#help-13
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you’ll notice that when you set x = 2 however that you have two unknowns still
so just choose another convenient value for x and you’ll solve an easier system of equations
this happens when you have this repeated factor situation
what did you do there?
first
i halved the second equation
then i subtracted the first equation from the second equation
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i have a question about the concept of second order differtial equation
for ay''+by'+c=0, there are 3 cases:
- determinant >0 ,then y=c1e^r1t+c2e^r2t
2.D=0, then y=c1e^rt+c2te^rt
3.D<0,y=..........
im confusing about the first case and the second case
in the second case, why y2=c2te^rt but not c2e^rt, there is a multiple of t
yes D = 0 is a repeated root
why we cannot say that y=ke^rt, where k=c1+c2
because there's another solution in D = 0 you'd miss
just imply the repeated root to case 1
i don't know what you're saying here
plug y2 into the differential equation when D = 0
i've searched that y1 and y2 must be linearly independent but i don't know why y1 and y2 must be like that
i know the solution but i don't know the principle
is the differential equation with respect to t?
yes y is a function in terms of t
kk
im not too sure of the specific logistics but its supposed to make the equation linearly independent
but why it must be linearly independent
like if you just use the same value of r for both parts of the equation there wont be a specific answer
why a repeated root give out a different y1 and y2
You can just do this to prove it to yourself
i dont know how the additional t makes it accurate but it does allow for a single solution
And try to plug it into the DE when D>0 and see that y2 doesn't satisfy the DE
the same kind of equation resolution is used in difference equations as well
i think i have some ideas that y1 and y2 must be linearly independent base on this reply from AI
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Guys
hello Tom
$c_1^4 + c_2^4 + c_3^4 + c_4^4$ ?
Ann
what are these meant to be?
A single term
Like
They can be written in a different form
And simplify the calculation
who asked you??
wot?
lol why are you guys asking me this stuff
mf wrote it incorrectly lmaooo
/j
casual math error moment
the top and bottom number have to be reversed lol
hold on tho uhh
no but what does this all mean
like right now all i can see is $(c_1)^4 + (c_2)^4 + (c_3)^4 + (c_4)^4$ and i don't know what these $c_i$ are
Ann
They meant 4C1 + 4C2 + 4C3 + 4C4 I think
$C^n_k = \frac{n!}{(n-k)! k!}$ ?
Ann
Yes
ok, do you know $\sum_{k=0}^n C^n_k = 2^n$ ?
Ann
$C^k_n$ actually, he wrote it incorrectly
36% Carbonized
better off memorizing binomial theorem more generally
i.e. $(x+y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k$
Ann
I know this
(replace the notation for combinations with whatever you like best)
ok then you can put x=y=1 and get the earlier thing
I just cannot recognize that to be 2^n
Sure
let x=y=1
I think I should do more practice
Thank you Ann
The certified smart people
Also 36% alcohol
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36 
are you carbonite or crabonite
crab
A family has 4 children.Given that at least one of them is a girl.
Question 1) The possibility that the family has exactly one girl
2)Possibility that the family has at least 3 girls
- Possibility that the oldest child is a girl.
possibility?
@tropic oxide
Yes
are you sure it says that and not probability
.reopen
✅
Probability sry
I’m in a hurry rn
bruh
Certainly
ok and OP was calculating the number of possibilities for the children's genders
which he could have done with the sum written
or as 2^4 (all possibilities) minus 1 (the one we can't have, which is all 4 boys)
Is this the french defense? Your username? But i think this question can be solved by making the chart of all possible outcomes assuming 50-50 chances of being boys and girls.
@civic coral Has your question been resolved?
!redir
This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.
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,rccw
$\alpha = \frac{\pi}{2} - \beta = \beta + \gamma$
What?
Indeed
I think its $\gamma$ not $y$..
k
And yes it is
Do u know how tan and cot are cofunctions?
U should consider this
Yeah
oh okay
1 divided by 0 equals Infinity
consider this
In conjunction with sum of angle for tan (maybe)
basically $\cot{\alpha} = \frac{1}{\tan{\alpha}}$
1 divided by 0 equals Infinity
I can see where this is going
But do u know some more faster way of doing it?
I mean this shouldn't be the only way u are telling
There must be better one right?
since $\alpha + \beta = \frac{\pi}{2}$
1 divided by 0 equals Infinity
then $\tan{\alpha} = \cot{\beta}$
1 divided by 0 equals Infinity
I know this one
Yeah i understand
..
try to draw a triangle or smth
since $\alpha + \beta = \frac{\pi}{2}$
1 divided by 0 equals Infinity
then the right triangle should look like this
now since $\beta + \gamma = \alpha$
1 divided by 0 equals Infinity
we can split $\alpha$ in the diagram
1 divided by 0 equals Infinity
1 divided by 0 equals Infinity
and angle DBC is $\beta$
1 divided by 0 equals Infinity
Thank you
i think from this diagram
Yeah i understand
you can visualize what's going on
Mhmm
np
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i didn't even think of this solution lmao
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I thought Leibniz looks for some L > 0 that is a constant such that |f(b) - f(a)|/|b - a| <= L
I think the definition of lipschitz is for any a and b in the domain of definition
And when b goes to a your fractions goes to the derivative of f in a
lipschitz and leibniz are different surnames xd
Did you solve your dynamics problem?
i did not, but i haven't spent enough time on it yet :)
Why isn't this Lipschitz
plug in u = 0
and consider what happens as x->0
u?
here they use x and u
Oh, it is usually (point, function of point)
Huh? No
well you have two points through which you compute a slope
if the slope is bounded then the function is lipschitz
Wait, hold on
Wait, how does this work
sqrt(1) - sqrt(0)/ (1 - 0)
Absolute value of this whole thing is still 1/ 1 = 1
why are you plugging in 1
What is f(x) = sqrt(x) on?
[0,1]
What do you mean?
otherwise it's a pretty useless definition
No a and b are any points in [0;1]
I thought it was plugging the end points in from what he did in class
it does say "for all x,u in A" here though
Yeah that’s not how it works
So, how does this work then?
Probably he took that for granted, hopefully it's not the first time you see something similar
What goes into f(x) and f(u)
You take any x and u in a he domain
It is the first time
For this theorem
Abstracting it as a rep?
So, |x - u| just stay that way
And to show a function is lipschitz, you need to show f(x)-f(u)/x-u is lower than a constant for all x and u
But I'm really sure you have already studied/been taught similar theorems dealing with an interval [a, b]
@lucid zephyr
Suppose f is a function defined on an interval
Draw the graph of this function.
Pick any two points on the graph, draw a line between them, and find its gradient
We say f is a Lipschitz function if this gradient has a maximum (i.e. no matter what points on the graph we took)
I meant from the definition alone
Using this.
f(x) = ?, f(u) = ?, x = ?, u = ?
Is it choosing any x, u in the interval? Or is it for all? How is for all representd
Loosely, we can relate this to a function having a finite maximum derivative (it's not quite this, because our f can be non-differentiable, but it's a good intuition)
For all
Cool. How is it represented?
$\forall$
Waes (Wires)
BRUH
What is a pencil? How is it represented?
Here is an emoji: ✏️
Like - BRUH
Really?
Disingenious
What do you want to represent even?
TF sorta explanation did you expect?
In relation to the problem
Dumbass
A bit respect would be welcome if you want any help
When you're the one being taught, you don't reserve the right to call others a dumbass, for one
For two
I’m not the one who doesn’t understand fkn lipschitz
Respect this idiot 🖕
Can't understand a basic question
Disingenious prick
Can’t explain what you want wdym
you really have a talent for making people like you
Bruh. Are you dense?
What is a + b = 2 here?
Oh, a + b is for all here
Are you able and I formulate anything coherent?
Are you a bovine idiot?
I think so

We say $f:I->\bR$ for an interval $I\subset \bR$ is Lipschitz if
$$\exists L>0 .\forall x, u \in I, \frac{|f(x) - f(u)|}{|x-u|} \leq L$$
Because you can’t formulate then to be understandable
Uh.... it means that you are to take for all individual repersentatives and add them
Like - dude is king of speaking indirectly.
A non-answer lol
You couldn't formulate understanding my questions
Not a good way to talk to your interlocutor.
Waes (Wires)
What kind of three-year-old answer is that
This is a conversation between A and B, you can C your way out.
You have your answer
Call back, nice
The one you have been giving this whole time? You lack self-reflection
Damn he be spitting bars like new Kanye
I’m just trying to help you
@lucid zephyr Regarding this, what question(s) do you have?
What more do you want then the explicit enunciation of the theorem
What was my original question
Figure that out
*than.
Infer from my previous question what I wanted. Read it slowly.
Your original question stems from a misunderstanding of the definition of a Lipschitz function
Follow the conversation till now.
Dude is correcting me while not understanding simple mathematics
Okay, and after that, what did I ask once I finally understood we aren't plugging in endpoints.
You are almost there.
This is already addressed from what I discussed about an informal way to think about this
Nope. Try again
You will get.
Read it again
You will get it*.
Nice.
Ratio
Dude your the one asking for help why are you this condescending
"It" doesn't really work when you've asked multiple questions; let me address them all
Hmm, I wonder - probably because someone started patronizing and deliberately started being dense and disingenuous.
This function isn't Lipschitz because by taking a derivative we can show there exists a point where there's no finite L for which the condition can suitably hold
Here is your hint.
Wrong again.
You aren't addressing what my concerns were after I found that out.
Look at the hint
This is wrong, again, because of the definition - Lipschitz requires you to find L sufficient for ANY two points in the interval the function acts on
Lol. You can't read
The derivative is going to infinity when approaching zero si taking a=0 and b going to a f(a)-f(b)/a-b is going to infinity which means you can’t find any L bigger than f(a) - f(b) /a-b for all a and b
How many times do I have to say "look at the hint".
Aid, you lack basic comprehension skills; these need more addressing than your university mathematics.
Dude - look in the mirror. This is more reflective of your illiteracy skills than mine. Stop deflecting.
You can't even answer my basic point of contention.
What don’t you understand in that
Because you don't understand how to look at the hint that I specifically directed you over 5 times loool
I've addressed any and all questions thus far from when I first started talking here; if you're still adamant in your unaddressed questions being unaddressed, the fact is you haven't even asked them, let alone succeeded in making clear where your confusion lies.
If you came to insult people then just go somewhere else what is your problem dude
Why should I address a strawman?
Did you know I addressed your concerns about dragons being real? I've addressed any and all questions thus far from when I first started talking here; if you're still adamant in your unaddressed questions being unaddressed, the fact is you haven't even asked them, let alone succeeded in making clear where your confusion lies.
Oh hey, yes I did know, because it's vacuously true that you did address these, BECAUSE I DIDN'T ASK ABOUT DRAGONS.
This is another hint where it is practically the answer.
f(x) having x? Really?
How is that a "hint", per se?
Oh hey, yes I did know, because it's vacuously true that you did address these, BECAUSE I DIDN'T ASK ABOUT THE LIPSCHITZ THEOREM!
If you have a point "x", and a function "f", then you have "f(x)"
Come on. You can do it!!!
That is literally the definition of what functions do
You are almost there you illiterate and benighted idiot!
ITS THE DEFINITION OF LIPSCHITZ WHICH YOU HAVE BEEN ASKING FIR YOU MORON
What is point x!!!!
<@&268886789983436800>
Come on. ALmost there 👏
Thx
Any point on the interval that the function f acts on
Dude just went completely crazy out of nowhere
I think he’s gone
@lucid zephyr There is no need to talk to people like that, especially when misunderstandings come from you not expressing your desires in any sort of understandable way. You've had issues with helpers before and they don't seem to have improved. I don't know what the core problem is, but it seems like you aren't willing to carefully read what texts say, or pay attention when being taught in class. You need to work on all of those things, and fast.
@lucid zephyr Has your question been resolved?
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Hi i need help ASAP w my hw😭😭
hi! just post your problem!
hii could you post your specific question?
HELLO SORRY TO BOTHER YOU BUT UHM ITS CURRENTLY 11:30PM HERE IM ABT TO SLEEP AND I JS REMEMBERED I HAVE A HOMWWORK
i lowk forgot what to do here
sorry guys i ws too busy w other subs, havent had enough sleep and i ended up sleeping in math
Both
lets start with 1 then
OK
how would you clear denominators?
HEH IDK
Tbh the teacher havent teached that yet, so he made it our homework so we can study it and present it to the board tmrw
ok, have you heard of lcd before? (least common denominator)
yes
mk, do you know how to find it in this case?
I think so?, btw do u know what to do there?
can you find it?
6?
hmm, your answer should contain x
6x
not quite, could you tell me where you got that from?
3x and 2..
ah, well those are the numerators. you want to multiply the denominators together to get a common denominator
like standard form?
mhm!
OK
what grade and quarter is that lesson in
i somehow cannot remember it😭
we just finished factoring quadratics
ok, so if i gave you $x^2+3x+2$, would you be able to factor it?
Frances
good! now can you go backwards? (i.e. if i gave you the (x+2)(x+1) would you be able to write it in standard form?)
x² + 3x + 2 = 0
ok, now can you do the same to (x-1)(x+1)?
hmm, can you walk me through your process?
cuz like
NO
dont say that about yourself 
its negative and positive, so if u add that its 0
so it shouldnt be x...
x² + 1?
you got the x^2, now you have a -x and a x added together, what happens
so the expanded form would be...
of x² - 1?
reposting so i dont have to scroll up
BUT IDK HOW X² - 1 WORK
alr, so pretty much youre going to multiply (x+1)(x-1) on both sides
oh
mhm
what
oh
alr so the left side doesnt really need the expanding we did earlier
my brain is shutting down its 12am
so can you tell me what each fraction becomes?
me i would just multiply everything by 3x+1 to get rid of the denominator
we're working on the first question ^^ :)
oh
ill write it for you like this: $\frac{3x(x-1)(x+1)}{x+1}+\frac{2(x+1)(x-1)}{x-1}$
Frances
two things cancel out here
what are they?
from the numerator and denominator
@true wasp ^^
okey
take $\frac{3x(x-1)(x+1)}{x+1}$
Tan
its like
X + 1
it lowkey looks like the quadratic formula something something
Yes
leaving you with...?
so now we're left with?
3x(x - 1)
$\frac{2(x+1)(x-1)}{x-1}$
Tan
now i multiply?
we have
3(x-1) + 2(x-1)
wait
@silk gust help
3(x-1) + 2(x-1) = 4
yes
ack sorry i dipped for a second
what next
what does this tell u abt x
waitt youre forgetting something on the rhs
rhs what
your question is already pinned by the bot
Oh
right hand side, you forgot to multiply by (x+1)(x-1)
Oh ..
when you have this, the lhs got multiplied by the lcd but the rhs did not
it should be 4(x+1)(x-1)
idk im not from the us we dont use those terms 🥹
3(x-1)+2(x-1)=4(x+1)(x-1)
lhs= left hand side of the equation
OK what next
rhs=right hand side of the equation
im gon be honest.. idk where my left and right is
3(x-1)(+2(x+1) is ur left hand side here
cuz its the left side of ur equation
5
what r we supposed to do in that equation? Is it like get the standard form and solve?
Tan
expand
well you distribute the constant in front into the parentheses
yep, thats the left side!
OK
5x²
left side shouldnt have x^2 terms
but 3x + 2x is not 5x²?
@true wasp
it isnt
So no ²
yes
Ok
5 chocolates
or 5 chocolates^2
same logic with variables
yes
And positive 6?
WAHT
whats -3-2
show it
theres no () anymore once youve expanded it
isnt it 3x-2+2x-3
But he said😭😭
constants are the other way around but yh
theres is a + sign ahead of it
plus + minus =???
minus
so its
-3-2
=-5
yes, thats correct
oke
replied to wrong message oops
now for the right side
as we said previously, (x+1)(x-1)=x^2-1, right?
distribute the 4 to both terms :)
4x² - 4
yep
so now youre solving the quadratic 5x-5=4x^2-4
yes!
since you learned factoring, go ahead and factor it :)
Ok
instead of 5x-5-4x² -4=0,
you do 0=4x²-4-5x+5
you shifted 4x² -4 to the left hand side
Yes
but you can also shift 5x-5 to the right hand side
and the coefficient of x² will be positive
try it
Oh😭
i dont rhink i have time since its 12:30am and im gon start prepping for school at 4am
i barely have time for sleep
🥹
okay sorry
no its ifne
i struggled way more than you
use .close to close this channel
so other people can occupy it
so i just factor it and im done?
How would u factor it..
hmm
trial and error ig
like just try factors of 4 (leading coeff) and 1 (constant)
OK ill work on it
Thankyu(ill js copy from my cm’s) BUT I ACTUALLY learned how to standard form it tyy
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Where did the x from the 3 go
which 3
oh
wat
sorry my brain is not functioning anymore
maybe ill just fail math
ok that was not a good joke
u want me to explain the process (but with the correct problem ofc) or figure it out yourself?
math is my first sub
Idk if i can do it within 4hours with no sleep
sorry
ill just pray that i dont get picked
ill get humiliated in math if i do😭😭😭
we dont want you to die <3
you've been doing this for 1 hour
bruh
what ..
oh
please sleep 🙏
humiliation is only when you choose to suffer
i have to go as well so uh
BUT HEAR ME OUT,
meow you should really sleep
you dont have to be humiliated for not being able to solve questions after getting 4 hours of sleep
you might answer with a gravestone if youre deprived of sleep like that
real
my teacher does not care tho
he will prolly say
"guys math is so ez blabla"
WHAT SHOULD I DO
im legit gon cry
i cant w the pressure
is this the last question you have?
i have 2 more
or do u have more hw
Total of 3 questions
just this once is fine
either sleep or pull an all nighter
you gotta just remember next time to do the homework before the deadline hits you like a metal club
math is about understanding logic
once u get the logic
its easy
when you dont
its impossible to solve
Oh btw uhm, the hw he gave he did not teach it, he said "study this equation you must solve it in the board you cant say no"
but then again the chances of anyone thinking logically at 1 am is pretty low
YES THATS IT cuz yesterday i did not sleep too because i had so much to do
i had research, projects, and asynchronous
the other day too
...
i was cramming our ppt
omg
and had to study my explanations and stuff
no hw=no sleep
theres this saying
Ok i wont bother u guys ill js watch a tut and hopefully i understand it
that forgiveness is easier than permission
good luck soldier
(and please try to get at least 1 hr of sleep)
ok guys goodmornight
good luck and try and get some sleep
how is that connected to math
i swear u never had like a strict strict teacher before who would humiliate their students
Infront of the board
im asian
😭
i js wish i can vanish
I hope im alive 3years from now
ok bye guys
how do i close
i know what it is like to study 3 months in a row with less than 4h of sleep per day
type .close
good luck!
.xlose
have a good night 
.xlose
that was close
.
almost there
.close
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can someone help me with this
i put log x+1 with base 3 as t
i am getting t= -2 and t= 1/2
can someone solve now and tell me what the answer is coming
Sure, but one of them is apparently invalid
why
so what will be the answers
One of them will be invalid as log base and input cannot be negative
why base isnt coming negative if u put x = -8/9
no, it's about t
t = $log_3 (x+1)$
e4 e5 Qh5 Nc6 Bc4 Nf6 Qxf7#
also when i put log 3 with base x+1 as t i am getting different answer
I'm not really in a good condition to do math rn, I'll dip out.
Oh i see, I thought it was just x + 1
can u help
To get the answers, raise both sides of this equation to power 3 and sub in the values of t you got
but t is log 3 with base x+1 so how can i raise it like that i put t = log 3 with base x+1 so i get quadratic and get roots then put value of t to get x
oh you did it that way
yea
Um in that case you will have to raise it to the power (x+1).
.
I think you should have instead put t as log of x+1 with base 3
That will be much better to work with
oh yes sry mb yes i put that as t
so i am getting -8/9 and root3-1
but when i am putting log 3 with base x+1 i am getting diff answer
like then i am getting a 8
Why do you want to do that?
what
Hmm, I think you messed up with one of the roots.
If t = 2, you get the answer 8
So you put the wrong sign
hm
!show
Show your work, and if possible, explain where you are stuck.
2tsquare +3t -2
what will be its roots?
oh yes wait i think i did mess up one sign
You can factor it as (t -2)(2t+1)
So the roots are 2 and -1/2
So, in fact, you got the wrong sign for both of them
yea
?
I think I factored wrong
lmfao what is happening
ok wait the equation will be 3+2/t=2t
so that will become 2tsquare -3t -2
can u factor that
Yeah
so we would get roots -1/2 and 2
And if you sub that in, you get the correct answers
Notice how one mistake messed up the entire solution
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So I understand how to find all 6 ratios for the inverse functions in the parentheses, but I don't know how it helps solve the problem. Obviously I can leave it in terms of asin and acos but I don't think that's a complete solution.
You can find it by changing cos-1 into sin-1 and tan-1 to sin-1
Sum of angle
Bruh
Please don't repeatedly close and claim a new channel with the exact same question. 
This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. 
Please be patient, even if your channel has not received much attention. 
You've done this twice already
What about the previous explanations confused you
We've literally given you like three different methods
Pythagoras theorem
??
a^2+b^2=c^2
so you're saying I still end up with inverse function, there's no way to get a "numerical" angle?
Probably :/
…
No confusion about that
That’s formula can be applied
Sum of angle..
You need to study something like this: https://math.libretexts.org/Bookshelves/Precalculus/Precalculus_1e_(OpenStax)/06%3A_Periodic_Functions/6.03%3A_Inverse_Trigonometric_Functions
You've already been told what to do not just geometrically but also have been given explicit formulas you can just plug in by multiple people multiple times at this point.
Cos-1 in terms of sin-1 will be 5/4
No bro there is range in inverse functions
we're taking principals here
Up to u m8
Just try reading it you will get some clarification
Sorry if I'm being extra thick, I will go through the text
Js saying but
$\arcsin(\sin(x) - \sin(y)) \neq x - y$
k
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Wonderful
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I think I get the general idea with this problem is to ibp from negative infty to positive infty but i keep going in circles - I have to use the statement in order to prove it if that makes sense
what step are you specifically confused on in the IBP?
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note that the dirac delta is 0 at anywhere but 0, not approaches, is 0.
integrating i get $x \delta (x) - \int_{-\infty}^{\infty} \delta(x) dx$
doublevcodes
yes
so the first part becomes 0
yes
im unsure how the second part gets me to - delta(x)
you're integrating the other side as well
oh i get you
to preserve equality
yeh :)
you can show both sides are equal to -1 via properties of dirac delta but that's pretty much it
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can't confirm the final number but the working out seems correct
oh, thank you
thats all i needed
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hi my hw is due in an hour can someone directly give me the answers and solution🥹 I WILL LEARN IT I SWEAR
hi again!
hiiii
hmm, i dont know if im allowed to give you the solution directly (per mathcord rules) but i can guide you as fast as i can :)
okok
gotchu
OK
for the first one
yes
yea u add them up
ye
