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cedar kilnBOT
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fair fox
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Idk if i can ask here but "I usually dont study so idk how to focus and that stuff , but now i really need a good grade so, can anyone explain me combinatorics pls"

fair fox
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Idk if that helps but i am in 12 grade

green coral
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as riemann said
if you need help with the task of studying #study-discussion
if you need help with combinatorics as a topic #study-discussion
if you need help with specific problems of combinatorics, you are in the right place, ask a few problems, helpers will try to help you understand them

cedar kilnBOT
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@fair fox Has your question been resolved?

cedar kilnBOT
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austere hull
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hi

cedar kilnBOT
austere hull
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there was a question said, solve for $8\mu\text{A} +5\text{mA}+ 24\text{mV}=0$

wraith daggerBOT
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Aκιρɑ

austere hull
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my status at 1

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i just had no idea what the units will be on this

hollow trail
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can you show the full context here?

austere hull
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that was the full question

hollow trail
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do you have a picture of it?

austere hull
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i dont unfortunately since it was a question from midterm i have done this morning

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it said like this

hollow trail
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what are μ, A, m and V?

austere hull
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mirco, amps and voltage

sonic thistle
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you mean microampers and microvolts?

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wait no

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microampers, miliampers and milivolts

austere hull
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yep

sonic thistle
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and what am i supposed to find

austere hull
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i was supposed to calculate the whole thing

hollow trail
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so you aren't setting it equal to 0, you are trying to add them up?

austere hull
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yea

hollow trail
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you can't add voltages and currents, they're not compatible units

austere hull
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thats what i thought too

hollow trail
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there needs to be some conversion factor (probably a resistance)

sonic thistle
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the question is like asking:
8 bananas + 5 banana trees + 25 lemon trees = 0

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are you sure that it's the full question?

austere hull
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yea it was a question i had in midterm

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ill close this bc it literally didn't makes sense

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.close

cedar kilnBOT
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hollow trail
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there may be some context you are forgetting to include. but we can't really know without a picture of the midterm

austere hull
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im 100% it was like this

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but ill wait until results come out to see if i missed something

cedar kilnBOT
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thorny frigate
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In axler linear algebra he said a polynomial function p \in P(F) and he defined earlier P(F) to be set of all polynomial functions from F to F .. now later he took a polynomial function and he put T ... An operator as an input.. how can he do that!!! Input has to come from a field

split ice
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do you have a screenshot/picture of the relevant page?

thorny frigate
abstract breach
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he defines it like this

dawn junco
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axler does say it is somewhat of a notation abuse just after the definition of P(T)

thorny frigate
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I think there is a connection or more formally some isomorphism between algebra of polynomial and polynomial functions set ig

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For infinite fields

abstract breach
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yes

thorny frigate
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But I don't get my own sentence very clearly 🙂 what does it actually mean

abstract breach
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think about F_p (also known as Z/pZ or Z_p)

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the function that maps x to x^p is equal to the identity at all points of Fp

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but the polynomials X^p and X are not the same

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however in an infinite field, you will always be able to map the polynomial to its corresponding function (it's an isomorphism)

hollow trail
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since in LADR you pretty much exclusively work with R and C you don't really have to worry about cases where the isomorphism fails

thorny frigate
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Like if a polynomial function p : F \to F is defined as p(z) = a + bz so it's isom to polynomial expression a+bz?

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For infinite field

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Basically it determines the ordered coefficients? Uniquely

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Right?

abstract breach
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yes

thorny frigate
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And can we prove a+bz won't ever be equal to some z³ or something any other .. for infinite fields

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Isomorphic*

abstract breach
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I would say equal rather than isomorphic

thorny frigate
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Oh yes it has exactly 1 roots

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It can't have more something like that we will use

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And it can't hage infinite roots

abstract breach
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basically yes

thorny frigate
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Ohkieee thankssssssssszumm

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.close

cedar kilnBOT
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hollow trail
cedar kilnBOT
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ivory cedar
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if asked to find/sketch traces, how do I determine whether to set the variable to be 0 or k? Or is that arbitrary?

Also, when sketching traces in 3D plane individually, how do I determine orientation? I’m having some trouble with the hyperbolas

cedar kilnBOT
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@ivory cedar Has your question been resolved?

split ice
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the equation of an arbitrary trace is always z=k, x=k, or y=k, because 0 gives you one specific trace

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when you're actually sketching the traces, though, you pick a few specific ones to give you the idea of the shape. usually, you want to pick 0 as one of these "specific ones," so you can start near the axis

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i like to do 1, 0, -1 to start, then 2 and -2 if needed
so 3-5 traces per direction

ivory cedar
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ohh, I see

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thanks

cedar kilnBOT
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sly schooner
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idk if im being stupid but idk how to do this

mental trail
sly schooner
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i can only prove the only if part

mental trail
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Really? How did you do it

sly schooner
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I mean idk if it’s valid but

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Ignore the bottom part

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i think i mightve assumed that the range of h is the domain of X

mental trail
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The statement after that is all you need

mental trail
mental trail
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And you haven't really proven the assertion with the "proof" you wrote

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to prove "g ○ h ≠ f", you have to show that there is some x such that g(h(x)) ≠ f(x)

sly schooner
# mental trail Also this isn't the only if part, it's the if part

Ik the proof is wrong but surely since I’m saying that if the range of f and g r different then goh isn’t f, contradicting the friends definition, then im saying the range must be the same for g and f to be friends but not necessarily that the range being the same means they are friends

mental trail
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Say A is the proposition "f and g are friends"

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And B is "f and g have the same range"

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You've tried to prove that not(B) implies not(A)

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And so that implies [A implies B]

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This is normal, it's the contrapositive

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I have no problem with this line of reasoning

mental trail
sly schooner
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Yeah ngl I was just tired during the session and wrote smth wrong down sry abt that lol

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Do u mind telling me how I’m supposed to prove the question?

mental trail
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Well I would've just gone for a direct proof of "A implies B"

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Suppose f and g are friends, which tells us f = g○h for some bijective h

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To show the ranges of f and g are equal, just do double inclusion

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Take z = f(x) for some x in X

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Then z = g[h(x)], so z is also in the range of g

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Vice versa, it's easy with the property that h is bijective

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First try to write that down properly

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And then we'll talk about "B implies A"

sly schooner
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Would this do?

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ok i kinda rushed the explanation where if z is in the range of f its also in the range of g

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but i do need to sleep soon

mental trail
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So you only have proved $range(f) \subseteq range(g)$ for now

wraith daggerBOT
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Raphaelisius Maximus MMIII

sly schooner
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Consider z=g(h(x))
Since gOh=f,
z=f(x)
thus if z is in the range of gOh, it is in the range of f

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is that correct?

mental trail
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If z is in the range of g, what gives you the right to say "z = g(h(x))"?

sly schooner
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oh yeah

mental trail
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You only know z = g(y) for some y in Y

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But you don't know if y = h(x)... or do you?

sly schooner
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oh cus h is bijective

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so it outputs all values in Y?

mental trail
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For every y in Y, there is a unique x in X

sly schooner
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it also takes all inputs of x

mental trail
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Such that h(x) = y

cedar kilnBOT
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@sly schooner Has your question been resolved?

cedar kilnBOT
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hidden prawn
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Yo can someone please help me with this inequality question I was thinking to expand the stuff in the brackets so I end up with a quadratic or some but like there’s a lot of roots and stuff and I don’t think it’s finna work out

cedar kilnBOT
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@hidden prawn Has your question been resolved?

ancient nova
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Also don't forget about the bound,x has to be more than or equal 1

hidden prawn
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.close

cedar kilnBOT
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cedar kilnBOT
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delicate palm
#

i found this image online, and i’m wondering what are the angles of triangle b.
i’ve found
\begin{align*}
\angle 1 &= 240^\circ \
\angle 2 &= 60^\circ \
\angle 3 &= 240^\circ
\end{align*}
i wonder whether that’s right.

wraith daggerBOT
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@delicate palm

cedar kilnBOT
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@delicate palm Has your question been resolved?

cedar kilnBOT
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@delicate palm Has your question been resolved?

cedar kilnBOT
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@delicate palm Has your question been resolved?

floral arrow
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Are these all semicircles? If so they just add or subtract 90º on each side, so you are correct. Calling b an equilateral triangle is an enormous stretch though.

cedar kilnBOT
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@delicate palm Has your question been resolved?

delicate palm
cedar kilnBOT
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floral arrow
# delicate palm equilateral, not equiangular =)

. Calling b a triangle is an enormous stretch. You can argue all you want about the "sides" being of equal length, you may even argue about the underlying space being non-Euclidean so that these "sides" would in fact be straight lines, but nothing like that is mentioned so this cannot be seen as a triangle. An equilateral triangle is a polygon (planar geometric figure made up of straight line segments) with three sides of equal length, which inevitably leads to its angles being equal as well.

surreal snow
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I'm working on 5 d) now, I know that we can write the directional derivative of F at a point q in direction v as $v^i\frac{\partial f}{\partial q^i}$.

(as it's for an assignment i don't want to be given the exact answer, just guidance on if i'm on the right track)

surreal snow
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I've already gotten that $\overline F$ is $(x^2+y^2)(x^2+y^2+1)$, and q is $(x,y,x^2+y^2)$ as an element of X. I don't think i can derivate wrt $q^3$, but i might be able to do it with leaving q3 as z and then adding in the restraint that $z - x^2 -y^2 = 0$

wraith daggerBOT
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Frank's Sriracha

surreal snow
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I'm just not sure how to go about it properly

hidden mural
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@surreal snow do u see that X is diffeomorphic to R^2

surreal snow
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👍

hidden mural
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how did you get overline{F} btw

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i'm think about approaching this slightly differently

surreal snow
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i got it as restricting F to X by setting z = x^2+y^2

hidden mural
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you can also replace x^2+y^2 with z to get z + z^2

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so pi: X --> R^2 given by pi(x,y,z) = (x,y) is a diffeo and gives u a global chart

surreal snow
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I've done that in the working out, i left it as x and y to make the partial derivatives easier

hidden mural
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i think of tangent vectors as diff ops that u get from curves

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so i would consider an arbitrary curve gamma on X

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in global coords u can write it as t |--> (x(t), y(t))

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then find \overline{F} (gamma(t))

surreal snow
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atleast to me that seems like extra steps that would need more proofs

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I get how that comes up and works, though

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I've ended up with $v^1(2x+x^3+4xy^2)+v^2(2y+4x^2y+4y^3)+v^3(2(x^2+y^2)+1)$ using z substitution

wraith daggerBOT
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Frank's Sriracha

surreal snow
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Does that make any sense to work?

hidden mural
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ru thinking of v as a vector in R^3

surreal snow
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👍

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i did define the tangent space before, so that might be wrong

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I got it as span{(1,0,2x),(0,1,2y)}

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would i have to write v as (a,b,2ax+2by)?

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i would have to do that at the end though

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To sum up my process through the whole question, i set psi (localisation) as (x,y,x^2+y^2), then found the rank of Dpsiv, that left me with a matrix {{1,0},{0,1},{2x,2y}} which i used the span of the column space for to find the the tangent space at q, then the directional derivative operator to get to where i'm at now

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We haven't really done anything like it before so i'm just stuck on if my process is actually right

cedar kilnBOT
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@surreal snow Has your question been resolved?

cedar kilnBOT
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@surreal snow Has your question been resolved?

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strong stirrup
#

How does multiplying by the conjugate cancel out and get same denominator when you have to use it in f(x+h) -f(x) /h

strong stirrup
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Alg 2 last year was in one ear out the other and i have first test over derivatives in but

fossil dawn
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!original, please

cedar kilnBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

stiff brook
maiden rover
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Hi guys

stiff brook
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hello

cedar kilnBOT
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@strong stirrup Has your question been resolved?

naive bough
#

time to get better at math

cedar kilnBOT
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clever frigate
#

I have doubt in logarithm questions

cedar kilnBOT
frosty creek
clever frigate
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When I get lnx while solving integration questions , idk what to do next

fossil dawn
#

!original, please.

cedar kilnBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

clever frigate
#

<@&286206848099549185>

bleak orbit
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ok so what have you done so far

clever frigate
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Nothing

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I don’t know what to do

bleak orbit
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ok do you know what is work formula

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@clever frigate ?

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Basically the formula is dW=Fdx

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Where W is work, F is force and x is displacement

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To find total work, you can just integrate this over the limits given, x=1 and x=e

cedar kilnBOT
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@clever frigate Has your question been resolved?

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clever frigate
clever frigate
#

If I put in in definite integration what’s the next step , like if it was 1/x I would have converted it into lnx but what happens to lnx

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<@&286206848099549185>

scenic narwhal
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!15min

cedar kilnBOT
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bleak orbit
#

You can use integration by parts if so

fallen hollow
cedar kilnBOT
#

@clever frigate Has your question been resolved?

cedar kilnBOT
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tawdry terrace
#

Hi!

cedar kilnBOT
tawdry terrace
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Prove that 101010.....01 is always composite except for 101.

mighty shuttle
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so like 10101 is part opf this

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1010101 too?

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,w is 1010101 prime

tawdry terrace
mighty shuttle
tawdry terrace
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no problem my g

sacred iron
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Do you still need help with your question?

tawdry terrace
#

i do

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i just said that there was no problem with wai not being able to help me

sacred iron
#

I see…

vivid valley
#

can someone explain how I get to the solution of simplification : b-1 / b+1 ?

tawdry terrace
#

wth

vivid valley
tawdry terrace
#

!help

cedar kilnBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

tawdry terrace
#

!occupied

cedar kilnBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

vivid valley
#

sorry I will open a channel!

tawdry terrace
#

np

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The number always has an odd number of digits. Let the number of digits be 2n + 1, where n >= 2.
10101010.....01 with 2n + 1 total digits = 10^(2n) + 10^(2n-2) + 10^(2n-4) + ..... + 10^2 + 1 = 1 + 10^2 + 10^4 + ..... + 10^(2n-2) + 10^(2n) = 1 + (100)^1 + (100)^2 + ...... + 100^(n-1) + 100^n =
Now if n + 1 is composite, (n+1)/f groups of f consecutive terms can be can made and the expression can be factorized, proving that the expression is composite for n + 1 = composite. Now consider the case that n + 1 is prime and n + 1 ≠ 2

(100^(n+1) - 1)/99 = (10^(2n + 2) - 1)/99 = ((10^(n+1))^2 - 1)/99 = (10^(n+1) - 1^(n+1))/9 * (10^(n+1) + 1^(n+1))/11
The numertaor of the first factor is always divisible by 9. For n >= 2, n + 1 >= 3. We conclude that the first factor is always an integer greater than 1.
Now since n + 1 is prime, n + 1 is odd (since n + 1 ≠ 2). Since the he numerator of the second factor is divisible by 11 and n + 1 >= 3, the second factor is an integer greater than 1.

Hence our original number is a product of two beautiful numbers; it's composite.

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How is my proof?

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<@&286206848099549185>

cedar kilnBOT
#

@tawdry terrace Has your question been resolved?

tawdry terrace
#

<@&286206848099549185>

thick arch
#

What's the problem?

tawdry terrace
whole nexus
#

I mean, any number after 101 would just be divisibile by 101 itself

thick arch
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Yeah

tawdry terrace
#

,w factor 10101

wraith daggerBOT
whole nexus
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Like (11, 111, 1111, 11111)*101 gives 10101, 1010101, 101010101, 10101010101

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Don't know though, let me check with calculator too

neon egret
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it doesnt

whole nexus
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Nope, that ain't correct

neon egret
#

101*11 is 1111

tawdry terrace
#

11 * 101 is not equal to 10101

whole nexus
#

Alright my bad

tawdry terrace
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No prob

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<@&286206848099549185>

cedar kilnBOT
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@tawdry terrace Has your question been resolved?

normal hedge
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hi sir

thick arch
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I borrrowed this phone, answer is 5

tawdry terrace
#

what

tawdry terrace
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.cose

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.close

cedar kilnBOT
#
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cedar kilnBOT
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cerulean maple
#

Hello, I'm trying to program my own character rigging system like the one seen here: https://youtu.be/vTTdchYmzJM?si=WE7Frj8iWiU2bynP&t=14 but I am struggling to understand how to do the rotations.

If you visualise the skeleton as a bunch of nodes, you can see, for example, red = left shoulder, left arm, left hand, blue = right shoulder, right arm, right hand, and purple = torso. In the video, you can see that the nodes rotate 45 degrees around a horizontal axis to give it a flat rotation effect. What is the math behind this?

This Bitstrips tutorial shows how to pose and rotate your avatar and other characters in the Comic Builder.

Find hundreds of fun comic activities for your students at http://www.bitstripsforschools.com.

▶ Play video
hot cipher
#

This server is probably the wrong place to ask for

#

For this particular case, i dont think this is result of real math about rotations, more like prefabs of different positions

cerulean maple
#

Just to clarify, I'm not asking for programming help... just the math behind it.

hot cipher
#

If you wanna do bone rigging, you can define a point at a fixed distance from another in sort of dependency manner

#

and associate rotation values as fixed numbers that are then applied depending on the prefab youre using

cerulean maple
#

You can ignore the sprites and things (I've already figured out how I'm going to do that). What I'm interested in is the position of the nodes (e.g, how do the blue nodes rotate around the horizontal axis in 45 degree increments).

cerulean maple
hot cipher
#

Just fabricate this 5 versions of the model

cerulean maple
#

And the side would be like this.

hot cipher
#

All the left-rotations are just mirrored versions of the previous

#

If you have defined values for the bone rigging, how to aplly falls pretty easily

cerulean maple
# hot cipher

Would I not only need 4? Couldn't the back also be a mirrored version of the front?

hot cipher
#

You still would have to draw the sprites for the back side of the body

#

with red and blue switched

cerulean maple
#

Ah, I see.

hot cipher
#

And rotations would apply backwards

#

imagine from the front, lets say a pi/2 angle means its moving its whole arm towards the camera
then in backside that same pi/2 means that its arm is moving against the camera

#

Thats what i meant with prefabs

#

it stands for "pre-fabricated"

#

Its not math on the fly, you just simply set it as a particular option in your rigging system

#

Mostly cause true 2d models dont go well with rotations around the xz plane

cerulean maple
#

So you're saying I would be better off just using a matrix of hardcoded angles [-180, -90, -45, 0, 45, 90, 180] etc. and then just move them? Sorry, my English isn't very good.

hot cipher
#

Imagine that your "default rotation" is front

#

You would have to hardcode every rotation around the horizontal and create specific sprites for each one

#

Then assign some value for each one, and let the user choose from it

#

But they wouldnt work like rotations

#

Just like entirely different models

#

One that faces front
One that faces right 45
One that faces right entirely
One that faces back 45 from right
One that faces back
And so on for the left side

cerulean maple
hot cipher
#

yeah

#

0,1,2,3,4,5,6,7 would probably best suited

#

Then have a function which reads from it
and display the correct model

#

Thats mostly why i said this is not really suited for a math server

cerulean maple
#

And model is just the image of the part?

hot cipher
cerulean maple
#

Oh okay, I will try this.

cerulean maple
hot cipher
#

np

cerulean maple
#

Probably unlikely but I don't suppose you would be interested in creating a prototype of this system? Would pay money, of course.

hot cipher
cerulean maple
#

Ah, okay, no worries. But thank you for the help :)

#

.close

cedar kilnBOT
#
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cedar kilnBOT
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gleaming oar
#

yo

cedar kilnBOT
gleaming oar
#

is anyone expiereced with data managment

wicked mantle
#

What are you looking for?

sacred iron
# gleaming oar yo

Just for future reference, do you mind posting the image/question as your first message so the bot doesn’t pin greetings or requests for help? This way, if the conversation continues for long, helpers don’t have to dig.

I’m sure many people here are experienced with data management. However, does your problem correlate to math? If so how?

gleaming oar
#

In a tree diagram, you have 4 ways to do the first event, 3 ways to do the second event, 5 ways to do the third and 4 ways to do the fourth. For each of the following, state whether it is true or false and explain why.

You can add the numbers to get n(S). False

You can use the fundamental counting principle to get n(S). True

There are 240 different pathways through the tree. True

There are 16 total pathways for n(S). False

gleaming oar
#

i first want to confirm if these are correct

cedar kilnBOT
#

@gleaming oar Has your question been resolved?

gleaming oar
#

@uncut veldt

chrome elk
#

That's a user lmao

#

<@&286206848099549185>

gleaming oar
#

bruh

sacred iron
cedar kilnBOT
#

@gleaming oar Has your question been resolved?

sacred tusk
# gleaming oar

There are 49 marbles in a box. 6 of them are red marbles and the rest are blue marbles. You randomly pick 6 marbles from the box. What is the probability that you either pick 3 or 4 red marbles?

gleaming oar
#

oh i did lottery 6/49 lol

gleaming oar
#

this is the answer i came up with

sacred tusk
gleaming oar
cedar kilnBOT
#

@gleaming oar Has your question been resolved?

cedar kilnBOT
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small wing
#

does anybody know how to manipulate leslie matrixes so that the eigen value becomes 1 for example this matrix has an eigen value of 1.05306 how would i manipulate the matrix so that its 1

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@small wing Has your question been resolved?

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lament epoch
#

o/

cedar kilnBOT
twilit escarp
#

Need help with maths ?

past glacier
cedar kilnBOT
#

@lament epoch Has your question been resolved?

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charred wharf
#

Can anyone help me w fractional indices ion really understand it

tropic oxide
#

do you understand integer indices

#

ie when they are whole numbers & not fractions

charred wharf
#

Ya those are pretty basic I think it’s js that when like brackets n stuff come into play ion rlly understand

tropic oxide
#

mkay

#

do you understand square roots

charred wharf
#

Ya

tropic oxide
#

aight, good

#

let's see: do you also understand index laws?

#

in particular $a^{m+n} = a^m \cdot a^n$ and $a^{mn} = (a^m)^n$

wraith daggerBOT
charred wharf
#

Yup

tropic oxide
#

wonderful

#

so the idea behind extending the defn of exponentiation to allow the index to be fractional is going to be based entirely upon the desire to keep these index laws working.

#

for example, whatever $x^{1/2}$ should be, we definitely want to have $$x^{1/2} \cdot x^{1/2} = x^{\frac{1}{2} + \frac{1}{2}} = x^1 = x$$

wraith daggerBOT
tropic oxide
#

in other words, squaring x^(1/2) should give back x itself.

#

that make sense?

charred wharf
#

Yup

tropic oxide
#

the big reveal is that that's exactly what the square root of x does.

#

and this is why $\sqrt{x} = x^{1/2}$

wraith daggerBOT
tropic oxide
#

you can see similarly why $\sqrt[3]{x} = x^{1/3}$ and generally why $\sqrt[n]{x} = x^{1/n}$

wraith daggerBOT
charred wharf
#

Ya okay

tropic oxide
#

that's basically all there is to it

charred wharf
#

Like for example
27 over 8 powered to 2/3 how do we solve smth like this

tropic oxide
#

aight you're gonna need to post a picture

charred wharf
#

Alr one sec

tropic oxide
#

\verb|27 over 8 powered to 2/3| is ambiguous: $$\frac{27}{8^{2/3}} \quad\mbox{or}\quad \paren{\frac{27}{8}}^{2/3}?$$

wraith daggerBOT
charred wharf
#

The one on the right

tropic oxide
#

ok then you need brackets

#

(27/8)^(2/3)

#

would you know what to do if the 2/3 index were some integer instead

charred wharf
#

What is it

tropic oxide
#

... this isn't a clear "yes"/"no" and so doesn't answer my question

#

let's imagine that instead of 2/3 there is some whole number instead; would you know what to do, yes or no?

charred wharf
#

Oh ya ya

tropic oxide
#

ok, what would you do?

#

for example if we were looking at $\paren{\frac{27}{8}}^{4}$

wraith daggerBOT
charred wharf
#

U power the 27 by 4 and 8 by 4

tropic oxide
#

just tell me what one next step you'd take

tropic oxide
#

you distribute the index to the top and bottom

#

and are left with 27^4 / 8^4

#

wonderful

#

now im gonna tell you to go do the EXACT SAME THING in your question!

charred wharf
#

So multiply the 27 by 2over 3 n same thing for 8

tropic oxide
#

the 2/3 is not a multiplier

#

it's an index

#

$27^{2/3} \neq 27 \times \frac{2}{3}$

wraith daggerBOT
tropic oxide
#

other than this major wording error, yes.

#

work out the rest of the thing on paper.

charred wharf
#

Alr one sec

#

Had to smth mb

#

54/3

tropic oxide
#

that doesn't look right to me

#

in fact it doesn't look right at all

#

it looks like you "timesed" 27 by 2/3 after me telling you that was wrong

#

so what's up w that?

charred wharf
#

How else could u solve that besides multiplying it by 2 and dividing it by 3 tbo

tropic oxide
#

i mean uhhhhhh

#

we... went over the meaning of fractional indices just now, didn't we...

#

raising to the power of 1/3 means the cube root...

#

like. mate, you kept telling me "yes" when i asked if it made sense to you

#

are you now telling me that the explanation you heard just now was in one ear and out the other

#

yknow what i think i need to go

charred wharf
#

.close

cedar kilnBOT
#
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cedar kilnBOT
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ancient nova
#

<@&268886789983436800>

cedar kilnBOT
#
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timid basin
cedar kilnBOT
timid basin
#

then whats the maximum value of this?

cedar kilnBOT
#

@timid basin Has your question been resolved?

jade blaze
cedar kilnBOT
#

@timid basin Has your question been resolved?

cedar kilnBOT
#

@timid basin Has your question been resolved?

timid basin
#

guys please i have no idea

#

what i even have to do

zealous plinth
#

is this from a vector calc class?

#

have you learned lagrange multipliers

#

since that's what im thinking would be used for this problem

crimson sedge
#

is anyone here

zealous plinth
#

yes there's an open problem here but there's several open help channels if you need help

zealous plinth
timid basin
#

i know some high school calculus

#

im def not in a vector class

zealous plinth
#

this seems like a hard problem without the tools of vector calc 😭 I'll try to see if I can find a suitable way to do this like calc 2 style

#

i couldn't figure out a good way to write the first equation in terms of one variable which is why I'm thinking this would be like a vector calc type question

#

okay ngl i can't seem to find anything like that, i can only find vector calc methods

#

i could i guess write out an overview of how you would do the problem using vector calc, if you'd like?

timid basin
#

i kinda understand what the concept of that method

#

from what ive read, these type of problems will have a boundary (in this case its that 9x + 9y = thing)

#

and the actual function to calculate the min max

timid basin
#

Yk

#

Ill try to learn calc 3

#

Ill set this problem aside for now

#

.close

cedar kilnBOT
#
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cedar kilnBOT
slender atlas
#

,rccw

safe nest
slender atlas
#

,rccw

wraith daggerBOT
chrome elk
#

,rotate

wraith daggerBOT
clever venture
#

4 quadrillion rotations

chrome elk
#

Okay so he starts at x

#

Then goes up to 1.05x

#

Then goes up to 1.07*1.05x

#

,calc 1.07*1.05

wraith daggerBOT
#

Result:

1.1235
chrome elk
#

Why is there a y

#

What is the x then

#

And what is x then?

#

...no

#

x and y are the same thing

sacred iron
#

!noans

cedar kilnBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

#
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vernal kite
#

how do i do this q?

cedar kilnBOT
floral arrow
#

This is a quadratic, it has two roots. You should know something about complex roots of polynomials

vernal kite
last apex
#

Something a bit more specific

vernal kite
#

conjugate complex pairs?

last apex
#

Yes

vernal kite
#

so the roots are i and -i

crimson delta
#

well thats a bit overcomplicating it

#

just plug in

vernal kite
#

oh right

crimson delta
#

they dont actually come in pairs if the coefs are not real

#

so thats false

vernal kite
#

yea thats what i thought originally

last apex
vernal kite
#

.close

cedar kilnBOT
#
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vestal horizon
#

i would like some help on algebra

cedar kilnBOT
sacred iron
#

Just for future reference, do you mind posting the image/question as your first message so the bot doesn’t pin greetings or requests for help? This way, if the conversation continues for long, helpers don’t have to dig. catlove

Do you have a specific question?

vestal horizon
#

no i just need help for my finals

last apex
#

What about them

sacred iron
#

What do you need help with about your finals?

jade blaze
vestal horizon
#

perpandicular lines and standard form

#

um

vestal horizon
sacred anchor
sacred iron
vestal horizon
#

ok

#

my as well close this then

#

.close

cedar kilnBOT
#
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cedar kilnBOT
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knotty kernel
#

Can someone verify my work and tell me what I did wrong, my buddies are saying the integration by parts is right but I might’ve made an algebra mistake but I don’t see one

wraith daggerBOT
oak anchor
#

- - = +

knotty kernel
oak anchor
#

$\int u'' v = u'v - ( \int u' v' ) = u'v - (u v' - \int u v'')$

wraith daggerBOT
#

Médicis

oak anchor
#

the two negative signs cancel out

knotty kernel
#

thx

oak anchor
#

you're welcome

knotty kernel
#

.close

cedar kilnBOT
#
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pale lake
#

i need some help plz answering the first part

pale lake
#

im quite lost

#

this is all ive done so far

#

Is this correct so far?

cedar kilnBOT
#

@pale lake Has your question been resolved?

pale lake
#

<@&286206848099549185>

dawn junco
#

well A*v(mu) is a linear map R^3 -> R

#

if you know what it does to some basis of R^3, you know what it does to all of R^3 (i.e. "finding" the map)

pale lake
#

i think i might have it

#

for both part

#

could i send u

dawn junco
#

sure

pale lake
#

and lmk if u agree with it

#

thx

pale lake
#

hope i did it right

#

cant think of any other way

dawn junco
#

where did you pull that from ?

#

seems extremely sus

pale lake
#

vector indenities

#

its a common rule

#

lemme show u

dawn junco
#

right ok

pale lake
dawn junco
#

I'm looking at the second part rn

pale lake
#

i used the 'hint' given in the question to help me

#

with the 2nd part

pale lake
dawn junco
# pale lake any luck?

I think your answer's good, but it's prolly better if some other eyes check your thing also

pale lake
#

appreicate it

#

.close

cedar kilnBOT
#
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wild belfry
#

Can I say f(x) = x - 1?

cedar kilnBOT
flint plinth
#

does it map every number in N to a number in N?

wild belfry
#

Im not 100% familiar with this topic so I want someone to confirm haha

flint plinth
#

what's the smallest number in N?

wild belfry
#

1

#

(for our course)

flint plinth
#

and what is f(1)?

formal glacier
wild belfry
#

0

flint plinth
#

is 0 in N?

wild belfry
#

no (in our course)

flint plinth
#

so f doesn't map N to N

wild belfry
#

Awesome!

#

Thanks guys

#

❤️

flint plinth
#

wait

wild belfry
#

.close

cedar kilnBOT
#
Channel closed

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formal glacier
#

lol

wild belfry
#

.reopen

flint plinth
#

why are you saying awesome

cedar kilnBOT
wild belfry
#

Oh?

flint plinth
#

your answer doesn't work, for that reason

wild belfry
#

Oh

formal glacier
#

its not surjective

flint plinth
#

it's not even a function from N to N, so it can't be an injective function from N to N

wild belfry
#

Ahhhh I see

flint plinth
#

try going the other way

#

instead of subtracting 1...

wild belfry
#

Ohhh

#

x + 1

flint plinth
#

yea see if that works

wild belfry
#

Well nothing maps to 1

flint plinth
#

right

wild belfry
#

So it should be good right?

flint plinth
#

so it's not surjective

formal glacier
#

wait wait

flint plinth
#

and it does map every element of N to an element of N

#

so just check whether it's injective

wild belfry
#

Well 1 maps to 2

#

And every number greater than 2 maps to itself +1

#

So thats all of them right?

formal glacier
#

do you know what a surjective function is

#

its an onto function

wild belfry
#

Everything in the codomain maps to something in the domain

formal glacier
#

and we need that to not happen

wild belfry
#

Yeye

#

I think f(x) = x + 1 is good right?

formal glacier
#

ye

wild belfry
#

Ok awesome!!

#

Thanks again haha

#

❤️

#

.close

cedar kilnBOT
#
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opaque narwhal
#

Im completely stuck on this real analysis question. From my understanding so far, f is discontinuous at every single point such that at least one of the digits in a square index is non zero, but it is continuous at between some points where all of those digits are zero. As im writing this, im beginning to think its just discontinuous everywhere. Anyone have any idea? Been trying to wrap my head around this for 3 hours now

cedar kilnBOT
#

@opaque narwhal Has your question been resolved?

opaque narwhal
#

<@&286206848099549185> anyone?

hot mauve
#

this function isn't technically well-defined: f(1.000...) = 1.000..., but f(0.999...) = 0.099099...

#

but I guess you're supposed to use the digit representation with trailing zeros instead of trailing 9s, then I think it's well-defined

opaque narwhal
#

Thats what ive been working with, and trying to extend it generally to prove that every point is discontinuous, as there will always be a jump if you go far enough right if that makes sense. I just cant seem to put it on paper

hot mauve
#

no no, a function being well-defined has nothing to do with it being continuous. I'm saying that since a real number doesn't necessarily have a unique digit representation, you can't just define the function based on its digit representation - some numbers can be written two different ways, so the function takes on two different values depending on which representation you choose

#

you're familiar with the fact that 0.999.... = 1?

opaque narwhal
#

No lmao

#

I mean ive seen it, but never fully undestood it

#

What im trying to show is that the limit from the right will always be f(a) but the limit from the left can never be f(a), because there will always be some sort of gap at the square index

hot mauve
#

it's being comfortable with the fact that 0.999 = 1, but you can do that later, just bookmark https://en.wikipedia.org/wiki/0.999 for example

In mathematics, 0.999... is a repeating decimal that is an alternative way of writing the number 1. The three dots represent an infinite list of "9" digits. Following the standard rules for representing real numbers in decimal notation, its value is the smallest number greater than every number in the increasing sequence 0.9, 0.99, 0.999, and s...

#

anyways, I don't think the function is discontinuous everywhere - there are some points where it's continuous

#

which definition of continuity are you using? epsilon-delta?

opaque narwhal
#

yeah

hot mauve
#

oh wait, you might be right actually, I didn't think about the limit from the left side 🤔

opaque narwhal
#

Yeah what im working with is the example of the limit at x goes to 100. From the right its 100, but from the left its just 0.0990999 and so on. Then Im trying to generalize it to show that those kinds of gaps will exist at any square index, and then show that between every 2 real numbers there will always be a number with at least one of those gaps

viral sundial
#

There should be a definition for “decimal expansion” in the book, removing the ambiguity. Let's assume that decimal expansion does include the form ending with infinite 9's.

opaque narwhal
#

yeah were not using a book

viral sundial
#

Let's first consider irrational number x0. For any epsilon, we can find 10^{-n} < epsilon, where the digit on 10^{-(n+1)} is not 0. Then take delta to be 10^{-(n+2)}. The decimal representation for any number x in the range (x0-delta, x0+delta) should have the same decimal representation until 10^{-n}, and f(x) also have the same decimal representation. |f(x)-f(x)| should be less then 10^{-n} < epsilon.

#

For rational number x0, there must be a lot of 0's at the end. We can find a square numbers n^2 , the decimal representation are all 0's after n^2-1. For epsilon < 10^{-(n^2 + 1)}, for any delta for any x in the range (x0-delta,x0), f(x) - f(x0) > 8*10^{n^2} > epsilon.

hot mauve
#

Wouldn't f be continuous at 1.111... for example? I'm starting to think it's only discontinuous at points that have 0s on square indices, because then the left side limit of f(x) wouldn't equal f(a)

viral sundial
#

Oh, my bad. Then it should be number with a finite represent and numbers without a finite representation.

cedar kilnBOT
#

@opaque narwhal Has your question been resolved?

opaque narwhal
#

I really dont understand it at all

hot mauve
#

oops, I mean lim_{x -> 1.111...} f(x) would be f(1.111...)

#

which is 0.0110, which is the same as the right sided limit

#

Sorry, I'm not quite awake enough to give a proof right now, but the idea is that you can choose a delta small enough such that all x such that |x - a| < delta have the same n first decimal digits as a, but only if a doesn't end in repeating 0s

viral sundial
#

for any N, we can find a neighborhood of 1.1111111....., where the first N digits for x in the neighborhood does not change, so the first N digits for f(x) does not change either. So f(x) is close to f(1.11111), and the difference would be less than around 10^N.

hot mauve
#

so the numbers close to 1.00 would be between 0.999 and 1.001 which don't have the first same digits, but the numbers close to 1.111 would be between 1.1110... and 1.1112, which do

#

yep, fefe can explain the details 💪

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worldly walrus
#

Say you took a circle and drew a diameter and then put a point on the opposite side. Why is the measure of that angle always 90 degrees?

ancient lodge
worldly walrus
#

I read that and I still don’t really understand

whole nexus
#

Well you can prove it yourself through congruency

#

Draw a point opposite to the diameter

#

Connect centre to it

#

Then connect both ends of circle where the diameter touches the circumference to it

#

You'll have two triangles, one with vertex at centre, point and one end if diameter, the one would have at centre, point, and other end of diameter

#

Now prove the triangles equal by congruency

#

And now prove that the central angle is perpendicular

worldly walrus
#

Ok I got it

#

Thank you

whole nexus
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weak granite
#

what do you MEAAAN the answer is a? (first on the right)

HOW WAS V AT P 2?!?!?!?!?!?

8V LOST IN THE 0 RESISTANCE WIRE?

hollow trail
#

the battery only enforces that the voltage difference between P and S is 10V

#

it doesn't enforce any absolute voltage value (that's dictated by the placement of the ground)

weak granite
hollow trail
#

different compared to what?

weak granite
#

(yes ik consume here is the wrong word to use but idk what's the proper word for it)

#

(convert energy?)

hollow trail
#

well yes, and that is shown in the voltage drops

#

the only physically meaningful measurement is a voltage difference, the actual value of voltage is just a matter of where you put your reference point

weak granite
#

so negative values

#

would make sense here

hollow trail
#

yes, there's nothing physically wrong with negative voltage

#

it just means it's below the reference point (ground)

weak granite
hollow trail
#

since only voltage drops are physically meaningful, to define a voltage you have to choose a point (a reference point) which you declare to have a specific value of voltage, usually that value is 0 (in which case we call it a ground and use the ground symbol)

cedar kilnBOT
#

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balmy prawn
cedar kilnBOT
tranquil oracle
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
balmy prawn
#

ik the IQR

tranquil oracle
#

so it's just interpreting it right

balmy prawn
#

yep

tranquil oracle
#

you know the IQR, how about try stating what it means

balmy prawn
#

the difference between the lower quartile and the upper quartile

#

Q3-Q1

tranquil oracle
#

yeah, so interpret that with the situation

balmy prawn
#

so the middle is basically 32,000

#

32,000 is the IQR

tranquil oracle
#

try making a statement about "the middle 50% of sale prices"

balmy prawn
#

but isnt that what the median do

tranquil oracle
#

I'm talking more of "if you sort all the sales prices, then you can use the IQR to say something about the two middle quartiles (which span 50% of all the prices)"

balmy prawn
#

?

#

two middle quartiles?

tranquil oracle
#

sorry i got confused

#

the two middle quarters of the data

balmy prawn
#

waitt so whats the difference between median and IQR

tranquil oracle
#

median is Q2 right

#

IQR is Q3-Q1

#

but now you need to interpret it with words

#

i'm trying to motivate an answer that talks about "the sale prices that go from Q1 to Q3"

#

which form half of all the sale prices

balmy prawn
#

so not including the first quarter and the fourth quarter

#

.close

cedar kilnBOT
#
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torn marsh
cedar kilnBOT
torn marsh
#

could someone explain this

#

I dont understand

bold lotus
#

Which part dont you understand

torn marsh
#

Basically all 3 slides

#

I mean the last 2

#

slides

bold lotus
#

Was there a specific step that confused you

#

do you understand $y = \ln(x)$

wraith daggerBOT
#

(λs.ss) λx.x

torn marsh
#

From second line of second slide

noble granite
#

do you just want to understand why ln(x) d/dx = 1/x, or do you want to understand this specific proof
in other words, whats the context here, this seems like a very unnecessarily complicated proof unless its trying to do something which i think it does

torn marsh
bold lotus
#

we dont know how to find the derivative of the natural log right

torn marsh
bold lotus
#

so this form is not helpful to us

#

but we know how to get rid of the natural log

#

$e^{\ln(x)} = x$

wraith daggerBOT
#

(λs.ss) λx.x

bold lotus
#

do you understand that?

torn marsh
#

I think we could find the derivative of a natural log

bold lotus
#

yes, that's what the slides are doing

torn marsh
#

From ln

bold lotus
torn marsh
bold lotus
#

that's the definition of a logarithm

#

do you know what logs are?

torn marsh
torn marsh
torn marsh
#

Well the derivative of lnx is 1/x

bold lotus
#

you cant just say this is the derivative

#

you need to find it

#

how did you go from ln(x) to 1/x

torn marsh
#

Oh then idk about that

#

The slides are explaining that process right?

bold lotus
#

they are showing how you find that result in the first place

#

should we go back to explaining the slides?

torn marsh
#

Sure

bold lotus
torn marsh
#

yes

cedar kilnBOT
#

@torn marsh Has your question been resolved?

bold lotus
#

what result do you they give you?

#

for example what is the meaning of $\ln(2)$

wraith daggerBOT
#

(λs.ss) λx.x

dusk goblet
#

\ln

bold lotus
#

for example what is the meaning of $\ln(2)$

wraith daggerBOT
#

(λs.ss) λx.x

cedar kilnBOT
#

@torn marsh Has your question been resolved?

cedar kilnBOT
#
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zinc quarry
#

Could I get some help on these? Not even sure where I’m starting

zinc quarry
#

I know I’m using the quantifiers but how am I supposed to express them?

zinc quarry
#

Like I get the quantifiers but how do I express (for example, a) "drivers do not obey the speed limit"

#

as a quantifier?

drowsy rock
zinc quarry
#

How would I write the second part of that sentence?

drowsy rock
#

In plain english?

zinc quarry
#

I know the first part would be the existential quantifier (backwards E), but would I just write out in english the second part?

#

Oh alright

drowsy rock
#

Keep in mind though, it's asking for the negation not just the proposition itself

zinc quarry
#

oh true

#

alright ill see if i can read into the textbook for the negation part

#

thanks!

drowsy rock
#

Yw

zinc quarry
#

.close

cedar kilnBOT
#
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dusk goblet
#

,avbob_kerman

wraith daggerBOT
#
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cedar kilnBOT
#
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zenith sedge
cedar kilnBOT
zenith sedge
#

the answer key says this is true but im confused how it is

#

because suppose if f(0.5) = 5 then for g(f(x)) we'll have g(5) but if g(5) isn't defined then it isn't continious when x = 0.5

last apex
#

You are right

#

Just make sure the question doesn't have a broader context,

cedar kilnBOT
#

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honest knoll
#

I would love some help with an exercice on functions and exponentiels chapter (12th grade).

the function f is defined on R by f(x) = ln(x^2 +1) + 3 - ln (2)
show that f is an even function

determine the limits of f in - infinity and in - infinity

determine the expression of f'(x)
study its variation on R and show a variation table of f in y showing the exact minimum value and its limits of - infity and + infinity

with the variation table of f give the values of K for which f(x) = K gives 2 solutions

solve for f(x) = 3 + ln 2

mighty shuttle
#

Define an even function for me

honest knoll
#

a function is even if f(x) = f(-x)

mighty shuttle
#

Apply that here

honest knoll
#

f(-x) = ln((-x)^2 +1) + 3 - ln (2)

#

and since (-x)^2 = x^2 so then its even ?

mighty shuttle
#

yes

honest knoll
#

okk

#

how do i determine its limits

mighty shuttle
#

notice that as x-> infty, ln(x^2+1)-> infty

#

can you do the other limit based on this

honest knoll
#

3- ln (2)

#

for - infinty

mighty shuttle
#

no.

#

it's an even function

honest knoll
#

okkk

#

I dont understand this chapter 😭

fiery violet
#

You've shown that f(x) is even

fiery violet
#

so if the limit approaching infinity = infinity, it follows that..?

cedar kilnBOT
#

@honest knoll Has your question been resolved?

honest knoll
fiery violet
#

so $lim_{x\to\infty} f(x) = \infty$

wraith daggerBOT
upper laurel
#

use \lim instead of lim to get the letters to stand up and look nicer

fiery violet
#

then $\lim_{x\to -\infty} f(x)$ should be?

#

thank you

wraith daggerBOT
fiery violet
#

was wondering how to do that xD

honest knoll
#

still dont get it

fiery violet
#

okay

#

so if the function f is even

#

then, for example

#

what will f(5) be the same as?

honest knoll
#

f(-5)

fiery violet
#

cool, and that should hold for every number, right?

honest knoll
#

yes

fiery violet
#

so as f approaches a really large number in the positive direction

#

say, f(10^4)

#

that'll be the same as?

honest knoll
#

f(-(10^4))

fiery violet
#

which means that as f approaches infinity, that's the same as..?

honest knoll
#

-infinity

fiery violet
#

perfect

#

so you've got the limit approaching infinity, solve for the other limit

honest knoll
#

f(x)=∞+(3−ln(2))=∞

fiery violet
#

Yes!

cedar kilnBOT
#
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honest knoll
#

.reopen

cedar kilnBOT
honest knoll
#

f'(x) for this I have to use e ?

fiery violet
#

as in the constant? not quite

#

what's the derivative of ln(x)?

honest knoll
#

ln (u) = 1/u

#

ln(x2+1)

#

so then 1/x2+1

fiery violet
#

yes, but u missed a step

honest knoll
#

ln(2) ?

fiery violet
#

if i take the derivative of f(u) where u = x^2, i need to..?

honest knoll
#

+1

fiery violet
#

not quite

#

chain rule!!

honest knoll
#

same denominator

#

nvm

fiery violet
#

also not quite

#

an easier function- say, (x^2 + 3)^4

#

how would you derive that?

honest knoll
#

i dont know how to derive

#

i litteraly didnt understand the chapter

fiery violet
#

okay

#

try familiarise yourself with this rule

#

you were on track with 1/(x^2 +1)

#

u just missed a step

honest knoll
#

ohhh

#

yes

crimson sedge
#

is your has done

cedar kilnBOT
#

@honest knoll Has your question been resolved?

#
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cedar kilnBOT
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hot folio
#

is my proof correct?

cedar kilnBOT
tropic oxide
#

your handwriting's hard to read

#

Q -> not(Q -> ????)

hot folio
#

P

tropic oxide
#

this 7D is P?

hot folio
#

it's (not P) sorry for the hand writing hahaha

void mortar
#

its just not P i guess

tropic oxide
#

ok right..

#

im not sure i follow the logic of your proof

#

why are you supposing two things back to back

#

why are you supposing $P \land Q$ and also $Q \to \neg P$

wraith daggerBOT
tropic oxide
#

what are we even doing

hot folio
#

I supposed that P is true and Q is also true not the logical connective and

tropic oxide
#

ok then why are you supposing 3 things then

#

not that it would've made much of a difference

#

imma say your proof is not signposted enough as it stands rn

hot folio
#

what would be the proper proof for it?

tropic oxide
#

maybe something like:

1. P [given]
2. Assume: Q & ~~(Q -> ~P) [negation of goal]
3. Q & (Q -> ~P) [#2 + double negation]
4. ~P [#3 + modus tollens]
5. Contradiction in steps: 1, 4
6. Therefore, last assumption (step 2) is wrong.
7. Therefore, goal is true.
#

which isnt written the best way possible but this is all i can do without descending into bureaucratic anxiety

hot folio
#

in number 2 why did conditional symbol became and? The Q & ~~(Q -> ~P)

oak anchor
#

imo the proof is correct but you could improve it

#

by way of contraposition

hot folio
#

idk know that, I'm just beginning to write proofs

oak anchor
wraith daggerBOT
#

Médicis

hot folio
#

oh that's called contraposition

#

I know that but I didn't know that that's how it's called

#

damn you're right

#

thanks

oak anchor
#

you’re welcome c:

hot folio
#

.close

cedar kilnBOT
#
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torn marsh
cedar kilnBOT
torn marsh
#

Is this correct

neon egret
#

the integration looks correct

sacred iron
#

Is this the integral? $\int_0^1 e^{-4x}\di x$

wraith daggerBOT
#

𝙸𝚗𝚏𝚒𝚗𝚒𝚞𝚖³

torn marsh
#

Ye-

#

Yep

#

Im wondering if it mathes here

elder scroll
torn marsh
#

Ok thanks

#

.close

cedar kilnBOT
#
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zenith grail
#

is there an easy way to remember when to use law of cosines and when to use law of sines when solving oblique triangles?

pastel vault
#

law of sines is used for AAS, ASA

zenith grail
#

so as long as i remember SAS and SSS for law of cosines, everything else is law of sines?

pastel vault
#

then to find the angles you then need to use the sine rule afterwards