd(a, c)\
Breaking x = gcd(a, bc) down, we have that $x | a$ and $x | bc$, which implies that $a = xm_1$ and $bc = xm_2$ for $m_1, m_2 \in \mathbb{Z}$.\\
Next we will look at y = gcd(a, b) and z = gcd(a, c). First we have that y = gcd(a, b) which implies that $y = ak_1 + bk_2$ for $k_1, k_2 \in \mathbb{Z}$. We also have that z = gcd(a, c) which implies that $z = al_1 + cl_2$ for $l_1, l_2 \in \mathbb{Z}$\\
Now lets look at gcd(a, b) gcd(a, c). This is equivalent to:\
$(ak_1 + bk_2)(al_1 + cl_2)$\
$(a^2k_1l_1 + al_1bk_2 + ak_1cl_2 +bk_2cl_2)$\
$a(ak_1l_1 + l_1bk_2 + k_1cl_2) + bc(k_2l_2)$\
As defined earlier, we have $a = xm_1$ and $bc = xm_2$:\
$xm_1(ak_1l_1 + l_1bk_2 + k_1cl_2) + xm_2(k_2l_2)$\
$x(m_1(ak_1l_1 + l_1bk_2 + k_1cl_2)) + m_2(k_2l_2)$\
gcd(a, bc) $|$ gcd(a, b) gcd(a, c), as desired \qed \
rip
forgetmenot
oh wait it worked
i wanted to ask if there was a better way to do my proof
because this is gross
@vast shale Has your question been resolved?
@vast shale Has your question been resolved?
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Does this look right for finding the values of x for which the series converges?
@real stone Has your question been resolved?
Not sure what to do here. Is n=2 as the lower bound a significant detail? Because I’ve only encountered n=0 so far
I know I’m supposed to set this <1, but how do I find the limit?
Am I doing something wrong?
you simplified wrong
recheck your x
redo the entire thing in fact
oh the x^(n+1) should be an x, my bad
how? I don’t understand
[
\map \ln{\f x y} = \map \ln x - \map \ln y {\c r {}\ne{}} \map \ln{x-y}
]
also it is better u don't do that either, you will see why after you fix up your original expression
oh god I’m out of it 🥲
I’m not sure what convergence test I should use
okay so you were on the right path with what u were doing with the ratio test
so just redo your simplification and tell me what the new expression you have is
but how do I deal with the absolute value?
ln(n)/ln(n+1) would still be infinity/infinity
but how do I differentiate |ln(n)| and |ln(n+1)|
see
i want you to look back at your series
what is the first index of your series?
as in, where does it start from?
OH that’s why the 2 is significant
yep
so the absolute value is unnecessary
because those ln's are always positive anyhow
so u can drop it completely except for the x
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Am I being stupid or what? How is it convergent? What am I doing wrong?
Or are we saying integral of g(x) is the same range as f(x) so 0 and 1/2 rather than the usual 1 and infinity?
So in our case g(x) is actually convergent
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@hearty storm Has your question been resolved?
Whats the integral ?
$\frac{1}{x^{something} - x^{something}}$
hibyehibye
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the index starts at -1
don't chain equations,
your work is unclear
my bad
also 16 + 9 isn't 24
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Can I have a clue on where to begin with this question
I drew the graph
I think x will be 2pi bc that’s the only way u can get the area to be 0
But I’m not sure how to solve for t
solve for t?
I’m not sure what the question is asking me to do then
X=2pi is that the only solution?
seems to be
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,rotate
hello uh- i just want to see out whether my way is right- for d- i think its 64 too as they have the same arch
:]
8.d)?
ya u r right
ty btw
pls send it again
ah sure sure
im missing something
how did you find<ACB
<OBC isnt 64 for sure now
thingy-
can u tell how did u find it?
who are related
same arch
owh-
it aint?
to find <OBC first find <OCB
i uh-\
can u find <OCB
you know m<oca
find <OCA
R.I.P.
:]
⚰️
AOC is isoceles
13 plus 64 is 77-
now can u find <OBC?
obc is also isoceles
why is obc isocels>
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What is the greatest integer k such that 80! is divisible by 45^k?
@summer spade Has your question been resolved?
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Did i answer this question correctly?
@unreal sparrow Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
☝️
@unreal sparrow Has your question been resolved?
<@&286206848099549185>
@unreal sparrow Has your question been resolved?
<@&286206848099549185>

probably don't ping multiple times
yea
is the 3.1 mph relative to the river or the bank
assuming it's relative to the river
because if it's relative to the bank than the 75° angle thing is not really possible
yeah I get 0.83 mph
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B) do I need to use two line notation to do this or just use the cycle notation?
@narrow hamlet Has your question been resolved?
.close
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i'm on my last attempt
well plug in x = 1 and y = 0 and solve for C
F(1) = 0 just tells you when x is 1, y (aka the value f(x) is 0 )
what's arctan 1
pi/4
it's been a while since i took math sorry
i believe
remember tan = sin \ cos which is basically slope of rise \ run
-(5-3pi/4)
so slope from 0, 0 to a point on the unit circle is 1 when the angle is at 45 degrees or pi / 4
or 3pi/ 4 but range of arctan is -pi/2 to pi/2
but that doesn't matter bc it's multiplied by a constant after
so is C = -(5-3pi/4)
i would like someone to double check
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hey
@alpine trout Has your question been resolved?
#old-network for physics server
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Hi
Okay so my Qn is expand the following equation
log9(3x^3/y)
I am confused with the 3x part
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my bad
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
1
what exactly is the question?
it is to expand this
log9(3x^3/y)
the brackets is the product of the log
the argument
and the 9 is the base
productrule as you have 3 times something and then powerrule for x^3.
so does it mean it is 3log9(3x)?
Is that 0 suppose to be there?
how tho?
are you sure? is it (3x)^3 or 3x^3?
Because in 3x^3 the ^3 is for x and not for the 3 as well
Oh wait
is it log9(3)+3log9(x)-log9(y)?
the latter
log9(3x^3)= (productrue) log9(3)+log9(x^3)=(powerrule) log9(3)+3log9(x)
Not quite this
hmm
log9(3x^3) does equal 3log9(3x)
set x = 1 and you would get log9(3) =3 log9(3) which cant be right.
so is my answer right?
this is right.
.close
.close
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.My bad, I was thinking you could do power rule first then product but it was the other way around
its finee
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well you know the slope
can you find the equation of the tangent line (y = f(x))
tangent line is the line that just barely touches the curve
(this is not the actual line)
meanwhile, the normal line is the line perpendicular to the curve at the same point
what
perpendicular
it mean
its a verticle line?
better way to phrase it would be to say that the tangent touches the graph at only one point
well that's not always true..
find the equations of the 2 lines
o
but in most cases that is true
or is it not
hmm
well
there are infinite infinities of functions
so not really a way to say "most functions are..."
unless there are only a finite number of cases where it's not true
well most functions that are taught at this level
i guess
are you sure that equation is the normal
the normal is the one perpendicular to the tangent
wha
it makes sense that the tangent has only one intersection here
lol
bot summon is your question resolved
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I considered the numbers to be a_1<a_2<a_3<...a_50(=100)
So, (a_26+a_27+...a_50)/25=((a_1+a_2+...a_25)/25)+50
I'm stuck
start by considering the largest possible arithmetic mean of 25 distinct integers each less than or greater than 100
i meant equal to whoops
Hmm
might as well multiply through by 25
I did that
Yeah
Ann
,calc ((100101)/2)-((7576)/2)
Result:
2200
Is this the maximum possible sum of 25 distinct integers each being less than 100
so it would appear.
,w sum integers 76 to 100
sounds good
So, the maximum possible sum of a_i for i in {1,2,3,..25} will be 2200-1250
and hence a_1+a_2+a_3+...a_50=2*2200-1250
Result:
38
ok, we can
,calc 4400-1250
Result:
3150
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quickest way to find x intercepts?
there is no quick way, you gotta solve it
indeed
cubic in this case
since its with a ^3 term
you use the rational root theorem to find the first factor of the function
2/1?
are these the possiblities?
-1/-1 =1
1/-1 = -1
2/-1 = -2
2/1 = 2
for a i got -1,1
for c i got -2,-1,1,2 ?
then you do c/a and find out best fit?
long division of what
divide the factor
by
the equation
you can do any type of diviosn
synthetic, long, short
you just divide it
uh wait no what
ok so
what are factors of 2
theres
2
-2
1
and -1
you plug those values into the equation
and see which = 0
ok
ty
is this
the best way
?
what if i used
different quotient
what would that help find
wdym diff quotient
what does using dif quotient
achieve
if i were to use it
in here, for example
i plug in h-> 0
then set = 0 ?
and i should get +- sqrt 1?
oh ok
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can someone help me simplify this: https://gyazo.com/8f5ab3564ef50c3a5db747d740278dd3
alternatively you can write the vectors like u=(u1,u2,u3) etc and then just simplify that
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!15m
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hello???
@vale palm Has your question been resolved?
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so they were explaining how the opposite of differentiation is integration
Yuo
and till x^n+1 makes sense to balance the equation
Yup
and it is so much more ❤️
but why are they doing n+1
:")
Derivative it if you get x^n then your integration is right
in physics we use integration alot as an infinitely "narrow" summation
works wonders
Derivation of answer is the question
i just started calculus, dont know anything
find the derivative of x^ndx?
Hmm you want a brief or a summary?
No x^(n+1)/n+1
what
i dont feel so good ive been struggling with calculus forever
it is nx^n-1
That's derivative
ya
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ty everyone
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is -12/-7 basically 12/7


