#help-13
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sad
wdym
the central intensity theory explains that
at the center of any force
the intensity is the greatest
Hehe
central force intensity theory*
afk rq
So
it explains that at the center of every force
the intensity of the force
is the stronges
afk
Back
Okay
thats the source
<@&268886789983436800>
Bluds cooked
riemann is a genius
Lol question so stupid riemann himself came to bash you for it
REAL
That gotta be some sort of achievement
That’s wild bro
that must be why your mum eats so much
Damn
the centre of her body i.e. her stomach has the strongest gravitational attraction
The past size intensity theory
okay
explains that in the past, organisms were bigger
Please keep help channels to actual math help questions

but..
I am going to close this. @surreal frost if you want to screw around, use #chill or #discussion
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✅
read #❓how-to-get-help
#how to get help
And do not troll and waste our time
.close
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💥
LMFAO
🤡
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Could anybody please explain this to me, im not sure what it means in this section
<@&286206848099549185>
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Emmmm
Is it ok if I ask physic question
Only physic 11 though
So
How did u identify
Work out and work in and p out and p in
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Can someone explain me with this topic
I struggle
@fringe moth Has your question been resolved?
@fringe moth Has your question been resolved?
is this correct?
You may translate it into english
The two results are obvious if you expand the right part
(using the formulas of x_1 x_2)
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https://youtu.be/wP4vOS4SmYA?feature=shared
Does this work in all cases?
Vedic Mathematics is a collection of Formulae/Techniques called Sutras which help us solve arithmetic problems. The techniques are said to have been taken from multiple Sanskrit texts. The Sutras in Vedic Mathematics were put together by Indian Mathematician Shri Bharati Krishna Tirthaji around the early 20th century
Easy way for multiplication...
It's in Hindi but you should be able to tell with the numbers shown
Put at 2x speed
looks right
Could you please explain how it works?
I didn't understand why or how it works
i think it works
ABxCD = (10A+B)(10C+D) = (100AC + BD) + 10(AD+BC)
it's like dissecting the two digit number into its expanded form, and it looks similar to doing FOIL method
Oh
So it like when we reverse digits in a 2 digit number
Takes 10s place as 10x
Well thx
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I've been struggling a little with the proof for the Boundedness theorem
I don't quite understand how for every n, there's a x_n where f(x_n)>n
like, isn't n an index
where did the inequality f(x_n)>n even come from
n is a natural number ...so you can use it as an index or as a value
for instance a_n=2n is a valid sequence
in this case, a_n>n ,,,as in the proof
since i know those two are connected
alright uh
let me go through the first sentence
ok just substitute f(x_n)>n with f(x_n)>b_n where b_n=n
so we have an f that isn't bounded above
which means f goes to infinity
cause it isn't bounded
like f(x)=1/x
right ... but you don t know a priori where f goes at infinity
but we know it definitely goes into infinity
since its unbounded
and its continuous
right ...so it must exists a sequence x_n such that ....
so now the sequence (x_n) is defined across the interval [a,b]
the sequence should be (x_n) where x_n=x
now we know its infinitely dense, [a,b]
so n can go to infinity
so how does f(x_n)>n?
like on what basis do we make such a statement?
whats the, uh, proof, or logic behind f(x_n)>n
you define x_n such that it does that specific thing
what specific thing
x_n are not just random numbers in [0,1]
this one
depends on f actually
it doesn't?
like if f(x) is continuous along [0,1]
that means x must be every value from [0,1]
here the continuity plays no role
to be a sequence between [0,1] doesn't mean that it is infinitely small
well if x cant be 0.0...01
yes I know, but your doubt is not related with the property of being continuous... you didn't understand how we know that f(x_n)>n
that means it clearly contradicts the statement that f(x) is continuous isn't it?
right
yep
so we don't know the rate in which f(x_n) increases
we know n will increase to infinity
but that doesn't mean f(x_n) will increase to infinitely faster than n
to maintain the inequality f(x_n)>n
let's start from the beginning ... I will construct a sequence such that f(x_n)>n ok?
right
so f is unbounded ..so it is not true that f(x)<1 for every x in [0,1]
so it must exists some x_1 in [0,1] such that f(x_1)>1
wait what does it exactly mean by unbounded
note that this x_n could be equal to 1/2 for example...you don't know how much near to zero it is
i mean i know bounded means |f(x)| <= M for some M
unbounded = not bounded
yep but what does that imply
that this M doesn't exists ...even for M=1
ok
right ...you need just one x
right
yep
so we can do the same argument for M=2...so we can find x_2 in [0,1] such that f(x_2)>2
yep it is guaranteed to find a real number M whereby f(x)>M for some x
in that way you are able to construct a sequence x_n such that f(x_n)>n
but here the proof says for every natural number n
there exists a x_n where f(x_n)>n
if its for some number n there must exist f(x_n)>n that makes sense
are you saying that my argument doesn't work for n=100 maybe?
well we dont know when f(x) goes into infinity
I was asking a different thing though
so f(x_n) where n=100 may be at 3
x_100 may be 3.1238719
well then f(x_n) certainly wouldn't be larger than 100
no ...because f is NOT bounded in [0,1] ...not [0,3]
right I'm a little confused
so ,... is it okay my argument for n=100 ?
right n=100 is certainly correct
n will go to infinity
x_100 must be somewhere say, 0.1872368172
ok so if you cannot find a bug for every n...then you are sure to construct such a sequence
if not, tell me a specific n when my argument stops to work
right, my argument is that x_100=0.1283761827368, however f(x_100) it may be 0.0011
so f(x_100) would not be larger than n
thus f(x_n)>n is invalid for every n
x_100 has the property that f(x_100)>100
because it exists
do you think that such x_100 could not exists maybe ?
x_100 definitely exists
since x_n is defined along the interval [0,1]
even x_298719283 exists
yes
doesn't mean that f(x_298719283)>298719283
it seems like your x_100 is a random number, isn't it?
f(x) is unbounded, doesn't mean that f(x)=infinity for all x in [a,b]
well
x_100 is certainly a value between [0,1]
ok another time
we dont know exactly what x_100 is
is it true that |f(x)|<100 in [0,1] for every x?
see the problem is that the proof says for all n
not for some n
if its for some n
of course its correct
but now it states for all n
yeah, and how do you show that f(x_100) must be larger than 100?
I am not say that f(x_100)>n for every n
you have already showed it
here
what?
alright I'll
I'll go take a bath to clear my mind
I'll come back to this later
my brain is fried currently
thank you for the explanation

I'll try
plotting an unbounded graph from [0,1]
perhaps it'll be easier to understand visually
in this first part continuity plays no role
right
then you will use it
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Hello
Guys I need help here
I need a really smart person to help me
<@&286206848099549185>
just ask
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
So, basically, what is the coefficient of a 0,5 meters segment that is 15° away from the horizontal axis, like, how do I calculate that?
coefficient?
Prolly asking about length of projection
Just multiply it with cos 15 for it's length on x axis and sin15 for y axis
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When solving $\lim_{x\to2} \arcsin(\frac{1}{(x-2)^2})\ln(x^2-3)$ how to show that $\arcsin(\frac{1}{(x-2)^2})$ is not defined at neighbourhood of 2?
Slowaq
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Anyone can explain why the bounds are -5/2 and 5/2 ?
The seccond part where you show it oscilates between -4/3and 4/3 is pretty easy with limits alegbra, but i just cant understand the bounds of /2 come in
they have a typo. should read the denominator is always $\ge 2n >0$ and numerator is bounded ... between $-5n$ and $5n$.
riemann
so $\frac{-5n}{2n} \le a_n \le \frac{5n}{2n}$
riemann
Alr ty
How exacty is the numerator between -5n and 5n though?
As surely we have 4n(-1) + 0 as a minimum value and then 4n(1) +1 as a max value
So -4 - 4n +1
Thats where im getting tripped up
sin^2(n) is bounded below at 0 no?
yea calc and onward is a lot of learning and memorizing tricks
Half my lectures are just my pure mathematics lecturer pulling some fancy tricks that noone would think of
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I'm very lost
did you use the hint at all
Nvm I see it now it's a geometric series I'm dumb
fun problem
I need to read more, just copied the problem to my paper and didn't read the hint
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Hey
-ln(x) = ln(x^-1)
think of it as 1/e^ln(5/t)
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square both equations and add them together
Ooh thx!
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@runic condor Has your question been resolved?
@runic condor Has your question been resolved?
@runic condor Has your question been resolved?
have you tried chatgpt
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can someone give me a better explanation on why this is correct
what is shown that proves it’s a horizontal dilation
wait is it bc b is less than 0
wtf
bro i hate how they word the questions 😭
$(3^x)^b = 3^{bx} = f(bx)$
knief
how does this help
yes
what is it
when the thing
nope
wait
yep
who said anything about a parabola
stretches or shrinks horizontally
generalize it to all functions
normally it’s a parabola tho
this is just reformulating the words in english
what
saying it’s a horizontal compression is the exact same thning
i asked if you knew what it was
yea
and all you did was just use a synonym
Kneief are you a helper
you did say explain it
what
Can u help me after
you didn’t explain it or demonstrate that you know what it is
how do i explain what it is without describing it
with math
symbols
that we use to communicate definitions
how does a horizontal dilation arise
again you’re not at all doing what i’m saying
it’s ok to admit you don’t know
imagine you asked me what a vertical shift was and i just said it’s when the function is moved vertically
like what
no kidding
restating it with synonyms isn’t indicative of understanding what it is
you can restate anything with synonyms while knowing absolutely nothing about it
what does it have a deeper meaning
it would be better to say a vertical shift is a transformation of a function of the form f(x) + c for some constant c
see idk what that means
now what is the transformation for a horizontal dilation
no way
bro what
just say that instead of pretending you know by using synonyms
that’s not a constant
this isn’t a vertical shift because i didn’t add the constant to the function
ok then what is a horizontal dilation
we’ve established that adding a constant isn’t because it’s a vertical shift
what else can we do
when you divide or multiply x
where?
uh
and multiply by what?
but use function notation
i hate that
because f(x) = x is just one function
we want to generalize it to all functions
and 2x can also be confused with a vertical dilation since in this case it does the same thing
so you have to be more specific with what you mean
how would that be confused with a vertical
because a vertical stretch by a factor of 2 for f(x) = x is also just 2x
would you like to write it with coordinates
for instance, a vertical shift can be represented as (x,y) -> (x, y + c)
you can classify it as either
but they’re not the same for all functions
why not
consider a counter example
f(x) = x + 1
a horizontal dilation by a factor of 2 would be 2x+1 but a vertical stretch by the same factor would be 2x+2
2x+2 certainly isn’t the same as 2x+1
dumb that down
to show that a horizontal and vertical stretch aren’t the same thing for all functions we just have to show that there is at least one function such that it’s not true
does 2x+1 = 2x+2
no
there ya go
what
they aren’t the same transformation then
was i supposed to understand
that they aren’t the same transformation
is that all
sure
we still haven’t formalized what a horizontal dilation is
use proper notation
what’s that
either functional notation or with coordinates
ok
here is an example with coordinates
x,y * c
no that would be a vertical stretch
(x,y) -> (x, cy) is a vertical stretch
yep
yes
or cx,xy
that’s precisely what a horizontal dilation is
cx,cy
no
what’s that
ok
but i can write this using functional notation
f(x) -> f(cx)
because before the input was x, now it’s cx
hmm doesn’t that look like what we had in our problem
^
so then we can safely say that it’s a horizontal dilation
ohhh yeaa
knief
you multiply exponents
mhm
cause of the parentethees
yep
so you’re fine with this?
not sure i can explain it any better
but i’ll finish explaining the problem
i’ve already shown why it’s a horizontal dilation so now we are between 2 answers
$3^{bx} = 3^{-cx} = f(-cx)$
knief
yea
a reflection over the y axis is of the form (x,y) -> (-x,y)
if the negative is on the x it reflects over the y axis right
hence in our problem we have a horizontal dilation and a reflection over the y axis
when does it reflect over the x axis
and if it’s like (x,y) -> (x,-y) then it reflects over the x axis
it’s easy to visualize
how would i see this in like a function thingy
ohhh
f(x) is really y
yea i remb
ik
ok if i see a problem like this im 2015 Steph curry swishing
i fr shouldn’t have taken pre calc im too lazy for ts
lol
ap pre calc
i needa pass the final
fr?
yes
it’s a new ap
mhm
no wonder the videos are so ass
yep
bro istg when i tell u this
the things we study and practice
are not on any tests or quiz
lol the ap physics c e&m videos were fucking atrocious
like
i wish we had test formatted questions to practice
ts so dumb
i seen a video talking abt it
it’s like learning to build a house and then being told to build a skyscraper
and expecting to know how to do it
math is fun
i hate
i took the class bc i thought it would be hard and it is but i was a different guy last year
i was on some academic power up booster
now idgaf and regret ts
ight im done yapping i gotta sleep
interesting how you go from liking school to not
3.8 gpa to borderline crashing out
hey man don’t give up
inspirational
schools hard don’t get me wrong I get it
I’m a senior in high school doing so many AP’s and internships but you can’t give up bro
what are you taking
marc you know what im talking about
It’s worth it If your doing stem or law or something
you study all of this stuff
and when the exam comes
you are expected to know some bs u didn’t study
yeah man I have over 30 college credits
wtf
As a senior
they teach you how to think
nice
Exactly
school should teach you how to think and problem solve
that’s why math and science is so important for students
Not necessarily because of the material
But because it teaches you how to think
i must be a below average problem solver
I mean look at the S&P 500 like a good portion of those ceos are engineers
You’re not bro
trust
you need to learn how to think if that makes sense
I’m not calling you stupid
I’m saying that’s the key to all of it
Don’t give up
Once you find that one teacher who inspires you you’ll be set
no
marc how much hours of sleep do you get
how much elo do u have
in?
chess
1700 rapid
Like 7-8
but i quit
same
i skipped hella school
in the start of the year
mainly bc i didn’t wanna get out of bed
I got all A’s first quarter and now I’m just getting B’s bc it’ll show up as an A first semester for colleges
my school starts at 7 am
I just dgaf anymore
it’s good
Mine starts at 7:45
Nah bro I have a full schedule and dual enrollment classes😭
why
College credits
don’t you have enough
I wanna be an engineer and my school is goated
yeah but I want full rides and shit
how much money we talking
idk what that is
Georgia State too
but how much money once you get the job
York College offered hella and SUNY buffalo
Oh
Depends what part of industry but where I’m from the median is like 125 starting
fire
are you from new york too?
what is md
maryland
MarylanD
that makes no sense
yes
Where at bro
nunya
U like it
yes
What’s that
lol
i didn’t take school seriously until 11th grade
ain’t no way
same
what was your gpa junior year do you remeber
i made friends with the wrong people in middle school
Real
that’s tuff
yep
i had to double up on math classes to take all of the classes i wanted since i took classes my friends were taking
in middle school/early high school
yeah
dumbest thing ever
i was at the top in 7th grade then i hung out with jocks and took dumbass classes until 11th grade
And all the nerds in my classes don’t
marc
Wsp
wdym offers
honors is the minimum mate
yea that’s what im thinking
that doesn’t make you stand out
Oh like offers from school
Nah bro not really
AP and Dual Enrollment or IB
Those r the big three
APs are not enough for offers lol
they are trust
they again are a minimum
hell no
yes but to what school
And 3 DE’s
T20 schools are not giving full rides because you took 15 APs
arent AP classes literally college level classes
marketed as such
Virginia tech is my top choice I could care less abt a prestigious rich school
virginia tech is good
i hate schools
if i get offers im denying them and crashing out
just become a fortnite pro bro
real talk imma go to a community college and get my associates and if i fw it i’ll transfer for a bachelors
at some 4 year
if you plan on going for a higher education i’m not sure an associates will do all that much for you but going to community college is common for people who want to save money i guess
for the first two years
then transfer
but if you don’t like school i’m not sure why you didn’t want to go into a trade
what is a trade
i have friends who are by no means academics who were doing trades in high school and are working now no debt
plumber, electrician, HVAC, carpentry etc
they get paid pretty well
what do you think
not all plumbers though
where i don’t have to encounter that
that’s what im asking
plumbing consists of more than fixing toilets
lay pipe yea
you don’t have to
heating, ventilation, and air conditioning
no it’s not low-key
oh really
yea it’s quite popular
is carpentry like carpet shit
strange, most people i know enjoy getting splinters
really
oh yea
i had one as a kid and i went to bed thinking i wasn’t gonna be alive when i woke up
still haunts me
scary
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for 10, you need to remember a few things:
- How do multiply variables and numbers
- How do you distribute multiplication over a sum of two numbers
How do i distrubute it
To distribute the product of $12h$ and $\frac{-3}4+2$, you first calculate the product of $12h$ and $\frac{-3}3h$, and the product of $12h$ and $2$, then you add those two products together. In math language, distributing multiplication would look like
$$(12h)\times\left(\frac{-3}4h+2\right)=((12h)\times\left(\frac{-3}4\right))+((12h)\times(2)$$
SWR
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
11.Because the numerator and denominator are having x so divide both sides by x so you have is (2x-3)/3
correct
close.
First, I'll say that you calculated $(12h)\times2$ incorrectly. Minor mistake, but definitely needs to be corrected
SWR
Not quite. One more thing
you made an error with multiplying with your fraction
When you multiply a whole amount by a fraction, you multiply only the whole amount with the numerator of the fraction. The denominator remains unchanged
$(12h)\times\left(\frac{-3}4h\right)=\frac{(12h)\times(-3)\times h}{4}$
SWR
Show what the actual answer would be
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
Almost, don't forget that there is another h after -3/4 (I forgot to write it on spot, so I apologize if I misled you there)
You are only multiplying by one h here, but there are two h's being multiplied.
correct
And now one last thing: You have a 36 on the numerator and a 4 on the denominator. You can simplify
And finally the last, last bit: If you have a 1 in the denominator, you don't need to write it. Just 9h²+24h will do
Is this right too
You forgot to consider the negative in the denominator
So -2x-3
You forgot to consider the double negative for that last -3 term
$-(2x-3)=(-2x)-(-3)$
SWR
What does double negetive mean
The negative of a negative value is the positive value
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Oh aii
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hello
hello sir
i think the answer
oops
well
idk the answe
but abt these questions i know that the zeros are found at the top and the holes are what cancels out fom bottom and top
where is the verical asymptote found and where is the horizontal asymptot found
Since x equals positive 3 we can cross out B as an answer
A hole in the function is formed when you can cancel out the (x-3) from the bottom
and you can do that in both a and c
so D is left
alright
but in general
where is the vertical asymptote found
in the numerator or denom
where the function approaches infinity
so as the denominator approaches 0
for example
f(x)=1/x
when x is really close to 0
like 0.0000001
then 1/(0.00000001) is very large
denominator
Is this a test
loll
Use the binomial expansion
thats literally what the question said 😭
im trying to find my notes
ran1zy do you know how to get the coefficients each term
with combinations
i used to
i need to find my notes for a refresher
where the flip is it in this folder
You need to start with 4C0 because thats the first term
that equals 1 so all options are correct so far
the second term will have 4C1 which is equal to 4
so every option is wrong except C
multiply by hand :3
haha
i know this question is easy but is it reflected over x or y axis
im thinking its A
but idk how to tell if the x axis or y axis its being flipped over
yeah thats right
it would be flipped over the x axis if the x was negative
so if the negative is not in parenthesis its x axis and if its in the (-x +4) it would be over y
when is your test
tmr
lol
but i know like half of the stuff
this is just last second review touching on things i migfht not know
ok
do you know what x/2 is the same as
or wait thats a dumb question
do you know how a number to the power of a fraction works
no it's not negative
oh right
im back
alright so
basicaly
square root of 16
bc it was to the 1/2 at first
and thats the same thing
yeah wait ill give you some more examples
would it be C
yes
i dont really get this
bro they word these so complicated but it's simple
the function h is the function k times 9
lol
what the flip
what grade are you? or math level
ok yeah just read it slowly then
i didnt pay attention to this unit so tjhts on me