#help-13
1 messages · Page 361 of 1
MæthIsAlwaysRight
yep
knowing the approximations is extremely useful
you can just eyball the limits then
yes and its 2in1 cuz if you can you them for trig identiites
anyway thanks for help have a nice christmas and a happy new year
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You too :)
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Let $H$ be a semi-group with neutral element $e$. Then there is
[ G := G(H) := {g \in H \mid \exists h \in H s.t. gh = hg = e }. ]
Show that $G$ is a group.$\$
So far I managed to show that the composition of two elements of $G$ is in $G$ again (closure).
Now I would like to show associativity, but I am stuck, and in the solution it just says that associativy follows immediately from $H$ which I don't see how. Any help would be cool!
𝔸dωn𝓲²s
Think about how the operation in G relates to the operation in H. Since H is a semigroup and associative
oh, he answered first
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can you help me with this
!msgdel
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I think it'll do it automatically
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acctually i didn't find the solution i typed solved just cus it seems that there was a problem with this channel
Are you able to find the cdf of max_n (U_n) with n just being some arbitrary integer less or equal to k?
How can you use this cdf to potentially solve 1?
@rigid dome Has your question been resolved?
i didn't get you
could you elaborate ?
Let K be a random variable defined as K = max_n (U_n). If K is less than k then this is equivalent to U_1, U_2 , ..., U_n all being less than k
If you assume each U is independent of each other how could you derive the distribution for K?
i.e. calculating P(K<k)
If you're completely clueless to this then you could also look up ordered variables on the web
*order statistics
U_n are not independent of each other
U_1 , U_2, ..., U_n aren't independent of each other?
What's their relation?
the only thing that is given is that they have the same distribution
If they're dependent but we aren't given a joint distribution then we can't solve the problem
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✅
i see got you, then there is a mistake in the exercise
Often those who make these problems are just a little lazy and leave that detail out, because it's usually always taken for granted
but i still didn't get how it will lead to the solution 😅
Try applying the rule P(A n B) = P(A|B)P(B) and formulate it in a possible way that could make use of this
ok i'll try with it, thank you so muchhh
(Using this method to solve the problem you'd have to do this recursively, about k times or something, for it to work)
you're referring to this formula right?
Yup that's right
I will also recommend looking at the Wikipedia page on order statistics since the first problem is basically just a case of this
Could give you some hints, even tho there aren't any super good explanations of the formulas there
thank you so much i just checked it yeah it already gave me an idea on how it could be solved. thank you so much 🙏
np
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help me to prove .
have you seen eigenstuff ?
What property does the eigenvalues of T have?
What's eigenstuff?
eigenvalues eigenvectors, was writing lazily
Oh should have been able to guess that. Thought it was some ytber for a sec
Well there’s eigenchris 
Learned topology in 5 min from that guy
im sorry i dont understand
why eigen here
what do you mean
to prove invertible we have rank n =n or ker={0}or dim !=0 right
There's a ton of other criteria you know
what can you help me
What does it mean that det(T - sqrt(2)I) = 0 ?
no invertible
Regarding eigenvalues/vectors
why eigen here
Well that looks a lot like the characteristic poly of A yk
Except instead of x we plugged in sqrt(2)
To find the elements of kerT you're basically solving for x in Tx = 0 right
You can rewrite this as Tx = lambda x with lambda equal to zero
Thus if ker T contains a nonzero element it must have an eigenvalue equal to zero
What can you then say about the eigenvalues if T was invertible?
@cosmic umbra Has your question been resolved?
Yeah i guess you don’t need to mention eigenvalues directly if you don’t want to @cosmic umbra
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You multiplied by 2
2(sqrt(z-3)-1)=2
expanding the bracket
the 2 gets distributed
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[
\lim_{x \to +\infty} \left( \sqrt{x^2 + 3x} - \sqrt{x^2 + x} \right)^x
]
maxy
How can i solve this with taylor?
@pine brook Has your question been resolved?
Ok so I should know this but ngl I'm kinda struggling too. Have you tried Taylor expanding the first term with anchor point at sqrt (x^2 + x) @pine brook ?
You will then get a power series with z = 2x
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Why does I(this is an i not an L) disappear?
So its cancels out… like 1-1?
it cancels out like $2 * 2^{-1} = 1$
ashy!
and $1 * x = x$
ashy!
type .close
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Hello, I need help with understanding a question in a math textbook regarding the set of all elements which aren’t an element of themselves:
It’s question 5
I don’t understand how one can define x as E since that breaks the rule that builds the set
Since E contains itself
So I don’t understand how that invalidates the existence of the set containing all elements which aren’t an element of themselves
,rccw
Sa l'aire compliqué
Is it because since a set is defined only by its elements, the property that all elements of a set have in common doesn’t apply to the set itself, which is the cause of the paradox in the case of “the set which contains all elements which don’t include themselves”?
Ah tu parles français?
L1
ah sa doit etre francais moi chui au quebec
Oui, mais l’anglais me va aussi
non jveut dire L1 sa doit etre un systeme francais et non quebecois parce que jen ai jamais entendu parler
De la théorie des ensembles?
Ah ok
en se moment je suis au cegep, on a fait les dérivées, quand même assez interessant
Nous on a fait ça en terminale
terminale?
Oui
sa veut dire quoi
Last year of high school
ah wow
🙂
bon le system francais est plus en avance que celui quebecois
j'aimerais visiter la france une journée, pas pour la tour eiffel mais vraiment pour voir les différences culturelles entre les deux pays
ah bon moi chui pas rendu la dans mon acheminement mathématique, du coup je te souhaite bonne chance et salut
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Hello, I can't seem to figure out where I'm going wrong with this question (I'm trying to get from RHS to LHS)
wait why not?
because you're taking out a 2 per factor
2 * 2 isn't 2 * (1 * 1)
ohhh
i was treating it as if it was an addition
but with multiplcation i would have to take out 2^n not just 2
yes that makes it work, thanks!
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Nine sixteenths two thirds is
What is that?
Please don't occupy multiple help channels.
I also don't know what the question here is 
is this nine sixteenths times two thirds?
nine sixteenths plus two thirds?
what are you asking?? 
I can't read... Polish I think this is?
well uh, I don't exactly feel compelled to 
may I ask if you could state your original question more precisely?
🤣
looks like some sort of game show
hiii lilith
without further context i would assume it means something like "nine sixteenths of two thirds" which would correspond to multiplying them
english
If it is then you multiply 9/16 by 3/2
is this like a game show?
No
Rioke
If it is (9/16)/(2/3)
Then you multiply by the inverse of the bottom fraction
so now it's (9/16) X (3/2)
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Dude I am trying to help you
👺
I just don’t understand
When you are dividing by a number less than 1 youre making the number bigger
Like 1 divided by 0.5
1/0.5
1/(1/2)
so instead you multiply by the inverse of the fraction
But both lower than 1?
,calc 0.6/0.6
Result:
1
Bo…
,calc (9/16)/(2/3)
Result:
0.84375
,calc (9/16)*(3/2)
Result:
0.84375
See
,calc 9/16
Result:
0.5625
,calc 3/2
Result:
1.5
Do you see how it flips when you multiply by the inverse of the fraction
okey
does it make sense now
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I've done the first two parts. I don't know how to approach the third part.
plug in t=1 for the 2 above integrals, also notice 1! = 1, 2! = 2, 3! = 6
ohhh because LHS of eq2 is the derivative of LHS of eq1
and further, LHS of eq3 is the derivative of LHS of eq2
ok then it can be solved from here, if t=1
this might be a dumb question, but how do you know to plug in t=1? i'm really bad at maths
1+tx = 1+x when t=?
@ancient ore Has your question been resolved?
You want the bottom integral to match the above integrals so you do what riemann said
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"an" is a unit vector. does last sentence mean we scaled "an" vector with |b|*cos(theta) to get the desired vector?
Yes it does
(This is known as vector projection)
if it wasn't projected onto a unit vector,
would that change anything in the equation?
The projection of some vector b unto another vector a would still involve the unit vector for a.
If it wasn't a unit vector (call it a), you would end with the new vector scaled by |a|
a.b=|a||b|*cos(theta)
Yh
to cancel out we would have to divide right?
Yep
|b|*cos(theta) = a.b/|a| where left side is length of projected matrix?
aah my brain fried
nvm i give up
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how does this proof of mine look?
lmk if you spot any glaring mistakes 
looks fine
I guess there's some nitpick to be done if you take boundary points, in the case of manifolds with boundary


bleh 
but I don't think the proof really changes at all in that case
isn’t this just immediate from the definition? i didn’t read the proof and assumed it was right
I think ISM just does those by taking charts in the half-plane right
idk, nothing is immediate for me 
ic
neat
the exercise tells you that it doesn’t matter what chart you pick
smooth functions are smooth in every atlas chart
I noticed that it was like, very close to the def of smoothness
but the main thing I see missing is the F(U') \subseteq V'
I didn't conclude that during my proof
well you can just restrict U’ if F(u) is outside V’ for u in U’
everything is so nice in smooth manifolds
because you can just restrict to a smaller subset
so smoothness doesn't depend on what charts we use
yeah and the proof will pretty much use the composition of smooth functions being smooth
like not even reading your proof too hard i bet that’s one of the only things needed
I feel like the definitions are so... bulky?
like there's just so many moving parts 
no like, all the smooth manifolds defs I've ran into so far take like
3 sentences to state

so when I need to prove smth, there's a lot to do
geometric ideas can be hard to make precise and sometimes result in very verbose mathematical statements
because the moral is much shorter
right, I get the feeling that a large part of the definitions are just there for technical reasons
do you know vakil
the author, or his AG book?
the author
sure I do
vakil came to give talk at my university and one of the main points that he really wanted to hammer home is that people prove things before they come up with precise definitions sometimes
which was a cool concept
he gave this idea when he was talking about “bott periodicity in AG” which they just released a paper about
but the whole point was about talking about what it should “look like” first and only after doing that coming up with “good” definitions
does he mean like, people will try to prove smth based on a moral defn, and then slowly add conditions to the defns of the objects in order to make the proof work?
yeah
I see 
but this is true of many definitions in math and you should be looking for morals in all of them
and especially something so closely related to physics like manifold theory
this is part of why history of math is such a good subject to pair with the math itself
like it can really put your definitions into context
not that you would have to do that
just knowing some sort of morals is good enough
gotcha 
hold on, I gotta go shovel snow 
if you have more to say, say it here and I'll be back in 15min to read it
hats it
that’s
okie dokie
I'll close the channel then
thank you derivada and smay for the help and the insights!
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http://www.cs.rpi.edu/~magdon/courses/cf/notes/american.pdf
I need help understanding the proof of Exercise 4.1 here. There is some subtlety once it introduces the expectation under a measure that loses me.
in particular, it is not clear to me what we are integrating over in there
like I can see that our probability space is the space of paths, but are the variables functions from paths to reals?
something about it isn't clicking
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@frozen spindle Has your question been resolved?
@frozen spindle Has your question been resolved?
Try uhhhh #advanced-probability
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is it possible to find a way to go from two points by only moving in certain increments? ex: moving 1 away from where you started, but you can only iterate by 0.3 units
in a 2-dimensional space?
yes
well then intuitively yes
if you're closer than .3 you can get there in 2 steps
yeah ik cuz you'd just make an isosceles triangle
yeah
i should ask is there a formula or something for it
well thats what i meant to ask rather
for what, the least number of steps?
i think you can most likely achieve a minimum if you just go directly towards your destination
i guess so, i've just realized if it's less than the distance you can just b-line it and then make an isosceles triangle
let me visualize it rq
it doesn't feel optimal to do 3 steps
if you have 0.3 unit-long steps to go 1 unit total then if you do the simple method you have 5 steps total
but 4 is possible
exactly
so is there a way to find the angles needed to go 4 units
wait nvm i see it all
im overcomplicating it
.solved
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The 1st image is the question, 2nd image is the answer from this book to the question. I am confused at the answer, why the n(-4/n) becomes 4, why no negative?
looks like a mistake
@dry pawn Has your question been resolved?
I see, thanks
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https://en.m.wikipedia.org/wiki/Heptadecagon
do anyone know how they "solved for X"?
I thought that was the part the derivation should be explaining
💀
@untold lichen Has your question been resolved?
You will probably want to consult one of the references
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chatgpt is giving me this:
but on wikipedia I'm seeing this:
so it would seem that chatgpt is giving me the negation of the actual formula on wikipedia?
dont trust chatgpt.
I'm just trying to confirm it's formula is incorrect, and there isn't something I'm not seeing
I believe here ${\bf r_{21}}={\bf r}_2-{\bf r}_1$
derivada.schwarziana
while $\widehat {\bf r_{21}} = \dfrac{{\bf r_{21}}}{|{\bf r_{21}}|}$
derivada.schwarziana
also
, can be an useful tool at times but only if you know enough to be able to fact-check its answers. LLMs aren't well suited for mathematical reasoning since they're basically text prediction with a lot of resources lol
I'm just using it to guide myself, and fact checking everything it says, which is why I'm here, because it looks to be exactly the same as the second form given on wikipedia, given r21 = r2 - r1, but the answer is it's negation, so the F12 from chatgpt is incorrect?
Reading books is a much better guide because they don't waste your time being wrong
that's okay
I think it depends on the order convention of the indices
if you wanna check chatgpts calculation post the whole calculation not only the result.
this would be a force vector pointing from r_1 to r_2, so if F_{21} is the gravitation force that body #2 exerts on body #1 then that's fine
if not then it's the other way around. boils down to convention
I was asking about it's recreation of the formula, but I'll definitely keep that in mind in future
.resolve
thank you!
(and admittedly I'm not a physicist so I'm rusty on this lol)
the command is .close
.close
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for
(Delta t)^2
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a child has 6 pockets and 5 coins and in how many ways can he put the coins into the pockets
i wanna understand the logic
the coins are all the same i assumev
There are 5 coins and 6 pockets
The key to understanding the logic behind combinations is to first understand the logic behind permutations
this doesnt have much to do with combinations i believe
can 1 pocket contain multiple coins
if the coins are identical, where there is no order then wouldnt that be a combination?
if yes, then ⭐ 📊
Stars and Bar theorem?
Yay someone understood it
That is combinatorics
combinations are the binomial coefficients
Combination is like C(2,3) right
ye
Is this question dealing with that?
like wouldnt it be similar to saying if you have 6 positions and 5 people, how many different ways can you position those people
we need answer to this
@lilac flame
ye
There are 5 coins and 6 pockets
*****|||||
you only need 5 seperators
the pockets will be between them
e.g.
* | * * | * | | * |
this is similar to a problem I've encountered before dealing with functional antennas lol
op asks question and then just dips 
this would mean
1st pocket has 1 coin
2nd pocket has 2 coins
3rd pocket has 1 coin
4th pocket has 0 coins
5th pocket has 1 coin
6th pocket has 0 coins
He got scared by 4 helper tryna help him
Let's just finish it anyway lol
soo we are essentially just counting the number of strings with 5 coins (*) and 5 seperators (|)
there are 10 total characters in such string
and we need to choose 5 characters to be the seperators
hence 10 choose 5
this is where the choice function comes in
and that should be it
this is not the way
The following error occured while calculating:
Error: Undefined function C
,w 10 choose 5
252
this is the way
⭐ & 📊
,calc combinations(10,5)
Result:
252
question its the same as having aaaaabbbbb and finding how many ways you can like scramble them right
yep
so yea 10!/((5!)(5!)) would also work
!noans 
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which is the same as 10 choose 5
!nosols
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Wait those two are different
reminds me of this question I had did a while back that I was struggling with lol
still dont quite understand the solution
of this or of mistav's problem?
oh wait no nvm it make sense looking at it again
this one
mistav still hasnt come back lol
i skipped combinatorics and probability so im not good at it
I havent taken a class in it either so I've been trying to read this book on my own
I think its a really intersting book
has some pretty intriguing questions and examples
how do you translate no two defectives are consecutive
I think that you could start by arranging the functional ones
and then there will be gaps
in each gap, you can place at most 1 defective
and this way, you will ensure that no defectives will be consecutive
It means this is not possible | * | ** | * | * where * is defective and | is functional
is it n - m + 1 choose m btw?
yep
@lilac flame Has your question been resolved?
what if it said no three consecutive
Then | * | ** | * | * would be possible and that means instead of allowing only one non-functional position between each bar there can be two, which in turns double the number of positions you can have for non-functional antennas, so it'd be
C(2(n-m+1), m)
@dusk finch does this sound right
sounds right
thanks
oh awesome ty
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can someone help me 108
You want to minimize the distance from some general point (x,y,z) to (4,2,0), thus you'd be minimizing the distance formula sqrt((x-4)^2 + (y-2)^2 + z^2) given the constraint z^2 = x^2 + y^2
what do you mean sqrt((x-4)^2 + (y-2)^2 + z^2) you mean the answer should be small as much as posible ??
Minimize means that, indeed
This is an optimization problem and with these problems the goal is to identify your contraint function and your objective function. Here the constraint function is stated in the question but the objective function, the function we wish to minimize or maximize is given through words. It says we want to find the closest point to (4,2,0) given that we are constrained to our constraint function $z^2 = x^2 + y^2$. So out of all points that lie on this cone we want to find the point closest to (4,2,0), meaning we need to find the point that has the minimum distance to (4,2,0). We find the distance between points using the distance formula $\sqrt{(x-{x_o})^2 + (y-{y_o})^2 + (z-{z_o})^2}$ where $(x_0, y_0, z_0) = (4,2,0)$. If we want to find the closest point then we must find (x,y,z) that minimizes this distance formula. Think back to finding the minimum of a function in early calc 1 by seting the first derivative to 0 and applying the first derivative test
Olivia
Here with multivariable functions you might use something like lagrange multipliers
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a boy has 6 pockets and 5 coins in how many ways can he put the coins in his pockets, answer is 6^5 i wanna understand the logic
first coin can go to 6 different pockets
i assume they did first coin can go into 6 pockets and so on, but whats wrong with the approach of first pocket can get 5 coins
up here
oh yeah sorry i went to eat lunch mb
and so on
think of it like this
yeah i understood that
" but whats wrong with the approach of first pocket can get 5 coins" whats wrong with this
its not wrong it just takes too long to go case by case
the second pocket also can get 5 coins
and the other ones too
then umd have to do case 4 coins 1 coin
then 3 2
you read that?
Yep
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ABC is an equilateral triangle
how to show BD+CD=AD
@hollow kiln Has your question been resolved?
<@&286206848099549185>
Use the law of cosines.
Firstly, you can infer that angle ADB = angle ACB = 60 deg and that angle ADC = angle ABC = 60 deg (why?)
AB = AC
Use law of cosines on triangle ADB and triangle ADC with the angles ADB and ADC which are 60 deg each as deduced earlier.
You can easily eliminate other variables so that only AD, BD and CD are left in the system of equations.
You'll be left with $a^2 - c^2 = ab - bc$ which implies $(a+c)(a-c) = b(a-c)$ and so $(a+c) = b$ where a, b and c are BD, AD and CD respectively.
anshul6368
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a^(2n+1) = a - ab^(2n)
a - ab^(2n) + b^(2n+1) = 1
a = (1 - b^(2n+1))/(1-b^(2n))
I found a in terms of b and n. Does this mean that ive found the solutions?
You could instead say $a^{2n}=x; b^{2n}=y$. Then $x+y=1, ax+by=1$
solve for x and y now
and then n
think about that second equation again
ƒ( wai ina teacup)= I don't know
ok thanks
why does my solution not work?
it says there are infinite solutions and i have given the expression for a in terms of any b and n
but are there infinitely many solutions?
yeah
presumably you are supposed to solve for a,b for a fixed n
That's when a,b,x,y are all unrelated
But here a^n=x
Same for b and y
oh
Wdym
Are you supposed to solve them simultaneously?
yeah
so find x and y in terms of n
for example x = 5^n + n or something
Is that x and y thing even necessary then?
Not rly
ok
I think there are no answers apart from a=1 and b=0 or vice versa
Because suppose either of them are not 0
yeah
a^2n is a positive value as well as b^2n
yeah
a^(2n+1)<a^2n since a<1
yea
Same with b
U got it?
yep thanks
K
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i need to study the variations of f
but first i wanted to prove that whats inside the ln is positive(or at least what the domain is so that it stays positive)
aaand i cant quite get my hand on it
u=e^x substitution
@crimson sedge Has your question been resolved?
god im so stupid
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hey
sorry about last time my internet was awful
i wanted to ask about injective and surjective functions
can someone please explain them to me? all i get on google are those stupid circles with arrows...
like... the two seem VERY similar to me
from the explanations that i read
i am here @mighty shuttle
okayy
Essentially in a one one function, each output hasa. a unique input
okay so no more and no less than one input
wai you need to be more precise
cuz it can be 1 with different inputs
injective and surjective depend hugely on domain and codomain
how so
Technically speaking a functions is said to be one -one , if an element in the codomain has at most one pre-image in the domain
okay
and surjective is really similar... or is it not?
cuz the way we prove it
what
what's your defn
nvm
nothing
each y in the codomain has an x in the domain
each y in the co domain has ateast one x in the domain

and with injective, it has just one?
one x in the domain?
is that the difference?
at most one x
cool, then can I quiz you to ensure you've understood?
sure
define $f(x) to be -x^2 , if x<0, and x^2 if x \geq 0$
CUPS
okay hmmm
This is a bit hard, so don't be discouraged
awesome!
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Best way to go about this
Imo
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how do I differentiate arctanx with respect to tanx? (for xε(-π/2,π/2))
do you know what a derivative of a function with respect to another function means in general
yes, but im not familiar on how to approach problems that require to take the derivatewith respect to a whole function
sure, but we'll write it a bit differently
Let $f(x)=\arctan(x)$ and $y(x)=\tan(x)$. Then $$\dv{f}{y}=\dv{f}{x}\dv{x}{y}$$
kheerii
does this make sense
if we treat it like a fraction too, yes
this is precisely what the chain rule says
$\dv{x}{y}=\frac1{\dv{y}{x}}$
kheerii
yes
in general $\dv{y}{x}=\frac{\dv{y}{t}}{\dv{x}{t}}$ where $x$ and $y$ are functions of another variable $t$
kheerii
in the task, it also says: consider known the derivative of tanx. (doesnt say anything about the derivative of arctanx with respect to x) With the help of the definition of the derivative find d/dy(arctanx)
does it want me to calculate in some other way?
@lyric narwhal
@weary thistle Has your question been resolved?
@weary thistle Has your question been resolved?
@weary thistle Has your question been resolved?
<@&286206848099549185>
it wants me to find
in the task, it also says: consider known the derivative of tanx. (doesnt say anything about the derivative of arctanx with respect to x) With the help of the definition of the derivative find d/dy(arctanx)
okay, so you know the derivative of tanx is (secx)^2
if y = tanx, then arctan(y) = arctan(tan(x)) = x
(assuming that x has an appropriate domain, which it does here)
oh yes
actually wait sorry i did that backwards, let y = arctanx, then tan(y) = tan(arctanx) = x
you ultimately want to find y'
no y=tanx
implicitly differentiate and use your known tan derivative and chain rule
it says here
okay this problem is written very poorly, d/dy (arctanx) is clearly 0
are you meant to find the derivative of arctanx?
like d/dx
No
ohh
how am i supposed to do that
Look
Neil if I may
then you're looking for this
Xtra write x in respect of y
Saying that x equals arctan y
Plug that into arctan x
Then you have the arctan of arctan of y
Then differentiate with respect to y
It should be 1/1+(arctany)^2 times 1/1+y^2
If not check wolframalpha
this is what the task is saying
It might just be another way to get the same answer
what does it mean "definition of derivative?"
also it doesnt say consider known the derivative of arctanx like it does for tanx
so how will i say that d/dx(arctanx)=1/1+x^2
maybe it wants me to do it some other way around?
It looks like I’m right I googled it
i know, but is there any othe rway?
Honestly I don’t know I’d have to think about it
Would it matter if you did it differently?
i dont know, thats the thing haha
thanks. You can DM me if you want. If you dont think anything else, thats ok. im tired of this problem, been looking it for 2 days now. im closing this channel, and plz let me know if anything
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Is the ans to 6÷2 (1+2)... equal to 9 or 1 ?
9
But am getting 1 from even my sharp calculator
6/2*3
the parentheses say that you do 1+2 first, and then you do left to right
Yes
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Why isn't the first one correct but the second one is?
Btw how do we graph implicit differentiation in desmos?
I do not think there is a way to do it. But I could be wrong.
,w diff cos(xy(x))

Use y' instead of dy/dx
we want to find dy/dx of xy=sin^-1(2x)
ooh
appears I'm correct
are these results equal?
For some reason the book does it this way 
,w diff arcsin2x/x
def not 
Unless if I'm graphing these implicit equations wrong
I'm so conflicted
Do I believe myself and wolframe or the book 💀
,w diff arcsin2x/x

This is the book's answer btw
Hmm okay
I think this is correct
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Honestly it's pretty weird I think what would've been most helpful would've been to be able to graph the equations
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Same as this
No that's the alternative forms for when you divide throughout by x
All three answers are literally the same.
They just have different styles.
Cosxy = √{1-sin²(xy)}
@fallen trail
OOOOOOOOOOOHH
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ty
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Oh
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Question: is there an intuitive way to understand why the chain rule works for find the derivative and integral of a function: like x² for example. Why is it that the derivative is 2x and the integral is 1/3x² ?
Like many things in mathematics, these are just results of applying the definition of something; here the definition of a derivative which is essentially a limit.
Applying this definition leads to results such as power, product, chain rule etc. or specifically that derivative.
[ f'(x) := \lim_{h \to 0} \frac{f(x+h)-f(x)}{h} ]
So with $f(x) = x^2$ you'd have
[ f'(x) = \lim_{h \to 0} \frac{(x+h)^2-x^2}{h} ]
and if you calculate that limit you get $f'(x) = 2x.$
𝔸dωn𝓲²s
The answer is gonna depend on what's intuitive for you
So would it be difficult to make a logical conclusion that doesn't rely on proofs?
Hmm I suppose so
I have researched many ways to interpret integrals and derivatives
derivates fundamentally I roughly understand
If you don't understand the algebraic steps then you're not gonna have a good time in calculus and beyond
If you yearn for greater understanding, I would try to analyze the definition rather? Why would someone define exactly like that a derivative and what is the intution behind that, instead of a specific example that is really just computation.
The algebra isn't a problem
So you mean that the chain rule is something too specific to try to intuitively understand?
No I meant your example with x²
Ah yes well that is just and example for what I meant
There are a lot of intuitive videos that explain the idea and definition of a derivative
But now that I think about it it does seem a bit arbitrary
This video animates the idea behind the derivative of a function. We show how to think about the definition of the derivative of a function visually by using a limiting process of slopes of secant lines to obtain the slope of the tangent line (which measures the instant rate of change of a function at a point).
#manim #calculus #derivatives #de...
Derivative is less so a problem for me
I more struggle with integrals
and also the relation between the two
@dire geode sums haha
Integrals are also based on limits, the idea behind integrals is to find the area under a curve vaguely speaking
"The Riemann Sum."
The Riemann sum is a method for approximating the value of an integral that is the area under a curve. This method was named after the German mathematician Bernhard Riemann.
SUBSCRIBE for more Videos 👇.
https://www.youtube.com/channel/UChiIkRQe6frRchyaBvys-Pg
#shorts
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But before this you should be familiar with limits
Limits are also fine for me
I'm going to take my example again but tell me if I am thinking to deep about it
But why is it that 1/3x³ describes the area under x² ?
I hate to say it but that is the result from applying the definition
But I suppose like you said that that is just the result of doing the math after taking the conclusion
Hmm yes
There is not really something special about why it's x^3 now or 1/3 instead of any arbitrary other term
Okay
I guess I'll just think about it a little more
I appreciate your and the other persons help immensely!
It's like say you have or define X and from X there results something new called Y.
Now you are asking me how and why Y exactly? But see this is just a consequence of something deeper, here X, or in your example the definition of an integral.
btw f(x)=x^2 isnt a very good example to see the chain rule
Yes I suppose so
How so?
2x * x' = 2x * 1 = 2x
it is because one the functions in the composition is just g(x)=x
it's like a trivial chain rule

What would be a better example?
f(x) = x² and g(x) = sin(x)
Consider g(f(x)) = sin(x²)
thats exactly the same example i was thinking of 
Okay, thanks!
Also here you can see the "chain rule" is based again on that very definition of derivative
https://en.wikipedia.org/wiki/Chain_rule#First_proof
You don't have to understand it but be grateful that such results make life more abelian (simple)
Standing on the shoulders of giants I suppose
Alright, I appreciate the help from everyone
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anyone can help me with that?
1.- DERIVAR:
f(x)= 〖(2X-3)〗^5 〖(X^2+4X)〗^6
2.- DERIVAR:
f(x)= 〖(4X-3)〗^3/〖(2X-3)〗^4
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1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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7. None of the above
1
You will need chain rule for both problems
you'll nee product rule for the first problem, and quotient rule for the second
espanol?
yes
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I need to prove that the angle phi between the medians of the triangle is equal to the term in the image. The sides of the equilateral triangle are b and the base is a. I have a feeling I need to use the law of cosines but I can't seem to materialize it. Sorry for the low quality
Isosceles?
Yes sorry I'm not familiar with the terms in English


