help-13

[quaint heath]

u mean rpm?

[teal wraith]

?

[graceful quartz]

You have to use the balanced redox equation and count the number of sigma bonds and bond hybridization. Then find the rate law of the reaction by determining the rate determining step but you have to use steady-state approximation to get rid of the reaction intermediate!

Hope that helps

[quaint heath]

based on the units u get from the question ?

rotations is unitless as well

basically if you know whats going on with the object / the problem you'll know what unit to use

idk

[teal wraith]

what

thats not true

[graceful quartz]

@quaint heath nice just get the wrong answer

Har har x

[frigid sinew]

actually no im stupid

nvm LOL

[hollow trail]

rad/s and rpm are both units of angular velocity, m/s is not

which one you get depends on dimensional analysis, but it should be noted that rad/s is the SI unit

[quaint heath]

nvm im stupid bro

LMAO

i was thinking of something else

[cedar kiln]

@frigid sinew Has your question been resolved?

Channel closed

Closed by @frigid sinew

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

can someone show me how to do long polynomial division

[crimson sedge]

(2x
3
+8x
2
+x−22) divided by÷ left parenthesis, x, plus, 3, right parenthesis(x+3)

wait

how do i know which numbers are the remainder

<@&286206848099549185>

aw man

how do you find the remainder in long division for polynomials

[steel crest]

act as if it normal long division

2x^3 = 2x^2(x+3)-6x^2

14x^2=14x(x+3)-42x

[crimson sedge]

but what is the remainder

how would i know

[cold timber]

Keep doing this till the zero degree

[crimson sedge]

so

until its equals 22?

[cold timber]

what

[crimson sedge]

22 is zero degree

i got the first part with all the numbers

but like how do i divide to get remainders

[cold timber]

What do u get

[crimson sedge]

i know the numbers

[cold timber]

U will get a constant, and that’s not divisible by x, that constant is the remainder

[crimson sedge]

whats the next

part

i have 22 but idk what to dfo with it

[cold timber]

I’m not sure what this is😭

[crimson sedge]

then why do you try to help then

[idle tusk]

i know polynomial long division but i don't get what i am looking at

[crimson sedge]

idk its my teazh

she sucks

and i get deducted az lot of points because i get the aznswer in the wrong wzay

[idle tusk]

i think you are supposed to be multiplying not 2x^3 + blahblah but rather x+3 in order to match coefficients in 2x^3 + blah

[crimson sedge]

and apparently this is her way

its loike box/foil method

[idle tusk]

oh

but that's for multiplication

not division

[crimson sedge]

apparently she said it cazn be applied for division as well

wait

actually i think its hopeless

no one does it her way

im failing ong

.close

[cedar kiln]

Channel closed

Closed by @summer lagoon

Use .reopen if this was a mistake.

[idle tusk]

look up long division on youtube and do it that way

[crimson sedge]

i did

and its niot the same

they do it through like farsimpler ways comp[ared to my teacher

[idle tusk]

that sucks

.reopen

[crimson sedge]

and i still get it wrong because its not the way she wants

[cedar kiln]

✅

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rare pasture]

$\varphi$ is a linear transformation in $\mathbb{R}^3$ of projecting onto the line $x=0, y=t, z=t$. I have to find the standard matrix of $\varphi$, and find bases in $Ker(\varphi)$ and $Im(\varphi)$. I've calculated the matrix to be $\begin{bmatrix} 0 & 0 & 0 \ 0 & 0.5 & 0.5 \ 0 & 0.5 & 0.5 \end{bmatrix}$. From this, with Gauss elimination I get $\begin{bmatrix} 0 & 1 & 1 \ 0 & 0 & 0 \ 0 & 0 & 0 \end{bmatrix}$. I'm unsure as to how to proceed because I believe that the kernel of this matrix should be the plane perpendicular to the line, going through the origin, but I cannot seem to get that.

[wraith dagger]

max

[cedar kiln]

@rare pasture Has your question been resolved?

[rare pasture]

<@&286206848099549185> may i get a little help pretty please?

[cedar kiln]

@rare pasture Has your question been resolved?

[frozen relic]

i can try helping

just give me a tiny bit

[frozen relic]

@rare pasture

tbh i don't know if its truly correct either 😭

[cedar kiln]

@rare pasture Has your question been resolved?

[rare pasture]

i see what you're getting at, but i think the kernel should be a whole plane

if we consider it non-numerically, projecting stuff onto the line perpendicularly should result in a whole plane going into the zero vector

[cedar kiln]

@rare pasture Has your question been resolved?

[cedar kiln]

@rare pasture Has your question been resolved?

[buoyant heath]

@everyone

i NEED help

[calm magnet]

@everyone

I need HELP

plz find all (k, n) where 1 + 2 + ... + k = (k + 1) + (k + 2) + ... + n

please help me

[cedar kiln]

@rare pasture Has your question been resolved?

[worldly chasm]

@rare pasture if you haven't yet, one way to think about the kernel is it's the eigenspace associated with the 0 eigenvalue. You can just solve the eigenvalue problem for this matrix to get a twice repeated eigenvalue of 0, then find two associated linearly independent eigenvectors.

We can rewrite your matrix into a single constraining equation, y = -z. So we have eigenvectors [1 0 0] (x is unconstrained) and [0 1 -1] these form a basis of your null space.

The image is the eigenspace associated with the rest of your eigenvalues. You can find the final eigenvalue and the eigenvector associated with it to get a basis for this space. Or you can do regular vector tricks to find one. (Take a random vector v linearly independent of both [1 0 0] and [0 -1 1], take the dot product with the first of these vectors to get the projection of v onto it, subtract it away from v, then repeat with the second one.)

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral vapor]

i was doing this question, but when i divided everything by (ef + df + de), i get 3 Cs, so idk how choice D is correct (based on the answer key), i did it and got c = 3def / (cf + df + de)

[undone halo]

show your work

[floral vapor]

uh

wait leme type it out

cuz no camera to take a pic of the paper lol

phone aint work

gime a sec

73 / c = 73 / d + 73 / e + 73 / f

multiple everything by 1/73 to remove the 73s

1/c = 1 / d + 1 / e + 1 / f

multiply everything by cdef

def = cfe + cdf + cde

divide everything by fe + df + de

def / (fe + df + de) = c + c + c

def / (fe + df + de) = 3c

3def / (fe + df + de) = c

that's how i attempted to solve it so pls tell me where i went wrong

[undone halo]

you should only have 1 c

not 3

...
def = cfe + cdf + cde
def = c(fe+df+de)

[floral vapor]

oh

LMFAO

😭

mbbbb

welp that's like a 500 on my sat 2 days later

kk how to close

[undone halo]

.close

[floral vapor]

.close

[cedar kiln]

Channel closed

Closed by @floral vapor

Use .reopen if this was a mistake.

[floral vapor]

ty btw

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lost thunder]

is this line I added incorrect?

[lost thunder]

they say complementary but didn't add the line

[cedar kiln]

@lost thunder Has your question been resolved?

[mental trail]

I think what you added is correct

$\left|\overline{\bigcup_{i\in [n]}A_i}\right| = |\mathcal U| - \left|\bigcup_{i\in [n]}A_i\right|$

[wraith dagger]

rafilou is not not born in 2003

[mental trail]

and you apply this

to get back to the formula of the "complementary case"

$-(-1)^{|S|+1} = (-1)^{|S|}$

[wraith dagger]

rafilou is not not born in 2003

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

I need help

[cold timber]

ok

[crimson sedge]

Ok so I need help with determining the range of a function

in a graph

I will send a ss of the answers and I just need help with you explaining the answer me and why the answer is that answer

one moment

@cold timber

[cold timber]

Yeah?

[crimson sedge]

Could you help me with question 10

[cold timber]

Range is just all the y value of that line

Oh

Number 10 is Domain

So it is the x value

[crimson sedge]

Could you explain why and how it’s a Domain

[cold timber]

Domain is all the x, and range is all the y

What is least x value this line have?

[crimson sedge]

I wouldn’t be able to say because I’m trying to understand how I can identify x and y on this line

[cold timber]

This way, you can identify the x and y of a point

[crimson sedge]

I’m overthinking this which is making me confused

If the y is 5

[cold timber]

yes

[crimson sedge]

And the green points to the number in the x line which is 4

[cold timber]

yes

[crimson sedge]

Why does is show 6< x < - 5?

Is the - 5 supposed to mean it’s the y value answer?

[cold timber]

You mean option D?

[crimson sedge]

Yes

[cold timber]

It is a wrong one

[crimson sedge]

Oh

So then the answer would be B

[cold timber]

Yes!!!

[crimson sedge]

Ok don’t close the ticket yet because I have a whole lot of questions and pages

[cedar kiln]

@crimson sedge Has your question been resolved?

Channel closed

Closed by @south sun

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Please don't occupy multiple help channels.

[crimson sedge]

I closed the other

[past wave]

!show

[cedar kiln]

Show your work, and if possible, explain where you are stuck.

[crimson sedge]

1 sec

,w (5-10i)(-3+8i)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by anjaliji_74295

[crimson sedge]

yes, it's right,

Thx

[livid hound]

isn't in the specified form

[crimson sedge]

the bot is never wrong

If I did it in the form

[livid hound]

yes

[crimson sedge]

thx do you mind checking my other one that I thought was right but wasnt in this form?

I need to double check

[empty spear]

nice

u right

[crimson sedge]

.close

[cedar kiln]

Channel closed

Closed by @hushed solstice

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic spruce]

hi

[exotic spruce]

can u show me the most difficult quadractic equation if all time

[crimson sedge]

Quadratic equations can't be hard

[past wave]

real coeff or rational?

[crimson sedge]

But questions based on quadratic equations can be

[exotic spruce]

rational

[crimson sedge]

Find all integers 'a' such that (x-a)(x-12) + 2 can be factored as (x+b)(x+c) where b and c are integers.

[past wave]

$x^2 + 58812x + 764387$

[wraith dagger]

Wumpus Man

[crimson sedge]

What's hard in this?

[past wave]

idk

[exotic spruce]

eventually u can solve it i mean

[crimson sedge]

Try mine.

[exotic spruce]

its just a w of time

[past wave]

https://tenor.com/view/galaxy-galaxy-brain-perndorfer-meme-uw-u-gif-26321098

[exotic spruce]

i am dumb af tell me how u so,ve it

ok w8

root a - root a-x = x, root a = x + root a - x ,a = (x + root a-x)sq = a = x2 + 2roota-x(x) +(a -x)

then

i got bored

[crimson sedge]

1. Solve the equation root(a) - root(a-x) = x, where a>0.
2. Find all integers 'a' such that (x-a)(x-12) + 2 can be factored as (x+b)(x+c) where b and c are integers.
3. Find necessary and sufficient conditions an a, b, c, d so that the equations: z^2 + az + b = 0, z^2 + cz + d =0 are collinear in the plane.
4. Find the value of the positive integer k for which the quadratic equation as shown has solutions alpha and alpha + 1 for some alpha.

[exotic spruce]

wtf is this

which grade r u in?

ws fine till the 3rd part

then got cooked

.close

[cedar kiln]

Channel closed

Closed by @exotic spruce

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce roost]

is this injective, surjective or both?

[fierce roost]

I would say that is both injective and surjective

[weak gull]

yea

[fierce roost]

the teacher said that is neither

... I am confused

[weak gull]

R<=0 means all reals less than 0 right ?

[fierce roost]

yeah

[weak gull]

well then i can't see how its neither

[fierce roost]

me too

.close

[cedar kiln]

Channel closed

Closed by @fierce roost

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe elm]

i need help with this question

[severe elm]

,rccw

[severe elm]

#10

i’m not sure how to structure my solving of the problem

<@&286206848099549185>

<@&286206848099549185>

[quaint berry]

Tan20=y/(x+300)
Tan42=y/x

[cedar kiln]

@severe elm Has your question been resolved?

[quaint berry]

Do you get it

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar sequoia]

How to prove the orthogonal part of the orthogonal decomposition theorem is orthogonal to the vector

[lunar sequoia]

Say y proj onto u

Is yhat

How is y - yhat orthogonal to u

All I got was orthogonal def is the inner product is 0

[dire geode]

and did you take the inner product of y-yhat with u?

[lunar sequoia]

No

I think it wants a proof

[dire geode]

that is the proof

[lunar sequoia]

Ohhh

So the u dot u cancels out

Leaving y - y dot u = 0

Y = y dot u

If u is not a zero vector then the right side is a scalar

Y= scalar?

I’m confused

Does u dot u not cancel out

Yhat =( y dot u / u dot u ) u

[dire geode]

can't tell if you don't show your whole work

[lunar sequoia]

Yhat dot u= ( y dot u / u dot u ) u dot u

Since it’s commutative it shout cancel out right

That is my work

[dire geode]

i can't tell the order of steps

[cedar kiln]

@lunar sequoia Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dire radish]

Why is the answer to this just infinity? Can’t you use l hospital rule

[dusk goblet]

because both go to infinity

[dire radish]

Oh

Infinity isn’t indeterminate

I forgot

I thought it was for some reason

[quaint berry]

L hospital is fo 0/0 or infinite/infinite not infinite times infinite

[dire radish]

Yea

Thanks

.close

[cedar kiln]

Channel closed

Closed by @dire radish

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[empty spear]

Lmao

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic current]

PHP question

Im stuck for this question. Im assuming I need to show that we have 93 holes right

I know that any integer from S will have a remainder from {0, 1, ..., 8} when divided by 9

Total possible unique pairs: (9*8)/2 = 36

and the pairs of remainder that sum to 9 from those 36 pairs are:

(0, 0)
(1, 8)
(2, 7)
(3, 6)
(4, 5)

Im not sure where to go from here.

[nimble veldt]

how many numbers do you have with remainder 0, 1, 2, ....?

[civic current]

just 0, 1, 2 or 0,1,2,3,4,5,6,7,8?

[nimble veldt]

for all (therefore the "...")

[civic current]

the answer to this should be 202 right?

[nimble veldt]

how many for remainder 0? how many for remainder 1? how many for remainder 2? how many for remainder 3? and so on.

[civic current]

for remainder 0 I think its 22 since floor(202/9) = 22

but im not sure how to find for the others

[nimble veldt]

if you have 22 for remainder 0, then every successor has remainder 1. so there must also be 22. the same for remainder 2, and so on. you only have to check the last few numbers above the largest number < 202 divisible by 9.

[civic current]

im sorry but Im kinda confused by "successor" here...what do you mean by that

[mental trail]

Since you're starting at 1, maybe there might be a little more numbers with remainder 1 than remainder 0...

[nimble veldt]

if 18 has remainder 0, 19 has remainder 1.

[civic current]

ohhhhh

so for the first 4 numbers its 22

0,1,2,3

[nimble veldt]

no.

[mental trail]

no

[civic current]

shit

[mental trail]

22 is correct for remainder 0

but 22*9 = 198

[nimble veldt]

up to 198 you have 22 for each reaminder. then look at 199 - 202.

[mental trail]

so there are 4 remainders with one more

(or alternatively, look at the first four in the set)

[civic current]

wont 199 give remainder 1
200 will give 2
201 will give 3
202 will give 4?

[mental trail]

yes

[nimble veldt]

thats why 22 ofr reaminder 1 is wrong.

[civic current]

so its 23 for 1?

[nimble veldt]

yes

[mental trail]

yes

[civic current]

24 for 2, 25 for 3, 26 for 4

[nimble veldt]

no.

23 for 2, 23 for 3, 23 for 4.

[civic current]

ah

where do I go from there

[nimble veldt]

how many numbers with raminder 0 can you use for the coice of 94 to avoid a sum divisible by 9?

[civic current]

any 2 number with remainder 0 should result in a sum divisible by 9 right? so none?

[nimble veldt]

one is possible.

[civic current]

mhm let me think one sec

idk

[nimble veldt]

two is not allowed (then you would have a sum divisible by 9) but one is ok.

[civic current]

I dont get it

[nimble veldt]

if one number has reaminder 0 (lets call it a) and all other have remainders not 0, then the sum of a with any other has a remainder not null, so its ok to have one.

max. one number.

[civic current]

oh I understand what you mean now

but how does this help

[nimble veldt]

so we take one number with raminder 0, and all with remainder 1, all with remainder 2, all whith remainder 3 and all with reaminder 4.

how many numbers do we have?

[civic current]

1 + 22 + 23 + 23 + 23

92

[nimble veldt]

no.

1+23+23+23+23

[civic current]

oh remainder 1,2,3,4 mb

ok I get it now

tysm

.close

[cedar kiln]

Channel closed

Closed by @civic current

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid kernel]

The wuestipn wants us to decide the values a and b

In order to solve the equation

I don’t know how I’m supposed to continue

Helloo

[cedar kiln]

@frigid kernel Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ancient quarry]

Let $A$ be an $n$ by $m$ matrix with rank $m$ and SVD $A = U \sum V^T$. Show that the least-squares solution can be written as $$
x = \frac{b \cdot u_1}{\sigma_1}v_1 + \ldots + \frac{b \cdot u_m}{\sigma_m}v_m
$$

[wraith dagger]

Bean Man

[cedar kiln]

@ancient quarry Has your question been resolved?

[ancient quarry]

<@&286206848099549185>

[flint plinth]

least squares solution to what problem?

what is b here?

[ancient quarry]

Sorry, the least squares solution of the $Ax = b$

[wraith dagger]

Bean Man

[flint plinth]

do you have a general formula for the least squares solution to this problem?

something involving the pseudoinverse of A?

[ancient quarry]

There is no more information about A, x, or b

[cedar kiln]

@ancient quarry Has your question been resolved?

[ancient quarry]

.close

[cedar kiln]

Channel closed

Closed by @ancient quarry

Use .reopen if this was a mistake.

[crimson sedge]

hello

can anyone help me

.reopen

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@pine jay Has your question been resolved?

[pine jay]

<@&286206848099549185>

[cedar kiln]

@pine jay Has your question been resolved?

[cedar kiln]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager vapor]

where did .675 come from

[meager vapor]

very confused

[dire geode]

Not enough information

Gotta show the question

[celest flume]

z score of .75 is between .67 and .68

[meager vapor]

yeah idk how it ties into the question

[dire geode]

He told you in the first sentence

z score of .75 is between .67 and .68

[meager vapor]

beetween .67 and .68 of what

[dire geode]

Do you know how to read a z table

[meager vapor]

yeah'

.75 goes to .7734

unless im dumb

[dire geode]

That's not how you read the table

0.75 is the z score

P(Z < z) = z score

P(Z < 0.67) < 0.75 < P(Z < 0.68)

So they just took the midpoint of 0.67 and 0.68

[meager vapor]

yeah honestly I get confused with all the z score terms

[dire geode]

Then it's better to say that

https://youtu.be/5S-Zfa-vOXs?si=mb_z_d5MtTYzhOHq

https://youtu.be/S5_5KyCVjrU?si=vxJU0CpUJHFI9Vn9

[cedar kiln]

@meager vapor Has your question been resolved?

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith slate]

Can someone do this and teach me

[fair geyser]

i never tried this kind of thing but i have some idea

[solemn quail]

There's a good way to make a chart of this information. It's very useful, almost essential.

[fair geyser]

i think there's no trick to this

you make a table

and just read it over and over

and infer

[solemn quail]

Like this

[fair geyser]

that's too powerful

but thanks

[solemn quail]

It'll be smaller than that. It's absolutely what I'd do, but I suppose it's not necessary.

[fair geyser]

maybe this one is harder than it looks in fact

we can write this, it says Kieran was 2nd, and he's not physcis

but in (1) we learn he's not the math

so biology

from 2 and 4 we can deduce that 3 is granola

it's not obvious

apple is earlier than something, and bagel is earlier than something, so they must be 12 or 21

then Kieran is not granola and not bagel (from 1)

ok then (2) is talking about Kieran

and (1) completes it

so we didn't need the expanded table

but we needed a tricky inference

[cedar kiln]

@wraith slate Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[analog summit]

hi guys

[analog summit]

how to show that

f(x,y) = (exp(xy)-1)/(x²+3y²) non continuous at (0,0)?

[sharp lotus]

well what is the definition of continuous?

[analog summit]

lim(f(x,y)) when (x,y) -> (0,0) = f(0,0)

i forgot to add

f(0,0) = 0

[sharp lotus]

oh

[analog summit]

yh srry

[sharp lotus]

then youll have to evaluate the limit

[analog summit]

i tried finding a sequence that converges to (0,0)

but doesnt seem to work

[sharp lotus]

did you learn about evaluating limits along different paths?

[analog summit]

no...

[sharp lotus]

=\ then you'd have to learn about that, otherwise youre just trying to do a problem with concepts youre not familiar with

[analog summit]

so i can't do it with sequences?

[sharp lotus]

sorry i'm not too fluent in this stuff so i can't say

i just know that way of thinking of it would be quite straightforward

[analog summit]

well i only know the sequential definition and the epsilon definition of the limit

[sharp lotus]

because there are 2 independent variable, you can sort of think of it, well if you approach that (x, y) coordinate in the xy plane, you could do so from various directions

and the limit will exist if the limit as you approach it matches up for all directions

so one direction would be for example along x axis...y = 0 there so it reduces to plugging in y = 0 then evaluating the limit as x ->

you can also approach along y axis ... x = 0 there similarly

or along some arbitrary line y = kx, you'd just plug in y = kx then evaluate the limit as x - > 0

that should give you the answer you need

[analog summit]

we didnt learn about that yet so idk

i can use that but

i dont know if it counts

[sacred grail]

its okay to produce two sequences limiting to 0 such that f(those sequences) give different limits

along the lines y = kx

[analog summit]

so what are the sequences?

[sacred grail]

try come up with a sequence which approaches 0, but also lies on the line y = kx for some fixed k

[analog summit]

huh? (1/n, k/n)?

wdym

[sacred grail]

yeah that works

try evaluating the limit ig

[analog summit]

mmhh

isnt the numerator always going to be 0?

when n -> +inf

lim exp(k²/n²) = 1

[sacred grail]

ye but the denom is also

you get a 0/0 indeterminate form

[analog summit]

yes

then

i dont know this limit

@sacred grail how do i find this limit then?

[sacred grail]

,, \lim_{n \to \infty} \f {\exp(k/n^2) - 1} {(1/n^2) + 3(k/n)^2}

[sacred grail]

this?

[analog summit]

yes

[sacred grail]

okay so

its the same as

,, \lim_{n \to \infty} \f {\exp(\f k {n^2}) - 1} {(1 + 3k)(\f 1 {n^2})} = \lim_{t \to 0^+} \f {\exp(kt) - 1} {(1 + 3k)t}

[sacred grail]

agreed?

[analog summit]

yes

[sacred grail]

okay now

,, \lim_{t \to 0^+} \f {e^{kt} - 1} {kt} = \lim_{h \to 0} \f {e^h - 1} h

[sacred grail]

agreed?

[analog summit]

yes

[sacred grail]

okay

do you recognise this limit?

[analog summit]

no but i just checked and it's 1

[sacred grail]

it is 1

heres how you might know it

,, f'(x) = \lim_{h \to 0} \f {f(x + h) - f(x)} h

[sharp lotus]

cool

[analog summit]

yes indeed

[sacred grail]

you now have to use this fact to evaluate the original limit up here

basically just faff about with some scaling factors

nothing too fancy

[analog summit]

ok...

so it is
k²/(3k²+1) wich is obviously not always 0

[sacred grail]

something like that

i didnt check the details

i think i messed up the algebra at some point too

[analog summit]

well i know it's not 0 so i dont really care about the exact value

thank you

.close

[cedar kiln]

Channel closed

Closed by @analog summit

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wild belfry]

I converted this into the form

So the right fraction I can integrate really easily

And the left fraction is in the form where the numerator is the derivative of the denominator

For the left fraction, I forget what the next step is though...

[wild belfry]

Like why did I want it in this form? I know there is a method but I forget it

[normal cipher]

Integration by partial fractions

I forgot how to do it

[unique nest]

Note x^2+2x+8=t

then (2x+2)dx=dt

[wild belfry]

Yeye I remember I needed to get it in this form

[normal cipher]

Ah

[wild belfry]

I just dont know what the next step is

Now that the numerator is the derivative of the denominator

[muted timber]

the antiderivative of dt/t is immediate

it's ln|t|

[wild belfry]

How come sry?

[unique nest]

Well...the next step is, you integrate $\frac{\frac{3}{2}dt}{t}$

[wraith dagger]

Wild123

[muted timber]

do you not have a table of immediate integrals?

[wild belfry]

Never even heard of it

[unique nest]

you integrate 1/t... it's formula

[muted timber]

something like this?

[unique nest]

just google images 'integration formulas'...there's plenty

[wild belfry]

Ah ok

Im self taught kinda I dont have a teacher so I dont really know everything 😅

[muted timber]

are you following a textbook?

[wild belfry]

A website

It kinda functions like a textbook I guess

[muted timber]

it should have some a table of the sort, and/or proofs for some

but on this specific case, the natural logarithm is defined to be the result of that integral

[wild belfry]

So its just (3/2)(ln(x^2 + 2x + 8)?

For the lhs

[unique nest]

forgot the 3/2

[wild belfry]

sry hehe

[muted timber]

(3/2)*ln|x^2+2x+8|

[wild belfry]

Ah oke

[muted timber]

the absolute value needs to be there

[wild belfry]

I get it now!

Thank you everyone!!

❤️

.close

[cedar kiln]

Channel closed

Closed by @wild belfry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sonic holly]

WTF IS HAPPEN HELP

[unique nest]

trying to 'pull the squares' from under the sqrt? (I don't know if that's the proper wording)

[sonic holly]

?????

[unique nest]

For example... you know $\sqrt{y^2}=?$

[wraith dagger]

Wild123

[sonic holly]

y(1/2)

y powered by 1/2

[unique nest]

afraid not. that's just $\sqrt{y}$

[wraith dagger]

Wild123

[unique nest]

the square root is equivalent to raising to power 1/2.

so here, $\sqrt{y^2}=({y^2})^{\frac{1}{2}}$

[wraith dagger]

Wild123

[unique nest]

How much is this?

[sonic holly]

y powered by 2/2

[copper cove]

No

It is not y.

[unique nest]

True. 1 missing detail, since y could be negative 🙂

[copper cove]

The squared is inside a sqrt.

If it were outside that would be true.

[sonic holly]

if y would have been negative it woulda been i square root y

[copper cove]

No

Because it is squared

Always positive

[sonic holly]

dawg we're getting off track i need help with ts

[copper cove]

You need to chill and listen

We are teaching you.

[sonic holly]

Ok

[copper cove]

y^2 is always positive

So it does not matter if it is y negative or y positive, it will be positive

That is why sqrt(y^2) is not y

but |y|

Do you understand this?

[sonic holly]

yeah

[copper cove]

Ok, so what is your question now?

[sonic holly]

its telling me simplify

and when i go to gpt

it tells me 2 square root 3

[copper cove]

Do not use that, use your brain

First of all

the context, are we on real numbers?

[sonic holly]

it told me assume all variables are positive so yeah

[copper cove]

then you ignore absolute value

and you can say sqrt(y^2) is indeed y

now you do the same with sqrt(x^7)

recall x^7 = x * x^6

[muted timber]

never use chatgpt for maths

[copper cove]

so you can rewrite as sqrt(x) * sqrt(x^6)

and now you can simplify the second

[native zinc]

Never use AI for math

[sonic holly]

arent getting anywhere my professor is telling me something and your telling me something

.close

[cedar kiln]

Channel closed

Closed by @sonic holly

Use .reopen if this was a mistake.

[copper cove]

i think the problem here is neither the professor or us, you have to study more

[coral jewel]

$\nogpt$

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact epoch]

errm guys i could need help on this. Some people say i did it wrong here while others told me to do it like that

[cedar kiln]

@compact epoch Has your question been resolved?

[cedar kiln]

@compact epoch Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mossy aspen]

Could someone please help me with this. Im a bit clueless.

[proven herald]

This is easy but I am into much complex thing

[pastel vault]

do you see that the white triangle in the square has area 1/4 * a^2

divide the square into 4 equal parts in an X shape

[mossy aspen]

yeah

[pastel vault]

cause the square is just rotated

that other tilted square also has the same area, a^2

[mossy aspen]

mhm

[pastel vault]

hence can you find the grey area now?

[mossy aspen]

ohhhhhhh

thanks so much

yeah i get it now

[pastel vault]

np!!

[mossy aspen]

.close

[cedar kiln]

Channel closed

Closed by @mossy aspen

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mortal yarrow]

yo do you guys know any good books for learning euclidean and non-euclidean geometry?

[crimson sedge]

euclidean geometry in mathematical olympiads

[mortal yarrow]

is that the title of the book?

and who is the author?

[lyric narwhal]

Evan Chen

he has a few chapters available for free online

[crimson sedge]

yes

[cedar kiln]

@mortal yarrow Has your question been resolved?

Channel closed

Closed by @mortal yarrow

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact crown]

.open

How would i begin to solve this?

[compact crown]

I kind of don't understand the question

is the bottom table the same width but just longer? So its basically a rectangle

am i supposed to get the square root of 2.25 to find the length, which is 1.5 meters?

okay i think its a square but it looks like a rectangle so its confusing

[cedar kiln]

@compact crown Has your question been resolved?

[cerulean star]

The table begins as a square

[compact crown]

Yes

[cerulean star]

The area of that square is 2.25 m^2

[compact crown]

Right

[cerulean star]

So then x^2 = 2.25 m^2

And the width is the square root of that

[compact crown]

the square root of 2.25?

[cerulean star]

Yes, that number is in square meters

[compact crown]

1.5 is the square root of 2.25

so 1.5 meters is 1 side

[cerulean star]

Cool

Yes

[compact crown]

alright so the next step would be?

[cerulean star]

The second image says the leaf is 40 cm long (0.4 m)

[compact crown]

yeah

do i have to convert 40cm to meters

[cerulean star]

You need to work with consistent units to solve an equation

[compact crown]

okay so we're talking meters here then right?

so .40 meters?

[cerulean star]

Yes

We need to reach 4.05 square meters

[compact crown]

Right thats what i dont get

so .40 times 1.5 ?

[cerulean star]

So we have the starting table's area plus an unknown number of leaves' area, which should equal 4.05 m^2

[compact crown]

until we get 4.05 meters?

[cerulean star]

Uhuh

So then

[compact crown]

.40 times 1.5 is like a formula for a rectangle right ?

because since it gets longer

it turns into a rectangle?

[cerulean star]

2.25 m^2 + (0.6 m^2)k = 4.05 m^2

[cerulean star]

Yes, the formula for the area of that leaf

[compact crown]

OKay so according to bedmas

[cerulean star]

We can calculate that easily actually, it's 0.6

[compact crown]

so then its 2.25m2+ 0.6 ?

[cerulean star]

I have the equation above

[compact crown]

oh right i need to squaRE 0.6 ?

[cerulean star]

k is the unknown number if leaves required

No

[compact crown]

2.25 times 0.6 ?

[cerulean star]

(1.5 m)(0.4 m) = 0.6 m^2

[compact crown]

right

but i thought we mulitply

[cerulean star]

That is multiplication

[compact crown]

here , i thought we multiply 2.25 and whatever is in the bracket

[cerulean star]

There's a plus there

[compact crown]

yeah i see that my bad

so we;re adding 2.25 + 0.6 ?

[cerulean star]

The total area is the starting area plus the area of however many leaves

let k be the unknown number of leaves

The area of a leaf is 0.6 m^2

[compact crown]

of how many leaves to get to 4.05m2 right

[cerulean star]

Yes

[compact crown]

are we supposed to dividee 4.05m2 by 0.6m2 ?

[cerulean star]

By the way, you don't need to write the units to solve this problem, but it helps keep your work organized

And helps you check that your formulas make sense

[compact crown]

Alright yes

How do we begin to find the k

[tribal kite]

no

you need to subtract the original area

then divide

[compact crown]

the original area being 2.25 ?

[tribal kite]

yep

do u know why u have to subtract the original?

[compact crown]

i don't

what do i subtract the original with ?

[tribal kite]

okay so if u take 4.05 divided by 0.6

you get the number of leaves needed to get 4.05m^2 right

[compact crown]

4.05 divded by 0.6 ?

its 6.75

[tribal kite]

ok chill dont

dont go with the calculations first

[compact crown]

ohh okay

[tribal kite]

if u do 4.05/0.6

you're finding the number of leaves

such that the area of the leaves

is 4.05m^2

correct?

[compact crown]

ohhh

okay yeah

[tribal kite]

but they want the TABLE to be 4.05m^2

not the leaves

[compact crown]

right

[tribal kite]

so you start with A

[compact crown]

the num,ber of leaves needed

[tribal kite]

they tell u

[compact crown]

to increase the area to 40.5

4.05***

[tribal kite]

A+0.6k=4.05

correct?

[compact crown]

0.6 came from l x w right/

from the leaf

[tribal kite]

yes

yes

[compact crown]

okay

[compact crown]

yeah

[tribal kite]

0.6 is area of 1 leaf

ok so

you want to find k

do u know what A is

[compact crown]

yes i need to find k

A is original ?

[tribal kite]

yes

[compact crown]

the 2.25

[tribal kite]

yes correct

so 2.25+0.6k=4.05

how do u find k

[compact crown]

I dont know how to find k here

[tribal kite]

ok so what happens if i do

2.25-2.25+0.6k=4.05-2.25

is that correct

i take away 2.25 from both sides

so they are still equal right

[compact crown]

0 +0.6k = 4.05-2.25?

[tribal kite]

yes!

[compact crown]

ohhhh okay

[tribal kite]

0.6k=1.8

right?

[compact crown]

so we are moving it over

[tribal kite]

whats k

[compact crown]

1.8+0.6 ?

[tribal kite]

yess

[tribal kite]

nono

0.6*k=1.8

not +

[compact crown]

4.05-2.25= 1.8

[tribal kite]

yes

[compact crown]

um are we multiplyuing

[tribal kite]

ok how do u undo a multiply

[compact crown]

1.8 times 0.6 ?

what do you mean undo

[tribal kite]

if i have x*3

how do i find x

[compact crown]

x to the power of 3??

[tribal kite]

times

[compact crown]

oh times

okay

[tribal kite]

x times 3

how do i find x

[compact crown]

3 times 1

[tribal kite]

nono

ok look

if i have 3x=3

to find x

[compact crown]

do i isolate the x?

[tribal kite]

i divide by 3 on both sides

yes

you want to isolate the x to find x

[compact crown]

x= 3+3 ?

[tribal kite]

no

[tribal kite]

^^

whats 3x/3

[compact crown]

its 1

[tribal kite]

no

[compact crown]

3 divded by 3 ?

[tribal kite]

whats 3x divided by 3

theres an x

[compact crown]

ohh so its 1 x?

[tribal kite]

it just becomes x right?

yeah!

[compact crown]

oh okayy

[tribal kite]

so if i have 3x=3

i divide on both sides

3x/3=3/3

[compact crown]

x = 3 divded by 3 ?

[tribal kite]

yes

whats that

[compact crown]

1x

[tribal kite]

is there an x?

[compact crown]

not in this one

[tribal kite]

3/3 has no x right

[compact crown]

its just 1

[tribal kite]

yeah

so x=1

yeah!!

[tribal kite]

so here

[compact crown]

alright

[tribal kite]

i have 0.6 times k =1.8

how do i find k

[compact crown]

k= 0.6 divided by 1.8

[tribal kite]

are u sure

[compact crown]

no way its the other way around

[tribal kite]

yesss

[compact crown]

k= 1.8 divided by 0.6

[tribal kite]

1.8/0.6

=3

[compact crown]

oh my god

[teal wraith]

dude

[tribal kite]

so whats k

[teal wraith]

let him multiply by 10 on both sides

so it'd easy

[tribal kite]

what for

[compact crown]

k= 3

[tribal kite]

theres no point he can do division bruh

[compact crown]

so we always divide when we isolate the x?

[tribal kite]

yes correct!!

[tribal kite]

no

if u have x times something

[compact crown]

like when you switch it over

ohhh

[tribal kite]

you can divide by something on both sides

to get x

because something/something is 1

[compact crown]

but since we made an equation out of the square

[tribal kite]

no you didnt

k wasnt squared

you dont have to do anything

3 is the answer lol

[compact crown]

k is the number of leaves needed

[tribal kite]

yeah

[compact crown]

yeah i know 3 is the answer, i jus twante dto understand

the division part

[tribal kite]

ah ok

[compact crown]

like when to do it

[tribal kite]

so

[compact crown]

x times something becomes division then

[tribal kite]

if u have n times x = 7 how do u find x

[teal wraith]

clearly hes having trouble doing it

[tribal kite]

hes having trouble with EQUATIONS

theres a difference

[teal wraith]

ok

[tribal kite]

^^

[compact crown]

n= 7 divded by x ?

[tribal kite]

yes but you want to find x, not n

[compact crown]

so its x= 7 divded by n

[tribal kite]

yes!!

how about x+n=7

[compact crown]

okay so is it the same with addiction and subtraction

like u swap

wait

x = 7-n

[tribal kite]

yes!!

[compact crown]

ohh okayyy

thats what i get confused on sometimes

[tribal kite]

how about x divided by n = 7

[compact crown]

like the swapping

x= 6 times n

i mean 7

[tribal kite]

yes!!

yeah i think u got it

[compact crown]

okayy i just gotta remember the swapping rule

i didnt get it before

i forgot about it

[tribal kite]

okay nice

if u dont have any other questions u can use .solved or .close

[compact crown]

thank you so much, i understand this problem now

im just a bit slow, havent done math in so many years

I have one more question

is this probability of indepdenent events ?

or is it probability of mutually exclusive events

they show 2 different formulas

Probability of independent events
P(A and B) = P(A) × P(B)

[teal wraith]

it says "or"

[compact crown]

Probability of mutually exclusive events
P(A or B) = P(A) + P(B)

yes im wondering which formula do i use for this

[teal wraith]

i think add

since its or

generally for or u add

For and u multiply

[compact crown]

ohhhh okay

so how do i begin this equation here

[teal wraith]

also it literally says "or" in this formula

[compact crown]

P=30 + 5 ( ? )

[teal wraith]

favourable outcome/ total

[tribal kite]

or is +, and is x

[tribal kite]

put them in a fraction of the total time

[compact crown]

so theres 3 colors

where do i put the 3

[teal wraith]

number of seconds red is displayed/ total seconds

total seconds is number of seconds for red + yellow + green

[compact crown]

so 30 times 60 first

[teal wraith]

yes

so thats 1/2

for yellow u get 5/60 right

[compact crown]

30 times 60 is 1800

[teal wraith]

No

You're supposed to divide

[compact crown]

ohhh right

so 30 divded by 60

0.5

[teal wraith]

yes

[compact crown]

5 divded by 60 shows up as 0.083

[teal wraith]

for an easier method just add 5+30/60

[compact crown]

25 divded by 60 = 0.41

[teal wraith]

this gets reduced 35/60

[compact crown]

so 35 divded by 60= 0.58

[teal wraith]

ye

its 7/12

[compact crown]

are we rounding 0.58 to .60 ?

[teal wraith]

U got 35/60

[compact crown]

ohhh

[teal wraith]

Now divide both 35 and 60 by 5 to simplify

[compact crown]

i get it now

when i divided 7 by 12

its the same

[teal wraith]

since u divide both the answer doesn't change

Yeaah

[compact crown]

from 35 divded by 60

[teal wraith]

correct

[compact crown]

so if its or

its additionfirst

like when it says 2 things

adding those 2 probabilities first?

addition**

[teal wraith]

yeah in this case

if the denominator isn't same you add seperately

In this case they were same that is 60

u could also solve seperately and add

[compact crown]

when it shows a fraction?

[teal wraith]

just a lengthy method

[compact crown]

the bottom number u mean?