help-13

[twilit bison]

okay

we don't need to add 11 to 13

[ember kindle]

thats what the video said i needed to do

so

[twilit bison]

is the problem in the video different?

[ember kindle]

no

its the same problem

but different numbers

[twilit bison]

are you able to share the video or does it require an account or something?

[ember kindle]

im unable to share it and any screen recording apps i use do not take in any sound

[glad peak]

If you are on windows you can use snipping tool

Also, are you sure it said to add them and not subtract?

[ember kindle]

that doesnt screen record.

that just takes screenshot

[glad peak]

Yes it does

[frigid dust]

all you need is a screenshot

[ember kindle]

its a VIDEO not a picture

[frigid dust]

but you can take a picture of the formula in the video

[ember kindle]

it doesnt keep the formula up for the whole time

theres limited space yk

[frigid dust]

does it show it at any point in the video?

take a screenshot at that moment

[ember kindle]

but thank you for ur help . ive already gotten the answer

[frigid dust]

alright

[twilit bison]

sorry i can't help without more info

i can't understand 11+13

[cedar kiln]

@ember kindle Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[maiden wave]

I need help.

[maiden wave]

How do you do this question. I am trying to find the answer.

[digital cliff]

do you have any ideas?

[maiden wave]

I am given the slope intercept and the points

slope intercept is y=mx+b

[digital cliff]

yup

then what

[maiden wave]

Then you need to put the y intercept into a fraction

[digital cliff]

im not sure what that means

[maiden wave]

You're finding B first.

Since we need the b to finish this equation.

[digital cliff]

you do, i agree with that much, i just dont get what putting 'the y intercept into a fraction' means

[maiden wave]

That what I thought I should do.

[digital cliff]

im speaking about the wording, the phrase doesnt mean anything how you worded it

but are you just saying to replace b with the given intercept?

[maiden wave]

Yeah.

[digital cliff]

thats the way to go indeed

[maiden wave]

YAY.

[digital cliff]

now what?

[maiden wave]

Now we need to find the slope

since we have the B value and also the intercept.

[digital cliff]

how would we do that?

[maiden wave]

Just replace the B value with the intercept.

[digital cliff]

we already did that, no?

[maiden wave]

yeah.

[digital cliff]

im asking how we can find the slope after

[maiden wave]

We need to know the Y values and the X values.

[digital cliff]

do we have any?

[maiden wave]

Y1 is the intercept

and y2 is just -9

[digital cliff]

youre throwing around the word intercept a lot

but it doesnt apply

intercept is where one thing meets another, typically when talking about a line, its where it crosses the axes

(-3,-9) is just a point

[maiden wave]

-3 is a X value and -9 is a Y value.

[digital cliff]

it is

when x=-3, y=-9

[maiden wave]

Now we need the other X and Y.

[digital cliff]

youre thinking too much here

you dont need the formula m=(y1-y2)/(x1-x2)

you already have y=mx-75/7

[maiden wave]

yes

[digital cliff]

just plug the point into it

[maiden wave]

The X value is just -3.

[digital cliff]

uh, si?

[maiden wave]

And the M value is just 4/7.

[digital cliff]

,w (-9+75/7)/(-3)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by aldrnari_

[digital cliff]

you have a sign issue, but otherwise alright

[maiden wave]

So the answer is -4/7x-75/7

[digital cliff]

y=, si

[maiden wave]

Thank you.

👍

I have one more actually.

They didn't give me the X or Y

The X and Y are positive though.

But they are not whole numbers.

[violet flume]

.close

[cedar kiln]

Channel closed

Closed by @violet flume

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow owl]

Hi

[narrow owl]

i have a test and i wanna know if theres ways to know what methods i need to use to solve

how i can tell the methjod i need to use

the topics are direct/indirect variation word problems

[dire geode]

just do problems

help channels are for specific problems or topics

[cedar kiln]

@narrow owl Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy tusk]

what is the appollonius median theorem and when is it used-?

wrong chat

.close

[cedar kiln]

Channel closed

Closed by @worthy tusk

Use .reopen if this was a mistake.

[worthy tusk]

ok wait maybe i lied my friend was not useful ;-;

allow me to resend!

what is the appollonius median theorem and when is it used?

-sigh- if only i can understand the foreign language of maths

[proud vigil]

the best i can tell you is that "its the formula stated below the words" because i have never seen that applied before

[worthy tusk]

oh ok ty

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gilded widget]

HELLO

[gilded widget]

My attempt

can anyone suggest me ways to find ab+bc+ca

hello

<@&286206848099549185>

[dull oxide]

!15m

[cedar kiln]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[gilded widget]

oh my bad

hello

[proud vigil]

uh.

[gilded widget]

can anyeone help

[proud vigil]

i think this is solvable just using a sum and noting the expansion of (a+b+c)^2

[gilded widget]

like i did get to a point where a^2+b^2+c^2 =(138- (ab+bc+ca))/2

[proud vigil]

hmm.

[gilded widget]

wait i m wrong

um tihis

is correct

[proud vigil]

maybe do some subtraction.

[gilded widget]

nah it's not working

[proud vigil]

II-III and then I+(II-III) would seem to work to get all the squared terms cancelled

ab+2b^2+bc-ac

ah, yeah

thats a bit annoying.

[gilded widget]

okay so the key here is to find

[dull oxide]

,rccw

[gilded widget]

ab+bc+ca

[gilded widget]

hello

[earnest idol]

i did solve it but i feel there can be a shorter way

its nothing difficult just manipulation of many equations

oh theres a beautiful geometric way as well using cosine rule

[cedar kiln]

@gilded widget Has your question been resolved?

[gilded widget]

oh yuh

i did find that solution

but i do not understand

the cosine rule

like isaw it on quora

u apparently hav to use cosine rule then

heron rule or smth like that

h3i

[cedar kiln]

@gilded widget Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vague blade]

Power is 14

[slate lintel]

u-sub

[vague blade]

Can you explain more?

[proud vigil]

you can let u=e^-x here

[slate lintel]

i'd go e^x but yeah

[proud vigil]

oh its

can i spoil

,texsp ||$\int(\frac{u^2-1}{2u})^4\cdot\frac{1}{u}du$||

[wraith dagger]

;(

[vague blade]

The power is 14, not 4, does that change something?

[proud vigil]

yeah it does

mb i misread

[cedar kiln]

@vague blade Has your question been resolved?

[vague blade]

So, can you help me out?

[proud vigil]

you saw this

now its just working it out algebraically

[vague blade]

I'm kinda bad at this and understanding math at english, can you explain how exactly to do it algebraically?

[cedar kiln]

@vague blade Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid radish]

I need assistance for the formula to determine the primative function of this function

[vapid radish]

could be rewritten as 4*x^-0.5 I think

or just 4 * 1/x^0.5

[fallen moat]

what's giving you trouble on finding it?

[vapid radish]

Well, the answer is supposed to be 8*sqrt(x) so im wondering if its just rewritten or if theres some other formula

,w integral 1/x^0.5

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by meguvex

[fallen moat]

do you recall the power rule?

[vapid radish]

?

[fallen moat]

lemme grab

Note that for
f(x) = x^n
then it's antiderivate F(x) is
F(x) = x^(n+1) / (n+1) +C

so for this situation,
f(x) = 4 * x^(-0.5)
F(x) will be
4 * x^(-0.5+1) / (-0.5+1) +C

and also, for any af(x) where a is a constant
it's antiderivate will be aF(x)+C

[vapid radish]

so since its divided by 0.5 it becomes 2 * 4 * x^0.5 which is 8squrtx?

[fallen moat]

yep

[vapid radish]

I get

it

Thanks so much

[fallen moat]

Cheers!

[vapid radish]

.close

[cedar kiln]

Channel closed

Closed by @vapid radish

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty river]

Little help?

[undone star]

start with factorising what u can see already

[jaunty river]

I'm supposed to put 7 and -x on the left side right?

[undone star]

sure

[undone star]

ok nice

do the first 2 terms resemble the last 2 terms?

[jaunty river]

No becuase of the 7

[undone star]

they look pretty close but not quite there

ok what can u do to simplify the first 2 terms?

[jaunty river]

take x^2 out

[undone star]

ok nice so what does that look like now?

[jaunty river]

but i dont have the other part

[undone star]

this right now is
x^3 - 7x^2 +x - 7 = 0

and then u arranged it to

$x^{2}(x-7) + ? = 0$

[wraith dagger]

Dootud

[undone star]

what are we missing from before?

[jaunty river]

x-7

[undone star]

ok right so it now looks like?

[jaunty river]

or with parentheses if you wnat

i have a mental note of the =0

[undone star]

can you group them somehow now?

[undone star]

it might be a little easier to see with the paranetheses around x-7

[jaunty river]

they are both (x-7)

[undone star]

ok right

[jaunty river]

I think theres a step regarding that but im not sure what it is

[undone star]

hmm how about this

what u have above is the same as writing

$x^{2}(x-7) + 1(x-7)=0$

[wraith dagger]

Dootud

[jaunty river]

ohhh

[undone star]

does that look a little bit more familiar?

[jaunty river]

(x^2 + 1) has to be used right

[undone star]

ye ye

[jaunty river]

wait

[undone star]

👍 u on the right track

what does that leave u with now?

[jaunty river]

Yes thank you

oh wait

I think there is one part i have a question on

yea i didnt get it right

I have to solve for all real number solutions and I'm not sure how to do that

[undone star]

just stay with this for a moment and it will make sense

so we are solving $(x^{2}+1)(x-7)=0$

[wraith dagger]

Dootud

[jaunty river]

don't you have to separate the x^2

into two different thingies

[undone star]

(x+1)(x+1) isnt the same as x^2+1

try expanding it

[jaunty river]

oh your right

so now what?

[undone star]

ok so remember when we are solving, we just need to find when that expression is 0

so that is just the same as finding when either
x-7=0
or
x^2+1 = 0

because 0 x (any number) = 0

[jaunty river]

oh it uses the i doesnt it

[jaunty river]

I'm confused

[undone star]

i think i phrased that poorly

[jaunty river]

no not becuase of you

I just got stuck

[undone star]

what im trying to say is that, as long as one of the brackets is equals to 0

then whats in the other bracket doesnt matter

because 0 x (anything) is just 0

[jaunty river]

when was 0 being multiplied?

[undone star]

so we are now just solving separately
when is x-7=0
and when is x^2+1=0

[jaunty river]

or is it just that we only need to use one

[undone star]

remember we are solving $(x^{2}+1)(x-7)=0$

[wraith dagger]

Dootud

[jaunty river]

Right

I separated the (x-7) and made it equal 0 and got positive 7

[undone star]

for the left hand side to =0, it occurs when
(x-7)=0
or
when (x^2+1)=0

[undone star]

ok nice

thats a good start

ok lets think about x^2+1=0, do u see any problems with this

[jaunty river]

is it because i isn't a real solution

[undone star]

yes

good

the quesiton only wants real solutions

and i is imaginary

[jaunty river]

thats why we didnt use the other ones answer right

[undone star]

so that means the only solution we have is x=7

[jaunty river]

ok great

thanks

you actually made it seem really simple

[undone star]

u got there by urself pretty much

👍

[jaunty river]

thanks man, have a great day

[undone star]

u2

[jaunty river]

.close

[cedar kiln]

Channel closed

Closed by @jaunty river

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal sandal]

This correct or nope

[cedar kiln]

@vestal sandal Has your question been resolved?

[glad peak]

What is the span of the columns of A_2

[vestal sandal]

what?

[glad peak]

Are they linearly independent

Is what I meant to ask

More specifically, is the third column lin indep

[vestal sandal]

A2 all columns are linearly independent

[glad peak]

What is the result of adding the first two columns?

[vestal sandal]

Omg I wrote it wrong 🙂

[vestal sandal]

Yeah it's the third column

So the dimension is 2

Of U2

And the basis is the first two columns

For u2m

?

[glad peak]

Mhm sounds about right

[vestal sandal]

thank you so much

btw

it is just the first two columns as it is right

for the basis

of U2

and U1 to

[glad peak]

Yes, a valid basis will be, for any a and b, { a(c_1), b(c_2) }

Except a, b = 0

So a = b = 1 would just be the two columns

[vestal sandal]

Perfect amazing

thank you so much

.close

[cedar kiln]

Channel closed

Closed by @vestal sandal

Use .reopen if this was a mistake.

[vestal sandal]

.reopen

[cedar kiln]

✅

[vestal sandal]

@glad peak

Is part c correct same question

[glad peak]

I don’t think it is. Are you just finding a basis for [B_u1, B_u2] here?

[vestal sandal]

what i did is Ax = b where b is 0

and A

i got

via

a1u1 + a2u2 = b1w1 + b2w2

where u1 and u2 are the columns of the basis of u1

and w1 w2 are columns of basis u2

a1 a2 b1 b2

are the coefficents

which forms the x

a1u1 + a2u2 -b1w1 -b2w2 = 0

[glad peak]

Yeah this sounds correct so far

[vestal sandal]

A matrix is comprised of u1 u2 -w1 -w2 x is a1 a2 b1 b2

and then equals to 0

and i found x

and the x I gave above

so its correct?

[glad peak]

You can check by seeing if the basis you found is an element of both subspaces

If it is then you know you didn’t make any computational errors

[vestal sandal]

right so if i could form the vector using u1 u2's basis vectors

[glad peak]

Yes

[vestal sandal]

right perfect thank you so much

.close

[cedar kiln]

Channel closed

Closed by @vestal sandal

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusky cape]

$2x^2 +x-3 =0$

[wraith dagger]

Simon James B

[dusky cape]

$delta = 1^2 - 4 * 2 *(-3) \newline delta = 1 +24 = 25$

[wraith dagger]

Simon James B

[dusky cape]

$x1 = (-1 +5) = 2$

[wraith dagger]

Simon James B

[dusky cape]

$x2 = (-1-5)/2 = -3$

[wraith dagger]

Simon James B

[dusky cape]

what am i doing wrong here? because these are not the right answers

the correct answers are supposed to be -3/2 and 1

did i get delta wrong or..:(

[upper ruin]

Nope, ∆ is correct

[dusky cape]

ok

[upper ruin]

You forgot that the quadratic formula has 2a in the denominator

In this case 4

[dusky cape]

omg

i am used for a to always be one so i always forget 2a 😭

[upper ruin]

Well if a is usually 1, you should be used to dividing by 2

[dusky cape]

OH i FORGOT to divide it all?

omg

thanks i got it now

.close

[cedar kiln]

Channel closed

Closed by @dusky cape

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid radish]

It said to use a calculator and describe the answer. It became infinity so I assume that means it lacks a value because the graph is unlimited?

[vapid radish]

aka it grows forever when x gets closer to 1/2

?

[odd verge]

,w Plot y=tanπx

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ishigamisenku_

[frigid dust]

,w int tan(pi x)dx from 0 to 1/2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by .bonk__

[frigid dust]

yup

mby they meant from 0 to 1?

[vapid radish]

0 to 0.5

so youre right

[slate lintel]

that would also not exist

[frigid dust]

but cant you use symmetry and just say its equal to 0?

,w int tan(pi x)dx from 0 to 1

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by .bonk__

[vapid radish]

so whats the conclusion chat? is it continously growing therefore lacks a value when going closer to 1/2?

[vapid radish]

which means it doesnt touch each other because its a tan graph?

[frigid dust]

,w tan(pi x) dx from -1/2 to 1/2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by .bonk__

[frigid dust]

🤔 that does converge but from 0 to 1 doesnt?

[round geode]

Probably due to the fact that from 0 to 1 is crosses an asymtote

[odd verge]

,w int tan x

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ishigamisenku_

[frigid dust]

but you can just use u-sub to convert it into the same integral but from -1/2 to 1/2, no?

[vapid radish]

quick question . is the 4 the answer or just implying that the righthandside is 4 times bigger?

[frigid dust]

its the same thing

since 4 doesnt depend on x you can keep it outside of the integral

[vapid radish]

oh nvm i didnt see the lefthandside 4 😭

[cedar kiln]

@vapid radish Has your question been resolved?

Channel closed

Closed by @vapid radish

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid dust]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[vapid radish]

whats the question? is it how many values x has within 0 to 360degrees?

[oblique cliff]

yes and ive checked the awnser but i dont understand how to get to it

[vapid radish]

put in 1,2,3 ect into both your n equations and take notes of the value if its within 0 and 360 degrees

so like 30 deg + 0 times 180 then 60 deg + 0 times 180 then repeat untill its larger than 360

[oblique cliff]

so 30, 60, 210 and 240, man i went about it so wrong

[vapid radish]

which you stop

yeah

[oblique cliff]

thanks

!close

[vapid radish]

np

[oblique cliff]

.close

[cedar kiln]

Channel closed

Closed by @oblique cliff

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sterile quarry]

This more of a physics question but yeah

[sterile quarry]

As we say physics is juste applied maths

So it’s for question b

I know it is in French but all there is to know is that we’re trying to find the differential equations pour the mouvement of the ball

This is what I did

But in the answers they do something completely different but the answers are very similar and only change by a factor of a constant

So the question is where did I go wrong/ why can’t we do what I did

[cedar kiln]

@sterile quarry Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout shadow]

hi can someone help me check if this is correct

[cedar kiln]

@devout shadow Has your question been resolved?

[sterile quarry]

wtf he’ll nah

.reopen

[fresh patio]

You timed out, need to open a new channel

[cedar kiln]

@devout shadow Has your question been resolved?

[cedar kiln]

@devout shadow Has your question been resolved?

[river heart]

i swear if 1 person says helpers

[cedar kiln]

@devout shadow Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steep wyvern]

hi

[dim tiger]

hi

so whats the question

[pallid parrot]

show me your question

[steep wyvern]

1 min

[frigid dust]

!da2a

[pallid parrot]

i could translate it for him

[cedar kiln]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[dim tiger]

sure

[dim tiger]

aha ok i understand the question

[pallid parrot]

Find a simplified form of the summation

[dim tiger]

although i am not sure if i will be able to answer it

but let me try anyway

[steep wyvern]

thx

[pallid parrot]

in this context i guess it can be simplified

k² + k = k(k+1)

so substitution into this equation

k!(k(k + 1) + 1)

if you expand this it will be

k! * k(k + 1) + k! * 1

since you're multiplying by everything inside the parenthesis

او بتضربي مضروب ال k في كل شي في القوس

[steep wyvern]

yeah I will try ,thank you

where r u from

[pallid parrot]

egypt

[pallid parrot]

hint: k * (k + 1)! = ((k + 1) - 1) * (k + 1)!

[steep wyvern]

nice to meet u

[pallid parrot]

ty

[quasi current]

use google lens to translate it next time :)

[pallid parrot]

nice to meet u 2

[pallid parrot]

Arabic can have different translations

sometimes it can be inaccurate

[steep wyvern]

yeah

[quasi current]

oh yeah..

[dim tiger]

ok so try this

[dim tiger]

first split this into 3 sums

by expanding and separating the sums

after that use $k^2=(k+1)^2-2k-1$

[steep wyvern]

thank u so much

[dim tiger]

try it and if anything isnt clear or if you are stuck somewhere along the way tell me

[steep wyvern]

@dim tiger and then

[pallid parrot]

well in my own way

id distribute

[steep wyvern]

Yes

[dim tiger]

did you try what i told you about

what i said was like this

[pallid parrot]

just like how a(b+c) = ab + ac

[steep wyvern]

No still

[pallid parrot]

what do you feel like doing choose it and ill help

[dim tiger]

$\sum_{k=1}^n k!(k^2+k+1)=\sum_{k=1}^n k!k^2+\sum_{k=1}^n k!k+\sum_{k=1}^n k!$

[dim tiger]

from here work with the first sum

[dim tiger]

using this

and then distribute and simplify

[pallid parrot]

you could simplify the k equation first then use the sum

[dim tiger]

after that you will get a subtraction of 2 summations

which cancels out things

and leaves you with the closed form that you are looking for

[steep wyvern]

tysm

[pallid parrot]

also before you cancel put in numbers to test and see which is cancelled

and after you cancel try numbers and check if they're the answer

that's pretty much it

[dim tiger]

try that and then if you have questions about it you can tell me

[steep wyvern]

I complete?

[dim tiger]

now rewrite k^2 as this

[steep wyvern]

on side 1 or 2

or both

@dim tiger

[dim tiger]

on the right hand side of the last equation in the last line

[steep wyvern]

@dim tiger

[dim tiger]

not exactly

maybe you meant another thing idk but what is written here is incorrect

you need () around (k+1)^2-2k-1

since all of this is multiplied by k!

[steep wyvern]

yeah

@dim tiger

like that?

@dim tiger

[dim tiger]

yes

now distribute that

and separate it into 3 sums

[steep wyvern]

in the right side

@dim tiger

[dim tiger]

yes

[steep wyvern]

@dim tiger

Yes ?

@dim tiger

[dim tiger]

almost everything is correct

$-\sum_{k=1}^n k!(-1)$ should be $-\sum_{k=1}^n k!(1)$ instead

[dim tiger]

after you do this simplify as much as you can

so if there are things that will cancel out and so on

[steep wyvern]

@dim tiger

@dim tiger

Where r u

@dim tiger

[dull oxide]

don't ping spam

[dim tiger]

i am here

[steep wyvern]

Sorry

[dim tiger]

tysm

[steep wyvern]

Let's complete 😭

[dim tiger]

dw about it

[steep wyvern]

Cuz I tag so much

[dim tiger]

hmmm how did you get this

[steep wyvern]

Sorry

Yes I forgot 1

[dim tiger]

you had $\sum_{k=1}^n k!(k+1)^2-\sum_{k=1}^n k!(2k)-\sum_{k=1}^n k!+\sum_{k=1}^n k!k+\sum_{k=1}^n k!$ and then $-\sum_{k=1}^n k!+\sum_{k=1}^n k!=0$ but you forgot $\sum_{k=1}^n k!k$

[dim tiger]

alright

you can simplify more

why

because $\sum_{k=1}^n k!(2k)=2\sum_{k=1}^n k!k$

[dim tiger]

so what happens to $-\sum_{k=1}^n k!(2k)+\sum_{k=1}^n k!k$?

[steep wyvern]

Now I can @dim tiger

[dim tiger]

so how can you simplify more

[steep wyvern]

1 min

[dim tiger]

alright take your time

[steep wyvern]

@dim tiger

[dim tiger]

ok you forgot k! in the first term of the right hand side but thats just a typo

so from here

[steep wyvern]

Yes

[dim tiger]

$\sum_{k=1}^n k!(k+1)^2-\sum_{k=1}^n k!k=\sum_{k=1}^n k!(k+1)(k+1)-\sum_{k=1}^n k!=$ ??

[dim tiger]

k!(k+1)=?

[steep wyvern]

K!2k

[dim tiger]

no

[steep wyvern]

Yes that's wrong

🥲

[dim tiger]

k!=k(k-1)(k-2)...(3)(2)(1)

so now if you muliply that by k+1 what do you get

[steep wyvern]

K!k+k!

[dim tiger]

hmmm let me ask you in another way

what is (k+1)!

[dim tiger]

can you write it in a form like this

[steep wyvern]

But I didn't understand (3) (2)(1)

[dim tiger]

i meant that they are multiplied

what is k!

[steep wyvern]

So (k(k_1)(k_2).....(3)(2)(1))(k+1)

[dim tiger]

and what is k(k-1)(k-2)...(3)(2)(1)

[steep wyvern]

K! 😭

[dim tiger]

alright great

so (k+1)!=??

[steep wyvern]

(K+1) (k-1)(k-2).....(3)(2)(1)

?

[dim tiger]

yes but use this

so write (k+1)! in terms of k!

[steep wyvern]

(K(k-1)(k-2)....(3)(2)(1))((k+1)(k-1)(k-2)....(3)(2)(1))

?

[dim tiger]

(k+1)!=(k+1)k(k-1)(k-2)...(3)(2)(1) and k(k-1)(k-2)...(3)(2)(1) so (k+1)!=??

[steep wyvern]

(K+1)!=k!

No

(k+1)!=k!(K+1)

[steep wyvern]

.

@dim tiger

[dim tiger]

alright

[dim tiger]

so now use this to rewrite the right hand side here

[steep wyvern]

@dim tiger

[steep wyvern]

I forgot ! In the left

@dim tiger

And now?

[dim tiger]

ok

so now is the last step

write some of the first terms of each of these sums

and notice that a bunch of terms cancel

write down what remains

and that will be your closed form

[steep wyvern]

yes I will try and tell u

[dim tiger]

ok

[steep wyvern]

that's right

?

@dim tiger

[dim tiger]

,rccw

[dim tiger]

what changed from the second line to the third ?

the left hand side is wrong by the way

[steep wyvern]

k!to !

[dim tiger]

i am only paying attention to the right hand side

[dim tiger]

you didnt do this

[steep wyvern]

what should i do now

[fallen heath]

$\sum_{k=1}^n k!(k^2 + k + 1) = \sum_{k=1}^n k!\cdot [(k+1)^2 - k] = \sum_{k=1}^n (k+1)^2 k! - \sum_{k=1}^n k\cdot k! = \sum_{k=1}^n (k+1)\cdot (k+1)! - \sum_{k=1}^n k\cdot k!$

[wraith dagger]

Arya

[fallen heath]

It's a one-liner. Can you proceed from here @steep wyvern ?

[steep wyvern]

will try

[fallen heath]

Write down terms from both the Sum and you'll know what to do next

[steep wyvern]

The same result here

@dim tiger

@fallen heath

[fallen heath]

Yes, I can see that

You need to use that relation by writing terms of both the sums and noticing if you can maybe simplify

[steep wyvern]

Can I do that??

@dim tiger

@fallen heath

[fallen heath]

No

How'd it go from $\sum_{k=1}^n (k+1)\cdot (k+1)! - \sum_{k=1}^n k\cdot k!$ to $\sum_{k=1}^n (k+1)\cdot (k+1)! - 2\sum_{k=1}^n k\cdot k!$

[wraith dagger]

Arya

[steep wyvern]

Or

[fallen heath]

The one before was correct.. you're just supposed to write out the terms, as in

(2•2! + 3•3! + ... + (n+1)(n+1)!) - (1•1! + 2•2! + ... + n•n!)

[steep wyvern]

That's correct

?

[fallen heath]

No

[fallen heath]

.

[steep wyvern]

So

[twilit bison]

from this point you need to change indexes

[steep wyvern]

I wanna complete this

[steep wyvern]

.

[twilit bison]

yeah you're almost there

$\sum_{k=1}^{n} (k+1)\cdot (k+1)! = \sum_{k=2}^{n+1} k\cdot k!$

[wraith dagger]

Axe

[fallen heath]

You reached here @steep wyvern And that is correct. Now to proceed from here, you need to write out each term of the sum

[twilit bison]

there's probably different ways to do it if you don't want to change index

[steep wyvern]

After this I should write out each term of the sum

[frigid dust]

,rcw

[dim tiger]

yes

[steep wyvern]

But how

[dim tiger]

so what does $\sum_{k=1}^3 k$ mean for example

[dim tiger]

it means 1+2+3

[steep wyvern]

Yes

[dim tiger]

so basically what you do is that you start from the point you set

in this case k=1

substitute this value in what is inside of the sum

then add the next term which will be substituting k=2 instead of k=1

and repeat the process till you reach the upper limit of the index that you set

so for example $\sum_{k=1}^n k^2=1^2+2^2+3^2+\cdot\cdot\cdot+n^2$

[dim tiger]

so now do the same thing here to write the sum term by term

[steep wyvern]

And the Solution should be 1 side

[dim tiger]

thats what is meant by term by term

so how do you write $\sum_{k=1}^n (k+1)!(k+1)$ term by term

[steep wyvern]

I didn't understand how to write term by term because of this (k+1)!(K+1)

[dim tiger]

substitute k=1

thats the first term

then add the next term

you get the next term by substituting k=2

so what do you get if you substitute k=1

[dim tiger]

in (k+1)!(k+1)

[steep wyvern]

(1+1)+(2+1)!(1+1)+(2+1)

?

[dim tiger]

how did you get that

[steep wyvern]

.

[dim tiger]

??

[steep wyvern]

I didn't understand 🥲

[dim tiger]

my question is like this : what is the value of (k+1)!(k+1) for k=1

[steep wyvern]

And n=?

[dim tiger]

there is no n here

[dim tiger]

just forget everything above for now and think about this

[steep wyvern]

It's 4?

[dim tiger]

think of this as independent of anything above

[dim tiger]

alright

what is its value for k=2 ?

[steep wyvern]

18

[dim tiger]

thats right

ok so $\sum_{k=1}^2 (k+1)!(k+1)=??$

[steep wyvern]

22

؟

[dim tiger]

great

so now $\sum_{k=1}^n (k+1)!(k+1)=??$

[dim tiger]

just write it as a sum of terms

[dim tiger]

so you said that this is 22 . why? because it is 4+18 or in other words it is (1+1)!(1+1)+(2+1)!(2+1)

[dim tiger]

now do the same thing here

[steep wyvern]

Yes

[dim tiger]

write it as (1+1)!(1+1)+(2+1)!(2+1)+???

only write the first few terms then ... and the last few terms

[steep wyvern]

+(n_1+1)!(n-1+1)+(n+1)!(n+1)

?

[dim tiger]

there is a small mistake here

you forgot a term between these 2

what comes after (n-1)!(n-1)?

is it really (n+1)!(n+1)

[steep wyvern]

Only n?

[dim tiger]

wdym by only n

you mean only n instead of n+1

so n!n?

[steep wyvern]

No

[dim tiger]

then what did you mean

[steep wyvern]

no I was wrong

[dim tiger]

ok so what is your correction

[steep wyvern]

yes

why

cuz

10 before it 10-1

for exemple

[dim tiger]

is n-1=(n+1)-1??

[steep wyvern]

no

[dim tiger]

ah wait

nvm i misread mb

[steep wyvern]

so what

[dim tiger]

what you wrote is correct

[steep wyvern]

yeah

[dim tiger]

alright so $\sum_{k=1}^n (k+1)!(k+1)=(1+1)!(1+1)+(2+2)!(2+2)+\cdot\cdot\cdot+(n-1+1)!(n-1+1)+(n+1)!(n+1)$

[dim tiger]

now do the same process for $\sum_{k=1}^n k!k$

[steep wyvern]

(1.1 )+(2.1+)....(n-1!.1)+(n!.1)

[dim tiger]

??

[steep wyvern]

no wait

(1!.1)+(2!.2)+....(n-1!.n-1)+(n!.n)

[dim tiger]

alright

[steep wyvern]

nd then

[dim tiger]

now $\sum_{k=1}^n (k+1)!(k+1)-\sum_{k=1}^n k!k=(1+1)!(1+1)+(2+1)!(2+1)+(3+1)!(3+1)+\cdot\cdot\cdot+(n-2+1)!(n-2+1)(n-1+1)!(n-1+1)+(n+1)!(n+1)-[1!1+2!2+3!3+\cdot\cdot\cdot+(n-1)!(n-1)!+n!n]=(1+1)!(1+1)+(2+1)!(2+1)+(3+1)!(3+1)+\cdot\cdot\cdot+(n-2+1)!(n-2+1)(n-1+1)!(n-1+1)+(n+1)!(n+1)-1!1-2!2-3!3-\cdot\cdot\cdot-(n-1)!(n-1)!-n!n=??$

[steep wyvern]

yeah

can we complete tmrw plz

you really helped me

thank u so so much

[dim tiger]

you still need one step

just simplify this now

notice that almost all of the terms cancel

only 2 terms remain

work out which 2 remain and you are done

with this i am done

think about it when you want

and i am sure you will get the answer

[steep wyvern]

thank u

so can i send tmrw

[dim tiger]

sure np

[steep wyvern]

tysm

[cedar kiln]

@steep wyvern Has your question been resolved?

Channel closed

Closed by @steep wyvern

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Please don't occupy multiple help channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dapper lotus]

can someone explain how we get Z here?

[dapper lotus]

is it given? is there a way of calculating it?

[clear umbra]

normal table

[dapper lotus]

normal table?

[clear umbra]

normal distribution table

[dapper lotus]

could you exaplain?

[clear umbra]

you have 95% confidence right

[dapper lotus]

yes

[clear umbra]

whats the alpha value for it

[dapper lotus]

could you explain to me like i have no idea what i'm talking about

what is an alpha value

[clear umbra]

this your first time learning this?

[dapper lotus]

yes

[clear umbra]

alpha is just 1 - confidence

95% is 0.95

so alpha = 1-0.95 = 0.05

[dapper lotus]

okay

[clear umbra]

and this is a confidence interval

there will be two sides

so you'll need to divide it by 2

[dapper lotus]

i divide 0.05 by 2?

[clear umbra]

yes

[novel veldt]

is this statistics

[dapper lotus]

okay but how does this get me any closer to Z?

[dapper lotus]

data analysis

[clear umbra]

0.05/2 is 0.025 correct

?

[clear umbra]

patience

[dapper lotus]

yes

[clear umbra]

now do you have a normal distribution table

[dapper lotus]

what does this mean

[clear umbra]

do you know the normal distribution

[dapper lotus]

let's say no

[clear umbra]

?????

[dapper lotus]

what is the normal distribution

i don't know man

describe it

[dapper lotus]

no

i do not

[clear umbra]

oh dear lord

[fresh patio]

Normally distribute deez nuts

[novel veldt]

bro just assume its given

[clear umbra]

ill take one thank you very much

[fresh patio]

!

[dapper lotus]

i am so cooked

[clear umbra]

why are you learning confidence intervals when you dont know what a normal distribution is

[dapper lotus]

no idea to be honest with you man

do you know how to use R? cause i know we're meant to be using that but the professor does not show us how that is involved in the "getting Z process"

[clear umbra]

i havent used R in months lol

[dapper lotus]

me neither i basically passed the entire subject and then got told a month later "yo by the way you missed this one midterm (i dislocated my leg at the time) and you need to retake it, oh and by the way if you fail this you fail the whole subject"

the first half of the subject is R and excel and data analysis

second half is all discrete math

and i already passed all the discrete math shit

and a good majority of the data anlysis shit

this is the only thing i don't understand

[clear umbra]

https://math.arizona.edu/~rsims/ma464/standardnormaltable.pdf

take this

[dapper lotus]

if it helps the professor said we'll be given this on a second sheet of the exam

along with the rest of the"equation sheet" but this is the most relevant thing

[clear umbra]

then just use that and dont care how you get it

but thats not what your question was is it

[dapper lotus]

dude i'm running off no hours of sleep right now

i appreciate your help a lot though

i'm going to leave for now, and assume that Z is given

thank you for your help

if i need more i'll rejoin

.close

[cedar kiln]

Channel closed

Closed by @dapper lotus

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense shoal]

Could someone help here? I am very confused because there is no x approaching sign

[dense shoal]

Is the question just wrong?

[livid hound]

they probably intend
limit for x to inf

[dense shoal]

But the question is wrong right?

Becuase you need a limit?

[livid hound]

poorly worded question

[dense shoal]

Should I just assume x-->+inf?

[livid hound]

yes

[dense shoal]

okay thanks

[dense shoal]

also last question, this doesnt have a limit right? DNE?

[livid hound]

wrong

why do you think it's dne

[dense shoal]

well doesnt limit mean approaching? like you cant touch the number?

[livid hound]

no

[dense shoal]

Oh, so its -1?

[livid hound]

you can attain the value,
the limit will indeed be -1

[dense shoal]

alright, I see, and this one would be 0 as the limit to confirm right?

[livid hound]

yes

[dense shoal]

okay thank you so much!!

[cedar kiln]

@dense shoal Has your question been resolved?

Channel closed

Closed by @dense shoal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid cipher]

I have a set of parametric equation: x=2t+1 and y=2-t, when I graph it, I can't find the limitation and I just have a continious line, so how do I find the limitation?

[livid cipher]

I know I am supposed to use the orginal parametric and graph x vs t graph and y vs t graph

but even if I graph it, I still don't know what the limit is

[dire geode]

Limit of what as what

[livid cipher]

like on the x and y coords on the x vs y graph

which will be the graph I am trying to get

[dire geode]

Do you want a graph or do you want a limit of something

[livid cipher]

I want the graph, but the graph, which is a line, won't be continious, and I want to figure out from which point to which is the graph

because it will have some limitations because of t

[dire geode]

What limitations are there on t

[livid cipher]

well, you can check on desmos

but i will put a screenshot here

actually nvm

im being dumb

[dire geode]

Where did the requirement 0<= t <= 1 come from

[livid cipher]

yea

i just saw that

i think desmos did it automatically

i didn't see it until now

mb

.close

[cedar kiln]

Channel closed

Closed by @livid cipher

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid cipher]

quick question, in parametric, does x^2+y^2=t^2?

[swift olive]

What was the original question?

[livid cipher]

the one I just asked

in parametric, does x^2+y^2=t^2

[crimson sedge]

wdym parametric?

[livid cipher]

parametric equation

because in polar

x^2+y^2=r^2

[swift olive]

Correct

The parametrization of a circle would be
x = rcos t
y = rsin t

[crimson sedge]

the question is poorly asked to be honest. If you can express x and y as functions of a parameter (probably just one), you can find lots of parametrizations

[livid cipher]

.close

[cedar kiln]

Channel closed

Closed by @livid cipher

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[delicate yacht]

@livid cipher assuming that you meant the previous parametrisation,

$x=2t+1$ and $y = 2-t$, then

$x^2+y^2= (2t+1)^2+(2-t)^2 = 5t^2 + 2t + 5 $

... so, no, it isn't just $t^2$... and it wouldn't be a single circle anyway

because $t$ takes multiple values.

[wraith dagger]

Jay

[cedar kiln]

@delicate yacht Has your question been resolved?

[delicate yacht]

Hopefully @livid cipher will see thus comment, even though the bot thinks I am asking a question...

So...

.close

[cedar kiln]

Channel closed

Closed by @delicate yacht

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim gulch]

the last part

[feral juniper]

!status

[cedar kiln]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[dim gulch]

3

[feral juniper]

can you show it?

[dim gulch]

i got 3400pi

but cant figure why its wrong

[dim gulch]

i cant

can u find the right answer please

[feral juniper]

do you know what is meant with similar in this context?

[dim gulch]

yeah ik what

i understood

i did...

[sly swan]

idk

[dim gulch]

$$ 4000\pi - 1000\pi + 20^2\pi $$
$$ = 3400\pi $$

[sly swan]

can u explain what similar means

[dim gulch]

@feral juniper

which should be correct right

[wraith dagger]

hades

[sly swan]

does it mean same ratios?

[dim gulch]

u trolling?

[feral juniper]

yes

[sly swan]

nah i just have a hard time understnading definitions

[dim gulch]

oh lmao

[feral juniper]

so @dim gulch what is the ratio of s to r

[feral juniper]

we are all here to learn ^^

[dim gulch]

wdym bruv

i am talking about last part

in the second pic

[feral juniper]

I know

[feral juniper]

you want to derive that r = 20cm

[dim gulch]

i did that

ik how

[sly swan]

wait hades

[dim gulch]

but do the calc the surface area

[sly swan]

which one do u need help with

the first pic or the second pic?

[dim gulch]

the one i sent

[sly swan]

i see