#help-13

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dusk finch
#

$\frac{\cos\left(x\right)-1+x^{2}}{\left(x+\sin\left(x\right)\right)^{2}}=\frac{-\frac{x^{2}}{2}+x^{2}}{\left(x+x\right)^{2}}=\frac{\frac{x^{2}}{2}}{\left(2x\right)^{2}}=\frac{x^{2}}{8x^{2}}=\frac{1}{8}$

wraith daggerBOT
#

MæthIsAlwaysRight

dusk finch
#

yep

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knowing the approximations is extremely useful

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you can just eyball the limits then

inner solar
#

yes and its 2in1 cuz if you can you them for trig identiites

inner solar
#

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cedar kilnBOT
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dreamy void
#

Let $H$ be a semi-group with neutral element $e$. Then there is
[ G := G(H) := {g \in H \mid \exists h \in H s.t. gh = hg = e }. ]
Show that $G$ is a group.$\$
So far I managed to show that the composition of two elements of $G$ is in $G$ again (closure).
Now I would like to show associativity, but I am stuck, and in the solution it just says that associativy follows immediately from $H$ which I don't see how. Any help would be cool!

wraith daggerBOT
#

𝔸dωn𝓲²s

proper mortar
#

H is associative

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G is a subset of H

dreamy void
#

lol

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i didnt realize

copper cove
#

Think about how the operation in G relates to the operation in H. Since H is a semigroup and associative

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oh, he answered first

dreamy void
#

ok I think i get it now, thanks both

#

.solved

cedar kilnBOT
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rigid dome
#

can you help me with this

trim tendon
cedar kilnBOT
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rigid dome
#

.solved

#

.close

trim tendon
#

I think it'll do it automatically

cedar kilnBOT
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rigid dome
#

acctually i didn't find the solution i typed solved just cus it seems that there was a problem with this channel

rigid dome
#

plz can anyone help me (Q1 only 🙏 )

timid flower
#

too much for my lvl

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for me only algebra

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no calc

grim yacht
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Are you able to find the cdf of max_n (U_n) with n just being some arbitrary integer less or equal to k?

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How can you use this cdf to potentially solve 1?

cedar kilnBOT
#

@rigid dome Has your question been resolved?

rigid dome
#

could you elaborate ?

grim yacht
#

Let K be a random variable defined as K = max_n (U_n). If K is less than k then this is equivalent to U_1, U_2 , ..., U_n all being less than k

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If you assume each U is independent of each other how could you derive the distribution for K?

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i.e. calculating P(K<k)

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If you're completely clueless to this then you could also look up ordered variables on the web

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*order statistics

rigid dome
grim yacht
#

U_1 , U_2, ..., U_n aren't independent of each other?

grim yacht
#

What's their relation?

rigid dome
grim yacht
#

If they're dependent but we aren't given a joint distribution then we can't solve the problem

cedar kilnBOT
#
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cedar kilnBOT
#

rigid dome
grim yacht
#

Often those who make these problems are just a little lazy and leave that detail out, because it's usually always taken for granted

rigid dome
grim yacht
rigid dome
grim yacht
rigid dome
grim yacht
#

Yup that's right

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I will also recommend looking at the Wikipedia page on order statistics since the first problem is basically just a case of this

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Could give you some hints, even tho there aren't any super good explanations of the formulas there

rigid dome
grim yacht
#

np

rigid dome
#

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cedar kilnBOT
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cedar kilnBOT
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cosmic umbra
#

help me to prove .

cedar kilnBOT
dawn junco
#

have you seen eigenstuff ?

grim yacht
#

What property does the eigenvalues of T have?

grim yacht
dawn junco
#

eigenvalues eigenvectors, was writing lazily

grim yacht
#

Oh should have been able to guess that. Thought it was some ytber for a sec

dawn junco
#

Well there’s eigenchris devilish

grim yacht
#

Learned topology in 5 min from that guy

dawn junco
#

Maybe we should ping him at this point

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@cosmic umbra

cosmic umbra
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im sorry i dont understand

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why eigen here

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what do you mean

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to prove invertible we have rank n =n or ker={0}or dim !=0 right

dawn junco
#

There's a ton of other criteria you know

cosmic umbra
#

i watched it

cosmic umbra
dawn junco
#

What does it mean that det(T - sqrt(2)I) = 0 ?

cosmic umbra
#

no invertible

dawn junco
#

Regarding eigenvalues/vectors

cosmic umbra
#

why eigen here

dawn junco
#

Except instead of x we plugged in sqrt(2)

grim yacht
grim yacht
#

Thus if ker T contains a nonzero element it must have an eigenvalue equal to zero

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What can you then say about the eigenvalues if T was invertible?

cedar kilnBOT
#

@cosmic umbra Has your question been resolved?

dawn junco
#

Yeah i guess you don’t need to mention eigenvalues directly if you don’t want to @cosmic umbra

cedar kilnBOT
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trim wagon
cedar kilnBOT
trim wagon
#

pls😭

#

how the hell did -2 appear

worldly chasm
#

You multiplied by 2

undone star
#

expanding the bracket

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the 2 gets distributed

trim wagon
#

thanks 😭

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pine brook
#

[
\lim_{x \to +\infty} \left( \sqrt{x^2 + 3x} - \sqrt{x^2 + x} \right)^x
]

wraith daggerBOT
pine brook
#

How can i solve this with taylor?

cedar kilnBOT
#

@pine brook Has your question been resolved?

grim yacht
#

Ok so I should know this but ngl I'm kinda struggling too. Have you tried Taylor expanding the first term with anchor point at sqrt (x^2 + x) @pine brook ?

#

You will then get a power series with z = 2x

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heady salmon
#

Why does I(this is an i not an L) disappear?

vestal bluff
#

identity matrix is basically

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multiplicative identity

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anything times I = anything

heady salmon
#

So its cancels out… like 1-1?

vestal bluff
#

it cancels out like $2 * 2^{-1} = 1$

wraith daggerBOT
vestal bluff
#

and $1 * x = x$

wraith daggerBOT
rocky harness
#

type .close

heady salmon
#

.close

cedar kilnBOT
#
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modest hamlet
#

Hello, I need help with understanding a question in a math textbook regarding the set of all elements which aren’t an element of themselves:

modest hamlet
#

It’s question 5

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I don’t understand how one can define x as E since that breaks the rule that builds the set

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Since E contains itself

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So I don’t understand how that invalidates the existence of the set containing all elements which aren’t an element of themselves

dire geode
#

,rccw

wraith daggerBOT
solemn trail
modest hamlet
#

Is it because since a set is defined only by its elements, the property that all elements of a set have in common doesn’t apply to the set itself, which is the cause of the paradox in the case of “the set which contains all elements which don’t include themselves”?

#

Ah tu parles français?

solemn trail
#

oui

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c'est des mathématiques de quel niveau?

modest hamlet
#

L1

solemn trail
#

ah sa doit etre francais moi chui au quebec

modest hamlet
#

Oui, mais l’anglais me va aussi

solemn trail
#

non jveut dire L1 sa doit etre un systeme francais et non quebecois parce que jen ai jamais entendu parler

modest hamlet
#

De la théorie des ensembles?

solemn trail
#

moi je pensais plus a un niveau scholaire

#

oui

modest hamlet
#

Ah ok

solemn trail
#

en se moment je suis au cegep, on a fait les dérivées, quand même assez interessant

modest hamlet
#

Nous on a fait ça en terminale

solemn trail
#

terminale?

modest hamlet
#

Oui

solemn trail
#

sa veut dire quoi

modest hamlet
#

Last year of high school

solemn trail
#

ah wow

modest hamlet
#

🙂

solemn trail
#

bon le system francais est plus en avance que celui quebecois

modest hamlet
#

Pour les maths peut être, pour le reste pas sur…

#

On est derniers d’Europe

solemn trail
#

j'aimerais visiter la france une journée, pas pour la tour eiffel mais vraiment pour voir les différences culturelles entre les deux pays

modest hamlet
#

C’est une super ambition!

#

Mais pour ma question dcp?

solemn trail
#

ah bon moi chui pas rendu la dans mon acheminement mathématique, du coup je te souhaite bonne chance et salut

modest hamlet
#

Merci bcp! Merci qd mm d’avoir essayé

#

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cedar kilnBOT
#
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cedar kilnBOT
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silent island
#

Hello, I can't seem to figure out where I'm going wrong with this question (I'm trying to get from RHS to LHS)

livid hound
#

this step

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2 * 4 * ... * 2n
isn't
2 * ( 1 * 2 * ... n)

silent island
muted timber
#

because you're taking out a 2 per factor

livid hound
#

2 * 2 isn't 2 * (1 * 1)

silent island
#

i was treating it as if it was an addition

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but with multiplcation i would have to take out 2^n not just 2

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yes that makes it work, thanks!

#

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cedar kilnBOT
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odd flower
#

Nine sixteenths two thirds is

What is that?

cedar kilnBOT
#

Please don't occupy multiple help channels.

void sand
#

is this nine sixteenths times two thirds?

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nine sixteenths plus two thirds?

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what are you asking?? pandaohno

void sand
#

I can't read... Polish I think this is?

odd flower
#

Yes

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Ask chat gpt to translate

void sand
#

well uh, I don't exactly feel compelled to kongouderp

#

may I ask if you could state your original question more precisely?

opaque root
#

What is that timer?

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Is this a test?

odd flower
#

🤣

brave copper
#

oh hey its rioke again

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👋

hollow trail
#

looks like some sort of game show

odd flower
#

hiii lilith

hollow trail
#

without further context i would assume it means something like "nine sixteenths of two thirds" which would correspond to multiplying them

odd flower
#

Why multiplying?

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I thought it’s division

dusk goblet
#

english

odd flower
#

It’s

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(9/16)/(2/3)

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I believe….

opal pebble
#

If it is then you multiply 9/16 by 3/2

dusk goblet
odd flower
#

No

opal pebble
#

Rioke

#

If it is (9/16)/(2/3)

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Then you multiply by the inverse of the bottom fraction

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so now it's (9/16) X (3/2)

odd flower
#

Ik

#

#

Ok fine.

#

Genjitsu

#

.close

cedar kilnBOT
#
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opal pebble
#

Dude I am trying to help you

odd flower
#

👺

odd flower
opal pebble
#

When you are dividing by a number less than 1 youre making the number bigger

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Like 1 divided by 0.5

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1/0.5

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1/(1/2)

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so instead you multiply by the inverse of the fraction

odd flower
#

But both lower than 1?

opal pebble
#

Yesh

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Yes

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The new number will still be less than one

odd flower
#

,calc 0.6/0.6

wraith daggerBOT
#

Result:

1
odd flower
opal pebble
#

,calc (9/16)/(2/3)

wraith daggerBOT
#

Result:

0.84375
opal pebble
#

,calc (9/16)*(3/2)

wraith daggerBOT
#

Result:

0.84375
opal pebble
#

See

odd flower
#

,calc 9/16

wraith daggerBOT
#

Result:

0.5625
odd flower
#

,calc 3/2

wraith daggerBOT
#

Result:

1.5
opal pebble
#

Do you see how it flips when you multiply by the inverse of the fraction

odd flower
#

okey

opal pebble
#

does it make sense now

odd flower
#

but the answer is actually in fraction

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Yes

opal pebble
#

It's rooted in what I said about (1/0.5)

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dope

#

.close

cedar kilnBOT
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ancient ore
#

I've done the first two parts. I don't know how to approach the third part.

dire thorn
#

plug in t=1 for the 2 above integrals, also notice 1! = 1, 2! = 2, 3! = 6

ancient ore
#

ohhh because LHS of eq2 is the derivative of LHS of eq1

and further, LHS of eq3 is the derivative of LHS of eq2

#

ok then it can be solved from here, if t=1

ancient ore
dire geode
#

1+tx = 1+x when t=?

cedar kilnBOT
#

@ancient ore Has your question been resolved?

dire thorn
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tidal vapor
#

"an" is a unit vector. does last sentence mean we scaled "an" vector with |b|*cos(theta) to get the desired vector?

quasi merlin
#

(This is known as vector projection)

tidal vapor
#

if it wasn't projected onto a unit vector,

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would that change anything in the equation?

quasi merlin
#

The projection of some vector b unto another vector a would still involve the unit vector for a.

If it wasn't a unit vector (call it a), you would end with the new vector scaled by |a|

tidal vapor
#

a.b=|a||b|*cos(theta)

quasi merlin
#

Yh

tidal vapor
quasi merlin
#

Yep

tidal vapor
#

|b|*cos(theta) = a.b/|a| where left side is length of projected matrix?

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aah my brain fried

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nvm i give up

#

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void sand
#

how does this proof of mine look?

cedar kilnBOT
void sand
#

lmk if you spot any glaring mistakes kongouderp

prisma laurel
#

looks fine

void sand
#

thanks derivada

prisma laurel
#

I guess there's some nitpick to be done if you take boundary points, in the case of manifolds with boundary

limber marsh
void sand
prisma laurel
#

but I don't think the proof really changes at all in that case

limber marsh
prisma laurel
#

I think ISM just does those by taking charts in the half-plane right

limber marsh
#

oh it’s existence

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like the definition only requires existence

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okay

void sand
#

ic

limber marsh
#

neat

void sand
#

I'm also trying to understand like

#

what this exercise is telling me

limber marsh
#

the exercise tells you that it doesn’t matter what chart you pick

#

smooth functions are smooth in every atlas chart

void sand
#

but the main thing I see missing is the F(U') \subseteq V'

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I didn't conclude that during my proof

limber marsh
#

well you can just restrict U’ if F(u) is outside V’ for u in U’

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everything is so nice in smooth manifolds

limber marsh
#

because you can just restrict to a smaller subset

void sand
#

so smoothness doesn't depend on what charts we use

limber marsh
#

yeah and the proof will pretty much use the composition of smooth functions being smooth

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like not even reading your proof too hard i bet that’s one of the only things needed

void sand
#

like there's just so many moving parts ded1

limber marsh
#

which moving parts

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the atlas?

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or smoothness

void sand
#

no like, all the smooth manifolds defs I've ran into so far take like

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3 sentences to state

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so when I need to prove smth, there's a lot to do

limber marsh
#

like what

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like 3 sentences isn’t too bad of a problem to have

prisma laurel
limber marsh
#

because the moral is much shorter

void sand
void sand
#

the author, or his AG book?

limber marsh
#

the author

void sand
#

sure I do

limber marsh
#

vakil came to give talk at my university and one of the main points that he really wanted to hammer home is that people prove things before they come up with precise definitions sometimes

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which was a cool concept

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he gave this idea when he was talking about “bott periodicity in AG” which they just released a paper about

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but the whole point was about talking about what it should “look like” first and only after doing that coming up with “good” definitions

void sand
limber marsh
#

yeah

void sand
#

I see holothink

limber marsh
#

so manifolds have definitions that are spawned from good morals

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in some sense

void sand
#

interesting!

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thanks for sharing c:

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that's a nice perspective

limber marsh
#

but this is true of many definitions in math and you should be looking for morals in all of them

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and especially something so closely related to physics like manifold theory

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this is part of why history of math is such a good subject to pair with the math itself

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like it can really put your definitions into context

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not that you would have to do that

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just knowing some sort of morals is good enough

void sand
#

gotcha holoapple

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hold on, I gotta go shovel snow kekehands

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if you have more to say, say it here and I'll be back in 15min to read it

void sand
#

okie dokie

#

I'll close the channel then

#

thank you derivada and smay for the help and the insights!

#

.solved

cedar kilnBOT
#
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frozen spindle
frozen spindle
#

in particular, it is not clear to me what we are integrating over in there

#

like I can see that our probability space is the space of paths, but are the variables functions from paths to reals?

#

something about it isn't clicking

cedar kilnBOT
frozen spindle
#

it has a typo, should say combining

#

<@&286206848099549185>

cedar kilnBOT
#

@frozen spindle Has your question been resolved?

cedar kilnBOT
#

@frozen spindle Has your question been resolved?

dire geode
cedar kilnBOT
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fair wing
#

is it possible to find a way to go from two points by only moving in certain increments? ex: moving 1 away from where you started, but you can only iterate by 0.3 units

fair wing
#

yes

mystic egret
#

well then intuitively yes

twilit bison
#

if you're closer than .3 you can get there in 2 steps

fair wing
#

yeah ik cuz you'd just make an isosceles triangle

twilit bison
#

yeah

fair wing
#

i should ask is there a formula or something for it

#

well thats what i meant to ask rather

twilit bison
#

for what, the least number of steps?

#

i think you can most likely achieve a minimum if you just go directly towards your destination

fair wing
#

i guess so, i've just realized if it's less than the distance you can just b-line it and then make an isosceles triangle

#

let me visualize it rq

fair geyser
#

it doesn't feel optimal to do 3 steps

fair wing
#

if you have 0.3 unit-long steps to go 1 unit total then if you do the simple method you have 5 steps total

#

but 4 is possible

fair geyser
#

exactly

fair wing
#

so is there a way to find the angles needed to go 4 units

#

wait nvm i see it all

#

im overcomplicating it

#

.solved

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dry pawn
#

The 1st image is the question, 2nd image is the answer from this book to the question. I am confused at the answer, why the n(-4/n) becomes 4, why no negative?

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#

@dry pawn Has your question been resolved?

dry pawn
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untold lichen
teal wraith
#

💀

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fresh patio
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light knoll
#

chatgpt is giving me this:

cedar kilnBOT
light knoll
#

but on wikipedia I'm seeing this:

#

so it would seem that chatgpt is giving me the negation of the actual formula on wikipedia?

nimble veldt
#

dont trust chatgpt.

light knoll
prisma laurel
#

I believe here ${\bf r_{21}}={\bf r}_2-{\bf r}_1$

wraith daggerBOT
#

derivada.schwarziana

prisma laurel
#

while $\widehat {\bf r_{21}} = \dfrac{{\bf r_{21}}}{|{\bf r_{21}}|}$

wraith daggerBOT
#

derivada.schwarziana

prisma laurel
# nimble veldt dont trust chatgpt.

also this, can be an useful tool at times but only if you know enough to be able to fact-check its answers. LLMs aren't well suited for mathematical reasoning since they're basically text prediction with a lot of resources lol

light knoll
dire geode
#

Reading books is a much better guide because they don't waste your time being wrong

prisma laurel
#

I think it depends on the order convention of the indices

nimble veldt
prisma laurel
#

if not then it's the other way around. boils down to convention

light knoll
#

.resolve

#

thank you!

prisma laurel
#

(and admittedly I'm not a physicist so I'm rusty on this lol)

prisma laurel
light knoll
#

.close

cedar kilnBOT
#
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light knoll
cedar kilnBOT
light knoll
#

is this saying the square of delta t, or the delta, of t squared?

#

full formula:

dire geode
#

(Delta t)^2

light knoll
#

awesome thanks

#

.close

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lilac flame
#

a child has 6 pockets and 5 coins and in how many ways can he put the coins into the pockets

lilac flame
#

i wanna understand the logic

fair oracle
#

the coins are all the same i assumev

steel heart
#

There are 5 coins and 6 pockets

hexed vortex
#

The key to understanding the logic behind combinations is to first understand the logic behind permutations

dusk finch
#

this doesnt have much to do with combinations i believe

coral jewel
#

can 1 pocket contain multiple coins

hexed vortex
#

if the coins are identical, where there is no order then wouldnt that be a combination?

coral jewel
#

if yes, then ⭐ 📊

steel heart
dusk finch
steel heart
#

That is combinatorics

dusk finch
#

combinations are the binomial coefficients

hexed vortex
#

Combination is like C(2,3) right

dusk finch
#

ye

hexed vortex
#

Is this question dealing with that?

#

like wouldnt it be similar to saying if you have 6 positions and 5 people, how many different ways can you position those people

dusk finch
coral jewel
#

@lilac flame

steel heart
#

There are 5 coins and 6 pockets
*****|||||

dusk finch
#

you only need 5 seperators

#

the pockets will be between them

#

e.g.

* | * * | * | | * |

hexed vortex
#

this is similar to a problem I've encountered before dealing with functional antennas lol

coral jewel
#

op asks question and then just dips P_SobbingPien

dusk finch
dusk finch
#

Let's just finish it anyway lol

#

soo we are essentially just counting the number of strings with 5 coins (*) and 5 seperators (|)

#

there are 10 total characters in such string

#

and we need to choose 5 characters to be the seperators

#

hence 10 choose 5

#

this is where the choice function comes in

#

and that should be it

coral jewel
#

this is not the way

dusk finch
#

wait no

#

there are 5 coins

#

i forgor

wraith daggerBOT
#

The following error occured while calculating:
Error: Undefined function C

dusk finch
#

,w 10 choose 5

wraith daggerBOT
dusk finch
#

252

coral jewel
#

this is the way

dusk finch
#

⭐ & 📊

hollow trail
#

,calc combinations(10,5)

wraith daggerBOT
#

Result:

252
fair oracle
#

question its the same as having aaaaabbbbb and finding how many ways you can like scramble them right

dusk finch
#

yep

fair oracle
#

so yea 10!/((5!)(5!)) would also work

steel heart
cedar kilnBOT
# dusk finch 252

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

fair oracle
#

which is the same as 10 choose 5

coral jewel
cedar kilnBOT
steel heart
#

Wait those two are different

hexed vortex
#

reminds me of this question I had did a while back that I was struggling with lol

#

still dont quite understand the solution

dusk finch
hexed vortex
#

oh wait no nvm it make sense looking at it again

hexed vortex
#

mistav still hasnt come back lol

fair oracle
#

i skipped combinatorics and probability so im not good at it

hexed vortex
#

I think its a really intersting book

#

has some pretty intriguing questions and examples

fair oracle
#

how do you translate no two defectives are consecutive

dusk finch
#

I think that you could start by arranging the functional ones

#

and then there will be gaps

#

in each gap, you can place at most 1 defective

#

and this way, you will ensure that no defectives will be consecutive

hexed vortex
dusk finch
#

is it n - m + 1 choose m btw?

hexed vortex
#

yeah

dusk finch
#

yep

cedar kilnBOT
#

@lilac flame Has your question been resolved?

fair oracle
hexed vortex
# fair oracle what if it said no three consecutive

Then | * | ** | * | * would be possible and that means instead of allowing only one non-functional position between each bar there can be two, which in turns double the number of positions you can have for non-functional antennas, so it'd be
C(2(n-m+1), m)

hexed vortex
hexed vortex
#

thanks

fair oracle
#

oh awesome ty

cedar kilnBOT
#
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cosmic umbra
#

can someone help me 108

cedar kilnBOT
hexed vortex
# cosmic umbra can someone help me 108

You want to minimize the distance from some general point (x,y,z) to (4,2,0), thus you'd be minimizing the distance formula sqrt((x-4)^2 + (y-2)^2 + z^2) given the constraint z^2 = x^2 + y^2

cosmic umbra
#

what do you mean sqrt((x-4)^2 + (y-2)^2 + z^2) you mean the answer should be small as much as posible ??

upper ruin
#

Minimize means that, indeed

hexed vortex
# cosmic umbra what do you mean sqrt((x-4)^2 + (y-2)^2 + z^2) you mean the answer should be sma...

This is an optimization problem and with these problems the goal is to identify your contraint function and your objective function. Here the constraint function is stated in the question but the objective function, the function we wish to minimize or maximize is given through words. It says we want to find the closest point to (4,2,0) given that we are constrained to our constraint function $z^2 = x^2 + y^2$. So out of all points that lie on this cone we want to find the point closest to (4,2,0), meaning we need to find the point that has the minimum distance to (4,2,0). We find the distance between points using the distance formula $\sqrt{(x-{x_o})^2 + (y-{y_o})^2 + (z-{z_o})^2}$ where $(x_0, y_0, z_0) = (4,2,0)$. If we want to find the closest point then we must find (x,y,z) that minimizes this distance formula. Think back to finding the minimum of a function in early calc 1 by seting the first derivative to 0 and applying the first derivative test

wraith daggerBOT
#

Olivia

hexed vortex
#

Here with multivariable functions you might use something like lagrange multipliers

cedar kilnBOT
#

@cosmic umbra Has your question been resolved?

cosmic umbra
#

.close

cedar kilnBOT
#
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lilac flame
#

a boy has 6 pockets and 5 coins in how many ways can he put the coins in his pockets, answer is 6^5 i wanna understand the logic

hexed vortex
#

😭

#

we answered this one

hollow kiln
#

first coin can go to 6 different pockets

lilac flame
#

i assume they did first coin can go into 6 pockets and so on, but whats wrong with the approach of first pocket can get 5 coins

hollow kiln
#

therefore 6 ways

#

2nd coin can also go to 6 different pockets

#

another 6 ways

hexed vortex
lilac flame
hollow kiln
#

and so on

fair oracle
lilac flame
#

yeah i understood that

fair oracle
#

u technically have aaaaabbbbb

#

and in how many ways can u arrange those

lilac flame
#

" but whats wrong with the approach of first pocket can get 5 coins" whats wrong with this

fair oracle
#

the second pocket also can get 5 coins

#

and the other ones too

#

then umd have to do case 4 coins 1 coin

#

then 3 2

lilac flame
#

Ohhhh

#

I see

#

Ty ty

hollow kiln
lilac flame
#

Yep

fair oracle
#

but then u's also have to consider 1 3 1 dor example

#

1 2 1 1 cases

#

takes too long

lilac flame
#

Real

#

Well thanks for the help all of the 4 helpers lol

#

.close

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#
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hollow kiln
#

ABC is an equilateral triangle
how to show BD+CD=AD

cedar kilnBOT
#

@hollow kiln Has your question been resolved?

hollow kiln
#

<@&286206848099549185>

uneven quartz
#

Firstly, you can infer that angle ADB = angle ACB = 60 deg and that angle ADC = angle ABC = 60 deg (why?)
AB = AC
Use law of cosines on triangle ADB and triangle ADC with the angles ADB and ADC which are 60 deg each as deduced earlier.
You can easily eliminate other variables so that only AD, BD and CD are left in the system of equations.

#

You'll be left with $a^2 - c^2 = ab - bc$ which implies $(a+c)(a-c) = b(a-c)$ and so $(a+c) = b$ where a, b and c are BD, AD and CD respectively.

wraith daggerBOT
#

anshul6368

hollow kiln
#

so clean

#

thanks sir

#

.close

cedar kilnBOT
#
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uneven quartz
#

No problem.

cedar kilnBOT
#
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worldly socket
#

a^(2n+1) = a - ab^(2n)
a - ab^(2n) + b^(2n+1) = 1
a = (1 - b^(2n+1))/(1-b^(2n))
I found a in terms of b and n. Does this mean that ive found the solutions?

worldly socket
mighty shuttle
#

You could instead say $a^{2n}=x; b^{2n}=y$. Then $x+y=1, ax+by=1$

#

solve for x and y now

#

and then n

crimson delta
mighty shuttle
#

oops

#

my abd

wraith daggerBOT
#

ƒ( wai ina teacup)= I don't know

worldly socket
#

ok thanks

#

why does my solution not work?

#

it says there are infinite solutions and i have given the expression for a in terms of any b and n

crimson delta
#

but are there infinitely many solutions?

worldly socket
#

yeah

crimson delta
#

presumably you are supposed to solve for a,b for a fixed n

worldly socket
#

any b, n has an a that works

#

oh so express a, b in terms of n

earnest geyser
#

But here a^n=x

#

Same for b and y

worldly socket
earnest geyser
#

But if I take a=0 b=1

#

Then there r infinite n which satisfy the equation

worldly socket
#

yeah

#

so do i find x, y in terms of n?

earnest geyser
#

Wdym

dusk finch
#

Are you supposed to solve them simultaneously?

worldly socket
#

yeah

worldly socket
#

for example x = 5^n + n or something

dusk finch
#

Is that x and y thing even necessary then?

worldly socket
#

no

#

but it makes it easier to see

earnest geyser
#

Not rly

worldly socket
#

ok

earnest geyser
#

I think there are no answers apart from a=1 and b=0 or vice versa

#

Because suppose either of them are not 0

worldly socket
#

yeah

earnest geyser
#

a^2n is a positive value as well as b^2n

worldly socket
#

yeah

earnest geyser
#

a^(2n+1)<a^2n since a<1

worldly socket
#

yea

earnest geyser
#

Same with b

worldly socket
#

oh ok

#

ok thanks

earnest geyser
#

U got it?

worldly socket
#

yep thanks

earnest geyser
#

K

worldly socket
#

.solved

cedar kilnBOT
#
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crimson sedge
#

i need to study the variations of f
but first i wanted to prove that whats inside the ln is positive(or at least what the domain is so that it stays positive)
aaand i cant quite get my hand on it

crimson sedge
#

i get e^2x-e^x>-1

#

but how do i get rid of the exp

onyx dove
#

u=e^x substitution

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
cedar kilnBOT
#
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crimson sedge
#

hey

cedar kilnBOT
crimson sedge
#

sorry about last time my internet was awful

#

i wanted to ask about injective and surjective functions

#

can someone please explain them to me? all i get on google are those stupid circles with arrows...

#

like... the two seem VERY similar to me

#

from the explanations that i read

mighty shuttle
#

sure

#

ping me when you're here

crimson sedge
#

i am here @mighty shuttle

mighty shuttle
#

Cool

#

so let's start with injective functions or one - one functions

crimson sedge
#

okayy

mighty shuttle
#

Essentially in a one one function, each output hasa. a unique input

crimson sedge
#

okay so no more and no less than one input

mighty shuttle
#

Let's have a short quiz, shall we

#

is sin(x) injective

crimson sedge
#

yeah

#

no

crimson delta
#

wai you need to be more precise

crimson sedge
#

cuz it can be 1 with different inputs

crimson delta
#

injective and surjective depend hugely on domain and codomain

crimson sedge
#

how so

mighty shuttle
#

Technically speaking a functions is said to be one -one , if an element in the codomain has at most one pre-image in the domain

crimson sedge
#

okay

#

and surjective is really similar... or is it not?

#

cuz the way we prove it

#

what

mighty shuttle
#

nvm

#

nothing

crimson sedge
mighty shuttle
#

Yup!

#

well, almost

crimson sedge
#

but thats the same thing with injective lol

#

every y has an x in the domain

mighty shuttle
#

each y in the co domain has ateast one x in the domain

crimson sedge
#

and with injective, it has just one?

#

one x in the domain?

#

is that the difference?

mighty shuttle
#

at most one x

crimson sedge
#

now i understand

#

thank you wai

mighty shuttle
#

cool, then can I quiz you to ensure you've understood?

crimson sedge
#

sure

mighty shuttle
#

define $f(x) to be -x^2 , if x<0, and x^2 if x \geq 0

#

is f(x) injective

crimson sedge
wraith daggerBOT
crimson sedge
#

okay hmmm

mighty shuttle
#

This is a bit hard, so don't be discouraged

crimson sedge
#

im thinking hold up

#

🧠

#

yes

#

its injective

mighty shuttle
#

awesome!

crimson sedge
#

🔥

#

thanks

#

.close

cedar kilnBOT
#
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agile swallow
#

Imo

cedar kilnBOT
#
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weary thistle
#

how do I differentiate arctanx with respect to tanx? (for xε(-π/2,π/2))

lyric narwhal
#

do you know what a derivative of a function with respect to another function means in general

weary thistle
#

yes, but im not familiar on how to approach problems that require to take the derivatewith respect to a whole function

lyric narwhal
#

sure, where y is a function of x

#

okay

#

do you know what the chain rule is?

weary thistle
#

yes. [f(g(x))]'=f'(g(x))g'(x)

#

not familiar with liebnix notation tho

lyric narwhal
#

sure, but we'll write it a bit differently

#

Let $f(x)=\arctan(x)$ and $y(x)=\tan(x)$. Then $$\dv{f}{y}=\dv{f}{x}\dv{x}{y}$$

wraith daggerBOT
#

kheerii

lyric narwhal
#

does this make sense

weary thistle
#

if we treat it like a fraction too, yes

lyric narwhal
#

no, we aren't treating it like a fraction

#

it just looks that way

weary thistle
#

ohh and ill do it with the help of differentials?

#

oh ok

lyric narwhal
#

this is precisely what the chain rule says

weary thistle
#

ok so df/dx is 1/1+x^2

#

dx/dy is??

lyric narwhal
#

$\dv{x}{y}=\frac1{\dv{y}{x}}$

wraith daggerBOT
#

kheerii

weary thistle
#

so cos^2x

#

so the derivative is (cos^2x)/(1+x^2)?

lyric narwhal
#

yes

weary thistle
#

oh

#

wait

lyric narwhal
#

in general $\dv{y}{x}=\frac{\dv{y}{t}}{\dv{x}{t}}$ where $x$ and $y$ are functions of another variable $t$

wraith daggerBOT
#

kheerii

weary thistle
#

in the task, it also says: consider known the derivative of tanx. (doesnt say anything about the derivative of arctanx with respect to x) With the help of the definition of the derivative find d/dy(arctanx)

#

does it want me to calculate in some other way?

#

@lyric narwhal

cedar kilnBOT
#

@weary thistle Has your question been resolved?

cedar kilnBOT
#

@weary thistle Has your question been resolved?

cedar kilnBOT
#

@weary thistle Has your question been resolved?

weary thistle
#

<@&286206848099549185>

austere coyote
#

Yes

#

Whats the question?

weary thistle
#

it wants me to find

#

in the task, it also says: consider known the derivative of tanx. (doesnt say anything about the derivative of arctanx with respect to x) With the help of the definition of the derivative find d/dy(arctanx)

austere ember
#

okay, so you know the derivative of tanx is (secx)^2

if y = tanx, then arctan(y) = arctan(tan(x)) = x

#

(assuming that x has an appropriate domain, which it does here)

weary thistle
#

oh yes

austere ember
#

actually wait sorry i did that backwards, let y = arctanx, then tan(y) = tan(arctanx) = x

#

you ultimately want to find y'

weary thistle
#

no y=tanx

austere ember
#

implicitly differentiate and use your known tan derivative and chain rule

weary thistle
austere ember
#

okay this problem is written very poorly, d/dy (arctanx) is clearly 0

#

are you meant to find the derivative of arctanx?

#

like d/dx

austere coyote
#

No

weary thistle
#

no it wants d/dy

#

its like saying d(arctanx)/d(tanx)

austere ember
#

ohh

weary thistle
#

how am i supposed to do that

austere coyote
#

Look

austere ember
#

lmaoo that makes more sense

#

right this is just abusing chain rule

austere coyote
#

Neil if I may

austere ember
austere coyote
#

Xtra write x in respect of y

#

Saying that x equals arctan y

#

Plug that into arctan x

#

Then you have the arctan of arctan of y

#

Then differentiate with respect to y

#

It should be 1/1+(arctany)^2 times 1/1+y^2

#

If not check wolframalpha

weary thistle
#

hm

#

i get what you are saying but

weary thistle
austere coyote
#

It might just be another way to get the same answer

weary thistle
#

what does it mean "definition of derivative?"

#

also it doesnt say consider known the derivative of arctanx like it does for tanx

#

so how will i say that d/dx(arctanx)=1/1+x^2

#

maybe it wants me to do it some other way around?

austere coyote
#

It looks like I’m right I googled it

weary thistle
austere coyote
#

Honestly I don’t know I’d have to think about it

#

Would it matter if you did it differently?

weary thistle
#

i dont know, thats the thing haha

austere coyote
#

Does your teacher care?

#

Is this an online class?

weary thistle
#

ive sent him an email asking him

#

no but its christmas break

austere coyote
#

hmmm

#

Okay I’ll think about it

weary thistle
#

thanks. You can DM me if you want. If you dont think anything else, thats ok. im tired of this problem, been looking it for 2 days now. im closing this channel, and plz let me know if anything

#

.close

cedar kilnBOT
#
Channel closed

Closed by @weary thistle

Use .reopen if this was a mistake.

ocean zenith
#

Is the ans to 6÷2 (1+2)... equal to 9 or 1 ?

lyric kite
#

9

ocean zenith
lyric kite
#

6/2*3

steel crest
#

Do left to right

#

6/2*3 = 3*3 = 9

lyric kite
#

the parentheses say that you do 1+2 first, and then you do left to right

steel crest
#

Yes

cedar kilnBOT
#
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fallen trail
#

Why isn't the first one correct but the second one is?

fallen trail
#

Btw how do we graph implicit differentiation in desmos?

worldly chasm
#

I do not think there is a way to do it. But I could be wrong.

dire geode
#

,w diff cos(xy(x))

fallen trail
dire geode
#

Use y' instead of dy/dx

fallen trail
fallen trail
fallen trail
#

are these results equal?

#

For some reason the book does it this way thinkies

odd verge
#

,w diff arcsin2x/x

fallen trail
#

Unless if I'm graphing these implicit equations wrong

#

I'm so conflicted

#

Do I believe myself and wolframe or the book 💀

odd verge
#

,w diff arcsin2x/x

wraith daggerBOT
fallen trail
#

Please explain

odd verge
#

Divide through by x

#

@fallen trail

fallen trail
fallen trail
odd verge
#

Hmm okay

odd verge
fallen trail
#

alr

#

.close

cedar kilnBOT
#
Channel closed

Closed by @fallen trail

Use .reopen if this was a mistake.

odd verge
#

You should probably get other opinions too though.

cedar kilnBOT
#
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fallen trail
fallen trail
#

.close

cedar kilnBOT
#
Channel closed

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odd verge
odd verge
fallen trail
# odd verge

No that's the alternative forms for when you divide throughout by x

odd verge
#

All three answers are literally the same.

#

They just have different styles.

#

Cosxy = √{1-sin²(xy)}

#

@fallen trail

fallen trail
odd verge
#

Anything else?

cedar kilnBOT
fallen trail
#

.close

fallen trail
odd verge
odd verge
cedar kilnBOT
#
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twilit badger
#

Question: is there an intuitive way to understand why the chain rule works for find the derivative and integral of a function: like x² for example. Why is it that the derivative is 2x and the integral is 1/3x² ?

dreamy void
#

Like many things in mathematics, these are just results of applying the definition of something; here the definition of a derivative which is essentially a limit.

Applying this definition leads to results such as power, product, chain rule etc. or specifically that derivative.

[ f'(x) := \lim_{h \to 0} \frac{f(x+h)-f(x)}{h} ]

So with $f(x) = x^2$ you'd have
[ f'(x) = \lim_{h \to 0} \frac{(x+h)^2-x^2}{h} ]
and if you calculate that limit you get $f'(x) = 2x.$

wraith daggerBOT
#

𝔸dωn𝓲²s

dire geode
twilit badger
#

So would it be difficult to make a logical conclusion that doesn't rely on proofs?

twilit badger
#

I have researched many ways to interpret integrals and derivatives

#

derivates fundamentally I roughly understand

dire geode
#

If you don't understand the algebraic steps then you're not gonna have a good time in calculus and beyond

dreamy void
#

If you yearn for greater understanding, I would try to analyze the definition rather? Why would someone define exactly like that a derivative and what is the intution behind that, instead of a specific example that is really just computation.

twilit badger
#

The algebra isn't a problem

twilit badger
dreamy void
#

No I meant your example with x²

twilit badger
#

Ah yes well that is just and example for what I meant

dreamy void
#

There are a lot of intuitive videos that explain the idea and definition of a derivative

twilit badger
#

But now that I think about it it does seem a bit arbitrary

dreamy void
twilit badger
#

I more struggle with integrals

#

and also the relation between the two

dreamy void
#

@dire geode sums haha

#

Integrals are also based on limits, the idea behind integrals is to find the area under a curve vaguely speaking

#

But before this you should be familiar with limits

twilit badger
#

Limits are also fine for me

#

I'm going to take my example again but tell me if I am thinking to deep about it

#

But why is it that 1/3x³ describes the area under x² ?

dreamy void
#

I hate to say it but that is the result from applying the definition

twilit badger
#

But I suppose like you said that that is just the result of doing the math after taking the conclusion

#

Hmm yes

dreamy void
#

There is not really something special about why it's x^3 now or 1/3 instead of any arbitrary other term

twilit badger
#

Okay

#

I guess I'll just think about it a little more

#

I appreciate your and the other persons help immensely!

dreamy void
#

It's like say you have or define X and from X there results something new called Y.
Now you are asking me how and why Y exactly? But see this is just a consequence of something deeper, here X, or in your example the definition of an integral.

dim tiger
#

btw f(x)=x^2 isnt a very good example to see the chain rule

dreamy void
dim tiger
twilit badger
#

Oh

#

sorry

dreamy void
#

it's like a trivial chain rule

opaque root
twilit badger
#

What would be a better example?

dreamy void
#

f(x) = x² and g(x) = sin(x)
Consider g(f(x)) = sin(x²)

dim tiger
twilit badger
dreamy void
#

You don't have to understand it but be grateful that such results make life more abelian (simple)

twilit badger
#

Standing on the shoulders of giants I suppose

#

Alright, I appreciate the help from everyone

#

.close

cedar kilnBOT
#
Channel closed

Closed by @twilit badger

Use .reopen if this was a mistake.

cedar kilnBOT
#
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neat fern
#

anyone can help me with that?

1.- DERIVAR:
f(x)= 〖(2X-3)〗^5 〖(X^2+4X)〗^6
2.- DERIVAR:
f(x)= 〖(4X-3)〗^3/〖(2X-3)〗^4

cedar kilnBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
neat fern
#

1

dull oxide
#

You will need chain rule for both problems

#

you'll nee product rule for the first problem, and quotient rule for the second

neat fern
#

idk

#

my english is bad

dull oxide
#

espanol?

neat fern
#

yes

cedar kilnBOT
#

@neat fern Has your question been resolved?

cedar kilnBOT
#
Channel closed

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cedar kilnBOT
#
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upbeat lotus
cedar kilnBOT
upbeat lotus
#

Q61

#

How to proceed ?

#

NVM I did it

#

.close

cedar kilnBOT
#
Channel closed

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cedar kilnBOT
#
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noble trench
#

I need to prove that the angle phi between the medians of the triangle is equal to the term in the image. The sides of the equilateral triangle are b and the base is a. I have a feeling I need to use the law of cosines but I can't seem to materialize it. Sorry for the low quality

worldly chasm
#

Isosceles?

noble trench
#

Yes sorry I'm not familiar with the terms in English

worldly chasm
#

It's ok

#

So I don't see a way to solve this yet

#

But I will point out that the medians of an isosceles triangle make other smaller isosceles triangles, and this might wind up being important