uhh parallelogram?
#help-13
ripe lance
thats complicated wait a min
i think so yea
but the parallelogram argument is basically additional
unless theres some easier way to prove it
ripe lance
yea
steel crest
So P' M' and D are less weird
ripe lance
yep
honestly i think one way or another we gonna prove this
just a matter of making it least complicated
steel crest
Yes
ripe lance
honestly i think one way or another we gonna prove this
like using parallelograms to simplify the probelm
steel crest
Yes
ripe lance
Yes
yea so i think i can sleep now
seeing as the problem is not that important
cuz we def can solve it if we want
steel crest
?
ripe lance
nah i just meant then i think i dont need to solve this question anymore, seeing as we can def solve it if we want
just a matter of chasing angles n stuff
steel crest
Maybe
ripe lance
hmm i posted on mathstack tho
steel crest
Ok
steel crest
I was thinking we could do something like
Line connecting OB+OE and OA+OC
No that is complicated
ripe lance
yep the parallelogram arg is false tho
steel crest
I got it
steel crest
Let P' be the midpoint of AC
ripe lance
it does cross through D, but how does this help with proving MNP is collinear
diagram to accompany 💀
steel crest
We can shrink everything by a factor of 2
ripe lance
We can shrink everything by a factor of 2
this is homethety?
steel crest
Yes
ripe lance
noice
steel crest
Let P' be the midpoint of AC ig MP' bisected OD we are done, right?
ripe lance
Let P' be the midpoint of AC ig MP' bisected OD we are done, right?
yes
u can just use MP tho
steel crest
So if I prove DP' is parallel to OM I am done, right?
ripe lance
yess
steel crest
Let DP' meet BE at K, if BKD = 90, I am done, right?
steel crest
Yes
steel crest
All we have left to show is that distance from M to OD is distance from P' to OD
steel crest
But just parralel is not enough
ripe lance
BKD=180-(EBC+ACB)
how does this imply its parallel wait a min
steel crest
EBC+ACB=90
ripe lance
All we have left to show is that distance from M to OD is distance from P' to OD
ahh so we end up with the same kind of stuff
steel crest
But in this case it is simple
Since AOP' = AOC/2 = (180-BOE)/2 = 90 - BOM
We have OM = AP' = DP'
ripe lance
AOP=AOC/2?
steel crest
Meant AOP'
ripe lance
AOP=AOC/2?
nah still how
steel crest
P' is midpoint of AC
ripe lance
EBC+ACB=90
also this how?
steel crest
AOC is isosceles
ripe lance
also this how?
this?
ripe lance
Since AOP' = AOC/2 = (180-BOE)/2 = 90 - BOM
as in distance of M and P from DO is the same right?
steel crest
Yes
ripe lance
this?
nvm i got it
all right then its easier to use MP to prove cuz DO is weird right?
ripe lance
yea
ripe lance
actually the original original question is this
steel crest
Yep
ripe lance
actually the original original question is this
so like in original context we just phantom the N instead
LOL
@steel crest can i discuss geo by dm u in future? (i promise i wont bother u)
steel crest
Sure
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worldly cradle
Prove that x = (y/2)
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Prove that x = (y/2)
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rancid dirge
hello
opaque root
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thin wagon
how do you figure out all the roots (including imaginary) of a function with degree greater than 2? its easy for deg 1 and deg 2 has a formula, but theres no formula for deg 3+
thin wagon
but im talking about anything more than 2, what about 5, 6, 7, 13, 19, 243?
proper mortar
these provably don't have a general formula beginning at 5
only thing you can do is either guess a root
if you hit, then you can long divide by the linear factor and reduce the degree by 1
or you approximate all the zeroes
thin wagon
guess an imaginary root, things can get really crazy like that, it could be anything
proper mortar
there are polynomials where it's impossible to write down the zeroes using only elementary operations and roots
thin wagon
its easy to approximate real zeros, but complex zeros, no
thin wagon
like?
thin wagon
oh ty
thin wagon
anything else
proper mortar
I don't think there is any satisfactory answer for this
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trail dune
Why do compressions happen when > 1 and stretches happen when < 1?
trail dune
Idek if I said it right
But if it's like 1/2, it stretches but if its 2 it compresses
Like what is the algebra behind that?
Is that coefficent being multiplied to all x values?
cedar kilnBOT
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trail dune
ashen shard
lets take your example
csc(x) and csc(4x)
take x=1
you get csc(1) and csc(4)
or generally for any function f(x)
and say f(4x)
if you take any value, say x=1
f(x) = f(1)
f(4x) = f(4)
f(4x) is a compresses version of f(x)
noble flame
Yes bassically the x values of f(x) are increasing faster
Same as sinx vs sin4x
You divide the period by 4 with sin4x because they get more compact, since f(x) increases at a faster rate according to the x axis
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tight totem
im slow or is there no viable correct answer for this
cedar kilnBOT
im slow or is there no viable correct answer for this
tight totem
if we take the ratio of the corresponding sides that arent the same??
10/12 = 0.83333
6/4 = 1.5
noble flame
if we take the ratio of the corresponding sides that arent the same??
10/12 = 0...
Try drawing both diagrams, AB≠PS because of the order
tight totem
so one gives 5/6 while the other gives 3/2
noble flame
so is it 6/4 = 3/2
Yeah you got it
tight totem
Yeah you got it
ok the last 2 final questions ill ask
exams in 15 mins
the one above is SAS similarity right?
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cold timber
A group of 10 people visited a bookstore. It is known that:
1. Each person bought exactly 3 books.
2. For every pair of individuals, there is at least one book that both have purchased.
What is the minimum number of people who could have bought the most-purchased book?
cedar kilnBOT
A group of 10 people visited a bookstore. It is known that:
1. Each perso...
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
cold timber
Ahhh?
golden raven
as a "stupid" solution would be everybody gets the exact same 3 books
cold timber
Yay
cold timber
Yeah
golden raven
okay lets see if we can work that out.
so it needs to be of the form
a b c
a ? ?
a ? ?
a ? ?
b ? ?
b ? ?
b ? ?
c ? ?
c ? ?
c ? ?
right?
golden raven
because out of the remaining 9 people
they must share one book with person 1 at least
and only 3 other people can have a book which the person has
and since there are 3 books
this is the only option
golden raven
I don’t think 4 work
yeah you are right it doesn't work out
radiant scaffold
and since there are 3 books
think this assumption is wrong?
golden raven
think this assumption is wrong?
no??
there are 3 books in person#1's hand
okay lets see if 5 works
cold timber
6 work, but how could I know every possible 5 don’t
golden raven
huh this is hard
i feel like 5 should work
oh yay i got it
1 2 4
1 2 4
2 3 5
2 3 5
1 3 6
1 3 6
4 5 6
1 5 7
2 6 7
3 4 7
5 works
out of curiosity, where did you get this problem from
@cold timber
cold timber
oh yay i got it
Thanks!
golden raven
is this an aops problem or smth
golden raven
do u do competition math
golden raven
oh ok 👍
cold timber
.close
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cold timber
Thanks
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urban abyss
guys can anyone exxplain to me what the direction ratios are im totally confused what are ratios and proportionality at this point.
urban abyss
guys can anyone exxplain to me what the direction ratios are im totally confused...
if possible explain in the terms of a simple line and coordinates and numbers not along vectors
<@&286206848099549185>
worldly chasm
!15min
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worldly chasm
guys can anyone exxplain to me what the direction ratios are im totally confused...
Can you give an example?
urban abyss
its not a question
its a
i mean im trying to understand it
what direction ratios are
worldly chasm
So the term "direction ratios" is not one I'm immediately familiar with. Based on the fact you're talking about vectors, I'm assuming the subject is linear algebra, which is a subject I consider myself quite familiar with, so it might be a case where it's a concept I know, but not by that name, hence I'm asking for an example or a definition
urban abyss
ahmm how do i explain actually from my books its not from vectors tho it is from coordinates in 3 dimensional space
worldly chasm
I'm sorry, what you're asking is just not clear to me. Can you please explain what you do know about this topic and ask a specific question?
urban abyss
ok wait
worldly chasm
I'm not trying to be a hard ass or anything, it's just that you seem to be assuming I understand the context
And I just don't, I'm not even sure what course you're taking.
worldly chasm
Ok, so I'm googling around and I have the following:
urban abyss
yea please show me
worldly chasm
The direction ratios refer to the coefficients of a vector given a particular basis.
So if we are using the basis i-hat, j-hat, and k-hat, then if v = i-hat + 3 j-hat - 2 k-hat then our direction ratios are (1, 3, -2)
urban abyss
hey stop stop
can u explain in terms of simple line tho
i dont wanna enter vectors
worldly chasm
So, when you say a "simple line," do you mean a special sort of line that carries the name "simple" as in something like "rational" number, or are you using it colloquially?
If colloquially, can you give me an example line?
urban abyss
a simple line defined on a plane (x,y,z) having direction cosines l,m,n and direction ratios a,b,c. getting to know what direction ratios are would single handedly be a great thing because im staring at this paragraph for hours
from origin to a point p
op(x,y,x)
worldly chasm
Ok, specifically a line which passes through the origin
urban abyss
yea
worldly chasm
So if a simple line passes through a point such as (3, 4, 5) then (3, 4, 5) are the direction ratios. Also any multiple thereof. So (6, 8, 10) and (1.5, 2, 2.5) are also direction ratios for this line
worldly chasm
Ah, they're kind of throwing you into this a little hard
@urban abyss do you understand direction cosines?
If not I'm happy to explain
urban abyss
Yes I understand direction cosines
worldly chasm
So let's think about the line segment in terms of its length. Let's say it has length r from the origin to the destination point (x,y,z)
From the Pythagorean theorem, we know r = √(x^2 + y^2 + z^2)
And from the definition of direction cosines we know that rl = x, rm = y, rn = z
urban abyss
Yes
urban abyss
For what
worldly chasm
For what?
urban abyss
Huh
worldly chasm
Ok so
I'm still trying to figure out what your confusion is
But you're not exactly being helpful here...
urban abyss
My confusion is about what direction ratios are or ratios and proportionality in general
worldly chasm
Because you're telling me you don't understand anything on that page, but when I take the time to explain the first part of that page, you're acting like you understood it this entire time?
worldly chasm
My confusion is about what direction ratios are or ratios and proportionality in...
Ok let's try another tactic maybe
2d lines have a slope
urban abyss
Ohh god this my habit, like I know things but regardless yea I knew those tho
worldly chasm
This slope is a ratio of rise over run
urban abyss
Ok let's try another tactic maybe
Ok
worldly chasm
Let's reframe though
Instead of rise over run, we instead use two values, rise over length and run over length
These are equivalent.
We just need two pieces of information to characterize the line
worldly chasm
Yes that's rise over run
So this method, of rise over run has a problem in that it cannot describe vertical lines
urban abyss
Yea
worldly chasm
Because that would involve dividing by zero
urban abyss
Tan 90
worldly chasm
We want to describe any line, so we reframe to do rise over length and run over length instead
So we get 1 and 0 for rise over length and run over length respectively for vertical lines for instance.
Now note something if you would
These are cosines, they will have values between -1 and 1
And further for any pair of two, we will have that they lie on a unit circle
worldly chasm
For instance, for a slope of 1, these will be 1/√2 and 1/√2
I'm doing a 2D case
To give you motivation why we do things like this for the 3d case
So what we have lost is a single value, but we have gained the following:
- The ability to describe any slope
- A way of viewing the pair of cosines as a pair of points on the unit circle
urban abyss
Wait but I'm not understanding circle thing here
worldly chasm
Sure no biggie
urban abyss
Can u just explain what direction ratios and how that relation is derived and also how proportionality had to do with it
obtuse whale
@urban abyss can you stfu and listen, ive been watching this conversation and you are being unhelpful af
urban abyss
Sorry
worldly chasm
So if we draw a line that goes through the origin and a unit circle, this line will pass through the unit circle in two places
If we take one of these points, (x, y) and perform y/x we will recover the slope
You get the same slope no matter which of the two points you select (can you see why?)
So we can go from a line to a pair of points on the unit circle this way
We are doing it this way, because once we go into higher numbers of dimensions this new method generalizes better
For 3 dimensions we map a line onto a pair of points on the unit sphere.
And if you deal with 4, 5, etc dimensions then you would map the line onto a pair of points on the 3-sphere and 4-sphere respectively.
(the hypersphere is called a 3-sphere because the surface is 3 dimensional, just like the surface of a regular sphere is 2 dimensional)
urban abyss
Yooo I am feeling dumb
worldly chasm
But the key take away is that it generalizes.
Which is why we have a shift of perspective
Don't feel like you have to immediately understand.
urban abyss
Continue
worldly chasm
That's it, the generalization from 2d to 3d is just generalizing from a point on a circle to a point on a sphere.
The direction ratios go from 2 to 3
urban abyss
Imm process this all wait
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urban abyss
<@1177227971048771605> Has your question been resolved?
processing
worldly chasm
@urban abyss in that case be sure to click on the ❌
urban abyss
i think i got it some i can take things from here
urban abyss
<@1177227971048771605> in that case be sure to click on the ❌
thanks bro
worldly chasm
You're very welcome
worldly chasm
Use .close
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pulsar sierra
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pulsar sierra
I'm a bit unsure about the kerL basis. Can somebody tell me if my work is correct?
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hollow trail
the kernel basis seems reasonable
i'm not sure how you got vectors in R^4 for the image basis, though
i also don't really know how you got 4x4 matrices from generally
pulsar sierra
the initial matrix has a row of zeros
so it's rank cant be 5
I went to the next biggest minor matrix (4x4) and its det=/=0
which means that rank(l)=4
which is also the dimension of Im(l)
no?
hollow trail
yes
pulsar sierra
so you take the columns of the biggest minor whose det /=0
correct me if I'm wrong
hollow trail
you need to use columns of the original matrix
pulsar sierra
ahhhh
right right right
thank you for pointing it out
this would be it, right?
hollow trail
well that's a matrix, but the columns of that matrix would be a basis
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marsh warren
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marsh warren
how do i put this into the form 3^x
marsh warren
3^-1?
fair geyser
yes
round geode
Put everything in terms of 3^something
So sqrt 3 write 3 to the half and 9 is 3 to the -2
Then you can add the exponents onto base 3
marsh warren
im a bit confused how do i write the 9 into apart of the power
fair geyser
(1/3)(1/sqrt(3)) = 3^−1 × 3 ^ −(1/2)
marsh warren
this is the question btw
round geode
Yes
marsh warren
is the answer 3^-1/2?
round geode
$\frac{1}{3\sqrt3} = \frac{1}{3 \cdot3^\frac{1}{2}} = \frac{1}{3^{1+\frac{1}{2}}}$
fair geyser
no it's not
wraith daggerBOT
Nyxzore
marsh warren
so would that be 3^-1.5?
twilit bison
yeah
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lament obsidian
hello
lament obsidian
I need help with linear algebra diganolization question
I don't understand the solution process at all. can anyone explain simply ?
worthy basalt
hi
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worthy basalt
what did u non understood....?
lament obsidian
what did u non understood....?
the general idea
like we wrote the Diganolization formula
then we got it in terms of A then I got lost
like why did we get it in terms of A and what is this summation ? our teacher told us two application of eigen values and vectors would be differential eq and to solve power of something
worthy basalt
i just know we can write A like that so we substituted A and got P , P-¹ out by distributive law and we added all matrices to get single one
and there is expansion of e^-x we replaced that with
lament obsidian
i just know we can write A like that so we substituted A and got P , P-¹ out by ...
okay imma check it again after some mins
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shell pendant
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trail dune
If graphing a cosecant curve do you guys draw dat sin line first?
trail dune
no
Do you think cosecant and secant are harder to interpret than a sin or cos curve?
Ehh actually it's not bad honestly
dusk goblet
Do you think cosecant and secant are harder to interpret than a sin or cos curve...
to interpret? no
to graph
trail dune
Word
dusk goblet
sure
trail dune
.solved
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mortal yarrow
is it a good idea to read about math on wikipedia?
cedar kilnBOT
is it a good idea to read about math on wikipedia?
quaint spear
honestly i would never do that
cedar kilnBOT
dire geode
is it a good idea to read about math on wikipedia?
Books 
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trail dune
Does one period of cosecant have two curves, one at the top and one at the bottom, and that is the curves that repeat?
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Does one period of cosecant have two curves, one at the top and one at the botto...
@trail dune Has your question been resolved?
sand osprey
Does one period of cosecant have two curves, one at the top and one at the botto...
Yes
lost kindle
For this question, I read online that the answer is 2^12. It seems that it's because for every student/time-zone, there are two options (left or right timezone). However, doesn't previous pairing constrain future ones? For example, if 2AM pairs with 3AM, then doesn't that mean 4AM must pair with 5AM (since 3AM is paired already), thus only one option?
celest flume
yeah, i would say there are two options as well
GMT pairs with GMT-1 or GMT+1
then the rest get fixed
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bleak wraith
Dumb question.
But i have this for example:
1
1 3
1 5 7
1 8 2 4
the total number of components in this tree is: 10
and it is in the row 4.
How can I generalized it?
For example, what is the total number of components in row n ?
tardy current
Are you asking how many elements are in a triangular thingy with height n?
are the numbers supposed to mean something or are they just numbers
bleak wraith
are the numbers supposed to mean something or are they just numbers
just numbers
tardy current
so in the nth row, there are n numbers
and then n-1 numbers in the (n-1)th row
and so on until you get to 1 number in the 1st row
you essentially want to find what n + (n-1) + (n-2) + ... + 2 + 1 =
bleak wraith
yea i was just being dumb
(n+1)n/2
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ornate rune
An object with a mass of 100g has been thrown upwards with a force of 300N. How high will the object reach
How do you solve this?
slate lintel
potential and kinetic energy is the easiest way i can think of
fair geyser
yeah that must be shortest
ornate rune
What would be the steps
fair geyser
avtually it doesn't looks sovleable
like you need to assume the time in seconds, like maybe it took 0.1s to do the throw
but what's the right number
ornate rune
Uh assume 0.3 ig
fair geyser
even 0.1s makes it go with the speed of an airplane
ornate rune
even 0.1s makes it go with the speed of an airplane
Wait so ig my solution isn't wrong after all
I got 900m/s as initial velocity lmao
fair geyser
i suppose maybe it wasn't hand thrown, maybe it was some explosion
ornate rune
i suppose maybe it wasn't hand thrown, maybe it was some explosion
Well I just thought of that problem
ornate rune
An object with a mass of 100g has been thrown upwards with a force of 300N. How ...
I mean I made this problem so ig there's lots of flaws in here
Just some random thoughts to try and solve
fair geyser
,calc 0.1(900)^2/2
wraith daggerBOT
Result:
40500
when it moves at 900 m/s it has this kinetic energy
it all gets converted into potential energy at the highest point
and then it equals 0.1 × height × 9.8
,calc 40500/0.1/9.8
wraith daggerBOT
Result:
41326.530612245
41 km
fair geyser
it's tiny, so air drag makes a lot of difference
ornate rune
Or maybe the duration of throw is the one wrong
fair geyser
i mean, it's light, if it's also very tiny, maybe it doesn't
coral jewel
plot twist: air resistance is not negligible
ornate rune
plot twist: air resistance is not negligible
Isn't it neglegible if the object is a ball
coral jewel
fair geyser
no, it's negligibe when it's heavy for the size
a paper ball is not
so you can't throw it far
or like ping pong ball
round geode
An object with a mass of 100g has been thrown upwards with a force of 300N. How ...
dont you need the time which the force was applied to the object for to work this out?
ornate rune
dont you need the time which the force was applied to the object for to work thi...
Idk
round geode
im pretty sure you do
ornate rune
no, it's negligibe when it's heavy for the size
Isn't 100g heavy enough
fair geyser
we don't know the size
coral jewel
plot twist: air resistance is not negligible
fyi this was a joke
ornate rune
fyi this was a joke
Oh lmao
round geode
because you can work out the objects acc to be 2990.2 m/s² but we have no way to determine the objects initial velocity as all our kinematic equations for initital velocity require time of movement and if we consider impulse momentum theorem it requires the time which force F was applied for
and we need initial velocity to determine the height that it will reach
ornate rune
and we need initial velocity to determine the height that it will reach
Can't u get initial velocity using F=ma
round geode
did you come up with this question for interest sake?
ornate rune
I tried 0.5 but the answer doesn't seem to be reasonable
ornate rune
did you come up with this question for interest sake?
Yea
0.01 seconds seems more reasonable but idk if 46 meters is realistic
round geode
you want a practical answer? Lets say I throw the object instantaneously and we use 0.01
$F_{net} \Delta t = m \Delta v$
wraith daggerBOT
Nyxzore
round geode
$(300-9.8(0.1))(0.01)= (0.1) (0-vi)$
wraith daggerBOT
Nyxzore
round geode
,w calc (300-9.8(0,1))(0.01)
wraith daggerBOT
round geode
$2.9902 = -0.1v_i$
wraith daggerBOT
Nyxzore
wraith daggerBOT
Requested by nyxzore
round geode
void sage
u can use f=ma
then solve for a
after that use kinetic and potentioal energy
to figure it out
round geode
did that already
void sage
so its done ?
round geode
thats how i got that acceleration
void sage
wht do u need help with ?
round geode
its not me that opened this channel
ornate rune
Idk would 45.92 meters be a reasonable answer
round geode
300N implies that the force is capable of accelerating 1kg at 300m.s^2
your object is accelerating at 2990.2 m/s²
so its going to go farely far
ornate rune
since its mass is small
Wouldn't it go farther when mass is smaller
ornate rune
and approx 46 meters is also not that huge of a number
I don't think 46 meters high in the air is small
void sage
but 300N is also not small
ornate rune
What's the average force a human can do
round geode
actually mass is irrelevant to projective motion
I could throw 2 different mass objects with the same vi and theyd reach the same height
royal loom
Actually mass is directly relevant to projective motion if you consider the relative mass compared to the air resistance
round geode
yes its different when including air resistance
but we're not including it here to my knowledge
ornate rune
Yea
ornate rune
Tho how do u solve this using kinetic energy
void sage
that effects how far will it go up
ornate rune
I don't think kinetic energy would be helpful here
round geode
youd need initial velocity
void sage
we can assume u = 0
round geode
what is u, final velocity?
round geode
we cant assume that
we know that v=0 since we want to work out maximum height
but u != 0 as the object is given an initial velocity when thrown
void sage
if it is thrown with 300N force
3000 will be acceleration
so i think 3000m/s can be assumed
as initial velocity
but other than that
no value of "u" is mentioned
royal loom
Likely we need to consider this as a stochastic process and use the brownian motion
this will let us ignore the lack of initial conditions
void sage
Likely we need to consider this as a stochastic process and use the brownian mot...
wht do half of those words mean
royal loom
What level of physics is this?
round geode
random unpredictable process and brownian motion is the seemingly random movement of paricles in fluids, put in laymans terms
hollow osprey
wht do u think
grad ?
void sage
9th grade ?
royal loom
Oh
hollow osprey
oh
void sage
in india
royal loom
Yeah in India we do this in like 5th grade
so I assumed that he was higher up
nvm then
void sage
common that was a steretype
royal loom
Not in Madras
royal loom
If you're on track to be advanced AIR then they let you skip
..
but anyways
We can get back to this
doubt
void sage
If you're on track to be advanced AIR then they let you skip
wait wot ?
u got good rank in jee advance ?
i suppose from this msg
royal loom
Yes... but it has not much to do with this physics doubt
void sage
no wait
void sage
Yes... but it has not much to do with this physics doubt
who...are u ?
if u did this while "g" years old
royal loom
"g" years old?
royal loom
I was not 9.8 years old in 5th grade maderchod
royal loom
Like I said
void sage
u skipped 5th grade ?
void sage
which grade u started in
royal loom
I started in 8th
void sage
so u did 9th syllabus
royal loom
Briefly
void sage
when u were 11 ?
royal loom
I did the 9th syllabus
@void sage Anyways what is your physics doubt about this problem?
void sage
what was ur year ?
void sage
while you were only 15?
hollup , let him cook now
royal loom
Like I said this is personal
void sage
what we gonna do
royal loom
I don't know if you have any abusive intentions
hollow osprey
hollup , let him cook now
sorry you are right
void sage
find ur house
void sage
i am child
royal loom
They treat me with salt and abuse
lyric narwhal
They treat me with salt and abuse
Are you gandhi?
lyric narwhal
Damn britishers
royal loom
I typically also only wear a loincloth and shawl
and one day I will become a great lawyer
When I am done with my OCI stint
lyric narwhal
Did you go to law school in iit madras?
rocky harness
Guys i think we are supposed to be helping chronny and not trolling him
royal loom
~~Guys i think we are supposed to be helping chronny and not trolling him~~
Who is trolling? I keep asking what the remaining doubt is
are they trolling me
rocky harness
Chronny what is your doubt
royal loom
Did you go to law school in iit madras?
No, I did JEE adv and then became an OCI to pursue english educational studies abroad
royal loom
Would someone who would be jealous admit that to myself?
I remember one man
Nawal
he threatened to shoot me
void sage
ayoo
lyric narwhal
No, I did JEE adv and then became an OCI to pursue english educational studies a...
You are studying English literature?
royal loom
You are studying English literature?
Among many things yes
lyric narwhal
Your parents must be disappointed
void sage
Your parents must be disappointed
shut up will ya
rocky harness
He got rank 6.9 + 4.20 = 11.1 chronny what is your doubt
royal loom
Your parents must be disappointed
They are consulates. Too busy to concern themselves with my studies
but I also study law, mathematics, physics, and diversature practices
so they are satisfied
lyric narwhal
Overachiever I see
void sage
They are consulates. Too busy to concern themselves with my studies
bro wot family u live in
this a next level of sharman ji ka ladka
lyric narwhal
You might have had a 0.01% chance of getting into the best college in the world, Lovely professional university
void sage
You might have had a 0.01% chance of getting into the best college in the world,...
it is pretty seletive
royal loom
bro wot family u live in
It would endanger me to say such things here
void sage
(rhetorical question)
royal loom
Ah
void sage
ur relatives must have reached absolute 0 when they saw ur results
lyric narwhal
What is your doubt, professional disco dancer
royal loom
I think he is trolling, he refuses to acknowledge the physics that he opened this channel for
I have asked
ornate rune
I think he is trolling, he refuses to acknowledge the physics that he opened thi...
what
void sage
i did not open this channel bruv
rocky harness
Chronny what is your doubt
lyric narwhal
An object with a mass of 100g has been thrown upwards with a force of 300N. How ...
You can't solve this without the length of the time period that the force was acting in
royal loom
I forgot, what grade level are we assuming of knowledge for this?
lyric narwhal
You need the impulse
ornate rune
I forgot, what grade level are we assuming of knowledge for this?
no particular level
worldly chasm
The question is incomplete
royal loom
This is my thoughts, if we are only assuming 9th grade
rocky harness
Chronny the force needs to be applied for some amount of time as you have stated about 0.3s
worldly chasm
300N force is not enough information to find the total kinetic energy imparted, which is required to find the maximum height
royal loom
We can complete the general case if we are allowed outside assumptions on the physical intent of the system..
hollow osprey
They are consulates. Too busy to concern themselves with my studies
holy sHIT what
void sage
We can complete the general case if we are allowed outside assumptions on the ph...
please speak 9th grade
celest flume
300N force is not enough information to find the total kinetic energy imparted, ...
or impulse, if the time interval is given
royal loom
or impulse, if the time interval is given
Wow, nice profile picture sir
royal loom
He must be a genius
ornate rune
300N force is not enough information to find the total kinetic energy imparted, ...
how would you find this using kinetic energy
worldly chasm
Kinetic energy = potential energy
rocky harness
Uh assume 0.3 ig
This is the time interval
celest flume
He must be a genius
he was in this server, he left tho
royal loom
E=mc^2+AI
ornate rune
This is the time interval
0.3 seems to be very big
celest flume
seems to make sense to me
ornate rune
i got like 40km with that
lyric narwhal
!xy
cedar kilnBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
royal loom
Many would say that .01 is plenty
rocky harness
He made it up
lyric narwhal
Many would say that .01 is plenty
I agree
rocky harness
Please read the thread
rocky harness
i got like 40km with that
So you know how to do it given a time interval....
lyric narwhal
Omni has been typing for a while
royal loom
We could try expressing the unit impulse as a fourier system, to account for potential air resistance wave in different fractals
to do the general case
worldly chasm
An analogy might be useful. Let's say you have a glass, and you tell me that a pitcher pours 30mL/sec. And you tell me you used this pitcher to put water into the glass. This glass is a cylinder with a diameter of 3cm
Now I ask you, "how high is the water in the glass?"
@ornate rune ^ hope this helps with understanding what the problem is, the issue is directly analogous, but using different units.
rocky harness
0.3 seems to be very big
Is your question why a time interval needs to be specified or how to do this particular problem
ornate rune
Is your question why a time interval needs to be specified or how to do this par...
how to do this
royal loom
Sir is crashing oout
worldly chasm
!original
cedar kilnBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
rocky harness
how to do this
How did you get 40km with a 0.3s time interval?
ornate rune
How did you get 40km with a 0.3s time interval?
300/100*10^-3 = 3000m/s^2
then multiply it by 0.3
900m/s velocity
900-9.8t = 0
solve for t
4500/49
then sub the t in 900t-1/2(9.8)t^2
45.92 meters (i just said 40km cuz i dont remember exactly the amount)
ornate rune
!original
well its the original question, the question is just some thought that came into my mind that i wanted to solve for interest sake
royal loom
Sir
The question that came into your mind as you say
Does not have enough information to solve
ornate rune
Does not have enough information to solve
yea i found that out later on
so i made assumptions
rocky harness
45.92 meters (i just said 40km cuz i dont remember exactly the amount)
This is okay. So what exactly is your question now? (You do realise you have solved the questiom you made)
worldly chasm
Kinetic energy lost due to gravity is exactly the same as the potential energy gained due to gravitational potential (neglecting air resistance)
So we can find work = energy, which is Force * distance. So we just need to know how far the ball travels when under the influence of the force.
Alternatively, we can use time instead, but converting between the two is a little tricky without calculus
And as I understand it, you're in the 9th grade
Anyway, because energy is conserved, the energy of the ball leaving the source of force is equal to the energy of the ball at the apex of the path. Assuming up and down movement.
So you have Fx = mgy so y = Fx/(mg)
(where "x" is the distance over which the force is applied)
ornate rune
Uh I think using kinetic and potential energy is more complicated
OK anyways thanks for the help
.close
cedar kilnBOT
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Available help channel!
glass mauve
cedar kilnBOT
celest flume
what is her most likely position when the roundabout rotates through an angle of 2pi?
glass mauve
They are asking what her rotation is after 35.5 pie radians
1 rotation is 2 pie radians
celest flume
so where will her shadow be after 2pi radians?
glass mauve
So to get the full rotations, it would be 35.5pie/2pie
Which gives us 17.75 rotations
17 rotations and an extra .75
celest flume
yeah you can do it that way
glass mauve
And 0.75 radian is 270 degrees
From her original position
But something I don’t understand is
How can her original position and 270 degrees both be position B
celest flume
.75 rotations not radians
glass mauve
.75 rotations not radians
Right mb
celest flume
there are two spots where the shadow on the wall is at B
for the same reason if you block a light with your hand in front of your eye vs with your arm all the way out, the light is still blocked
glass mauve
I mean i can understand that, but that didn’t really help in understand what i was asking
celest flume
if you mark the point on the roundabout where jenny is, its a similar story
jenny is currently closer to the sun, when she rotates 0.75 rotations, she is closer to the wall
glass mauve
Ow i think I understand, let me draw it for you and you tell me if am correct
Like this?
@celest flume
So it will still cast a shadow, but this time because she is closer to the wall the shadow will either be bigger or smaller (idk how shadows work xd)
crimson sedge
celest flume
if you write the polynomial as (x-z)(x-z*)(x-r)(x-r) and only look at the constant term, you can compare coefficients
celest flume
we can know b by expanding (x-r)^2
cedar kilnBOT
@crimson sedge Has your question been resolved?
trim wagon
how did they graph it
cedar kilnBOT
how did they graph it
trim wagon
15d + 40r >= 9000
the other equation in "the first two inequalities" is
i solved for x and it seems accurate enough but i still dont understand how they graph it
nvm i think i get it
.close
cedar kilnBOT
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Available help channel!
gloomy mica
can someone explain whats been done here?
cedar kilnBOT
can someone explain whats been done here?
gloomy mica
ping me pls
rocky harness
can someone explain whats been done here?
Sine addition formula
gloomy mica
whats that
rocky harness
$\sin (a+b)=\sin a\cos b + \cos a \sin b$
gloomy mica
sin(a+b)?
wraith daggerBOT
4573r01d|)d357r0y3r 45²
gloomy mica
oh
rocky harness
Yes
rocky harness
They moved xy to the other side and then squared
rocky harness
Then its just algebra
cedar kilnBOT
cedar kilnBOT
Available help channel!
gloomy mica
cedar kilnBOT
cedar kilnBOT
cedar kilnBOT
Available help channel!
marsh warren
cedar kilnBOT
normal cipher
What was the working
normal cipher
No cap the 5 looks like S
marsh warren
yeah my bad
normal cipher
Seems correct
marsh warren
wait i meant to write 33 for the denom on the last one
right?
i dont know hwy i put 22
normal cipher
15 i meant lol
normal cipher
My brain not braining
normal cipher
np
cedar kilnBOT
If you are done with this channel, please mark your problem as solved by typing .close
@marsh warren Has your question been resolved?
cedar kilnBOT
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Available help channel!
frail cobalt
Can anyone help me with integrals? They're very basic i just started learning them but I don't get it Idk what i am doing wrong
coral jewel
send your question
cedar kilnBOT
@frail cobalt Has your question been resolved?
gaunt meadow
cedar kilnBOT
gaunt meadow
Can anyone help me with this qst pls
twilit bison
what is the question?
to pick the answer that can possibly be true?
to pick the answer that is necessarily true?
versed jasper
the latter i'm assuming
twilit bison
none are necessarily true
gaunt meadow
Can you explain why pls
