#help-13

1 messages · Page 368 of 1

crimson sedge
#

ye ok imma just send her a message

#

.close

cedar kilnBOT
#
Channel closed

Closed by @untold rock

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

inner dawn
#

,help

cedar kilnBOT
wraith daggerBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

kindred storm
cedar kilnBOT
#

@inner dawn Has your question been resolved?

#
Channel closed

Closed by @inner dawn

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

trail dune
#

Does this make sense or do I not know what inverse functions do?

twilit bison
#

i don't think that's the way they want you to solve it

trail dune
#

That's how inverse functions work ye?

#

Get back da OG angle

twilit bison
#

it should work, yeah

trail dune
#

.solved

cedar kilnBOT
#
Channel closed

Closed by @trail dune

Use .reopen if this was a mistake.

trail dune
#

ty

twilit bison
#

you'll need a calculator though

#

by the way

#

you need to make sure you put the angle in the right quadrant when you use inverse sin

hollow trail
#

you'd need to use a calculator to find x, but you don't need one to find sin(x/2), cos(x/2), and tan(x/2)

trail dune
#

.reopne

#

.reopen

cedar kilnBOT
#

trail dune
#

.closed

#

.close

cedar kilnBOT
#
Channel closed

Closed by @trail dune

Use .reopen if this was a mistake.

trail dune
#

.reopen

cedar kilnBOT
#

trail dune
#

How does this make sense? It feels like we just completely disregard it as being an inverse n just stick a theta symbol on it n tell da inverse to kick rocks

solemn quail
#

Ask yourself what cos inverse of x is really saying

soft holly
wraith daggerBOT
#

King Leo

solemn quail
trail dune
soft holly
wraith daggerBOT
#

King Leo

solemn quail
#

Yes, it's referring to an sable with a specific property

trail dune
#

I know but like

soft holly
trail dune
soft holly
trail dune
#

The value of cos right?

soft holly
trail dune
#

We can find the angle that was used to find the adjacent/hypotenuse ratio

soft holly
#

Perfect

soft holly
#

Can you explain sin in english?

trail dune
#

Opposite/hypotenuse

#

But I see it now

soft holly
trail dune
#

We get dat angle back apply it to sin2, n since it's double, we can apply da double angle formula

#

Is that correct?

#

ty for the help bro

#

.solved

cedar kilnBOT
#
Channel closed

Closed by @trail dune

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

novel veldt
#

The question is to find the gradient of the curve x=cos(2y) at x=0 (using the identity dy/dx = 1/(dx/dy))

novel veldt
#

This is the answer working out

#

I got dx/dy correct and the answer correct, but how did they achieve the second last step?

#

I dont see any similarity from the 4th to 5th step except for the 2's

hollow trail
#

they plugged in the equation they got for 2y into the derivative dx/dy

novel veldt
#

Ohh like evaluating -2sin(pi/2 + pi*k)?

#

Then it can only be 2 values?

hollow trail
#

it results in -2 if k is even and +2 if k is odd

novel veldt
#

I see, thank you so much

#

!close

#

.close

cedar kilnBOT
#
Channel closed

Closed by @novel veldt

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

urban otter
#

i got 7/20 but its wrong i need help

cedar kilnBOT
robust adder
#

why did you post the same problem here?

urban otter
buoyant python
robust adder
#

oh wait nvm

#

oh ok

urban otter
robust adder
#

i can help

urban otter
#

im gonna be late for school

urban otter
robust adder
#

so okay first

#

the question is asking in what probability do only one of the two will qualify, correct?

fallen heath
urban otter
#

yes

fallen heath
#

Question asks that ✓

urban otter
robust adder
#

First the chance of Jack Quilifying is 3/10 but Charlie NOT qualifying is 1/8

#

So you multiply that to get ONLY Jack qualifying

#

3x1/8x10

urban otter
#

FUCKK

#

WAIT

#

i got it wrong again

#

it generated a new question

robust adder
#

which would equal 3/80

#

??

#

Ok

#

Same thing

fallen heath
#

Same context

robust adder
#

the chance of Grace qualifies is 7/10

urban otter
#

i got 9/20

#

its correct

robust adder
#

No

urban otter
#

ty guys

robust adder
#

wha

#

21/80

urban otter
#

i gtg to schooll

#

ty bro

robust adder
#

np ?

cedar kilnBOT
#

@urban otter Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cosmic birch
cedar kilnBOT
swift olive
#

What the problem mean is that you have to isolate the variable "a"

#

Can you do that?

cosmic birch
#

The answer will be a= (then idk)

swift olive
#

yesss

#

can you do that

cosmic birch
#

No I need help

swift olive
#

I suggest you to expand 3(2a + b) first

cosmic birch
#

6a+3b?

swift olive
#

correct

#

so you now have w = 6a+3b - 4

#

since, like you said, we want it to be a =, what do you think is the next step we should do

cosmic birch
#

+4 to each side?

swift olive
#

correct

#

then what will be our new equation

cosmic birch
#

W+4=6a+3b

swift olive
#

correct

#

then what do you think we should do?

cosmic birch
#

-3b maybe?

swift olive
#

correct

#

then what will be our new equation

cosmic birch
#

W+4-2b=6a

swift olive
#

Nice!

cosmic birch
#

*3b

swift olive
#

what do you think we should do next

cosmic birch
#

Divide by 6

swift olive
#

nice

#

what will be the new equation

cosmic birch
#

(W+4-2b) over 6 = a

#

/close

swift olive
#

correct!

#

goodd job

cosmic birch
#

How do you close-

#

lol thanks for the help!

swift olive
#

you didnt realize it, but u just answered it on your own hahaa

#

its .close

cosmic birch
#

Yes lol-

#

.close

cedar kilnBOT
#
Channel closed

Closed by @cosmic birch

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar bobcat
#

hey any body will help me in basics of parabola?

native heath
#

!da2a

cedar kilnBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

native heath
#

just ask lol

cedar bobcat
native heath
#

the bot said what i mean

cedar bobcat
#

okay

#

u k parabola?

native heath
#

maybe.

cedar bobcat
#

explain me

#

m having exam tmr!

rough osprey
#

Like from the very basics?

cedar bobcat
#

ig!

#

u k gnrl expression

rough osprey
#

You know quadratic equation right?

cedar bobcat
rough osprey
#

And you know the graph of the quadratic equation is forming a parabola

cedar kilnBOT
#

@cedar bobcat Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

plain granite
#

$x^2 + 3x = 7a - 12 - a^2$ find all values of a such that the equation's product of roots is equal to 0

plain granite
#

I have no idea how to start

wraith daggerBOT
plain granite
#

.close

cedar kilnBOT
#
Channel closed

Closed by @plain granite

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
twilit escarp
#

<@&268886789983436800> lmao

cedar kilnBOT
#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

ionic bridge
#

Wtf

#

At first it looked like he was going to do some wwe move

#

Then i saw that thing

olive hedge
#

.close

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
vestal bluff
#

resend your question

cedar bobcat
#

will u teach me basics of parabola?

vestal bluff
#

cant do that without a specific question

cedar bobcat
#

wdym?

#

i mean just teach me the basic

cedar bobcat
#

wait lemme send u the q

#

help me to solve tht

#

x^2 -cosx ÷ sinx

blazing zephyr
cedar bobcat
#

this 1

pastel vault
#

this is related to the definition of trig functions

#

cos(x)/sin(x) = cot(x) by definition

cedar bobcat
#

nope v hve to solve by using function idk ?

#

tbh

pastel vault
cedar bobcat
#

shit

pastel vault
#

so you aren't solving anything

cedar bobcat
#

sry i hve send u the limits 1

#

find the coordinates of the focus, axis of the
parabola, the equation of the directrix and the length of the latus rectum

#

<@&286206848099549185>

native heath
#

i hate ncert

#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
cedar bobcat
native heath
#

it's very clearly ncert lol

cedar bobcat
#

?

cedar kilnBOT
#

@cedar bobcat Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

broken ice
#

could anyone help me find list of undefined math operation?

such as
division by 0, log(0), pow(0.0, 0.0), etc

just up to around bachelor university math

vestal bluff
#

im sure theres a wiki page somewhere

broken ice
#

I did find undefined math wiki, but I think the list is fairly not complete. maybe I open the wrong one?

#

In mathematics, the term undefined refers to a value, function, or other expression that cannot be assigned a meaning within a specific formal system.
Attempting to assign or use an undefined value within a particular formal system, may produce contradictory or meaningless results within that system. In practice, mathematicians may use the term...

cedar kilnBOT
#

@broken ice Has your question been resolved?

split yarrow
cedar kilnBOT
#

@broken ice Has your question been resolved?

broken ice
#

alright thx all

cedar kilnBOT
#
Channel closed

Closed by @broken ice

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

paper coral
#

I must aqquire helppp C:

cedar kilnBOT
paper coral
#

Similar values ​​have been found for mussels on the seabed in the Arctic
the age of the mussel and the length of the mussel shell as shown in the table.

Mussel age (years)
Shell length (cm)

In one model, it is assumed that the length of the mussel shell as a function of the age of the mussel is one
function of the type

L(t)=b.tª,

where L is the length of the shell (measured in cm) and t is the age of the mussel (measured in years).

a) Use the data in the table to determine the numbers a and b.

b) Use the model to determine the length of the shell of a clam that is 24 years old
old.

c) Determine the number L'(24) and describe what the number tells about the growth of the clam shell.

#

the table thingy the upper line is mussel age in years the lower part is shell lenght in cms

#

Ive used the formular for finding a and b but im not sure if ive done it right?

#

i mean i picked the two first coordinates is that correct?

#

this is the results i got

#

i dont understand how to begin on b T_T

#

im using Maple if that helps

#

like as a math program

#

this is my question to task b) im guessing that i have to put it like this? L(t)=0,79*24^1,335 ?

#

would that be correct?

#

dies in confusiono

cedar kilnBOT
#

@paper coral Has your question been resolved?

cedar kilnBOT
#

@paper coral Has your question been resolved?

cedar kilnBOT
#

@paper coral Has your question been resolved?

swift olive
#

I think I can help you @paper coral

#

Just give me a sec

#

So we want to fit the data to the model L(t) = bt^a

paper coral
#

ty for tryin tho idk how to close this

#

now

swift olive
#

Can I see?

#

Bc from what you sent, we arrived at a different answer

paper coral
swift olive
#

Okay goodjob but just for comparison what I got is a = 0.654787 and b=1.2302

#

Almost the same as yours 👍

cedar kilnBOT
#

@paper coral Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sterile elm
#

Help

cedar kilnBOT
sterile elm
#

So let’s say u got a bottle of cologne and it’s 500$ for 200ml

#

And u have 50ml left

#

How much is it worth ?

grand arch
#

you can write a ratio

sterile elm
#

?

grand arch
#

like a fraction of dollars to ml

robust adder
#

$500/200ml = x/50ml

#

You can divide the numerator and the denominator by 4

#

To get the same denominator

#

125/50 = x/50

#

x = 125$

cedar kilnBOT
#

@sterile elm Has your question been resolved?

#
Channel closed

Closed by @sterile elm

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

warm apex
#

Is there a formula to take 12 equally shaped sizes slices of a pizza?

warm apex
#

like i want 12 equally sized slices of pizzas

digital cliff
#

dont think you particularly need a formula
if you have a protractor or something just cut a new slice at 30 degrees from the previous (from the center)
assuming this pizza is a perfect circle anyway

cedar kilnBOT
#

@warm apex Has your question been resolved?

warm apex
#

oh that does make sense

#

ty

#

.close

cedar kilnBOT
#
Channel closed

Closed by @warm apex

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

winter tulip
#

Can I get an assist?

cedar kilnBOT
#

@winter tulip Has your question been resolved?

frigid dust
#

For which one

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

next iron
#

please help with this question of functions, the options are A) 4 B) 10 C) 11 D) 16

frigid dust
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
next iron
#

i dont know where to begin

frigid dust
#

Try filling in whats given first

next iron
#

I tried replacing x with x/3 but it didnt seem to help

frigid dust
#

Try filling in f(8)

high bridge
#

think about this, how do you fit f(8) into the equation f(3x)-f(x)=x

next iron
#

uh, i will try

frigid dust
#

Basically, fill in x=8 into the equation

next iron
frigid dust
#

Why did you do the x/3 stuff?

#

f(3*8)-f(8)=8

next iron
#

So I was looking for another approach to it

#

But couldn't think of any

frigid dust
next iron
#

it makes f(24) = 15

frigid dust
#

Yup

#

Im not sure how it helps us, but we have a new value 🙂

next iron
#

😭 I'm pretty sure I am more confused now

frigid dust
#

Questions like this are just a lot of trial and error

high bridge
#

I am not sure if this is trial and error

frigid dust
#

Going into paths that may lead to a dead end, but unknown until youre traced them

next iron
#

in the answer key they have replaced x --> x/3 infinite times

frigid dust
#

Unless you instantly see how to do it, its trial and error

next iron
#

Hold on I'll send the answer

#

I'm not sure how I'm supposed to think like this in the actual exam

#

@frigid dust @high bridge

high bridge
#

hmm

#

I dont get why replacing the x value with x/3 infinitely will result in the first term being just f(x)

frigid dust
#

f(3x)-f(x)=x
f(x)-f(x/3)=x/3
f(3x)-(x/3+f(x/3))=x
f(3x)-f(x/3)=4x/3

#

Hmmm

frigid dust
#

Its getting a new equation, and then plugging it back in

#

If you want you can take y=x/3 and get the same result

next iron
#

oh wait yeah

#

I think

next iron
next iron
frigid dust
#

X is just a dumm py variable

#

Dummy variable

#

Can be called anything

next iron
frigid dust
next iron
#

and f(14) becomes 13

frigid dust
#

\begin{align*}f(x)-f(x/3)&=x/3\f(x/3)-f(x/9)&=x/9\f(x)-(f(x/9)+x/9)&=x/3\f(x)-f(x/9)&=x(1/3+1/9)\end{align*}

wraith daggerBOT
frigid dust
#

Do you see whats happening?

next iron
frigid dust
#

From 2 to 3?

next iron
#

yeah

#

(f(x/9) + x/9) ?

frigid dust
#

We rewrite line 2 as: f(x/3)=f(x/9)+x/9

#

Then we plug that back into the equation on line 1, to get to line 3

next iron
#

ohhh

#

after the 4th line? what next

#

f(x) - f(x/9) = x(4/9)

frigid dust
next iron
#

Ohhhh

#

so basically replace x --> x/3 again?

frigid dust
#

Line 2 becomes x/9 and x/27

frigid dust
next iron
#

alrighttt

frigid dust
#

So we get f(x)-f(x/27)=x(1/3+1/9+1/27)

next iron
#

time alloted for this question is just 3 minutes in the exam

frigid dust
#

Infinitely many times

#

(Take the limit)

next iron
#

yeah

#

alr

#

thank you

frigid dust
#

Gl

next iron
#

.close

cedar kilnBOT
#
Channel closed

Closed by @next iron

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

solid cedar
#

Have I classified this algorithm correctly?

solid cedar
#

<@&286206848099549185>

#

.close

cedar kilnBOT
#
Channel closed

Closed by @solid cedar

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chilly forum
#

im not sure how to rearrange this, i got up to dy/dx (x) = y^2 but idk where to go from there

tight birch
#

this is separable

coral jewel
#

arrange everything so that you have dy with only things with y on one side and dx with only things with x on the other side

cedar kilnBOT
#

@chilly forum Has your question been resolved?

#
Channel closed

Closed by @chilly forum

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cedar kilnBOT
#
Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

obsidian crest
#

currently trying to learn functions for precalc and trying to find the domain of f(x)=1/x-3. i havent seen anything like this yet and dont really know what to do. thanks!

twilit bison
#

do you know the meaning of domain?

obsidian crest
#

its all possibilities of x?

crimson delta
#

1/x-3 or 1/(x-3) ?

twilit bison
#

yeah when the function is defined

obsidian crest
#

its 1 over x-3

twilit bison
#

the subtraction isn't going to be a problem but division is sometimes undefined

#

you can't divide by 0

obsidian crest
#

ah im kinda confused

#

i dont think i need to solve that equation

#

if i have -1=0.5x whats the proper way to factor?

twilit bison
#

solve?

#

factor?

obsidian crest
#

wait nvm i did it wrong

twilit bison
#

the range will be everything except when the denominator is zero

obsidian crest
#

heres what im trying to solve

twilit bison
#

this is a different problem

obsidian crest
#

yeah i was doing one i wasnt supposed to

prisma pike
obsidian crest
#

oh wow dang i was trying to find the equation

twilit bison
#

you can just read the graph

prisma pike
#

So g(2)=?

obsidian crest
#

4

prisma pike
#

Yep

#

Can you do b?

obsidian crest
#

whats the difference

#

oh is that y?

prisma pike
#

You’re finding the x such that the value of the function is 2

obsidian crest
#

is it -3?

prisma pike
#

Yeps

obsidian crest
#

so if its f(x)= 3 its on the x axis?

prisma pike
#

Well not how'd I'd phrase it but yes ig

obsidian crest
#

i dont really understand whats goin on on these graphs, we literally just went over what a function is

#

im suppossed to find f(-2) f(-1) f(0) f(1) f(2) of f(x)=8x^2-7x+3

#

i did them all individually just wondering if theres a faster way than just doing them all one at a time

cedar kilnBOT
#

@obsidian crest Has your question been resolved?

#
Channel closed

Closed by @obsidian crest

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

inner solar
#

how to dedtermine absolute convergence of this series

kindred elm
#

convert sinh to tanh

cedar kilnBOT
#

@inner solar Has your question been resolved?

inner solar
#

but these are identities for arctan not tanh arent they?

kindred elm
#

ohh mb i confused it

cedar kilnBOT
#
Channel closed

Closed by @inner solar

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

forest socket
#

the original exponent is n-3

i need exponent to be (n-2)/4
i dont know how to do it

forest socket
#

i got it

#

.close

cedar kilnBOT
#
Channel closed

Closed by @forest socket

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rare grail
cedar kilnBOT
rare grail
#

Do how you do these 2 question?

upper laurel
rare grail
upper laurel
#

for example 2x + 2 = 2(x + 1) could be an identity

#

you can use that here
instead of asking "find the value of sin(2x)"
you can ask "find the value of 2 sin(x) cos(x)"
and its guaranteed that sin(2x) and 2 sin(x) cos(x) are essentially the same thing

#

identities are figured out, but figuring them out I dont think is necessary for your problem? I am not sure though

rare grail
upper laurel
#

in that case we can take things one step at a time

#

first, with tan(x) = 4,

#

you know tan represents a ratio on a triangle, right?

rare grail
#

Yea

#

I think?

rare grail
upper laurel
#

now we can draw a triangle that represents this

#

you can think of a triangle with opposite side = 4 and adjacent side = 1

#

this would be a triangle where tan(x) = 4, right?

rare grail
#

Ye

#

Oh and by a² + b² = c² we can find out the hypotenuse

#

Hm ●_● doesn't that mean it's square root of 17

upper laurel
#

now from here, we need twice of the original angle

#

to think about this, notice something interesting about the ratio opposite / adjacent

upper laurel
rare grail
#

Oh no it wouldn't

upper laurel
#

that means if you scale all the sides of the triangle by the same amount, would its tan(x) change?

rare grail
#

No

#

So we should increase it until the hypotenuse becomes an interger?

upper laurel
#

but we have a way to work around this

#

think of drawing the triangle on grid paper

#

your triangle's diagonal would go from (0,0) to (1,4), right?

rare grail
#

Yea

upper laurel
#

now if we want to draw the same angle, we would need another triangle with the same shape

#

that would mean the opposite side is 4 times longer than the adjacent side

#

(and is at a right angle to the adjacent side)

rare grail
#

So we are going to make a square?

#

🥲

upper laurel
#

commonly, a square has all of its sides be the same

#

however I am asking you to make something else

rare grail
upper laurel
#

do you have grid paper with you?

rare grail
#

Nop

#

🥲 I'm grade 7 so I don't need grid paper at school

upper laurel
#

do they allow you grid paper on the test?

upper laurel
#

then you need to have grid paper with you

#

this is what it is for

#

this time I will show you what it looks like on a grid

rare grail
#

👍👍

upper laurel
#

here is what the original triangle looks like, right?

rare grail
#

ye

upper laurel
#

now take a look at this length

#

now notice that I am drawing this line from (1,4) to (-3,5)

#

you can see it looks like the same sort of length but rotated 90 degrees, right?

rare grail
#

ye

upper laurel
#

so can you trust that this new green line is 4x longer than the original (1,4) red line?

rare grail
#

uhhhh idk ._.

upper laurel
#

take a look at it this way

#

I made the green line by starting at the red point (1,4) then going 4 left, 1 up

#

compare that to the red line, which was formed by going 1 right, 4 up

#

if you think about it, these two directions must be at 90 degrees to each other

#

do you see why?

rare grail
upper laurel
#

its more of that the green triangle is a 90-degree rotation of the red one

rare grail
upper laurel
#

here's the original green length

#

now if I make the green length 4x longer, it would now look like this

#

you can see all I did was copy-paste the same "4 left, 1 up" kind of line

rare grail
#

oh ok but now what?

upper laurel
#

now consider this triangle

#

notice that this triangle has the side from (0,0) to (1,4)

#

and the longer side that we talked about

upper laurel
upper laurel
upper laurel
#

so does it make sense that the opposite / adjacent for the green triangle is 4?

rare grail
#

ye

#

cus its js 16/4 right?

pastel vault
#

by similar triangles you can use the ratio of the horizontal distance of opp (16) and the vertical distance (4) of adj

rare grail
#

So how do we calculate the awnser

#

I already know the awnser is 8/17

#

Cus I got the awnser sheet

#

But I'm js want to know how

upper laurel
#

remember that original side from (0,0) to (1,4) isnt 4

#

now whats important about the red and green triangle is around here

#

we've established that both of the triangles have the same tan(x)

#

so does it make sense that the same angle x would be in both triangles?

rare grail
#

Ye

upper laurel
#

now sin(2x) = sin(180 - 2x), right?

rare grail
#

Ye

upper laurel
#

now take a look at this triangle

#

then, this angle

#

we have x = the red angle

#

2x = red angle + green angle

#

then 180 - 2x is?

rare grail
#

Uhhh .-.

#

●_● yea I rly have no idea

upper laurel
#

@rare grail 180 - 2x is the white angle

rare grail
#

Wdym by white angle

#

😭😭😭

upper laurel
#

@rare grail the angle that is part of the white triangle

rare grail
upper laurel
#

@rare grail

#

so the white angle is 180 - 2x

#

does that make sense?

rare grail
#

Ye

upper laurel
#

now looking at this white triangle,

#

how long is the side from (0,0) to (-15,8)?

rare grail
#

17

#

?

upper laurel
#

yep

#

so what would sin(180 - 2x) be, knowing the sides of the white triangle?

rare grail
#

Oh so 8/17 = sin x

#

And uh

upper laurel
#

sin(180 - 2x) = 8/17

#

and sin(2x) = sin(180 - 2x)

#

so sin(2x) = 8/17 too

#

so you figure out now that sin(2x) = 8/17 by drawing a version of 2x then sketching its sine

rare grail
#

Oh wow thanks a lot!

#

Thx for ur help

upper laurel
#

np

rare grail
#

.close

cedar kilnBOT
#
Channel closed

Closed by @rare grail

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vestal sandal
#

Can someone prove associativity for Zn brev

upper laurel
#

so for example 2 + 3 would be the first or second line except with (2 + 3) for k

#

using this, you can show (a + b) + c = a + (b + c) by just having those appear in for k in the definition, then using the integers's associativity axiom

cedar kilnBOT
#

@vestal sandal Has your question been resolved?

vestal sandal
#

Are you saying something like this

#

Could you please explain further @upper laurel

upper laurel
# vestal sandal

a bar = {x in Z | x - a = 0 (mod n)}
b bar = {x in Z | x - b = 0 (mod n)}
a bar + b bar = {x in Z | x - (a + b) = 0 (mod n)}

vestal sandal
#

isn't the first condition only true for something that is completely divisible

#

like 6 mod 2 is 0

#

n times a

#

where a is 0

#

how do we know any a or any b is completely divisible or not

#

and isnt k the remainder itself

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

vestal sandal
#

.reopen

cedar kilnBOT
#

vestal sandal
#

.close

cedar kilnBOT
#
Channel closed

Closed by @vestal sandal

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cloud creek
#

We can construct a sequence of integers by adding to each number twice the sum of the digits that compose it. For example, starting from 1000, we obtain:

1000 + 2(1+ 0 + 0 + 0) = 1002;
1002 + 2(1+ 0 + 0 + 2) = 1008;
1008 + 2(1+ 0 + 0 + 8) = 1026;
and so on.
How many starting numbers strictly lower than 2025 make it possible to reach the number 2025?

native heath
#

huh

#

that's interesting

sly swan
#

i dont understand

#

why'd u put the 2 zeroes in between

cloud creek
#

wdym

sly swan
#

i have no idea wtf this sequence is

cloud creek
#

look

#

suppose i take the number 2000

sly swan
#

yes

cloud creek
#

the integers that compose it are 2, 0 ,0 ,0

#

right?

sly swan
#

yes

native heath
#

id write code honestly

cloud creek
#

so therefore

native heath
#

well it's def not any of the even numbers

#

for what thats worth lol

cloud creek
cloud creek
native heath
cloud creek
#

oh wait yeah

cloud creek
#

no it isnt

#

its a normal question

native heath
#

okay then ill think about it lol

sly swan
#

whats the next number

cloud creek
#

look so i got 2000 +2(2+0+0+0)

sly swan
#

1026 + 2(1 + 0 + 2 + 6)

cloud creek
sly swan
#

we are adding 18

cloud creek
#

yeah

sly swan
#

1044 + 2(9)

#

why are we adding 18

#

I feel like we just constantly keep adding 18

#

then it becomes 36

#

then 18

#

18 18 36

#

funny pattern

cloud creek
#

we have to like add a limit of numbers to test

quartz coral
#

the process onward is just trial and error and testing each number

#

which sucks

cloud creek
#

@native heath

quartz coral
#

yes

cloud creek
#

in the sense test numbers that could theroitacaly work like from suppose 1900-2025

#

cuz suppose below 1900 it possibily wouldnt get 2025

#

making the trial and error easier

#

also factoring out even numbers

#

but

#

I made a code in python

#

def sequence(num):
num_str = str(num)
digit_sum = 0
for digit in num_str:
digit_sum += int(digit)
result = num + digit_sum * 2
return result

count = 0
for num in range(1, 2025):
if sequence(num) == 2025:
count += 1

print(count)

#

it gives me 4 as the answer

#

but ima have to proof check that

vivid tundra
#

that only does the operation once though

cloud creek
vivid tundra
#

it does the x' = x + 2Sum(x) once

#

in the original question you can do it more than once

cloud creek
vivid tundra
#

yea

cloud creek
#

so how could i fix it

quartz coral
#

it needs to be in loop till 2025

vivid tundra
#

you need to apply sequence over and over again until it reaches 2025 or surpasses it

cloud creek
#

im blanking can u like input the needed improvemnts in the code

#

like form my message

quartz coral
#

you need to make a while loop

#

so it loops over and over

#

till it reaches the value

#

of 2025

cloud creek
#

def sequence(num):
num_str = str(num)
digit_sum = 0
for digit in num_str:
digit_sum += int(digit)
result = num + digit_sum * 2
return result

count = 0
for num in range(1, 2025):
if sequence(num) == 2025:
count += 1
print (num)

print(count)

#

so like i make the while loop

#

uh

native heath
#

this is still not right i think

cloud creek
#

wait

#

def sequence(num):
num_str = str(num)
digit_sum = 0
for digit in num_str:
digit_sum += int(digit)
result = num + digit_sum * 2
return result

count = 0
for num in range(1, 2025):
current_num = num
while current_num < 2025:
current_num = sequence(current_num)
if current_num == 2025:
count += 1
print(num)
break

print(count)

#

i think it makes sense now

#

i got 48 as a new answer

vivid tundra
#

nice, got that too

#

(also bruteforce)

cloud creek
#

1847
1849
1853
1855
1859
1861
1865
1867
1871
1873
1879
1885
1887
1889
1891
1893
1895
1903
1905
1907
1911
1913
1919
1925
1927
1929
1931
1933
1935
1937
1939
1941
1943
1945
1951
1957
1959
1963
1965
1967
1971
1973
1977
1983
2001
2003
2007
2013

native heath
#

love bruteforce

vivid tundra
#

same, it's great

cloud creek
#

wait just to clarify bruteforece as in trial and error right?

vivid tundra
#

checking every possible number, yea

cloud creek
#

damn

#

howu do that so fast

vivid tundra
#

just did it in desmos
basically
n = [0...2024]
n -> n+2*s(n)
then count how many there were reached 2025

cloud creek
#

wait no there is an error

vivid tundra
#

,calc 2007 + 2*(2+0+0+7)

cloud creek
#

but ur saying u got 48 too

wraith daggerBOT
#

Result:

2025
vivid tundra
#

there it reached

vivid tundra
cloud creek
#

wait

#

but

#

some of the numbers dont work

#

like 1847

vivid tundra
#

it does?
why doesn't it work?

cloud creek
#

look 1847 + 2(1+8+4+7)

#

is not 2025

vivid tundra
#

,calc 1847 + 2*(1+8+4+7)

wraith daggerBOT
#

Result:

1887
vivid tundra
#

yea

#

but now do it again

cloud creek
#

wdym

vivid tundra
#

1887 + 2*(1+8+8+7)

#

and then again on that new number

cloud creek
#

but we have to find numebrs by themselves that reach 2025

#

not a sequence of them

vivid tundra
#

that was your original question no?

cloud creek
#

no

vivid tundra
#

doing the operation until you get 2025

cloud creek
#

no\

#

2013 works

#

it has to be indvual number

vivid tundra
#

but if you mean just do the operation once, then it becomes much easier

cedar kilnBOT
#

@cloud creek Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

eternal pollen
#

Is this the correct way to tackle this problem?

eternal pollen
twilit escarp
#

36-4c = 0

#

so yeah

#

rather use discriminant here

eternal pollen
#

It was more to see that I wasn't making a mistake

twilit escarp
#

you did not

eternal pollen
#

But that would be an acceptable way of showing how I found c on an exam?

twilit escarp
#

to me yes but depends teachers so that's why its better to use delta = 0 cuz its probably how they want you to do

eternal pollen
#

Fair

#

But thank you

#

Oh another problem

#

How do I "show" that the graph of P(x) = x³ + x on crosses the x axis once?

#

Like properly

#

Because this feels like a dumb way of doing it

#

Especially the +x part

#

.close

cedar kilnBOT
#
Channel closed

Closed by @eternal pollen

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

weary lintel
#

In a paper of English there are 5 questions such that the sum of marks is 30 and the marks for any question is not less than 2 and not more than 8. If the number of ways in which marks can be awards is a 3 digit number xyz then value of (x+y+z) is

weary lintel
#

i tried solving with princle of inclusion and exclusion but wasnt getting any furthur

dusk finch
#

I'd try subtracting one from each mark

weary lintel
#

can you elaborate

#

first what i did is satisfy the lower condition of marks greater than 2

dusk finch
# weary lintel can you elaborate

I mean like instead of working with the marks itself, works with the marks - 1. That way the bounds will become 1 <= mark - 1 <= 7, and the "mark - 1"s will sum to 25

#

the motivation behind this is having better bounds to work with

weary lintel
#

let me try

fair geyser
#

does it want the sums?

#

it's not clear

dusk finch
weary lintel
#

sum of the digits of the three digit number

#

which we get after distributing

fair geyser
#

oh it sums to 30 i get it

dusk finch
#

It's basically ⭐ & 📊

weary lintel
#

basically it wants the total permutations of how we can distribute 30

fair geyser
#

i don't know how it's solved

weary lintel
dusk finch
#

I think

dusk finch
fair geyser
#

usaullay there's only a few cases that are not allowed, and i can manually figure it out

dusk finch
#

hmm it shouldnt be that complicated

weary lintel
weary lintel
#

when 1 question gets marks greater than 8, when 2 gets , when 3 gets

dusk finch
#

oh i forgot about the upper bound condition

#

that makes it slightly more complicated

weary lintel
#

the lower bound condition is pretty easy to do it

dusk finch
#

ye

weary lintel
#

the main complication is the upper bound

fair geyser
#

maybe it should just be upside down

#

we can get 40, and we want 30

#

so there's 10 negative marks to distributte

#

yeah

dusk finch
#

combining inclusion exclusion with stars & bars also works

dusk finch
weary lintel
#

will using 3 additional dummy variables help?

#

like thats the no of questions which can get a max of 8

#

and then if i put the lower bound condition

fair geyser
#

the smallest amount is 10, and there's 20 marks that go anywhere to add up to 30
but also the highest amount is 40 and there's 10 marks that we can subtract

#

and 10 is less than 20 so maybe it's easy

#

but it's not by much

weary lintel
#

will multinomial theorm help

dusk finch
#

i got an answer by inclusion-exclusion

#

i will just brute force it to verify it in python

#

Yep, it's correct

weary lintel
#

what did you get

dusk finch
#

826

#

basically I shifted the marks down by 2, which means that im just trying to find solutions to
a1 + a2 + a3 + a4 + a5 = 20, where 0 <= ai < 7

#

so firstly we can ignore upper bound and directly apply ⭐ & 📊

#

that'll be 24 choose 4

fair geyser
#

yeah so my way is a bit easier

#

10 into 5 but 7+ is not allowed
3 into 5 = 35 wrong ways
times 5 for the choice of which one is 7+

#

1001 − 175 = 826

#

because 10 is less than 20, there's no way to get two variables out of bounds

weary lintel
#

can you elaborate it a bit

#

okay i am getting the same from multinomial theorm

fair geyser
#

that's the same thing probably

weary lintel
#

yea thanks a lot!

#

.close

cedar kilnBOT
#
Channel closed

Closed by @weary lintel

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dusk pike
#

Isn't the lower quartile supposed to be 2.25th value and higher 6.75th values?

fallen heath
#

,rotateccw

wraith daggerBOT
cedar kilnBOT
#

@dusk pike Has your question been resolved?

cedar kilnBOT
#

@dusk pike Has your question been resolved?

crimson sedge
cedar kilnBOT
#

@dusk pike Has your question been resolved?

cedar kilnBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dire heath
#

TRIGONOMETRY

I cannot find the value of x in the image.

uneven quartz
#

Lmao 'THEME'.

twilit bison
#

oh you can find similar triangles

dire heath
uneven quartz
#

how

twilit bison
#

the angle at R is shared

#

so triangle RST is similar to triangle RPS

dire heath
#

yeah, but we don't know the angles

#

nor the SP length

twilit bison
#

we can use a property of similar triangles

#

the ratio of the sides are the same

dire heath
#

yeah i see, but how do I like.. find TP?

twilit bison
#

we don't need to find TP

dire heath
#

is it like 17 - x?

twilit bison
#

yes

#

TP is not a side in our similar triangles

dire heath
#

what would be the formula for it? since it's a obtuse triangle?

twilit bison
#

it doesn't matter if it's obtuse, we just set the ratios of sides equal

#

you can say RS/RP = RT/RS

dire heath
#

so basically, 10/17 = X/10 ?

twilit bison
#

Yes

dire heath
#

so, 100 = 17x, 17x = 100/17, x = 5.9 ? Like this?

twilit bison
#

Yes 5.9 is correct

dire heath
#

alright, thanks!

#

.close

cedar kilnBOT
#
Channel closed

Closed by @dire heath

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

outer jackal
#

hello I have a very quick question (vaguely related to series and limits):

if I want to show that some a(n) is bigger than another b(n) for n → ∞

is this enough proof, is it legit?:
lim(a - b) = ∞
→ a(n) > b(n) for n → ∞

concrete example:

ln(n) ≤ √n at n → ∞
because
lim(√n - ln(n)) = ∞

sorry for terrible notation I wrote this from my phone
any help is appreciated

outer jackal
#

if anyone replies pls ping me

dull oxide
outer jackal
#

is it legit

#

does it definitely prove that one is bigger than the other

#

@dull oxide

cedar kilnBOT
outer jackal
# dull oxide !xy

I mean there's no problem that was given to me I was just thinking about this
but we can use the example:

prove that n^p > ln(n) as n → ∞ for any p > 0

#

sorry if the question is simple lol it's late in the night for me

dull oxide
#

there's some ambiguity to the way it is asked

outer jackal
#

how so

#

is it about the n → ∞

#

we can also say c ≤ n < ∞ where c is just some big number

#

sorry I'm not good at making math rigorous

dull oxide
#

Consider the two series $a_n=2^{-n}$ and $b_n=-a_n$. Every $a_n>b_n$, but they converge to $0$. Also, you could do $c_n=n+a_n$ and $d_n=n-a_n$, now, both series diverge, but still every $c_n>d_n$, and their difference converges to zero

wraith daggerBOT
outer jackal
#

🤔

#

thank you for taking the time to write this down but I don't see how it relates to what I asked

#

wait nevermind

#

I see how my question is inherently flawes

#

flawed*

#

thanks for the time

#

.close

cedar kilnBOT
#
Channel closed

Closed by @outer jackal

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

buoyant perch
#

i am so bad at python 😭 hopefully people can see what im trying to do with the loop but it just doesnt work at all, im wanting to work out the derived length of a group and i know i have to use a recursive function but i have literally never done that before any assistance would be appreciated

modern tide
#

Please ask math questions.

buoyant perch
#

is this not a math question?

#

the derived length is the number of times you have to take a commutator subgroup of a group G until it is the identity group and not all groups have a derived length

#

if im not meant to ask this here could i be directed to where i can ask it

crimson delta
#

is PermutationGroup(M) doing what you hope it does?

buoyant perch
#

i figured basic python is a part of maths so idk a single degree you do where you wouldnt be doing this

crimson delta
#

I would expect from the name that it gives you the group operating on the elements in the list

#

not the subgroup generated by those elements

#

but thats just guessing, havent checked the doc

buoyant perch
#

PermutationGroup(x,y) gives you the group x^i*y^j for arbitrary x and y

#

theres a better way of saying it

crimson delta
#

hmm

buoyant perch
#

but also derived length of S2 should be 1 but it always just gives me the highest number i put as the range -1

crimson delta
#

wait

#

the last two lines should be intended, no?

#

you are just running through the loop ten times and then generate Q once

buoyant perch
#

if i had
x = Permutation(1,2)
y = Permutation(2,3)
P = PermutationGroup(x,y) would just be S3

#

honest to god i have no idea how loops work that well but ill try to see if it should be indented

#

omg im so stupid

#

i knew it would be something like this

#

i just didnt indent Q = PermutationGroup(M) lmao

#

how do i stop a loop early btw

#

that should be something i know

crimson delta
#

break

buoyant perch
#

okay thank you

#

im glad i had the right idea and it was an indentation error i feel less stupid

#

.close

cedar kilnBOT
#
Channel closed

Closed by @buoyant perch

Use .reopen if this was a mistake.

cedar kilnBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ember kindle
#

hi so uhm i need help with this question. ive tried multiple times with the steps provided on the video and it still says im incorrect , to the point i got fed up and used ai . i put in ai answers and its still wrong .

frigid dust
#

!status

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
frigid dust
#

what was your answer, and how did you get there

ember kindle
digital cliff
#

walk through how you might try to do this one

ember kindle
digital cliff
#

do you know the formula for the circumference of a circle?

frigid dust
#

do you know the formula for the area of a cylinder?

odd verge
#

Sniped twicebreadpensive

ember kindle
#

not rlly

#

maths isnt my strongest subject so im not rlly caught up to people in my class either

twilit bison
#

the area of the label will be its height times the circumference

frigid dust
twilit bison
#

it's like height times length but the length is wrapped around

ember kindle
frigid dust
#

do you not have a textbook you learn out of?

ember kindle
#

no?

frigid dust
#

where are you getting these questions from?

odd verge
#

You should get one

ember kindle
#

its homework

#

set everyweek

frigid dust
#

homework from who?

twilit bison
#

why does that matter?

frigid dust
#

the people that give the homework dont give explanations of how to do it?

ember kindle
ember kindle
frigid dust
#

oh, thats shitty

#

did you at least watch the video though? 🙂

ember kindle
#

yeah i used the same calculations and everything but it still ays im wrong

glad peak
#

Did you make sure to give answer to 1 decimal place?

ember kindle
#

yes.

glad peak
#

And you did 100 * green area / total area?

ember kindle
glad peak
#

And what were your calculations for the areas?

glad peak
#

Just replace the numbers with what you have now, I just need to see what formula you used

ember kindle
#

yes i have no data of ANY calculations ive done so i dont have ANYTHING right now but a blank answer

digital cliff
#

but do you have recollection of what formula you were using?

ember kindle
#

i check the video every time for that

glad peak
#

Did it look something like 2 * pi * 11 * 5?

odd verge
#

Learn the concepts instead

ember kindle
#

ok

frigid dust
#

you need to know them by heart (not needing to have to look it up each time0

ember kindle
twilit bison
#

do you know the formula for the circumference of a circle?

frigid dust
#

but you only need to look it up in the video once, then write it down right?

twilit bison
#

it's 2pi*r

ember kindle
twilit bison
#

the label is like a rectangle wrapped around a circle

#

it has a height, and its width is the circumference

#

so the area is height * width or height * circumference

ember kindle
#

oh

#

i think id rather do it myself atp .

twilit bison
#

oh

#

yes i understand

ember kindle
#

okay i take that back

#

i wanna ask

#

@twilit bison for part b

#

is it 38%

#

idk how to do part a , its not on the video anyway

odd verge
#

khanacademy

odd verge
twilit bison
odd verge
#

Learn about surface area if the course is available

twilit bison
#

i think you'll need to do part a in order to do part b

ember kindle
#

on the video

twilit bison
#

would you like me to check your calculations?

ember kindle
#

Yes pls

#

first i did

#

2xpix24x5

i got 24 by adding 11 = 13 together

then i did pi r squared which gave 25pi

i added 240pi and 25 pi and 25 pi to get 290 pi .

thats 1 calculation done

then i did rx11x2 to get 110

then i did 110/290 to get 11/29 to get 37.9%

#

omds the multiplication marks

#

disappeared

twilit bison
#

try putting \ before *

ember kindle
#

ill just put an x