help-17

[twin meteor]

Basudev

[vast shale]

umk

[trim walrus]

2=k^(1/p) -(i)
3=k^(1/q) -(ii)
6=k^(1/r) - (iii)

Agreed??

[vast shale]

yes k

[trim walrus]

Multiply i and ii

You get

[twin meteor]

Basudev

Basudev

[trim walrus]

Agreed ??

[low lance]

ntse question ahh

[trim walrus]

Now compare the power and do some Math and you should get 1

[vocal sleet]

@vast shale Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky adder]

hello, can someone please help me with my math homework? ive been stuck at circle and hasnt been able to answer the semi one,
if anyone wanting to help the topic is solving circles and semi circles (angles)

[dusky adder]

i tried solving the circle first (finding the x) but im a bit stuck and dont know where to multiply the ten, please do tell me if i did something wrong :)

btw please excuse my bad english grammar, it isnt my first language ^^

<@&286206848099549185>

[dim junco]

What’s the problem @dusky adder

[dusky adder]

im having trouble on the next step :')

[dim junco]

I see

But where’s the actual problem

Oh it’s above that

[dusky adder]

these r the questions

[dusky adder]

yep

[dim junco]

Wasn’t it

5x+15=180

[dusky adder]

yes

[dim junco]

So subtract 15 on both sides

Then divide by 5

For x

[dusky adder]

im sorry but can u explain what you mean but subtract 15 on both sides?

[dim junco]

Absolutely

So subtract 15 from the left side

And you get 5x

Subtract 15 from right side

And you get 165

So 5x=165

[dusky adder]

hold on, im trying to figure out what you mean, im rlly sorry :')

[dim junco]

You want to isolate x

So if 5x+15=180

You wanna get 5x by itself

So you get rid of the 15 on the 5x side by subracting it

[mighty walrus]

^
The reason you subtract 15 on both sides is because of the equality you want to make X alone so you can find it's value.

[dusky adder]

im sorry but is that for finding the x or finding the measurement of fg?

[dim junco]

Finding x

I thought that was what you needed

[dusky adder]

i needed that, but i thought "2x+5" would also be needed so i got a bit confused

[dim junco]

No I just put the 2x+5 and 3x+10 together

To get 5x+15

[dusky adder]

ohh, i thought you were talking abt solving the circle

[dim junco]

Oh

Do you need help with that

[dusky adder]

i need help with both :')
i didnt understand what our teacher meant and didnt explain it properly

sorry for confusing you

[dim junco]

Could you draw the circle again

[dusky adder]

okay

[dim junco]

It’s a little hard to understand right now

[dusky adder]

tell me if u dont understand thw writing

okay ^^

oh

ow waiy

yeah

in the given there were none

oh

should we try the semi circle then?

if you dont feel like it or if ur too busy rn, its alr

ohh

wait

should i draw it?

done

omg

my teacher is prbably sleeping at this hour

its currectly 12 am abt to be 1 am

do u think thiw will help?

thats the only photo sent in our math gc that could possibly help, the others are inscribed angles

wdym plug in?

like do i just put x in both 2x and 5?

ohh

and may i ask how you found the x?

yes

like multiply it by 2?

ohh

wait

im rlly rlly rlly sorry but im still confused

i mean, on how you solve it, is done in a specific order?

like do u add it after multiplying it?

yes

ohh

ok hold on

so after multiplying the two of them do we add them to eachother like this?

or this?

wait omg

i think i misclicked sum in my calc

do we plus it? if yes r we gonna do sum abt the x?

im still confused, how do u get 360 from adding 10 to just 40?

i tried adding it, i just got 50 and multiplying it iis 400

yeah

x is 32?

ahh okay

just another question

is the formula we used in circle the same for finding the x in semi circle?

so, we just add all of them?

[merry python]

Can you resend your question

I am unable to understand that pic

[dusky adder]

.

[dusky adder]

.

i founf the x

all i need are the arc measurement

[dusky adder]

heres another [hoto if ur confuse

[dusky adder]

i sent

[merry python]

Using linear pair you can easily find x

[merry python]

Okay is the intersection point of chords given as centre?

[dusky adder]

wdym?

[merry python]

The point at which the chords intersect, is that centre of the circle?

[dusky adder]

i just copied what was sent

it wasnt in the center

but idk yeah

[merry python]

If it is not given as centre, then it's not gonna be an easy deal finding arc lengths

[dusky adder]

wait

whats a centre

wait let me search

[merry python]

Probably you made a rough diagram and thus making it look like it is not the centre

[merry python]

Wha-
Centre is a point inside a circle fro. Where all lines to the cirumference are equal

[dusky adder]

i easily forget things

sorry

[merry python]

What grade are you in?

[dusky adder]

7

[merry python]

Do you know angle arc relationship?

[dusky adder]

i dont think we've discussed that yet

[merry python]

I am still not sure
Since I is not given as centre of the circle it may require some tricks

[dusky adder]

like?

[merry python]

idk

It would be better if you close this channel and open new one so as to get more help cuz pretty much no ones comming here

[dusky adder]

r u sure thats alr?

[merry python]

Yes

Just save those pics in case you haven't

[dusky adder]

okay then

.close

[vocal sleet]

Channel closed

Closed by @dusky adder

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stable oriole]

could someone help me with the following geometry problem:

[stable oriole]

R is the radius of the circumscribed circle

[vocal sleet]

@stable oriole Has your question been resolved?

[grim swan]

Sounds like there are two steps here:

1. Finding out the values of the angles in the triangle.
2. Using the angles and the radius of the circumscribed circle to find the lengths of the sides of the triangle.
   Are you comfortable with those steps?

[stable oriole]

yeah sure but how

oh wait

im so dumb

holy shit i cant believe how dumb i am

[grim swan]

What's wrong?

[stable oriole]

i can just say 12x = 180

and then find the angles

and then its smooth sailing from there

[grim swan]

Yup! This is because the sum of the angles in the triangle is 180°.

[stable oriole]

yeah

[grim swan]

Are you comfortable from this point on?

[vocal sleet]

@stable oriole Has your question been resolved?

Channel closed

Closed by @stable oriole

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[molten notch]

hallo

[molten notch]

is this correct?

idk what i just did tbh

[lyric fossil]

what is the problem asking you to do

[molten notch]

uhmmm

we go to the top triangle

and uhmm

which equation should i use

[lyric fossil]

for what

can you post the full question

[molten notch]

i also forgot to add a angle on the top triangle near the 6 ft

[molten notch]

that is the full question

oh wait

let 0 be the angle of elevation of the players line of sight when shooting a free throw to the basketball ring which equation describes the problem?

and then it ust gives me some tigonometric functions

@lyric fossil

<@&286206848099549185>

[vast shale]

0?

[molten notch]

no yk the

[vast shale]

as in theres no angle of elevation?

oh theta

[molten notch]

yea

so what do i do

[lyric fossil]

!15m

[vocal sleet]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[lyric fossil]

your diagram is wrong

[molten notch]

diagrm?

[lyric fossil]

drawing

[molten notch]

how

[lyric fossil]

it looks like the 6 and 10 are at the same height

[molten notch]

oh

noo 10 is the whole of the right side

[vast shale]

im still confused about what its asking you to solve for

[lyric fossil]

can you post the full question

[molten notch]

oh its asking me to find the tigonometric fuction to use

[lyric fossil]

as a picture

[molten notch]

ok

[vast shale]

to find what??

[molten notch]

there

[vast shale]

ohhh

that makes much more sense

[molten notch]

also is my drawing acurate

to the questions

and given

[vast shale]

so your graph is correct

[molten notch]

niceeeee

[vast shale]

but we're focusing on the top triangle

instead of the bottom triangle right

so you dont rly need that one ;-;

[molten notch]

ok

the bottom one?

[vast shale]

so

basically youre only finding the line of sight

[molten notch]

so on the top triangle we have 15 as the adja and we have 4 as the oppo

so were missing the hypo

[vast shale]

but you dont rly need it

since youre finding the angle

[molten notch]

oh

ohhhhh

that's what that evalation stuff meant

[vast shale]

so which trig function uses the opp and adj

[molten notch]

uhhh

tan

cos 0 = oppo/adja

[vast shale]

so it is tan

tan is opp/adj

[molten notch]

yea

[vast shale]

so what would be the ans

[molten notch]

uhmmmmmm

idk

dk how to use tan

ik how to use tan to find a side but not an angle

[vast shale]

15 is adj

4 is opp right

since 4 is on the opposite side of theta

and 15 is next to theta

[molten notch]

yea

[vast shale]

and since tangent is equal to opp/adj

what would it be

[molten notch]

ummmmmm

[vast shale]

for example if it opp was 7 and adj was 2 , tan = 7/2

[molten notch]

yea

it would be 15/4

no wait 4/15

[vast shale]

yup

[molten notch]

so we just divide it?

[vast shale]

theres your answer

[molten notch]

oh

OH

[vast shale]

you cant divide 4 by 15

gl :D

[molten notch]

ITS A

thanks bro

[vast shale]

np

[molten notch]

wait

but wait

how do we find the value of the theta tho

yk the degree

[vast shale]

so i dont think you learned this yet

but later

you would use inverse tangent to find theta

[molten notch]

how

[vast shale]

so tan^-1(4/15)

but you didnt learn this yet i think

its soon tho

[molten notch]

well i dont have a teacher

[vast shale]

oh

wait what

[molten notch]

im stuck on home

[vast shale]

ah

[molten notch]

cause i cant go to school cause of my foot injury

[vast shale]

ill show you it hang on

[molten notch]

ok

[karmic imp]

No it's not. Or you made a typo

[vast shale]

you understand this right

[vast shale]

oh yeah

its b

[molten notch]

what

oh yea its b

[vast shale]

since its tan

anyways

do you understand this

[molten notch]

i kinda dont get it

nope

[vast shale]

so

sin is opp/hyp

cos is adj/hy

*hyp

[molten notch]

yea

[vast shale]

and tan is opp/ad

adj

[karmic imp]

https://www.youtube.com/watch?v=i3bjEOA5_zc&ab_channel=TheOrganicChemistryTutor

[vast shale]

or that

ig

sure

[molten notch]

agreed

so whats next

[molten notch]

also why is cos 4/3

[karmic imp]

You should watch that video

[vast shale]

oh bad handwriting

its 5

but yeah watch that video

[molten notch]

but i want you to teach me

[karmic imp]

It explains most of what you don't understand

[vast shale]

nawr oct explains it much better than i do

[molten notch]

ok

[molten notch]

ok

thanks

.close

[vocal sleet]

Channel closed

Closed by @molten notch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight knoll]

Is this correct?

I have to find the limit of 1/sqrt x using the limit definition

Oh wait

[worthy citrus]

if you times the top of your fraction by $\sqrt{x+h}\cdot \sqrt{x}$ then you have to do the same to the bottom

[twin meteor]

ΣAC

[midnight knoll]

Oh right

I’ll update it

@worthy citrus how does this look

[worthy citrus]

it shouldn't be 4x on the bottom have another go

[midnight knoll]

Alright

@worthy citrus idk what I did wrong

[worthy citrus]

$\sqrt{x}\cdot\sqrt{x} \neq 2\sqrt{x}$

[twin meteor]

ΣAC

[midnight knoll]

Oh wait yeah just saw that

It’s 2x times sqrt x

[worthy citrus]

the whole bottom is yeah

[midnight knoll]

Alright thanks 🙏

.close

[vocal sleet]

Channel closed

Closed by @midnight knoll

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rare wyvern]

using part d) how do i prove part e)

[strange crater]

,rccw

[rare wyvern]

<@&286206848099549185>

[calm tulip]

@vocal sleet

[vocal sleet]

@rare wyvern Has your question been resolved?

[rare wyvern]

<@&286206848099549185>

[vocal sleet]

@rare wyvern Has your question been resolved?

[rare wyvern]

<@&286206848099549185>

[heady ibex]

hey i don't know if what i did was valid

but through some what seems to me to be rather vague ideas i got the right expression

i decided if d is true

let b = c = d = e = f

a special case of d

(d)

then let a = c = d = e = f another special case of (d)

[agile oxide]

What’s this

Or is it 21

[heady ibex]

you should go into a new help channel

@rare wyvern

after you find those two special cases of (d) you add them together

to get the equation

but i have no idea if that is proving anything or if i'm just fucking with the symbols

[rare wyvern]

wym by special cases

[heady ibex]

well a, b, c, d, e, and f can be any number > 0

and the inequality holds

that's proven in (d)

[rare wyvern]

yeah

[heady ibex]

you presumably did tha

t

[rare wyvern]

yeah you can assume d)

yeah cause i proved that alreasy

[heady ibex]

a special case of that is where b = c = d = e = f

and another one is where a = c = d = e = f

[rare wyvern]

then a = b

oh wait

nah becayse they are two seperate cases

aight lemme try that

[heady ibex]

to avoid confusion i should make it b = c = d = e = f and a' = c' = d' = e' = f'

but although i get the correct expression at the end

idk if i just did fucky stuff

or if it actually proves anything

[rare wyvern]

idk that might be it actually

[heady ibex]

i can give screenshot of what i did

[rare wyvern]

though i havent done a proofs question like that

[heady ibex]

if you want it

[rare wyvern]

yeah would be good thanks

[heady ibex]

the second to last line are the two special cases of (d)

[rare wyvern]

yeah that works

[heady ibex]

which you then add together

[rare wyvern]

i dont see a problem with it

[heady ibex]

to get the right expression

[rare wyvern]

damn

thanks a lot

this question was buggin me

[heady ibex]

you should ask a prof for clarification because i am not certain 😄

[rare wyvern]

i will but thanks again anyways

how do i close this

[heady ibex]

.close

[rare wyvern]

.close

[vocal sleet]

Channel closed

Closed by @heady ibex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny storm]

Its good. Here's a better clarified version

[thorny storm]

That was good man, never have I saw a use like that, and I'm going to graduate in maths this month 😂

[vocal sleet]

@thorny storm Has your question been resolved?

Channel closed

Closed by @thorny storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[umbral cove]

Hi, the answer to this is P = 2<-13/5, -19/5> + (1, -5) right?

[umbral cove]

My teacher got a different vector and I have no idea how

I checked my algebra like thrice

he got P = 2<-18/5, 6/5> + (1, -5)

idk how he got the 18/5

wait nvm

.close

[vocal sleet]

Channel closed

Closed by @umbral cove

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

.

How did my teacher determine that this would be in quadranttwo?

[vast shale]

I'm so confused

Because the triangle we have is in quadrant III

How did half of the tan end up in QII

[icy spear]

Quadrant III is the interval (pi, 3pi/2)

half of that would be the interval (pi/2, 3pi/4)

[vast shale]

How do you know that

We don't use unit circle

If that's what you're referring to

[icy spear]

you have to use the unit circle

otherwise it doesn't really even make sense to refer to angles being in quadrants at all

[vast shale]

How did she do it then

She like free stuff

Drew

You see the blue stuff?

[icy spear]

would you agree that angles in quadrant 3 lie in the interval (pi, 3pi/2)

[vast shale]

I know 3pi/2 is a coterminal angle in quadrant 3

I guess those are coordinates?

I've never been allowed to use a unit circle

She doesn't like it

[icy spear]

not coordinates, this is an interval

[vast shale]

What do you mean by that though

[icy spear]

wdym not allowed? how do you even define the tangent then

fine alright how about this.

[vast shale]

We define tangent as opposite over adjacent

Or 1/cotx

Those are identities though

[icy spear]

you see that's not really a definition because it tells you nothing about how to find the tangent as the function of an angle

like if i told you to find tan(2) you probably would have no way of knowing how to do that

[vast shale]

Pi/6

Wait no

[icy spear]

nope

[vast shale]

That's 1/2

[icy spear]

tan(2). not tan(x) = 2.

[vast shale]

Oh

What the heck is tan(2)

[icy spear]

the tangent of 2 radians

[vast shale]

Tan^-1

Inverse trig functions?

[icy spear]

the tangent is a function that takes in an angle and returns a number

[vast shale]

Or would that not work either

[icy spear]

you really do need to use the unit circle, i'm guessing you just haven't gotten to that yet.

[vast shale]

We're almost done with precalculus entirely

She said we'd never use it

[icy spear]

well unfortunately for you she's 100% wrong

[vast shale]

She's a Phd teacher too

I feel like she makes everything harder than it should be

[icy spear]

let's focus on the whole quadrant thing for a moment

[vast shale]

I understand it now

It's just splitting the quadrant system in half

And going from there

Sorry for taking your time up

Thank you for helping me though

.close

[vocal sleet]

Channel closed

Closed by @woeful prairie

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brave ruin]

Ignore the slash

Anyone see my mistake?

The solution is:

Assume Cal 1 knowledge

[outer warren]

you had issues with the application of product rule for

[brave ruin]

Isn't it
d/dx[x]*y + d/dx[y]x = y + dy/dx * x ?

[brave ruin]

^

[outer warren]

yeh, but you didn't have that in you work

[brave ruin]

Isn't it right below that part?

hmmm

I''m gonna rewrite it

it's very sloppy

[outer warren]

you're missing the x in the second term

[brave ruin]

ahhhh

[outer warren]

and you should also have parentheses around that whole part

[brave ruin]

I rewrote it

Hopefully that's easier to read

I stopped at 4

[outer warren]

same issue again

[brave ruin]

no way

can you point to the number

[outer warren]

again you somehow wrote
y dy/dx + 1
which isn't
the y + dy/dx x which i confirmed to be correct

(1), your work for the derivative of xy

[brave ruin]

shit

okay

I see that

is that the only error you see

[brave ruin]

^

[outer warren]

rewrite it, i didn't look at any of the work that involved the result of the wrong derivative

[brave ruin]

okie

[outer warren]

yeh

looks ok now

[brave ruin]

so

can I combine the two terms on the lhs

then on the rhs, I could subtract x^2 dy/dx to get it on the lhs

The idea is to isolate dy/dx

[brave ruin]

bruh

[brave ruin]

Like, after I do what I mentioned above, idk how I'm supposed to get to the solution I provided

[outer warren]

after isolating dy/dx and simplifying you should get the result

show your attemp

[brave ruin]

right

well that's the thing

The mess I got , i'm not really sure

I'll show you

<@&286206848099549185>

[outer warren]

this isn't any different from isolating a certain variable in any other linear equation

[vast shale]

B?

[outer warren]

separate terms with dy/dx from terms without that

[vast shale]

What to find..?

[outer warren]

would you be able to solve
(a + bc)(1/d) = e + fc
for c?

[brave ruin]

Ummm

For that I can divide (1/d) from the lhs

Oh

Wait

(1/d) = (e + fc) / (a + bc)

Hmmm

Yeah I can't figure it out here either

What's the algebra property here that I'm forgetting

[outer warren]

lets make things simpler and reduce this to a question with one variable

would you be able to solve
(2 + 3x)/5 = 2 + 7x

[brave ruin]

(2+3x) = 10 + 35x
.
.
(2 + 3x) - 35x = 10
.
.
.
x[(2+3) - 35] = 10
.
X = 10 / -30 ?

[brave ruin]

Dy/dx

[vast shale]

-32x=8
x=-1/4
Lol

[brave ruin]

5 - 35 = - 30

[outer warren]

(2 + 3x) - 35x = 10
x[(2+3) - 35] = 10
that step was invalid

[brave ruin]

Oh

[outer warren]

x isn't a factor of (2+3x)
you can't factor x out like that

[vast shale]

dy/dx= -(4x³y²+2xy)/2x³+2x⁴y-x
??

[vocal sleet]

@brave ruin Has your question been resolved?

[rough cairn]

Please show me its steps

[vast shale]

Int(2cos2x-1/1+2sinx)dx
=Int(2-4sin²x-1/1+2sinx)dx
=Int(1-4sin²x/1+2sinx)dx
=Int((1+2sinx)(1-2sinx)/(1+2sinx))dx
=Int(1-2sinx)dx
=x+2cosx +C

Use cos2x=1-2sin²x

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[rough cairn]

Thanks 😊

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rough cairn]

Please check this

[paper depot]

where's your solution?

[vast shale]

Bro, this LPP, u have to solve the equations to find intersecting point and hve to make its graph...

[rough cairn]

I want to confirm my ans

[tidal marlin]

what is your answer?

[paper depot]

show your answer and work

[rough cairn]

My ans is D

[thin vale]

Please show your work that got you to the answer of D

[rough cairn]

Hmm wait

[tidal marlin]

isn't z only infinite if either x or y is infinite?

[rough cairn]

Since it maximizing at 2 point so it should be infinite?

[tidal marlin]

Oh mb I read it wrong 😭

[rough cairn]

.close

[vocal sleet]

Channel closed

Closed by @rough cairn

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[storm idol]

Hi

[storm idol]

Not sure how to do this

Do I multiply both of them individually of their conjugate?

<@&286206848099549185>

[sweet frost]

@storm idol
What about taking LCM first?

[storm idol]

Oh

Would that be

Hmmm

How can I do that for m+i and m-i though

[sweet frost]

the LCM of two distinct denominators which cannot be reduced further is equal to their product

a/b +a/c
In above case denominators are distinct and their LCM would be bc

[storm idol]

Oh hmm

Brb shower real quick

Ok

Im back

[rough cairn]

I think you should multiply by its conjugate first

[storm idol]

Each one?

[rough cairn]

Yes individually

[storm idol]

Okok

On it boss

[rough cairn]

Their denomination will become same

[storm idol]

How do you know that

[gaunt pendant]

Well write it as a single fraction

then do some algebra to get it in standard form of a complex number

[sweet frost]

@storm idol are you done with your question?

[storm idol]

Nope

Im a bit busy rn

9 50 pm NZT

4 minutes*

[vocal sleet]

@storm idol Has your question been resolved?

Channel closed

Closed by @storm idol

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kind zephyr]

This is what I have so far

[vocal sleet]

@kind zephyr Has your question been resolved?

[vocal sleet]

@kind zephyr Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal sleet]

@late vessel Has your question been resolved?

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half cloud]

how to get the inverse of this?

[vocal sleet]

@half cloud Has your question been resolved?

[vocal sleet]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twin meteor]

OOKK

[onyx condor]

Let $p(x) = x^5 + x^2 + \bar{1}$ and $ E = \mathbb{Z}_2 [x]/<p(x)>$
I've shown that E is a field since p(x) is a maximal ideal, the dimension of E is 5 and that the number of elements in E is 2^5 = 32. We have that Z mod 2 is a subfield of E such that we can consider p(x) as a polynomial over E. How can we factorise p(x) over E?

[hard atlas]

do you know one root of p? what do you know about conjugation?

[vocal sleet]

@onyx condor Has your question been resolved?

[hard atlas]

dont ignore the bot while you are typing

[onyx condor]

no havent found any roots in E. Not entirely sure what the roots should look like. Are we looking for an x where x is a polynomial upto degree 4?

[vocal sleet]

Channel closed

Closed due to the original message being deleted

[hard atlas]

and dont delete the original message...

get a new channel

[onyx condor]

mb

was an error in the tex

[hard atlas]

then edit, dont delete

[onyx condor]

it wouldnt change

[hard atlas]

copy paste

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx condor]

Let $p(x) = x^5 + x^2 + \bar{1}$ and $ E = \mathbb{Z}_2 [x]/<p(x)>$

[twin meteor]

OOKK

[hard atlas]

the bot only lets you change the output for a few minutes

after that you need to write a new message

what is $p(\overline x)$ ?

[twin meteor]

Denascite

[onyx condor]

A polynomial?

[hard atlas]

no, if anything a residue class

with overline x I mean the residue class of x in E

[onyx condor]

aha

yeah so the elements of E are residue classes

[hard atlas]

yes

and each residue class includes a unique polynomial of degree < 5. which we usually use as the representant

[onyx condor]

mhm

so we are trying to write x^5 + x^2 + 1 as a product of some representatives of residue classes ?

[hard atlas]

no

you said that polynomial is irreducible

so how should we write it as a product

well ok, trivial products I guess

[onyx condor]

oh ok, thought the irreducibility was dependent on the field

[hard atlas]

well ok yes. we'll get there over E

first we want to find a root

and I'm asking you to please calculate p(overline x)

[onyx condor]

i dont know what p(overline x) is

[hard atlas]

plug overline x in

and use what rules about addition and multiplication you know in quotient rings

[onyx condor]

$\bar{x}^5 + \bar{x}^2 + \bar{1}$ ?

[twin meteor]

OOKK

[hard atlas]

yes

next?

[onyx condor]

$p(\bar{x}) = 0 \iff \bar{x}^2 = -1(x^5 + 1) \iff \bar{x} = i * \sqrt{\bar{x}^5 +1}$

[hard atlas]

what?

what is $\overline a \cdot \overline b$ ?

[twin meteor]

Denascite

[hard atlas]

what is i supposed to be

and who says you can take roots in E

[twin meteor]

OOKK

[onyx condor]

it woult be a * b mod p(x) ?

[onyx condor]

yeah thats the issue. not sure how to find roots in e

[hard atlas]

you are just supposed to follow my instructions for a moment. you are not supposed to solve the equation

[onyx condor]

ok leme go back

[hard atlas]

how do you multiply residue classes in a quotient ring

btw we are working mod2, so -1=1

[onyx condor]

(a + N)(b + N) = ab + N

is this what you mean?

[hard atlas]

ok we are switching notation but yes

$\overline a \cdot \overline b = \overline{ab}$

[twin meteor]

Denascite

[hard atlas]

so what is $\overline x ^2 = \overline x \cdot \overline x$ ?

[twin meteor]

Denascite

[onyx condor]

hmm

$\overline{xx}$ ?

[twin meteor]

OOKK

[hard atlas]

yes

or in more usual notation, $\overline{x^2}$

[twin meteor]

Denascite

[hard atlas]

what about $\overline x ^5$

[twin meteor]

Denascite

[onyx condor]

$\overline{x^5}$

[hard atlas]

{}

[twin meteor]

OOKK

[hard atlas]

ok, so now $p(\overline x) = \overline{x^5} + \overline{x^2} + \overline{1}$

[twin meteor]

Denascite

[hard atlas]

next, how do you add residue classes

[onyx condor]

$\overline a + \overline b = \overline{a + b}$

[twin meteor]

OOKK

[hard atlas]

yes

what do you get if you apply that

[onyx condor]

$p(\overline x) = \overline{x^5 + x^2 + 1}$

[twin meteor]

OOKK

[hard atlas]

yes

and what is that residue class equal to

[onyx condor]

alright

how do we go from here?

to finding roots in E

[hard atlas]

how about you answer my questions

[onyx condor]

man im blind

[hard atlas]

what is the residue class of p(x) in E

what is the usual representant

[onyx condor]

0 ?

[hard atlas]

yes

so p(overline x) = overline 0

so in E, overline x is a root of p

[onyx condor]

ok

[hard atlas]

ok

so we found one root

what do you know about field automorphisms

[onyx condor]

wait what? i need to process this for a sec

[onyx condor]

are they just maps from the field to itself?

[hard atlas]

no

they need more structure

[onyx condor]

i see they are isomorphisms

like permutations?

[hard atlas]

iso means bijective, so yes they are permutations

but special ones

[onyx condor]

ok, but im still uncertain what the question to factorise p(x) over E even means. Like what exactly are we looking for?

[hard atlas]

we will eventually get a factorisation (x-a)(x-b)(x-c)(x-d)(x-e) where a,b,c,d,e are elements of E

[onyx condor]

aha

[hard atlas]

we found the first factor with a=overline x

[onyx condor]

ohh now i see why it was a root

can we divide p(\overline x) by (x-\overline x) to get a 4th degree polynomial?

[hard atlas]

we could

but we wont

because then we'd have to do all kinds of calculations in E

and then just get out some random 4th degree polynomial which will be harder to argue with than with p

[onyx condor]

ok

so what now?

[hard atlas]

I was still asking you about field automorphisms

so we got that they are isomorphisms from E to itself. isomorphism in what sense. which operations do they respect

[onyx condor]

im thinking that it would map residue classes to residue classes

and preserve the addition and multiplication rules we just went through

[hard atlas]

well yes E is a set of residue classes

yes

did you do none of this in class?

[onyx condor]

this is the very last part of our intro to algebra class, and i missed the lecture they went through this exercise

we learned about the division algorithm, and when we get fields from ideals

[hard atlas]

in that lecture that you missed or before that?

[onyx condor]

before that

[hard atlas]

do you have notes from friends for the lecture that you missed?

[onyx condor]

yes, in the first half of the lecture they covered 1. definition of a maximal ideal 2. that an ideal I in R is maximal iff R/I is a field 3. That the ideal generated by p(x) in F[x] is maximal iff p(x) is irreducible over F

Also showed that F[x] is a vector space over F and that F[x]/<g(x)> is a finite dimensional vector space for g(x) in F[x] different from 0

[hard atlas]

hmm that is not enough to do this exercise. can you show me the original problem statement?

[hard atlas]

hmmm

[onyx condor]

i feel bad youve helped so much

we can stop here if you want to go. i can ask the classmates after easter what they did

[hard atlas]

did you have in class that over F_p, the map x^p is linear?

[onyx condor]

no

[hard atlas]

(a+b)^p = a^p + b^p ? not seen?

[onyx condor]

no, we've seen the binomial expansion but not this

[hard atlas]

hmm

well for p=2 its easy enough to see

I'm really wondering what they want to hear from you for this exercise

[onyx condor]

sometimes the professors assume we know stuff we dont

[hard atlas]

I guess we can at least factorize p(x)=(x-overline x)*(random degree 4 polynomial)

which is a factorization

not as good as you can do but well

but even seeing that overline x is a root is stuff that I wouldnt expect anyone to come up with

at least not within the time constraint that these assignments typically have

[onyx condor]

They said they intentionally include some questions that we aren't ready for yet to get us to think about the questions. It's not expected of us to solve them

[hard atlas]

oh

[onyx condor]

is there material you'd recommend to read up on for solving these kinds of questions?

[hard atlas]

any book on finite fields

or I mean, just field theory in general

[onyx condor]

thank you so much for all the help

[vocal sleet]

@onyx condor Has your question been resolved?

Channel closed

Closed by @onyx condor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique stone]

hey

[oblique stone]

question

how would i go about proving or disproving this. don't want the answer, just the first step

[strange crater]

use the definition of m|n first

[oblique stone]

what is the definition?

n=mk?

[strange crater]

you should have learned that if you are asked to prove things about divisibility

[oblique stone]

these are questions that haven't been covered yet

*topics

also is it assumed that the devisor is the same in all 3 statements?

@strange crater

[strange crater]

if m | n then there exists some k such that n = mk. you got that right

since the conclusion is a negative statement, it might be easiest to prove by contradiction

[oblique stone]

ah

so what would be the first step, assume d|m?

[rough barn]

yeah

[strange crater]

assume $m | n$, and $d \nmid n$ and $d | m$

[twin meteor]

cwatson

[strange crater]

and reach a contradiction

[oblique stone]

mhmm

so then i would do n=mk, n !=dk, and m=dk?

and then substitute?

[strange crater]

try it, see what happens

if you get stuck, come back

[oblique stone]

m!=d

ok

ok i tried assuming that d|m and ended up getting k!=1

i don't think im approaching the question correctly. no?

@strange crater

[strange crater]

so you have n=mk as one assumption, and you're also assuming the negative of the conclusion, so that d|m. but that doesn't mean m=dk; i.e., it won't be "the same k" for both necessarily

so assume m = dj for some j

so you have n = mk, and m = dj

then what would you do?

[oblique stone]

rearrange and get n/k=dj?

[strange crater]

no, do it one step at a time

but you were on the right track...

[oblique stone]

hmmm

[strange crater]

so, go back. what is the next step after seeing that n=mk, m=dj

[oblique stone]

substituting

[strange crater]

which gives you what?

[oblique stone]

n=djk

[strange crater]

now what does that mean, right there?

[oblique stone]

means m=dj

[strange crater]

you started w/ that already

just look at n=djk itself

and look back at your starting assumptions

[oblique stone]

oh

it breaks the definition of n=mk

[strange crater]

how would it? you used n=mk (along with m=dj) to get to n=djk

[oblique stone]

yes my bad

[strange crater]

no worries. look at all the starting assumptions

[oblique stone]

unsure

[strange crater]

what if it was written like n = d(jk)

think of the definitions you used to start the proof

[oblique stone]

i don't know

could i do d!|n = n!=gd

[strange crater]

if $m | n \leftrightarrow n = mk$ then what does $n = d(jk)$ tell you

[twin meteor]

cwatson

[strange crater]

remember, we're looking for a contradiction to be reached

[oblique stone]

i don't know, i just get back to m=dj

wait

[strange crater]

does $n=d(jk)$ contradict any of the assumptions: $m | n$, and $d \nmid n$ and $d | m$

[twin meteor]

cwatson

[oblique stone]

i think i understand it now but i don't know how to write it

[strange crater]

if you understand, then explain in words

[oblique stone]

actually my line of reasoning didn't make sense, nvm

ok i don't know. another hint? @strange crater

[strange crater]

if I tell you that you don't need to do anything more, does that help? you have enough finished to conclude the proof...

which of the 3 assumptions have we not used so far?

[oblique stone]

n!=gd

[strange crater]

yes

and with the other 2 assumptions we've shown that $n = d(jk) = (jk)d$

[twin meteor]

cwatson

[strange crater]

so what does that tell you?

[oblique stone]

d!=d?

[strange crater]

no, you're not manipulating equations here

if I told you "let g = jk"

then what?

[oblique stone]

djk!=gd

jk!=g

[strange crater]

but we are saying that g = jk.........

there's the contradiction

[oblique stone]

why is that something we can assume?

[strange crater]

because j and k are just integers. so their product is another integer. we can just call it "g", or "x", or whatever

[oblique stone]

ah i see fair enough

[strange crater]

so by saying $n = d(jk) = (jk)d = gd$, we are saying that $d | n$, which contradicts our (given) assumption that $d \nmid n$

[twin meteor]

cwatson

[oblique stone]

ok that's where the issue was in my understanding, got to jk!=g and didn't know where to go

thank you very much @strange crater

.close

[vocal sleet]

Channel closed

Closed by @oblique stone

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

idk how to convert them

[vocal sleet]

Please don't occupy multiple help channels.

[vast shale]

.close

[vocal sleet]

Channel closed

Closed by @coral gate

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet bough]

how do i solve for 0<x<180? i did tan(3)^-1 to get 71.57 and i divided that by 2 to get 35.78 but one of the other answers is 125.78 and idk how to get that

[dull bear]

if 0<x<180 then 0<2x<360 - for these types of questions it can be easier to make a substitution such as u=2x, solve for u first, and then from there solve for x

[scarlet bough]

.close

[vocal sleet]

Channel closed

Closed by @scarlet bough

Use .reopen if this was a mistake.

[vocal sleet]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gentle anvil]

Im trying to determine the function for the sum of this power series

[gentle anvil]

Im figuring its something with e^x^2 but the (n+1)n! Part is really throwing me off

[rugged vortex]

Hm

Yeah no that (n+1)! Is tricky

[dull bear]

Maybe make a substitution in the sum to change the n+1 into n

[river minnow]

Reindex

[gentle anvil]

Reindex?

[gentle anvil]

How would i go about doing that ?

Also according to wolfram its

[dull bear]

As in your original was
[
\sum_{n=0}^{\infty} \frac{x^{2n}}{(n+1)!}
]
we're suggesting to shift the terms so that the $n + 1$ turns into $n$ in the sum

[twin meteor]

@dull bear

[rugged vortex]

Yeah that's also what I got

Well

Without the -1

Hm

Because I let u = n+1

[dull bear]

||probably where your series started from and taking into account that||

[rugged vortex]

Oop

[gentle anvil]

How would i shift the terms so it would be n?

I cant see it

[rugged vortex]

Well let u = n+1

[dull bear]

this here

[brave ruin]

i actually tried and found it... a few steps after this and u r done

[gentle anvil]

Okay so i got, U!

How does that do anything cuz i dont know where to go from, dont think ive learned this approch looking through the text book

[brave ruin]

should i try to explain or share soln, cox soln is easy to look at and understand

[rugged vortex]

well they already know the answer

So showing steps is fine

[brave ruin]

cool

expansion of e^x^2 can be obtained using maclaurin & taylor series

[gentle anvil]

Thank you this makes so much sense i got it now!!! ❤️

.close

[vocal sleet]

Channel closed

Closed by @gentle anvil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[autumn badger]

what is number of term?

i found q, she said q is the common ratio

[sacred acorn]

So if u_1 = 16, then we want to find the number x such that u_x = 1/8. The question is just saying how far we have to go in the sequence to get to 1/8

[autumn badger]

hm, so n = 7

?

u1 = 16
u2=8
u3=4
u4=2
u5=1
u6=1/2
u7=1/4
u8=1/8

[sacred acorn]

that's right but you also have to include the 16 at the beginning in your counting so it would be 8

[autumn badger]

oh

thanks

[sacred acorn]

no problem 🙂

[autumn badger]

.close

[vocal sleet]

Channel closed

Closed by @autumn badger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade sparrow]

for this: https://i.imgur.com/HmN4rkF.png

[jade sparrow]

is it 15 * 14 * 13 + 10 * 9 * 8?

[loud walrus]

yes

[vocal sleet]

@jade sparrow Has your question been resolved?

[jade sparrow]

ty

[vocal sleet]

Channel closed

Closed by @jade sparrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast shale]

Have I evaluated this correctly?

[desert hornet]

,rcw

[desert hornet]

what do you need to calculate?

[vast shale]

F'(x)

[desert hornet]

not quite

you would have to multiply it by the derivative of the ineer function

due to the chain rule

[vast shale]

Oh, I thought the chain rule was just for say if it was like integral[5,x^2]

So would it just be F'= -4x^3tan(x^4)?

[desert hornet]

wait

I'm getting confused

i think it's best if somebody else helps you

[vocal sleet]

@vast shale Has your question been resolved?

[vast shale]

my original answer was correct *

.close

[vocal sleet]

Channel closed

Closed by @swift jetty

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank plover]

What math rule allows this?

[prime spear]

ithink its fractional exponent

[frank plover]

.close

[vocal sleet]

Channel closed

Closed by @frank plover

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing depot]

does derivatives mean slope?