#help-13

428200 messages · Page 474 of 429

dire geode
#

Pretty sure this is what Camil meant

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We learning cryptography now

hollow osprey
#

why the lol

wraith crypt
#

i'm looking up math 55

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and it looks really interesting

hollow osprey
#

hav u taken abstract alg

wraith crypt
#

i had something like that in my year 1

wraith crypt
hollow osprey
wraith crypt
#

depends on whether you like algebra?

hollow osprey
#

do you?

flint plinth
hollow osprey
#

lecture 1 is groups

wraith crypt
#

personally i don't have much of an intuition for algebra, so i only did groups through modules and fields, and some lie algebra, and stopped

flint plinth
#

Good grief, I didn't even know this fact about non-abelian finite groups, that at most 5/8ths of the possible pairs of elements commute, and that inequality is sharp.

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That's on homework 2

wraith crypt
#

ironically i found rings horrible, but lie algebras quite exciting, though maybe part of that is because the lecturer was much faster

gentle lintel
#

i’m doing chad’s final exam

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can i simply leave the key insights down

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i don’t want to work out concrete values 😦

hollow osprey
#

yeah

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no one stopping you lol

wraith crypt
flint plinth
hollow osprey
#

what's the prereqs for this class?

wraith crypt
#

as a freshman i would have totally welcomed it

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but my experience is atypical

flint plinth
hollow osprey
#

guys what would be the normal progression for a first year math major

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like calc 3 / diff eq / lin alg -> then what

flint plinth
wraith crypt
#

my course load in my very first sem, was five courses each covering the equivalent contents of four semesters

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that pattern carried on to the second sem

wraith crypt
#

on average maybe four hours?

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it was a hard year

hollow osprey
#

4 hours of sleep for a whole year?

wraith crypt
#

no, for two semesters

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winter and summer break, what do you think i spent time doing?

hollow osprey
#

9 months?

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catching up? idrk

wraith crypt
#

sleeping and in winter break, prep work

flint plinth
#

Winter and spring break would have called for hibernation with a schedule like that 😁 And I guess some video games

gentle lintel
#

for the first one, notice $\sin^2x = \frac{1 - \cos 2x}{2}$. everything is simple afterwards

wraith daggerBOT
#

Chromium

hollow osprey
#

yep

wraith crypt
gentle lintel
#

fot the second, $\frac{1}{x^3 + x^2 + x} = \frac{1}{x} - \frac{x + 1}{x^2 + x + 1}$.

wraith daggerBOT
#

Chromium

hollow osprey
#

second one you might actually wanna just finsh

gentle lintel
#

everythnig should also be simple

hollow osprey
#

cuz its not very hard

gentle lintel
hollow osprey
#

but yeah in essence that's it

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but PFD would be easier than the integrals themselvesl ol

gentle lintel
gentle lintel
hollow osprey
gentle lintel
#

how are the integrals hard

hollow osprey
#

they rnt but would be more challenging then just algebraic PFD

#

anyways what did you get for next Q

gentle lintel
#

2?

ripe stone
#

can anyone help me?

gentle lintel
#

2a just average the tip and tail of the line segment.

hollow osprey
ripe stone
#

this has four lines of symmetry right

gentle lintel
ripe stone
#

oh ok

gentle lintel
ripe stone
#

how do i get help

gentle lintel
wraith crypt
gentle lintel
#

❓how-to-get-help❓how-to-get-help

hollow osprey
#

❓how-to-get-help

gentle lintel
#

anyway

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2b, just sum some rectangles, some triangles, and a semicircle

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2c: F'(5) = 4

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2d: it's the perimeter of the semicircle

fallen heath
#

it'd be better to work out the specific values if intending to assess yourself

fallen heath
#

chad, what's the time allotted for the exam?

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2hrs?

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3?

hollow osprey
#

not sure

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but it would prob be 2 hours

wraith crypt
#

paper like this, no more than 2 hours, but 90 minutes feels more likely

fallen heath
#

camieee 2hrs is okay lol

wraith crypt
#

...where i'm at, 60 to 75 minutes for this kind of paper is expected y'know

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i'm being kind with 90 HAHA

hollow osprey
#

yeah i think the TA's period would be around 90 mins

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but that would be if he was taught all this stuff in a class and prepared for this final (which he wasn't)

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so i think 2 hours is fine

wraith crypt
#

2 hours is fine if chromie was actually writing down the full solutions and not...y'know

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also, i'm looking at 55a and 55b and now i wish i took it hnnng

fallen heath
#

I believe chromie should realllyyyy write the answers at least

cedar kilnBOT
#

@gentle lintel Has your question been resolved?

fallen heath
#

2 d) I believe is also a fun one :o

gentle lintel
fallen heath
#

._. what's the answer for 1 b)

hollow osprey
#

he just did the PFD and then said "integral is trivial"

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for 1b

fallen heath
#

lmao

hollow osprey
#

not even joking you can scroll up lol

fallen heath
#

more like, if you really wanna assess but also haste through it, just give us the answers and spare the solution lol

hollow osprey
#

true but he just wanted to make sure he got all the big picture concepts

gentle lintel
gentle lintel
#

so yea, won’t dwell on that lol

hollow osprey
#

$\int \frac{ax+b}{cx^2+dx+e}$

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
#

generalize this

fallen heath
#

lmfao

hollow osprey
#

it would take a while but it might be fun?

gentle lintel
hollow osprey
#

lot of constants you would have to work with however

gentle lintel
#

the other with trig sub

hollow osprey
#

trig sub? you mean formula

gentle lintel
gentle lintel
#

i don’t memorise those

hollow osprey
#

$\int \frac{1}{u^2 + a^2} = \frac{1}{a}\tan^{-1}\qty(\frac{u}{a})$

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this one is good to know IMO

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
#

this is the only one i have memorized

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and the integral of ln(x) cuz that one shows up a lot (and its not super standard)

gentle lintel
#

yea

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for 3, solid of revolution in terms of y coordinates
goes from -√3 to √3, 4 - y² - 1² is the integrand i believe

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for 4, only (b) is true, i think

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(based on the given information)

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5 involves work stuff, i’m not familiar

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6b, i don’t know what a centroid is

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for 6a, (√(1 - (y - 2)²/4), y) are on the given part of the ellipse

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one can easily craft a solid of revolution formula

wraith crypt
gentle lintel
dire geode
#

not doing very well on this final so far 😐

wraith crypt
#

LOL

gentle lintel
#

for 7, √(1+(f’)²) gives a perfect square

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,rotate

wraith daggerBOT
gentle lintel
#

(rough work, if anyone’s interested)

gentle lintel
fallen heath
#

time's not over yet and we don't have all your answers either

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cheating not allowed lol

gentle lintel
dire geode
gentle lintel
#

(8, 9 involve diff eq, i haven’t touched those either ;-;-;-;)

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here’s 10a

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,rotate

wraith daggerBOT
gentle lintel
#

2+C turns jnto C

gentle lintel
fallen heath
#

we really don't have any answers so I'm not sure how anyone's supposed to grade lol

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chromium, are you really that averse to solving the paper?

wraith crypt
#

i, too, would like to read full solutions when grading

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believe me, there's a reason why i rather enjoy giving zeroes to incomplete scripts

fallen heath
dire geode
fallen heath
#

lmao

wraith crypt
#

XD

hollow osprey
#

btw 7 can also be done by hyperbolic cosh / sinh

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few things to notice

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sinh^2-cosh^2 = 1

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d/dx sinh(x) = cosh(x) and d/dx cosh(x) = sinh(x)

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and that cosh(x) is just e^x's even part, and sinh being e^x's odd part

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that is.

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cosh(x) = (e^x+e^-x)/2 and sinh(x) = (e^x-e^-x)/2

fallen heath
#

examiner provides hints moment holoYay

hollow osprey
#

ikr 😮

wraith crypt
#

oh, are we grading already?

gentle lintel
#

10b is done by induction, but i’m stuck in some int (int f dx) dx situation

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it’s a 4 point problem, even lower than q1

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i believe i’m overlooking something obvious

wraith crypt
#

well, that's an exam for you

gentle lintel
#

or is it not induction at all

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wtf

fallen heath
#

welp, 20 minutes left and we still don't have any answers from you

gentle lintel
#

i’m struggling to do 10b

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lmao

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@dire geode just point out my mistakes

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i’ll attempt another paper later

fallen heath
#

we literally can't lmao, no one's got any clue what you did

fallen heath
#

🥺 👉 👈 pweaseee

dire geode
wraith crypt
#

you go ahead, i got an integration bee in a week to judge and have my own fun

fallen heath
#

integration bee blobsweat

wraith crypt
#

nah, knockoff of MIT's

dire geode
#

does sound fun

fallen heath
#

$\int \frac{e^x}{\ln x} \dd{x}$

wraith daggerBOT
fallen heath
#

Amen.

dire geode
#

But I soon learned that it's much harder to do calculus in the front of the room when the pressure is on.

gentle lintel
#

ibp

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i think

hollow osprey
#

10b is just IBP

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no induction needed (it also wouldn't be expected)

fallen heath
hollow osprey
#

Lol

hollow osprey
#

,w integral of e^x/ln(x)

wraith daggerBOT
hollow osprey
#

i was right!

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a u sub gets you that nice

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$\int \frac{e^{e^u} \cdot e^u}{u} \dd u$

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
#

and this is pretty non elementary

#

looking

fallen heath
#

those moments when your familiarity with integrals and the practice pays off

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.
.
.
kept telling myself, don't fuck up at the beginning, because there's so little margin of error on the easier integrals.

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damn, int bee looks scawy

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ntm, JEE calculus papers are scawy enough

wraith crypt
#

i don't like that type of competition tbh

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i like the type where i can sit down for five hours and do five questions

hollow osprey
#

!?

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Sounds like university homework

fallen heath
#

me imagining chromi interrogating about the proof for distributive property of determinants

gentle lintel
#

oh yea

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can i try some uni hw

fallen heath
#

Did you finish the paper?

gentle lintel
#

calc1-2 stuff

hollow osprey
#

this is the bonus question

gentle lintel
gentle lintel
hollow osprey
#

Prove that $\frac{x}{1+x^2} < \tan^{-1}(x) < x \text{ } \forall x \in \mathbb{R}^+$

fallen heath
#

FAILED TO RENDER

gentle lintel
#

lmao

fallen heath
#

no bonus question ;-;

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oof

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
dire geode
hollow osprey
wraith crypt
dire geode
#

answer

fallen heath
hollow osprey
wraith daggerBOT
fallen heath
#

everyone QED lmao

hollow osprey
#

Prove that $$\text{all nontrivial zeros of the } \zeta(s) \text { function have a real part of } \frac 12.$$

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
#

+300 iq + $1,000,000

fallen heath
#

lmao

gentle lintel
fallen heath
hollow osprey
#

and being REALLY smart with the inequalities

fallen heath
#

$\int_0^{2\pi} \sin^2 \theta \dd{\theta}$

wraith daggerBOT
hollow osprey
#

i think he said trig identity

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(power reduction)

foggy merlin
#

or sinx = (e^ix - e^-ix)/2 pandauh

fallen heath
#

lmao

hollow osprey
#

then does it become a complex integral

gentle lintel
foggy merlin
gentle lintel
#

consider cos 2x

hollow osprey
#

no contour integral!/

gentle lintel
#

what the fuck

fallen heath
#

$=\int_0^{\pi} (1 - \cos 2\theta) \dd{\theta}$?

wraith daggerBOT
foggy merlin
#

/2

wraith crypt
#

i find myself amused

gentle lintel
#

alright

dire geode
#

Camil tomorrow: automatic 0/100 for chromi. no cheating allowed

gentle lintel
fallen heath
#

wdym something like that?

gentle lintel
#

sin² = (1 - cos2x)/2, basically

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just use this

hollow osprey
#

WHAT?????

gentle lintel
#

integral is then solved easilt

fallen heath
#

sin²x = (1 - cos² x)/2?

hollow osprey
#

HE IS INVENTING TRIG!

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okay

fallen heath
#

ahem

hollow osprey
#

now its correct

fallen heath
#

okay umm

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I still don't understand what's wrong with $$=\int_0^{\pi} (1 - \cos 2\theta) \dd{\theta}$$

wraith daggerBOT
gentle lintel
#

i haven’t checked the bound changes and all

hollow osprey
#

he already accounted for the bounds i think

gentle lintel
hollow osprey
#

is the area from 0 to pi = to the area from pi to 2pi?

hollow osprey
#

then he already halfed it

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so ur answer is still fine ansh

fallen heath
#

next ??

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what did we do with this I wonder :o

sick ruin
#

Holy pain

hollow osprey
#

i told someone

gentle lintel
#

1/x - (x + 1)/(x² + x + 1) is the main insight

fallen heath
#

wrong

hollow osprey
#

chromium pfd'd it and then called the rest trivial

fallen heath
#

0 for this one ig :/

hollow osprey
#

RIP that's like

gentle lintel
hollow osprey
#

10% of the test right there

fallen heath
#

Yeah

gentle lintel
#

i don’t think it is

sick ruin
#

How is that wrong

fallen heath
#

It is

gentle lintel
#

or am i failing algebra

fallen heath
#

You're failing English lmao

dire geode
fallen heath
#

It is not the main insight

gentle lintel
sick ruin
#

😟

gentle lintel
fallen heath
#

so umm

wraith crypt
#

...is chromie suddenly chinese?

foggy merlin
fallen heath
#

nope, it's still not the main insight

gentle lintel
#

it is to me

fallen heath
#

no matter what you do :/

hollow osprey
#

this is gonna be chromum the day after that

fallen heath
#

Nope

sick ruin
gentle lintel
#

that’s split into two integrals, correct?

#

the former is ln x

foggy merlin
dire geode
fallen heath
#

could you explain how you plan to do $$\int \frac{x+1}{x^2 + x + 1}$$ ?

wraith daggerBOT
gentle lintel
#

yea

wraith crypt
fallen heath
#

Lmao

gentle lintel
hollow osprey
#

LOL

gentle lintel
#

generalisation here

fallen heath
#

:o

#

sure ig

hollow osprey
#

but do you know how to do that?

gentle lintel
foggy merlin
#

Vertex form on the denominator

fallen heath
#

oh right :o

wraith crypt
#

until and unless i have some proof you know how to do it, i will still give a 0

#

it's grading

#

no hard feelings

foggy merlin
#

and you do some shits to obtain arctan and log

fallen heath
#

0 for this one, yeah

gentle lintel
#

(at this point i could just copy from the sent video and you wouldn’t know, so 0 me i guess)

#

but i just looked it up

hollow osprey
#

-100% cheating

gentle lintel
#

so uh believe me or not

#

lol

fallen heath
#

what about this?

#

how?

gentle lintel
#

(2-4)/2

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=-1

fallen heath
#

why?

dire geode
#

so how do you feel about your assessment so far

gentle lintel
#

i fail enlgihs

#

uhh

fallen heath
#

umm?

gentle lintel
#

average of linear of [a, b]

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is 1/2 (f(a) + f(b))

fallen heath
#

what's the average of "f" defined as anyways

hollow osprey
#

1/2???

gentle lintel
#

i could do an integration

gentle lintel
gentle lintel
hollow osprey
#

oh wait yeah

hollow osprey
gentle lintel
#

(i’m too lazy for that either, sorry)

fallen heath
#

:o no worries

#

so your answer for this is -1?

gentle lintel
gentle lintel
fallen heath
#

so uhh

foggy merlin
#

$\phi \leq \int f \leq \ksi$

fallen heath
#

I'd like an answer to 2b.

gentle lintel
#

come on

#

i can’t be bothered to carry out the computations 🤦

fallen heath
#

what's $$\int_0^{10} \abs{f(x)} \dd{x}$$

wraith daggerBOT
gentle lintel
#

19 + area of semicircle

#

19 + 4pi

#

there

fallen heath
#

:o

#

well, okie

gentle lintel
#

my message

wraith crypt
fallen heath
#

can't read (@_@;)

dire geode
gentle lintel
#

it got colder here

#

and i can’t type

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or write in a neat way

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i mean if you insist, i will

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i just don’t want to

fallen heath
#

welp, if that's the case, we can leave at that ig... and here's a trivial assessment to your attitude with calculus:
$$\int 1 \cdot (\ln x)^k \dd{x} = (\int \dd{x}) (\ln x)^k - \int x [(\ln x)^k]' \dd{x}$$

wraith daggerBOT
gentle lintel
#

?

#

so what’s the assessment lol

hollow osprey
#

ansh

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wtf is this

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wait

wraith crypt
#

?

hollow osprey
#

ah nm

dire geode
#

integration by parts?

hollow osprey
#

i read it wrong

fallen heath
#

my version of IBP is $$\int u\cdot v \dd{x} = \qty(\int u) v - \int \qty(\int u) v' \dd{x}$$

wraith crypt
#

lol

wraith daggerBOT
hollow osprey
#

thought he randomly switched order of dx and lnx^k

dire geode
#

Ansh wants to insert as many integral signs as possible in all his formulas

wraith crypt
#

today, integration by parts

hollow osprey
#

then again its almodt 1 am

gentle lintel
wraith crypt
#

tomorrow, Abel's partial summation

hollow osprey
#

i hav excuse

foggy merlin
dire geode
#

Abel's death

fallen heath
#

at least less confusing than: $$\int u \dd{v} = \ldots$$ or whatever it is

wraith daggerBOT
dire geode
wraith daggerBOT
#

riemann

hollow osprey
#

no one knows

fallen heath
#

Yessir, recognize int stuff

hollow osprey
#

everyone usess DI / tabular

fallen heath
#

i forgot tabular ;-; but it sure is handy

#

sin^n x blobsweat [or smth like dat, pardon me]

hollow osprey
#

DI = holy grail

fallen heath
#

I feel like I made myself pretty clear but, I feel like Chromi's pretty not-comfy with the fundamentals of calculus

gentle lintel
#

so what do i do lol

#

rewatch some videos?

#

do more exercises?

fallen heath
#

wait for other assessments sad [that's just my personal opinion]

fallen heath
#

@dire geode 👀 what do you think?

#

Also considering every doubt chromi's ever have in last couple days

dire geode
#

probably need to do at least 100 integrals and struggle to identify when to use trig sub, ibp, u-sub, partial fractions

gentle lintel
#

lol

fallen heath
dire geode
#

additionally, you need to do them to completion on your own

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asking for help occasionally is fine

gentle lintel
#

here’s something i tried

hollow osprey
#

link is super skecth lookin

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so theres a picture of it

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its BPRP's 100 integrals

fallen heath
#

oops with the number there (@_@;)

dire geode
gentle lintel
#

i’ve tried those as well

hollow osprey
dire geode
fallen heath
wraith crypt
#

i have looked through all 90 and i have methodologies for about 85 of them in my head offhand

hollow osprey
fallen heath
#

ntm, there's another set of at least 500+ integrals in my additional sheet

wraith crypt
#

that does not mean i actually tried them

fallen heath
#

which we did as a holiday homework in winter vacation lmfao

#

so 7 days ✓

dire geode
hollow osprey
#

ive ever heard

dire geode
#

,w random number 1-100

wraith daggerBOT
gentle lintel
#

q2?

dire geode
#

god dammit

hollow osprey
#

LOL

#

that sucks

dire geode
#

go chromi

hollow osprey
#

chromium

#

do # 14

dire geode
#

the wolf gods have given you a blessing

#

less of a blessing

foggy merlin
hollow osprey
#

that's the hardest one ive seen so far

gentle lintel
#

harmonic addition formula

hollow osprey
#

(didn't know how to do it immediately)

foggy merlin
hollow osprey
dire geode
wraith crypt
#

LOL

hollow osprey
#

camil

dire geode
#

latex solutions also welcome

hollow osprey
#

u know what the "harmonic addition formula is"?

#

,w harmonic addiont ofrmula

wraith daggerBOT
hollow osprey
#

oh god

#

,w harmonic addition formula

wraith daggerBOT
hollow osprey
#

cringe

fallen heath
fallen heath
wraith crypt
hollow osprey
#

BPRP taught me

#

but would that even help?

foggy merlin
#

ah this shit : acos(x) + bsin(x) = Acos(x+phi)

hollow osprey
#

papa weirstrass

#

is here to save the day

fallen heath
#

🚶‍♂️

wraith crypt
#

yes that shit

hollow osprey
#

,w integral of (3sin(x)+7cos(x)-6)/(sin(x)+cos(x)+1)

#

wolfram uses papa weirstrass

fallen heath
#

de le te

hollow osprey
#

no way you can do that with harmonic whatever formula

fallen heath
#

🤦‍♂️

hollow osprey
#

porque del?

fallen heath
#

lmfao

hollow osprey
#

if chromium is workin on that

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he isn't being distracted by this

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cuz that would take a while

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chromium i c you

#

therefore you are not doing the integral

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disappointed

#

😦

fallen heath
#

Idek if we're done with concluding the $$\lim_{x \to -\infty} \qty(1 + \frac{1}{x})^x = e$$ discussion

hollow osprey
#

yooo

wraith daggerBOT
gentle lintel
#

definitely

hollow osprey
#

Chromium prove it via epsilon-delta

#

then we can be done.

fallen heath
#

:/

hollow osprey
#

no triangle inequality either

wraith crypt
hollow osprey
dire geode
fallen heath
#

👀 isn't it just... :whispers:

fallen heath
foggy merlin
hollow osprey
#

nah i could see where hes coming from

#

cuz if you let u = -x

#

then you would get the 1/-u in the inside

fallen heath
#

yeah lol

hollow osprey
#

and that looks like 1/e.... but its not cuz -u in the power

#

so whole thing to the power of -1 and then you get 1/(1/e) = e

fallen heath
#

would be more insight-ful if you visited the working of the limit

dire geode
#

"1/e is close enough to e, i understand it enough" --chromi, probably

gentle lintel
#

tangent half angle substitution!!!!

foggy merlin
#

well cya guys, ima do physics

hollow osprey
#

cya

gentle lintel
#

(applaud me. or not.)

fallen heath
#

Byee

hollow osprey
fallen heath
#

illegitim- (coughs)

gentle lintel
#

auhemdnkkekdd

#

what do.

#

now

dire geode
#

show your work for 14

hollow osprey
#

$\int \sin(x^2)dx$

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
#

"try this" --menace to society

#

or

#

$\int \sqrt{1+x^3}dx$

wraith daggerBOT
#

Shuri 4 honorable (Yottachad)

hollow osprey
#

please do not try these

#

try 41

gentle lintel
fallen heath
#

if you're done with 41. I'll check if there's a more fun one that I seem to recall

dire geode
#

you write 3 words down Camil's gonna give you 3 words of her own "what. the. f"

fallen heath
#

$$\int \frac{\sqrt{u+2}}{\sqrt{u}} \dd{u}$$ Now what??

wraith daggerBOT
fallen heath
#

$\sqrt{u} + \sqrt{2} = \sqrt{u+2}$ maybe?

wraith daggerBOT
fallen heath
#

surely ig :o

#

well, if you're done with this one as well, you're welcome to try: $$\int \sqrt{\frac{x - 3}{2 - x}} \dd{x}$$

wraith daggerBOT
fallen heath
#

Let u = x - 3 ? thinkies

#

Let x = 2 \cos^2 \theta ? thinkies

#

have fun :/

gentle lintel
#

jesus

fallen heath
# gentle lintel integrals are just puzzles

I'm amazed you realized. But your current study discipline doesn't depend majorly on your fluency with integrals but rather the basic stuff like how to evaluate a limit, what mistakes to avoid when differentiating/integrating, etc. and mainly the very definitions of couple stuff, and the fundamentals is exactly where I find you lacking.

fallen heath
#

no comment

hollow osprey
#

try this one

fallen heath
#

we're not done with the last three ones ig?

gentle lintel
#

in calculus

#

are you able to provide comment?

fallen heath
#

self-satisfaction

#

is all

hollow osprey
#

well how to do everything for sure

#

but prob a little less of the general "ideas" behind the stuff

#

such as epsilon delta definitoin of limits

#

riemann sums to derive all the arclength / volume formulas

gentle lintel
#

(i’ve seriously done everything in my power to strengthen the fundamentals, the definitions, and so on.)

#

(if that’s not enough, i don’t know what is)

hollow osprey
#

i think you've done pretty well my friend

#

but just look into some of the derivations

gentle lintel
#

(considering how most, i assume, cover these in a matter of weeks)

hollow osprey
#

to get a better grasp

wraith crypt
#

look, maybe i'll give you an anecdote, which so happens to be a true story that happened to me in my very first week of school

#

so i wanted to test into this advanced calculus class, because it's advanced calculus and i was pretty confident i could take it

#

famous last words, but that's not the point

dire geode
wraith crypt
#

to study for that test, which i was only told about 24 hours in advance about, i decided to hey let's read and understand limits and derivatives and stuff, and i did that in three hours, covering limits and riemann sums and basic derivatives and FTC

#

the problem is, i found a mock test after those three hours, and i had exactly zero clue how to do shit

#

i knew all the definitions and theorems, and that's the problem: that's all i knew

#

all those little nitty gritty that comes up in the process of solving problems, i didn't have a clue

gentle lintel
#

hey i’ve got an ancedote too

wraith crypt
#

how to write a proper argument for why $\sum \frac{1}{ne^n} < \infty$, no bloody clue

gentle lintel
#

uhh

wraith daggerBOT
#

Camilleone

wraith crypt
#

so i had to spend a lot of time re-learning everything, but this time making sure i did stuff properly, step by step, and that's how i finally learned calculus, properly

fallen heath
#

this anecdote would surely be nice words of caution for me

soft cloak
#

Yeah, there are some things you can only learn in practice

gentle lintel
#

should i share my ancedote lol

soft cloak
#

And at some point you need to get the hang of it

#

As Ben Finegold once said, theory and practice are the same thing in theory, but not in practice

gentle lintel
#

yea, waste of time and here i am again

fallen heath
# dire geode damn ansh, the truth hurts

Well, what else would you say if you find someone constantly questioning interesting questions, that one would probably not even expect from a, say top rank scorer in hs, only to later find out that this person substitutes x = 0 to find the indeterminate form of (sin x)/x and writes 1/x should have an undefined form?

gentle lintel
#

or tried things similar

#

i don’t think i expressed myself correctly

#

remember that stackexchange thing i sent

#

that you said was a ‘good finding’

#

i sent that because i completely agree with the top answer, and if you did agree with the top answer it would be pretty embarrassing, for me at least

#

and that happened so uhh

fallen heath
dire geode
gentle lintel
fallen heath
#

no thanks

wraith crypt
#

i must have missed that early part

dire geode
gentle lintel
#

through direct substitution, if you obtain 0/0, it’s indeterminate (which means whether the limit exists or not cannot be immediately determined)

dire geode
#

you haven't even sent us your answer to

gentle lintel
soft cloak
#

Oh that looks like a rancid integral

gentle lintel
#

is it wrong?

fallen heath
#

or to $\int \sqrt{\frac{x+1}{x-1}} \dd{x}$

wraith daggerBOT
fallen heath
#

but oh well

soft cloak
#

that also looks like it sucks

gentle lintel
dire geode
#

unfortunately for you, communication is important in math

gentle lintel
#

and i’d rather that said instead of a complete lack on fundamentals

fallen heath
#

:/ if I'm not misunderstanding your understandings of the concept, you're mistaken ^^"

gentle lintel
gentle lintel
fallen heath
#

Like the one fine example I love: $$\frac{\cancel{6}4}{1\cancel{6}} = \frac{4}{1}$$

wraith daggerBOT
fallen heath
#

:o

gentle lintel
dire geode
gentle lintel
#

uhh

#

‘i need training in computations that’s all’

fallen heath
#

Let's go through this one last time, so I rest in piece nozoomi

fallen heath
#

I agree to this too.

dire geode
#

the highest priority is doing problems quickly

fallen heath
#

but I disagree when you use "direct substitution" to explain yourself

dire geode
dire geode
fallen heath
#

and that there's a "proper" step by step approach to learning

#

being all over the place won't help you

jaunty mural
dire geode
#

Additionally, this is the coverage for GRE Math Subject. You can't escape tedious calculus if you want to get an advanced math degree

gentle lintel
jaunty mural
#

Assessing yourself...

#

just grab a paper from somewhere and try it 🤔

#

Lets see... judging by what youve done I think youve covered the A level/IB syllabus for Calc?

wraith crypt
#

dunno about IB, but technically it's not really A level calc

#

at least, not the one i took

jaunty mural
#

Ok, I feel like I covered this stuff in IB calc

#

The further maths calc paper might suit

wraith crypt
#

it's more...bits and pieces of a year 1 sem 1 calc course, i think

jaunty mural
#

He has gone into yr 1 stuff but uh

#

not gonna be able to do calc questions on those

wraith crypt
#

yeah, that

fallen heath
#

maybe it's a nice time to revisiting them basics now... considering you must've practically matured from the pre-calc stage. enough to promote developing your insights into the basics

gentle lintel
#

how can

#

‘revisiting’ be done

#

lol

fallen heath
#

:/

jaunty mural
#

For now try look up further math IB calculus past papers

#

thats where I feel you're at

#

If you want to gauge yourself

#

Might be hard to find them hmm

gentle lintel
fallen heath
#

Prioritize:

Limits > Continuity > Differentiation > Integration

And if possible, find topic specific papers to help enhance your understandings, the way you've preferred since the start

gentle lintel
#

do them?

#

-> mastery

#

(yeY)

wraith crypt
#

because, tutorials

jaunty mural
#

I guess

#

no idea myself much

fallen heath
#

Camie gonna make a question per day sad

#

challenge ur understanding types

jaunty mural
#

Well one thing, I don't think chromium has the speed

#

because of a lack of familiarity/confidence to apply this stuff

gentle lintel
jaunty mural
#

doing these Q's

#

I look back and can guess

jaunty mural
#

You guys were doing this earlier right?

#

If you're confident with integration, this can probably done in 5 mins

#

Or maybe im pointing at the wrong Q

#

whichever one you guys were doing

fallen heath
gentle lintel
#

$\int 2^x \sin x \dd x$

wraith daggerBOT
#

Chromium

gentle lintel
#

ibp

dire geode
#

pretty sure 90% of calc students can recognize a product and say "ibp"

gentle lintel
#

,rotate

#

workings here

#

,rotate

fallen heath
#

?

dire geode
#

,w integral 2^x sin(x)

wraith daggerBOT
fallen heath
#

$I(1 + \frac{1}{(\ln 2)^3}) = Y \implies I = (1 + \frac{1}{(\ln 2)^3})Y$?

gentle lintel
#

oh shit

wraith daggerBOT
fallen heath
#

Surely... gg

dire geode
#

i'd probably give 8/10 points

#

oh chromi deleted it

#

0/10 then

wraith crypt
#

...you could read that?

#

i don't even know what Y is

fallen heath
#

me neither. it's a 0

gentle lintel
#

yea whatever it's done lol

#

$\int \sqrt{\frac{x + 1}{x - 1}} \dd x$

wraith daggerBOT
#

Chromium

gentle lintel
#

lmao

#

,rotate

wraith daggerBOT
jaunty mural
#

then finish it off

dire geode
#

what does this even say

jaunty mural
#

Also, you would write working like this in highschool maybe

#

not at uni

dire geode
fallen heath
#

:o

jaunty mural
#

I'm complaining about a lack of words/direction/explanation

gentle lintel
#

that's technically rough work uh

dire geode
#

technically rough grade 2/10

fallen heath
#

the "trivial" trig-sub was done wrong :o

gentle lintel
#

oh yea

fallen heath
#

sure "oh yea"

#

Let's see you try something else as well ?

#

$$\int \sqrt{\frac{x - 3}{2 - x}} \dd{x}$$

gentle lintel
#

becomes integral of secant cubed, i think

fallen heath
#

oh right

#

$\int \sec^3 x \dd{x}$ is standard, I suppose?

wraith daggerBOT
gentle lintel
#

there's a wiki article devoted to it

#

yea

jaunty mural
#

...

fallen heath
#

well, good luck substituting everything back :o

jaunty mural
# wraith dagger

im out of practice, this would take me about 5-10 mins to figure out. I have no idea how to do it by looking at it rn, but I sure as hell wouldnt rely on a wiki article to do it

jaunty mural
#

theres a wiki article devoted to everything

#

You should be able to do this on your own hopefully

#

theres wolfram, why do we need to integrate

#

you should be able to do this stuff by yourself

dire geode
gentle lintel
#

i've done that integral before

#

so i think i'm qualified to copy from that article

fallen heath
#

yep it's understandable... it really is a common one

jaunty mural
#

if u have done it before

#

u shouldnt forget it in a hurry

#

Like at least remember how the integral is done

#

and then yes, perhaps you can skip it

#

Parts? substitution?

gentle lintel
#

i remember how

jaunty mural
#

how

gentle lintel
#

parts twice

#

then set up an equation to solve for the intnegral itself

jaunty mural
#

whats the first split for parts

gentle lintel
gentle lintel
#

int the sec^2

jaunty mural
#

ok sure

#

now in the time you told us, you couldve done it heheh

#

it looks like a pain, but it rlly isnt

dire geode
#

chromi's too advanced for ansh's problems

fallen heath
#

convinced.. moves forward

jaunty mural
#

You need to be on this level of confidence for algebraic manipulation

fallen heath
#

$$\int \sqrt{\frac{x - 3}{2 - x}} \dd{x}$$

wraith daggerBOT
fallen heath
#

ahem

gentle lintel
#

that's $\int \sqrt{\frac{x}{-x-1}} \dd x$

fallen heath
#

excuse me?

wraith daggerBOT
#

Chromium

gentle lintel
#

trig sub should yield sec^2

dire geode
#

do the trig sub

fallen heath
#

,w int sqrt(-x/(x+1)) dx

dire geode
#

damn this handwriting is getting worse

fallen heath
#

Is that your answer?

gentle lintel
#

i haven't worked it out yet

fallen heath
#

Also, even wolfram gave the wrong answer to this so ^^"

dire geode
fallen heath
#

please reconsider

jaunty mural
gentle lintel
#

$u = x + 3$

wraith daggerBOT
#

Chromium

jaunty mural
#

dont reuse the same damn letters

gentle lintel
#

it should've been u but sacrificing the holy 'x' isn't worth it

jaunty mural
#

when subbing indefinite integrals

#

and apparently thats wrong

dire geode
#

i like how by asking us, we're indirectly helping chromi solve problems even though he wants to be assessed

fallen heath
jaunty mural
gentle lintel
#

(alright fine i'll work out the steps.)

gentle lintel
#

$\int \sqrt{\frac{x - 3}{2 - x}} \dd x =\int \sqrt{\frac{u}{-u-1}} \dd u (u = x + 3)$

#

are u respond?

dire geode
#

what's wrong with pencil and paper?

gentle lintel
fresh geyser
fallen heath
#

handwriting?

gentle lintel
#

triggers my ocd (kinda, i dont have it)

dire geode
gentle lintel
fallen heath
fresh geyser
#

uh why

#

its a vid

#

i made

#

to watch

#

bruh

fresh geyser
#

if u want

wraith daggerBOT
#

Chromium

gentle lintel
#

$u = -\sec^2 t, du = -2 \sec^2 t \tan t$

fallen heath
#

And what's the trig substitution?

fresh geyser
gentle lintel
#

ah shit

wraith daggerBOT
#

Chromium

fallen heath
fresh geyser
#

lol

gentle lintel
#

$-2 \int \sec^2 t \tan t \sqrt{\frac{-\sec^2 t}{\tan^2 t}} \dd t$

fallen heath
#

x = sin t apparently keeps giving me wrong answers in certain scenarios T_T

wraith daggerBOT
#

Chromium

fallen heath
#

sure, use the imaginary number :o

gentle lintel
#

what the fuck

fallen heath
#

oh anyways, once you're done with this one, I'd like you to generalize a substitution for:

#

$$\int \sqrt{(x - \alpha)(\beta - x)^{\pm 1}} \dd{x}$$

wraith daggerBOT
fallen heath
#

Also, what you just did shouldn't have involved any imaginary numbers ^^" please don't joke with integration stuff

jaunty mural
#

I want to see chrom do the 'basic'

1/sqrt(1-x^2) properly

#

later

fallen heath
#

screams in german

gentle lintel
#

ah yes

fallen heath
#

🏃

gentle lintel
#

range problems, and domain problems

#

involving the absolue value

#

history repeats itself

#

oh yea

#

sfhsuifhs]fgdfg

#

fdg

#

df

#

g

#

dfg

gentle lintel
#

why did i take so long.

#

genius

jaunty mural
#

No

#

Do it by proper substitution

gentle lintel
jaunty mural
#

man did i write that shit the wrong way round

#

I had a good example, but ill have to hunt for it

#

of where substitution and care are needed

fallen heath
#

👀

gentle lintel
#

(discussing math with shuri while walking through a flower market was honestly one of the best experiences of my life)

fallen heath
#

$\int_0^{\infty} f\qty(x + \frac{1}{x}) \frac{\ln x}{x} \dd{x}$

wraith daggerBOT
gentle lintel
#

ok don't

fallen heath
#

?

#

:/

gentle lintel
#

$u = \ln x, x \dd u = \dd x$

wraith daggerBOT
#

Chromium

fallen heath
#

⁉️

#

done?

gentle lintel
fallen heath
#

wow

jaunty mural
#

when u first learnt sub

fallen heath
#

:o

tropic oxide
#

what problem, if any, is being discussed right now?

gentle lintel
tropic oxide
#

what is known about f?

gentle lintel
#

i think the final answer is in terms of f and x

fallen heath
#

nothing much really, but it'd be nice to add that "f" is continuous

tropic oxide
#

i mean

#

with the wrong choice of f, you can and will end up with a divergent integral

fallen heath
#

for example?

tropic oxide
#

f(t) = t

jaunty mural
#

lul

tropic oxide
#

you get int[0, +∞] (x + x^-1) log(x)/x dx

gentle lintel
#

log 🤢

tropic oxide
#

what

#

do you object to my use of log and not ln to refer to the natural logarithm?

fallen heath
#

,w integrate (x + 1/x) (ln x)/x dx from 0 to infty

tropic oxide
#

told you

gentle lintel
#

how did you know it diverges (nice comparison test exercise)

tropic oxide
#

the integrand behaves as log(x) at infinity

fallen heath
#

$f(x) \neq f(1/x)$ works?

wraith daggerBOT
tropic oxide
#

works in what sense?

#

this condition doesn't at all guarantee that the integral converges

#

say, where'd this problem come from anyway?

fallen heath
#

my module :o

tropic oxide
#

can you show its original statement there

#

i want to see it

#

cause i'm growing more than slightly suspicious of how you're presenting it

gentle lintel
#

$\int^{\infty}_0 x f \qty(e^x + \frac{1}{e^x}) \ \dd x$ is a pretty neat form i obtained

wraith daggerBOT
#

Chromium

fallen heath
#

$I = \int_0^{\infty} f\qty(x + \frac{1}{x}) \frac{\ln x}{x} \dd{x}$ \ $$= \int_{\infty}^0 f\qty(\frac{1}{x} + x) \frac{x\ln x}{x^2} \dd{x}$$

wraith daggerBOT
tropic oxide
#

you're not answering my question, ansh

#

do you or do you not have a picture of the problem as it was originally stated in your module?

fallen heath
#

I do

tropic oxide
#

okay then would you please be so kind as to send it here

fallen heath
#

x -> 1/x was the intended substitution, I presume

jaunty mural
#

looks like its D lul

fallen heath
#

Also, the answer was A)

tropic oxide
#

is nothing at all known about f?

gentle lintel
#

i don’t get it

tropic oxide
#

ok, hold on

#

we can let x := e^t

jaunty mural
tropic oxide
#

then the integral becomes $\int_{-\infty}^{\infty} t f(e^t + e^{-t}) \dd{t}$

wraith daggerBOT
gentle lintel
tropic oxide
#

which, assuming that f behaves nicely enough at infinity, would be 0 as the integral of an odd function over a symmetric interval.

#

but unless we know that f does indeed behave nicely at infinity (or even not at infinity - who knows, maybe it's so nasty it's non-integrable!), and the integral does converge (which, again, we aren't given),

#

we cannot say this integral even makes sense let alone converges

fallen heath
#

since the module was meant as a discussion for class... I'm certain sir discussed this through

#

of course it would be up to the student to notice such details, is why I planned to bring this up as a matter of subtlety when doing integration

gentle lintel
fallen heath
#

x -> 1/x brilliantly gives the answer 0, but does it?

jaunty mural
fallen heath
#

you advised x -> -x substitution lol

jaunty mural
#

oh nvm im blind

fallen heath
#

that's what chromi did

jaunty mural
#

x -> 1/x

gentle lintel
#

effectively leads nowhere

fallen heath
#

Yeah. I figured

#

$= -I \implies I = 0$

wraith daggerBOT
fallen heath
#

but as Ann mentioned, this depends on what's up with f(x) :o

#

ntm, you're also meant to assume that "I" is finite, to be able to play with the limit

fallen heath
# tropic oxide what problem, if any, is being discussed right now?

btw, in case you're lost, the topic of discussion was Chromium's assessment on calculus... and having had discussions with Chromium on several occasions, I felt like revisiting the basics via questions would be the optimal choice for him before moving on to Linear Algebra for multivar

tropic oxide
#

you don't really need calc directly for linear algebra

fallen heath
#

Linear Algebra for multivariable calc-

#

If I'm interpreting correctly, Chromium's intention is to proceed with multivariable calculus(!?)

#

the assessment is (probably) intended to gauge his understandings and if it's fine to move on.

gentle lintel
#

-> ok?

#

ib further maths calculus past paper, as shuri suggested

fallen heath
#

vectors / matrices?

gentle lintel
#

2, 3

#

q2, 3

#

not 1 4 5

#

bad

#

wait ynw, this is too simple

fallen heath
# gentle lintel so kinda do more questions

Just chill and devote yourself to questions for a while. Prioritize the order LCD(limit -> continuity -> differentiability), then Integration and do stuff accordingly, step by step, until you're able to properly arrive to the answer at least 7 out of 10 times